idk
#help-4
stark wedge
anyway you have to claim your own channel
tribal plover
????
tribal plover
anyway you have to claim your own channel
oh they were spamming scam links
and they left
i was here first
stark wedge
yeah but unfortunately their name got put on the channel
tribal plover
then they used like somethin
stark wedge
it's a technical thing
tribal plover
yeah but unfortunately their name got put on the channel
oh ok
oh just saying it had some corn
stark wedge
I can switch genders
i mean... 🏳️⚧️ but also just go to channels and roles
tribal plover
idk
stark wedge
and update your pronouns there
fickle rose
i was here first
and because they left, this channel will lock eventually
tribal plover
ok
vale dockBOT
Available help channel!
vale dockBOT
for patrt b why did they use the point 3,1
novel canyon
bum chicken
wet tundra
bum chicken
y12 is kinda hard
novel canyon
bro
ts isnt even the hardest thing uve done u have done more difficult (vectors??????........!!!!!!!!)
night ginkgo
Water
night ginkgo
convegence
are you doing well in your courses
novel canyon
are you doing well in your courses
no i got blasted by my math final yesterday
vale dockBOT
@wet tundra Has your question been resolved?
wet tundra
ts isnt even the hardest thing uve done u have done more difficult (vectors?????...
yea
logs are lowk harder than vectors
and proofs
novel canyon
logs are lowk harder than vectors
nah i think ur just cooked 😭
hearty kindle
Guys, I need help identifying the set of functions.
vale dockBOT
Guys, I need help identifying the set of functions.
drifting hornet
Guys, I need help identifying the set of functions.
which funcs
noble anvil
!xy
vale dockBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
hearty kindle
This is funcs
noble anvil
This is funcs
"Identify it"? As in what shape it represents?
flint sparrow
This is funcs
these X's hurt my soul
hearty kindle
I think it belongs to R except 1
flint sparrow
Yes that's most likely the domain
noble anvil
I think it belongs to R except 1
So you want the domain and not the shape?
wet night
hearty kindle
I also want its shape
noble anvil
Lmao w graph (x^2+x-1)/(x-1)
rocky lotusBOT
hearty kindle
I think we need a tangent line to the function.
noble anvil
I think we need a tangent line to the function.
Well what do you usually do to get the tangent line of a function that is not standard then?
hearty kindle
Well, in the exercise I'm doing they asked me to show that y=x+2 is an inclined asymptote of a function.
cloud coral
an inclined asymptote is typically not understood as a tangent line
vale dockBOT
@hearty kindle Has your question been resolved?
hearty kindle
If I want to enter the line y=x+2 in the graph as an inclined asymptote
noble anvil
Lmao w graph y= (x^2+x-1)/(x-1), y= x+2
rocky lotusBOT
hearty kindle
Thinks
cloud coral
the two functions look close to each other, what if we subtract them?
find their difference
hearty kindle
It is close to the function because it may be asymptotic.
Oh, you mean the function?
noble anvil
It is close to the function because it may be asymptotic.
Yes, so they're saying to subtract the functions.
If it comes out to be 0, then you've proven that line is an asymptote.
Can you tell me why that is so?
hearty kindle
Maybe because we did the subtraction between the function and the line y=x+2
I have no idea
noble anvil
If it comes out to be 0, then you've proven that line is an asymptote.
Oops, maybe I'm hallucinating
Ignore that
hearty kindle
Oops, maybe I'm hallucinating
What level of education are you studying at?
noble anvil
Oops, maybe I'm hallucinating
Yeah sorry, my method is to manipulate the first expression so you can get the asymptote in there. If you observe carefully you can see that:
$\frac {x^2+x-1}{x-1}$ is actually nothing but $(x + 2) + \frac{1}{x-1}$
rocky lotusBOT
Executor (ask on server b4 DM)
noble anvil
Now we can just take the limit of the term 1/(x-1) as x approaches infinity, so it becomes 0
terse silo
Oops, maybe I'm hallucinating
nah its right $\lim_{x\to\infty} f(x)-a(x)=0$ then $a(x)$ is an assymptote of $f(x)$ (and analogously with $-\infty$)
rocky lotusBOT
VincentBH
noble anvil
nah its right $\lim_{x\to\infty} f(x)-a(x)=0$ then $a(x)$ is an assymptote of $f...
Yeah I knew that lol but second guessed myself a bit because of the ❓
terse silo
**Executor (ask on server b4 DM)**
if you subtract $x+2$ then you get something that goes to 0
noble anvil
**Executor (ask on server b4 DM)**
But this method is valid as well
rocky lotusBOT
VincentBH
terse silo
But this method is valid as well
it is exactly the same haha
hearty kindle
it is exactly the same haha
You are right
noble anvil
What level of education are you studying at?
Sorry, don't think that's relevant.
terse silo
True <:bking:1373112658169040996>
but thats a good method to find what the assymptote has to be
noble anvil
Yeah, if you weren't given it 
hearty kindle
Sorry, don't think that's relevant.
Yes sorry
I have a problem with the change table and also with splitting the function
noble anvil
I have a problem with the change table and also with splitting the function
What is "the change table"?
hearty kindle
noble anvil
Splitting the function I can understand might be a little hard to visualise, but you're given what you want it to look like already, so that should make manipulating it easier.
Just add and subtract x+2
hearty kindle
What is "the change table"?
It is a table that shows you how the function will change, whether it is increasing or decreasing, but you must first split the function.
noble anvil
It is a table that shows you how the function will change, whether it is increas...
Well we already split the function.
Now to find its nature we just have to differentiate.
hearty kindle
Now to find its nature we just have to differentiate.
If you know a table of signs, you should study the sign of the function you have split.
noble anvil
If you know a table of signs, you should study the sign of the function you have...
So you're saying to find where the function is increasing or decreasing you put negative numbers in progressively and then positive numbers in progressively to see how the values change?
Or is there a different meaning to "table of signs"?
Though if it is what I just explained it's a pretty bad method lol
hearty kindle
This is an illustrative example.
noble anvil
This is an illustrative example.
So you do have to differentiate lol.
Could you differentiate the function given to us then?
hearty kindle
Could you differentiate the function given to us then?
What do you mean by separation?
noble anvil
Where did I say separation
I said take the derivative
Oh are you using a translate app?
hearty kindle
Yes, sorry I misunderstood.
hearty kindle
I said take the derivative
Yes, I am still learning English.
vale dockBOT
@hearty kindle Has your question been resolved?
dreamy trellis
During my last calculus 1 exam I answered the question regarding this function with “the function has 2 asymptotes”, I would like to ask if someone could please tell me if my answer is correct or not.
From the graph it seems to me that I see 2 oblique asymptotes but I would like a confirmation if it is possible to.
safe fulcrum
During my last calculus 1 exam I answered the question regarding this function w...
correct, the oblique asymptotes are given by $y = \sqrt{x^2} = |x|$
rocky lotusBOT
south
safe fulcrum
and that's made up of two straight lines, y = x and y = -x
vale dockBOT
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Available help channel!
next vortex
so I have this proposition that I wanted to prove
vale dockBOT
so I have this proposition that I wanted to prove
next vortex
here's my work
I'm fairly sure this works, but I'm putting this here in case somebody thinks there's a mistake
wild linden
@next vortex it looks like your images aren't coming through for me. I don't know if it's just me. I only have the first image in your second post.
wooden frigate
if you click on the image it shows up for me
next vortex
huh. the 2nd image is bugging for me
leaden cargo
Though (b) and (c) are not really about Lie groups, just basic group theory
next vortex
I can't upload it properly
next vortex
Though (b) and (c) are not really about Lie groups, just basic group theory
well yeah
I've not actually done any group theory prior to Lie groups though
so it'd be nice to check if I got those right too
leaden cargo
I can't promise that I've looked through every algebraic step 😅
next vortex
that's okay, I feel confident in the algebra 
idle void
<@456913063300431934> it looks like your images aren't coming through for me. I...
FYI: there's an outage affecting embeds
wild linden
FYI: there's an [outage](https://discordstatus.com/) affecting embeds
Thanks for letting me know. I probably am just touching a server that isn't working for those images.
next vortex
btw looks good to me
I'm gonna leave it here for another 5 min
and if no other words are said, I'll close 
.solved
vale dockBOT
vale dockBOT
Available help channel!
vale dockBOT
woven ivy
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Available help channel!
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lavish elbow
<@&268886789983436800>
vestal lotus
vale dockBOT
vestal lotus
just wanna make ure im not trippin
but the textbook says vertical stretch scale factor 1/4
it should be compression right?
quasi valve
well stretching by a factor of less than 1 is effectively compression yes
rough talon
stretch by 1/4 and compression by 4 is the same
quasi valve
but if you said "compress by a factor of 1/4" then that's gonna be confusing
quasi valve
yes
it's less error prone to simply say "vertical scaling by a factor of whatever"
and that's either a stretch or a scale (and also allows negative factors)
quick agate
no idea how to do this question
vale dockBOT
no idea how to do this question
quick agate
dont think i even did the diagram properly
vale dockBOT
@quick agate Has your question been resolved?
quick agate
<@&286206848099549185>
quick agate
.close
vale dockBOT
karmic yacht
Do you know that a displacement vector is a velocity vector scaled appropriately for time
vale dockBOT
Available help channel!
livid lantern
b) I am trying to solve
vale dockBOT
b) I am trying to solve
livid lantern
I know that the norm here is induced from an inner product
after that, how can I split the inner product in such a way that I get a <hn,g> and a <h,g> term somehow
.closed
.close
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open niche
Hello does the average value theorem of calculus state that ξ exists in (a,b) or [a,b] so that integral from a to b f(x)dx is (b-a) f(ξ)
open niche
I got 2 books one says (a,b) other [a,b]
leaden cargo
if f is defined on [a,b] then if you find it in (a,b) you also found it in [a,b]
Viceversa, if ξ is in [a,b] and is exactly one of the extrema, you can show that you can find one in (a,b) too, so they're basically equivalent
leaden cargo
if ξ belongs to (a,b) it also belongs to [a,b], no?
open niche
if ξ belongs to (a,b) it also belongs to [a,b], no?
What does the theorem say
glad pivot
I think they want to know how to prove that the theorem can be proven for the stronger result
leaden cargo
[a,b] implies a and b are included too
if your function f is defined on [a,b] and you find a ξ in (a,b) satisfying the condition of the problem, then since (a,b) is a subset of [a,b] then ξ is also contained in [a,b] and still satisfies the conditions
Viceversa, if you find a ξ in [a,b] satisfying the conditions you can show that you can also find another ξ' in (a,b) that satisfies the conditions
open niche
There is 1 theorem regardless of what is equivalent or similar to it
leaden cargo
So the two statements are equivalent, they are the same theorem
open niche
So the two statements are equivalent, they are the same theorem
(a,b) is a subset of R why not say the theorem says there is ξ in are ?
Cause thats not how the average theorem of calculus is
leaden cargo
(a,b) is a subset of R why not say the theorem says there is ξ in are ?
f is not defined on ℝ so it makes no sense to talk about ℝ
open niche
Bro just tell me what the theorem with that name says
Not what your own theorems that are equivalent say
leaden cargo
I am not your bro
open niche
Whats the point of avoiding my question and just giving me something equivalent
neon summit
if your function f is defined on [a,b] and you find a ξ in (a,b) satisfying the ...
what, lets say c is 5, its part of [5, 10] but not (5,10)
leaden cargo
I did not avoid your question
you found two different formulations of the same theorem in two different books, I am telling you they are both correct, there's no “more correct” version
leaden cargo
what, lets say c is 5, its part of [5, 10] but not (5,10)
As I said, if c happens to be 5, you can show there exists c' in (5,10) that also satisfies the theorem
glad pivot
They're not the same theorem but one is stronger than the other. I'm not even sure what the confusion is 🤣
open niche
I did not avoid your question
you found two different formulations of the same t...
Whats the version that got named theorem of average value of calculus
leaden cargo
They're not the same theorem but one is stronger than the other. I'm not even su...
How is one stronger?
open niche
They're not the same theorem but one is stronger than the other. I'm not even su...
Which is the theorem thats called average value of calculus
glad pivot
How is one stronger?
One states that ξ may always be chosen different from a and b
glad pivot
Which is the theorem thats called average value of calculus
They probably go by the same name
open niche
How is one stronger?
Bolzanos theorem says (a,b) . [a,b] is equivalent but its not what Bolzano said
Which version what the theorem said as from the guy who made it
neon summit
As I said, if c happens to be 5, you can show there exists c' in (5,10) that als...
yeah ok but in theorem it is explicitly (a,b)
leaden cargo
One states that ξ may always be chosen different from a and b
yes, but if ξ happens to be a or b then you can find ξ' different from a and b that satisfies the theorem, so it is not stonger in any way
leaden cargo
yeah ok but in theorem it is explicitly (a,b)
Apparently one book they were reading disagrees
And that doesn't make it less valid
glad pivot
yes, but if ξ happens to be **a** or **b** then you can find ξ' different from *...
ξ can be chosen different to a or b and satisfy the equation
open niche
And that doesn't make it less valid
It does cause the one theorem makes sure its in (a,b)
So if a is c
Then there is still another point in (a,b)
If theorem was [a,b] then a might be the only point
glad pivot
Yes. Maybe the function has the value f(a) and f(b) at points between a and b for example
glad pivot
The reason there's two version is because one is very easy to prove and other requires more steps
glad pivot
Is ξ in (a,b) or [a,b]
Both versions are true as (a, b) is always inside [a, b]
glad pivot
SHOW THE ORIGINAL THEN
neon summit
send pictures of both theorems
glad pivot
They're not the same theorem but one is stronger than the other. I'm not even su...
Really?
obtuse vault
Hey guys, does anyone know why the boundary here is [1, u/2] and not [1, 2] as from the transformation graph?
ivory valley
Hey guys, does anyone know why the boundary here is [1, u/2] and not [1, 2] as f...
The boundary y=2 becomes uv = y = 2, so that solving for v you get v = 2/u.
obtuse vault
The boundary y=2 becomes uv = y = 2, so that solving for v you get v = 2/u.
yes and then we draw the g boundaries
and it seems like the boundaries for u is [1, 2] and for v is also [1, 2], why did we write the u/2 in the upper limit in the integral?
ivory valley
Counter question: Why do you assume it's [1,2] still?
obtuse vault
gemme a sec
ivory valley
For a square you would need a 4th boundary too, so that it gets tranformed into a square possibly.
obtuse vault
For a square you would need a 4th boundary too, so that it gets tranformed into ...
aren't these the boundaries?
ivory valley
You have 3rd one too
vale dockBOT
@obtuse vault Has your question been resolved?
reef hull
Sup
reef hull
I'm trying to find the domain and range
And clearly got confused here
Don't quite remember how this works
cloud bluff
that looks really hard
reef hull
This is the function
leaden cargo
I have never seen someone write ∞⁺, it usually is +∞
the domain and the sign look correct
you were trying to get the inverse function (supposing that there is one)
you have to “find x” in the equation
let's continue from 2x-5xy = 3y+1
How would you go and isolate x?
reef hull
Kinda got lost there honestly
cloud bluff
wanna be friends
reef hull
How would you go and isolate x?
I am not sure how to
reef hull
you were trying to get the inverse function (supposing that there is one)
What should I do if not?
leaden cargo
I am not sure how to
have you tried factoring?
leaden cargo
this is just the distributive property
2(3+5) = 2⋅3 + 2⋅5
we're reading it in reverse
2⋅3 + 2⋅5 = 2(3+5)
leaden cargo
Since its dividing?
We are not dividing by x, we just “factored” it on the left
reef hull
Oh right
I can then
Divide by (2-5y)
The result is (3y+1)/(2-5y) = x this is the inverse?
Honestly I'm still kinda lost
I need to isolate y
leaden cargo
it is
f⁻¹(y) = (3y+1)/(2-5y) is the inverse of f(x) = (2x-1)/(3+5x)
Do you know why you looked for the inverse?
reef hull
Not really honestly just been experimenting
leaden cargo
Values in the range of f are the same thing as values in the domain of f⁻¹
So to look for the range of f is the same as to look for the domain of f⁻¹
reef hull
Oh so with this I can then get the Range
If I do the table
Oh wait I don't need the table
Since it has no restrictions on + or -
Just need to find the value where 2-5y = 0
Which is 2/5
And with this I think I have it, everything but 2/5 right?
leaden cargo
yh
leaden cargo
yes
reef hull
Neat Thanks a lot
Is there any other way to find the range that I could have used here?
manic igloo
Divide (2x-1) / (5x+3) = 2/5 - (11/5)/(5x+3). We have a horizontal asymptote y = 2/5 and the hyperbola -2.2/(5x+3) goes above in the I. quadrant, and below in the III. quadrant.
- sorry! Below in the IV. quadrant, and above in the II. quadrant.
reef hull
I don't know what half of that means, I know what quadrants are but kinda lost on that asymptote thing do wanna understand what you are doing though
manic igloo
It is like -1/x shifted by 2/5 in the y-direction
reef hull
Still don't understand
leaden cargo
I don't know what half of that means, I know what quadrants are but kinda lost o...
What they said presupposes that you know what a hyperbola is (their equation and graph) and how to perform division between polynomials
Don't worry, you'll get there at some point
manic igloo
It it a bit more of an advanced approach.
leaden cargo
But what you did before is perfectly valid
reef hull
Alright, I might check that out later, do either of you have any good videos teaching the topic you'd reccomend?
leaden cargo
don't you have a book you use for school?
reef hull
Yeah, but learn better from videos. I was looking just in case since once someone from here reccomended me one and I really liked it so I try to ask every time I can
But with that we're done
Thank you both
A lot
.close
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Available help channel!
lost marlin
vale dockBOT
lost marlin
i have proven that composite numbers cannot be the answer
stark wedge
do you know gcd(a,b) = gcd(a+kb,b)
lost marlin
yes
mental skiff
euclid's algorithm right?
stark wedge
yes
yeah ok so now consider (n+1)! = (n+1)*n!
gcd( (n+1)*n!, n!+1 )
try to manipulate it somehow
lost marlin
i got n+1 divides n!+1
stark wedge
n+1 divides n!+1??
lost marlin
yes
wraith heart
Review the definition of divides
stark wedge
,calc (9!+1)/(9+1)
rocky lotusBOT
Result:
36288.1
false for n=9
lost marlin
i did something like this earlier
factors of (n+1)! which also divide n! + 1 must contain n+1
mental skiff
Hello could someone like clarify in this
like in this question lets say hn is a*(n!+1) and b*(n+1)!
so like could we use some calculus approach ?
stark wedge
i did something like this earlier
factors of (n+1)! which also divide n! + 1 mus...
how did you get that
lost marlin
how did you get that
if any factor of (n+1) isnt divisible by n+1 then it is a factor of n!
and then it doesnt divide n!+1
mental skiff
hello
lost marlin
hello
stark wedge
if any factor of (n+1) isnt divisible by n+1 then it is a factor of n!
something is amiss here but i can't put my finger on what
mental skiff
I am trying to maximise hn
mental skiff
Like i am trying
stark wedge
well i can't make you not waste your own time ig
vale dockBOT
@lost marlin Has your question been resolved?
vague light
can someone explain how to work this question out because i cant find anything similar to it online
wild linden
@vague light you'll need to know two things, how to find the slope of a line perpindicular to another line, and how to find a line given a point and a slope.
vague light
i know that its just what i need to do to get to the answer, i know ive done it before i just cant remember the order to do things
wild linden
well,
tender sphinx
can someone explain how to work this question out because i cant find anything s...
this is a pretty rare question tbh
wild linden
Let's think this through then
wild linden
You have two things you need to do
find the slope from the other slope, and then find the line from the point and the slope
which of these two things can you do right now?
stark wedge
i know that its just what i need to do to get to the answer, i know ive done it ...
i wouldnt say theres really an order in this sort of question
it's more of a checklist
(of 2 entries)
to find the equation of a line in slope-intercept form, you need:
- its slope
- its y-intercept
wild linden
well, one depends on the other, so I don't object to the "order" idea.
stark wedge
sometimes you get the y-int for free like in this problem
sometimes you don't and so you have to defer it until you've found the slope
wild linden
oh, I suppose it is just the y-intercept in this case
stark wedge
point is even if you do stick to an order you understand why you do it in this order and so you're less liable to forget
wild linden
yeah you can just skip the point slope form of the line entirely
stark wedge
i mean point-slope is also good to know your way around but i am not about to try to teach 2 things at once
vague light
so i need to find the opposite gradient then just work out the equation of the new line?
wait but how do i work out the slope with only one point? am i being dumb? 😭
tender sphinx
do you know what perpendicular means?
vale dockBOT
@vague light Has your question been resolved?
vale dockBOT
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Available help channel!
gilded crow
yo can i ask a question
vale dockBOT
yo can i ask a question
tired condor
just ask
gilded crow
so in progressions what does the S stand for
noble anvil
so in progressions what does the S stand for
!xy
vale dockBOT
so in progressions what does the S stand for
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
opal pendant
so in progressions what does the S stand for
sum probably
gilded crow
sum probably
hm
noble anvil
Probably, yes, but until you show us the question nothing's for sure.
mental skiff
S yes sum
opal pendant
Probably, yes, but until you show us the question nothing's for sure.
yes ^^
mental skiff
!original
vale dockBOT
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
gilded crow
Probably, yes, but until you show us the question nothing's for sure.
there isnt a specific question other than that, i have my final exam on monday and thats one of the topics i need to relearn
noble anvil
Ok.
gilded crow
ok
mental skiff
ok
gilded crow
btw what grade do you learn stereometry
mental skiff
Stereometry ?
gilded crow
yeah
stark wedge
it's usually called 3D geometry in English
viscid spade
Space geometry
stark wedge
also it usually happens in grades 11 or 12
gilded crow
it's usually called 3D geometry in English
stereometriq in bulgarian so yeah
gilded crow
also it usually happens in grades 11 or 12
damn
gilded crow
i was ABOUT to ask if you're bg
bg li si
stark wedge
не, но живея в София от 2+ години
vale dockBOT
verbal badger
90 is correct. Maybe you're missing the degree sign or something but 90 is right
red bear
oh wait fr?
leme check
bro.
i hate doing my homework on this flipping website
i was scrambling my head trying to find the right answer lol
ima ask my teacher tmrw
thx
verbal badger
np
vale dockBOT
red bear
yeee
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Available help channel!
magic nebula
an "equalizer" of a triangle is a line that divides both the area and the perimeter of the triangle in half
find the smallest a such that there exists a triangle with integer side lengths a>b>c with exactly 2 distinct equalizers
neat locust
an "equalizer" of a triangle is a line that divides both the area and the perime...
!status
vale dockBOT
an "equalizer" of a triangle is a line that divides both the area and the perime...
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
latent mortar
Find 2 numbers that have sum of 4 and product 2. What are they?
latent mortar
Ik I did something wrong but what
noble anvil
Find 2 numbers that have sum of 4 and product 2. What are they?
sum of roots is -b/a
not b/a
latent mortar
Where did I do that
rotund parcel
a+b=4, ab=2
a+2/a= 4
a^2+2-4a=0
latent mortar
How come
rotund parcel
start with the 2 requirements then form the quadratic from it
latent mortar
a+b=4, ab=2
a+2/a= 4
a^2+2-4a=0
Can u put that on bot I can’t read that properly
rotund parcel
??
noble anvil
How come
Because sum of roots is -b/a, and you're given that the sum is 4.
so -b/a = 4
rotund parcel
it's all the same as tex besides the one division
noble anvil
What's a polyatheist 
latent mortar
Because sum of roots is -b/a, and you're given that the sum is 4.
so -b/a = 4
How do I know what’s a root
noble anvil
How do I know what’s a root
How else did you form the equation? You did it by applying sum and product of roots
latent mortar
Idk how to figure out what the root is what a what is it a root
rotund parcel
What's a polyatheist <:MenheraThink1:998772194714853388>
i believe many gods don't exists instead of just the one true nonexistent god
latent mortar
How else did you form the equation? You did it by applying sum and product of r...
Uh I just followed Stevins equation thing
B is something + something
C is something * something
noble anvil
i believe many gods don't exists instead of just the one true nonexistent god
Oh I see. So not agnostic then?
noble anvil
B is something + something
B is -(something + something), given the leading coefficient is positive.
Not +(something+something)
noble anvil
a+b=4, ab=2
a+2/a= 4
a^2+2-4a=0
Just follow this instead, it'll be clearer why you're doing what you're doing.
latent mortar
Idk how to read that
Is there a bot to make that numbers
Wolfram
Or smth
$
,$
;$
noble anvil
$a+b=4
ab=2
a+2/a = 4
a^2+2-4a=0$
latent mortar
;hi
noble anvil
There.
rocky lotusBOT
Executor (ask on server b4 DM)
noble anvil
You can just write b as 2/a
noble anvil
??
latent mortar
It’s not in the picture
I got it
I finished it by completing squares
Btw
When does completing squares not work
I have trouble knowing when to use which method. Like idk when I have to use 2nd degree equation thingy (the one with delta) or if I have to use stevia method or if I have to use completing squares or if I have to use Gerard’s stuff
@noble anvil
noble anvil
I have trouble knowing when to use which method. Like idk when I have to use 2nd...
I don't know anything except the first one.
By delta i assume you mean discriminant.
As for Stevia and Gerard, I've not been taught those, or they might have a different name where I am.
latent mortar
Gerard is the one where roots are a+b= a/c or smth
And a*b=c/a
Idk
If that’s right but u should know what I mean
This
latent mortar
As for Stevia and Gerard, I've not been taught those, or they might have a diffe...
I meant Stevins
noble anvil
I meant Stevins
I don't know that either
noble anvil
Gerard is the one where roots are a+b= a/c or smth
So vieta
noble anvil
Yes, this is what i was saying, sum of roots is -b/a and product is c/a
latent mortar
Lemme show u one
Steven is factorizing I think
This is Steven though
Wait that was wrong
There
@noble anvil
So like how do I know which method to use
Cause I get lost tryna figure out what to do
noble anvil
So like how do I know which method to use
Well, to make the equation you might need Gerard, and to find its roots you can use either gerard or stevins, and to check if the roots exist, are real or not,etc. you can use delta (discriminant)
latent mortar
Depends on what the question asks basically
What about completing squares
When do I use that
lyric sundial
There's no exact answer imo
latent mortar
I see
vale dockBOT
@latent mortar Has your question been resolved?
latent mortar
Wait
One more
I have a question saying 2 numbers add to 0,9 and those same numbers product is 0,2
I made the thingy
The equation
It’s a^2-0,9a = -0,2
What’s next
Idk how to work the decimal numbers
Oh I got it
I’m getting better at math everyday 
Can’t wait to become pro math player
And be able to go into other ppls questions without saying “what the actual hell is that” in my head
noble anvil
And be able to go into other ppls questions without saying “what the actual hell...
That's the spirit 
noble anvil
What
noble anvil
first?
latent mortar
Then looking for the number that multiplies 2*somehting= 1/3
Is that the right route?
Or is the delta (triangle) formula the only way
noble anvil
Is that the right route?
No
latent mortar
Thought so
noble anvil
Multiply by 12 on both sides of the equation
zinc fulcrum
just use the quadratic formula
latent mortar
Yeah
I am
But mutlypling by 12 will make it easier
Also
Can u answer
Does the lhs become 12
latent mortar
Cause if I’m multiplying both sides by 12 isn’t 0*12=0
zinc fulcrum
no if are mutpliyng by 12
on both sides
that is 12*1/2=1
and the other side by 12
latent mortar
What
zinc fulcrum
so 0*12=0
latent mortar
Yeah so the lhs stays 0
zinc fulcrum
yea
latent mortar
I mean rhs
zinc fulcrum
by 12*1/12=1
latent mortar
Not left whoops
latent mortar
Ok
zinc fulcrum
still
latent mortar
I just wanted to know if the rhs stayed 0
rocky lotusBOT
ppq#7826
latent mortar
**ppq\#7826**
Erm
noble anvil
just use a calcuator and plug the formula in
Based af.
latent mortar
Imma do it now my teacher taught me
zinc fulcrum
sorry i cant use the ai right
latent mortar
Imma end up confusing myself since this stuff is still new to me
noble anvil
sorry i cant use the ai right
For what
zinc fulcrum
the textit ai thingy
noble anvil
Imma end up confusing myself since this stuff is still new to me
If you confuse yourself then stare at the notebook until you confuse yourself even more and then it finally starts to make sense
noble anvil
So that’s correct right?
yuh
zinc fulcrum
yes though you need to do the *12 on both sides
write it on both sides
not as 1 side
latent mortar
write it on both sides
I did
zinc fulcrum
even though i know what you mean
latent mortar
not as 1 side
Oh
zinc fulcrum
I did
no you ahve to write it on boths dies like *12
you showed it but you have to wrtie it twice
ont once
latent mortar
I see
zinc fulcrum
even though it shows you did it too the whole equation
which is what you should be doing
regradless
noble anvil
yuh
latent mortar
noble anvil
<:smokingbread:1371585548334141480>
Your bread's nicotine addicted
Better get it off that shi
latent mortar
What did I do wrong here
Apparently the answer is 4/3
I really don’t know
Shouldn’t this method work here?
zinc fulcrum
just plug it into the formula
latent mortar
Ik but It’s easier to do it this way
zinc fulcrum
or complete the square to get vertex form and then slove it to get the roots
latent mortar
Nah it is
latent mortar
Uh
latent mortar
Yeah I don’t think I could do this method when y is not being multiplied by 1
zinc fulcrum
how do you not know what a gcf is
zinc fulcrum
i dont know how they teach it
latent mortar
Ight
latent mortar
I see
latent mortar
Alg
latent mortar
Imma do quadratic equation
zinc fulcrum
there no answer
the only asnwer is y=4/3
but thats not an answer
yea and if you cahnge the y with an x
the answer is x=4/3
@latent mortar
latent mortar
Yeah
21c
<@&286206848099549185>
I got the answer wrong but idk why
Wait I might know
I got it
My bad for the ping my glorious kings
(No glaze)
noble anvil
noble anvil
Ur missing a root
what
noble anvil
Lel
latent mortar
I toughtit was was a hard solution to my issue so I sent it whole I waited for someone to come I tried finding it out
Also I said ur missing a root cause one of the roots to the problem is -9
lol
noble anvil
kk
latent mortar
Ok I’m done for today
Almost 5 hours to do 2 pages of math
I have 6 pages for tmr and Sunday
So 3 for tmr and 3 for Sunday
And I have to learn the questions I was solving with u a while ago
11 of them
noble anvil
I thought you solved all of those
latent mortar
I thought you solved all of those
I did but I didn’t learn them all
I handed in the paper today
And I have to present them on Monday or Tuesday
I have to learn them all
Cause my teacher is gonna ask me a random one
Well technically it’s my group but they did absolutely nothing
noble anvil
You don't need to "learn" problems
latent mortar
I legit did everything
noble anvil
If you've solved them like twice you can reproduce it from memory
latent mortar
You don't need to "learn" problems
Memorizing isn’t good though
The point is to learn and apply them on future questions right
But yeah memorizing them is easier
Probably will try to for a few harder questions
Anything u wanna say before i close?
I don’t wanna cut you off
noble anvil
Anything u wanna say before i close?
No it's fine, just remember the stuff I've said till now don't rotelearn beyond what's needed
Cya 
latent mortar
No it's fine, just remember the stuff I've said till now don't rotelearn beyond ...
Roteleqrn?
What rhat
noble anvil
Roteleqrn?
memorise
latent mortar
An I see
Tysm bro
Basically almost every time I need help u helped me
No matter what day and time I’m on
Tysm
Means a lot
.close
vale dockBOT
sly cargo
does anyone know how to solve transendental equations?
vale dockBOT
Available help channel!
vale dockBOT
cobalt karma
I'm having a really hard time solving this
stark rivet
I'm having a really hard time solving this
What is this
vale dockBOT
@cobalt karma Has your question been resolved?
past wedge
help
stable parcel
past wedge
i thought i knew the topic until this thing appeared
vale dockBOT
@past wedge Has your question been resolved?
stark rivet
Just use the L'Hopital's rule. This gives [
\lim_{x \to 0} \frac{4 \sin(4x)}{18x}
].
Next apply this useful fact:
[
\lim_{x \to 0} \frac{\sin(kx)}{x} = k
]. This gives
[
\frac{2 \sin(4x)}{9x} = \frac{2 \cdot 4}{9} \cdot \frac{\sin(4x)}{4x} = \frac{8}{9} \cdot \frac{\sin(4x)}{4x}
]
[
\lim_{x \to 0} \frac{\sin(4x)}{4x} = 1
]
So the answer is 8/9
8/9
past wedge
Just use the L'Hopital's rule. This gives \[
\lim_{x \to 0} \frac{4 \sin(4x)}{18...
dang i feel bad, i dont know that method yet. i apreciatte it tho
median sun
They’d do lhöpital if they wanted to lol
rocky lotusBOT
a guy with no beard
median sun
There might be an easier solution I’m not seeing tho
past wedge
my proffesor is very picky if i dont follow his method he might give me half points
ill just bring the question to class on monday
stark rivet
my proffesor is very picky if i dont follow his method he might give me half poi...
Idk man. I don't see how his method is useful in this case
The denominator is x², not x
past wedge
Oh that’s not his method that’s just what I would have done
But I guess there is no way to do it with what I knew
stark rivet
What is his method then
past wedge
He says I force the one below
Inside the cosine
That’s what he would say
But he never target that problem before in class
Oh wow
stark rivet
That’s what he would say
If you force it, then 1/9x * 1-cos4x/x becomes an indeterminate as x approaches 0
tidal terrace
you could try showing lim x->0 (1-cosx)/x^2=1/2 and go on from there but idk if your teacher would accept it
median sun
you could try showing lim x->0 (1-cosx)/x^2=1/2 and go on from there but idk if...
If you show that u=4x substitution finishes the question yeah
Wait you also need to show that same thing for my long ass solution 🤦♂️
stark rivet
Just write a proof for the L'Hopital's at this point
tidal terrace
Just write a proof for the L'Hopital's at this point
lol
past wedge
I’ll just move on from this problem for now and ask my teacher on Monday. Thanks guys
vale dockBOT
@past wedge Has your question been resolved?
tardy jasper
I’ll just move on from this problem for now and ask my teacher on Monday. Thanks...
You can yous this
=1/2 it's a famous limit
So you have 1/9 × 1/2 × 16 = 16/18 = 8/9
past wedge
Thank for that, I’ll ask if that’s a valid way.
unkempt urchin
can someone guide me
vale dockBOT
can someone guide me
ivory valley
can someone guide me
I would first express y in terms of x and z. For the bounds, consider the plane projection on the xz plane.
unkempt urchin
so i have 2-x-z=0
ivory valley
Yeah, now solve for z
unkempt urchin
solve for z , i dont really get it
normally i will write x+z<=2
x from 0 to 2-z
and z from 0 to 2
rocky lotusBOT
ivory valley
For example
unkempt urchin
thank you i get the idea now
ivory valley
Also notice x,y,z >= 0
unkempt urchin
.close
vale dockBOT
vale dockBOT
Available help channel!
arctic violet
Differential equation 2nd order nonhomogeneous
vale dockBOT
Differential equation 2nd order nonhomogeneous
arctic violet
I got the second method solution correct, however it's different with the first method (manual/conventional method)
Anyone know where's the mistake?
The question is
y'' -6y' +9y' = 8e^x
And the solution from my 2nd method was\
$Y = (2e^x) + [e^3x (C_1x + C_2)]$
rocky lotusBOT
Awaww🦑
wild linden
I'm afraid I don't understand your first solution
It looks almost like you're using the first order non-homogeneous solution
wild linden
So how do you justify using a first order homogeneous solution for a second order non-homogeneous equation exactly?
arctic violet
i tried these method
it shows u how to solve the 2nd order non homogeneous by the first order non-homogeneous solution
and the result is still correct
wild linden
Ah I see
It's not clear to me how I is determined here
And you have determined a completely different I
arctic violet
And you have determined a completely different I
So...
$(D+1) u = 5\
\frac{du}{dx} + u = 5
I = \int{1} dx = x$
rocky lotusBOT
Awaww🦑
Compile Error! Click the 
reaction for more information.
(You may edit your message to recompile.)
arctic violet
oh hold on
wild linden
Forgive me, please, but I am not familiar with this particular trick, so this series of equations don't explain the justification
arctic violet
I think I know what u mean, I = e^integral p(x) dx right?
wild linden
Right, I gotcha now
arctic violet
so its same
arctic violet
I think I know what u mean, I = e^integral p(x) dx right?
I see some of you guys using this, but they teach different things in my country. However it still the same
wild linden
wild linden
I got the second method solution correct, however it's different with the first ...
Can you explain the rationale of why you are multiplying everything here by exp(-3x)?
arctic violet
That's the Integers factor, isn't it?
wild linden
Ah, ok I think I get what you did
arctic violet
is d/dx ([u] [e^-3x]) = [(e^-3x) (du/dx)] + [(- 3u)(e^-3x)] ?
wild linden
wild linden
I got the second method solution correct, however it's different with the first ...
Between these two lines, you're doing a lot here
And the line above it looks like you dropped a factor on y
-3y becomes -y
There's a definite mistake with the -3y becoming -y, but also there might be an error converting to the Integral a second time
wraith heart
-3 + 1 = -2
arctic violet
wait let me try to get a better photo there
wild linden
-3 + 1 = -2
I'm sorry, is that in response to me? If so, please explain?
wraith heart
No, his exponents are incorrect
wild linden
Ah
wraith heart
He did -3 + 1 = 4 somehow
wild linden
In the circled area?
wraith heart
Yes
wild linden
Yeah I thought something was wrong, but so much was going on, that I wasn't completely confident on what
wraith heart
Indeed.
arctic violet
arctic violet
**Awaww🦑**
however the result is still different with this
$Y = (2e^x) + [e^{3x} (C_1x + C_2)]$
rocky lotusBOT
Awaww🦑
wraith heart
isn't e^x / e^-3x equal to 1-(-3) ?
This is not what you have in the first line in the red circle
wraith heart
Did you distribute the exponential under the derivative on the third line on the left
arctic violet
Did you distribute the exponential under the derivative on the third line on the...
Yeah
arctic violet
**Awaww🦑**
back to the problem, my issue here is why is the answer a little bit too far from this
wraith heart
isn't e^x / e^-3x equal to 1-(-3) ?
Where in your work are you dividing e^x by e^(-3x)
wraith heart
On the left of the second line you're multiplying
arctic violet
On the left of the second line you're multiplying
tysm ❤️
i got the same answer with the 2nd method
.close
vale dockBOT
vale dockBOT
Available help channel!
mental skiff
Need help with this question
vale dockBOT
Need help with this question
vale dockBOT
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
there's no need to !status yourself btw you can just explain yourself without
mental skiff
okok i just did for clarity
stark wedge
show your progress tho
mental skiff
So like i was trying to find a relation between an-1 and an
i even tried finding values for ak for like from 0 to 4
but they have no relation
like a0=1 , a1=1/2 , a2=1/12, a3=0 and a4=-1/720
stark wedge
some commas would have helped
mental skiff
ok
stark wedge
hm. seems tricky.
maybe trying to look at the generating function of these a_n would help
(using the relation between them to derive some kind of form for it)
not yet sure how exactly but thats the only idea coming to mind rn
mental skiff
True but like i am stuck at this point
Look could we manipulate the fact that P(n) has utmost a degree 0f 2024
Like for maybe at max 2024 numbers
P(n)- this summation * n! is 0
hello?
hello ?
Ann?
mental skiff
what ?
stark wedge
ok but you still acted rather impatient