#competition-math

1 messages · Page 1 of 1 (latest)

vestal silo
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wait lemme think

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wait it’s not true that BD is a diameter

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well

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u can’t assume

limpid shore
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The key is that ABCD is a cyclic quadrilateral

vestal silo
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yeah but it could be a trapezoid

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which is cyclic

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iso**

limpid shore
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The angles restrict that Yes you're right but it's not important

limpid shore
vestal silo
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lemme think

near hill
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It doesn't look like we have enough information. The central angle theorem tells us the relative positions of A, B, and C, but D could be anywhere on the arc between A and B without changing any of the angles.

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Wait, no, I was reading the angles wrong. 🤦

placid tapir
barren iron
hidden sigil
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is there any short way to solve it?

jolly solstice
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I see a decent way of doing it by expanding the binomials and working through it that way, but may be better ways. I'll post my soln in a bit busy atm

pallid dragon
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you get 10 from 3322 or 22222, there's no third way
there are 8!/2!/2!/4! ways to shuffle 33220000
there are 8!/5!/3! ways to shuffle 22222000
each of them makes 1x^10

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so 476

hidden sigil
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0000?

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the power

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i see

hidden sigil
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let me apply it over another question

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supoose we have
(1+x+x^2+x^3)

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power is 2and we need to find x^4 coffi

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i guess i am wrong somewehere

pallid dragon
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the power is 5, so there's 5 numbers

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or 2 if the power is 2

hidden sigil
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sorry power is 2

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wow

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it is very very nice trick

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it will be 3

hidden sigil
pallid dragon
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but that's one way as far as i understand, you can't say it's a trick

hidden sigil
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one way?

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i see

pallid dragon
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the only way i meant

hidden sigil
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can we apply it here

pallid dragon
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i don't know sorry

hidden sigil
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it is okay thanks

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i will try

jolly solstice
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you could expand out the (1-2x)^18 and just look at the first 4 terms as a polynomial, then you're only really looking at a few things multiplied together

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$(1+ax+bx^2)(1+(-2)^1\binom{18}{1}x+(-2)^2\binom{18}{2}x^2+(-2)^3\binom{18}{3}x^3+(-2)^4\binom{18}{4}x^4)$

gilded haloBOT
jolly solstice
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x^4 term will just come from 3 terms multiplied, similarly for x^3 term

hidden sigil
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tq very much

idle fjord
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My sister (Rising 7th grader) is looking to get into comp math. Last year she scored a 12 on the AMC8. She can do basic algebra but nothing more, I gave her my old AOPS Vol 1: The Basics book but it was too hard for her.
Can someone send a list of AOPS books to do in order for her?

acoustic nova
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AoPS pre algebra

wanton bolt
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am I correctly interpreting this?

limpid shore
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Yes the second equation is what you want to conclude

wanton bolt
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got it, thx

radiant jasper
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IF ANYONE CAN PLEASE HELP ME APPLE FOR AMC AUSTRALIAN I WOULD HIGHLY APPRECIATE IT 😭 😭 😭 😭 😭 😭 😭

ornate blade
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if your school doesn't offer the competition you can't join

radiant jasper
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wait guys

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@ornate blade

ornate blade
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yeah

radiant jasper
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my school did a math competition earlier this year

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and they alr gave at awards

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but on the website

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it says its in AUGUST

ornate blade
# radiant jasper it says its in AUGUST

Australian Mathematics Competition Date Tuesday 6 to Thursday 8 August 2024 Time Primary divisions: 60 minutesSecondary divisions: 75 minutes Cost AUD$8.50 per student First run in 1978, the Australian Mathematics Competition is Australia’s longest running, largest and most well-known maths competition for school students. Like all our competiti...

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then what your school did wasn't the Australian one

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maybe the American one, which is also called AMC

radiant jasper
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OH

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how can I tell if my skl does it

ornate blade
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usually there's one maths teacher that runs all the maths competitions

radiant jasper
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okay

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this is what my school did @ornate blade

radiant jasper
ornate blade
radiant jasper
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ok if they are not

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can I ask them to do it?

ornate blade
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actually our school did a lot of competitions, the American one, Canadian, UKMT, and the Kangaroo one as well

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but I had to take the Australian one outside of school

ornate blade
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unfortunately the deadline to enrol in the paper-based test has already passed

radiant jasper
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how do u do it outside of shcool

ornate blade
ornate blade
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but then they would only let you do it online if they were your school

radiant jasper
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dangit

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😦

ornate blade
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unfortunately

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it's a nice competition, a lot like UKMT actually

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nothing impossible

radiant jasper
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are there any other comps this year

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for aussies

solar atlas
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whats 10+10 ?

radiant jasper
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idk

ornate blade
radiant jasper
ornate blade
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like it really depends on what your school offers

radiant jasper
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there is a thing

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called ME

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math enrichment

ornate blade
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oh interesting

radiant jasper
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if my school doesnt do it, can I request ?

ornate blade
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yeah join that one, at least you can practice and socialise with other people with similar interests to you

ornate blade
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many Australian schools have some kind of enrichment due to gifted and high-achieving students

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and maths is just such a common subject

radiant jasper
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wait is the math enrichment like a test

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or is it a course

ornate blade
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no it's like an after-school club

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or during lunchtime or something

radiant jasper
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oh

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there is another called

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AIMO

ornate blade
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oh AMT organises something of their own, interesting: https://www.amt.edu.au/enrichment

Maths Enrichment Date April – October 2024 Time  12–16 weeks Cost AUD$53 per student Maths Enrichment is an extension program for talented students to widen their mathematical knowledge and skills. Teachers receive comprehensive printed support material to extend both student learning and their own mathematical teaching practice. Enrichment mate...

ornate blade
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AIMO is actually from Hong Kong

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oh wait there are 2 with the same name lmao

radiant jasper
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bro all of this stuff is confusing

ornate blade
radiant jasper
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so basically

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should I Email my learning leader

ornate blade
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ah so this is another Australian one I haven't heard of

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but yeah it's like AIME just Australian it seems

radiant jasper
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if they can do these math stuff

ornate blade
radiant jasper
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wait what year level is u in

ornate blade
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doing a maths degree

radiant jasper
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noice

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NICE

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im in year 8

ornate blade
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oh nice

radiant jasper
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I wish to do AIMO year 8

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what are the topics?

ornate blade
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yeah I'm at UofAdelaide if you wanted to know

ornate blade
radiant jasper
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I mean it says this

ornate blade
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May include:

Parallels
Similarity
Pythagoras’ theorem
Diophantine equations
Counting techniques
Expansion and factorisation
Inequalities
Sequences and series
Number bases
Methods of proof
Congruences
Circles and tangents
Probability
radiant jasper
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but is it really like that?

ornate blade
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there are sample papers

radiant jasper
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cus like the first 3, inequalities, circle theorems, probability n stuff

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bruhh my learning leader is doing smth at diff country

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so she sent me an auto mailed

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ig ill email when she bacj

ornate blade
radiant jasper
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oh hell nah

ornate blade
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it is school holidays in a big part of Australia also

radiant jasper
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2017 is freaking impossible

ornate blade
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so yeah just be patient

radiant jasper
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bro is that like logarithms

ornate blade
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oh no question 2 is about different number bases

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so $2(b + 1)^2 + 3(b + 1) + 4$, that's what $234_{b + 1}$ means

gilded haloBOT
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southy

ornate blade
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like you know how 234 in base 10 is shorthand for 2 * 100 + 3 * 10 + 4

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same principle

radiant jasper
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brother what are u spouting

ornate blade
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but that's okay!

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everyone has to start somewhere

radiant jasper
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I mean I could just do all of them next year ig

ornate blade
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yeah you have time yk

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also not everyone who has the ability even needs to do Olympiad mathematics

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that's just one very specific type of maths

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I didn't enjoy competition maths all that much, well the initial rounds were fun but I didn't have interest in anything above that

radiant jasper
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do you have any tips when test taking?

ornate blade
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don't get hung up on the last few hardest questions, if you can't do them that's very natural

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also don't leave a question blank

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time is a weird thing when doing competitions; it always seems like you never have enough

radiant jasper
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Fr

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Do you know how I could get some mathematics awards from anywhere

ornate blade
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but check out GERRIC from UNSW, I did a winter mathematics enrichment course there in Year 7

radiant jasper
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I live Melbourne

ornate blade
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keep looking for opportunities I guess, I'm not exactly sure how much there is cause I didn't do high school in Aus

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but given mathematics is so popular there's a huge demand for this kind of stuff

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don't beat yourself up if you can't convince your parents to travel with you to Sydney

ornate blade
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<@&268886789983436800>

hidden sigil
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I learnt a method yesterday fir such questions

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But why the method is not working

pallid dragon
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in the previous exercise each way produced 1x^10, you need to pay attention to this

hidden sigil
pallid dragon
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221000
211100
111110

221000: 9 × −1 × 8 = −72
times 60, −4320
211100: 3 × −1 × 4 = −12
times 60, −720
111110: −1 × 2 = −2
times 6, −12

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i get d

hidden sigil
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I did not understand 9×-1×8?

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And 60 times

pallid dragon
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60 is 6!/2!/3!

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3×3 gives 9, we multiply 3x² by 3x² so there's a 9

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000 is 2×2×2 is 8

hidden sigil
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Ohh ohhh

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I missed coffiecients

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Tq

hidden sigil
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Is this cauchy schwarz?

limpid shore
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||rearrangement inequality|| I believe

acoustic nova
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yeah

gilded haloBOT
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shihgua
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

golden comet
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For nonnegative real numbers $a , b , c$ . How to show: $\frac{a + b + c}{3} - \sqrt[3]{abc} \leq \max {(\sqrt{a} - \sqrt{b})^2, (\sqrt{b} - \sqrt{c})^2, (\sqrt{c} - \sqrt{a})^2 $

gilded haloBOT
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shihgua

velvet aurora
hidden sigil
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Yes

gusty verge
# gilded halo **shihgua**

Perhaps do a WLOG proof, ie. Assume [(\sqrt{a}-\sqrt{b})^2\ge(\sqrt{b}-\sqrt{c})^2\ge(\sqrt{c}-\sqrt{a})^2]
As generally the maximum function is quite tricky to work with

gilded haloBOT
velvet aurora
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I also suggest substituting [x^3=a, y^3=b, and z^3=c] to use the identity involving [x^3+y^3+z^3-3xyz]. I haven tried it, but it may help.

quiet token
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I hate maths

leaden herald
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very deep thought

ornate blade
leaden herald
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$\sum_{i=0}^{5} 3\cdot 10^i$

gilded haloBOT
placid tapir
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Interesting

leaden herald
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if somebody wants to know, I want to qualify for the national olympiad in my country

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selection test is in March 2025, I hope I can get good enough by then

limpid shore
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Gl

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If your country isn't too hard you probably can

leaden herald
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proofs are a relatively new concept to me though, I have to grasp them

leaden herald
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it’s not too hard I think

limpid shore
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yeah doesn't sound unreasonable

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there are a few italians in the olympiads server, you could ask them for guidance

leaden herald
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I probably know some of them, if they’re gold medalists

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know by name I mean

limpid shore
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Idk if they're gold medalists

limpid shore
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team competitions are really cool, i wish there were more

ornate blade
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I mean why some countries do better on IMO than others is probably cause the other countries just don't care about competitions

ornate blade
leaden herald
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which my school has participated in the last 7 years or so

ornate blade
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also like many poor countries don't have the resources even if they tried

leaden herald
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in the semi finals

ornate blade
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but yeah not relevant to Italy

leaden herald
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all the good indian students study for jee

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not olympiads

ornate blade
leaden herald
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plus nobody likes geometry

limpid shore
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🧐

leaden herald
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I’m one of those who doesn’t study geometry for the olympiads, but if I want to get at least a bronze in the national, I have to

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when I read the solutions I think some things are built out of nowhere

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“draw the height of this small triangle AQK”, I would’ve never thought about that

limpid shore
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yeah geometry is largely about good intuition for how things "should be"

leaden herald
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I have some time

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8 months

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someone I know managed to get the bronze, starting pretty much from my same situation

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so it’s not impossible

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by the way, I’ll ask in the olympiad server, even though there’s not much to do, other than do many exercises

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and understand the official solutions, if I can’t solve a problem

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or if I can’t prove smth

limpid shore
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Too many people get invested in learning theorems, tricks, etc.. when the key is just experience and doing a lot of problems

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Nothing can replace that

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And it's the most important ingredient

leaden herald
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some things might help obviously

leaden herald
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like Vieta’s formulas and perfect squares mod 3 and mod 4

limpid shore
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You wanna constantly be reflecting on the way you think to think to find out why you couldn't finish the problem

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Learning from failure is extremely helpful

leaden herald
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absolutely

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for example I noticed that many times I forget restrictions, which can help me save a lot of time, by not trying all the cases

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knowing the solution is an even prime tells you that it must be 2

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but if you don’t put restrictions it’s way harder to notice

willow anvil
barren iron
radiant jasper
leaden herald
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😂

pallid dragon
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the leftmost one

willow anvil
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G>>>>>N>A>C

crisp forum
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Has anyone ever felt guilty doing contest math problems? I enjoy them a lot more than traditional book problems but sometimes feel I should just be using the time doing contest problems to go further in higher levels of math.

brave ocean
fickle token
# crisp forum Has anyone ever felt guilty doing contest math problems? I enjoy them a lot more...

I feel the same, it’s difficult because i feel like having good results from math competitions will also look good on college apps, but i’m just so much more interested in progress further in calc or diff equations than learning a bunch of random ways to factor polynomials that aren’t useful anywhere else other than competition-math. i set myself a goal by the end of high school to qualify for the AIME at least once, but it’s difficult to balance learning higher level math and competition math because of my specific interests.

scarlet niche
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I love competition math! I made it to the national competition in MATHCOUNTS once and got like 15th place

frosty nest
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help

novel karma
frosty nest
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fyi ive never tried anything like that

novel karma
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wdym?

frosty nest
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the type ofquestion

novel karma
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put all the a's on one side of the equation

frosty nest
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its for a competiton in august

novel karma
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ok

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do you need help or what

frosty nest
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yes i do

pallid tundra
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clear the fractions

frosty nest
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alot of it

novel karma
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yes

frosty nest
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...

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how exactly

novel karma
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idk if this is comp math honestly lmao

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try asking one of the help channels

frosty nest
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if ur wondering

novel karma
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so

frosty nest
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idk

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its from hakimo'

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by ocec

crisp forum
acoustic nova
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I feel like small branches of competition math like graph theory or game theory are a lot more interesting than like linear algebra. I don’t know linear algebra though so I’m just guessing but there is a lot of very cool competition math stuff (and these subjects are studied in detail outside of the competitions, ofc)

brave ocean
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linear algebra is an extremely deep and rich subject

acoustic nova
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yeah

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I don’t know it doesn’t look as interesting to me but I’ve only seen very tiny pieces of it

brave ocean
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which pieces have you seen?

pallid tundra
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the stuff about vector spaces and linear maps

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is a gateway into abstract algebra, analysis, etc

acoustic nova
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a guy in one of my classes was giving a presentation on like end behavior of markov chains, that was interesting though

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too hard for me to understand at the moment

golden comet
pallid tundra
leaden herald
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😭

leaden herald
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I've had this one week maths course at uni, it's completely different from what you're used to do in high school. An open mind is more important than learning things in advance

jaunty fern
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Im like 20 hours late but i joined this server an hour ago anyways

scarlet rootBOT
near hill
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I don't think that applies with the same force here as it does when the problems are homework.
(@ivory ember)

hidden sigil
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Anyone hints

barren iron
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Left to the reader

brave heron
leaden herald
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def

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it must be a lot of practice and that’s it

barren iron
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Perfect makes practice

willow anvil
sterile helm
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Does anyone here have a really good recommendation on how to prepare for math Olympiads?

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And resources on how to do so?

valid cairn
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depends on the level of the olympiad

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but i really like the soviet olympiad book :]

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theyre also helpfully categorised

willow anvil
sterile helm
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I was wondering how can one learn all what is necessary for Olympiad. Let's say I just started Olympiad and wanted to get to a really high level. How would one do so? What resources are good for that?

valid cairn
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again, it depends what level you want to achieve

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high school Olympiad can be done with little more than simultaneous linear equations, or quadratic equations

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of course you'll also need area/volume formulas but that's just an example

sterile helm
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Alright thanks

barren iron
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No problem

upper knot
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Hey can anyone from australia give some insight on AMC if they have done it?

brave heron
upper knot
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yeah

brave heron
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damn fast reply, I have an old copy of a 2017 senior a while back then, I joined one back then and I'd say it's kinda accurate on what will be part of the curriculum

upper knot
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oh nice

brave heron
upper knot
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thanks

brave heron
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it's a contest that goes progressively harder but it's possible to solve all in an hour, I suggest to focus most of your time on the harder ones first

brave heron
valid cairn
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the questions are a lot easier than they need to be

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additioonally, the timings are staggered and hence some people might have known then questions and potentially answers before going in

brave heron
valid cairn
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their questions are mostly brute-forceable

brave heron
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yah plus most of the questions are multiple choice so it's really easy to cut off answers

upper knot
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okok

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i just thinking whether i should do it or not

brave heron
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if you are a beginner, I think it's a great startup imo

upper knot
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alright

brave heron
#

then just work your way up from harder stuff like joining your own local IMO team selection smth

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you can even join despite being a beginner so you could get the feels

upper knot
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is there any specific prerequisites that you think would be helpful like most common topics

valid cairn
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just be familliar with the maths up to and including the year level of the competition

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and some introductory discrete mathematics

brave heron
upper knot
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year 9? quadratics, logarithms

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i'm assuming

ornate blade
brave heron
brave heron
ornate blade
#

oh interesting

brave heron
# brave heron yup

because grade 7 and 8 are all linear so you better advanced with quadratics at the start

brave heron
placid tapir
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Damn

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That's cool

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Interesting

barren iron
#

Engaging
Exciting

noble scaffold
#

pirate of the cartesian

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omg

placid tapir
#

Ohhhhhh

barren iron
ornate blade
barren iron
ornate blade
acoustic nova
radiant jasper
leaden herald
# brave ocean I like geometry!

I've tried a proof involving geometry right now: despite my proof being a bit more complicated than the official answer, I managed to get it completely correct

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one step closer

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I feel like I could get a medal at the national next year

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I'm improving day by day

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by the way I stumbled upon a combiantorics problem, and I can't really get out of it

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Count all the $8$ letter words with the following properties: \
a) the word only contains the letters $A, B, C, D;$\
b) the letters $A, B, C, D$ must be used at least once;\
c) there are never two identical letters next to each other\

gilded haloBOT
leaden herald
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my first idea was to count how many ways there are to put the $4$ forced letters $A, B, C, D$ in $8$ slots: $$\frac{8!}{4!}$$

gilded haloBOT
leaden herald
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I can't get past this

ivory ember
#

four letters - three letters + two letters

leaden herald
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no identical letters next to each other

ivory ember
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third point is the entire reason why I chose a pie approach (since you can just pick the first letter and run w/ it for each of the three terms)

leaden herald
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o lol

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I'm still not the best

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k lemme try

ivory ember
leaden herald
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I can't figure out the solution

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ok no let me try this one thing

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no that's not it

scarlet rootBOT
#

Show your work, and if possible, explain where you are stuck.

leaden herald
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ok

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that's not really calculations, just logic

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as I said before, since there are $4$ mandatory letters to insert, I've found in how many ways I can put them in a 8 letter word, and that'll be $$\frac{8!}{4!}$$
After that, I have $4$ empty spaces, that I have to fill accordingly, but by using PIE I'm not really considering everything. There could be a case with $5$ identical letters next to each other, for example: $$A B C D D D D D$$

gilded haloBOT
leaden herald
#

that step is not really clear

leaden herald
ivory ember
#

ex. If there's 4 letters, then pick the first letter and consider how many ways there are to assign each of the following letters

leaden herald
#

that goes like

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$$4 \cdot 3 \cdot 3 \cdot 3 \ldots$$

gilded haloBOT
leaden herald
#

the first letter can be chosen in 4 ways, the others in 3 ways

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but not idk if there are all the letters I need, this could even be ABABABAB

ivory ember
leaden herald
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ohh

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the four letter case will then be...

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uh

ivory ember
#

didn't you just write it

leaden herald
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4*3^7?

ivory ember
#

yeah

leaden herald
#

wouldn't it be

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$$4 \cdot 3 \cdot 3 \cdot 3 \cdot 3 \cdot 3 \cdot 2 \cdot 1$$

gilded haloBOT
leaden herald
#

or...

ivory ember
#

you're assuming that you need to shove the other two letters in at the end

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hence why I just did pie from the start

leaden herald
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ok wait

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the result turns out correct

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:)

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I'm still not sure why though

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I'll have to think about it a lot

leaden herald
ivory ember
#

but order would matter in a word

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🤔

leaden herald
#

ye

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$4 \cdot 3^7-4 \cdot 3 \cdot 2^7 + 6 \cdot 2 \cdot 1^7 = 7224$

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which is indeed correct

gilded haloBOT
leaden herald
#

I might need a moment to think about it though

ivory ember
#

,w 4 * 2 * 3^5

gilded haloBOT
ivory ember
#

as in 1944 is marked to be correct?

leaden herald
leaden herald
ivory ember
#

anyway I gtg

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👋

leaden herald
#

alright

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thanks for the help man

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there's a lot to learn about the inclusion-exclusion principle

vale pecan
#

Umm

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Is an average of 120 on the practice AMC 10 tests (former tests) a good score?

sleek slate
#

How former

vale pecan
#

From 2012-2023

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Or 2024

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Can't remember

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AMC 10 a's and b's included

vale pecan
sleek slate
#

Yea i think thats pretty good

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U can easily qual aime with that fs but for usajmo/usamo ud need like a 10 to guarantee it unless its 2023s

sleek slate
#

Acc if it hits dhr then u need like an 8

sleek slate
vagrant mango
#

is the info in the aops intro to geometry, intro to algebra, and intro to number theory enough to make aime?

vale pecan
vale pecan
#

for the last 5 idk

sleek slate
#

oh out of 15

vale pecan
sleek slate
#

uh probs close but last 5 could be all over the place

vale pecan
sleek slate
#

to qual u js need 100 so yea

sleek slate
vale pecan
#

oh

#

yay

pallid tundra
#

for pushing your abilities it helps to grind final fives

#

when test time gets close tho it’s strongly recommended to do full tests under test conditions

vale pecan
#

oh

#

When I have like 30%-40% probability of getting a question right do I leave it blank or write my answer?

#

cuz the competition's i've been in give no marks for unanswered questions (except gauss, which can't say much as the questions are all answerable)

pallid tundra
#

if guessing isn’t punished its better to just put something down

#

doesn’t apply to competitions like the AMC 10/12 tho

hidden sigil
#

hints please

gilded haloBOT
leaden herald
#

no idea, but at least it's readable now :)

vague maple
#

Help i can't figure this out

barren iron
silk gazelle
#

Hey guys, can you kindly help me out here, i accidentally passed my first comp and idk what to do for next round, this is a practice question from their previous previous year but i have no clue on how to solve it, thank you so much :)

ornate blade
#

anyways you can just use the cosine rule, so $\cos z = \frac{116 + 370 - 74}{2 \sqrt{116} \sqrt{370}}$

gilded haloBOT
#

southy

silk gazelle
#

😢

ornate blade
#

I know I'm not sure what they mean

#

by their hint

ornate blade
#

just don't simplify the sqrt(116) sqrt(370)

#

the answer is 11 somehow

#

basically in the sin z = sqrt(1 - cos^2 z) part of the calculation

#

you need to do 116 * 370 - 206^2

#

ugly but it evaluates to 484 = 22^2

#

so $\sin z = \frac{22}{\sqrt{116} \sqrt{370}}$ and hence the formula $\frac{1}{2} ab \sin C$ gives $\frac{1}{2} \frac{22}{\sqrt{116} \sqrt{370}} \sqrt{116} \sqrt{370}$

gilded haloBOT
#

southy

ornate blade
#

there's always more than one method in maths

silk gazelle
silk gazelle
ornate blade
ornate blade
#

we're simplifying cos z a bit

silk gazelle
ornate blade
gilded haloBOT
#

southy

ornate blade
#

= $\sqrt{\frac{116 \cdot 370}{116 \cdot 370} - \frac{206^2}{116 \cdot 370}}$

gilded haloBOT
#

southy

ornate blade
#

so that's how we need to do 116 * 370 - 206^2

silk gazelle
#

I see

#

But why do we need to get 206

#

Im sorry im a bit slow 😭

ornate blade
gilded haloBOT
#

southy

ornate blade
#

we just divided the 2 into the numerator

ornate blade
silk gazelle
#

Hmm

#

Ahh its from cosine rule?

ornate blade
#

yeah ok that makes sense that you were stuck there

#

so the side lengths are already squared

#

so to find XY instead of XY^2 we need to square root

ornate blade
red stream
barren iron
silk gazelle
brave heron
silk gazelle
#

Im trying to understand southy's explanation but im still confused as where 22² come from

silk gazelle
#

I dont think i did it right

#

Sorry its messy 😭😭

brave heron
#

it would be easier to express it as a b and c

#

it should end like this and just substitute

silk gazelle
brave heron
brave heron
# brave heron

you would want to get the last part, the one with the a^4 etc

#

it should be viable but yeh, using trig is probably much better

silk gazelle
silk gazelle
#

Im trying to digest this information

brave heron
brave heron
silk gazelle
brave heron
silk gazelle
brave heron
#

oh wow, i'm younger than you by 1 secondary

silk gazelle
#

😭that was my first comp idk what to do

brave heron
#

are you singaporean?

silk gazelle
#

No im not😢😢

brave heron
#

damn you're going onsite

ornate blade
#

like you have to find s

#

then subtract everything and ehhhh

ornate blade
#

I don't think that's realistic to memorise

silk gazelle
ornate blade
#

but yeah like if it's openbook then absolutely just do this

brave heron
#

it's a one way shortcut tbh, with easy derivation

#

kinda like sophie germain

ornate blade
#

yeah

#

people already did the algebra for you to get it into that form

brave heron
silk gazelle
#

OH I JUST ASKED MY.. UHH JUNIOR FRIND

#

He found a way

#

Without cosine and allat

#

With just.. drawing triangles

#

We tried that before but we draw the triangle wrong and he found a way for the correct triangel using the hints

#

Holy

brave heron
#

let me see

ornate blade
#

oh that's nice!

#

yeah I'm curious now

silk gazelle
ornate blade
#

okok

pallid tundra
#

there’s a proof I’ve seen that just uses Pythagoras a few times

#

for heron

silk gazelle
#

OHHMY

#

THEN FROM THAT ON JTS JUST FINDING AREAS AND SIMPLE MATH

ornate blade
gilded haloBOT
ornate blade
#

SHIT it's that simple

#

I should have drawn it

silk gazelle
#

HOW DOES BRO THINK OF THAT

#

AND HES LIKE UHH GR 8 LAST YEAR

ornate blade
#

,calc 1/2 (17 * 9 - 10 * 4 - 7 * 5) - 4 * 7

gilded haloBOT
#

Result:

11
ornate blade
#

I was lazy to try it on pen and paper

#

typing is easier for me

silk gazelle
#

😭😭

brave heron
#

hold on, i don't see it what

silk gazelle
#

I drew triangles too but wromg ones

#

Actually ive thought of that but never thought the triangle will be lookin like that

silk gazelle
brave heron
#

i'm so clearly lost opencry

silk gazelle
#

It was that easy?? Omg opencry bleakkekw

brave heron
#

ok I get it now

#

okay that's actually genius

silk gazelle
brave heron
#

geometry is my so so weakness

silk gazelle
#

Never thought it was actually a bigger triangle

pallid tundra
#

first step of any geometry problem

#

draw a diagram!

brave heron
#

you now have 3 possible methods for this, shows how most maths are interconnected

silk gazelle
silk gazelle
#

So cool and stuff

#

This is the most ridiculous question ive encountered opencry opencry

radiant jasper
silk gazelle
brave heron
silk gazelle
radiant jasper
brave heron
radiant jasper
#

or is it higher maths?

silk gazelle
radiant jasper
silk gazelle
#

No its so funny i found it in a sec thats why i called it ridiculous

silk gazelle
#

You dont even need to think abt maths

radiant jasper
silk gazelle
#

Think like a kindergartener and u probably find it opencry

silk gazelle
brave heron
#

man what

silk gazelle
brave heron
#

is that simoc?

silk gazelle
silk gazelle
#

Thats why i called it ridiculous

radiant jasper
brave heron
silk gazelle
#

😭😭😭

silk gazelle
brave heron
#

I was thinking modulo but that 0 to 1 doesnt make sense

silk gazelle
radiant jasper
#

umm i have a problem? with determinants using factor theorem

silk gazelle
vestal silo
ocean narwhal
silk gazelle
vestal silo
#

You could map a polynomial on the left

radiant jasper
#

what is the logic behind second point?

silk gazelle
ocean narwhal
radiant jasper
vestal silo
ocean narwhal
vestal silo
#

i do agree!

silk gazelle
#

Who put that question in that opencry i wanna talk to the creator of that question

brave heron
#

my sasmo book had some of that nonsense

silk gazelle
ocean narwhal
ocean narwhal
#

Id not expect that shit to pop in a math quiz thats for sure

silk gazelle
brave heron
#

gl with that simoc stuff

#

I think they just put that on the kindergarten stuff instead of the higher level category, if they did have logic questions, it's probably more reasonable than the amount of holes in a number

silk gazelle
#

Also ty to southy for helping :D

pallid tundra
#

cooking up an absolutely computationally evil geo problem

#

😁

#

unfortunately I can’t share it here bc I plan to put it on a math contest this fall

brave heron
silk gazelle
brave heron
#

I use youtube and some aops, in simoc there's also a syllabus for that

silk gazelle
#

Ohhh apps?

brave heron
#

nooo

#

art of problem solving

#

theres a lot of amc aime type questions there with solutions\

#

then a lot of concepts too

pallid tundra
#

their books are pretty good

#

even if the problems tend to be a bit dated difficulty wise

brave heron
#

large forum and even had a lot of solutions too for imo problems and other countries selection test

brave heron
# pallid tundra their books are pretty good

yah, I recommend buying Vol 1 and Vol 2 if you did consider joining a lot, but there are a lot of resources too especially for a contest like simoc since it doesnt use much higher forms of math

silk gazelle
silk gazelle
#

Ty yall

#

:)

pallid tundra
#

npnp

brave heron
#

it has a website too

pallid tundra
#

I applied to intern with them this summer but someone else had already taken the spot 😭😭

#

next year I guess

brave heron
#

damn lucky, you must have been an experienced olympian

pallid tundra
#

I was never that good 💀💀

#

only ever made AIME once, barely

#

but I have a good deal of experience writing problems

silk gazelle
pallid tundra
silk gazelle
#

I basically join random she that my school offers, thank god some dont have them... selections thingys😭😭

#

Im not that smart to begin with either

silk gazelle
brave heron
silk gazelle
#

Im so far away from that

#

How do you practice??

brave heron
#

a lot of practice from other materials + having a clique in your school would help a lot too, I asked a lot during my G7 to my other smarter seniors and that gave a lot of insights as well

#

solve easy ones

#

then solve harder ones, if you can't understand the concept, you can search for the concepts behind it and use that too

#

sometimes I use the alcumus of aops to solve specific topics

#

most questions from that came from existing AMC 12 and other existing contest, which is fun

#

nawh its free, just make an aops account

#

you can even do cauchy schwarz here which is kinda funny

ornate blade
#

hint (spoilered!):
||a + 4b + 9c = 16
4a + 9b + 16c = 25
9a + 16b + 25c = 36

a = 1, b = -3, c = 3||

silk gazelle
ornate blade
#

oh basically that's the same technique

#

so then we want $a(x_1) + b(4x_1) + c(9x_1) = 16x_1$

#

and so on

gilded haloBOT
#

southy

ornate blade
#

also we do have to show that $n^2 - 3(n + 1)^2 + 3(n + 2)^2 = (n + 3)^2$ to make sure the pattern holds

gilded haloBOT
#

southy

delicate basin
ornate blade
#

yeah and you only need 3 equations cause that's enough to figure out if there is one solution or not

there shouldn't be infinitely many solutions given the setup of the problem

brave heron
#

Theres a much more fun solution there tbh

#

Well not really fun but satisfying

#

Found it by dumb luck

ornate blade
#

wait but I don't have the year or the source

brave heron
#

Idk

delicate basin
#

people how the hell do you practice for amc10 😭

#

i did 1 practice test and im pretty happy with how it turned out (91.5) but idk where to start.. the difficulty seems to go up enormously at the end

ornate blade
delicate basin
#

i thought i wouldn't be able to do it because of school but nevermind i found out that time zones are not shooting me in the head for once

brave heron
#

But you can set the 16x1 + 25x2 as equation 4 as S

X1 + 4x2 .. = 1 as equation 1
4x1 + 9x2 .. = 12 as equation 2
9x1 + 16x2.. = 123 as equation 3

Then subtract 1 from 2, 2 from 3 and 3 from 4

To get eq 5 as 3x1 + 5x2 ...= 11
Then eq 6 as 5x1 + 7x2... = 111
Then eq 7 as 7x1 + 9x2 ... = S - 123

Then just subtract eq 5 from 6 and eq 6 from 7

To get 2x1 + 2x2 + 2x3 etc in both eq 8 and 9 which has 100 and S - 234 each, you can find S as 100 = S - 234 then S = 334

ornate blade
#

oh wow that's an amazing method

#

yeah so I convinced myself with $5x_1 - 3x_1 = 2x_1$ and $7x_1 - 5x_1 = 2x_1$

gilded haloBOT
#

southy

ornate blade
#

so yeah second difference constant implies that

ornate blade
#

,calc 3(123-12)+1

gilded haloBOT
#

Result:

334
brave heron
#

I'm on my smartphone and I don't know how to use LaTex sorrykekw

barren iron
#

$$a^2+b^2=c^2$$

gilded haloBOT
#

πrate of the Cartesian

brave heron
#

I realize since the second difference is constant. One could just take advantage of the difference of the sums [1,12,123,S] and branch them out, one could get the first differences [1,111,S-123] instead, then second differences [100,S-234] then get S as 334.

#

1 minute solutionopencry

#

Ultrasimplified version

delicate basin
#

ppl how the hell do you revise for amc10??

i did 1 practice test and im pretty happy with how it turned out (91.5) but idk where to start.. the difficulty seems to go up enormously at the end

pallid tundra
#

for problems you didn’t get correct, read over the solutions

#

final fives being hard is deliberate by design

delicate basin
#

but there’s all kinds of stuff that it seems I just have to.. know

#

like the modular arithmetic

pallid tundra
#

focus on maximizing your score on earlier questions first

#

91.5 is not a safe score for AIME qual

#

the late questions will tend to throw a lot of more obscure techniques at you

delicate basin
pallid tundra
#

if you can get, say, the first 15 locked down

delicate basin
#

Do you know why the average score has gone up lately?

pallid tundra
#

then you’ll be in a very good position

delicate basin
#

I checked and it went from like 5x to 6x

pallid tundra
#

test difficulty? fewer people taking it?

#

I haven’t looked at the last few years’ tests lmao

delicate basin
delicate basin
pallid tundra
#

with how low cutoffs have gotten

#

105+ is probably sufficient

delicate basin
#

and also how do I practice this kind of stuff again

delicate basin
pallid tundra
#

not unless you get far

#

say, USAMO+

delicate basin
#

ah 💀

#

so they don’t care about aime 😭😭

#

ill still try to get there

pallid tundra
#

the big names don’t particularly care about AIME

#

but outside that bubble it could give you an edge in admissions

delicate basin
#

ah

#

well

#

i wasn’t thinking too deep into amc

#

but now i realize that i am quite literally like 2 or 3 problems off aime so I want to try

pallid tundra
#

yea

leaden herald
#

in Italy no university cares, except maybe Scuola Normale Superiore (SNS) in Pisa (probably the best university for math in the world)

leaden herald
delicate basin
#

i was focusing more on harder exams instead of Olympiads

#

(which are.. much easier to prepare for lol)

#

the number theory and geometry especially on amc is giving me a headache

leaden herald
leaden herald
#

there are a lot of disconnected things to remember

leaden herald
#

here's one I've learnt some days ago

delicate basin
leaden herald
#

a perfect square $s$ is either $\equiv 1 \pmod{3}$ or $\equiv 1 \pmod{4}$

gilded haloBOT
delicate basin
#

Hmm

leaden herald
#

this is so random to me, but extremely useful

delicate basin
#

oh wait that’s actually

#

interesting

#

the proof is probably 2 years long or something

delicate basin
#

ohhh

leaden herald
#

but I've read that somewhere

#

or probably I remember it wrong

#

probably it was either 0 or 1 mod 3 and mod 4

near hill
#

Yeah, that would be correct.

leaden herald
#

here we go

#

right now I'm solving problems on the inclusion- exclusion principle

delicate basin
#

i did a bit of digging

leaden herald
#

it seems to be fundamental in competitions

delicate basin
#

what the hell are these theorems

#

“chicken McNugget theorem”

#

😭🙏

leaden herald
#

lmao

delicate basin
#

it’s literally needed

#

for an amc10B problem

leaden herald
#

pigeonhole principle

shrewd girder
#

pigeonhole principle might be the MVP of contest math problems ngl

near hill
shrewd girder
#

Yeah

leaden herald
leaden herald
#

but probably I've read some saying "since we have more elements than there are spaces" or things like that

willow anvil
#

php has been overshadowed by global

delicate basin
#

😭😭

shrewd girder
#

i mean the statement of it seems glaringly obvious

#

but

#

its a really powerful way of thinking

leaden herald
#

yea I realised

near hill
shrewd girder
#

In mathematics, the coin problem (also referred to as the Frobenius coin problem or Frobenius problem, after the mathematician Ferdinand Frobenius) is a mathematical problem that asks for the largest monetary amount that cannot be obtained using only coins of specified denominations. For example, the largest amount that cannot be obtained using ...

#

LOL

#

McNugget numbers

shrewd girder
#

when looking it up

leaden herald
#

this year we had a team competition, and our "jolly" problem literally was:

#

How many non-empty subsets of ${1,2,\ldots,13}$ there are, so that the product of their elements ends with $0$ ?

#

this is inclusion exclusion basically

#

(ps. we couldn't solve it, although it's not really hard)

gilded haloBOT
leaden herald
#

still not competition level, they're just generic PIE exercises

shrewd girder
#

imnot looking yet cause im gonna take a stab at it soon myself

#

||yeah that was my thought, like total is the size of the powerset and then subtract out the ones that don't at least one of both 2 and 5 in the factorization||

#

i just can't write out atm

jolly bridge
#

||i think that might be missing a -1 because it specifies non-empty subsets||

#

||but then it gets un-accounted for in 2^6||

gilded haloBOT
#

Vanellope von Schmugz

pallid tundra
#

hint: symmetry

sterile helm
#

Does anyone know how to do 90^2+56^2 really fast without calculator?

#

ok np

#

because in the solution I'm reading they went from 90^2+56^2=106^2 and in the test you cannot use a calculator

#

oh

#

how would u know that

#

what if I only knew a and b?

#

that will be tough without a calculator lol

#

oky

brave heron
brave heron
rough dock
#

anyone got resources to practice/learn on for someone who’s new to this level of math?

acoustic nova
brave heron
rough dock
brave heron
#

Yes(well if you searched the topic itself, I think) but the theory stuff does show up, and most of their problems had lots of solution from AMC to AIME to USAMO and Even IMO

barren iron
#

Keep asking

hidden sigil
#

66

#

B and C option are same?

#

I guess c is correct

leaden herald
#

it is

leaden herald
#

the actual solution is 2^13-1-(2^11-1+2^6), and, guess what, they cancel out

fading bluff
#

they aren't same

hidden sigil
#

Yeah

fading bluff
#

(a.b)= -c.a

brave heron
brave heron
#

Nawh obviously

#

My math teacher sent me stuff who is part of the wide connection of the deputy team leader of my country who is with the contestant

brave heron
# brave heron

For 1, obviously a case is all even integers but idk how to prove the others

#

I'll probably just get max 3 points by claiming that it's probably even integers(but hey atleast its a point)

lean sky
brave heron
#

it's all even though(great)

brave heron
#

i'm so cooked, till now I only have even integers case

brave heron
#

was it 54?

#

i hate these problems about constant rate stuff

#

I agree

#

where did 33 come from opencry

#

how is that a hint?!

#

ohhhhhh

#

my bad

#

I guess you could express this algebraically

#

from what I see on the internet, the 54 notion had a LOT of assumptions

gilded haloBOT
#

Vanellope von Schmugz

snow dirge
#

BTW the time she leave the school on normal day is 4PM?

#

1 hour head start = 12 mins early?

brave heron
#

yuh

snow dirge
#

Also the velocity of the girl walking during the school-station and station-home isn't the same?[

#

SRY to make this more complicated 🤣

brave heron
#

exactly, too much reliance on whatever

snow dirge
#

what is 33 doing here anyway LMAO

snow dirge
#

another question from me. Normally, when the girl reaches the station, does she meet her mother and get on the car immediately?

#

Or should I assume this one in my calculation for first of all?

brave heron
#

that's actually the supposed assumption to get 54

snow dirge
#

Ok ty

snow dirge
#

This is my simulation on Scratch. I created 2 sprites which represents the girl on normal day(cat) and on special day(woman). I set the time ratio by 1:600 as the picture below. The total distance is 480 units from school to house. Velocity on foot and by car are also mentioned.

#

The second picture describes that on special day she got picked up on the way between the station and house at x=60 which is a quarter distance to home.

placid tapir
#

Scratch scratch

snow dirge
#

But I made some mistakes there.

  1. As you can see the time for the cat should have started after he began to move.
  2. Both of the timer should have stop when they began to move faster(on car).
#

Yeah that’s what I thought 😂😂

#

It’s impossible to solve this problem without knowing the velocity.

#

Smash, next pls🤣

zealous violet
#

whats a good way to study for amc 10s?

#

ive been doing practice tests but cant seem to get my score up

brave heron
#

damn NNN GCA

#

best year in imo for someone who's geometry is their weakest

brave heron
#

OKAY P5 IS ACTUALLY REALLY EASY OMG

#

THE ANSWER IS THREE

#

The trick is to determine to location of the monster in the second row

#

if the monster is not on the edge, one should start at either adjacent of the monster, and go down and go to the direction behind the monster, worst case scenario, you die on your second attempt(bad luck) then you could just respawn easily on the other adjacent

#

if its on the edge, create a staircase like path starting adjacent on the monster then go left(or right) instead of down first(because its a 2024 by 2023 not a square), the go down left/right, down, left/right, till you either finish it or not, if you didnt, there are two cases, if the monster is encountered when you go left or right, then just go in the opposite direction till you got to the edge where monster 1 is encountered, if the monster is encountered when you go down, one shold take a step back in a row and not go left/right and just go double down and go in the opposite direction till you got to the edge

#

OMG P5 SOLVED in 20 MINS

#

why is it so easy

#

they screwed up(I think)

#

if a hobo like me who struggles at some low level competitions yet can solve a P5 in IMO then we are done

zealous violet
#

anyone got study tips for the amc 10/12?

#

so far ive been doing practice tests and tutoring sessions but they dont really seem to stick

#

i have heard that keeping a small notebook with formulas is a good idea, so I started to do that

#

but i was wondering what else I could do to boost my scores