#competition-math
1 messages ยท Page 43 of 1
the good news is that AMC10 shares around half its questions with AMC12
no worries!
im trying to aime qual with the amc 10
so hopefully i can get someting good next year
yeah, I reckon something like this would be around your current level
https://www.youtube.com/watch?v=UptxaTDsBLE
https://www.youtube.com/watch?v=AW0qmIKH_Yc
though this has better video quality (from the same COVID maths series)
the Luke Robitaille one is clearly not the best video
luke seems like a guy that uses intuition to solve most things
agree, but that would be if they did zero prep
stayed at their current level forever
im comparing the problems themselves?
fair
I mean there's different ways of responding to that, sure
this is my estimate of what can be done with only AMC8 knowledge
yeah and of course each test varies
what does ts mean
nvmi didint
your avg score?
national average
no amc 8 i mean
national avg means nothin
yeah the national average is usually pretty low
a lot of people take it 'for fun', which is great for promoting maths of course
or their maths skills aren't that great to begin with
i was kind of close to making mathcounts national but there were two brothers who were a lil too good
wow
so i always thought ppl took math competitin seriously
they do
which state
AZ
only a subset of people would actively be trying to qualify for AIME and so on though
kids these days have too much stress on their plates
dox
especially here in arizona where basis schools are a thing
the last year i took mathcounts arizona did surprisingly good
it was probably the brothers
who
bowen and ian
idk these ppl
the older one is taking calc bc in like 9th grade or sm
is that one kid puranjay still doing mathcounts
idk if hes in hs now
hs
damn
bubo which state are you from?
IL
ah
i remember in my 7th grade year basis kids were first second and fourth ๐
ban
Wait what are basis schools guys?
a chain of STEM charter schools in the US
ah, they don't focus on STEM actually
Ur a fan of Ado?
Wait what
Why they stem school if they donโt focus on stem ;-;
they're not actually a STEM school, my bad
Oh aight lol
wanna be friends?
Is anyone here preparing for the AIME? DM me, I have some study materials.
when does AMC results come
im not sure when the cutoffs will be out
i thought you could js ask proctor for score
AMC 10/12 official results historically are released in December
However the results have yet t be released
so idk
there is some discussion on 10B cutoffs being lower than 90 but not sure
nah bro
prob gonna be like 96
we do?
why are YOU in this server you dont even like math ๐ญ
who said that ๐ญ
for 10b they were js long and wordy asl
me
Get out of here
The only ones I got wrong were 3 and 5 ๐ญ
3 I sillied 5 I didnโt get
yeah but for aspiring aime quals theyd be focused there
aspiring aime quals ๐ญ
bro idk
๐
like ppl focused on the first 15 ish questions
they misordered the questions sm this yr
is aime prestige going down?
idk y but i heard that somewhere
aime has no prestige ๐ฅ
i feel like thats kind of true esp with the scandals going on
even oly is somewhat off putting
for you maybe
i think many would agree with me
what scandals
bro amc 10a fucked me up bad
not even the whole thing
literally just like one question in first ten ๐
so for the b, i started on q25 and worked backwards
aime looks good if its not your main gig i guess
u mean for uni?
hold up
yeah
q5 my dumbass counted wrong and thought the answer was 44
yeah ig
from there
yeah true
which is why its kind of not like that good if you make aime
eah
bc like unis cant rlly trust ppl
or at least these last couple yrs
yeah ofc
if you can oly qual thats better but still kind of doubtful
honestly, they can't trust olympiad results until amo/jmo
i think i guess if you can get like at least hm theyll trust you
so sad bro
like whats the point in grinidng if u can't get to national team level bcuz ppl still gonna doubt
Everyone and their mother cheating on ts
bro what
i remember one of my friends said smth like 40 or 50 percent of ppl cheated on this one cs comp ๐
i dont think it was usaco though
oh that was like MITIT
a bunch of ppl from outside the US cheating
no bro canada's co was so bad they canceled results for everyone
how do they prevent cheating on the amc tests, like if a teacher is in on it
lmao they can't
but how
wait nbm
i read what u said wrong
cuz i remember seeing ppl selling answers on reddit lmfao
yeah idk if those r real but ik ppl who bought answers, ppl who's teachers let them have an extra hour, ppl who's teachers did the questions with them before the test
its crazy bro
especially when it determines aime and ultimately usamo qual
insane
i guess it looks better for the school if the people do better but thats literally wild
ikr its seriously crazy what these teachers r doing
Hello everyone! I don't know if this is the right "chat" to send this or not (if not, kindly tell me where). But I am in 8th grade and I am passionate about mathematics (and coding ๐
and want to participate in the Mathematical Olympiad. I gave the IOQM this year from KVS and got 24 (lost selection by 1 mark) without any preparation. I want to get to the RMO or INMO next year and I am planning to start this year. I can't afford those expensive tuitions and I'll have to self study. I can't find good videos about it on YouTube so I've turned to Discord. If you have any tips / help / guidance, it's welcomed.
I have the PDFs for the following books, and I'll buy hardcopies of some (kindly tell me which ones).
An Excursion In Mathematics
- Challenges and Thrills of Pre-College Mathematics
- Mathematics Circles (Russian Experience)
- Functional Equations
- Problem Primer for the Olympiad
- Everything You Need to Ace Mathematics on One Big Fat Notebook
- Inequalities: An Approach Through Problems
?
?
sorry i dont know any of these i'm not english
Just get like aops volume 2
Or that + volume 1
Many of my peers are recommending A_Beautiful_Journey_Through_Olympiad_Geometry, Modern_Olympiad_Number_Theory, and Principles-And-Techniques-In-Combinatronics too. What about these?
How to do this calculation quickly manually?
The aops bookstore has some good books
I'd personally recommend volume 2
And maybe a specific book for an area you struggle with
For ex you struggle with geo get intro to geo
Buy print or online math books for gifted students. Purchase a full math curriculum plus math contest preparation for elementary through high school.
I don't know why but every time I look at your pfp I see whitebeard before I see luffy
I just hallucinate a mustache
๐ญ
๐ญ what
i dont think whitebeard has black hair bro ๐ฅ
nah its his cap
oh right
thats fair
this is probably the only way to do this without approximating every percentage
ud lose out on some values by doing so
Yeah these are good but advanced
Yeah thatโs a nice choice
I got 76.5 on amc 12 a
i got 1.5 for q25 will i get the additional 4.5?
also would this be enough for the cutoff?
24 was so ez im so stupid for getting it wrong
if i had to guess the cutoffs for A are gonna be inflated bc of 25
probably not
A typical continued fraction 1/(1+1/(1+...+1/(1+x)) with Fibonacci numbers as numerators and denominators.
Does anyone here know about the German math Olympiad, organized by the people who do this international stem Olympiad , the exams are tomorrow and I need someone to crash course me
guys what can i use (online) to study for the imo?
Just google some Olympiad books
There are stuff on number theory, geo, and combinatorics that are all free online
is this math
yea cuz whitebeard used calculus and PDE's to destroy marineford
ok thanks
Is there any books or online pdf that I could use to study for AMC 10
I need this
My mom is kinda homeless
aops volume 1 + mastering amc 10/12
id say the latter is better for the many exercises it has
Spoil ratio mastering amc 10/12 ?
? ๐ญ ๐ญ
Sohil rathi
What is the latter
This one
i see your solution and i dont think its the intended one ๐
I'll just skip the question lol
evan chen otis
if you're a billionaire
they have financial aid vro ๐
na but otis cheaper than a bunch of math schools/academies
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
4
Show your work, and if possible, explain where you are stuck.
Complementary counting obviously, and then focus just on the vertical lines, and the square the result. So, our answer is 1 - (x/100)^2 where x is how many ways can each of the two choose two random parallel lines (vertical for this case) without them overlapping (they can be same line, but no overlap). I got 60 somehow, and so I got answer of 16/25. But i don't think it's right
There will be a square of overlap only if there's overlap in each dimension, so it should be (1-x/100)^2 rather than 1 - (x/100)^2.
Oh yeah!
However, by my first count you should have x=16 rather than x=60.
hmmm... how?
Start with the 5 vertical lines, and go case by case, I think u should get 30, and then i multipleid by 2
could u tell me how u got 16?
thx
Actually now I'm getting 32 not 16. It's a bit of a messy count, though...
I did case by case. For a person, I did whether they're choice was length 1,2, or 3
And then x2 at the end
what problem is this from
I can't tell sry
it's part of a paid aops class
I would appreciate if u could try it tho
cause i got an answer
but dont think it's right
Okay, even newer count gives me 30 now. ๐คฆ
My main split is by the distance between the leftmost edge and rightmost edge of either of the two regions:
- if it's 4 then there are 3+2+1=6 possibilities, depending on the width of the gap being 0, 1, or 2 columns.
- if it's 3, then there are 2+1=3 possibilities for the gap width and positions, times 2 for whether the outside column is to the left or to the right.
- if it's 2, then only one possibility for the gap, but there are 3 ways to choose the two neighboring columns.
The total is now 6+6+3=15, and multiply by 2 to account for which player is choosing the left region, giving 30.
lol
thx for the help tho
anybody else?
i think u might be correct actually
i just need someone to verify
confirming 30 above ^ 30 unfavorable pairs in each dimension, so ||
(70/100)^2 = 49/100||
[https://www.programiz.com/online-compiler/8NTZ9ZK88B11X] yeah 30 is def good
Wow!
Thank u so much for the time and effort to do that!
U r the best!
PIGEON FOR THE WIN!!
it look like a minute so nw lol
i can try
On avarage how many question do i have to get right in the AIME II to go to the USAMO?
depends on amc 10 but prob around 10-13
guys suggest me some math topics to learn I'm going to interschool math competition in January 2
Plz
What is interschool?
anyone in tmsca
summation swap moment
Yeah
i got that the sum is equal to 3sqrt(e)
Perfect
its correct?
counting and probability
done ๐
Lmao
Yeah
Alr
Practice
Practice a lot
Mocks, past tests, aops textbook questions
I struggle in geometry and I try practicing it but the problem is I donโt know what else to practice
You can also use the aops textbooks for some concepts
like in geometry
are they free obline?
online*
No
shit
The only free books ik are mastering the amc 10/12
Imo itโs bad for learning theory but itโs pretty good for targeted practice
The problemsets are pretty good imo
yea
You can pirate all the aops books :))
yea ik ๐ญ
thats what i did but idk if i should be recommending it
true
<@&268886789983436800> piracy discussion
@glacial quarry we cannot allow discussion of piracy methods on this server due to discord TOS.
server rules prohibit discussion of piracy since discord would get on modsโ case otherwise
yea that
also goes for @jagged violet
Indeed, realistically I don't think any of us mods are actually ethically opposed to piracy, or at least out spokenly so, but discord is mean :(
sry
Discord prohibits piracy???
im telling discord you support piracy
alright i just sent in the email
Bro tf???
You know what they say
Snitches get stitches :))))))
infinite series formula for e:
$$
e = 1 + \frac{1}{1!} + \frac{1}{2!} + \frac{1}{3!} + \frac{1}{4!} + \frac{1}{5!} + \frac{1}{6!} + \cdots = \sum_{n=0}^{\infty} \frac{1}{n!}
$$
Written out fully for first few terms:
$$
e = 1 + 1 + \frac{1}{2} + \frac{1}{6} + \frac{1}{24} + \frac{1}{120} + \frac{1}{720} + \cdots
$$
Where $$ n! = n \times (n-1) \times \cdots \times 1 $$.
This infinite sum converges exactly to Eulerโs number $$ e \approx 2.71828 $$.
Okay, take a few hours of to decide if you really want to stay in the server.
What in the ChatGPT is this
where is this problem from
Olympiads, my friend gave it to me about a month ago
you can prob find a website that has an online pdf of the textbooks
might be a lil illegal but ive done it for many of my physics textbooks
it's not chatgpt, it's a very elementary result from calculus 2
it's the power series expansion of the exponential function
$e^x = \sum_{n=0}^\infty \frac{x^n}{n!}$
void
I think they meant they used ChatGPT to answer the question
Is it js me or is that Latin
son ๐ญ๐ญ๐ญ
im crine ๐ญ ๐ญ ๐ญ
Ts so disturbing
Gif name tho?
Hi
hey everyone I have 4 ish spots for a HMMT feb team in Chicago. Please DM me if youโre interested/want more info! You also have to be from chicago.
I see a lot of olympiad combinatoric problems have solutions involving graph theory. I'm a fan of graph theory myself, I wonder where I can read more about those
is it tuff
guys i have my math comp in a few months, any advice to start preparations
Take the day before, and the day of the competition off
my school signed me up as im the on of the best mathematicans there so they will cover that, they will also give me private tutoring but i still dont think thats enough
Believe in urself and try ur best to be confident
any undergrad level combinatorics textbook should have a few chapters on it
Yo anybody here have an HMMT Feb. Team with some spots (north cal). i really want to join pls
i have a math comp in 2 days (saturday) and ive done this many times, but i also wanna help the others who are joining me
any tips on how to teach effective math?
1+x+x^2/2!+x^3/3!โฆ
lol
2 days before is probably too late to get any substantial new content learned
youโd be better served having them practice past papers for whatever contest youโre doing
holy crap ur school sounds amazing
fr
my school signs everyone up for free? And g8 ra gets to do g9 for free too.
Anyone doing AMC 10 A/B AMC 8 or IMC
yes, amc8 and 10
that i go to rsm
like imc is rsm
Can somebody help me to solve the following problem: there are n sticks of the length 1,2,โฆ,n. How many incongruent triangles can be formed by using any of three sticks
i think use combinations
we choose 3 sticks to form a triangle out of n sticks
by that it must be nC3=n!/(n-3)!3!
since every stick is at different length
forgot a critical detail
nC3
It does
Why did u choose combinations?
i mean thats quite obvious, it's about choosing or arranging stuffs
for example you want to choose 3 players in a class with 30 people for a football team then the way to choose is 30C3 (aka choosing 3 out of 30)
now how about a class a n (n>=3) students? then its nC3
so apply the same to your question tho
I mean if u choose for example sticks with length 1,2,3, u will not be able to build a triangle because of the triangle inequality
Yeah
sorry for that i will try to solve again
lets multiply step by step
then any condition for n
ok yea its integer lol sorry im so dumb
It is a sequence of integers. Sorry that I didnโt clarify it
Understandable, but thanks for trying! @low olive
Oh ok ok
ok i give up, sorry for disturbing you so much
Well, dude i also didnโt have any clue how to solve it so I just uploaded it here, @low olive
And I looked the answer in my textbook (i just wanted to solve it myself or at least to ask the community)
still need to go the complex way๐ซ
i thought of new value to solve but i thought there must be a simplier way
but i guess there isnt?
It is complicated for me as well
Well this part of the textbook was about addition principle, but in more rigorous way
3 pages of solving is crazy
So its like a partition of a set
Yeah ๐ญ
I think i will play Minecraft now
I am too overwhelmed
yes
When are AMC 12A scores out?
They should be out already
Ask your teacher for em
12 or 10?
For 12 ye
For 10 not really
But close to aime
12
Why, it can be solved much shorter if you know about generating functions
I think this one is much easier
i havent learned about it yet, maybe i will look it up๐ค
Thanks
I don't know if this is considered competition math or not but i was wondering whether my attempt was correct or not.
Limit of n!/n^n
This one is pretty interesting because my own professor didn't know how to solve it.
correct
by scaling you can let c = 1:
e.g (2, 4, 6) is the same direction as (20, 40, 60)
so now what are a, b?
The only thing is that it wasnโt simply introduced in the textbook
You'll need to show more than the first 2 words of the problem statement ...
Wait, are you talking about $\lim_{n\to \infty} \frac{n!}{n^n}$ instead of the partial "Exercise 3 Let $(u_n)_{n\ge}$"? In that case the limit is 0:
$$\frac{n!}{n^n} = \frac{1}{n}\cdot\frac{2}{n}\cdot\frac{3}{n}\cdots\frac{n-1}{n}\cdot\frac{n}{n}$$
Each of the factors is at most 1, and half of them are at most $\frac12$, so their product is smaller than $(\tfrac12)^{n/2}$, which goes to 0 as $n\to\infty$.
Troposphere
Yes im talking about the limit when n approaches infinity
How did you know that half of them is at most 1/2?
@near hill
Each of the numerators from 1 up to n/2 are at most half of the denominator.
And how did we deduce that their product is smaller than (1/2)^n/2
Oh
$$\frac{n!}{n^n} \le \frac{(n/2)!}{n^{n/2}} = \frac{1}{n}\cdot\frac{2}{n}\cdots\frac{n/2}{n} \le \frac{n/2}{n}\cdot\frac{n/2}{n}\cdots\frac{n/2}{n} = \left(\frac12\right)^{n/2}$$
(That's for even n; there'd be a very small bit of additional footwork to make it fully rigorous for odd n too).
Troposphere
okay
I solved the question by another method but what is scaling ?
uhh this might be concerning, but i have been not paying attention to my olympiad classes lmao
and the comp is next friday 
am i cooked?
Yes ๐
<@&268886789983436800> ongoing competition
Which competition?
Uh, can you be less implicit?
In other words, how do I convince myself that you're right it's an ongoing competition before I take action?
yh it's still going
i believe you are allowed to ask for help?
unless im wrong?
Hmm, can you tell me how to find the question on that site? There's no link on "final challenges released".
you have to solve the previous problems to access the last set
you're allowed to search up like stuff, or like use some external tools like python or wolframalpha
Well, they're certainly not making it easy for moderators of external forums like this.
but like you can't actually just ask someone to do the problems
isnt the individual in the forum moreso asking for help
rather than asking someone to do the problem
i may be wrong though
But I think we've seen enough to nix this. @brisk osprey, don't use this server to cheat on ongoing competitions.
also ig this is also leaking clues
i suppose
(Relevant posts deleted).
apologies for confusion.
i mean in the help channel you seem to be sharing ur code and asking for help to make it work correctly
no the code is correct
Iโm asking where ive misunderstood
to be getting incorrect answers
you're also not really meant to be leaking problems
see here
my apologies.
I did not know this.
if you are genuinely confused by the wording of the problem, i'd recommend you email your teacher
who will best advise you on what to do
thank you
itโs just on weekends we cannot do that endeavour
as itโs banned
I just need help on the gear rotations and if physics has to be implemented.
You were clearly told not to do that.
that doesnโt have the hints
itโs the question numbers
aren't those the clues tho?
Nonetheless. No discussion of ongoing contests.
Well, @vernal axle, I looked up what a generating function is, but could you please explain your solution in more detail? I canโt quite follow it, and Iโm not sure how a generating function should be applied here.
Each question completed gives a clue
you then input it into the correct question number
but also yes it does very much say "teams should not seek help from online forums or elsewhere"
It will be too difficult to moderate if we have to make detailed decisions about whether a question actually leaks information or constitutes cheating.
especially given that we can't even see the last set of problems lol
Iโd like some help on equations of gear rotations if possible
Ok, suppose you want to count the number of pairs (a,b) of non-negative integers such that a+b=n.
You may consider a product of series (1+x+x^2+...)(1+x+x^2+...) If you expand the product you get that the coefficient at x^n is exactly the required number of pairs, since it is formed by sum of products: 1 * x^n+x * x^(n-1) +...+x^n * 1
i.e. the number of times the sum of exponents of x equals n:
0+n, 1+(n-1),..., n+0.
On the other hand 1+x+x^2+... = 1/(1-x). So, the required number of pairs is just the coefficient at x^n of the series 1/(1-x)^2, which equals binomial(n+1,1)=n+1, and which is obviously true.
Similarly for that problem above we want 2a+b+c+d=n-4.
So, we have to take 1/(1-x) three times and 1/(1-x^2) one time because it equals 1+x^2+x^4+...
so, we get g(x)=1/(1-x)^3*1/(1-x^2)
the rest is just a manipulation with the rational function g(x) and its partial fractions decomposition
you may search google or gpt for examples of generating function usages for combinatorial problems. There are many of them, like https://math.mit.edu/research/highschool/primes/materials/2018/conf/15-1 Manne.pdf
find the limit x->0+ of x^x
how to do this lol
hint: x^x = e^ln(x^x)
e^limx-0+(x*ln(x))
e^(xlnx)
lim x->0+ of xlnx
x*lnx=lnx/(1/x)
apply L'hopital rule:
its equal to limx->0 of (1/x)/(-1/x^2)=-x^2/x=x so it goes to -inf???
what?
the limit after lhopitals should be -x and as x goes to 0 from the right its js 0
and then e^0 = 1 -> lim = 1
oh also since it went to -inf, e^xlnx must be 0?
limx-->0+ of x^x by that equals to 0
ok look the LIMIT is 0, but that doesnt mean x*lnx is actually 0
as x goes to 0 (from the right), the exponent goes to 0, thus it becomes e^0 = 1
as x goes to 0 from the right, its -inf youre right on that
but for xlnx
its 0*(-inf)
thats an indeterminate form so you can use lhopitals
ah the logarithm function curve goes right down to -inf as it approaches 0, isnt it?
yes
no it doesnt apply here since were working with infinity
how do i get rid of that though? do i bring to ratio the same as i did
yes
xlnx -> lnx/1/x -> 1/x/-1/x^2 -> -x^2/x -> -x
lim as x goes to 0 from the right is 0
so 1/e^x as x reach inf into 0
Yes
thanks everyone๐ซก
how useful are cyclotomic polynomials and zsigmondy's theorem in math olympiad
$\int e^{\tan x}(\sec x - \sin x) dx$
fysch
Yeah
is it fully over
In one hour I didnโt even get half of the questions
And got even less correct
This was practice test 2
Wdym
This type of crap
Yeah
this like basic stuff
but the guy is younger so it's hard ofc
depends on the level of questions
dude he is younger then us
ofc it's easy for you cus you're older
when i was younger i didnt have problem with this stuff
now that im entering the rabbit hole shits getting serious
also tbh its harder cuz of the reduced attention spans
idk bro
yeah i feel like they havebeen nerfed hard
lol you're talking like you are 30
anyone got a solution
I have a feeling there're only 3 triples like that
What have you tried?
lol okay
p=2
but basically im just rephrasing the question and getting nowhere
i think..
I solved a scholarship exam problem in rational numbers and it was homework in a test i was the only one solved
and still teacher is still being mad for my writing style
nobody can read my writing
Use that fact that b must be equal to v2(n!)
i did that and im stuck ๐
Let a-y=x
So then get 2^y-1 =n!/2^x
U could probably use zsigmondy with bounding arguments to show thereโs no solutions for y>4
YES
chat gpt also gave me that sol
the thing is the proof for it is kinda complicated (for me)
just wondering if there was any other sol
hm ok ill tyr
Or taking mod 3
mm ok
would u consider zsigmondy as 'heavy artillery'
or its actually quite well known and im just ass..
bruh i just found out about catalan's conjecture and its proof is even more ๐
my face when i come across an easy diophantine equation and someone pulls out the "zsigmondy" or "mihalescu's theorem"
q
ive a fun one, prove that no rational numbers x,y exist such that x + y + 1/x + 1/y =2025
if so, find a real solution for the above.
Where is this from?
rmo 2025
OK, it looks like that is not ongoing anymore.
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Link for Rulebook
Link for Posters
Was that the first question to the 2024 Putnam
you can distribute and substitute as tanx and secx can be expressed in terms of sinx and cosx.
is anyone doing ritangle...
which test is this from
,ask minimal polynomial of T(x, y) = (-y, x)
Wolfram Alpha doesn't understand your query!
Perhaps try rephrasing your question?
Click here to refine your query online
nice problem
any useful sites to practice for national olympiads?
any strategies or topics which are absolutely necessary?
AoPS contest collections has an absolute glut of past contest problems to practice with
I don't understand why the number of parameters decrease by 3
In the last paragraph they say the number of parameters decrease by 3, because the sum of the vectors should be 0. Shouldn't it decrease by 2?
As a person who wants to do data science, there's data analysis questions in maths on my entrance and I do not know what to do
???
Imagine getting a graph and being asked to interprete it on the basis of profit, cost, investment and other stuff
Since this is a spatial linkage, every vector $\mathbf{u}_i$ has three components. So, $\sum \mathbf{u}=\mathbf{0} \implies \sum x_i=\sum y_i=\sum z_i=0$. Each of these equals removes one degree of freedom (or parameter) from the system, thus reducing the total number of parameters by $3$. (Note that because the spatial linkage is defined to have the vectors on a sphere, the vectors are 3-dimensional and not 2-dimensional).
Civil Service Pigeon
I Wana compete but I don't know where to start from
But, because the length of the vector is given, one of the 3 components is dependent on the 2 others right? (and that's how they got 2N instead of 3N
)
I still don't get it
undergrad math but in middle school?
Woah
my undergraduate math sucks ngl
australia
its from a book
no there is no substitution here
its the reversal of vu'-uv/v^2
hello I have my school exams in a month can any one suggest me study tips and methods
please
where are you from?
Each vector does only contribute two free paramteters since the length is fixed. However, the constraint $\sum \mathbf{u}_n=\mathbf{0}$ are \textit{global} constraints on the $2N$ parameters (aka they are not local to each vector). So, they are independent, meaning that they remove three degrees of freedom (one degree of freedom per equation). \ \
As a sanity check, for $N=3$, you have a triangle with fixed side lengths (which has no degrees of freedom up to rigid motion). So, the number of parameters in the case where $N=3$ should be $0$. Subtracting only $2$ instead of $3$ would fail to have this happen.
Civil Service Pigeon
Anyone doing ukmt this january (intermediates)
yk what misses me off abt it tho
when you search for like amc or aime problems the aops page doesnt even pop up
Oh ok thanks


its ok bro
are you sure
Its 53/135 marks
my friend got prize :/
thats 124/135
and hes not even a math nerd like me
my other friends: high dist, dist, credit and credit
come on bro
you tried your best
do you know why you didnt do well?
I havent done it before
and i canโt do it next year because i have camp in that term
when the contest is running
so ig ill have to do it in year 10
cannot tell but i am studying in senior secondary
No way b cutoff is 105 ๐ญ ๐ญ ๐ญ
Exactly my score ๐ญ
oh lol I have 100.5
these are last year cutoffs lol
any advice or help with Middle school Math Olympiad? I'm 7th grade, took lots of practice tests but still not confident im only getting 4/5 on the tests would like to make 5/5
excuse me?
moems?
Ya those are what Iโm currently doing.. Iโve practiced with the old tests as well.. just looking for more help
This should be part of it
predict dhr 126
for b
maybe 129
how did you guys originally break into competition math like study-wise where did you start off with
it lowk depends on how old u are
like i got introduced to comp math when i was in elementary school
but if ur a highschooler then just go straight into amc 10 really
alr
but like any resource ideas? ive been like watching aops textbook video lessons but like
uhh
i think reading aops vol1 textbook is a good starting place
but after that i wouldnt reccomend reading any of the other books
unless u feel like theres a subject that youre specifically struggling in
like after reading aops vol1 u should just start doing amc 10 questions
alrighty thanks
guys, are there any globally recognized math competitions that i can participate in, i graduated high school already and im in my gap year for uni
International Mathematics Competition (IMC) and William Lowell Putnam Mathematical Competition (if you enroll at a college in US or Canada)
Those are only 2 undergraduate math competitions I know
thank youu
is there any books or ressources to train for the (IMC)
I'm trying to survive my last year in highschool, I just do IMC problems (tbh I just try my best to understand the solution) from the past for fun so no
Short answer: No, maybe from past questions
answer is ฯ ?
seems like its pi in the internet well
yes , tan inverse expansion..
uhh a good free resource is sohil's amc8 series and free book online
its definitely a lot harder than moems but theres no harm in overpreparing
pick up some skills to take amc8 ig
@tacit prairie just practice more and learn more formulas and identities ig
is this real
if q25 gives me 25 i get 84.5........
...............
BRO
PLS DONT TELL ME THATS REAL
BPOAJGPOSDJ
oh nvm 82.5
but still
๐
guys im so confused
it's not out yet right
pls
yeah it aint out
Are those fake?
Itโs fake anyone can edit that page thatโs why
My heart dropped when I saw that tho ๐ญ ๐ญ
Hi
Fr
Practice ๐
Hmm
Smth has to be upโฆ right?
But like what concepts are the base fundamentals that 20% that make up 80% of maths or high-school maths
Algebraic manipulation I would say. Getting something into an equation that you can solve for an answer is used everywhere ๐
Wait genuinely wtf
was there a leak or something
Ok
We gotta wait and see ๐
Bro what are these cutoffs
how the HELL
This cannot be real
is dhr cut
shouldnt cuts be lower this year
because first 15 were harder than usual
predicted low 90s to a 105 is wild
ppl were literally predicting <90 ๐
and chatgpt
excuse me??
cursed ahh histogram
wait i heard 12b was really easy though
genuinely fried
WHAT
150 FOR HR ON AMC 12b
*a
AND 12b higher than 10b WTFFFFFFF
at least I got 100.5 on 10b :))
ts is gneuinely so fried
thank god i got like an alr score on the 12b otherwise it would've been wraps
more people got 150 than 90 on 12a
and the dhr cuts are higher than 10 for a and b
haha
"yes my name is maa yes i let students cheat and yes my test quality is becoming shit"
i didnt even dhr ๐ญ
i was predicting 129 dhr for 10b ๐
They actually need to stop paper tests and make it exclusively online
Or maybe just close it to only USA
Bc what happens for paper is that proctors get the test like 24 hrs before so they can print it but ig some proctors use that time to sell it to students
the online etests were horrible too
its so easy to cheat
theres no lockdown browser or anything u can just chatgpt
also the proctors can see the test on the maa portal im pretty sure
so they can see it no matter what
most of the people selling tests are just proctors in china
They should make it like the portals for deca bro
Any input that isnโt in the window or isnโt a left click gets flagged
so many cheaters lol
guys if a hypothetically aime qual do i have to take it at the same center i qualed
what u guys get
Holy cheaters
True that
They didnโt even count international ppl this time
๐ญ
Imagine if they did
๐๐๐
Mine was paper but mine ended like 11:40 est / 8:40 pst
Bruh for 10a ppl were telling me 94.5 would likely make it and the cutoff was 105 ๐ญ thankfully my 10b was good enough
Do students get additional 6 for q25 for 12a
yeah I think they even included it in the cutoffs
The plus6
bmt and smt get rigged anyways
Not even amc now๐ญ
What percentage is 84.5 for 12a
Just wanna write it for my linkedin
Bro
Tf
So stupid
So 82.5 is like top 25% of the participants?
I didnโt answer so I got 1.5
4.5*
only for online
yeah online ones
What is 82.5 on 12a as a percentile
105???? ๐ญ
in the big 25?????
god DAMN
i seem to remember the cutoffs going sub100 back when i was in hs
300 people got perfect score on 12a
cause of p25 void
so technically a 144, 145.5 and 150 were all turned into 150s cause of the void
bruh
how is it 150
๐
i got a 138 by studying for like hours everyday but wtf
hey its ok
theres always next year
unless youre an unc
What is 81 in 12a as in percentile
bro
the number of ppl i heard were using chatgpt
on ts
they do??
buddy ts has been going on for yrs
the cheat rate at our school might be over 10% ๐ญ
Whattt
My schools had cheaters but not from leaks
Just copying off one of the smart guys answers
it's not leaks its chatgpt
one of them didnt even qual ๐คฆโโ๏ธ
Eh that doesnโt fly in our school
isnt chatgpt supposed to get like
We r proctored lightly but still enough to get caught not having the test on ur screen
30 on amc
it's gotten better from the massive amount of money shoved in its mouth
nah i have next yr
uhh check the histogram
yeah i saw this
it got a gold on this years imo
honewstly the 10 cutoffs are not that bad
how the fuck
like a little high for the test difficulty but nothing crazy
what did u think
yeah yeah i didnt think they were that bad
i just saw 150 for amc12 dhr and was like
uhh
yeah thats stupid
idk i know someone who got 150 on 12a and b though
he said it was actually just really easy this year
cue the 50,000 flamewars on aops
oh yeah me too
aops is like the worst place ever
ppl on there actually do a whole lotta nothing
like anything but actually doing math
LMFAO the kids all getting ragebaited
freshman?
no ๐
oh
i know her thogh
thats my friends friend
which friend's friend
emily
i might know them
i mean
moonlight?
orz
wait how though..
holy shit
200 dollars a month for pro is crazy work
oh yeah but gemini got worse at math so
chatgptalso got 35/42 actually
wait you might want to delete this ๐
i tested deepseek a few months ago and it could do like aime #14 in a few minutes
not #15 tho #owned
ur talking like thats not u
alr bro whatever you say
man i keep selling on aime
ur dumb
cheating happens through people having the test beforehand
people have MAA insiders
this year it was mass leaked
and people got it for free
yeah the online ones pretty shit
all the procturing they have is a screen share in a zoom meeting of 1000 ๐ญ
no way bruh
i always taken it at my school on paper
