help-4

[radiant garden]

he means the quadratic formula

[latent mortar]

Ik how to do that yeah

[radiant garden]

good to hear

i think you'll be good on your own now

[latent mortar]

👍

[radiant garden]

alot of the people here are way better than me

so dont be afraid to ask

[latent mortar]

I won’t

Ty

[latent mortar]

Ur really good yourself though

[radiant garden]

haha. i wouldnt say so

thank you

[latent mortar]

I got f right

Did I do smth wrong

My book says answer is 2(x-5)^2

[tranquil zephyr]

take 2 common from (2x-10)

[latent mortar]

Oh

[tranquil zephyr]

can you tell me how you form the equation?

[latent mortar]

From what

[tranquil zephyr]

from ab=100 and a+b=-20

[latent mortar]

Yeah

I’ll do it rq

Want me to solve it

Is that what u wanted

[tranquil zephyr]

hm

[latent mortar]

Is it

[tranquil zephyr]

can i suggest a formula

[latent mortar]

Yeah

[tranquil zephyr]

x^2 - (a+b)x + (ab)

[latent mortar]

Erm

Oh yeah

Ik that

What about to

It

[tranquil zephyr]

it'll be to form the equation with it

*easier

[latent mortar]

Doesn’t that just factor

[tranquil zephyr]

yea you'll have to factor the equation after forming it

but forming it becomes easier

[latent mortar]

Well to make it easier I can just bring 100 to the lhs

[tranquil zephyr]

one sec

[latent mortar]

10+10=20

10*10=100

Boom factored

And

U can find answer fast

[tranquil zephyr]

anything that works for you is fine

[latent mortar]

Is that right

Forgot the +-

But

[tranquil zephyr]

oh u wanna find a and b?

[latent mortar]

I’m finding the toots

Roots

Isn’t rhat what u wanted?

[tranquil zephyr]

well

[latent mortar]

U asked me to form the formula with the a and b

[tranquil zephyr]

-10 is the answer

[latent mortar]

What’s the bot command to rotate again

,r

$r

I don’t remember

[tranquil zephyr]

its +10 in the image btw, i wrote - instead of plus lol

here

[latent mortar]

lol

[tranquil zephyr]

its very easy if you use the x^2 - (a+b)x + ab

[latent mortar]

Yeah

We call that stevin formula

In Brazil

[tranquil zephyr]

nice

we just call it x^2 - (a+b)x + ab

[latent mortar]

😭

[tranquil zephyr]

well keep working

i have an exam in about 8 hours

[latent mortar]

Gl

[tranquil zephyr]

ty

[latent mortar]

U still here

What numbers add up to -5 and multiply 6

Oh nvm

.close

[vale dock]

Channel closed

Closed by @latent mortar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[placid wasp]

Could someone please give me a hand with this?

[verbal badger]

multiply (2+i)(2-i) = 0 out

[frozen ledge]

p(x) has a zero at x = a if (x - a) is a factor of p

[placid wasp]

@verbal badger and then?

[frozen ledge]

5 = 0

[placid wasp]

OK, sorry, I'm not there yet. Something a little simpler please?

[verbal badger]

Sorry, lemme be a bit more precise

As the other guy said, if (x-a) is a factor of p, p(x) has a zero at a

[frozen ledge]

did you read my message?

lmao

[verbal badger]

so we want (x-(2-i))(x-(2+i)) = 0

where "a" are the two roots given

[placid wasp]

how do we know we want that?

[frozen ledge]

a polynomial can always be expressed as c(x - a_1)(x - a_2)…(x - a_n)

[placid wasp]

OK, got that far

[frozen ledge]

you’re given the roots

[frozen ledge]

so expand this

and we know that each root occurs once since p is degree 2

[placid wasp]

x^2-2ix-2ix+((2+i)(2-i)), correct?

Is that right?

[frozen ledge]

no

[vale dock]

@placid wasp Has your question been resolved?

[vale dock]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[compact knot]

b) (google translate translation) Let v ∈ R3 be arbitrary. Find the column vector that belongs to the vector Fv in the basis Π
b) (my translation) some v is an element of R^3. Find the column vector which is in the base pi and belongs to the vector F(v)
the solution is [3x, -2x-4x, -x+6y+z]
why is that the solution?

[stark vector]

a vector who belongs to a vector ? the question seems weird

[compact knot]

to be fair I translated it from slovene to english

[stark vector]

hm ok i got it

i mean i understood the sentence

[compact knot]

some v is an element of R^3. Find the column vector which is in the base pi and belongs to the vector F(v)

and the solution is [3x, -2x-4x, -x+6y+z]

[stark vector]

no clue sry

[compact knot]

<@&286206848099549185>

[stark vector]

do you have to use the matrix ?

if no, i can help for the start

[compact knot]

not sure which one you mean

[stark vector]

the one from question a)

,rotate

[stark vector]

i think this is true

but i have not verified so be careful

[compact knot]

oh I solved a)

for b) I dont have a clue

[stark vector]

the picture i sent is for b)

except if i have misunderstood again

[compact knot]

oh shit wait

im stupid

lol

youre right

[stark vector]

you found a simple trick with the matrix ?

btw i checked the picture i sent is right, i have to go bye

[compact knot]

thanks for the help : )

.close

[vale dock]

Channel closed

Closed by @compact knot

Use .reopen if this was a mistake.

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[green shore]

Can someone help me again

[green shore]

I just dont understand how i keep getting them wrong

I keep thinking i get it, then its wrong

Like i dont even see an up concave on here, i know this is easy stuff but i dont get the rules and would love help

[distant galleon]

Recall that:

• f’’>0 means f is concave up
• f’’<0 means f is concave down

[green shore]

I know, so WHY isnt the answer
(-inf, -4), (0, inf) correct?

It says its wrong

[distant galleon]

Also, in the future, please say what you’ve done so far - it’s annoying to say stuff for no reason

Ex. Here, you could’ve said “my answer was … because of …, but it’s wrong”

[green shore]

okay, so i dont get sent back to the beginning of this again i need to ask, do you think its (-4, 0)?

[distant galleon]

Yes, b/c that’s when f’’>0.

[green shore]

Also, i misread this because i have dyscalculia man, calm down

[distant galleon]

I was just marking the key points dw - no aggression intended.

[green shore]

oh alr, i think i just misread the intent

[green shore]

Alright this COULD be the last one so i can finally sleep, do you think its (-4, 0), (2, inf) ?

[green shore]

omg theres one more

im gonna rip my hair out

Oh this one is different

[green shore]

Alright man, i think ive got the last one down

Im thinking its (-4, 0), (0, inf) ?

or maybe just (-4, 0)

I really dont know why these rules are so hard for me to retain

Okay it was not the first option, i have one more try before im sent back to start

[distant galleon]

How did you get those

[green shore]

Well i thought that the downward from -4 to 0 meant concave up?

Did i remember the rule wrong?

[distant galleon]

The graph is of f’(x), not f(x)

Also if it was the graph of f, you’d include x=0

[green shore]

so it SHOULD be (-inf, 4), (0, inf)?

Im really trying here man

[shrewd notch]

Ur doing great bro

[green shore]

THERES MORE

I just want to sleep

Okay, so can someone explain what i did wrong? please

[distant galleon]

You might’ve read the value of f instead of x here

[green shore]

Oh my god

Im sorry mr pidgeon

Okay

This one should be the last one, then my bed is just over yonder

im THINKIN, (-inf, -6), (-3, 0)

[green shore]

Why are they doing this to me

[distant galleon]

[green shore]

I DID IT

[distant galleon]

[distant galleon]

[green shore]

Mr pidgeon i love you

Im going to bed

[distant galleon]

[green shore]

How do i close this?

So others can use?

[distant galleon]

!done

[vale dock]

If you are done with this channel, please mark your problem as solved by typing .close

[green shore]

.close

[vale dock]

Channel closed

Closed by @green shore

Use .reopen if this was a mistake.

[green shore]

!done

[vale dock]

If you are done with this channel, please mark your problem as solved by typing .close

[green shore]

Im sure its good now

Goodnight'

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[blissful void]

hi

[timber swan]

?

[blissful void]

is it possible to study integration in one day

[glass kelp]

how far are u in calculus

[timber swan]

Yes

But no

[blissful void]

why

[sleek nebula]

It depends to how deep a level you wish to learn it

[glass kelp]

fair

[sleek nebula]

And it depends on your existing capabilities

For example if i were to give someone with no math background all the materials he could learn

I doubt he would be able to solve MIT integration bee problems after 1 day

[vivid fiber]

Until what point?

Like until some basic rules prob yes but ur not gonna master those basic rules in one day

[glass kelp]

the essential thing

is to be able to truly understand the rationale behind integration

[blissful void]

basic

i have exam next week

[glass kelp]

have u learned

differentiation yet

[blissful void]

yes

[glass kelp]

then ye

its possible

[blissful void]

my problem is with properties

[glass kelp]

such as

[blissful void]

there is many functions

[midnight pier]

hello, mind if I post a question here?

[blissful void]

like d/dx[e f(x)]=e f(x).d/dx[f(x)].

[glass kelp]

another channel plz

[midnight pier]

alright

[glass kelp]

[ \frac{d}{dx}e^{f(x)} = e^{f(x)}\frac{df}{dx}]

[rocky lotus]

k

[glass kelp]

chain rule?

[blissful void]

hm

what should do

idk anything in integration

[glass kelp]

maybe watch a youtube

vid

or do khan academy

[fickle rose]

Some properties:
Linearity of Addition and Scalar Multiplication:
[\int Af(x)+Bg(x)dx=A\int f(x)dx+B\int g(x)dx]
Integration by Parts ("Inverse Product Rule"):
[\int f(x)g'(x)dx=f(x)g(x)-\int f'(x)g(x)dx]
U-Substitution ("Inverse Chain Rule"):
[\int f'(g(x))g'(x)dx=f(g(x))+C]
FTC, Part I:
[\frac{d}{dx}\int_0^xf(t)dt=f(x)]
FTC, Part II:
[\int_a^bf(x)dx=F(b)-F(a)]

[glass kelp]

or read documents provided in ur course

[rocky lotus]

PajamaMamaLlama

[fickle rose]

those are the basic ones, but in a regular calc course I'm sure things like trig sub will be covered

[glass kelp]

insane

[blissful void]

ok

what is the best way to study it

[fickle rose]

what k said, just Khan Academy of videos watching demonstrations :)

[blissful void]

ok

[fickle rose]

I know a lot of courses use Stewart's book (could be wrong about that)

https://patemath.weebly.com/uploads/5/2/5/8/52589185/james-stewart-calculus-early-transcendentals-7th-edition-2012-1-20ng7to-1ck11on.pdf

[blissful void]

thank you everyone

it was very helpful

[vale dock]

@blissful void Has your question been resolved?

[vale dock]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[modern forum]

is my ans correcT?

[golden gate]

Looks correct to me

[modern forum]

oh cool

thanks again !

.close

[vale dock]

Channel closed

Closed by @modern forum

Use .reopen if this was a mistake.

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusty zenith]

What s the measure of the angle between vad and vab

The plane thingy idk what its called in english

Well its angle BVD and 45° but idk how (i checked answers)

VA VB and VC are 9√2

Abc echilateral triangle with 18cm

D middle of bc

[timber swan]

Is that a tetrahedron?

[vale dock]

@dusty zenith Has your question been resolved?

[dusty zenith]

Pyramid

With triangle base

Ab is 18 and va is 9√2

[vale dock]

@dusty zenith Has your question been resolved?

[vale dock]

@dusty zenith Has your question been resolved?

[clever sentinel]

@dusty zenith

What angle you need to find exactly?

What you wrote above is very confusing, just tell me the angle that is asked to find.

[vale dock]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cobalt crow]

guys

[cobalt crow]

domain and range of the square root

how do i find it

[glass kelp]

inside >= 0

[heady pawn]

what values can you plug in such that it gives a real value = domain

[glass kelp]

outside >= 0

[heady pawn]

what are all the values that can come out = range

[cobalt crow]

sqrt : R -> R?

[ivory valley]

I would try to work with sqrt(x) and see how transformations affected the range. For example sqrt(x) -> sqrt(x)+1 so the range went from [0,oo) to [1,oo).

[glass kelp]

would say R^+U{0}

for domain

codomain is fine

[cobalt crow]

how did you figured sqrt(x) has range 0, oo

[ivory valley]

I take that as a fact

[cobalt crow]

codomain is R?

awinus is saying codo is 0,oo

[ivory valley]

Assuming f : [0,oo) -> R

[glass kelp]

can be R or smaller

if u want codomain to be the range then

[ivory valley]

Principle applies still with the codomain being a subset of R.

[glass kelp]

f : [0,oo) -> [0, oo)

[cobalt crow]

wait a moment

can someone tell me the range and domain of sqrtx

[glass kelp]

domain: [0, infty)
range: [0, infty)

[cobalt crow]

do you agree aswell anti algebraist?

[ivory valley]

Yes

[cobalt crow]

both are a subset of R

[ivory valley]

Isn't k trustworthy?

[glass kelp]

😭

[ivory valley]

Cautious! Codomain is not the same as range!

[cobalt crow]

i think he is, i just wanted to check everyone is in the same page

[ivory valley]

I feel that's confusing you?

[glass kelp]

https://tenor.com/view/pubgda-1-kill-alma-sevinci-gif-7037318915877847102

[cobalt crow]

the fuck?

[ivory valley]

I did a typo my lil bros, forgive me

[cobalt crow]

what would be codomain of sqrtx

R?

[ivory valley]

Yes, possible

You can define the codomain as you want

The worst that happens is, it restricts the range.

[midnight pier]

{0}

[noble anvil]

What

[cobalt crow]

is it possible domain of sqrtx is C?

xd

[ivory valley]

Well yes, you can extend it a complex function

I would also set the codomain C then

Since it maps to complex nunbers as well

[cobalt crow]

well i disagree

[glass kelp]

lets be real, guys

and not go complex

[cobalt crow]

yes i think this is right, srry

but in the traditional sense, sqrt is defined only for real positive numbers

[glass kelp]

or its just anything to the power of 1/2

..

[ivory valley]

If you dont take complex analysis, sure

[cobalt crow]

why is it a big deal when the sqrt only taking positive numbers?

[glass kelp]

wdym

[cobalt crow]

sorry for my English, I'm non native

[glass kelp]

its only taking positive numbers U {0} if we wanna stay real

i believe we are familiar with the notion of i

[steady charm]

you can only take positive numbers if you want your codomain to be R or some subset rather than C

if you allow the codomain to be C then the domain can by any subset of R or C

and the math you are most familiar with almost always uses functions with a domain of some subset of R and codomain R

[ivory valley]

Unless you are intersted into surjections, injections and bijections, you go with codomain R

[cobalt crow]

i appreciate it haha i think i get the gist of it rn

[cobalt crow]

yes, ty guys

i appreciate all the info said

and the time taken

.solved

[vale dock]

Channel closed

Closed by @cobalt crow

Use .reopen if this was a mistake.

[fierce delta]

um can I ask a math doubt here?

[leaden cargo]

This channel is not available yet, you have to use an available one

[fierce delta]

oh

ok

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[daring forge]

Hello.
I am trying to solve a programming problem.
Given :
A square of side length L, defined by points A, B, C, and D.
A point S, strictly inside the square.
A unit vector N.
X is a point on the square, such that X = S + d.N. Where d is the distance between S and X.
Find the value of d.

I don't require a detailed explanation. I just need advice about the best way to go about solving the problem.
I think performing a ray - line intersection against every edge of the square is a viable solution, but I think I can do better.

[vale dock]

@daring forge Has your question been resolved?

[daring forge]

Update:
I was able to solve this problem by testing the ray for intersection against all four edges of the square.
Reference : https://rootllama.wordpress.com/2014/06/20/ray-line-segment-intersection-test-in-2d/

I am keeping this channel open in case someone has a better idea. 🙂

[vale dock]

@daring forge Has your question been resolved?

[vale dock]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[jade verge]

An equilateral triangle has centre O and side length 1. A straight line through O intersects the triangle at two distinct points P and Q. The minimum possible length of PQ is:

a) 1/3 b) 1/2 c) root3/3 d) 2/3 e) root3/2

I have found the length from vertex to midpoint to be 3/4 discounting e but obviously this is the maximum, its not necessarily working it out then i find hard here, i do not definitively know what is the shortest distance. It is an MAT q from 2019

[vale dock]

@jade verge Has your question been resolved?

[jade verge]

hmm, the answer is 2/3 but the markscheme i think goes about it in quite a convoluted way

[trail patrol]

Oh, I misread

The segment I proposed doesn't even pass through O

Ignore me

But even tho, I think my suggestion could be used anyway

The point O is at the height sqrt(3)/6 from the base

And the segment PQ parallel to the base at this height has length 2/3

[jade verge]

wait whats the reasoning for getting from sqrt(3)/6 to 2/3?

[trail patrol]

Let me sketch it

And here's the segment I mentioned

And how to get it, it's pretty simple if you know that the centorid divides each median into parts in the ratio 2:1

The height is sqrt(3)/2, so just 1/3 * sqrt(3)/2 = sqrt(3)/6

[jade verge]

oh right ok, thank you

not too difficult, i would probably forget that in an exam tho

[trail patrol]

Then calculate PQ

[jade verge]

.close

[vale dock]

Channel closed

Closed by @jade verge

Use .reopen if this was a mistake.

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sweet pasture]

Didn’t I do a mistake when doing this

Right where I do the star beside number 5, isn’t the equation x -3y -2z = 9

Do the equation that it equals is 5x - 7y = 15

Not = -3

?? Idk I did this a while ago and I’m just refreshing my memory but it looks wrong

how did i get the right answer tho be (2,1,4) is right

oh

nvm

i got it lol

ik my mistake

ahah

.close

[vale dock]

Channel closed

Closed by @sweet pasture

Use .reopen if this was a mistake.

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusty zenith]

The one between the 2 planes vab and vad

[vale dock]

@dusty zenith Has your question been resolved?

[vale dock]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tardy hamlet]

can someone help

[vale dock]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[tardy hamlet]

someone helping?

[river shale]

Interesting

[neon summit]

16 squares in 1st one

hmm

[vocal tusk]

from what i counted
bottom area is 9+e and top area is 7-e for ur line

e is let's say the bottom area of bottom left square

[tardy hamlet]

i got the first one

[vocal tusk]

so you prolly wanna shift it down a bit

[vocal tusk]

what did you get

[tardy hamlet]

its 8

because

you can do

pythag

if you add to make a square

but since its odd rows for second you cant do it

[vocal tusk]

huh

what was your partition

ur line through M

[tardy hamlet]

wdym

speak elemently english pls im stupid

[vocal tusk]

what is 8?

[neon summit]

total area after partition ig

[tardy hamlet]

yeah

[vocal tusk]

yes 16/2 = 8

[neon summit]

can u send ur line

[tardy hamlet]

each side is equal to 8

[vocal tusk]

how do you edit images on discord

[neon summit]

the half erased one in the figure isnt correct

[tardy hamlet]

yeah

[candid monolith]

Anyone helping me as well ?

[vocal tusk]

no

[tardy hamlet]

i did working on another one

[vocal tusk]

!help

[vale dock]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[neon summit]

you didnt reply

[candid monolith]

Check help-35 | yuto-designer

[neon summit]

yeah check it again

[vocal tusk]

you drew another line?

does this work?

[tardy hamlet]

yes i got that

[vocal tusk]

do you know if it's correct

[tardy hamlet]

yeah that one is correct

but the 2nd one i dont know if i got right

[vocal tusk]

ok so you checked all the trig

[vivid fiber]

It doesn't need trigom

[vocal tusk]

or pythagoreas

[vocal tusk]

yes true

[tardy hamlet]

so how do you do the 2nd one

[vocal tusk]

you can just use that area of triangle = 1/2 * area of surrounding rectangle

[tardy hamlet]

yeah

i did that

[vocal tusk]

i think you would check it much the same way as the first

[tardy hamlet]

um

can i explain my answer?

so

i did

theres 25 squares so each side has to have 12.5 squares, and on the bottom right side theres 3 essentially spare blocks which leaves the rectangle, so then the length at bottom is 7 and total area is 9.5 because 12.5-3 spare, so then the other length would be 19/7 after you do the working

[vocal tusk]

ok lemme check

i think ur bottom area is 13.5

3 + (7*3)/2

[vocal tusk]

oh are you trying to work backwards?

yes but you're not guaranteed 3 "spare" squares this way

[tardy hamlet]

😭

im cooked

[vocal tusk]

that's only for the line u drew

[tardy hamlet]

can you do it and show how you did it?

[vocal tusk]

good try

i haven't done it yet

[vocal tusk]

do you agree with this

so basically you need to shift ur line down a bit

cuz u want bottom area to be 12.5

[tardy hamlet]

but i think the placement doesnt matter for the line

i just mainly is the explaination of how

[vocal tusk]

what

the question is to find the right line

and explain why it works

[tardy hamlet]

hmmm

oh yes

so do you reckon you could show the explaination?

[vocal tusk]

oh i can see u already wrote 13.5

u gotta communicate more pig

[tardy hamlet]

sorryyy

what was the question

[vocal tusk]

did you try this

[tardy hamlet]

yes

[vocal tusk]

i see you wrote 10?

explain

[tardy hamlet]

the bottom would equal 10

[vocal tusk]

communicate

ok good

[tardy hamlet]

yes ok so

m and that point

is striaght

[vocal tusk]

so it should be somewhere in between

between 10 and 13.5

[tardy hamlet]

yes

[vocal tusk]

to get 12.5

[low olive]

hi

[tardy hamlet]

yes

[vocal tusk]

any other ideas?

[tardy hamlet]

im kind of stuck now

because

[vocal tusk]

you could try this

[tardy hamlet]

i realise the height it not in the corner

yes it would be there

but what woukd the explaination be?

[vocal tusk]

well find area below the line

hopefully it should be 12.5

if it is then the top is also 12.5 because total = 25 and 25/2 = 12.5

[vocal tusk]

using ur rectangle method

using this rectangle

where the line goes corner-to-corner

[tardy hamlet]

yes so

the height

should be 19/7

[vocal tusk]

ah i think this line doesn't work

you get 11+e

[tardy hamlet]

Why?

[vocal tusk]

so this is area 6

(6*2)/2

+5 + e

[tardy hamlet]

the area of what is 6

[vocal tusk]

triangle

below the red line

[tardy hamlet]

why is it 6?

[vocal tusk]

it's the same thing u've done before

[tardy hamlet]

i mean like

[vocal tusk]

base = 6

height = 2

do u see that

[tardy hamlet]

why wouldnt you extend the line to the endpoint and just the small triangle

its not to scale tho

[vocal tusk]

yes but squares are squares

[vocal tusk]

cuz it meets the corners

so you know the base and height exactly

[tardy hamlet]

would you reckon its a square though because i first drew the line too high?

[vocal tusk]

what is a square

[vocal tusk]

we define the line to be such that it crosses this corner

there is no further assumption

[vocal tusk]

so yeah the correct line should be somewhere between the red and gray one

so it will not be a clean solution

it will be a bit messy

to find it, i think you would have to use trigonometry

[tardy hamlet]

but im year 9

and we havent learnt trig yet

😭

[vocal tusk]

maybe they just want an approximate solution

but in the first case u can get exact solution without trig

[tardy hamlet]

yeah

[vocal tusk]

this one

[tardy hamlet]

the first one has even number of rows so its always in that spot

[vocal tusk]

this is the case of an even number of rows

and it generalizes to any even number of rows, not just 4

which is part b

[tardy hamlet]

so what does n=2k have you do with it?

[vocal tusk]

wdym

[tardy hamlet]

like what is n=2k

[vocal tusk]

n is even

[tardy hamlet]

even number of rows?

[vocal tusk]

yes n is the number of rows

ah yeah i guess they didn't define n

if n is even then n = 2k for some k

conversely every number of the form 2k is even

[tardy hamlet]

😭

can you explain how that relates to the quesiton

[vocal tusk]

do u get this

[tardy hamlet]

yes

[vocal tusk]

ok and in part b we assume n is even

so n = 2k for some k

[tardy hamlet]

yes

[vocal tusk]

do u get this

[tardy hamlet]

what is for some k?

[vocal tusk]

there exists a number k

such that n = 2k

eg if n = 10

[tardy hamlet]

then k is 20

so its a number

[vocal tusk]

k = 5

[tardy hamlet]

oh shoot

yes

because 2x5=10

sorry

[vocal tusk]

n = 22

[tardy hamlet]

11

[vocal tusk]

k = 11

yes

[tardy hamlet]

what does k relate to though in the question

like the area

or

[vocal tusk]

what is k here?

[vocal tusk]

(number of rows)/2

[tardy hamlet]

1=

1

unc?

you there

[vocal tusk]

sorry

[tardy hamlet]

alg

[vocal tusk]

uhh idk what to say

[vocal tusk]

what is 1

[tardy hamlet]

k =11

i meant

1

[vocal tusk]

no

[tardy hamlet]

k=1 because n=2

[vocal tusk]

how many rows are there

[tardy hamlet]

ohhh

total rows

theres

4 total rows

[vocal tusk]

go on

[tardy hamlet]

so k=2

[vocal tusk]

yes

[tardy hamlet]

but what does 2 have to do with the probelm

[vocal tusk]

do u get how n=2k works

[tardy hamlet]

yeah

but what does k have to do though with the

problem

[vocal tusk]

can u find the solution when k=3

[tardy hamlet]

n=6

[vocal tusk]

it is a way of talking in more generality

something we do in higher math

[vocal tusk]

yes but i meant the solution to the line

when n=6 you get a new pyramid

[tardy hamlet]

would be the 3rd corner

[vocal tusk]

and 3 = k

[tardy hamlet]

ohhh ok

[vocal tusk]

u just wanna describe the solution for any n=2k

[tardy hamlet]

so answer would be that k = the corner where the end of line lies on?

[vocal tusk]

if you specify how you're counting corners, yes ...

what does " k'th " corner really mean

[tardy hamlet]

uh i dont know how to explain

like

[vocal tusk]

you could say - start counting from the bottom right square and go along the right edge of the pyramid and choose the k'th square. then the line should cross the top left corner of this square

[tardy hamlet]

oh ok i understand

so start bottom right corner and go up what k is

could you lastly help with second part of a?

[vocal tusk]

go on

[tardy hamlet]

this one

how to prove that the line is there

[vocal tusk]

what i drew there is not the right answer

[tardy hamlet]

oh why

[vocal tusk]

ok i gtg, good luck

maybe someone else can come help

worth keeping the channel open

just a tip: try to make ur questions specific

[tardy hamlet]

yes ok thanks so much tho

[vocal tusk]

omg i just realized your 19/7 thing is correct

i get what you mean now

[tardy hamlet]

??

[vocal tusk]

that is the solution for part a second part

[tardy hamlet]

😭

thanks again for all the help though

[vocal tusk]

ok

ru still confused about smth

u gotta try to communicate better

but u smarter than i thought pig

[noble anvil]

Nice name unc

[vocal tusk]

appreciate it

[tardy hamlet]

thanks unc

what grade are you

[tardy hamlet]

yeah sorry its kinda hard to talk online, im better irl explaining by showing

[vale dock]

@tardy hamlet Has your question been resolved?

Channel closed

Closed by @tardy hamlet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[compact knot]

in this example, why is the result (5, 2), when we're not in the standard basis anymore?
from the video: https://youtu.be/kYB8IZa5AuE?si=WGWn27MRqx3zRCes&t=243

[vagrant coral]

ok sir

[high elm]

We've switched from the standard basis {(1 0), (0 1)} to {(1 -2), (3 0)}

to find where the vector lands in some arbitrary basis you just replace ihat with the first basis vector and jhat with the second basis vector

in the standard basis you would have
-1 * (1 0) + 2 * (0 1)

which is just (-1 0) + (0 2) or (-1 2)

[vale dock]

@compact knot Has your question been resolved?

[compact knot]

oh ok, got it

[vale dock]

Channel closed

Closed by @compact knot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worldly ledge]

how do I work out C?

[worldly ledge]

my thought process was soemthing like

if you have 2 matrices such that their subspaces are the x and y axis then their linear combination would move out the axis therefore it has to be false

is that vague?

[arctic folio]

exactly you are creating a symmetric curve

[vale dock]

@worldly ledge Has your question been resolved?

[vale dock]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lime bone]

I choked!

[lime bone]

I cannot believe it

(2,0,2) and (2,2,0)

I cannot calculate the area of triangle that spans by these two vectors

Oh my Mickey lord

Kinda of mad

Mickey lord saves me

[vivid fiber]

!status

[vale dock]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[lime bone]

I ahh

Ahh

Mickey lord, I see him

It is the cross product

Is there any other way to do it

[noble anvil]

Heck are you on about.

[noble anvil]

sure

find points of intersection in the cartesian plane

[vale dock]

@lime bone Has your question been resolved?

[vale dock]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lime bone]

Hello

[lime bone]

Please elaborate

[noble anvil]

Actually meant just points, but yeah

Consider 0,0,0 (the origin) the point from where these vectors begin (their tail)

Then you can find the other two points of the triangle

And calculate area

[vale dock]

@lime bone Has your question been resolved?

[vale dock]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[drowsy lagoon]

1.b

I have no clue at all

what am I reading :-:

[vale dock]

@drowsy lagoon Has your question been resolved?

[drowsy lagoon]

.close

[vale dock]

Channel closed

Closed by @drowsy lagoon

Use .reopen if this was a mistake.

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[noble anvil]

Good for you, time to type .close

Do you have a question?

Why not start with it

[copper stump]

surely your maths class would cover it in near future no?

[noble anvil]

#help-18 message

[noble anvil]

derivation of the nx^(n-1) formula.

[copper stump]

some khan academy or equivalents videos then

[noble anvil]

Also, you don't need that right now.

What do you wish to know the derivation for?

[still talon]

to derive it you need to know about limits and stuff

[copper stump]

bruh, you dont need it now is the worst reason to not learn something

[still talon]

Yk that?

[noble anvil]

If they don't know about limits, it's probably best to learn those first before looking for derivations of derivatives.

[still talon]

then u should wait

[midnight pier]

Just brought stewarts early transcends for calculus..got any tips how to tackle it? Like a guide or smth

[vale dock]

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

[copper stump]

I mean, the general idea that the derivatives are slopes of tangent is good enough to understand, without rigorously going thru the basics

[noble anvil]

Yeah but that doesn't really help you derive the derivatives themselves.

If you say so

Good for him

[glass kelp]

wonderful

[noble anvil]

.

Bruh

[vale dock]

Channel closed

Closed by @delicate frost

Use .reopen if this was a mistake.

[noble anvil]

Hacks

[still talon]

U stole his chalantness

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dawn mountain]

Question is to find the value of sinx

the answer given is tan^2 alpha/2.

[modern rune]

First, what's your value for the hypotenuse

[dawn mountain]

derived it using tan-1; 1+cos alpha

lemme see if i can latexify the question rq

gimme a minute 😂

lesgoo

o crap

[rocky lotus]

Hobbes_

[dawn mountain]

there we go

third times a charm

oh no

silly mistake

forgot about denominator in sin-1

.close

[vale dock]

Channel closed

Closed by @dawn mountain

Use .reopen if this was a mistake.

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar crypt]

I need help factoring this

[cedar crypt]

Don’t mind my previous attempts

[noble anvil]

Factor the first expression individually

[cedar crypt]

(y-5)(y+1)(4y²+6y+1)

[storm perch]

Can you further factor the last expression (asking if possible or not)?

[vale dock]

@cedar crypt Has your question been resolved?

[stark wedge]

do you mean factor or expand?

[stark wedge]

factor* not equation

please dont misuse the word "equation" as a helper

[storm perch]

My mind is freid

I was thinking of "expression" and wrote down "equation"

[vale dock]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[noble anvil]

.reopen

[vale dock]

✅

[noble anvil]

No, not unless you use the quad formula

But then it'd just be ugly

I would just leave it like this

.close

[vale dock]

Channel closed

Closed by @noble anvil

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lofty mist]

The graph of a function of the form
f(x) = c \cdot x^3
lies below the graph of
g(x) = 2x^2
for 0 < x < 1.
What values are possible for c?

[vale dock]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[lofty mist]

1

[stark wedge]

you want the inequality $cx^3 < 2x^2$ to be true for $0<x<1$.

[rocky lotus]

Ann

[lofty mist]

is it because cx^3 lies below 2x^2

[noble anvil]

Yes

[ruby sleet]

that's what it means "inequality-wise" for the curve/graph of a function to be below another

[vale dock]

@lofty mist Has your question been resolved?

[vale dock]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[compact mountain]

How am i suppose to find the value of k?

[misty wing]

you know that the point lies on the line 2x-y=4

plug in x=k and y=2 to solve for k

[compact mountain]

Omg that make sense

Im so sorry for being dumb

.close

[vale dock]

Channel closed

Closed by @compact mountain

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flint peak]

everyone's here to learn never apologize for learning

[flint peak]

.close

[vale dock]

Channel closed

Closed by @flint peak

Use .reopen if this was a mistake.

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[marble lark]

An infinite geometric series converges to a sum of 32. The sum of its first two terms is 24.
a) Find the first term(s) a and the common ratio r of the series. (Assume r != 1)
b) Verify that the series indeed converges with the found values of a and r and justify.

[marble lark]

I got part a) wrong or atleast not completely right and for b) I didn't really read the instructions with the found values of a and r part but i got full credit for saying "Since the geometric series has an r-value such that |r| < 1, the series will converge."

idk if b) is what your supposed to do originally but can someone explain a, i might be dumb or something

[tidal terrace]

For a) you could use a+ar=24 and S=a/(1-r) to find the value for a1 and r
And as you stated in part b because |r|<1 then the series would converge

[marble lark]

can u show out that work

i get the S = a/(1-r) = 32

how do you know its a+ar = 24

and not like a + ar^n-1

[tidal terrace]

"The sum of its first two terms is 24. "

[marble lark]

but i thought it can be like a + ar^n or ar^n-1

[tidal terrace]

nth term of a geometric sequence is a_n=ar^n-1
first two terms indicate first and second term

[marble lark]

what was ur r value>

?

is it 1/2

or -1/2

[tidal terrace]

Both would work you can test it

[marble lark]

so

would they both get u the same answer?

as in a1

and a2

[tidal terrace]

a1 would be different for different r though

[marble lark]

oh ok

makes snese

i guess thats what it meant by first termSS

i thought it meant a1 and a2

not two diff a1s

okok thanks @tidal terrace

[vale dock]

@marble lark Has your question been resolved?

[vale dock]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[worn sparrow]

fixed version

[vale dock]

@compact knot Has your question been resolved?

[compact knot]

<@&286206848099549185>

noone?

[compact knot]

<@&286206848099549185> anyone?

can I have two different questions open at once?

.close

[vale dock]

Channel closed

Closed by @compact knot

Use .reopen if this was a mistake.

[noble anvil]

Yes i think so

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vale dock]

@teal marten Has your question been resolved?

[vale dock]

@teal marten Has your question been resolved?

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[vale dock]

@teal marten Has your question been resolved?

Channel closed

Closed by @teal marten

Use .reopen if this was a mistake.

[vale dock]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lyric sundial]

!status

[vale dock]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[clever needle]

2

i know the basics of this but this qution is really confusing for me

[unborn python]

alright let's see

first of all, you know what this question means right?

[misty wing]

what have you done so far?

[unborn python]

^A much better question :>

[clever needle]

i dont know where to begin

[lyric sundial]

Then it's 1, not 2 😅

[clever needle]

so angle YOB is also 90 degrees right

linear pair

[unborn python]

ok you got somewhere

and since OD is a bisector, that means that DOB=?

[clever needle]

lmeme see

AOC

its equal to aoc

vertically opposite angle?

[unborn python]

ok that is also good to spot

but let's get back

you figured out YOB is 90

[clever needle]

yeah

[unborn python]

the question provided that OD is a bisector of YOB

therefore BOD is equal to?

[clever needle]

1/2 90

45

[unborn python]

yes

therefore AOC=?

[clever needle]

45?

[unborn python]

nice

[clever needle]

3x = 45?

[unborn python]

3x=45

then what is x?

[clever needle]

x = 45/3

[unborn python]

keep going

[clever needle]

15

[unborn python]

absolutely correct

[clever needle]

yay thank you so much

[unborn python]

np :>

[clever needle]

i love your way of making me understand first

[unborn python]

^how math should be taught

anyways remember to close the channel when you are done

[clever needle]

okay

.close

[vale dock]

Channel closed

Closed by @clever needle

Use .reopen if this was a mistake.

[clever needle]

.reopen

[vale dock]

✅

[clever needle]

@unborn python sorry for pinging but im also stuck on this

[glass kelp]

Rational root

Theorem

[clever needle]

what

remainder root?

i didnt leanr that

[pallid oasis]

1 -23 +142 -120=0

[toxic ridge]

Id say guess a root by subbbing x = 1, -1

Then factorise into quadratic

[glass kelp]

This

[stark wedge]

rational root theorem.

[glass kelp]

Yes

I’m

[pallid oasis]

Use this fact to factorize into quadratic and then factorize quadratic

[glass kelp]

This

[clever needle]

how do i use that?

[toxic ridge]

Okay

Thanks i didn't know what it was called

[clever needle]

im JUST hearing this theorum as we speak

[pallid oasis]

It means that x=1 is a root i.e x-1 is a factor

[clever needle]

ohhh remainder theorum / facctor theorum

our school give it different names idk

why

[pallid oasis]

That is correct, indeed

[toxic ridge]

No

[glass kelp]

I mixed the name of remainder theorem with rational root theorem

[toxic ridge]

That's not rational root theorem

[clever needle]

im getting confused

[toxic ridge]

This is factor theorem

[pallid oasis]

They never claimed that

[toxic ridge]

Rational root theorem is something different

[clever needle]

wait

[toxic ridge]

But what you are explaining is not the point of the question

[clever needle]

is rational root theroum the

trial and error thing

[toxic ridge]

You're mixing his concepts up

[toxic ridge]

Kind of

[pallid oasis]

The point of the question is to factorize the polynomial

[toxic ridge]

"According to the rational root theorem, the rational zero of a polynomial f(x) is of the form p/q where p and q are factors of the constant and leading coefficient respectively."

[toxic ridge]

And how did you find out x = 1 is a root?

Did you do that by factor theorem? Remainder theorem? No?

[clever needle]

should i consider the main q as p(x) then just try out different divisors of 120?

like +-1 , +-2

[toxic ridge]

Yes

But no need to use higher factors of 120 since 1 does the work

[clever needle]

ohhh okay