#geometry-and-trigonometry | Mathematics | Page 356

trim breach May 27, 2021, 9:02 PM

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Yes!

haughty eagle May 27, 2021, 9:02 PM

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ok thank you

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and to check b is 12.6

trim breach May 27, 2021, 9:03 PM

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Yes.

haughty eagle May 27, 2021, 9:03 PM

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thanks

trim breach May 27, 2021, 9:03 PM

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Assuming you are told to round to tenths.

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No problem — glad to help.

upper karma May 27, 2021, 9:19 PM

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any one know this

trim breach May 27, 2021, 9:32 PM

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upper karma

Work with what you are given. You have three side lengths and only one congruent angle. Some of the options are not even ways you can prove similarity.

edgy juniper May 27, 2021, 10:11 PM

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i need help 🥺

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i thought this was trapezium
and i learned it was 1/2 x ( 5 + 3 ) x 7

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but that = 28 and when i looked at the answer it says 31

silent plank May 27, 2021, 10:17 PM

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the is a shape composed of a trapezium and rectangle

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conveniently split by the dotted line

edgy juniper May 27, 2021, 10:18 PM

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ah

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so i do rectangle and trapezium and then add them together?

silent plank May 27, 2021, 10:18 PM

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yes

edgy juniper May 27, 2021, 10:19 PM

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silent plank yes

thanks

upper karma May 27, 2021, 10:41 PM

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trim breach Work with what you are given. You have three side lengths and only one congruen...

thanks but i already solved it before seeing your msg

upper karma May 28, 2021, 1:28 AM

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hello

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can someone finish off my gr 12 data?

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assignment

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please

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i only have till 11

fathom flame May 28, 2021, 2:33 AM

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the axes in an ellipse are always perpendicular to each other and bisect one another, what would the axes share then? i said center but im not 100% sure

manic crown May 28, 2021, 8:58 AM

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What theorem in geometry guarantee us that the chord of a 40° angle is less than than the chord of a 20° angle

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I mean it's painfully obvious that it is but is there any theorem

silk patio May 28, 2021, 9:05 AM

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It’s the sine rule

dark sparrow May 28, 2021, 9:05 AM

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sine is increasing on [0,pi/2]

manic crown May 28, 2021, 9:07 AM

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I am reading a book on trigonometry

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And this is the first chapter questions

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I am asked to prove if we drae any central angle, the double it . Will the chord of the double angle always be less than twice the chord of the original angle

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haughty spire May 28, 2021, 9:12 AM

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@manic crown here https://math.stackexchange.com/questions/1601606/will-the-chord-of-a-larger-central-angle-be-longer-than-the-chord-of-a-smaller-c

Mathematics Stack Exchange

Will the chord of a larger central angle be longer than the chord o...

"In a circle, suppose we draw any central angle at all, then draw a second central angle which is larger than the first. Will the chord of the second central angle be longer than the chord of the f...

silk patio May 28, 2021, 9:31 AM

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It’s less cause of triangular inequality

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Draw a little triangle

dark sparrow May 28, 2021, 9:31 AM

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manic crown I am asked to prove if we drae any central angle, the double it . Will the chord...

let O be the center of the circle, mark off three points A, B and C on the circle in ccw order s.t. angles AOB and BOC are equal (and call their common value θ)

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arc AC subtends an angle of 2θ

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the lengths of segments AB, BC and AC are crd(θ), crd(θ) and crd(2θ)

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AC < AB+BC by triangle inequality

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...okay so i took the radius of the circle as 1 but this makes no meaningful difference

silk patio May 28, 2021, 9:37 AM

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I really like this, it shows sin is less than linear

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Like a concave function

dark sparrow May 28, 2021, 9:40 AM

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less than linear is stronger than concave i think

edgy juniper May 28, 2021, 12:56 PM

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r means perimeter right

dark sparrow May 28, 2021, 12:59 PM

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no

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r means radius

edgy juniper May 28, 2021, 12:59 PM

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oh

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whats the perimeter

dark sparrow May 28, 2021, 1:00 PM

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?

edgy juniper May 28, 2021, 1:00 PM

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it asked me to get it here

dark sparrow May 28, 2021, 1:00 PM

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,rccw

somber coyoteBOT May 28, 2021, 1:00 PM

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dark sparrow May 28, 2021, 1:00 PM

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okay so do you know how to find the circumference of a circle?

edgy juniper May 28, 2021, 1:00 PM

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yeah

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and the area

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but it never told me about perimeter

dark sparrow May 28, 2021, 1:01 PM

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the perimeter of a shape is the length of its outer boundary, if such a thing makes sense to talk about

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which it certainly does for a circle

edgy juniper May 28, 2021, 1:03 PM

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dont think i understand

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wait is perimeter the same as circumference?

dark sparrow May 28, 2021, 1:10 PM

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for circles yes

edgy juniper May 28, 2021, 1:10 PM

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ok

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thanks ann

languid frigate May 28, 2021, 1:16 PM

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hello..was wondering if someone could help my little sister in this parallelogram exercise

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I'm having trouble figuring this out as well lol.

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∠EHO = ∠OPE, AFAIK
HE = PO, AFAIK
for 3, segment HP = EO, is this right?
because if my assumption in #3 is correct, then the question number 4 doesnt make sense to me
i get a different answer
segment HP = 24 units, based on the diagram

dark sparrow May 28, 2021, 1:20 PM

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no, HP isn't necessarily equal to EO

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you will need to find the values of x and y to calculate the length of EO

languid frigate May 28, 2021, 1:22 PM

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if point S is the center, then HS = SP, is this right?

dark sparrow May 28, 2021, 1:22 PM

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yes

languid frigate May 28, 2021, 1:22 PM

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then that would make ES = SO

dark sparrow May 28, 2021, 1:23 PM

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in a parallelogram, the diagonals split each other in half

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yes

languid frigate May 28, 2021, 1:26 PM

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ohh, poor eyesight XD...now I know why, it was 3x - 6, not 3x + 6

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thank you very much!

edgy juniper May 28, 2021, 1:31 PM

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to get the perimeter of a semi circle, isnt it just the whole circle divided by two?

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i did 3.142 x 20 % 2 = 31
but the answer tells me its 51

haughty ore May 28, 2021, 1:32 PM

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almost but if you are dividing a circle in half you would be missing one part

edgy juniper May 28, 2021, 1:32 PM

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hmm the center?

haughty ore May 28, 2021, 1:33 PM

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so this is how half a circle would look like right

edgy juniper May 28, 2021, 1:33 PM

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yeah

haughty ore May 28, 2021, 1:33 PM

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so then you need to?

edgy juniper May 28, 2021, 1:38 PM

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add the line?

haughty ore May 28, 2021, 1:39 PM

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yupp 🙂

edgy juniper May 28, 2021, 1:39 PM

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oh cause it becomes part of it, so it would be 31 + 20 = 51 right

edgy juniper May 28, 2021, 1:40 PM

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haughty ore yupp 🙂

thanks ❤️

haughty ore May 28, 2021, 1:40 PM

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good job 😄 my best tip for geometry courses is to just draw everything and try reason from that. at least that helped me alot

edgy juniper May 28, 2021, 1:40 PM

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good idea

arctic edge May 28, 2021, 3:08 PM

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does anyone know how to approach this problem i think it is something to do with soh cah toa but im not very good at that could someone explain how

silent plank May 28, 2021, 3:20 PM

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apply the most basic formula for area of a triangle

arctic edge May 28, 2021, 3:23 PM

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im dumb just realized

haughty spire May 28, 2021, 3:31 PM

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lol

upper karma May 28, 2021, 4:31 PM

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hello everyone i am new here i just came now can anyone tell me what are we discussing

hollow plank May 28, 2021, 4:31 PM

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nothing

upper karma May 28, 2021, 4:31 PM

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ok

hollow plank May 28, 2021, 4:31 PM

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basically we just wait for people to ask doubts

upper karma May 28, 2021, 4:32 PM

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oh

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u all are in high school

hollow plank May 28, 2021, 4:34 PM

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arctic edge does anyone know how to approach this problem i think it is something to do with...

the information that the obtuse angled triangle's area is 144 is unnecessary to solve this question

hollow plank May 28, 2021, 4:34 PM

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upper karma u all are in high school

some are

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some are in middle

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some in college

upper karma May 28, 2021, 4:34 PM

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ok

velvet valve May 28, 2021, 4:46 PM

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Anyone know this?

hollow plank May 28, 2021, 5:00 PM

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use tan x

shut venture May 28, 2021, 6:36 PM

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cosine law

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2 equal sides and an angle inside

tiny vessel May 28, 2021, 6:39 PM

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velvet valve Anyone know this?

you could special right triangle

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angle R is 45

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so as angle S

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length is 7 square root of 2

upper karma May 28, 2021, 6:43 PM

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is this supposed to be
(1,6)
or
(-1,-6)

Screen_Shot_2021-05-28_at_8.42.48_AM.png

upper karma May 28, 2021, 7:14 PM

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a plane is at an altitude of 822m trying to land. The angle of depression towards the airstrip is 8 degrees. since there are too many planes on the first runway, the aircraft must land on the next runway which is triggered at a 7 ° depression angle to the aircraft. What is the distance between the two airstrips

trim breach May 28, 2021, 7:25 PM

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upper karma a plane is at an altitude of 822m trying to land. The angle of depression toward...

Did you sketch the situation yet?

upper karma May 28, 2021, 7:25 PM

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trim breach Did you sketch the situation yet?

No I’m not too sure how

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To sketch it.

trim breach May 28, 2021, 7:26 PM

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Alright, give me a sec.

upper karma May 28, 2021, 7:27 PM

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trim breach Alright, give me a sec.

Ok

trim breach May 28, 2021, 7:31 PM

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upper karma Ok

Does this sketch make sense to you?

upper karma May 28, 2021, 7:31 PM

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Yeah

trim breach May 28, 2021, 7:32 PM

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So what you can do is solve each leg for the runways separately using trigonometry.

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You know the angle of depression for the first runways is 8 degrees.

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So the angle inside the triangle is what?

upper karma May 28, 2021, 7:36 PM

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trim breach You know the angle of depression for the first runways is 8 degrees.

Ok this may be rlly dumb but 82?

trim breach May 28, 2021, 7:36 PM

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That’s right. They have to be complementary.

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So do you know how to solve for the leg using trigonometry?

upper karma May 28, 2021, 7:38 PM

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trim breach So do you know how to solve for the leg using trigonometry?

Waht is the leg again?

trim breach May 28, 2021, 7:39 PM

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A leg can refer to either side of a right triangle that is not the hypotenuse.

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So, for example, in that triangle, one leg is 822.

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The other one is unknown, and we are trying to solve for it.

upper karma May 28, 2021, 7:46 PM

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trim breach The other one is unknown, and we are trying to solve for it.

Can we use tan?

trim breach May 28, 2021, 7:46 PM

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Yes!

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Are you able to set up the equation?

upper karma May 28, 2021, 7:47 PM

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trim breach Are you able to set up the equation?

Tan0=822/x

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?

trim breach May 28, 2021, 7:48 PM

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Why tan(0)?

upper karma May 28, 2021, 7:48 PM

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Or no tan 82

trim breach May 28, 2021, 7:48 PM

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Yes.

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But the other side needs flippedX

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It is opposite over adjacent.

upper karma May 28, 2021, 7:48 PM

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trim breach But the other side needs flippedX

Yeah how do you do that?

upper karma May 28, 2021, 7:49 PM

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trim breach It is opposite over adjacent.

Ok

trim breach May 28, 2021, 7:49 PM

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No, I mean just flip the fraction.

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What you have is adjacent over opposite.

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You need opposite over adjacent.

upper karma May 28, 2021, 7:49 PM

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Ok I didn’t even know I could do that

trim breach May 28, 2021, 7:50 PM

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So your equation should be:

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tan(82) = x/822

upper karma May 28, 2021, 7:50 PM

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Ye

trim breach May 28, 2021, 7:51 PM

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x is the distance to the first runway.

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So when you solve for x, make note of it so we can use it later.

upper karma May 28, 2021, 7:52 PM

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trim breach So when you solve for *x*, make note of it so we can use it later.

Ok should I solve it?

trim breach May 28, 2021, 7:53 PM

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Yes.

upper karma May 28, 2021, 7:53 PM

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Ok i think its 5848.833

trim breach May 28, 2021, 7:53 PM

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Correct.

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We need to repeat the same steps to find the distance to runway 2.

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So first find the angle we use for inside the triangle.

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The angle of depression is 7 degrees this time.

upper karma May 28, 2021, 7:54 PM

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trim breach So first find the angle we use for inside the triangle.

83

trim breach May 28, 2021, 7:54 PM

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Yep!

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Can you set up the equation?

upper karma May 28, 2021, 7:55 PM

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Tan83deg=x/822

trim breach May 28, 2021, 7:56 PM

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Yes!

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Solve for x.

upper karma May 28, 2021, 7:57 PM

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6694.652

trim breach May 28, 2021, 7:57 PM

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Yes!

upper karma May 28, 2021, 7:57 PM

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I think

trim breach May 28, 2021, 7:57 PM

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So, do you know how you would find the distance between the two runways?

upper karma May 28, 2021, 7:58 PM

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No I don’t think I do

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I thought I learned how u can do this with 2 triangles I just don’t remember

trim breach May 28, 2021, 7:59 PM

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Does this make it more clear?

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x1 is the distance from the plane to the first runway. x2 is the distance from the plane to the second runway.

upper karma May 28, 2021, 8:00 PM

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Remove x1 from x2?

trim breach May 28, 2021, 8:01 PM

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Yes.

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x2 - x1 is the distance between the two.

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You don’t need to worry about the angles anymore.

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You only needed the angles to be able to get x1 and x2.

upper karma May 28, 2021, 8:03 PM

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trim breach You only needed the angles to be able to get x1 and x2.

Ok so 845,819

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?

trim breach May 28, 2021, 8:03 PM

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Yes!

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Maybe my explanation was not the greatest, but I hope it helped a little bit.

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These problems are mainly about being able to draw the situation.

upper karma May 28, 2021, 8:03 PM

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trim breach Maybe my explanation was not the greatest, but I hope it helped a little bit.

No it was perfect

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Yea

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Sometimes I just don’t know where to start that’s why I have trouble w these

inland mountain May 28, 2021, 8:27 PM

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How is this done?

tiny vessel May 28, 2021, 10:05 PM

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i think you translate 1 right and 4 up base on your original point

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(9.2+1,12+4)

upper karma May 29, 2021, 9:28 AM

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can anyone solve Q1

dark sparrow May 29, 2021, 9:41 AM

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we do not give out answers here

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have you made any progress on this question, or did you expect someone to do it for you? @upper karma

upper karma May 29, 2021, 9:42 AM

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i dont have any clue

dark sparrow May 29, 2021, 9:42 AM

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have you made a diagram yet?

upper karma May 29, 2021, 9:50 AM

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dark sparrow May 29, 2021, 9:56 AM

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okay

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may i suggest considering the area of triangle BCD, and its ratios to the areas of ABCD and CDE?

haughty spire May 29, 2021, 10:23 AM

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upper karma can anyone solve Q1

ayy IOQM paper
da memories

haughty spire May 29, 2021, 10:24 AM

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upper karma

use the fact the areas of similar triangle are proportional to the square of sides , it is in class 10 ncert book chap 6 triangles

upper karma May 29, 2021, 10:36 AM

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ok

dark sparrow May 29, 2021, 10:39 AM

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@haughty spire do not give out answers here.

haughty spire May 29, 2021, 10:39 AM

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dark sparrow <@828150220533137459> do not give out answers here.

oh okay

edgy juniper May 29, 2021, 2:03 PM

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dark sparrow May 29, 2021, 2:13 PM

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that's not a zero with a line through it

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that's a greek letter, specifically the greek letter theta

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it will not appear on your calculator

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it is a variable just like x or y

edgy juniper May 29, 2021, 2:13 PM

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dark sparrow it is a variable just like x or y

yeah

edgy juniper May 29, 2021, 2:14 PM

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dark sparrow it will not appear on your calculator

oh, but how do i do that formula that it shows

dark sparrow May 29, 2021, 2:14 PM

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wym

edgy juniper May 29, 2021, 2:14 PM

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like theta/360 x pi x 10^2

dark sparrow May 29, 2021, 2:15 PM

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that's like asking "how do i do 6y + 11 on the calculator"

woeful jackal May 29, 2021, 8:55 PM

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hello

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anybody free?

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i would like to get some help solving this problem

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https://stewartmath.com/dp_fops_samples/dp8.html

silk patio May 29, 2021, 9:03 PM

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What have you tried?

woeful jackal May 29, 2021, 9:36 PM

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so

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i have calculated

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formulas

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for both

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functions

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and added them to each other

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and got this:

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y=2300sin(pi/60)*t +3200-32000sin(pi/60)

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then i wrote its mid line and amplitude

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i wanna know what is its phase shift

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@silk patio

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u here?

upper karma May 29, 2021, 11:42 PM

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im taking a trigonometry test rn. can anyone help me with the 4 questions i dont know?

trim breach May 29, 2021, 11:46 PM

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upper karma im taking a trigonometry test rn. can anyone help me with the 4 questions i dont...

No.

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That is literally the most important rule of the server.

hasty valve May 30, 2021, 12:15 AM

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hi, ill try to translate this as best as i can

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im struggling to draw the diagram for the circle k1:

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A triangle ABC is inscribed in a circle k, such that <ACB = 30deg. The circle k1 with center O lies on top of k, passing through A, C and the line through AB at a point Q such that A is between Q and B and QB = sqrt(3)AB

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maybe i have translated incorrectly but it seems like the diagram is impossible, in that A cannot be between Q and B

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actually ive managed to do it nvm

hasty valve May 30, 2021, 12:55 AM

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ok i actually am stuck

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i have no idea how to answer: a) find the measures of the angles of the triangle ABC

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b) the face (area?) of ABC if we're told that the bisector of the angle ACB has length l (not 1)

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it seems to me that there are infinitely many answers for (a), i don't see how the circle k1 affects the angles of ABC, i fail to see the constraint

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i tried to draw it in geogebra and im convinced there's infinitely many solutions

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if i just move A and B around the circle k

prisma kernel May 30, 2021, 2:42 AM

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can someone help mw with geom?

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trim breach May 30, 2021, 2:58 AM

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prisma kernel can someone help mw with geom?

Which ones?

upper karma May 30, 2021, 6:42 AM

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can anyone solve Q 24

silk patio May 30, 2021, 8:55 AM

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Yes

haughty spire May 30, 2021, 11:25 AM

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upper karma can anyone solve Q 24

bruh its a proof...and plus why r u doing challenges and thrills of pre college mathematics for ioqm....in ioqm no proofs...instead practice those pyqs like u did yest..dont do this shit

upper karma May 30, 2021, 11:25 AM

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ok bro

haughty spire May 30, 2021, 11:26 AM

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this book is for rmo+

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dont do now

bitter lance May 30, 2021, 1:49 PM

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hasty valve

i also got infinitely many solutions for a.)

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u can literally move C around the circle and A, B, and Q will stay fixed

hasty valve May 30, 2021, 2:50 PM

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damn , well thanks for taking a look at it. i was pretty sure i translated it correctly. I might ask someone who knows bulgarian a bit better than me

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somehow the circle k1 is meant to restrict the angles of ABC but i dont see it yet

hasty valve May 30, 2021, 4:03 PM

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bitter lance i also got infinitely many solutions for a.)

I have revised it and it wasn't clear to me that the center of k1 must be on k. it was translated but not emphasised

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so i think there's two solutions:

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120, 30

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60, 90

bitter lance May 30, 2021, 4:05 PM

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oh it's clearer now

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connect center of k to A and B

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show that OAB is equilateral

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oh but wait wait sori

deep mural May 30, 2021, 8:58 PM

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anyone want to take a crack at this? https://math.stackexchange.com/questions/4155551/sum-of-angles-extension-to-crossed-polygons

Mathematics Stack Exchange

Sum of angles Extension to crossed polygons

Im trying to figure out the details of this algorithm posted here Extension to crossed polygons(Scroll down).
The algorithm states that the sum of angles of any polygon can be found by the formula ...

upper karma May 31, 2021, 2:25 AM

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hi i need some help

trim breach May 31, 2021, 2:49 AM

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upper karma hi i need some help

With?

haughty spire May 31, 2021, 3:47 AM

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hey can someone help me with this

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i know that British Flag Theorem can be used here

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but it dosent yield a proper ans

bitter lance May 31, 2021, 3:53 AM

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oh

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yeah british flag works

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but this one uses a trigonometry bash

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i had a solution before that uses reflection of M to help with the calculations so it isn't that messy

haughty spire May 31, 2021, 3:58 AM

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bitter lance but this one uses a trigonometry bash

oh god

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can u help me pls

bitter lance May 31, 2021, 5:17 AM

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i kinda let MA, MB, MC be 2,3,5 respectively

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since we want to minimize side length

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i then rotated M about be 90 degrees so that it's outside side BC

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HAHAHAHAHA

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here on im still figuring out how i did it

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if we let M' be the point of M after rotation, we get MBM' to be 45-45-90 right

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and M'C=MA since it also rotated 90 degrees because square has 90 degree angke

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and i used cosine law twice (triangle AMC and another triangle involving M' idk am sori)

haughty spire May 31, 2021, 5:59 AM

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ok tysm dude

tight grove May 31, 2021, 11:33 AM

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Hi. I need some help for my trigonometry homework

junior light May 31, 2021, 11:55 AM

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@tight grove Where are you stuck, and what have you tried?

tight grove May 31, 2021, 11:56 AM

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Number 1. I tried any other formulas but I can't solve it right

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I tried SSS theorem and any other theorems

junior light May 31, 2021, 11:59 AM

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Okay, start by splitting the largest hypotenuse(measuring 15 units) into y and (15-y) units, about the point where the perpendicular touches it

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Then use Pythagoras on the two smaller triangles

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Get rid of the x^2 term using elimination(subtract one of the equations from another), and solve for y

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Then plug back in to find x

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Problem 2 uses similar ideas

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Problem 3 is SAS

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I will leave 4 and 5 to you, but Pythagoras is the key.

tight grove May 31, 2021, 12:02 PM

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Oh okay lemme compute it

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Thank you so much

junior light May 31, 2021, 12:02 PM

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No worries.

light solar May 31, 2021, 12:49 PM

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Screen_Shot_2021-05-31_at_10.49.40_pm.png

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Screen_Shot_2021-05-31_at_10.50.06_pm.png

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this is the answer

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how do i get the surface area

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with the working out

pure cape May 31, 2021, 12:53 PM

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are there any other information?

light solar May 31, 2021, 12:53 PM

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no

pure cape May 31, 2021, 12:53 PM

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like are the top and bottom squares?

light solar May 31, 2021, 12:53 PM

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top and bottom are rectangles

pure cape May 31, 2021, 12:54 PM

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5.3 is the length of the slanted segment right?

light solar May 31, 2021, 12:54 PM

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yeah

pure cape May 31, 2021, 12:54 PM

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hmm

light solar May 31, 2021, 1:04 PM

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nvm got it

pure cape May 31, 2021, 1:04 PM

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really?

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interesting problem

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havent really figured it out for me

light solar May 31, 2021, 1:05 PM

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its (9.2x5.3)+(6.2x5.3x2)+(6/2(9.2+12.5))x2+(12.5x5.3)

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9.2x5.3 is the bottom rectangle

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6.2x5.3x2 are the areas of the left and right rectangles

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6/2(9.2+12.5)x2 are for the front and back trapeziums

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and 12.5x5.3 is the top rectangle

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its 5.3 because rectangles dont have diagonal sides and dont stretch

pure cape May 31, 2021, 1:06 PM

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wait so 5.3 is the length of the bottom side

light solar May 31, 2021, 1:06 PM

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yeah

pure cape May 31, 2021, 1:07 PM

#

alright guess thats quite badly notated

light solar May 31, 2021, 1:07 PM

#

yeah its supposed to be a trick question ig

pure cape May 31, 2021, 1:07 PM

#

so 6.2 is the slanted side then?

light solar May 31, 2021, 1:07 PM

#

yup

pure cape May 31, 2021, 1:07 PM

#

hmm ok

light solar May 31, 2021, 1:08 PM

#

Screen_Shot_2021-05-31_at_11.08.03_pm.png

#

theres also this thats confusing

#

i get everything except the triangle part

pure cape May 31, 2021, 1:08 PM

#

well at least this looks better

light solar May 31, 2021, 1:08 PM

#

because apparently 16 is the height of the triangle and 9.6 is the base

pure cape May 31, 2021, 1:08 PM

#

since the number are seperated out more clearly

light solar May 31, 2021, 1:08 PM

#

but 16 is the hypotenuse so it wouldnt make sense for it to be the height

#

i thought it was 12.8 at first tho

pure cape May 31, 2021, 1:09 PM

#

so this shape here isnt a rectangle?

#

if so that would be very badly drawn lol

junior light May 31, 2021, 1:16 PM

#

It's a projection perspective

light solar May 31, 2021, 1:17 PM

#

pure cape so this shape here isnt a rectangle?

wait which one?

#

the slope?

#

thats a rectangle

pure cape May 31, 2021, 1:17 PM

#

yes

light solar May 31, 2021, 1:18 PM

#

around the triangles are rectangles

pure cape May 31, 2021, 1:18 PM

#

junior light It's a projection perspective

no i mean, projection perspective has to be accurate too, hence that not being a rectangle seems illogical

#

then that diagram is clear

#

16 is hypotenuse, and 12.8 and 9.6 are the base of the right triangle

light solar May 31, 2021, 1:19 PM

#

9.6 is the base

#

the area of both triangles is 1/2x9.6x16x2

#

x2 because two traingles

#

sorry not 12.8 i meant 16

#

but i dont get why its 16

#

because its the hypotenuse

#

and it doesnt make sense for it to be the height of the triangle

pure cape May 31, 2021, 1:23 PM

#

something is wrong then

#

since BCDE is a rectangle

#

BC is 12.8

#

hence the area of ABC is 1/2 * 9.6 * 12.8

#

maybe ask your teacher about it

light solar May 31, 2021, 1:23 PM

#

i did

#

he said its a right angled triangle so i can find the height there

pure cape May 31, 2021, 1:24 PM

#

if 16 were meant to imply BC, then BCDE is not a rectangle

light solar May 31, 2021, 1:24 PM

#

and it was the end of class so i asked him and left

pure cape May 31, 2021, 1:24 PM

#

yes the height of ABC is 12.8

light solar May 31, 2021, 1:24 PM

#

wait what how?

pure cape May 31, 2021, 1:25 PM

#

because BCDE is a rectangle

#

if the question claims so

light solar May 31, 2021, 1:25 PM

#

wait so the base would be 9.6

#

and height is 12.8?

pure cape May 31, 2021, 1:25 PM

#

yes

#

and the hypotenuse is 16

light solar May 31, 2021, 1:26 PM

#

Screen_Shot_2021-05-31_at_11.26.13_pm.png

#

this is the answer

#

i got 414.72

pure cape May 31, 2021, 1:26 PM

#

the surface area of the whole shape?

light solar May 31, 2021, 1:26 PM

#

yeah

pure cape May 31, 2021, 1:26 PM

#

lemme get my calculator

light solar May 31, 2021, 1:28 PM

#

i did (9.2x12.8)+(9.6x9.2)+(16x9.2)+(1/2x9.6x12.8x2)

#

i got 476.16

pure cape May 31, 2021, 1:28 PM

#

yeah should be the correct answer, just ask your teacher about it

light solar May 31, 2021, 1:28 PM

#

but when i change the height of the triangle from 12.8 to 16 it becomes 506.88

pure cape May 31, 2021, 1:29 PM

#

the question got some issue

light solar May 31, 2021, 1:29 PM

#

yeah

#

the worksheet im doing has some mistakes so thing may be one of them

pure cape May 31, 2021, 1:30 PM

#

since if the height of the right triangle is 16 then the whole question breaks down

#

or another way you can see it is that if the right triangle has height 16 then the rectangle is 9.2 by 16 not 12.8

keen aspen May 31, 2021, 2:59 PM

#

This question has me stumped, I feel like there’s not enough info?

#

Or am i missing something here

silent plank May 31, 2021, 3:07 PM

#

what are the original markings on the diagram

keen aspen May 31, 2021, 3:07 PM

#

Just 54 on the left and a

#

Angle a

silent plank May 31, 2021, 3:08 PM

#

that?

keen aspen May 31, 2021, 3:09 PM

#

Ya

silent plank May 31, 2021, 3:09 PM

#

then yeh, there is insufficient info

keen aspen May 31, 2021, 3:10 PM

#

Figured

#

Because you could shift this line up and down and change the angle a

silent plank May 31, 2021, 3:10 PM

#

yes

unborn palm May 31, 2021, 5:17 PM

#

#

My techear say the answer will be J

#

but how?

#

can anybody explain?

tribal wind May 31, 2021, 5:39 PM

#

translation just means adding, (3,5)+(-4,6)

tough bane May 31, 2021, 9:13 PM

#

#

I need to draw a straight line that separates this shape in 2 that passes through (0,0)

silent plank May 31, 2021, 9:16 PM

#

are there any other conditions on how it's split?

tough bane May 31, 2021, 9:16 PM

#

Nope

#

I just need the function of this line

#

I have the awswer available and they present the question like this

#

#

Still clueless even with the awswer available

#

silent plank May 31, 2021, 9:19 PM

#

oh...

#

split into 2 (shapes with equal area)

#

the bolded part is important

tough bane May 31, 2021, 9:20 PM

#

Forgive me, I explained myself poorly

silent plank May 31, 2021, 9:22 PM

#

anyway start by drawing an arbitrary line like they did that roughly splits the shape into 2 equally sized pieces

#

as indicated in their diagram, the length of b is currently unknown

#

and the x coordinate of P will be 5 - b

#

b can be determined from the formula for the area of a trapezium

tough bane May 31, 2021, 9:24 PM

#

That does start to make sense

#

Oh of course

#

That still doesn't answer how knowing the area of one half is going to help me know the line that passes through them

#

Never mind it does

#

You use the fact you know what P is to calculate the line

#

Alright thank you so much :)

crisp cloud May 31, 2021, 9:59 PM

#

anyone here able to help me?

trim breach May 31, 2021, 10:22 PM

#

crisp cloud anyone here able to help me?

Yes, just post the question.

crisp cloud May 31, 2021, 10:23 PM

#

ok

#

#

trim breach May 31, 2021, 10:23 PM

#

Is this for a test or quiz?

crisp cloud May 31, 2021, 10:24 PM

#

its a quizzes

#

quizz

trim breach May 31, 2021, 10:26 PM

#

We cannot help on tests or quizzes.

#

Outside of those types of assignments, we are able to help with whatever you need.

crisp cloud May 31, 2021, 10:26 PM

#

ah damn

trim breach May 31, 2021, 10:27 PM

#

If it is open-book, you might want to try consulting your notes.

rapid tartan May 31, 2021, 11:17 PM

#

anyone know what it means when it’s say if necessary write in simplest radical form?

#

i have the question if needed example

upper karma May 31, 2021, 11:18 PM

#

hello guys

#

Have fun! (please read the notes in the question )(if you can not find the answer, I can give the my answer)

#

and you can find the m(ACB)

#

good luck

celest sequoia Jun 1, 2021, 12:03 AM

#

i need help for a math question, i did it but not sure if it is right, there are no solutions page and i want to know if im doing it properly can i get some help for (trigonometry btw)

#

where should i go to send my photo and answer, do i put it here?

#

question number 2

Desktop_Screenshot_2021.05.31_-_20.10.24.88_2.png

#

im just wondering if my answer is right if thats ok

trim breach Jun 1, 2021, 12:12 AM

#

What did you write as your answer?

celest sequoia Jun 1, 2021, 12:12 AM

#

i ended up getting s= 2.89m , not sure tho

trim breach Jun 1, 2021, 12:13 AM

#

s?

#

Is that the leg or hypotenuse?

celest sequoia Jun 1, 2021, 12:13 AM

#

im tlaking about the adjacent

#

i could be wrong, i assume i was trying to find the adj

trim breach Jun 1, 2021, 12:15 AM

#

Solving a triangle usually means finding all angles and sides.

trim breach Jun 1, 2021, 12:16 AM

#

celest sequoia i ended up getting s= 2.89m , not sure tho

What did you do to get this answer?

#

It is wrong, but I think you probably went wrong in just one step.

silent plank Jun 1, 2021, 12:31 AM

#

the label is also wrong.
by convention the lowercase letter represents the side opposite the angle/vertex

#

in this case s would represent the length of RT which is given to be 5m

upper karma Jun 1, 2021, 12:58 AM

#

#

Need help with this one

junior light Jun 1, 2021, 1:22 AM

#

@upper karma What have you tried so far?

upper karma Jun 1, 2021, 1:22 AM

#

Well, not sure how to do it is the thing.

junior light Jun 1, 2021, 1:23 AM

#

Hint: ADB and ADC are congruent right triangles.

#

Does that help?

upper karma Jun 1, 2021, 1:24 AM

#

No, not really.

junior light Jun 1, 2021, 1:24 AM

#

Do you know what congruent triangles are?

upper karma Jun 1, 2021, 1:26 AM

#

Matching triangles?

junior light Jun 1, 2021, 1:26 AM

#

Yes. More like, they're the same triangles, just labelled and oriented differently.

#

So the important thing here is, both ADB and ADC have the same base and perpendicular.

#

What does this entail for their hypotenuse?

upper karma Jun 1, 2021, 1:30 AM

#

They're also the same.

junior light Jun 1, 2021, 1:30 AM

#

Correct!

#

You have been told the lengths of the hypotenuse, in terms of an unknown x. Can you now determine x?

upper karma Jun 1, 2021, 1:31 AM

#

I don't know how to get X, that's the thing.

#

Unsure of how to solve the equation.

junior light Jun 1, 2021, 1:32 AM

#

What's the equation you wrote?

upper karma Jun 1, 2021, 1:32 AM

#

oh i haven't written anything yet.

junior light Jun 1, 2021, 1:32 AM

#

Okay, what do you think the equation here should be?

#

Given that AB and AC are equal

upper karma Jun 1, 2021, 1:33 AM

#

Hmm.

#

4x+6=5x-6

junior light Jun 1, 2021, 1:33 AM

#

Yes.

#

Can you solve this for x?

upper karma Jun 1, 2021, 1:34 AM

#

unsure of where to start.

#

Not sure where to add or subtract, from or to.

junior light Jun 1, 2021, 1:35 AM

#

The objective with an equation in a single unknown is this: move all the terms with variable to one side, everything else to the other. The order in which you do this doesn't matter.

#

Try to get rid of 6 from any one of the sides first?

true portal Jun 1, 2021, 2:05 AM

#

Paying 10$ for someone to go through 12 geometry examples and explain em - they’re homework and I need to understand em dm me

junior light Jun 1, 2021, 2:16 AM

#

This server is not ideal when looking for tutors(since transaction disputes have legal implications, and cannot be moderated by the server). Other than that, if you can probably try learning on your from Khan Academy or a similar source, maybe you'd understand it better?

#

If you still need help, feel free to drop your question here.

versed echo Jun 1, 2021, 9:58 AM

#

Can someone be active and help me with my mathematics homework, i will be posting screenshots. Help me!!!

#

Its due in one hour

onyx granite Jun 1, 2021, 10:35 AM

#

versed echo Can someone be active and help me with my mathematics homework, i will be postin...

Sorry for being late, but just post the question

storm portal Jun 1, 2021, 3:57 PM

#

versed echo Can someone be active and help me with my mathematics homework, i will be postin...

JustAsk

dull blade Jun 1, 2021, 4:11 PM

#

I have to find missing side AC and AB

#

can someone help me

trim breach Jun 1, 2021, 4:14 PM

#

Have you started an equation?

dull blade Jun 1, 2021, 4:15 PM

#

so

trim breach Jun 1, 2021, 4:18 PM

#

I’ll just assume not…you need to use trigonometry to solve this triangle.

#

The only angle you are given is 51 degrees, so we can start there.

dull blade Jun 1, 2021, 4:18 PM

#

for AC would it be tan

#

oh ok

trim breach Jun 1, 2021, 4:18 PM

#

Yes.

#

Do you know how to set up an equation to solve for that side?

dull blade Jun 1, 2021, 4:20 PM

#

and so would it be tan51 9/AC

#

like dat?

trim breach Jun 1, 2021, 4:20 PM

#

Yes.

pseudo scroll Jun 1, 2021, 4:20 PM

#

trim breach The only angle you are given is 51 degrees, so we can start there.

angle C is given as 90degrees

#

which means angle B is 39 degrees

#

lmao deez gimme a sec i gotchu

dull blade Jun 1, 2021, 4:22 PM

#

ok

#

but also would i cross multiply next?

trim breach Jun 1, 2021, 4:22 PM

#

You want to isolate AC.

#

They easiest way is to multiple both sides by AC.

dull blade Jun 1, 2021, 4:23 PM

#

oh

#

ok

pseudo scroll Jun 1, 2021, 4:23 PM

#

trim breach Jun 1, 2021, 4:23 PM

#

So you have: AC tan(51) = 9

#

Then divide both sides by tan(51).

#

To get AC = 9/tan(51)

pseudo scroll Jun 1, 2021, 4:24 PM

#

lidoh chill bro i got everything right in that image

dull blade Jun 1, 2021, 4:24 PM

#

so i would get tan(51)AC=9

#

and thank you abood

pseudo scroll Jun 1, 2021, 4:25 PM

#

np

trim breach Jun 1, 2021, 4:25 PM

#

Well, you named your variable AC.

pseudo scroll Jun 1, 2021, 4:25 PM

#

https://www.calculator.net/triangle-calculator.html

Triangle Calculator

This free triangle calculator computes the edges, angles, area, height, perimeter, median, as well as other values of a triangle. View a scaled diagram of the resulting triangle, or explore many other math calculators, as well as hundreds of other calculators addressing finance, health, fitness, and more.

trim breach Jun 1, 2021, 4:25 PM

#

It is one side, so you want to isolate it to find its value.

pseudo scroll Jun 1, 2021, 4:25 PM

#

that website you just have to change the numbers and itll give you everything

dull blade Jun 1, 2021, 4:26 PM

#

oh ok

#

kk abood

trim breach Jun 1, 2021, 4:28 PM

#

pseudo scroll that website you just have to change the numbers and itll give you everything

A calculator like that is only useful when you never have to reproduce the steps in the math. It is important to learn the process for understanding, especially if you have an exam on it.

dull blade Jun 1, 2021, 4:28 PM

#

also not exam just work assignment

pseudo scroll Jun 1, 2021, 4:29 PM

#

scroll down and itll show the theorms and things it used to get the answer

dull blade Jun 1, 2021, 4:29 PM

#

u can still explain Lidoh

#

cuz i need explanation to

trim breach Jun 1, 2021, 4:30 PM

#

Did you find AC?

dull blade Jun 1, 2021, 4:30 PM

#

so AC would be 7.288?

trim breach Jun 1, 2021, 4:30 PM

#

Yes!

dull blade Jun 1, 2021, 4:30 PM

#

oh yeye

#

much thanks

#

I think i can do the other one alone now

#

its da same process no but just changing tan

#

right?

trim breach Jun 1, 2021, 4:32 PM

#

Yes. You would use a different trigonometric ratio instead of tangent.

dull blade Jun 1, 2021, 4:32 PM

#

yep

trim breach Jun 1, 2021, 4:32 PM

#

Steps are similar though.

dull blade Jun 1, 2021, 4:32 PM

#

thank tho

#

mhm

trim breach Jun 1, 2021, 4:32 PM

#

Good luck!

dull blade Jun 1, 2021, 4:32 PM

#

thanks

topaz meteor Jun 1, 2021, 7:10 PM

#

trim breach Jun 1, 2021, 7:59 PM

#

topaz meteor

Do you know how to use trigonometric ratios?

#

The problem I was helping with above earlier today was actually very similar.

lethal crow Jun 1, 2021, 8:26 PM

#

can someone pls help me with this

humble pulsar Jun 1, 2021, 8:27 PM

#

lethal crow can someone pls help me with this

use tangent twice

shut venture Jun 1, 2021, 8:28 PM

#

it should be 12%

#

for the ramp?

lethal crow Jun 1, 2021, 8:28 PM

#

shut venture for the ramp?

yea i think

shut venture Jun 1, 2021, 8:28 PM

#

I remember doing this

#

you have mostly what you need

#

then get the angles from the arc

#

right @humble pulsar ?

humble pulsar Jun 1, 2021, 8:29 PM

#

shut venture it should be 12%

how are you getting a percent for an angle..?

humble pulsar Jun 1, 2021, 8:30 PM

#

shut venture then get the angles from the arc

there's also no arc

shut venture Jun 1, 2021, 8:30 PM

#

i meant like the inverse

humble pulsar Jun 1, 2021, 8:30 PM

#

yeah, where does 12% come into this?

shut venture Jun 1, 2021, 8:31 PM

#

actually

#

it should be 8%

#

?

humble pulsar Jun 1, 2021, 8:31 PM

#

there's no percents...

shut venture Jun 1, 2021, 8:32 PM

#

i know it has no percents

humble pulsar Jun 1, 2021, 8:32 PM

#

you're writing percent signs

shut venture Jun 1, 2021, 8:32 PM

#

give me a sec

#

maybe im not doing the math right

humble pulsar Jun 1, 2021, 8:32 PM

#

you're not. there's no percentages

#

$\tan(B)=\frac{1}{12}$

somber coyoteBOT Jun 1, 2021, 8:33 PM

#

Mosh

shut venture Jun 1, 2021, 8:34 PM

#

@humble pulsar (1/12)*100

lethal crow Jun 1, 2021, 8:35 PM

#

thnx

humble pulsar Jun 1, 2021, 8:35 PM

#

????

#

why the fuck would you be doing that

shut venture Jun 1, 2021, 8:35 PM

#

@humble pulsar nevermind

#

it was just fun

#

dont need to be that radical

humble pulsar Jun 1, 2021, 8:35 PM

#

I mean what you said had no merit in helping determine the angles A and B

shut venture Jun 1, 2021, 8:36 PM

#

i know

#

i never said the opposite

#

it was just fun thats all

#

but tan(b)=1/12 wont give degrees either

lethal crow Jun 1, 2021, 8:39 PM

#

idek at this point

trim breach Jun 1, 2021, 8:54 PM

#

Utilize a trigonometric ratio. You have the side adjacent to the angle, and you want to find the other leg.

narrow seal Jun 1, 2021, 9:03 PM

#

#

r both of those correct?

idle bobcat Jun 1, 2021, 10:14 PM

#

Hi, is 138.47 degrees correct for the direction of the wind vector?

#

I'm getting 13.16km/h for the speed and 138.47degrees for the direction

hollow fossil Jun 1, 2021, 10:45 PM

#

Im not sure if this is the right place to ask this, but is there a similar geometric understanding for tan, cot, sec and csc like there is for sin and cos? I know that sin and cos are the y and x values of a point on the unit circle, but I'm not sure what that understanding would be for other trig functions.

idle bobcat Jun 1, 2021, 10:49 PM

#

tan is the slope

umbral snow Jun 1, 2021, 10:57 PM

#

,w (250cos318, 250sin318) - (240cos320, 240sin320) angle

somber coyoteBOT Jun 1, 2021, 10:58 PM

#

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

hollow fossil Jun 1, 2021, 11:00 PM

#

oh, didnt think I would be getting an answer, but anyway, what do you mean by slope, do you mean the slope of the radius with the input angle? Also, is there anything about sec in the geometric model of it

umbral snow Jun 1, 2021, 11:00 PM

#

That's what I'm getting for wind

#

@hollow fossil
The slope of the terminal arm is also tanθ

hollow fossil Jun 1, 2021, 11:01 PM

#

umbral snow <@591387439583592452> The slope of the terminal arm is also tanθ

got it.

umbral snow Jun 1, 2021, 11:01 PM

#

Slope is rise/run = sinθ/cosθ

#

Unfortunately there's no easy rule for the inverse trigs. They do have interpretations on the unit circle but they're a pain

#

hollow fossil Jun 1, 2021, 11:03 PM

#

oh, cool, that actually makes alot of stuff more intuitive, like that tan a squared plus 1 is sec a

#

cuz pythagoras

idle bobcat Jun 1, 2021, 11:04 PM

#

@umbral snow how do I translate that -81.5403 into the direction of the wind

#

like the true bearing

umbral snow Jun 1, 2021, 11:05 PM

#

Easy way to memorize that rule, take:
sin²(x) + cos²(x) = 1

And divide both sides by cos²(x) to get:
tan²(x) + 1 = sec²(x)

idle bobcat Jun 1, 2021, 11:06 PM

#

oh i guess i would do 360-81.5403

#

since we're in the 2nd quadrant

hollow fossil Jun 1, 2021, 11:06 PM

#

umbral snow Easy way to memorize that rule, take: sin²(x) + cos²(x) = 1 And divide both sid...

well, I knew that rule from the algebra of it, but I find geometry more intuitive, so the diagram seems so easy to derive from

idle bobcat Jun 1, 2021, 11:14 PM

#

umbral snow That's what I'm getting for wind

do u mind explaining the steps, im still unsure of how to get the correct direction for the wind

upper karma Jun 1, 2021, 11:38 PM

#

lethal crow can someone pls help me with this

for this . B=arctan[1/12]

dull blade Jun 2, 2021, 12:03 AM

#

can someone help I am confussed

idle bobcat Jun 2, 2021, 12:53 AM

#

use tan

#

opposite/adjacent

#

and solve for x

terse sparrow Jun 2, 2021, 2:06 AM

#

Anyone here good with convex hulls? If so, please ping me (@)

copper marten Jun 2, 2021, 4:07 AM

#

39 degrees is the reference angle, so what is BC (30) to 39 and what is "x" to 39? x is the opposite side and 30 is adjacent.
use SohCahToa
"Toa" or tangent, uses opposite and adjacent, so we'll use tan:

tan(reference angle) = opposite/adjacent
tan(39) = x/30
multiply by 30 both sides
tan(39) x 30 = x
x = 24.293521

pearl owl Jun 2, 2021, 5:56 AM

#

https://cdn.discordapp.com/attachments/594291451446165554/848423911524007966/5b2d6e1b55db1c4847fa82d70dbe070f.png

#

i am confused

dark sparrow Jun 2, 2021, 6:30 AM

#

@pearl owl do you still need help with this?

pearl owl Jun 2, 2021, 6:30 AM

#

yea

dark sparrow Jun 2, 2021, 6:30 AM

#

ok

#

there are six problems here, which one would you like to start with?

pearl owl Jun 2, 2021, 6:31 AM

#

number 1 please

dark sparrow Jun 2, 2021, 6:31 AM

#

okay

#

so in each of these problems, the two shapes they give you are known to be similar, yes?

pearl owl Jun 2, 2021, 6:32 AM

#

yea

#

p sure

dark sparrow Jun 2, 2021, 6:32 AM

#

if they weren't it'd be nigh impossible to solve the problem

pearl owl Jun 2, 2021, 6:32 AM

#

i have 0 knowledge on this btw

dark sparrow Jun 2, 2021, 6:32 AM

#

really?

pearl owl Jun 2, 2021, 6:32 AM

#

yea sadly

dark sparrow Jun 2, 2021, 6:32 AM

#

do the words 'scaling factor' not ring any bells to you?

pearl owl Jun 2, 2021, 6:32 AM

#

nope not at all

dark sparrow Jun 2, 2021, 6:33 AM

#

when two shapes are similar, it means you can get one of them by shrinking or enlarging the other by some factor

pearl owl Jun 2, 2021, 6:35 AM

#

ohhh okok

dark sparrow Jun 2, 2021, 6:35 AM

#

like in this example, the big triangle is twice as big as the small triangle

#

so we say the scaling factor between these is 2

pearl owl Jun 2, 2021, 6:35 AM

#

right right

dark sparrow Jun 2, 2021, 6:36 AM

#

now theres something important you need to know: while lengths scale by the scaling factor, areas scale by the square of the scaling factor

#

for example, making a shape 4 times bigger gives it 16 times the area, not 4 as you might think.

#

does this make sense to you?

pearl owl Jun 2, 2021, 6:39 AM

#

yes

dark sparrow Jun 2, 2021, 6:39 AM

#

okay

#

now let's look at number 1

#

the big triangle has a base of 12 inches while the small triangle has a base of 5 inches

#

what's the scaling factor to get from the small to the big?

pearl owl Jun 2, 2021, 6:42 AM

#

uh

dark sparrow Jun 2, 2021, 6:43 AM

#

5 times what equals 12?

pearl owl Jun 2, 2021, 6:44 AM

#

2.4

dark sparrow Jun 2, 2021, 6:45 AM

#

i'd rather you'd have said 12/5, but ok

#

so this is our scaling factor

#

do you understand why?

pearl owl Jun 2, 2021, 6:46 AM

#

no

#

lol im so sorry

dark sparrow Jun 2, 2021, 6:46 AM

#

... i have a feeling this might take way too long

pearl owl Jun 2, 2021, 6:46 AM

#

no no it wont if you just

dark sparrow Jun 2, 2021, 6:47 AM

#

you need to look up and read stuff / watch videos about similarity, scaling factors, etc.

pearl owl Jun 2, 2021, 6:47 AM

#

not give me the answer but

#

show me work on how to a similar problem

#

if u get me

dark sparrow Jun 2, 2021, 6:47 AM

#

but back to the problem... the big triangle is 2.4 times as big as the small triangle.

#

we know it's 2.4 times and not some other number because we're given those side lengths

#

5 and 12

pearl owl Jun 2, 2021, 6:48 AM

#

ahh

dark sparrow Jun 2, 2021, 6:48 AM

#

when you scale up, the side length of 5 becomes 5 * 2.4

#

= 12

#

does that make more sense?

pearl owl Jun 2, 2021, 6:48 AM

#

yup

dark sparrow Jun 2, 2021, 6:48 AM

#

yeah, ok, so now we have our scaling factor as 2.4

#

we want the area of the big triangle

#

and we know the area of the small triangle: 20 in^2

#

remember what i told you about areas? they scale with the square of the factor.

#

so the area of the big triangle is 20 * 2.4^2 square inches.

pearl owl Jun 2, 2021, 6:50 AM

#

do i simplify the 2.4???

#

then multiply

dark sparrow Jun 2, 2021, 6:50 AM

#

wym "simplify the 2.4"

pearl owl Jun 2, 2021, 6:51 AM

#

do 2.4 x 2.4

dark sparrow Jun 2, 2021, 6:51 AM

#

you can write it as a fraction instead of a decimal if you'd like. the only reason i wrote it as a decimal is to make my explanation a little more palatable

#

oh you mean simplify the 2.4^2

pearl owl Jun 2, 2021, 6:51 AM

#

yeeeee

dark sparrow Jun 2, 2021, 6:51 AM

#

i mean you're just doing the arithmetic either way

pearl owl Jun 2, 2021, 6:52 AM

#

alr alr sorry for interrupting, continue

dark sparrow Jun 2, 2021, 6:52 AM

#

eh?

#

we're done from here, more or less.

dark sparrow Jun 2, 2021, 6:52 AM

#

dark sparrow so the area of the big triangle is 20 * 2.4^2 square inches.

refer to this

#

at this point you might even put that into a calculator

#

,calc 20 * 2.4^2

somber coyoteBOT Jun 2, 2021, 6:52 AM

#

Result:

115.2

dark sparrow Jun 2, 2021, 6:52 AM

#

there

pearl owl Jun 2, 2021, 6:53 AM

#

oh wowzers

#

i can use this same example for the rest right

#

up until 5 n 6

dark sparrow Jun 2, 2021, 6:54 AM

#

almost

#

numbers 4 and 6 ask for the perimeter

#

which is a length, and so you will not be squaring the scaling factor as we did

#

but 2, 3 and 5 also ask for the area

pearl owl Jun 2, 2021, 6:56 AM

#

alright, any video suggestion i can watch for the perimeter

#

i dont want to waste your time

#

peepohappy

dark sparrow Jun 2, 2021, 6:57 AM

#

...the principle is the same in all six of your problems,

#

the only difference is that the perimeter is a length, and so scales with the scaling factor itself rather than its square

pearl owl Jun 2, 2021, 6:58 AM

#

oh

#

lol

#

i understand

#

thank you for your time

#

i appreciate you

edgy juniper Jun 2, 2021, 3:19 PM

#

how do i go about solving this?
just went over pythagoras’ theorem, but it didnt teach me anything about this sort of case.
it only taught me about how to get hypotenuse if you have the other two sides, or how to get one of the other side if you already have one and you have the hypotenuse

#

im guessing the fact that they are the same is how you can solve it, but i cant think of a way that that would help

limber patio Jun 2, 2021, 3:27 PM

#

Ok so, I have to find the intersection point between a cubic equation and a sinusoidal.
So I decided to set them equal to each other right
2x^3-10x+3=-5sin(2x/3)+2
But no matter what I did, I couldn't get rid of the x^3 term...
How does one solve this without using a graphing calculator?

#

Same thing applies @edgy juniper

#

You just use x^2+x^2=6^2

#

And that gives you 2x^2=36

#

x^2=18

trim breach Jun 2, 2021, 3:28 PM

#

edgy juniper how do i go about solving this? just went over pythagoras’ theorem, but it didnt...

Do you know the Isosceles Triangle Theorem?

limber patio Jun 2, 2021, 3:28 PM

#

And in this case, as you only need the positive solution, x =3sqrt(2)

edgy juniper Jun 2, 2021, 3:28 PM

#

trim breach Do you know the Isosceles Triangle Theorem?

no

edgy juniper Jun 2, 2021, 3:28 PM

#

limber patio You just use x^2+x^2=6^2

wait so

limber patio Jun 2, 2021, 3:28 PM

#

Alternatively, you can recognize this as a 45/45/90 degree triangle and just divide your hypotenuse by sqrt(2)

#

But you shouldn't worry about that because you just learned Pythagoras' Theorem

edgy juniper Jun 2, 2021, 3:31 PM

#

limber patio Alternatively, you can recognize this as a 45/45/90 degree triangle and just div...

so i should use this or no

#

only for 45/45/90 triangles

limber patio Jun 2, 2021, 3:31 PM

#

Have you learned your special right triangles yet?

#

So the logic behind this is that if you take a right triangle with leg measurements of 1

#

Then since they're the same, then those two sides are equal and thus, their corresponding angles are equal.

#

Meaning, that those measurements are 45 degrees.

#

Now, the logic behind special right triangles is that if you memorize a certain triangle, then because angles that have the same degree measurements are similar to that triangle, you can just scale it up by a certain factor. And when dealing with trigonometric functions this is especially useful because you're constantly dealing with ratios anyways.

#

But if you don't understand this don't worry about it.

#

But if you do, you should try it out in your free time and try some online practice problems.

#

It's good to hone your skills for these as it'll make trigonometry a lot easier.

edgy juniper Jun 2, 2021, 3:36 PM

#

i understand the gist yeah, i will take it fully, very soon in trigonometry when i reach it

#

thanks for explanation

limber patio Jun 2, 2021, 3:37 PM

#

limber patio So the logic behind this is that if you take a right triangle with leg measureme...

The reason why you divide by sqrt(2) is because the hypotenuse is sqrt(2) in this right triangle.

edgy juniper Jun 2, 2021, 3:37 PM

#

yeah

limber patio Jun 2, 2021, 3:37 PM

#

Just if that was unclear

inland dock Jun 2, 2021, 4:46 PM

#

What describes function $\frac{x}{cos(t)}+\frac{y}{sin(t)}=1$?

somber coyoteBOT Jun 2, 2021, 4:47 PM

#

FAF

tiny snow Jun 2, 2021, 5:26 PM

#

,w plot y=sin(t)-xtan(t)

somber coyoteBOT Jun 2, 2021, 5:26 PM

#

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

upper karma Jun 2, 2021, 10:51 PM

#

dull blade can someone help I am confussed

You still need help?

dull blade Jun 2, 2021, 10:52 PM

#

Yep

upper karma Jun 2, 2021, 10:52 PM

#

Alr bet

#

https://media.discordapp.net/attachments/326138757474680852/849438033891950643/Screenshot_2021-06-01_5.02.57_PM.png

dull blade Jun 2, 2021, 10:52 PM

#

Wait

#

I think I get it

upper karma Jun 2, 2021, 10:52 PM

#

Oh alr nvm

dull blade Jun 2, 2021, 10:52 PM

#

Sin is soh right

upper karma Jun 2, 2021, 10:52 PM

#

🤣

dull blade Jun 2, 2021, 10:52 PM

#

So I use opposite and hyp

#

Bruhhhhh

upper karma Jun 2, 2021, 10:53 PM

#

Yeah opposite over hyp

dull blade Jun 2, 2021, 10:53 PM

#

Ohnbruh

#

I big dum

#

Thanks anyway

#

👍

upper karma Jun 2, 2021, 10:53 PM

#

You can do tanx and tan z too

#

You just need to find one angle

#

Yeah no problem

dull blade Jun 2, 2021, 10:53 PM

#

K

#

🙃

leaden dome Jun 2, 2021, 11:35 PM

#

hi I need help finding a tangent point

#

y=-2cos2(theta)

#

the slope is -2 and the domaine is 0<=theta<2pi

#

no idea where to start

dreamy ridge Jun 2, 2021, 11:37 PM

#

So when we differentiate-2cos 2ø we get 4sin2ø

#

We know the gradient =-2

#

So 4sin2ø=-2

#

Solve it

#

And then make sure your ø is in the domain

leaden dome Jun 2, 2021, 11:38 PM

#

im solving for theta right

dreamy ridge Jun 2, 2021, 11:38 PM

#

Yeah sorry

#

Ø isn’t theta ik

leaden dome Jun 2, 2021, 11:39 PM

#

okay no worries its just ive never done a question like this before

#

this is gonna sound really dumb

#

but where do I start?

#

not sure how to do it with sin

dreamy ridge Jun 2, 2021, 11:41 PM

#

So 4sin2ø=-2
sin2ø=-1/2
Inverse sin -1/2 to find 2ø

#

Divide by 2

leaden dome Jun 2, 2021, 11:42 PM

#

id use sin^-1

#

right?

dreamy ridge Jun 2, 2021, 11:43 PM

#

Yea that’s what I mean by inverse sin sorry

leaden dome Jun 2, 2021, 11:43 PM

#

okay thanks

#

I really appreciate it

near whale Jun 3, 2021, 2:33 AM

#

https://i.imgur.com/53OmQea.png

...now maybe I'm not thinking right - but I'm pretty sure I am.

Isn't this impossible?

tan = opp over adj.

sin(theta) < 0 only occurs in Q3 and Q4 right? So you couldn't have a positive 3/4 tan?

Imgur

#

I feel like there's a missing - in that question.

#

like tan is supposed to be -3/4.

storm portal Jun 3, 2021, 2:37 AM

#

$\tan(\theta) > 0$ in either Quadrant 3 or 4.

somber coyoteBOT Jun 3, 2021, 2:37 AM

#

Shen

storm portal Jun 3, 2021, 2:37 AM

#

@near whale

#

Picking the right one will allow you to get the desired answers

near whale Jun 3, 2021, 2:59 AM

#

Thanks, that actually helped out.

solar heath Jun 3, 2021, 3:43 AM

#

can anyone help me with my quiz?

humble beacon Jun 3, 2021, 4:43 AM

#

can someone help with these questions

#

$math.png$

humble beacon Jun 3, 2021, 6:19 AM

#

i just need help with the 3rd and 4th now

#

anyone? pls?

silent plank Jun 3, 2021, 6:26 AM

#

Pythagorean trig identities
double angle identities

whole fulcrum Jun 3, 2021, 6:30 AM

#

Hi, does anyone know how to calculate boundary values for the equation? I know how to calculate for a single variable but confused how they calculated for 2 variables

upper karma Jun 3, 2021, 7:21 AM

#

dark sparrow Jun 3, 2021, 7:23 AM

#

you know you can select in paint and then copy paste here...

#

anyway, what is the goal here?

#

@upper karma what does your problem ask for?

upper karma Jun 3, 2021, 7:25 AM

#

what si max value of s

dark sparrow Jun 3, 2021, 7:25 AM

#

okay, why didn't you put that in your diagram...

upper karma Jun 3, 2021, 7:26 AM

#

i forgot

dark sparrow Jun 3, 2021, 7:27 AM

#

you forgot the most important part of the problem

#

the goal

#

but ok

#

why the ban on coordinate geometry?

upper karma Jun 3, 2021, 7:28 AM

#

i did not get with trigo and similiar triangles i wanna know how to do with that

dark sparrow Jun 3, 2021, 7:30 AM

#

one thing that jumps to mind is to express s in terms of R and the angle at C somehow

#

it would help if the diagram was cleaner and had more labels for points

upper karma Jun 3, 2021, 7:33 AM

#

i made the diagram very clear what u want more

dark sparrow Jun 3, 2021, 7:34 AM

#

i said "cleaner"

upper karma Jun 3, 2021, 7:34 AM

#

oh

dark sparrow Jun 3, 2021, 7:34 AM

#

right now it is not very aesthetically pleasing

upper karma Jun 3, 2021, 7:35 AM

#

i cannot snap a photo with my cam because the photo comes inverted so i made in paint

dark sparrow Jun 3, 2021, 7:37 AM

#

inverted?

#

if it's rotated by 180 degrees the bot can fix it

#

wait a minute.

#

if you keep R fixed while increasing the angle at C toward 90° the square will only grow bigger, won't it?

upper karma Jun 3, 2021, 7:39 AM

#

wait can u plz send me the soln afterward my class will start

dark sparrow Jun 3, 2021, 7:40 AM

#

...

#

i have no solution to send

upper karma Jun 3, 2021, 7:50 AM

#

i think we should write s in terms of R and then diffrentiate that expression and equate it with zero

dark sparrow Jun 3, 2021, 7:54 AM

#

wait, hold on

#

are C and R both allowed to vary?

upper karma Jun 3, 2021, 7:56 AM

#

C is fixed but R can vary

dark sparrow Jun 3, 2021, 7:56 AM

#

oh so R can vary...

#

why not let R approach infinity

#

then the square will grow larger and larger without bound

upper karma Jun 3, 2021, 8:01 AM

#

upper karma i think we should write s in terms of R and then diffrentiate that expression an...

i think this is better but how to find that realtion between R an s

dark sparrow Jun 3, 2021, 8:01 AM

#

...

#

s is clearly proportional to R tho

#

are you absolutely sure it's not C that can vary?

upper karma Jun 3, 2021, 8:03 AM

#

https://youtu.be/_yYZZ4HAdXs

YouTube

Michael Penn

Did I make this too hard?

We look at a nice geometry problem. Among other places this is found here:

Sacred Mathematics: Japanese Temple Geometry: https://amzn.to/2ZIadH9

Suggest a problem: https://forms.gle/ea7Pw7HcKePGB4my5

Please Subscribe: https://www.youtube.com/michaelpennmath?sub_confirmation=1

Merch: https://teespring.com/stores/michael-penn-math
Personal We...

▶ Play video

#

see i have seen this problem from this video

#

they solved it using coordinate but can u solve it by trigo

dark sparrow Jun 3, 2021, 8:06 AM

#

i'm at the gym rn so i'll need some time before i can watch this video

upper karma Jun 3, 2021, 8:08 AM

#

ok bro

dark sparrow Jun 3, 2021, 8:10 AM

#

don't call me bro.

#

i knew it, you missed an important detail!

#

AB = 1

upper karma Jun 3, 2021, 9:06 AM

#

ohh

#

thx bro

dark sparrow Jun 3, 2021, 9:08 AM

#

i JUST said

#

don't call me bro

#

and you ignored it

#

sully

#

@upper karma what the actual fuck

upper karma Jun 3, 2021, 9:22 AM

#

ok sorry

junior light Jun 3, 2021, 10:51 AM

#

upper karma thx bro

Knock it off, and make sure you don't do something like that in future.

lofty oxide Jun 3, 2021, 5:04 PM

#

#

just wonder what i did wrong

#

for the second angles

#

like why cant i rotate the pi/12 to the second quadrant

#

(its a little messy cause i wrote with a mouse sorry)

#

pls ping if anyone responds

cerulean moss Jun 3, 2021, 5:35 PM

#

lofty oxide

I got solutions 0, pi, pi/2, 3pi/2

#

I think i'm wrong though because i'm still learning this

lofty oxide Jun 3, 2021, 5:36 PM

#

lol thats not it

cerulean moss Jun 3, 2021, 5:36 PM

#

oh

#

what is it

lofty oxide Jun 3, 2021, 5:36 PM

#

haha nice try tho

#

pi/12

#

5pi/12

#

13pi/12

#

and

#

17pi/12

#

just need someone to help

cerulean moss Jun 3, 2021, 5:37 PM

#

😐

#

Omg

#

I used the double angle identities

lofty oxide Jun 3, 2021, 5:37 PM

#

i dunnnooo

cerulean moss Jun 3, 2021, 5:38 PM

#

waittttt

#

dont the answers have to be within 0<theta<2pi

#

bruh nvm

lofty oxide Jun 3, 2021, 5:39 PM

#

lol

full pewter Jun 3, 2021, 5:57 PM

#

Does anyone know where I can find all of the trig identities?

haughty rune Jun 3, 2021, 5:57 PM

#

someone help ASAP

#

trim breach Jun 3, 2021, 6:32 PM

#

Do you know how to use trigonometric ratios?

storm portal Jun 3, 2021, 6:34 PM

#

full pewter Does anyone know where I can find all of the trig identities?

internet

haughty rune Jun 3, 2021, 6:58 PM

#

trim breach Do you know how to use trigonometric ratios?

i forgot

#

can you help

trim breach Jun 3, 2021, 7:07 PM

#

haughty rune can you help

We want to start by solving for side PS.

#

We have 64 degrees as a reference angle.

haughty rune Jun 3, 2021, 7:08 PM

#

ok

trim breach Jun 3, 2021, 7:08 PM

#

Which is the ratio to express the opposite side and the hypotenuse?

#

Sine, cosine, or tangent?

haughty rune Jun 3, 2021, 7:08 PM

#

sine

trim breach Jun 3, 2021, 7:09 PM

#

Yes. Can you write an equation to solve for side PS?

lapis robin Jun 3, 2021, 7:32 PM

#

haughty rune Jun 3, 2021, 7:36 PM

#

trim breach Yes. Can you write an equation to solve for side PS?

wait im done that

#

#

Need help asap

cloud stump Jun 3, 2021, 7:55 PM

#

Anybody knows how to draw a quadrilateral that's both cyclic and tangential

trim breach Jun 3, 2021, 8:03 PM

#

haughty rune

Have you used the Law of Sines yet?

cloud stump Jun 3, 2021, 8:05 PM

#

,rotate

somber coyoteBOT Jun 3, 2021, 8:05 PM

#

cloud stump Jun 3, 2021, 8:06 PM

#

10=xcot60+xcot40

inland mountain Jun 3, 2021, 8:23 PM

#

#

The figurw to the right was a kite btw

#

So how would I figure out Acause I dont remeber how to and I dont know where to start

cloud stump Jun 3, 2021, 8:31 PM

#

lol

dull blade Jun 3, 2021, 11:01 PM

#

can somone help me

#

dull blade Jun 3, 2021, 11:30 PM

#

plez

#

😦

#

am confused on this one

trim breach Jun 4, 2021, 12:30 AM

#

dull blade can somone help me

Still need help?

dull blade Jun 4, 2021, 12:31 AM

#

Yes

trim breach Jun 4, 2021, 12:32 AM

#

What is the relationship between the two triangles?

dull blade Jun 4, 2021, 12:32 AM

#

Um idk

#

They are similar I guess

trim breach Jun 4, 2021, 12:33 AM

#

Yes.

#

So do you know what a scaling factor is?

dull blade Jun 4, 2021, 12:34 AM

#

Is it when it gets bigger or smaller

#

U scale down when less than 1 right

#

And scale up when highgher than 1

#

Right?

trim breach Jun 4, 2021, 12:34 AM

#

Yes.

#

Because these triangles are similar, they are scaled.

dull blade Jun 4, 2021, 12:35 AM

#

Ohhh

trim breach Jun 4, 2021, 12:35 AM

#

LMN has to be scaled down from XYZ.

dull blade Jun 4, 2021, 12:35 AM

#

Mhm

trim breach Jun 4, 2021, 12:36 AM

#

I presume that means any scale factor less than one is an acceptable answer since there is nothing else given.

#

So just scale the dimensions and find the lengths.

dull blade Jun 4, 2021, 12:36 AM

#

Am still confused a bit

trim breach Jun 4, 2021, 12:37 AM

#

The question states LMN is smaller.

dull blade Jun 4, 2021, 12:37 AM

#

I get it I think now

trim breach Jun 4, 2021, 12:37 AM

#

Therefore, the scale factor has to be less than one.

#

You can choose any scale factor that fits this criterion.

dull blade Jun 4, 2021, 12:38 AM

#

So I can put 12.5 divide by 1/2

trim breach Jun 4, 2021, 12:38 AM

#

Multiply*

#

But yes.

dull blade Jun 4, 2021, 12:38 AM

#

Oh ok

#

Thx

#

Much thanks

#

Didn't get it at all

silent plank Jun 4, 2021, 5:02 AM

#

what's your issue with these questions?

empty slate Jun 4, 2021, 5:27 AM

#

anyone up to vc and discuss a problem?

upper karma Jun 4, 2021, 1:42 PM

#

Can anyone help me understand how should I work out the x-coordinate of G?
For the y-coordinate it's just a triangle but I cant figure out the relation between s and xG

balmy stream Jun 4, 2021, 2:11 PM

#

cloud stump Anybody knows how to draw a quadrilateral that's both cyclic and tangential

It's called a bicentric quadrilateral. You can find a simple construction of it, on stack exchange or Wikipedia.

cloud stump Jun 4, 2021, 2:17 PM

#

balmy stream It's called a bicentric quadrilateral. You can find a simple construction of it,...

Yeah I didn't know its name but I ended up finding it on wikipedia, thanks anyway

upper karma Jun 4, 2021, 2:30 PM

#

Can anyone help me understand how should I work out the x-coordinate of G?
For the y-coordinate it's just a triangle but I cant figure out the relation between s and xG

cloud stump Jun 4, 2021, 3:09 PM

#

I don't understand Italian

upper karma Jun 4, 2021, 3:14 PM

#

It's a rotating half disk

#

does not really say anything apart from this

#

G is the barycenter of the disck

#

i can find it's y-coordinate just by tackign l-lsin\theta where l is the height of the line with A

#

but i cant seem do find anything for the x-coordinate

balmy stream Jun 4, 2021, 6:23 PM

#

upper karma but i cant seem do find anything for the x-coordinate

Is that AG, perpendicular to the flat surface of the circle?

spring forum Jun 4, 2021, 6:30 PM

#

#

how do i find a numerical value for 4theta without finding theta

silk patio Jun 4, 2021, 7:00 PM

#

Use the first two equations to find a relationship

onyx knot Jun 4, 2021, 7:14 PM

#

Could someone help me with this? I have little knowledge on the subject, I just wanna see the steps on how to solve it. Thanks

tiny snow Jun 4, 2021, 7:39 PM

#

@onyx knot It’s a right angled triangle. Every inscribed triangle with the diameter as a base is right angled. Is that sufficient for you to solve the rest on your own?

grim rampart Jun 4, 2021, 8:19 PM

#

can someone help me

#

whats the difference between vertex angles and verticle nagles

silent plank Jun 4, 2021, 9:52 PM

#

do you have some context of where vertex angles is being used?

grim rampart Jun 4, 2021, 10:25 PM

#

yes, i wrote few notes but im confused on the terms

#

#

for A2

#

he mentioned that verticle angles are the same as saying vertex angles?

silent plank Jun 5, 2021, 12:28 AM

#

it doesn't say vertex angles anywhere

#

the "vertex" points to the common vertex

#

the marked angles are congruent since they are vertical angles (or vertically opposite angles, which are the official terms)

#

"vertex angles" isn't really a common term but would refer to angles at a vertex (usually for polygons)
and just because there are angles at the same vertex doesn't necessarily mean that they're congruent

#

@grim rampart

leaden birch Jun 5, 2021, 1:35 PM

#

haughty rune

i just saw this but is this the correct way to do it?

trim breach Jun 5, 2021, 1:53 PM

#

leaden birch i just saw this but is this the correct way to do it?

I used Law of Sines to get the hypotenuse for the 30-60-90 and solved for x that way.

#

I got 5.65 though.

leaden birch Jun 5, 2021, 2:08 PM

#

oh

#

was there a mistake in my process?

#

so would my y be (xrad3)/3 using your 30-60-90 triangle method?

trim breach Jun 5, 2021, 2:45 PM

#

Yes…I cannot really find a mistake in your process. Maybe I did something wrong?

silent plank Jun 5, 2021, 2:46 PM

#

mistake in the very first line

trim breach Jun 5, 2021, 2:47 PM

#

Oh.

#

Yeah…wrong ratio.

#

Idk why I just glossed over that.

near whale Jun 5, 2021, 6:59 PM

#

I just discovered the hexagon chart for sin/tan/sec/cos/cot/csc and oh my god it's so helpful.

leaden birch Jun 5, 2021, 9:49 PM

#

silent plank mistake in the very first line

oh whoops lol