#precalculus
1 messages · Page 40 of 1
I am so confused 👁️ 👄👁️
about what?
The Graph
Inverse functions are flipped over the line y=x
The green graph is the inverse of what you’re trying to find
yep
And how do I find the inverse? (I’ve forgot some stuff in precalc)
Switch the x’s and y’s
what is it?
Sharp
that’s right
please i need help🙏
can you rewrite what is written?
integral (dx)/a+b(tanx)
How do I do b?
you need the consonant-vowel pattern to be CVCVCVC exactly
i.e. the consonants have to go in slots 1, 3, 5 and 7 while the vowels go in slots 2, 4 and 6
no other way to make them alternate
Yeah but how do I figure out how many ways there are to arrange them?
did you do part a
Yes and c
what was your answer for part a
5040
right, 7!
Yes
so it is almost the same here
you are arranging the consonants amongst themselves (there are 4 of them)
@hexed totem i sent the question
and also the vowels amongst themselves, independently of the consonants (there are 3 vowels)
Yeah so what do I do?
well how many ways are there to place the consonants
you are definitely able to answer me this
4?
4!
3!
144?
would have been better as a computation than as a value
4! * 3! is what i wanted to hear
but you are correct
Uh @willow bear ig the problem doesnt expect us to use all the letters or some shit then?
The answer key says 288
Yea well if it is 144 for c and then it has to be 144 for b too, the ans key is wrong
For question b
yeah the answer key seems wrong
Okay
for this problem in particular
Ann i have a question
Since you have the combinatorics role nd you said you are pursuing a masters,
I assume you are takin some combi courses
What do they tchr in combi at your level?
wrong time and place for that
Ahem ;-;
im tired and i dont want to answer this rn
Okyy thats fine
(n-1)! = n!-n so it is equla (2n!-n)/(n) I hope it is correct 🙂
isn't it equal = 2n!-1
Well nope
Well n!= n*(n-1)*....*2*1
n! = 123..*n
Yep
This one is confusing me
I tried everything and I just don’t even know how to do this
(x!*(x+1) + x!/x )/x! = x+1+1/x=x`2+x+1
The answer key says (x^2+x+1)/x
i have a quick question about partial fraction decomposition, and ill use this problem as an example:
(x^2 - x + 2) / (x^3 - 2x^2 + x)
why isn't A/x + B/(x-1) + C/(x-1) the correct form?
from what I understand, it should be written as A/x + B/(x-1) + C/(x-1)^2 but i dont really get why thats the case so if someone could explain thatd be nice
that's what happens generally when you have repeated factors
You can just combine the B and C terms if it were like that
Also the LCM of your denominators needs to be degree 3
I guess you should think of that term as (Px + Q)/(x - 1)^2
Where the deg of the numerator is one less than the denominator
Then Px + Q = R(x - 1) + S and it follows
curious: how do you claim not to know what n! means even though you were able to use factorials just fine in an earlier problem
yo can someone help solve these precal problems? https://docs.google.com/document/d/13z7_yAqtYYXr4tfzUpL8mGXVsKN9Eb1Qc2jIyXM7T2s/edit?usp=sharing
mb i think I forgot to change access
I mean they might have been taught a different notation? Or maybe no notation at all yet just expected to write it all out
kind of defeats the point of factorial
they answered my questions with the exclamation point notation
Oh shit lmao-
Idk we were formally told about the exclamation mark notations 2-3 hours after we began combi, it might be their first class too
But yea as ann pointed out this assumption of mine is wrong
combi?
Combinatorics
Welll all the "find the number of way.... " kinda thingies come under it for one
to put it somewhat tongue in cheek, combinatorics is the science of counting
namely that of calculating the cardinalities of finite sets
i can do that! 1, 2, 3, 4, 5, 6, jk XD
counting != enumerating the naturals in order
is it more theoretical than applicational?
XD
@daring tapir to answer your question from last night re: what is taught in uni-level combinatorics, the course im taking right now deals with certain combinatorial optimization problems (e.g. what's the highest number of subsets of {1, ..., n} you can make such that any two of them have intersection consisting of at least k elements)
i mean idk
you can apply basic combinatorics to find some probability shit
like if you're calculating card game probabilities
oh yeah thats true
of any variety
that reminds me, what are the applications of sequences and series (from calc 2)?
i'm kind of confused why it seems to be the prerequisite for a lot of higher math classes, at least at the colleges ive seen
cuz like i dont know when it even appears again
Damn that sounds insanely fun
i mean sequences of all kinds appear damn near everywhere
- if you're studying analysis you're gonna have to deal with limits in more exotic settings
and series are used a lot in numerical methods too, such as for calculating shit like e^x or sin(x) on computers
many calc 2 classes do a terrible job of actually teaching much in the way of substance for series and their motivations
*most
true
a lot
but maybe it's a bit unrealistic to give tons of sequence and series examples without going into analysis
Anyways you should know that the harmonic series exists and it diverges
so that you know that just cause a sequence tends to 0, the summation doesn't have to converge
And you should obviously know the geometric series by now
And maybe some other series would be cool to do series tricks on, like telescoping
but that wouldn't be in a remit of a normal calc course
I havent learned calculus yet but why does the secant disappear at the tangent? (we're learning calc)
disappear in what sense?
as in this is in geogebra or a similar graphing utility, and you're asking why the green line disappears if you drag the red point to coincide with the blue point? @late karma
Geogebra
Disappear algebraically i think
the slope of that thing is $\frac{f(a+h)-f(a)}{h}$, and if you take $h$ to be 0, then that fraction becomes $\frac{0}{0}$
|Ann⟩
since you are learning calculus: the \textbf{limit} of that fraction as $h$ goes to 0 is called the \textbf{derivative} of $f$ at $a$, written $f'(a)$.
|Ann⟩
Ohhh alr thanks
I was first confused while doing the question, but then I figured it out. In that question n! Just meant n(n-1)
n! does not mean n(n-1).
I wrote it as that and got the correct answer in the end
I just multiplied the expanded it and got n^2-1
And then I did the factoring after adding the other (n-1) with n^2-1.
And I did the same with the denominator
And I ended up getting the same answer as the textbook answer key
In a similar question like that, my teacher wrote n! As n(n-2)(n-1)! And in the denominator there was (n-2)!
though that is not what you did
you mean n(n-1) * (n-2)!.
and the (n-2)! cancelled out, yes.
but saying 'the n! meant n(n-1)' is just wrong
No I wrote it is that I meant to say
I did do that
In the question I sent, If I cancelled out the n(n-1) in the numerator and denominator. I was getting the wrong answer
I don’t understand these questions too well
Because the teacher made it an independent unit which meant she just gave us questions and we had to find out how to do them online
theres basically exactly one trick here and it is unfolding the factorial
like n! = n * (n-1)! = n(n-1) * (n-2)! = n(n-1)(n-2) * (n-3)! = ...
aside from this, it is just run of the mill fraction manipulation bullshit
you didnt say that you did that though
Well I got (n-1)(n+1)/(n-1)(n-1) and then I just cancelled
first, you cannot write fractions like this without putting parentheses around their numerators and denominators
second, already the first line looks wrong
Well that’s not how I wrote it on paper. I just don’t know how to make fractions on my phone
And even though you are saying it looks wrong, I still got the right answer so I don’t know
Maybe you could show me the correct way to do it? And then send me a picture
the original expression is $\frac{(n+1)! + (n-1)!}{n!}$, yes?
|Ann⟩
@golden cairn
Isn’t that what I did?
your first line reads to me as $\frac{n(n-1) + (n-1)!}{n(n-1) - (n-1)!}$
|Ann⟩
Yeah well I forgot to write the ! After n(n-1)
ok so you were sloppy and careless
Yeah
and in so doing downgraded your work from "correct" to "made a positive even number of mistakes and ended up at the right answer"
It was a mistake
I know even though it doesn’t change the answer I should have wrote it, I just forgot to.
Thanks, I was confused about that question but now I get it.
hii, anyone down to help me with part d? 😭
have you done c?
yes
show what you got for part c
missing parentheses around the whole thing & the 0 and 1 are positioned a bit weird, but ok.
you also did part b, right? if yes, show me what you got for part b.
@onyx dirge
your notation has several issues
but ok
notice that $6 - 3x^2 \sqrt{x^3+x} - \sqrt{x^3 + x} = 6 - (3x^2+1)\sqrt{x^3+x}$.
|Ann⟩
this means that you can (and should) integrate your function for d using your answer for part b, and also your knowledge of how to integrate the constant function 6.
ohh alright, I did not infact notice that.
What’s the answer to this?
I got (x+3)(x+2)/(x)(x+1)!
I don’t have an answer key for this question
I have a feeling it’s wrong
Or (x+3)(x+2)/x!
That is the correct simplification
Okay
Is this a level?
wdym?
for us students it's roughly analogous to ap classes
Analogous idk what that even means that’s how I know u good at maths 😭
it's calculus
analogous just means like relatable to or similar to
somehow good at english = good at math 😂 also yes cloud gud at math
Damn i wish I was good at either
Need to be good at maths cus i got an exam in like 1.5 weeks
what exam
I'm so confused
If 5 is the base of the exponent, and the resulting number is 5.25, how is the exponent equal to 1/4?
It's not $\log_5(5\tfrac14)$ -- it's $\log_5(5^{1/4})$.
Troposphere
Oh
The typography could be better, though..
Thanks
i haven't learned this. is $(x+n)!=(x+n)(x+(n-1))\dots$? or is there some other way to interpret this
syzygy
there might be a better way to write out what i mean lol it looks a bit weird
Yes.
okay thank you
(The factors continue all the way down to 1, of course, they don't stop at x or x+1).
does this assume that all numbers involved are natural numbers
Yes, the ! notation is generally used only for natural numbers.
okay thanks 😁
Once in a blue moon you may see it abused as
$$ \frac{(x+n)!}{x!} = (x+n)(x+n-1)\cdots(x+2)(x+1) $$
even if $x$ is not an integer, but that is not really standard.
Troposphere
I understand that a lot less lol I might be missing something
Well, suppose both $x$ and $n$ are natural numbers. Then,
$$ \frac{(x+n)!}{x!} = \frac{(x+n)(x+n-1)\cdots(x+1)x(x-1)\cdots 3\cdot 2\cdot 1}{x(x-1)\cdots3\cdot2\cdot1} $$
so all the factors in the denominators cancel out with the tail end of the numerator.
Troposphere
so this uses that idea and applies it to non-integers?
Yeah. It is, as I said, somewhat nonstandard.
Okay 👍
Is this right or am I tweaking
that looks right
hmm
I don’t remember much about this kinda stuff lmao but that does still look sus
would the Ws be replaced with Es?
how does your book define those
I think my answer sheet on the book is just wrong
nice lol
it happens lmao
especially in these “textbooks” that people just shit out on the daily
there are bound to be errors when they can’t be arsed to write solutions to everything
Public education 
Yeah unfortunately typos in questions are all too common
As long as you understand how to do it by resolving the x- and y-components of each vector, then finding the total x- and y-displacements
I wouldn't worry
hi! how can i calculate the domain of the function f(x)= sqrt(cosx -3sinx) ? thanks
hello, what have you tried?
or what do you think?
cosx-3sinx>=0
make it look like x-3y>=0
-3y>=-x
you will divide -
so the >= will change to <=
y <= x/3
sin<=cos/3
idk if i got it right but i tried.
i might be wrong
i think im wrong
idk
wait
im wrong
i remember now
cosx-3sinx>=0
cosx - 3sinx = 0
cosx = 3sinx
cosx/sinx = 3
cosx/sinx = cotx
cotx = 3
i still dont know if im right😂
someone help
this is what cosx - 3sinx looks like idk how you’re supposed to write the domain
cotx>=3
right cotx>= ty
w
then you write the domain based on cot-1(3)
the problem is probably sqrt(3)
the graph lol
its bouncing like free throw
First try to solve this question the method we shared here, and then try to solve your problem yourself!
._.
...bruh
oh maybe
nah bruh how you do that 💀
partial fraction decomposition doesn't work, it doesnt factor
u sub doesnt work
integration by parts doesnt seem like it would work
well actually lemme try
U can write x+1 as 1/2*(2x+4) - 1 and split it
Where did that answer come from😅😅😅😅😩😩😩😩
wha?
how does that do anything
tru
do u know how to do it
it looks like pain 💀
It might work to find a substitution that makes the denominator into u²+constant.
hmm
u=x+2?
OH
hmm
i dont think that worked
brep
theoretically, if you factored x^2 + 4x + 6 taking complex numbers into account and then did partial fraction decomposition could you get the answer
or would that not work
i'm not sure since its messing around with the imaginary plane lol
prob not
oh yeah and then u have integral of complex number that aint goin well 💀
nvm
that just doesnt make sense
After the substitution you'd have to split (u-1)/(u²+2) into u/(u²+2) and 1/(u²+2) and integrate each separately. The first is a further substitution t=u²; the second can be scaled to a well-known trigonometric solution.
ohh wait how do you integrate 1/(u^2 + 2) ?
do you do that weird inverse tan(x/a) thing?
isn't that a/(x^2 + a^2) tho
the derivative of inverse tan(x/a)
hm
The a in the numerator there is just a constant that you can lift out of the integral.
Why is y=log(x) the inverse of y=10^x?
It was briefly mentioned in class that logarithmic functions are inverses of exponential functions
what part of it do you not understand
like do you not understand why the inverse is an exponential function, or do you not understand where the 10 came from, or....what
Sorry. I don't understand why logarithmic functions are the inverse of exponential functions.
I feel like I'm pretty close to understanding.
"inverse of this exponential function" is pretty often how "logarithm" is defined.
I know how to set up a logarithm, and that log is used to find the exponent you have to raise a base to in order to get a specific value.
maybe this help?
Try it yourself.
i wrote it down and do not see how it help lel
cuz you can cheese the numerator into looking something like the derivative of the denominator by doing it that way
U must’ve done something wrong then because from there it’s just a u sub and arctan thing
?
Why is the denominator of the integral on the second line 2x+4?
because you have to multiply by du/(2x+4)
I think you split the integral incorrectly, should be
(x+2)/(x^2+4x+6) - 1/(x^2+4x+6)
I did that’s what u turn x+1 into
i don't see
Don see what?
why you would do that instead of (x+2)-1
cuz u can’t just change the numerator liek that
you...can?
x+1 = (x+2)-1
and then you can split it into two fractions
is 1/2 * (2x+4) - 1 different from that?
i mean you don't have to 😂 but that would be the idea
is ur method just the same or
yeh
if you know the generalized arctangent
derivative
which i should know better than i do
i memorized the regular arctangent but not the other one ;-;
I’ve never used the other one before lol
yeah
come to think of it i don't think i've really ever used the derivatives of any inverse trig functions besides tangent
derivatives or antiderivatives
lol
this channel is precalc btw
(In some places basic integrals are introduced in precalc tho)
this is based on the US precalc curriculum so I don't think it's introduced in precalc
and I don't think that integral is basic either
india moment where you learn differential geometry and graduate from harvard at the age of 6
lmao first of all, thats just objectively wrong, secondly i have heard of some precalc classes in the us touching basic integrals towards the end
yep i was being sarcastic lol
when the FUVK did (y) get added to derivatives
... what do you mean
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
Find the minimum value of "a" so that the equation can be solved
You need the RHS to be between -1 and 1 (end points included).
You should know why
What is RHS
Right-hand side (of the equation)
So i should solve inequality?
Alberto Z.
Which is equivalent to $$2a^2+5a-6\geq -1 \quad \wedge \quad 2a^2+5a-6\leq 1$$
Alberto Z.
How to unify the solutionz
Yes
you want the set of all values of a which satisfy both inequalities at the same time.
how do you get that from each inequality's solution set?
As i said before, i already solve the inequality
But what should i do next in this question
that's what im trying to have you reason out by yourself
you solved both inequalities. each one gave you a solution set, yes?
Idk man i am struggling here i gotta get good at this shit in like 2-3 weeks and i am losing my mind
I don’t remember but i think i saw a bunch of Ys in my text book
One sec ill check again
I think i am tweaking
They just added that shit and didnt explain anything
this looks like implicit differentiation to me
Oh my god, i watch some voices aboyr it yesterday, I didn’t understand shit. I am not looking forward to retrying
I did not know what on earth this is until like 10 seconds ago
but it seems like ur just assuming y is a function of x and differentiating both sides
then solving for y'
that is in fact exactly what is done
just has a fancy name
The slope of that line is 1
And when x = 2, y = 0, so you have y = x - 2
0 = 2 - 2
you're looking at the limit from the right-hand side
because for x>1 it's x-2 so RHL would be x-2?
Yah got it .Thanks for the help
npnp
the question itself was put here ;-; but yeh
at that point why even pretend its not calc ._.
Lmao tell the tchrs xD
😂
What if we move calc down to precalc and move RA down to calc
what if we move calc down to 5th grade
actually not a bad idea tho
😢
for 6th grade analysis ig
these 10 year olds need to understand Taylor series and integration techniques
whats LA and RA?
why not???
#linear-algebra and real analysis
They must numerically compute integrals without closed forms by hand
if they know y=mx+b they’re ready for linear algebra
ok sheesh i dont mean like being great at it but
being able to understand the concepts and how to do the problems
._.
They should teach 1729-dimensional fourier transform to kids for them to multiply numbers efficiently
just give the riemann zeta function to them and tell them it’s graded on accuracy
Just give the normal zeta function and let them make an analytical continuation
Guys I need some help I keep getting the wrong answer 😞
It’s on my pre calc final and highkey idk what I’m forgetting
ok
what is the question
i got the answer
but whats the question so i can know which answer they need
Why can the coefficiant of a logarithm be moved into the exponent of the number in a logarithm?
Like 2log(x) is equal to log(x²) right?
wait
yes
2 infront
goes back
to the power
x^2 yes
if its logx^2 it will be back to 2logx
yes, this corresponds to the exponent rule that [ (a^b)^c = a^{b \cdot c} ]
cloud
Hmm I figure maybe I don't understand why the all of the exponent rules work either
right
you have to know the rules
Everything you need to know about logarithims is covered in this free math video tutorial by Mario's Math Tutoring. We discuss:
0:25 What is a Log?
1:08 Changing from Log form to Exponential Form
4:09 Switching from Exponential Form to Logarithmic Form
5:47 Evaluating Logarithms
8:35 Graphing Logs
11:56 Properties of Logs
14:01 Expanding Logs
...
watch this video
what is the question
i dont know what they asking u to find
The inverse
oh
oh
And a 4 comes into the equation
is that cube on top
Yeah
do we have to do (y+1)(y+1)(y+1) correct and then times 2?
or nah
wait
nope
i understand
x = 2(y+1)^3
divide 2
x/2 = (y+1)^3
now you cube both side
i got cude root x/2 = y +1
and i got the y by itself
so y = cuberootx/2 - 1
Alr thank you :)
I somehow did this on my own before watching the video :D i am so fuckin proud
✅
Thanks g
precalculus chat really? I joined the wrong server. Even Missy can do that.
You shall be free to leave if you cannot abide the thought of someone being less advanced than you.
Who else thinks this dude doesn’t even know what ln is
(I mean he was probably joking considering his name being sheldon as in the sheldon from young sheldon he had his bachelors at like 15 iirc tho he is fictional)
you do realize there are more chats...
.
Everyone quick, go look up degenerate conics, this is interesting AF
degenerate convicts are cool 👍
💀
Also if two linear slopes intercept, are they tangent to each other?
no, i would think the tangent line of a straight linear line is the linear line itself
linear line 💀
wait
yes
sorry i misread what you said
lol
The only def of a tan is that you intercept once
they the same line so ye they tangent to each other technically
are you sure thats the official definition?
It would be undefined then, because it has to both match the slope and only hit once
if thats the definition
but its not undefined
so its probably not the correct definition
like
that definition works for curves, but not when you get to lines
i don't know what the definition of a tangent line is
but if you take the derivative you get the same slope, and it has to intersect the same point, so uh . . .
I think I commited a syntax error
I need a sanity check
$3\csc^2(x)-2\cot^2(x)-4=0 \
\implies 3\csc^2(x)-2\left(\csc^2(x)-1\right)=4 \
\implies 3\csc^2(x)-2\csc^2(x)=6 \
\implies csc^2(x)=6 \
\implies x=\asin(\frac{\sqrt{6}}{6}\
\text(vs) \
3\csc^2(x)-2\cot^2(x)-4=0 \
\implies \frac{3-2\cos^2(x)}{\sin^2(x)}=4\
\implies 3-2-2\sin^2(x)=4\sin^2(x)\
\implies 1=2\sin^2(x) \
\implies x=\pm\frac{\pi}{4}$
basically I get two different answer sets with $3\csc^2(x)-2\cot^2(x)-4=0$, where one is $x=\asin(\pm\frac{\sqrt{6}}{6})$ and the other is $x=\pm\frac{\pi}{4}$
GoldenPhoenix
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
GoldenPhoenix
and I'm not sure where things are going wrong here
if anyone wants to try decoding all that latex then that'd be helpful, as it shows my work
work shown:
\begin{gather*}
3\csc^2(x)-2\cot^2(x)-4=0 \\
\implies 3\csc^2(x)-2\left(\csc^2(x)-1\right)=4 \\
\implies 3\csc^2(x)-2\csc^2(x)=6 \\
\implies csc^2(x)=6 \\
\implies x=\arcsin(\frac{\sqrt{6}}{6})\\
\text(vs) \\
3\csc^2(x)-2\cot^2(x)-4=0 \\
\implies \frac{3-2\cos^2(x)}{\sin^2(x)}=4\\
\implies 3-2-2\sin^2(x)=4\sin^2(x)\\
\implies 1=2\sin^2(x) \\
\implies x=\pm\frac{\pi}{4}
\end{gather*}
cloud
arithmetic mistake on 2nd last line, should be 6 sin²(x)
actually it's arithmetic mistake on the third to last, it should be positive 2 because it's -2(1-sin^2)
which then explains the top as well
dangit
thanks
all units have order 2 dangit
wouldn't that just get you back to where you were?
oh wait i see
wait naw i dont see
yeah, and then in the first workings out I forgot that it's -2(csc^2-1) which then becomes positive 2
i mean its accidentally correct
lol
or like the result is
the bottom is correct in conclusion, I forgot a negative in the text but fixed it in the next line
yea
while I didn't notice it in the upper work
whats syn?
like cos^2(x)?
or you mean discord syntax
yeah
cos^2(x) = [cos(x)]^2
is correct syntax
both are
guys, what is the inverse of a function value absolute?
and with the same incomprehensible wording...
the preimage of f(x)=|x| is g(x)={x,-x} but it ain't a function.
?
why is not a function
because I'm slightly abusing notation, and it's not returning a single set, it's returning both a positive and negative value, i.e. each member of the domain is mapping to two members in the range
wait you're responding to something?
I thought you just said that for no reason
this thing
how is each member of the domain mapping to two members in the range
|-x| = |x|
f(x)=|x| goes from the reals to the non-negative reals, and maps two values to each real number
thus the preimage of f, f^-1(x) goes from the non-negative real numbers to the real numbers, and maps each number to its positive and negative values
pre-image means basically reading the function backwards(i.e. inverting it), and sometimes that makes it not a function anymore
|x|=3 implies that x∈{3,-3} (x is an element of {3,-3}, that is, x=3 or x=-3)
okay sure i get what you mean
but in response to his question, you can construct a piecewise definition of one
yes it's not a function, but that wasn't really his question right?
he asked for the inverse of a 'function value absolute' which I assumed (potentially poorly) was the absolute value function, thus I gave him the inverse relation, but I wanted to stress that it isn't a function in my response because at precalc and lower it's often assumed that the inverse of a function is a function.
Can someone explain how to solve these for me
Since my teacher won’t teach me it
😭🙏
,rotate 90
do you know how to draw these graphs?
you can draw all these 3 graphs tbh
and "erase"
the regions that are not of concern to you
every function has an inverse, they're only functions when the original is a bijection, otherwise they're relations.
Not really
It wasn’t something taught
anybody?
Can you describe in words what the function is?
I'm not able to start this question
Can somebody help?
Hello everyone, i am a maths helper, good with algebra, calculus and statistics. Kindly feel free to DM me incase you need tutoring. Thank you guys and have a nice learning experience
Thanks for offering
Can you please help with the question above?
i could be wrong, but if |x_0| < 1, then x_(n+1) is getting smaller, right?
wait
x0 might be positive too
It's not a guarantee
It might go both ways
Depends on the value of x0
well the least we know is sqrt(1-(x_0)^2) is a positive number less than 1, right
nope
Someone suggested me to substitute x0 for Cos2∅ as it formed an identity
But I couldn't take it from there.
nevermind
yeah i thought of that too idk what it would do though lol
hmm
Yes that's true don't doubt yourself for that
I have the same reaction when I tried
I literally thanked the guy for giving me some insight and ended up reaching nowhere lol
oh yeah its squared im dumb lol
😂
I think I should ask the same person again
XD
I'll message here when I get the approach
alr
wait but x_n has to be positive for n!= 0
I didn't get you?
if you plug in x_0, x_1 will be positive and less than 1
and all the x_n after that will have to be positive and less than 1
Yeah that's true
I get it now
But does that take us anywhere?
if you multiply a bunch of positive but less than 1 numbers
I'm really weird out by this now
It approachs zero
Yeah
That's a cool insight
then the limit has to approach 0, right?
too bad that aint an option
oh wait i meant infinity
the bottom approaches 0, then the limit approaches infinity
but the logic is flawed somewhere
lol
Not really it isn't necessary that a limit approaches infinity just like that
We have to check up the numerator a bit too
why not?
its a positive number less than 1, no?
yeah sum is wrong 💀
I think there's some flaw in our thinking
yeh
I've solved many limits that seem to tend infinity just 'cause they are 1/0 but when I manipulate, they really don't
Naah this is calc
But there isn't a channel for that here I guess
calc 2?
I idk that
oh there is
series calc?
I'm actually from India
We don't have those systems here
We just have math that has calc
does it use anything with sequences and series calc? like series expansions or smthn...
i don't really know what im asking cuz i don't fully understand that
lol
im just gonna keep assuming there is a way that we can get 💀
also there is a #calculus channel
fair 💀
It isn't there in the tabs shown to me though
Those really aren't much used in calc here
Like you're asking convergence, divergence ?
Or hear me out since it is an mcq just let, x_0 = 0
What the hell man 💀
You really talk like the character on your pfp
I literally heard that guy's voice in the sentence
You kinda can do that even tho it doesnt help xD
Anyhow post that in #calculus it has a much higher probability of getting answered there
i'm stil confused on why the answer is not infinity ;-;
Recursion's a bitch
💀
is this something i would know better if i understood calc 2 more ;-;
maybe for some reason the denominator doesnt converge to 0
💀
i dont see why it wouldnt tho 💀
Idk it shoud though
I mean wait
Guess we gotta ask so high
fr
Hm it probably is
💀 neon can probably also solve this rather easily but for that op gotta post in #calculus
what is calculus and precalculus
Troll spotted <@&268886789983436800>
What? Doesn't seem like a troll to me
difficult to say
precalculus is literally anything pretty much
oh ok
calculus includes limits, derivatives, and integrals
Uh okay then i guess
and different kind of applications to them
damn yeah idk what that is lol
you learn it in calculus
kk
or sometimes precalculus
It’s literally just graph the function idk what else to do 😭
a function takes an input value and returns an output value
you can use this information to plot points and try to draw the shape of the graph
or you can just know the shape originally, plot a few points and draw accordingingly
But the graphing looks really weird 😭
wait do you know what a piecewise function is?
No
oh, its a function that is composed of multiple functions on different intervals
that's why I asked. If you can't read what it's trying to do, then you can't graph it.
so on the interval -1 to 2, it could look like the graph of |x|, whereas on the interval of 3 to 5, it could look like the graph of 2x
so with ur piecewise function
Heres this 😭
do you see the three intervals?
notice how you have it cut into pieces?
do you see like 2x + 3 for x < -2
you need to find which graph puts the right shape piece on the right region
that means for all the values before -2, its the graph of 2x + 3
So I just use a graphing calculator or whatever
Ooooh okay
you don't need one for this, really, it's asking about rough shapes, especially when they gave you this. Things to check would be the endpoints of each interval, and where the graph should be increasing or decreasing
Okay
do you know the difference between the open and closed circles?
yep
Okay I got this 😼
The teachers never taught us what they actually mean
Unfortunately
😭
Or they like vaguely went over it
Because we only get a semester of pre calc, algebra 2 and 1, and calc and trig and calc3
when I say x<3, what does that mean?
X is less than 3
ok, now what about x__<__3
so in the first one, can x be 3?
No
so should a graph be able to touch 3 with that condition?
No
and what about the second one?
OOOOOOH THAT MAKES SENSE
The second one it can be touching 3
most math symbols and conventions are designed to show what they're trying to tell you. This is one of those cases
Cause it’s filled
yep!
That makes sense 😼
so I would look very closely at the conditions of the intervals and see how they compare to the endpoints on the graph
Hey @winter comet
I got that one
I can explain if you want
Please do
Honestly it wasn't a moment ago
Even when I knew that substitution
Well the cosine GP formula to the rescue
Now after substituting
We note that Sin2theta is 2SinthetaCostheta
One of the Costheta below cancels
Then the half angle formula again
And all the CosTheta like terms cancel
Leaving us with 2^n times Sin(Theta/2^n)
And as n goes to infinity Sintheta can be written as theta
Yea no i kinda just remembered that as a formula in itself so uea xD
Hmmm damn
Aaah it was too long to type ngl
I'm kinda new to doing math full time so I don't really know many such patterns
Now you know one more!
Yeah that's growth
I have one more integration question
Maybe I should post that directly to the calculus section now
Is the correct option d?
any advice on to reduce mistakes on math tests(one solution im gonna try is to get more sleep)
- get more sleep
- try not to make mistakes as you go, think through everything but don't go too slow cuz you gotta make sure you finish.
- if you have time, check you work, you can mark any areas you were unsure about as you go.
i do 2 and 3 but i still have so much mistakes
my grade is down atleast 10% just from mistakes
theres a reason people say just keep practicing 💀
just make sure everything makes logical sense
like you actually know what you're doing, not just going through the motions
i spend way to long practicing💀
maybe don't over-practice and get burnt out, but 💀
what do you make mistakes on btw?
what kind of mistakes
simple mistakes
could you give me an example?
arithmetic operations, swapping the symbols, and just simply doing dumb stuff for example when finding complex roots I forgot to divide the degree in the equations
its so dumb that even my teacher feels bad for me 💀
ok i really really think like
knowing exactly what you're doing
it's hard to explain in a generic way lol
knowing how and why what im doing works?
as a basic example
x - 4 = 4
(x - 4) + 4 = (4) + 4
x = 8
very basic tho, i don't have an example because i dont know exactly what mistake you've made or smthn XD
but you get what i mean?
and also on each step
you can check if your previous step was correct
ok
just really think about it
ill try that
yeah
ill give another example
yk systems of 3 linear equations
yeh
ok so normally they are easy
yeh
but i somehow kept messing them up on the test(i had to redo them 2-3 times) but i got the correct answer eventually
i dont know where or how i got it wrong
but that feeling was so weird
cuz it feels like u did it correctly but it just doesnt click
if you spent more time thinking through each step, maybe it would have helped you not make mistake?
of course it depends on how well you're concentrating
we all have those days when you make bajillion mistakes but yeh XD
thats everyday for me xD
XD
rn ima j try getting some sleep and just go w the flow ig
alr
if ur taking an exam, gl
ty lol
xD
finals this wed and im at border 90% (im cooked)
i will
also what would u do if u ever got burned out
cuz mg burn outs are killing me
you mean like tired of doing math, during a test?
or what do you mean
and thus being more likely to make mistakes?
tired from just grinding(practicing)
XD
ahh
take a break, do a different kind of problem, or try to wake up 💀
also
try to really think about what you're doing
don't just follow the method, understand the process and why it works and how you're doing it
i picked up that habit after geometry xD
btw if you want to recheck your answer, try verifying it from a different approach, use a different method to recalculate the answer, or check for mistakes like wrong unit or wrong plus minus
bet
breaks dont work for me because i just spend half the day on break and the day is just done
thats how i was able to verify it
yeah
if you get an answer, you plug into all systems, and it works, theres like no way you made a mistake 💀
unless you've made four mistakes and they all happened to give the same answer 💀
💀
don't do anything during the break
sometimes you dont even realize you make a mistake because its not the calculation thats wrong, but the logic behing the working step (like tom give 2 apple each to his 5 friends but you instead 2 + 5 = 7)
it makes you bored and then you WANT to do the math XD
guess ill take a nap
naw, then ur gone forever 🗿
oh shi
thats not a healthy way of putting itxDDD
😂
BRROOOOOO I LEGIT DO THAT TOO MUCH
its beyond sad how much i suffer from those exact types of mistakes
thas what im saying the most general advice "think about what ur doing" mhm mhhm
💀
its so general that it aint even help 💀
yeh
1.Could anyone explain what is the greatest integer function?
2.And why is it different for integral and non integral values?
3.Why the values of c+ and c- are different?
the greatest integer function finds the greatest integer less than or equal to x
which is the same as "flooring" or "rounding down"
Can you answer other 2 questions?
i'm not sure what you mean by different for integer vs non-integer values
and c+ is any number slightly larger than c, whereas c- is any number slighly smaller than c
the greatest integer less than or equal to 3 is 3
Like decimals and integers
