competition-math

[acoustic nova]

u have a system of three linear equations in three variables so u will get a unique solution (easy to see, which is all u need, u don’t have to find it in terms of anything). I don’t know why this was starred challenge

[soft vigil]

It gets worse lol

Orz is child’s play compared to every thing else: admits, Xooks, iltg, 1434, etc

It’s pretty bad

[reef condor]

Basically, an nth degree polynomial has its coefficients entirely determined by its values at n+1 distinct inputs

And there’s a relatively clean way to interpolate a polynomial which passes through those points which you can search up

[reef condor]

sobad

[reef condor]

_ook

?

If p(x) = ax^2 + bx + c

You have h=a+b+c, j =4a+2b+c, i=9a+3b+c

A,b,c solely determined by h,i,j

[reef condor]

I mean yeah

Yeah…

[zinc venture]

Can someone solve 1^x=2 (answer is complex)

[gritty dawn]

suppose you have two n -degree polynomials P and Q agreeing on n+1 points

then P-Q has n+1 roots but has degree max n. thus P-Q=0

[hushed charm]

what even are these things

[vital heart]

the answer is idk

[steel onyx]

just take logs no?

[novel karma]

ok

[lapis kayak]

yea just take any non principled branch of $log_1(2)$

[gilded halo]

woomy

[lapis kayak]

in general, for $z \neq 0$, we define that: $log_e(z) := ln|z| + iArg(z) + 2\pi in$ for any integer n, and any argument between -pi (not included) and pi (included) to find for $log_1(z)$ just use the fact that $log_a(b) = \frac{log_c(b)}{log_c(a)}$

[gilded halo]

woomy

[lapis kayak]

@zinc venture

[lapis kayak]

atleast this is the definition i found in a course about complex analysis but im sure there are other definitions

[soft vigil]

r u sure this is comp math

[lapis kayak]

oh

mb i didnt see the channel

sorryyyy

actually i also wanted to ask if anyone knows if any math olympiad entrance exams of the 2023/2024 period have been released yet (with solutions but not necessarily),

[soft vigil]

wdym entrance exams

[lapis kayak]

umm im not sure it works the same everywhere but in switzerland there is a 35 question logical exam (based more on intuition rather than math) that acts as an "entrance" exam for the SMO team, theres a cutoff in this first exam and those who make it go to SMO, and then there are more exams (i think 2 or 3) and after all of them only the 6 who remain go to IMO

[soft vigil]

there are a bunch of tst's on aops

you can prob find USA tst on there

[lapis kayak]

ill go check! thanks :)

[soft vigil]

np

[radiant jasper]

LOLL not you asking random ass questions

Waffler

[soft vigil]

huh

[radiant jasper]

We all know your true motive to talking outside of discussy

Bubo..

[willow anvil]

P-Q is 0 at the points it agrees on. if a polynomial has more roots than its degree, its identically 0

[gilded halo]

GammaRadio

[nocturne valley]

Sub u=log a

And solve for u first

[jolly solstice]

what's the base of the log, e?

[nocturne valley]

Think it's base 10

[jolly solstice]

[nocturne valley]

[jolly solstice]

well let's just say it's base b for now, then I'd substitute a=b^x and it becomes ceil(2x)=ceil(3x)

[radiant jasper]

log(a) is less than 1 but greater than -1

i do not know how to proceed from here

[nocturne valley]

10^-1<a<10

Totally not bs

[radiant jasper]

yes but there are other restrictions that i cannot find

[ornate blade]

from Desmos the answer is $a \in (10^{-2/3}, 10^{-1/2}] \cup (10^{-1/3}, 10^{1/3}] \cup (10^{1/2}, 10^{2/3}]$

[gilded halo]

south

[ornate blade]

hope this gives you some insight

even though I still don't know how to approach it completely

the main thing is to prove that both ceils must be equal to -1, 1, 2

[nocturne valley]

Im pretty sure the answer is a range though

Desmos can't draw all the solutions so they only draw a few

[ornate blade]

of course, this is a range

[ornate blade]

I'm not stupid, of course I plotted the left and the right as separate graphs

when I plotted the equality I knew that didn't look right

[nocturne valley]

Oke

[prisma portal]

Holy shit guys
Planning my studies is difficult

[little harness]

Hi can I have some resources to self study comp math

i am currently preparing for the COMC

[radiant jasper]

Pathfinder jr? Yea

For rmo, no

[zinc venture]

The whole point of my question was to see if someone would work it out to the people saying just take the log its not that simple as logc(2)/logc(1)=x because that would result in a division by zero the way you would (simplified) is you set c=e(use ln) the you turn one polar so it would be ln(2)/ln(e^2πi+2πm)(for m is a negative or positive natural number) then cancel the ln and e so you get ln(2)/2πi+2πm then you multiply the top and bottom by -i to get (so it looks better i set m to 0)x= i -ln(2)/2π then using the power log rule you rewrite it as x =i ln(0.5)/2π then if you plug that in you get x=-0.1103178i

[jolly solstice]

I don't buy it. I say 1^x = 2 has no solutions. Similarly by analogy with a different problem I can manipulate S = 1-1+1-1+... = 1 - S so then S=1-S so 2S=1 and S=1/2. But just because I can do algebraic manipulation doesn't make the conclusion valid.

[zinc venture]

Fair but I like still try to get an answer to question like that and in this case (at least the way i did it) if you plug my answer in you do get 2 well very close to it its like 2.0000000002 but that could just be human error

[jolly solstice]

in a way this sort of boils down to definitions, but I would say 1^i = 1, I'm guessing you'd argue that 1^i = e^{-2pi} or something?

or like is it somehow multivalued as 1^i = e^{-n2pi}

main reason is if 1^i = 1 then 1^{a+bi} = 1^a * (1^i)^b = 1 for all complex numbers for me

[zinc venture]

I would have to work out 1^i first but it doesn't all ways have to be 1

Every one was told in school that 1 to the power of anything is just 1 but that really only true for real numbers

most people I meet people do see imaginary number as real numbers and the doesn't help but i the imaginary unit was a missing piece of math it gives answer to question once thought impossible.

History has a funny way of repeating it's self people a long time saw negative numbers the same way saying there not "real" if you got a negative number as an answer you would just turn it positive like people would say the answer for x+x = x-1 was undefined but now we say x=-1 it took a long time for everyone to add negative s to the number line and to even use them in every day life and I think i is just the same it is recognized as the squareroot of negative one but still it not on the commonly used number instead casted aside to the complex planing and given the name imaginary

[dense gale]

every mathematician since the like 19th century accepts and uses complex numbers

[zinc venture]

Yes but not every person does am not talking about mathematicians am talking about the average person they most of the the time may learn about it but still dont of them as real numbers

[dense gale]

the average person probably doesnt know anything about math at all

[zinc venture]

Fair

[dense gale]

and they dont need complex numbers anyway

they dont have the same daily applications that real numbers have

[zinc venture]

Yeah but there still cool and that what people thought about negative numbers to

[jolly solstice]

how do you work it out?

[zinc venture]

You can use a Formula to raise a number to a imaginary power x^a+bi = x^a(cos(bln(x))+isin(bln(x))

And when you put your number in the natural log make them polar

If you want i could work it myself

[jolly solstice]

Does this mean 1^{a+bi} = 1^a (cos(b ln(1)) + i sin(b ln(1))) = 1 * (cos(0) + i sin(0)) = 1

[soft vigil]

why do you take a in front of the parens

[jolly solstice]

I'm just following the formula he gave

I assume he meant x^(a+bi) on the left if that's what you're referring to

[reef condor]

Nah it does

Most ppl don’t even need real numbers

Just calculator for everything

But the technology obviously requires complex number s

[placid tapir]

How? Complex numbers can't be used anywhere in a real situation

There are no real life applications where you go like "ah that's a+ib"

It is used for creating many things

[burnt trail]

how can I get started in oly math from the groundup?

[placid tapir]

Practice questions

[burnt trail]

which ones

can u send me a link

[placid tapir]

Whatever your Olympiad covers

[burnt trail]

how do I find those

[placid tapir]

Huh?

You don't know what you're gonna write?

[slender saddle]

The reals are still generally more useful to a layman than (non-real) complex numbers

[placid tapir]

It is useful!

[jolly solstice]

I like using them to solve 2D geometry or physics problems where scaling or rotating can be involved in the solution, since it's a little less cumbersome than matrices to be able to freely divide and solve

[placid tapir]

Matrices and determinants lol

[swift imp]

Country?

[burnt trail]

peru wbu

[radiant jasper]

do you guys know about IOQM ??

if yes , provide some resources for it 🙏

[quasi condor]

Heeyy, is anyone here who studies physics ?

[quiet token]

No

I hate physics

It ruined mylife

[hushed charm]

it is not cool to talk about physics here

[echo hare]

Physics is basically almost as bad as engineering in the eyes of a mathematician. Oh the rule breaking.

[mint cove]

Physics and engineering are the bane on my existence

(I’m in physics, studying to be an engineer)

[reef condor]

Yeah

[peak kestrel]

but physics is just a branch of applied mathematics

[lime lake]

real

[hushed charm]

Actually you are right. But this channel is mainly focused on math competitions so I think it is not cool to talk about physics here

[lilac citrus]

Maths created physics... then to discard it?
Preposterous!!!!

[mint cove]

Theirs a dedicated, in network physics server to go to

https://discord.gg/physics

Physics discussion/questions belong there imo

[atomic shore]

Guys anyone has a solid book for math olympiads

PDFs

I’m looking for a source for number theory mainly

[hushed charm]

https://artofproblemsolving.com/store/book/intro-number-theory

[atomic shore]

I’ve skimmed through this

Do you have one which is more problem based

For practice

[radiant jasper]

Oh wow $55

That’s a lot

[hushed charm]

certainly it is, but a lot of people like this one, i am reading introduction to algebra and it is a pretty good book

[hushed charm]

aops is known for being really problem based, their mainly philosophy to learn is by learning through practicing a lot of problems. anyways, unfortunately i don't know any other number theory book

maybe you can check in #book-recommendations

[hushed charm]

( a shuttle number is a number that : the first digit is greater than the second. The second digit is less that the third digit. The third digit is greater than the fourty. The fourty digit is less than the fifty digit... )

How many 7-digit numbers formed by the digits 1, 2, 3, 4, 5, 6 and 7 are shuttle numbers? For example, 4253617 is one of these numbers. But 5372146 is not (2 is greater than 1 and 1 is less than 4) and 2163457 is not either (4 is less than 5).

[ivory ember]

Idk if thinking of it like this is absolutely necessary, but this was my first intuition

upstroke -> increase in digit (ex. digit 3 is greater than digit 2)

downstroke -> decrease in digit (ex. digit 2 is less than digit 1)

Based on this, what numbers must be "at the bottom" (digits 2, 4, 6)? What about "at the top" (digits 1, 3, 5, 7)?

Further hint: ||Place 1. Can you place 2 in the top row?||

[shy oar]

i think it's important to note that the numbers themselves don't really matter but only their relation to each other. So there are just as many 5-digit shuffle number with digits 1,3,4,5,7 as digits 1,2,3,4,5. You can get a nice recursion from this

[zinc venture]

This is why i said turn 1 polar so e^i2π so ln(1)= i2π that more like a bypass so it doesn't just equal 1 I guess you can that make to answer but technically there more if you do ln(1)=i(2π+2πm) for m is a positive or negative natural number to even more answer you see with complex number there infinite answer to problem like this and only one of them equals 1

[proper sundial]

bro was ignored

[proper sundial]

path finder 👅

[jolly solstice]

part of the problem though is if you turn 1 into $e^{i 2\pi n}$ for some integer n, then now when you solve $1^x=2$ you have $x = \frac{\ln 2}{i 2\pi n}$ - but now your solution depends on which version of 1 you picked. To be explicit, for any integer m you can write $1=e^{i 2\pi m}$ and now raising to the power with one of your solutions $x$ which depends on $n$ gets us $1^x = (e^{i 2\pi m})^\frac{\ln 2}{i 2\pi m} = 2^{m/n}$ which means your solution requires you to represent 1 a special way and the solution a special way, because you get infinitely many wrong answers when they don't match up.

[gilded halo]

Mero

[jolly solstice]

let me phrase it a bit backwards, let's say I tell you -i0.0022 is approximately a solution to 1^x=2 how do you check?

[reef condor]

Modern olympiad number theory (MONT), search it up on aops

Also you can probably find pdfs of aops books online if cost is really an issue… ofc I do not endorse this

[wary magnet]

Try AoPs Number Theory Books

[south socket]

Modern Olimpiyad Number Theory is a good book

[reef condor]

Me misremembering it as math Olympiad number theory is crazy

[south socket]

lol

[hazy mirage]

could anyone answer this?

[south socket]

$z=1+i(2-\sqrt{3})$

[gilded halo]

physicular

[south socket]

i dont understand the question

[hazy mirage]

its a special complex

[ornate blade]

you didn't ask a question

[mint cove]

Yeah if you’re looking to solve for z, that answers gonna come out to be

$z = 1 + 2 \cdot i - \sqrt{3 \cdot i}$

[gilded halo]

Airhead

[ornate blade]

wdym solving for z, there is no equation and z is already given as that

[mint cove]

I was joking cause it already says what z is

Therefore z has been “solved for”

[vivid ingot]

What special about this?

[near hill]

It's one of the two only points in the complex plane that makes an equilateral triangle with 2i and 2+2i.
That's ... um ... at least somewhat special? A little? If you squint?

[zinc venture]

Simple you solve 1^x=-i0.0022 then if you get the same answers as 1^x=2 then i0.0022 is one of the answers of1^x=2

[zinc venture]

But a problem that I do see with this is that if there a infinite number of answer. Graphing a log function that takes any number(but zero) will have infinite towers of dots on the negative side and since there is a rule of a function saying one input must have one output that would make the log function a multifunction(a function with more then one output for a given input)(when I say "log function" I mean $f(x)= \log_{10}(x)$ )

[gilded halo]

Coolkid7

[wary magnet]

I need help on a problem.
The set of ordered triples {A, B, C} is the solution for the alpha numeric AA+BB=CC Where A, B, and C are distinct natural numbers. How many distinct ordered triples are in the solution set?

[ocean narwhal]

a,b,c are supposed to be like digits? or a = 10 counts and AA = 1010 for that?

cuz for the latter there are infinitely many solutions i guess? as you can write the equation as

10 A + A + 10B + B = 10 C+ C
11A + 11B = 11C
A+B = C which obv has infinitely many solutions

[radiant jasper]

to be fair, there is the restriction that A, B and C must have the same amount of digits

which is not terribly hard to fulfil and still allowed infinitely many solutions

[wary magnet]

The answer says 32 triples. AA+BB=CC is obviously not infinite bc CC has to be a 2 digit number...👍

My way of thinking: you can choose any combination of 11, 22, 33, 44, 55 for AA and BB and also you can have 11+77, 11+66, 11+88, 22+66, 22+77, 33+66 that satisfies CC.

therefore, i did, 5P2 (because they can be rearranged and still be distinct) to choose between 11, 22, 33, 44, 55 which is 20

and then there are 6 more possible combinations but multiple by 2 because AA and BB can be rearranged which gets 12

add the ways to get 20+12=32 triples

The book says its a Mathcounts question so does anybody know which year it is so i can read the official solution?

[reef condor]

This probably is the official solution

Or something close to it

[slender saddle]

You didn’t say that it was a two digits number at first

You didn’t provide enough information when you were asking the question

[wary magnet]

I typed exactly what the question typed on the paper. Sometimes the wordings are tricky

i didnt make the questions. the people who make mc competetion questions do

the book answer is 32 triples

[wary magnet]

btw, alphanumeric means digits 0-9

[wary magnet]

no, alphanumeric means digits 0-9

[limpid shore]

Alphanumeric means it's in the alphabet or it's a digit

[radiant jasper]

I haven't made aime yet either

But I'm trying to

[radiant jasper]

A, B, and C are presumably digits in the case of alphanumeric problems

[ocean narwhal]

well they should mention it but alright

[radiant jasper]

Yeah unless otherwise specified they are typically one digit numbers

I haven't seen other problems where represent two digit numbers anyway

[ocean narwhal]

idk every exam that ive ever been to just said they are digits instead of alphanumeric but yea

alphanumeric kinda suggests using something other than base 10 anyways

[radiant jasper]

True

[hallow finch]

hello everyone, Im attempting to enter the Math olympiad for the first time, does anyone have any reccomendations as to how to begin training?

[ornate blade]

bruhhhhh just rationalise

what would you do instead?

[rich cradle]

||u=1/x is a root of cu^2+bu+a=0||

[rich cradle]

This is the most morally correct way to do it

[ornate blade]

oh holy shit

that's smart

[main crown]

this channel reminds me of why i quit comp math

Generally because i’m too stupid 💀

• the teacher was messy and sketchy

[rich cradle]

This explains why it kinda looks like the quadratic formula but inverted

[main crown]

he would do things like change grades after they were due

weird stuff

he played favorites so he would determine if “you did good enough” for him to change it

yeah so at that point i just realized it’s ok to enjoy math, and be good at it without being in comp math

High school yeah.

I was invited to my highschool math team, joined it because it was prestigious then dropped out because the teacher was annoying.

Yeah everyone was shocked because nobody ever dropped out after getting invited

now i’m labeled in the math team discord server as “dropout”

🤓🤓

[reef condor]

Watesiggma

Bro got invited

Orz

Joining the math team is mostly for fun since you get to attend more tournaments tbh

But it’s not helpful if ur tryna get good at comp math

Vs self studying

If ur just trying to make aime then review some amc questions

And try to get the first 15

But if there’s problems in the 10-15 range ur stuck on, then don’t be afraid of going into the 16-20 range since there’s sometimes a problem that’s way easier than it seems

For problems in the 1-10 range though, you should just do all of them

[main crown]

twas invite only

[reef condor]

Still orz

[main crown]

orz?

i’m not sure what that means

[reef condor]

Rbo Orz isn’t even that bad
But ok

[reef condor]

It means ur good

But tbh that sounds like a bad idea for a math team to make it invite only

Just make a “varsity” team with serious ppl and a “JV” team with not so serious ppl or smth

#serious-discussion message is wild

[cyan hollow]

Those who are preparing for isi/cmi ,2025 DM me.

I need competition

[main crown]

yeah they’ve now made a separate school for it.. it’s private and really sketchy

i’m not risking my school career for comp math

oh and yeah the comp math counted as a class

so it’s not even really extracurricular

[wary magnet]

sketchy

is that in number theory book?

[novel karma]

no way

[ocean narwhal]

💀 i mean if you need 4 digit numbers then yea you're gonna have to deal with computing

[wary magnet]

a number times 51 or 501:
exg: 51*64
=3264
line up half the number first and then the number same thing works for a number times 501

[main crown]

yes

[main crown]

the dude was also rich and had relations to the people who ran the competitions

soooooo

some conclusions can be drawn

(it was legit a cult)

[main crown]

they did

legit called “math 1”

-“math 4”

i have like

4 aops books

that i dont use

i should probably read them

got it for free because once again the teacher was rich and was good friends with the owner

richard smth

the team has won a lot

like hella titles

i think they have like 20 smth national titles so it’s working. It’s just sketchy

actually i can’t send that

i would b doxxing myself

it was a picture of the dude

who taught it

and it said the school

and if you reversed google searched it you could see the exact city i live in 💀

i think you could find it

anywhooo

moral of the story it’s sketchy

and don’t trust a rich dude with your school career

[main crown]

he plays favorites and does things like change people’s schedules to look better.fir example, if someone is taking one of his classes at an alg 2 level, he would put AP precalc there instead

which is just cheap. i wanna graduate and do well off of merit not because a rich dude payed people to let me in

i’d be more inclined to do it if it wasn’t actually a class i had to take in place of math classes

[cyan phoenix]

Aops books trash

All are free online

And they trash anyway

They're insanely overpriced too

Just use the pdf online if u really want trash books

[hushed charm]

Why do you think that?

[main crown]

Yes, but he cares so much about winning that he takes up normal math classes with comp math classes

[willow anvil]

yeah aops books are very overrated

[acoustic nova]

why they are pretty good in my opinion

[wary magnet]

how do you find the number of odd multiples of a number?

[cyan phoenix]

It's general knowledge

[cyan phoenix]

There are either infinitely many or there are none

Be more specific

[wary magnet]

sorry let me restate: how do you find the number of odd multiples of a number in a given range?

[reef condor]

Yo wtf

[slender saddle]

How come?

[wary magnet]

bro i wish

[wary magnet]

how do you get the pdf online

the pdf and the textbook are not the same

unless someone made pdfs of the textbooks illegally (which there are) but im not considering using

[acoustic nova]

the harder stuff in the books is definitely not. I think the intermediate books are very good

[reef condor]

Dyk mathluis

Mathcounts,a competition for middle schoolers

In USA

He is brain rotted (like me) so thats probably better for you

Less braineotted than me though

[shadow dirge]

How did u improved your geometry? Im struggling with this issue

Oh🗿

Where r u from?

I see

What kinds of math competition happens there?

Ok

[ornate blade]

eu não sou brasileiro, mais que eu sei da examinação de ENEM

só 3% pode aprobar

oh you just say passar in Portuguese instead, that's such a cheat

other Brazilians have said there are more specialised exams for maths and science,

and that the main problem with the ENEM is just the reading and the fricking eye-strain

when you have to read a whole paragraph or more for each question, also like they test everything

muito obrigado

I don't actually know Portuguese, I'm just converting it from Spanish

woah, Icelandic?

wdym you don't really speak it

interesting

my real analysis prof is actually from Iceland

I can still remember what I said, he was quite touched

takk fyrir að kenna mér

[acoustic nova]

I disagree. what books are better then? I think the AoPS books are great

[radiant jasper]

At least the entire math team doesn't hate you lol

[willow anvil]

Overpriced, too slow, you can learn the same stuff and more by just doing mocks

[cyan phoenix]

Not only do many aops books fail to cover fundamentals, (ie. intro to number theory, etc.) it is also reported that they have much more added depth and rigor, and fail to teach students with no general understanding. They are overpriced and meant for the rich kids who already have a decent knowledge of the topic. If you are serious about improving at competition math, I would recommend non-stop grinding AMC 8/10/12 practice tests (depends on level) because no book can help you prepare for tests better than actual past tests/practice tests with all of the same types of problems. (I used that strat to get into AIME) Also, that doesn't mean just do one practice test and move on. It means often you will have to do hundreds before complete mastery. If you are still clinging to the idea of a textbook, there are infinitely many options to choose from. I can only say so much to change your mind from buying an aops textbook, and if you would like to, go for it. I can only share my opinion.

I wasn't even on

[radiant jasper]

I dunno if I'm allowed to post links but never ever pay for those academic books

[soft vigil]

<@&268886789983436800> look up

[blazing osprey]

yea no we don't link to piracy sites here

[gusty bolt]

How do I make this into a formula without summation notation

[cyan phoenix]

Damnnnnnn how many eboys u got

Lofi girl type shi

[gusty bolt]

rude

[turbid brook]

i mean the website's actually good

and the classes are also pretty alright

and the books arent that expensive...

[cyan phoenix]

50 bucks for an ass book you tell me

[cyan phoenix]

No one talkin to you bruh

@fair bronze you better not type another fkin paragraph

[turbid brook]

blud its not that bad

like

literally whats a better one

well beast academt

[cyan phoenix]

I told you not to

I'm not reading that whole damn essay

Also I never argued with ur points I just made my own

We have conflicting viewpoints

If u look carefully

I didn't reply to any message

[willow anvil]

The point is that the content isn’t worth the cost. Sure, the content is alright but it’s not hard to glean the same information from elsewhere for less time and money

[cyan phoenix]

I told you before

It's general knowledge

Now just sit there and stop debating I'm too lazy

[radiant jasper]

What grade are all of you in? Also, have you had any prior experience in olympiads? Just curious

(if you are in grade school at all)

[hushed charm]

Your point is valid, what do you recommend when you said about "elsewhere"

[willow anvil]

i just did mocks and was active on aops

[radiant jasper]

I mean they're not bad but like AMC tests are better

You kind of already need to know the content to do AoPS books

[willow anvil]

i had volume 1 and volume 2 but i got bored of them quickly so i did mocks, by the time i had the motivation to do them i already learned all of the content in it

for computational thats enough

[hushed charm]

That is interesting, and about contents that you didn't know, where you used to search

[willow anvil]

if i was doing a problem that i didnt know how to do i would read the solution

then if there was some theorem used i didnt knwo i would research it

[radiant jasper]

they have detailed solutions in the textbooks

and there was a discussion channel for the problems are well

[hushed charm]

gotcha

[willow anvil]

Why not?

[main crown]

my dream

def got into a good school too

[willow anvil]

You can read the solutions and learn

That’s how I learnt most of the theory for computational

well yeah

im talking about for amcs and stuff

[radiant jasper]

sorry i'm in middle school

people are saying stuff like that all the time

?

[main crown]

how did you get so smart

[radiant jasper]

~~i literally hear stuff like skibidi and sigma and orz 24/7😭 ~~

[main crown]

maybe ill just be ok with being lazy

💀

whyyy

im taking like

[radiant jasper]

what is this

[main crown]

5 ap classes

i have no time

[radiant jasper]

also why are you named after that glitch girl from wreck it ralph

ah

[main crown]

rbf is real

yeah ive recently been stressed about making sure i get into good universities when im older.

but a lot of people have told me it doesnt matter as much as some people make it out to be

[radiant jasper]

what grade are you in?

[main crown]

10th

[radiant jasper]

oh ok

[willow anvil]

yeah same, computational is mostly just drilling problems

[main crown]

"resting bitch face"

IDK i feel like its not enough of a diffrence. Going to MIT wont be the diffrence between me working at nasa or working at mcdonalds

ugh

now i feel even more preassure lol

i have a 4.8 weighted gpa if that helps

just something in me feels like i need national titles to get into a good uni

max is 4.0

max weighted is 5.0

which means you would be taking all aps (literally has to be all aps) and all a’s

sooo next to impossible

i’m considering going to a local college striaght out of highschool, building up my resume there, then applying to higher level colleges for grad school, since i’m pretty sure that makes it easier to get in

that’s good

yeah i need to chill

just relax and enjoy highschool

[radiant jasper]

what would be some good classes to take in high school? just wondering

i am in us and will be starting freshman year next year

[main crown]

But i also feel like i might regret spending all my time and missing out on fun trying to get into these big universities

so either way there will be “regret”

philosophy is so cool

but it stresses me out

BRO I AM NOT MAKING IT TO HARVARD

😭😭😭

still too lazy

ima be ok with being mid

it’s been gone dw

i don’t have a head atp

like

that little thing in the back of your head that tells you when something is like rational

it’s gone

also that little voice that tells me not to do things

doesn’t exist

i’m dead ass

my adhd removed it

yesterday in the store i just said “YOOO LOOK AT HER GYATT”

i didn’t realize i said it out loud.

the girl turned around and look right at me

it was scary

[slender saddle]

So sigma

[acoustic nova]

def don’t need that for Oxford

[radiant jasper]

Understood. I’m sorry about that

[acoustic nova]

the books are very cheap for what they are

[willow anvil]

Not cheap for it’s worth

[turbid brook]

😭

[wide dome]

If anyone here is interested in writing a Back-to-School math contest to prep for school + competitions, feel free to write this contest prepared by the Math Contest Repository: https://mathcontestrepository.pythonanywhere.com/contest/cw1
Discord: https://discord.gg/xv6ZEnVJaR

[shadow dirge]

Is it free? And will it help me to prepare for exams like AMC and AIME??

[arctic vortex]

and more importantly how hard will it be bcs i think theres a very varied skill level here

[acoustic nova]

It is

[main crown]

Hey, what is this from, because it really helped me out

[wide dome]

yeah it's free, and I'm sure it will help with those contests too

[wide dome]

It's roughly AMC 12 difficulty

[shadow dirge]

But the questions needs calculus but in the contest we dont need calculis

[reef condor]

Wtf

[main crown]

true

[warped wedge]

Are there any mock tests for AMC 12 that have similar difficulty to recent ones

[gusty verge]

UKSMC is very similar to AMC

[hushed charm]

ludoviajante

[radiant jasper]

…

[hushed charm]

Given n distinct points in the plane there exist [ n(n-1) ] / 2 pairs of points. Find all positive integers n, with n ≥ 3, for which there exists a set of n points in the plane such that for each integer d in the set { 1, 2, ..., [ n(n-1) ] / 2 } there exists a pair of points with distance equal to d. Remember that for values ​​of n with this property it is necessary to show an example and for values ​​of n that do not have the property it is necessary to justify why the set of points does not exist.

Any ideas?

[mellow portal]

How many points do you need to qualify for aime in amc 10

And also what about amc 12?

[reef condor]

150

Is more than enough

But probably 90

To 100

Is cutoff for both

Depends on test difficulty tho

[reef condor]

Triangle inequality

[mellow portal]

So it’s based on rankings of ppl’s scores not a specific amount of points you need to reach?

[reef condor]

Yes, around top 8%

[noble quest]

Do we have any IMO medallists here?

[keen lake]

There are definitely plenty in this server (I am not one of them)

[burnt trail]

I'm not one of them either

[ornate blade]

they have better things to do with their lives I can imagine

than be on this server

[south socket]

I know a few of them, if you need them.

(4,4,4),
(12,4,4),
(68,20,4),
(4,4,12),
(12,4,44),
(68,116,4),
(4,20,12),
(12,20,4),
(164,4,44).
(4,20,68),
(44,4,12),
(4,116,68),
(44,4,164),

these are solutions

but i cant prove it

[ornate blade]

$\frac{x^2}{1} + \frac{y^2}{1/2} + \frac{z^2}{1} \ge \frac{(x + y + z)^2}{2}$

[gilded halo]

south

[south socket]

thanks

[ornate blade]

I just threw an idea around, didn't do anything

it has some non-negligible chance of helping you, that's all

Titu's is lovely innit

[south socket]

Actually, I can say this gave me an idea.

[ornate blade]

cool

[south socket]

It can be shown that all numbers must be a multiple of 4.

[noble quest]

Nah man, I was just curious

[south socket]

K

(Potasium)

[cyan hollow]

If anyone preparing for isi/cmi 2025 DM me @everyone

[hushed charm]

Yeah, I am having problems to prove that n cannot be greater than or equal to 5

[wide dome]

only three days left to write it, and there are $40+ in prizes :)

[modest marten]

hey guys

i finished all sections of AOPS alcumus

could i now pass the AMC 12 and qualify for AIME in 2 months?

is it likely

[near apex]

if you understand all of alcumus, then probably

however make sure to also look over past AMC tests

[gilded halo]

Vanellope von Schmugz

[ocean narwhal]

,w factor $27a^2d^2- 18abcd - b^2c^2 + 4ac^3 + 4b^3d$

Are you sure its factorisable

[brave heron]

Bruh what

[ocean narwhal]

XD

It looked weird

[gilded halo]

Vanellope von Schmugz

[ocean narwhal]

Thats factorisable only in a very specific case anyways

And adding terms sucks for factorisation

The simplest example i can think of is

1+a+b +ab & 2 +a+b+ab

[dapper magnet]

i hate how i know that this is a cubics discriminant

but no, u cant really factor it

if u can, then the cubic is probably nice

[quiet token]

I can factorise hard problems

[ocean narwhal]

Factorise my life

[quiet token]

Unfortunately there are no primes

😦

Just as a jk

dont mind it

@ocean narwhal

[ocean narwhal]

Yea no my name says that

[quiet token]

Truth

Which grade ?

R u in btw

[dapper magnet]

no this is the full cubic discriminant

im somewhat experienced in this

do u want me to send u my progresses

a strategy would be to "depress" the cubic by a transformation of coordinate system

what i mean is that, say u have f(x) = ax^3+bx^2+cx+d, u want to find k such that f(x+k) has no x^2's coefficient

[dapper magnet]

when u do that, u will notice that the what-would-be b term will dissapear alot

[vapid cipher]

guys how do i actually study and learn competition math

[wide dome]

If anyone here is interested in writing a Back-to-School math contest to prep for school + competitions + calculus, feel free to write this contest prepared by the Math Contest Repository: https://mathcontestrepository.pythonanywhere.com/contest/cw1
Discord: https://discord.gg/xv6ZEnVJaR
only two days left to write it, and there are $40+ in prizes :)

[swift imp]

practice and understand

[brave heron]

pattern recognition

[ocean narwhal]

💀 one way is to take log_2 x as a, log_2 y as b, log_2 z as c and solve the linear equations

also why does it look like some amc pyq

[ornate blade]

$\frac{x}{yz} \frac{y}{xz} \frac{z}{xy} = 2^{1/2 + 1/3 + 1/4}$

[gilded halo]

south

[ornate blade]

now you know what 1/(xyz) is

so you know what xyz is

so you can do x/(yz) * xyz = x^2 and so on

y/(xz) * xyz = y^2

[glacial jolt]

m/n = -7/8

Is it correct?

[slow sluice]

How many ways can you arrange the letters of word "MATH".

1. 1
2. 2
3. 3
4. 4
   <@&286206848099549185>
   Please help me out of this problem
   Guys please

[jagged sun]

that is factorial of 4

[hushed charm]

none of these

[slow sluice]

No one of them should be

[hushed charm]

In the first digit you can put m, a, t or h, supposing you choose a. In the second digit you can't put a anymore because you have already used this letter, supposing you put m. In the third digit you can choose t or h, supposing you choose t. For the last digit you can only choose the h

[slow sluice]

Mann its a question, i can't believe

[hushed charm]

what do you mean

[hushed charm]

Does that make sense?

[slow sluice]

Yes We can also use P and C

But still i don't know mann i wrote it as three

[hushed charm]

actually there is no correct alternative

[slow sluice]

Yes

Tk

[plain dirge]

he is just spamming/trolling, posted the question in many channels.

[slow sluice]

NO

[hushed charm]

oh

[slow sluice]

Way

[hushed charm]

that is bad mate

[slow sluice]

I only used this server for my maths

[slow sluice]

Bro no mann, I didn't

I don't have any alternative

[plain dirge]

help43, help 21, here, help1 ,,,

[slow sluice]

Also i am not spammming

Bruh i used this server only na

No ones giving right answer thats why i asked

[plain dirge]

you posted te same question in many channels

[slow sluice]

I won't repeat that, my mistake, sorry

[hushed charm]

The right answer is 4 * 3 * 2 * 1 = 24

But that is not an alternative in your question

[slow sluice]

Okay thank you very much guys

[south socket]

.

[vapid cipher]

thinking about it logically i think its 24 ways because if you take 1 letter, lets just say M, there are 6 other ways to configure the word when the combination starts with M. 6*4 is 24. Also I think I was looking at a problem like this a while ago, and the answer is n! where n is the quantity of objects that can be rearranged. so in this case there are 4 letters so 1x2x3x4=24

oh this was answered a long time ago💀

[pallid dragon]

i would say 1

if those are the options, must be 1

[radiant jasper]

i would guess 4, but it doesn’t really matter if every option is wrong

[wide lagoon]

8 8 8 8 8 8 8 8 = 1000
add any number of + - * / ^ in lhs to make the equation true.

[pearl holly]

Any tips to get better at Competition Math and books (exclude AoPs)?

no wait, scratch that, Any tips to get better at problem solving?

[radiant jasper]

are brackets allowed?

[wide lagoon]

na

[wide lagoon]

u could use a small dose of coolmath games

lol

[radiant jasper]

you’re certain this is possible?

can i assume PEMDAS applies?

[ocean narwhal]

888+88+8+8+8

[slender saddle]

Let me brute force 💀

[solemn arrow]

888 + 88 + 8 + 8 + 8 = 1000

[glacial jolt]

$\sum_{i=1}^{3}\frac{1}{i!} = \frac{0.1\overline{6}}{\log_{n}2}$```

Anyone try to solve this which is created by me

[gilded halo]

KingDanger

[glacial jolt]

Solve for n

[pseudo flax]

2^10

[wide lagoon]

1024

[gilded halo]

DaFlameSlayer

[ashen jacinth]

chicken pizza

[hot flicker]

4! = 1x2x3x4 = 24

[reef condor]

but why did you amke this bruh

[vale pecan]

Is scraping (just passing) the AIME floor for AMC 10A good? Am I cooked?

[reef condor]

Depends on your goals

If your goals are making aime then grind some more

It also depends on how long ago you are scraping aime floor (20 years ago? Cooked. 10 years? Kinda cooked. Recent? 50/50)

And ofc if you bomb the actual test then ur cooked

Like if ur the type of guy to cook mocks and bomb the real test

[weary void]

tbh theres definetly time to make aime

especailly since it seems you have a decent foundation for amc

[soft vigil]

what about the guy who bombs mocks and cooks the real test

last year i got 6~7 on aime mocks and 10 on the real test

[pearl holly]

The AMC 8 - 10 provided by AoPs themselves is good book

[reef condor]

Oars

[radiant jasper]

Yeah in general I tend to do better on real tests too

[swift imp]

For sure I’m more focused on real tests

Mocks more likely to be distracted

[soft vigil]

Oh no

[vale pecan]

ah ok ty

hopefully i get to aime

[hot flicker]

yo @radiant jasper and @soft vigil, how old are yall??

[vale pecan]

ill grind ig

[hot flicker]

just curious since i wanna know if anyone is close to my age

[radiant jasper]

angle bisector theorem states that the angle bisector splits the side AC in a ratio of AB:BC i believe

[ornate blade]

42

oh wait it's 43

chicken nuggies

[brave heron]

meanwhile combinatorics is some good pie

[peak kestrel]

hairy ball theorem

law of the unconscious statistician

[lusty plover]

hi

[wary magnet]

#help-12 Can someone help me please

[pallid notch]

1+1

[south socket]

3

[ornate blade]

window

[modest marten]

thats what im going to do for the next 2 months until the contest

[weary light]

I love mcnugget

[modest marten]

GUYS
how do i register for the AMC 12
my school doesnt offer it
do i like email another test site
but its on a wednesday
so i have school
how does that work
i just have so many questions
could someone maybe dm me and help me out?
thanks

[jolly solstice]

lookg like a=(x,y,z) and b=(y,z,x) in the dot product a*b = |a||b| cos theta and it follows

lol

I thought of trying something like that or an AM-GM type thing but that seemed like more work having to expand it out when I saw the dot products staring me in the face

[slate light]

My mental calculation is good

[jolly solstice]

not interested in attempting personally

what you have is good too

[slate light]

good

[jolly solstice]

as long as that means you doing it, sure go ahead knock yourself out

lol

[weary void]

isnt that just ||muirheads?||

or just am gm

[acoustic nova]

easy with cauchy-schwarz

[jolly solstice]

basically the same as the dot product solution tbh

[acoustic nova]

(x^2 + y^2 + z)(y^2 + z^2 + x^2) >= (xy + yz + zx)^2 by cauchy

so (x^2 + y^2 + z^2)^2 >= (xy + yz + zx)^2

x^2 + y^2 + z^2 is positive so it just immediately follows

[weary void]

oh yeah its pretty interesting, im pretty sure it can be derived from just am-gm or the general cauchy-schwarz but i forgot

am-gm: LHS = (x^2+y^2)/2 + (y^2 + z^2)/2 + (z^2 + x^2)/2 >= sqrt(x^2y^2)/2 + sqrt(y^2z^2)/2 + sqrt(z^2x^2)/2 = RHS

yeah i saw it in an evan chen handout

[acoustic nova]

they cover cauchy schwarz in intermediate algebra its good

[soft vigil]

💀

this is trivial

(inequality)

[peak kestrel]

x² - (p+q)x + pq = 0
D = (p+q)² - 4pq >= 0
p² + 2pq + q² - 4pq >= 0
p² + q² >= 2pq
Doesn't seem to generalize to cubics tho

[dapper magnet]

mmm

not sure

cuz

[radiant jasper]

can some one help

[hazy island]

Before trying this beast out, i would like to guess

is it 0??

[modest marten]

GUYS
how do i register for the AMC 12
my school doesnt offer it
do i like email another test site
but its on a wednesday
so i have school
how does that work
i just have so many questions
could someone maybe dm me and help me out?
thanks

[last pier]

hello i am having some issues with bijections, can someone help me out on a vc tmr or smthing

[cold cove]

[weary void]

check the maa website it has some resources

[last pier]

I am a fearless person, but that thing..... it haunts me

[radiant jasper]

nuhh

[weary void]

i think this is an attempt to generalize using polynomial discriminate and real nums, also does work as a solution to the problem you sent

[modest marten]

i did

i dont get it

i just need someone to walk me through ti

if someone could dm the that woud be much appreciated

[weary void]

send a screenshot of what you see

[south socket]

There are 100 positive real numbers arranged around a circle. Each of these numbers is greater than the product of the first two numbers immediately following it clockwise. At most how many of these 100 numbers can be positive integers?

[weary void]

is there a typo? AFAIK all numbers being 1/2 works

[slender saddle]

Yeah but it wouldn't be 'at most'

infact it's the least amount possible for the condition

[rich cradle]

You can easily make 99 of them positive integers

But 100 is impossible

[radiant jasper]

actually chat gpt sasys its zero but tbh idk the answer

[rich cradle]

Cuz each number would be larger than the next number clockwise

[rich cradle]

Never mind

[rich cradle]

I think we can do 49

But idk if can do any better

[south socket]

how

[rich cradle]

1, 1-c-c^2, 1, 1-c-2c^2, …, 1, 1-c-49c^2, 1-c, 1-c-c^2+c^3
For sufficiently small c > 0

Uh no

Wait

I think that works

I think it is true that at most 49 of the numbers are >= 1

Cuz if two consecutive numbers are >=1 then everything is >= 1

And then there is quite easily a contradiction

If there are 50 numbers >=1 in alternating order then still there is a contradiction

So answer should be 49

[slender saddle]

!nogpt

[scarlet root]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[hazy island]

I didn't use chatgpt i guessed

[south socket]

sorry i dont understand

why "If there are 50 numbers >=1 in alternating order then still there is a contradiction"

and why it is >= and not > cuz problem said greater than not greater than or equal to

[rich cradle]

Well let’s say the numbers are
a1, b1, a2, b2, …, a50, b50
and a1, a2, … are >= 1
Then by the condition we have b1 > b2 > … > b50 > b1

So that gives a contradiction

[rich cradle]

Well if a number is a positive integer then it must be >= 1

So >= is more useful here

[south socket]

thanks

[weary void]

oh yeah i’m stupid

[radiant jasper]

ig u can use sterlings approx

here

[keen lake]

How do I learn DIT and DDIT

[rich cradle]

Ask people you know that are familiar with it

(They might not respond)

[frozen hatch]

Will watching lectures on tensors focused on General Relativity still be helpful if I need to learn deep learning?

or nah?

[tight beacon]

Hey. I was in trouble.

What happens to the value of the function that describes the ratio of the sine of a number to that number itself as the number gets closer and closer to zero?

[hazy island]

You mean lim x->0 (sin(x) /x)??

[hazy island]

It equals 1

[willow anvil]

Just read the markbcc or yau awards handout

[tight beacon]

How can I prove that?

[ornate blade]

https://math.stackexchange.com/questions/75130/how-to-prove-that-lim-limits-x-to0-frac-sin-xx-1
multiple proofs here

[brave heron]

Is this some barycentric coordinate bashing typa stuff?

[willow anvil]

No

It’s projective

[hazy island]

give me some ideas regarding this

[acoustic nova]

wolfram alpha says no solutions

[abstract plover]

You can write q^2 + 3p = 197p^2 + q as q/p = 1 + m/n. If you rewrite the equation as q^2 - q + 3p - 197p^2 = 0. If you know Quadratic formula it will be q = [1 ± sqrt(1 - 4(3p - 197p^2))] / 2.

After that I could not find a proper answer actually xd

I mean it seems like there is no maximum value for l+m+n

[ivory ember]

p=17, q=239 works

,w q^2+3p-197p^2-q, p=17, q=239

[gilded halo]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by civil_service_pigeon

[ivory ember]

Rewrite it as $$197p^2=q(q-1)+3p$$

[gilded halo]

Civil Service Pigeon

[ivory ember]

Then, you can see that ||q(q-1) is a multiple of p||, and hence ||(q-1) is a multiple of p||

See what you can do from here

[hazy island]

Ooh, I missed that

Shoulda seen it

[acoustic nova]

oh

[shadow spruce]

MTH

[shadow spruce]

listen to courses maybe?

[shadow dirge]

Guys i need a little help

I can solve the question of AMC 12

BUT i want to solve other ques paper from different countru

Country*

Can anyone suggest a olympiad which is has similar level or a little bit higher level of difficulty

[shadow spruce]

Chinese that ends 12 hours ago

[kind sonnet]

go for Aime first!

[tawny sorrel]

what number theory book should i take after aops intro to nt

[shadow spruce]

Elementary Number Theory

[nimble valve]

2+2=5

[regal cliff]

True statement, but what if I told you 5=4!!!

therefore 4=2+2

and 2=4-2

which is 2

so 2=2

this is also a true statement

proving that 2+2=5!!!!

https://tenor.com/view/richard-nixon-twitter-gif-6755347737707332000

[tranquil pilot]

isn't this an ioqm question

[halcyon zephyr]

nope

[hazy island]

Yep

[last pier]

hello

[shadow spruce]

analytical?

or just 2D geo

I have actually never read the whole book, I just went over it real quick: Try solving these problems and examples before looking at explanation and then compare your answer with the explanation would help

[shadow spruce]

You can

Try taylor?

$sinx = x-x^3/3!+x^5/5!-x^7/7!+x^9/9!+Rn(x)$

[gilded halo]

Aestusy

[shadow spruce]

and everything cancels except

x

so x/x

or L'Hospital cosx/1 and cos0=1

Or, squeeze theorm

[novel karma]

simplify (log_28 216)(log_6 sqrt(7)) in simplest form without logarithms

[weary void]

egmo may be too difficult for amc 10

but if you can get through it its definitely a good resource

[weary void]

or geometry

[novel karma]

hey can anyone help me solve this

[warped wedge]

How much easier are the first 14 or so questions on 2010-2017 AMC 12s vs more recent ones?

If I want to qualify for AIME would getting 96-100 ish on those earlier ones be a good indication

[marble grove]

oh wait I should ask here

my question is comp math ig? its called study

in help forum

[shadow spruce]

sin/n = 1 when n is small enough, proving it geometrically is beautiful

[shadow spruce]

Yeah but going over it helps even if the book is at a higher level

[weary void]

yeah radians are the best!

[weary void]

yeah but if you’re not able to solve the problems you won’t get much out of it, i mean it’s probably still worth it to take a look

[brave dirge]

im having trouble solving it

[shadow spruce]

:(((

[mellow portal]

On an amc practice test I got 2 questions wrong bc I forgot to distribute properly and thought 4/60 was 1/20 💀

[green warren]

y=mx+?

[ornate blade]

what?

y = mx + c btw

[green warren]

C

[ornate blade]

so what about it?

[green warren]

IDK functions are just fun to do

[wary dawn]

where can I find some good materials that approaches Calculus 1 and algebraic structures(rings, groups, polynomials, etc) for math olympiads?

[frigid gorge]

for calc 1 you can read thomas calculus,its a great book

[ornate blade]

calculus is not required at all for any high school olympiads

are you talking about for something like Putnam which is at university?

yeah sounds like it

[wary dawn]

my math society that organizes this includes that

[ornate blade]

at uni?

[wary dawn]

high school

[ornate blade]

jesus christ

[frigid gorge]

are you preparing for JEE

[wary dawn]

romanian math olympiad

if I couls find something in english, its just as good

[ornate blade]

these topics are definitely not on the IMO so that's overkill

[frigid gorge]

I think have calc 1 for olympiad is fair enough

[wary dawn]

I just want to get some national olympiad medal

so i am fine with that

[shadow dirge]

Tnx

[shadow spruce]

@river iris

[weary void]

for fundamental algebra i recommend evan chens handout, just they first few chapters. gives a nice introduction to groups rings ideals fields etc

[shadow spruce]

Better for looking at specific problem-solving strategies

[willow anvil]

Napkin

[prisma dune]

How do I make nationals in math counts I live in tx tho

[prisma dune]

I will make aime this year hopefully (I’m in 8th)

[novel karma]

do uil instead

tmsca

[shadow spruce]

:(((

[prisma dune]

i am doing both

i wouldve got 4th in math but i curved my e's

6th in sci(tie but percent accuracy)

[reef condor]

Ur cooked

[reef condor]

For Texas u need JMO or ur kinda cooked low key

[radiant jasper]

b

[marble grove]

Can someone list good formula's to know for optics and astrophysics rq

[wary magnet]

you probably already know

[marble grove]

ok ty

theese were in the books I was reading but I just skimmed it

[wary magnet]

yeah

these are very important

and also remember both the planet and the sun move bc of gravity (earth also have a gravity). The sun is not completely stagnant but it moves ever so slightly

[ripe blade]

yo aussies

anyone do aimo today?

[ornate blade]

oh it was today

it was also R U OK day today lol

[pseudo flax]

sed

[shadow spruce]

Real Mathematics

[hot flicker]

yo im also in 8th

les go

im grinding to IMO currently

my goal is to get to IMO by 11th grade

[sterile helm]

is qualifying to AIME very hard?

[reef condor]

No

[warped wedge]

Are the first 13 questions on recent AMC12s harder than earlier ones or is it just later ones that get harder

[torpid carbon]

AMC gets progressively more difficult with each year. Each question usually gets more difficult when question number increases

[royal estuary]

Hey i wanted tips on proof writing

Specifically in combinatorics and inequalities

Can anyone help

[shadow spruce]

Thank you very much.

[weary void]

recently (as in last year) it’s been getting more easier, especially the 10

but it could have just been by chance

[merry thistle]

yeah

[ornate blade]

there's a trick: $B = A - \left( \frac{1}{2^2} + \frac{1}{4^2} + \frac{1}{6^2} + \cdots \right)$

$= A - \frac{1}{2^2} \left( \frac{1}{1^2} + \frac{1}{2^2} + \frac{1}{3^2} + \cdots \right)$

[gilded halo]

south

[buoyant arrow]

can you send a enhanced solution please

[ornate blade]

which part didn't you get?

[buoyant arrow]

after thus

this*

[ornate blade]

well, you just have B = A - 1/4 * A

[buoyant arrow]

Ohhh

Thanks

[ornate blade]

no worries

[buoyant arrow]

is it too hard que for grade 10th?

or an easy

[ornate blade]

competition maths is a bunch of tricks

I wouldn't be surprised if you got something that was awfully challenging for 10th grade

this question is quick if you know what to do

[buoyant arrow]

can i ask more que?

from that test?

[ornate blade]

sure

(just ask one question at a time pls)

[buoyant arrow]

okey

[ornate blade]

oh so you want to lose 12 hours in total (I thought it was 24 hours but the question assumes there's no AM/PM)

so that is 12 * 4 = 48 days

[buoyant arrow]

which date?

[ornate blade]

ah so be careful, so from 1st of July to 31st of July you have 30 days

[buoyant arrow]

its 5 oct

[ornate blade]

that option isn't listed

the question is vague yes

[ornate blade]

should be 18th of Aug with this assumption

[buoyant arrow]

But how?

indeed 18th is correct

how did you pridicted it?

[ornate blade]

read everything I said again

and that 48 = 30 + 18 ofc

so try counting up to the end of the month so that you don't mess up

[buoyant arrow]

Ohhh

How are you soo good man

what are you persuing sir?

@ornate blade

[ornate blade]

I only made it past the first round of my country's olympiad and not any further and I got questions significantly harder than this

https://www.scribd.com/document/723920289/Aimo-Sample-Questions-g8

this is for grade 8

[buoyant arrow]

it is still a fascinating achivement

[ornate blade]

but I will say this is a similar difficulty to the first half of questions in the American AMC10

[buoyant arrow]

ohh

[ornate blade]

https://artofproblemsolving.com/wiki/index.php/2023_AMC_10A_Problems

for example

20 to 25 should be challenging and they definitely will be at your level

[buoyant arrow]

okey

let me try

Yaa

i got 2/5

How can i get good at maths too

[ornate blade]

sounds like you just guessed

the uncomfortable truth is that maths takes effort and time

[buoyant arrow]

Yaa

[ornate blade]

and competition maths needs an entirely different set of tools

it's not like school maths at all

[buoyant arrow]

im the smartest in my class in maths but i want to go higher

[ornate blade]

that's admirable

and you don't have to force yourself to learn more, just do it cause you like learning new things

[buoyant arrow]

i got 97/100 in my 9th exam in maths

do you know about

jee adv from

indian?

[ornate blade]

oh yeah

man India is just insane

glad you're doing well so far but 11th and especially 12th require a lot of effort for many people, cause there's a jump in difficulty

and you probably already know that adv is miles beyond the regular 12th syllabus for NCERT

[buoyant arrow]

yaa ik i was just asking have you attempted its que?

you are from?

where?

[wanton badge]

Jee advance ez
Go for Olympiads if you want diff problems

[ornate blade]

Hong Kong

I've done a few AMCs but I graduated high school before 2023

[buoyant arrow]

Ohh

[covert dock]

does anyone have gaokao math subjects in english?

ill trade this year's admission exam for the university of bucharest which was also interesting :3

[livid hawk]

what is heterolytic cleavage?

[shadow spruce]

🤔

[hot flicker]

for the first question i got r = 6

am i correct?

[silent dove]

yeah

hows you go

howd

[ripe blade]

yeah not bad i got all of the first 8

hbu?

[silent dove]

damnnnn

i got 1-7 and q9

what'd u get for 7 and 8

[reef condor]

open ai o1 going crazy

although it probably requires absolutely absurd amounts of computing power

[ripe blade]

98 for q7, 240 for q8 (the binary one?)

[ripe blade]

how did u get q9???

[silent dove]

i got 98 for q7 and 128 for q8

i think i got q8 wrong

and some ppl are saying that the answer for q7 was apparently 86

[silent dove]

i did this:

[ripe blade]

woah

i got the prime^2 thing

but not the n = prime^prime^2-1

thats amazing

[ripe blade]

😟

[silent dove]

oh nice

[silent dove]

lol

[dapper magnet]

are u from india

[timber island]

Hey guys, got a big competition tomorrow

Got any advice?

[sour depot]

i'm new here but

eat and sleep well! (also alot of people like eating chocolate right b4 idk why tho)

[echo owl]

Seems like it

[brave heron]

Sugar overload enhances the brain

I do it a lot

[ornate blade]

,w r+s+t+u+3v=8,r+s+t+3u+v=9,r+s+3t+u+v=7,r+3s+u+t+v=6,3r+s+t+u+v=5

[gilded halo]

Results provided by WolframAlpha

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Requested by sooouth.

[ornate blade]

you can check yourself!