#precalculus

1 messages · Page 19 of 1

warm oyster
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why have you posted a chemistry question in a math server and that also in a channel that says calculus lmao

lunar viper
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is the map of a vector b which underwent a transformation by an nxn matrix equal to the vector v given by the vector b multiplied by the matrix?

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also i understand what these means in terms of functions but what does it mean with matrices

paper oriole
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Someone explain to me what the hell the prime notation (') symbolises please

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I am braindead

oblique sapphire
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Depends on the context

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Usually when u see f'(x) it means the derivative of f(x)

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Usually y' is also a derivative of y

rotund crystal
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Why does f(x) have negative zeroes? Isn't its leading coefficient x^4, an even number meaning it should have only positive zeroes?

summer ruin
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Isn't its leading coefficient x^4, an even number meaning it should have only positive zeroes
not sure why you would think that would ever be true

summer ruin
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x^4 - 1 has negative zero

rotund crystal
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Right

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Ah yeah that makes sense

hushed sphinx
drifting root
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Have no idea what’s going on here

viscid thistle
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Help guys

hushed sphinx
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That doesn't seem to belong in precalculus.

viscid thistle
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somone help understand

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pls

olive whale
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j'

remote mesa
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explain slope intercept

pine geyser
warm oyster
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this might be useful

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also i think this is the wrong channel for this

remote mesa
pine geyser
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but that khan academy video would help you alot

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<@&268886789983436800>

pine geyser
remote mesa
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After I find the y intercept the rest is like thin air to me, also our instructor switches the numbers around without showing their work so it's irritating

pine geyser
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alright

pine geyser
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for example, im asking you to find the intercepts of x+2=y and -x+4=y

remote mesa
arctic dragon
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Guys I need help with one question

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I have it partially completed

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it's very likely that the last part of the question is wrong

turbid creek
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Please.

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I need help with this.

arctic dragon
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end behavior? forgot what that was

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but ur doing logarithms right?

vestal lake
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who can help me

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will pay

turbid creek
hushed sphinx
turbid creek
vestal lake
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need help asap

arctic dragon
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quadratic formula

turbid creek
arctic dragon
arctic dragon
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give me 2 seconds

turbid creek
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y= b^2+-squrt -b+4ac over 2a.

vestal lake
turbid creek
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100^2 +- squrt -100+4(4.9)(318) over 2(4.9) =y

vestal lake
arctic dragon
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A is 23 seconds. B:828.204 peak

turbid creek
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don't know if thats what you are looking for.

arctic dragon
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that's what I got

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use the -b/2a equation, whatever you get from that plug it in the equation and that gives you the answer for num 3

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q.3

turbid creek
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Anyone help me with this?

arctic dragon
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no one answered my question sad

arctic dragon
turbid creek
arctic dragon
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looks like it

turbid creek
arctic dragon
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do you have any previous work

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that is the same as that question

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so we can kinda guide ourselves

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lol

turbid creek
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not really.

arctic dragon
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so is this the first time you are seeing this?

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damn like I need some material else I won't be able to help u

turbid creek
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Yeah.

vestal lake
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@arctic dragon

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u know how to do this

arctic dragon
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that's an odd fuction

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positive i think

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hm

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roots are -4,-1,2,4

turbid creek
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Like I have tryed to look stuff up so I could figure it out on my own and can't find anything.

arctic dragon
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have you asked chatgpt

vestal lake
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u know how to do this one

arctic dragon
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yes

vestal lake
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wait

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i meant this

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@arctic dragon

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help me with this one my king

arctic dragon
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check on desmos

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oh you changed pics

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lol

vestal lake
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my bad

arctic dragon
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vertex is -3,1

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I can't remember correctly, sorry

turbid creek
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Think It gave me the right answer.

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ty

arctic dragon
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👍

somber onyx
arctic dragon
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long division

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synthethic there might work but use long division

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lmk what you get

arctic dragon
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I still don't get this:

arctic dragon
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ok I think i get it now

alpine flicker
worthy bridge
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anybody know the inverse function formula?

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im trying to solve $x=y^2+y$ and get y alone

obsidian monolithBOT
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x927373

summer ruin
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this is quadratic equation in y

solar olive
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there will be two inverrses though

storm gust
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Can I have a rectangle where the domain of the length of one side is [0, p/2] where P is the perimeter?
In this case the rect will have two sides and both of them will collapse to be on the line
Is this valid? This is mentioned in the solution to one of the questions in the book I am reading

pine geyser
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Just tell me what are the answers for x and y. Let's not talk about intercepts for now

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x+2=y
-x+4=y

arctic dragon
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I think that’s how it goes and then just solve for x

grim oyster
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I tried by taking (dz/dy)^2 common from rha, but idk

arctic dragon
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is that derivates

fleet crater
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how to draw the graph of x^6(1-x)^7

pine geyser
# worthy bridge im trying to solve $x=y^2+y$ and get y alone

if you remember, we could find "x" in a quadratic equation and we say x=(-b +or- sqrt(b^2 -4ac))/2
basically you only have to do the equation for y and find out y= your answer
but im not quite sure if that function can be inversed, because there are two "y"s for one x.
but if you want to get the y alone, you just have to put it in the quadratic equation and solve it

prisma oriole
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no way this is pre calc 💀😰

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scary

red knot
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People here seem to type whatever random things to these channels

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Partial derivatives? Seems pre-calculus to me!

haughty tapir
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Yo

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this is the prompt for my assignment "Sketch the graph of each function by transforming the graph of an appropriate function of the form
y = xn
from the graphs below."

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Just wanted to know if there was a quick vid that explained how it all worked

ashen bolt
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i think it might be -1, 1, 2

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im not sure if 4 would be one of the actual zeros since you dont see it hit the x axis on the graph

haughty tapir
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its still wrong 😢

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Not sure

viscid thistle
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leading thing is four

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so there has to be four zeros

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and imaginary zeros come in pairs

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hmmCat maybe they wnat you to put -1 twice

ashen bolt
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ohh yeah, theres a double root at -1 which is why it turns (triple would be inflection , and 1 root would just pass, like at 1 and 2) lol sorry i forgot

fleet crater
haughty tapir
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it was -1 twice

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idk why i dont understand it but that was the answer

ashen bolt
haughty tapir
daring mantle
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Heee

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Guys

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Who study math here

fast kiln
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I’m stuck on part b here, I got the right answer for a by finding each volume individually and finding the difference but im not getting the right answer for b

viscid thistle
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is anyone there ?

delicate bolt
warm oyster
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any help with this please🙏

digital mirage
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how is this possible

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log can nver be equal to 0 as per its range and here they have equlity with 0

warm oyster
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@digital mirage output of log function can be 0

digital mirage
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range of log is (0 to infinty )

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@warm oyster

warm oyster
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no

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that is not range, that is domain

digital mirage
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ohhhh

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right

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tahts is exponential lmaooo

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@warm oyster but still cos(sinx) must not hold equlity with 1

summer ruin
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there's no such point where cos(sin(x)) > 1

digital mirage
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yes but im saying here as it is written as >= 1 is not possible by log properties

summer ruin
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log(x) >= 0 for x >= 1

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it's zero for x = 1 and monotonically increasing for x > 1

digital mirage
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??

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is this wrong ?

summer ruin
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no

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a = 3, y = 0 in your case

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cos(sin(x)) >= a^y = 3^0 = 1

digital mirage
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cos(sin(x)) > a^y is what property say

summer ruin
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the definition of log

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log_a(x) is a number y such that a^y = x

digital mirage
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ya but what about this property ?

summer ruin
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what property

digital mirage
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how these 2 can be true at same time ?

summer ruin
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they are not true at the same time

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they're true for suitable values of a

digital mirage
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but my Q is stasfying those suitable values

summer ruin
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one is true for a > 1, the other is for a between 0 and 1

summer ruin
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3 > 1, but not 0 < 3 < 1

digital mirage
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wait let me explain

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ok i got it

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ty

paper cedar
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can logarithmic spirals pass theta=2pi? my calculator stops there

viscid thistle
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probably

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spiral has to complete multiple cycles

flint thicket
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can someone help explain what this means 🥲

summer ruin
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solve the equation sin(x) = -sqrt(3)/2

primal hill
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like I need help like 12 hours from now if your active because I left my HW at school and only have like 30 mins to finish it

summer ruin
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I won't be here by that time

primal hill
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hm ok

flint thicket
summer ruin
flint thicket
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thats where im confused-

summer ruin
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well I need to know what you're doing

flint thicket
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i apprecate the help anyways :)

viscid thistle
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Or memorize the key points and know how to apply that into a given equation (in this case it would be pretty simple)

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It’s generally easy when dealing with sin/cos

viscid thistle
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Do you know what is In(a)+In(b)?

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The formula

shell nova
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ln(a) + ln(b) = ln(ab)

digital mirage
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here sin(1/x) can give values from -1 to 1 . now if it gave the value 0 then it will lead to 0/infinty and further leading to 0/0 .... then how to solve it ?

obsidian monolithBOT
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saddayyy_

solar olive
lilac sand
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do u guys think i could like self study over thanksgiving break

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to be ahead / used to precalc or will it be like 2 hard to do

fluid jewel
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Anyone know any good videos on logarithmics, its something I just cannot fully wrap my head around no matter how hard I try

hexed charm
# fluid jewel Anyone know any good videos on logarithmics, its something I just cannot fully w...

View full lesson: http://ed.ted.com/lessons/steve-kelly-logarithms-explained

What are logarithms and why are they useful? Get the basics on these critical mathematical functions -- and discover why smart use of logarithms can determine whether your eyes turn red at the swimming pool this summer.

Lesson by Steve Kelly, animation by TED-Ed.

▶ Play video
tribal jolt
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Should I precal and calc

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Or should I just follow the IB curriculum

summer ruin
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<@&268886789983436800>

steady cloud
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how do u turn a negative exponent fraction positive again.. doghuh

molten flare
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reciprocate the b ase

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base

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example

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1^-1/2

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= (1/1)^1/2

formal forge
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Hey guys, been stuck on this for 10 minutes, how do you solve this?

pine geyser
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Any number to the power of zero equal one

formal forge
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Holy shit

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I knew I forgot something

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Thanks man

pine geyser
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No problem

formal forge
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So, it's gonna be 1 = (x²/7x-1) right?

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Why do I feel like I'm goin to use the quadratic equation

pine geyser
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You are feeling right

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That's how you solve this question

formal forge
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Oh

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It's pretty late for some quadratic equations, imma sleep now. Thanks again!

pine geyser
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Ah alright, good night!

thorn grotto
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i think for a im supposed to plug in x=1 through x= 12 in to graph the equation but lmk if im not doing this right

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but i need assistance with this problem

viscid thistle
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Then looking at that would give you the answers to b and c

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Just plugging a few numbers in won’t account for any irregularities

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Which could affect answers to b and c

viscid thistle
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The qst asks us to find the function for this graph

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I know this function is 1/x. But it is flipped so that makes it -1/x.

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And there is a VA at x= -1 so that means the function is -1/(x+1)

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The part i am confused about is how in the world is the x intercept 2 and the y intercept -2? I plugged the -1/(x+1) into desmos but it gave me this

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Am i missing something? Does it have to do with the hole?

vocal mantle
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Does anyone have anki cards for mathematics

lilac sand
lilac sand
strong roost
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Ummm so how can I understand trigonometric identities

turbid creek
viscid thistle
near rampart
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hi i was wondering if someone can help me with a question

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i need to find the coordinates for a point (x,y,f(x,y)) but all i got is the function f(x,y)=y^2+2xy and the tangentplane z=6x+4y-11 in the point (x,y,f(x,y))

near rampart
lilac sand
alpine bramble
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help

grave gyro
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I have an exam tomorrow in calculus

errant pilot
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hello my guys

sweet tree
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I'm trying to get help in the channel, but maybe I can ask here

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I want to know if a table of values is correct or not. A teacher presented me with a table of (x,y) values that looks like this: (0,1) (1,4) (2,10)(3,20)(4,35). This to me appears immediately to be a tetrahedral function/sum of triangular numbers. y=1/6x(x+1)(x+2). Simple. However, of course, a true tetrahedral would have a slightly transposed table of values: (0,0)(1,1)(2,4)(3,10)(5,20)(6,35) etc. So what's up? Did the teacher just mistype the list of values or do I need to figure out a different function?

sinful moth
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hello guys

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how do you guys do these types of equation for ellipse?

uncut mulch
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wdym by "do"

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what exactly are you being asked for

sinful moth
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like how do you get the proper form

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like when (x-h)^2+(y-k)^2=1

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like dis

uncut mulch
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divide both sides by the value such that the right side will be 1

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what's currently the right side of the equation?
thus what should you divide by?

uncut mulch
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you divide both sides by that same value

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then do some additional manipulation if needed

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the first goal is the get 1 on the right side

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do what i mentioned and tell me what you get

uncut mulch
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how are you getting 9 in the denominator

sinful moth
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36/4

uncut mulch
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isn't 1/9

sinful moth
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oh yeahh

uncut mulch
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also missing the () and ^2 for the y-8

sinful moth
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i divided it by 1/4

uncut mulch
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you shouldn't be doing that

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always remember, same operations to both sides of the equation
divide both sides by 4
or multiply both sides by 1/4
or equivalent

sinful moth
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well i divided it by 1/4 as fraction rules so i got 4x2 and (x-8)^2 x1

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thats how i got it

uncut mulch
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that's not division by 1/4

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that's multiplication by 1/4

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and regardless that won't give you 9 in the denominator

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division by 4 is multiplication by 1/4

sinful moth
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no its for the left one'

uncut mulch
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?

sinful moth
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since its also a fraction

uncut mulch
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doesn't matter

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division by 4 is multiplication by 1/4
by definition

sinful moth
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my bad 😛

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alright ill try and redo it

uncut mulch
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you might be doing some valid math for some parts but aren't properlly describing what you're doing

sinful moth
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wait ill show my work and please judge it

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here

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dont mind my handwriting 😛

uncut mulch
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so yeh, as mentioend before

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36/4 is NOT 1/9

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$\frac{36}{4} \redneq \frac{1}{9}$

obsidian monolithBOT
#

ℝαμΩℕωⅤ

sinful moth
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ohh

uncut mulch
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don't overthink what its supposed to be

sinful moth
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its 4/36

uncut mulch
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no

sinful moth
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wat

uncut mulch
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you're overthinking this

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really overthinking this

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4 * what = 36

sinful moth
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lel i put 9 instead of 4

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my fault

uncut mulch
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still NO

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4 * what = 36

sinful moth
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aint it just 4/36

uncut mulch
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no

sinful moth
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and simplified 1/9

uncut mulch
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$\frac{36}{4} \redneq \frac{4}{36}$

obsidian monolithBOT
#

ℝαμΩℕωⅤ

uncut mulch
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36 divided by 4 is NOT the same as 4 divided by 36

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1/2 is not the same as 2/1

sinful moth
uncut mulch
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and that's why its wrong

sinful moth
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4 as nominator

uncut mulch
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which is wrong

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forget about the elipse equation / the final desired form

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this is a simple question about division

sinful moth
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alright im joking i know its 36/4

uncut mulch
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what is 36 divided by 4
how many times does 4 go into 36

sinful moth
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gosh lel

uncut mulch
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i can't tell if you're joking

sinful moth
uncut mulch
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no

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why are you still saying 1/9 despite me saying its wrong 5+ times

sinful moth
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AHHWAHAa

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4 divided by 36 is 1/9

uncut mulch
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those two questions were asking the exact same thing

sinful moth
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😛

uncut mulch
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yes, 4/36 is 1/9,
but you don't have that here

sinful moth
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yeah my fault

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bad comprehention

uncut mulch
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36/4 is simply 9

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dividing both sides by 4, you should have
$$\frac{(y-8)^2}{8} + \blue{9(x+1)^2} = 1$$
and to explicitly express the $\blue{9(x+1)^2}$ in the form $\frac{(x+1)^2}{\red{k}}$ you can apply the reciprocal relation between multiplication and division. \
$$\frac pq = \frac{1}{q/p}$$
$$9 = \frac{1}{1/9}$$
thus
$$9(x+1)^2 = \frac{(x+1)^2}{\red{1/9}}$$

obsidian monolithBOT
#

ℝαμΩℕωⅤ

sinful moth
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im sorry for all this trouble and its just because i forgot basic math opencry

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thank you for helping mee

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Tymsss

viscid thistle
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for me 3ln(ab)

viscid thistle
arctic dragon
digital mirage
solar olive
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i mean just u =1/x ?

viscid thistle
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what is the difference between pre calc and algebra 2?

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like the topics

uncut mulch
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there's quite a bit of overlap

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they're just labels certain places assign

viscid thistle
opal vault
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the value of sin 1/x approaches 0 and denominator goes to infinity so it should be 0

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0/inf = 0

lapis bramble
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what do I start now?

novel creek
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do a few lessons and see what you feel comfortable with doing :)

lapis bramble
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well I want to go to calculus cuz my old math teacher said you don't really need precalculus but I don't want to skip anything to important

novel creek
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i would say precalc is very important to calculus

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but that just depends on how much precalc you already know

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i.e. trig, logs, exponentials, etc

lapis bramble
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I did alj 2 so yea I know all those things

sacred junco
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if x+1=4, then what is 2x+2? Im really struggling with this question.

soft warren
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  1. u can solve for x
  2. u can multiply both sides by 2 for the first equation and get ur answer directly
dreamy void
hallow lodge
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does anyone have a trick to trigo identities?

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i literally dont understand anything

warm oyster
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like trick to memorise them?

hallow lodge
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for example

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Tan theta can both equal to

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sin0/cos0 or tan0 = 1/cot0

hushed sphinx
#

Most of those I'd derive as necessary by writing everything in terms of sin and cos.

warm oyster
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pretty strange sometimes i just dont get notified about the pings

hallow lodge
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or do i js literally disregard everything there and just write everything to sin and cos

hushed sphinx
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As far as I'm concerned, csc(x) is defined as a shorter (and less enlightening) way to write 1/sin(x), so the identity is trivial.

hallow lodge
hushed sphinx
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No, if it says 1/csc(x), that means 1/(1/sin(x)) which is the same as sin(x).

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(Unless the lhs is not defined due to division by zero).

hallow lodge
hushed sphinx
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1/csc(0) is not defined, whereas sin(0) is.

desert timber
#

what's with these ridiculous exercises like "express log6(16) using log12(27)"? i don't see any kind of pattern for solving them, you just have to guess the right order of steps that might lead you to the answer?

hushed sphinx
#

Hmm, you could start by expressing the two values as $\frac{4\log2}{\log2+\log3}$ and $\frac{3\log 3}{2\log2 + \log3}$ ... but that doesn't really seem to point to any nice relation between them in this case.

obsidian monolithBOT
#

Troposphere

hushed sphinx
#

But you can reduce the number of "unknowns" by declaring that the logarithms in those fractions happen to have base 3, and then you're looking at expressing $\frac{4x}{x+1}$ in terms of $\frac{3}{2x+1}$ which is a matter of (slightly messy but) straightforward algebra.

obsidian monolithBOT
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Troposphere

desert timber
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hmm our teacher hasn't used unknowns in any of these exercises so far

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this is the solution in my textbook, under 3)

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looking at these solutions, I have no idea how I was supposed to think of that... each exercise has its own incredibly specific trick

hushed sphinx
#

That looks like it's basically the same computation I suggested, but more confusingly written by writing log3(2) all the way through, where I decided to name it x to make it more unobtrusive.

desert timber
#

I see

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do you have some kind of method for solving these

hushed sphinx
#

The solution in your screenshot is just the final proof, with no easily visible trace of how it was found.
My reasoning might have been a bit brief, but at least the first step in it was pretty systematic: express everything in terms of logarithms of primes.
The trick of choosing one of those primes to be the base of all the logarithms probably is something you only gain from experience.
But after that the only logarithm left was log3(2), which allowed me to use elementary algebra to relate the fractions.
If you haven't even seen algebra, it feels like asking you to come up with such rewritings on your own sounds like a rather big task.

desert timber
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thank you, I'll try to apply this in the future

digital mirage
warped cipher
#

,rccw

obsidian monolithBOT
digital mirage
digital mirage
#

and this is correct

warped cipher
digital mirage
#

fx under cos must be from -1 to 1 ... that what i did

warped cipher
#

wdym fx?

warped cipher
digital mirage
dry cave
#

depends on the questions

haughty tapir
#

Hello

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How do I read the graph to get the domain n range?

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it wasnt tauight from what i remember in class he just guestimated the lines

summer ruin
#

recall the definition of domain and range

tropic moat
ruby sparrow
#

Hi everyone, does anyone know of a location where I can obtain quality exercise with challenging problems and corrections? *

hallow lodge
#

can someone explain how (1-sin)(1+sin) = 1 - sin^2

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why is 1 not cancelled out?

warm oyster
obsidian monolithBOT
#

🐱!Yajat! 【Catfan1398】🐱

warm oyster
obsidian monolithBOT
#

🐱!Yajat! 【Catfan1398】🐱

hallow lodge
warm oyster
#

yes for 1^2 is 1

untold python
#

guys how do you do this

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how can i determine if it's x^3 and x^4 or more

novel creek
#

in other words, if f(-x)=f(x), it's symmetric over y-axis, if -f(x)=f(x), it's symmetric over x-axis. The only one not explicitly identified here is symmetric about origin, which means a function is odd which means f(-x)=-f(x)

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so just tests these and you should be good :)

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@untold python

untold python
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Ohhhhhh!!! Thank you sooo much!!! @novel creek

north dirge
#

Hey does anyone have some good videos to watch for reverse chain rule and integration by substitution?

upbeat falcon
#

yes

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organic chemistry tutor

north dirge
#

thanks

vast quartz
#

thats what im slaving away at rn

soft warren
novel wharf
#

Idk how many people are in Canada
However you would it be realistic to study all of Precalc in 3 months over the course of the summer as with also advance functions?

#

Would it be good enough preparation of getting a solid 90 or 85?
With also adage of studying more advance stuff on the side as per calc?

fervent yarrow
#

How do I solve this?

willow skiff
#

or equivalently, f is the inverse of g

fervent yarrow
#

Is it correct?

willow skiff
fervent yarrow
#

Number 18 how do I solve this?

willow skiff
#

no worries

willow skiff
#

try substituting x = 1 etc into those definitions

#

(you can think of these functions graphically: even functions have left-right symmetry, and odd functions have symmetry across quadrants 1 and 3; 2 and 4)

fervent yarrow
willow skiff
#

and (4, 7) is the reflection of (-4, 7)

#

so it works out

#

that function is even

fervent yarrow
#

Okay

#

Then for the second option?

#

It is odd

#

Cause -x,-y exists?

#

@willow skiff

willow skiff
#

yeah the 2nd is odd

#

now try option C

#

with x = 1

fervent yarrow
#

Okay

#

Neither even not odd

#

C is the ans

willow skiff
#

yep C is correct

willow skiff
#

you get f(0) = -f(0)

#

or that f(0) = 0

#

in other words, every odd function must pass through the origin

fervent yarrow
willow skiff
#

and if f(0) = 0, that means when x = 0, y = 0

#

that point is precisely the origin

#

like if x = -x, adding x to both sides gives you 2x = 0

#

or x = 0

viscid thistle
#

<@&268886789983436800> uh spam ig?

oblique sapphire
#

In other words, if an odd function is defined at x=0, it must pass through the origin

mental sonnet
#

hey so i feel like I have a solid basis of algebra and trigonmetry but I really don't know how to tackle calculas. Its something that I have heard about and would love to learn about but I don't know where to begin

soft warren
lapis bramble
ornate depot
#

is there anyway to do the last step without using a calcukator

#

140*1/2^25/20

viscid thistle
#

hi can someone help me find this limit

#

i know the answer might be something easy cuz log base 7 of 0 does not exist, but i also got that x > 0 so it might range in the positives?!

magic wolf
# ornate depot

I'm pretty sure that the 140 at the end gets the exponent as well

magic wolf
viscid thistle
#

it approaches +inf or -inf?

magic wolf
#

-inf

#

Mb

viscid thistle
#

k ty

magic wolf
#

You're welcome

mental sonnet
hallow lodge
#

how to turn this into logarithmic?

twin vortex
#

can anyone explain calcules to me please ?

gaunt carbon
#

what do you want to know
calculus is a pretty wide field

twin vortex
#

can you explain the bare basic in bare basic terms

gaunt carbon
#

yeah

#

so, in simplest terms, calculus is two main operations
differentiating and integrating, and they're opposites

#

i can't easily explain what they do but they're both based on the concept of a limit
which is a value a certain function approaches (but this doesnt necessarily mean it'll reach it, it's just what it approaches)

#

so if you have a function like this and you're trying to take the limit as x approaches zero from the right, you're going to get a value of zero
but if you take the limit as x approaches zero from the left, you're going to get a value of three

#

and thats the bare minimum i can explain easily

#

the notation looks smth like this

#

where right and left are noted by plus or minus signs next to the a

delicate thistle
#

Can anyone help me with this practice problem

ornate depot
gaunt carbon
# ornate depot How?

so the first step here is gonna be taking the 4x our front and making it an exponent right

ornate depot
gaunt carbon
#

so the 4x can become an exponent of the 7 because we're working with logs right

#

yeah that works too

ornate depot
#

I just don't get the step where (4x+1)In 7

gaunt carbon
#

i mean if it doesnt i dont see errors there

gaunt carbon
ornate depot
#

the one where you distribute the 4x+1

gaunt carbon
#

yeah so as far as i know that just works like any other multiplication problem
it looks like you did it right from what I can tell

ornate depot
gaunt carbon
#

OHHH okay

ornate depot
#

I don't get how (4+1)in7 = 4x*in7+in7

gaunt carbon
#

yeah so basically. all we're doing in that step is multiplying 4x by ln 7 and then multiplying ln 7 by 1

#

its the natural log so we treat it like any other number or variable

#

when we multiply like that

#

so like. if you have smth like this

ornate depot
#

okay

#

O I get so he didnt multiple the Nartual log of 7 with 4x because the number dont share the same variable so he left as 4*in7

short iron
#

I have an equation ax^2+bx+c=0. What are the conditions on b and c such that the solutions are

  1. real and positive
  2. real and negativ
    if a<0
shadow summit
#

the discriminant is sqrt(b^2 - 4ac)

#

you may see it in the quadratic equation, if the result of the discriminant is positive and larger than 0, than the roots are positive and real. If the discriminant is positive and less than 0, than the roots are negative and real. And if the discriminant is negative the roots have complex feelings and want to be special.

gloomy walrus
#

(x^2)+3x+9

(-3(plusminus) root[9-36])/2

(-3(plusminus) root[-27])/2

(-3(plusminus) 3root[-3])/2

(-3(plusminus) 3iroot[3])/2

1.5(plusminus) 1.5iroot[3]

1.5+1.5iroot[3], 1.5-1.5iroot[3]

pulsar vessel
#

I have an exam coming up and I was wondering if anyone would help me study

pulsar vessel
shadow summit
pulsar vessel
#

Mostly expanding logarithms and giving the exact solutions to them.

#

I’ll show what my exam says so you understand what I mean by giving exact solutions.

shadow summit
#

Are you doing everything in base 10 (log_10(x) or log(x))? or are you doing logs of different bases?

#

How familiar with your logarithm rules are you?

pulsar vessel
#

Not very familiar

shadow summit
pulsar vessel
#

Here’s another example of what I need help understanding

pulsar vessel
shadow summit
#

Okay lets start with q6a) ln(x^3 * y)

pulsar vessel
#

Ok

shadow summit
#

We can apply the law of products which stats that log(ab) = log(a)+log(b)

#

so we will have ln(x^3)+ln(y) //then we can apply the law of exponents which is log(a^b) = blog(a)

#

that means the final solution is 3ln(x)+ln(y)

pulsar vessel
#

Ok I follow

shadow summit
#

I will go over the second question as its a bit more complex, then have a go at the final question.

pulsar vessel
#

Ok

shadow summit
#

log( (sqrt(x)*k^2)/(m+1) )

#

Start by applying the law of ratios
log(sqrt(x)*k^2) - log(m+1)

#

actually, i think thats it

pulsar vessel
#

Oh I don’t need to do anything further?

shadow summit
#

I don't think so, I though it said sqrt(xk^2), but because it just says sqrt(x)*k^2 we dont have to go any further

pulsar vessel
#

Ok makes sense

shadow summit
#

But if you have to, like in the final question, recall that a square root can be expressed as a fractional exponent

pulsar vessel
#

I don’t think I have to do that

shadow summit
#

for the final question you have to change the inside of the logarithm from the fourth root to the power of 1/4, then use the law of exponents to move it to the front of the logarithm.

pulsar vessel
#

Oh ok how do I do that?

shadow summit
#

Look at the inside, it is

#

you can change that to be (ab^3/c^2)^(1/4)

#

then you can use the law of exponents to move the 1/4th to the front of the log

pulsar vessel
#

Oh I see. Does that get rid of the square root?

shadow summit
#

yes

pulsar vessel
#

So it would be written as 1/4 log ab^3/c^2

shadow summit
#

yes

pulsar vessel
#

Do I use the law of ratios after that?

shadow summit
#

yes

pulsar vessel
#

Ok I think I’m starting to get it

shadow summit
#

The last question is a bit complex

pulsar vessel
#

Yes it is

shadow summit
#

Tell me once you think you have gotten the answer

pulsar vessel
#

Ok

shadow summit
#

okay, what did you get?

pulsar vessel
#

3 (1/4) log3 ab - 2(1/4) log3 c

shadow summit
#

okay, this is pretty much the answer, and you would probably get full marks, but you can move 1/4th to the front of some brackets to make it look cleaner

shadow summit
pulsar vessel
#

Oh I thought I could

shadow summit
#

because log_3(ab^3) isnt log_3(ab)^3

pulsar vessel
#

Oh right

#

That makes sense

shadow summit
#

i sometimes mess up like that as well, so dont worry

pulsar vessel
#

Right. I’ll make a note of that

shadow summit
#

do you know how to do question 12a in the original work sheet you posted?

pulsar vessel
#

No

shadow summit
#

This one is pretty easy

#

you should be able to recall that 2^3=8

pulsar vessel
#

Yep

shadow summit
#

so for these types of questions you need to make everything have the same base number
so 2^(4x+5)=8 would become 2^(4x+5)=2^3

#

Now, using the same base rule of exponents, if x^a=x^b, then a=b

#

so 4x+5 must be equal to 3

#

so you'll just have to solve the equation 4x+5=3. which gives you the answer x=-1/2

pulsar vessel
#

Oh right! That makes sense now

shadow summit
#

And to verify, plug in -1/2 into the original equation.

pulsar vessel
#

Right

shadow summit
#

Now, im going to go through q12c just so you can take a very important note

pulsar vessel
#

Ok

shadow summit
#

Because both sides have different bases you cannot use that trick to solve for x.

pulsar vessel
#

Ok so does that mean we need to make the same base?

shadow summit
#

Nope! We can use logarithms! (yay)

pulsar vessel
#

Oh ok

shadow summit
#

We can take the log of both sides (doesnt matter the base of the log)

#

but because you are learning natural logarithms, i will be using ln(x), which just means log_e(x)

pulsar vessel
#

Ok

shadow summit
#

3^(x-4)=7^(2x+5)
ln(3^(x-4)) = ln(7^(2x+5))
(x-4)ln(3) = (2x+5)ln(7)

#

from here, it should be pretty easy to figure out, but if you havent already, i will continue

#

xln(3) - 4ln(3) = 2xln(7) + 5ln(7)

#

xln(3) - 2xln(7) = 5ln(7) + 4ln(3)

#

x( ln(3) - ln(49) ) = 5ln(7) + 4ln(3) factorise x

#

x= (5ln(7) + 4ln(3)) / ((ln(3)-ln(49))

#

@pulsar vessel and that is the exact value

pulsar vessel
#

Ok I follow

#

Just writing it down

shadow summit
#

I would probably write this down on a book or a notepad

#

okay, good job

#

if you need clarification i am more than happy to make a line easier to understand

pulsar vessel
#

I think I understand

#

Once I take a good look at it I can see what you did

shadow summit
#

a helpful tip you should try doing is writing down the law you are using next to the line you used one in.

pulsar vessel
#

Oh good idea

shadow summit
#

Or if you want to be more precise, write down what process you are using if you arent using a specific law, like when i took the common variable (x) out of the logs in the 6th line

pulsar vessel
#

Oh ok

shadow summit
#

Do you think you are starting to understand logarithms and exponents now?

pulsar vessel
#

Yes I think I’ve got it now

shadow summit
#

okay, try this question

#

You will need to use the law of exponents, law of ratios, law of products

#

btw alog(b^c) = log(b^ac)

pulsar vessel
#

I got logb(8m^12/3)

shadow summit
#

good job, you got the correct answer!

pulsar vessel
#

Awesome!

#

I think it’s finally starting to click. Now that I’m getting more familiar with all the rules

shadow summit
#

Now, the best way to keep improving from here (aka getting more consistant) is to just do a bunch of questions. Use the textbook your school gives out, or ask your teacher for more resources, and just start doing problems.

pulsar vessel
#

Ok I will do that. My textbook has a whole unit on this with practice questions

shadow summit
#

When I was learning logarithms initailly I think i did over 300 logarithm questions in 10 days (outside of school). But you don't have to do that many, just like 50 and you should understand them.

pulsar vessel
#

Wow that is a lot of practice 😂

shadow summit
#

It was only like 30-45 minutes a day

pulsar vessel
#

Ah fair enough

shadow summit
#

A lot of the questions when i started were stuff like log_2(256)=x

pulsar vessel
#

Right. I was going to say

#

That’s better

shadow summit
#

sometimes i type too fast for the math to math

pulsar vessel
#

Haha I get it

shadow summit
#

Anyways, you also said you were doing simultaneous solutions (systems of equations) on your exam?

pulsar vessel
#

Yes but I’ve got those down pretty good

shadow summit
#

Ahh, thats good. They will show up everywhere in algebra and calculus.

pulsar vessel
#

I’m starting to notice that lol

#

That’s why I decided to actually learn them this time around

shadow summit
#

yeah, good idea.

pulsar vessel
#

Anyways, thank you so much for helping me! Really means a lot

shadow summit
#

np

green badger
#

Can someone help me with my homework? I would really appreciate it .

green badger
#

Analyzing graphs of functions

shadow summit
#

How much difficulty are you having with the topic?

green badger
#

A lot, I’ve had covid and I’ve missed the past two weeks of school and I’m really behind.

shadow summit
#

Okay, give a few examples of the questions you are having difficulties with.

green badger
shadow summit
green badger
#

Yes I know how to do that just everything else is confusing

shadow summit
#

Okay, so you don’t know what continuous and disconnected equations are?

oak oriole
#

Can you help me with both parts

#

<@&286206848099549185>

lunar viper
tender questBOT
# oak oriole <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

pulsar vessel
#

When solving a system of equations using matrices, how do you know if you have no solution or infinite solutions?

summer ruin
#

when you have an equation of the form 0 = 1 or 0 = 0

ornate depot
#

for the quadratic equation does A always have to be equal to one like for example problem 2x^2+3x-10

tawdry viper
#

can anyone help me?

#

@here

warm oyster
#

!da2a

tender questBOT
#

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

shadow summit
viscid thistle
#

Find the sum of all values of $\theta$ such that $\theta\in[0,2\pi]$ and$$ \cos(\theta)+4\sec(\theta)=8 .$$

obsidian monolithBOT
#

Mathboy123

shadow summit
obsidian monolithBOT
#

TheLord26

shadow summit
#

From there, how I went about solving for $\theta$ was to let $\cos(\theta) = x$, and solve for x using the quadratic equation.

obsidian monolithBOT
#

TheLord26

viscid thistle
shadow summit
viscid thistle
#

(x=2\sqrt{3}+4\ x=-2\sqrt{3}+4)

shadow summit
#

That is correct.

viscid thistle
#

so 8?

shadow summit
#

Then you will have $\cos(\theta)=x$, and from there you will find that $2\sqrt{3}+4$ does not have a possible solution, so when you use $-2\sqrt{3}+4$ you will find the value of $\theta$ to be 1.00522.

obsidian monolithBOT
#

TheLord26

shadow summit
#

Finally use the general solution to find all values between 0 and 2pi.

#

And well, add them all together.

viscid thistle
#

So whats the answer

#

1.00522?

shadow summit
#

yes

frigid trout
#

if im given this and its telling me to expand

#

is it okay to write it like this

#

or would I have to distribute the 1/5 to each one

#

ex) 1/5 + 4/5 - 4/5

warped cipher
ornate depot
#

How is a = 2 is because 2=2?

viscid thistle
#

<@&286206848099549185>

lunar viper
tender questBOT
# viscid thistle <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

lunar viper
#

you didnt even POST your question

#

🤦‍♂️

viscid thistle
#

I mentioned people for her question not mine lol

hushed sphinx
#

Well, don't.

viscid thistle
#

Can anyone help me find the derivative?

#

<@&286206848099549185>

lunar viper
#

💀

warm oyster
#

!15m

tender questBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

lunar viper
#

!15m

tender questBOT
#

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

lunar viper
#

🤦‍♂️

viscid thistle
#

Oh sorry I didn't see the message

lunar viper
viscid thistle
#

Ok I'm sorry what I'm suppose to say

pulsar vessel
#

Can the domain of a log be negative?

warm oyster
#

nah

pulsar vessel
#

Ok 👍

vital cairn
#

Because exponential can be negatives

#

If you allow stuff the be complex

thorn creek
#

quite famously, e^(iπ) = -1

turbid garnet
#

why is this possible to do and why do you do this?

shadow summit
# turbid garnet why is this possible to do and why do you do this?

It's because the you are multiplying by 1, and in trigonometric proofs you can multiply by 1. The reason you do this is you hope to simplify the right side and turn it into the left side, what you should be looking at now is expanding the top of the fraction and manipulating it to be equal to cot(x)-csc(x)-1.

viscid thistle
#

Hey guy's, i had a question, is algebra 2 enough to proceed into precalculus?

digital mirage
#

why we dodnt write g(lambda+pi/2 ) ? lambda is also varibale here

#

and why lambda cannot be zero ...

stable vessel
#

Why quadratic functions graphs are always curved?

sinful halo
stable vessel
#

a linear function can be determined by y = x and a quadratic function by y = x²?

sinful halo
#

The difference between the graphs

#

It's the slope

#

The slope of a linear function is always constant whilst for a quadratic it changes

stable vessel
#

why?

sinful halo
#

Because x is squared — $2^2=4$ $3^2=9$ $4^2=16$ see how 4 changes to 9 which then changes to 16? It changes from +5 to +7 and so on

obsidian monolithBOT
sinful halo
#

Linear functions don't have that characteristic and change at a constant rate which is "m" in y=mx+b

stable vessel
#

I am getting to understand it, can I apply this logic for other type of functions like cubic or fraction ones?

sinful halo
#

By fraction do you mean $\frac{1}{x}?$

obsidian monolithBOT
stable vessel
slim steppe
#

I believe it's called Khan Academy

pulsar vessel
#

How do I insert this into a calculator? I can’t do the vertical line

shadow summit
#

but, that one isnt possible.

pulsar vessel
shadow summit
ruby cloud
#

Hey everyone. I don't understand the statement "Since MA> 0, the extremum points of the function d(x) and MA are the same". Why exactly we can conclude that?

#

Sorry for such weird typing, I used a translator to translate Russian into English from the image

hushed sphinx
#

That typography is truly bizarre.

#

But it must mean: Since MA(x)² = d(x) and MA(x) is always positive, the x that maximizes d(x) is the same as the x that maximizes MA(x).
(This is because the function that squares a number is strictly increasing on the positive reals).

#

@ruby cloud ^^

prisma bridge
#

Tropo quick and random question. Are you a Ph.D student by any chance

hushed sphinx
#

No.

#

That time is long past for me.

prisma bridge
viscid thistle
outer patrol
#

How do I do dis

warm spoke
# outer patrol How do I do dis

first divide both isdes by 8 so u got cos(4x)=3/8 and then do inverse cos each sied so now u got 4x=arccos(3/8) and then divide by 4 so u got x=arccos(3/8)/4 and then plug into ur calculator

#

also remmeber to set to radians or degrees but idk what u doing

digital pendant
# stable vessel Why quadratic functions graphs are always curved?

If you look at f(x)=x^2 then look at the increase that f(x+1) gives:

f(x+1) = (x+1)^2 = x^2+2x+1
f(x+1)-f(x) = (x^2+2x+1) - (x^2) = 2x+1

You should notice that the function increases by 2x+1 when going from f(x) to f(x+1). Meaning that the amount the function increases by increases as x gets bigger. Whereas if you compare g(x)=x to g(x+1)

g(x+1)=x+1
g(x+1)-g(x) = (x+1)-(x) = 1

You should see that the function only increases by a constant amount which isn't dependent on x.

viscid thistle
#

I understand this isn’t a help channel but it won’t let me open a help channel 😭

#

is anyone available?

warm spoke
#

but next time bro when you got a question just ask it otherwise then someone gotta respond to you first asking for the question and wait for u to respond back

umbral sandal
#

guys can someone help me

#

im low key lost rn

warm spoke
warm spoke
#

third one no because its undefined at x=3

#

fourth one no because u got another undefined point

#

which also happens to be a hole

paper pagoda
#

need help with this

#

ive had no problem with any problem so far, but this one is tripping me up

vernal pine
#

I have this equation, x^2 + y^3 = b^x. And i wanna find for what values of b (inequality) will give a graph with 3 roots. I started solving this with y as zero, yet im not exactly sure where to go next from this

#

,tex $x^2$ + $y^3$ = $b^x$

obsidian monolithBOT
vernal pine
#

im left with:

obsidian monolithBOT
vernal pine
#

but dunno what to do next

#

pls ping with any help!

viscid thistle
vernal pine
viscid thistle
#

I can't think of any other than your approach

#

The reason why other solutions are non-elementary, is because when you solve the given equation:

vernal pine
#

Hm thats a shame

viscid thistle
#

$x^2 = b^x$

$\implies ln(x^2) = ln(b^x)$

For $x > 0, 2lnx = xln(b)$

$\implies lnx - x\frac{lnb}{2} = 0$

$\implies xe^{-x\frac{lnb}{2}} = 1
=> (-x\frac{lnb}{2})e^{-x\frac{lnb}{2}} = -\frac{lnb}{2}$

obsidian monolithBOT
#

𝓘 .

vernal pine
#

Hm

viscid thistle
#

And this is of the form

#

$ue^u = -\frac{lnb}{2}$

obsidian monolithBOT
#

𝓘 .

viscid thistle
#

Whose inverse, called the Lambert W function, is non-elementary

vernal pine
#

Damn

#

I'll have to consult my professor on this it seems

#

Quite a weird question

viscid thistle
#

I mean there could be another approach of solving this

#

But currently I can't think of any

vernal pine
#

Thank you for your help

viscid thistle
# obsidian monolith **𝓘 .**

Also b>0 here (and when you solve it in the end using Lambert W, b has to be greater than or equal to e^(2/e) because to solve for ue^u = w, there is a restriction of w≥-1/e, for Real u and w)

worldly crater
#

How good or bad is the Baron's E-Z Precalculus book?

obsidian monolithBOT
#

TheLord26
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

shadow summit
# paper pagoda need help with this

Take the log of both sides, $\log(6^{1-8x})=log(7^{x})\(1-8x)(log(6))=xlog(7)$ from there, it’s a simple equation, expand brackets and do the logarithms.

obsidian monolithBOT
#

TheLord26

viscid thistle
#

Can someone verify the equation

#

Can’t go on Desmond

#

Desmos

shadow summit
chilly summit
#

hi i have a problem where i want a formula like:

formula(d, f(x)) = a

where f(a) is the smallest number where the number of digits in f(a) = d

is this possible?

#

for example:
let f(x) = n * (n+1) / 2
let d = 4

then formula(d, f(x)) = 45

because f(45) = 1035, which 1035 is the smallest number where the number digits of 1035 = d ( 4 )

reef hazel
#

can someone help me with this

Suppose a car is travelling 40 feet/sec and it loses control on wet asphalt. How long will its skid marks be?

viscid thistle
viscid thistle
#

And mass?

reef hazel
#

not given

viscid thistle
#

Yeah mb it's not needed

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Well, where are you getting stuck?

reef hazel
#

solving it

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i have to find the "How long will its skid marks be?"

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and the answer should be stated with feet

viscid thistle
#

Please send the complete question because it still seems incomplete. While skidding, is the car still being accelerated? Were brakes applied at that time?

viscid thistle
vapid plaza
viscid thistle
#

I also thought about that too, but it would be better if OP sends the full question

viscid thistle
reef hazel
#

that was the full question

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This is one example j was given

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And this is the Qs

viscid thistle
#

Well, just substitute the values in the given relation

reef hazel
#

I did but doesnt give the right answer

viscid thistle
#

Could you please show your working

reef hazel
#

This when I substituted

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The value

viscid thistle
#

You are substituting the values in the relation incorrectly

#

The speed of the car while it was drifting is given 40ft/s

reef hazel
#

Yes

viscid thistle
#

You have to find the distance d (i.e. the length of the skid mark)

viscid thistle
shadow summit
#

also f(x)=x*(x+1)/2, dont yse n if you say f(x), use x or f(n).

viscid thistle
#

Plot (3pi/8, 0) and (3pi/2,0)

floral holly
#

Hello

viscid thistle
#

What’s the best way to cram for a pre calc test

trim kindle
warm spoke
warm spoke
viscid thistle
#

can anyone help me answer this rq <@&286206848099549185>

warm spoke
#

and with trig functions the x component will be 45m * cos61
the y component will be 45m * sin61

#

make sure ur calculator is in degrees too and not radians

viscid thistle
#

preciate it

smoky pendant
warm oyster
#

preciate it?

smoky pendant
#

is the first one right or do you distribute the expontents and simplify

warm oyster
#

ye it is

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correct

smoky pendant
#

which

warm oyster
#

oh

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ok

#

both seem correct

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but the right one looks more good

smoky pendant
#

alr thanks

warm oyster
#

no problem mrverdevelt_43754

tender questBOT
viscid thistle
#

Can someone explain why this is true:

#

Is it just a coincidence or is there a more general trigonometric relation that explains it

warm spoke
#

i am writing it on the online whiteboard so gimme a sec

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wait i messed up somewhere

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bro screw this i keep messign up the algebra

#

i will find out late

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later

warm spoke
#

and unit circle

viscid thistle
# warm spoke

Thank you, but I was looking for the explanation of this relationship in a more general way. It seens odd to have two arbitrary tangents summing to an integer. I was wondering if there is a more general relation from which this equation is just an instance

shadow summit
vernal pine
#

I think it might still involve Lambert but im not sure

#

,tex $x^2 + y^3 = b^x$

obsidian monolithBOT
vernal pine
#

For b = 2, will there be three roots on the graph?

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Meaning three zeroes

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I know there are, i just need help solving

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Because im stuck on the step:

obsidian monolithBOT
vernal pine
#

And im not sure how to continue

viscid thistle
#

There are actually multiple values of b for which the graph has 3 roots

vernal pine
#

Yes, but this hones in on just the value of b = 2 now

#

For simplicity of the question 😂

viscid thistle
#

Well you can draw the graphs and count the intersection points

vernal pine
#

Yeah, but from like an algebraic standpoint

viscid thistle
#

It may require slight amount of calculus

vernal pine
#

In my guidelines, i am allowed to look at graphs for inspiration, but need to solve this solely without that

viscid thistle
#

From algebraic standpoint,
for x > 0
2lnx = xln2
=> lnx - x (ln2)/2 = 0
=> x e^(-x (ln2)/2) = 1
=> (-x (ln2)/2)e^(-x (ln2)/2) = -(ln2)/2

#

So still you have to use Lambert W

vernal pine
#

Hm, could you perhaps help me tweak this question to be able to solve without using Lambert W

viscid thistle
#

So using intersection points from the graph and some basic knowledge calculus, you can solve this more easily

viscid thistle
vernal pine
#

Hm, would using Lambert W help me solve this question, like get a definitive answer

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Also, do i need an indepth understanding of it?

viscid thistle
#

Yeah

vernal pine
#

Is that Yeah to both questions

viscid thistle
#

But it's not needed for you at this level, use graphs

viscid thistle
vernal pine
#

Thank you for your help

vernal pine
#

,tex $b^x$

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and instead just b

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Would it work?

obsidian monolithBOT
viscid thistle
#

Yes

vernal pine
#

without lambert w*

viscid thistle
#

Because when you will put y=0

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x² = b

vernal pine
#

Yea then i can sqrt easily

viscid thistle
#

Yes, ±√b

vernal pine
#

Do you think that question would be too simple

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Or is it in the slightest challenging

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Thats a stupid question sorry

viscid thistle
#

I mean it depends on context

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In the actual question (not this one), is b just an integer?

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Or a real number?

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If b is an integer, it may become easier to solve

vernal pine
#

I assume b would be an integer

viscid thistle
#

Then substitute values of b and find intersection points using graph

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Yeah so use b as an integer then

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Because for other non-integral real solutions of b, Lambert W would pop up

vernal pine
#

Good to know

#

Thank you

unreal frigate