#precalculus

1 messages Β· Page 59 of 1

tawdry canopy
#

well yea

winter comet
#

desmos doesn't explicitly tell you about open holes

tawdry canopy
#

it is

winter comet
#

if you hover over tan(x) cos(x) it doesn't do that

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weird

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i guess it doesn't recognize there are open holes there πŸ’€

winter comet
tawdry canopy
#

cos(pi/2) = 0
tan(pi/2) = undefined

winter comet
tawdry canopy
#

why multiplying it equates to 1

winter comet
#

basically, it approaches 1 but doesn't equal 1

tawdry canopy
#

tan x = opp/adj
cos x = adj/hyp

(opp/adj)(adj/hyp)
opp/hyp
sin x

willow skiff
tawdry canopy
#

tried a bit of algebraic manipulation

tawdry canopy
willow skiff
#

exactly

tawdry canopy
#

well, idk

willow skiff
#

so your tan x would be undefined

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as you said, tan(pi/2) is undefined

tawdry canopy
#

maybe

willow skiff
#

you can't work with tan(pi/2) then

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but you can take the limit as Vicious Viper said

tawdry canopy
#

0 x 1/0
0/0
0^0

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idk

winter comet
willow skiff
#

as in $\lim_{x \to \pi/2} \cos(x) \tan(x) = \lim_{x \to \pi/2} \sin(x) = \sin(\pi/2) = 1$

willow skiff
obsidian monolithBOT
#

southlander!

tawdry canopy
#

use of manipulation

winter comet
#

outside of limit context, 0^0 i think is defined to be 1 πŸ’€

tawdry canopy
#

i understand now

tawdry canopy
#

if 0^0 is 1 or undefined

willow skiff
winter comet
willow skiff
#

you should:

  1. take the limit
  2. simplify the expression inside the limit
  3. now you should be able to sub in an x-value directly, if you did the right thing for 2)
tawdry canopy
#

yeah

willow skiff
#

to find the limiting value of something that is undefined

tawdry canopy
#

because desmos recognizes 0^0 as 1

willow skiff
#

you could also try 0^x as x approaches 0

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but yeah

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there's a very good reason why a lot of mathematicians define 0^0 = 1

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binomial theorem for instance

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and stuff to do with empty products

grand shard
#

everything outside of calculus says its 1 lol

tawdry canopy
#

jump discontinuity

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it equates on two values, 1 and 0

willow skiff
#

interesting

tawdry canopy
#

does limit of x^x as x approaches 0 exist?

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i dont understand anything

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like x/x = x^0, why x/x is undefined and x^0 is 1

winter comet
river drift
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x/x = x^0 for x β‰  0

tawdry canopy
jagged patrol
river drift
#

0/0 = 1??

jagged patrol
willow skiff
#

......

jagged patrol
#

0=a

river drift
#

that's a rule which holds for a β‰  0

jagged patrol
#

therefore 0/0=1

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dividing 0 elements into 0 sets means there is 1 element in each set

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well actually there could be 0 as well

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because 0 times 0 is also 0

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or 5

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because 0 times 5 is also 0

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maybe 0/0 should be considered undefined or indeterminate because any number satisfies 0/0=x because 0/0 (0)=x (0) 0=0x 0=0

willow skiff
#

like dividing an empty set is by definition undefined

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there's just nothing to divide

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as you probably know 0 is not the same thing as the empty set

jagged patrol
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i divided nothing and got nothing

willow skiff
jagged patrol
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but i got nothing not everythnig

willow skiff
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also I'm talking about partitions of an empty set

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that's not the same as dividing 0 by something

jagged patrol
#

ahh

wooden vapor
viscid thistle
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It's like one

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(It's one)

shadow summit
winter comet
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also they sometimes introduce limits in precalc

granite temple
mighty thistle
#

trig is screwing me

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got my unit exam tmrw, i got a good understanding of the graphing aspect (70-80% ish) but i got a 40% on my unit circle quiz

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I got like 90 min to study, what would u recommend i study?

willow skiff
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if you're not confident with the unit circle I'm pretty sure you're not confident with solving trig equations

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namely, that if sin(x) = k, then sin(pi - x) = k also, or that pi - x is the 2nd solution in a period

similarly, cos(x) = k implies cos(2pi - x) = k, so 2pi - x is the 2nd solution

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tan(x) = k is the easy one as there's only one solution per period

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this might be useful

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if you understand the unit circle, the sin reflection identity is across the y-axis
sin theta = y = height remains unchanged

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the cos reflection identity is across the x-axis
cos theta = x = width remains unchanged

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so don't memorise all these identities

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understand them by thinking about x and y on the unit circle, where things are the same

jagged patrol
jagged hedge
#

I'm cooked

potent salmon
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hii

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cab someone help me slove this with induction

ocean owl
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hello can someone help with complex analysis

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I need to calculate this by hand using residue theorem

ocean owl
#

ok thank you

undone shoal
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hey sorry guys, I cant get an answer in math-help, so posting here. Are the maximal elements {3,5} and the upper bounds as well? I dont really get it :/

formal bronze
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Did we divide the 6 by three?

undone shoal
formal bronze
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I assume the 4’s went bc of compensation but idk if it makes sense here

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Wait correct me if I’m wrong
But the 4 went with the 6, then he substracted the 4 with the 3= 1

tender cove
cloud steeple
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Hey

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How do i identify a graph that varied from sine or cosine

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Idk if this is sine or cosine

tidal horizon
#

It can be either since cosine is just a shifted sine graph

cloud steeple
tidal horizon
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Cosine starts at the peak of the wave while sine starts at zero. You can recreate that graph as either sine or cosine if you wanted to

#

Just by shifting it horizontally

cloud steeple
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Oh ok thanks

grave quartz
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I have a question. Can I manipulate both sides of an equation to prove a trig identity? Or would I have to make the more complicated side look like the less complicated side without changing the less complicated side?

uncut mulch
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most teachers frown on mixing sides

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you could get around that by doing stuff like

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given the goal is prove
a/b = c/d
starting with the left,
a/b =a/b * d/c * c/d
and simplify the bolded part to 1

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= rhs

grave quartz
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Ah, I see. Thank you so much!

jagged patrol
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-2

cloud escarp
#

Hi,
Im a high school student. Our school is conducting a maths club in which everyone has to submit a working model (it can be related to any topic in maths) so im a little confused about the working model so can anyone give me some suggestions for my project that would be really helpful i want to present my best at my max potential for this project.
Thanks

tall fractal
#

∫ (cosh^3(x) * sinh^2(x)) dx

willow skiff
obsidian monolithBOT
viscid thistle
#

he asked it in a helpchannel

willow skiff
willow skiff
#

okay

willow skiff
formal bronze
#

Can someone explain how the domain went past -2?

cloud steeple
#

Guys

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I need help with periodic functions

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Like
Sin
Cos
Tg
Csc
Sec
Cot

cloud steeple
placid lotus
tame pike
#

I’d like to receive support for this question

willow skiff
#

also you can Google what the equation will be

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"inverse of exponential function"

tame pike
#

Thanks

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I suppose I use log

willow skiff
#

log of the same base also

willow skiff
#

then reflecting them and joining the dots

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rather than trying to calculate log3 (x) for a bunch of different x values

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just saying

tame pike
#

Thank u for ur support

willow skiff
willow skiff
#

Anyways if you have it

cerulean holly
jovial hare
#

Os this actually a precslculus question

magic meteor
#

It's D

magic meteor
silent prism
silent prism
river drift
# magic meteor

completely random conclusion unrelated to anything else presented

fading monolith
# magic meteor

Not how complex log works on complex but ok. Its completely wrong anyway

viscid thistle
jolly pebble
viscid thistle
#

?

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i have no idea what complex logarithm is πŸ˜”

jolly pebble
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You can have it if you're brave enough

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But there are multiple possible values of it

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Because of periodicity with e^{ix}

river drift
#

,, \ln z = \ln(r e^{i\theta}) = \ln r + i\theta

obsidian monolithBOT
viscid thistle
#

i forgot we were in the complex plane πŸ’€

fading monolith
placid lotus
#

Sub in the values from the table

willow skiff
#

also why did you delete the image

#

I was going to say that the amplitude = (max - min)/2

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one of the variables gives you the amplitude directly

tame pike
tame pike
#

I just resent it

obsidian mortar
#

@rigid canopy

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See that area

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In orange

rigid canopy
#

yeah

obsidian mortar
obsidian monolithBOT
#

Luh Roub

obsidian mortar
#

Also if youre familiar with derivatives

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Integrals are the opposite

rigid canopy
#

so it calculates the orange part

dark thorn
# cerulean holly

This is a fun equation because it looks stupidly complex but all it is is algebra used in pre calc

viscid vine
#

can i solve it for you guys orrr

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do i wait

sharp nova
#

Here's one: e^5 = sqrt 2x

Would i just solve for e^5, then square them to get rid of the sqrt on 2x, then divide by 2?
making sure my math is mathing

winter comet
#

idk what u mean by "solve for e^5" but yes

sharp nova
#

Goes in the same realm as logarithms and such
I don't really know what it means but anything that is e with an exponent is solvable basically

winter comet
#

i think you're thinking of if there is a variable in the exponent

winter comet
sharp nova
#

Well, i know you can do stuff like this

sharp nova
# winter comet (e^5)^2 = e^10

I figured solve for e^5 which is a definite number, then i should be able to give both sides an exponent of 2 to get rid of the sqrt on the right side

#

ln sqrt 2x = 5 is the original equation, sorry

winter comet
sharp nova
#

Which i should be able to do by writing in expoential form?

winter comet
sharp nova
#

What is e^number used for in the world, anyhow? I don't even know what it is other than the. . . inverse of a natural logarithm, which is the . . . inverse of an exponential function?

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I think i have that right

sharp nova
#

roughly equivalent to 3.14, and is used in cirlces to determine area and diameter?

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That Pi?

winter comet
#

yup

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e is roughly equivalent to 2.71

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and uhh

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hmm

sharp nova
#

what was the eponential parent function again?

winter comet
sharp nova
#

I remember something about all expoentials sharing a coordinate

sharp nova
#

gimme a sec

sharp nova
#

lemme find my notes on it

winter comet
#

ok

sharp nova
#

I think the parent exponential function is f(x) = a^x?
And all exponential functions pass through (0,1) because a^0 is always 1
a is apparently the indicator for whether or not the function slopes upward or not

winter comet
#

yeah

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ah i see what u meant by sharing coordinate lol

sharp nova
#

The hell is a natural logaritm anyway?!?

winter comet
winter comet
#

see i would say e is useful for exponential growth but you dont necesarily need e you just need exponent lol

#

but its better to work with πŸ’€

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if you differentiate e^x you get e^x sotrue

winter comet
sharp nova
#

I'm not sure i'll ever understand what difference it makes
because if e^x = ln(x), which is another form of logarithms, and logarithms are inverse of f(x) = a^x, then wouldn't e^x be the same as f(x) = a^x?

#

But even then it still begs the question of practical usage

winter comet
#

πŸ’€

sharp nova
#

Doesn't sound familiar

winter comet
#

i really can't think something that specifically uses e without calculus

#

something that practically uses e and has to use e (like can't really bypass it)

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like exponential growth sure but you can just use f(x) = a^x

#

πŸ’€

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doesn't have to be a=e

winter comet
sharp nova
#

AH

winter comet
#

πŸ’€

white stump
winged pawn
#

How would I solve these problems

willow skiff
# winged pawn

are you familiar with the problem where you just have a rectangular grid?

#

if so, extend the figure in part a to a rectangular grid

#

count the number of ways which pass through the top right corner and the point below it
multiply by 2
then do total ways - previous answer

#

seems like you might need generating functions for the other two

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the other two are pretty insane

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or you know just count how many ways there are to get to each intersection point

cloud steeple
#

Help

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$\frac{sec(x)+csc(x)}{1+tan(x)}$

obsidian monolithBOT
#

Callisto(Moon)

cloud steeple
daring tapir
cloud steeple
#

Ok let me try

#

I got

$\frac{cos(x)}{cos(x)(sen(x)+cos(x))}+\frac{cos(x)}{sen(x)(sen(x)+cos(x))}$

obsidian monolithBOT
#

Callisto(Moon)

daring tapir
#

and see if stuff cancels out

cloud steeple
#

Om thanks

fiery mountain
unborn brook
#

Am I supposed to be punished for this

quiet pine
#

it looks like a magnetic field lol.

winter comet
#

pretty sure its just the unit circle πŸ’€

quiet pine
#

nuhnuh, i see those vectors going from one point to the next

winter comet
#

plus thats a dotted line not vectors

quiet pine
#

Nuhnauh nauhnuh nuh

#

πŸ‘€

vernal path
#

decibels/angle or sth

unborn brook
#

At least it was intended to be so

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The graph of the equation was actually a perfect circle

winter comet
cold nexus
#

Could someone explain to me why its -14 and not -13 because I'm pretty sure -34+21 is -13

obsidian monolithBOT
#

Result:

9.7027
terse pebble
#

9.7027 > 6.626 hence when you divide 6.626/9.7027 it’ll be < 1

cold nexus
terse pebble
#

i just explained it to you

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literally

terse pebble
#

,calc (6.626)/((1.67)(5.81))

obsidian monolithBOT
#

Result:

0.68290269718738
terse pebble
#

what we have is

#

0.683 x 10^(-13)

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but in scientific notation

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6.83 x 10^(-14)

cold nexus
#

Ohhh

#

I didn't even notice that

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Thx

hushed veldt
#

bruhh

#

this class some bs

shadow estuary
#

hi

jovial hare
#

Hi

winged pawn
willow skiff
#

for a it is possible and that is what I have suggested

winged pawn
#

im cooked for this lmao

#

they also said you can use binomial theorem for it

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which I have no clue how

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but i'll get it

willow skiff
#

it's not worth doing something super convoluted

winged pawn
rain flower
#

hey guys how i calculate this function f(x) = -xΒ² + 7x + 12 ? Cause the square root of delta is not exact

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my delta is = 97

willow skiff
#

,calc 7^2 - 4(-1)(12)

obsidian monolithBOT
#

Result:

97
willow skiff
#

the solution is just to leave the sqrt(97) as a square root

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don't try and write it as a decimal or it won't be exact

rain flower
#

okay

#

but

#

what now?

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x = -7 sqrt(97) / -2

rain flower
willow skiff
willow skiff
obsidian monolithBOT
willow skiff
#

you were missing the plusminus

rain flower
willow skiff
rain flower
#

ah okkkk

willow skiff
#

Β°
One of the greatest motivating forces for Donald Knuth when he began developing the original TeX system was to create something that allowed simple construction of mathematical formulae, while it looking professional when printed. The fact that he succeeded was most probably why TeX (and later on, LaTeX) became so popular within the scientific...

rain flower
#

now how i calculate this thing?

#

just stay there?

willow skiff
#

but we can still calculate those roots

rain flower
#

ok

willow skiff
#

,calc (-7 + sqrt(97))/-2

obsidian monolithBOT
#

Result:

-1.4244289008981
willow skiff
#

,calc (-7 - sqrt(97))/-2

obsidian monolithBOT
#

Result:

8.4244289008981
willow skiff
#

there

rain flower
#

wow

#

i think i made something wrong

willow skiff
#

,w -x^2 + 7x + 12 = 0

obsidian monolithBOT
rain flower
#

cause my book is tell me the answer is 3 or 4

willow skiff
#

are you sure it's not x^2 + 7x + 12 = 0

rain flower
#

'-'

willow skiff
#

yeah you wrote the question wrong

willow skiff
rain flower
#

yeah yeah

#

sorry about that

#

nvm

willow skiff
#

it's okay

#

at least you know the quadratic formula

rain flower
#

-xΒ² + 7x - 12

#

now is correct

willow skiff
#

ahhhhhhhhhhhh

#

okay yes x^2 - 7x + 12 = (x - 3)(x - 4)

#

ahh I see

willow skiff
rain flower
rain flower
#

yeah it worked

#

is just because of 12

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i accidentaly changed the sinal

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signal

#

idk

rain flower
#

it worked

willow skiff
#

no problemo!

covert galleon
#

hey lads just asking, i've been trying to find a book of excercises for Non-linear system of equations (i think thats what its called translated, the ones with more than two equations which equals a certain variable) (the ones that you learn in algebra), and for the life of me i cannot find them, anyone have a suggestion?

#

most books i've checked only has linear equations

summer ruin
#

there isn't such a book

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just search for algebra books instead

shadow hinge
#

Can u ask for help here?

willow skiff
shadow hinge
#

Alr then. Imma post my query

#

How would you solve:

willow skiff
#

sorry at x = 1 there is a removable discontinuity

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with the 2nd function, continuous at x = 0

shadow hinge
#

How would you prove that using continuity tests tho…

willow skiff
#

but also that the the limit equals the actual value of the function at the point

shadow hinge
#

So f(1) =-2

willow skiff
#

I assume they mean f(1) = 0

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even though the limit exists and equals -2

formal bronze
#

Can someone help me understand how the 2 became negative in this?

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The original question is h(x)=2x-xΒ²

jolly pebble
#

2*(-x)=(-2)*x=-2x

formal bronze
#

Ohhh so you just removed the functions and timed them together.. makes sense tysm

quick pagoda
#

is there any seperate # for calculus like differentiation or integration etc for jee mains or advanced level

jolly pebble
river drift
#

this server does not have channels dedicated to any particular examination

viscid ore
#

is anyone able to help me with this problem been struggling with it

covert galleon
winter comet
covert galleon
#

In thai it's translated as Nonlinear, maybe I wrote my explanation wrong
It's more of like
2equations with 2 unknowns

#

With 2 variables

winter comet
#

like
5x+4y = 6
4x + 3y = 2
this?

covert galleon
#

Yes

winter comet
#

that just a regular system of equations

#

linear

#

uhh

winter comet
covert galleon
#

I've looked at the book contents as well

winter comet
#

strange

covert galleon
#

I've went from JEE exercises to God knows what

winter comet
#

i feel like the majority if not all algebra books should have it...

covert galleon
#

I've accidentally stumbled upon PDEs on my search

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And ODEs

#

Fun topic

winter comet
#

πŸ’€

covert galleon
covert galleon
#

I mean we have them in thai, but it only contains like 60ish questions

#

Actually I have the PDF why don't I just send it bruh

#

Here something like this

split hound
#

can someone help me please?

viscid thistle
viscid thistle
#

No calculus channel available to me so I'll put it here

#

The function p represents the profit per item sold, where x is price sold for, a is the production cost, and y is the profit per item
p(x)=x-a
The function c is used to model the amount of customers and how the amount of customers decays as the price increases, where x is price the item is sold for, b is the total market, and m is the percent decay per dollar of price increased, and y is the amount of customers.
c(x)= bm^x
Given these variables, when, in terms of the given variables, will the total profit be maximized

obsidian pewter
#

The next key point is pi/4, 0

lusty phoenix
#

I have a question, after we find possible zeros of a polynomial function with [p/q] , do we have a choice of using synthetic or long division to find the rest of the real zeros or only one can work?

obsidian pewter
#

Use synthetic division for all your zeroes and check - if one works, use the quotient to do synthetic division

lusty phoenix
#

like this for example

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do we have a choice of using long division if we dont wanna do synthetic?

obsidian pewter
#

But synthetic is faster

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IMO

lusty phoenix
#

I see

#

thank you

viscid thistle
#

Lowk long division my opp

obsidian pewter
viscid thistle
#

Takes up half the paper, and is weird

left cave
#

guys can someone tell how to cover parabola, ellipse and hyperbola in the least possible time 😭?

viscid thistle
left cave
#

bruh wattπŸ˜₯

fading monolith
tender questBOT
rain flower
#

hey guys

#

i need help with this

#

Find the values of m for which the function f(x) = mxΒ² + (m + 1)x + (m + 1) has a double real root.

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my last answer was delta = -3m +1 -4mΒ² πŸ’€

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i'm not expert in math but i think was is not right

#

nvm guys

#

i find the answer lol

jagged patrol
viscid thistle
#

Does anyone know where x went? I know it took x as a common factor but in the beginning it had x^2, shouldnt x^1 remain?

willow skiff
#

yeah that's clearly a misprint

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,w (d/dx (cos 2x)/x^2) - (-2x sin(2x) - 2 cos(2x))/x^3

willow skiff
#

other than the misprint it's correct

viscid thistle
#

Thank you!!!

daring tapir
#

Sub the valuea

rugged flame
#

how do i start out with calculus. Like i know limits and stuff. Trigonometry is done, im good with algebra and graphs

willow skiff
# rugged flame how do i start out with calculus. Like i know limits and stuff. Trigonometry is ...
#

yes then you should start by learning the rules for differentiation

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sum rule and constant multiple rule

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then product rule, quotient rule, and chain rule

rugged flame
willow skiff
rugged flame
#

THANKS! I NEEDED THAT

willow skiff
#

no worries!

rugged flame
#

where you from btw?

#

Australia ig

#

ur name is south and ur profile pic....

tame pike
#

How do I graph these log functions?

pulsar mason
tame pike
unborn brook
#

Why do we constrain k as such?

#

Is it to avoid repetition?

fading monolith
#

Yes

#

Consider the case k=n and see what happen

pseudo turret
#

anyone have any good recommendations for a good precalc textbook

willow skiff
#

or Axler's Precalculus

willow skiff
viscid thistle
obsidian pewter
#

But like the front of the AP Calc BC book is where I learned most of my precalc (the review portion)

hushed harness
#

pretty much brand new to logarithms right now and im lowkey lost at this part. I got up to here but dont know where to go next.

got cut out in the picture but the packet says to use the natural log

#

i have no idea if im even doing it right rn

tidal horizon
#

You applied the right rules but there is a step where you could have isolated x

#

And then if you wanted to, the denominator simplifies to ln(0.6) as well

willow skiff
#

alternatively, $5^{(\log_5 3)x} = 5^{x + 2}$

$(\log_5 3) x - x = 2 \implies x = \frac{2}{\log_5 3 - 1}$

obsidian monolithBOT
willow skiff
#

same thing by change of base rule

narrow basin
#

Could someone provide a correction? I'm unsure about my answer because my teacher said it was wrong.

river drift
#

it's correct. so it may be that your teacher wants you to justify it in some different way, in which case you would have to ask your teacher directly

narrow basin
#

I really appreciate it!

jagged patrol
buoyant shell
willow skiff
#

order of operations is super important

willow skiff
# buoyant shell

say you wouldn't think $\log_{16} 32 = \log \frac{32}{16} = \log 2$

when it's really $\frac{\log 32}{\log 16} = \frac{5 \log 2}{4 \log 2} = \frac{5}{4}$

obsidian monolithBOT
willow skiff
#

the biggest difference is that the first one is still a logarithm

#

when 16 and 32 are related by powers of 2 so you should have a fraction

buoyant shell
willow skiff
#

choose another answer choice and I'll tell you if it's right

buoyant shell
#

d

willow skiff
#

yeah it's D

buoyant shell
#

thanks

willow skiff
#

explanation for why above ^

#

nw!

buoyant shell
#

πŸ‘

formal bronze
#

Y’all how is this not one to one?
I understand from the graph of it bc of the horizontal line test, but still I can’t figure out how in the equation way

willow skiff
obsidian monolithBOT
willow skiff
#

you could also have $x_1 = -x_2$

obsidian monolithBOT
willow skiff
#

that's what they mean

formal bronze
#

@willow skiff Tysm

#

Apparently this is with x square’s I get it now, Ty again !

obsidian pewter
#

But like yeah most resources are free

#

The university of Waterloo also has most of its pre calculus courses online

ocean leaf
obsidian pewter
muted turret
#

Is this some high school or precalc channel or university precalc channel?

#

I am just wondering cause I may need help with sketching a trigonmetric wave

river drift
#

there isn't enough of a distinction between "high school precalc" and "university precalc" to have separate channels, so this covers both

muted turret
#

Ahh ic

obsidian pewter
#

Most precalc is taught in high school

mint pulsar
#

see , you can also solve it in 2 variables

radiant grove
#

I have given this sinus function: in the form f(x)=a*sin(bx+c)+d

I have to determine all the parameters:

a=1
c=0
d=0

I am stuck with b . I cant figure out. how long the funtion takes for one cycle. anyone got an idea?

lapis gull
#

after you get that value you get the answer

#

here sin is one at pi/4 so its reaching its peak at half the x expected so b would be 2

hybrid crow
#

without b cycle cant be identified

balmy pebble
#

someone help me with

#

piecewise function

#

i dont get it

#

@cinder veldt

cloud pivot
#

hi

#

how would i do this without having a unit circle handy

#

or memorized

#

can i plug sin 1/2 into my calc to get these or what

winter comet
# cloud pivot can i plug sin 1/2 into my calc to get these or what

if sin(x) = 1/2, you know that one value of x = arcsin(1/2). Similarly, sin(x) passes 1/2 two times per period. not sure how you would do this part without the circle, but the other value per period is pi - arcsin(1/2). Anyway, then since sine has a period of 2pi, you know that the two solutions are x = arcsin(1/2) + 2pi n and x=pi-arcssin(1/2) + 2pi n for every value of n. But now I just realized most calculators will calculate arcsin(1/2) as an approximate answer instead of an exact answer in terms of pi.
honestly i would just try to know the unit circle bre πŸ˜”

cursive ocean
# cloud pivot can i plug sin 1/2 into my calc to get these or what

I think it’s best to memorize the unit circle tbh

Although scientific calculators have an inverse sin function, which can be used for finding x in that equation (for that question, calculator mode MUST be in Radians mode and not Degrees mode because the value in the given equation is not written in degrees ), the calculator is going to give an exact value in degrees for x, which is: 30. However, it will not give the other correct value , which is 150.

Which is why I think it’s best to know or memorize the unit circle because 30 is not the only answer for that question

cloud pivot
cursive ocean
cloud pivot
#

i heard it was a good dea to memorize it

#

but i never took it seriously LOL i see why i should have now

olive phoenix
#

YO

#

can someone help me with my study guide and walk me throug hit

unborn brook
#

Is the only way to prove this identity is to assume it is true and then combine the two to see if they undo each other?

#

Plus what is that kind of proof called?

river drift
#

define $f \circ g \circ \ell = h$ then by definition $h^{-1}$ is the function such that $(h \circ h^{-1})(x) = (h^{-1} \circ h)(x) = x$

obsidian monolithBOT
river drift
#

so to prove that h^{-1} is given by a certain formula you just need to show the formula follows that definition

feral bear
#

help me please number 7

chilly fern
#

Imma be taking this class during my winter semester, what do you guys think i should have do to prepare myself for the class?

lunar kraken
#

hey'

#

could anyone help me with continuous fourier series and transforms?

#

i kind off have my test

modern valve
lunar kraken
#

thank u

lapis dove
#

then you wont struggle with bad grades if thats what your worried abut

chilly fern
#

I dont want anything lower than a B

lapis dove
#

What grade are you in

#

Won’t matter if it’s senior, although you being here means most likely your not a senior

viscid thistle
lapis dove
tawdry canopy
sharp nova
#

I don't remember how to solve this, but i remember it being very simple

#

seems like it was something like . . . I(20) = x?

winter comet
lapis dove
#

I don’t really know however so I can’t be sure

sharp nova
#

I feel like this is just asking for the inverse.
Am i wrong?

winter comet
regal tulip
#

does anyone know this answer

#

is quite easy

#

very easy

winter comet
#

what about it?

fallow oak
#

so no

regal tulip
#

40
_

#

3

winter comet
#

40/3 yea

hallow imp
#

Since it's the inverse

willow skiff
obsidian monolithBOT
willow skiff
#

since I(x) is the number of ice cream cones, number of ice cream cones = 20

#

yeah this is confusing

#

easier would be to note that I(x) has:
input = number of dollars, output = number of cones

hence I^(-1) (x) has:
input = number of cones, output = number of dollars

#

number of dollars for 20 cones

jagged patrol
#

Oh yeah south explained it better

jagged patrol
#

Also @sharp nova important note f^-1 or f inverse β‰  (f)^-6

#

So if you have the function f(x)=x f(6) would equal 6

#

But f^-1(6) wouldn't be 6^-1 or 1/6

dim acorn
#

I have a question and I'm getting contradicting answers, idk if this is where I ask. However my dilemma is when performing the transformation g(x) = f(2(x+1)) would you shift to the left one or compress it first

sharp nova
#

HUH?
I didn't realize that this worked on logarithms as well

#

i thought it was just exponents with the same bases

jolly pebble
#

No one except yourself knows what the "this" you're referring to is

sharp nova
#

sorry, using the one-to-one property to solve for x in logarithmic equations

#

apparently if you just have two logarithms you can just. . . discount them from the rest of the equation?

#

and solve using just the arguments inside?

jolly pebble
#

Yes

sharp nova
#

I know you can do the same with exponents, an example being
3^2x-5 = 3^7+4
and rewrite as
2x-5 = 7+4

jolly pebble
#

This is because the logarithm is an injective function

#

I.e. it has an inverse

#

You can see it as raising the base of the logarithm to the power of either of the sides

jagged patrol
#

In the question

river drift
#

well exponents of the same bases and logarithms are inverse functions, so the fact that one is invertible implies the other

jagged patrol
shy folio
#

i need help understanding how f^-1(x) works on a graph

#

so i have a question which is "give the domain of g^-1(x)" and the graph that it gives me is g(x)=2arcsin(x)

#

is the domain [-pi,pi]

river drift
#

the domain of the inverse function is the range of the original function

terse aspen
#

Can someone help me with this the simpliest way possible number 35

viscid thistle
obsidian monolithBOT
terse aspen
#

The conjugate okay thanks

terse aspen
viscid thistle
#

Busy rn sorry

terse aspen
#

Oh pk all good

south wave
#

How would I do 3c? How would I expand it ( the rhs) or...

willow skiff
#

Then try to factorise or something

sturdy hound
#

can someone help me, when im creating a piecewise function from an abs value function, how do i find the domains of the piecewise function

#

this is an example of what im talking about the yellow highlight part, how do i determine that part

#

because ive tried setting the piecewise in the same format greater than equal to/greater than/ lessthan equal to/less than to 0 but it doesnt work

willow skiff
obsidian monolithBOT
willow skiff
#

$x$ if $x \ge 0$ and $-x$ if $x < 0$

now replace $x \mapsto x - 3$, everywhere that $x$ appears

obsidian monolithBOT
sturdy hound
willow skiff
obsidian monolithBOT
willow skiff
#

that may be even more unintuitive

try choosing a positive x and a negative x to see how it works

#

np!

zinc matrix
#

help.

south wave
shut hazel
#

The question asks for 10 terms. Start with 2, 3 terms and see if you can find a pattern.

tropic hemlock
#

could anyone please help me with simple induction? i dont understand the last step in proving the IH and IG and where to sub them into the formula

tender questBOT
viscid thistle
#

Just substitute ri8

south wave
viscid thistle
#

yw 😊

onyx nacelle
#

hi, i need help with this math problem

#

i need to find the values of x in which that is correct

#

this is the answer btw

fading monolith
fading monolith
#

Which one?

onyx nacelle
#

for the quadratic one

#

oh wait yea

fading monolith
#

Definition

onyx nacelle
#

it cant be zero

fading monolith
#

Yep

onyx nacelle
#

and the same for the base aswell

#

it must be > 0, thank you

#

and can you help with number 9? We must find the smallest whole number for which that is true

#

i dont know what to do with the 2x - 3 in the log

solid shuttle
warped shuttle
#

Write a function named f which fofof(x) = x
f should be a reciprocal function [(ax+b)/(cx+d)]

anyone have an idea ?

onyx nacelle
#

and dont know what to do from there

onyx nacelle
#

yea?

solid shuttle
#

and then 4=log_2(16)

onyx nacelle
#

ohhh

#

so 2x-3 = 2

solid shuttle
#

2x-3<=16

#

by the way

#

mind that 2x-3>0

onyx nacelle
#

hmm something is wrong

#

im getting this as an answer

#

and we are trying to find the smallest whole number that is an answer to it

#

in this case its 5, but in the answers its 2

solid shuttle
onyx nacelle
# solid shuttle just solve 2x-3>0

oh my god when i flipped the 3 to the other side i wrote it as a nine πŸ€¦β€β™‚οΈπŸ€¦β€β™‚οΈπŸ€¦β€β™‚οΈ

#

im really sleepy, sorry

#

and is it possible that there are more than one logs with variables in them?

solid shuttle
onyx nacelle
#

yea but i can only derive that they must be > 0

#

and i dont think thats enough to solve it(?)

solid shuttle
onyx nacelle
#

ill just hope i dont come across such a thing, thank you so much though

inland ether
#

I could use some help with non right triangles

atomic linden
#

I'm gonna cry. I wanna skip Maths.

#

But I can't.

crisp bane
#

I've never got this concept but why is sum from k=1 to n of a_n =na_n

raven tundra
jolly pebble
#

I doubt the person you're replying to thinks math is as fun as you do.

raven tundra
#

Just gotta look in the right places

dusty palm
#

hello im having trouble with this study guide my teacher gave me im not sure what to do from here:

#

i took the natual log on both sides but an unsure how to simplify it from here

crisp bane
#

ln((125)^x) =xln(125) and ln(1/25) =ln(1)-ln(25)

#

By logarithmic properties

sturdy hound
# willow skiff np!

i ended up finding a solution that is easier for me, doing sign checks yay

sturdy hound
# dusty palm

i think before u take the natural log of both sides u should make both sides have the same base so i would simplify this to 5^3x = 5^-2

#

and then try simplifying from there

sturdy hound
dark cypress
#

ngl i personally would just use same base rules

#

also are there specific scenarios where you have to use ln?

#

if so please explain

#

would the answer to the question change based on me using ln and base log?

dark cypress
sturdy hound
#

ln is more simple for me imo

sturdy hound
dark cypress
#

why not just take log base 5 of each side?

dark cypress
sturdy hound
dark cypress
#

no

sturdy hound
#

if you take the log base 5 of each side u would still ahve to simplify it anyways

#

so why not just do it all in one step

dark cypress
#

whats difference between ln and log like when you use them, does it make a difference?

sturdy hound
#

hmm

#

idk im dumb

#

i just like ln cuz it doesn tshow the base i guess 😭

dark cypress
#

cuz thats sooo much easier

sturdy hound
#

"i think before u take the natural log of both sides u should make both sides have the same base so i would simplify this to 5^3x = 5^-2 "

#

thats what i said earlier

dark cypress
#

oh yea

#

you coulda just replied to it lmao

#

i have a test on all of this tommorow 😭

#

im deadass studying what a log is

#

am i cooked

#

wait

#

mods

sturdy hound
#

sorry i thought u were trying to learn

dark cypress
#

im sorry for swearring

#

mb mb guys

dark cypress
#

i got a 69 percent on my last quiz

sturdy hound
#

i have my math final tomorrow dont worry

dark cypress
#

failed but 1 point 😭

sturdy hound
#

im prettyh sure i was supposed to get 50% on my test but my teacher curved it so much it ended up as an 80%

#

cuz the teacher changed it from out of 80 to out of 40 points

#

πŸ’€

dark cypress
#

bro on a spanish test i lost 8/10 points and got a 100

sturdy hound
#

dang

dark cypress
#

she doesnt give ec and hates me too

#

πŸ’€

sturdy hound
#

oof

dark cypress
#

but its mb for sleeping in that class

dark cypress
#

on a physics test i got a 50 percent with extra credit πŸ’€

sturdy hound
#

i heard physics is realy hard

dark cypress
#

it is

#

especially as a freshman

#

πŸ’€

sturdy hound
#

FRESHMEN?

#

at my school juniors take physics

dark cypress
#

yea

sturdy hound
#

how are u taking physics as a freshman

dark cypress
#

im taking it as an ap too

sturdy hound
#

ok how

dark cypress
#

its mandatory

sturdy hound
#

so does everyoone learn physics early then?

dark cypress
#

yea

sturdy hound
#

oh thats odd

dark cypress
#

theres 48 people and all of us learn ap physics first

sturdy hound
#

i guess biology will be refreshing for u then

#

that is dumb

dark cypress
#

then ap chem then ap bio

#

idk bout seniros

sturdy hound
#

why do u learn all the aps first

dark cypress
sturdy hound
#

at my school u have to take the honors class first b4 taking the ap class

dark cypress
#

just as aps

#

its mandatory for me

#

i dont have a choice

sturdy hound
#

so for example freshman i took honors bio, next year i had ap bio and honors chem

dark cypress
#

what year you in?

sturdy hound
#

that sucks

dark cypress
#

sophmore?

sturdy hound
#

yes

dark cypress
#

damn

sturdy hound
#

what

dark cypress
#

you taking pre-calc?

sturdy hound
#

yeah

#

im assuming ur taking it too right

dark cypress
#

im tryna take bc and physics c (physics 1 with calc) by junior year (both ap)

dark cypress
sturdy hound
#

next year not sure if i wanna take ap calculus ab or bc

#

but i have an A- rn so..

dark cypress
#

depends i mean

#

bc is calc 1 and 2

sturdy hound
#

if i just worked harder i probably could have an A rn

dark cypress
#

but ab is just calc 1

#

bc is 2 college semesters of work

sturdy hound
#

oh so is bc just faster learning pace then

dark cypress
#

and harder too

#

if you take bc then you might be able to calc 3 (3d calc) if your school offers it

muted shore
#

bc doesnt cover all of calc 2

#

you should probably take a dc calc 2 class before doing calc 3 at school assuming no prior experience

sturdy hound
#

i think after ap calculus bc for us its multivariable calculus

dark cypress
#

no

#

its the same for everybody

sturdy hound
#

its different for us tho

#

im not sure if we take linear algebra or multivarialbe after bc but its one of those

dark cypress
#

idk bro

#

its your school

#

aight gotta lock in

#

ttyl some day in the future?

#

yea

#

for sure

sturdy hound
#

ok same lol

sturdy hound
#

im going to try to stay off discord for 2 hours challenge

#

cya

terse prism
#

What would base level precalculus look like?

digital mango
#

Limits derivatives is what im learning rn

winter comet
daring tapir
#

Not really preparations

winter comet
digital mango
#

I kinda thought that was review of alg 2

#

it was like linear and angular velocity

winter comet
terse prism
#

Oh ok

sturdy hound
#

wait this pdf doesnt work let me get a different one

#

here are screenshots i would really appreciate it if someone could find any more practice questions i can do liek these questions

viscid thistle
#

Does anyone know if the answer is a or C? Cus on chatgpt it says C but my question bank answer key says its A (but sometimes it puts the wrong answers to trick students on purpose)

rustic oasis
#

A is correct

obsidian monolithBOT
viscid thistle
#

time to use commands sotrue

tender questBOT
tender questBOT
# rustic oasis A is correct

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

viscid thistle
#

wait i didnt read the question

#

MB

#

sorry :P

rustic oasis
viscid thistle
#

sorry

rustic oasis
#

Ok so can u tell yr process if u are not confirmed with yr answer

versed mirage
#

Hello, i'm working on a demonstration right now, and i needed to use summations(not sure of the term) but i'm not sure on how it works with funtions(i'm using wikipedia and they don't develop much further than just that you can use them in summation)
Does anyone know where i could learn how to use summation with functions?
(Is this the right chat)

jolly pebble
#

I'm not sure what you mean by summation with functions

versed mirage
#

I'll try to take a screen shot of the thing

jolly pebble
#

Something like this: $\sum_{i=3} f(i)$?

obsidian monolithBOT
#

daniel

versed mirage
#

Yeah

#

Exactly

jolly pebble
#

So what is your issue?

versed mirage
#

I'm just wondering how do i write the rest, like after

jolly pebble
#

As in what it's equal?

versed mirage
#

Yeah

jolly pebble
#

That example I posted is just $f(3) + f(4) + f(5) + \dots$

obsidian monolithBOT
#

daniel

mystic shell
#

Hey uhh I need help understanding system of equations with and without substitution and process of elimination

#

In word problems

versed mirage
#

?

versed mirage
#

I meant more like in between those number,

jolly pebble
#

If it's from $k$ to $n$ it's $f(k)+f(k+1)+f(k+2)+\dots+f(n-1)+f(n)$

versed mirage
#

With like 2.3

obsidian monolithBOT
#

daniel

jolly pebble
#

It's always integers

versed mirage
#

Good to know

#

I'll need to find another way then, thanks for answering

warm cove
#

I studied so hard for my precalc test and this test I found it so easy it is geninually concerning for me as I don't usually find math a strong point for me

jolly pebble
#

How is it genuinely concerning that you're doing well

#

That's good

warm cove
jolly pebble
#

That's good

#

Keep improving πŸ‘

warm cove
main glacier
muted turret
#

Anyone have strategies for graphing these functions?

atomic linden
barren jewel
#

Let’s say I have a graph the says the f value that equals 1 and g value that equals 2

#

Let’s take (f+g)(x)

#

We can add the f and g values together

meager pilot
#

guys i know grade 6 to 8 maths geometry algebra and trigonometry form youtube should i start learning precalculus??

uncut mulch
#

yes

warm vector
muted turret
sturdy hound
# muted turret Anyone have strategies for graphing these functions?

look at the behavior of the graphs
for example g(x) has a larger negative value around the left of the graph, while f has a smaller value, and they both grow in size which means if you were to add them together the value would be large negative and then eventually grow to positive

sturdy hound
terse aspen
#

Hey if a function can algebraically be switched with the x and y and coefficients moved to the x side than is it a inverse thats all thete is to it?

summer ruin
#

inverse on what domain is a question worth considering

terse aspen
#

Nimber 14

quiet hornet
obsidian monolithBOT
terse aspen
#

🀯

quiet hornet
# obsidian monolith

the swimming pool is 8 feet longer than it is wide.
let w represent the width of the pool: the length of the pool is (w+8)

the pool is surrounded by a walkway of width four feet. the combined area of the pool and the walkway is 1280 ftΒ³
if the walkway has a width of 4 feet, then we can find its dimensions including the pool by adding 4*2 to the width and length of the pool, so the area of the walkway and pool combined are (w+8)(w+16).

set this equal to 1280 and solve
(w+8)(w+16) = 1280

#

wish i could draw...

terse aspen
quiet hornet
#

oh yeah

#

www

terse aspen
#

Wait im a dumbadd

#

Ss

quiet hornet
#

me too lol

terse aspen
#

Its 24 since the positive one and than just add to lengrh for length

#

Thats ok

raven tundra
sturdy hound
jagged patrol
obsidian monolithBOT
#

Couldn't find an attached image in the last 10 messages.

jagged patrol
#

,rccw

obsidian monolithBOT
jagged patrol
#

,rccw

obsidian monolithBOT
jagged patrol
#

,rccw

obsidian monolithBOT
jagged patrol
#

,rccw

obsidian monolithBOT
jagged patrol
#

perfect

unborn brook
#

Is it wise to leave the conic sections for calculus itself rather than taking it during precalculus?

#

I've just checked and seen that Stewart's book has a section for conic sections, which doesn't really contain something that the section from the precalculus book doesn't.

unborn brook
modern valve
unborn brook
#

Yep

modern valve
#

What's in the conic section part of your precalculus book

unborn brook
modern valve
#

I'd say it's probably up to you

#

it probably won't hurt if you skip it

unborn brook
# unborn brook

"Rotation of axis" confuses me though. I can't see it in the index of Stewart's

modern valve
#

Don't worry about it

unborn brook
#

So it's covered?

modern valve
#

It won't prevent you from learning calculus