#competition-math
1 messages · Page 1 of 1 (latest)
The key is that ABCD is a cyclic quadrilateral
The angles restrict that Yes you're right but it's not important
This means <DAC=<DBC=30 and <ACD=<ABD=45.
lemme think
It doesn't look like we have enough information. The central angle theorem tells us the relative positions of A, B, and C, but D could be anywhere on the arc between A and B without changing any of the angles.
Wait, no, I was reading the angles wrong. 🤦


I see a decent way of doing it by expanding the binomials and working through it that way, but may be better ways. I'll post my soln in a bit busy atm
you get 10 from 3322 or 22222, there's no third way
there are 8!/2!/2!/4! ways to shuffle 33220000
there are 8!/5!/3! ways to shuffle 22222000
each of them makes 1x^10
so 476
i will wait
0000?
the power
i see
it is absoulety short and nice
let me apply it over another question
supoose we have
(1+x+x^2+x^3)
power is 2and we need to find x^4 coffi
i guess i am wrong somewehere
but that's one way as far as i understand, you can't say it's a trick
the only way i meant
i don't know sorry
you could expand out the (1-2x)^18 and just look at the first 4 terms as a polynomial, then you're only really looking at a few things multiplied together
$(1+ax+bx^2)(1+(-2)^1\binom{18}{1}x+(-2)^2\binom{18}{2}x^2+(-2)^3\binom{18}{3}x^3+(-2)^4\binom{18}{4}x^4)$
Mero
x^4 term will just come from 3 terms multiplied, similarly for x^3 term
tq very much
My sister (Rising 7th grader) is looking to get into comp math. Last year she scored a 12 on the AMC8. She can do basic algebra but nothing more, I gave her my old AOPS Vol 1: The Basics book but it was too hard for her.
Can someone send a list of AOPS books to do in order for her?
AoPS pre algebra
am I correctly interpreting this?
Yes the second equation is what you want to conclude
got it, thx
IF ANYONE CAN PLEASE HELP ME APPLE FOR AMC AUSTRALIAN I WOULD HIGHLY APPRECIATE IT 😭 😭 😭 😭 😭 😭 😭
you have to ask your school to enrol you
if your school doesn't offer the competition you can't join
yeah
my school did a math competition earlier this year
and they alr gave at awards
but on the website
it says its in AUGUST
Australian Mathematics Competition Date Tuesday 6 to Thursday 8 August 2024 Time Primary divisions: 60 minutesSecondary divisions: 75 minutes Cost AUD$8.50 per student First run in 1978, the Australian Mathematics Competition is Australia’s longest running, largest and most well-known maths competition for school students. Like all our competiti...
then what your school did wasn't the Australian one
maybe the American one, which is also called AMC
ask the maths teachers in your school
usually there's one maths teacher that runs all the maths competitions
wait if my school did the one above, would they likely do this one too?
it depends, they might or they might not
actually our school did a lot of competitions, the American one, Canadian, UKMT, and the Kangaroo one as well
but I had to take the Australian one outside of school
how!
unfortunately the deadline to enrol in the paper-based test has already passed
how do u do it outside of shcool
can I do online
there was a maths club that organised it outside of my school
yeah of course
but then they would only let you do it online if they were your school
which leads me to believe that it isn't common to offer that competition
unfortunately
it's a nice competition, a lot like UKMT actually
nothing impossible
whats 10+10 ?
idk
not that I know of
oh wait
like it really depends on what your school offers
oh interesting
if my school doesnt do it, can I request ?
yeah join that one, at least you can practice and socialise with other people with similar interests to you
yeah you can request
many Australian schools have some kind of enrichment due to gifted and high-achieving students
and maths is just such a common subject
oh AMT organises something of their own, interesting: https://www.amt.edu.au/enrichment
Maths Enrichment Date April – October 2024 Time 12–16 weeks Cost AUD$53 per student Maths Enrichment is an extension program for talented students to widen their mathematical knowledge and skills. Teachers receive comprehensive printed support material to extend both student learning and their own mathematical teaching practice. Enrichment mate...
yeah I've heard of that one also
AIMO is actually from Hong Kong
oh wait there are 2 with the same name lmao
bro all of this stuff is confusing
Australian Intermediate Mathematics Olympiad Date Thursday 12 September 2024 Time 4 hours Cost A$22.30 per student Australian Intermediate Mathematics Olympiad (AIMO) is a highly challenging maths competition designed to identify and stretch talented students. The AIMO paper is pitched at a Year 10 level but may also be of interest to motivated ...
ah so this is another Australian one I haven't heard of
but yeah it's like AIME just Australian it seems
if they can do these math stuff
yeah
wait what year level is u in
oh nice
yeah I'm at UofAdelaide if you wanted to know
they're on the website
I mean it says this
May include:
Parallels Similarity Pythagoras’ theorem Diophantine equations Counting techniques Expansion and factorisation Inequalities Sequences and series Number bases Methods of proof Congruences Circles and tangents Probability
but is it really like that?
there are sample papers
cus like the first 3, inequalities, circle theorems, probability n stuff
bruhh my learning leader is doing smth at diff country
so she sent me an auto mailed
ig ill email when she bacj
yeah cool
oh hell nah
it is school holidays in a big part of Australia also
2017 is freaking impossible
so yeah just be patient
oh no question 2 is about different number bases
so $2(b + 1)^2 + 3(b + 1) + 4$, that's what $234_{b + 1}$ means
southy
like you know how 234 in base 10 is shorthand for 2 * 100 + 3 * 10 + 4
same principle
brother what are u spouting
probably stuff you don't know yet
but that's okay!
everyone has to start somewhere
I mean I could just do all of them next year ig
yeah you have time yk
also not everyone who has the ability even needs to do Olympiad mathematics
that's just one very specific type of maths
I didn't enjoy competition maths all that much, well the initial rounds were fun but I didn't have interest in anything above that
do you have any tips when test taking?
read and underline the question carefully, start off with the easier questions first (not necessarily the first few ones, maybe the middle ones)
don't get hung up on the last few hardest questions, if you can't do them that's very natural
also don't leave a question blank
time is a weird thing when doing competitions; it always seems like you never have enough
well a lot of it would be through your school
but check out GERRIC from UNSW, I did a winter mathematics enrichment course there in Year 7
I live Melbourne
yeah
keep looking for opportunities I guess, I'm not exactly sure how much there is cause I didn't do high school in Aus
but given mathematics is so popular there's a huge demand for this kind of stuff
don't beat yourself up if you can't convince your parents to travel with you to Sydney
<@&268886789983436800>
Here
in the previous exercise each way produced 1x^10, you need to pay attention to this
221000
211100
111110
221000: 9 × −1 × 8 = −72
times 60, −4320
211100: 3 × −1 × 4 = −12
times 60, −720
111110: −1 × 2 = −2
times 6, −12
i get d
60 is 6!/2!/3!
3×3 gives 9, we multiply 3x² by 3x² so there's a 9
000 is 2×2×2 is 8
||rearrangement inequality|| I believe
yeah
shihgua
Compile Error! Click the
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(You may edit your message to recompile.)
For nonnegative real numbers $a , b , c$ . How to show: $\frac{a + b + c}{3} - \sqrt[3]{abc} \leq \max {(\sqrt{a} - \sqrt{b})^2, (\sqrt{b} - \sqrt{c})^2, (\sqrt{c} - \sqrt{a})^2 $
shihgua
this is Chebyshev’s inequality
Yes
Perhaps do a WLOG proof, ie. Assume [(\sqrt{a}-\sqrt{b})^2\ge(\sqrt{b}-\sqrt{c})^2\ge(\sqrt{c}-\sqrt{a})^2]
As generally the maximum function is quite tricky to work with
Max
I also suggest substituting [x^3=a, y^3=b, and z^3=c] to use the identity involving [x^3+y^3+z^3-3xyz]. I haven tried it, but it may help.
I hate maths
very deep thought
Rubix
Interesting
if somebody wants to know, I want to qualify for the national olympiad in my country
selection test is in March 2025, I hope I can get good enough by then
proofs are a relatively new concept to me though, I have to grasp them
Italy
it’s not too hard I think
yeah doesn't sound unreasonable
there are a few italians in the olympiads server, you could ask them for guidance
I’m not new to the olympiads, but I always participated with a team
I probably know some of them, if they’re gold medalists
know by name I mean
Idk if they're gold medalists
Does italy have many team competitions?
team competitions are really cool, i wish there were more
I mean why some countries do better on IMO than others is probably cause the other countries just don't care about competitions
- smaller populations
very true
there’s only one I’m aware of
which my school has participated in the last 7 years or so
also like many poor countries don't have the resources even if they tried
in the semi finals
India is an example
but yeah not relevant to Italy
ah that's so true
it’s hard to organise stuff tho
plus nobody likes geometry
I’m one of those who doesn’t study geometry for the olympiads, but if I want to get at least a bronze in the national, I have to
when I read the solutions I think some things are built out of nowhere
“draw the height of this small triangle AQK”, I would’ve never thought about that
yeah geometry is largely about good intuition for how things "should be"
I have some time
8 months
someone I know managed to get the bronze, starting pretty much from my same situation
so it’s not impossible
by the way, I’ll ask in the olympiad server, even though there’s not much to do, other than do many exercises
and understand the official solutions, if I can’t solve a problem
or if I can’t prove smth
Good mindset
Too many people get invested in learning theorems, tricks, etc.. when the key is just experience and doing a lot of problems
Nothing can replace that
And it's the most important ingredient
I’ve noticed that 90% of times I can’t finish an exercise because I can’t figure out the process, not because I don’t know a theorem
some things might help obviously
Yes exactly
like Vieta’s formulas and perfect squares mod 3 and mod 4
You wanna constantly be reflecting on the way you think to think to find out why you couldn't finish the problem
Learning from failure is extremely helpful
absolutely
for example I noticed that many times I forget restrictions, which can help me save a lot of time, by not trying all the cases
knowing the solution is an even prime tells you that it must be 2
but if you don’t put restrictions it’s way harder to notice
🤬🤬👺👺👺😡😡

No emphasis on geometry
the team is made of 7 people, and only one person actually wants to do geometry
😂
the leftmost one
G>>>>>N>A>C
Has anyone ever felt guilty doing contest math problems? I enjoy them a lot more than traditional book problems but sometimes feel I should just be using the time doing contest problems to go further in higher levels of math.
I like geometry!
I feel the same, it’s difficult because i feel like having good results from math competitions will also look good on college apps, but i’m just so much more interested in progress further in calc or diff equations than learning a bunch of random ways to factor polynomials that aren’t useful anywhere else other than competition-math. i set myself a goal by the end of high school to qualify for the AIME at least once, but it’s difficult to balance learning higher level math and competition math because of my specific interests.
I love competition math! I made it to the national competition in MATHCOUNTS once and got like 15th place
simplify the equation first
fyi ive never tried anything like that
wdym?
the type ofquestion
put all the a's on one side of the equation
its for a competiton in august
yes i do
clear the fractions
alot of it
yes
so
That's interesting I'm the complete opposite where I enjoy learning weird theorems in geometry that are useful for Olympiad problems or other obscure tricks.
I also don't really know how helpful for college it is. I would say if you took say higher level courses at a college in highschool still that would probably look just as good or better.
I feel like small branches of competition math like graph theory or game theory are a lot more interesting than like linear algebra. I don’t know linear algebra though so I’m just guessing but there is a lot of very cool competition math stuff (and these subjects are studied in detail outside of the competitions, ofc)
linear algebra is an extremely deep and rich subject
yeah
I don’t know it doesn’t look as interesting to me but I’ve only seen very tiny pieces of it
which pieces have you seen?
the stuff about vector spaces and linear maps
is a gateway into abstract algebra, analysis, etc
matrix computations idk
a guy in one of my classes was giving a presentation on like end behavior of markov chains, that was interesting though
too hard for me to understand at the moment
I have tried, but I only get the minimum zero!
matrix computations are boring when they're unmotivated (describes the majority of high school and lower division undergrad treatments)
if you plan on studying math at uni, that won't be a problem. They'll teach all you need, and if you have developed good logic skills that'll be easier
I've had this one week maths course at uni, it's completely different from what you're used to do in high school. An open mind is more important than learning things in advance
Here, i could have written it better, but ive done it like this, ask if you have any questions
Im like 20 hours late but i joined this server an hour ago anyways
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
I don't think that applies with the same force here as it does when the problems are homework.
(@ivory ember)
Anyone hints
Left to the reader
Interesting, I'm also competing in the same competition
Does anyone here have a really good recommendation on how to prepare for math Olympiads?
And resources on how to do so?
depends on the level of the olympiad
but i really like the soviet olympiad book :]
theyre also helpfully categorised
Help
Thanks
I was wondering how can one learn all what is necessary for Olympiad. Let's say I just started Olympiad and wanted to get to a really high level. How would one do so? What resources are good for that?
again, it depends what level you want to achieve
high school Olympiad can be done with little more than simultaneous linear equations, or quadratic equations
of course you'll also need area/volume formulas but that's just an example
Alright thanks
Hey can anyone from australia give some insight on AMC if they have done it?
amc you mean australian mathematic competition?
yeah
damn fast reply, I have an old copy of a 2017 senior a while back then, I joined one back then and I'd say it's kinda accurate on what will be part of the curriculum
oh nice
thanks

it's a contest that goes progressively harder but it's possible to solve all in an hour, I suggest to focus most of your time on the harder ones first
if you aim to do IMO level, you have to really spend like most of your time doing just math and practice your proving skills in all math curricula, especially when you live in a country with lots of competition
not a great competition overall
the questions are a lot easier than they need to be
additioonally, the timings are staggered and hence some people might have known then questions and potentially answers before going in
that's more of an organizer issue I guess? but I do agree that it's easy compared to some non-IMO competitions out there
their questions are mostly brute-forceable
yah plus most of the questions are multiple choice so it's really easy to cut off answers
if you are a beginner, I think it's a great startup imo
alright
then just work your way up from harder stuff like joining your own local IMO team selection smth
you can even join despite being a beginner so you could get the feels
is there any specific prerequisites that you think would be helpful like most common topics
just be familliar with the maths up to and including the year level of the competition
and some introductory discrete mathematics
be a level advanced, if you are grade7, learn till quadratics, g8 learn till trigonometry
bruh WHY ARE SO MANY PEOPLE INTERESTED IN THIS ONE CONTEST
one of the big contest organizers in my country hosts it sooo
yup
oh interesting
because grade 7 and 8 are all linear so you better advanced with quadratics at the start
- it has its own wiki page too
Engaging
Exciting
Ohhhhhh

if I remove the p, will you be irate?
lol
no if u remove the pi he’s rate
they will eat yummy foods in the future
I've tried a proof involving geometry right now: despite my proof being a bit more complicated than the official answer, I managed to get it completely correct
one step closer
I feel like I could get a medal at the national next year
I'm improving day by day
by the way I stumbled upon a combiantorics problem, and I can't really get out of it
Count all the $8$ letter words with the following properties: \
a) the word only contains the letters $A, B, C, D;$\
b) the letters $A, B, C, D$ must be used at least once;\
c) there are never two identical letters next to each other\
Rubix
my first idea was to count how many ways there are to put the $4$ forced letters $A, B, C, D$ in $8$ slots: $$\frac{8!}{4!}$$
Rubix
I can't get past this
ngl I'd just do PIE
four letters - three letters + two letters
does this include the third point?
no identical letters next to each other
third point is the entire reason why I chose a pie approach (since you can just pick the first letter and run w/ it for each of the three terms)

could you give me some more steps to solve that?
I can't figure out the solution
ok no let me try this one thing
no that's not it
Show your work, and if possible, explain where you are stuck.
ok
that's not really calculations, just logic
as I said before, since there are $4$ mandatory letters to insert, I've found in how many ways I can put them in a 8 letter word, and that'll be $$\frac{8!}{4!}$$
After that, I have $4$ empty spaces, that I have to fill accordingly, but by using PIE I'm not really considering everything. There could be a case with $5$ identical letters next to each other, for example: $$A B C D D D D D$$
Rubix
that step is not really clear
this
oh I kinda meant to just abandon this
ex. If there's 4 letters, then pick the first letter and consider how many ways there are to assign each of the following letters
Rubix
the first letter can be chosen in 4 ways, the others in 3 ways
but not idk if there are all the letters I need, this could even be ABABABAB
hence why I did this
didn't you just write it
4*3^7?
yeah
Rubix
or...
you're assuming that you need to shove the other two letters in at the end
hence why I just did pie from the start
ok wait
the result turns out correct
:)
I'm still not sure why though
I'll have to think about it a lot
because
eh 4 * 3 * 2 * 1 * 3^4 -> order the first four letters and let the last 4 be whatever
but order would matter in a word
🤔
ye
$4 \cdot 3^7-4 \cdot 3 \cdot 2^7 + 6 \cdot 2 \cdot 1^7 = 7224$
which is indeed correct
Rubix
as in 1944 is marked to be correct?
no?
this is what I did
alright
thanks for the help man
there's a lot to learn about the inclusion-exclusion principle
How former
is that good?
Yea i think thats pretty good
U can easily qual aime with that fs but for usajmo/usamo ud need like a 10 to guarantee it unless its 2023s
you mean another 10 marks?
no worries 😄
thanks a lot
Nono like on the aime
Acc if it hits dhr then u need like an 8
Np
is the info in the aops intro to geometry, intro to algebra, and intro to number theory enough to make aime?
So aime is 10/?
for the first 20 questions definetly
for the last 5 idk
oh out of 15
yes
all of them?
uh probs close but last 5 could be all over the place
how hard is that?
to qual u js need 100 so yea
first 10 rnt too bad then last 5 can be bad some years like 8-15 r pretty difficult but some years 1-10 r rly easy
for pushing your abilities it helps to grind final fives
when test time gets close tho it’s strongly recommended to do full tests under test conditions
oh
When I have like 30%-40% probability of getting a question right do I leave it blank or write my answer?
cuz the competition's i've been in give no marks for unanswered questions (except gauss, which can't say much as the questions are all answerable)
if guessing isn’t punished its better to just put something down
doesn’t apply to competitions like the AMC 10/12 tho
Rubix
no idea, but at least it's readable now :)
Help i can't figure this out

Hey guys, can you kindly help me out here, i accidentally passed my first comp and idk what to do for next round, this is a practice question from their previous previous year but i have no clue on how to solve it, thank you so much :)
they seem to have a really elegant method but I don't know how to do it
anyways you can just use the cosine rule, so $\cos z = \frac{116 + 370 - 74}{2 \sqrt{116} \sqrt{370}}$
southy
I dont think calculator is allowed thats why im asking here
😢
but it's doable by hand actually
just don't simplify the sqrt(116) sqrt(370)
the answer is 11 somehow
basically in the sin z = sqrt(1 - cos^2 z) part of the calculation
you need to do 116 * 370 - 206^2
ugly but it evaluates to 484 = 22^2
so $\sin z = \frac{22}{\sqrt{116} \sqrt{370}}$ and hence the formula $\frac{1}{2} ab \sin C$ gives $\frac{1}{2} \frac{22}{\sqrt{116} \sqrt{370}} \sqrt{116} \sqrt{370}$
southy
there's always more than one method in maths
It is 11 from the answer sheet i js dk the way :'D
Hmm i understand 1/2 ab sinC but thats all i understabd
ok that's something at least
okay then (116 + 370 - 74)/2 = 206 right
we're simplifying cos z a bit
Yeaa
and then $\sin z = \sqrt{1 - \left( \frac{206}{\sqrt{116} \sqrt{370}} \right)^2 }$
southy
= $\sqrt{\frac{116 \cdot 370}{116 \cdot 370} - \frac{206^2}{116 \cdot 370}}$
southy
so that's how we need to do 116 * 370 - 206^2
all we are saying is that $\cos z = \frac{206}{\sqrt{116} \sqrt{370}}$
southy
we just divided the 2 into the numerator
that's the same as this
oh RIGHT yeah it is the cosine rule
yeah ok that makes sense that you were stuck there
so the side lengths are already squared
so to find XY instead of XY^2 we need to square root
yes
I see
Hello. Has anyone done any of the problems from the mathematical reflection journal? Here is the link of the problems: https://www.awesomemath.org/wp-pdf-files/math-reflections/mr-2024-03/mr_3_2024_problems_2.pdf. I would really appreciate if one of you guys have solved or could solve one of the problems for me.

WOAH SIMOC
I gave up
if you want a more psychotic solution, you could express each side as a, b, and c, and you could apply herons formula for that, you would have to multiply 4 trinomials but it would end in a satisfying way such that all terms are squared, then you could use the given options
Im trying to understand southy's explanation but im still confused as where 22² come from
I tried herons because my friend requested it and it turns to
I dont think i did it right
Sorry its messy 😭😭
it would be easier to express it as a b and c
it should end like this and just substitute
I accidnetally passed amo with just bronze and now my mom put me in so idk whattodo now😢
you would want to get the last part, the one with the a^4 etc
it should be viable but yeh, using trig is probably much better
Ahhh
I think so too
Im trying to digest this information
what category?
it's a question 25 anyway, it's fine, I'm pretty sure simoc is like 2 hours from what I know
nvm its 90 but expanding that 4 trinomials is kinda easy cause of the lack of coefficients and also, a lot of things will cancel out
IDK 😭😭the math one..???
I mean as a secondary 1, 2 , 3 , 4, SS?
Sec 4
oh wow, i'm younger than you by 1 secondary
😭that was my first comp idk what to do
are you singaporean?
No im not😢😢
damn you're going onsite
I considered Heron's at first but I realised that would be insane
like you have to find s
then subtract everything and ehhhh
you'd have to know the 3rd form here ye
I don't think that's realistic to memorise
Yea i did it substituting as x but then i remember i need to put x back in 💀
OH YEAH THIS
it's a one way shortcut tbh, with easy derivation
kinda like sophie germain
just familiarize yourself with a lots of concepts, I like AMO and SASMO because its kinda similar to AMC 10 and 12
OH I JUST ASKED MY.. UHH JUNIOR FRIND
He found a way
Without cosine and allat
With just.. drawing triangles
We tried that before but we draw the triangle wrong and he found a way for the correct triangel using the hints
Holy
let me see
Waiy ill redraw his triangle
okok
this one?
,rotate
,calc 1/2 (17 * 9 - 10 * 4 - 7 * 5) - 4 * 7
Result:
11
I think they were just willing to try
I was lazy to try it on pen and paper
typing is easier for me
😭😭
hold on, i don't see it what
I drew triangles too but wromg ones
Actually ive thought of that but never thought the triangle will be lookin like that
Also very not to scale sorry for bad drawung💀💀
i'm so clearly lost 
dude just saved me from stress wth
It was that easy?? Omg

Right!! I never thought of that, i thought of shapes before but i was only thinking how to make a rectangle work
geometry is my so so weakness
Never thought it was actually a bigger triangle
you now have 3 possible methods for this, shows how most maths are interconnected
:D math is so interesting but so frustrating sometimes abhahaha i have love hate relatiobship with math
for reall
But once you actually solved just that 1 question you feel like everything is
So cool and stuff
This is the most ridiculous question ive encountered

yeaa but i love how every thing is connected in it and how everything is so significant
I dont think this is even maths

yah especially geometry is so frustrating where most questions can't be solved with just drawing triangles(you have to learn about this obscure theorem to solve it)
😭😢
What was the question makers thinkin abt when creating this question.. pity points for those who cant math?
(me)
it must have to do someting with SnS right?
I had a math contest question during G7 which can be solved using stewarts theorem and I only learned it during G8
or is it higher maths?
Whats sns
Sequence and series
No its so funny i found it in a sec thats why i called it ridiculous
Its simpler than that
You dont even need to think abt maths
then tell us the logic🤔
Think like a kindergartener and u probably find it 
Look at dem holes in the numbers

man what
Thats dumb
Exactly!!
is that simoc?
I think so idk 
ewww😂
i didn'teven thought that far lol
this is terrible
if you solve this riddle, you are smarter than 99.99% type question
I thought of that first time (i have the brain of a 6 yo)
😭😭😭
Ikr

I was thinking modulo but that 0 to 1 doesnt make sense
BAHAHHA 😭😭😭 THOSE NONSENSE QUESTIONS ARE LIKE SOMETIMES SNEAKED IN IDK WHY
umm i have a problem? with determinants using factor theorem
Thinking too far
I thought it was some weird series for the left col
I was thinking( how many ways can you write the number a product of primes) - 1, treating 0 as an exception
No its just batshit nonsense 💀💀
You could map a polynomial on the left
what is the logic behind second point?
Yall r too smart for this wtf 😭😭 i did it first try because im dumbfounded with the other questions hellkkpfnm
Thatd actually make so much sense
#precalculus , or maybe #linear-algebra
me as well
not really 💀
okay
Way better than looking at holes.
i do agree!
BAHAHAHAHAH I AGREE
Who put that question in that
i wanna talk to the creator of that question
my sasmo book had some of that nonsense
LOL
Report them to the proper authorities if you find them
"logical reasoning"
Id not expect that shit to pop in a math quiz thats for sure
😂😂😂but no logic
Reall
gl with that simoc stuff
I think they just put that on the kindergarten stuff instead of the higher level category, if they did have logic questions, it's probably more reasonable than the amount of holes in a number
i think they should too
cooking up an absolutely computationally evil geo problem
😁
unfortunately I can’t share it here bc I plan to put it on a math contest this fall
consider studying trigo solutions because most of the time, there might be a trigonometric solution
Alright! Also where could i find math resources to study from?? :)
I use youtube and some aops, in simoc there's also a syllabus for that
Whats aops??
Ohhh apps?
nooo
art of problem solving
theres a lot of amc aime type questions there with solutions\
then a lot of concepts too
their books are pretty good
even if the problems tend to be a bit dated difficulty wise
large forum and even had a lot of solutions too for imo problems and other countries selection test
yah, I recommend buying Vol 1 and Vol 2 if you did consider joining a lot, but there are a lot of resources too especially for a contest like simoc since it doesnt use much higher forms of math
Ahhh is that a book?
npnp
I applied to intern with them this summer but someone else had already taken the spot 😭😭
next year I guess
damn lucky, you must have been an experienced olympian
I was never that good 💀💀
only ever made AIME once, barely
but I have a good deal of experience writing problems
Okk lemme searcgh
How do u get experience help all i joined is noob competitions and i still cant do them because skill issue
I basically join random she that my school offers, thank god some dont have them... selections thingys😭😭
Im not that smart to begin with either
Tysmm
well start a lot of noob competitions, that's how I started too when I was G7, now I qualify for an area stage for imo selection in my country(I'm still bad tbh,will try again this year)
Wow thats so good thoo
Im so far away from that
How do you practice??
a lot of practice from other materials + having a clique in your school would help a lot too, I asked a lot during my G7 to my other smarter seniors and that gave a lot of insights as well
solve easy ones
then solve harder ones, if you can't understand the concept, you can search for the concepts behind it and use that too
sometimes I use the alcumus of aops to solve specific topics
most questions from that came from existing AMC 12 and other existing contest, which is fun
nawh its free, just make an aops account
you can even do cauchy schwarz here which is kinda funny
hint (spoilered!):
||a + 4b + 9c = 16
4a + 9b + 16c = 25
9a + 16b + 25c = 36
a = 1, b = -3, c = 3||
Tyy! I do agree having friends to help r rly useful and im grateful that i do :)
oh basically that's the same technique
so then we want $a(x_1) + b(4x_1) + c(9x_1) = 16x_1$
and so on
southy
also we do have to show that $n^2 - 3(n + 1)^2 + 3(n + 2)^2 = (n + 3)^2$ to make sure the pattern holds
southy
lol south i just joined this and you're here 😭
lol
yeah and you only need 3 equations cause that's enough to figure out if there is one solution or not
there shouldn't be infinitely many solutions given the setup of the problem
Theres a much more fun solution there tbh
Well not really fun but satisfying
Found it by dumb luck
oh is it on AOPS
wait but I don't have the year or the source
Idk
people how the hell do you practice for amc10 😭
i did 1 practice test and im pretty happy with how it turned out (91.5) but idk where to start.. the difficulty seems to go up enormously at the end
you're in the right place my man
i thought i wouldn't be able to do it because of school but nevermind i found out that time zones are not shooting me in the head for once
But you can set the 16x1 + 25x2 as equation 4 as S
X1 + 4x2 .. = 1 as equation 1
4x1 + 9x2 .. = 12 as equation 2
9x1 + 16x2.. = 123 as equation 3
Then subtract 1 from 2, 2 from 3 and 3 from 4
To get eq 5 as 3x1 + 5x2 ...= 11
Then eq 6 as 5x1 + 7x2... = 111
Then eq 7 as 7x1 + 9x2 ... = S - 123
Then just subtract eq 5 from 6 and eq 6 from 7
To get 2x1 + 2x2 + 2x3 etc in both eq 8 and 9 which has 100 and S - 234 each, you can find S as 100 = S - 234 then S = 334
oh wow that's an amazing method
yeah so I convinced myself with $5x_1 - 3x_1 = 2x_1$ and $7x_1 - 5x_1 = 2x_1$
southy
so yeah second difference constant implies that
same as what Vanellope did haha
,calc 3(123-12)+1
Result:
334
I'm on my smartphone and I don't know how to use LaTex sorry
$$a^2+b^2=c^2$$
πrate of the Cartesian
I realize since the second difference is constant. One could just take advantage of the difference of the sums [1,12,123,S] and branch them out, one could get the first differences [1,111,S-123] instead, then second differences [100,S-234] then get S as 334.
1 minute solution
Ultrasimplified version
ppl how the hell do you revise for amc10??
i did 1 practice test and im pretty happy with how it turned out (91.5) but idk where to start.. the difficulty seems to go up enormously at the end
for problems you didn’t get correct, read over the solutions
final fives being hard is deliberate by design
on my practice I didn’t even attempt the last 6

but there’s all kinds of stuff that it seems I just have to.. know
like the modular arithmetic
focus on maximizing your score on earlier questions first
91.5 is not a safe score for AIME qual
the late questions will tend to throw a lot of more obscure techniques at you
definitely not lmao 😭
if you can get, say, the first 15 locked down
Do you know why the average score has gone up lately?
then you’ll be in a very good position
I checked and it went from like 5x to 6x
test difficulty? fewer people taking it?
I haven’t looked at the last few years’ tests lmao
On my practice I got 12/15 of those right, skipped 2, got 1 wrong cuz im silly 😭
do you know what’s a good score to aim for that’s actually realistic
and also how do I practice this kind of stuff again
out of interest do you know if universities care about this kind of thing
the big names don’t particularly care about AIME
but outside that bubble it could give you an edge in admissions
ah
well
i wasn’t thinking too deep into amc
but now i realize that i am quite literally like 2 or 3 problems off aime so I want to try
yea
this year I've decided to focus on math olympiads just to prove to myself that I can do it
in Italy no university cares, except maybe Scuola Normale Superiore (SNS) in Pisa (probably the best university for math in the world)
all throughout high school I've never felt challenged by standard math questions, that's why I'm pushing higher
good point :)
really!
i was focusing more on harder exams instead of Olympiads
(which are.. much easier to prepare for lol)
the number theory and geometry especially on amc is giving me a headache
well if you don't compete at IMO level you can pretty much forget entering that uni
number theory is quite hard
there are a lot of disconnected things to remember
oops
here's one I've learnt some days ago
it’s very basic number theory and it’s still confusing me
a perfect square $s$ is either $\equiv 1 \pmod{3}$ or $\equiv 1 \pmod{4}$
Rubix
Hmm
this is so random to me, but extremely useful
oh wait that’s actually
interesting
the proof is probably 2 years long or something
144 is neither.
.. true
but I've read that somewhere
or probably I remember it wrong
probably it was either 0 or 1 mod 3 and mod 4
Yeah, that would be correct.
i did a bit of digging
it seems to be fundamental in competitions
lmao
pigeonhole principle
pigeonhole principle might be the MVP of contest math problems ngl
It's slightly more dignified to call it the "Frobenius coin problem".
Yeah
I've never read a solution stating "by the pigeonhole principle"
aops themselves called it
chicken mcnugget theorem
but probably I've read some saying "since we have more elements than there are spaces" or things like that
php has been overshadowed by global
😭😭
i say it sometimes just to convey the idea of whats being done but its the principle behind it
i mean the statement of it seems glaringly obvious
but
its a really powerful way of thinking
yea I realised
Well, the goal for contest preparation is not to be dignified, but to be memorable.
In mathematics, the coin problem (also referred to as the Frobenius coin problem or Frobenius problem, after the mathematician Ferdinand Frobenius) is a mathematical problem that asks for the largest monetary amount that cannot be obtained using only coins of specified denominations. For example, the largest amount that cannot be obtained using ...
LOL
McNugget numbers
That and also if he wants to look into it further + related stuff he'll probably be better off calling it coin problem instead
when looking it up
this year we had a team competition, and our "jolly" problem literally was:
How many non-empty subsets of ${1,2,\ldots,13}$ there are, so that the product of their elements ends with $0$ ?
this is inclusion exclusion basically
(ps. we couldn't solve it, although it's not really hard)
Rubix
this morning I was lost, but I've tried a few exercises and I'm getting it
still not competition level, they're just generic PIE exercises
imnot looking yet cause im gonna take a stab at it soon myself
||yeah that was my thought, like total is the size of the powerset and then subtract out the ones that don't at least one of both 2 and 5 in the factorization||
i just can't write out atm
||i think that might be missing a -1 because it specifies non-empty subsets||
||but then it gets un-accounted for in 2^6||
Vanellope von Schmugz
hint: symmetry
Does anyone know how to do 90^2+56^2 really fast without calculator?
ok np
because in the solution I'm reading they went from 90^2+56^2=106^2 and in the test you cannot use a calculator
oh
how would u know that
what if I only knew a and b?
that will be tough without a calculator lol
oky
I'm willing to bet this is 2023 AIME I Problem 5
This is just 28 45 53 so you could take advantage of that
anyone got resources to practice/learn on for someone who’s new to this level of math?
yeah
Art of problem solving. The whole website is great
thanks! does it have solutions and all the theory stuff too?
Yes(well if you searched the topic itself, I think) but the theory stuff does show up, and most of their problems had lots of solution from AMC to AIME to USAMO and Even IMO
ok, thanks so much
it is
it somehow cancels out
the actual solution is 2^13-1-(2^11-1+2^6), and, guess what, they cancel out
Yeah
(a.b)= -c.a
Nawh obviously
My math teacher sent me stuff who is part of the wide connection of the deputy team leader of my country who is with the contestant
For 1, obviously a case is all even integers but idk how to prove the others
I'll probably just get max 3 points by claiming that it's probably even integers(but hey atleast its a point)
I saw this on aops, I don't really get how case 2 and 3 works
it's all even though(great)
i'm so cooked, till now I only have even integers case
was it 54?
i hate these problems about constant rate stuff
I agree
where did 33 come from 
how is that a hint?!
ohhhhhh
my bad
I guess you could express this algebraically
from what I see on the internet, the 54 notion had a LOT of assumptions
Vanellope von Schmugz
BTW the time she leave the school on normal day is 4PM?
1 hour head start = 12 mins early?
yuh
Also the velocity of the girl walking during the school-station and station-home isn't the same?[
SRY to make this more complicated 🤣
exactly, too much reliance on whatever
what is 33 doing here anyway LMAO
another question from me. Normally, when the girl reaches the station, does she meet her mother and get on the car immediately?
Or should I assume this one in my calculation for first of all?
that's actually the supposed assumption to get 54
Ok ty
This is my simulation on Scratch. I created 2 sprites which represents the girl on normal day(cat) and on special day(woman). I set the time ratio by 1:600 as the picture below. The total distance is 480 units from school to house. Velocity on foot and by car are also mentioned.
The second picture describes that on special day she got picked up on the way between the station and house at x=60 which is a quarter distance to home.
Scratch scratch
But I made some mistakes there.
- As you can see the time for the cat should have started after he began to move.
- Both of the timer should have stop when they began to move faster(on car).
Yeah that’s what I thought 😂😂
It’s impossible to solve this problem without knowing the velocity.
Smash, next pls🤣
whats a good way to study for amc 10s?
ive been doing practice tests but cant seem to get my score up
OKAY P5 IS ACTUALLY REALLY EASY OMG
THE ANSWER IS THREE
The trick is to determine to location of the monster in the second row
if the monster is not on the edge, one should start at either adjacent of the monster, and go down and go to the direction behind the monster, worst case scenario, you die on your second attempt(bad luck) then you could just respawn easily on the other adjacent
if its on the edge, create a staircase like path starting adjacent on the monster then go left(or right) instead of down first(because its a 2024 by 2023 not a square), the go down left/right, down, left/right, till you either finish it or not, if you didnt, there are two cases, if the monster is encountered when you go left or right, then just go in the opposite direction till you got to the edge where monster 1 is encountered, if the monster is encountered when you go down, one shold take a step back in a row and not go left/right and just go double down and go in the opposite direction till you got to the edge
OMG P5 SOLVED in 20 MINS
why is it so easy
they screwed up(I think)
if a hobo like me who struggles at some low level competitions yet can solve a P5 in IMO then we are done
anyone got study tips for the amc 10/12?
so far ive been doing practice tests and tutoring sessions but they dont really seem to stick
i have heard that keeping a small notebook with formulas is a good idea, so I started to do that
but i was wondering what else I could do to boost my scores
