#help-4
1 messages · Page 48 of 1
ye
so that can be re-written as : 4x^2 - 4x^4
ye
and you replace x^2 with some other var.
ye
ye
ye
that's a quadratic equation
but its y^2
do you understand the next step?
i think so
because y = sin(2t) -> y e [-1,1]
1-y^2 e [0,1]
we have sqrt(1-y^2)
if 1-y^2 e [0,1] the sqrt of that e [0,1]
so its between 0 and1?
yes
let b = sqrt(1-y^2)
our two values become r^2= (1-b)/2
R^2=(1+b)/2
because of the quadratic
since b is between 0 and 1
1-b is greaterequal 0
and 1+b is greaterequal than 0
both r^2 and R^2 are greaterequal than 0
both are nonnegative and the - root is the smaller one
the inner radius
r^2
so we have the two radiuses now you integrate for 1 -1
pi integral 1 -1
i solved wait so R^2 - r^2 is sqrt(1-y^2)
so V = pi integral range 1 -1 of that
Pi^2 /2
um
where are you stuck?
ok so its between 0 and 1 since 1-y^2 =0, y=0,1
and im stuck on the greaterequal to 0 for r^2 and R^2 and how is it squared if x^2=(1+/-sqrt(1-y^2))/2
and like where did the radius stuff come from TT
wait wait
so, we solved that for a fixed height we got x^2 = (1+-sqrt(1-y^2)) /2
this is clear right?
ye
let's replace the square with b so b = sqrt(1-y^2)
yep
it's easier for me to write as well
so we have y = sin(2t)
that's between -1 and 1
is that clear?
y = sin(2t) -> y is between -1 and 1
so y^2 is between 0 and 1 from here
okok
yes
y^2 can't be negative
and it's always between 0 and 1 cos y is between -1 and 1
so 1-y^2 will be also between 0 and 1
you can see it directly
if y = +-1 then 1-y^2 = 0
if y = 0 then 1-y^2 = 1
thats the limits
the endpoints
yes ok
y is between -1 and 1 if you replace y with 1 -1 and 0 you'll see it
that 1-y^2 is between 0 and 1
is this clear so far?
so we get outer and inner radius from here
yes
max|x| among the intersection points and min|x|
outer radius R^2y = maxx^2
or (1+b)/2
ok
ok
what?
R^2 - r^2 yeah
the integral is pi integral (range from 1 to -1)
of A
i mean the pi from A goes infront
ok:
A = pi ( (1+b)/2) - (1-b)/2) )
A = pi sqrt(1-y^2)
V = pi integral (from 1 to -1) sqrt(1-y^2) dy
or in other words:
pi and area of semicircile radius 1 which in the end is pi^2/2
where b is from before b = sqrt(1-y^2)
so A = pi b
but how do u solve that by hand
integral of sqrt(1-y^2)
ye
what is b?
the circle is x^2+y^2 = 1
y=sqrt (1-x^2) -> upper semicircle
x = b right semicircle
y is between -1 and 1
so b is semicircle of radius 1
ok
the area is Pi/2
ok
ok
no the thing is
this question is part 3 of this booklet we have to do right
and for the other questions
😭😭 sorry that took so long
it's cool
i think i got most of it
if you're confused about a part ask
itrs js the R^2 and r^2 thing... i think i get it but.... so like would it matter if i did r^2-R62
yes
r^2 is the smaller radius
the inner
R^2 is the outer
of the figure
the area is outer - inner
pi outer^2 - inner^2
bad drawing
inner and outer radius
pi sqrt(1-y^2)
pi (R^2 - r^2)
see the 1 -1? that's the integral (1 -1)
@frozen tree Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
X - sinx/x + cosx why is this not 1 gang
Lim x tends to inf
Sinx/x goes to 0
as x -> inf, the x term -> inf
Yes
Alexis_Fx
as x -> inf we can disregard the sin(x) and cos(x)
since their contributions aren't really significant
Sinx cosx can only be -1 to 1 so they become 0 when x tends to inf
.

How
because of the x in the denominators
why do you think it's not 1?
Is it this: $x - \frac{\sin x}{x} + \cos x$?
Alberto Z.
It's 0
Nope
put brackets then
I forgor the brackets
they said it's this one
Well, it's a typo then, very likely. Either a misprint in the answer key or in the question itself
Are u extremely sure
Yeah o wanted her to realise but I know it's too much of a request 🙈 🙈
$99.\bar{9} %$
Can u really cancel out x it it tends to inf? It's an indeterminate form isn't it? Inf/inf can't be cancelled
Alberto Z.
nah you can
they grow at the same rate
never of such a weird fact
$\lim_{x\to\infty}\frac{2x}{x} = 2$
frosst
$\lim_{x\to\infty}\frac{2x}{x+1} = 2$
frosst
$\lim_{x\to\infty}\frac{2x+3}{x+1}=2$
frosst
you can really just cancel it
(100000000^100000)x and 2^logx grows at the same rate too
Not at all
Sorry i changed
Still not
Depends on how you bracket it and what base the log is in
For example (100000^1000000)x and 2^{log_2(x)} grow at the same rate
They are both multiples of x
Yea
$\lim_{x\to\infty}\frac{x^2}{x^3}=0$
frosst
Huh?? They are a power and a log (or, if you really mean what you've typed, they're a polynomial and a power containing a log)
the numerator and denominator don't grow at the same rate
Can we cancel inf/inf?
i said we can "cancel the inf/inf" but like i was lying
No, of course
Limit 1?
it's true we can cancel but it's not cancelling like a fraction
Both of them are polynomial asymptomatically
"inf/inf" is sometimes 0, sometimes inf, sometimes a number
Here you can cancel
(asymptotically)
For the question i posted what will be the answer? @pallid oasis
Aq to u
This question?
1
The answer was 0
Ok
but it is
is it this, or the one replied to by shiru?
it's that one
theyre the same lol
argumentum ad populum btw
That's not how it works
Skewed distribution
It seems like you have gotten adequate hints to solve this as well
oh oops, i thought you were referring to the one written by alberto, my bad
I got 1 as well but the answer was 0
did whoever telling you it's 0 also tell you why?
No it was the answer key
and the answer key has no working provided, i presume
No
looks like it's off to the teacher
@vernal folio Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
can someone please explain this question?? and answer
<@&286206848099549185>
!15m
Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.
Is there any way that we can convert any time series graph into a taylor series function !?
!occupied, sorry
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
tnx
well, we know the gradient of a graph is how steep it is at a given point, i presume?
yes
so if we consider the first part of the graph, from the left side until the turning point there
from what i know, derivate is basically gradient of a function, and i think its A because the the function y is going up
the graph is going up, sure, but it slowly tapers off towards the turning point. agreed?
It has 2 turning points hence we can rule out ABE
yes but then it goes back up no?
no, it heads down
it heads down towards the second turning point on the right first
then it tapers off again, and heads back up
so at two points the gradient is 0
And then just observe the part between two turning points
It starts from flat, decreases and then reach some max decrease and starts increase and becomes flat at the other turning point
so if derivative = 0, the points will be a postive number and a negative,
If derivative = 0
derivative = 0 just means that the gradient is 0
The graph would have a turning point
meaning at that point, the graph is "horizontal", if just for a bit
Right
this happens at turning points
because for a graph to turn, it has to first be horizontal for a little bit
so the answer is e?
Nope
e has been ruled out already
We have two turning points in the graph
it can't be e because we have two turning points, so we need the gradient function to cross zero twice
explain
it crosses x axis twice
But C also crosses twice
the graph is negative?
what graph is negative?
At which part?
you've got to clarify this one
from max to min
Not quite
so you're saying that between the two turning points, the slope is negative, therefore it's D?
you're correct in saying that the slope is negative between the two turning points
but that is exactly the reason why D is off
From max to min, the graph first increases the rate of decrease, and then decreases the rate of decrease to 0 so that it can reach the min and not continue to decrease
consider the region of the graph of D that's in between the two zeroes
is it positive or negative between the two zeroes?
its is c because the graph eventually rises, hence the gradient must be positive, and should cross x axis twice, which seems just like C
Right!
incomplete reasoning, but C is indeed correct
C is correct here because the graph starts out with a positive, but decreasing, gradient
it hits 0 at the first turning point and then has a negative gradient, which slowly increases back to 0 near the second turning point
after the second turning point, the gradient turns positive again
which is exactly the situation described by C
i am a bit confused, what would be a proper explaination for this then?
i just gave you the proper explanation
is there any part of the explanation that confuses you?
so the derivate should basically explain the situation of original graph?
the slope of the original graph
i think i get it
nope, thank you both so much
If you are done with this channel, please mark your problem as solved by typing .close
.close
Closed by @floral vigil
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
does anyone know how to solve this quadratic equation?? i have no clue since i was only taught how to solve them when they’re in standard form
Well, you can still use the classic quadratic formula, however, you need to plug i for the determinant, using i = sqrt(-1)
this one you can just solve outright
have you studied complex roots?
Yeah, this
no we haven’t started
for the time being, u can just say that there exists no real roots by checking the discriminant
what is a determinant
so ur b is 0
7x^2=-3
x^2=3/7
x=± √(-3/7)
if the discriminant is negative that means there’s no real solution right
there is no real answer as sq root of -3 is just impossible to find
so if i just put no r sol i would be correct??
you do need to show steps and then say that
wait can i show u mine
sure
if it says find discriminant then u use formula
you can just solve it right away if it says find x
no way you write 8 like that 😭
the question just says solve
then just solve for x, no need for the formula
how r u supposed to 😒
huh
wdym you need the formula tho
do i just use my calculator then
this is the quadratic formula, if it says use this formula then use the formula, if it just says solve you just find x using algebra
7x^2=-3
x^2=3/7
x=± √(-3/7)
this way
through the formula??
no the algebra part, i don’t think she’ll accept it
then use the formula
yes
so it would be this right
yes
If you are done with this channel, please mark your problem as solved by typing .close
Closed by @long quail
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I think i messed up idk if you can change sum and integral operators with an improper integral, ik its int from a to b but idk if a or b can be negative or positive infinity
@lavish totem Has your question been resolved?
Closed by @lavish totem
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hi guys
hi
uhm do u guys know trigometry
!da2a please, just send your question over!
No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
ouu okayyas
sorry im new here
no problem! it's encouraged to just send your question so helpers can immediately see them
also, the bot pins your first message, so it makes it easier for helpers to see your question if your first message is itself the question
gentle reminder to OP to share question, if you have one
@spring stratus Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Fellas
what properties of the determinant do you know, that might be applicable here?
ok toss ur answer + work
3^6 x 6^2
yep looks good
If you are done with this channel, please mark your problem as solved by typing .close
@vernal folio Has your question been resolved?
As op is not responding and his doubt seems to be solved
I'll close the channel
.close
Closed by @craggy girder
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
.close
.close (He's gone)
Closed by @river shale
Use .reopen if this was a mistake.
:((
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
how do you find B and C
similarity
do you see that little 3 - 4 - ? triangle
it's similar to the big one
well, since the ratio is equal, c/4 = b/3 = 12/5
now just solve it
that's a key property of similarity
equal ratios of corresponding sides
np
Closed by @silk magnet
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Need help with this don’t know what to do
Plug in the values of x into the equation
So for the first point, we want to find y when x = 1. So if x = 1 and y = x+1, y = ?
Ik what to do on the top part I just don’t know where to put the points at
Ok well your horizontal axis is the x-axis and the vertical is y
So you want to select the points which have a horizontal (x) coordinate and vertical (y) coordinate that match your results
Does that make sense?
But how do I know what side to start on the left or the bottom. And not really
1 sec
Here's the first point as an example
Notice that horizontally, it is 1 square to the right (directly above the "1")
And vertically, it is up 2 squares, which is directly to the right of the 2
If you do this right, all 3 points should form a straight line
Have you ever played battleship? @plucky wolf
That's a fire way of explaining this
Ok, otherwise it was the same concept as that game
Not exactly! So the point that you added has coordinates x = 2 and y =6
Huh
That's because it is 2 squares to the right, which is right above that 2 at the bottom, and 6 up which is flat with the 6
So it can’t be touching the same number
You want your next point after (x=1, y=2) to be (x=4, y=5)
It can touch the same number, you just need to select different numbers
Here's the answer to the question
?
Can you see the connection between the points and the numbers in your table?
So, what's missing here is consideration for both the x and the y. While your y values are correct, you need each point to also reflect the x values
@plucky wolf Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
We were learning about finding inverse functions in AP Precalc
We wrote the restriction for inverse of g as x>=2
But why do we need to write that? Isn’t it already implied in the function itself? In the part where it shows (x-2) we can see the restriction already
i mean.... it depends on the teacher
some teachers doesn't require it
but some teachers for some reason gets really offended
just do whatever the teacher told you to, after all, they are the one giving you marks
Oh 💀😭
I thought there was some kinda mathematical reasoning behind it that I wasn’t aware of
Somehow
not really
Alr ty 👌👌
like, my IB teacher doesn't require me to like put down the domain of a function every time we write one
Oh
Maybe my teacher just wants us to practice it
Okey dokey ima close this channel then
.close
Closed by @unkempt maple
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
So I did the one quadrant now I’m in to 4
where exactly is your question
Idk how to do the points on these ones
what does "do the points" mean
yes i see the graph of the line
(-1, 7) is selected which is correct.
what are you stuck on?
I just don’t know if it’s correct cause it’s going in different quadrant
what is "it" in "it's going in a different..."
not sure what you're trying to indicate with that line
I’m asking is it OK for it to go in different areas cause I thought it was only supposed to be in the areas where equals?
still not sure what you mean by "it" in "it to go in different areas"
all lines go through more than 1 quadrant
Are u able to just show me get to do it
i don't know what you're stuck on or what your question is
I want to also know if it’s right or wrong
you did this point correctly. did you use the same method to pick the other points
Yes but idk if I should keep going after that
in no uncertain terms, explain the goal of the exercise
because I'm an observer and I also don't know what you're being asked to do
Does anyone know what Wolfram Math is?
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
I just need to know when I’m trying to stop on an equation
try plotting one of the points and we'll tell you if it's correct or not
Im at this one I need to know if im done or not or need to do the one below it
If i may-
So this is just a faster way of doing?
But I don’t know why it’s only letting me place two dots not more than that
?
i cant answer technical difficultys on the app. what course is it on ixl?
Algebra
Oh i see. you only need 2 points.
I’m at 50 need 80
Nvm i see why u talking about
What*
I’m talking about my score
what about the score?
My score is at 50 and I need to get that 80
So I need to answer a question to get to 80
that I’m trying to hurry up and get this done so I can do my test cause I have to do test after this
just answer more questions if you want the score higher no?
Yes, you’re right. I just don’t know what to do to get the questions done
This
press that
But is it right? What I put down
like this no?
6-6 is good but
the first point x-8 and y-1
is wrong i think.
you have it on y-2
yours?
Yours
Are u able to help with the rest till I get done?
It’s chill
well i can look at it. but im no pro haha
Painting gimi a sec
K
Let me check
?
so its not on x-8 y2
you have a point on x-1 y2
smthing more like that
i belive
The hats right I’m at 64
correct?
Yes
Yay
No on too this
K
Where the ? Is are all those supposed to be ones cause I don’t know if we’re subtracting or what cause it doesn’t say.
y = 1
that means its just 1
only x changes.
draw it up for me :3
y 1 and x-4
y 1 and x 7
well. almost. you mixed up Y
you have it on -1
not 1
so its below where it should be
X is correct.
see?
Compeare the last image i sent ya. to the one you just gave me.
see the green line?
Yes
where would 9 be
I see now
ye good, now point to 9 on the Y axis
okay. were getting there. so now one point is on Y 9.
Dose Y ever change?
or is it "static"
Static
right. so where should the other point be?
It would be 9y 9x?
Why 9 x?
I meant 5x
hmm. here perhaps this will help
So the
Orange is X
and Purple is Y
Green is the result.
so. one of your points is correct.
Dose the "purple - Y" add up with your second point?
so where should it be? on Y
Like this
Ah i see where your caught up.
Lets define it like this
1 point on the graph. is the Combiantion of 2 values. Y and X yes?
alright so. why is Y value of one of the points on Y0
And X0
you have 2 points right now.
One point is on X -1 Y9
the other is X0 Y0
when you should have something more like X0 Y9
X5 Y9
Better. now you have one point on X0 Y9 and the other on X5 Y0
So one Is correct. the other you need to alter the Y value to 9
why did you change the X0 Y9 point to -> x-1 y9
see?
Ye I think
Like this?
Your X is correct yes. but the Y is still wrong on the second point.
x is correct yes. by y is wrong. perhaps this will help
Do you see where every axis is?
and what numbers they have?
No, not really I don’t know which side is going to be negative or not
ah i see.
well look at the numbers for one.
so top and right is positive
left and down is negative
Red is negative Green is positive here
sadly i cant. but you are very close. lets go back to this.
this point here
is the problom rn
now you did y - 2 now its at y - 1
you moved the Y down
to the nagative values
move it to y9
This shit Is yo confusing
OKAY its the correct direction.
So it’s right
no- but your getting closer
i want you to point to what changed rn.
like draw a line or something
Idk what changed
That the bottom is negative and the top is positive
do you know how to tell where ON the y axis something is?
?
the y axis has numbers yes?
Yes
So what are u trying to say idk what your saying
do you understand what i mean by value of y ?
No
Yes
Y
so can you point to Y 4
circle it for me
yes. so what is Y 9
are you circling 10? or lower?
Lower
aigh. so what Y is this on?
Idk
and what if i were to do this-
5y
mmm- so lets try again, point a line at y9
a straight line
a line that goes along Y9
Yes. good. now. if that is y9. what is the blue point on that isnt on y9 on?
what Y is it on?
Idk this is confusing
lts focus on this point
What do you mean focus
5 and 9
yes- and what Y should they both be on?
ah. we will get to that.
5 and 9
so. here you see a list. yes?
Yes
you see how the y is always 9 ?
👍🏽
So that’s it?
Yes
so what Y should the other point be on.
5
why do you think that?
i want you to point where you are getting the 5 from
-9?
Ye
you see how these are conected yes?
Yes
what if i were to do this-
What are u asking me
do you see how the X is connected to the graph?
No
Yes
so- if we put them on top of each other
you see where the lines cross each other?
Yes
But I can only place 2 points
yes you only need 2. it gives you 5 values
but the 5 values only show different POINTS on a line.
you need to draw the line
Well, what about the five don’t has to go vertical
so do you understand a little bit whats going on here?
using the same logic?
we just used?
we can do better- as the line is correct but one of the points are a little off
that might trigger a fault
so on the picture i sent
you see how 1 of your points dosnt line up with a intersecting red and green line?
i want you to line it up
is that lined up?
remember how you lined one of the points up?
with the green and red lines
right at the intersection
No
Yes
do you understand why we put the point there?
I can only place 2 so do I move one
yes you do need to move one. but do you understand why
Cause don’t look great
hm?
The first one looked right to me
So I don’t know what to do can we go to the next one cause this one is confusing
Like you said the first one was right, but then you said we can do better like what else can we do to make it better?
And you’re saying draw a line I don’t know which line I’m supposed to draw in which point to take away
the line. is drawn between the points you place down.
the list gives you the location of multiple points. from the list you choose 2 points
your LINE between the points was correct. but the location of the points themselves was not.
Idk what your saying I have to do way more questions we been on this for 2 and a half hours
you need to understand Why your doing what your doing. not just doing the questions.
if you understand why you can do as many of them as you wish
Tell me what you dont understand
I don’t understand where number is cause they’re both weird and it just looks weird like the left side is also y the right side is also y like it’s just confusing
I’m a visual learner so just typing isn’t really working that’s why I’m used so like pictures and stuff
hm.
alright.
this is a visual indication
of the numbers
and where they are on the graph
are you following with me so far.
Yes
and you understand how the red is pointing to the X axis
and the GREEN is pointing to the Y axis
yes?
if not say so and il explain that
more in depth
I see
No
okay- the point where the lines meet. is the location of ONE of the TWO points you need. do you understand why?
- i need to go sleep. can someone else pick this up T.T
@plucky wolf Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hey Im trying to find the sides of this window
i know its 10=2x+2y+ something
Im basically trying to find the curved length
the radius would be 2x divided by 2
cool, maybe don't crop off the first sentence of a question next time
so you know the curved part is half of a circle with radius x
do you know how to write down what its length is
Idk the formula of the perimeter of the circle
that so?
does C = 2πr look foreign to you?
i mean, what did you even think the number pi was if you somehow went without knowing this
It doesn’t but I havnt touched it in a long time
dawg did you think pi was just a funny number mathematicians made up for no reason 😭
I lowk think you are baiting bro
what’s there to be bait about bro I’m fr 😭
I was always bad with this
oh so you just never thought about that beyond this.
got it.
well you will have to somehow burn the formulas for the area and circumference of a circle into your brain mate
they are also easy to Google unless you have fingers falling off disease (which iirc you don't)
(or OP can just directly WA in this channel i think?)
wa?
yeah if he has a severe form of cant get off discord disease
which iirc he also doesn't
So half of it’s just pi*r
well yes only instead of r you got x
but woudnt that account for this length as well
when you find the circumference of a circle, does it include the diameter of the circle?
Nope
then why are you worried the circumference would take into account the diameter?
where did the extra 2pi come from?
pi*x
i said this, did you see it?
so 10= 2x +2y + pi*x
yes
Closed by @north scarab
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hello
What do you need help with?
sorry i needed help answering question 3
Do you have any thoughts on what the answer is? 
i did but i think im doing it wrong because its saying theyre incorrect
Well, what did you think the answer was?
4
Ok. The thing to note about limits is that they are not concerned with the actual value at c given x -> c. Limits are only concerned with the value of a function as it gets infinitely *close * to x = c.
oh alrighty
What do you think the answer is now?
im sorry im not entirely sure
The limit is x -> 3 so you have to look at what the function is doing on both sides of x = 3.
right
Try to imagine a point on the left side and right side on the line. What value of y is it approaching?
is it 2?

