#help-4

1 messages · Page 17 of 1

tidal swift
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and we know the heights of the chord related to the radius

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our goal now is to find the length of the chord made by the bottom of the boat

stuck night
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and how do we do that ;-;

tidal swift
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let's take this step by step

stuck night
#

okay

tidal swift
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first, what's the radius of the waterway?

stuck night
#

5.5ft?

tidal swift
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good

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we know that the surface of the water is 4.5ft from the very bottom of the semicircle.
do we know how far from the center of the circle it is?

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if unclear, we are finding this length marked by the double arrows

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O is the center

stuck night
#

we can subract the radius to y axis?

tidal swift
#

mhm. what do you get?

stuck night
#

(0,-4.5)

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i think

tidal swift
#

nah, just quote it in feet

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and it's not 4.5

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4.5ft is the distance from the bottom to the water surface

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you're finding the distance in red (which is given and doesn't need to be found)
what's the distance in blue?

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the answer is a very small number

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ok maybe not super small but yeah

stuck night
#

1?

tidal swift
#

correct!

stuck night
#

ah! :0

tidal swift
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so we know the water surface is 1ft under the center of the waterway

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now, we are told that the boat submerges another 1ft down

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so the bottom of the boat is ___ ft under the center of the circle

stuck night
#

so 3.5

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ft

tidal swift
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no, that would be from the bottom

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sorry, i meant from the center

stuck night
#

does it 2.5?

tidal swift
#

why 2.5?

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it's not, btw

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but i want to hear why

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we're finding the length in blue again btw

stuck night
#

cus as u said the water is 1 below the center and the boat is submerge 1 more

tidal swift
#

mhm

stuck night
#

or im jsut wrong]

tidal swift
#

1+1 is?

stuck night
stuck night
tidal swift
stuck night
#

uhm ;-;

tidal swift
# stuck night btw why 4.5? the radius is 5.5

the water surface is 4.5ft from the bottom. but we know the radius of the waterway is 5.5ft. so we want to know the distance between the center of the circle and the water surface

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now, the distance between the center of the circle and the bottom of the waterway is a radius, since it's a straight line from the center to the circumference

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so to find the missing length we just do some good old subtraction

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ok now we know that the bottom of the boat is 2ft away from the center of the circle

stuck night
#

yes its 2 ft

tidal swift
#

mhm

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can you take it from here?

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if not, i'll give you a hint: you need trigonometry

stuck night
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ill try

tidal swift
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also another hint - find a right angle somewhere

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the initial length you get will most likely be half of what you need

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i'll be here for another 10 minutes or so. you have my permission to @ me directly if you're stuck

stuck night
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okayy tahnkss

modest ginkgo
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u can also @ me

stuck night
#

is it like this or im completely on the wrong path ;;

tidal swift
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wrong path

stuck night
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hehe

tidal swift
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if you do this you have two unknown sides

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your line of thinking is right. you have to form a right triangle

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but that's not the side you form it on

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hint: you know one of the points must be on the circumference. you know one side must be the 2ft you found earlier
what other known length do you have that connects to a point on the circumference?

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got it?

stuck night
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no yet T^T

tidal swift
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oh sorry to disturb then

stuck night
#

noooo its fine

tidal swift
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i'm still here if you're stuck

stuck night
#

im kinda stuck but still thinking

midnight pier
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Wow so much math going on here

stuck night
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do i form the triangle from teh center?(checking if im still okay;-)

stuck night
#

OH

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WAIT

tidal swift
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let's go?

midnight pier
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Good luck guys and girls

stuck night
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welp i have the idea but idk where to go next ;-;

tidal swift
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show your sketch

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just to make sure you are on the right track

stuck night
tidal swift
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you identified the horizontal line as the 5.5ft radius

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but what about that diagonal line?

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it goes from the center to the circumference

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what is it called?

stuck night
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hypotenuse

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but

tidal swift
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in the context of the circle?

stuck night
#

uhhhhh

tidal swift
stuck night
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radius?

tidal swift
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correct!

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the diagonal line is another radius

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and its length is?

stuck night
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still 5.5? because the radius came from above the water

tidal swift
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correct

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now you have two sides of the triangle

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i wonder what famous theorem you can use here

stuck night
#

AH

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PYTHAGOREAN

tidal swift
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something something squared = another thing squared

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there we go!

stuck night
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hehe wait

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aahhh i didnt bring my sci cal with me but its root of 21

midnight pier
#

Wow u guys are deep into maths

tidal swift
#

i'll give you the answer for this then

stuck night
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but were find the whole lenth so root of 21 times 2

tidal swift
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it's 5.85ft (3sd)

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but is this the final answer?

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wait i may have mistyped

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hang on

stuck night
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🥹

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9.165ft

tidal swift
#

5.12ft*

stuck night
#

ah

tidal swift
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that's the length of the other side

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but is this the final answer?

midnight pier
#

I wanna butt in but it's so long that I can't read it all😭😭

stuck night
tidal swift
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what's pythagoras' theorem?

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a^2 + b^2 = c^2, right?

stuck night
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yes

tidal swift
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but we have a and c

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so we wanna find b

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so what do we do

stuck night
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i got b^2= 25-4

tidal swift
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and the square root?

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eh hang on

stuck night
#

its 4.582

tidal swift
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5.5^2 is 25?

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the radius is 5.5ft, not 5ft

stuck night
#

ay

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ah

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xDD

tidal swift
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oopsie

stuck night
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my bad

tidal swift
#

anyway so we agree on 5.12ft?

stuck night
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yess

tidal swift
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good

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but is this final?

stuck night
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i think no

tidal swift
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look at your diagram again

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mhm

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what do we need to do now

stuck night
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multiply by 2

tidal swift
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you have the length of part of the chord

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correct!

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you're essentially done

stuck night
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10.24

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ft

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:0

tidal swift
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wait

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is this physics?

stuck night
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uhm

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pre calculus:>

tidal swift
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if it's not, you can get away with putting the answer as 10.24

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ok then yeah go ahead with 10.24ft

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if it was physics, i'd recommend you round to 3sd
but well done!

stuck night
#

okeee thnkks

tidal swift
#

remember to .close when done so others may use the channel!

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good luck with the rest of your homework!

stuck night
#

thank you🥹

#

.close

vale dockBOT
#
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vale dockBOT
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still egret
vale dockBOT
glass kelp
#

let ${\sqrt{2} + 1 =a}$

rocky lotusBOT
glass kelp
#

notice

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[ (\sqrt{2} + 1)(\sqrt{2} - 1) = 1 \implies (\sqrt{2} - 1)a = 1]

rocky lotusBOT
glass kelp
#

this thing reduces into a quadratic

still egret
#

what about the power

glass kelp
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just let a^x = u

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or some variable

still egret
#

(a)^x - (a-2)^x ?

glass kelp
#

huh

#

the equation becomes
[ a^x - \frac{1}{a^x} = \frac{3}{2}]

rocky lotusBOT
glass kelp
#

let ${a^x = u}$
[ u^2 - 1 = \frac{3}{2}u]

rocky lotusBOT
still egret
#

Ok thnaks

#

.close

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still egret
#

Find natural number xy such that xy^2 + x divides x^2y+y

stark wedge
#

did you mean you want to find x and y individually or that you want to find all values of the product x*y

still egret
#

x,y

safe tundra
#

I have some questions about graphs. Is the formula y=mx+c because of change in x and change in y

vale dockBOT
safe tundra
#

I keep getting it wrong

stark wedge
#

this channel is currently taken by someone else, please move to a free one!

safe tundra
#

Y

stark wedge
safe tundra
#

Yes

normal hollow
stark wedge
# safe tundra Y

this channel has somebody else's name on it, you have to move and claim your own

vale dockBOT
#

@still egret Has your question been resolved?

still egret
#

x(y^2+1)|y(x^2+1)

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then x|y because gcd x2+1,x=1

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bounding on first step dont work

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and y^2+1|x^2+1

stark wedge
#

ok actually here is a thought

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clearly any pair of the form (x, x) will work

still egret
#

Hm ok

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But how to prove that

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Eh wait

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Nvm

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x<=y implies x^2 + 1 <= y^2+1
But y^2+1 <= x^2 + 1

Therefore y^2+1 = x^2+1

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y=x

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So any pair of (x,x) will work

cloud coral
#

Assuming 0 is not counted as a natural number (which may depend on which teacher you are under)

still egret
#

0,0 is undefined

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So clearly not

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0/0 i mean

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(x,x) where x in Z>0

vale dockBOT
#

@still egret Has your question been resolved?

vale dockBOT
#
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#
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mild python
#

Hey

vale dockBOT
mild python
#

So I'm kind of having a problem right now solving this quadratic formula

stark wedge
#

in the future you should just send your question(s) here without a preface

mild python
#

Is it 25+24 or 24-25

stark wedge
#

neither, it's 25 - 24.

mild python
stark wedge
#

(-5)^2 - 4 * 2 * 3

the (-5)^2 simplifies to +25
the 4 * 2 * 3 simplifies to 24
giving

25 - 24

mild python
#

Which means the answer is going to be 5+1 / 4

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Right?

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I just want to make sure

mild python
stark wedge
#

(5 ± 1)/4

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you have to put brackets when writing fractions in plain text like this

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but yes the answer will be (5 ± 1)/4

mild python
#

Oh alright thank you for your help

mild python
#

.close

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#
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vale dockBOT
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mild python
#

Can anyone check on my answers and see if its right

mild python
#

I legit don't know where I got the (5) from

timber swan
#

Its wrong

glass kelp
#

12^2 = 24 💔

slate folio
#

? Why is 5 in the square root???

severe ledge
#

wrong

timber swan
#

😔

glass kelp
#

oh ye

glass kelp
mild python
#

I am now just realizing all the mistakes I did

severe ledge
mild python
timber swan
#

Do u not think while writing 💔

mild python
severe ledge
mild python
#

I would do that but

#

My teacher strictly said to use the quadratic formula

severe ledge
severe ledge
timber swan
#

💔

severe ledge
mild python
#

Thanks for your help everyone 💔

severe ledge
timber swan
#

Just check by PUTTING THE VALUES

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😭😭

severe ledge
#

that’s not what I said

timber swan
#

No im telling that

severe ledge
#

can you use your eyes?

severe ledge
mild python
#

Yeah

#

.close

vale dockBOT
#
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unique smelt
#

Guys I am searching for someone to do group study on regular bases.
Topic - Differentiation.
Anyone down?

unreal warren
#

hm

unreal warren
unreal warren
#

DM me

vale dockBOT
#
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mild python
#

Can anyone check if my answer is right again

mild python
heavy pecan
#

bro

#

ur supposed to solvenit further

stark wedge
#

(-7)^2 = 49 not -49. you messed up under the root again

#

negative times negative gives positive, yeah?

mild python
#

Wait so -7² will always equal a positive number?

stark wedge
#

(-7)^2

mild python
#

Oh

#

That's what Google’s calculator said

stark wedge
#

there's a difference between (-7)^2 and -7^2

mild python
#

Oh

#

OH

#

That's why I always keep getting it wrong

stark wedge
#

also with all due respect you should not be relying on Google calculator for single digit multiplication imo

mild python
#

Eh fair

#

I know that 7×7 is 49

#

I just wanted to make sure

#

Whether it was positive or not

#

.close

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#
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rough talon
mild python
#

This is what I searched

#

Which I know is completely different

north olive
mild python
#

Well I got x = (7 ± √ 37) /6

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37 isn't a perfect square

mild python
north olive
#

,w solve 3x²-7x+1=0

rocky lotusBOT
mild python
#

where did the 1/6 came from

north olive
mild python
#

Oh okay

#

Thank you

vale dockBOT
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north scarab
vale dockBOT
north scarab
#

Isn’t this wrong

#

I was watching a video and the denominator caught my eye

slate folio
#

show the whole thing

north scarab
#

It should have been 16x^4

noble anvil
#

Bro

#

The whole thing

north scarab
#

why the whole thing I’m only confused with this part

noble anvil
#

:/

wet night
north scarab
noble anvil
#

We cant say if they cut something or not without looking at the numerator

wet night
#

yh the denominator should be 16x^4

red tulip
north scarab
#

But thanks guys

#

.close

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latent breach
#

woudl anyone be able to explain why the lorry slows down after car is added

latent breach
#

even though it mentions nothing ab out friction and that is onyl way to interact

brittle epoch
#

does it slow down?

latent breach
#

It might actualyl speed up but why

brittle epoch
#

conservation of momentum i think

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add the momentum of the car and the lorry and then divide it by the total mass

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and see if the lorry would speed up

turbid valve
#

Momentum must be conserved - so if the lorry's effective mass is increased (because oh idk it's got an extra car on top of it some-the-heck-how mad props to whoever the film students are lol) then the lorry's velocity has to decrease to compensate

brittle epoch
#

would the velocity decrease?

turbid valve
#

The lorry's? Most likely

brittle epoch
#

the car is moving faster than the lorry

turbid valve
#

Oh right, if you were to also consider the car's momentum

wise imp
#

hey guys, im the friend of @latent breach

turbid valve
#

You'll have to figure out the total momentum of the system

wise imp
#

i am doing the question right now, and i have some questions about assumptions made in this case

brittle epoch
#

$\frac{momentum_{car}+momentum_{lorry}}{mass_{car}+mass_{lorry}} > 25.5 m s^{-1}$

rocky lotusBOT
#

General_Jacob

wise imp
#
  1. would it be valid to assume the lorry and the ground have no friction between them
brittle epoch
#

the friction doesnt matter

wise imp
#
  1. if so, why would the car landing on the lorry accelerate the lorry?
brittle epoch
wise imp
#

do we assume there is friction between the car and lorry

latent breach
#

it doesn't matter it becomes one entity

wise imp
#

because if not then there is no horizontal force acting on the lorry therefore it will remain in constant motion

latent breach
#

and there has to be as it breaks

wise imp
latent breach
#

they are physically connected

wise imp
#

and if there IS friction between the car and lorry, will we not need to know the size of the car or the distance between its wheels because we cannot assume the car instantly lands on the lorry as one body

wise imp
latent breach
#

@brittle epoch @turbid valve can you help explain why he is wrong

wise imp
#

@brittle epoch please help asap

#

also why are you interrupting wacky

wise imp
turbid valve
#

Wacky's the OP here

latent breach
#

both

wise imp
#

can you read my messages above please

brittle epoch
#

what is the breaking force of the car

wise imp
noble anvil
#

...

wise imp
#

and prove it is 600N

latent breach
wise imp
#

nothing ☺️

#

just to brighten the mood

brittle epoch
#

you need to show that the stunt is possible

wise imp
#

with breaking force 600N yes

brittle epoch
#

where did you get this problem from?

latent breach
#

its an a level practice question

#

we are both 15 though so thats why he still doesn't know much

brittle epoch
#

is it on the internet?

latent breach
#

i assume

brittle epoch
#

can you send me a link to it

wise imp
#

since he already forgot newtons first law and said that 2 bodies moving at different speeds can be classed as one body with one unchanging centre of mass

latent breach
#

IK just have the question

wise imp
#

if someone can read my messages before and disprove/clear up assumptions then that would be greatly appreciated

brittle epoch
latent breach
#

I think

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I calcaulte thgge new momentum as it has to be conserved

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I can calcualte the new speed of the lorry

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then w = f x d

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I know distancce

brittle epoch
#

and does the car have enough room to brake?

latent breach
#

it says it does we have to prove it

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the entire arguemnt is weather the loprry changes speed

brittle epoch
#

it speeds up

latent breach
#

can u disprove my friend please

cloud coral
wise imp
#

like the question specifies

cloud coral
wise imp
#

so we reduce the car to its center of mass?

vale dockBOT
#

@latent breach Has your question been resolved?

wise imp
#

i said dis

latent breach
#

how do I say question uayd been resolved

spring jackal
#

type .close

latent breach
#

.close

vale dockBOT
#
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vale dockBOT
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vague monolith
#

When i cancel out |x| will it become 1 or 2

vague monolith
#

Or i cant cancel it out

glass kelp
#

depending on ur x

#

wait

#

(2)

vague monolith
#

Oh alr

#

Its bc x^2 is always positive so when it is canceled by a positive value it needs to return a positive value too right?

stiff lily
#

x^2 = |x| |x|

vague monolith
#

Thx yall

#

.close

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#
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river shale
vague monolith
#

alr thx @glass kelp

vale dockBOT
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fathom oasis
#

clknrvejknevf

vale dockBOT
west cloud
fathom oasis
#

@oak crane

fathom oasis
west cloud
vale dockBOT
fathom oasis
oak crane
#

hai

fathom oasis
#

its this

#

my homework

oak crane
west cloud
stiff lily
#

did you find your notes / make an attempt

fathom oasis
#

but i got stuck on 9/4

oak crane
#

you can show work

fathom oasis
#

here

#

dm my handwriting i always had bad handwriting lmao

#

i can send my notes if needed so u guys can explain to me it

tidal terrace
stiff lily
#

are those -9 or do you write your 9s weird

fathom oasis
#

but after that i really just got lost

fathom oasis
tidal terrace
stiff lily
#

you shouldn't be doing that then

#

- * - → +

fathom oasis
tidal terrace
#

$(a\pm b)^2=a^2 \pm 2ab + b^2$

rocky lotusBOT
#

qimmah

fathom oasis
#

right right

fathom oasis
tidal terrace
fathom oasis
#

oh wait

#

i mean

cloud epoch
#

yes that's it

fathom oasis
#

x^2 - 2 * x * 3x + 7?

tidal terrace
tidal terrace
cloud epoch
#

then you can turn it into the left side

oak crane
#

,tex .cts

rocky lotusBOT
#

アキラ (>⩊<)

oak crane
#

you can use this

#

and tell us what you have for left side

fathom oasis
#

im a bit confused

fathom oasis
cloud epoch
stiff lily
#

you've completed the square
the next step is to explicitly express it as such

#

x^2 - 3x + 9/4 = what^2

cloud epoch
#

You have x^2 -3x + 9/4 now
You know that a^2 + 2ab + b^2 = (a+b)^2
So what must a=? and b=? such that:
a^2 + 2ab + b^2 = x^2 -3x + 9/4?

tidal terrace
#

lemme do something rq

#

$x^2 -2(x)(\frac{3}{2}) + (\frac{3}{2})^2$

fathom oasis
tidal terrace
#

$(a\pm b)^2=a^2 \pm 2ab + b^2$

rocky lotusBOT
#

qimmah

tidal terrace
#

looks similar doesn't it

rocky lotusBOT
#

qimmah

cloud epoch
fathom oasis
#

a is x^2 and b is -3x

cloud epoch
#

not quite

tidal terrace
cloud epoch
#

and a

#

both are wrong

fathom oasis
#

What

tidal terrace
tidal terrace
fathom oasis
#

oh i need to find mb i didnt see that

#

gimme a sec

cloud epoch
#

You can write them like that one under the other, then you can easily see what a and b are

fathom oasis
tidal terrace
tidal terrace
cloud epoch
#

(3/2)^2 = 9/4

#

ye

fathom oasis
tidal terrace
cloud epoch
#

What you need to do right now is find a and b then you can move forward

cloud epoch
fathom oasis
#

uh

#

x and 3/2?

cloud epoch
#

yess

#

so a=x and b=3/2

fathom oasis
#

okay

cloud epoch
#

now you know that a^2 -2ab + b^2 = (a-b)^2

#

so x^2 -3x + 9/4=??

fathom oasis
#

(x-3/2)^2

cloud epoch
#

exactly

fathom oasis
#

UAY

fathom oasis
#

whats next

tidal terrace
#

hell yeah

fathom oasis
#

i feel like i was taught differently

tidal terrace
cloud epoch
#

now by looking at your original equation, you have:
(x-3/2)^2 = 7 + 9/4

tidal terrace
fathom oasis
fathom oasis
#

my paper is so dirty alr

#

oml

#

so this is correct?

tidal terrace
# fathom oasis

yep now continue solving
for me I would first add 7+9/4 then continue on

fathom oasis
#

thats rhe thing

#

i dont know how to add or subtract fractions

#

thats where i got stuck on earlier lol

cloud epoch
#

Im sorry, i wrote 7 on the right, but it is -7

tidal terrace
#

ok lemme try to find it cuz I hate typing it out

cloud epoch
#

so your last equation should be -7 on the right

fathom oasis
#

OH RIHT

#

right right

tidal terrace
#

$\frac{a}{b}+\frac{c}{d}=\frac{d}{d}\cdot\frac{a}{b}+\frac{c}{d}\cdot\frac{b}{b}$

rocky lotusBOT
#

qimmah

tidal terrace
#

that's the general idea having common denom. then you can add them

cloud epoch
#

You just want to write it so that all the things you add have the same number on the bottom

#

then you can add all the top numbers normally, and the bottom number stays the same

fathom oasis
#

-7/1 + 9/4 right, automatically has 1 as its denominator?

tidal terrace
rocky lotusBOT
#

qimmah

fathom oasis
#

db are denominators?

tidal terrace
#

like I know that's extra explanation but it's good down the road

cloud epoch
#

because 7/1 = 7

#

then you can multiply the top and bottom by the same number, and it wont change the fraction

#

for example 7/1 = 14/2 = 21/3 = ...

tidal terrace
oak crane
tidal terrace
fathom oasis
#

(4)(-7)+(9)

(4)

#

?

cloud epoch
#

exactly

oak crane
cloud epoch
fathom oasis
#

?

tidal terrace
cloud epoch
#

You forgot the -

fathom oasis
#

HUH

cloud epoch
#

lol

fathom oasis
#

wait

cloud epoch
#

(4)(-7) = -(4x7)

fathom oasis
fathom oasis
cloud epoch
#

4x7 = 28

#

so -28 here

fathom oasis
#

what about + 9?

#

because i added 9

cloud epoch
#

you add it

#

yes

#

so -28+9

#

and then divide it all by 4

fathom oasis
#

so its -37/4.?

#

ohh divide

#

mbmb

cloud epoch
#

noo

tidal terrace
cloud epoch
#

-28 + 9 = ?

#

or ye 9 - 28= ?

fathom oasis
#

ohh

#

19

#

-19

cloud epoch
#

so you have -19/4

fathom oasis
#

yes

#

now divide by 4?

cloud epoch
#

it is divided by 4

#

you can leave it as -19/4

#

you can also write with a decimal, like -4.75, but you'll find that leaving it as a fraction is what is usually best

#

We usually prefer integers divided by integers over writing it with decimals

fathom oasis
#

-7/1 + 9/4 = 19/4

cloud epoch
#

-19/4

fathom oasis
#

i js noticed apple has auto calcu

#

oh yea right

#

-7/1 + 9/4 =-4.75

#

6/4 + 2/5 =1.9

cloud epoch
#

but leave it as -19/4

fathom oasis
#

it calculates automatically thats so cool

#

okay

#

so do i write that down as my next uhh

#

like thing in the solution

cloud epoch
#

step

#

yes

#

now you have (x-3/2) ^2 = -19/4

fathom oasis
#

dang its already 1:30am

#

Whats next?

cloud epoch
#

oof

fathom oasis
#

also, can i send my notes so u can like see how they taught us?

cloud epoch
#

If you want sure

fathom oasis
#

look at uh

#

example 7

#

closest comparison to our original equation

cloud epoch
#

yes

fathom oasis
#

x^2 - 3x + 7

cloud epoch
#

Problem is on the right you have a negative number

#

and you can't just root a negative number

fathom oasis
#

uh huh

cloud epoch
#

unless you have seen imaginary numbers?

fathom oasis
#

yes

cloud epoch
#

You know what that is?

fathom oasis
#

sqrt i

cloud epoch
#

i^2 = -1

fathom oasis
#

yeah but i didnt understand it that much

#

i just know that if its not a perfect square, imaginary roots are applied

cloud epoch
#

the only thing you need to know is that i^2 = -1

fathom oasis
#

okay

cloud epoch
#

incorrect

#

2 isnt a perfect square, but sqrt(2) has no imaginary

#

it's just to find the root of a negative number

tidal terrace
cloud epoch
#

all positive numbers have a square root

#

the only time where we need imaginary numbers is for the root of a negative number

cloud epoch
#

or the root of an imaginary number itself, but not useful here

#

soo

#

you have -19/4 on the right

#

-19/4 = -1 x 19/4
and i^2 = -1
so
-19/4 = (i x sqrt(19/4))^2

#

do you follow?

fathom oasis
#

oh and should i also write it like this already like on my lecture?

#

-19/4*

cloud epoch
#

i dont know how your teacher wants it

#

but in France where im from we Never ever write sqrt of something negative

fathom oasis
#

oh

cloud epoch
#

I think its a pretty common take

#

in math

tidal terrace
cloud epoch
#

same for me

fathom oasis
#

oh yeah i see

cloud epoch
#

but you never write the root of a negative with the symbol

fathom oasis
#

there are no sqrts of negative number

#

its all positive which are in radical

tidal terrace
fathom oasis
#

yes yes

cloud epoch
#

ye so basically, because your equation is (something)^2 = something negative you have no real solution

#

but you can find the complex solutions with imaginary numbers

fathom oasis
#

(x-3/2)^2 = -19/4

tidal terrace
#

the word imaginary itself is misleading to the complex unit

cloud epoch
#

so as i said
-19/4 = (i x sqrt(19/4))^2

#

but also
-19/4 = (-i x sqrt(19/4))^2

fathom oasis
#

uhh

cloud epoch
#

you follow?

fathom oasis
#

so something like this?

cloud epoch
#

you can write +- in front of i

#

its + or - i

#

i^2 = -1
(-i)^2 = (-1)^2 x (i)^2 = 1 x (-1) = -1

fathom oasis
#

FIUGRHJEGJHSBDKJGVDKHGVES

fathom oasis
#

oiay

cloud epoch
#

you need to thoroughly understand it so you're able to do it urself

#

the point of math isnt to get done with the homework and just have the solution, you need to understand so you can do it again

fathom oasis
#

yeah

#

but you kinda have to draw it out for me 😭

cloud epoch
#

Thats not a problem

tidal terrace
#

Something like this would show btw and it may help

fathom oasis
cloud epoch
#

just if anything is confusing tell me so i can elaborate

#

yeah its complicated by just typing

fathom oasis
#

and its also nearing 2am so my brain is fried

cloud epoch
#

ofc

cloud epoch
#

i just dont like it because you write sqrt(-1) but that may be just me

#

maybe your teacher doesnt care

tidal terrace
cloud epoch
#

I understand it, I just dont like it lol

tidal terrace
cloud epoch
fathom oasis
#

not really

cloud epoch
#

hm

#

did you understand what i was saying?

fathom oasis
#

like why did we only distribute x to -3?

#

why not the whole fraction (-3/2)

#

or did they just write it wrong

cloud epoch
#

he did root

#

so he didnt multiply

#

he rooted both sides

#

so the square on the left goes away

#

no distributing

fathom oasis
#

i maybe should get some sleep

cloud epoch
#

yeye

#

sleep is goated

fathom oasis
#

i do not remember the last like 3 steps

#

ill ask my friends for help tomorrow too

cloud epoch
#

sounds good

fathom oasis
#

but i understood what u guys were teaching me

#

WAIT

#

BEFORE I SLEEP

tidal terrace
#

calm down lol

fathom oasis
#

can u teach me the fraction part again

cloud epoch
#

ok

#

I can if you want

fathom oasis
#

cuz i feel like thats one of the biggest obstacles ill face in completing swuars

#

yes pls

cloud epoch
#

lets say you wanna add these

fathom oasis
#

yes

cloud epoch
#

what you do multiply the left by the bottom of the right side and vice versa

#

so on the left you multiply by d/d and on the right by b/b

fathom oasis
#

so b x d
a x c?

#

a

cloud epoch
#

i didnt understand what you said

tidal terrace
#

$\frac{a}{b}+\frac{c}{d}=\frac{d}{d}\cdot\frac{a}{b}+\frac{c}{d}\cdot\frac{b}{b}$

rocky lotusBOT
#

qimmah

cloud epoch
#

yeah

#

that way you have the same bottom on both sides

tidal terrace
#

but just a note for the future if it happens

cloud epoch
#

example if you wanna visualize better

tidal terrace
#

$\frac{a}{b+e}+\frac{c}{d+f}=\frac{d+f}{d+f}\cdot\frac{a}{b+e}+\frac{c}{d+f}\cdot\frac{b+e}{b+e}$

fathom oasis
#

hm

#

wait

rocky lotusBOT
#

qimmah

tidal terrace
fathom oasis
#

is that the same for

#

cuz i find this the easiest

tidal terrace
cloud epoch
#

when you have the same bottom, you can write the whole under one unique bottom

cloud epoch
#

lmfao

tidal terrace
fathom oasis
#

i know common fractioons

cloud epoch
#

I know but idk if he knows it

fathom oasis
#

my bed feels so heavenly

cloud epoch
tidal terrace
cloud epoch
#

man just go to sleep

fathom oasis
#

LMFAO

#

alr

#

thank u guys

#

big life savers

cloud epoch
#

glad we could help

#

sleep tight

fathom oasis
#

^^

#

thanks thanks

fathom oasis
#

BYEBYEE

#

.CLOSE

#

.close

vale dockBOT
#
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Use .reopen if this was a mistake.

fathom oasis
#

😭😭

vale dockBOT
#
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left glacier
vale dockBOT
ivory valley
river shale
vale dockBOT
#

@left glacier Has your question been resolved?

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vale dockBOT
#
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twin garden
#

I dont think my picture is correct, I also have no idea how to continue from where I am at

vale dockBOT
#

@twin garden Has your question been resolved?

shut cobalt
#

@twin garden Think of a property of a 45 45 90 triangle

#

more generally of triangles with angles $\alpha, \alpha, \beta$

rocky lotusBOT
#

Katharine

twin garden
#

so my drawing isn’t wrong?

cloud epoch
#

your drawing isnt wrong

#

@twin garden what can you say about the lengths of the different sides of the triangles ABM and CDM?

vale dockBOT
#

@twin garden Has your question been resolved?

#
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#
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After 15 minutes, feel free to ping <@&286206848099549185>.
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timid briar
vale dockBOT
timid briar
#

i need help

#

ive tried over

#

a million times to get this right

#

someoneee

#

anyonee

tidal terrace
#

just to make sure the formula is Pe^rt ?

fleet dune
fickle rose
#

so (P\qty(1+\frac{r}{n})^{nt})?

rocky lotusBOT
#

PajamaMamaLlama

fleet dune
#

yes

#

I would find the factor the loan grows by from 2003 to 2008

vale dockBOT
#

@timid briar Has your question been resolved?

final adder
#

!nosols

vale dockBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

desert stone
#

The identity here because bank takes interest each year so the rate is one time per yes

#

The formula thus $P(1+r)^n=P’$

rocky lotusBOT
#

Emmaaaaa

desert stone
#

n is year and solve this $1+r=(\frac{P’}{P})^{1/n}$

rocky lotusBOT
#

Emmaaaaa

desert stone
#

And then just plug in will be fine

vale dockBOT
#

@timid briar Has your question been resolved?

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#
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delicate lotus
#

hello i would like someone to help me calculator weighted grade in my biology class because i don't know how they got this number lol

delicate lotus
#

my final grade is the "final adjusted grade:

#

"

oak crane
#

ur 75% is 110, right?

delicate lotus
#

i dont know, it went from 99.96/110 to 61.83/75, and i dont know where they got the 61.83 and the 75 from

#

it went from 90% to 82%...

wintry oxide
oak crane
#

have you did the exam?

#

for 75% i got 68

#

,calc (99.96/110)*75

rocky lotusBOT
#

Result:

68.154545454545
oak crane
#

whatever the 30% is its probably affected

delicate lotus
#

i did everything but this is another thing

oak crane
#

ah d2l

#

maybe try contacting them it must be a typo

spring jackal
#

i see an exam 4 in the announcement but not in the d2l, i wonder if that's why

#

i.e. grades arent released yet and the teacher didn't drop it either so it shows up as a 0

delicate lotus
spring jackal
delicate lotus
#

i also did that bonus thing but they didnt count it i think

delicate lotus
oak crane
oak crane
delicate lotus
#

does the final adjusted grade seem correct>

spring jackal
#

iirc it did something funky for me too, they kept saying "your D2L grade is not indicative of your final grade, check [other software]"

oak crane
spring jackal
oak crane
#

for me it looks they made a mistake cause of d2l stuff

#

so ask them catthumbsup

delicate lotus
#

omg my course closes after tomorrow ;-; I NEED TO CONTACT THEM ASAP AND TYSMMM

oak crane
#

yw

spring jackal
#

aaa good luck!

oak crane
#

dont forgot to close the channel!

#

!done

vale dockBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

delicate lotus
#

.close

vale dockBOT
#
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azure sun
#

can someone tell me how to do this i let the sin cos expression as alpha and wrote numerator as
8+alpha-1/8+alpha
and now just did range but i think i am missing like denominator cant be zero stuff so can someone help me here but yea use the method i used

wraith heart
#

Where's the question

azure sun
#

this is the question

#

u gotta find range of it

wraith heart
#

Find the domain of the inverse

azure sun
#

8 + alpha>=0?

#

so yea now what to do i am having a lil problem in applying this domain to my range that came

#

like removing the values cuz 6/5 is coming in the actual answer too and i have no idea how

#

<@&286206848099549185>

fleet dune
#

I would probably first find the range of 12sin(x)-5cos(x) but that may be difficult

slate folio
#

find the range of 12 sin x - 5 cos x

fleet dune
#

(there is a clever way to do it though)

slate folio
#

it's not that difficult

#

therr's a quick formula for that

azure sun
fleet dune
#

yep

slate folio
#

now what you need to do is suppose 12sin x - 5cos x = t

azure sun
ashen prawn
azure sun
slate folio
#

wait a second

fleet dune
#

so we have (\frac{7+t}{8+t}) with (t\in[-13,13])

rocky lotusBOT
#

Sapien

slate folio
azure sun
ashen prawn
# azure sun yea sure

ok. isme aisa hua hoga ki you know acosx+-bsinx ki range nikali hogi, jo aai hogi [-13,13] and uske saath some 't' wla term too

slate folio
#

and since the numerator and denominator are both linear functions

azure sun
#

and then split the denominator

ashen prawn
#

acc to that result aaya hoga

slate folio
#

it has to cover all real values

azure sun
#

the problem is that denominator cant be zero so i have to makae a seperate condition of that and i am having a problem in applying that condition

ashen prawn
#

i tried ma best

slate folio
#

nvm I was wrong

#

doesnt cover all real values

azure sun
#

yea

slate folio
#

oh I figured it out

#

I made a dumb mistake

slate folio
#

and it has an asymtope at t = -8

#

so you can draw a rough graph of it

vale dockBOT
#

@azure sun Has your question been resolved?

#
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night patio
#

If I roll a fair 6 sided die, what would be the expected number of rolls before 5 comes? Would it be 6 rolls?

merry crystal
#

yes

west cloud
night patio
#

this was the main question

west cloud
#

ah

night patio
#

I mean ig i get what they want

#

btw i already know the answer is 2.45

#

How do i go on approaching this problem

fleet junco
#

notice

#

how

#

theres only 2 cases for the minimum

#

eitehr 5 or 6

#

so just calculate the probablity u roll a 6 bfeore a 5 and the probably u dont

#

and just calc expected val based on that

#

wait nvm

#

i miseread

night patio
#

hmmm i got confused haha

west cloud
#

ig u can do casework

mild marsh
#

Does conditioning on the min not work?

night patio
#

I was thinking of making cases for when 1 is the min, or 2 or 3 or 4

#

But then I got confused about how many rolls should i consider

#

ig it should be 6 rolls then, since ill get a 5 before 6 rolls?

#

thats expected right

mild marsh
#

For the min=4 case, suppose we finish in k rolls, then we need m 4’s to appear, k-m-1 6’s to appear and one last 5 to appear which has sum(m=1 to k-1 of (k-1)Cm) ways of occurring and probability 1/6^k for each case

fleet junco
#

ok

#

i think

#

i got it

#

the expected value

#

is

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P(min >=5) + P(min >= 4) + P(min >= 3) + P(min >= 2) + P(min >= 1)

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which is just a geometric series which is ez to calculuate

mild marsh
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Yep

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But keep in mind that to calculate expected value, you need P(min=5), P(min=4), etc

fleet junco
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@night patio

night patio
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i need a bit of time to process all of this sorry

fleet junco
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yeah lol

night patio
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im dumb 🙏

fleet junco
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but P(min >= 2) = P(min = 2 or 3 or 4 or 5)

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so when u expand the sums

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u get

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sum(x P(min = x) )

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which is the foormula for EV

night patio
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isn't k always bigger than m

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so woudn't the mC(k-1) term be 0 for all values of m < k-1

mild marsh
night patio
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(k-1)Cm?

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this right?

mild marsh
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Yep!

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Fixed it

night patio
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okay easy

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got it

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thank you

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let me read the other messages too