#precalculus

1 messages · Page 301 of 1

civic furnace
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f(1) = -1, f(5) 10, f(6) = 11

willow bear
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yes

civic furnace
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yeah, (-3,0)

willow bear
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that sounds like an open interval

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so your claim about the book's claim is false

civic furnace
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but it achieves a zero for -3

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smallest integer n such that 3n > -3 is 0

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so whether it means a point or an interval doesn't matter because both the point (-3,0) and the interval (-3,0) are incorrect, as the correct answer is [-3,0)

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which might as well be written [-3, -1]

echo wagon
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No [-3, 0) and [-3, -1] are not the same

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Nonintegers exist

civic furnace
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only integers are used here

echo wagon
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They are using interval notation but only referring to integers? sully

civic furnace
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what's wrong with it?

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besides, it's unclear whether they mean a point or an interval

echo wagon
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Interval notation is almost always used for all real numbers between the endpoints. It only refers to integers in rare cases like in number theory if you don't work with real numbers at all.

civic furnace
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it fits the definition, no?

echo wagon
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In a precalc or calc course, they really shouldn't do that especially since students already get confused about interval notation

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What definition?

civic furnace
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of an interval

echo wagon
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Do you have a definition?

civic furnace
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(-3, 0) = {x in Z : 3<x<0}

echo wagon
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You left out a minus, but sure if you define it that way, it is correct. I am saying I think it is bad to define it that way since it is non-standard and a lot of students already think intervals only contain integers when they encounter them so seems like a bad idea to promote that

civic furnace
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alright

echo wagon
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I agree the answer is [-3, 0) regardless of whether it only means integers or real numbers

civic furnace
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thank you all

willow bear
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there is a less sus notation for integer ranges

raven kindle
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@willow bear is this right?

willow bear
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no

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look at your very last line

the endpoints are (-6,3) and (6,3)
this literally flies in the face of the problem statement

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congratulations. you've managed to completely disregard the problem.

raven kindle
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ohhhhhhh

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okay

willow bear
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a : b
defined as {x in Z | a <= x <= b}

civic furnace
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looks like a ratio to me

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why can't mathematicians invent new symbols

raven kindle
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@willow bear how about this one? this is from my friend

willow bear
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🙃

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i mean it looks correct now

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tell your friend she's succeeded at making the computer do it

raven kindle
surreal crest
daring vault
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but that will not contain 'b' kekw

surreal crest
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Correctamundo

spark glade
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how tf do u solve this

tired axle
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That's about 257.12

dim egret
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The mirror in Alan’s flashlight is a paraboloid of revolution. If the mirror is 8 centimeters in
diameter and 4.5 centimeters deep, where should the light bulb be placed so it is at the focus
of the mirror?

I got 0.889cm if rounded to three decimal places.
Can someone check to see if I'm right?

viscid thistle
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your answer is correct

civic furnace
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How do I calculate the % of males that live in a village if I know the number of women/100 males on avg, in cities, and in villages?

echo wagon
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Assuming there are only women and men in the village, let's say there are x women per 100 males. Then out of 100+x people, there are 100 males. So, 100/(100+x) * 100 will give you the percentage of men

civic furnace
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Thanks

civic furnace
# echo wagon Assuming there are only women and men in the village, let's say there are x wome...

You've given a wrong answer but I had thought I could use it to calculate the correct one. You've calculated the % of males in the villages, whereas the question asks you to do so generally. The idea is that since the avg in this case is 96.7 women/100 males, whereas for the cities it's 99.7/100 and for villages it's 91.6/100 you have to take into account the fact that the number of people that live in the cities is greater

echo wagon
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Your question said you knew the average number of women/ 100 men in villages. But okay, so long as you have the correct answer now.

civic furnace
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I had thought

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I didn't solve it cause idk how

willow bear
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i don't see how luna's statement is wrong

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the proportion of men in the village is 100/(100+x) where x is the number of women per hundred men

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which you say you know the value of

civic furnace
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(# of women living in the cities + # of women living in the villages)/(# of men living in the cities + # of men living in the villages) = 91.6/100

The question asks you to find the # of males living in the villages/( # of males living in the villages + # of males living in the cities)

willow bear
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okay, hold on

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do you have a screenshot of the problem?

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even if it's in a foreign language.

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as-is, your wording is making me confused.

civic furnace
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Idk how to calculate how many more men live in the cities than villages if I know these proportions between men and women

willow bear
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should i repeat myself?

civic furnace
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96 b)

willow bear
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...alright looks like my knowledge of russian is not quite enough to decipher the polish

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can you translate 96b?

civic furnace
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Calculate the % of males aged 20-24 that lived in the villages

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so as I had said

The question asks you to find the # of males living in the villages/( # of males living in the villages + # of males living in the cities)

willow bear
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% of males aged 20-24 that lived in the villages
among all males?

civic furnace
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You know only that women/100men for the age bracket 20-24 is: avg = 96.7, in cities 99.7, in the villages 91.6

willow bear
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so wouldn't this require knowing the number of people in every age group?

civic furnace
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Nah, it only asks for the 20-24 age bracket

willow bear
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but you just said "among all males"

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not "among all 20-24 y/o males"

civic furnace
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Where have I said all males

civic furnace
willow bear
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and then i asked "among all males?" and you said yes.

civic furnace
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Sorry

civic furnace
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@willow bear Could you, please?

willow bear
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no

civic furnace
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Also, how do I solve:

Show that the following inequality is true
sqrt(2^50 + 1) + sqrt(2^50-1) < 2^26

willow bear
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i have a solution that i am 100% certain you'll be unsatisfied with

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...actually no nevermind

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there is one that doesn't involve convexity

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show $\sqrt{x^2 + 1} + \sqrt{x^2 - 1} < 2x$ for $x \geq 1$, then take $x = 2^{25}$.

obsidian monolithBOT
willow bear
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you might find it easier to prove $\sqrt{x^2 + 1} - x < x - \sqrt{x^2 - 1}$ instead, which is equivalent.

obsidian monolithBOT
vapid plaza
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(But if you know a bit of calculus you can skip the red completely)

civic furnace
# vapid plaza

I think you are missing a +1 on the LHS of the 2nd red line

vapid plaza
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Nah I divided everything by 2

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Lol

civic furnace
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Doesn't make sense

vapid plaza
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Why not?

civic furnace
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Look at the rhs

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n + n - 1

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lHs should be n + 1 + n

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You only have 2n

vapid plaza
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?

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I see nothing wrong

civic furnace
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I'll show you once I come back home

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Can't highlight it on phone

vapid plaza
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Try to work it out yourself; I think you will reach the same result

hollow lance
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The write-up is fine

civic furnace
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IMO 1st redline isn't equal to the 2nd

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due to LHS being different

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They differ by 1

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Oh wait

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Nevermind, I didn't see the. 1 there

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I'm blind sry

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Huge thanks

opaque wraith
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hi can i have help setting this up

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i dont rlly know where to start

vapid plaza
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Suppose that the fare is $p.
Try to express the revenue in terms of p

tranquil haven
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What do they want?

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I don't understand the question

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Why are so many questions in books super vague

jagged glade
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I think, if they give you sin(x)
Then you need to find cos(x) and tan(x).

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And if they give you cos(x)
Then you need to find sin(x) and tan(x).

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And if they give you tan(x)
Then you need to find sin(x) and cos(x).

tranquil haven
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How to do such a thing ? I'm stuck

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Nevermind

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Nope I'm stuck

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How to solve such a thing ?

viscid thistle
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Sin 3/5 is 3 is opposite 5 hyp

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Now find cos and tan

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Maybe no

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What's x?

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,nvm sry

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I don't understand too

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X is the angle

tranquil haven
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Yeah

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Vague right

viscid thistle
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Sry i couldn't help

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, x is the right hard bracket

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Maybe

jagged glade
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Like you can draw a right angled triangle to solve for the magnitude of the sine cosine tangent, and then find the sign +/- using the ASTC

viscid thistle
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You have to put between those numbers or choose the right one?

jagged glade
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Like for example 7,
sine is positive
cosine is negative
tangent is negative

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And you draw a right angled triangle with side lengths 3,4,5

tranquil haven
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Wait, I can find adjescent with pythagorean theorem

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Wait 3s

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Found them!

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sin x = 3/5, cos x = 4/5, tan x = 3/4

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Only one mistake

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Fuck

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The signs

viscid thistle
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Is it the answer?

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What about x

jagged glade
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Yea the signs

tranquil haven
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I got it

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The next one...

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Leaves me even more clueless

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And this is just chapter 1.3

viscid thistle
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Tan 2 so is sin 2 cos 1?

tranquil haven
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x has the range of [0,pi/2]

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so sin x cannot be sin 2

viscid thistle
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Nvm

tranquil haven
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This is from the book Thomas Calculus

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I'm trying this after following KhanAcadamy

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But damn these questions are hard, I feel like I barely learnt anything on that website

viscid thistle
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Khan doesn't explain that good

upper tundra
# tranquil haven

x is in [0,π/2] hence, sin x and cos x are positive so, sin x=2/√5 and cos x=1/√5.

hard prairie
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yo

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the answer would be 1/x right

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since g(x) = x-7 and (fog) = 1/x-7

sick steppe
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no

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or if it is, it's not the obvious answer

mild swan
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f o g = f(g(x))

g(x) = x-7

f(g(x)) = f(x-7)

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$f(x-7) = \frac{1}{(x-7) - 7} = \frac{1}{x-14}$

obsidian monolithBOT
mild swan
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f o g means f(g(x))

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f(g(x)) means that instead of f(x) (where x is the input), the input is now g(x).

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In this case, g(x) = x - 7, so the new input to f is x - 7.

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@hard prairie

hard prairie
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but isnt h(x) = (f o g)?

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where did the 1 on the numerator come from?

mild swan
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I misread the problem, my bad

hard prairie
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wait so im right?

mild swan
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but isnt h(x) = 1/(x-7) = (f o g)?

hard prairie
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yeah

mild swan
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f o g = 1/(x-7)

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f = 1/x?

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yeah f = 1/x

hard prairie
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f(x) = 1/x right

mild swan
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Because that's the function that makes f o g (or f(g(x))) = 1/(x-7)

hard prairie
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since f(g(x)) = f(x-7)

mild swan
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yup

hard prairie
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and if your plugging x-7 into f then f has to be 1/x

mild swan
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And you need that to be h(x) = 1/(x-7)

hard prairie
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nice

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so were on the same page right? 😂

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ive been pulling my hair out over this single problem for the past 30 min 😂

mild swan
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You should be good

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Dw about it too much

hard prairie
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thanks bro i appreciate the help fr

mild swan
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👍

ornate island
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How do i find the end behaviors of say y = (tan^-1 x)^2 without using a calculator?

ornate island
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<@&286206848099549185>

small tree
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how can i graph this?

proud raven
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try to split apart pieces so theyre easier to think about

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im dumb there are no zeros 😄

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it may be easiest to think of the function without looking at the +1

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then translate it upwards after

red tree
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It's an exercise in plotting translations and dilations of the graph of a function

small tree
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can someone please explain how the system got that answer? (thank u)

jagged glade
obsidian monolithBOT
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Biscuit

red tree
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I think that kind of muddles the fact that logarithm is a function with a well defined definition

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$\log_a x$ is the unique real number $b$ such that $a^b=x$

obsidian monolithBOT
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Icy001

red tree
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Much better way to state the definition

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We shouldn't be scared to say "such that" in front of high school students

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😤

acoustic dagger
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Any ideas? (Mustn't use derivative)

willow bear
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you could do some multiplication-by-the-conjugate tricks, couldn't you?

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@acoustic dagger do you even need help with this still?

acoustic dagger
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I solved it right away

simple glade
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How I can solve it ?

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The answer is 6

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But how

uncut mulch
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consider combining your terms into a single fraction

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@safe hamlet

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its not H

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consider combining your terms into a single fraction

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what do you have after doing my recommendation

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show your work

simple glade
burnt lodge
vapid plaza
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Probably DEF

bleak lance
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Sorry bad image

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Could someone please help me find the domain?

dusk elm
# bleak lance This

The domain of a composition of function is the intersection of the functions f and g

simple glade
bleak lance
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Could someone please help me find the domain?

small tree
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i dont know how to graph this.. i m confused about the 5x part?

sick steppe
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log[5(x+2)]-3

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then just do your typical transformations

nova moat
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what is a math major

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what year is that

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@sick steppe

sick steppe
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I major in math...

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google it if you don;t know.

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Also dont know why you felt the need to ask here as opposed to a discussion channel

nova moat
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I'm new here

small tree
dusk elm
# bleak lance

Doesn’t seem you got an answer yet. The domain is all x values that give a real number output. When do you not get a real number output for f(x)?

small tree
sick steppe
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the 5 is inside the function

small tree
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so what does the 5 do

small tree
hard prairie
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hellooo

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follow professional mathematicians

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quick question

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what de frick happened to the 3/4

lapis sphinx
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It’s reciprocal, 4/3, was mutiplied to both sides

uncut mulch
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3/4 is irrelevant to the zero product

hard prairie
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oooooh

uncut mulch
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whether 3/4(x+4)^2 is 0 solely depends on (x+4)^2

hard prairie
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multiplied both sides by the reciprocal

lapis sphinx
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Whats the zero product

hard prairie
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i get itttt

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nice

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thanks bois

lapis sphinx
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Or instead of 4/3 multiplied to both sides, 3/4 were divided from both sides

uncut mulch
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the product of stuff that results in zero

lapis sphinx
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((e^ipi) + 1)^2

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@uncut mulch is this also considered a 0 product

willow bear
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$-\log(5 \cdot 6) = -(\log(5) + \log(6)) \neq -\log(5) + \log(6)$

obsidian monolithBOT
willow bear
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and $-\log(5) - \log(6) \neq -(\log(5) - \log(6))$

obsidian monolithBOT
willow bear
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this is just basic algebra

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if you thought it had anything to do with logarithms you were mistaken

sullen zealot
# bleak lance

So, you want to find values of x where the function is undefined first, so either where the denominator is 0 or where you are taking the square root of a negative number. Here there are no square roots and so you want to solve the equation 9x - 5 = 0 where 9x-5 is the denominator. This will then be the x input where the function is undefined and it's domain will be all other inputs other than this.

lean ibex
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how do I take the domain and range of a composite function given the graphs of the functions

small tree
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how did the system got that answer 7 years?

sick steppe
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15000=1750e^(.3t)

small tree
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thank u..

signal rover
#

which is more difficult?
pre-cal or cal 1

oblique cave
#

probably calc 1... i thoguht so at least

viscid thistle
#

ayooo

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guys i need help with identities

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can someone explain how the book got this answer

faint basin
#

they rewrote sin3x as sin of 2x+x and apply the sin(a+b) formula

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then the one for 2sinxcosx which is indeed sin2x

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u just gotta know your identites here

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not that hard tbh

lucid flame
#

Alright I'm having a bit of trouble with this problem, I'm supposed to look at the graph and answer what the X-ints are and then confirm my answer with the equation

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But the thing is

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When I plug in zero, it works for 3 just fine but for some reason on the other one it just doesn't work

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You'd get X=5

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So I don't know if I'm just doing something real dumb or what

uncut mulch
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ab = c
generally doesn't mean that a=c or b=c
(if c isn't 0)

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it would also be much simpler to plug in your x values into the given quadratic equation to see if you get y=0

lucid flame
#

that would be much easier. and i also found the answer to what i was trying to do, apparently i was supposed to put the entire equation on the other side

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so it

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it'd be -x^2+2x+3

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for some reason i guess

cedar bramble
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is this corect!?

tranquil moth
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yes

cedar bramble
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thxx

sterile cobalt
#

So guys this problem is asking me to solve for all real values of x

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\sqrt{2x+1}+1=x

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I think I'm supposed to add 1 on both sides

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Then square both sides to get rid of the radical

native panther
#

I have 3w + 2l = 1000

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so far

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And then I wrote out A(w)=w * (1000-3w/2)

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does this seem like a decent first step towards finding the perimeter so I can solve for the area?

civic furnace
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Find such real numbers a and b so that the expression 10a^2 + b^2 + 6ab + 4a + 1 acquires the smallest value.

Got to:
(3a+b)^2 + (a+1)^2 + 2a and don't know what to do now

somber sigil
#

btw that is not really calc

civic furnace
#

<@&286206848099549185>

stuck lark
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@civic furnace pls post questions 1 at a time

civic furnace
#

@stuck lark why>

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rules don't say anything about it

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also

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have you really fucking deleted all my questions

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could you please restore them

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i don't have them written anywhere else

stuck lark
#

pls don't try to find loopholes here. spamming questions as you did is obnoxious

civic furnace
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nobody has found an issue with it before

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including @willow bear

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aren't moderators supposed to moderate according to the rules?

stuck lark
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i was writing a reply to the previous points but forget it; you've escalated your rules lawyering to a point where i find you in bad faith. goodbye

willow bear
#

b&?

stuck lark
#

b&

willow bear
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good, they were giving off bad vibes at nearly every turn anyway

viscid thistle
#

Hey guys I have a question, I saw it on a paper and I cannot solve it, anyone up for help?

clever sandal
#

Hey guys is there any way to closely estimate sinx in terms of basic equations

willow bear
#

what do you mean by "basic equations"?

proud raven
clever sandal
clever sandal
willow bear
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$\sin(x) = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \dots$

obsidian monolithBOT
proud raven
#

it depends on how accurate you want it to be

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but yea

willow bear
#

this is the taylor series for sin(x)

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for the exact value the series goes on forever

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but if all you want is an approximation you can get away with only calculating finitely-many terms

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is this what you were looking for?

proud raven
#

its also better for angles close to 0 displacement

clever sandal
proud raven
#

so if youre in a small angle the so called "small angle approximation" $\sin (x) \approx x$ works more or less fine

obsidian monolithBOT
#

jan Niku

willow bear
#

engineer moment

proud raven
uncut mulch
#

note to use radians

proud raven
#

theres a great 3b1b video on this exact topic

clever sandal
#

nice

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thanks y'all

viscid thistle
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Pre calc makes me want to cry

viscid thistle
#

How do we get rid of log(y)=x if the base isn't mentioned?
I wans the log on the other side

small aspen
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i think in most texts log is treated as base e

clever sandal
viscid thistle
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so will it be y=10^x?

clever sandal
#

yeah

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ln is base e, lb is base 2 ok?

small aspen
clever sandal
#

this is confusing now

small aspen
#

actually maybe it depends on where

clever sandal
#

yeah

small aspen
#

from what i learnt log is base e but fair enough i know people who use log as base 10

clever sandal
#

I learnt log = base 10

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and use ln for base e

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I'm kinda dum when it comes to these notations

rough mason
#

hey can someone tell me what this is?

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<@&286206848099549185>

slow mural
#

Can someone write me a written solution to this answer please. It would be greatly appreciated.

proud raven
#

any ol solution should be okay why this one?

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is there something youre confused about in the solutions to these in general?

unreal dawn
#

can i teach myself precalc

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im currently a sophomere taking alg II

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i want to take ap calc next year so i can take multivar in my senior year

twilit wolf
abstract moss
#

hi, idk if i'm chatting in the right text channel but i really need help with my hw. i'm not asking for answers, i really want to understand the lesson and i wanna know how to solve for the answer or something. my teacher cancelled our class for this week so yeah i'm really having a hard time understanding this.

merry ledge
abstract moss
#

so i'm gonna substitute f (x) into g (x)?

merry ledge
#

(f o g)(x) = f[g(x)]

merry ledge
abstract moss
#

ohh okay, are there any video tutorials on youtube for that?

merry ledge
abstract moss
#

okayy, thank you very much your help :))

slender cargo
#

hi can someone please explain why in the answers they don't first differentiate the equation to get the velocity?

hollow lance
slender cargo
#

yeah just realised

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thanks

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what's the difference between average velocity and acceleration

robust star
#

How do I find the zeros of x^3+2x^2+4?

willow bear
#

it doesn't look like the zeros can be readily expressed

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are you asked explicitly to find the zeros?

robust star
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I need to sketch (x^3+2x^2+4)/(2x^2+1)

willow bear
#

hm.

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well i can tell you from graphing that x^3 + 2x^2 + 4 appears to have only one real root and it's a nasty decimal

robust star
#

yah ill just say I used a graphing utility to find it

west swallow
#

How this happen explain me lol

merry ledge
river summit
#

Heyo anyone open to help me out?

rough mason
#

helppp

uncut mulch
#

consider the second derivative

viscid thistle
fiery crag
robust star
#

What is the x-intercept? I got x=-1

toxic flame
#

yes

robust star
#

i got it wrong tho

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wdym

#

ah i c now ty

remote jungle
warm forum
toxic flame
#

oh pfttt

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continuously extend it bruv who cares 💀

torn locust
#

New here

robust star
#

Is there a way to find a zero of this function without testing all the possible roots? It takes way too long to test them all.

tawdry wing
#

You could find one root, then perform polynomial division and factor the quotient to find the other roots.

torn locust
#

is it possible to locate the center or create a standard equation given only the "vertex" and asymptotes? If yes, what should I do?

bleak elbow
#

can somone help me with this?

rare flame
#

hey can someone help me

#

i'm new here

uncut mulch
rare flame
#

Consider the following polynomial.

F(x)=x^3+x^2−22x−40
Use synthetic division to identify integer bounds of the real zeros. Find the least upper bound and the greatest lower bound guaranteed by the Upper and Lower Bounds of Zeros theorem.

Upper Bound:
Lower Bound:

tired axle
rare flame
#

i couldn't figure it out

tired axle
#

Chaucy's Bound

#

Where are you stuck

rare flame
#

with solving it the equation and found no solution

tired axle
#

Did you identify the least upper and greatest lower bounds first?

rare flame
#

no

tired axle
#

That will help you

#

Also it's part of the problem

rare flame
#

i need that help

tired axle
#

Oh, it's the entire problem

#

Ok, read the theorem

rare flame
#

okay

tired axle
#

So what should you do

#

Or what numbers should you use

rare flame
#

what i should do

tired axle
#

What does the theorem say to do

rare flame
#

the same

tired axle
#

What are a_0, a_1, ..., a_n?

rare flame
#

@viscid thistle

#

@sick steppe

viscid thistle
rare flame
#

ok i could

sick steppe
#

That's the question... not your work

rare flame
#

oh i don't have it

sick steppe
#

so you have made no attempt on your own to try and do the problem...?

vestal wyvern
vestal wyvern
#

try to solve the problem first

rare flame
#

i did it online but not in my notes

vestal wyvern
#

o wat

#

can you screenshot your work online..?

rare flame
#

i believe it is Positive Real Zeros: 1 , Negative Real Zeros: 2 or 0

vestal wyvern
rare flame
#

ok

#

here you go

uncut mulch
#

f(x) is not the product of a magical number f and x

rare flame
#

it's not

tired axle
#

@rare flame this is an easy problem, get a pencil and paper and hack it out, the computer is going to slow you down

rare flame
#

okay

tired axle
#

Look at the theorem, it tells you what to do, and it is all you need to do

viscid thistle
#

I have a question that I asked 3 hours ago but still not answered pls help-22

#

It's a cambridge question btw

tired axle
#

@viscid thistle when you bump, quote your original post

#

You dont have anything else in this channel from today

viscid thistle
viscid thistle
#

If sum of first p terms is q and sum of first q terms is p then what is the sum of first (p+q) terms?
my efforts...
sum of first p terms = (p/2)(2a+(p−1)d)=q
and sum of first q terms = (q/2)(2a+(q-1)d)=p
Idk how to proceed further
I guess i need to find "a"(first term) and "d" (common difference)

willow bear
#

sum of first p terms of what?

#

is the sequence you're summing actually known to be arithmetic?

amber marsh
#

is sin^2(x) the same as saying sin(x)^2 ?

sick steppe
#

$\sin^2(x)=[\sin(x)]^2$

obsidian monolithBOT
amber marsh
#

huh. does that apply for all the functions?

sick steppe
#

no

#

trig notation for powers is just shit sully

amber marsh
#

ralphwiggum_imindanger.jpg

viscid thistle
sick steppe
#

no

viscid thistle
#

Why? What can make you say yes ?

sick steppe
#

My choice to not let you dm. And nothing.

#

I'm also more than happy to dm mods if you continue to pester me

viscid thistle
#

I know... how can I change your mind about it?

sick steppe
#

Nothing, now stop pestering me.

viscid thistle
#

What.... ok

coral parrot
#

can anyone help me for the love of gof

glacial juniper
#

I thought reference angles were always in the first quadrant?

cunning epoch
#

i know that i could just use the table to find it, but i need help understanding why those values on the table correspond to the values in the question.

small tree
#

hi, i dont get how the system got these answers... the only one that i get is part C. bcuz 360 - 315 = 45..

proud raven
#

this looks wrong?

#

i mean the drawing

#

the length of that vector isn't sqrt 2

#

@small tree

#

ignoring the drawing the rest of it is right

#

oh, a point

#

nevermind 😄

#

well you found a point on the line,

#

and then the sqrt 2 is just from like

#

the distance formula

#

$d = \sqrt{ x^2 + y^2} = \sqrt{1 + 1} = \sqrt 2$

obsidian monolithBOT
#

jan Niku

jovial stratus
#

Can someone help?

Problem:
Find the first three terms of the geometric sequence whose sum is 7/16 and product is 1/312

I don't seem to go anywhere with this problem, i've tried

x/y + x + xy = 7/16
x/y * x * xy = 1/312

But still I don't get the right answer

#

If x = ³√1521/78, how do i find y?

echo wagon
#

How do you get that x value?

#

x/y * x * xy = x^3 = 1/312

#

To get y plug the value of x into the other equation

jovial stratus
echo wagon
#

It's a quadratic polynomial

#

So solve it using quadratic equation

teal matrix
safe gate
#

Can you further simplify this equation

late mica
safe gate
#

Lemme try again

late mica
safe gate
#

Yes

teal matrix
late mica
# safe gate Yes

That was replying to Alejandro. You specified you needed help, I just can't read yours.

safe gate
#

2 . cos²x . cos²y + 2 . sin²x . sin²y

late mica
safe gate
#

There

late mica
teal matrix
safe gate
#

I just wanted to know if we can further simplify this 2 . cos²x . cos²y + 2 . sin²x . sin²y

safe gate
#

Something to do with that yeah

late mica
safe gate
#

ok

late mica
teal matrix
late mica
# safe gate ok

Hm, I'm not seeing identities. The only identity I can think of cos^2x = 1 - sin^2x. You could factor out 2 from both terms and try something with that - I don't see any, though. Perhaps someone else will?

late mica
# teal matrix ok

Once you've got that, subtract f(x) from it, then put it all over h

safe gate
#

yeah i was thinking about factoring aswell

late mica
late mica
opaque citrus
#

a transformation image of the graph of y=f(x) is represented by the equation y+2=-2f(1/2(x+3)). The point (-9,2) lies on the image graph. What are the coordinates of the corresponding point on the graph y=f(x)?

#

i got (-21,-6) but now that i look at the question again i think i got the wording confused

#

did it maybe ask me to do something else?

#

im confused

late mica
late mica
teal matrix
opaque citrus
#

could some1 help me pls :((

#

<@&286206848099549185>

pseudo harbor
#

a

warped shoal
#

when i did it, the answer became zero, as only h was left

tired axle
#

^via nth root theorem. I guessed the root was -3 and guessed right. Then I guessed it had multiplicity-2 (repeated root) and was correct again. Last two roots had to be imaginary to get x^2 + 1

#

needed a binomial where there is no middle term and the constant comes out positive. That's imaginary conjugates.

#

or more generally, complex conjugates

#

no, check it:

#

(a+bi)(a-bi) = a^2 -bi + bi -b^2 * i^2 = a^2 + b^2 (always)

#

and in fact, (x-i)(x+i) = x^2 - i^2 = x^2 -(-1) = x^2 + 1

glacial juniper
#

<@&286206848099549185>

tired axle
glacial juniper
tired axle
#

Oh, I thought the first one, I, was -pi/6. Looks like 2 of the answers work, -pi/6 and 7pi/6. But that was wrong for some reason

hazy viper
#

Hello everyone I would like to get ur suggestions regarding to the materials and Topics I've to go through in Pre-Calculus .

inner blade
#

can you help me with factoring?

mellow tapir
obsidian monolithBOT
#

not discordmod

uncut mulch
#

that isn't right

viscid thistle
#

plz help

#

number 46

willow bear
#

@viscid thistle do you still need help with this?

void wing
#

are you there?

#

i can write it out but would rather write it out if you would eventually see it

#

just ping me

foggy frigate
#

If y’all can just answer a relatively simple answer for me I’d appreciate it. (Ill put it down in this mssg as well) currently I’m trying to find the roots of f(x)=x^4-4x^3+2x^2+x+4, a 5 term function degree 4, I see what the roots are but would it be possible to solve for the answer without graphing it on a graphing device? Because the roots are decimals so im lost how id solve on paper.

tired axle
#

You can try and estimate using intermediate value theorem, but you really want to use Newton's Method, which is introduced in Calculus.

foggy frigate
#

Okay I see let me dig into that, thx for the suggestion.

tired axle
#

One other idea though

#

If you get lucky, a simple guess at the complex solutions will give you a quadratic

#

So maybe see if i and -i are roots

#

Using synthetic division

#

(I mean, wolfram will tell you)

#

(Nope.)

foggy frigate
#

I just used the newtons law and i was able to show my work for this, Had to learn what derivatives were but I think I got the hang of newtons law. I am not understanding how I’d use i and -i with synthetic division in your other idea honestly my teacher last yr barely skimmed over i last yr.

#

Newtons law?!?! Lmfao newtons method

foggy frigate
#

I used the rational root theorem you mentioned as well on my next problem to guess it completely without adevice so i appreciate your help

tired axle
#

Oh good!

tired axle
robust star
#

how do i convert this into logarithmic form?

jagged glade
#

Take log on both sides?

#

Or you wanna keep the numbers?

robust star
#

wdym by that? the problem is that the fraction is confusing me

jagged glade
#

You may have to show your work to make it clear what you want and have a chance for other people to help you 😄

viscid thistle
#

guys i need someone to help me rnw plz

willow bear
#

@viscid thistle apologies for not being able to respond earlier after you replied to me when i was already asleep.

#

i take it you still need help solving the equation $\frac{4}{\sin(x)} + \sin(x) + 5 = 0$, and you have made zero progress so far?

obsidian monolithBOT
viscid thistle
#

Hi so with the ambiguous case with law of sines, how do you determine the number of solutions?

#

What I'm getting, is that if the sum is less than 180, then there are two solutions, but if it is more than 180 it is only one solution

heady nymph
#

anyone here knows where I can do math exercises with step by step solutions? preferably math exercises of functions, domain, asymptotes, interceptions, derivatives etc

sly hamlet
#

How would you solve:

ax + atan(x) = (a*pi)/2
a = Any real number
Solve for X, no estimates
In range 0 < x < pi/2

All me and the other students were able to find is that

There are 2 solutions
x1 + x2 = pi
x1 = pi - x2
x2 = pi - x1
tan(x1)/tan(x2) = -1
and
tan(x2)/tan(x1) = -1
(and obv tan(x1) = -tan(x2))

Aside from these observations I don't think we found anything else

x1 is about: 0.710462737775517
x2 is about: 2.43112991581428
slim echo
#

i need help with 57 and 59!

keen gazelle
#

Hello! Quick one. How would I find the average rate of change using a slope function? Thanks lads.

bronze relic
#

Hello!! My name is Koyaaa and I need help with my homework I'm stuck and it was due 15 minutes ago 🥺 please help

#

Can anyone help please

#

Ahh 😧 what happened

#

Ok I think I see what your saying @viscid thistle

viscid thistle
#

sorry I was on my phone for that.

bronze relic
#

No worries!!

keen gazelle
#

No-one click on these links! <@&268886789983436800> Can you please remove?

viscid thistle
#

<@&268886789983436800>

gilded sapphire
viscid thistle
#

So I got this problem involving inequalities

#

if the solution to this is -2<=x<=2

#

What is k?

#

I tried squaring both sides and going from there but thought that there was no way that that's the intended way to do it

#

So I checked the solution

#

And it was just like 2 lines long

#

The above condition is satisfied when the line y=kx-2 passes the point (2, 2)
2=2k-2
=> k=2

#

I drew it on desmos

#

To get a feel for what it looks like

#

It makes a lot of sense

#

But what I want to know is how do I know that it should be like this

viscid thistle
#

What's -x/9=x/5?

#

Gave me 90 but idk how

#

<@&286206848099549185>

#

Been getting 14x

placid knot
viscid thistle
#

A little blurry since I'm on mobild bht

#

mobile but

#

You can see the question and A the answer choice i said it was..

placid knot
#

i guess no procedure is shown

#

the solution should be 0

viscid thistle
#

There's no answer choice that is 0 lol

placid knot
#

can you show the original question? to make sure we're not missing something

viscid thistle
placid knot
#

,rotate

obsidian monolithBOT
placid knot
#

wait lol

#

the 28 is not the question number, it's part of the problem

viscid thistle
#

OH LMAO

#

I WAS SO CONFUSED LOL

placid knot
#

i think that's enough for you to solve it 😛

#

me too lmao

viscid thistle
#

Thank you so much and sorry if I wasn't clear on my question or came off a little rude

placid knot
#

aight, mystery solved. no problem lol

viscid thistle
warped tundra
#

Hello! I need some help with my precal homework. My teacher sent me an example but I’m too embarrassed to ask her any questions again.

viscid thistle
#

So what I'm thinking is this
Log5(128)xLog128(2)=Log5(2)
5^3=125~128
2^7=128
So 3/7=Log5(2)
lol

Log5(75/8)=Log5(75)-Log5(8)=Log5(25)+Log5(3)-3Log5(2)
Log5(3)=Log27(3)Log5(27)~2/3 (Since 27 is kinda close to 25)
So Log5(75/8)=2+2/3-3x3/7

#

Oh wait they already gave you Log5(8) and Log5(3)

tepid cloak
#

can someone help me pls

viscid thistle
#

Those are just circles, I think
(x-1)^2+(y+2)^2=26
(x-6)^2+(y-3)^2=16

tepid cloak
#

wait im confused

#

how do you get the x and y values if the distance is given

viscid thistle
#

Think of it like this
P(x,y)
P1(1,-2)
The vector PP1 = (x-1,y+2) has a length sqrt((x-1)^2+(y+2)^2)
You want that length to be equal to sqrt(26)

#

In mathematics, physics and engineering, a Euclidean vector or simply a vector (sometimes called a geometric vector or spatial vector) is a geometric object that has magnitude (or length) and direction. Vectors can be added to other vectors according to vector algebra. A Euclidean vector is frequently represented by a ray (a directed line segmen...

tepid cloak
#

oh but how did you get 1 and -2 values

viscid thistle
#

That's point P1

uneven basin
#

Can someone help me with this?

viscid thistle
#

I think if you can multiply u by a constant c so that it's equal to v then they are collinear
meaning
cu=v
(-8c,5c)=(x,-2)
-8c=x
5c=-2
<=> x/-8=c=-2/5
I hate arithmetics

uneven basin
#

ok thanks

uneven basin
#

just needed help with this last question on my review

small tree
#

hi, can some explain to me why the system got this answer? thank you..

opaque flicker
# small tree

because in the domain [0,90] the cos function is an increasing function, so cos(30) < cos(40)

oak drum
#

does anyone know how to find values a, b, and c given three points (0,4),(1,14),(2,20) and the exponential equation S(t)=ae^bt +c?

gilded sapphire
oak drum
gilded sapphire
oak drum
cunning raptor
#

How would I approach this question? I tried using trig identities and the squeeze theorem but still can't quite get it:

opal prairie
cunning raptor
willow bear
#

who typeset this

#

it looks horrible

#

$\lim_{x \to 0} \frac{\sin(29x)}{\tan(2x)}$

obsidian monolithBOT
willow bear
#

anyway, may i suggest multiplying and dividing by x?

#

so you have $\lim_{x \to 0} \frac{\sin(29x)}{x} \cdot \frac{x}{\tan(2x)}$

obsidian monolithBOT
cunning raptor
willow bear
#

well, are you able to find the limit of sin(29x)/x as x -> 0?

cunning raptor
#

well yes, it would still be in Indeterminate form

quiet marsh
#

can someone explain to me how to solve this?

obsidian monolithBOT
#

RaghavJeyan

trim epoch
#

@quiet marsh

quiet marsh
#

wait is that it

#

oh my god that is it

#

thanks

oak drum
#

would this simplify to 6=ae^b(2)-ae^b, if so I likely did something wrong in the previous parts.

willow bear
#

yes, $ae^{2b} - ae^b \neq b$.

obsidian monolithBOT
willow bear
#

...wait, what

#

what even happened there

#

did you try to add on the left side but subtract on the right?

#

looks like this is nonsense in more ways than one.

#

@oak drum do you happen to have the original problem statement that this is the solution for?

oak drum
#

i’m not even sure what happened i’ve got it in a huge mess 3: it’s a multi step problem where i am to use three points to find an exponential model, i can get a screenshot of it

oak drum
oak drum
#

problem resolved, i met with my professor privately today kwa

spark junco
#

guys whats the F(x) here??

vapid plaza
#

You mean f(x)?

spark junco
#

no the integral

vapid plaza
#

..integral?

#

You mean sigma?

#

Summation?

spark junco
#

no

#

what is the integral of f(x)

vapid plaza
#

Oh

#

Just integrate every term in the sigma

spark junco
#

😐

#

and how do i do that

vapid plaza
#

Use the power rule for integral

spark junco
#

wait do i just have to add +1 to every n

vapid plaza
#

And divide the term by n+1 as well

#

I reckon

spark junco
#

oh ok

#

lol

#

i thought i had to eliminate the sum notation somehow

vapid plaza
#

The sum notation is the general form for some N-degree polynomial

spark junco
#

alright thank you

small tree
#

hi, can you plz explain how the system got this answer.. thank you!

full pagoda
#

rewrite cscx*tanx in terms of sin and cos

small tree
#

yeah lol but how

small tree
#

nvm i got it

short pilot
#

does someone here know about perpendircular lines

#

and general ecuation

#

i really can not do resolve this one

#

it says finds the k value so that these general equations are perpendicular

uncut mulch
#

do you know the relation between the slopes of perpendicular lines?

eternal void
#

is this not correct?

#

nvm

#

i just found out

small tree
#

hello, can you please explain, these 2 to me.. like why is option "d" the answer to 1- tan(theta)/1+tan(theta).. and also the orange one thank you!!

astral root
#

I’m having trouble understanding why -1<=cos x<=1 becomes -|x|<=xcos x<= |x|

#

Actually I understand it now nvm

limber compass
plucky perch
#

hi

#

anyone active here rn?

#

I m interested to know why wolfram thought of resolving that limit instead of the given one, as in, how did it come up with the 1/4 term and +3 term?

rugged briar
#

is this precalc?

plucky perch
#

i suppose?

#

limits of series are done before continuous limits so i thought it should be

sick steppe
#

yeah this is just a geometric series, so it's fine in precalc

#

I also wouldn't personally follow what Wolfram gave, the sum $\sum_{i=0}^n(\frac{-1}{3})^n$ has a known explicit formula

obsidian monolithBOT
plucky perch
#

that is?

ionic sparrow
#

Pls help

#

This is 1,3, and 5 right?

echo wagon
#

Yes

ionic sparrow
#

Oh

#

Tyyyy

echo wagon
#

👍

ionic sparrow
#

I have a feeling this might be wrong

#

Can u let me know pls

echo wagon
#

Oh

#

But if you are allowing duplicate roots and not considering multiplicity, then your previous answer is wrong

ionic sparrow
#

Oh

echo wagon
#

Then a 5th degree polynomial function can have 4 roots

#

e.g. (x+1)^2(x+2)(x+3)(x+4)

ionic sparrow
#

Hm

#

So if it’s a duplicate root and not considered multiplicity, a 5th degree can also be said to have 4 roots??

echo wagon
#

Yes

#

Or 2 roots

ionic sparrow
#

And a 4th degree can only have 3 real roots when there’s a duplicate root and not considered multiplicity

#

Ohh

echo wagon
#

No, a 4th degree polynomial can only have 4,3,2,1 or 0 roots if you don't consider multiplicity, and 4,2,0 roots if you do (by which I mean a repeated root is counted twice)

ionic sparrow
#

Ohhh

#

That makes a lotta sense tyyyy

echo wagon
#

👍

gilded sapphire
#

1 -1/3 + 1/9 - 1/27 + ..... here r is -1/3

#

and a is 1

#

the forumla for gp is a(1-r^n)/(1-r) when r < 1, r^n where n -> infinity is basically zero so the formula for some of infinite gp will be (a - ar^n)/(1-r) => a/(1-r) [as ar^n -> 0]

astral root
#

How do I use the squeeze theorem to evaluate the limit as x->0 of x^2sin(1/x)

echo wagon
#

-1 <= sin(1/x) <= 1, and x^2 >= 0

#

Combine those to get bounds for your function whose limits are the same

sharp owl
#

Hey guys,
Anyone from Kuwait?

obtuse dagger
#

Hello. I am having trouble understanding how to find the difference quotient of a function; apparently, f(x) = (see attached image) and not 5/4h^2, when the difference quotient of f is f(x + h) - f(x) / h. Does anyone know why?

round hemlock
#

We can't tell how to do it if you give an answer but no question

#

Are you saying that the difference quotient is $$-\frac{20}{(4x+4h-3)(4x-3)}$$

obsidian monolithBOT
#

Omega Warrior

round hemlock
#

and not $$\frac{5}{4h^2}$$

obsidian monolithBOT
#

Omega Warrior

obtuse dagger
#

@round hemlock Yes, exactly.

round hemlock
#

Ah I get it

#

But what is the problem?

obtuse dagger
#

Hold on. I will post the question

round hemlock
#

Alright

obtuse dagger
round hemlock
#

ok

#

you should get $$\frac{\frac{5}{4(x+h)-3}-{\frac{5}{4x-3}}{\frac{5}{4h-3}}$$

obsidian monolithBOT
#

Omega Warrior

you should get $$\frac{\frac{5}{4(x+h)-3}-{\frac{5}{4x-3}}{\frac{5}{4h-3}}$$
```Compilation error:```! File ended while scanning use of \frac .
<inserted text> 
                \par 
<*> 538528087764107274.tex
                          
I suspect you have forgotten a `}', causing me
to read past where you wanted me to stop.
I'll try to recover; but if the error is serious,
you'd better type `E' or `X' now and fix your file.```
round hemlock
#

ok nvm it didnt work

obtuse dagger
#

Actually, I think I saw my mistake

round hemlock
#

oh

obtuse dagger
#

I only subtracted the denominator (4x - 3) and not all of f(x), which is 5/4x-3

round hemlock
#

yeah

obtuse dagger
#

Tehe

round hemlock
#

you need to take the entire function and substitute each part in

#

so x for x, x+h for x, etc.

obtuse dagger
#

Right

#

Can I ask you one more question

#

?

round hemlock
#

sure

obtuse dagger
#

Ok

#

hold on

round hemlock
#

I'm in Calculus, so I get anything in Precal

obtuse dagger
#

Ha

#

I have to take Calculus, too -- after I finish precalc, of course

round hemlock
#

yeah

#

I'm taking Calculus I and II this year and Calculus III next year

obtuse dagger
#

Ok, so, number 87 in the picture I posted has an answer of 2x + h - 1. However, I got 2x + h. Do you know where the -1 came from?

#

I'm doing the same but for precalc (I and II) :l

round hemlock
#

oof

#

we only have one year of precal

obtuse dagger
#

Ohh no. I am only doing one year, too; I am taking precalc I now and precalc II in the spring

round hemlock
#

on 87 you should get $$\frac{((x+h)^2-(x+h)+4)-(x^2-2x+4)}{h^2-2h+4}$$

obsidian monolithBOT
#

Omega Warrior

round hemlock
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@obtuse dagger

#

when you substitute all of the values

#

and then simplifying you get:

obtuse dagger
#

What?

round hemlock
#

$$\frac{((x^2+2xh+h^2)-(x+h)+4)-(x^2-2x+4)}{h^2-2h+4}$$

obsidian monolithBOT
#

Omega Warrior

round hemlock
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doing further simplfying gives $$\frac{((2xh+h^2)-(-x+h))}{h^2-2h+4}$$

obsidian monolithBOT
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Omega Warrior

obtuse dagger
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You solved this differently than I did

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Hmm

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I got the answer right, but I was just missing a -1 :\

round hemlock
#

oh

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wait

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i realized i made a mistake

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thats why its not solving right

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$$\frac{((x+h)^2-2(x+h)+4)-(x^2-2x+4)}{h^2-2h+4}$$

obsidian monolithBOT
#

Omega Warrior

round hemlock
#

this is what it actually was

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$$\frac{((x^2+2xh+h^2)-2(x+h)+4)-(x^2-2x+4)}{h^2-2h+4}$$

obsidian monolithBOT
#

Omega Warrior

round hemlock
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$$\frac{((2xh+h^2)-h)}{h^2-2h+4}$$

obsidian monolithBOT
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Omega Warrior

round hemlock
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wait

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I DID IT WRONG AGAIN

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AAAAAAAAAAAAAAAAAAA NOTATION SUCKS

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anyway

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$$\frac{((x^2+2xh+h^2)-(x+h)+4)-(x^2-x+4)}{h^2-h+4}$$

obsidian monolithBOT
#

Omega Warrior

obtuse dagger
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I think you are miscalculaing the denominator. It's just h, remember ?

round hemlock
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ohhhhh

obtuse dagger
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Lol!

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It's ok, though

round hemlock
#

my brain is slightly dead from doing fundamental theorems of integrals

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so sorry

obtuse dagger
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It's aww

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it's all good dude

round hemlock
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$$\frac{((x^2+2xh+h^2)-(x+h)+4)-(x^2-x+4)}{h}$$

obsidian monolithBOT
#

Omega Warrior

obtuse dagger
#

I will take a look at this problem tomorrow

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Don't sweat it

round hemlock
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$$\frac{((2xh+h^2)-h)}{h}$$

obsidian monolithBOT
#

Omega Warrior

round hemlock
#

and thus, 2x+h-1

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@obtuse dagger there solved it

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Sorry about that, I wasn't taking a good look at the problem

obtuse dagger
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Ha! You did 😏

round hemlock
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yep

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I should have written the problem down first, I wasn't looking at the question

obtuse dagger
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No worries! I can't believe I overlooked that

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lol

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Dude, thank you

round hemlock
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No problem

obtuse dagger
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I am going to bed now, though

round hemlock
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Oh

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gn

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I'm not going to bed until another 2 hours or so

obtuse dagger
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Have a goodnight and, try not to work too hard!

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Eesh!

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I can't unfortunately

round hemlock
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I'm most likely in a different timezone than you lol, so that's why

obtuse dagger
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Ahhh

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That may be it lol

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Either way, have a goodnight and thanks again!

round hemlock
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No problem and goodnight

short pilot
#

Trad: the right soports of the sides of a triangle are:...

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Find the a,b,c

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I tried to the distance but it didn't work

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What can i do to find the a,b and c

round hemlock
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where AB and AC intersect is Point A, where AB and BC intersect is Point B and where AC and BC intersect is Point C

short pilot
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Aaaaa

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Thank u

round hemlock
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no problem

short pilot
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I didn't think about do that

round hemlock
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@short pilot anything else?

short pilot
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Nope, thank u fr

round hemlock
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you're welcome 😄

quasi bolt
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hi, i have a question

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what is the next state of precalculus?

willow bear
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"next state"?

vapid plaza
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That would be postcalculus opencry

quasi bolt
late mica
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Calculus

gilded sapphire
static linden
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hello

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can someone help me its not precalucls

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but i couldnt have permission to send in chats

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<@&286206848099549185>

round hemlock
static linden
willow bear
static thistle
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@willow bear why is that a rule of something

willow bear
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what, the not giving out answers thing?

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yes, it's a rule on this server.

static thistle
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hmmm why tho it doesn’t seem ethical wrong

willow bear
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we are not chegg

static thistle
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well yeah of course this a improper forum board

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but what is ethically wrong with giving someone an answer that they want

round hemlock
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Unless like you say that 0.1x=90

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Idk

willow bear
willow bear
round hemlock