help-4

[torn herald]

For the fourth column in the augmented matrix, is it always just the coefficients of q(t), if so, why is this the case

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[eternal hawk]

This is just a study plan quiz not graded.

So I need to make a formula for the table.

I'm assuming that s means salary and I'm assuming that the pay per hour is $18 per hour since we start at 2 hours for 36 and continue scaling up by adding another 18 per hour.

So is the formula s=h(18) correct?

[eternal hawk]

I've done the reverse math by using my own formula to calculate

like s=3(18) gives me $54

[frozen ledge]

it’s just linear

slope is clearly 18

then use point slope formula

also why not hk-47?

[vale dock]

@eternal hawk Has your question been resolved?

[eternal hawk]

My SWTOR character was HK-49

Also yeah the slop is clearly 18 but

What is the point slope formula?

I used s=3(18) and it came back as a correct answer

Well

I mean I used

s=h(18)

[frozen ledge]

$y - y_1 = m(x - x_1)$

[rocky lotus]

knief

[frozen ledge]

HK-47 is better

[eternal hawk]

Is this a joke? p.p

Should I have used that? I'm in intermediate algebra section 1 and s=h(18) was correct on the quiz

[frozen ledge]

h(18)?

you should say 18h

but yes

[eternal hawk]

So for the future I should try to say 18h? instead of h(18)

How come? Just looks nicer or what?

[frozen ledge]

yea

well it’s standard to just right the number as a coefficient

and h(18) looks like function notation

[eternal hawk]

Uhhh

yeah I understood that

I'm still learning the basics

how like when you are converting an english phrase as an algebraic expression

that LESS THAN means you are taking or adding to a number

so like

Two more than a number is x + 2

or fifteen less than a number is x - 15

sometimes my brain wants to do it the other way around when I read the less than ones

[frozen ledge]

youll get comfortable with it

[eternal hawk]

I hope

Question is done bot

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[lofty crown]

am i supposed to use these properties to show this question or is there a simpler way

[gleaming kindle]

hint: $\mathrm{graph}(\phi)\ss V\times W$

[rocky lotus]

ロケット・ジャンプ

[lofty crown]

im still confused

does it have anything to do with this proposition

[gleaming kindle]

if A is a vector space and B is a subset of A then B is a vector space (with operations inherited from A) if and only if B is a subspace of A

[lofty crown]

oh so VxW is a vector space

[gleaming kindle]

if you didnt know that already, take some time to convince yourself why

[lofty crown]

oh right

addition is component wise in V x W right

[gleaming kindle]

yes

[lofty crown]

ah got it, thanks

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[gleaming kindle]

np

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[eternal hawk]

I need some help doing long division to convert the fraction 170 over 11 into a mixed number

[eternal hawk]

Apparently I can't remember how to do it at all xd

11 goes into 1 no times so you move onto 17 yes?

11 goes into 17 once

11 x 1 = 11 obv so

then you get this?

Do I subtract 11 from 17 then? Or do I bring the 0 down and then subtract 110 from 170?

[midnight iris]

yes

first u do the subtraction

[eternal hawk]

yes to which 😔

[midnight iris]

and then u bring the 0 down

[eternal hawk]

okay so 11 from 17 first

[midnight iris]

yesyes

[eternal hawk]

So that becomes 60 then

and now I'm lost on what to do

This where I got lost when I was doing it on paper while going through my study plan

[midnight iris]

u know the table of 11?

[eternal hawk]

Wym?

[midnight iris]

11 * 1
11 * 2

etc

[eternal hawk]

yeah I know anything times 11 is like doubled or whatever

11 * 2 = 22

[midnight iris]

yes what comes before 60

which multiple of 11

[eternal hawk]

11 * 5?

55?

[midnight iris]

yes

yes

[midnight iris]

do u know what to do next?

[eternal hawk]

So what do I do there

No

I have that 55 but I don't know what to do with it

[midnight iris]

subtract from the 60

and write 5 in quotient

like u did with the 1

[eternal hawk]

So how do I show that I found the 55 that way on my paper

do I write 11 * 5 off to the side?

[midnight iris]

which grade are u in

cuz idt its necessary u can just say mental calculation

[eternal hawk]

Intermediate algebra college.. I haven't done algebra in like 7 years 😭

maybe 8

I'm breaking down here I should know this but I've just forgotten it

[eternal hawk]

Like this?

[midnight iris]

what is 60-55?

[eternal hawk]

5..

[midnight iris]

[eternal hawk]

I haven't eaten or slept all day..

[midnight iris]

rewrite jt

[midnight iris]

bro

[midnight iris]

sleep and eat fkrst

they are very imp

get some sleep

[eternal hawk]

I can't.. I'm too stressed out about this intermediate algebra class

[midnight iris]

so now u have your remainder, quotient and divisor

[eternal hawk]

So then I write the faction as 15, 5 over 11?

[midnight iris]

yesss

[eternal hawk]

guh I tried to write out the fraction here

😔

I feel so fucking stupid

[midnight iris]

nah dw i get what ur trying to say

u wanna try some other divisions too?

[eternal hawk]

Sure I would like to..

[midnight iris]

12√1464

[eternal hawk]

so 12 goes into 14 once as 12

12 can't go into 2 so I bring down the 6..?

or do I bring down the 6 and the 4?

[midnight iris]

try yourself

trust your process

[eternal hawk]

I mean..

[midnight iris]

well there is a little trick

[eternal hawk]

12 can go into 264 22 times

[midnight iris]

if u bring down one number

and its smaller than the divisor

then u put 0 in quotient

[eternal hawk]

Which one is the divisor again 😭

[midnight iris]

and bring down the other number

[midnight iris]

in this question 12

[eternal hawk]

1464 is the dividend?

[candid temple]

hello, can anyone here help with calculus level math? calculus 2 perhaps?

[midnight iris]

yes

[midnight iris]

u need to claim a help channel

[eternal hawk]

And the numbers on top are the quotient?

I just wanna write these parts down before continuing so I can be less confused

[midnight iris]

yesd

[midnight iris]

fosho !

[eternal hawk]

Okay so back to the problem

lemme read what you said about the trick

[eternal hawk]

So bringing down 6 doesn't make the number smaller than 12

so I DO NOT put a 0 in the quotient?

Cause that makes it 126?

Or wait no that makes it 26?

Like this?

[midnight iris]

yes

so u just solve it like u did with 14

[eternal hawk]

12 goes into 26 1 time

I put a 1 on top and a 12 under the 26?

[midnight iris]

are u sure

[eternal hawk]

2 times

Sorry

[midnight iris]

no sorry here

ur trying to learn it doesn't include sorry

[midnight iris]

lessgoo

[eternal hawk]

So this looks good..?

[eternal hawk]

ty 😔

Now I drop down the 4 and do it again?

Since 24 is bigger than 12

[midnight iris]

yess

[midnight iris]

lesgoo

[eternal hawk]

Did I do it right..?

Drop down the 4 to make 24

12 goes into 24 twice coming out as 24

so 24 - 24 = 0

[midnight iris]

[eternal hawk]

Do I do anything with that 0 at the end or no?

[midnight iris]

yess

[midnight iris]

thats the remainder

try 13√1293

[eternal hawk]

Okay so nothing since it's a 0

[eternal hawk]

Okay

Real quick before doing that math problem

The previous one you gave me

To turn it into a mixed number I would get

122 0/11?

So it'd just be a whole number?

[narrow arrow]

yh

[midnight iris]

thats correct

[eternal hawk]

Okay

I'll do that other problem now

Okay so

13 doesn't go into 1

13 doesn't go into 12

13 goes into 129 9 times?

[midnight iris]

are u using a calculator

[eternal hawk]

Just for the multiplication

😭

I'm doing the division by hand because that's what I really need to learn

[midnight iris]

😭

its allowed in exam?

[eternal hawk]

yes

as well as notes

[midnight iris]

[eternal hawk]

what : (

[midnight iris]

ur doing good

[eternal hawk]

okay I'll continue

[midnight iris]

solve the whole question

[eternal hawk]

okay

no

[midnight iris]

ohh

[eternal hawk]

okay so

so I do it again?

since 13 can go into 19 once

cause if I do it again

I get 981 remainder 6

[midnight iris]

huh

[eternal hawk]

what : (

[fossil mulch]

You stop here

[eternal hawk]

Okay

so

[narrow arrow]

If he can use calculators in exams why doesn't he just [1293/13] and (1293-[1293/13]) /13

[eternal hawk]

98 remainder 19

[midnight iris]

no

the answer is 99

[eternal hawk]

where did I mess up huh

I just back tracked

and still got 98

: (

[midnight iris]

why not take 117?

[eternal hawk]

13 goes into 129 9 times for 117

oh

I'm stupid

[midnight iris]

why did u take 8

[eternal hawk]

because I'm stupid and starving and tired

and I for some reason didn't think that 13 would go into the number 9 times again

[midnight iris]

no ur not stupid

[midnight iris]

im not gonna interact with u further

first go eat something

[midnight iris]

starving yourself isn't helping u

[eternal hawk]

wait

[midnight iris]

so go eat something

and take a nap

[eternal hawk]

Atleast tell me if I did it right

99 r6

I can't take a nap it's 12:30am

[midnight iris]

yes u did

[midnight iris]

sleep

giving exam exhausted will only flunk it

[eternal hawk]

cause idk any calculator tricks I have no idea what you just typed here : (

The exam isn't until thursday

I'm mostly trying to figure out if I have what it takes to do this class or if I should drop it for something else..

Well it's just a small quiz on thursday

[midnight iris]

do u enjoy doing it?

[eternal hawk]

no but I have to take intermediate algebra either here or at the community college

[midnight iris]

its more about if u like learning about it

[eternal hawk]

Well that's a lie

I liked the 1.1 stuff a couple hours ago

I don't hate it I just hate my brain I guess idk

And I hate that I'm trying so hard to maintain a 4.0

[midnight iris]

brains are weird to different talents

[midnight iris]

just drop it if u don't enjoy learning

ut

cuz it will just feel like a burden either way

[eternal hawk]

I mean I have to do it for my degree

I'm just hating on the stress trying to maintain a 4.0 causes me lol

I considered dropping the course for something easier. And doing the intermediate algebra with the local community college and transferring it

It should transfer and transfer grades don't impact your gpa

I have until the 24th to drop it

I'm TRYING to get to the first quiz (Which is due thursday night)

To see how I do

I only need 576/640 points for an A since it's on the 90 to 100% grade scale

[narrow arrow]

Just ignore what I said lol👍🏻

[eternal hawk]

I'm hoping to get 168 points from the easy homework, discussions, and extra credit

so that leaves me with 408 to get from the 4 quizzes and 4 tests.

Each quiz is 30 points each and each test is 100

[eternal hawk]

Sorry 😔

None of the long division problems are as big as what @midnight iris gave me

Like the few I've had so far which were meant to convert improper fractions to mixed numbers

were like

25 / 4

[narrow arrow]

So what I meant was do the division on the calculator you will get some number with decimals like let's say 13/3 you get 4.33
Take the next number smaller than that so 4 in this case do 3x4 for the whole number part and (13-3x4) /3 in the fractional part

But just ignore that

Man I hate how discord messes up *

[eternal hawk]

:v

[narrow arrow]

Good luck on your quizes

[eternal hawk]

Thanks 😔

@midnight iris Any chance I can bother you in the future for a refresher? 😔 if I need it

prime facorization is next.. : (

I'll be back tomorrow for more help guh.. but before I do that

I'mma do one more problem someone check it pls..

Did I do this long division problem correctly

I need to go get something to eat like let said. If someone could let me know about that problem that'd be great. : (

[vale dock]

@eternal hawk Has your question been resolved?

[vale dock]

@eternal hawk Has your question been resolved?

[midnight iris]

for sure ! 😭

[eternal hawk]

I tried adding you but I couldn't :c

[midnight iris]

i added u ^^

[midnight iris]

yess thats correct lessgooo

[eternal hawk]

Ty ty..

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[warm valley]

Is anyone here able to explain how to compute backpropagation on a neural network?

I understand roughly, but doing it to the loss functions/relu/etc is making my head spin.

Example questions:

[warm valley]

I dont have an assignment or anything, just trying to study for a midterm

If y'all have any tips for stuff to put on a cheat-sheet, id appreciate that as well

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@warm valley Has your question been resolved?

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@warm valley Has your question been resolved?

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@warm valley Has your question been resolved?

[stable nacelle]

All correct

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[dreamy scroll]

.open

How would i find the vertex of a parabola of the form Ax^2+By^2+Cxy+Dx+Ey+F

[jolly ledge]

.open is not necessary btw

[dreamy scroll]

ic

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@dreamy scroll Has your question been resolved?

[dreamy scroll]

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@dreamy scroll Has your question been resolved?

[jaunty briar]

gradient is 0 at vertex, you will get 2 linear equations solve them.

[dreamy scroll]

hmm why is the gradient 0

[jaunty briar]

by definition, it is a point where parabola is maximum or minimum

[dreamy scroll]

ohh yea

It's a local maxima or minima so the gradient would be 0

[dreamy scroll]

thankyou

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[worthy stirrup]

may someone provide me a definition of an isolated point using mathematical notation, like in the epsilon delta definition for limits/continuity? i understand isolated points are anything that isnt a limit point but its easier for me to use a definition if its in that format

[verbal badger]

!occupied but let $A \subseteq X$ where X is some topology. $x \in A$ is an "isolated point" if $\exits \text{open set } U \subseteq X$ s.t. $U \cap A = {{x}}$

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Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[worthy stirrup]

👍

[rocky lotus]

Stitches
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

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@alpine sierra Has your question been resolved?

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@alpine sierra Has your question been resolved?

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[elder dagger]

have to find orthognal of this

[vale dock]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[elder dagger]

tried this

,rotate

[elder dagger]

2

[elder dagger]

what to do from here

<@&286206848099549185>

soo..

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[winged lake]

Studying for a Calculus III exam tomorrow, currently, I am stuck on this problem.
I am just really confused on whether or not this is printed correctly.
Since the inner integral is integrating with respect to x, shouldn't the bounds of the inner integral be in terms of y?
Reversing the order of integration from y=x^(1/3) to y = 2 gives me x = 0 and x = y^3, meaning that the bounds should be from 0 to y^3, yet the integrating and then trying to plug in the values, I get that y=y^3. which doesnt really make sense (Can be seen on the right side of the equals sign)

So Is this really meant to be solved or should I just keep it at that since it just says to reverse the order of integration? Or can it actually be solved and I am looking at it the wrong way?
I asked ChatGPT for help and it said that the inner integral being in the bounds for x should be x=y^(1/3) which is what I thought but idk if its halucinating as usual.

[ivory valley]

there seems to be an error in the integral

[winged lake]

So I'm not going crazy is what you're saying? it actually is just the instructor that gave something unsolvable?

[ivory valley]

Yes, there is very likely a printing error

else you have bounds from x=x^(1/3) to x=2 which for the lower bound is nonsense

[winged lake]

yeah thats the error I encountered at the end when I realized that the notation implied y=y^3

so I thought I messed up somewhere

but good to know

thank you

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[winged lake]

how do I close this?

[neat locust]

it is already closed

!done

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[barren imp]

Hi I need help with some word problems

[feral sapphire]

Just ask your question.

[golden gate]

!da2a

[vale dock]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[barren imp]

Oh- ok

I have done this before but I cant remember how I did so

[golden gate]

!status

[vale dock]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[barren imp]

1

[golden gate]

Do you know how to solve equations with a single variable?

@barren imp

[barren imp]

Not great with word problems

[fleet grail]

Ok!

We can help

me and tandon

Imma set up a word problem.

[golden gate]

Sure, but do you know how to solve equations

[golden gate]

He already has a question, we're trying to guide him to the solution

[barren imp]

All I know is theres 7 cm and the new square has 42 cms more

[fleet grail]

$7x = 42$

[rocky lotus]

Average_X^2

[fleet grail]

Hold up

[barren imp]

?

[fleet grail]

7 * 42?

[golden gate]

If I gave you a question like $5x + 10 = 20$ can you solve this?

[rocky lotus]

@golden gate

[fleet grail]

$x = ?$

[rocky lotus]

Average_X^2

[barren imp]

Yeah

[barren imp]

But its not like that

[fleet grail]

$Ok, solve it!$

[rocky lotus]

Average_X^2

[golden gate]

Yes, but we'll get to it

Do you know the formula for perimeter of a square?

[barren imp]

I believe its length²?

[fleet grail]

no.

[golden gate]

That's area

[fleet grail]

Its $4s$

[rocky lotus]

Average_X^2

[barren imp]

Oh

[fleet grail]

But you got the area of a square right. It is $s^2$

[rocky lotus]

Average_X^2

[barren imp]

Wai-

4(l)

[fleet grail]

no.

[golden gate]

4l or 4s both work

[fleet grail]

Not l

But they both function as the same thing

[golden gate]

Ok so, so far we have established, Perimeter of a square is 4 * l, wherein l is the length of the side of the square

Now

[fleet grail]

$4l = 4w = S^2 = Perimeter of a Square$

[golden gate]

s^2?

[fleet grail]

Shoot.

[barren imp]

Ok

[golden gate]

Now, try to represent the statements, using what we said here

[barren imp]

Ok well maybe... 4(L)+7?

[golden gate]

l is the length of the side, when we make a new square by increasing the length by 7, how do you think we'll represent that?

[golden gate]

Not quite

[barren imp]

Oh.

[golden gate]

You see we've increased the length by 7

So $l \mapsto l + 7$

[rocky lotus]

@golden gate

[golden gate]

Since the perimeter is 4l

For the new square it will be ______

[barren imp]

+42?

[golden gate]

No I meant like what would the application of the formula look like on the new square

$$l_n = l + 7$$
$$P(l) = 4 \times l$$
$$P(l_n) = ?$$

[rocky lotus]

@golden gate

[barren imp]

This seems a bit confusing with the way this is being set up

[golden gate]

Hm...

Ok do this

If we have a square which has a side of 10

What is it's perimeter?

[barren imp]

40

[golden gate]

Good

[barren imp]

Wait what if its set up 4(l + 7)= something 42

[golden gate]

Yes

The new perimeter will be 4(l + 7)

from the formula that is

Ok cool

Now we're saying this is equal to

42 more than twice the length of the side of the original square

[golden gate]

Can you try converting this statement to an expression, the same way we did the first one

[barren imp]

Hmmmmmmm

I.... do not know how to set this part up

[golden gate]

Ok

42 more than, means we're going to add 42 to the thing which is to the right of this
twice, means 2 *
the length of the side of the original square, recall that is equal to l

Putting this all together

42 + 2l

Now equate both the expressions

4(l + 7) = 42 + 2l

[barren imp]

Oooo so its something like- well yeH- that

[golden gate]

Yea

can you solve this now?

[barren imp]

Ok

So length is... 7cms?

[golden gate]

Yes

Alr cool

For the next time remember in word problems, the key is to apply all the steps stated in the English statement step by step

It doesn't help to look at the statement and trying to come up with what it means all at once

try to partition it

[barren imp]

I see

[golden gate]

generally, look for what you don't know

and assign it a variable

then, start applying the procedures stated to the variable

A couple of things to be careful of are, don't take two variables to represent the same thing

and remember the order of operations and priority of operations

You got this

!done

[vale dock]

If you are done with this channel, please mark your problem as solved by typing .close

[barren imp]

CanI ask a few more?

[golden gate]

Yea sure

[barren imp]

Ok so this one I think Im using slope but Im unsure

[golden gate]

Well no

This is a question of similarity of triangles

Are you aware of that concept?

[barren imp]

Oh!

Right!

💀

[golden gate]

?

[barren imp]

Ok I got 10

[golden gate]

That's wrong

[barren imp]

Oh wait-

I set this up like pythagorean theorem...

Ok I need help setting this up.

[golden gate]

Ok, can you draw rough figures for the question?

Draw one for the person and one for the tree

[barren imp]

They're both trees

[golden gate]

They aren't but that's not important to the question

[golden gate]

Good

IDK why you calculated the distance between the top of the person's head and the shadow's head

but in any case

Mark the angle between the base and the hypotenuse as being equal on both the triangles

[barren imp]

I dont know💀

[golden gate]

Ok

Can you label the diagrams

Like maybe triangle ABC for the first one

and PQR for the second one

[barren imp]

Ok

[barren imp]

How do we set up this equation

[golden gate]

Now, in this figure, $\angle BAC = \angle QPR$

[rocky lotus]

@golden gate

[golden gate]

Now we'll use similarity

If you're not aware In similar figures the ratios of the corresponding parts are equal

[barren imp]

I should probably bring up the fact this is linear equalities

[golden gate]

Well yes, this will result in a linear equation

but I don't think you can use anything except similarity to get the relation between the two figures

which we then use to form the equation

[barren imp]

Ok

6 ft is the height 8ft is the shadow

[golden gate]

$\Delta ABC \sim \Delta PQR \implies \frac{AC}{PQ} = \frac{BC}{QR} = \frac{AB}{PQ}$

[rocky lotus]

@golden gate

[golden gate]

Correct

[golden gate]

We can ignore $\frac{AB}{PQ}$ here

[rocky lotus]

@golden gate

[barren imp]

Ha?

[golden gate]

Well yea

because it doesn't matter to the question

we just need the height of the tree

not the distance from the top of the tree to the top of the tree's shadow

We just need to exploit $\frac{AC}{PQ} = \frac{BC}{QR}$ here, to find $QR$

[rocky lotus]

@golden gate

[golden gate]

We already know the other three

[barren imp]

Ok

True

But how do we plug it inas equation?

[golden gate]

This is an equation

just put the values in here

An equation is two expressions concatenated with an equal to sign

[barren imp]

Ah...

Applications of linear functions souldnt be this frustrating for me and yet here we are trying to remember for the life of me before the test

[golden gate]

Hey, it happens to the best of us

DW about it

[barren imp]

Thanks

[golden gate]

For now just prep for your exams

Best of Luck for them

[barren imp]

Thanks

So back to the equation?

[golden gate]

sure, can you solve it?

[barren imp]

Hmmmm

Is it something like
...
6/x=8/27?

[golden gate]

Yes

[proud leaf]

😭

you cant solve this?

[golden gate]

They never said they can't

[barren imp]

Ouch

[proud leaf]

i just assumed

anyway

what is it with you

[barren imp]

I just needed help deciphering the way to set it up

I suck at word problems

[golden gate]

What is what with me?

[proud leaf]

you talkin to me?

[golden gate]

@barren imp did you get the answer now?

[barren imp]

Im working it out

[golden gate]

k, cool

[barren imp]

Ok so far I have 8x=6(27) is this correct?

[golden gate]

Yes

[barren imp]

So then x=20.25

[golden gate]

correct

Good!

[barren imp]

Also question how does the multiplying work do you just flip the 8/27 and multiply it on both sides to cross cancle I just want to make sure

[golden gate]

Yes, that's pretty much it

[barren imp]

I see

Ok let me try another one before I show the next word problem I struggle with

[golden gate]

Ok, I gtg for now though

[barren imp]

Oh shoot ok

[golden gate]

Open another help channel with your next problem so that people can help you on that

Alr

And once again, good luck for your exams

I'll close this one for you

.close

[vale dock]

Channel closed

Closed by @golden gate

Use .reopen if this was a mistake.

[barren imp]

On

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
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• Show your work, and if possible, explain where you are stuck.
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[bright goblet]

if you have an undirected graph
you can get from any vertex to any other vertex
it has 21 edges and 12 vertices

how to know if every vertex's degree is even (it has Eulerian circuit)?

and how to answer this in general, not for a special case?

---

in this task nothing is said about cycles, so idk what to do with them

[low ice]

Sum of degrees is 2×edges = 42. To have an Eulerian circuit, all degrees must be even and the graph connected Can’t know that from just edges and vertices

[bright goblet]

description (in case I missed something):

In the old town, streets are arranged so that they connect intersections. Each intersection is connected to the others by paved streets. A cyclist wants to cycle through the city, riding along each street exactly once, and then return to the starting point.
There are 12 intersections in the city. All streets are two-way. A total of 21 streets run between various intersections. From any intersection, you can travel to any other. Some intersections are connected by multiple streets.

[bright goblet]

does that mean that one needs to draw the graph to and count degrees?

they say that this problem has a general solution

[low ice]

Yes exactly.

[low ice]

Connected graph has an Eulerian circuit if all intersections have even streets. Just check connectivity and degrees

[bright goblet]

yeah that's the special case

[low ice]

Right the special case is just applying the general rule connected + all degrees even → Eulerian circuit.

[bright goblet]

hmm, so if I mention Eulerian circuit in my soln, would it count as general? idk

[low ice]

Yes if you mention Eulerian circuit and the rule “connected + all degrees even,” that counts as a general solution

[bright goblet]

alright then, I'm closing, thanks

[low ice]

no worries!

[bright goblet]

.close

[vale dock]

Channel closed

Closed by @bright goblet

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[stuck plover]

\

[stuck plover]

hi im not sure what to put in the middle

for a) and b) i tried couple of different ways and it did not work

but i got the answers right

[quiet marlin]

middle where?

[stuck plover]

the blank spaces

[quiet marlin]

word

you're concerned with some x value slightly larger than -1; what is f(x) for such x values?

[vale dock]

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• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tidal garnet]

Hi the solution for this problem is 7 23 31 37 , however that not the main issues, my main problem is trying to understand the question.

I am currently thinking that the puzzle was asking : What combination that 2 number Beth and 2 number Cloe play such that it force Anne to can not play on first and last round.
my code that brute force this approach yield no solution. Perhaps i don't fully understand question
I wrote a program to brute force trying all possible combination of number that beth and cloe can play such that it force Anne to have a number that she can not play on first and last round, yield no solution
maybe my undestanding of question is wrong
Please don't tell me how to solve it, i just want to know if my understanding of question is correct. (I will solve this on my own)

[icy sigil]

is this a math problem or an informatics problem

[feral sapphire]

Ann went first so you should brute force that before Beth and Chloe.

[tidal garnet]

got it , that should make sense, ill try to solve this on my own now

.close

[vale dock]

Channel closed

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• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[steel maple]

hi

[dreamy scroll]

[vale dock]

@steel maple Has your question been resolved?

[vale dock]

Channel closed

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Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[turbid mist]

Hi is there anyone here to help

[vale dock]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[turbid mist]

I got the answer D for this is that right

[dreamy scroll]

hmm there was a cmd for this

[dreamy scroll]

ye

[turbid mist]

Whats a CMD?

[dreamy scroll]

command

[turbid mist]

Okay thannk you

[dreamy scroll]

for this bot

it diffrentiates for you

but i forgot how

[turbid mist]

Oh not sure just joined this server

[dreamy scroll]

I'm new as well

[dreamy scroll]

.close if you don't have anymore doubts

[turbid mist]

Oh alright so your a math teacher?

[halcyon forge]

is this D?

[dreamy scroll]

I'm a student

[turbid mist]

I have a few more questions later are you going to be available?

[dreamy scroll]

you can send them here someone should be free

or you can dm me , i can do them when i'm free

[halcyon forge]

hi

[dreamy scroll]

this one is occupied

[dreamy scroll]

use an unoccupied one pls

[turbid mist]

Thats alright if he has a question you can help it out i dont mind

[halcyon forge]

thanks a lot

[honest stone]

?? Has to claim a new channel for his to be answered. This is your channel.

[turbid mist]

Oh okay

[halcyon forge]

okay sorry how do I do that

[honest stone]

#❓how-to-get-help

Basically, send your question in an open channel, like #help-19

[dreamy scroll]

yo infinium

[honest stone]

Hi.

[dreamy scroll]

ye it's D

[halcyon forge]

okay I went to this

[honest stone]

yes should recieve help soon. You can also ping helpers in 15 min

[halcyon forge]

hey i created my own channel

[honest stone]

!nosols

[vale dock]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[dreamy scroll]

oh mb

[halcyon forge]

Im confirming the

answer thats why

[dreamy scroll]

no he meant that you gotta open a new channel

[halcyon forge]

I did at help 19

[turbid mist]

Hi

I need help for this question

I got -22 is that right?

Hi

Is there anyone available

[feral sapphire]

,wolf f''(1) for f(x)=(3x^2 - 5x)^2

[rocky lotus]

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[feral sapphire]

Yes.

[turbid mist]

<@&286206848099549185>

Hello

I got D for this is that right

<@&286206848099549185>

[fleet burrow]

,w derivative of y = (x - 1)(x^2 - 4)

[rocky lotus]

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Requested by .brasserie

[fleet burrow]

,w solve 3x^2 - 2x - 4 = -4

[rocky lotus]

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Requested by .brasserie

[fleet burrow]

yeah looks to be correct

[turbid mist]

Thank you so much

And one more

This im not sure

I think its C

Is C right or no?

<@&286206848099549185>

.close

[vale dock]

Channel closed

Closed by @turbid mist

Use .reopen if this was a mistake.

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• Do not immediately ping people or roles. After 15 minutes, feel free to ping <@&286206848099549185> once.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[viscid hawk]

https://discord.com/channels/268882317391429632/1428302592043122749

[river shale]

Hello, I'm having difficulties understanding how to solve (mostly even start to solve) for the following questions:

I'm requesting a proof of just the first 3-4 steps and I'll figure out the rest from there.

for B) I'm not sure what to do beyond the quotient rule; should I apply the chain rule? How would I best apply the chain rule?
for P2) I have no idea of how to deal with this.

(This is my second time taking this course after a few years of no math to improve my grade, I have incredibly spotty memory, but I have learned this before)
While I understand most of the properties, I often get lost on where to apply them, or get lost figuring out when it would be useful to apply them. Additionally, I have:
Diagnosed memory issues with basic rules, such as exponent rules sometimes.
Slight discalculia, I will read longer numbers completely incorrectly and will say something completely different from what I thought I said.
My one braincell working very hard, but sometimes the silence is too loud for that one braincell to actually mentally process anything.

I do have accommodations to try to aid me, and I do write down every step (with written descriptions) to combat small errors.

While I'm at it, if there are any recommendations or easier way to associate things, I'd gladly appreciate it. I often am left doing proofs for tests to catch if what I think I can do is sound logic, which hogs my time.

[river shale]

I move it here for you so that people don't need to go back to the original post

[viscid hawk]

ahh ok thank you

I just noticed nobody was looking at the initial post

here is where I started getting stuck for B

also, side note, is this correct? I thought the answer was odd, and google is saying a completely different answer :')

[vale dock]

@viscid hawk Has your question been resolved?

[clever sentinel]

(2x^1/2)'
= 2 × 1/2 × x^(1/2 - 1)
= x^(-1/2)

you did that wrong

[viscid hawk]

thank you

I missed my -1/2 in my notation, thank you

I was wondering why I left a space -

[clever sentinel]

I googled it gave same answer

that's correct

[viscid hawk]

oh, alright! mine came out fumbled.

[safe fulcrum]

,w d/dx (x^2 e^x) / (x^2 + e^x)

[rocky lotus]

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Requested by sooouth.

[safe fulcrum]

yeah that's equivalent to yours

[viscid hawk]

for this one, is there a trig identity I am overlooking?

or is this seriously the answer..

minus the hiccup with the +x instead of +1/(sqrt(x))

,w d/dx (v^3-2v)(v^(-4)+v^(-2))

[rocky lotus]

Results provided by WolframAlpha

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Requested by flop_ed

[viscid hawk]

whar

how???

[clever sentinel]

maybe because you didn't define v to be function of x so it thinks v is a constant

[viscid hawk]

ohhh

,w d/dv (v^3-2v)(v^(-4)+v^(-2))

that's better

still confused cuz I screwed something up

oh... wait ugh I gotta multiply the exponents out don't I?

,w simplify (3v^2)*(v^(-4))

[rocky lotus]

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Requested by flop_ed

[viscid hawk]

wait huh

I didn't mess up there?

,w d/dv (v^3-2v)(v^(-4)+v^(-2))

[rocky lotus]

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[viscid hawk]

,w simplify (-4*v^(-5))(v^3)

oh found it

,w simplify (-4*v^(-5))(-2v)

,w simplify -8v^4-2v^(-4)

[rocky lotus]

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[viscid hawk]

uhhh... okay can't do that

[viscid hawk]

this is the only one I'm left stuck on

,w d/dx e^(3x)

alright just checking...

can never be too careful..

,w d/dx e^(tan(2x))+sin(e^(3x))

[rocky lotus]

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[vale dock]

@viscid hawk Has your question been resolved?

[viscid hawk]

,w d/dx (x+2*x^(1/2))/(x^2cos(x)-1)

[rocky lotus]

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Requested by flop_ed

[viscid hawk]

how did it get there??

,w d/dx (x^2cos(x)-1)

[rocky lotus]

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Requested by flop_ed

[viscid hawk]

uhhh..

what did I do wrong 😭

am I finished??

[proud leaf]

easy equation

[viscid hawk]

no no

[vapid sand]

Bro that does not help him

[viscid hawk]

I was double checking my math

[proud leaf]

want me to help you or sum

[proud leaf]

is it wrong or what

[proud leaf]

aight aight

[viscid hawk]

am I finished? (ignore the mixup where I don't have the -1/2 power on the first x

[vapid sand]

Sorry I am tired lol

I am evil

[proud leaf]

it was wrong from the begining man

[proud leaf]

np

[viscid hawk]

ngl no clue how it got here from what I have but for now I won't have to solve farther if what I have in B has as much trig canceled out

[viscid hawk]

wait wdym

[proud leaf]

the first rule is
d(numerator) * d'(Denominator ) - d'(numerator) * d(Denominator ) // (Denominator )^2

you didnt do the Denominator

oh my bad

[viscid hawk]

wait yeah I did though?

[proud leaf]

sorry i didnt finish reading

but the cosx one was wrong

cause its like Product Rule

[viscid hawk]

can you point it out again? I do have a square in the denominator

[proud leaf]

this one i mean

[vapid sand]

Negative sin

Oh wait he put derivative markers

So it should be fine

[viscid hawk]

and i do take it as (f/g) = (f'.g-g'.f)/(g^2)

[proud leaf]

thats the rule

[proud leaf]

wait fr?

i dont get it why people do it it tricks me sometimes

[vapid sand]

Well I am assuming he later takes the derivative of them if he puts the markers

[vapid sand]

Yeah I think it’s dumb too

[proud leaf]

he did it wrong too

[vapid sand]

It’s very bad practice I think

[viscid hawk]

ah I call it the power rule, I meant product my bad

[proud leaf]

ong man

[proud leaf]

same thing

[viscid hawk]

I take all the steps, I'd use d/dx but it takes longer to write and takes more space on paper

[vapid sand]

Just put it as 2x times cosx plus negative sin x times x squared

[proud leaf]

power rule product rule chain rule they all the same rule

[viscid hawk]

I kind of write big, so every inch matters

[viscid hawk]

look at the step below it

there are two pages (And a page gap)

[proud leaf]

twin you gotta change your way of doing math this lowk tricked me

[vapid sand]

Wait sorry can you restate what your question was again and your work I am too lazy to look back at it

I came in late

[proud leaf]

let him talk first

[vapid sand]

lol

[viscid hawk]

I'm wondering if ((1+x^(-1/2))(x^2cos(x)-1)- x*(2cos(x)-xsin(x)))(x+2x^(1/2)))

over the denominator is as far as I can go

in terms of reducing the trig functions

[proud leaf]

show me the original equation

[viscid hawk]

this was my last step

the original equation is at the top

[proud leaf]

am lazy to go back up there

mention me

[viscid hawk]

still the same message lol

[vapid sand]

Bro wtf how fucking evil is your teacher

[viscid hawk]

"place I got stuck" is the exact thing I just sent a screenshot of, the only difference is I accidentally missed the power on the first x in that screenshot

[vapid sand]

That is not okay

That has got to be against the rules

Why would he ever assign something like this

[viscid hawk]

uhh... I've had two evil calc teachers... so I thought it was normal?

be hard on the students and they can survive calc 2 is their mindset LOL

[vapid sand]

First of all cancel of out one of the x^2 times cosx - 1

[viscid hawk]

I took calc 1 in my sophomore year of HS but I dropped it by second quarter cuz I didn't think I could survive. I bombed the sem. final so I got away with a low B and an incomplete for the class :')

[vapid sand]

Rip

[viscid hawk]

now it's college

[proud leaf]

isnt it supposed to be -1/2?

[proud leaf]

exactly my thought lmao

[vapid sand]

I am a Sophomore rn, I took BC last year and Multi, and my multi teacher was also evil so I feel for you

[viscid hawk]

(yes, I forgot to add it)

[vapid sand]

Also did you do this yet

[viscid hawk]

BC is so much more forgiving than calc 😭

way easier

[viscid hawk]

how though? there is a minus sign in between them

[proud leaf]

he could use one of the Identifications too

[viscid hawk]

also, there doesn't seem to be a way to do that

[vapid sand]

Ok I am home now let me work it out on paper rq

I will be back when I finish

[viscid hawk]

this is the question in wolfram

[proud leaf]

he meant these

[viscid hawk]

sooo... atp am I done and it's basically just... expanding?

[proud leaf]

you could cancel the ^2

[vapid sand]

Wait which one is the derivative you are trying to find then? The one in wolfram is a different one

[proud leaf]

literally missed alot of steps

but good work

[vapid sand]

Also yeah sorry I was walking and didn’t see it

You can’t do that

[viscid hawk]

y'all both confusing me 😭

[proud leaf]

thats how math is

am specialised in integrals and diifeq so @vapid sand help me twin

[viscid hawk]

I didn't skip any steps, it was four steps and then I think wolfram just expanded at that point but nothing really cancels in terms of trig functions / finding trig identities to cancel things out

[vapid sand]

Ik give me five I am solving it on paper

[proud leaf]

its ez but there's some tricks

[viscid hawk]

I'm just wondering why my teacher gave me a problem with such an unclean answer

[proud leaf]

its clear but kinda there's tricks

[viscid hawk]

my last problem is to find where the normal line at (-1,1) of x^2-xy+y^2=3 intersects a second time into the graph

[proud leaf]

use Identifications if you know some

[vapid sand]

Holy fuck this is hell

[viscid hawk]

I'm checking, and there's nothing that cancels out.. because I'd need some squares on the cosines I believe?

[vapid sand]

I need like two lines to write the whole thing

Yeah no nothing does

[viscid hawk]

alright so that problem is done...

[vapid sand]

No wait

I am still doing it

[viscid hawk]

for this one, I have to set it to y=mx+b form and then use limit as h -> 0 of the whole kinda eq right?

for the f(x+h) yadayada eq?

I'm guessing that's what it means by "normal line"?

[vapid sand]

Okay if you don’t simplify anything at all this is the answer, don’t mind the numerator, it’s that whole ass top thing in the box

Sorry I would simplify it but maybe another day

[proud leaf]

literally what i solved

[viscid hawk]

the sideways picture makes it difficult to read :')

[vapid sand]

Wdym

[proud leaf]

i solved like this but i applied some simplifications

[vapid sand]

Where though

[proud leaf]

it took a whole ahh page to simplify

[viscid hawk]

ahhh you took the second derivative of the original eq (which was asking about the first derivative) of (x+2x^(1/2))/(x^2cos(x)-1)

[vapid sand]

BRUH

that was already the derivative

I am going to end it bro

[viscid hawk]

I hate to break it to both of you, but I'm wondering how you misread so much information lol

[vapid sand]

Took the second for no reason

[vapid sand]

Bro because I asked what is the question, we were trying to find the derivative, and you sent that equation

It’s okay

[viscid hawk]

I was wondering if that was the clean derivative (in terms of reducing trig functions), and wolfram kinda already says so

[vapid sand]

You can find concavity now

[viscid hawk]

look at what I typed to wolfram...

[proud leaf]

its clean if your teacher says otherwise touch him

[viscid hawk]

I already gave him my eggs /insidejoke

(context, I have chickens, he got chicken eggs)

[vapid sand]

Agreed

[viscid hawk]

sooo for this last problem

[vapid sand]

Well finding that second derivative I think was all the derivative practice I need for a year

[viscid hawk]

is this correct?

I should substitue y=1 for all the y values, right?

[proud leaf]

thats the answer

i am too lazy to solve it so i used a tool

[viscid hawk]

ahh thank you

[proud leaf]

np

[viscid hawk]

kind of weird how I'm solving without derivatives, though?

[vapid sand]

No your teacher hates children so he is probably just going crazy and handing out random problems atp

[viscid hawk]

well, it's my only homework assignment with like 6 questions before the next unit test so

[vapid sand]

Actually wait it wasn’t even that bad

The only reason I thought it was hell was because I was taking the second derivative

The first was very easy

[viscid hawk]

he keeps saying it is the "bare minimum", at least I'm not getting pop quizzes on all of trig like I was in my high school for the first two weeks

[vapid sand]

The second was just absolute hell

[proud leaf]

so we agree he should be touched

[proud leaf]

which one

[viscid hawk]

mm I also found the second derivative of y=e^(tan(2x))+sin(e^3x)

[vapid sand]

Yeah but not too hard because taking the first derivative wasn’t that bad

[viscid hawk]

But I did that by myself

[proud leaf]

i once got 3rd derivative

[viscid hawk]

ended up being a long aaa thing

[vapid sand]

The BC exam last year was such a scam bro

[viscid hawk]

but what is the point of that? beyond acceleration, like actually what is the third derivative?

[vapid sand]

I got a 5 but they had a polar and two series on the frq

[proud leaf]

volume and shi

[viscid hawk]

ahhh I forgot

[vapid sand]

They have a polar like once every five years and have like never had two series (albeit they always have one)

[viscid hawk]

We didn't do much of that... not even in ap physics so

[vapid sand]

It’s for mass in multi variable

[proud leaf]

there's an annoying nerd on help 33 i just wanna block him

[vapid sand]

And for like some other stuff

[viscid hawk]

does anyone have a clue on how my teacher probably intended for me to solve the last one?

I understand how the easy way works, but he was very clear that we needed to understand how to apply limits/derivatives as well

Makes no sense that the last question involves none of that

[proud leaf]

anything else you need help with

[viscid hawk]

uhh besides that, nope

[proud leaf]

aight if you need anything tell me

[vapid sand]

Wait

I can explain

I think he probably wants you to obviously find the normal line which you first have to find the derivative to do, and he probably wants you to use that and then take the derivative again to find at what points it intersects the graph

That’s probably the easiest way

[proud leaf]

@viscid hawk how old even are you

[viscid hawk]

it says in my bio...

I'm 19 😭

[proud leaf]

ah normally i dont go to people's bio

[viscid hawk]

You guys are just proving people on discord have trouble reading

oh, well, ig that's fair

(not to diss you guys, just it's kinda amusing rn as I'm frustrated)

[vapid sand]

Bruh

[viscid hawk]

I can't read either, I'm dyslexic and have dyscalculia too.

[vapid sand]

Also does this make sense? By using the derivative I mean finding the mins and max’s to find the zero. Albeit the easier way is algebraically setting it to zero and solving

[viscid hawk]

lol it was mentioned when I first started this at like 4-5 hrs ago

😭 5 hrs on homework...

[viscid hawk]

hmm alright

so the derivative at (-1,1)

[proud leaf]

try two days on homework

[vapid sand]

Don’t worry, I have to get up at 5 am to take an online class before my Japanese high school as I am in Japan on an exchange year and I don’t want to lose my math skills, so whatever your sleep schedule is trust me I got it worse lol

[viscid hawk]

I was sick for the beginning of this week, so I did actually only have two days, but I've been feeling awful since

plus, homework is due the day after he teaches us the last stuff

[proud leaf]

send me the equation again

to double check

[vapid sand]

Well the calc part of the question is just taking the derivative at the point and then the inverse to find the normal line

[viscid hawk]

I feel you lol, normally I'm to bed at 10 pm and awake at 6 am whether I've slept enough or not.

[vapid sand]

Bruh that’s still like eight hours lol

[viscid hawk]

x^2 - xy + y^2 = 3

[viscid hawk]

yeah, sometimes I can't sleep