#precalculus
1 messages · Page 84 of 1
@rough leaf
yeah
,,f(x) =x^2
calvin
do you know about limits
yeah
do you know about limit definition of a derivative
2x
yes
yeah
yeah
oh
2(1) is 2 right
yeah
yeah
yes
that’s js 2x+6
yeah so the x value
mhm
my teacher always tells me to use $y-y_1 = m(x-x_1)$ when finding linear equations
calvin
calvin
it’s simply easier
why is this in a pre calc course
so your gonna get y-4=8(x-1)?
yes
myf i’ll remove it afterwards
oh
no no i’m asking why is this in your course/lesson plan
thag wasnt even that bad
it’s not
someone was doing it
if it’s pre calc and it isn’t the end of the year
ohh okay
i’m an alg 2 student
why do you know calc in alg 1
Use y=mx+b
idk i self taught it
it’s the same thing
same thing
Formula is c=b
y9 2026
i’m tryna do this tn
i’m in geometry
rn*
what does this mean
same thing just y intercept
Cool
im in grade 9 in 2026
geometry anf alg2
What about b=c=C/B
wait so 8th gr rn?
australian school years start in february
oh
bro what 😭
ohh
wait
what is this
It’s from Ax+By=C
m=-A/B and b=c=C/B
i’m in y9 roo
where did this come from
but why
these equations are the same [\begin{align*} y&=mx+b \ &= mx+c \end{align*}]
it’s js a diff variable
calvin
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
same equation
Solving slope from standard form
yo in algebra 1 and 2 memorize difference of squares and factoring
bro alg 2 isn’t that deep
it’s lwk easy
so far in calc bc you need to have difference of squares and how to factor memorized to your core
wat is bro solving for
y
i memorised that shit before i self taught calv
calc
Cuz this formula
wait
what are you doing in alg
or whag have you done
me too it was big in pre calc
last yewr
idk my school just did algebra
yeah
alg 1 or 2?
worst unit oat btw
REAL
i i think he in 2
i agree
Me?
my school hasnt done quadratics yet
yes
bro i have to lock in and grind out calc bc
i self tsught
I’m in Pre-calc
i’m lwk behjnd
did you do pre calc yet?
what does calc ab and bc entail
i self taught
oh up to what topics
methods units 12 in y11
calc ab is like calc 1 calc bc is like calc 2
then units 34 in y12
when i self taught i hit parametrics and mateicies
reg precalc
ok nice
and pre calc on khan
are matrices easy
not light but tedious
i never hit parametrics
they look really complicated
i did mattices
it’s also very easy currently because it’s very elementary operations
im doing combinatrics rn
js plug and chug
wow
why
some times
wait what are parametrics
i might’ve done
but it might be named diff
what unis are you guys tryna go to
a function bounded by time instead of x values
wait what grade areuou in
mit or harvard
university of michigan
hmm
geade 9
same as me then ig
yeah i didn’t do this
wait ru 15 or 14
never encountered
same
for example (t^2,2t-1/t)
i turned 14 a couple months back
interesting
me too
i’ve never done this
idk if its good enough for qt
bro i kinda hated the trig part of pre calc
trig is easy as shit
i learned that in a wrrk
week
like 6 months sho
ago
i finished the chapter
i bombed my pythag teat
yeah i did too but i hated solving sinsidoul equations
parametrics also have direction
test
did you learn sin and cos addition rules
that’s the easy part
that’s kinda important for calc sometimes
yeah never seen this
i dont think so
fairly simply
it’s like
sin(a+b)=sinacosb+cosasinb
wait its like $\sin(\th) = \sin(180-\th)$
things like this
calvin
rhats diff
i shld prolly lock in
me too
i’ll prolly grt some calc done tmtw in english class
it’s good for when you have the definition of a derivative and need to find the derivative of a trig function
combi is really annoying but im really eager to learn it
what grade ru in
interesting
yo
thanks
i’ve always wondered the proof for the derivative of sin of x
i was too lazy to do it myself
yup it’s that
i went to the 3rd derivative
it goes sin cos -sin - cos
wait
does this mean that
,,f^{(n)}(x) =\lim_{h\to0} \frac{f^{(n-1)}(x+h) -f^{(n-1)}(x)}{h}
calvin
i think
nah you got that
they reject geniuses bro 🥀
gcses are deadass easy i could lowk ace them if i cbf to learn stats
i’m lwk doing ap stats bext year
okay thays not bombing the test
i lost 2 markssasss
wait what even is stats
then
for the other mark everyone lost one
cuz wr had to be “practical “
graphs data and plots
means medians and estimates
really pisses me off
oh
i know i know
do ap calc bc
all my tests r out of ≈35-40 marks
i am
so 1 mark lost is crucial
also for parametric this is how it shows direction (as time increases)
and ap csa
interesting
you can graph movement of anything really then you can differentiate a parametric to get its rate of change at any point, seems really applicable in real life
😭
i have a mid term tmtw too✌️
rip
gl
i’ve done exactly
damm yeh you shld go to bed
zero minutes of practice for it
it’s a writing mid term in french and idek what we gonna write abr so how is mans supposed to prepare
i got 76% hwk completion in french
we find out what we gonna write abt 2 minutes before we do
bro i’m lwk locked in on french
or i was
i got the french award at my old school
i wish my school had latin
mine doesnt even have japanese or german
at least i can take ap french
i think mine might have japanese
not german tho
i hate it✌️
not gonna take it in y12
i’m js decent at it
i’m gonna cuz i need thay ap credit
yk what ap is right
?
how does the american system work
like a harder version of class right
yh
COLLEGE??
yeah
alr show me your ap maths stuff
when i get there sure😭✌️
you gotta wait till september
if i had an energy left
thid doesnt seen
seem*
THAT bad
to attempt
and do
I assume z=(a+bi)
idk
Wait
Is that you showed me the remainder theorem
Just do direct substitution
Okay
Though
It is divisible or it’s a root
Since it came out with 0
can you do this?
i’m looking at these problems
i could do them
ngl most of the ap stuff is much easier than college but some colleges will give u credit if u do well on the ap test
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
Do you know what the "One-to-One property" is?
No that’s why I’m confused
If you have a one-to-one (also known as injective) function $f$ with $f(x)=f(y)$, then $x=y$
Civil Service Pigeon
In this case, recall that exponentials $a^x$ with $a \neq 1$ and logarithmic functions are both one-to-one (or injective)
Civil Service Pigeon
So, for example, let's say we had $6^t=6^2$. Then, if we define $f$ to be the one-to-one function given by $f(x)=6^x$, then $f(t)=f(2) \implies t=2$.
Civil Service Pigeon
(the easiest way to convince yourself of this on an intuitive level is to just look at the graphs)
do you still need help?
Nah I got it
I might need help with this though
2 and 3 cuz I’m really confused how to do the whole thing
Don’t love this but the assumption is that $h$ is sufficiently small so that you don’t cross the domain boundary of $x=-1$. \ \
$f(x)$ is the result of inputting $x$ into $f$. So, $f(x+h)$ is the result of inputting $x+h$ into $f$. You can also think of this as replacing every $x$ in $f(x)$ with $f(x+h)$:
$$f(x)=x^2-2 \implies f(x+h)=(x+h)^2-2$$
Or you could do it as a piecewise based on whether $1+h$ is more or less than $1$ (which you’ll have to do for 3 anyway).
Civil Service Pigeon
not the sketching, vectors and parametrics
i can’t do that part either
it’s 3d vectors i think
i havent done those
i could do some of the imaginary bumber stuff tho
yh
i could do question 2 for 7 marks
what are the bases of precalculus
algebra, working with linear and quadratic equations
if you're not making dumb misconceptions like $(a + b)^2 \ne a^2 + b^2$ or $\frac{1}{x + y} = \frac{1}{x} + \frac{1}{y}$ you're on the right track
south
ok
help please
Rewrite using cos and sin
I guess not but its very useful in calculus
I havent exactly done it but i'm pretty sure u'll get an upper hand at math in general with this
Dont deep dive too much into it other than quadractic equations part tho
<@&268886789983436800>
This is only based on my jee exp
Soo
If ur aiming for olympaid ye go for it
Hey
how do I understand an integral
Which type
An integral is essentially just sum of
∫
huh
but sigma notations exist
no i know the integral symbol iwas just inquiring if there was a specific type you wanted to know like the ones below
What is that symbol where the sum and the integral are merged??
$\oint$, path integral around a closed path
south
Integration is u taking really thing parts and adding them up for a result u gotta do it by taking elements that are basically thr small parts as a function of x and integrate with respect to x
idk i got it from unicode
Itd basically taking really small things and adding them up a sigma notation wont work because the required element ur adding is really small
is this related to a riemann sum
I havent learned reimann sum and i understand intehrals fine
But yes its pretty corrolated
If ur doing jee i can send a video on understanding how to take elements
Very useful for phy
But in jee math irs just the anti derivative of a function
Thanks for letting me know a website where I can find it
Dang it, I don’t think it’s there either
Found info on it
👋
@modulators waver
curimouse
hi, whats up
(its a bot/compromised account)
oh rlly
ping was no worth tbf
weirdest type of bot id say. whats the point in just waving everywhere? unless the scam comes in if you reply or something
no that's a good thing to mod ping over
its to build a record of "legitimate activity"
modulators 💀
me too
whatd de precal
College and high school dual credit
oh
rhen you shpuld be seeing limits at the end of the year ish
like your last unit probably
GUYS OMFG
I NEED HELP I HAVE A PRECAL SUMMATIVE
TMRW
FUCK IM SO COOKED I HAVE NO IDEA WHATS GOING ON
can you show what you need help with?
i'll try
ok, what do you not understand ?
i understand kinda finding vertical asymtopes and i understand y-int
and the factoring is kinda annoying like
one sec
one sec let me do it on paper
the whole idea of all of this is that you can just take the 'biggest' terms in the numerator and denominator
for example, (x^5 + 2x^3) / (x^4 - x) behaves like x^5 / x^4
for x to infinity
wouldn’t that just be 3?
indeed
yeah, to 1/(x - 3)
like for this why was the gcf 4 and 4 and not 8 and 2
vertical asymptote to a function is just a line to a curve where y-> infinity or - infinity
,rotate
thats so cool ngl
oh yeah I should have typed ,rccw
-# rcw for clockwise
ahhh, okay so x^2 - 16 = x^2 - 4^2
that's a difference of two squares
the idea is that you can do $x^2 + 4x - 4x - 4^2$
south
which factors as $x(x + 4) + (-4)(x + 4) = (x - 4)(x + 4)$
south
so you need to find smth to cancel out with the denominator?
yeah
you just factored x^2 - 16 wrong
but your idea with cancelling out is spot-on
yeah you could expand it yourself and it doesn't give you the original back
okay and im also so confused on holes and slant asymptotes
or you could just do $a^2- b^2 = (a+b)(a-b)$ since $16 = 4^2$
would that work as well or woukd it be too complicated while solving?
scoob
oh south already mentioned it
yes it will
yeah this is really testing your algebraic skill
if you remember that x-intercepts are when y = 0 (this is why Quizlet / Anki can be really helpful for maths), then if you want to find (2x - 5) / (x + 3) = 0, basic algebra tells you that you can multiply both sides by (x + 3) to get 2x - 5 = 0
no worries!
just making an extra point in case you find you have more algebraic difficulties
experience will help in algebra
wpuld there be a hole at x=-4
or am i geeked
nvm
there’s an asymptote there
i think this goes in geometry
Ohhh ok thanks
highkirk
OKAY @topaz maple @willow skiff GOOD NEWS AND ABD BEWS
yeah?
bad bews
INDIDNT GET NY SCORE BACJ BUT IM GUESSING I DID BAD
dw
idk cause my schools ass
but at least like ny midterms are just for my ap classes
so ap bio and ap chem but theyre still hard yk
Gng i dont understand what they did for the second question
Where did 3x and 4y came from
Take the normal vector (6,8,0) and scale it down to the scalar multiple (3,4,0)
Then use this
Huh
D is constant?
I understand now but
It just used the value again
3x +4y
Where x is 3 and y is 4
Did they use it because the coordinates (3,4,0) are tangent of plane S
$3x+4y$ is constant (aka the same value) for \textit{all} points on the plane. This includes the point $(3,4,5)$, so they used this to find the value of said constant.
Civil Service Pigeon
Oh
(3,4,0) is used in this?
And (3,4,5) are taken from the question
(5)(0)=0 so the z coordinate doesn’t contribute anything
But they’re still technically using (3,4,5) and not (3,4,0)
Read what they wrote
I can do more questions happily now 😍
anyone got notes on the following topics:
Polynomial and Rational Functions (Combination of rational function) and Characteristics of Functions
this is for precalc culminating
Isn't there a bunch of material on this on the Internet?
yes
Okay show me plz I learned these before
Also inverses and boundedness
um im not saying the country but im grade 12😭
why 😭?
why do logs exist im gonna crashout
FUCK IM IN THAT UNIR ROO?
LOGARITHMIC SHIT AND STUFF
NO IM ACTUALLY GOING TO GO CRAZY
I do kinda get it
but I havent reached flow state yet…
I also kinda screwed myself
Im the buggest procrastinator ong
do you have finals coming up?
Me too
I’m also doing logs it’s easy
Logs is not easy what are you on about
real
Probably in the grand scheme of things but thats just what I find difficult to comprehend rn 🤷♀️ to each their own
Logarithm outputs exponents
..
Chat what is an asymptote
search it up and you'll know
👍
Practice mlre u'll get if
Small question
Actually
I realized it's not a small question at all
Im just going to google it
?
I wanted fo ask about partial-differential equations
I shant be of any help for i have not studied that dope shit
Whats the question
I'm looking for a study partner for probabilities any one in interested
Hi, I can see you've posted this message across multiple channels
Please don't -- that's spam. It's best to keep your message to just relevant channels
Maybe #probability-statistics would be relevant? If not, maybe ask in #math-discussion
ok sorry
Thank you for being understanding
who are you
haven't seen you
integration
For future reference, this belongs in #calculus, not #precalculus.
Also, when asking for help, please show what you've done so far - it gives us more context and saves time from explaining things unnecessarily. \ \
I'd do integration by parts here. Split the integral as:
$$\int \frac{\sec^2 x}{\sin^{2022} x} \dd{x}-\int \frac{2022}{\sin^{2022} x} \dd{x}$$
and do integration by parts on the first integral.
Civil Service Pigeon
it’s like a line the function bever touches
it gets really close
but doesn’t touch
i multiply num and den by sec^2022x , and sec^2 = 1 +tan^2 so for example sec^2022 , we can write as (sec^2)1011= (1+tan^2)1011 , tan =t , dt= sec^2
you cant integrate second part directly , its dx not cosxdx
whats pre calculus then ?
You should've gotten that one of the integrals from your integration by parts cancels with the second integral (also idt that the pythagorean identity is relevant here)
A preparation for calculus course
it's an american thing that's a grab bag of algebra review and random topics
i cant get that , sec^2 gives tanx , second integral has no tanx
Did you try writing $\tan x$ as $\frac{\sin x}{\cos x}$?
Civil Service Pigeon
where will the cos go ?
i meant second integral has no cos
Yeah that shouldn't be an issue because the cos x should cancel
which is why I'm asking you to show me what you have
i cant show , i am on pc rn
ah mb
yea its cancels out
we differentiate sin too
i took a longer approach ig

Js multiply by sin²⁰²²x
i see that differential approximation and tangent line are having relation with each others but i dont see it clearly, can someone help me understand deeper?
you can use a tangent line to make approximations
for example, suppose you’ve found the equation for the tangent line to y = sqrt(x) at x = 4
that equation is: y - 2 = 1/4 (x - 4)
now we can approximate the square root of numbers close to 4 using that tangent line
for example, to approximate sqrt(4.2), we can simply plug in x = 4.2 to the tangent line equation, to get y - 2 = 1/4 (4.2 - 4), that is y = 1/4(0.2) + 2 = 2.05
in actuality, sqrt(4.2) is 2.0493901…
and you can see the approximation is quite good
notably, this only works well (by hand) when you know a certain value exactly already and the one you want to approximate is close to that
Hey is this limits
sorta! limits allow us to define derivatives, and derivatives allow us to find equations of tangent lines
so in a roundabout way, yes
but typical limit calculation problems look different
can someone help me understand weeks 4 to 8?
btw can i ask another question, how do we come up with the tangent line equation, like we dont exactly know which line can cut the function right at one point lol, the equation sounds like derivative but idk why
it's a good question, indeed it's not obvious how to find it. That's exactly what the derivative in calculus is for!
there's actually a neat approach for the derivative of polynomials
say you have the cubic f(x) = x^3 - 2x^2 + 3x - 4
and you want this line, ax + b, to be tangent to the cubic at say, x = 1
then there must be a double root of (x^3 - 2x^2 + 3x - 4) - (ax + b) at x = 1
so that must be in the form (x - 1)^2 * (x - p)
so now compare coefficients of x^3 - 2x^2 + (3 - a)x + (-4 - b) with that form expanded, which is x^3 + (-p - 2)x^2 + (2p + 1)x - p
and you get -2 = -p - 2, 3 - a = 2p + 1, and -4 - b = -p
so find p and that allows you to find a, b
and hence the tangent line ax + b
that’s very cool!
yeah I've seen this technique before somewhere
thanks for the appreciation!
also it took a lot of effort to properly type out
you can read it in 1 minute but it took much longer to write
can somebody help me figure this out.. idk what to do after getting to (7x- ) (x+ )
what factors into 27 and gives -4 and 27x ?!?
If you want a straight answer you can put in the calculator. But if you want to solve this without the calculator you can probably start with finding the easiest which is -4 since it doesn't have a variable of x. So the possible multiplications are:
- -1 x 4 = -4
- 1 x -4 = -4
- 2 x -2 = -4
- -2 x 2 = -4
Now that we know the possibilities we can try to put it in the bracket thingy:
- (7x - 1)(x + 4) = 0
- (7x + 1)(x - 4) = 0
- (7x + 2)(x - 2) = 0
- (7x - 2)(x + 2) = 0
To know which one of these is the correct one, you could expand these four and compare it with the equation given. You should be able to find + 27x. My explanation might be complicated but I hope it helps. Mine is more about trial and error so it might be not that efficient
Thank you, i've figured it out to be x= 1/7 , x = -4 my issue was that i couldn't see when factoring earlier that 7x in (7x-1) (x+4) multiplied to give 28x - 1x giving me the 27x. this helped! thanks
You're welcome
Use ac method
Move -4
you forgot (7x - 4)(x + 1), (7x + 4)(x - 1) by the way
hey guys i have a new question
indeed if you write enough of them your brain should click onto 27 = 7 * 4 - 1
how would I solve this
x^2+27x-28=0
no, divide everything by 2
once you have x^2 + ... , you need to divide the coefficient of x by 2
then square it
Making it x^2+(9/2)x+ ? = -(1/2)+ ?
so x^2 + 9/2 x + 81/16 - 81/16 + 1/2 = 0
Yeah that one as well
x^2 + 9/2 x + 81/16 is a perfect square
oh not together? so it wouldnt be 9x/2 but (9/2)x??
same thing
I did x^2 + 9/2 x + 81/16= 81/16 -1/2
wutttt the
$\frac{9x}{2} = \frac{9}{2} x$
south
bro what in the worlddd
x^2 + 9/2 x + 81/16= 81/16 -1/2
this is arithmetic on fractions
say with numbers, $\frac{2 \cdot 3}{5} = \frac{2}{5} \cdot 3$
south
right that makes sense
you can think of it as 2 * 3 * 1/5 = 2 * 1/5 * 3
the order of multiplication does not matter
Factor
(x+9/4)^2 = 73/16
ah i guess i get it now, its just weird seeing it being written in different ways i guess, in my coursework the video has an easily divisible example by 2 so this 9x just threw me off
i will try to follow this video now ill be back
Yes
it's called completing the square for a good reason
okay nvm im lost already now what her example isnt helping me
how do i do (9/2x / 2 )^2
it's the coefficient of x
so (9/2 divided by 2) squared
Take the sqrt
sooo 13/2 squared?
here
no, you need to divide everything by 2 first
it only works when you have x^2 + ... = 0
yes, now you can complete the square
South
Ima do the work
Can you explain to her
So taking half of a fraction is multiplying by 1/2
why did we multiply 9/2 to 1/2? the 9/2 / 2 ?
righttt
yes
i think
dividing a fraction by a fraction multiply denominator with a 1 under to 9/2 right
yes, multiplying by 1/2 is the same as dividing by 2
yes so you multiply the denominators
$\frac{9/2}{2} = \frac{9}{2} \cdot \frac{1}{2} = \frac{9}{4}$
south
okay so now i have (9/4)^2
South can you explain this
Yea
oh that's messy
basically x^2 + 9/2 x = -1/2
x^2 + 9/2 x + 81/16 = -1/2 + 81/16
(x + 9/4)^2 = 73/16
Multiply by 8 on -1/2
Yes
If you are factoring you are taking its sqrt
Take sqrt of each side
Gets
im slowly deciphering where the numbers are coming from for 81/16
9/4 * 9/4 81/16
ok that makes sense
pause a minute to understand this:
divide 9/2 by 2 = 9/4
square 9/4 = 81/16
yeah
To x+9/4=+/- sqrt(73)/4
where does
taking sqrt
where does 8/8 come from on the right side
Common base
Is 16
2 x 8 gets to 16
from x^2 + 9/2 x + 81/16 = -1/2 + 81/16
you can write x^2 + 9/2 x + 81/16 = -8/16 + 81/16
fractions need to have the same denominator to be added
so then we multiply -1/2 by 8/8 for the right side
then what about the left side?
To continue its then x =(-9 +/- sqrt(73))/4 by subtracting 9/4
It has the GCF so don’t need to do anything
Their GCF is 16
the left side is a perfect square, (x + 9/4)^2
okay I think i get that part a little then
Yea
Practice practice practice
Go on TikTok or anywhere find these similar questions
And solve them
Are you solve more
You will get it
Eventually
That’s how I learn these
damn, may i ask if youre in college or higher education?
oh no wonder
it gets easier the more you practice
I'm at uni but any competent 9th grader will be able to explain it the way I did
LOL i never paid attention in math
this is like my first time again in math and doing it yk
thank you
how did 73/16 become 73/4
bcuz we took the square root?
wait what how did this happen
yes, take the square root of both sides
$x + \frac{9}{4} = \pm \sqrt{\frac{73}{16}}$
south
so 9/4 is normal but the only thing that changes about sqrt 73/16 is the denominator
when u take the sqrt?
yes, okay time for rules of exponents/roots
$\frac{\sqrt{73}}{\sqrt{16}} = \frac{\sqrt{73}}{4}$
south
𝑓(x)
ohh i didnt notice that 16 was also sqrt'ed
and then since they share the same denominator its just -9
Wow 🫠
yes, so very importantly, don't forget the plus-minus sign
so that actually means x + 9/4 = sqrt(73)/4
or x + 9/4 = -sqrt(73)/4
It’s 2 solutions
But I like to make it
every time you square root both sides, you need one plus-minus sign
x = (-9+sqrt(73)) / 4 or (-9 - sqrt(73)) / 4
but they write it like jake right, -9 +- sqrt 73 /4
say x^2 = 25
x = 5, but also x = -5
Order doesn’t matter
we can write $x^2 = 25 \implies x = \pm 5$ to mean both solutions at once
south
yeah
Okay thank you jake & south, I will definitely try to remember this
Yes
is ur completeing square question solved
?
i can help if it is not solved
@round geyser
Unrelated but is Stewart's Precalculus a good book?
Done
ok noice
Yea
hi
I GOT AN A ON MY PRE CAL TEST TODAY
IT WAS SUPER SUPER EASY BUT I STILL GOT AN A
Congratulations! Great job
Good job, really impressive
Anyone got good AP precalc resources or a textbook pdf?
Don't troll
Do troll ❤️
2x-4=0
(1)(2x-4)=0
<@&268886789983436800> the above comment is clearly off-topic
my precalc teacher made me do it💀
goofy ahh ciricullum
easiest class ever
but that was at like the beggiuning of the year but still
not really
its like everything in between alg 2 and calc
so liek trig conic sections limits vectors matrices
that kinda stuff
<@&268886789983436800>
is limits precalculus
yes
Does epsilon delta fall under precalc?
Is there a good way to remember radians (unit circle)?
it’s not “standard” for it, but I could imagine an ambitious teacher attempting to cover it
I crawled my way through trig without memorizing them, but then I hit polar coordinates.
Polar and rectangular
it’s recommended that you understand why 0, pi/2, pi, and 3pi/4 have the values they do, then you can always figure them out easily; then that you memorize the values for pi/6, pi/4, and pi/3 (the reason they have the values they do comes from special right triangles); then various values in other quadrants can be found from those ones by reflecting around the circle
I understand it, and the quadrants in which they are positive/negative (ASTC)
It's just how long it takes my brain to figure it out
sounds like you’re doing it right; you’ll likely get faster as you do more problems
I mean it depends for me
Not basics limits that need to be done using Taylor series are not precalculus
no, that's straight-up calculus
i js got them wirh practice
yes also i love your mirror man pfp
does integrals fall in precalculus
oh thanks

Just remember the first quadrant and subsequently put negative values and positive values respectively for cos and sin for each quadrant as it is. Like surely, x is -ve in the 2nd quadrant and y is +ve, so all values of cosine are negative, but not sine.
Also for -ve values just subtract from π/2
If less than π/2 ofc
And for greater than that, use π (obtuse) and 2π for reflex angles
Just remember π=180°
180/2=90=π/2
Yoooo can someone help me understand as to why certain quadrants have pi subtract or add reference angle?? Would appreciate it
I am reviewing for exam so like im tryna remember why that’s the case
Look
135° can be written as 90+45 right?
So 135 is just π/2 + π/4
which is 3π/4
So since the angle(x input) is in the 2nd quadrant, it's an obtuse angle
We can also write it as -π/4
As x is -ve in 2nd quadrant.
THAT is when we subtract -π/4 from π
As sin-x would be just -sinx
But to get proper values of other trig ratio we need such values by Adding or subtracting po
Pi
This is just my conception
It makes it ez for me to understand
Hope u find it helpful
Cheers @bleak jacinth
Ohhh that makes sense, tysm i appreciate the help!!
Happy to help
How would u solve this one
For the first one,y=2 and x is probs 1 (correct me if wrong)
No need
The bottom is just the log property of lo(a/b) = loga-logb