geometry-and-trigonometry

[grizzled lantern]

yep

[upper minnow]

Ok so 24.14 is the answer?

[grizzled lantern]

i believe so

[upper minnow]

Ok nice

Are these all correct as well

The fill in the blank words one

[grizzled lantern]

you shouldnt count on me to look over the rest of the statements because i haven't done geometry since freshman year

[upper minnow]

Oh ok

[grizzled lantern]

but they look good

get confirmation

[upper minnow]

Ok I will

[zenith garnet]

what type of quadrilateral is this?

how can i prove its classification?

im leaning towards kite because i dont think it has any parallel sides but im not 100% sure

[silk patio]

It doesn’t seem like anything

Just a random quad

[zenith garnet]

im supposed to classify it to the best of my abilities

[sleek depot]

its a kite

only one diagonal is being bisected

if both are being bisected then its a rhombus

[upper minnow]

<@&286206848099549185>

[wintry tundra]

do the binomials refer to the side lengths or the angle measures

[silk patio]

The middle one is the average of the two others

[spark flint]

I've got this number .707 an angle between two vectors

Im not sure how to convert it to degrees? google doesn't seem overly helpful or I just dont know how to read what im seeing

[silk patio]

Use inverse cos

Angle between vector (1,1) and vector (1,0) ? Just look at it with your eyes

[spark flint]

I know its 90 degrees

But Im trying to program the formula

[silk patio]

How’d you know that

[spark flint]

Wait I mean

😅

Sorry its hard to explain what im doing

Even harder when I dont understand so well

1,0 to 0,1 is 90 degrees right?

the issue is the number im getting out of my formula is only 60

[silk patio]

It’s not that useful to use formulas you don’t understand

What’s the point

[spark flint]

Trying to learn

[silk patio]

You don’t learn by using formulas you don’t understand

What are you confused about exactly

[spark flint]

How to use inverse cos

I got up to

0.707

I can read an figure all that out properly

I think

Just when you say "inverse cos"

over my head sorry

[silk patio]

0.707 isn’t an angle

[spark flint]

FUckkkk me

https://onlinemschool.com/math/assistance/vector/angl/

Angle between vectors

?

[silk patio]

Yeah, it gives you cosine of the angle

Why are you using online calculators to cheat yourself to an answer

When you can literally use your eyeballs to look at what the angle is

[spark flint]

Because im trying to program it into a particle simulation

so I need to get hte forumla right

I cant tell the computer to

"just use your eyeballs"

[silk patio]

Sounds like bullshit

[spark flint]

Thanks tho

for calling my career bullshit

apperciated

[silk patio]

Career? How’d you make money from it

[spark flint]

I work for a major gaming company

[silk patio]

Ask one of your colleagues about trig functions

[spark flint]

Cant because this isn't work related

Thanks for your help tho

[silk patio]

Inverse cosine of 0.707

[wintry tundra]

lmao what happened here

why did this get so passive aggressive

[upper karma]

I fucking hate you, but thanks for the help, deeply appreciated. But also fuck you cunt.

This convo represented in a sentence

This convo is quite funny

[wintry tundra]

Gonna love it when some innocent 8th or 9th grader comes in here for help and see this

[oak citrus]

Too much toxicity.

[wide barn]

WOW ok

[strong gulch]

i need help

assignment closes in a few min and i don't know where to start

[upper karma]

Can someone help me with these 2

[oak citrus]

This isn't geometry, but I will still help you.

Do you know what growth rate/factor means?

[upper karma]

@oak citrus not certian no

[oak citrus]

Growth rates are the percentage change in a given time period.

[upper karma]

ok

[oak citrus]

In this case, the percentage change in this one year is 4.7%

[upper karma]

ok

so that would be stated as the groth rate just 4.7%

[oak citrus]

Yep.

[upper karma]

ok

and how about growth factor

[oak citrus]

As for growth factor, I forget.

[upper karma]

ok

can you help me with 11

[oak citrus]

Yes.

Did you learn any of the formulas in class?

[upper karma]

I think i Did i can go back to check real quick

[oak citrus]

Alright, sounds good.

[upper karma]

there were 4 formulas i was given

This is the first 2 of our notes

[oak citrus]

Ok.

[upper karma]

and the other i cant find but was for present time and future time

[oak citrus]

You have been given the principal which was $150 I think + 13% interest rate.

You know that the 13% is compounded annually

[upper karma]

yes

[oak citrus]

AKA once every 12 months.

It's a periodic payment.

[upper karma]

okay

[oak citrus]

So which formula is going to be used?

[upper karma]

so r would be .13

periodic

[oak citrus]

Yes.

Exactly

[upper karma]

and A would be 500?

[oak citrus]

Why $500?

[upper karma]

oops

150

lol

[oak citrus]

No, A=total account balance.

[upper karma]

ok

[oak citrus]

$150 is the Principal.

[upper karma]

so thats what we are solving for

[oak citrus]

Yes exactly.

The Principal is the money in the bank that is accruing interest.

[upper karma]

ok let me plug this in real quick to the equation and ill try to get back with the answer

[oak citrus]

Ok.

[upper karma]

what would n be then

since t is 12

[oak citrus]

What is n equal to?

the times per year

[upper karma]

so that would be 12

[upper karma]

yes

[oak citrus]

The number of times that it's compounded is once per year.

[upper karma]

so it would be just 1

[oak citrus]

Yep.

[upper karma]

ok

would that make T 12 then

[oak citrus]

You leave it as t

[upper karma]

ok

[oak citrus]

You plug stuff into t when you want to solve

[upper karma]

k

[oak citrus]

if you wanted to find the Account balance after 12 yrs, you plug in t=12

[upper karma]

so we leave it or plug in 23

12

[oak citrus]

Leave iy

it*

[upper karma]

k

so

we would do .13/1 to the power of 1 first right

[oak citrus]

yeah

[upper karma]

which would just leave it the same

then we would add one

which would make it 1.13/1

[oak citrus]

?

[upper karma]

no

ok

umm

om confused now

[oak citrus]

Think of t=1 as the first day in the bank.

[upper karma]

im sorry im slow I do not understand

[oak citrus]

I am going to wash my hands give sec

[upper karma]

k

[oak citrus]

t=1 is the same value.

The .13 hasn't been compounded yet.

[upper karma]

ok

so how would we start first

[oak citrus]

t=2 is basically the first year in the bank.

[upper karma]

k

im sorry so would the eqution look like 150(1+.13/1)^(1)(2)

[oak citrus]

$A=150(1+ \frac{.13}{1})^2$

[somber coyote]

Euler's Identity

[upper karma]

ohh

you added both together

[oak citrus]

?

[upper karma]

the exponent

you added the ones together is that how you got the 2

[oak citrus]

2*1=2

[upper karma]

oh

ok

[upper karma]

@oak citrus can you help me one more time

For 10.b

[oak citrus]

Uh.

[oak citrus]

I don't remember the definition.

[upper karma]

I have been stuck on this ever since

Oh

Ok

Sorry for the ping

[oak citrus]

It's perfectly alright.

[upper karma]

https://pages.uoregon.edu/rgp/PPPM613/class8a.htm

Indentity found this

[molten bronze]

can someone help me on this question

[upper karma]

@molten bronze have you tried anything so far?

[molten bronze]

yea, i did whats it called

alitude method

i just wanna make sure i did it correctly

[upper karma]

Altitude method?

[spark star]

Sorry to bother, but

[molten bronze]

ya

[spark star]

What channel would this go too?

[molten bronze]

i think thats geometry

and those two triangles are congruent as all 3 angles are the same

[spark star]

Oh wait

Congruent Triangle.

I don't think it works like that.

It may look the same, but it doesn't mean it is the same.

[molten bronze]

oh, then mb

[spark star]

It's okay

I always thought that too.

[upper karma]

@spark star that's geometry but this channel is occupied. Please post your question on another unoccupied channel.

[spark star]

Okay.

Thanks.

[upper karma]

@molten bronze okay just checked

Don't know what altitude method is, but 4 is correct.

[molten bronze]

how did u get 4 :?

without using alitude method

[upper karma]

Don't know what's the altitude method.

[molten bronze]

oh okay, how did u get answer :?

[upper karma]

I may know it by another name or i may just won't know it, there are multiples approaches to a problem.

[molten bronze]

thats true

okay i have one more question

sorry, just realized im not sure if its c or d

[upper karma]

I'm confused, didn't you solved it? If you have your method and it works you don't need to worry about anything else

[molten bronze]

i always do silly mistakes.

[wintry tundra]

Scoot I helped u with that yesterday

I guess I didn't explain it too well so I could try again if u want

I help scoot with math

[molten bronze]

thats nice 🙂

[wintry tundra]

I dont think he understood that AAA can't be a congruency proof

You always have to have at least one side defined to be able to have a congruency proof

[grizzled lantern]

@tawdry flame

you decide

id say they look awfully familiar

[wintry tundra]

yeah

they just described the distance formula with words

[shadow hemlock]

how would u take 236625 blocks and figure out the lengths of each edge to make a smooth rectangular prism with it

trying to do this to put 236625 into a visible comparison for some friends

[humble pulsar]

prime factorization

then take any 3 combinations of them

[shadow hemlock]

uhuh

[limpid gust]

all these angles are 60 right?

this is the full thing but juts angles 3 4 and 5

[humble pulsar]

3 isnt 60 so no

[limpid gust]

so 3 and 5 arent 60

and 4 is right?

62 62 and 56

??

or 4 is 62

am i right?

[humble pulsar]

idk you tell me

[limpid gust]

I think im right so i will write that down

just wasnt sure cause i dont know what those lines mean

[humble pulsar]

the lines mean they're equal in length

[limpid gust]

ohhh

thank you

[limpid gust]

https://media.discordapp.net/attachments/741228202076405761/802358546179162122/unknown.png can i get help with this one please?

these two actually

[wintry tundra]

hmm

@limpid gust why does the problem say 1 point right beside it

[hidden fern]

hey, I need some help. I am pretty sure that this is a simple problem, but I need help

I need to find all the unknown angles and sides

And I feel like I am doing it wrong

[upper karma]

,rccw

[wintry tundra]

@hidden fern have u learned about the 30 60 90 triangle and its set side lengths?

Well all triangles have set side lengths but 30 60 90s have easy ones

[hidden fern]

@wintry tundra

I think I figured it out, is this correct?

[wintry tundra]

How is just y 12 cm

[jagged tangle]

Can someone recommend me a way to remember/get comfortable with double angle and half angle formulas? I'm in calc 1 and have only come across 1 problem needing it so far, but I might as well get it down

[wintry tundra]

To classify a side u say both the end points of it @hidden fern

[hidden fern]

I just followed the SohCahToa video my teacher sent

[wintry tundra]

Hm

I'm gonna show u something really cool

[hidden fern]

?

[wintry tundra]

This is the sides of a 30 60 90 if the small side is a

(Knowing this automatically will be good for trig btw)

[hidden fern]

The teacher has already set the opposite side as 6 cm

[wintry tundra]

Yeah the small side is 6

So u can use this guide for that triangle to show the sides

But of course if u have to use the basic trig functions then I can help u with that too

[hidden fern]

I am confused. Cause the teacher told me to yse SohCahToa and the example he gave was the hyp was 12 cm

Use*

[wintry tundra]

Yeah if XY is 6 then XZ has to be 12

[hidden fern]

Ahh

Ok

[wintry tundra]

Bc of 30 60 90 side lengths

[hidden fern]

Was my YX correct?

Cause I feel like it isn't

Teacher told me to have solutions

[wintry tundra]

YX could be anything u have to have 1 side length definite to find sin cos and tan

sin cos and tan are ratios

[hidden fern]

Which is why I am asking if it is correct. I used cos to get it

I need like a definite yes or no if it correct. So I know i am doing it right

[wintry tundra]

So u said hyp = 12 was given already for this triangle?

[hidden fern]

He gave the opp and helped woth the adjacent

Yes

With*

[wintry tundra]

Adjacent to what angle

30?

60?

[hidden fern]

Yes

[wintry tundra]

Oh ok 30

[hidden fern]

He said that it should always be that angle when doing SohCahToa

[wintry tundra]

I mean u can use any angle

Except for the right angle

But if he wants to keep u guys using the small angle then that's fine too

Just dipping ur toes in the trigonometric waters

Anyways sin 30 would be 6/XZ

And from there u can use cos or tan to find the adjacent

[hidden fern]

I used cos

And got 5 cm

[wintry tundra]

Hmm

That's not right

Show me the picture again so I don't have to scroll continuously

[wintry tundra]

,rotate

[hidden fern]

Isn't cos adjacent/hyp

?

[wintry tundra]

Sry my brain is dead uhh cos 30 = x/y

So its unfindable for now

[hidden fern]

Ahh

[wintry tundra]

U gotta find x or y another way

[hidden fern]

Thats why I got it wrong

[wintry tundra]

Yeah no

[hidden fern]

I did cos but adjacent/opp

For some reason

[wintry tundra]

cos 30 is technically 6sqrt3/12 but we won't talk about that

That's something called a cotangent

Which is one of the 3 other trig functions

[hidden fern]

I am pretty sure thats not what my teacher wants

[wintry tundra]

Yeah don't use it

tan^-1 is better than cot in my opinion

Anyways

I think u should use the proven side to find either x or y

So use a function that include opp

[hidden fern]

I already have y

I just used 12Cos30 and got 10.3923

Is that correct?

@wintry tundra

[wintry tundra]

Hmm

So sin 30 is 6/y right

tan 30 is 6/x

So u gotta divide either sin or tan 30 by 6

wait oh u found y

My b

so cos 30 would be x/12

So yeah 12cos30

[hidden fern]

Yeah, y, or XZ is 12 cm

Thank you for the clarification :)

[wintry tundra]

Yeah np

[hidden fern]

It was my mistake doing Cos with Adj/opp

[wintry tundra]

Ur gonna LOVE trig if u like this kind of stuff

[hidden fern]

I was just confused

[wintry tundra]

Yeah don't worry

Sohcahtoa is something different when u learn it

[hidden fern]

@wintry tundra do I round up or round down 10.3923? Or keep it as is

Or to the 10th decimal

[wintry tundra]

Depends on what ur teacher wants

I'd round to hundredth place

[hidden fern]

Ok

Thank you

[wintry tundra]

Welcome

[hidden fern]

Ok, the next question has me confused because its a word problem.

[wintry tundra]

Ok show it

[hidden fern]

Its number 6

[wintry tundra]

U should draw a picture

[hidden fern]

A right triangle?

[wintry tundra]

And show me the picture so I can check it

Well just draw someone flying a kite at 72 degrees in relation to the ground

[wintry tundra]

Also it says the kite string is 200 m

[hidden fern]

Did I put the angle in the right place?

[wintry tundra]

Yeah

[hidden fern]

I notcied I put the angles wrong

Hold on

[wintry tundra]

Realistically the other angle would be 72 but who cares

[hidden fern]

@wintry tundra ?

[wintry tundra]

Yep

Go ahead and solve from there

[hidden fern]

And I just SohCahToa it

[wintry tundra]

Mhm

[hidden fern]

Thank you, I'll solve this real quock

[wintry tundra]

Nice

[hidden fern]

You said that realistically the other angle should be 72 degrees

Should I move it to A?

@wintry tundra

[wintry tundra]

It doesn't matter

It's the math that counts not the picture

One of the worst things u can do in geometry or trig is "they look blank so they are blank"

[hidden fern]

But it would be better if I did have A as 72 degrees right?

[wintry tundra]

Doesn't change anything at all

Just more work for u to do

[hidden fern]

Ok

@wintry tundra

,rotate

[wintry tundra]

thats right @hidden fern

[hidden fern]

Thank you

@wintry tundra quick question

Should I use a right triangle for these questions?

I already did number 7 but I just need to double check

[wintry tundra]

well do non-right triangles have hypotenuses?

[hidden fern]

Are the other triangle shapes use the same stuff as just a Right triangle?

And no I believe non triangles don't have hypotenuses

[wintry tundra]

other triangles cant use sin cos or tan without being split into right triangles @hidden fern

[hidden fern]

Ahh

Ok

Thank you

[limpid gust]

@wintry tundra my hw is just graded like a test, ya know? Please? Yeah you get it.

[wintry tundra]

hmm

i suppose so...

anyways if u still need help i guess i will

[limpid gust]

Nahh I just guess on those

Worst I can get is wrong

Guessed*

[fickle sleet]

Honestly trig feels like it's more about circles than triangles...

[humble pulsar]

it is

well, it's mostly about angles.. circles just encompass any possible angle

[alpine cliff]

Circles are sorta dope for trig

[wintry tundra]

im having a bit of a hard time graphing $y= \cos(\frac{\pi}{12}x) + 6$

[somber coyote]

hiidostuff

[wintry tundra]

<@&286206848099549185> could u help me?

[stone zephyr]

^use desmos to clarify. We know the amplitude is 1 and the period is usually 2(pi)/b and is shifted 6 up. Therefore, the period is 24 and if it is shifted 6 up you have to remember that a cos graph behaves differently from a sin graph, so because its amplitude is one it will start at 7

[wintry tundra]

the issue is the graph i use goes from -9 to 9\

so idk a point that has an integer y

thats from -9 to 9

[stone zephyr]

You can usually plug these values in a calculator for x. Are you doing that in math currently. There are ways to manipilate this equation to find exact values of x

One sec

Are you trying to find the values of y where x is -9 and 9?

[wintry tundra]

no

im saying the range given is from -9 to 9

so i can only plot points at x= -9 to 9 and same for y

[bright thistle]

I need help that should be easy like i kinda just starter this

If the area of a polygone unknown is 135 cm2 and one of the side is 5~ and that the apothem is 4.5, how many side does it have? With solving if possible

<@&286206848099549185>

[unkempt oak]

how do Trirectangular tetrahedrons and Orthocentric tetrahedrons differ? is one a subset of the other?

[wintry tundra]

Oh god how

<@&286206848099549185> so far I have $4\sin({\frac{\pi}{2}x - 1}) + 1$

[somber coyote]

hiidostuff

[silent plank]

you made a minor error

$4\sin({\frac{\pi}{2}\red{(}x - 1}\red{)}) + 1$

[somber coyote]

ℝamonov

[wintry tundra]

Oh wait horizontal translations are in parentheses?

Augh I had no idea

[steep temple]

So how am I meant to solve for x if I get 2 solutions for x

🤔

oh nevermind the question acknowledges there are multiple solutions i just didn't read it properly

[silent plank]

you're missing 2 soultions

[steep temple]

yeah i know

but i wanted to ask here first before i apply the periodicity

because i wasn't sure if i was meant to have 2 solutions in the first place

i.e. x_1 and x_2

but yeah the questions does say solutions and i just misread

[silent plank]

similar principles for all these types of problems

doubt there's any issue with quadratics/polynomials etc

(having multiple solutions/ possible values of x)

[steep temple]

yeah i did recognise it was a quadratic so it could have multiple solutions, which is why i was confused the question only asked for 1 solution but i did misread it

[nocturne vale]

how do i solve for x

[wintry tundra]

well u should use some geometry techniques

if its for school, think about what u learned that day

[nocturne vale]

@wintry tundra i did

and guess what

nothing like it is on there

it's a pythagorean theorem problem

but theres not enough information to solve for x

x could be many numbers

[rugged flint]

it can be solved but not with pythagorean theorem

but I think it still uses it, just needs something else first

nvm for x is just one theorem

[nocturne vale]

can you try to solve it

[rugged flint]

I know what it is but I want you to try to look for whatever they have teached you at school

what theorems have you seen about triangles

I'm pretty sure there's a nice visual proof of how the theorem for this kind of exercises works but I forgot it

they should have showned you the formula for the theorem at least

[nocturne vale]

it's not there dude

i searched my whole book

[rugged flint]

a theorem in which a right triangle is split into two from the proyection of the right angle

like the one in the problem

euclid theorem

[nocturne vale]

never heard of it

[rugged flint]

oh

look it up, it's not that hard to apply

you just need to use one of the formulas of the theorem

[rugged flint]

could you do it?

[silk patio]

You can do it with pythag

[rugged flint]

oh

[hidden dragon]

can someone help me w a geometric proof

[oak citrus]

[hidden dragon]

ty

ill send u the pic

[oak citrus]

Ok.

[oak citrus]

Can you take a screenshot?

[hidden dragon]

thats how the ss turned out

its ok if u cant help i get it, its hard to read

[oak citrus]

It's pretty hard for me to read.

Is there any way to send the site or something?

[hidden dragon]

ugh no there isnt

its ok, im trying to help my friend w her math hw but i took geometry a year ago so i dont remember everything

the website is multiple choice so it wont plug in the answer ik to be right, but im sure its right?

anyways thanks for trying i appreiciate

[oak citrus]

Sorry I couldn’t help.

[hidden dragon]

nono its ok!!!

[umbral fossil]

In the Alternate Cosine Formula: Cos A = (b^2 + c^2 - a^) / 2bc

Is the one opposite to the given angle a

[silk patio]

What are you asking exactly?

[red isle]

Find an equation that represents the area of a circle of radius a, minus the blue section (theta=120 degrees) as shown in the figure. I'm completely stumped on how to start, I'm not seeing it.

[silk patio]

What have you tried

[umbral fossil]

ill post a pic

is 3.7 = a

[silk patio]

Yep

[nocturne vale]

@rugged flint @silk patio ok so i had another teacher explain it

and it was real easy

my teacher didnt even interpret anything she just showed her way of doing it

which provided nearly no proper explanation

omfg

[cedar ginkgo]

Im so lost

cause the answers I get are not a decimal or some integer

[rugged flint]

what theorem or method did she use? just the pythagorean theorem?

[nocturne vale]

dude she didnt even use an established method

[rugged flint]

oh

[nocturne vale]

she just used her pencil and traced the triangles to figure out stuff

which doesnt make any sense

she ignored all of the explanations in the text and said she doesnt like words

she just likes numbers

[rugged flint]

mmmmm

what was the result

[nocturne vale]

what do you think was the result

nobody knew wtf was going on

the teacher didnt even explain what a "geometric mean" was

she was just like "ugh too wordy"

then the homework she gave us

not even made by her

featured tons of work that she didnt even explain

thank goodness she uploaded a video of the other teacher with her lesson or i surely wouldve failed the homework

i've never seen a math teacher like this one

[rugged flint]

well just in case one side of the hypotenuse times the other side equals the height squared

[nocturne vale]

yes i know

i watched the video and it told me about it

thanks anyways

@rugged flint i passively asked her to upload every video from now on of the other teacher

just to "clarify things"

[rugged flint]

hehe

it's ok

to look out for other sources

[nocturne vale]

hopefully she says yes

cuz

[rugged flint]

you'll probably will have to do it many times

[nocturne vale]

that's the teacher i was looking for

[rugged flint]

like actively looking info for yourself

[nocturne vale]

imagine encouraging kids not to read the explanations

lol

[rugged flint]

kinda counterintuitive

[nocturne vale]

i have no idea what in her mind told her it was a good idea to do that

[rugged flint]

but did you actually see euclid's theorem in class?

[nocturne vale]

just ignore the instructions and jump straight into it

No

[rugged flint]

oh

[nocturne vale]

She didnt even mention it bro

[rugged flint]

and that's how it was done right?

[nocturne vale]

didnt even have a single idea of what was infront of me

Yes

[rugged flint]

well

the more you know

[nocturne vale]

imagine the other kids

blindly following the teacher

and then they see the homework

[rugged flint]

that's why you shouldn't just stay with whatever you see

question it

[nocturne vale]

she has no answers

LMAO

[rugged flint]

and look for complementing your knowledge elsewhere

[nocturne vale]

"It just is"

Cant wait till i get to college bro

[rugged flint]

it has happened to me many times that just seeing a video or something about a subject that it finally "clicks" on me

[nocturne vale]

works gonna be harder, but hopefully the explanations will be much clearer

which is exactly what I need

[rugged flint]

mmm

depends on the teacher

[nocturne vale]

Dude im talking about uni

lol

[rugged flint]

but it tends to be that way

yes

I'm at uni rn

[nocturne vale]

yeah the people who teach you

know what they're talking about

they have to

[rugged flint]

and some teachers are like

they know what they have to teach about but they're not teachers

just studied something of which they're teaching about

it tends to happen

they know about it but don't have that good of a teaching skill

[nocturne vale]

well the purpose is to feed the information to you

in uni the goal is to have you be fully independent

[rugged flint]

some read powerpoints while others literally proof from scratch

[nocturne vale]

yeah proving from scratch

my type of teacher

cant wait till i get to uni bro

i just want to escape this fuckin system

[rugged flint]

wish you luck

it ain't easy

[nocturne vale]

never has been g

[rugged flint]

but you're on good tracks with the mentality

and knowing you need to look for things

because most of it isn't served on a plate

[nocturne vale]

yeah

[rugged flint]

welp, gotta go

[nocturne vale]

wait

one more thing

[rugged flint]

what

[nocturne vale]

the uni im going to has a 62% acceptance rate

that's pretty good right?

[rugged flint]

eh, idk how that works but it seems fine

[nocturne vale]

it's an aeronautical uni

oh ok

cya

[rugged flint]

in my country it doesn't work that way I think

nah but you look like you can

or at least seem like with the interest

of looking more into it

that's important

[nocturne vale]

i just wanna be involved with aeronautics bro

been a childhood dream

i cant help but marvel at airplanes

like holy shit

look at it

[rugged flint]

you can't just learn a^2+b^2=c^2 from memory and leave it there

as an example

well good luck on that

[nocturne vale]

thanks

[rugged flint]

pursue it

[nocturne vale]

im gonna need it

[rugged flint]

if you want it go for it and don't let anyone tell you otherwise

it's your choice

ok gtg

[nocturne vale]

nobody can lol

[rugged flint]

yep

[nocturne vale]

yeah cya

[rugged flint]

gn

[alpine cliff]

either make sure ur using radians

or draw a unit circle

and plot an angle that roughly gives 0.1 for cos

then add pi radians to it and draw the next angle

make a conclusion from that

[upper karma]

Anyone know how to solve this

<@&286206848099549185>

[alpine cliff]

whats the root of the denominator

like the zero^

[upper karma]

Pardon

[silk patio]

This isn’t geometry

[upper karma]

Its trig

[silk patio]

No it’s not

[upper karma]

Dude then its what??

[silk patio]

What do you think trig is?

[upper karma]

Euler , what is it then?

Its algebra 2, therefore its trig

Anyways

[silk patio]

Not all algebra is trig

[upper karma]

Omg

Well is algebra 2 trig or not?

[silk patio]

No

[upper karma]

Then where should I chat?

[silk patio]

Algebra

[upper karma]

What type

[silk patio]

pre-algebra

[upper karma]

There's no algebra in general.

How is this pre-alg

But alright then

[silk patio]

It’s prealgebra-algebra

[upper karma]

Dude u just changed it

XDD

Bruh

Very funny

[silk patio]

I’m not an admin

[upper karma]

Well someone did

[silk patio]

Paranoid

[naive thicket]

nah it’s always been Prealg-algebra

[upper karma]

Yeah right

Alright

[naive thicket]

it would be goofy for the most dedicated mathematics disc to not have a general algebra channel lol

Can anybody explain to me how to do this? I’m lost and can’t find any similar examples online (i missed the lesson covering this at school due to some covid issues)

[silk patio]

It’s the one where the angle at the centre is twice the angle at the edge

[naive thicket]

yes yes because the angle is sitting on the circle but i do not know the actual process for solving for x in this situation

[silk patio]

You get an equation using the angle at the centre is twice angle at edge and then you solve for x

[naive thicket]

i don’t quite get what you mean by angle at the center? I thought an angle sitting on the edge was half of the arc length or so

[wintry tundra]

Circumference formula derives from radians to degrees conversion right

Or is related to I should say

[onyx cloud]

whenever you're dealing with distance and angles, you want to use radians

so the circumference formula uses radians

[upper karma]

would this be SSS?

@graceful totem

@dark sparrow

[dark sparrow]

did you really see the giant [AWAY] next to my name & then ping me anyway?

[upper karma]

can you tell me if it's sss

[dark sparrow]

i don't know what the problem asks you to do, so no.

[upper karma]

it

[dark sparrow]

but also, you need to realize you're just not supposed to ping specific people for help.
if nobody arrives within 15 minutes, you can tag the helpers role.

[upper karma]

hold on i'll send you screen shot

[dark sparrow]

man

nice dodge

[upper karma]

there it is

[frank osprey]

I joined to ask a question, but found gold happening right before my eyes instead.

[upper karma]

what?

[upper karma]

what do you mean

[frank osprey]

lmao

[upper karma]

what would be the answer i think it is sss

[dark sparrow]

moo, can you tell me what "HL" is supposed to stand for?

[upper karma]

am i right

it's fine i got it thanks for the help

[dark sparrow]

blurgh

don't thank me when i've provided no help at all.

bye.

[frank osprey]

Where's the early university geometry channel?

[dark sparrow]

you can go here or in a questions channel

[neon hamlet]

Can you use angle angle here?

[oak citrus]

Yeah, I think so.

These are similar triangles.

The side lengths aren't the same, but the angles are.

@neon hamlet

[neon hamlet]

alright thanks

[oak citrus]

No problem.

[hidden fern]

Hello guys, I need a little help

[patent plume]

Draw a diagram and send here pls

[hidden fern]

Yeah, this is what I got so far

And I am stuck

,rotate

[patent plume]

do you have a calculator?

[hidden fern]

yes

I punched in the numbers

[patent plume]

Oh crap

[hidden fern]

and something seems wrong

[patent plume]

yeah you will negative won't you?

[hidden fern]

yeah

[patent plume]

mm

[hidden fern]

and I am pretty sure that that side is supposed to be the longest side

I believe

[patent plume]

I mean

[hidden fern]

The way my teacher teaches is confusing

[patent plume]

Idt you can use cos this way ngl

this isn't a right triangle after all

[hidden fern]

yeah

I made a mistake

[patent plume]

So like, the formula here, iirc is c^2 = a^2 +b^2 - 2abcos(theta) where theta is the angle between a and b

c = x here btw

[hidden fern]

yes

I should be using the pythagorean theorem

[patent plume]

So like x^2 = 900^2 + 1100^2 -2(900*1100) * cos(160)

Ah

Hm

This became exponentially harder

pun not intended

[hidden fern]

which is why I am very much confused

been stuck on this question for like an hour

[patent plume]

yeah this is not a great problem to use pythag. I mean, there's a solution, but it's a 7 lines - page long depending on how many steps you skip

My advice would be to drop a perpendicular from the 160 angle @hidden fern

And then just spam pythagorean theorem until you get a definite answer lol

Just ping me when you get stuck

[hidden fern]

ok

I will try that

thank you

[hidden fern]

@patent plume should I be using Tan to find the perpendicular angle?

[patent plume]

dw about angles

Just worry about the sides

[hidden fern]

I only need one side to be found

my head hella hurting from this XD

[devout cove]

I got 8.999 and got it wrong

[patent plume]

You did tan(40) = 14/x correct?

[patent plume]

rip ok let's see if we can make some progress here

[devout cove]

yes

[patent plume]

uh can you use one of the question channels pls?

[patent plume]

mm then you made an error with computation

[patent plume]

Alright can you show me the diagram where you dropped the perpendicular?

[hidden fern]

the angle?

[obtuse tapir]

@finite comet UW=UV

and angle v is perpendicular

[patent plume]

@obtuse tapir pls move to q9 thx

[patent plume]

Oh I should have been specific sorry bout that. Basically, draw a line from the starting point to the line you have marked as AB such that it forms a 90 degree angle with AB

Somethign like htis

[hidden fern]

Idk if that would work with my teacher

cause I have never seen that before

[devout cove]

i dont understand

do i se cos

use

[obtuse tapir]

Do you know what angle of elevation is?

[devout cove]

no

what does it mean by find the altitude

[patent plume]

wdym?

@hidden fern it's just a line dropped down from the first point. There's literally no other way to solve using pythagoras

[hidden fern]

the bottom left corner is 44 degrees

@devout cove

[devout cove]

yeah i

[hidden fern]

thats the angle of elevation

[devout cove]

know that

so the equation is sin(44) times 22

[obtuse tapir]

Wait what

[hidden fern]

what

[devout cove]

im lost

[obtuse tapir]

use tan

tan(44)

[devout cove]

ok

[obtuse tapir]

tan(44)=x/22

[hidden fern]

I need like a second opinion on how to solve my problem. Horny can you help me?

[obtuse tapir]

😳

[devout cove]

so it is 21.2

[hidden fern]

this was the question

[hidden fern]

and here is the mistake that I made

@obtuse tapir

[obtuse tapir]

yes

send the question

[hidden fern]

I did

click to see attachments

[obtuse tapir]

I cant see them

[hidden fern]

I used Cosine when it shouldnt be

hold on, I will resend

https://cdn.discordapp.com/attachments/326138757474680852/803318461405069372/unknown.png

[hidden fern]

https://cdn.discordapp.com/attachments/326138757474680852/803318622096588850/528408414469226506.png

I used cosine when cosine shouldn't be used, so ignore that

I need to find x and I have been stuck for almost 2 hours

@obtuse tapir

[obtuse tapir]

trying to do it

[patent plume]

@obtuse tapir you aren't allowed to use cosine rule, and must use pythagoras, and are not allowed to construct extra lines

[obtuse tapir]

wait what

[hidden fern]

I don't even know if only pythagoras can be used

cause the last assignment had a similar question and Cosine worked fine

[patent plume]

Yes, but I'm assuming that triangle was a right triangle

This triangle is not

[hidden fern]

it wasn't

[patent plume]

??

Then I'm very very very confused

[hidden fern]

Idk, my teacher is confusing

[patent plume]

can you please send me the other one?

[hidden fern]

its with my teacher

[obtuse tapir]

dunno man

You’ll have to use cosine rule

[hidden fern]

But when I used cosine

[patent plume]

Or you'll have to drop a perpendicular

[hidden fern]

it was -

[patent plume]

Again, you can't use cosine in that sense lol

[hidden fern]

my teacher has never taught dropping a perpendicular

[patent plume]

That rule for cosine only works for 90 degree triangles

[hidden fern]

so I will assume that is not allowed

[patent plume]

The rule for cosine for a non right triangle is posted above

[obtuse tapir]

Math is math @hidden fern

[patent plume]

May I please have the other question where you used cosine and it wasn't a right triangle?

And how you solved it?

[hidden fern]

Its all with my teacher. We don't keep our assignments

[patent plume]

bruh wtf is this

[hidden fern]

I know

[hidden fern]

But the teacher didn't teach that, pretty sure he will be like, wtf

[patent plume]

RIP

The saddest statement to hear from any teacher

"I didn't teach it this way"

[oak citrus]

😭

[deep iron]

how do you calculate the slope of a line in 3D?

[patent plume]

good question

[upper karma]

there is no such thing as "slope"

[oak citrus]

There is only:

$\frac{\Delta{y}}{\Delta{x}}$

[somber coyote]

Euler's Identity

[hidden fern]

@patent plume

I solved it

Used law of cosines

4 hours of being an idiot XD

felt stupid af after solving

[wintry tundra]

A trig word problem is giving me trouble...

I know the midline is 10.5

And I think the Amp is -7.5

And idk what the period or the horiz translation is

[scenic gust]

anyone that can help me ?

the triangle ABC is isosceles

and we gotta prove that the angle C1 is the angle A/2

[west basin]

Is this for a test?

[odd ravine]

homework

[west basin]

alright

What have you tried so far for 3?

[odd ravine]

tried 2x-10=16

[west basin]

alright i see where you got that but actually it turns out 16 is the length of the ENTIRE side not the portion you are trying to find

It should be (2x-10) = 16 - 10

because you are looking strictly for the portion 2x-10

[scenic gust]

still got some time left @west basin ?

[zenith garnet]

how can i prove what type of shape this is

*quadrilateral this is

[oak citrus]

There are 4 right angles

Do we know if all the side lengths are equal?

[wintry tundra]

its at least a trapezoid

i think

[stuck dragon]

welll

[native mirage]

Any help please

S is forcus

[patent plume]

@hidden fern Rip I told you law of cosines at the beginning........

[native mirage]

<@&286206848099549185>

[visual haven]

anyone taking psat today

[wintry tundra]

SPQR

[upper karma]

?

[left nebula]

Who understand lesson 3.1-3.4 in honors geometry

[split stump]

just wondering if any of these are wrong, no this isnt a test, my teacher grades hw on accuracy

[oak citrus]

These things aren't standardized like that lol

[sinful tide]

I you give more information on what it covers than someone can help you.

[upper karma]

anyone know how to do this?

[silent plank]

apply bisection theorems and pythagoras

[hidden fern]

Yup

I got it confused with regular cosine

sorry

[upper karma]

Can you help me ?

With some entry level trig

I got this so far

<@&286206848099549185>

[twin prawn]

Did you just put an equality sign under the root

[upper karma]

I did not mean to-

I fixed it

lol

[onyx cloud]

now isolate the x

[upper karma]

So divide 18 by the square root of 2

[onyx cloud]

yep

[upper karma]

but then you have a fraction wherre the dinomonator is a square root

that does not work

[onyx cloud]

then rationalize

do you know how?

$x=\frac{18}{\sqrt{2}} = \frac{18}{\sqrt{2}}\cdot\frac{\sqrt{2}}{\sqrt{2}} = \frac{18\sqrt{2}}{2}$

[somber coyote]

maximo

[onyx cloud]

$x=9\sqrt{2}$

[somber coyote]

maximo

[upper karma]

What the fk

I got the rationalize bit

My dumb brain thought

[onyx cloud]

be nice to ur brain

[upper karma]

$x=/frac{18/sqrt{2}{/sqrt{2}$

[onyx cloud]

$ at the end

[upper karma]

How do you make it work ?

[onyx cloud]

and you're missing a } at the end

[upper karma]

$x=/frac{18/sqrt{2}{/sqrt{2}$

[somber coyote]

Skyler
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

Skyler
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[twin prawn]

backslashes

\

not /

[onyx cloud]

$x=\frac{18\sqrt{2}}{\sqrt{2}}$

[somber coyote]

maximo

[onyx cloud]

you can't simply rationalize by multiplying by $\sqrt{2}$ because it makes it a different value

[somber coyote]

maximo

[onyx cloud]

we can multiply by $\frac{\sqrt{2}}{\sqrt{2}}$ because $\frac{\sqrt{2}}{\sqrt{2}} = 1$

[somber coyote]

maximo

[onyx cloud]

so we can actually do

$1\cdot x=\frac{18}{\sqrt{2}}\cdot 1$

[somber coyote]

maximo

[onyx cloud]

so the left stays the same, and the right we can treat as root2/root2

does that make sense

[upper karma]

Oh

Well , turns out im an idiot.

I got this

[onyx cloud]

lack of knowledge doesn't make you an idiot

you just didn't know

[upper karma]

$x=\frac{18\sqrt{2}}{\sqrt2}$

This is what I had gotten.

[onyx cloud]

hm not sure how

[somber coyote]

Skyler

[upper karma]

I messed up

That

I did that

[onyx cloud]

how'd you get to that?

[turbid glade]

How do i type this on a calculator