#precalculus
1 messages Ā· Page 8 of 1
just because the product of two numbers is 1, does not mean either one of them has to be equal to 1
it's called the null factor law for a reason.
Oh okay š
a counter example would be (-1)(-1)=1 or any other number, call x, choose 1/x and we have they multiply to 1, (given x is not 0)
trigonometry was significantly harder
there's just a lot more to remember
but it's also more conceptually loaded, having to learn the unit circle
understand it
Interesting
that would be 1 / cos y which can be rewritten as sec y.
in hindi?
what about post-calc?
Thatās where itās proofs and it gets tricky
the amplitutde will be 2, and the period will be pi
gonna need some more context there chief
hmm no way to just define what this is saying?
i mean
presumably s is a function of some kind, maybe with N as its domain
and A is some number
i just wanna know what each element is saying
and the limit of s(n) as n goes to infinity equals A
we couldn't tell you why this would be true or indeed whether it's true at all, though.
s(n) is a sequence
in this case
yeah
maybe with N as its domain
okay, so s(n) is a sequence
s(n) is a sequence which approaches A
we say that the limit of infinite sequence $a_n$ is (equal to) $A$ if for any positive $\varepsilon$ there exists a natural number $N$ (which could depend on epsilon) such that for all elements of a sequence $a_n$ which are enumerated with numbers starting from some number $n_0 > N$ all such elements satisfy the inequality $|a_n-A| < \varepsilon \\$
in other words all elements $a_{N+1}, a_{N+2}, ...$ are within epsilon distance away from the limit $A$
or rather, taken at face value, the snippet you posted reads: "The sequence s(n) [which the reader already knows about] approaches A."
Transparent_Elemental
so. as n approaches infinity s(n) approaches A
is this really helpful
anyway so what you're saying is you didn't know what the lim notation meant? and your question was about notation and not content?
well both ig
just how each element relates to the other
element...
notation
well here it is, it will take some time to parse it, but it's worth it to understand what limit means
ok let me read it
I suppose you already have at least intuitive notion of what a sequence is
yes
at the very least
you there?
a question
are limits only used when f(x) is undefined?
no
You can tell from the equation the x intercept, y intercept and gradient. Write those down and compare to the graphs š
what program is this
i finally get it
took me a while to visualise it but damn it actually fit in my head
anyone know good resources based on how my class is structured?
Chapter 1: Functions and their Graphs
Chapter 2: Polynomials and Rational Functions
Chapter 3: Exponential and Logarithmic Functions
Chapter 4: Trigonometry (Basics)
Chapter 5: Analytic Trigonometry
Chapter 6: Applications
Chapter 7: Systems
Chapter 8: Matrices
Chapter 9: Sequences and Series
Chapter 10: Analytic Geometry
Doing math corrections, can anyone explain how to do 16, 17, or 18? I need it for tomorrow
mine was set up a bit differently last year since the 2nd half seems a bit different compared to the Units we had, but pauls online math notes would probably work although cant guarantee the units will be in order
anyone tryna vc and help me out?
goodluck finding that here
how
I think pre-calc is like the junk drawer of the math classes. It's got a lot of useful things, but they're just kinda all thrown into one drawer of "this is useful, but I don't know where else I could put it."
Literallt
no complex numbers?
Did that last semester this is for this semester
oh i see
i wonder, what year do u take pre-calculus
we have different systems where im from so im trying to understand the concept better
i'm in 12th grade taking precalculus
most people seem to take it 11th though
I'm a 10th grader and I take precalculus
there's a 9th grader in my class but all he does is use photomath on assessments
idek how our teacher hasnt caught on yet
considering its name sake is just "before calculus" and not connected to any one section of mathematics, I guess it's to be expected
Thatās the normal curriculum some people are 1 year ahead and even more 2 or 3 years ahead
So thatās why
But youāre just where you need to be
As early as you wish; if you get stuck, go back and review your knowledge
Better to be familiar with precalc concepts sooner rather than later
Don't try to ping everyone for math help please... it doesn't work and it's not appropriate
Bro really told 130000 people to join vc
and only 4 came
guis
why do we complete squares.
sorry if its a dumb question
i know how
i just wanna know why
till now ive only done it because book tells me to
because it simplifies the expression
e. g. show that the expression 2x^2 + 5y^2 + 6xy is greater or equal to zero for any x and y
it converts expressions to an equivalent form from which certain info may be more easily obtained
Write an equation for a cosine function with an amplitude of 1, a period of 4pi, a phase shift right of 5pi/6 and a vertical shift up of 3.
What would that be^?
asking for the answer here doesnt really benefit anyone
This trigonometry video tutorial focuses on graphing trigonometric functions. It explains how to identify the amplitude, period, phase shift, vertical shift, and midline of a sine or cosine function. In addition, it discusses how to graph sinusoidal functions using transformations. The graphs of tangent, cotangent, cosecant and secant are cov...
this is helpful
there are 2 general ways of plotting. The first is to follow transformation steps, ie horizontal compression with the A in the expression. The 2nd is to locate certain points on the graph like max or min and connecting the dots
how do i know what kind
?
does anyone have a recommendation for a precalc textbook?
Someone help me
I tried solving it many times
But my answer doesnāt match the final answer
We can factor out cosĪø, and we get cosĪø(cscĪø - 2) = 0. Now we can see that either cosĪø is 0 or cscĪø - 2 = 0. The only values of Īø that make cosine 0 and are within the bounds are pi/2 or 3pi/2.
If cscĪø - 2 = 0, then cscĪø = 2. We can substitute cscĪø for 1/sinĪø, which gets us 1/sinĪø = 2, or sinĪø = 1/2. The only values of Īø that make this true and are within the bounds given are pi/6 or 5pi/6. So our final answer is Īø = pi/6, pi/2, 5pi/6, or 3pi/2.
Am I doing this right?
not the five part
oh nvm im stupid
its 1/2 or 2
smh u wrote cosx=1
oh nvm 2 doesnt exist
š oh
Youāre right
cos x = 1/2 cos x = 2
you got it right mostly except the last part
Thank you
np
I fixed it
well done
what's people classify as algebra 2 or equivalent covers mostly the same stuff
khan is a decent place to start
Hello, can someone explain to me why arctan of -1 is pi over 4? In my head, I'm thinking it would be 7 pi 4 (going off of a unit circle) with consideration to the tangent restrictions. I'm guessing since 1 is negative, I should start clockwise?
because the range of arctangent is from -pi/2 to pi/2, 7 pi/4 is bigger than pi/2
so arctan(-1) is some number between -pi/2 and pi/2
specifically it's a number x such that it's tangent tan(x) = -1 given the constraint on the range of arctangent (and hence domain of this equation)
and the angle there isn't pi/4, but negative pi/4
7 pi/4 describes the same angle, but as I said it's outside of range of arctangent
Thank you for answering. I think this makes sense to me now.
cot - root 3 is - pi over 6*
,calc -pi/3-pi/6
Result:
-1.5707963267949
jedben2
can someone teach me calculus from beginning i have to do hc verma
lmaoo idt anyone is going to do that
you could try learning some stuff on the internet or asking for some resources and coming back with more specific questions š
ok
email hc verma to teach you
š
lmao
three blue one brown is good
on youtube
he provides some pretty intuitive explanations for all the rules and stuff
intuitively understanding maths is like always helpful on top of concrete proof and stuff
at least for me so far lol
and btw this is precalc channel i just saw
Got a 96% on my precalc midterm exam
Is your name really Ryan Chapman? Thereās a philosophy YouTuber with the same name. Congratulations btw on the score!
Yeah that is my name lol
what do you guys advice me to learn before precalculus?
know your algebra
like moving around stuff in an equation should feel natural to you
so pre-precalculus
3blue1brown
Blackpenredpen
The organic chemistry tutor
Eddie woo
Are all good youtube channels for those new to calculus. Although they also cover more advanced stuff as well.
if a cubic graph has 0 as a function what does that do to the solutiobn
Hey, can I ask a simple question about limits?
It's really simple, it will take 2 seconds, I promise.
I did. it's in help-27
It's not even a problem really, i'm just confused over some definitions.
@viscid thistle try Professor Leonardās Lectures on YouTube too
If you want something more like a classroom experience
Pair that up with Paulās online math notes
LMAO I watch the organic chemistry tutor for chemistry like periodic trends stuff I saw from him, I see math Olympiad questions from blackpenredpen others I don't know
Okkkk
Yo, do you learn integration during precal or is that reserved for only calculus?
yea but in the last chapter.
in what dimension are yall learning integration in precal wtf
Lmaoo
In my high school introduction to limits and continuity is included at the end of precalc
lmao what
Anyone good with unit circle stuff
If you have a question, just ask; the worst thatāll happen is that you get ignored completely
@harsh vale
@grizzled citrus
note that after
$$\br{x+\frac1x}^3 = x^3 + \frac1{x^3} + \underbrace{3x + \frac3x}_{3\br{x + \frac1x}}$$
$$f\br{\red{x+\frac1x}} = x^3 + \frac1{x^3} =\br{\red{x+\frac1x}}^3-3\br{\red{x+\frac1x}}$$
and hence
$$f(\blue{x}) = \blue{x}^3 - 3\blue{x}$$
āamonov
Oh, I just sub -1 on the second function to get -1 + a - b + c then do the same thing on the first function to get -1 -3(-1) from x³ + 1/x³
that's normal
you even do some linear algebra in high school at my place, it's not too abnormal but yea
easy
if you replied to mines, ya duh, its high school math; not meant to be hard lol
Well hello
Yeah, only a total of seven messages from you
oh damn ya
Iāve been introduced to derivatives but my math textbook sucks because it doesnāt have enough optimization problems which is my weaker side. Do you have a good source for harder problems for free?
Albert.io, Khan Academy, or just make up your own problems
yo, does anyone have any recommendations for pre-calc textbooks
aops book or even this website
nvm that website has been take down
lol
it was a illegal website
lukcily i downloaded the books but cant share here as file too big
š§ šø
does OpenStax have any?
$$\trig$$
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$\trig$
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@viscid thistle what are you trying to achieve?
literally nothing
i didnt even mean to do that in this channel
i wanted to do it in #latex-testing
I missing the day we learned about polar coordinates with squares. Can someone help explain this to me?
well not illegal but the internet says otherwise. its libgen
usually, illegal websites like free movie websites are only illegal if you download any movies. i think it should be ok as long as you use a vpn. or so im told.
im not sure if the same thing applies to libgen
Guys, is the general formula of a circle and graphing it considered as pre calculus?
So it has to be unsolved
What is calculus anyways. I'm still quite new to algebra so I don't know what Calculus is all about
Im not sure lmao
I dont even know what algebra is to
Its like we use coffe and water and not knowing anything about the differences lmao
06
Or i am not sure what u r asking
Like r u on secondary hs?
Idk man im not sure what other countries education system is using
O
Im grade 11
Someone who is 16 year old
And has one year left of high school
Which is at grade 12
Ohhh
Yessir
Im 1 year behind you
So which country do you live in?
calculus is applied real analysis
real analysis is about looking at real valued functions
do you know pythagoreas
What makes you think someone who is new to algebra, and asking about what calculus is, will understand what āapplied real analysisā and āreal valued functionsā means
if you substitute a limit, and it outputs a non undefined answer, will that always be the answer to the limit
though the value at f(x) can be different from the limit of f(x), so should I verify the limit with other methods to make sure?
or is substitution not calculating the value at f(x)
value of f(x) at a point has little in common with what the limit at a point is
and substitution calculates value of f(x)?
and as I said earlier if you compute a limit it is not possible for that limit to have two or more different values
what
you can directly substitute only because 5x+2 is continuous everywhere and at x=-4 in particular
should I skip substitution entirely if it only works sometimes
except for simple limits like this
I never said that
well for a more difficult limit you're not going to be able to directly substitute anyway
because you won't get any meaningful result
so does this mean, if substitution gives a solution to the limit, then you don't have go any further with solving the limit?
just want to make sure
hmm
yes
thank you
(z+1)^5 = z^5 implies |z+1|^5 = |z|^5
Which would imply |z+1| = |z|
Then write z=a+ib
This would imply (a+1)^2 + b^2 = a^2 + b^2
Thus, (z+1)^5 = z^5 has no solution
This is definitely wrong
But I can't see where the argument fails
We're over C
Wait, I'm not familiar with these but taking the 5th root on both sides gets you z+1=z. I dont think there is a solution to that. Is this a viable method?
"The fifth root" doesn't make sense for complex numbers
It does have solutions over C
Ah I see. Ok
I'm an idiot lol
(a+1)^2 + b^2 = a^2 + b^2
This has solutions
Ignore everything
Fundamental theorem of algebra still works
Can someone please explain for me why when a plane intersects the vertex of a cone we have a degenerate conic section? In terms of rotations and stuff
Just learned rationale zero therom today. Professor said "look only 23 possibilities"
exchange x with -4
transform csc(x) into sine
what can you say about sin(-x)
no clue \
how can you express sin(-x) using sin(x)
how do you cancel off an absolute function like this?
what is the sign of x+7 when x approaches -7 from the left?
Can someone explain this briefly?
Brother this is calculus not precalculus
Ok I'll ask in the Uni chat. I'm not from the US and this is a part of our high school curriculum. I'm not really familiar with your terms of pre calc vs calc etc
Construct a triangle
Hope it's not too late but I think it should be 18/x
how come it 18/x
because the height of the ladder is 18ft
np
here are some cool precalc notes i took #8 and #9 (sorry i forgot to post)
@lucid trench Your notes are so neat holy
Yeah, but do they understand the concepts>
Bro those notes are god tier
pov me in algebra
of course
Nice pfp
ty
godly notes , best ones I've ever seen
multiply numerator and denominator by x
these type of notes get you straight Cs
bro the handwriting hater
the penmanship police
Taking pretty notes is honestly a bad habit, I know cause I used to do it
The return on investment (the investment being time) is super low
But this is really funny though, I chuckled
hey i need help with how to start this, this is an exponential problem, it aint homework just extra stuff
basically exponential growth and decay stuff
ok so the paper is .75 mm thick
and when you rip it, you have two pieces with a thickness of .75 mm
so stacking them would double the height of the stack
repeating the process will double the height again
until you've done it 50 times
yes yes alright i got it
now what kind of equation you use for that? i mean i know there are a couple
okay
How do you spend your time more effectively in class?
First of all, you pay more attention. And especially in Math and Physics, try to visualize and analyze the steps you are learning. Try to figure out if there are any other methods and etc. And take notes without without that much time.
Can someone check my work? \
Find: $D_{f\circ g},$ given $f(x)=\frac{x}{x+5}, g(x)=\frac6{x}.$ \
$$R_g \subseteq D_f \implies \frac6{x}\neq-5 \implies \textcircled{1}, x\neq -\frac6{5}.$$ \
$$\because D_{f\circ g} \subseteq D_g$$ \
$$\textcircled{2} \therefore x\neq 0$$ \
$$\textcircled{1} \cup \textcircled{2} : D_{f\circ g}={x \mid x\neq 0, x\neq -\frac6{5}}.$$
Anonymous_H
I got 5697.25
5679, 5697.25 isn't an integer
Ah, I didn't even see the whole number part, but is my answer correct?
Yes
Is it 5679 or 5697?
5697
Ok thanks
Actually wait
@brisk pasture
That's wrong
On the first day the viewer count is 1590
It only then increases by 20 percent for the next six days
I already sent it
It's 4202
Bruhh
Just say to your teacher that you made an error and show your work
how'd you get that?
1590*1.2^6
wow Math classes are reaching out to gen z hahahahaha
?
this is sarcasm
we do not give answers here @icy merlin
Can you rewrite the question
No where. This is a place to learn and expand your knowledge and not a place of freebies
well supposedly the heading for your question d) which I'm assuming is part of question 1 would describe the type of method that would be used to solve that
and also this is calculus, not pre-calc
love the frog lol
wow those notes are so neat jeez
how do you calculate this exactly
huh?
the limit is 4/3 but how do you end up with that
Well, if you were to directly substitute it'd make the whole expression be 0/0, indeterminate form. That means you're able to evaluate the following by using L'hopital's rule. \
$$ ,If, \lim_{x\to a}\frac{f(x)}{g(x)}=\frac0{0}, \frac{\infty}{\infty}, then:,$$
$$\lim_{x\to a}\frac{f(x)}{g(x)}=\lim_{x\to a}\frac{f'(x)}{g'(x)}.$$
That should be in #calculus but pre-calculus
Anonymous_H
much appreciated
š
will keep note
I know this is true, but how do I "show" that it is true?
mathematical expressions do not change if you use different letters
@lucid trench tysm!! Your notes are great
You should ping me whenever u post notes
I'm jowo
fully aware, i just was curious how i would show understanding in my answer rather than writing "they are the same." i ended up just writing that they both produce the same values in a table and the same graph.
l'hoptials
L'HƓpital = bad
kappa
No, not even if you fix k=2.
(That gives one of the prototypical examples of a lacunary function, which is too ill-behaved in the complex plane to be described by a nice closed expression).
Thanks
factoring out cosecant
for number 4, i got cos^2x instead of 1-2cos^2x
is the answer key wrong or can somebody explain why the answer of 2sin^x - 1 is right
for number 4?
act. 2sin^x - 1 =1- 2cos^x
cause 2sin^x - 1 =sin^x+sin^x-1=sin^x+(sin^x-1)=sin^x+(-cos^x)=sin^x-cos^x
1- 2cos^x=1-cos^x-cos^x=sin^x-cos^x
how can i find the monotonicity of function f(x)=(x+4)/(x+1) ?
The typical systematic approach would be to look at its derivative, but that's hardly a "precalculus" solution...
I have no idea, I just practiced a lot and remembered
Thanks
The left should be sin theta
Ye
I'm not sure about a method, I usually just base it off of patterns
Ig you could rewrite the equation as tan theta=1 and then take the inverse
Wait are there more answer choices not shown here?
I get how pi/4 and 5pi/4 are answers but not pi/2 and 3pi/2
But pi/2 is a 90 degree angle
yes yes
i think
um
that
the sin, cos, or tan oif something is equal to 90*
then convert to radians at the end
thats what you do
Idk it doesn't really concern me anyway
its alright thank you though
Np
a pair of common factors was cancelled out from the top and bottom
Factored out the four to cancel out the factor pairs
if I am given a quadratic, and 2 factors, how would I find the intercepts?
Set the 2 factors=0 and solve for x in each
Set the factors equal to zero
You want to convert degree measure to radian measure?
so if I have (-3x+7)(x-4), I just set (-3x+7) = 0, and (x-4) = 0and solve for both x-intercepts
Yes
coolio thx 
Yes
if there is no denominator to a function, does it automaticely make it unrestricted?
no
example: f(x) = ln(x) it is restricted to positive real numbers since ln function is undefined for x <= 0. There are other undefined things than division by zero
Pretty sure it's based off of cos^2(x)+sin^2(x)=1
Which can also be expressed as 1+tan^2(x)=sec^2(x) and cot^2(x)+1=csc^2(x)
im lost on all of these but just 41 for now 
iām supposed to do 41-54 but the textbook and teacher arent much help
,rotate
ln(a/b) = ln(a * b^-1)
Yo guys
Need help on this one
It about principle of mathematical induction and stuff
for any shape, given that the surface area increases by x cm squared per second and all, and the formula for surface area is S, how to find the rate of change as a general formula ?
Show n=2 works then do induction step with algebra
Doesnāt seem like precalc tbh
Hello, I wnated to ask a question about the domain of an inverse function
Can I send a picture of the problem?
Sure but I can't guarantee I'll be able to answer it
so this is the answer
but
originally i put that the x cannot equal 2
but that was wrong apparently. So what is this domain
domain of what
the inverse function
everything besides x = 2
or did i solve it wrong
i may have solved it wrong
oh
i put a negative on 2x
wait no
i think iām right
alright i just forgot to write a negative
is there a way to find local minimum and maximum values algebraically?
Dont need help with anything just wondering if it is possible
Without having to use a table and waste time
by showing that the function is bounded above/below by some value and then constructing a point which achieves this bound
or by taking first derivative and finding extreme points, if you can solve the resulting equation
Quick question but if in a fraction, if the numerator and denominator are both negative, is it correct to simply them to a positive fraction even though the fraction hasnāt been evaluated?
https://youtu.be/QP0inFktTOo
found this video helpful on determining a limit of a rational function
The video shows how to evaluate a limit.
What are some good online sources to learn and master precalc?
yoo, is that sqa exam type ques,,???
how would I do this?
When a function is described like this: f : R x R -> R, does it means that its domain is R x R and its range is R?
what your definition of range
hmmm
kinda ambigious but i think of it as the set of what f(x) equals to for all x
ok do you know what a codomain is
ive heard of it
but idk what it is exactly
its the set of allowed outputs
as opposed to the range which is the set of actual outputs
when writing f:A->B, A is the domain and B is the codomain
thanks 
ill search some more about codomain
RokettoJanpu
the domain and codomain is R. the range is [0,infty) which doesnt equal the codomain R
$\trig$
RokettoJanpu
Have you studied limits with graph interpretation
kind of. I got DNE, 1, and -3 for a b and c
idk if they are correct
do you know what the rest would be
would it be 0
Are you guessing
is finding zeros with the quadratic equation the same as completing the square
yes, I dont know how to do this
Okay, so, what is the defined function value at x=1
so b is 1?
Yes,
A doesnt exist correct?
Correct
thanks, how would I do d?
Do you see that minus sign above the number?
Called a superscript
The question is asking you: What function value is the function approaching to from the left of 1
The minus indicates that you are approaching from the left side
And what do you think a plus sign will indicate?
approaching from the right side
I think its -3?
is it the value on the x axis?
Yes, you're approaching 1 on the x axis, and what is the limit as you approach 1 from the left side of it
Basically, to what function value are you approaching to as x-> 1
from the left side
would it be -1
No, okay, look at (1,0)
yes, there is a hollow circle
The question is asking you, what is the function value approaching to as the domain of the function approaches to x=1 from an infinitesimal distance
I'm going to draw it out for you, so you can see
OH its 0
Yes, there we go
lets go
Finally
I believe e must be 0 as well?
Do you know what a hyperbola is?
yes
Okay, so, do you know the behavior of it as the domain extends far out to positive infinity?
[1,infinity) ?
okay
It's an asymptote
yes, i understand
That means, that there is an infinite discontinuity for that function at x=1
okay
So, the function will approach to positive infinity from the right of x=1
and negative infinity from the left of 1
yes
Do you understand why that is?
so would the answer be infinity?
im sorry, Havent taken any math classes for over a year so im braindead
Okay
Take 1/x-1
And take some infinitesimal number to the right of one
like 1.000000000000001
okay
and take an even smaller number
1.000000000000000000000000000001
and continue this
@woven roost Don't actually do this
This is basically intuitive
yeah I get it
But, the point is, the closer you approach to 1, the larger your result will become
okay
oh
so why would it be 0 from the left? and why not negative infinity
because its in one piece right?
Both work, but I prefer positive infinity
More discrete
than just saying "dne"
Okay, now, try problem f)
is it a numerical answer
Can't tell you, you figure it out
so its as x approaches negative infinity, the numebr gets smaller
Where is the function approaching to as x gets innumerably large
in the negative domain
What is the approaching function value as the domain of the functions approaches to greaters negative numbers?
that is 1 on the y axis
so the answer is 1?
Yes
okay finally last one looks too confusing i got no clue
For this one, you can just plug in 0 into f(x)
OH
so that comes out as 0
and what is the approaching y coordinate as x approaches to 0
1
im getting -4
Yes, it's 0
thank you very much, was a lengthy assignment lol
if I'm trying to find the points of intersection between 2 functions, would I just combine the 2 and solve for x?
What kinda functions are they
Cuz you can just solve for x like you said
Then just plug the x values into the function thatās intersecting
Or any
To find the points where they intersect
linear
coolio thx
Np
is "Pre-university" like when your still in normal school?
Yeah like high school
Lol
He hasn't learned calculus yet, so it must be pre-calculus. Simple.
ez
You did the problem?
(sighs at bizarre American naming of school subjects)
nah i was responding to tropo
Oh
lul
So my instructions didnāt work or
didn't say that
Prolly pre algebra
what's your level
ok
Have you even asked a question yet?
Hurt did
for all we know he could be the only PDE solving middle schooler
I answered it
Oh, I meant, its difficult to tell which channel RoastedChicken's question belongs in when we don't know what it is he intends to ask.
Npnp dog
the question has a quadratic and a linear to find the points of intersection for
write what it means for two functions to be equal at a point
I think it's asking for the points of the secant line, but i'm not sure how to find those
find points of the intersection of two functions
secant line
huh?
it's quite literally plugging in the definition of f(x) and g(x) and solving for x
one is a quadratic, one is a linear
I interperated it as, when you graph each function, what would be the point of interseption. but now that i'm re-reading, there isn't even a possible secent line.
If there was something related to secant lines, the task would mention them
Would love a crack at this. Share answers after? If up for it.
isn't this cal?
Wdym
what math are you in
Calculus
And combinatorics
Actually In my country, you need to study a lot of stuff in high school
Which are mainly college level stuff in other countries
Finland got the best education system dunno what these other countries doing
Everyone should copy them
Having the best education does not necessarily intel the greatest outcome
Yes.
Solid point
It's a defined point
It's a graph
It can be a hollowed out or a defined point
A limit is defined as something that one is approaching to
A point is just a point
There is no left or right domain that extends from the point
Hold on, what grade are you in
No, I mean, what grade are you in in school?
What math class did you have in your senior year?
Thanks for sharing š
A function that approaches to 2 from the right side
so a line?
If that line holds true for the other questions in the problem set, then yes
im thinkng that The points (1,2) and (1,1) are graphed as solid circles to represent the limit as x approaches 1 from the right and left
for d and e?
They can be open circles, the question doesn't specify which
okay, so for e, is there a horizontal line that goes from the asymtote, to 1,1?
asymtote at x=-1
There's a jump discontinuity at x=1
Because from the left, it's approaching to 1
and from the right, it's approaching to two
Oh, you said negative one
hold on
does this make sense as an answer for the whole thing
Thing is, the questions are so ambiguously stated
yeah, there are many possible answers
Because b) the graph can have a negative range
and also a positive range
It doesn't specify to which "infinity" it is approaching to
a positive
or a negative
does my graph seem reasonable though
I'd have to look at it later, I have to run now
Perhaps ask transparent
He can help you
no
you didn't cover half of the questions
oh
and even while f(2)=0 is correctly drawn you didn't put an empty circle on the graph to show that it's not continuous there
yes
I don't get what else I'm missing
I can tell there isn't anything on the left side of the asymtote
b), c), f), h)
I put b as an asymptote on x=-1. You can't really see it
And c is the point on 0,-1
F is the dotted line spanning from x=-1 to x= 1
Idk about h
@summer ruin you here
so 2 lines coming from the right?
like where should i plot it
it's already plotted I guess
oh really
but f) is not quite done
recall the definition of continuity from the left in a point
or from the right for that matter
yeah. i dont understand how ill do that with the asymtote blocking the way
this has nothing to do with the asymptote
oh
asymptote is not even in that region
do i need to plot a solid point at x=1?
is f the last one i have not done
I don't know what your asymptote looks like
it is what I did for the question b) i plotted a vertical asymtote at x=-1 spanning infiniteley
what does that mean
i put a vertical line at x=-1
yo you there
<@&286206848099549185>
i dont want to start a new conversation with someone new
well that would be wrong
have you ever seen an asymptote
yeah, it is a line where the function cant cross
invisible line
that's not true
sin(x)/x has a horizontal asymptote at y=0 which it approaches as x approaches infinity
yet sin(x)/x crosses it's asymptote infinitely many times
oh
so in this case, i am able to plot the line through this asymtote?
and hardly drawing it as a vertical line is accurate
you're asked to draw a function
which meets these properties
okay
what would you suggest I fix
bro im losing braincells
7 hours at this
look at how any other asymptotes look
the exercise is not about drawing everything in some precise way
which you seem to be trying to do drawing straight lines
okay, does the asymtote exist at x=-1 though?
what do you think based on limit f(x) = infinity as x-> -1?
its negative 1
so this graph seems right now
im actually nauseous now
why is your function going to negative values if the limit is infinity
you should also draw what it behaves like as it approaches x = -1 from the left
i dont get it, do I need to make 2 lines that look like a mirror image on each side of the asymtote?
that curve up?
yes, though not necessarily mirror image
what do you mean
left continuity
oh a hollow point at -2,1
?
Ohh do you mean I should extend the line that cuts off at 1,1
what
function f evaluated at x = 1 outputs a value of 1
because it says that f is continuous from the left at x = 1
Okay... so what do I need to do
Thanks for the help btw
think about what's wrong with your current drawing
and why it doesn't meet the left continuity at x = 1
Because its discontinued
that's too broad of a reason
there are discontinuous functions which are left continuous
no
that actually didn't change anything
do you want me to change what I already have or build onto something
can you markup edit it and show me
I want you to look up the definition of left continuity of a function at a point
the change is so small it's not even worth trying to give a hint because that'll be the entire answer
is it changing a hollow circle into a solid one
is that it?
rest is good?
yes
alright, thanks man
even though the function spans from [-5,5], I can have a solid circle connecting? in the center?
how are these concepts even related
im confusing 2 things arent I
I don't know
anyways, thanks
for radical functions with an even root, the domain is only restricted by what produces a negative radicand?
ex. f(x) = 4 sqrt(x+1) - 3
isolate radicand into inequality
1. x + 1 >= 0
2. x >= -1
that is proper work for finding the domain here?
yes
how do you calculate this?
The exponent is the same in the numerator and in the denominator
So take the ratio of the coefficients
And that is 81
and 3 to the 4 is 81
,rccw
have you done part a?
!status
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
highlight in red
since the division have the same base why is it -n+(n-1)
Instead of 2^n-1-(n-1)
read the text book
for your class they usually help and give out example how to do each problem and variation
of each problem
Uhhh im confused
What ariah walking got to do with this
Thats as close as i can get
Hmm, the exercise appear to make most sense if you assume that the boat's velocity relative to the water stays the same before and after it "encounters a current" -- even through I'm not sure that's a particularly realistic assumption.
I would understand it as saying
- the water moves with a velocity of (12,7) relative to the Earth
- the boat moves with a velocity of (0,35) relative to the water
- Ariah moves with a velocity of (-5,0) relative to the boat
and you're supposed to find (the magnitude of) Ariah's velocity relative to the Earth.
Unsure about books but ask your professor for the recommnded book
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Got my first Pre Calc exam this Thursday wish me luck!!! Im feeling pretty good going into the test.
Guys i reqlly need help with this problem Proving trig identities pleaseee help me now with steps or imma fail soonššš
Butterfly rule
Tysm
bad typesetting 
$\sin(y) = \floor{\frac{\sqrt{1+x} + \sqrt{1 - x}}{2}}$
Ryuzaki
<@&268886789983436800> spamvertisement?
Another way would be to replace (1-cos(x)^2) with sin(x)^2 using the pythagorean identity
You don't need all the information in the problem there. What is the simplest way you can imagine to find out what n is?
For both ones.
wait how is the second one 7?
I mean, it's the same expression for both parts of the question -- n doesn't vary between them.
When you know n, you can apply the binomial theorem to (5x+4y)^n.
so its (5x^2 + 4y^5)^7
No.

