#competition-math
1 messages · Page 24 of 1
aops has a large collection of contest problems
or just the IMO website itself
I would second AoPS
Compendium will have all of them + shortlist as well
But AoPS will have RMM, APMO, Balkan MO and all (or at least most) of the other international competitions
Aⁿ +bⁿ + cⁿ has no integer solutions for n>2
let n be odd and b=-a and c=0.
wow how original
not only did you misstate fermat’s last theorem
but said theorem was proved decades ago
and a^n+b^n+c^n is not even an equation
Literally
I got a 285 on mathcon as a freshman. Can I qualify to mathcon finals
no need to ping
This has no integer solutions for n > 2
wrong statement, again.
Fermat's last theorem applies when the three terms are nonzero
why do I even bother
Yes
Cutoff was low
wRonG sTateMEnt AgAiN!!!!!
It was never specified that all a, b, c and n were integers
😱
I think it was clear from context that they were trying to state Fermat’s last
but horribly mangled their statement
What problem?
halp
ah that usamo problem…
first thought is to use euler’s totient theorem somehow
totient seems hard to apply if (a,n) != 1 (unless you can filter out that case easily - intuition tells me it's going to be pretty nontrivial)
so my direction would to go by contradiction: assume there exist two residues r1, r2 such that a!n = r1, r2 infinitely often (a!n is the power tower thing)
alternatively if you have x in the sequence s.t. $x\equiv a^x (mod n, \phi(n), \phi^2(n), \dots)$ and we have that $gcd(a, \phi^k(n)) = 1$ for all $k$ then this also implies constant
cow
Proof by contradiction
actually not that difficult to filter out these cases!
so the generalized version of the euler totient theorem uses the Carmichael function
which is defined as:
$\lambda(x)$ is the smallest positive integer m such that $a^m \equiv 1$ mod n for all integers a coprime to n
Cozmogrgdfschkipkhrshtensi
totient(x) can be thought of as the order of the multiplicative group of the integers mod n
carmichael(x) must divide totient(x) since the order of an element must divide the order of the group
once you have that, knowing that totient(x) < x
you get that each successive power you tack on must reduce the order of the group, which must eventually reach 1
oh waaaaaaait just because the order goes to 1 doesn't mean it is the same value, might not be a fixed point, hmmmm
i have a hole in my reasoning, sorry for ping lol
if u want for subjective then i would highly recommend excursion in mathematics. however u must have some basic knowledge ont he topics as the book might be hard for beginners. for ioqm thrill of pre college mathematics is good and also pathfinder by pranshant jain
I didn't know where to begin
split n into p_1^k_1 etc.
so it suffices to show for prime powers
say p^k
now if gcd (a,p) neq 1
then eventually a^a^... = 0 mod p^k allways, done
if gcd(a,p) = 1 always then totient spam
thanks
what should i use to prep for amc 12 and aime
is there like a textbook that would cover all of it
art of problem solving vol 2?
i finished my SMGF 2025 Grade 12 last 2 weeks
i think aops vol 2 is a decent start but i dont think its complete topic wise and it doesn't give you a lot to practice with
you definitely need as much practice as possible
Yall I just finished 6th in my regions Math League as a freshman who skipped a grade, making me the youngest competitor
What are you talking about
Find some mock tests online or solve problems from previous years on the AoPS website.
Is that good enough prep or should it also be supported with theory and shit
aops 2 is like 30 years out of date at this point
its still not a bad book
lol aops v2 still calls the amc 12 the ahsme
it’s got a lot of content holes and the problem difficulty just doesn’t stack up anymore
That's nice. Congratulations!
lots of student written texts have popped up in recent years
of uh … varying levels of quality
Interesante
AoPS forums are full of them
and of course AoPS also has a huge plethora of problems
both from official contests and from student-written sources
oh some particularly ambitious students have tried writing their own textbooks
on various Olympiad topics
most common thing tends to be short form notes
(I’ve written quite a few of those myself)
Hi, i’m a sophomore in highschool and i am currently taking Geometry. next year im taking Algebra 2 but i would also like to advance and take pre calculus. is there a way for me to do that outside of school that’s an actual course?
look into online courses, try to find one that your school will recognize for credit
and/or ask your teachers about it
also this is not exactly competition math lmao
the AoPS inter alg and combo books are definitely still good enough
AoPS
proof they are actual courses:
the Kangaroo competition is a pretty famous competition worldwide
you're definitely not alone
I remember taking it myself
anyone doing kangeroo?
lmaoooo
im taking it a bit stressed ngl
Yeah
I know, I meant the Spanish Canguro
I refuse to believe that's not the same as the one internationally
Hey! Thank you ur method worked ! (Nest surds) that method is so smart
And it is pretty cool too
We show a universal method to de-nest the radicals for the square root case.
no worries!
Has anyone done All-Russian MO finals and st Petersburg MO? If yes, in what way are those problems nice (assuming that they are)
I dont know any cyrilic

$Q+Q^T=0\implies v^T(Q+Q^2)v=0\implies v^T Qv+v^T Q^Tv=0$
Actformain
tell me if anythings wrong
😭
hi
Only at 6th?
how much of a difference really is there between AIME qualifer x2 or x3 and AIME qualifier x1 since colleges know that u can qualify for AIME if you have qualified before
Only the likes of MIT would care
The vast majority of unis aren't even aware of this fact
admissions peeps at the top schools have seen it all
they probably wouldn't be particularly impressed unless you scored high at USAMO or smth
rate my birge kalifa equation
Hello! I am an aspiring math olympic and i need someone to help me with building my preparation plan for the next year. I also want to do well in selection test for IMO. Is there someone that can help me?
Suppose 91 distinct positive integers greater than 1 are given such that there are at least 456 pairs
among them which are relatively prime. Show that one can find four integers a, b, c, d among them
such that gcd(a, b) = gcd(b, c) = gcd(c, d) = gcd(d, a) = 1.
I tried a graph approach but was unable to achieve anything
the immediate response when i see a question like this is pidgeonhole principle
have not tried it but that would be my first method of attack after trying simple cases
My method was similar
I tried to prove that 4 cycles must exist for 456 node graph
But was unable to prove it
if im doing alcumus should i do hard normal or insanely hard i aint doin easy
i would recocmened arthur engel's problem solving strategies for problems and help
its online as well, the book i mean for free
You can’t beat those Chineses trust me.
okay buddy 😭
i mean i agree
but thats like
a bit sterotypical
lowk
lets not
No bec they work harder than everybody else
If u practice 8h they will practice 16h
Thank you very much! Besides this, are AoPS books great to use?
I mean the olympiad recommandations
Bro i want to get to imo first
Just do AMC OR AIME
I’m not discouraging u lol
But it’s the fact
If u are a child prodigy like Terrence Tao or Jordan Ellenberg you can try to beat them
If u are not just don’t even try
That is actually ridiculous
Don’t waste ur time on that 1% success rate
I DON T WANT TO BEAT CHINESE PEOPLE
But u can’t even be in the team without beating them
Wth lol
I m not chinese bro
Ok man I m actually pretty started up and i want to do this
Is there any competitions that only Americans can participate in? lol
I m not american bro
this feels so stereotypical, and im a chinese-indonesian
Ok
But it’s the facts they are smart bec they work hard then everyone
What? You mean you can get to IMO just if you are gifted?
Hard work builds talent bro
? Wow good understanding skills
Well by Child prodigy that s what you mean
💀
Good, i ll be from that 20%
i dont think u should listen to that person, its not really 80% 20%, i feel.
90 and 10?
Yeah this guy is wierd af
Bro if u just wanna waste time on that fine
Man I know some persons that went on IMO and got bronze, and they didn t even took 70% on regional math olympiad next year
They are clearly not that Terry Tao level
Well if your team is not america then u can try
WELL IS NOT
there is no such thing as "Wasting time" when u lose a competition
because each time, u gain new experience
It s romania
which will be valuable for ur future endeavor anywas
That is competitive too
if u want to try, go ahead @dry rune , u shouldnt let anyone stop u
that kind of tenacity serve u in the long run
And i ll beat the shit, i ll grind hundreds of days and i ll achieve my dreams
Lock tf in
I m going rn on starting my way
Hope u don’t got frustrated after you see how intelligent those geniuses are
Bro i am not american
I know this guys are good af
At least i m getting lot of information
now ur just being bitter.
I don t take bad words from online people so idgaf anyway
Just avoid those people that just tell u the good stuffs of the thing and don’t tell u the bad stuffs
u are NOT that guy 💀
dude dont listen to him he's just an ass
just try. best case scenario u win, worst case scenario u gain experience for the next competition, and along the way u will learn new math techniques
Wdym by weighted lesson?
💀 bro we get it its not easy, why do u keep trying to discourage them
if u had bad experiences with math competition, dont project it on other people
Chinese?????
I’m just saying they are hard working it does it means I comment negatively
Or based on bias
And u just understand as I’m being racist to the lol
Them
Nah man we got it, but these arguments don t lead to me not doing it
Yeah
Just my suggestions
That is actually against the rule I guess
Attacking people verbally
theres also this. whats ur point?
If u are a short temper person I have no idea how to solve it
u repeat a stereotype, tried to discourage someone trying to reach their dream, and for what?
Discourage did not means discriminate
did i say that?
Well if u said that is stereotypes I have no idea, cuz my Chinese classmates are indeed Hard working students I see their work
Yeah. That discouraging is not against the rule
It’s still their choices to do or not lol
with that line of reasoning, i wouldnt be surprised if u turned out to be racist, ngl .
though morally repulsive to do so. literally noone asked about how much better the chinese are, he was here for informations regarding math competition
I did not say “ Chinese people are always smart”
i never said u said that either, learn to read
That is a stereotype
I said they are smart bec they are hard working
If u are genetically hate whites or Americans I have no words to say
Do some yoga or mindfulness
lmaoo 🤣
sanest #competition-math discussion
Any Arabic-speaking high school students wanna enter a team-based math competition? It's Purple Comet
seriously what is with people being racist all the time
lmao actually just read this convo, wtf happened
ikr
uhhh <@&268886789983436800> can someone deal with this? ty
uhh i think u said ur country is romania?
not too familiar with how the romania selection works but yeah probably just grind out relevant past papers
ik RMM is quite theory heavy compared to other olympiads so idk how much theory u'll need for romanian olympiads but in general, i think it's always good to start with just doing problems to improve ur problem solving abilities
there's a great selection of problems&solutions on the AOPS forums
also idk what sort of ability you are, but one thing i'd recommend is to generally don't be shy trying problems that are you think are hard
if you think difficulty X is your limit, try doing difficulty X+epsilon, you might find that actually difficulty X+epsilon is not as hard as you might think
(so even if you don't think ur ready for IMO it can be worth trying some of the easier IMO problems etc.)
yeah they are I answered one of the Romanian maths magazine problems for them
looks like gun
lol
it’s not all about practice time
of course
(and thankfully)
what the fuck is this
Bro put it in math terms
it's nonsense, don't give it attention
Hi
math server do be like that
Interested?
oh fuck I did Purple Comet too as a secondary schooler
don't ask me about it though
hello
Heyo
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
where do I ask then?
did you not see these channels right above this one
me if i ever decided to make tests
Why? 我就不是很厲害呀
thank you for your nonviolence
what is this 💀
what’s happened here
yeah
how bout you?
i am unfortunately really good at G
pure geo?
my geo is suck
You’re aiming for medal?
cooking
cooking at 2:20am 👍
You got in that top 15 that get imo tst and you are not going?
Do you think 1800 hours of study imo/imo tst math is good enough or should I work like double of this?
it's top 24 but yeah
just work as hard as you can
dont aim to do X
just work
overplanning is a curse
That s great advice
But how much hours a day did you work ?
To get here
Just an idea of it
I want to be the best in my region and i want gold to national but the competition in my country is so good
Cause they are from a private school special for olympics(and they are doing just this stuff)
I mean they are doing just math
And it s hard to
Beat them
But i want to be better than them so i will work like 6 hours a day
For a year
Not pause days
no idea, just worked when i could
everyones hours will be different
also dont forget that olympiad math is like
nothing like any other math
its not the same set of skills as say research math
and very different from math education work
not that there aren't any overlaps, but just keep in mind not to overassume its value
top performers can be good career mathematicians, but not necessarily
Same here in Brazil, every year, the same 2 schools have at least 1 or 2 students going to the imo
Guys, do you think that these AOPS alumnis are strictly from the paid courses? Besides that, how good do you guys think these paid courses from aops are?
just so you know the only reason this is true is because aops gives free course access to all the campers
aops is not worth it
they teach you via a chatroom
yeah ofc ig?
lol
Have they already given you this free course?
im not american
its only for american campers
they literally teach you via chat theres no video or voice btw
doing well gives u lots of opportunity for unis and whatnot
knowing proofs helps a lot
often if you learn advance techniques there is decent overlap in lin alg, abs algebra
wth, it is $800 or something like that
crazy
Actually it can be cheaper, but literally just chat
not worth it -- do not reccomend
yeah
does anyone know how do i start doing competition math from nothing
I've never competed before
From all countries?
no
<@&268886789983436800> is this a real thing? idk if it was an appropriate ping but
we do not allow unsolicited advertisements
if you want to advertise a math competition, please dm @quick aurora and we can discuss it
No, excuse me, I'll ask, I rlly need help😭😭😭
you can ask other people though
Can you at least tell me the curricula I should cover?
Or the books you used
I'd be rlly rlly thankful

I aksed, and the information didn't seem to help much

Prove that there are infinitely many primes of the form p = m^2 + n^2 for positive integers m,n.
POP QUIZ: if I wanted to add every single whole number from 1 all the way to 50 up without actually doing all the addition, what formula would I use? The formula should give the same amount as 1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30+31+32+33+34+35+36+37+38+39+40+41+42+43+44+45+46+47+48+49+50
It would be 1,275
n(n+1)/2
prove it by pmi
Si
I think infinite descent
penalise or penalize
penalize
try easiest rounds of your countries math competition
How would you apply it?
澳門人?
Sigma notation
how does placing restrictions on homogenous inequalities work?
like can i just say "oh let abc = 1"
or a+b+c = 1
yep
as in formally, for a homogeneous inequality, say like x^2 + y^2 + z^2 >= xy + yz + zx
it's true for (x,y,z) iff it's true for (kx, ky, kz) for k > 0
so you can always scale s.t. abc=1 or whatever
anyway yeah that means you can always go backwards to place whatever appropriate restriction you want
no 天津人
help me i need food
what do you want us to do? email you food?
Country and age
If you still in school, it's really easy
There are lots of resources online
And school level competition isn't too hard
so i can make like literally any restriction
actually nvm thats stupid
yeah but in all likelihood there is very little chance that i.e. assuming a^5 + 3a^2b + c^7 = 29873 will be useful at all
ur much more likely to assume say abc = 1 or a+b+c=1
(well ok any restriction provided you can get there by scaling x,y,z by the appropriate amount)
(also you need it to be achievable, i.e. x^2 = -1 will obviously not work)
You gonna rock it
Portugal is really small
Not many people
If you've got some talent and practice, I'm sure you'll get great results
Portuguese Mathematics Olympiad
Portuguese kangaroo tests
@amber gull
ya
bro i never done competitive math before
liike i have vthis problem
There's always a first time for everything
if i see a olympiad quuestion i suddenly dont know what todo
What is VTHIS?
*this
What 😭
Let's try
Wait a minute
Show me a olympic question you don't get
ok
Oh fuck
I thought it was the one above
And I was terrorized
Let me translate this
this is just the finite geometric series formula with ratio r = -a
the x is some placeholder value, showing you that the exponents go down by one, alternating sign
the x here is written and used a little weirdly
but otherwise has no function, its just showing you whats happening when the entire alternating sum is written out and simplified
@pearl crater
btw just to mention
i do a levels so im actually in a different curriculum than the actual portugese one
na is fine go focus on ur own stuff
is my issue i should handle them alone anyway
like some sort of international curriculum
Oh
Cool
Bcuz you rlly smart or bcuz you chinese in Portugal?
Or for some other reason?
bcuz im chinese in portugal
Ok
like i just do a different system
alright
Really easy exercises with broadly published answers
thanks alot man for the help
Let ABC be a triangle with ∠BAC = 70°, ∠ABC = 50°, and M be the midpoint of side AC. Let P and Q be points on lines BC and BA, respectively, such that the circle passing through P, M, B is tangent to BA and the circle passing through Q, M, B is tangent to BC. What is the measure of the angle ∠PQB?
(A) 60°
(B) 70°
(C) 80°
(D) 90°
(E) 100°
Yeah I realized after saying that that by that logic I could just set them all to be 0
Which would he stupid
So probably the restricted set has to be some kind of interval
resource and teaching quality? yes
amount of stress it gives? hell no
here's an intresting and fun problem that i found on reddit :
Suppose there are 7 runners on a circular track, and they all start running clockwise at the same point
on the track. For all 1 ≤ k ≤ 7, runner k runs at k miles per hour. Given any point in time t, let σ(t) be
the current permutation of the runners, reading from the start of the track clockwise for one loop. How
many distinct possible permutations σ(t) are there if the runners can run for an arbitrarily long amount
of time? Assume that a valid permutation has all the runners at distinct positions on the track.
for anyone wondering from where i got the question, it was on the recent r/mathmemes online competition
Mathcounts is very fun
real
howd u do
Hey guys am I allowed to to promote a math competition here
Event Timing: April 12th, 2025. 12:00 PM -12:20 PM: Check-in. 12:20 PM - 5:00 PM: Competition and Awards.
Event Address: Westford Academy - 30 Patten Road, Westford, MA, 01886
Contact us at contact.wamt@gmail.com
Please note that if you are registering multiple students, please submit the form one time for each student you are registering.
Ahh I see
Where’s mod mail
top of the users list
buddy put ads at that primary school or highschool boards. proablity that you find candidate, is nearly zero
Who you advertising to
Min age for Discord is 13
7th and 8th graders
Wha if I don't have friend to get Teams of 4-6
Individual sign ups work too!
We will randomly assign a team on day of competition or you can also participate as an individual for the team round though it might be a little challenging!
What If I live in the ocean
K. But I don't live there so...
It’s ok
I’d appreciate if u could share it to mass people
Tho
We will try to make it online nest year
K then
😭
yeah uh
your target audience is mostly too young to be on this discord lmao
I was thinking that at first but it's actually fairly plausible
the reason it's inacessible is actually the location
you need to be American and live in the rough vicinity of Boston
me trying to advertise my LA area contest be like
lmao
they're not wrong though
where
im in Huntington beach
usc
registration has already closed since the contest is uh
this saturday
but if you want to compete with us in the fall that's an option
hello guys, how can I start competitive maths and what really is competitive maths?
more problem solving and critical thinking types of problems. The difficulty isn’t really in the calculations usually but in how you go about solving a problem using logic
thanks for the insights, is 16 too late to start?
you can start at any age, it’s just a new way of thinking
look at like the amc10 from this year and try the provlems
thanks mate.
No
great
I am not sure if this is the right place to mention and talk about stuffs but is there a prepared roadmap?
thanks a lot, it helps!
@wintry juniper to answer your question on "how to use Jensen in part (c)"
- find such function f
- prove that f is concave: https://math.stackexchange.com/a/3011915/290189
- apply Jensen's inequality ||on a, b, and c, following his assumption that a + b + c = 3||
#help-21|아리스킨충1 message
would you say thats useful for amc12 also?
I should have been more specific, I didn’t understand how u get the function in the first place
Taking the derivative is easy
But then I realized the intended function is supposed to have no constants
But should have x in there
Idk why
Of course, btw I haven't seen anywhere on this page saying that the recommendations are only for a specific olympiad
The foundations are kinda the same: problem solving, writing proofs, algebra, geometry, number theory and combinations/probability...
I think you didn't read the page, but it is simply introducing math olympiad, with some good first books and nice ways to start
from homogenization, followed by the application of the assumption that "a + b + c = 3" ||twice (once on each side)||
But why twice
I understand that if u do that then u get the function
But it doesn’t look motivated to apply it twice instead of once
Like why not just make it - 1/16
When you finish part (a), you'll see why
I call it twice cuz once on each side
If I count once on each denominator, then it would be four times
Wait
The most important thing is that after de-homogenization in part (b), you get a cyclic sum of a single-variable rational function
No I know what u mean
That's where f comes from
wait
no so the desired function is
1/(x+3)^3 - x/16
im wondering why u use this function instead of
1/(x+3)^3 - 1/16
ok well its some multiple of it
i forgot what it is but its like
16/(x+3)^3 - 16/x
i forgot but u get my poit
why do we replace the right term too with x
instead of like 1
Do part (b) first, and you'll see why
you may show us your work, so that I know where you're stuck
The coefficients in your functions are wrong
if you've tried, it's more likely that you get them right
yeah part b is what im confused on
the intended answer for part b is f(x) = 16/(3+x)^2 - 1/x
but im wondering why we cant use 1/(3+x)^2 - 1/16
obv the latter is one where we cant use jensens
but whats the modivation to not use this instead?
first show us how you got this function, so that we understand more the context of your question
The answer for your "why not this function" question is simple, and doesn't require any calculus.
Only basic knowledge on convex functions is needed
There're a couple of lemmas needed to answer your question
One of them is ||the fact that the reciprocal of a positive concave function is convex||
i think he has amc advice
If you assume twice differentiability the equivalent condition f’’(x) > 0 is probably easier
there're some problems in which even with twice (or even infinite) differentiability assumed, the secondary derivative would be tedious to calculate, and the solution will be much less elegant and readable than an elementary one
say to determine the convexity/concavity of the set Rₛ = {(x, y) ∈ ℝ² | |x|ˢ + |y|ˢ ≤ 1}
where s is a positive number
vin100
due to symmetry, it suffices to consider the upper right quarter of this set
i.e. {(x, y) ∈ [0,1]² | xˢ + yˢ ≤ 1}
this will give the function x ↦ (1 − xˢ)¹⸍ˢ, and a pretty straightforward solution
however, i don't find this beautiful cuz i don't see the reflectional symmetry along the line y = x throughout such argument
a much more elegant solution would be to make use of the convexity/concavity of the mapping x ↦ xˢ on [0, 1]
then the curve will slice the unit square [0, 1]² into two parts. choose an appropriate part and prove that it is convex
in the whole process, you'll observe the symmetry between x and y, cuz swapping the x-coordinates and with their corresponding y-coordinates won't change the argument
do u mind explaining Jensen’s inequality? I feel like I’ve hear of that in several places but never rlly saw it. I’m not sure if it’s above my level
,tikz
\draw[->, gray] (-1,0) -- (8,0); % draw the real line
% draw the points a, b, c
\foreach \x/\name/\fx/\lblpos/\text in {0/a/3/above/x_1, 2/b/2/below/x_2, 6/c/4/above/x_3} {
% on real line
\node(\name)[circle, fill, inner sep=1.5pt, label={[blue!40]below:{$\text$}}] at (\x,0) {};
% on the curve
\node(f\name)[circle, fill, inner sep=1.5pt, label={[blue!40, font=\scriptsize]\lblpos:{$(\text, f(\text))$}}] at (\x,\fx) {};
}
% labelled curve
\draw[yellow!50!black] plot[smooth, tension=1.3] coordinates {(fa) (fb) (fc)}
node[anchor=north west, font=\small] {convex function $f$};
% draw convex polygon
\draw (fa.center) -- (fb.center) -- (fc.center) -- cycle;
\node(fd)[circle, fill, inner sep=1.5pt, label={[red!30,font=\tiny]below right:{$(w_1 x_1 + w_2 x_2 + w_3 x_3, w_1 f(x_1) + w_2 f(x_2) + w_3 f(x_3))$}}] at ($(fa)!.8!(fb)!.25!(fc)$) {};
\draw[->] (fd) |- ++(2, -1) node[draw, align=left, font=\tiny, right]{$f(w_1 x_1 + w_2 x_2 + w_3 x_3)$\$\le w_1 f(x_1) + w_2 f(x_2) + w_3 f(x_3)$};
\node[font=\bfseries\large] at ([yshift=10pt]current bounding box.north) {Visual guide to Jensen's inequality};
vin100
convex function equivalent to the function's epigraph is convex
how did u get all of that so fast lol
thanks btw
wait what’s an epigraph
i pinned that in my DM with @gilded halo
Here the weights wᵢ satisfy 0 ≤ wᵢ ≤ 1 and
-# n
∑ wᵢ = 1
-# i = 1
I transferred the inductive step from Jensen's inequality's proof to the lemma that
convex combination of points in a convex set is still inside that set
the above lemma is
- more abstract, so more reusable
- more visually intuitive
I don't understand
!da2a
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
what's the original question
is the BDA0 and 1B7C part of the original question?
nvm solved
nah a,b,c,d is 2,4,6,9
,calc 246*26
Result:
6396
AH I misinterpreted the multiplication
what kind of order is that???
ABC * A for BDA0 and ABC * C for 1B7C wtf
ah then it should be C * C = C so you were indeed correct
May I ask in hs competitions, may it happen that problems link combinatorics and geometry, or combinatorics and number theory?
If yes, can someone recommend a problems textbook, not for one branch, but one that links branches?
happens all the time, a good introductory combo textbook should expose you to a lot of the common ones
A can be only 2 or 3 and C can only be 6 (1 and 5 are obviously excluded). So it is easy to guess that it is 246*26
Freemont
so true
how is 5 obviously excluded?
ah right I see now, was focusing on the wrong multiplication
Anyone on?
Anyone preparing for IMO?
most of the olympiad students hang out in the server linked in the channel description
is this a math contest question?
that seems to be a basic word problem
so #prealg-and-algebra or a usual help channel or #math-discussion would be a better place
my bad
Let $ \Lambda $ be a lattice in $ \mathbb{R}^2 $ with determinant 1. Let $ \vec{v} = (v_1, v_2) $ be a lattice point of $ \Lambda $ with positive $( v_1, v_2) $. Let $v_1 v_2 \leq \frac{1}{2}.$ Prove that there exists a line passing through the point $ \vec{v} $ and cutting off a triangle from the first quadrant that contains no lattice points of $ \Lambda $, other than the origin and the point $\vec{v} $.
kenshin
Doing school project on end-users insights sort of like an interview where. https://docs.google.com/forms/d/e/1FAIpQLScGqyZVUqd6ohqK1bVYawpHwb1nddQU9krMmMakseYh6PyekA/viewform?usp=header
<@&286206848099549185>
I am grade 10 and I was gonna say oh no is this what I will have to study but then I looked at it again and it's understandable with some studying
ah yes putting a Putnam B6 in a precollege contest channel
Need some help please
Find the number of ways of choosing the vertices of a regular 17-gon so that the three vertices form an obtuse triangle
<@&286206848099549185>
don’t ping helpers immediately.
oh sorry
i didnt know that
please help though
i have 20 miutes left and ive worked on it for an hour
i only know its 17c3 and that theres no right triangles
20 minutes left for what
<@&286206848099549185>
Is this pre college
Putnam is basically the undergrad math contest in America at least
No I mean is this channel only for pre college?
Does it say that anywhere I couldn’t find it
Putnam questions are pretty cool I think it’s fine to post here, some are easier than IMO questions and can be done with HS maths
it's listed under the pre university category
and its audience is mainly precollege students
but yea thats fair
Does anyone know about how many questions you should solve on the Awesome Math admissions test to be accepted?
!!!!!
idk but i heard 6 out of 10 is enough for a solid chance
Alright thank you
I imagine we need to use the formula for convergence of geometric series
by setting the formula for each series equal to each other I found a = 333(1 + r)
I'm not really sure what else to do here though. ideas would be appreciated
set them equal to 2025 !
if soh cah toa exist, then why cho sha cao doesnt?
how am i supposed to solve this problem:
Consider n (> 1) lotus leaves placed around a circle. A frog jumps from one
leaf to another in the following manner. It starts from some selected leaf. From
there, it skips exactly one leaf in the clockwise direction and jumps to the next
one. Then it skips exactly two leaves in the clockwise direction and jumps to
the next one. Then it skips three leaves again in the clockwise direction and
jumps to the next one, and so on. Notice that the frog may visit the same leaf
more than once. Suppose it turns out that if the frog continues this way, then
all the leaves are visited by the frog sometime or the other. Show that n cannot
be odd.
cause cho = cosecant = 1/sin x = hyp/opp
sah = secant = 1/cos x = hyp/adj
and cao = 1/tan x = adj/opp
sure you can make those acronyms but they're not particularly useful
when it's easier just to remember those as the reciprocals of sin cos tan
Mod
proceed by contradiction assuming n even?
Guavas
Anyone here know when Fermat (cemc math contest) honor roll comes out??
Why should 1/0 be infinite
It’s not, it’s undefined
The limit of 1/x as x approaches 0 is infinity
Oh
now
the limit of 1/x as x approaches 0 from the right is infinity, from the left its -infinity and the entire limit does not exist
Ah
Depends from which direction
I mean it’s infinity either way just negative or positive
Can I check those anywhere or does my teacher have to tell me
How much was honor roll do you know
which contest
Fermat
its like 130ish
I got onto the honor roll!
im a freshman prepping for amc 10/aime next year and wtf are these problems 😭
Let $a, b, c$ be pairwise coprime integers. Consider the vector $\mathbf{v} = (a, b, c)$ and the plane $\pi$ in three-dimensional space $\mathbb{R}^3$, which is orthogonal to $\mathbf{v}$ and passes through the origin. Prove that the set of points in this plane with integer coordinates, i.e., the set $\pi \cap \mathbb{Z}^3,$ forms a lattice (in the plane $\pi$), and find its determinant.
kenshin
Study modular arithmetic
Who's from Nigeria here?
never seen module problems in amc
Tbf a lot of the questions use mods but don’t use the actual mod notation
But looks like they gave up here lol
i know quite a bit of modular arithmetic but this is too much for an amc problem
this would be like p4-5 on the aime
i could swear there was one on this year's amc 12
Oh actually
I only took amc 10 idk about 12
I am planning to give, how do I prepare 😭
Like tuition is too expensive, I can afford it but still
I just do the previous contests questions
oh alr like past papers?
Yeah I think it's what he meant
Btw what is amc ? Sounds fun
it’s like a math exam eventually leading up to IMO
bruh most people who take the AMC aren't thinking about IMO at all
Oh ok, and is it mendatory to access IMO ?
Why ? Is it because one is much harder than the other ?
yes
think about it, for the IMO you can have maximum 6 people from your country
lmao "ah yes q1 here leads to the IMO"
Oh ok, but is the AMC international too ? And does it mean that it's open for everyone ?
yes, and yes
the only restriction is that your school needs to offer the competition
there's a paper version and an online version
it's the first round of the olympiad selection process
all computational
So it's hard 😭
the 12th grader competition is on the hard side definitely
UKMT senior is nowhere near this hard
that's correct
And in the case where your school doesn't allow you to participate/doesn't have any papers, you can't participate ?
yep
no worries!
Obviously?
yeah sorry, never searched anything about math competition before... you're right, kinda stupid to ask
so ukmt is easier than amc 12?
If you are a US citizen yes
The senior maths challenge? Yes
yea but it’s the first step
Am not so don't know if it applies
What country are you from?
Alright thank you so much ! I'll look that up
Yeah so I'm pretty much cooked, my ego fell off so hard just by looking at the exercises 😭💀
Has anyone any advice on how to simply get better ? (other than doing every former exam)
Hi
got all of 90 minutes of sleep Friday night and then had to host a big contest at my university on Saturday
pain.
what university just wondering?
?
usc 💀
holy
even though i'm not from the us, google told me how good it is
strength to you
how do you know?
there's probably loads of other good universities outside Anglo countries
the US just has the money and resources to be able to do good research
for good teaching material factors aren't relevant beyond a certain base level
Yeah probably, but unfortunately sometimes it's the quality and the reputation of the school that gets you hired or not
But I agree, in terms of education as long as have at least good teachers and a decent infrastructure, wether it's maths or science, you should be juste fine
I know lots of people

i have to lock in next year for my comps
i can get a 24/25 on the amc trustttttt i just need better time management
8, 10, or 12
how have those been recently difficulty wise
i got 19 this yr which is a big step up
the last one I took was in 2017 😭
not that bad
once you learn the topics
nice
ik a lot of other contests have increased dramatically in difficulty since I last took them
but i consistently got in the 20's on practice tests
has the same happened for the amc 8
oh not that much
you can still go back to previous years
nice nice lol
2002 was insanely easy but other than that all the years are abt the same
my highest score was a 22 iirc
thats good
and yea it doesn’t really get hard until the last five
yeah ikk
Yea literally
What's nice though is that, I believe, for example, tech companies are evaluating more and more technical skills and less where you learned them
Kinda niche but it can also mean that learning maths could always be a plus in those fields at least, no matter where you're from
Also maths are cool so its another big plus
You know what they say, aim for the stars so that if you fail, you'll land on clouds
Or something like that
Don't worry I have faith in you mate 
<@&268886789983436800>
Is that how the amc numbering works?
Like amc 9 for grade 9 students, amc11 for grade 11, 12 for 12 and all?
Question, what are the rules here? Basic math competition rules or something more
there are only 8, 10, and 12
8 is the catchall middle school level contest
10 is the easier high school contest
12 is the harder high school contest
discuss math competitions and math competition problems, of any level
it's based on grade levels yes
so AMC(n) is for grade levels n and (n - 1)
I understand the solution (mostly) but how did they find w
if you are summing (n choose 5k) you would choose the 5th roots of unity then sum all 5 expressions, and so on
it's really based on the fact that the sum of the roots of unity is always 0
hence you have 1 + w + w^2 = 0 for both the coefficients of nC1 and nC2, if w is a 3rd root of unity
Hey y'all!
Got any advice to start with comp. math?
I'm grinding prealg as we speak
even though im in grade 11 :PPPP
I just want to strengthen my math background for fun
💀
no
its for grade levels <=n
I'm starting too, but I guess you could test yourself by doing former exams of the maths competitions you're aiming for
Or any exam if you don't know your goal yet ig 
Oh? What grade are you in?
I believe that the US equivalent would be 10th grade
But I'm clueless too about where to start
Do you know what comp you want to pass ? @pearl holly
Australian Math Compet and PMO (Philippine Math Olympiad) :PPP
I am not that exposed to any competition math yet
but I did a week ago since it was a stats comp and it felt like my first math comp
Let me google that real quick
Are those national comps ?
You can try AoPs and Alcumus!
Ok I'll search, ty
||You can find some math comp. books online if you just search AoPs books||
||*mostly best to search up "How to pirate books" on reddit||
||ok thanks, I promise I won't tell ;)||
Oh and good luck btw
National comps are kinda hard
Thank you!
Yeah, thats why im grinding and strengthening my math background.
Goodluck to your comp. math as well!
Maybe in the future I'll see you at the IMO 👀
I'd be in college by then HAHA
Thanks ! But I don't even know if i'm really gonna participate in one. Depends on school and i've been busy with homework lately : (
Hope so ! That would be incredible tho
You should participate in one! It could boost your chances getting into a good university both internationally and locally!
You're right. Gotta inform myself about comps that my school could offer as a way to start maybe ? But I think I missed one this year 2 days after the end of subscriptions 
That's okay!
My school doesn't let me join math comps since they only join 1 💀
Thats why im planning on covering the expenses for the registration in math comps for myself (and if the venue where the contest is, I won't join cuz I transpo is expensive and tiring HAHA)
And I also have a huge global maths exam tomorrow, every class of 10th grade passes it and I'm getting eaten by stress rn 
Uh oh HAHA
Its best to start now!
Even with a little bit of effort/knowledge, what matters is that you gained experience
Comp. math is rote memo in terms of solving problems
Damn, kinda sad
But it doesn't have to be big at first ! If national comps are too expensive, even local ones are already great i believe
True true
Well, anyways, goodluck with math comp!
Hi
Hello !
Is there someone who will study in maths together?
What do you mean by that ?
Ohhh, no unfortunately I can't I gotta go now
Np
Does it ? 😂 Not meant to be but funny
Gl then !
Thnx
This isn't exactly competition math but did anyone here apply to PROMYS india?
My best win was like, the French olympiad
I'm not French tho
do yall know any good math comp yt channels or lectures
Can you tell me more about it ?
@knotty quiver
roots of unity filter mentioned
Idk if I’m crazy but looking at that problem reminds me of gauss sums
what can i do to study for australian math competition
to get like high distinction
its in like august but i wanna know so even if i procrastinate slowly ill do better
You're participating in the AMC, too?
Hope its not too personal.. what country are you from?
Gonna jump directly to the Grades 11 - 12
I have no comp. math experience prioor LOL
u dont really need it its kinda easy (imo)
i got distinction last year but thats top 20%
high distinction way harder so i want that and i wanna study
I'm still gonna strengthen my math background for fun haha
Well...
for u its 25% distinction
o
For the intermediate books.. uhh AoPs books and other Olympiad-style books
thanks bruh
Which competition are U people talking about
I wanna join too if I can join please bruh
Are you in high school
Australian Mathematics Competition Date Tuesday 5 to Thursday 7 August 2025 Time Primary divisions: 60 minutesSecondary divisions: 75 minutes Cost AUD $9.00 per student *bundle discounts available First run in 1978, the Australian Mathematics Competition is Australia’s longest running, largest and most well-known maths competition for school s...
,iamnotstudying
Removed the studying! role from you.
Idk if there is any other way to get better
You can try some other national olympiad or junior olympiad
You can ask people who do French olympiad what theory is useful
Yeah but I don't know any tbh
And you probably should learn angle chasing for geometry, induction, pidgeonhole principle, and invariants(Idk if Im writing in correctly in english it is not my first language) for combinatorics, and modulo, Fermat's little theorem and Euler's theorem(the one that is the generalisation of Fermat's little theorem) for number theory
I won't tell you how hard is your olympiad
Because I can't find the papers lol