#geometry-and-trigonometry | Mathematics | Page 346

lethal sigil Mar 25, 2021, 5:36 PM

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(b xh) - [4(pi x r^2)/4]

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4/4 = 1

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@sw3atydemon

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@devout cove

near imp Mar 25, 2021, 5:48 PM

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so this is something new we are learning today and i’m still trying to understand how to go about solving this

trim breach Mar 25, 2021, 5:56 PM

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near imp so this is something new we are learning today and i’m still trying to understan...

The question is just applying those definitions, really. Have you studied the graphs of trigonometric functions yet?

near imp Mar 25, 2021, 5:57 PM

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trim breach The question is just applying those definitions, really. Have you studied the g...

not really i have the notes but no proper explanation on what i’m suppose to do this is the first day we’ve done this

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i think whats really throwing me off on this equation is the numbers in the graph for some reason

trim breach Mar 25, 2021, 6:02 PM

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Along the x-axis, that is actually pretty standard. If you Google the graphs of f(x) = sin(x) and f(x) = cos(x), you might be able to get a feel for how the graphs look and how to apply some of the terms.

near imp Mar 25, 2021, 6:03 PM

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hm ok i see what you’re saying!

trim breach Mar 25, 2021, 6:05 PM

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Cool…just ping me back if you get stuck or have any questions!

near imp Mar 25, 2021, 6:05 PM

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ok thank you for your amazing help!!

abstract prairie Mar 25, 2021, 6:55 PM

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Can anyone help me with these PES2_EmbarrassedAsk

abstract prairie Mar 25, 2021, 7:17 PM

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man

meager karma Mar 25, 2021, 7:28 PM

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do @.helpers

wintry tundra Mar 25, 2021, 7:28 PM

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circles are hard im sorry ;-;

meager karma Mar 25, 2021, 7:29 PM

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can u help with this real quick

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i just wanna know if i set it up right and how i would solve that 🧍‍♂️

wintry tundra Mar 25, 2021, 7:35 PM

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U set it up right

meager karma Mar 25, 2021, 7:36 PM

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wintry tundra U set it up right

how would i solve it

wintry tundra Mar 25, 2021, 7:36 PM

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That's what I'm trying to see

meager karma Mar 25, 2021, 7:37 PM

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would u do 360/2 to find the base of one of the triangles

wintry tundra Mar 25, 2021, 7:37 PM

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Nah cuz they aren't split evenly

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Alright I found it

meager karma Mar 25, 2021, 7:37 PM

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o

wintry tundra Mar 25, 2021, 7:37 PM

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Ur learning trig?

meager karma Mar 25, 2021, 7:37 PM

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yeah

wintry tundra Mar 25, 2021, 7:37 PM

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Cool

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This will be ok then

meager karma Mar 25, 2021, 7:38 PM

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okok

wintry tundra Mar 25, 2021, 7:38 PM

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Alright so first u need to find the supplement of the sum of the angles of depression

meager karma Mar 25, 2021, 7:38 PM

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huh

wintry tundra Mar 25, 2021, 7:40 PM

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Do u know how to do that

meager karma Mar 25, 2021, 7:42 PM

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noo we’re learning ab the law of sines and cosines so i think i have to use that

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it’s easy but my brain is dumb so

wintry tundra Mar 25, 2021, 7:42 PM

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Nah ur fine

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Some people either don't get math off the bat or didn't get taught an optimal way so don't beat urself up

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Anyways let's break down what I said

meager karma Mar 25, 2021, 7:42 PM

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yeah my teacher isn’t that great lmao

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ok

wintry tundra Mar 25, 2021, 7:43 PM

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What are the angles of depression

meager karma Mar 25, 2021, 7:43 PM

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the 72 and 40 degrees

wintry tundra Mar 25, 2021, 7:43 PM

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Yeah

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So now take the sum of those

meager karma Mar 25, 2021, 7:44 PM

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so 112 degrees

tiny snow Mar 25, 2021, 7:44 PM

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wintry tundra What are the angles of depression

It's what you get when you evaluate the root of evil 😉

wintry tundra Mar 25, 2021, 7:44 PM

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tiny snow It's what you get when you evaluate the root of evil 😉

Fair enough

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Alright so what is a supplement @meager karma

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With respect to geometry of course

meager karma Mar 25, 2021, 7:44 PM

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i have no idea 🏃‍♂️🏃‍♂️

wintry tundra Mar 25, 2021, 7:44 PM

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Oh

meager karma Mar 25, 2021, 7:45 PM

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HAHA i don’t remember

wintry tundra Mar 25, 2021, 7:45 PM

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Well a complement is an angle measure that makes another angle 90 degrees or pi/2 radians

meager karma Mar 25, 2021, 7:45 PM

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ok then

wintry tundra Mar 25, 2021, 7:46 PM

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A supplement is the same but for 180 degrees or pi radians

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Remember those

meager karma Mar 25, 2021, 7:46 PM

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okkkk

wintry tundra Mar 25, 2021, 7:46 PM

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So now find the supplement in degrees of the sum of the angles of depression

meager karma Mar 25, 2021, 7:47 PM

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bruh

wintry tundra Mar 25, 2021, 7:47 PM

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Find the supplement of 112

meager karma Mar 25, 2021, 7:47 PM

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68?

wintry tundra Mar 25, 2021, 7:47 PM

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Yep

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Nice

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So now the top angle of the large triangle is 68

meager karma Mar 25, 2021, 7:48 PM

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yes

wintry tundra Mar 25, 2021, 7:48 PM

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Alright

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Now we gotta use everyone's favorite: parallel lines and transversals

meager karma Mar 25, 2021, 7:48 PM

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ok how

wintry tundra Mar 25, 2021, 7:49 PM

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Do u remember interior angle and alternate angles and all those

meager karma Mar 25, 2021, 7:49 PM

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kinda

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i learned geometry years ago 🧍‍♂️

wintry tundra Mar 25, 2021, 7:49 PM

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Yeah its needed here

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So because we want to find how high the blimp is, we can say that the blimps height and the ground are parallel

meager karma Mar 25, 2021, 7:50 PM

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yes

wintry tundra Mar 25, 2021, 7:50 PM

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Aka the blimp is not approaching the ground or getting higher from the ground

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So I want to find the rightmost angle on the big triangle

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Post the hw again for me

meager karma Mar 25, 2021, 7:51 PM

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ok

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one sec

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wintry tundra Mar 25, 2021, 7:53 PM

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Alright so let's say the side of the triangle that the 40 is by is infinite and is crossing both the height and the ground

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Then there would be even more angles

meager karma Mar 25, 2021, 7:53 PM

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okkkk

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so do u want me to find the rest of the missing angles in the whole triangle

wintry tundra Mar 25, 2021, 7:54 PM

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Well

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I guess but there's more to that

meager karma Mar 25, 2021, 7:54 PM

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ya so what do we do

wintry tundra Mar 25, 2021, 7:54 PM

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So this is what would happen with the side

Screenshot_20210325-145351_Paint_Free_-_Drawing_Fun.jpg

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We want to find the angle with the ? by it

meager karma Mar 25, 2021, 7:54 PM

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so alt angles for both 72 and 40

wintry tundra Mar 25, 2021, 7:55 PM

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Yeah

meager karma Mar 25, 2021, 7:55 PM

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ok

wintry tundra Mar 25, 2021, 7:55 PM

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Alt int angles

meager karma Mar 25, 2021, 7:55 PM

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so the angle on the left would be 72 and the right 40

wintry tundra Mar 25, 2021, 7:55 PM

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👍

meager karma Mar 25, 2021, 7:55 PM

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yess so now what

wintry tundra Mar 25, 2021, 7:55 PM

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Now we can split the 68

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So u need to find the complement of 40 and 72

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Complements my bad

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So the comp of 40 then the comp of 72

meager karma Mar 25, 2021, 7:56 PM

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so for 40 it would be 50

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and for 72 it would be 18?

wintry tundra Mar 25, 2021, 7:57 PM

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Yep

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And 50 and 18 happen to add up to 68

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How nice

meager karma Mar 25, 2021, 7:57 PM

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very nice

wintry tundra Mar 25, 2021, 7:57 PM

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So put 50 and 18 where they belong

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Then we will use trig to get our answer

meager karma Mar 25, 2021, 7:57 PM

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so which triangle do u wanna use to solve how high the blimp is

wintry tundra Mar 25, 2021, 7:58 PM

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Doesn't matter

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Whatever works

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But let's use 40 degree triangle bc why not

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Alright so do u remember the law of sines?

meager karma Mar 25, 2021, 7:59 PM

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uhh yes

wintry tundra Mar 25, 2021, 7:59 PM

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Well let's use it then

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Wait a sec I might have missed a step lemme check

meager karma Mar 25, 2021, 7:59 PM

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wait what ab the base of the triangle

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do we need for find that

wintry tundra Mar 25, 2021, 7:59 PM

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Nvm we are good

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Well we have every angle we need so we can use the law of sines

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To get the sides

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So what angle side pair do we have

meager karma Mar 25, 2021, 8:00 PM

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it would look like this right

wintry tundra Mar 25, 2021, 8:01 PM

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Yeah we need the big triangle

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My bad

meager karma Mar 25, 2021, 8:01 PM

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o

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LMAO my drawing skills

wintry tundra Mar 25, 2021, 8:04 PM

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Looks fine to me

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Anyways there's only one angle and side that are opposite each other

meager karma Mar 25, 2021, 8:05 PM

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uhhh

wintry tundra Mar 25, 2021, 8:05 PM

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What are they?

meager karma Mar 25, 2021, 8:07 PM

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bruh idk wouldn’t there be multiple that are opposite of each other

wintry tundra Mar 25, 2021, 8:08 PM

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Nah bc there's only one side that we know of

meager karma Mar 25, 2021, 8:08 PM

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so would it just be the 68 degrees and 360

wintry tundra Mar 25, 2021, 8:08 PM

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Yep

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So we want to find the hypotenuse of the 40 triangle

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What angle on the big triangle is opposite to that hypotenuse

meager karma Mar 25, 2021, 8:09 PM

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would it be 90

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cause it’s a right triangle orrr

wintry tundra Mar 25, 2021, 8:09 PM

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On the small triangle yes

meager karma Mar 25, 2021, 8:09 PM

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ok

wintry tundra Mar 25, 2021, 8:09 PM

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On the big triangle no

meager karma Mar 25, 2021, 8:09 PM

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oh on the big one

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72

wintry tundra Mar 25, 2021, 8:09 PM

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Yep

meager karma Mar 25, 2021, 8:09 PM

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oops

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ok

wintry tundra Mar 25, 2021, 8:09 PM

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So use law of sines now

meager karma Mar 25, 2021, 8:11 PM

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so wouldn’t that be x/sin72 and 360/sin68 or am i dumb

wintry tundra Mar 25, 2021, 8:11 PM

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U are smart

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Bc that's right

meager karma Mar 25, 2021, 8:11 PM

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yay lol

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ok

wintry tundra Mar 25, 2021, 8:12 PM

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Man I'm excited to take trig next year with these kinds of problems

meager karma Mar 25, 2021, 8:12 PM

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why are u excited 😭😭

wintry tundra Mar 25, 2021, 8:13 PM

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Bc I've already self studied this year so I can breeze thru the class

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But what did u get for x

meager karma Mar 25, 2021, 8:13 PM

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o ok wait

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so setup would be 360sin72/ sin68 right

wintry tundra Mar 25, 2021, 8:14 PM

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Yep

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And don't turn that into decimals

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Just keep it like that

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So we can be more accurate

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But now it's time for the last step

meager karma Mar 25, 2021, 8:14 PM

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wait so it’s 369.27

wintry tundra Mar 25, 2021, 8:15 PM

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Yes but don't turn it into that yet

meager karma Mar 25, 2021, 8:15 PM

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o

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how come

wintry tundra Mar 25, 2021, 8:15 PM

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It's less accurate

meager karma Mar 25, 2021, 8:15 PM

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so what do we do now

wintry tundra Mar 25, 2021, 8:15 PM

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Use the small triangle

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Last step time

meager karma Mar 25, 2021, 8:15 PM

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ok

wintry tundra Mar 25, 2021, 8:15 PM

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So now we want to find the height which you can use the law of sines for

meager karma Mar 25, 2021, 8:16 PM

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oh wait so we just solved the hypotenuse of the small triangle rights

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right

wintry tundra Mar 25, 2021, 8:16 PM

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( sin(72)360 / sin(68) ) / sin 90 = x/sin(40)

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Also yeah we did

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The 40 triangle hypotenuse

meager karma Mar 25, 2021, 8:16 PM

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man what is that

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yeah^

wintry tundra Mar 25, 2021, 8:17 PM

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Thats the last thing to do

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But luckily

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guess what sin(90) is

meager karma Mar 25, 2021, 8:17 PM

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1

wintry tundra Mar 25, 2021, 8:17 PM

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Mhm

meager karma Mar 25, 2021, 8:17 PM

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ok so what does that last step do 🏃‍♂️

wintry tundra Mar 25, 2021, 8:17 PM

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Get the answer

meager karma Mar 25, 2021, 8:17 PM

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HA ok wait

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so 369.27=x/sin40

wintry tundra Mar 25, 2021, 8:18 PM

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Don't turn it into decimals

meager karma Mar 25, 2021, 8:18 PM

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o

wintry tundra Mar 25, 2021, 8:18 PM

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Keep it as fraction

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Only turn the answer into decimals

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Do u know what to do for the answer?

meager karma Mar 25, 2021, 8:28 PM

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oh sorry there was a police man at my door LMAO

meager karma Mar 25, 2021, 8:30 PM

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wintry tundra Do u know what to do for the answer?

woukd it be 237.36

wintry tundra Mar 25, 2021, 8:32 PM

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It sure would

meager karma Mar 25, 2021, 8:32 PM

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wow thank u sm this took 68000 years

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ur the best

wintry tundra Mar 25, 2021, 8:32 PM

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No problem

vivid schooner Mar 25, 2021, 9:41 PM

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I see congruence because of reflection and the sides of both triangles which I thought was -ss ; not enough info- but the correct answer was -sss congruence-. how?

silent plank Mar 25, 2021, 9:46 PM

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the triangles share a common side

upper karma Mar 26, 2021, 4:23 AM

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Any one willing to help me w these?

vast python Mar 26, 2021, 4:31 AM

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Use Gaussian Elimination can someone walk me through this

dark sparrow Mar 26, 2021, 4:39 AM

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,rccw

somber coyoteBOT Mar 26, 2021, 4:39 AM

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dark sparrow Mar 26, 2021, 4:40 AM

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okay so @upper karma @vast python one of you will need to move out of this channel

upper karma Mar 26, 2021, 4:41 AM

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Oh.. why?

dark sparrow Mar 26, 2021, 4:41 AM

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you posted your questions within minutes of each other

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and presumably you both want help

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but having that happen in one channel won't do

vast python Mar 26, 2021, 4:42 AM

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I’ll leave then

dark sparrow Mar 26, 2021, 4:42 AM

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just go to another channel, there's no need to leave the server outright lol

dark sparrow Mar 26, 2021, 4:42 AM

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upper karma Any one willing to help me w these?

okay so with this

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which problem number would you like to start with?

upper karma Mar 26, 2021, 4:43 AM

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dark sparrow which problem number would you like to start with?

7

dark sparrow Mar 26, 2021, 4:43 AM

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uh huh

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so you've done 5 and 6 already, yes?

upper karma Mar 26, 2021, 4:44 AM

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oh but i fuigured out 9 and 10

upper karma Mar 26, 2021, 4:44 AM

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dark sparrow so you've done 5 and 6 already, yes?

yea

dark sparrow Mar 26, 2021, 4:44 AM

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okay

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the concept's the exact same here.

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get the slope of your line by using its perpendicularity to the given line, and then pin down the y-intercept by using the point.

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is something giving you trouble in number 7 that didn't come up in 5 or 6?

upper karma Mar 26, 2021, 4:45 AM

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dark sparrow is something giving you trouble in number 7 that didn't come up in 5 or 6?

yea

dark sparrow Mar 26, 2021, 4:45 AM

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okay, what is it

upper karma Mar 26, 2021, 4:46 AM

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oh shoot nvmm i saw what i did i pinned it wrong which got me whole nother answer

dark sparrow Mar 26, 2021, 4:46 AM

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well then

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i guess that's taken care of

upper karma Mar 26, 2021, 4:46 AM

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well tyyy

dark sparrow Mar 26, 2021, 4:47 AM

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anything else?

upper karma Mar 26, 2021, 4:47 AM

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nope im good😀

dark sparrow Mar 26, 2021, 4:49 AM

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ok

upper karma Mar 26, 2021, 11:06 AM

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hi

near imp Mar 26, 2021, 2:50 PM

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i think i’m overthinking it again but can someone help me with this problem (there’s more like this but this is just one of them i don’t wanna ask for too much)

dense perch Mar 26, 2021, 2:55 PM

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We know it goes from -pi to 3pi

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So the period is 4pi

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Since it goes 4 to -4 on altitude... the amp is 8/2 or 4

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Btw B would be 2pi / 4pi, or 1/2

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Hope that helps!

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Ping me if you don’t get it por favor, and I’ll try to help

near imp Mar 26, 2021, 3:01 PM

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dense perch Ping me if you don’t get it por favor, and I’ll try to help

hm ok i got what you’re saying it makes total sense thank you so much!! this confuses me quite a bit you’re a really great help !!

dense perch Mar 26, 2021, 3:02 PM

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Np

near imp Mar 26, 2021, 3:02 PM

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i have 2 more equations like this if it’s alright can you help me with them as well?

dense perch Mar 26, 2021, 3:02 PM

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Go for it

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I’m bored anyways

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I’ll try my best to help lol

near imp Mar 26, 2021, 3:03 PM

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here they are lol

dense perch Mar 26, 2021, 3:03 PM

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Alright, so amplitude is always (highest point - lowest point) /2...

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So the first one goes from 1/2 to -1/2

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A distance of 1

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Divide that by 2 and you have the amp

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For period, we know it goes pi/8 increments

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So it’s distance is 4pi/8 when we count

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And B would hypothetically be 2pi /(4pi/8)

near imp Mar 26, 2021, 3:06 PM

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hm ok so with the amp would it be 1/2 since we divide the distance by 2?

dense perch Mar 26, 2021, 3:06 PM

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Yes

near imp Mar 26, 2021, 3:06 PM

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ok got u

dense perch Mar 26, 2021, 3:06 PM

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Do you want to try the amp for the second one?

near imp Mar 26, 2021, 3:06 PM

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i can try!

dense perch Mar 26, 2021, 3:07 PM

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What do you think it is?

near imp Mar 26, 2021, 3:07 PM

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i want to say it’s a decimal or fraction because of where it is located where it’s increasing

dense perch Mar 26, 2021, 3:08 PM

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First: find the max and min values:

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That would be 2 and -2

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We then subtract: 2 - (-2) = 4

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And the amp is 4/2 = 2

near imp Mar 26, 2021, 3:08 PM

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oh ok i get what you’re saying

dense perch Mar 26, 2021, 3:08 PM

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Then, for period...

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Increments of pi:

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We go from 1pi to 5pi

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The period would be 4pi as a result...

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And B would hypothetically be 2pi/4pi = 2

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Do you think you get it?

near imp Mar 26, 2021, 3:10 PM

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so the period in the end would be 2

dense perch Mar 26, 2021, 3:10 PM

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No...

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Have you learned the equation for these problems yet?

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If not Dw about “B”

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Your answer is 4pi

near imp Mar 26, 2021, 3:11 PM

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ohhhh wait i get what you’re saying

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sorry i was overthinking it

dense perch Mar 26, 2021, 3:11 PM

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Nah lol, your good

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It’s really confusing sometimes

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You’re definitely not the only one

near imp Mar 26, 2021, 3:11 PM

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yeah it is lol but i get what you’re saying thank you for the help!

dense perch Mar 26, 2021, 3:11 PM

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Np, if you have more questions, feel free to ping me

woeful gyro Mar 26, 2021, 3:12 PM

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Plz,backup. before i go crazy. How do i go about calculating the angle PQR

dark sparrow Mar 26, 2021, 3:12 PM

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it... looks like there isn't enough info?

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oh wait no nvm

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there is

tiny snow Mar 26, 2021, 3:13 PM

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Like we said in another channel...

dark sparrow Mar 26, 2021, 3:13 PM

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you can just calculate all sides of triangle PQR and apply the law of cosines

tiny snow Mar 26, 2021, 3:13 PM

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^ that

woeful gyro Mar 26, 2021, 3:14 PM

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to calculate RP hypotenuse id need an angle to work with? same for hypotenuse QP?

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should i just assumed 90 degrees or what

dark sparrow Mar 26, 2021, 3:14 PM

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this whole shape is a prism, is it not?

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so presumably the front and right faces are both rectangles

dense perch Mar 26, 2021, 3:15 PM

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woeful gyro to calculate RP hypotenuse id need an angle to work with? same for hypotenuse QP...

Do you know how to solve for an angle given two sides of a triangle?

woeful gyro Mar 26, 2021, 3:15 PM

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ok if thats the case, i got RP to 12.8cm and QP to 15.6cm

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i know how to solve angles for 3 sides no angle and 2 sides 1 angle.

dense perch Mar 26, 2021, 3:17 PM

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Basically, we know all the sides of the face (triangle on the top)

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So use trig to find angle QR”X” on the face

dark sparrow Mar 26, 2021, 3:17 PM

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do you really need that tho

dense perch Mar 26, 2021, 3:17 PM

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Use the 180 degrees in a triangle rule to find RQ”X”

dark sparrow Mar 26, 2021, 3:18 PM

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all you need is the length of RQ, which is just sqrt(12^2 + 8^2)

dense perch Mar 26, 2021, 3:18 PM

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dark sparrow do you really need that tho

Aren’t we solving for an angle or something?

dark sparrow Mar 26, 2021, 3:18 PM

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yeah but not the one you were talking about.

woeful gyro Mar 26, 2021, 3:18 PM

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yes, angle PQR

dense perch Mar 26, 2021, 3:19 PM

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Oh lol, my bad, I just woke up

woeful gyro Mar 26, 2021, 3:21 PM

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soo assuming my calculations for RP and QP is correct. how to i find myself an angle to work with/ the last side

dark sparrow Mar 26, 2021, 3:22 PM

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dark sparrow all you need is the length of RQ, which is just sqrt(12^2 + 8^2)

see here

woeful gyro Mar 26, 2021, 3:23 PM

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what u do there tho? p^2=12^2+8^2-2* 12*8 *cosp?

dark sparrow Mar 26, 2021, 3:23 PM

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??

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figuring out RQ is just the pythagorean theorem

woeful gyro Mar 26, 2021, 3:24 PM

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oh, right.

dark sparrow Mar 26, 2021, 3:24 PM

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after that, your angle is just $\arccos(\frac{RQ^2 + PQ^2 - RP^2}{2 \cdot RQ \cdot PQ})$

somber coyoteBOT Mar 26, 2021, 3:24 PM

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Ann

woeful gyro Mar 26, 2021, 3:25 PM

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gotcha cheers, the the figure itself makes me confused xd

lament shell Mar 26, 2021, 3:35 PM

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what did i do wrong?

dark sparrow Mar 26, 2021, 3:36 PM

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lets see...

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it appears that your only problem is rounding when you weren't asked to

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x should be 10/3, which is not equal to 3.30 exactly.

silent plank Mar 26, 2021, 3:46 PM

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problem is 4*8 = 32 not 24

lament shell Mar 26, 2021, 3:48 PM

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yeah im dumb lol

dark sparrow Mar 26, 2021, 3:50 PM

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or that

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which somehow escaped me lol

dapper bronze Mar 26, 2021, 4:05 PM

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Need help

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Someone help

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Looking for the angle

trim breach Mar 26, 2021, 4:19 PM

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dapper bronze Need help

It’s a rhombus. There is a property of diagonals that makes the triangles solvable.

candid forge Mar 26, 2021, 4:41 PM

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Can someone explain why e^iθ= cosθ+isinθ intuitively? I understand the proof using Taylor series but I would like a more geometric approach

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I don’t if this is the correct channel to ask that

keen abyss Mar 26, 2021, 4:47 PM

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Try watching 3b1b s video it's pretty nice

keen abyss Mar 26, 2021, 4:48 PM

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dapper bronze Someone help

It's just 2ABE use pythagoras and inverse trig it's pretty simple

wraith cargo Mar 26, 2021, 4:49 PM

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trim breach Mar 26, 2021, 4:53 PM

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wraith cargo

Those are similar triangles in 10 since two angles between them are congruent. You can set up a proportion knowing this fact.

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And 11 is an angle bisector problem where you can set up a proportion to solve for x.

wraith cargo Mar 26, 2021, 5:01 PM

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fickle geyser Mar 26, 2021, 5:25 PM

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yo

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yo

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yo

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do yall know proofs

trim breach Mar 26, 2021, 5:50 PM

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Someone here can help, so you can just post your question.

lofty granite Mar 26, 2021, 6:06 PM

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anyone available?

dark sparrow Mar 26, 2021, 6:09 PM

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no clearly nobody is ever available on this server which hasnt been posted to in 10 years (/massive sarcasm)

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post your question.

lofty granite Mar 26, 2021, 6:11 PM

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lmao okayyy

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i did 648^2 and got that large ass number

dark sparrow Mar 26, 2021, 6:15 PM

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648^2?

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why would you do 648^2?

lofty granite Mar 26, 2021, 6:15 PM

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is the formula not a^2 + b^2 = c^2?

dark sparrow Mar 26, 2021, 6:15 PM

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it is

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but what you are doing is c = (a^2+b^2)^2 apparently

lofty granite Mar 26, 2021, 6:15 PM

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wait

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so do i sqaure 648?

dark sparrow Mar 26, 2021, 6:16 PM

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no! you don't!

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you have c^2 = 648

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this doesn't mean c = 648^2 at all

lofty granite Mar 26, 2021, 6:17 PM

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ooh

dark sparrow Mar 26, 2021, 6:17 PM

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you want the opposite of squaring.

lofty granite Mar 26, 2021, 6:17 PM

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so

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square root it?

mint dune Mar 26, 2021, 6:18 PM

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~yes~

lofty granite Mar 26, 2021, 6:19 PM

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oh

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sorry, im still trying to understand trig

mint dune Mar 26, 2021, 6:20 PM

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at least you're asking questions

lofty granite Mar 26, 2021, 6:21 PM

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yeah, my teacher is no help lol

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mind if i double check with another question?

fickle prairie Mar 26, 2021, 6:26 PM

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Hey everyone! I'm stuck with an analytic geometry problem.
Given that VABC is a tetrahedron where AB = AC = BC = a, VA = VB = VC = b, b>a, I have to prove that (VA x VB) x VC = ( (2(b^2) - a^2 ) / 2) AB

mint dune Mar 26, 2021, 6:26 PM

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fickle prairie Hey everyone! I'm stuck with an analytic geometry problem. Given that VABC is a...

you've written c and b in different places

fickle prairie Mar 26, 2021, 6:27 PM

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Indeed, thank you.

lofty granite Mar 26, 2021, 6:27 PM

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fickle prairie Mar 26, 2021, 6:28 PM

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fickle prairie Hey everyone! I'm stuck with an analytic geometry problem. Given that VABC is a...

I have used the triple product expansion formula but I am stuck at the trigonometry part of this...

lofty granite Mar 26, 2021, 6:28 PM

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is 19.03 correct? im not sure if i did it right

mint dune Mar 26, 2021, 6:28 PM

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fickle prairie I have used the triple product expansion formula but I am stuck at the trigonome...

are those vectors or lengths

fickle prairie Mar 26, 2021, 6:28 PM

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What I have so far is:
(b^2 cos(VA,VC)) VB - (b^2 cos(VB,VC)) VA

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I have to prove for vectors, but the given data is for lengths

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I don't know how to indicate vectors here

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And I have to prove this

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Sorry about the bad image quality.

lofty granite Mar 26, 2021, 6:48 PM

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can someone explain how i got the answer for X as 25.45 but it says its 18 square root 2 which is literally the same answer

upper karma Mar 26, 2021, 6:50 PM

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can someone help me with this

upper karma Mar 26, 2021, 6:53 PM

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lofty granite

lofty granite Mar 26, 2021, 6:54 PM

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upper karma

very appreciated. but i dont understand where the 2 square root comes from

fickle prairie Mar 26, 2021, 7:12 PM

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It comes from the same theorem

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Think of it like this: a^2 + b^2 = c^2. In your case c is 10, and X takes the place of either a or b, but in this case of both, because of the 45 degree angle

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This makes it 2 * a^2 = c^2

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And now extract square root from both sides

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Now you have square root 2 * a = c

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And thus Heisenberg's answer follows

upper karma Mar 26, 2021, 7:32 PM

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lofty granite very appreciated. but i dont understand where the 2 square root comes from

dude that's a rule

onyx knot Mar 26, 2021, 7:39 PM

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How would I solve this

wise hornet Mar 26, 2021, 7:50 PM

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what have you tried

wise hornet Mar 26, 2021, 7:52 PM

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onyx knot How would I solve this

oi

onyx knot Mar 26, 2021, 7:52 PM

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mb somebody is helpin in me #help-9

woven haven Mar 26, 2021, 8:00 PM

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onyx knot How would I solve this

46/13= 3.538...
3.538...*5= 17.69230...
Round to the nearest 100th: 17.70

upper karma Mar 26, 2021, 8:03 PM

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Sorry,I didn’t see you answered m8

upper karma Mar 26, 2021, 9:02 PM

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this is chemistry but anyways.

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can you think of what 28% of Na, 32% of Cr and 40% of O means with respect to the mass of each component? any ideas?

storm portal Mar 26, 2021, 10:35 PM

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@fallow ruin ^^

upper karma Mar 26, 2021, 10:48 PM

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Can anyone help

upper karma Mar 26, 2021, 11:26 PM

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Hey, I need help

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trim breach Mar 26, 2021, 11:31 PM

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upper karma

In a 45-45-90 triangle, the Pythagorean Theorem essentially is 2(a^2) = c^2.

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And since it is 45-45-90, both legs are equal length.

copper marten Mar 26, 2021, 11:54 PM

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upper karma

https://www.dummies.com/wp-content/uploads/372023.image1.jpg

upper karma Mar 27, 2021, 12:00 AM

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Tysm!

lofty granite Mar 27, 2021, 1:13 AM

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is anyone able to hop in a vc and help explain this math problem to me?

proven moat Mar 27, 2021, 2:40 AM

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someone help me please

trim breach Mar 27, 2021, 3:09 AM

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proven moat someone help me please

Use Pythagorean Theorem to solve for y.

grand widget Mar 27, 2021, 3:41 AM

#

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What is the answer?
Can you?

tiny snow Mar 27, 2021, 8:56 AM

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Once you draw the sketch it's a very straightforward solution

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@grand widget ^

fickle prairie Mar 27, 2021, 11:46 AM

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Can someone help with university analytic geometry? I posted a problem yesterday but I'm still stuck with it

dense perch Mar 27, 2021, 12:47 PM

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For anyone looking to help laszlow, this was his question: Hey everyone! I'm stuck with an analytic geometry problem.
Given that VABC is a tetrahedron where AB = AC = BC = a, VA = VB = VC = b, b>a, I have to prove that (VA x VB) x VC = ( (2(b^2) - a^2 ) / 2) AB

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PS: I have no clue how to answer this lol. Gl

silk patio Mar 27, 2021, 1:43 PM

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Is that a cross product?

lyric quest Mar 27, 2021, 4:24 PM

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trisecting an angle with straightedge and ruler

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how do i do it for acute angles where it is possible

dark sparrow Mar 27, 2021, 4:55 PM

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straightedge and ruler?

lyric quest Mar 27, 2021, 4:55 PM

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straightedge and compass

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lmao

dark sparrow Mar 27, 2021, 4:56 PM

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is it even possible for any acute angles

lyric quest Mar 27, 2021, 4:56 PM

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well apparently its possible for 45

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and 27

dark sparrow Mar 27, 2021, 4:57 PM

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so it boils down to constructing an angle of 15 or 9 degrees respectively

lyric quest Mar 27, 2021, 4:58 PM

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well thats my issue really

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is it truly a trisection to construct an angle

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because if it is, 45 degree trisection is easy

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simply impose an equilateral triangle onto it

dark sparrow Mar 27, 2021, 4:58 PM

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trisection in the general case is impossible

lyric quest Mar 27, 2021, 4:58 PM

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60-45=15

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but in these specific cases

dark sparrow Mar 27, 2021, 4:58 PM

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so thats all you can get

lyric quest Mar 27, 2021, 4:59 PM

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like i am not even using the 45 degree angle to trisect

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i am just double bisecting a 60 degree angle

weary barn Mar 27, 2021, 7:39 PM

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https://cdn.discordapp.com/attachments/704699788100108440/825435921486315530/743706779187413023.png

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https://cdn.discordapp.com/attachments/704699788100108440/825436057859260476/743706779187413023.png

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how can I solve it without this assumption?

feral plank Mar 28, 2021, 3:38 AM

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Geometry pre test lol

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I missed a couple weeks due to a few personal reasons and my teacher wont help me setup a date after school or sometime to catch up

waxen glen Mar 28, 2021, 3:48 AM

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feral plank I missed a couple weeks due to a few personal reasons and my teacher wont help m...

do you still need help

feral plank Mar 28, 2021, 3:48 AM

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yeah lmaoo

waxen glen Mar 28, 2021, 3:48 AM

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hah okay lol

feral plank Mar 28, 2021, 3:48 AM

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im so stuck im trying khan academy shit dont work for me D:

waxen glen Mar 28, 2021, 3:48 AM

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do you know what is similiar triangles

feral plank Mar 28, 2021, 3:49 AM

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uhh

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like what?

waxen glen Mar 28, 2021, 3:49 AM

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what does similiar mean

feral plank Mar 28, 2021, 3:49 AM

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yeah i know that

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kinda

waxen glen Mar 28, 2021, 3:50 AM

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do you know what is "K number" in the similiar triangles

feral plank Mar 28, 2021, 3:50 AM

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tbh no 😓

waxen glen Mar 28, 2021, 3:51 AM

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okay lets start from what is ismiliars

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so similiar triangles' chosen side's ratios are always same

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and ratio is showen with K letter

feral plank Mar 28, 2021, 3:51 AM

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yeah

waxen glen Mar 28, 2021, 3:51 AM

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their height's ratios are equal to k too

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so K is ratio between similar triangles

feral plank Mar 28, 2021, 3:52 AM

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ah yeah

waxen glen Mar 28, 2021, 3:52 AM

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can u say which sides are similiars in your question

waxen glen Mar 28, 2021, 3:52 AM

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feral plank

.

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wait a min let me draw

feral plank Mar 28, 2021, 3:53 AM

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okay

waxen glen Mar 28, 2021, 3:53 AM

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can you say that AB side and A1C1 sides are similiar?

feral plank Mar 28, 2021, 3:54 AM

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so it would be

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the left and bottom?

waxen glen Mar 28, 2021, 3:54 AM

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no it is not, similiarity is ratio between chosen or right sides/heights

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so AC and A1C1 are similiar

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in similiar triangles, their angles are always same

feral plank Mar 28, 2021, 3:55 AM

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OHHHHH

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i got it lol that makes sense

waxen glen Mar 28, 2021, 3:55 AM

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as you can see, AB side is between 90 and 30 angle

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A1C1 is between 90 and 60

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so, they cant be similar sides

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if you want to find k, just divide similiar sides/heights/medians etc

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so AB/A1B1=AC/A1C1

feral plank Mar 28, 2021, 3:57 AM

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ab divided by a1b1 = ac divided by a1c1?

waxen glen Mar 28, 2021, 3:58 AM

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yes, because, ab/a1b1= k which is ratio between similiar sides

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AC and A1C1 are similar sides too

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so their ratio will be equal to k

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i think i did it a bit messy lol

feral plank Mar 28, 2021, 4:00 AM

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I was just making sure that the "/" was divide

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because some people write it weird

waxen glen Mar 28, 2021, 4:00 AM

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oh yes lol

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like, why humans write ÷ ? it looks like + and actually it is a bit different than normal divide "/"

light fable Mar 28, 2021, 6:30 AM

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waxen glen like, why humans write ÷ ? it looks like + and ***actually*** it is a bit differ...

The symbol ÷ is a fraction where the numerator and denominator are unknown (dots)

waxen glen Mar 28, 2021, 6:30 AM

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there are more difference between / and ÷

light fable Mar 28, 2021, 6:30 AM

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how so?

waxen glen Mar 28, 2021, 6:31 AM

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their solving order are a bit different

dark sparrow Mar 28, 2021, 6:31 AM

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nobody uses ÷ outside of primary school

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also you are NOT going to pull out this 6÷2(1+2) shit

waxen glen Mar 28, 2021, 6:31 AM

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o-okay

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hssssss

light fable Mar 28, 2021, 6:32 AM

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@waxen glen I believe they're exactly equivalent down to how they're used

waxen glen Mar 28, 2021, 6:33 AM

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yes'nt

light fable Mar 28, 2021, 6:33 AM

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and yes, ÷ is less common in professional math contexts, but there are some times it could be preferable

dark sparrow Mar 28, 2021, 6:34 AM

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really now

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are fractions not good enough for you

waxen glen Mar 28, 2021, 6:34 AM

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dark sparrow also you are NOT going to pull out this 6÷2(1+2) shit

can i use 6÷2(1+2) shit for explaining p-please

light fable Mar 28, 2021, 6:35 AM

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dark sparrow are fractions not good enough for you

Fractions are great but you don't always want to have to break out of normal line size

dark sparrow Mar 28, 2021, 6:36 AM

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then put parentheses in such a way that your expression is unambiguous.

light fable Mar 28, 2021, 6:36 AM

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you don't have to tell me

fair locust Mar 28, 2021, 8:24 AM

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waxen glen can i use 6÷2(1+2) shit for explaining p-please

is the answer to this not 9? [ like (6÷2) ×(3) = 3×3 =9 ]

or is it somehow 1 because 6 ÷(2×3) =6÷6=1 for some reason

dark sparrow Mar 28, 2021, 8:32 AM

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the whole point is that it's ambiguous as written.

fickle prairie Mar 28, 2021, 10:41 AM

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silk patio Is that a cross product?

Yes

fickle prairie Mar 28, 2021, 10:42 AM

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fickle prairie I have used the triple product expansion formula but I am stuck at the trigonome...

.

fickle prairie Mar 28, 2021, 10:42 AM

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fickle prairie

.

smoky yew Mar 28, 2021, 11:31 AM

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hi, i'm pretty new here :)) i can solve this thing but it will take too long for me to type in each value. Is there any practical solution for solving this types of things?

sharp plume Mar 28, 2021, 11:32 AM

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You need to write it summation form?

smoky yew Mar 28, 2021, 11:32 AM

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there is no instruction about that but if i need to, i will... my teacher isnt that strict about methods

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as long as the correct answer is given

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and im still in grade 9 so i might not understand a lot of stuff :<<

silent plank Mar 28, 2021, 11:40 AM

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consider some properties of sine
sin(x) + sin(360° - x) = 0
sin(x) + sin(180° + x) = 0
and/or the locations unit circle.
you should see that there will be a lot of cancellation

smoky yew Mar 28, 2021, 11:42 AM

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thank you :)) will update later if i struggle xD

tiny snow Mar 28, 2021, 5:08 PM

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How would you go about proving that something can be inscribed in an ellipse? Five points, foci, something else?

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Fiddling with the construction can be done here: https://www.geogebra.org/geometry/ttkza5zj

Geometry - GeoGebra

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Some kind of projection? A "skewed" hexagram looks like a regular hexagram seen in three dimensions from a perspective.

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Maybe not, it can become quite elongated...

dark sparrow Mar 28, 2021, 5:19 PM

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do circles not become ellipses when seen in 3d perspective?

tiny snow Mar 28, 2021, 5:19 PM

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I think so.

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I suppose that if I can find the projection that takes an ellipse to a circle it should take each vertex point to 60 degrees apart, and then we're done, but I am not so sure that is the simplest way.

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That's also given that my hunch about the perspective is right.

silk patio Mar 28, 2021, 5:31 PM

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It reminds me of the reflection property of the orthocentre across a side

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Are angle bisectors persevered under projective transformations? 🤔

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Surely not

tiny snow Mar 28, 2021, 5:42 PM

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But I can by continuous movement of the point A transform that thing to a regular hexagram on geogebra, while all the bisectors remain bisectors.

silk patio Mar 28, 2021, 6:12 PM

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Projective transformations don’t seem to work here

tiny snow Mar 28, 2021, 6:16 PM

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No, I think trilinear coordinates may be a way forward, as mentioned here: https://en.m.wikipedia.org/wiki/Steiner_ellipse

Steiner ellipse

In geometry, the Steiner ellipse of a triangle, also called the Steiner circumellipse to distinguish it from the Steiner inellipse, is the unique circumellipse (ellipse that touches the triangle at its vertices) whose center is the triangle's centroid. Named after Jakob Steiner, it is an example of a circumconic. By comparison the circumcircle ...

silk patio Mar 28, 2021, 6:18 PM

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Bashing won’t give you a vivid solution

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This reminds me of the incircle-excircle lemma if you’ve seen that

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I figured it out. It’s a generalisation of the 9 point circle

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The same construction works for any point, the angle bisector condition is redundant

mighty shell Mar 28, 2021, 6:56 PM

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I understand the working out, but I keep getting the wrong answer. How do I put the right equation into my calculator? It keep giving me a totally different answer

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That’s the answer, when I put what h equals to it’s giving my a different number

mighty shell Mar 28, 2021, 7:24 PM

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Nvm

tiny snow Mar 28, 2021, 8:14 PM

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silk patio I figured it out. It’s a generalisation of the 9 point circle

Thanks, I’ll look into that tomorrow. Are some of the same points sufficient to determine the ellipse, or did you mean something else when you said generalization?

silk patio Mar 28, 2021, 8:22 PM

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Yeah 9 special points are on the ellipse. Pick a point P inside the triangle. Draw the ellipse through the midpoints of AB AC and BC as well as the midpoints of AP and BP and you’ll see it passes through the midpoint of CP as well as the intersection of AP and BC, intersection of BP and AC, intersection of CP and AB

humble narwhal Mar 28, 2021, 9:45 PM

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Can anyone help me ?

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Where tau is a translation and rho is rotation

humble narwhal Mar 29, 2021, 1:16 AM

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<@&286206848099549185>

feral plank Mar 29, 2021, 2:04 AM

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I don't understand tbh. kinda giving up at this point bc i feel stupid

waxen glen Mar 29, 2021, 4:11 AM

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@feral plank if triangle's chosen sides' ratios are same, then they are similiar

feral plank Mar 29, 2021, 4:12 AM

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I already turned it in man dont waste ur time

waxen glen Mar 29, 2021, 4:12 AM

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so, divide 10,15 or 20 with 4,6,8 and look that are they same or not

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oh

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ok lol

feral plank Mar 29, 2021, 5:22 AM

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second part i guess

dark sparrow Mar 29, 2021, 5:31 AM

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is this a test hmm

feral plank Mar 29, 2021, 5:31 AM

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pre test

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the "1 point" thing is added up, like an actual test, but it goes to the hw category for our grade.

dark sparrow Mar 29, 2021, 6:06 AM

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okay

feral plank Mar 29, 2021, 6:07 AM

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I was wrong actually, it goes into the review category for my grade

dark sparrow Mar 29, 2021, 6:08 AM

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anyway

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do you still need help with this question

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i know it's been like half an hour

feral plank Mar 29, 2021, 6:08 AM

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yeah lol

dark sparrow Mar 29, 2021, 6:08 AM

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sorry for the delay on my end

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ok

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do you know what the midsegment of a triangle is

feral plank Mar 29, 2021, 6:08 AM

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yea

dark sparrow Mar 29, 2021, 6:08 AM

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okay

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what can you tell me about the midsegment

feral plank Mar 29, 2021, 6:09 AM

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i used to be good at them but like kinda forgot the stuff bc i havent done it in so long

dark sparrow Mar 29, 2021, 6:09 AM

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bruh

feral plank Mar 29, 2021, 6:09 AM

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this is last chapters stuff

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lmao

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i failed the test but this should help it

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i mean my grade anyway

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reviews are like 30 or something %

dark sparrow Mar 29, 2021, 6:10 AM

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nice question dodge

feral plank Mar 29, 2021, 6:10 AM

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midsegment i think like

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connects two angles?

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or like

dark sparrow Mar 29, 2021, 6:10 AM

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no

feral plank Mar 29, 2021, 6:10 AM

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add each angle and it equals that distance?

dark sparrow Mar 29, 2021, 6:10 AM

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...

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why did you lie to me about knowing what the midsegment is

feral plank Mar 29, 2021, 6:11 AM

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lol uh i thought thats what it was

dark sparrow Mar 29, 2021, 6:11 AM

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the midsegment connects the midpoints of two sides

feral plank Mar 29, 2021, 6:11 AM

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ah yeah that

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i meant sides not angles whoopsie

dark sparrow Mar 29, 2021, 6:11 AM

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in any case, triangles ABC and DBE are similar, with a scale factor of 2

feral plank Mar 29, 2021, 6:12 AM

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so the answer is 2 then?

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but how 😱

dark sparrow Mar 29, 2021, 6:13 AM

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no the answer isn't 2

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just because i said the number 2 somewhere doesn't mean the answer to your problem is 2

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sully

feral plank Mar 29, 2021, 6:15 AM

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lol welp im dumb what can i say

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i was kinda confused bc u said scale factor but thats not really the thing

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the type of solving its asking

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i mean

dark sparrow Mar 29, 2021, 6:15 AM

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one triangle is half the size of the other

feral plank Mar 29, 2021, 6:16 AM

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oh yeah lol

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i see that now

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LOL how the fuck did i not see that before

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oml im special

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yeah that makes sense

silent plank Mar 29, 2021, 6:17 AM

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is it just me or is the diagram over specified

feral plank Mar 29, 2021, 6:17 AM

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idk

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im dumb thats why im here

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so

dark sparrow Mar 29, 2021, 6:17 AM

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doesn't look overspecified to me

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there's an x, a y and a z

silent plank Mar 29, 2021, 6:18 AM

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the angles don't seem the match the values of the sides given that DE is the mid seg

dark sparrow Mar 29, 2021, 6:18 AM

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why not? angle C could be 72 degrees, and angle EDB could be 63 degrees

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and angle B = 45°

feral plank Mar 29, 2021, 6:19 AM

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so is x 45 ?

dark sparrow Mar 29, 2021, 6:20 AM

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bruh what the hell

feral plank Mar 29, 2021, 6:20 AM

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uh idk man

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im all over

dark sparrow Mar 29, 2021, 6:20 AM

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i was not even talking to you, i was addressing ramonov's doubt about the angles

feral plank Mar 29, 2021, 6:20 AM

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ik

dark sparrow Mar 29, 2021, 6:20 AM

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how about you actually read the messages i am sending instead of plucking a number i said out of context and asking me whether that's the answer

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4 234 45367 2342 2345623 324565344 6574536345 345345 3223453 464654562 345624579 454569 223463458 42069

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9919299135825 32838383548 232234 01341012049 56934596394593 220342 65534

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hymnth

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triangle DBE is literally the same as triangle ABC but shrunk by a factor of two

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idk what else to tell you

feral plank Mar 29, 2021, 6:22 AM

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aight

dark sparrow Mar 29, 2021, 6:22 AM

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if this isnt enoyugh for you to find the length of DE

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then maybe you need to review similar triangles

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instead of making me majorly upset like you just did

silent plank Mar 29, 2021, 6:22 AM

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based on the length of sides, wouldn't the angles work out to be around: ||~55.7°,~41.4°, ~82.8°||

feral plank Mar 29, 2021, 6:23 AM

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if u got upset bc im retarded ...

dark sparrow Mar 29, 2021, 6:24 AM

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there was no need to call yourself a slur

copper marten Mar 29, 2021, 6:54 AM

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feral plank if u got upset bc im retarded ...

if u still need help here's the explanation:

they are similar triangles and the mid segment is DE, that means CE and EB are the same and AD and DB are the same. 5+5 is 10 which is one side of the triangle ABC and 5 is the length corresponding to 10 of triangle DEB

therefore we can divide the corresponding side lengths to get the scale factor:
10/5 = 2

since we now know the scale factor is 2, then we can find x

what is the corresponding side length to x? it's AC which is given the value of 8.
the scale factor is 2, so divide 8/2 which gives you 4

x = 4

hope that helped cat_wink

feral plank Mar 29, 2021, 6:55 AM

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thank you

copper marten Mar 29, 2021, 6:55 AM

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no prob !!

feral plank Mar 29, 2021, 6:55 AM

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it did

copper marten Mar 29, 2021, 6:55 AM

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yay :))

feral plank Mar 29, 2021, 6:55 AM

#

little confusing but ill reread for the next couple to figure them out

copper marten Mar 29, 2021, 6:56 AM

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ok if you have any questions then just @ me or something lol

feral plank Mar 29, 2021, 6:56 AM

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yes i will tysm

hidden oracle Mar 29, 2021, 10:12 AM

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VECTOR

safe canyon Mar 29, 2021, 3:22 PM

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One message removed from a suspended account.

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One message removed from a suspended account.

vapid stag Mar 29, 2021, 4:11 PM

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hey if tan x= 1/3 and tan x = sin x/cos x. This means sin x = 1 and cos x = 3 right?

silent plank Mar 29, 2021, 4:13 PM

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no

vapid stag Mar 29, 2021, 4:32 PM

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well shit

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i just messed up my mid term question then

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how was i suppose to tackle this if not?

silent plank Mar 29, 2021, 4:35 PM

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draw a triangle,
apply pythagorean identities

next flower Mar 29, 2021, 4:53 PM

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how would i solve for z and y. ive solved for X it is 16.2 but i dont know how to solve for z and y

605d273facd61acbf76e2a6e_rich-text-file-2021-03-26T00-13-51-80Z.png

vapid stag Mar 29, 2021, 5:42 PM

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well it looks like i suck at math

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time to look for a new major?

storm portal Mar 29, 2021, 5:50 PM

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@vapid stag not necessarily

storm portal Mar 29, 2021, 5:50 PM

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next flower how would i solve for z and y. ive solved for X it is 16.2 but i dont know how t...

you have to use similar triangles

#

i think you also have to assume that the angle made with side x and side y is a right angle

steel sage Mar 29, 2021, 6:42 PM

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Help?

upper karma Mar 29, 2021, 7:21 PM

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help too? lol

trim breach Mar 29, 2021, 9:11 PM

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steel sage Help?

The problem gives you the range of the function, which is [4, 10], and the time span it takes to reach low tide from high tide.

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Knowing that high tide would be 10ft, and low tide, 4ft, you should be able to produce a wave function.

covert ridge Mar 29, 2021, 9:40 PM

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Can anyone help me with this question?

#

copper marten Mar 29, 2021, 10:07 PM

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next flower how would i solve for z and y. ive solved for X it is 16.2 but i dont know how t...

similar triangles and find the scale factor

tender grail Mar 29, 2021, 10:09 PM

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am i able to ask questions for geometry here?

copper marten Mar 29, 2021, 10:10 PM

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tender grail am i able to ask questions for geometry here?

yep !

tender grail Mar 29, 2021, 10:10 PM

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ok thanks

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so basically ive been working on flow charts a bit ima send a pic of the problem

#

#

all ive really gotten written down is the basic parts like whats given

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i was hoping to get some help on solving this

copper marten Mar 29, 2021, 10:14 PM

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im rlly bad at writing proofs so um .... if u dont get a response from someone then @ the helpers tag after 15 minutes

tender grail Mar 29, 2021, 10:14 PM

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ok thanks

woven haven Mar 29, 2021, 10:38 PM

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next flower how would i solve for z and y. ive solved for X it is 16.2 but i dont know how t...

find the ratio of the two right triangles
So 6/15= 0.4
And then 0.4 * 16.2: y
0.4 * 6 : z

tender grail Mar 29, 2021, 10:39 PM

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<@&286206848099549185>

dim plaza Mar 29, 2021, 11:07 PM

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does anybody know how to

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I need to prove that the triangle AEF is isosceles. DA and FX are parallel

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AD is also the bisector of the angle BAC

dim plaza Mar 29, 2021, 11:32 PM

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wait I think I got it

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I basically cut AD and FX with the transversal AC so DAC = AEF and then cut AD and FX with the transversal BF and BAD = BFX

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no idea if it's correct though

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should be

trim breach Mar 30, 2021, 12:17 AM

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tender grail i was hoping to get some help on solving this

Do you still need help?

tender grail Mar 30, 2021, 12:18 AM

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trim breach Do you still need help?

yes please!

trim breach Mar 30, 2021, 12:19 AM

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Because of the givens, you can assume that RS is congruent to QT.

tender grail Mar 30, 2021, 12:19 AM

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ok i got that part so far, but i was unsure of the "official" reasoning

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i wrote cpctc as the reason

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is that ok or should i change that?

trim breach Mar 30, 2021, 12:21 AM

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Hm…I am not certain what you would write in the proof for that lol.

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It’s been a while.

tender grail Mar 30, 2021, 12:21 AM

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ah no worries

trim breach Mar 30, 2021, 12:21 AM

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I think you can use CPCTC.

#

Do you know the subsequent steps?

tender grail Mar 30, 2021, 12:22 AM

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im a bit confused what you mean by that

trim breach Mar 30, 2021, 12:22 AM

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Basically do you know how to prove what you need to prove besides that step.

tender grail Mar 30, 2021, 12:22 AM

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Not really, let me grab a screen shot of what ive done so far, its really basic

#

#

sorry one second

#

that was my previous one

#

#

heres the newer one

trim breach Mar 30, 2021, 12:26 AM

#

So you have proven two sides of SQR and TRQ congruent.

#

And we know triangle PRQ is isosceles.

tender grail Mar 30, 2021, 12:27 AM

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ah ok

trim breach Mar 30, 2021, 12:28 AM

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Well, you’d need to document that RQ is congruent to RQ by reflexive.

tender grail Mar 30, 2021, 12:28 AM

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ok one second

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sorry how would i write that? would it just be rq is congruent to rq by reflexive or is it something else

trim breach Mar 30, 2021, 12:30 AM

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The actual property is called the Reflexive Property of Congruence.

tender grail Mar 30, 2021, 12:30 AM

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ok thanks

trim breach Mar 30, 2021, 12:31 AM

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So now we have two sides of them congruent.

tender grail Mar 30, 2021, 12:31 AM

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ok

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since you know RS=QT and PS=PT would you be able to prove they are congruent from that?

trim breach Mar 30, 2021, 12:32 AM

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You need one more thing.

tender grail Mar 30, 2021, 12:33 AM

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ah ok

trim breach Mar 30, 2021, 12:33 AM

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You have two sides.

tender grail Mar 30, 2021, 12:33 AM

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PR and PQ?

trim breach Mar 30, 2021, 12:33 AM

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Yes. There is a way to prove the angles in that larger triangle are congruent.

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Angles PRQ and PQR

tender grail Mar 30, 2021, 12:34 AM

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Im not sure of the proper way to say it but

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woudlnt it be because it is an isosceles

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and the bases are equal as well as the legs

trim breach Mar 30, 2021, 12:34 AM

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Yep. The Isosceles Triangle Theorem.

tender grail Mar 30, 2021, 12:35 AM

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Ok so I should add that onto the chart right?

trim breach Mar 30, 2021, 12:35 AM

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Yep!

tender grail Mar 30, 2021, 12:35 AM

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ok one second ty!

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Ok ive added it

trim breach Mar 30, 2021, 12:36 AM

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So your next statement should be about the triangles you just proved are congruent.

tender grail Mar 30, 2021, 12:37 AM

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PRT and PQS?

trim breach Mar 30, 2021, 12:37 AM

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No.

tender grail Mar 30, 2021, 12:38 AM

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which ones would that be then?

trim breach Mar 30, 2021, 12:39 AM

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This is what you have.

tender grail Mar 30, 2021, 12:39 AM

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Yeah

trim breach Mar 30, 2021, 12:40 AM

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Those angles are in the triangles SQP and TPQ.

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Because we only know that the largest triangle is isosceles.

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PRQ.

tender grail Mar 30, 2021, 12:41 AM

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in the screen shot you sent there is p on the triangle twice, which one are you referencing

trim breach Mar 30, 2021, 12:41 AM

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Yeah, I just noticed that.

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My.

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Mb*

tender grail Mar 30, 2021, 12:41 AM

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lol all good

trim breach Mar 30, 2021, 12:41 AM

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Bottom left should be R.

tender grail Mar 30, 2021, 12:42 AM

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yeah does SQP and TPQ stay that or is it switched to SRP and TRQ

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wait

trim breach Mar 30, 2021, 12:42 AM

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It doesn’t matter what order when you talk about triangles.

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Only angles order matters.

tender grail Mar 30, 2021, 12:43 AM

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ok

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I think we are good

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it seems pretty simple from here I was kinda struggling with the begining

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I appreciate all the help

trim breach Mar 30, 2021, 12:44 AM

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Cool. Ping me back if you get stuck or have a question.

tender grail Mar 30, 2021, 12:45 AM

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ok thanks!

tardy surge Mar 30, 2021, 7:43 AM

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Hey guys anyone able to how me with a trigonometry question ?

#

#

Need the area

wicked grove Mar 30, 2021, 10:18 AM

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tardy surge Hey guys anyone able to how me with a trigonometry question ?

do you have the actual diagram

tired pine Mar 30, 2021, 11:14 AM

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tardy surge

Try connecting some points to create simpler figures

tiny snow Mar 30, 2021, 11:57 AM

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I believe this was given the necessary attention in one of the question channels earlier (cross-posted).

dark sparrow Mar 30, 2021, 4:36 PM

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alright so i got a bit of a weird question here

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it's not that i don't know the solution, i'm just blanking on how to find it without coordinate-bashing

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pic incoming

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ABCD is a rectangle, BD = 7, AB = 4, show that BX = 3

upper karma Mar 30, 2021, 4:39 PM

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sick drawing

dark sparrow Mar 30, 2021, 4:39 PM

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thanks i made it in 40 seconds in ms paint

silent plank Mar 30, 2021, 4:40 PM

#

similarity?

dark sparrow Mar 30, 2021, 4:40 PM

#

oh yeah good point

#

EBX and EDC

upper karma Mar 30, 2021, 4:40 PM

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BX = 3

dark sparrow Mar 30, 2021, 4:40 PM

#

excellent, this fills the gap in my student's 3d geometry problem.

upper karma Mar 30, 2021, 5:22 PM

#

Does anyone know how to do proofs?

#

Not paragraph form. My teacher makes us do statements and reasons

willow bramble Mar 30, 2021, 5:24 PM

#

@tiny snow : Is it IM that is == 5 ? or IJ ?

tiny snow Mar 30, 2021, 5:24 PM

#

IM

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IM = 5, IC = 4, KM = 4, AK = x

upper karma Mar 30, 2021, 5:27 PM

#

#

Can anyone explain how to do this to me?

trim breach Mar 30, 2021, 6:47 PM

#

upper karma Can anyone explain how to do this to me?

Do you have a specific question in mind that needs solved? You posted completed proofs, so do you just need the logic explained on those ones?

#

Either way, if you really don’t understand it, it might be something you want to set aside a block of time to go over with someone.

near imp Mar 30, 2021, 8:35 PM

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can someone please help me on this if possible

storm portal Mar 30, 2021, 9:20 PM

#

@near imp start with a diagram

near imp Mar 30, 2021, 9:20 PM

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i got everything figured out! except the function

near imp Mar 30, 2021, 11:03 PM

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can someone help me with these problems please

copper marten Mar 30, 2021, 11:10 PM

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use sohcahtoa and sum of angles

trim breach Mar 30, 2021, 11:10 PM

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near imp can someone help me with these problems please

The first one you can find angle Y easily since there are 180 degrees in a triangle. You just find the sides by using trig ratios.

#

Well, actually, all of the problems posted make use of trig ratios.

#

Except Question 2, which can be solved using an easy shortcut with Pythagorean Theorem.

near imp Mar 30, 2021, 11:16 PM

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trim breach Except Question 2, which can be solved using an easy shortcut with Pythagorean T...

i don’t believe my teacher taught us how to solve that way

trim breach Mar 30, 2021, 11:17 PM

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Have you Google’d the Law of Sines?

#

From the first question.

near imp Mar 30, 2021, 11:18 PM

#

oh wait nevermind i got number 2

wanton phoenix Mar 30, 2021, 11:18 PM

#

What about law of Sine for Q2 for Q3 since it’s a 45 45 90 there is a pattern

#

The hyp is usually the adj side with root 2

near imp Mar 30, 2021, 11:21 PM

#

ok i got the answer for question 2

trim breach Mar 30, 2021, 11:21 PM

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Good.

wanton phoenix Mar 30, 2021, 11:22 PM

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Sry I meant for the last question in the order that it was given sry

near imp Mar 30, 2021, 11:22 PM

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oh don’t worry lol!

wanton phoenix Mar 30, 2021, 11:23 PM

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Yeah so for Q3 just use law of sine

near imp Mar 30, 2021, 11:23 PM

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ok i got the answer for Q3

wanton phoenix Mar 30, 2021, 11:23 PM

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Cool cool

near imp Mar 30, 2021, 11:28 PM

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and i got Q3 now i just need the first problem

rough grove Mar 31, 2021, 1:02 AM

#

i need to simplify (sin x + tan x)/(1 + sec x)

#

i've tried everything I can think of, I can't simplify it

#

i know I'm just overlooking something - I really need an answer because I couldn't find anything anywhere on the internet

sweet dew Mar 31, 2021, 1:38 AM

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Can someone please give me and explanation

#

ASAP

#

trim breach Mar 31, 2021, 2:08 AM

#

sweet dew Can someone please give me and explanation

Plug 5 in for d since it was five days later that it doubled. Basically, that second factor should equal 2, since the population doubled to 20,000.

#

In the correct choice, the second factor does simplify to 2 with the properties of exponents.

torn tundra Mar 31, 2021, 2:26 AM

#

how do i solve this? i tried it 5 times with the formula my teacher gave me and it didnt work

trim breach Mar 31, 2021, 3:16 AM

#

torn tundra how do i solve this? i tried it 5 times with the formula my teacher gave me and ...

Because those are two tangents, the measure of arc JL is double the measure of angle JKL.

#

You can set 2(mJKL) = mJL.

#

Solve for x, then the rest is straightforward.

torn tundra Mar 31, 2021, 3:36 AM

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@trim breach i did that bro

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try doing it yourself and see if it works

#

wait

#

shit

tiny snow Mar 31, 2021, 6:14 AM

#

Alright, so the problem I posted yesterday was missing two lengths, which made it have an infinite number of solutions. Here's the correct problem statement. It was supposed to be a continuation of a problem that was posted here yesterday, so it's not as well placed now as it was then.

sweet dew Mar 31, 2021, 6:46 AM

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trim breach Plug 5 in for *d* since it was five days later that it doubled. Basically, that...

Thank you so much 💜

somber coyoteBOT Mar 31, 2021, 8:39 AM

#

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

tiny snow Mar 31, 2021, 9:09 AM

#

I mixed up a square root... now the imaginary numbers are gone.

#

,w y^2+3^2-z^2=2^2, l=sqrt(33)+m-z-y, m^2+x^2=7^2,(l-sqrt(33)+y+z)/7 = z/3, (l-m+z+y)/7=y/2

somber coyoteBOT Mar 31, 2021, 9:09 AM

#

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

tiny snow Mar 31, 2021, 9:10 AM

#

So, what is the obvious solution that x = 8/3? I cannot see it...

silent plank Mar 31, 2021, 9:15 AM

#

you could do it with trig and sine rule

tiny snow Mar 31, 2021, 9:17 AM

#

I see how we can find <AFE, but <DHG?

silent plank Mar 31, 2021, 9:19 AM

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sine rule

#

also don't explicitly need the angles

#

just knowing the sine of the angles is sufficient

tiny snow Mar 31, 2021, 9:22 AM

#

You mean this "sine rule"?

silent plank Mar 31, 2021, 9:22 AM

#

dunno what that 2R on the end is supposed to represent

#

but yes

tiny snow Mar 31, 2021, 9:23 AM

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Radius of the circumcircle.

#

In order to use that you would need actual triangles, right? That have not been truncated by the square. Would you extend EF and GH to produce these, or introduce segments HE and FG?

silent plank Mar 31, 2021, 9:28 AM

#

no additional construction is needed

tiny snow Mar 31, 2021, 9:28 AM

#

You'll have to give me some more info then 🙂

silent plank Mar 31, 2021, 9:28 AM

#

you can determine sin(<AFE) from triangle AFE
from that you can determine sin(<DHG) using the sine rule (in triangle FHP)
that would also be equal to x/7
and you can then determine x

tiny snow Mar 31, 2021, 9:30 AM

#

Ah, now I see it. Ok, let me work it out.

tiny snow Mar 31, 2021, 9:47 AM

#

Thanks @silent plank, that was much more straightforward.

#

Generally $x = \frac{|AE||FP|}{|HP|}$

somber coyoteBOT Mar 31, 2021, 9:51 AM

#

Roenbaeck

tiny snow Mar 31, 2021, 9:55 AM

#

So $\frac{|DG|}{|FP|} = \frac{|AE|}{|HP|}$ (nice ratio)

somber coyoteBOT Mar 31, 2021, 9:55 AM

#

Roenbaeck

loud wolf Mar 31, 2021, 11:47 AM

#

#

#

I need to calculate the TSA and V of this

#

I was wondering what do I do with the 135 degree angle, can I convert it to mm or is there a formula or formulas I can use it in to get a more accurate Area/volume

zenith copper Mar 31, 2021, 12:04 PM

#

Does anybody have any idea on if you can write

#

$\frac{1}{2} ln(1 - x^2)$ in terms of inverse hyperbolic trig functions

somber coyoteBOT Mar 31, 2021, 12:04 PM

#

Free Martin Shkreli

zenith copper Mar 31, 2021, 12:05 PM

#

$\cosh\left(\tanh^{-1}{x} \right) = \frac{1}{\sqrt{1 - x^2}}$

somber coyoteBOT Mar 31, 2021, 12:05 PM

#

Free Martin Shkreli

zenith copper Mar 31, 2021, 12:06 PM

#

so

#

$\ln\left(\cosh\left(\tanh^{-1}{x} \right) = \frac{1}{\sqrt{1 - x^2}}\right) = - \frac{1}{2}\ln(1 - x^2)$

#

$\ln\left(\cosh\left(\tanh^{-1}{x} \right)\right) = - \frac{1}{2}\ln(1 - x^2)$

somber coyoteBOT Mar 31, 2021, 12:07 PM

#

Free Martin Shkreli

zenith copper Mar 31, 2021, 12:07 PM

#

so ln(cosh(atanh(x)) looks suspiciously like an inverse hyperb. trig function of its own to me

#

because $= -\frac{1}{2} \left( \ln(1 - x) + \ln(1 + x) \right)$

loud wolf Mar 31, 2021, 12:08 PM

#

Can anyone help me...PLEASE 🥺

somber coyoteBOT Mar 31, 2021, 12:08 PM

#

Free Martin Shkreli

tiny snow Mar 31, 2021, 12:08 PM

#

loud wolf I need to calculate the TSA and V of this

If you accurately model that shape in a 3d modeling program, it can immediately give you the volume.

zenith copper Mar 31, 2021, 12:09 PM

#

loud wolf Can anyone help me...PLEASE 🥺

don't ask to ask please.. just ask your question

loud wolf Mar 31, 2021, 12:09 PM

#

I know I've paid a guy on fivver to make me a 3d model. But I have to show working out on area and volume

#

@zenith copper I asked already

zenith copper Mar 31, 2021, 12:09 PM

#

oh, sorry

#

my bad

loud wolf Mar 31, 2021, 12:09 PM

#

#

What do i do with 35 degree

#

135 degree*

tiny snow Mar 31, 2021, 12:10 PM

#

loud wolf I know I've paid a guy on fivver to make me a 3d model. But I have to show worki...

So this is a math exercise, or why do you need to show calculations?

loud wolf Mar 31, 2021, 12:10 PM

#

It's an assignment

tiny snow Mar 31, 2021, 12:11 PM

#

That's pure evil if you have to calculate it.

loud wolf Mar 31, 2021, 12:12 PM

#

Part A is a worksheet- done that

Part B is a 3d model of a real life object along with calculations or TSA and volume showing working out

Part C is showing your research and putting together a report/ analysis

#

That is about 1000 words atleast

tiny snow Mar 31, 2021, 12:12 PM

#

Wait, so you picked this object?

loud wolf Mar 31, 2021, 12:13 PM

#

Yes becuase anything less complicated wouldn't get me an A

#

I need an A to get in advanced classes so a different school will take me becuase I've gone under a large amount of emotional abuse at this one and want to leave it behind

#

I got jumped and they gave the people a 10 minute detention. I basically go to school in the hood 😂😂

tiny snow Mar 31, 2021, 12:15 PM

#

I'd ask what the least complex object that would give me A would be, while explaining the problems with the current one, then switch.

loud wolf Mar 31, 2021, 12:16 PM

#

This is set in stone...

#

My teacher said I don't have to use the angle and just make it straight and use the height measurement for the width to get a about right answers but I'd have to compare to the one my 3d software gives me and explain why mine has a margin of error

#

I just want to do the angle because I want this to be perfect

tiny snow Mar 31, 2021, 12:18 PM

#

Tough luck. I doubt calculations would be any more accurate than what you get from a 3d program.

#

So school pays some other person to do the modeling work?

loud wolf Mar 31, 2021, 12:19 PM

#

I know my 3d program will give me 100% accuracy. But I want to get almost the exact same as the 3d model software gets to prove that I know my shit

#

I had to pay the guy...

#

Plus paid for the software, I've spent about $200

tiny snow Mar 31, 2021, 12:20 PM

#

Why not do it yourself? There's free software, like SketchUp.

loud wolf Mar 31, 2021, 12:21 PM

#

I've already gone too far. I also have no idea what I'm doing with 3d models

#

I've already paid the guy and brought solid works

tiny snow Mar 31, 2021, 12:21 PM

#

But it sounds from the assignment that you should know 3d modeling?

loud wolf Mar 31, 2021, 12:21 PM

#

It's a maths class not a 3d modelling class

#

They shrug and say "lol figure it out on your own lmao"

#

#

@tiny snow will you help me?

tiny snow Mar 31, 2021, 12:31 PM

#

I'd split it into these parts:
A - rectangular prism minus semi-cylinder
B - triangular solid prism (x 2)
C- rectangular solid prism
D - rectangular solid prism minus 4 cylinders (x 2)
Given that I understood the drawing correctly. That'll give you simple calculations and a rough estimate.

#

If it's hollow you'd have to do some other division, but you get the idea.

loud wolf Mar 31, 2021, 12:36 PM

#

Me and you had a preaty simmler idea

#

#

Any pointers on the other sides?

#

@tiny snow how do I find the measurements of A B C

tiny snow Mar 31, 2021, 12:42 PM

#

A B C? Measurements are in the blueprint.

loud wolf Mar 31, 2021, 12:42 PM

#

Well A has a length of 330.21mm but how do I find the width

tiny snow Mar 31, 2021, 12:43 PM

#

What A? What are you doing?

loud wolf Mar 31, 2021, 12:43 PM

#

#

A

tiny snow Mar 31, 2021, 12:44 PM

#

Aha

loud wolf Mar 31, 2021, 12:44 PM

#

For the triangles I have the hypotenuse so I just do a^2 + b^2 = c^2 right?

tiny snow Mar 31, 2021, 12:44 PM

#

The blueprint is drawn to scale, so you can measure missing stuff directly and scale it appropriately.

loud wolf Mar 31, 2021, 12:45 PM

#

Have to find a big peace of paper lol ight thank you for your help

dim cliff Mar 31, 2021, 1:01 PM

#

can someone pls help with these two swaggy questions? thank you 🙂

finite swan Mar 31, 2021, 4:10 PM

#

Sure, I'll try. Hold on a sec

finite swan Mar 31, 2021, 4:26 PM

#

So for 1, you can first expand the whole thing into the base functions sin and cos: $\frac{\frac{1}{\cos^{2}x \cdot \frac{1}{\sinx}}{\frac{1}{\cos^{2}x + \frac{1}{\sin^{2}x}}}$.
Then you can simplify these into: $\frac{\frac{1}{\cos^{2}x \sinx}}{\frac{\sin^{2}x+cos^{2}x}{\sin^{2}xcos^{2}x}}$
Then you can simplify the numerator of the denominator to 1. $\frac{1}{cos^{2}sinx} \cdot \frac{cos^{2}xsin^{2}x}{1}$
If you simplify this, you will eventually get an answer of $sinx$.

somber coyoteBOT Mar 31, 2021, 4:27 PM

#

6EQUJ5

So for 1, you can first expand the whole thing into the base functions sin and cos: $\frac{\frac{1}{\cos^{2}x \cdot \frac{1}{\sinx}}{\frac{1}{\cos^{2}x + \frac{1}{\sin^{2}x}}}$.
Then you can simplify these into: $\frac{\frac{1}{\cos^{2}x \sinx}}{\frac{\sin^{2}x+cos^{2}x}{\sin^{2}xcos^{2}x}}$
Then you can simplify the numerator of the denominator to 1. $\frac{1}{cos^{2}sinx} \cdot \frac{cos^{2}xsin^{2}x}{1}$
If you simplify this, you will eventually get an answer of $sinx$.
```Compilation error:```! File ended while scanning use of \frac .
<inserted text> 
                \par 
<*> 272412535410393098.tex
                          
I suspect you have forgotten a `}', causing me
to read past where you wanted me to stop.
I'll try to recover; but if the error is serious,
you'd better type `E' or `X' now and fix your file.```

finite swan Mar 31, 2021, 4:29 PM

#

oof

#

wait

#

So for 1, you can first expand the whole thing into the base functions sin and cosine.

$\frac{\frac{1}{cos^{2}x} \cdot \frac{1}{sin x}}{\frac{1}{cos^{2}x} + \frac{1}{sin^{2}x}}$

Next, you can combine both the numerator and the denominator into one fraction.

$\frac{\frac{1}{cos^{2}x sin x}}{\frac{sin^{2}x + cos^2{x}}{cos^{2}x sin^{2}x}}$

Then you can multiply the reciprocal of the denominator times the numerator.
$\frac{1}{cos^{2}x sin x} \cdot \frac{cos^{2}x sin^{2}x}{1}$

Finally, you can simplify and eventually get the final answer of $sinx$.

foggy perch Mar 31, 2021, 4:44 PM

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For 2 you can rearrange it to get $(\sin x )^2=1/2$ so then you have two equations, $\sin x=\sqrt{2}/2$ and $\sin x=-\sqrt{2}/2$. Find the values of x in the asked interval for each, then combine both lists

somber coyoteBOT Mar 31, 2021, 4:44 PM

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Mikey

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6EQUJ5

dim cliff Mar 31, 2021, 4:52 PM

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thank you guys! for number two tho mikey, i don’t really know how to do the interval thing could you help with that as well

dim cliff Mar 31, 2021, 4:52 PM

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foggy perch For 2 you can rearrange it to get $(\sin x )^2=1/2$ so then you have two equatio...

^

foggy perch Mar 31, 2021, 4:54 PM

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dim cliff thank you guys! for number two tho mikey, i don’t really know how to do the inte...

So this is kinda just looking at the unit circle, for the first equation find what values make sin x equal sqrt(2)/2 and do the similar thing for the second. You should find two values from each equation

silk glade Mar 31, 2021, 6:02 PM

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Can someone please help me with this question

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vestal pendant Mar 31, 2021, 6:08 PM

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https://media.discordapp.net/attachments/636011896528699414/826880741668683796/image0.jpg?width=355&height=473

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Does anyone know how to solve this

earnest echo Mar 31, 2021, 6:39 PM

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You can find the height of the given right triangle

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And after that use Pythagorean theorem

vestal pendant Mar 31, 2021, 6:40 PM

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@earnest echo and to find the height i'd need to do 40/tan 45, or do i use special right triangles

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our teacher is out on leave and we have no one to teach us this unit, we were basically on our own

earnest echo Mar 31, 2021, 6:41 PM

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Use the area

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And where are you getting tan45???

vestal pendant Mar 31, 2021, 6:41 PM

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45-45-90 triangle

vestal pendant Mar 31, 2021, 6:41 PM

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vestal pendant our teacher is out on leave and we have no one to teach us this unit, we were ba...

excuse any dumb questions i make lol

earnest echo Mar 31, 2021, 6:41 PM

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How do you know that?

vestal pendant Mar 31, 2021, 6:42 PM

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true

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we arent given a second angle measure

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so it could literally be 90 44 and 46 for example, so i shouldnt use that

earnest echo Mar 31, 2021, 6:43 PM

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Yeah

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Use the area

vestal pendant Mar 31, 2021, 6:43 PM

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alright

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@earnest echo Thanks. I was able to solve it.

earnest echo Mar 31, 2021, 6:48 PM

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👍

vestal pendant Mar 31, 2021, 7:01 PM

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https://cdn.discordapp.com/attachments/636011896528699414/826893957824905226/image0.jpg

upper karma Mar 31, 2021, 7:10 PM

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vestal pendant https://media.discordapp.net/attachments/636011896528699414/826880741668683796/i...

vestal pendant Mar 31, 2021, 7:11 PM

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@upper karma Already solved, and they arent looking fo simplest radical form

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"to the nearest tenth of a meter"

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Thanks though ❤️

upper karma Mar 31, 2021, 7:14 PM

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Oh, I missed that detail sorry bud ❤️

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Does anyone know how to factor equations

humble pulsar Mar 31, 2021, 7:17 PM

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upper karma Does anyone know how to factor equations

lots of people do

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next time just ask your question

upper karma Mar 31, 2021, 7:17 PM

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Yeah

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so do you?

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I need help in this question

finite swan Mar 31, 2021, 7:32 PM

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https://dontasktoask.com

Don't ask to ask, just ask

inland mountain Mar 31, 2021, 8:10 PM

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Whats the equation in order to get cos x?

silent plank Mar 31, 2021, 8:11 PM

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pythag

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to get the 3rd side

inland mountain Mar 31, 2021, 8:11 PM

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Ok thank you

finite swan Mar 31, 2021, 8:18 PM

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After you get the 3rd side, remember cosx = adjacent side / hypotenuse

inland mountain Mar 31, 2021, 8:19 PM

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Yea I did cos-1(12/20) and got 53.13

finite swan Mar 31, 2021, 8:19 PM

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Nope

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You got the right side length

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The adjacent side is 12. The hyponetuse is 20. Therefore, cosx =?

inland mountain Mar 31, 2021, 8:21 PM

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Uhm

finite swan Mar 31, 2021, 8:21 PM

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silent plank Mar 31, 2021, 8:22 PM

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the question doesn't ask you to find x, nor do you need to

finite swan Mar 31, 2021, 8:22 PM

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Yup

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You solved for x

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The question asks for cosx

inland mountain Mar 31, 2021, 8:22 PM

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Oh so the answer is just 12/20

finite swan Mar 31, 2021, 8:22 PM

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Yup

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But you can simplify

inland mountain Mar 31, 2021, 8:23 PM

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Oh thats why I was confused

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So if I have to find the measurement of c would I use tan?

obtuse tapir Mar 31, 2021, 8:36 PM

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yes

obtuse tapir Mar 31, 2021, 8:38 PM

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silent plank to get the 3rd side

or use complementary angles???

silent plank Mar 31, 2021, 8:41 PM

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wdym

inland mountain Mar 31, 2021, 8:53 PM

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It would be 1 right?

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Im just checking

storm portal Mar 31, 2021, 9:12 PM

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inland mountain It would be 1 right?

👍

inland mountain Mar 31, 2021, 9:25 PM

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Steve is standing on a hill and his line of sight is 51 feet directly above the ground. He can see two deer grazing in the distance. If the angles of depression to the deer are 35° and 47° how far apart are the deer?

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Okay so this is my homework question and I dont know how to even send up the triangle to this question

trim breach Mar 31, 2021, 9:32 PM

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inland mountain Steve is standing on a hill and his line of sight is 51 feet directly above the ...

Have you drawn a picture of the situation?

inland mountain Mar 31, 2021, 9:33 PM

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I tried it doesnt look right

trim breach Mar 31, 2021, 9:37 PM

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Just a sec.

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Handwriting is bad and small lol.

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But it should look like this.