#precalculus
1 messages Β· Page 54 of 1
aaaah yeah i get it now is the answer e^u
well yeah but remember you gotta sub u back in after and add C
xD
If I had access and time, I would check every single neuron in my brain when I am doing math and some other smart person, mathematician's neurons and compare both to find what wrong am I doing
this may sound the worst possible way, but it would be the best for me
because there's nothing else I can understand
yeah
you can understand more
i think the first step is understanding how to do the chain rule
rn
first step is, how to think
don't overthink it π
https://www.youtube.com/watch?v=HaHsqDjWMLU&ab_channel=TheOrganicChemistryTutor have you tried watching this video?
to be honest, my mind has given up understanding these things
I still will try if I can
maybe you could take a break and start again in like 30 minutes or somthing π
what application to use?
oh i just use the snip tool on my computer π
take picture of empty space and edit it lool
simplify logarithm
LOL
I don't know how to do that
at least you know how to do math
yes
Last year I didn't know how to do dunks, but from one moment to the next I developed a lot of love for dunks.
The final equation:-
a + b(log 7)/(log4) + 60(log14)/(log8) = 0
put any base of log
let's take 10 because i only know 10
yes
a + 0.84b + 60(0.84 + 0.3)/9 = 0
you have to find another equation to know the value of a and b
exact
integer values are asked
a + 0.84b + 68.4 = 0
a and b is 0
no
why
XDDDDDDDDDDD
a + 0.84b + 68.4 = 0
putting a & b = 0, 68.4 is not equal to 0
ok
0,-82 approx
a = 0;
b = -82
Is $$\lim_{x \to 0}\frac{\log_a(x+1)}{x}$$ the same with
wolly5114
$$\lim_{x \to 0}\frac{\ln(x+1)}{x}$$?
wolly5114
lim x->0 log_a(x+1)/x = lim x->0 ln(x+1)/ [x ln(a)]
i knwo the answers theyre
-20 and -40
but
im not sure how to
get them
you remember sec(x) = 1/cos(x)?
Ok
again, i'd just use the unit circle XD
Ok π
Iβm assuming thatβs the only option
more or less yeah
Iβm supposing that u use the method too
yeah i'd just use the unit circle
Likewise
Aye wassup @winter comet
i dont think you understand theyre trolling you lol
how are you calculating it with "unit of circle"
Each angle in the unit circle corresponds to the sin and cos value
lol
the unit circle is a better tool
the word unit there means it's radius is 1. makes measurements simple
fair lmao never learned that
so the hypotenuse is always 1.
so instead of sin x = o/h, you just have sin x = o/1 or just sin x = o
yeah i see now how itd be a better approach
and u able to deal with negative values
makes sense, cheers mate
it's fun
whats your major?
Taylor series is the best method generally imo
That or using complex numbers
Deriving identities became really easy with those two stuff
i agree with that part
guys how long would it take to master pre calc from 0?
Probably 6 months
r u trolling
I doubt so
Normal people take 12 years
(entering kindergarten to highschool)
taking pre calc in kindergarten lmao
i got an 760 on sat math section so i have everything else decently mastered
To master precalc from 0 means that you have to master everything before it
lets say i mastered everything before and have a good understanding of trig and a2
how do we solve this question?
At first sight I can say that tan(B-C) = (b-c)/(b+c) cot A/2 might work.
@quasi elbow That indeed works.
This it the thing.
i got the answer but i did not know about this thing
thank you
i think that would be my next topic, yes
got it, thank you.
This is the analogy.
yep that's it
Btw does your worksheet cover all of trigonometry?@quasi elbow
Including inverse trigonometry functions?
it's divided chapter-wise
Can you send it to me? It'd come in handy.
if you wanted me to share the worksheet(s) of inverse trigonometric functions, i can
well
a minute
Send the trig equations and sine cosine rule part too.
eh, how does that work though?
Only approved sites can be opened.
interesting
what are you guys majoring in?
computer science; what about you?
I'm in 11th grade, i intend to major in math.
Most people I know on discord are majoring in CS.
Seems pretty competitive.
it is but if you know what you are doing, it is also very easy
unlike math
but that is subjective, of course
Definitely easier to earn money with CS?
i mean
i do not know about that part honestly
do math majors make a lot of money?
does any major make a lot of money?
I guess they do.
it's okay, you will get there! just take it easy and remember: one thing at a time
for an exam
fair enough
i find the subject very, very vast though
I does depend on what you do as a math major.
But if you want to earn money you can.
yes
i never liked math though, it has always been my weakest subject
i just took it straight on my degree lmao
i try my best to. it's just many things which are obvious to other people are not obvious to me and then i am like is this problem fucking stupid or am i fucking stupid
turns out, it's me
but oh well
interestingly, we do not have that in our course
i mean we did have mathematics-I and mathematics-II but
Relatable.
that did not include trigonometry
i do not know why an exam for computer science has 60% math
but it is what it is
That's what you think.
It's hard for everybody.
That's a damn reality, and I have come to terms with it.
So should you.
practice later, regret now
also once you have regretted, you will hate it
rly?
"Fr fr no cap"
but maybe not forever
in that case, you have to move on quickly
and stand back on your feet
perchance for eternity,
you will have to move slowly like a snail
and sit down
and relax
why does this seem like a poetry section lol
might as well be unborn
+1
what would be the first step to solve such kind of questions?
guys, can you tell what are the missing details here
all about unit circle
weird question but is there anyone here who could just give me a bit of their time and explain some questions about calculus and maybe give me a better idea?
(basically asking for as hort free tutoring session cuz i don't understand π )
I would bring them to one side like sin x...> 0 and then try to write it as sin nx > 0
My first thoughts say that you can write it as sin 4x > 0 and then solve.
Ask in #calculus
This is literally precalculus.
got it, let me try
it works! thank you
Even better, you can divide both sides by (sin x cosx)^2
As a general tip, observe if dividing or multiplying xΒ² can help with the inequality at hand.
It can save some work.
ah yes that's simpler
got you
Btw your consistency is inspiring.
You are so negative towards your own self bruh.
try this
hes a mathematician, no?
yeah he was
About to start a 6-7h study marathon, no coffee, no energy drinks and be as productive as I imagine myself to be.
I'll be working on simple stuff: Law of sines and cosines. I'll be working on some trigonometric equations as well βοΈ
good luck
thx! π
Takes breaks as needed please!!
Definitely! I'm alternating 50 minutes activity/10 minutes breaks so that I can last long enough
I'll try this too next Sunday
Thanks for the idea
all that for laws cosin and sin is crazy
what did u get?
if I remember correctly, it was indeed sin(4x)
like the other person said
Is pre calc hard?
not really if you practice enough
Gotta take it next year πͺ
it wasnβt that bad imo
I would like some help with this problem if possible with finding the inverse
I keep getting this as an answer
but this is also the answer but am just confused on how 6 becomes the base even tho they are the same or whatever
,, x = \log_4(4^x) \textbf{ then } \frac{\log_4(4^x)}{\log_4(6)} \text{ then I guess a change of base was performed }
bacc (unhelpful)
so how would the change of base be performed because I'm just unsure on how we get to the base being 6 and whatnot
bacc (unhelpful)
okay I think I understand
how would you get
this
into this
I understand the chaning of x and Y but would I turn it back into a the b^x=y format and then solve it up
and then I would be able to get to this point
unless I'm confusing myself π
I'm pretty sure I'll understand it in moment
I got it thank you
haha
take a look at this again
yeah I was confused on how it got to that point but now I understand how it got to that point, but yes a change of base was performed on where 6 became the base and whatnot
ya
No ππ I'm actually doing a mega review of 4-5 modules. Law of sines and cosines are the new notions that I have in my workload today π
My people
thx bro, it help me a lot
Am I tripping or smth, where does this "i" come from?
faiyrose
they are assuming that the number inside the square root is negative
does calc ab count as pre uni?
yes
you might want to have the undergrad role to have access to the calculus channel n stuff
.
If we know the limit =0, how can we determine the value of n?
there are multiple values of n that could work
basically, n < 3
Why n<3?
cause you know how $\lim_{x \to 0} x = 0, \lim_{x \to 0} x^2 = 0$ and so on right
south's secret twin brother
so you need $x^{3 - n}$ to be $x^1, x^2 \cdots$
south's secret twin brother
I'm not sure if I understand but I feel n=3 also works
oh sht it's x^(4 - n), right
so n < 4
then you have a mistake cause you should have + o(x^5)
How is the degree of x in this o determined?
it's the next term
so you have x^4 / 3!
the next term would be x^5
no, it's the next higher power of the Taylor series of (x - sin x) x
np!
Is it possible to find its original equation if we only know the soln like this?
What level of math is this, my school goes on a # system (ex. Math 3) instead of calling it algebra 2 or precalc so Iβm curious
yes. it must be a solution of a quadratic equation
since that is two roots
idk either. What's the topic called
so how can we find the quadratic equation corresponding to this ?
the brute-force way is to expand $(x - (1 + i))(x - (1 - i))$
south's secret twin brother
over time though people realised that you just need the sum and product of the roots to write down the quadratic
cause $(x - a)(x - b) = x^2 - (a + b)x + (ab)$
south's secret twin brother
0_Χ
it could be a parametric equation
$y'' = -1 \cdot \left(\frac{d}{dx} (\frac{1}{\sin t}) \frac{dy}{dt} + \frac{1}{\sin t} \frac{d}{dx} (\frac{dy}{dt}) \right)$
there's like a million chain rules
south's secret twin brother
but basically d/dx = dt/dx * d/dt = 1/(dx/dt) * d/dt as mentioned before
that would be $\frac{1}{dx/dt} \cdot \frac{d}{dt} \frac{1}{\sin t}$
south's secret twin brother
Normal day at precalc channel when people just casually do calc π
ooh sorry I misread the channel's name, I'll delete it
You don't need to delete, tho. I am just saying
it happens all the damn time
I'm not surprised
I wanna solve conics
how did we get this step?
Write tan x/2 and cot x/2 in terms of sine and Cosine.
I recommend posting questions like these in #competition-math the next time
yeah but
oh wait
Try to add the two fractions
wow yeah that was a stupid question; i was thinking about something else
thank you still
How's it going people?
Everyone so serious.
i want to be able to read arabic
It's pretty easy
can u type in #chill ?
Let me add general to my channel list.
no, chill
wait, there's no general
only #discussion
but that channel is overcrowded
chill channel = #chill
Discussion 2 is quiet rn
Composite functions
in this question
here's my work:
how can I check which option is correct? I can see that it's not (1) but what after that
what would be the first step to solve this question
i can kind of see that here we can apply the formula used when two angles and included side is given
but i do not get how to
or maybe that's not what we're supposed to use here
law of sines says that sinA/a=sinB/b=sinC/c for any triangle, so if you're given additionally that cosA/a=cosB/b=cosC/c for this triangle, then what can we say about tan of the sides?
oh
um, i am not sure if this is correct but
do we put a= ksinA; b= ksinB; and c= ksinC?
ah
so cotA=cotB=cotC
got it
thank you!
yeah cot if you do cos/sin and tan if you do sin/cos but either way that can only be true if A=B=C so there's your answer
makes sense, thank you
np
Is the answer β3 units?
I guess it's easier this way
yeah
interesting. i am normally confused which formula to use where in this chapter
The law of cosines is gonna help in this one easily
yeah it makes sense
how did we get this?
also, bump
Since the angle is 90 it's a right angle triangle
Go from there
first calculate c and then the area and A
not really the best
what about you?
i have got a huge quiz tomorrow
and i am running on two hours of sleep and i have got classes for the next ten hours and then there's internal exams and then there's math and i feel super overwhelmed
i need to get my shit together lmao
i know
i just
i make a lot of stupid choices after 9 pm and them regret them the next day
and, database management system
also you didn't answer me
i am good, thank you for offering though! π»
Khan Academy
oookay ill look there first
CEO of Khan Academy
Genghis Khan
say what
why :(
why not
what part of the integration part is confusing π
JEE?
ye
who
you π
why
r u gona take it?
ye
i am good at other chapters
noice
i am leaving complex numbers and integration part
Broh Integration is important though
pretty scoring in advance
even if it is i know i am going to leave its questions
why waste the time in that
i have to just do 15 questions in maths
like it's gonna come in differential equations too. It's like differential equations are just to recall the integration.
i am doing the ones that i think i can nail
i feel like jee integration is more pain than just average integration π
fact
"more pain" is not enough to describe it xD
exactly
Well I feel you bro I hate this fkin chemistry as you hate the math. I just don't understand anything bruh.
you could be fine to take differential equations and do integration
and do horribly on JEE
(me, probably) as an example
π
agreed
i don't know a single thing about chemistry
Bruh it makes no sense man I literally don't know if I know the basics bruh
like maybe a bit about the periodic table and like neutrons/protons/electrons vaguely and thats about it π
i got a list of 11 chapters which have a high concentration and can give you upto 50 marks in maths
in jee
π
I bet trigonometry is not one of them
i started to just try to understand it
But you're gonna see trigonometry mixed with other chapters, mostly in integration and differential equations and derivatives
then sequence and series
trigo is easy for me
Nah it's not that easy bro, it's gonna blow your mind when you solve the questions purely from trigo
nothing is "that easy" on JEE π
true
i got a 95 in goc test that happened this sunday
but a 4 in comlex numbers
lmao?
I can tell it's reverse in my case
my physics and chemistry are good enough to get me above 90 percentile in both
but i have to manage my maths more
i feel like i am weak in organic chemistry so i focused too much on that and forgot maths
I gotta manage my physics and chemistry too bruh, it's like how do I do that man. It was my fault too. I messed up my organic in 11th grade.
I gotta give boards too and my writing skills are literally down to 0 after 10th
dude idk chemistry at all but then again im not taking the jee π
lol
yall actually screwed, im just theoretically screwed
i will try to unfuck my self
Fkin coaching, Imma stop going in there after 10 days cause they gonna complete the syllabus till 25. Going there isn't helping me at all
i take online on zoom so that saves me a lot of time
it is good too
Yea I guess but I gotta manage for boards and JEE in these 2 months, November and December. Gotta make a proper plan.
Our chemistry teacher is always like he is on weed or something, broh comes to class after having a cigarette and when he comes closer, his mouth smells like hell bruh
His face makes me sleepy all the time in class.
how is that even i allowed
Nah teachers are allowed to do that, out of like 50m away from the coaching
fuck the institute
Our maths teacher is the best we got till today. Broh it's like he knows each and every thing. He got 20-21 years of experience in that.
are you in 12th?
jee 2025?
lore accurate chem teacher
which institute
Well my maths teacher smokes too and with that he will put that gutka in his mouthπ
Lord
what jee does to a mf:
Aakash
Nah but I gotta tell you It's the best maths teacher we got in the Institute
that's good
Going down.
whats your avg mains score
everybody going through the same shi
I probably get about 130 and yea that's too bad.
oh
how to memorise periodic table fully?
mnemonics
mnemonics
beta maange car scooter baap raazi π
i get around 200s or 210s in mains, but thats pretty trash considering the expectations on me
Bruh even teachers don't remember that. Ours says that he just remembers it when he teaches inorganic chemistry.
Lol
Yea
f-block is mostly ignored
he li na ki rubina se friendship
until that chapter
Life status: π
[N]ewzealand [P]akistan (A)u(s)tralia (S)a(b) (B)h(i)kari (M)****(c)ho*
Lol
Well it was around 86 I guess.
ic
aw
My school was like gangster type bruh
which school
every indian school
tf
That's common nowadays
lmfaoo
Ughh
π
Yea
me when deleted message logs
That could've been a discussion for #chill
I'd be interested in learning about the exploits of your principal
Yea it but started with mathsβchemistryβlife statusβchill
wild
@viscid thistle try these, these are logical enough to remember
obviously you need to know hindi for this
Ayoo I tried this one and the calculation is going wild. I got the answer 2(β3 - 1)
Nah wait calculation is easy, I made it look big with extra steps TT
Try to simplify.
It's one of the "standard" modifications if you know what I mean
the bottom sines have their arguments quite symmetric
their differences gives pi/6, something you can evaluate
thats why they mult and divided by sin pi/6 = the numerator there
This allows you to use those expansion formulae
^^^
The numerator becomes $\sin{\left[\left(\frac{\pi}{4}+\frac{k\pi}{6}\right)-\left(\frac{\pi}{4}+(k-1)\frac{\pi}{6}\right)\right]}=\sin{\left(\frac{\pi}{4}+\frac{k\pi}{6}\right)}\cos{\left(\frac{\pi}{4}+(k-1)\frac{\pi}{6}\right)}-\sin{\left(\frac{\pi}{4}+(k-1)\frac{\pi}{6}\right)}\cos{\left(\frac{\pi}{4}+\frac{k\pi}{6}\right)}$
L moment
Dang I don't even know how to use Latex
welp works i guess
Ayoo it would be 0 then, edit it.
oh lmao
@sturdy canyon
Yea that's good
i will get back to it later, thank you
what happened here?
also, please do not give me the whole solution next time. I do not mean it in a bad way or anything -- i am just fairly new to it so I want to understand how things can work
but, thank you πΈ
unfortunately, i do not
but yeah it is kind of making sense now
Just plugged in values for k.
Kinda like rationalising in algebra.
Fudge you familiar with telescoping?
i have definitely heard of it
Yea I expanded the summation in a way to observe the pattern in which the terms get cancelled. As you can see the pattern there, there is a cancellation of terms from right to left and in this way you don't need to write the whole expansion to 13 terms.
In this way
It's called the telescoping method, it's like you have equipped a telescope to see the farther terms. Lol
Yea sorry for that I get excited with the trigonometry π
lmao that's fine
you do need to learn telescoping series though
its usually taught in this chapter
in a telescoping series you need to see how you can modify the summand in such a way that after subbing values for k or whatever variable you end up with cancelling terms
and one of those modifications if you see a fraction like this is
writing the numerator in terms of the difference of something in the denominator
This fraction modification method will be used in a more generalised way in Integration further down your math course
called Partial fractions
Take the following example:
$\sum\limits_{k=1}^{n}\left(\frac{1}{n(n+1)}\right)$
@sturdy canyon
Notice that the denominator is a product of some terms; this is a biiig hint that this is a telescoping series (obv this is not a general thing to rely on but you may as well try)
And that you need to use partial fractions
Notice that the difference of the terms on the bottom is $n+1-n=1$, which is exactly the numerator
@sturdy canyon
You would modify the summand like this
$\sum\limits_{k=1}^{n}\left(\frac{1}{n(n+1)}\right)=\sum\limits_{k=1}^{n}\left(\frac{(n+1)-n}{n(n+1)}\right)$
@sturdy canyon
Now, separate the fractions
$\sum\limits_{k=1}^{n}\left(\frac{(n+1)-n}{n(n+1)}\right)=\sum\limits_{k=1}^{n}\left(\frac{\cancel{(n+1)}}{n\cancel{(n+1)}}-\frac{\cancel{n}}{\cancel{n}(n+1)}\right)=\sum\limits_{k=1}^{n}\left(\frac{1}{n}-\frac{1}{n+1}\right)$
@sturdy canyon
Substitute integers for k and you'll notice that the terms start to cancel
that's a lot of information
real
i think i get it; i need to practice questions on it though to understand when to do what
but thank you so much! π»
yes
,w differentiate r(100-r^2)^(3/2) wrt r
,w solve for r: -4(r^2-25)\sqrt{100-r^2}
well do i take 10 or 5
,w differentiate -4(r^2-25)\sqrt{100-r^2}
whats this for?
idk much about differntiation
to check what values are the maximum and what are minimums
differentiating once and setting it to 0 gives you the points
where it is either max or min
differentiating it again and putting values will tell you which is max and which is min
so after differntiating it again i equate it to 0?
you would put the values you got before
aka 10 and 5
and check what it gives
,w differentiate -4(r^2-25)\sqrt{100-r^2} at r=5
,w differentiate -4(r^2-25)\sqrt{100-r^2} at r=10
ok so -ve value means maximum point
okay thanks @sturdy canyon
if that's what we're supposed to do here, that is
at the second last step subst y = 2s - x - z @quasi elbow
$\Delta\left[\frac{\cancel{2s-x-z}}{(s-x)(s-z)}\right]=y=\cancel{2s-x-z}$
would squaring work though or nah
yeah the next step is squaring
fair
@sturdy canyon
do it ye
Does "s" Here represent semi-perimeter?
update: my quiz got postponed and it is on november 21st now
So like is it given that x, y, and z are sides of a triangle?
yeah
They can be any real values though
yes
also yes
my bad
this should get you to: $\frac{1}{2}\left[(x+z)^2-y^2\right]=xz$
@sturdy canyon
question
and simplifying, $x^2+z^2=y^2$ which makes $\angle Y=90^\circ$
is there another way to solve this question? a shortcut, maybe?
@sturdy canyon
Β―_(γ)_/Β―
no idea tbh
Ayoo I will try this one, can u elaborate on what we have to prove.
And the given things.
tan(x/2)=x/(y+z)
Ok and what is given?
$\forall x,y,z\in\bR$, $x$, $y$ and $z$ are lengths of three sides of a triangle with the angles opposite to them $X$, $Y$, $Z$.
@sturdy canyon
tan(x/2)+tan(z/2)=2y/(x+y+z)
So is it tan(X/2) or tan(x/2) lol
X
i am sorry
after deducing that the given triangle is a right triangle you can proceed with the proof
Lol I was literally confused on this one.
yes, i got it. thank you!
Maybe you can try something like conditional trigonometry with condition
X + Y + Z = Ο.
I guess it will do somehow.
Y = X + Z here as well (after proving the above)
Hmm interesting. I should try it myself.
but would not that just make it more complicated
real
Oh I will try it once for sure π, gotta take the risk
i guess it'll be
But after some tea β
$\tan{\left(\frac{X+Y}{2}\right)}=\tan{\left(\frac{\pi}{2}-\frac{Z}{2}\right)}$
@sturdy canyon
doesn't seem like it'll go anywhere tbh
Hmmm it's worth a shot though, gotta satisfy myself
π€¨
Ayoo don't take it other way π
notty hora ke
I am curious whether this question can be solved that way.
bro is sus
someone help me plz π
!da2a
No need to ask βCan I askβ¦?β or βDoes anyone know aboutβ¦?ββitβs faster for everyone if you just ask your question! See https://dontasktoask.com/
oh ok cuz i posted my question in the helpers section but no one has responded. i need help with these
i think ive gotten the horizontal and vertical intercepts but the rest im not sure how to write them do u guys know the answer?
The intervals in which function would be increasing is where it's slope is positive
this i understand but when it comes to writing it how would i go about that?
like i could point it out but like do i just write 2 xβs? if that makes sense
like for the first part where its going up would it be (-inf, -1.5)?
I don't understand, are u asking for the notation of interval?
i think so yes
interval notation is just
[a, b] => all real numbers between a and b, including a and b
(a, b] => all real numbers between a and b, including b but excluding a
[a, b) => above, but including a and excluding b
(a, b) => all real numbers between a and b, excluding a and b
clearly a has to be < b
In the interval you gotta plug in those x co-ordinates
so its not like yk how it normally is with (x , y) for this case its (x1 , x2)?
like how the first x leads ti the second?
Like starting from left, the function is decreasing from (-inf, to where it slope becomes 0)
No it's the x co-ordinate only
you're mixing coordinate notation with intervals
its the same notation i get it but yes
oh ok i think i get that so now what about the intervals where concave up and down and the point of inflection how do u write those?
by "Intervals where Increasing/Decreasing" they mean you need to find such x1, x2 that f(x) is going to give greater/smaller values as you increase x1
the mnemonic i use is if it looks like a smiley face its concave up
For example the function f(x) = xΒ² is decreasing when the x varies from -inf to 0
So you would write "f(x) is decreasing in (-inf, 0]."
so in this case Concave up is [-3, 2]
ohh so like if im imagining kind of like a semi circle wether it be facing up or down?
yes
you have another concave up from 2 to 5
rest of the curves are down
Points of inflection are the places where the curve seems to "turn"
oh ok cool so then the point of inflection is just whenever i think it switches so that would be my closest estimate i think right?
thank u guys sm π its like 4 am rn i needa finish this quick i have 2 classes tmrw π
this is the last one
ou
tomorrow as in, today?
ill try thanks so much
,w area enclosed by f(x)=x^4-4x^2 and g(x)=5x^2
f
i wonder why is it taking the second word and not the first
,w area
,w area enclosed
,red balloons
in such type of questions, how do we know which option to choose to start from? like even though we know that it is a standard question, is there any way you could probably eliminate a couple options out?
with cot and tan its really not possible
with sin and cos you can eliminate out of range ones
why?
well like
i am sorry if that is a stupid question
How do I approach a quadratic inequality that is a fraction?
Give an example
Well you factorize.
I plug dominator and nominator separately in a quadratic formula but then I get 4 solutions and then I dont know what to do with 4 solutions
Upper one is factorisible as (x-5)(x+4)
Did you get any imaginary answers?
Nevermind
Nope, x1=4 x2=-5 and x1=5 x2=-4
The lower one is factorisible too
That's not how one does it
You factorize and cancel the terms, then use wavy curve.
Do you know what the wavy curve method is?
It's basically streamlined commonsense but...
Thats how our professor did it and then he just crossed equal sign on the first x solutions and then did a table with + and - and got a solution
Explain
Nope, I never really studied math before but since going to college I am like putting 90% of my focus only on math's cuz I really wanna understand it
If your professor did it then it must be right.
Lemme send a picture
Google wavy curve then
do you know how to solve inequalities like $\frac{x-a}{x-b}\leq 0$?
Ϊ―Ω Ϊ©Ψ§Ϊ©
Incomprehensible
I do not, I know how to solve a basic one
Yea my handwriting is really bad, lemme try to find a pic from someone else
You should start with these.
Ooh I already did a couple of those, normal ones
@quartz pagoda How quickly do you want an explanation?
I might try writing it if you can wait
I've learned how to do it from this guy
This algebra video provides a basic introduction into solving quadratic inequalities using a sign chart on a number line and expressing the solution as an inequality and using interval notation.
How To Solve Simple Quadratic Equations: https://www.youtube.com/watch?v=-KWsS2FZVTA
Solving Quadratic Equations By Factoring:
https://w...
I am in no hurry, I am just casually practicing maths
If the quadratic is factorisible you can do this.
That's probably what your professor did too, but I've not got a way of knowing.
The thing is, you examine where your expression flips signs
Thats it? That doesnt seem complicated at all
That's really it.
It's very uncommon to have polynomials with non rational zeros in such problems
But can you do this?
,rotate
But could we not like do it separetly, like x^2+x-20=0 then do quadratic formula, then x^2-x-20=0 and do formula for that separetly
Yeah but that's tedious
On the line?
The pic I sent?
Yea
No, it's good for all reals
Like why is 5 included
Oh, the expression can only flip signs at those points. Like if x > 5 no term in the expression is negative.
Then if x<5 only one term is negative, thus the whole expression is negative.
*but greater than 4
Then if x<4 but greater than -4 two terms are negative and the expression is positive on the whole.
And so on, I hope you get it.
Try $x^2-x-20 \leq 0$ alone.
Ϊ―Ω Ϊ©Ψ§Ϊ©
It'll help.
Hmm lemme try
Done?
Bcs it's less and including 0, both are included right?
Or 5 shouldnt be included?
Ϊ―Ω Ϊ©Ψ§Ϊ©
This will teach you something
So if its less than and equal to zero or greater than and equal to, that means both numbers are included right?
Unless they are in the denominator.
You might be a little explicit here because your professor might think that you are pretending to know the answer.
$(x-5)(x+4)\leq0$
@quartz pagoda
Ϊ―Ω Ϊ©Ψ§Ϊ©
You should write this step.
So now the only place where you may have a problem is when the expression has complex roots.
You can have roots in this? Jeezus
What exactly are you asking?
English isn't my first language.
Ooh mine neither hahaha, you said when the expression has complex roots I was just suprised it can get even more complicated because one of the problems we were doing in class took a whole ass page
When it has complex (imaginary) roots, meaning when you can't factorize the quadratic, what will you do then?
I am still on this a bit confused is there no solution cuz it says less or equal to zero but its all positive there is no negative on the line
Yep it has no solution.
Congrats
But how did you get that it has none?
Couldn't find an attached image in the last 10 messages.
You messed it up actually
Ooh I did where?
Ϊ―Ω Ϊ©Ψ§Ϊ©
I am a dumbass wow
But I'm surprised at how you did it afterwards
My dear JEE brother is this precalculus?
Jeeezus christ what the hell is this
Integration, calculus
It ain't that hard when you learn it.
Or you're prolly wondering at the question.
Nah I am just shocked at the imageπ€£
How are you pre university when you know all this stuff mate?
He's indian actually
So you need to know it there.
I am asking you hahahaha
It's taught here, though I can't do this particular question.
@quartz pagoda You better practice or your professor will eat and roast you.
Roast and eat
Oh dang wrong channel
Yeah actually it is.
But you should state your reasons.
Sketching a graph would help.
Tbh I havent sketched a graph for any inequality or equation
hi
i think its wrong
Yeeeeeeeep very much so hahahah
x-5<0 is x<5
You should.
Otherwise you'll probably commit suicide as your course progresses.
Like searching for the tallest building in the city? π€£
Probably.
how can we prove this?
what
Like ain't this beautiful?
i do not think so
Draw the full triangle with the incentre, if you want to do it geometrically.
I'll send something wait.
bro is mathsexual
hi limey, how have you been?
i have been fine :D hby
Nvm the picture quality is ass
i have been okay too, thank you x
i might just skip this proof lmao
Fr fr no cap
Noooo
also which grade book is it
Just write the root forms of cos a/2 etc
how low my level is
You'll probably get it that way too
why is there a turd in the corner
π
...
Apparently you turd has a weird texture, I bet it hurts you.
@quasi elbow You got the proof?
Emm did you die due to sleep deprivation?
Have I solved this correctly?
how do i do this https://discord.gg/math
wrong paste crap
i feel like i know how to do it but i think im doing it wrong
i got -4 , 0 for first table from left to right
and 5 and -11 for the next
im like plugging stuff in and stuff like
exactly
for n(x)=-3m(2x)+5
try x=0, 1, 2, 4
solving shouldnt be hard from there
How do I calc this
use kings rule and simplify
you will get the idea
Tysm
for future please place calculus problems in #calculus
someone explain the proving of sin a cos a + sin a cos a = 2 sin a + cos a im having a hardtime since theres 4 variable and after simplfying it appears to be 3 to me
Where are the 4 variables? I can only see one that is 'a'.
ig he trolling
he probably meant 4 trig functions
did you mean:
$$\sin\alpha\cos\alpha+\sin\alpha\cos\alpha=2\sin\alpha\cos\alpha=\sin2\alpha$$?
0_Χ
he's wearing eyeglasses
maybe the solution is to fix ur glasses 
Fun fact: I'm wearing glasses too 
cool fact
π€
jk more like π
fr
Is anyone intrested in helping me with maths ?