#help-4

1 messages · Page 45 of 1

merry jasper
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mb, we currently stopped at the quotient rule and then went to finding the derivative of trigo, explaining chain rule and general power rule

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which part does it explain the f'/f^2

fringe niche
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i think you need to watch the whole thing to understand the lesson as a whole

safe fulcrum
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and the power rule of course

fringe niche
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but it's 40:23

safe fulcrum
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so $\frac{1}{f(x)}$ is $d(f(x))$ where $d(x) = \frac{1}{x}$ right

rocky lotusBOT
fringe niche
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yeah consider 1/tanx as tan^-1(x)

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and apply power fule

safe fulcrum
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tan^(-1) (x) = arctan(x)

fringe niche
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no

safe fulcrum
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jesus christ just google it

fringe niche
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tan^-1 is a power

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not the reciprocal

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that's why arctan even exists

safe fulcrum
fringe niche
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to avoid the confusion

fringe niche
safe fulcrum
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no, tan^(-1) (x) means arctan(x) unambiguously

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you can write (tan x)^(-1) if you really want 1/(tan x)

fringe niche
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that's just a nitpick

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most people write power on the function

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rather parenthesis

safe fulcrum
fringe niche
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never seen that before

safe fulcrum
fringe niche
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to avoid confusion arctan was made

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and arctrigfunc in general

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which is why it's not a problem

merry jasper
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So i just apply the f'/f²?

safe fulcrum
fringe niche
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only calculators use power -1 for a reciprocal trig func

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afaik

safe fulcrum
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do you agree that by the chain rule, $f'(x) = 2 \cot 3x \cdot \frac{d}{dx} (\cot 3x)$?

rocky lotusBOT
fringe niche
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yeah

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why would u leave it as d(cot3x)/dx

merry jasper
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so this is correct?

safe fulcrum
merry jasper
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this is the function im trying to solve

fringe niche
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this is taking waaay too long

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just apply the simple rule

safe fulcrum
fringe niche
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i think chatgpt should be able to do these

fringe niche
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squared

safe fulcrum
rocky lotusBOT
safe fulcrum
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there's actually another chain rule, so you multiply by 3 cause it comes from d/dx (3x) = 3

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and then the derivative of cot is -csc^2

so -csc^2 (3x) cause you leave the inside unchanged
then multiply by 3 from another chain rule

fringe niche
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he got confused and multiplied the 3 by the 2 he got

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but the first line is correct

safe fulcrum
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yeah so the (1 - ) should not be there at all

fringe niche
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why not

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mutlplying by 1 does nothing

safe fulcrum
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no, there's a 1 - csc^2 here

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and that's wrong

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I think they misunderstood the chain rule

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oh yeah they misread what they wrote

merry jasper
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This calculus video tutorial explains how to find the derivative of trigonometric functions such as sinx, cosx, tanx, secx, cscx, and cotx. It contains examples and practice problems involving the use of the product rule, quotient rule, and chain rule.

Derivatives - Free Formula Sheet:
https://www.video-tutor.net/calculus-formula-...

▶ Play video
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this is the vid im following

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24:39

safe fulcrum
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the 1 is the exponent, so $2 [\cot 3x ]^1 \cdot - \csc^2 (3x) (3)$ is correct

safe fulcrum
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we're telling you what exactly you did wrong

rocky lotusBOT
merry jasper
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thats my first line

safe fulcrum
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so that simplifies as $2 \cot 3x \cdot -3 \csc^2 (3x) = -6 \cot 3x \csc^2 3x$

rocky lotusBOT
safe fulcrum
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in your work, you didn't write the multiplication

merry jasper
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where did the 3 come from in -3csc

safe fulcrum
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so csc(3x), differentiate the inside and you get 3

merry jasper
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ohhh, its the

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derivative of the

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3x

safe fulcrum
merry jasper
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and then you multiplied 2 and -3 to get -6cot

safe fulcrum
safe fulcrum
merry jasper
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oohh okay, let me try the number 10

vale dockBOT
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@merry jasper Has your question been resolved?

merry jasper
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,w d/dx -csc(1/2x)

merry jasper
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okay mb wiat

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@safe fulcrum

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oops i forgot x on the cot1/2x

safe fulcrum
merry jasper
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okay

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.close

vale dockBOT
#
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vale dockBOT
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shrewd vine
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Hey i have a problem, i need to study the signs of the following function : g(x) = ln(1-x)+x

Can someone help me out to find how to tackle that?? Just by giving clues or something like that as it's not a product

verbal badger
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What do you mean by “the signs”

drifting hornet
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like when it's positive and negative?

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I'd try looking at both the parts and examining those individually first

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perhaps plot a graph (or sketch)

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if u know some calc, you could use it as well (study the derivative)

shrewd vine
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Yeah it was about positive and negative but we found a way with my friends

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But the derivative doesnt really help as it would give me the variations, but we just made it so we compare it to an exponential, that is always <0 , and we got 1-x>e^-x , and so >0

drifting hornet
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if so then its wrong

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the derivative does help btw

shrewd vine
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Wait i can send a pic but i'll close the help channel later

drifting hornet
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wait no

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it does work

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okay so you got to 1 -x >= e^-x

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how did you conclude that ln(1-x) + x >= 0?

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because that conclusion is wrong

viscid spade
shrewd vine
drifting hornet
# shrewd vine Why??

because it is wrong. The question is how did you arrive at that faulty conclusion

shrewd vine
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Maybe it is on the interval the function works

drifting hornet
shrewd vine
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]-inf;0[U]0;1[

drifting hornet
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and on that interval, the function is negative, except for 0 where its 0

viscid spade
drifting hornet
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g(0) = ln(1-0) + 0 = 0

shrewd vine
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Idk lmao

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Wait i'll go back later to this for the moment i'll close the channel

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Thanks for the help tho

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I have to go

viscid spade
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D'ailleurs pour tout x dans R tu as 1+x <= e^x

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For all x you have that e^x >= 1+x

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But the method that works anytime is using differentiate it and look at the variations + extreme points

vale dockBOT
#

@shrewd vine Has your question been resolved?

vale dockBOT
#
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surreal tide
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What did I do wrong?

vale dockBOT
frozen ledge
weary pilot
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its always the arithmetic

frozen ledge
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limit as it approaches -2 from below not 2 from below

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you did the same for the limit as you come from above

paper fossil
paper fossil
# frozen ledge what

uhh then he can continue to solve as is, then put the value for t, which will give the answer

frozen ledge
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why

paper fossil
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t or h, whatever is comfortable

paper fossil
# frozen ledge *why*

uhhh cuz that guy almost did the right thing, with +2,
its just another way to do it

frozen ledge
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don’t do this

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just read the problem carefully

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-2^- is not 2^-

paper fossil
vale dockBOT
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@surreal tide Has your question been resolved?

vale dockBOT
#

@surreal tide Has your question been resolved?

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ancient berry
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Did I find the correct average absolute deviation?

ancient berry
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I redid it to make it easier to read

normal hollow
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This seems right

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But answer might differ basing on how many decimal places u take to determine the value

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Also put on modulus over each subtraction, js a precaution uk

ancient berry
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Ok

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While I’m here, how do I find the average percent error?

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The true value is given as 88.4

normal hollow
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The answer seems right but u need to put modulus over the subtraction u did here too and it's measured value-true value
So it's supposed to be
|88.3-88.4|

vale dockBOT
#

@ancient berry Has your question been resolved?

vale dockBOT
#
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bitter gate
#

Yall can anyone help me with GCSE- level further maths? Id like to have an idea on how to do the working in some exercises from a past paper ^^

spring jackal
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we can definitely help with that! is there a specific exercise or kind of exercise that you'd like help with?

bitter gate
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Well i have a couple! I js need help with the working really cause i really had no idea on how to solve em. I wanna clearly understand them and like confidently answer similar ones. Ill send some over!

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I have more but i dont wanna send to much😅

normal hollow
bitter gate
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I dont know how to solve them

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And i fear that i should

normal hollow
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I dont think u will need any more than these 3 for the ones u sent

spring jackal
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let's start with 1(a): take $\dv{x}$ of both sides so you end up with $$\dv{y}{x} = \dv{x}\big(4x^9 - 3x^3 + 8 + 2x^{-5}\big),$$ so we are simply differentiating the right side

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there is another rule that's quite helpful, called the addition rule: if you have two functions or expressions, say $f(x)$ and $g(x)$, then
$$\dv{x}\big( f+g\big)(x) \quad=\quad \dv{f}{x} + \dv{g}{x},$$ i.e. you can "distribute" the derivative across addition and subtraction. \ \textit{You cannot, however, distribute it through multiplication.} There is a seperate rule for that.

rocky lotusBOT
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haseeb

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haseeb

spring jackal
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With that in mind, can you simplify the right side of what i sent?

bitter gate
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Hmm

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I have no idea;-; is it like 2d+f+g/dx?

spring jackal
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oh sorry i meant the question itself, the 4x^9 - ...

vale dockBOT
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@bitter gate Has your question been resolved?

bitter gate
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Oh

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Well

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Ill check it out again

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Ty

vale dockBOT
#

@bitter gate Has your question been resolved?

#
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vale dockBOT
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hardy mango
#

Not entirely sure what to do here, know it has something to do with the standard form of sin but I don’t know exactly how area fits into that equation

hardy mango
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Standard form of sin:

rocky lotusBOT
hardy mango
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Oh my fault

wraith heart
hardy mango
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It doesn’t use that equation?

wraith heart
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it only uses y = sin(x)

hardy mango
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I figured because it has the y = sin, and x being equals to pi being the period

wraith heart
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B is not 2

hardy mango
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It isn’t? Isn’t the period for sin usually 2pi?

wraith heart
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yes the period of y = sin(x) is 2pi

hardy mango
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The graph show 3.14 so I figured 2pi over 2 is equal to pi like the graph shows right?

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I might be thinking about it wrong

wraith heart
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indeed. they rounded pi to 3.14

fringe glen
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isn't it just a standard sin graph

wraith heart
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another giveaway is they told you y = sin(x)

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the steps to solve this problem are:

  1. count number of rectangles.
  2. assume they are all equal width
  3. find the width of each rectangle (they're all the same becase of 2.)
  4. find the heights of each rectangle
  5. find the areas of each rectangle
  6. sum the areas of the rectangles
hardy mango
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Got it, just wanted to ask though how are those steps relevant to the information given above?

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Like if that were the case where does sin come into play

fringe glen
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the height of the rectangles corresponds with the sin values of the x axis

wraith heart
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y=sin(x) is needed to do 4.

hardy mango
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Got it, I’ll look into it. Thanks for the help 🙏

fringe niche
vale dockBOT
#

@hardy mango Has your question been resolved?

vale dockBOT
#
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dapper narwhal
#

I am so confused someone said it y=3x+3, y=3x+6 y=2x+2 ??

tawny moon
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!original

vale dockBOT
#

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

dapper narwhal
quiet tide
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that helped so much

dapper narwhal
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sorry

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like idk what the pattern

quiet tide
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what class is this for

dapper narwhal
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wym?

quiet tide
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like

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what class is it for

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that question is effectively unsolvable

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with no context as to what they want

dapper narwhal
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like the figure is adding through and I need to find the pattern as y=mx+b

dapper narwhal
quiet tide
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thats a stupid question ngl i wouldnt think to hard on it

dapper narwhal
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ok

quiet tide
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idk how to do it and i know y=mx+b

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someone might still help tho so dont like close channel

dapper narwhal
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ok

river shale
dapper narwhal
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huh

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oh

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no

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it don;t

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没有

river shale
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它這樣寫沒人看得懂

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你可以簡單說明一下是哪門課的內容嗎?

dapper narwhal
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要找pattern

river shale
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亦或者老師有沒有其他口頭說明

dapper narwhal
dapper narwhal
river shale
dapper narwhal
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哦哦

river shale
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上課內容主要在說什麼

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English or Mandarin will do

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That’s what diamond was asking

dapper narwhal
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找到y=mx+b然后graph出来

river shale
dapper narwhal
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river shale
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你可以截圖一下課本上在說什麼嗎?

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Because the question doesn’t make sense with current information

dapper narwhal
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这不是课本啊,只是homework而已

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hint上写的

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fig 1 就是加了3个啊

vale dockBOT
#

@dapper narwhal Has your question been resolved?

river shale
# dapper narwhal

除非它是一個riddle,不然你老師給的題目條件太少了

dapper narwhal
#

ummm

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我明天去问问吧

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谢谢你for helping

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.close

vale dockBOT
#
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dapper narwhal
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.reopen

vale dockBOT
#

dapper narwhal
#

huh

#

oh

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nvm

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.close

vale dockBOT
#
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vale dockBOT
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brisk grove
#

Having trouble understanding this section

brisk grove
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Theorem 4.1. If a system of equations Ax = b is changed into the new system Cx = d by
elementary operations, then the systems have the same set of solutions.

brisk grove
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My understanding breaks down when it says one variable is pivot in B and free in C

merry crystal
#

do you know how row reductions preserve rank of the matrix

brisk grove
merry crystal
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think of what row operations do:

you add linear combinations of a row to another or swap rows, this preserves the subspace generated by taking the span of the row vectors or column vectors. Hence the dimension of the column or row space is preserved which implies that the rank is preserved

brisk grove
merry crystal
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apologies, im not familiar with this specific matrix language bearlain

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i always view linear systems through rank

brisk grove
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it's fine

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I'll tackle this problem tmr, thanks for the help so far

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.close

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green fjord
vale dockBOT
green fjord
#

if he jumps without skipping any pad, removing block 12, 21 , 32, 23 should work right ?

river shale
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can u show us your grid first?

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cuz our numbers may differ

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@green fjord

green fjord
river shale
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yes, your example works

green fjord
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like 29 options

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where he can't go home

river shale
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alr I figure it out

river shale
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There are 29 of them

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what have you tried?

green fjord
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i can't figure out how the combination works here tbh

river shale
green fjord
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every scenario = 7C2 right?

river shale
#

For example, if you wanna remove the lily pads from the table, how many possible ways can you remove them?

river shale
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that's called "Every scenario"

river shale
green fjord
river shale
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now is the difficult part

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Impossible scenario means "even if you remove the pads, the frog can still get to its home"

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can you find me an example ?

green fjord
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removing 23 33 and 11 21 allows it to go home

river shale
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I take that back

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mb

green fjord
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ahh it's fine

river shale
green fjord
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okk... so 35

river shale
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So now we are looking for the way that the frog can acheive its home

river shale
green fjord
#

7? or was it 7C2 ?

river shale
green fjord
#

yeah I'm talking about tht, there's a formula to it

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and I can't remember it

river shale
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it's the permutation of 2 ➡️ and 2 ⬆️

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ye, fixed again

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💀

green fjord
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😭

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4C2

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the formula was (m+n)C(n)

river shale
green fjord
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goes 2 step to the right and 2 up

river shale
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yep

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now just simplify

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convert every material into the final answer

green fjord
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4C2 is 6

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so 7C2 - 4C2 ?

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that's 35-6 = 29

river shale
green fjord
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thanks a lot 😭

river shale
#

np

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don't forget to close your channel

green fjord
#

.close

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#
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river shale
#

have a good one

green fjord
#

yep

vale dockBOT
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wintry coral
#

Hi I'm currently self studying real analysis and would just like someone to help me check if I made mistakes in my solution, thanks!

wintry coral
#

Will ask in real analysis channel instead

#

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lime bone
#

honey

vale dockBOT
lime bone
#

my honeyboos

#

is determinant signifies the parallelogram spanned by two vectors

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a intuitive thing

vale dockBOT
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@lime bone Has your question been resolved?

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knotty star
vale dockBOT
knotty star
#

Hi is this how you solve this problem?

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As I am trying out this qns but I personally feel that smth is off

keen tundra
knotty star
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So any odd numbers work for this solution right?

keen tundra
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Yes

safe fulcrum
#

yes you could have N = -1 and so on

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modest hemlock
#

yo guys

vale dockBOT
modest hemlock
#

id like to buy the 991ex but how do i tell if they r real or nah

copper stump
#

what does this even mean?

#

is this part of a math question or some irl shopping (in that case you need to read reviews of the item)

errant gyro
#

sounds like OP wants to avoid getting scammed

modest hemlock
#

calculator

#

thought u guys would know idk

wanton jasper
hearty belfry
wanton jasper
modest hemlock
modest hemlock
copper stump
#

ah yes, my bad for not knowing every single calculator model in existance 😭

modest hemlock
#

the most popular 1 for

#

hs

#

no?

#

maybe thats js my system cuz we cant use graphing calca

errant gyro
#

then why not go straight to a bookstore?

modest hemlock
#

cos its

#

not being made anymore

#

theres a new model but its ahh

wanton jasper
#

then just buy it from a reputable source like an amazon official store if that exists

hearty belfry
copper stump
#

>most popular
>not being made anymore
?

errant gyro
#

bookstores should still have old stock, no?

modest hemlock
#

but its terrible

hearty belfry
#

are you talking about cg50?

modest hemlock
modest hemlock
#

991cw

#

its similar tho

wanton jasper
#

@modest hemlock whats ur region

modest hemlock
#

Georgia country

errant gyro
#

guess you'll just have to review scan and pray?

modest hemlock
#

🤣🤣🤣

#

i gurss so

#

guess*

drowsy kraken
#

Not the right server 😭😭😭

modest hemlock
#

Bruh😂

drowsy kraken
#

Or

#

.close

modest hemlock
#

COLDDD

drowsy kraken
#

:((

errant gyro
drowsy kraken
#

Sorry

drowsy kraken
errant gyro
vale dockBOT
errant gyro
#

give them this instead

drowsy kraken
#

Alr

vale dockBOT
#

@modest hemlock Has your question been resolved?

vale dockBOT
#
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#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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verbal hound
#

.

vale dockBOT
verbal hound
#

i used convolution method to find this

#

lemme show my progress

#

for s belongs to [0,1] the indexes of integral i got is from s-1 to s

#

but in solution its showing different

#

i solved all the methods correctly i believe

#

maybe you guys can just make me ensure whether im doing correct or not

#

or just tell me in which line i made mistake

modest stirrup
verbal hound
#

but can u tell me why 0 to z ? idk what im asking but i m still confused and yeah putting index from s-1 to s leads to integral 1

modest stirrup
#

If you are finding pdf of Z, then the value of X can not be more than z. So, X must be between 0 to z.

verbal hound
#

sorry, i still didnt get it

#

is it clear what i wrote above in my solution

#

?

gritty sinew
verbal hound
#

0<u<1
0<s-u<1

from here i got
max{0,s-1}<u<min{1,s}

modest stirrup
#

If Z is 0.7 say, and Z is sum of X and Y. How can X be more than 0.7 because X and Y are non negative.

verbal hound
#

lemme think

#

ohh

gritty sinew
verbal hound
#

now i got it

verbal hound
#

thanks @modest stirrup

gritty sinew
#

how do you get from up to down here ?

#

I'm saying there an error here

#

the max isn't s-1 here, it's 0

verbal hound
#

for s belongs to 0,1
max value will be s-1 isnt it right ?

gritty sinew
#

why do you think it is ?

verbal hound
#

wait wait

#

im so sorry

gritty sinew
#

s-1 is negative

verbal hound
#

im just doing dumb mistakes

verbal hound
#

thanks to you too

#

.close

vale dockBOT
#
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vale dockBOT
#
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silk peak
#

I dont know how to graph that

vale dockBOT
silk peak
#

can I get some help with 5a

north walrus
#

i think it is just a parabola

woeful rover
#

Are you familiar with quadratics?

north walrus
#

with coefficient $\pi$ and only graph between 0 and 10

rocky lotusBOT
silk peak
#

what does r e mean

north walrus
#

that mean r is inside of something

#

(intervals I think)

woeful rover
north walrus
#

square brackets mean including endpoints

silk peak
#

so like

#

the graph is up to y 10?

north walrus
#

x up to 10

#

starting from 0

#

(I mean r)

woeful rover
north walrus
#

not 0?

#

and I think it includes endpoints

woeful rover
#

From (0,0) to (10,100π)

silk peak
#

why 100pi

woeful rover
#

Because if you plug in 10 into πr^2, you get 10^2 π or 100π

silk peak
#

gow dk you know 10 is the r

woeful rover
#

And that's the maximum r given

#

And thus the maximum of the function

silk peak
#

so how wohld I graph that

woeful rover
#

Draw 2 axes

silk peak
#

something like that? the sketch is really rough because im drawinf it on my knees

woeful rover
#

Hmm

#

It's not a downward facing parabola

#

Also

#

You should consider the positive direction of x only

silk peak
#

but you said maximum

#

wouldnt it be minimum then

woeful rover
#

Hmm

#

Alright let's consider r = 0

#

And our function is A(r) = πr^2

#

What is the value of A when r = 0?

silk peak
#

0

woeful rover
#

Alright

#

What is the value of A when r = 1

silk peak
#

1pi

woeful rover
#

Alright

#

If we kept going, the values will stay positive and they will go up

#

Until we reach r = 10

#

The problem tells us to stop when r = 10

#

So in this case, what is the maximum value of A?

silk peak
#

100pi

woeful rover
#

Exactly

silk peak
woeful rover
#

If you can lower the belly of that curve, you will draw a proper sketch of it

silk peak
#

belly?

woeful rover
#

Yeah the middle part of the curve

#

I think it would be easier if you plotted points and traced them

#

It should show you how the behavior of the curve will look like

silk peak
#

is tmit the same for 6

#

ouh ehat

#

wait

woeful rover
#

No 6a tells you to draw 2πr

#

Do you know what type of function 2πr is?

silk peak
woeful rover
# silk peak

This is not the correct shape for the function

#

For 2πr

#

@silk peak are you there?

vale dockBOT
#

@silk peak Has your question been resolved?

vale dockBOT
#
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vale dockBOT
#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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atomic blaze
#

A sphere's angular diameter is 2asin(diameter / 2*distance), iirc. This means that the radius that one sphere needs to have to look like it's the same size as another sphere that's further away is r2 = r1 * dist2 / dist1.

The problem is, I'm working on a game, and sqrts are expensive to run every frame. Is there any way to contort this to use distance-squared?

hardy coral
#

I'm assuming you're calculating distances with sqrt; hence your question

#

Not a mathematical answer, but I feel like you're worrying about the wrong thing. Nowadays it isn't that expensive to run a couple of sqrts every frame. Have you actually measured and determined that this was a bottleneck?

cerulean bronze
#

hi

#

myself suman kundu

ashen prawn
vale dockBOT
#

@atomic blaze Has your question been resolved?

vale dockBOT
#
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keen lily
#

find the determinant of the 2nd order

vale dockBOT
keen lily
#

i need help with в

#

so im sure there is a formula im forgetting

stark wedge
#

,rccw

rocky lotusBOT
keen lily
stark wedge
#

,rccw means rotate counterclockwise

#

,rcw for clockwise instead

#

anyway sin^2(alpha) + cos^2(alpha) = ?

keen lily
#

1

#

oh

#

ok

#

0

#

ty

hot tide
keen lily
#

wait both have to be alpha?

#

or does the angle not matter

hot tide
#

it does matter

keen lily
#

alr

stark wedge
#

the angle has to be the same in both

keen lily
#

ye

#

alr

keen lily
vale dockBOT
#

@keen lily Has your question been resolved?

vale dockBOT
#
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simple orbit
#

guys theres this question.... its a simple one but am still stuck. the question is-
in what ratio is the line joining A(8,9) and B(-7,4) is divided by the point (2,7).

wild linden
#

how do you define division of a line by a point?

#

I don't know of any such definition

opal pendant
simple orbit
#

no theres a line and (2,7) is basically on that line so we have to tell in which ratio its cutting that line

opal pendant
#

section formula

ripe trail
#

I think he's trying to say what the ratio of the distance AC to the distance AB is.

opal pendant
simple orbit
wild linden
opal pendant
simple orbit
# opal pendant

thanks alot this is the formula of internal division of section formula

ripe trail
#

2/3

#

1/3

simple orbit
#

2:3 is the correct ans

ripe trail
#

yeah

simple orbit
#

thanks alot

#

.close

vale dockBOT
#
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short solar
#

i forgot factoid

#

.🥀

opal pendant
#

i think its !nosol

#

!nosoln

#

!nosol

#

!nosols

vale dockBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

opal pendant
#

ahh

tropic loom
#

been playing silk song for an hour or so

#

its pretty good

#

although the font is

#

questionable

wild linden
#

Please take this to discussion, this is a closed help channel, and it liable to lock unexpectedly due to bot shuffling (and also it's off-topic here)

tropic loom
#

oh shit

#

wrong channel;

#

mb

wild linden
#

nw

vale dockBOT
#
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deep mantle
#

Hello, i have a question

vale dockBOT
river shale
deep mantle
river shale
#

It’s okay, just post your question

wild linden
#

This is the appropriate place for mathematics help, yes

stark wedge
#

send us your question

deep mantle
river shale
deep mantle
molten plume
#

Ymm

vale dockBOT
#

@deep mantle Has your question been resolved?

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still dust
#

help

vale dockBOT
still dust
#

um! hi!

hazy pivot
#

Shoot

still dust
#

how would you guys know whether x=-1 is a maximum or a minimum?

hazy pivot
#

Essentially you make a small interval around it

still dust
#

id say it is a minimum but ai is telling me it would be a maximum

hazy pivot
#

And see if the value in that interval is lower than the value at x = 1 everywhere

#

Wait -1

still dust
#

oh

#

right

#

so then it would be a maximum

hazy pivot
#

No -1 is a minima

still dust
#

its not about the pendant

still dust
hazy pivot
#

Cuz take any point close to -1 that isn't -1

still dust
#

between -inf and -1 is positive

hazy pivot
#

The function value is higher

hazy pivot
still dust
#

it's f'

hazy pivot
#

All that matters is the value is a small interval around the point you're considering

still dust
#

how would i do it then

hazy pivot
#

Like I said

#

Take a small interval around -1

#

Check the value there

still dust
#

but i dont have the function

hazy pivot
#

No but you have the graph

still dust
#

i only have the graph of f'

hazy pivot
#

Wait it's f'?

still dust
#

the derivate of a function

hazy pivot
#

Oh fuck me then hold on

#

What's the definition of local minima/maxima

still dust
#

a point that goes from like

#

increasing

#

to decreasing

#

in a function

hazy pivot
#

In terms of the derivative?

still dust
#

i think?

hazy pivot
#

Yes that is correct for a maxima

#

A minima is just the other way

still dust
#

yeah

hazy pivot
#

How do you define this in terms of the derivative though

still dust
#

what do you mean?

hazy pivot
still dust
#

it equals 0?

hazy pivot
#

Yes

#

Now you have the graph of f'(x)

#

Where is it zer

brave grail
hazy pivot
#

That's the graph of f', not f

brave grail
#

mb

still dust
# brave grail

but how do you determine whether we're on about the upper one or the lower one

hazy pivot
#

His approach is just wrong, ignore it lol

still dust
#

oh

#

nws

hazy pivot
still dust
hazy pivot
#

Zero*

#

Sorry

still dust
#

at 1

#

so then it has to be a maximum

#

?

hazy pivot
#

No how is it zero at 1

still dust
#

because of like the values from the sies

#

sides

still dust
hazy pivot
#

Okay I've been being dumb so far

#

The function is increasing to the left of 1 cuz the derivative is positive

#

And decreasing to the right cuz the derivative is negative

hazy pivot
brave grail
hazy pivot
#

I feel like there's a language barrier here,

#

Do you speak French, quad?

still dust
#

oh? i'm not french lol

#

spanish

hazy pivot
#

Well all romance languages look the same to me

#

My bad though

brave grail
hazy pivot
#

Well do you speak spanish

brave grail
#

no but you guys can speak in whatever you like cuz im leaving anyways

hazy pivot
#

Oof

#

@still dust let's start from the very beginning

#

What happens at a maxima

still dust
#

my bad

#

laptop acted up

#

crashed

still dust
hazy pivot
#

What is pendant

#

No genuinely, I've never heard that term

still dust
still dust
hazy pivot
#

So essentially this means, on the left of the maxima, the derivative is positive and on the right it's negative

#

And the opposite for a minima

#

(I'm guessing you're referring to the derivative when you say pendant?)

still dust
#

I’d say so?

#

the derivative does like determine it

hazy pivot
#

I see

#

Anyway so back to the original question

#

What happens at x =-1

still dust
#

im sorry

#

my pc crashed

#

its a maximum

hazy pivot
#

Glld

#

Good

vale dockBOT
#

@still dust Has your question been resolved?

vale dockBOT
#
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charred root
#

So I'm stuck in this because I don't understand why at the end after 1/3 Un +2 < 1/3 Un+1 +2 turn in Un+1 < Un+2
And how we know P(n+1) is true
If anyone can speak french and help me maths, it's would be great

spring jackal
#

par notre definition de la relation, $u_{n+1} = \frac{1}{3}u_n + 2$, donc on faire ce subsitution à gauche

rocky lotusBOT
#

haseeb
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

spring jackal
#

._.

#

pour le droit: ajouter un a l'index pour obtenir $$u_{(n+1)+1} = \frac{1}{3}u_{(n) +1} + 2,$$ ou, simplement $$u_{n+2} = \frac{1}{3}u_{n+1} + 2$$

rocky lotusBOT
#

haseeb

spring jackal
#

pour ces preuves, il faut qu'on réarrange la récurrence pour obtenir la "regle" de récurrence, puis faire la substitution comme indiqué

vale dockBOT
#

@charred root Has your question been resolved?

vale dockBOT
#
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boreal charm
#

any good videos on like trigometry for dummies or such (do i need to open a help for this)

merry crystal
boreal charm
#

10hours ;-;

#

.close

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#
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verbal hound
#

.

vale dockBOT
verbal hound
#

3rd one must be defective so its fixed and
1st one and 2nd one can interchange with each othr one being defective and other one being non defective

#

so prob should be (2C1 * 3C1 * 2!)/(5C3) which gave me 2/5 = 0.4 but its incorrect how ?

vale dockBOT
#

@verbal hound Has your question been resolved?

flint pumice
#

There are two cases: 1) 1st defective 2nd not defective 3rd defective and 2) 1st not defective 2nd defective 3rd defective

verbal hound
#

2C1 is selection for one defective piece
3C1 is selection for one non defective piece
and 2! is for arrangement of above two pieces
and last and 3rd is fixed so

flint pumice
#

wait oh I think I figure it out: (2 C 2)((5-2) C (3-2))/(5 C 3)

#

(2 C 2)(3 C 1)/(5 C 3) = (3 C 1)/(5 C 3)

flint pumice
#

3/10

#

ye

verbal hound
#

how ?

flint pumice
#

the sucess state is defective lightblub

verbal hound
#

2c2 3c1
also include case of defective defective non defective

flint pumice
#

there are 3 draws

verbal hound
verbal hound
flint pumice
verbal hound
#

3rd one must be defective

flint pumice
#

oh nvm

verbal hound
#

what ? mate ?

flint pumice
#

if the 3rd one must be defective I think the probability is 0.2

vale dockBOT
#

@verbal hound Has your question been resolved?

flint pumice
#

if you test 3 blubs and all 3 are not defective you know automatically the 2 left over are defective

#

4:07

vale dockBOT
#
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pseudo burrow
#

Don’t understand how to get to the answer but i know the answer

pseudo burrow
#

teacher just kind of gave the answer and it’s the first day of the class

#

kind of lost

chilly violet
#

Presumably, you’ve encountered that

pseudo burrow
fleet burrow
pseudo burrow
#

i don’t understand how to get to the point

chilly violet
fleet burrow
#

Q6 part a?

pseudo burrow
fleet burrow
pseudo burrow
#

should have specified

#

Q6 and Q7 B

fleet burrow
#

the center will be the midpoint of the two points, can you see that?

fleet burrow
fleet burrow
#

you can find the equation of the circle

pseudo burrow
#

OH

#

so the centre is the in between of 3.3

#

and 5,t

#

5,5

#

so it would be 4,4

fleet burrow
#

yup

pseudo burrow
#

then from there i can just plug and get the radius

#

okay that makes so much more sense

#

thank you

fleet burrow
#

that works too

pseudo burrow
#

yes but i don’t know all the values

#

mainly x and y

fleet burrow
#

wait nvm

pseudo burrow
#

oh

fleet burrow
pseudo burrow
fleet burrow
#

what

#

they give you the centre in the question

pseudo burrow
#

yes

#

oh wait

#

5,4

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sorry used to changing it from the equation

fleet burrow
#

that radius is wrong btw

fleet burrow
vale dockBOT
#

@pseudo burrow Has your question been resolved?

#
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vale dockBOT
#
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craggy bough
#

Hello I need help

vale dockBOT
craggy bough
#

I need help starting a problem: prove that a mod b = b mod a if and only if a = b

#

How do I start working through this?

hardy coral
#

Suppose WLOG a > b

craggy bough
#

ok

hazy pivot
#

Then what is b mod a

craggy bough
#

b

hazy pivot
#

Good

craggy bough
#

and a mod b is a-b

hazy pivot
#

Not necessarily

#

Consider 7 and 2

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7 mod 2 isn't 5

craggy bough
#

right, my bad

hazy pivot
#

But we don't need to worry about that

#

Since we know a mod b = b mod a

#

But then this gives us a mod b = b

#

Now what

hardy coral
hazy pivot
#

a mod b = b mod a, and b mod a = b

hardy coral
#

Oh fair enough

craggy bough
#

im not sure whats next

hazy pivot
#

Wait I just realized I'm using the cs mod and not the number theory mod

hardy coral
#

I would just say a mod b < b

hazy pivot
#

But I think it works regardless

hazy pivot
#

So what do we have here

craggy bough
#

its a contradiction

hazy pivot
#

Good

#

What is it a contradiction to

craggy bough
#

a=b

hazy pivot
#

No no, it's a contradiction to a > b

#

So it gives us a = b

craggy bough
#

ohh ok

#

but why a=b and not a < b?

#

if a < b then a mod b = a

#

then b mod a = a

hazy pivot
#

Same argument

#

b mod a < a

craggy bough
#

right

#

that makes sense

#

thank you

#

this was helpful

#

.close

vale dockBOT
#
Channel closed

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tawdry belfry
#

im confused on integration, like how do i get to the result i know about the power rules and stuff but like how do I get there im just confused on the steps and why they are that

tawdry belfry
#

i just started calc2 so

small vine
#

Are you wanting proofs of the rules?

#

@tawdry belfry

vale dockBOT
#

@tawdry belfry Has your question been resolved?

feral sapphire
vale dockBOT
#
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verbal hound
#

@bruh_sophie0521 thanks

vale dockBOT
verbal hound
#

.close

vale dockBOT
#
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vale dockBOT
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worn locust
#

Hi

vale dockBOT
worn locust
#

need help with calculus

#

its basic

#

I don't understand

hazy pivot
#

Well what is a limit

worn locust
#

I don't really understand limits

hazy pivot
#

Well essentially

#

It's the value a function takes "close" to a point, coming from one direction

worn locust
#

okay

hazy pivot
#

This doesn't need to be the same as the function value at that point

worn locust
#

so for (a)

#

the answer is whatever's closest to -7?

rocky lotusBOT
#

Xavier 🌺

$x \rightarrow -7^{-}$ talks about approaching -7 from the left
worn locust
#

so, -6?

hazy pivot
#

Good

worn locust
#

nice!

#

b) -4?

tawdry belfry
#

son of a bitch

hazy pivot
#

!redir

vale dockBOT
#

This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

hazy pivot
#

Wrong one

worn locust
hazy pivot
#

!occupied

vale dockBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

hazy pivot
#

Now the arrows on that mean that the graph gets closer and closer to a point but never really achieves it

#

Intuitively you can think of it reaching that value at infinity

worn locust
#

hmm okay

hazy pivot
#

Wait no

worn locust
#

its from the right no?

hazy pivot
#

It's x → 5+

#

So it's from the right yes

#

So it won't be -4, that's from the left

worn locust
#

but its an empty point

#

so what do i do

hazy pivot
#

Doesn't matter

#

You don't care about the value at the point

#

You only care about the value close to the point

worn locust
#

ok so 7

hazy pivot
#

Wait hold on are you in school or in college

worn locust
#

freshman in college

hazy pivot
#

Oh okay

worn locust
#

i took honors calc senior yr but i forgot everything lmao

hazy pivot
#

Have you seen the proper definition of a limit?

#

Ah cool in that case I can drop some of the training wheels

worn locust
#

ye

hazy pivot
#

Are you familiar with the epsilon-delta definition of a limit?

worn locust
#

nope

hazy pivot
#

No like do you recall having seen it before

#

Or is it completely new to you

worn locust
#

i don't know what the epsilon delta definition is

hazy pivot
#

Cool

worn locust
#

maybe my teacher said it already but never used those words specificallyt

#

is c) infinity

hazy pivot
#

No

hazy pivot
#

Read this and the next message

worn locust
#

oh im dumb

#

2

hazy pivot
worn locust
#

?

hazy pivot
#

I'll have to check the diagram brb

worn locust
#

ok thx

hazy pivot
#

Yes it's 2

worn locust
#

thanks for helping bro

#

i appreciate it