@thin meadow Has your question been resolved?
#help-4
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stark wedge
@thin meadow you should tell us what issue(s) remain about this topic
thin meadow
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rare wolf
Hi everyone,
I’m working on the mathematical modeling of a slot machine and I’ve already calculated the RTP (Return To Player) for all the base game combinations.
However, I’m stuck on the Free Spins part: I don’t really know how to factor their contribution into the overall RTP.
Should I treat Free Spins as a kind of “credit reward” that can be converted into an equivalent payout, or as a sub-game with its own RTP that needs to be weighted back into the global calculation?
Any guidance would be greatly appreciated
vale dockBOT
Hi everyone,
I’m working on the mathematical modeling of a slot machine and I’v...
@rare wolf Has your question been resolved?
loud karma
struggling with this sequence a bit. the answer they're looking for is not what I came up with and I can't find the rule for it. ||they're looking for 17 when I thought it was 20 (+3,+6,+9 skipping one starting from the 1st number, +4,+6,+8 skipping one starting from the 2nd number ||
2, 3, 5, 7, 11, 13, ?
stark wedge
aren't those just the primes lmao
heady pawn
loud karma
aaaaaaalright that explains it I guess. would you count 20 as a correct answer? 😄
either way, thank you!
.solved
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opal wasp
English version- Given is the side length of a regular hexagon 4 cm.
Determine the area of the colored figure. I have successfully found the area of hexagon and a part of the colored part of the circle, in which hexagon is enclosed. I am just struggling with the extra circle part. Ans is (68.sqrt(3))/3 + 16/9*pie
hazy pivot
You have the side length of that equilateral triangle
And the smaller circle circumscribes it
Do you know how to calculate circumradius?
hazy pivot
You can use inclusion exclusion stuff
You are double counting the overlapping part between the small circle and the hexagon
You can split it into one triangle, two segments of the small circle and one segment of the bigger circle
Then you can calculate area of all those and subtract that from the sum
opal wasp
Clear. Thanks a lot man
hazy pivot
Actually you can do easier than this, you have one section of the big circle and two sections of the small one
The triangle will be part of the section of the big circle
I'm not using the correct terms cuz it's been a while lol
opal wasp
I got your point. Thanks
hazy pivot
Good luck!
opal wasp
.closed
river shale
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opal wasp
.close
hazy pivot
You can close channels for other people?
river shale
Only moderators and those with helpful role
hazy pivot
Ic
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wet flower
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steady charm
stark wedge
your cancellation of u sqrt(3) on one side and -u sqrt(3) on the other was incorrect
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pallid adder
Hello
sinful sinew
hi whats the problem
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No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/
sinful sinew
Tips? got any problems with certain eq?
weary pilot
pallid adder
Currently suffering from an 99 Percent hit rate from 3 books so no doubts
sinful sinew
So no questions?
pallid adder
So no questions?
Yeah pretty much
sinful sinew
Yea im sorry but not here. We dont know what you are struggling with. Math discussion is better for these typa things
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dim wasp
i need help learning basic stats
vale dockBOT
i need help learning basic stats
storm perch
i need help learning basic stats
Just send the questions/concerns
dim wasp
i dead dont get one thing about stats is there any way we can hop on a call and i can share my screen and you can just teacg me it
spring jackal
i dead dont get one thing about stats is there any way we can hop on a call and ...
what's the thing? is there maybe a hmwk question that has it? (would probably be easier to work off of that)
-# p.s. welcome to mathcord! :D
dim wasp
im trying to do my 26 question pre test rn for my college class
ive never took stats and he dont teach so
spring jackal
pre test is like a test review?
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@dim wasp Has your question been resolved?
jovial scarab
vacuous truth is the big idea here
sharp whale
its possible to have the RHS be true and the LHS be false
LHS being false would mean there exists an x in E where A(x) is true, but B(x) is false
now this does mean B(x) is no longer true for all x in E,
so RHS being true would mean "for all x in E; A(x)" must be false as well so that true comes from false => false
so that means:
- there exists an x where A(x) is true, but B(x) is false
- there exists another x where A(x) is false
so all we would need is an example of an x where A(x) is true, but B(x) is false
and for A(x) to not always be true
as an example, have E = integers
A(x) = true iff x is 0
B(x) = false
you can simplify both sides and see that this all works out
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late fable
I ain’t good in math can someone help me here
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I ain’t good in math can someone help me here
@late fable Has your question been resolved?
fringe niche
its possible to have the RHS be true and the LHS be false
LHS being false would...
this is why our math teacher doesn't accept => in exams
he just tells us to use so and therefore
fringe niche
I ain’t good in math can someone help me here
you need to work on two intervalls
check what values the absolute value of 3x-1 can take in IR
and solve for both
then check if the intersection has one or multiple elements
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patent abyss
the instructions said “Determine whether each pairs of figures is similar. If so, find the scale factor. Explain your reasoning.” I don’t know where to start
cobalt valley
the instructions said “Determine whether each pairs of figures is similar. If so...
If angle xzw=angle xzy then you could say triangle WXZ is proportional to XYZ due to 2 sides and an angle
But idk if there is proof for the angle being split in half
cobalt valley
how to find the scale factor? there’s no numbers
Considering the triangles are similar it would be 1:1 since the side is the same(the one marked with “|”)
whole void
help
whole void
stiff lily
what's the question asking you to do?
whole void
Sum and product
gray ivy
this looks easy but isn’t.. I think
whole void
its factoring general trionomials
gray ivy
Sum and product
Ohhh
whole void
u have to 3x2 times 60 right?
stiff lily
no
whole void
that is not it
60 and 3
oh wait maybe it is
yea a times c
fam i dont understand such complex equations
stiff lily
the first thing you should look for is seeing if all terms have a common factor
whole void
but just help me do the question
stiff lily
which they do here
factoring that out first makes things simpler and a lot less tedious
hardy coral
think of a number that multiplies to (a \times c)
Really? You may want to check your method
orchid moat
3(x^2+x-20)
3(x+5)(x-4)
(3x+15)(x-4)
whole void
if its not equal to 1
stiff lily
you can do other things first
whole void
by factoring out 3 u mean removing 3?
stiff lily
no
orchid moat
by factoring out 3 u mean removing 3?
In that quadratic what is a common factor?
stiff lily
factoring means factoring
whole void
In that quadratic what is a common factor?
3 cuz the common factor cant be higher than the givens
stiff lily
the presence of 3 / it's effect remains
it doesn't disappear
chrome sail
can you guys let one person explain, I'm low-key getting confused and I'm aware of how factoring works
whole void
yea me too
orchid moat
3 cuz the common factor cant be higher than the givens
Okay so divide everything by three
whole void
3=1 3=1 3=20
stiff lily
e.g pq + pr = p(q + r)
p is still there, it doesn't get "removed"
whole void
1 1 20
stiff lily
try applying that and first factor out 3
whole void
e.g pq + pr = p(q + r)
p is still there, it doesn't get "removed"
where tf did u get p from
1
3 becomes 1
stiff lily
arbitrary example
stiff lily
just stating the distributive property and what it means to factor out a common term
whole void
factoring out 3 means it becomes 1 right?
fleet burrow
factoring out 3 means it becomes 1 right?
what is 'it'?
stiff lily
factoring our 3 means that the result afterwards would be:
$$\red3\br{\text{something}}$$
don't ignore the $\red{3}$
whole void
2
rocky lotusBOT
ℝαμOmeganato5
chrome sail
lmao
orchid moat
i think hes ragebaiting
orchid moat
5x-10 what can you factor out to simplify this
fleet burrow
i thought about dividing by 2
are you still factoring the quadratic 😭
orchid moat
Glorious I think you should restart ur course on factorisation and quadratics
whole void
5x-10 what can you factor out to simplify this
5 or 2?
whole void
Glorious I think you should restart ur course on factorisation and quadratics
im not taking a course its highschool
orchid moat
What looks right to you
whole void
if u factor out 5 and 10 u get 2
orchid moat
So what would your simplified expression be
whole void
-2x
orchid moat
What
stiff lily
where's the rest of the expression
whole void
2
orchid moat
where's the rest of the expression
?
What do you mean
Im using a simplified example
orchid moat
Okay so we have just x
whole void
yes
orchid moat
What about -10 divided by 5
whole void
-2
whole void
in the middle?
orchid moat
No, think again
chrome sail
there's genuinely no way this guy isn't ragebaiting
orchid moat
there's genuinely no way this guy isn't ragebaiting
He 100% is
whole void
outside?
fleet burrow
@whole void Okay so using this guy's example,
5x + 10
you can notice that it is the same as 5(x + 2). Expand it and we will get back the same thing.
Doing this is called factorisation. You can take one thing and turn it into the product of multiple things.
orchid moat
being dumb is being ragebaiting now?
Well no its just because this is really basic stuff and youre saying everything but the answer and you know it
whole void
im not i just have other things on my mind
fleet burrow
<@903874856658018345> Okay so using this guy's example,
5x + 10
you can notice...
do you understand...?
orchid moat
im not i just have other things on my mind
But you chose to post the problem here so it was pretty important that you got help for it?
whole void
nah like i have other solutions n shi
orchid moat
I dont think if you had other stuff on ur mind youd post it here and speak about it for 20 mins
whole void
i was multitasking now im only doing this
orchid moat
nah like i have other solutions n shi
If theyre your solutions i wouldnt trust them
whole void
lez js get back to the problem
orchid moat
I think you should watch a video on factorisation first
whole void
i js need help doing ts
orchid moat
Well you cant even understand factorising so I think that the problem u posted isnt the only thing u need help on
whole void
i watched a vid i get it now
orchid moat
Okay nice try it
fleet burrow
okay then why didnt you use that in the first place? 😭
chrome sail
you can
orchid moat
😭 😭 😭
chrome sail
we're not
orchid moat
@whole void quick question what do u do in class?
whole void
then the whole problem becomes 3x squared+3+60+60
orchid moat
Like you personally
whole void
<@903874856658018345> quick question what do u do in class?
i dont remember
orchid moat
then the whole problem becomes 3x squared+3+60+60
3x^2+3+60+60?
whole void
yea cuz 60 and 3 is what u get to get 180
chrome sail
Like you personally
as much as I want to troll, I don't think it's a good idea in a help channel
whole void
or do u replace 180 with the 60 at the end
orchid moat
as much as I want to troll, I don't think it's a good idea in a help channel
ah good point
Well i mean
whole void
so 3x squared+3+60+180?
orchid moat
This is blatant ragebait
whole void
bro i cant even turn to chatgpt for help cuz hes ass at math
fleet burrow
so 3x squared+3+60+180?
bro if you arent ragebaiting you geniunely need to like ask your teacher for help or smth like this is horrendous levels of mathematical illiteracy 😭
orchid moat
🤣🤣🤣
fleet burrow
just close the problem 😭
chrome sail
I see the moderator typing
stiff lily
What you may find easy may not be as simple for others. Please stop with the insults or move on somewhere else.
queen agate
mathematical
What’s that
chrome sail
What you may find easy may not be as simple for others. Please stop with the ins...
I agree with this but I think in this case there's a large chance this is ragebait
whole void
he literally just said what u may find easy may not be as easier for others
queen agate
I agree with this but I think in this case there's a large chance this is rageba...
You’re concluding that simply because it’s easy for you
That’s not fair to Mr Lebron
I also am similarly disadvantaged and want to see how this problem works out
chrome sail
did this mf just hire a lawyer 💀
orchid moat
bro im crying this is so funny
stiff lily
If you have concerns about a user, dm @feral pebble for that.
Its a really bad experience for a user if they need help, are trying only to be abused.
queen agate
You tell them uhhhhh
whole void
why do i need chemistry for math let alone organic
queen agate
Your name is really hard to spell
Omeganato5?
Whats the thing in the beginning
Anyways
whole void
ohh i thought that was the video
i was wondering why u told me to watch a vid about organic chemistry
stiff lily
don't let the channel name fool you,
they have a lot of great content on math
whole void
aight
stiff lily
as I've mentioned
the ac method can be applied to that directly if you want
but i'd recommend doing something before that to make things easier
as if applying the ac method directly, your work would involve looking for factor pairs of 3 * - 60, or -180
which is quite big and a pain to work with when looking for factors
whole void
what happens to the whole equation if u do A C?
stiff lily
here like i've said, you get big numbers which is a pain to work with
with ac method you'd end up looking for a pair of values that multiply to
ac = 3 * -60 = -180
that sum to
b = 3
to see how to split the middle term
but following that, the work would still require you to factor out common factors
deft siren
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deft siren
solving continuity there
solved domain for all reals except 1
and limits on left and right give both -infinite
id assume its a vertical asymptote
hardy coral
and limits on left and right give both -infinite
Really?
deft siren
Really?
no
but simplified is that
you get a number close to 0 in both numerator and denominator
so i learned to just note it as 0
hardy coral
That's... not how you compute limits
deft siren
i think in left is something like 0.03/0.01
deft siren
That's... not how you compute limits
im solving continuity on 1
hardy coral
Yeah I understand that
When you see a fraction of polynomials (aka a rational fraction), one of the first things you should think of is factoring
deft siren
When you see a fraction of polynomials (aka a rational fraction), one of the fir...
i know, bhaskara can be done there
and probably cancel out a (x-1) term
hardy coral
bhaskara?
hardy coral
Ok fair enough
hardy coral
and probably cancel out a (x-1) term
Right, so why not actually do it?
deft siren
i didnt do it because i thought youre meant to see which values does it tend to on left and right
and they were meant to be infinite or negative infinite
hardy coral
Yeah, and simplifying the expression makes it much easier
deft siren
on vertical asymptote at least
hardy coral
No, not always
deft siren
Yeah, and simplifying the expression makes it much easier
so in this case it probably tends to -2
so theres a vertical asymptote in -2?
deft siren
Does your course material not list the possible types of discontinuity?
it does
essential
as in it cannot be redefined
and removable
i dont know how to redefine a function though
never had to do it
deft siren
That's an odd way to phrase it but sure
im translating it directly from spanish
it specifically tells me to not graph it
hardy coral
Well, technically it's not preventing you from graphing it
You just can't use the graph to verify the continuity
deft siren
if try to play around it and read the fine print hes just marking it wrong
ill solve it with no graphs so i avoid problems
hardy coral
?
I'm just suggesting to look at the graph to build intuition
I'm not suggesting to use the graph to answer anything
Anyway... can you tell me what the function becomes if you properly factor it?
deft siren
Anyway... can you tell me what the function becomes if you properly factor it?
probably x-3
hardy coral
Ok, so it's a line, right?
So at the discontinuity, the limits on both sides obviously converge to the same point
deft siren
so it doesnt have any
hardy coral
It does, because by definition f isn't defined at x=1
deft siren
well yea
hardy coral
It's just a line without that specific point
hardy coral
Yes
So if you want to properly redefine the function, you need to split it into two cases: x=1 and x=/=1
Though I don't know what your teacher expects you to do exactly
deft siren
Though I don't know what your teacher expects you to do exactly
i dont either
hardy coral
I'm sure you can just specify the domain of the function instead
hardy coral
Is that a previous question?
deft siren
no
but i need to find the number out of the domain to know where to check for discontinuitie
s
hardy coral
Ok so that's one way to redefine the function, just f(x) = x-3, but for all x =/= 1
deft siren
Ok so that's one way to redefine the function, just f(x) = x-3, but for all x =/...
what does that / in the middle mean
hardy coral
not equal
deft siren
ok
deft siren
there are?
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Available help channel!
north scarab
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stiff lily
no need, your mistake seems to be +4x^2 turning into -4x^2
from 3rd to 4th line in pink
and that would factoring not expanding
north scarab
no need, your mistake seems to be +4x^2 turning into -4x^2
I dont see it
if u mean this
i just rearranged it
and cancelled it out
stark wedge
is this an explicitly written 1 exponent??
north scarab
yes
stark wedge
...why
north scarab
so I wont get confused when im trying to differentiate the outer function
stiff lily
why bother viewing it as a composition in the first place
stark wedge
but why even have an outer function at all lmfao
it's as if you deliberately blind yourself to the fact that a^1 = a ?
stiff lily
I mean the line after
but this,
in the following line you have -4x^2
north scarab
but this,
in the following line you have -4x^2
yep I see the mistake now
stark wedge
btw if you're going to put the function in expanded form at the end
north scarab
but why even have an outer function at all lmfao
but did I get any consequences for putting a 1 in the exponent
stark wedge
why not expand it to begin with, and save yourself the trouble of using any rules but power?
(it's a 4th degree function, so not really all that bad)
stark wedge
but did I get any consequences for putting a 1 in the exponent
you got the consequence of weirding out the reader
north scarab
you got the consequence of weirding out the reader
true 😭
stiff lily
wasted ink
stiff lily
seems ok
it's fine to just leave in factored form unless told otherwise
esp with problems that have higher powers
north scarab
it's fine to just leave in factored form unless told otherwise
but if the question doesnt ask, we don't have to becauuse
theres extra steps
I assume
stiff lily
yes and the factored form is more useful for getting stationary points
north scarab
yeah that is true
the question is
how am I supposed to factorise out 16x^3+72x^2+54x-54
vale dockBOT
@north scarab Has your question been resolved?
stiff lily
as in do that not knowing where it came from?
standard approach
common factor between all terms
then if grouping doesn't seem viable,
then approach with rrt
tiny torrent
So im trying out latex but doesnt this look a bit hard to read?
tiny torrent
maybe im just tired
everything just looks so evenly spaced that its hard to put together atleast for me
have an extra parenthesis in there
I wonder if there some plugin that can notify you of unclosed brackets
man this looks actually rough to read for me but im low on sleep rn so idk if its just sleep or if its actually hard to read
vale dockBOT
@tiny torrent Has your question been resolved?
midnight pier
So im trying out latex but doesnt this look a bit hard to read?
so the latex looks good but I believe it should be "for all" since "for some" is logically equivalent to "there exists", which isn't equivalent to the defn. of cartesian product. great otherwise
^in the first line
tiny torrent
I think there exist is the definition of cartesian product
it sort of acts as an iterator through the sets
midnight pier
tiny torrent
from my set theory book
for some a in A allows any a that is in A (which makes for some a in A true) to be used as the first coordinate
it kind of works like for all when inside a set I think
dont take my word on that but thats how I think about it
midnight pier
yeah this actually looks right
tiny torrent
So im trying out latex but doesnt this look a bit hard to read?
I think the font is throwing me a bit off so im gonna try some different fonts
tiny torrent
so the latex looks good but I believe it should be "for all" since "for some" is...
I looked deeper into it because I was curious and found this explanation that helped me understand it better
https://math.stackexchange.com/questions/2737243/what-are-all-underlying-assumptions-in-the-definition-of-cartesian-product-in-na
.close
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coral lagoon
Is there a faithful and transitive action of S_5 on 30 objects?
keen tundra
!status
vale dockBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
oh yeah i dont know where to begin...
keen tundra
Thinking
stark wedge
it's easy enough to do it on 5 objects, but 30...?
coral lagoon
yup... i'm relatively new to group theory so i have no idea how one would approach something like this
-# actually this isnt homework so i have no idea if a non painful approach even exists
oh i can show that there are no transitive and faithful action of S_5 on 6 objects though -
the idea is that S_5 is generated by a=(1 2) and b=(1 2 3 4 5) . b would have to act on the 6 objects by a 5-cycle, and for the action to be transitive a would have to swap the remaining sixth object with some other object
and so no matter how you choose the actions of a and b, the action of (ab)^4 isn't the identity, although (ab)^4=1 in S_5
apparently i have made a mistake somewhere
vale dockBOT
@coral lagoon Has your question been resolved?
keen tundra
oh i can show that there are no transitive and faithful action of S_5 on 6 objec...
There is one. The action of S5 on its 5-Sylow subgroups
coral lagoon
There is one. The action of S5 on its 5-Sylow subgroups
OH
that makes sense ...
but then you could just let S_5 act on the 30 pairs (number in {1,2,3,4,5}, Sylow 5-subgroup of S_5), right?
this might actually be a satisfactory action...
coral lagoon
that's the question
keen tundra
I think there is something. The action on S5 on the cosets of a subgroup generated by a 4-cycle.
coral lagoon
I dont think so
actually isn't this action transitive though? 5-sylow subgroups of S_5 would be isomorphic to Z_5, hence would have to be of the form <(a b c d e)>
for a b c d e some permutation of 1 2 3 4 5. so if you wanted to send the pair p_1 = (1, <(1 2 3 4 5)>) to p_2 = (n_2, <(a_2 b_2 c_2 d_2 e_2)>), you would rotate the latter cycle so that 1 and n_2 align and select the permutation conjugating one cycle to another?
so for instance if n_2 = c_2, we would have p_2 = (n_2, <(c_2 d_2 e_2 a_2 b_2)>), and so the permutation sending 1, 2, 3, 4, 5 to c_2, d_2, e_2, a_2, b_2 would turn p_1 into p_2 ?
coral lagoon
I think there is something. The action on S5 on the cosets of a subgroup generat...
oh but this seems a lot easier :D thanks !
keen tundra
actually isn't this action transitive though? 5-sylow subgroups of S_5 would be ...
You have to send each coordinate to the other using the same element of S5.
keen tundra
This is a very strong assumption
coral lagoon
and the above procedure does accomplish that too
keen tundra
You need to prove both actions are "simultaniosly transitive"
And I understand your argument to be given (x1,y1) and (x2,y2) send x1 to x2 and then y1 to y2
coral lagoon
no we can really do that
for example if we had two random pairs, say (3, <(1 2 3 4 5)>) and (2, <(1 2 4 5 3)>)
we could rewrite as (3, <(3 4 5 1 2)>) and (2, <(2 4 5 3 1)>)
and so the permutation (3 2 1) would simultaneously send the coordinates to each other, i.e. (3 2 1) sends 3 to 2 and conjugation by (3 2 1) sends (3 4 5 1 2) to (2 4 5 3 1)
keen tundra
I am not convinced...
coral lagoon
how so?
vale dockBOT
@coral lagoon Has your question been resolved?
north scarab
I need my answer checked thank you
vale dockBOT
I need my answer checked thank you
stark wedge
a) is good
are you sure that station A would take five hours to get to the distressed boat though?
tawny moon
it's hilarious to think that a three-digit speed vehicle takes hours to cover two-digit distances
stark wedge
5 hours in, i think the boat would fucking drown a dozen times over 💀
tidal swift
boat would turn into titanic
stark wedge
ditto for station B -- are you sure that they would require six HOURS to get there?
@north scarab
tawny moon
why did you even do that
north scarab
instaed leave it as a decimal of 0.09
stark wedge
no but why did you decide to multiply by 60
north scarab
I thought it would turn it into hours
tawny moon
your speed is in km/h
north scarab
so 6 minutes?
stark wedge
I thought it would turn it into hours
the 0.09 figure is already in hours. what unit did you think it was in?
tawny moon
so 6 minutes?
if you choose to keep the mult by 60, then yes
north scarab
I see
north scarab
because 0.09h just doesnt feel right
stark wedge
i mean it is better for intuition to put it in minutes rather than some tiny decimal of an hour
tidal swift
fair enough
stark wedge
you seem to have used the same distance for both stations
stark wedge
uh. wrong image?
north scarab
I also need this question checked
tidal swift
how did an integral get involved in a simple straight line distance problem
finish the prior question first
!1q
vale dockBOT
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north scarab
oh alr
north scarab
you seem to have used the same distance for both stations
they are both the same distance tho
oh
i read that wrong
tidal swift
how are they both the same distance.
north scarab
just a misread
stark wedge
they are both the same distance tho
no they aren't.
tidal swift
looks much better
north scarab
moving to question 7, what do yall think 
tidal swift
did you perhaps forget to chain rule the binomial
tidal swift
they're both the same integral, are they not
stark wedge
!1q
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stark wedge
go move to a new channel & close this one
vale dockBOT
vale dockBOT
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north mantle
can someone help me out with calc 3 3d coordinate system and circles
north mantle
its kinda breaking my brain
the second image is the question of what im trying to graph
i dont think its right tho because the radius is not 3 on the desmos graph and the y plane is not 6 either
stark wedge
i think it's interpreting the thing as x^2+z^2=9y AND 9y=6
stark wedge
north mantle
thank you
hardy coral
x^{2}+z^{2}=9\left\{y=6\right\} also works
vale dockBOT
@north mantle Has your question been resolved?
limber shoal
vale dockBOT
charred burrow
maybe try a trig sub?
limber shoal
of?
charred burrow
$x^2=\tan \theta$
rocky lotusBOT
DaveyLovesSocks
charred burrow
im not sure this helps actually, it reduced to a bad fraction
rocky lotusBOT
IИFINITE_.
limber shoal
or just 1+x^4
jovial edge
I tried wolfram alpha and it couldn't solve it lol or it doesn't have one. I tried sub and it haven't led me to anything so far
frank pasture
or just 1+x^4
The entire term
jovial edge
This's tough
frank pasture
This's tough
Its really not trust
frank pasture
Diffrentiate
limber shoal
alr
frank pasture
$\int \frac{\sqrt{t^2-1}}{(2-t^2)t}dt$
charred burrow
<:sadthink:899608203736780821> I tried wolfram alpha and it couldn't solve it l...
not even integral-calculator.com could do it
marble arch
root in denominator would mess up the partial fraction though
limber shoal
not getting it bro
frank pasture
root in denominator would mess up the partial fraction though
Wait lemme
limber shoal
can you provide your solution
frank pasture
$t^2 = 1 + x^4$
rocky lotusBOT
Evix
marble arch
<@&268886789983436800>
limber shoal
moderators pulling up for help?
frank pasture
$2t\frac{dt}{dx} = 4x^3$
rocky lotusBOT
Evix
marble arch
IDK about this one dude, the calculators aren't giving an answer and even we're unable to do anything
rocky lotusBOT
Evix
marble arch
use your magic
Doesn't help with Maths mate
marble arch
Yup, IDK if this'll work, maybe a trig sub though?
yeahhh no, contrasting identities in numerator and denominator, it'll get pretty messed up
limber shoal
I swear its probably gonna be this with the most specific ass sub which will cancel everything out
marble arch
I swear its probably gonna be this with the most specific ass sub which will can...
The calculators would have found that though
frank pasture
Il give you the answer
But before thay
I would have to
Pull out a nb
Give me a sec
limber shoal
ig i just need to differentiate the options
marble arch
Wait Evix might be onto something
marble arch
Yeah I saw that, didn't really see anything past it though
vale dockBOT
@limber shoal Has your question been resolved?
limber shoal
this is the answer btw according to the solution
marble arch
**Evix**
Yeah similar to the answer integral calculator gives to this
take 1 + x^4 = t^2 then
vale dockBOT
@limber shoal Has your question been resolved?
marble arch
take 1 + x^4 = t^2 then
Have you tried this @limber shoal ?
limber shoal
Have you tried this <@742612257275641876> ?
I've found the solution
substitute this
limber shoal
limber shoal
frank pasture
But thank you i will try it in the morning!
vale dockBOT
@limber shoal Has your question been resolved?
halcyon tree
I have the equation but I dont understand how to solve it
stiff lily
do you know the formula for average rate of change (aroc)
halcyon tree
yeah for this it would be f(5)-f(1) over 5-1
stiff lily
yes
halcyon tree
how would I solve the top of the fraction?
stiff lily
the values of f(5) and f(1) are readable off the given graph
stiff lily
yes
stiff lily
that's it
halcyon tree
oh I thought there was more okay thank you for the help
stiff lily
apply the formula and simplify
that is all
halcyon tree
can I ask another question?
stiff lily
, is it the same topic?
stiff lily
from which x- values to which
halcyon tree
just the bottem 2 boxes they say the function is increasing/decreasing on the intervals
i dont understand what the intervals are and what I need to find
stiff lily
try to identify the part(s) of the graph that if you were to increase the x-value
the y-coord also increases
and isn't that stuff in the video guide?
halcyon tree
so -1?
stiff lily
you should have more than 1 value
can you highlight the relevant section of the graph
halcyon tree
you should have more than 1 value
can you highlight the relevant section of the ...
I dont know how to get another value
stiff lily
put your finger along the graph
halcyon tree
okay
stiff lily
and move the finger right
and tell me all the locations the finger goes up while following the curve
stiff lily
no
stiff lily
no, the end goal is to get just the x-values
halcyon tree
so 0 and 1?
halcyon tree
okay
stiff lily
now follow the curve slowly
atm is your finger moving up or down
halcyon tree
mhm
stiff lily
that would be your interval
assuming it does indeed go on infinitely like this, you'd represent that as
(-1, inf)
halcyon tree
oh okay
this would be the increasing right?
and is it (-1, inf) or is it [-1, inf)
halcyon tree
okay why is that?
wait it says syntax incomplete
wait nvm
its good
so decrease would be
(-inf, -1)
stiff lily
yes
vale dockBOT
vale dockBOT
Available help channel!
wraith barn
idk if this belongs here but
vale dockBOT
idk if this belongs here but
merry crystal
use the principle of superposition
merry crystal
add up each individual displacement to get the full wave when they interfere
merry crystal
yeah that looks alright
wraith barn
wait like deadass
merry crystal
u just cancel out the shapes
wraith barn
oh shit
wraith barn
u just cancel out the shapes
so its just this?
merry crystal
looks good to me
merry crystal
yeah the third one is what i was thinking its gonna be
wraith barn
yeah the third one is what i was thinking its gonna be
thank you bro
greatest to ever do it
.close
limpid stirrup
How do I solve when one bound is infinity?
vale dockBOT
How do I solve when one bound is infinity?
merry crystal
let the upper bound be a variable t
compute the definite integral using standard techniques (in terms of t)
then take the limit of t to infinity
limpid stirrup
compute the definite integral using standard techniques (in terms of *t*)
still confused by what you mean sorry 🥲
merry crystal
compute the definite integral from 1 to t
https://www.youtube.com/watch?v=ND9cEdfCFr0
see the first example
limpid stirrup
https://www.youtube.com/watch?v=ND9cEdfCFr0
see the first example
thank you
.close
vale dockBOT
vale dockBOT
Available help channel!
hardy snow
I need healp
vale dockBOT
I need healp
tawny moon
do you have a question?
hardy snow
do you have a question?
Would y= 1/7x+4 be the equation for a line with (-4,0) and (3,1) for points
static girder
Would y= 1/7x+4 be the equation for a line with (-4,0) and (3,1) for points
!status
vale dockBOT
Would y= 1/7x+4 be the equation for a line with (-4,0) and (3,1) for points
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
hollow sentinel
Would y= 1/7x+4 be the equation for a line with (-4,0) and (3,1) for points
are you saying $\frac{1}{7x}$ or $\frac{1}{7}x$
rocky lotusBOT
ava 💕
hardy snow
2nd
hollow sentinel
ok
tawny moon
let's see
hollow sentinel
lemme see if ur answer is right rq
ok no
do you know how to find the slope between 2 points?
tawny moon
once you've gotten the slope, you should have the form
y = mx + c
where m is already known
hardy snow
How it becom a fraction
tawny moon
then just substitute either point
hardy snow
What is c
tawny moon
the y-intercept
tawny moon
well
tawny moon
you have $y = \frac{x}{7} + c$
rocky lotusBOT
Hanako
hardy snow
Y1-y0=m(x-x0)
hollow sentinel
Y1-y0=m(x-x0)
try to use this here
hardy snow
Yea i did
hollow sentinel
which point do you want to use
hardy snow
Das how i got 4
tidal swift
why not try Hanako's method then
hardy snow
Did y- 0=1/7(x-(-4)
tidal swift
Did y- 0=1/7(x-(-4)
writing it this way is a bit confusing btw
hardy snow
Shi mb
tidal swift
might wanna just write it on paper and show us
hardy snow
Alr
hollow sentinel
Did y- 0=1/7(x-(-4)
$y-0=\frac{1}{7}(x-(-4))$ ?
rocky lotusBOT
ava 💕
hollow sentinel
ok from here you need to simplify
you dont need to plus 0
since well 0 doesnt make a difference
y-0=y
tidal swift
just toss the -0
tawny moon
from there you should expand the RHS first
hollow sentinel
use distributive property
hardy snow
The what
tawny moon
I jus did it to look easier cuz im dum
isn't it easier to just toss -0 away
hardy snow
Expand meaning
hollow sentinel
distribute
tawny moon
multiply out
hollow sentinel
do you know distributive property
hardy snow
X times 4
tawny moon
no
hardy snow
Invisible 1 times -4
rocky lotusBOT
ava 💕
hollow sentinel
now you simply distribute here
hardy snow
Oh
tawny moon
i'll leave this to ava then
tawny moon
i did nothing, thank ava instead
hollow sentinel
I got it thx <@497400463008727041> <@1147985492319670373>
wait so what did oyu get as your answer
hardy snow
wait so what did oyu get as your answer
Yea 1/7x +4/7
hollow sentinel
its 11:54pm for me i have no life :3
hollow sentinel
do you have any other problems to do
hardy snow
tawny moon
Thanked both cuz of ur time
nah, i don't deserve any. gl with the rest of your work!
hardy snow
do you have any other problems to do
Yea dis
hollow sentinel
do you know synthetic division
hardy snow
Naw
hollow sentinel
long divison..?
hollow sentinel
i dont think i can teach long divison in 3 minutes unfortunately
or well explain it through text efficiently
hardy snow
Fair
hollow sentinel
i would most likely need to convey through paper but i cant rn 😭 i am sorry
hardy snow
All good thx foe ur time
hollow sentinel
go to youtube and watch "theorganicchemistrytutor" video on long divison
polynomial long divison*
stiff lily
polynomial division is similar to division of numbers
where instead of multiples of powers of 10, you're dealing with multiples of powers of x
hollow sentinel
i prefer the box method for myself
its like backwards of multiplying polynomials
stiff lily
determine how many times the
leading term of the divisor: x
goes into
the leading term of the dividend: x^4
that will be the first term of the quotient
multiply that to the divisor and subtract from the dividend (same as numerical division)
then repeat until the degree of the remainder is less than the divisor
vale dockBOT
Available help channel!
final crescent
Hi there, I'm wondering why is my result different than in the book ?
Thanks in advance 🙂
final crescent
I tried to replicate it in python to understand better
final crescent
Oh, isn't it a multiplication to have two elements next to each other ?
craggy girder
,w 7 + 7/48
rocky lotusBOT
craggy girder
Oh, isn't it a multiplication to have two elements next to each other ?
it usually is
2/5 is a proper fraction as 2<5
but if you have 13/5 which is an imporper fraction
ppl like to re write it as 2 + 3/5 or just $2\frac35$
rocky lotusBOT
Wumpus Man
craggy girder
tho you are right it is misleading
final crescent
SO confusing yeah, I hate syntax caviar
Thanks @craggy girder , how to tell the bot it's been answered ?
craggy girder
!close
final crescent
!close
summer oxide
hi
craggy girder
!done
vale dockBOT
If you are done with this channel, please mark your problem as solved by typing .close
final crescent
.close
vale dockBOT
craggy girder
always confuse the two
vale dockBOT
Available help channel!
tired oyster
can solve the limit im only getting c=0
vale dockBOT
can solve the limit im only getting c=0
vale dockBOT
vale dockBOT
Available help channel!
flat kiln
Q8
hot tide
which question
flat kiln
which question
8
I didn't understand the hint.
Why will such k exist satisfying both condns in 3rd line of hint
hot tide
why do you think there shouldn't?
there are finitely many integers betwen -m and n
thus by well ordering principle there is a largest integer
satisfying some property
unless you take $0 \in \bN$, the set of integers between $-m$ and $n$ is nonempty (since $n, m \leq 1$)
rocky lotusBOT
artemetra
hot tide
oh and even if 0 in NN then you still need one of m and n to be distinct from 0 for -m < n to hold
so yeah
hot tide
I didn't understand the hint.
Why will such k exist satisfying both condns in 3r...
so yeah
if you can clarify what specifically you have doubts on you'll be able to get more precise help 
vale dockBOT
@flat kiln Has your question been resolved?
lyric pasture
"represent the signal as the sum of a continuous signal and unit step signals, $x(t) = \cos(2\pi t)[u(t) - u(t-1)]$"
just to check if I have the idea right. we transform $\cos(2\pi t)$ to match the boundary points of the step functions (0,0) and (1,0) to make it continuous, and then add unit step signals to turn it back into the original signal?
rocky lotusBOT
johnseymour20
lyric pasture
then the decomposition is $(\cos(2\pi t) - 1)[u(t) - u(t-1] + [u(t) - u(t-1)]$
rocky lotusBOT
johnseymour20
vale dockBOT
@lyric pasture Has your question been resolved?
lyric pasture
.close
wet granite
vale dockBOT
jovial edge
could you translate the question?
wet granite
could you translate the question?
a) Calculate the value of A when x = 16.
b) Simplify the expression B.
c) Find the integer values of x such that A - B is an integer.
versed granite
and the question please?
thin valley
!status
vale dockBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
woeful rover
and the question please?
The image is the original and the message above you is the translation
thin valley
Yes but what is his question regarding that
wet granite
thin valley
Yes, but what do you want us to help you with?
woeful rover
Do you have trouble starting? Did you start and got stuck?
versed granite
The image is the original and the message above you is the translation
right, but I can't read the actual question, I got the subpart translation
midnight pier
Do you have trouble starting? Did you start and got stuck?
Yeah
wet granite
Do you have trouble starting? Did you start and got stuck?
I finished A) but I’m struggling with b and c
woeful rover
!occupied
vale dockBOT
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
midnight pier
Finded anything