competition-math

[outer raven]

ah, ok, so, being from argentina this must not affect me

[patent kernel]

ioqm->rmo(regionals)->inmo(nationals)->training camp->tst(team selection test)->IMO

Is what the order is

if you want to go to the IMO in india

[patent kernel]

What do you mean by "not affect"

[outer raven]

that i can not participate

[patent kernel]

oh

[outer raven]

all my life i hace wished being part of an international team for IMO

[patent kernel]

Well

Argentina probably has a similiar cycle

[outer raven]

but i lost always at regionals or national in this case, this year

[outer raven]

yeah, that the problem, like, they select from the national the best ones, prepare them, and send them to the IMO, have you ever been in a IMO?

[outer raven]

@patent kernel did you speak spanish?, to talk faster

[patent kernel]

I can try

I don't know Spanish that well

[outer raven]

which is your mattern language?

[patent kernel]

Hindi

[outer raven]

ok, so you are from India or near areas?

[patent kernel]

Yes, I am from India

I do have an Argentinian friend who might help you

[outer raven]

oh, that could be really helpfull

[outer raven]

have ever been in a IMO? or at least in the InMO

[patent kernel]

yes, I gave the inmo this year

[outer raven]

me too, first time or more?

[patent kernel]

uhh well this is awkward

he's not in this server

could you join the server mentioned in the pins

[outer raven]

like, OTIS?

[patent kernel]

No, I mean this

[outer raven]

thanks bro

[foggy python]

no first qualifying round for IMO in india

[vital vale]

Absolute Banger Channel.

[patent kernel]

He fell off hard

Recently

[vital vale]

fr

[dusty fable]

someone do this pls and show me the soln

[pallid tundra]

hint: rearrangement inequality

(what do you need to do to attain equality?)

[steady elbow]

Looks like weighted AM-GM

[hard rune]

I am curious for your solutions to see your ideas 💡.

[sonic oxide]

54, for the numerator, interchange a,b and c then you get a cyclic expression, add all the 6 and then everything cancels and only 4^a+b+c is left which can be expanede using summation properties

[foggy python]

right on

[plain cedar]

rearrangement and taking the value of the whole series as S

I think if you rearrange it in a a-b-c cycle and add maybe

[foggy python]

yeah 6 cycles

[random rain]

What books should i use for ref to progress in math cuz i want to do math olympiads in 11th

pls ans

[hard rune]

Maybe this can help you: https://www.google.com/url?sa=t&source=web&rct=j&opi=89978449&url=http://www.ssmrmh.ro/wp-content/uploads/2024/10/OLYMPIAD-PROBLEMS-ALGEBRA-VOLUME-1_compressed.pdf&ved=2ahUKEwjhlvCznriQAxXYgf0HHZtOACcQFnoECCkQAQ&usg=AOvVaw2za3tttg49-SxjXPGbQCFz

[random rain]

ooh

thanks

[hard rune]

If you need to work on something specific, such as matrix, polynomials or anything else you can ask to send you other books. 👍🏻🙏🏻💪🏻

Another one

[junior mason]

Do cengage completely
Illustration,practise exercise and numerical types for building basics

[junior mason]

U can use coaching material for olympiads rather than books

[scarlet root]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[hard rune]

@scarlet root This problem is proposed by me for you to solve. I know how to solve it, I usually post problems to be challenges, when I don't know how to solve a problem I also post what I tried and my ideas 💡.

[foggy python]

cengage for olympiads? it's for jee

[barren meadow]

No idea at all

Hard question

[dry monolith]

1. I don't know whaere to begin.

[nova isle]

5 rows each?

rows*

[hollow lance]

cengage is too damn easy bro.. i have solved all of the books

its better to solve russian books u know

cengage has questions which are theoretically wrong

this has been verified by many of my teachers who are like phd holders from princeton , cambridge and all other premier institutes out there..

[dry monolith]

Okay but ur saying smthg thats unrelated to the question. He didnt ask if u were good at it he asked "Do cengage completely Illustration ,practise exercise and numerical types for building basics. Stop Glazing urself buddy

[junior mason]

He is in 10th class first he will build basics or directly jump on tough question

If ur saying he should directly jump on russian books or some advanced books that ur wrong
Bcz u can qualify the first 2 qualifier rounds easily by just solving coaching material or cengage

For some topics u need to use some more material but the syllabus is of 9th and 10th class

[radiant jasper]

phy and chem too?

[radiant jasper]

rmo is tough toh

*tho

[foggy python]

frfr

[glossy tinsel]

how do i prove sum from k = 0 up to n of (nCk)^2 = 2nCn using combinatorics

i thought it would be good to split up say, 2n lots of people into 2 groups of n then choose k people from them and then use the multiplicative principle to say ive got nCk choices for the first group and nCk choices for the second group so multiply them together but i’m not sure if this is correct

[radiant jasper]

notice that nCk = nC(n-k)

so you can do something a bit different with the second group

[glossy tinsel]

ah yes i noted this down when trying the question, but am i thinking along the right lines

i hate combinatorics so much

[heavy pagoda]

ban this guy mods

[radiant jasper]

Yes

the idea of picking some things from 2n things and dividing the 2n things in 2 groups of n is the right approach

[stoic tinsel]

If you’re going for a solution with a combinatorial argument, there is an easier way

Try to find 2 ways to make a group of any size (including size 0) from n people

[iron ferry]

[random rain]

yo is there any books for explanation of these concepts cuz the book u sent ealier was just the slved problems. FYI I've only done Grade 10 syllabus so far. I intend to do olympiads nxt yr so im not exactly familliar with certain topics

[hard rune]

This book is good for polynomials, it has also theory and problems, but it's not free on internet, you have to buy it.

Also this one includes both algebra and analysis, but I can't find a PDF free on internet. You can tell me what topics the 11th grade Maths Olympiad are supposed in your country, because it could differ from mine.

[valid ermine]

chat how do i do this

[jaunty ginkgo]

Where did you get this problem?

Is this even solvable? csc(x) isn't defined at 0

[rare sable]

Dude is this solvable?

[radiant jasper]

i failed

[rare sable]

Bro use #chill

And u actually didn't fail, u found a way how not to pass an exam!

[radiant jasper]

what is no access

i was talking about that integral above

lmao

i differentiated it and it leads to no solution for a

it gives, csc^2 asec^2 a= 0

[austere marten]

can someone tell me the topics i need to go over to absouletly crush this comp ? (so a bit of extra depth)

please and thank you 🙏🙏

[rare sable]

Okie, mb

[radiant jasper]

number theory, geometry, some pre calculus i see there and may be a little bit of functional equations

[barren meadow]

Lw

Id js do mor questions tbh

U got this 👍

[austere marten]

questions of what bro 😭

im 10th grade so i havent even took geo yet

[sleek ivy]

what level is it?

olympiad?

[nova isle]

It is.
The value is e - 1
(ACCORDING TO GOOGLE. I don't know integration so i couldnt do it myself. But i was curious and searched it up.)

Didn't understand a thing.

👍

[jaunty ginkgo]

My calculator doesn't agree so

[nova isle]

Should I try and write it out?

[jaunty ginkgo]

eh, I could just use wolfram alpha

[radiant jasper]

No way in hell I cleared IOQM

I’m so damn lucky😭😭😭

[nova isle]

Congrats.

[radiant jasper]

Thanks

[scarlet seal]

You guys say stuff I don't udnertand

This is for alevels right

[radiant jasper]

Tbf I also don’t understand half the stuff

I’m in 8th so that’s expected

[scarlet seal]

Wdym 8tj

8th

Is this an American server

??

[tranquil oracle]

8th grade is a fairly universal concept is it not

[radiant jasper]

Uh I’m in class 8

[scarlet seal]

Nah live in the UK

The have it like
Yr11

Yr12

Yr13

Then uni

[scarlet seal]

Year 8??

[radiant jasper]

Yes

[scarlet seal]

Bro what

How, u doing calculus in year 8

[radiant jasper]

Not calc man

The most complex thing that I did is

Permutation and combination

Tho I ain’t rlly a master at it

[scarlet seal]

Bruh what

[radiant jasper]

I gotta refine ts

[scarlet seal]

Nah I got it bro

How old are u

[radiant jasper]

13-14

[scarlet seal]

💀💀💀

U gonna be a genius

[radiant jasper]

Nah vro

There are like

3-4 kids like me at my school

[scarlet seal]

Bro your doing really good for ur age

[radiant jasper]

Not to mention a senior who solves JEE problems

[radiant jasper]

Thanks man

[scarlet seal]

Takes practice dw

I'm sure you'll get there too

[radiant jasper]

Can someone recc me some books for RMO preparation

Smth that covers stuff from the basics

Cuz I ain’t like IMO clearing lvl good at maths

I’m jst in a zone with a low cutoff

[agile gazelle]

just write to your teacher there is no need to ask chat gpt for exercices because they are often wrong

[buoyant dirge]

GUYS

I CLEARED IOQM

[barren meadow]

Do y'all not have the past papers available?

[barren meadow]

Wild dawg

[proud stratus]

Congrats buddy! Looking forward to see you in RMO and INMO

[agile gazelle]

Did any1 had the chance to compete in the IMC

[nova isle]

Congratulations.

[austere marten]

first version

[abstract vale]

as someone who absolutely hates combinatorics, calculus easier

[sleek ivy]

ON GOD

[jaunty ginkgo]

As some body grinding both combinatorics and calculus atm. When a problem is hard then it's hard regardless of the type

[sleek ivy]

all my homies hate counting

[jaunty ginkgo]

But I still hate combinatoric

[radiant jasper]

I’m jst a newbie at it so idk

Can someone tell me some books/prep material for RMo

I’m clueless rn

I’m using my IOQM prep book rn but idk

[radiant jasper]

there is book called

Challenge and thrill of pre college mathematics

[radiant jasper]

Hmm

Ki

Kk *

Lemme look it up

[radiant jasper]

its used extensively for RMO

[radiant jasper]

Hmm it seems good

However I don’t think that I can get the physical copy

why?

I’ll consult this with my maths teacher and then ig I’ll download and print it

india right?

[radiant jasper]

Cuz like

It says that the book will be delivered by 13 November

And RMO is on 16

[radiant jasper]

oh shit

well i mean

digital version is just as fine

and print it out at best

[radiant jasper]

Time to sail the high seas ig

i never buy physical

too much time consuming

[radiant jasper]

Btw

Does it explain stuff from the basics

yeah it got everything needed of number theory and geometry covered

Cuz I’m from a low scoring region
And I ain’t actually IOQM level

yeah

its good

[radiant jasper]

Hmm Kk thanks

if u can do it good

u def getting it up there

in RMO

its not even that big as well

so its doable

has good stuff

im not sure if the last one is covered or not

[zealous totem]

Hi guys, I'm new here.
I have an upcoming math competition in december this year, the questions seems similar to AMC 10.
I'm fairly new to math competitions, how can I prepare and master the fundamentals? Any resources? please ping

[jaunty ginkgo]

seems familiar to AMC10?

So it's not AMC10?

[zealous totem]

No, it's a local one, but i mean in question style

[jaunty ginkgo]

AoPS is great for AMC in general

So you could try that and their books

[zealous totem]

which book exactly?

[jaunty ginkgo]

Hm I dunno, never take AMC10 myself but I know some people prepare AMC10 here using AoPS

[zealous totem]

Ah okayy

[barren meadow]

Reallll

[nocturne bone]

Hi

[late flint]

heyyy who here is doing usemo rn

[near hill]

If they are, they'll hopefully have read the point in the rules where it says collaboration is not permitted, which presumably includes any sort of online discussion of the contest.

[opaque oasis]

vol 2

[gaunt badger]

whats the best way to study for the amc 12 in like 10 days

[dire flare]

challenges and thrill of pre college mathematics but id recommend doing mathematical circles(russian experience) first because ctpcm is quite difficult to learn from because its overly formalised

[rose condor]

it depends a lot on your prerequisites - but if I were you, I'd do a couple of old problems, identify my weaknesses and then study those weak areas by reading articles / chapters of a book and doing as many exercises as possible in this short timeframe.

[swift peak]

wouldnt vol 1 be better for beginning comp math

[lethal wigeon]

Please, does anyone here have any recommendations or books I could use to prepare for math competitions as a beginner

[jaunty ginkgo]

what competition, Pucci?

[lethal wigeon]

Oh , you know JoJo , Fiona the human , that's great . AMC , IMO , any one really, I find them interesting, but ik a beginner at any of those questions and I haven't seen any proper resources to help me yet

[jaunty ginkgo]

American? you might want to grind everything in the aops alcumus first

[lethal wigeon]

Is it like a website or a book

[jaunty ginkgo]

a website

https://artofproblemsolving.com/alcumus

Well it has basic, and it has a bit advanced

[lethal wigeon]

Oh k , do I have to sign in or pay

[jaunty ginkgo]

Nah

I meant

You have to make an account, but you won't have to pay anything

[lethal wigeon]

Ok

Thank you very much

[tiny spire]

Guys do you know how to approach math modelling...

All my teammates flaked on me and its fine for rn since its just a mock competition bit idk where to start at all

[modern grotto]

Wdym those questions look like beginner modelling ones

is that GCSE ?

[tiny spire]

Yeah because im a beginner dude 😔 this is my first time doing this sort of stuff and im not all that good at math and reasoning to begin with...i did figure some stuff out though

[austere marten]

kaust ?

[faint thorn]

does anyone wanna talk through solving BMO problems later

or SMC problems

[jaunty ginkgo]

British MO?

[high goblet]

i mean if you post problems here, ppl will be able to help

the UK section of MODS is more active tho, link is in the channel info

[zealous totem]

Yup, are you participating?

[merry spire]

how to solve? a³+b³=c³+2025 methodically? i know the answers are 28, 81, 82 but i dont seem to know how to solve it.

[faint thorn]

Is there more information

[worldly oar]

Uh fermants last theorm

But not exactly you can consider 2025 as a cube root of cube of itself
So its
a^3+b^3=c^3+d^3
Where d^3=2025

Idk modular arethamtic might work

[near hill]

There's no such d, though (at least if everything is supposed to be integers).

[jaunty ginkgo]

hmmm let d=-c => a^3+b^3+d^3=2025

2025 = 0 mod 9

for any integer t , t^3 =0 or 1 or -1 mod 9

So a,b,d = 0 mod 9 or a=-1 mod 9, b=1 mod 9, d=0 mod 9

This's the most I can do atm

[subtle sundial]

i assume theyre all unrelated

i dont think theres a cleean way to solve this lmao

[subtle sundial]

we could try factoring, maybe? and find someth out with divisibility?

[
a^3 + b^3 - c^3 + 3abc = (a + b - c)(a^2 + b^2 + c^2 - ab + ac + bc)
]

[gilded halo]

pxdoru | 9¾

[subtle sundial]

equate to 2025 + 3abc

[sleek ivy]

could factor that as 3*(625+abc)

idk if that does anything tho

[subtle sundial]

hmm

itd probably simplify things? no

[
(a + b - c)(a^2 + b^2 + c^2 - ab + ac + bc) = 3(675+abc)
]

[gilded halo]

pxdoru | 9¾

[jaunty ginkgo]

You guys try it, I have to finish some powerpoint things atm🥀

[subtle sundial]

too much work and substitution

[scenic cape]

Usually what is the cutoff for amc 12a for aime?

I thought 85 was safe no

[sleek ivy]

https://artofproblemsolving.com/wiki/index.php/AMC_historical_results?srsltid=AfmBOoo7MCEisPqlGDbM7oz-DNDyG-eO99emSckfsqSZIyCr0bbbz5QX

historically 90 is safe

[pallid tundra]

i havent been keeping track of how low theyve been getting but

last i remember they were hovering around the 90s

[sleek ivy]

for b yes

for a it was 76.5

[pallid tundra]

76.5

jfc

😭

have participant numbers really plummeted that much

[sleek ivy]

hey man i aint complaining

just let me qual

[pallid tundra]

true

[wanton kelp]

100 is as safe as you can be

but tbf if last year was 76 then like

you could prob get away with like a 90

[sleek ivy]

the boundary cant be above 100 by definition so yea

[sleek ivy]

in the last 4 years the highest its been is 93

and its getting lower every year

[soft vigil]

Just get >100

Like if you can secure that you make aime

[sleek ivy]

yea well motivation was never my issue

[soft vigil]

Like realistically

I wouldn’t say it is that difficult to get if you properly prep

[merry spire]

natural numbers and nope.

[merry spire]

Wait thats true

[jaunty ginkgo]

yeah

[merry spire]

ah idk im still kinda puzzled since it was a question to be solved in 15 minutes

[jaunty ginkgo]

,w expand (3x+1)^3

[gilded halo]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by fionna_fx

[jaunty ginkgo]

,w expand (3x+2)^3

[gilded halo]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by fionna_fx

[jaunty ginkgo]

1 mod 9

[jaunty ginkgo]

8 or -1 mod 9

[zealous totem]

Hey yall
How do I practice for this upcoming competition? This is the only sample questions given. I have no idea how to solve most.

any advice really helpful

[nova isle]

thats also an identity??

[austere marten]

yeeaah

[proud stump]

guys with all the plug and play and memorization with no intuitive understanding does it ever finally click 😞🥺

[odd talon]

hi malak

[odd talon]

do practice tests with a timer, and look at the solutions after to see what methods are used and what formulas/concepts are useful

[odd talon]

no intuitive understanding is cooked

[subtle sundial]

yeah, just manipulated a little

[nova isle]

Oh yeah I see it.

Just manipulated the identity a³+b³+c³-3abc?

[sand hill]

Given a circle and points A, B, and C on it, which do not form an isosceles triangle. For every point P not in the set {A, B, C} on the circle, let A_P, B_P, and C_P denote the intersection points of the tangent at P with the tangents at A, B, and C, respectively.Prove that there are exactly three points P not in the set {A, B, C} on the circle such that the points A_P, B_P, C_P exist, and the perpendiculars erected from A_P to the line segment BC, from B_P to the line segment CA, and from C_P to the line segment AB are concurrent (meet at a single point).Furthermore, show that these three points P form an equilateral triangle

Hi guys

Idw

To waste time on this so someone pls help

[hard rune]

Hello!
I need a little help with this problem.

I would like a solution without barycentric coordinates or complex numbers.

[sand hill]

Kk

[subtle sundial]

mhm

[zealous totem]

Sup hunk didnt know you were here too
Tyy

[scarlet root]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[proud stump]

This is most of public school academia students I’d guess until maybe further in a stem degree and even then

[hard rune]

I solved it with barycentric coordinates and I am looking for a synthetic solution, but I am out of ideas in this way.

[slender shoal]

Have you tried Thales? Considering that MNP is similar to ABC.

Because MN,MP and NP are parallel to the coresponding sides, considering the fact that they're midpoints.

[reef condor]

Some undergrads even

Like oly math is deeper than much of undergrad math (see Evan Chen image on this)

[stoic tinsel]

I’m too lazy to do it rn but u could try something with Homothety about the centroid of ABC

Bc a scale of -1/2 from the centroid of ABC constructs MNP, and then u might be able to use Euler line for some additional info

[lucid depot]

i guess it sort of depends on the exams you're taking cause like where i'm at the exams force you to have a good intuition of the mathematical concepts behind questions (which i'm incredibly grateful for).

[novel karma]

let p be a point inside square abcd such that apd = 65 and dpc=70 what is the degree measure of pda

seems easy but its hard idk

[pallid tundra]

set $\angle PDA=x$ and see what you can conclude from $\triangle APD$ and $\triangle CPD$

[gilded halo]

elrichardo1337

[pallid tundra]

wait nvm that doesn't lead anywhere

[latent berry]

hi, any last minute tips for the COMC

[vernal axle]

Because APC=135, D is a circumcenter of APC, so DA=DP=DC. The rest is easy.

[rustic path]

@odd imp (excuse me for my English, is not my first language, if you don't fully understand or have any questions feel free to ask me) The maximum possible digit sum of a five-digit number is (9 + 9 + 9 + 9 + 9 = 45), which happens with the number 99999.

Since we want the digit sum to be 39, we need to subtract 6 units from that maximum.
So the question becomes: In how many ways can we subtract a total of 6 units from the digits of 99999, while keeping each digit between 0 and 9?
Now you can break it down in cases:
Case 1: Subtract all 6 units from 1 digit, since we have 5 digits there are 5 combinations.
Case 2: Subtract the 6 units from 2 digits, split the 6 into the sum of 2 integers (1+5, 2+4 or 3+3) and count in how many ways you assign these values to the digits. If you do it correctly you will get 50 combinations for this case.
Case 3,4, and 5: Subtract the 6 units from 3,4 and 5 digits respectively, this is similar to the case 2 but I won't write the combinations. If you do it all correctly the answer should be 210. You should search about combinations and integer partitions, it may be helpful

[gilded halo]

zcrxs_

[tiny spire]

This is what I ended up writing!! I don’t think it’s bad, pretty solid in general and as a first attempt according to my teacher

[vital ermine]

personally stars and bars is probably an efficient way of doing this but
a+b+c+d+e=39 where a is an integer from 1 to 9 while b,c,d,e are integers from 0 to 9
based on the bounds, we have
(8-a)+(9-b)+(9-c)+(9-d)+(9-e)=38
we get
a+b+c+d+e=6
by stars and bars, since we already set the bounds in the first step we can just do (6+5-1) C (5-1)=10C4
=210

Another way to add to @rustic path solution is since 9+9+9+9+9=45 using stars and bars is just basically let your digits be (9-a)+(9-b)+(9-c)+(9-d)+(9-e)=45 then it still becomes a+b+c+d+e=6 so thats still 10C4=210

i suggest learning stars and bars involvign inequalities

[odd imp]

oh i really like your method, i did something similar i just thought about it differently. I will definetly look at partitions

[odd imp]

i had never seen any method taking about stars and bars, i will take a look at it

[weary vortex]

Found this interesting problem:

Find all natural solutions for $(a, b, c, d)$ such that $2^a + 3^b = 5^c \cdot d$ and $2^b + 3^a = 5^d \cdot c$

[gilded halo]

azart

[weary vortex]

Furthest progress I was able to make is finding that a = 1 (mod 4) and b = 1 (mod 4). Consider = as a congruence sign in this case

obviously (1,1,1,1) is a solution but I highly suspect that it is the only one. I'm unable to prove it tho

[granite zenith]

Could someone recommend me an introduction to combinatorics, especially to permutations and basic counting? I would really appreciate it

[frank valve]

I hate number theory

[gilded iris]

how study for amc10

[junior mason]

Which country

[granite zenith]

What do you mean?

[junior mason]

U can follow richard p.stanleys book

[granite zenith]

Thanks

[junior mason]

Or Daniel A. Marcus

[junior mason]

Its teaches by problem solving

[hearty tendon]

enum combinatorics???

thats pretty advanced

aops c&p is good

or brualdi for a more classic reference

[toxic arrow]

Yo

[rough frost]

How do I solve this problem?

finding the value of S btw

[solemn vapor]

Easy but wants time ! sorry

[vernal axle]

use this identity https://en.wikipedia.org/wiki/Sophie_Germain's_identity

every time you see x^4+4y^4 🙂

[rough frost]

I see it now, much appreciated for the help!

[hoary vigil]

hi guys

can anyone provide help for AMC12

hehe

[brave horizon]

Help guys
Ive read AOPS part on ellipse but I wanted to read more high level content... like line with ellipse and other juicy stuff... but other books dont teach stuff on problem solving they;re just slapping me with proofs... I get it that proofs are super important but I also wanna know the stuff intuitively...
Any help, even a lil bit is helpful
are there books for students trying to learn for engineering college and involves all of algebra, precalc, counting and calc necesarry in advanced levels? like super advanced and gives intuitive understanding like aops does?

🔥 🔥 🔥 🔥 🔥 🔥 🔥 🔥

[worn siren]

any book recommendations on functional equations?

[zealous aurora]

is anyone here planning to take putnam this December, HMU.

[candid fern]

There is Amir hossein's book
You can as well check my youtube functional equations playlist on little fermat channel

[worn siren]

okay thanks man

[subtle sundial]

theres a really quick way to solve this, takes not more than 5 minutes

oh gosh this was 2 days ago

lmao

[weary vortex]

Consider a finite set of prime numbers $P = {p_1, p_2, p_3, \cdots, p_n}$. Show that, if there exist two integers $a, b$, which are coprime to all elements in $P$, such that, the given condition: $p\ |\ (a^p+b)$ is satisfied for each element in $P$, then $p_1 p_2 p_3 \cdots p_n\ |\ (a + b)$.

first time creating and submitting an olympiad problem myself. What do you think of it? is this good for Republican level olympiad?

[near hill]

Can't you just set both a and b to the product of all the given primes?

[weary vortex]

didn't think of it. Let me add a little condition

[gilded halo]

azart

[weary vortex]

This may be borderline non-sense of a problem description

[near hill]

The logical structure of the specified goal is a bit off:

if (there exist a and b such that bla bla) then (conclusion that involves a and b)
As written this doesn't make sense: the a and b in the conclusion are not inside the scope of the "there exist" quantifier.
You probably meant to write something like
Asuume p1, p2, p3, .... pn are a finite set of primes, and that a and b are integers satisfying (... coprime and p | a^p+b ...). Prove that p1p2p3...pn | a+b.

[weary vortex]

Consider a finite set of prime numbers $P = {p_1, p_2, p_3, \cdots, p_n}$ and integers a and b, such that:

1. a and b are coprime to all elements in $P$. \
2. For all elements in $P$, $p\ |\ (a^p+b)$.

Prove that, $p_1 p_2 p_3 \cdots p_n\ |\ (a + b)$.

I think this clears up the ambiguity

[gilded halo]

azart

[near hill]

Thanks, then it's clear what you mean.

I can't say whether or not the problem would be appropriate for any particular contest (and I don't even know what a "Republican level" olympiad is). However, it seems like it ought to be fairly straightforward for an audience that is prepared to tackle questions about primes and divisibility:
The goal p1p2p3...pn | a+b immediately suggests using the Chinese remainder theorem to split it into proving p | a+b for each p in P. From that point the plurality of primes disappears from the picture and we just have to prove that if p | a^p + b then p | a + b. But that's essentially Fermat's little theorem, so if we know that, we're done.
On the other hand, a contestant who doesn't already know Fermat's little theorem would probably be stumped. So the problem tests more for "do you know these two important theorems" than for ability to be clever after seeing the problem.

(By the way, the proof goes through unchanged without the assumption that a and b are coprime to each of the designated primes. When I suggested just multiplying them all together, I had misread the "if" in your first formulation, so I thought the task was to find such an a and b).

[weary vortex]

Alright. Thanks for the feedback, appreciate it a lot

[crisp forum]

Topics in Functional Equations by Titu Andreescu. Honestly all his books I would say are phenomenal but do require some serious work.

[outer thunder]

okay i think i solved this one

given a^p + b = 0 mod p, we have a + b = 0 mod p or p | a+b

if each prime divides a + b, then the product must as well by the specific case of chinese remainder thm for primes

[outer thunder]

i didn't even use one i think haha

anyway who knows how to solve this

[near hill]

You seem to be implicitly appealing to a^p == a (mod p), which is exactly Fermat's little theorem.

[outer thunder]

yes this is a well known result as you said

this nt is not hard problem

[near hill]

I might have misunderstood what it was you said you weren't using.

[outer thunder]

yeah, the thing I didn't use is fact #1.

in the problem

[near hill]

Okay, then we're in agreement.

[near hill]

There are only 8 divisors of 30. It seems feasible to go through them in descending order and for each of them compute how many more numbers can be expected before you hit 30.

In fact, the precise divisor you've landed at is not important -- only how many of the three prime factors of 30 are in it. Viewed in that way, the process really only have four states to compute an expectation at, rather than eight.

• When we have all 3 prime factors, we're at 30 already and expect 0 more numbers.
• When we have 2 prime factor, the only place we can move the next time is to 30, so we expect 1 more number.
• When we have 1 prime factor, there are three next numbers to pick between -- one of them has a next expectation of 0, two of them have a next expectation of 1, totalling up to 1 + (1/3)·0 + (2/3)·1 = 5/3.
• ...

[stuck tartan]

i think the key idea here is using states based on the number of prime factors of the number you are currently on, as the # of prime factors of each number in the list is non-decreasing. Let a_n = expected number of additional numbers needed to reach 30, given you are at a number with n prime factors for 0≤n≤3 and then solve the system of equations

a_3 = 0
a_2 = 1/2(a_2) + 1
a_1 = 1/4*a_1 + 1/2*a_2 + 1
a_0 = 1/8*a_0 + 3/8*a_1 + 3/8*a_2 + 1

with k prime factors in ur current number, there are 2^(3-k) possibilites for the next elmeent in the list since 30 = 2*3*5

[outer thunder]

yeah i solved it same way diff notration

alr i will now try this problem

[stuck tartan]

this the aops mock amc 12?

[outer thunder]

yeah i did trash on this

only like 101.5

holy chopped

[stuck tartan]

bro got the legendary imposible score

r u a junior?

[outer thunder]

wym impossible

i got it

[stuck tartan]

101.5 is not a possible score on the amc 12

[outer thunder]

wait i literally got it though

i can check

yeah ur right

it wouldn't be possible

and i got 103.5

the breakdown was 15 C 1 IC

how tf does one recognize something like that

[outer thunder]

yes

hbu

[stuck tartan]

yeah same

[stuck tartan]

its cuz ur score must be divisible by 1.5

[outer thunder]

true dat

[stuck tartan]

since your score is determined by a linear comibnation of 6 and 4.5

so gcd(6,4.5) | score

by euclidean

anwyays

i think i did like 1-22 on this

and sillied like

i forgot

i sillied 2 of them

i sillied p17 cuz i added wrong

and i sillied one of hte early ones (the sqrt(2k) one) cuz i missed a case

[outer thunder]

the best one I ever got was 126

hbu

[stuck tartan]

best mock score in general?

[outer thunder]

yes

[stuck tartan]

oh alr

i feel like it depends hella on the test itself tho

[outer thunder]

ikr

[stuck tartan]

cuz user made mocks differ vastly in dificulty

[outer thunder]

this one was really difficult

[stuck tartan]

really?

i thought this one was like

reaonable difficulty

[outer thunder]

idk maybe

look at like amc12b 2018 i think

[stuck tartan]

cuz p15-20 were rlly easy in comparison

[outer thunder]

might've been the easiest test of all time

15 tripped me up tho

[stuck tartan]

fr

holy yap of a probelm

p16-p19 were really eas ytho

[outer thunder]

so damn you are really smart man

[stuck tartan]

not reallly

but like p19

they give you all the info

[outer thunder]

how long have you been mathematicing

[stuck tartan]

uh i took the amc 10 in 8th grade for fun and got like an 84 or smthg

cuz i didn't really study much in middle school due to covid

and then i studied over the summer

after getting like a 16 on amc 8 💀

but i failed like 9th grade amcs

[outer thunder]

icl this is my first year like

[stuck tartan]

96/87 or smthg like that

[outer thunder]

i feel so behind how will I ever get to usamo yk

[stuck tartan]

and then uh

[stuck tartan]

feeling behind is so real 😭

i felt like a bum after not qualling 9th grade

[outer thunder]

doesn't stop until being ter tao

which is never

[stuck tartan]

lmao

[outer thunder]

wann vc

[stuck tartan]

vc?

[outer thunder]

yes

[stuck tartan]

for wut

[weary vortex]

I gotta admit, I overrated the difficulty of the problem while creating it

[worldly oar]

Ya do you know about any olympiaf calculas course

[iron terrace]

What are the imporant formulas that I need to remember for mathcounts

[pallid tundra]

calculus is not a standard math contest topic

[pallid tundra]

if you’re having to ask that question then to be blunt you’re not gonna do well

[crisp forum]

The calculus course through the art of problem solving is good. I have seen some community colleges have honors calculus courses that use spivak that would give you a similar experience. You won't see Olympiad style calculus classes as it's not in highschool contests. It's probably better to move into real analysis at this point like Pugh or rudin if you want hard problems.

[violet dagger]

you’re better off studying from a textbook

*self-studying

the AoPS course is very superficial imo

[oblique hamlet]

is anyone able to help me here😭

[pseudo forge]

How?

[oblique hamlet]

Amc 10

does anyone know a lot about it

[pseudo forge]

Oh lemme check

[oblique hamlet]

aight

[pseudo forge]

I've never seen this but ig this is like Olympics math?@oblique hamlet

[oblique hamlet]

hm

it's quite famous

but the thing is it's really

ambiguous

changes a lot

[pseudo forge]

Ohhh

[oblique hamlet]

it got a lot harder

and the topics are fluctuating

[pseudo forge]

Oh my God

[oblique hamlet]

so I'm like tryna find someone who knows a lot

about it

[pseudo forge]

I hope you will find someone but it's sure not me sob

[oblique hamlet]

😭 dang

alr

[stuck tartan]

hasn't it got much easier?

like 2023/2024 were quite easier in difficulty in comparison

[oblique hamlet]

???

😭wait what

[stuck tartan]

wdym

like if you take the difficulty of the 2022 amc 10

it was much harder than the 2023 amc 1`0

2024 amc 10 was slightly harder than 2023 amc 10

but it was still quite easy

especially 2024 amc 10b

[jagged shuttle]

Doing the AMC 10

I need to lock tf in

How and what do I practice

Rq

And cram in some time

I have 3 days

I’m hella scared

[soft vigil]

just do a few mocks

not too much

[jagged shuttle]

K

[lunar pilot]

crazy finding you here

@soft vigil

[soft vigil]

https://tenor.com/view/ishowspeed-try-not-to-laugh-gif-7682731162751353849

[scenic cape]

any doctors engineers or technicians in the server

[pallid tundra]

1. why are you asking this in a pre university channel
2. why are you even asking this in the math server at all

[tiny raven]

i am all the above

[sterile void]

guys any ghp tips??

[hazy flame]

i need help🥲

[jaunty ginkgo]

the question seems wrong

Oh wait

There is only one way I could think of

[ornate blade]

recall from precalculus that this function has a bounded range

you can set $\frac{-13n + 9}{n^2 + 13} = k$, rearrange and set the discriminant to $0$

[gilded halo]

south

[jaunty ginkgo]

Yeah I was gonna say...

(-13x+9)/(x^2+13) >=1 or (-13x+9)/(x^2+13) =<-1

the only valid values are 2 to 12 and then we try all lmao

[ornate blade]

with this way, you only need to try k = -1, 0, 1, 2 lol

it should be immediately clear which quadratics are factorisable and which aren't

once you rearrange

[jaunty ginkgo]

fair, I'm just bad at integer number question ig

[hazy flame]

oooo okay thank you

[ornate blade]

no worries!

[sleek ivy]

alcumus is currently helping me a lot

to prep for amc12

its on aops website

[novel karma]

11

I know that its casework but idk

[sleek ivy]

casework

if the 6 is first, then he couldnt have rolled a 1

if the 6 is 2nd then 1/5 chance

if the 6 is 3rd then 2/5 chance

if 6th is 4th then 3/5 chance

thats to roll a 1

to not roll a 1

do 1- whatever that adding allat gets you

[midnight valley]

I understand question 9 but I wanna know how people go about the question when they first see it

because it took me a second

[novel karma]

@sleek ivy wait why? Why is it those fractions?

[sleek ivy]

look

we're asking

roll a dice 4 times

what are the odds that you get a 6 before you get a 1

assume you get a 6

there are 4 cases

roll 1 is a 6, roll 2 is a 6, roll 3 is a 6, roll 4 is a 6

now itll be easier to find the probability that you will get a 1, rather than that you wont

so if you get 6 first you defo wont get a 1 before a 6

if you get a 6 2nd, you need to get first a 1 then a 6, so the probability will be 1/6*1/6

then a 6 3rd, you can either get a 1 first or a 1 2nd, so 2 cases here

then 3 cases for the 3rd

you consider them

add the probabilities at the end

then do 1-that

[novel karma]

Wait what about the /5 fractions first

[sleek ivy]

yea i was tripping

shoulda been over 6

[near hill]

Hmm, I can expand to 2^127 + 2^126·3 + 2^125·3^2 + 2^124·3^2 + ... + 2·3^126 + 3^127
so A is out, and E is also out because the binomial coefficients in the expansion of (2+3)^127 are missing.
Then I'd be at least temporarily stuck ...

Ooh, perhaps rewrite further to 2^127(1+(3/2)+(3/2)^2+...+(3/2)^127) and dig up/derive the formula for a finite geometric series for the right-hand factor.

Which leads to answer ||(C)||.

[sleek ivy]

Difference of squares

[midnight valley]

I thought about that but I think I made a mistake setting it up

probably easiest way yeah

[near hill]

Oooh.

[violet dagger]

can someone please help, i have no idea how to solve this, spent the past 15 mins on it

it’s just so confusing

[near hill]

It smells a lot like a power-of-a-point problem.

[violet dagger]

yeah i’ve used it but idk how to get the answer from that

[near hill]

Hmm, power of a point tells us that PC = 9, so in principle that's enough to draw the diagram and find the circle that goes through the four points. But to do that with coordinate bashing would still be painful.

[novel karma]

AD is diameter but I have no idea how to prove it

[stuck tartan]

discus 💔

[stuck tartan]

AD = 2sqrt(73) by LOC and AC = sqrt(243) by LOC

since AC^2 + CD^2 = AD^2, angle ACD is 90 degrees, so AD is a diameter

r^2 = 73

[violet dagger]

what if i have a terrible memory and can’t remember the law of consines even after doing a ton of similar problems

what do i do then

[stuck tartan]

can't remember the formula for LOC?

or when to use it

[violet dagger]

when to use it

like i know the formula but i have no clue what could motivate me to use it in this specific problem

[stuck tartan]

the 60 degree angle

and the fact that ur given many legnths, so you can find more lengths

[violet dagger]

yeah that makes sense, i couldn’t figure out how to use the 60 degree angle at all

[stuck tartan]

oh ok

yeah angles + ton of side lengths is alwyas LOC or LOS

most of the time

[near hill]

And law of cosines is particularly nice for 60° because the cosine is rational.

[midnight valley]

does anyone have tips/where i can learn for how to learn how to apply the AM-GM inequality (I know I can look at practice questions)

I can sometimes see when it could technically be applied but I often don't know how to set it up

when it's not straightforward

[soft vigil]

you can also see that APC is 30 60 90

[pallid tundra]

there are tons of compilations of inequality problems you can practice on

[stuck tartan]

🤫

[soft vigil]

ehh

both ways work but i think the one i stated is maybe a bit easier to see

but realistically it depends on the person

[stuck tartan]

yeah it is

i js didn't realize 30-60-90 💀

[novel karma]

So like I got6 problems right on that mock 😭 😭

[stuck tartan]

Discus is a ridiculous ass mock

I’m Js happy I solved p22 😭

[novel karma]

Last minute amc advice?

[azure bloom]

I also got AMC tomorrow

Good luck bro

@novel karma Sorry but I don't accept DM's from people I don't know

[novel karma]

You good sorry bro

[azure bloom]

No problem

[bronze widget]

It's so over

Good luck everyone

[sly pawn]

THE AMC IS TOMORROW GUYS

THIS IS BIG

[sly pawn]

Planning on getting to AIME this year!?!?!?!?

[sly pawn]

Go study, get 8 hours sleep, don't study before the test and burn yourself out

Big rest

Rest a lot

[novel karma]

Got it tmr 💪 ty and good luck

[sly pawn]

On all the practice tests I've done I score like anywhere from 6-18 points higher with good rest vs very tired

Rest is big, makes a big difference

[novel karma]

Yeah fs

[sly pawn]

Btw are you taking the 10 or 12?

[novel karma]

10

[proven tendon]

Good luck, guys

[sly pawn]

Ok the 10 is much harder to advance if you take it so good luck

[proven tendon]

🫶

[sly pawn]

I'm predicting that the cutoff for 10 will be something like 100-105 and 12 will be 75-85

That's the usual range I believe

[novel karma]

I have morning swim practice tmr. Should I go

[sly pawn]

Yes

But sleep early

[novel karma]

Ok

[sly pawn]

Getting like 8 hours of sleep and waking up atleast 3-4 hours before the test is a good idea

[sly pawn]

I got some practice 10 problems on the harder side if you want them btw

can post here

[sharp olive]

Have you guys checked Aops mock test yet, this is the 10 one

[sly pawn]

haven't done it yet no

[swift peak]

Good luck on amc 10/12 guys!

[novel karma]

You got the answer key?

[novel karma]

Sure thanks

[sly pawn]

Here's a hard one

Yo does anyone remember the parking function counting technique btw?

[tiny eagle]

Yeah I did I got a 99 bruh

Forgot to multiple volume of sphere by 4/3 😢

I silly so much

[real pier]

1344

[surreal willow]

Guys how yall feeling bout the amc tomorrow?

[sly pawn]

yes good

[sly pawn]

mixed

[scenic cape]

If i got somewhat around 50 last yr at amc 10

Would it be impossible for me to get like 90 in amc 12 this yr

[tiny eagle]

So scared, 2 years ago I got 60, last year 90, this year I wanna aime qual

But it’s hard, I’ve been mocking like average 100

Which is pretty bad

[surreal willow]

Yes bro

Someone got 60 one year

And the next year they got 120+

[surreal willow]

Wait if ur taking amc 12 then that’s enough

[scenic cape]

Impossible? Or possible

[tiny eagle]

Taking the 10…

[surreal willow]

I meant yes to getting aime lol

[surreal willow]

Oh damn

If your getting 100s it might be enough

What grade u in btw?

[scenic cape]

But like getting 50 on amc 10 and the year after u get 90 on amc 12..

[tiny eagle]

I’m in 10th

[surreal willow]

Oh same

[tiny eagle]

Cool, have u qualified for aime before?

[surreal willow]

Nah but I think I’ll be able to this year

[tiny eagle]

Nice, gl bro

[surreal willow]

Thx

Gl to u too

[tiny eagle]

Ty

We BOTH are qualifying for aime trust

[surreal willow]

Real lol

[surreal willow]

You should’ve qualified for the aime last year tho…

The aime floor for amc 12 is usually 80s

[scenic cape]

50 isnt good enough for aime

[surreal willow]

What bout the 90?

[scenic cape]

I got 50 this yr

But im aiming for 90 this yr

Well not me but my friends

[surreal willow]

Ohhhhhhh

Okok

[scenic cape]

Do u think thats like realistic

[surreal willow]

Yea it’s def possible bro

[scenic cape]

Possible but unlikely?

[surreal willow]

Bro it definitely possible if you tried and studied

You just gotta work out what you want beforehand

If you want a 90 then try to answer like 17 questions hoping you get 15 correct

Wait not even 15

13

[stoic tinsel]

This one’s neat

[surreal willow]

Then you have the 12 points from the unanswered questions which can give you a 90

[stoic tinsel]

Lowk just go for accuracy instead of attempts

15/15 is 105

[deep walrus]

Who’s ready for the AMC 10/12 tmrw?

[stoic tinsel]

I’m hella worried

U?

[deep walrus]

Is a 117 a good score for jmo qual

[stoic tinsel]

It mostly depends on AIME now

[stuck tartan]

not really but with the aime update this year its fine

[deep walrus]

I gotta lock in for aime tho

I’m usually getting 5-6 correct 💀

[stuck tartan]

wut grade

[deep walrus]

9

[stuck tartan]

yeah with like a 115 amc 10 u need at least an 11 on aime

[deep walrus]

I’m cooked 💀😭

[stuck tartan]

or mayb 10

ts aime update frying me 💔

[tiny eagle]

I feel like a bum as a 10th grader trying to aime qual when there are 9th and 8th graders easily qualifying and going for a/jmo

[stuck tartan]

this is so real

if im being real the difficulty to aime qual is underemphasized cuz people online make it seem really easy

js keep doing what ur doing 🙏

[tiny eagle]

Yes bro, thanks

[surreal willow]

Yea but you hafta assume that you can get that 15

Damnnnnn

You taking the AMC tomorrow?

[little lintel]

yes

fried

[snow thistle]

this is the best thing that's ever happened to me

cuz im only gonna get like 130 on amc so before i was gonna have to get 12 on aime or something

but now i can get 11 yippee

[stuck tartan]

ts sounds like the gaokao bro 😭

[little lintel]

how do i go from 115amc to 130 😭

[surreal willow]

Oh aight

[surreal willow]

Fr lol

[snow thistle]

whenever someone asks me a question about how to improve i just say read egmo 😭

but do not do that

umm

for amc 10 just grind problems 20-25 or smth

amc is too fast paced for me

[little lintel]

bruh same

[snow thistle]

i feel like prepping aime is better

[little lintel]

but i can do 20 qs max

too little time for more

[snow thistle]

because if u study for aime itll still make you better at amc 10 but the other way around not so much

[snow thistle]

ohh

then maybe you should just do timed mocks to improve ur speed

[little lintel]

i shall

staying up until 3am tn

[snow thistle]

usually i score low cuz my accuracy rate is bad

[little lintel]

doing mocks

[snow thistle]

yoyoyo

wait

thats like

not a good idea at all

[little lintel]

😛

[snow thistle]

im not doing any math today

the day before

like realistically trying to cram the night before is not gonna help you as much as you think

its not like a school test where you can cram all the info

because u dont know what the test is gonna be like

its better to just rest and think about how ur gonna go about it

[little lintel]

yeah imma just read thru some formula sheets or wtv

[snow thistle]

some people dont do math like the whole week before

[snow thistle]

yeah thats probably good

[little lintel]

there is gonna be a misplaced problem that i sink too much time into

i have to know to skip

[snow thistle]

yeah fs

that happens to me too

[stuck tartan]

egmo for the amc 10 💔

[snow thistle]

read mathematical reflections next ❤️

[stuck tartan]

egmo is peak

i've done like 3 chapters but i kinda left it

[snow thistle]

after chapter 4 its kinda stinky

i didnt read most of them

[stuck tartan]

bary bash 🗣️

[snow thistle]

the inversion chapter was the only one that was semi useful

i dont spend that much time doing oly geo

[pure agate]

guys what will be the qualifying score for the amc 10 this year

[snow thistle]

for aime?

[pure agate]

yeah

[snow thistle]

uhh

depends on the difficulty

if its easy then probably like 105

but i feel like the questiosn are gonna be weird this year

like last year

they were weird last year but also easy

[pure agate]

yeah last year was weird

[snow thistle]

so maybe this year theyll be weird and hard

[pure agate]

nooooo

i hope they are normal and hard

[snow thistle]

but 110+ should be qual fs

[snow thistle]

agree

[pure agate]

yeah

[stuck tartan]

nooo 💔

[snow thistle]

honestly now that im thinking about it the thing to make aime twice as important probably didnt even matter that much

[pure agate]

are yall eighth ninth or tenth grade

[snow thistle]

like normally u probably wouldve need 240ish to qual which is 132+11

and this year i feel like its gonna be around 350

which is still 132+11

😭

[pure agate]

🙁

[snow thistle]

for jmo i mean

not usamo im not taking 12

[snow thistle]

im a freshman lmao

[pure agate]

lol

can i get my score from a 99 to above a 105 in a week?

like is it even possible?

[snow thistle]

yeah probably

like its only 1 question difference

if you get lucky u can

[pure agate]

i can only hope ...

[snow thistle]

unless ur mock score is 140+ it can still vary a lot

[pure agate]

i make so many stupid mistakes 🙁

[pure agate]

yeah fs

[snow thistle]

last year ik someone who was mocking low 120s and got 138

[pure agate]

what did you get last year

[snow thistle]

he said the amc 10b felt like an amc 8 😭

[snow thistle]

ermmm

lets not talk about this

[pure agate]

lol

[snow thistle]

i got fried on both im gatekeeping my score

and on aime

[pure agate]

nooooooooooooo

above 110?

[snow thistle]

yeah but not by that much 💀

[pure agate]

hey if it qualifies it qualifies

[snow thistle]

i guess but now im more concerned with jmo

im aiming for 135

actually my goal index is 132 + 11 😭

[pure agate]

lessgo

[snow thistle]

last year a lot of people got 11 cuz the aime was easy

both of them

so this year we'll have to see how it goes

[pure agate]

yeah

if I qualify 💀

[snow thistle]

if i do bad on 10a its gonna cook my performance on everything else 😭

im going to hmmt on friday right after amc 10a

[pure agate]

wait are you taking both a and b

[snow thistle]

and when i get back i have 10b

[snow thistle]

yup

[snow thistle]

u got this

i believe in u

[pure agate]

thanks lol

[stuck tartan]

i mean he has a point

[sly pawn]

It's a cool problem

[sly pawn]

ME

[sly pawn]

The amc8 felt way harder when I took it in 8th grade

But I also knew like nothing then

[sullen zenith]

Is the test going to be online or on paper?

Is the test going to be online or on paper?

[surreal willow]

depends on which one you take lol

[sullen zenith]

I'm taking the 10A at a test center nearby (UTD)

[surreal willow]

oh

if its held at a university its prob gonna be on paper

[sullen zenith]

Oh okay. Thanks! Good luck!

[surreal willow]

np lol

gl to u too

[hexed lion]

gl everyone!

[dapper sand]

gl guys

[deep walrus]

Gl everyone!!!!

[cloud dome]

im taking amc 10 no prep first time

[swift imp]

Guys I’m getting a 6 or a 7

[cloud dome]

help

its tmr morning

[swift imp]

LOL

What time

And it’s on paper

I’ve been there the last 3 years for amc

[real pier]

Which contest are u all talking about?

[ruby ivy]

i believe this is about the amc

[real pier]

Oh its prestage of aime; ic

[woven tapir]

Hello 🙂
I have the opportunity to take two selection exams to maybe get a spot in the national team of my country for the IMO. But I'm not sure if I'm able to solve question like the ones in these exams in just 240 minutes. I'd like to get some idea of things I should know before I take these exams, i still have 2 weeks to prepare.

[scenic cape]

Solving 10 questions and leaving the rest will give me 82.5

Would this be enough for amc 12?

I heard that the rules changed for this year

Like international students result doesnt affect the average

[slow mason]

hi

[trim bramble]

good luck yall

[random lichen]

how was the test if u took it

[surreal willow]

Rise and Shine Mathletes

Good luck on all ur tests today!

[bronze shoal]

What are some number tricks I should abt 2025

For the AMC 10

[vestal yacht]

6-7 thousand qualifiers ✌️✌️✌️

[vestal yacht]

depends on the difficulty of the test

[ornate blade]

if you get 100 for AMC12, that can be achieved with 14 questions correct and 11 questions unanswered

soo, if you work hard enough you can guarantee yourself an AIME spot

that's like top 10% I know, but you really don't want to waste a year if you have the time and energy to practice
time just keeps on ticking and soon you'll be trying to qualify in senior year

[zealous aurora]

anyone down to study for putnam together?

[ornate saffron]

wait, y'all participate in the amc to qualify for aime?

oh lord, i am so doomed...

[scenic cape]

I need to get 100 for aime?

[scenic cape]

So possibly only getting 9 questions right can quality me if the test is hard?

Its never been this way

[small loom]

same 😭

[surreal willow]

Yo it’s u

Did ya get into aime last year?

[swift imp]

I got a 150

[near hill]

AMC 10/12 A takes place today. Everyone please be aware that competition rules forbid discussing the problems online until 8.00 ET the day after the contest, which (if my timezone conversions are right) will be in 19½ hours from now.

[solid sluice]

yep

[late flint]

what happens if u do discuss it

do u die

[near hill]

You run a high risk of getting banned from the server, at least.

[small loom]

Do you know me?

I didn't make it sadly, I missed the cutoff on 10B by 4.5 points 🙁

[tiny eagle]

Gl everyone I hope we all do well 🙏

[late flint]

oh i see

i would be sad if yall banned me

[marble orbit]

ok got it

[marble orbit]

yep follow amc big corporation rules like a good boy

collegboard ahh

[surreal willow]

Yea I think so

Ur Indian right?

I think I remembered you complaining about how you didn’t make the amc 10 or something in 8th grade

Was that u?

[surreal willow]

Yea

Trust

[late flint]

oh shi

[blazing comet]

By any chance is anyone here doing the british algorithmic olympiad 💀

[deep monolith]

yeah i am

why

[cloud dome]

anyone here finished amc 10?

[blazing comet]

Oh really

Wanted to ask how much python do u actually ahve to know

[deep monolith]

i looked through some past papers and asked a couple of ppl in the year above me, and they said that the questions are practically impossible without knowing coding

[blazing comet]

Hmmmmmmmmmmmmmmm

[deep monolith]

u dont need python specifically though

any decent language would prolly work

[blazing comet]

Do u think i can learn in a week 💀

[deep monolith]

uhhhh

u might be a lil cooked

[blazing comet]

Lmao

[deep monolith]

ig u can learn the basics

but nowhere near enough what u need to do the bao lol

[mild raft]

i answered 2 questions on amc 10 💀

didn't rlly study but that's still atrocious

[near hill]

AMC 10 A is still under embargo; it will be 16 hours before you're allowed to discuss questions online.

[mild raft]

not discussing the actual questions