geometry-and-trigonometry

[bronze jewel]

ram

can you help me

[silent plank]

the horizontal eye level is perpendicular to your tree

THOSE are the locations where the 90° right angles are formed

[bronze jewel]

https://media.discordapp.net/attachments/326138757474680852/788577300199112714/image0.jpg?width=833&height=625

[silent plank]

no wtf

fml

you should NOT be doing anything related to trig atm

go back and review basic geo from something like khan

i'm out

[sleek axle]

Fancy just giving me the answer?

[bronze jewel]

can some1 help me

[final tapir]

a

[late lion]

are there any nice points besides the roots on the graph of tan(x)?

[silent plank]

yes

consider when tan(x) = 1 or -1

[humble pulsar]

idk, tan(x) ~=2.605089 is pretty nice too

[upper karma]

Yo

Can someone help me

With my math

[humble pulsar]

@upper karma idk if I can

cause you never posted a question

[upper karma]

Lmaooo

I’ll send one rn

@humble pulsar

[humble pulsar]

Like I said, idk if i can

and I cannot

[upper karma]

Lmaooo Alr

[upper karma]

I think I’m going insane trying to figure this out

[silent plank]

what have you tried?

,rotate

[upper karma]

I've tried comparing every thing, I've been looking at it for like an hour and just been so confused

I'm honestly just considering writing down x=5 because it makes sense when you just look at the photo

[silent plank]

how do you think x=5 makes sense here?

[green osprey]

sry

[upper karma]

Well, we can see that angles Q and P are pretty similiar, since P is 23, i can try to make equation q somewhat similiar, i think i'll be good on my own now but it'll just have to be trial and error until the X's add up

[silent plank]

don't use trial and error

use algebra

if the values aren't nice, trial and error gets you nowhere

[upper karma]

well i found the answer

with trial and error lol

[silent plank]

if the values aren't nice
here they are

[upper karma]

x=5

[silent plank]

instead consider angle sums of triangles, on lines and/or exterior angle theorem

[upper karma]

the answer is 47

[silent plank]

degrees yes

[upper karma]

Can someone help me with this please

@silent plank can you help me with this?

[slate blade]

you know your trig rules?

[upper karma]

No I don’t

[slate blade]

ok so here's a useful mnemonic called
SOH-CAH-TOA

do you know the concept of opposite, adjacent, hypotenuse?

[upper karma]

No

[slate blade]

give me 2 seconds I'll draw it up ok?

[upper karma]

Ok thanks

[slate blade]

So this works for any right angled triangle

[upper karma]

Ohhhh that

Yeah I know what that is

[slate blade]

The side adjacent (touching the angle) is the adjacent one

[upper karma]

H, A, and O

[slate blade]

So you have your special things called sine, cosine, tangent

[upper karma]

Yeah

That’s what I’m having trouble on

[slate blade]

so take a look at your original question right,

[upper karma]

Yea

Do you mind if we go to dms?

[slate blade]

what information do you have? I suggest you redraw it in a triangle

sure thing

[strong gulch]

I need help please and thank you

[zenith apex]

https://cdn.discordapp.com/attachments/486844829209198613/788645084945973288/BigBlueButton_-_Period_3_-_Google_Chrome_12_14_2020_11_06_12_AM_LI_2.jpg

any one have a clue as to how my teacher got there?

[zealous onyx]

3

[upper karma]

For a, if its a reflex angle it should be 180<x<360

Then r = sqrt(p²+1)

[tardy fulcrum]

i just learned this recently and then had a short break from class so now i’m confused again, can anyone help?

[dusky surge]

Looks like there's not enough information

[silent plank]

^

[tardy fulcrum]

i think i got it , i just use the sin cos tan formula 🙂

but does anyone know how to find similar triangle ?

[silent plank]

did you cut off information in your screenshot?

[dusky surge]

https://www.mathsisfun.com/geometry/triangles-similar.html

[tardy fulcrum]

yes i did by accident, the hypotenuse side is equivalent to 88

[upper karma]

https://prnt.sc/w43ofr

help

[dark jacinth]

The sides of a polygon are cyclically extended to form rays, creating one exterior angle
at each vertex. Viewed from a great distance, what theorem does this figure illustrate?
Could anyone illustrate what this problem is talking about^
I am not sure what they mean by "cyclically extended sides" to form rays

[left loom]

uh help

[pseudo kindle]

help lmao

[open pecan]

help

pls

what are the 5 median rules

[upper karma]

I got (0,1) for P’ bit Ian confused on Q

[vestal pendant]

hello

i’m confused on both

[lilac pine]

The angle (not x) next to 40 is 140

So the triangle is

X - 90 - 20

X is 70

And for the other one

Solve

[vestal pendant]

oh

[lilac pine]

2y + x = 180 and 3x + y = 180

Should be easy

[vestal pendant]

thanks bro

means a lot

i was stuck on 1 more but i was planning on doing it on my own

[lilac pine]

No problem

[vestal pendant]

i missed like 2 weeks of school since i had the rona

[lilac pine]

Oof

My condolences

[vestal pendant]

that’s why i’m confused af

❤️

ignore the shit below it

[lilac pine]

Huh

Is it just

10x + 1 ?

Is this all of the question?

[vestal pendant]

yeah

[lilac pine]

interesting

[shadow wadi]

I need serious help proving this identity

Thanks in advance

Photomath is helpless

This tgalfa+1/tgalfa-1

[foggy talon]

Please help me with this one

[grizzled knot]

SSS therom

side side side

if the three sides of a triangle are equal to the three sides of another triangle

I think that's how it works

[supple onyx]

@shadow wadi plug in sin and cos expression for tangent, expand numerator and denominator so they are both one fraction that end up having the same denominator of cos^2 which can be cancelled out. Then you're left with a fraction in terms of a difference of two squares and you can apply a partial fraction decomposition to it to get the final result

[grizzled knot]

$\frac{cos\theta-sin2\theta}{cos2\theta+sin\theta-1}=cot\theta$

[supple onyx]

No need to use double angle formulae

[grizzled knot]

for the second equation which I expanded

do I leave -1 alone

[supple onyx]

Wdym

Where did that cotangent come from

[grizzled knot]

$\frac{cos\theta-2sin\theta cos\theta}{cos^2\theta-sin^2\theta+sin\theta-1}$

[somber coyote]

LightBrin

LightBrin

[grizzled knot]

solving identities

I'm trying to prove Left side = Right side

[supple onyx]

Ah

[foggy talon]

wait @grizzled knot please explain a bit further I’m sorry I’m really slow

[supple onyx]

Triangles are congruent if they have equal sides

[grizzled knot]

It says SSS therom which means side side side I think. This means the 3 sides of a triangle are the same as the three sides of another triangle

and if you look at the three triangles on your screen

which two have the same sides

Going back Narwhal

I leave -1 alone?

or is there some other step

do you know

[supple onyx]

Lemme do the identity on paper real quick

[grizzled knot]

ok np

[foggy talon]

Is the answer right

[shadow wadi]

Sorry bro did this I dont get the requested

Photomath wouldve known that anyways

But photomath is kinda confused

[supple onyx]

@grizzled knot yeah expand 1 with pythagorean identity

Then top and bottom have a common factor that cancel out and you get your required result

Honestly you could have just tried that and seen if it worked though

[foggy talon]

Please check this answer

[supple onyx]

@shadow wadi youve done it wrong i believe just did it in my head and it works just fine

@foggy talon thats correct

Anyhow i gtg sleep

[grizzled knot]

is the pythagorean identity

[foggy talon]

okay thank u

[grizzled knot]

$1 = sin^2\theta + cos^2\theta$

[somber coyote]

LightBrin

[foggy talon]

Guys please check if I did it right

I don’t want to mess up

This is ixl

if I get one wrong my grade drops

[shadow wadi]

Here you go @supple onyx

[foggy talon]

Guys what about this one

Crap I got it wrong

[grizzled knot]

@supple onyx is the pythagorean identity

$1 = sin^2\theta + cos^2\theta$

[somber coyote]

LightBrin

[grizzled knot]

and if so why is it

It's negative 1

I forgot this part so could you explain

btw, idk if I'm allowed to tag you

cause there was a rule about helpers before

[pearl python]

light you can use the reply thing instead of @

[grizzled knot]

oh

I forgot baout that feature

[foggy talon]

@grizzled knot can you check my answer?

[grizzled knot]

seems about right

[foggy talon]

Oh I got it wrong

I just checked

But thanks

[pearl python]

think i could get some help on that first problem i sent?

[grizzled knot]

send again

I don't see it

I can't help but someone else can

[pearl python]

its simple i just dont remember how xDC

[grizzled knot]

I don't remember either, I'm sitting here trying to prove trig identities

[pearl python]

xD

[grizzled knot]

wait a second

there was a radian unit circle here all along, omg that would have helped me so much if I had known earlier

[foggy talon]

@grizzled knot I’m sorry to bother you but can you check this

[grizzled knot]

yup, it's correct

just make notes

SSS means side side side

which means 3 sides of triangle = 3 sides of another triangle

SAS means side angle side

two sides and the included angle of one triangle = two sides and the included angle of another triangle

[upper merlin]

wait you might have to rearrange the order of the vertices

[grizzled knot]

and the last one which is ASA

whic his angle side angle

[upper merlin]

it would be hgi is congruent to bca

[foggy talon]

Okay thank u

[echo badger]

someone help out

<@&286206848099549185>

[humble pulsar]

@echo badger find angle B

[echo badger]

119

what is BC and AC

[humble pulsar]

yeah, then do law of sines

[echo badger]

what si the formula for law of sines?

is*

[humble pulsar]

$\frac{\sin{A}}{a}=\frac{\sin{B}}{b}=\frac{\sin{C}}{c}$

[somber coyote]

moshill1

[upper merlin]

alternatively

[echo badger]

2r/1 ?

[upper merlin]

i meant a/sinA=b/sinB=c/sinC=2R

[echo badger]

oh

[upper merlin]

where R is the circumradius

the circumradius part wont help u much with this problem but its good to know

[echo badger]

what do i do next?

for BC and AC

[upper merlin]

what c/sinC in this case

[echo badger]

c/sin36?

oof

[upper merlin]

c is given, its 28

so 28/sin36

[echo badger]

ohh that c

the line c

[upper merlin]

now let BC=a

we know c/sinC=a/sinA

by law of sines

c/sinC is 28/sin36, and A is 25

[lament cobalt]

Idk, if this is the right spot to post this?

[echo badger]

uh

[upper merlin]

so u have the equation 28/sin36=a/sin25

now solve for a

[humble pulsar]

F pattern

[echo badger]

k

[upper merlin]

and then use the fact that sum of angles = 180 to find the 3rd angle, then use law of sines again for b and sinB

[echo badger]

do i cross mulitply?

to find a

sorry i am new to it thast why

[lament cobalt]

?

[humble pulsar]

F pattern means the angles w/ x are equal

[lament cobalt]

oh,thank you👍

[silent plank]

what's troubling you with this one?

[lament cobalt]

how do I determine what SQRLike I figured out what X is,but When I Go to put x in,it said that it was wrong

[silent plank]

show your work

i.e. how you determined x and what you got when subbing it in

[lament cobalt]

This was the 1st half

This is the 2nd half

My handwriting is kinda bad

[silent plank]

your set up is completely wrong

why are you setting your angles equal to each other?

[lament cobalt]

I thought that is what we was supposed to do

[silent plank]

no

2 adjacent angles aren't necessarily equal

you should be applying angle sum on a line

[lament cobalt]

I thought I was looking for the segment bisector

[silent plank]

the image indicate anything being bisected by anything

don't make poor assumptions

[lament cobalt]

my bad, I try not to

[halcyon hound]

i need help w something

[foggy talon]

Can someone help me with this

I really don’t understand this

[silent plank]

what specifically don't you understand about it?

consider exterior angle theorem which can be derived from the combination of:
angles sum in a triangle
angle sum on line

[foggy talon]

like all of it the textbook is really crappy and it doesn’t explain it well

what is this

like the u

what’s with the angles

[humble pulsar]

This is SPARTA

[silent plank]

the u is a variable

that represents a certain value

[foggy talon]

alright and how do we find u

[silent plank]

consider exterior angle theorem which can be derived from the combination of:
angle sum in a triangle
angle sum on line

[foggy talon]

alright and what’s the next step

[silent plank]

manipulating and solving a linear equation

do same shit to both sides etc
work towards isolating the variable you intend to find (in this case u)

and then you'll know what u is, which is what the question wants

[foggy talon]

so how do we put the equation?

I’m sorry I’m very slow

[silent plank]

consider exterior angle theorem

if you don't what that is look it up

[foggy talon]

I actually really don’t

please keep explaining

[silent plank]

look it up

or apply the combination of

angle sum in a triangle
angle sum on line

spend a little effort yourself

[foggy talon]

look I’m sorry I am looking into it

[vestal pendant]

questions 1 3 5

confusing af

[upper karma]

for question 5 the base angles are 85

the exterior angles described therefore are 180-85, or 95

for question 1 the side you're attempting to find is equal to 21

x is equal to 12

[vestal pendant]

o

im confused, DMs

[foggy talon]

Hi can someone check my answer

<@&286206848099549185>

pls I’m so tired

I need to know if it’s right

[vestal pendant]

No

its not

[foggy talon]

okay what’s the correct one

and thank you for answering

I also thought it was ASA

@vestal pendant

[vestal pendant]

its no

its not

it cannot be proven

all you have is angle side

[upper karma]

@foggy talon sorry for being late but your answer is correct

you can't prove congruence with only two sides

[foggy talon]

I got it wrong

[upper karma]

huh

what was the answer then?

[foggy talon]

it said SAS

[upper karma]

well in that case it must've been an error

[foggy talon]

I still need help with the one above

So if someone can help

[silent plank]

for the previous question you were told two sides were congruent from the markings.
one of the sides were also common in both triangles.
the marked angles are also congruent (and between the corresponding sides)
hence you have congruence by SAS

[upper karma]

well then that's my mistake

[foggy talon]

okay thank you for exposing

explaining

[upper karma]

i thought the marked angles weren't congruent because of the way they were marked

[silent plank]

both marked with a single red arc (with no values attached) in context implies they're congruent

[foggy talon]

But what about my latest question?

[upper karma]

i apologize for having misunderstood that

the triangles in the latest question shouldn't be provable

there are only two congruent angles and no congruent sides as far as i can see

oh and the vertical angles are congruent

also i found this weird identity and i need help proving it

here's a unit circle with all the trig functions

[viscid garnet]

can someone help me with this explanation? I know that the ratios are equal but my teacher said to include how the 2 acute angles are complementary and how that factors in

[zenith garnet]

maybe start by labeling the sides

other than that idk

anyone else?

[upper karma]

well i know an identity that would help but it won't be useful if they don't show how they proved it

[viscid garnet]

oh

[upper karma]

@viscid garnet have you learned that sin(x) is equal to cos(90-x) before

oh

[viscid garnet]

my teacher wrote that out when she was telling me to incorporate the complimentary angles

but i haven't made the connection to write it out in words

because i feel like just writing the ratios out is too basic

[zenith garnet]

yeah i was gonna say the ratios technically prove it?

[upper karma]

so you know the concept but can't explain it using complementary angles

[viscid garnet]

yes

like am i missing some key phrase that explains it well or is just mentioning that the angles are complementary enough

because i dont know why them being complementary is significant

[zenith garnet]

maybe prove sin(x) = cos(90-x)? first sorry im just throwing out ideas

@upper karma any ideas?

sorry @viscid garnet im not sure

[upper karma]

let me try to write out an explanation

[viscid garnet]

okay thanks!

[upper karma]

i think i've got it

i wont put my words directly in your mouth

first, explain that the acute angles in a right triangle are complementary

[viscid garnet]

yes

[upper karma]

then explain how the ratios are equal

conclude by stating sinx=cos(90-x)

[viscid garnet]

ok

thanks

thanks you for help

[upper karma]

np

yes?

[zenith garnet]

how do u prove that angles are acute in a right truiang;le

wait no

the actue angles are complemtnary

i mean

sorry

i have autism

so

its hard for me to type

[upper karma]

well complementary angles add up to 90

[zenith garnet]

dont they multiply to 90?

[upper karma]

any triangle must have interior angles that add up to 180

[viscid garnet]

drizy no

[zenith garnet]

i thought it adds up to 360

[upper karma]

in a right triangle one angle is 90 already

[viscid garnet]

they add to 90

[zenith garnet]

but a right angle is 180

[viscid garnet]

???

[zenith garnet]

??

[upper karma]

therefore the two remaining angles must add up to 90

[zenith garnet]

the two remaining add up to 180

[upper karma]

therefore they must be complementary

[zenith garnet]

bc 180+180=360

...

[upper karma]

the sum of interior angles is always 180

right angles are 90

[pearl python]

<@&286206848099549185>

[amber wraith]

this should be under algebra

try forming the equation from the word relation first, then solve for A

[pearl python]

oh its not geo my bad

[foggy talon]

<@&286206848099549185>

pls help with this one

I keep getting it wrong

[amber wraith]

Do u know what is the exterior angle theorem? @foggy talon

[foggy talon]

no I really done

don’t

I need to learn but I search up examples and I don’t get it

[amber wraith]

do u know the sum of angles on a straight line?

[foggy talon]

A bit

But not really

[amber wraith]

what's the sum?

of angles on a straight line =

of angles in a triangle =

[foggy talon]

180
90

I think

[amber wraith]

90?

180 for straight line is right

but triangle 90?

[foggy talon]

Yeah the last one I knew it was wrong

It sounded off

That’s for right

[amber wraith]

u need to know that before u can solve

[foggy talon]

is it also 180

[amber wraith]

yes

now we can form 2 expressions for the unmarked angle

using the straight line, what is the expression for the unknown angle of the triangle?

[foggy talon]

31x+49=180

[amber wraith]

31x+49+the angle=180

to be more precise right?

[foggy talon]

yes

[amber wraith]

now forget about that for a second, focus only on the triangle, what is the expression for the unknown angle of the triangle?

[foggy talon]

31x+49

[amber wraith]

ignore that, look at the triangle only

[foggy talon]

180?

[amber wraith]

the 3 angles in the triangle should add up to 180 yea?

[foggy talon]

yes they should

[amber wraith]

write it out

[foggy talon]

x+36+x+42???

I’m not sure

[amber wraith]

x+36+x+42+the angle = 180

now u have 2 eqn and 2 unknowns, u can solve simultaneously

[foggy talon]

so add the 36 and 42

??

[amber wraith]

yup

[foggy talon]

It’ll be 78

So then what do I do

Subtract?

180-78

It’ll be 102

@amber wraith is what I said right?

[amber wraith]

yup

so 2x+ the angle=102

thats one eqn, combine this w the one we found earlier

[foggy talon]

2x+31x+49=102

33x+49=102

It’s around 2

is that right

[amber wraith]

31x+49+the angle=180
2x+ the angle=102

this 2 :_

🙂

[foggy talon]

wait so the answer is 2??

I get confused I’m sorry

[amber wraith]

do u know how to solve simultaeous eqn?

[foggy talon]

no I don’t think so

I’m sorry but it’s 12am here

I really need to sleep

is it 2?

[amber wraith]

nope

[foggy talon]

I’m sorry to ask but what’s the correct answer

[amber wraith]

1

[foggy talon]

okay thank you so much @amber wraith

[supple onyx]

@shadow wadi separate denom as difference of two squares and perform a partial fraction decomp. @grizzled knot yes that is the correct identity. The fact it's -1 will allow you to cancel with the earlier positive cosine squared term and the denominator will factor with sin

[nocturne thicket]

Why the heck is #13 a right angle?

The answer key says its a right angle

[amber wraith]

180-35-(25+30)=90

angle ACB is 90 so triangle ABC is a right-angled triangle

[nocturne thicket]

tf? I thought it was 25 + 30?

[amber wraith]

angle ABC is 55 degrees yes

they're asking the type of triangle not the type of angle

[nocturne thicket]

Also, that can't be right because if ACB = 90 and ABC = 90 BAC must equal 0

[amber wraith]

ABC is 55 not 90

[nocturne thicket]

but a 55 degree angle = acute????

[amber wraith]

as long as 1 angle in a triangle is 90 then the triangle is considered a right-angled triangle

[amber wraith]

it is an acute angle yes

[nocturne thicket]

oh my god

I see

you're right

im dumb, thanks for clarification

[granite violet]

"You know that cos v = 0,25. How big is the angle?

Someone who know the answer?

[amber wraith]

75.5 degrees?

v= inverse cosine 0.25

[granite violet]

ok

[amber wraith]

it could be 284.5 as well

75.5 is the principle angle

[foggy talon]

pls help me with this one

[silent plank]

what seems to be the issue here?

[foggy talon]

I just need to know if it’s right

Is it right

Or wrong?

[silent plank]

ASS is NOT a valid justification for congruence

[foggy talon]

OKAY THANK U

so I was wrong

I’m pretty sure this one is right

I really need to double check

[silk patio]

You’re baiting answers

[silent plank]

perhaps you should explain your reasoning

[silk patio]

Explain why you think it is what it is

[silent plank]

yeh just realised you're baiting

[foggy talon]

I’m not baiting I need to double check there’s this website my teacher assigns us

if we don’t get it right it lowers our grade

Look

I’ve answered 147 questions

I just need the reassurance that my answer is right

[silent plank]

is this some sort of competition with tangible rewards?

timed too so its pretty much borderline a test

[foggy talon]

It’s not timed

It’s how many hours you’ve spent on it

I’ve been on it for like 2 hours

[silent plank]

with this new revelation I'd only be comfortable with telling you to review the valid justifications for congruence and determine whether they're applicable

[fresh topaz]

Why u giving me big words i don’t speak English good and I don’t know where my reviews is

[silent plank]

i.e. the valid justifications are: ..
in my diagram i have: ...
hence conclusion

that comment as not for you

[fresh topaz]

What?

[foggy talon]

@silent plank alright I think it’s not congruent because there’s no side

sides

[fresh topaz]

Can you help me??

[foggy talon]

I really don’t know I’m not good at math I’m sorry @fresh topaz

[fresh topaz]

Ok

[silent plank]

how nice of you to cover probably the most important part of the question with your mouse cursor

[upper karma]

7 I believe

[fresh topaz]

7

sorry

[upper karma]

that's a one in a million chance right there

[fresh topaz]

lol

[silent plank]

apply properties of parallel lines

identify corresponding, alternate angles etc

[fresh topaz]

5?

[silent plank]

what 5 supposed to be?

[fresh topaz]

dude i'm confused can you say it in small words your texting in like a whole new level words for me

[silent plank]

which part of

apply properties of parallel lines
identify corresponding, alternate angles etc
is confusing

[fresh topaz]

all of them

[silent plank]

these are all terms you should already be familiar with

when doing these types of questions

if not

[fresh topaz]

bruh nvm imma just do my self

i don't need ur help

[silent plank]

look of a guide by doing a google search on:

properties of parallel lines

[fluid sparrow]

can someone ghelp me

idk hgow to do this problem

@silent plank

[silent plank]

I'm only a level 10 Psychic. I'm not good enough to know your problem.

@fluid sparrow

[fluid sparrow]

geometry

[cosmic pebble]

#questions

For a list of rules about asking on this server, please see #❓how-to-get-help.

[fluid sparrow]

i can send right?

[silent plank]

don't ping people directly without their permission

[fluid sparrow]

oh mk

[umbral snow]

At least take a look into vector addition, please.

[granite violet]

How do I solve x?

[rich mason]

SOH CAH TOA

[granite violet]

Yes but I don't get it

[rich mason]

Just follow this ^

So you have the values of theta (the angle) , the opposite (which is x) and the hypotenuse (which is 5)

Then use one of the formulas

[jagged magnet]

is 10 and 13 alternate or same side

[rich mason]

Same side

[jagged magnet]

precaite it

[upper minnow]

Can anyone please help

Pleaseeee anyone

BRUH PLSSSS HELP ITS PROOFS

@everyone

[jagged magnet]

yo arent tehy all the same

[upper karma]

order of vertices matters

[granite violet]

Thanks for the info! I got the answer 4,33m. Sin 60 = x/5 Sin 60 * 5 = x = 4,33m

[rich mason]

Great work!

[loud flare]

Can someone please help with this

[upper minnow]

Can someone help

[upper karma]

why was I unfortunate enough to take geometry in the 8th grade

and biology

[humble pulsar]

no clue, do you have a question or just complaining?

[upper karma]

complaining

[upper minnow]

Ok

Help now

@upper karma

Pls

[upper karma]

?

I can't do proofs like that

parallel proofs are my weakness

[upper minnow]

Noooo

Damn

[upper karma]

and parallel proofs in shapes

are even wose

worse*

my teacher usally does a bunch of lines

but when triangle

nope

[upper minnow]

Ok can u try this

[upper karma]

aren't u in 10th grade?

[upper karma]

why are u asking a 8th grader for help

[upper minnow]

No I am not in 10th

[upper karma]

9th?

[upper minnow]

Yes

U seem smart

[upper karma]

well I take a different geometry

[upper minnow]

Oh

🕴🕴🕴🕴

[upper karma]

things look much different

it's the same but different proofs

[upper minnow]

Bruh

[upper karma]

yea

look

I got a F first quarter

second quarter my teacher showed mercy

and exempted me from 2 0's

lol

see

the purple thing

[upper minnow]

I mean u have a’s and shi idk bru

[upper karma]

I got almost all 100's besides in math and reading

idk

[upper minnow]

You was me in 8th I almost failed and now I have high a in all my classes

[upper karma]

dang

[upper minnow]

Yea💩💩

[upper karma]

I'll give u another server

[upper minnow]

Nicee

[loud flare]

?

[lament cobalt]

Im about to take my final

Im very nervous,this determines if I fail or pass

[umbral snow]

Yes

[nocturne thicket]

How do I do this?

also ignore the 2c that's a misclick

[jagged tangle]

I'd try using the distance formula or midpoint formula and manipulate those to get the answer. Look at the answers and see if you get one of them. I'm rusty on geometry, so I don't have much more than that rn

[nocturne thicket]

That doesn't quite help me

<@&286206848099549185>

plz help

[granite violet]

-I can calculate the area of ​​the triangle if I get to know the angle between the sides a and b and its lengths.

Determine a formula for the area of ​​the triangle.

[blazing pond]

x=1 right?

[deft bear]

I am not sure how to do this

[spare widget]

@deft bear You still need help with this question?

[lavish surge]

Can anybody help me set this up to solve, im completely puzzled

[upper karma]

any one know how to do this

@spare widget can you help me

@molten kayak can you help me

[lavish surge]

First one is SAS, second one is ASA third one is SSS

@upper karma

[upper karma]

thanks

what about these 2

[wintry tundra]

Lol I haven't done geometry in forever

[upper karma]

ok nvm i am done

[wintry tundra]

Which isn't a good thing since I want to be an engineer lol

[alpine latch]

you speak german, i can give you analina homework

[inland canyon]

Find the measure of YP in degrees

i was gonna say its 128 but its not a centeral angle

<@&286206848099549185>

[humble pulsar]

YP isnt an angle

also wait 15 mins before pinging

[wintry tundra]

yp is a curve right?

[inland canyon]

ye

its uhh

it says find the measure of yp in degrees

thats all it says

A.) 166
B.) 147
C.)90

D.) 128

this is just some reveiw shit im doing cuz i dont understand it

so like

am currently trying to understand it

@wintry tundra

And everything i can find to try and help me is only talking about centeral angle

ik about centeral angle

[molten bronze]

Can anyone help me with math rn :?

[wintry tundra]

Oh sry

I'm bad at circles so uh sry

I'm an algebruh

[inland canyon]

bruh

[wintry tundra]

@molten bronze what do u need

[molten bronze]

I’m sorry I’m back

Also I’m in geometry so I don’t think u can help ‘e ?

[near tendon]

Would anyone be able to provide the answers with the work shown for my younger brothers Quadratics math homework. Tried to help him but I honestly just don't remember how to do it and came here for some help. Thank you, questions are below

🙂

[humble pulsar]

@near tendon no one provides answers

[molten bronze]

Can someone check my work :?

I feel like this question has 2 answers but one answer is unethical and I’m confused

[near tendon]

@humble pulsar could I get the steps or work?

Instructions maybe

[granite violet]

What did I do wrong

c)

[inland canyon]

bro

how the fuck

am i meant to find the god damn

length of an arc

when i dont have the radius

bruhh

[granite violet]

Um use x

[molten bronze]

Teddy can u help me :?

[granite violet]

Probably not

[molten bronze]

Ahh okay 😉

;~)

[granite violet]

What is it?

[molten bronze]

Geometry

9th grade lvl

[humble pulsar]

@molten bronze youve yet to actually post a question

[granite violet]

Lol

[molten bronze]

Ahh I normally post when someone can help me

I don’t wanna peer pressure them I’ll do it rn lol

[humble pulsar]

well that isnt how the server works

Rule 1 on #❓how-to-get-help

[molten bronze]

Cause when I look closely they don’t look like it

Ahh mb (I didn’t actually read that I’ll do it rn ) also these are verticals angles right

[granite violet]

Aight boutta head out

Sry I cant answer

[molten bronze]

All g 🙂

Also I just read the rules and I got it now

[wintry tundra]

@near tendon I can give u guidelines

I won't give answers tho since u know

[heady sapphire]

pog

[small blade]

I'm here for my little brother what's an arc

He needs help and his teacher won't respond to emails from him or me

[rain holly]

https://www.mathsisfun.com/geometry/arc.html

@small blade

[cyan oracle]

i know this one isn't A lol

buttt still confused

[dusky surge]

Yea, A can be proved if you assume AD and BE are straight lines.

For SAS, you'll have length of two pair of sides equal and the angle between those sides are equal.

[wintry tundra]

@upper karma BD is 24 cm

[somber elbow]

How do I solve for the circumference

[amber wraith]

find diameter and radius first

[somber elbow]

All I have is angle A

So I would use that

[amber wraith]

try cutting the big square into 4 identical small squares

that might allow u to see something

[somber elbow]

Is it option c?

[west basin]

yes

[somber elbow]

Thank you

[analog wedge]

hlep plaese

[native crow]

may i have assistance

[dusky surge]

All of them?

[native crow]

any question is fine

[green osprey]

can someoen help me with this later

its so god damn confusing

[dusky surge]

https://www.mathsisfun.com/algebra/trigonometry.html

[native crow]

danke 🙏

[green osprey]

ok are you guys done now?

[dusky surge]

So hard man@DimwitQ#5847

[green osprey]

it is .-.

[dusky surge]

First thing, do you think they're similar?

[green osprey]

no?

wait yes?

same shape?

[dusky surge]

A and B have some hints for ya

If they are similar, angles should be congruent and corresponding sides are all proportional in length

[green osprey]

so its either a or b

actually

can i get help with this instead

[dusky surge]

Ehhh?

[green osprey]

which do i do first

reflection or dialation

[dusky surge]

I think reflection first

[green osprey]

what does it mean with y = -x

[dusky surge]

Reflect along that line

[green osprey]

oh

fuck

[dusky surge]

,w graph y=-x

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by Biscuit#5208

[dusky surge]

Haha

[green osprey]

back to the first one

how ?

[dusky surge]

...

[green osprey]

is it a?

[dusky surge]

Nope...

[green osprey]

wait

that would mean its a square if its a

so what does similar even mean

if its the same shape?

because if its that then i can figure this out

fuck it im choosing b

[dusky surge]

If you forgot what similar means, you may wanna read your notes before continuing

[green osprey]

i chose b

already submited the hw

was it right?

[dusky surge]

Nope

[green osprey]

god dammit

what was it

[dusky surge]

https://www.mathsisfun.com/geometry/similar.html

[green osprey]

well shit

there goes my B

[modern knoll]

anyone?

[night basin]

The line y=2x+1 is reflected about the line y=1/2x

what is the equation of the reflected line ?

this is like a mega challenge problem lmao

[foggy talon]

guys how do you do the exterior angle therom

again

[silent plank]

combination of angle sum on a line and angle sum of a triangle

and/or apply the theorem directly

[wintry tundra]

Is that geometry? I haven't taken it in a bit so

[west basin]

i think a and b are vectors

its asking if the magnitude of a-b = magnitude a+b

[wintry tundra]

Oh ok

I dont know

I was going to say if a or b is 0 then yes cuz I thought abs

[hollow ridge]

does this look correct

[wintry tundra]

I never learned hyperbolae but I think so

Since its like reverse circle formula

[granite plank]

Anyone able to walk me through the steps on solving a polynomial inequality

[wintry tundra]

Same thing but inequality

[whole carbon]

Hey can someone help me solve this

.05x - .25 = .12x - .74; Solve for x

[upper karma]

@upper karma combine like terms and then divide - isolating the x terms

[whole carbon]

@upper karma hey

Do u know how to do this

https://cdn.discordapp.com/attachments/704944645712642098/789627345291313152/image0.jpg

9. A B C

[upper karma]

img is loading

😐

[whole carbon]

https://cdn.discordapp.com/attachments/704944645712642098/789627345291313152/image0.jpg

[upper karma]

bruv

[whole carbon]

U see it?

[upper karma]

nope

[whole carbon]

How about now

[upper karma]

I feel you

[jaunty wren]

Can someone help me on these

[wintry tundra]

i can barely see each equation

[jaunty wren]

This better?

[west basin]

alright for 1 what do you think?

its 4 half circles of radius 2.5

and a square with sides of 5

[wintry tundra]

yes

i can see

[west basin]

the perimeter will just be the circumference of the circles

[jaunty wren]

Howd you get 2.5

[wintry tundra]

so whats the formula for a circle?

[west basin]

divide 5 by 2

[jaunty wren]

Idk how I can write it

[wintry tundra]

pi*r^2

[jaunty wren]

Yes

[wintry tundra]

so if you have a square surrounded by half circles

whats the formula for a half circle

(pi*r^2)/2

[jaunty wren]

Yeah

So pi*2.5^2 x 1/2

[wintry tundra]

so then since 4 half circles are 2 circles

just so 2pi*r^2

[jaunty wren]

Ok

I think I got it

[wintry tundra]

but pi is a variable probably so dont worry about multiplying by pi

[jaunty wren]

Be back when I'm done with this problem

[wintry tundra]

just do it in x*pi form

[jaunty wren]

Yeah my dad told me that but hes asleep rn

[wintry tundra]

ok

im guessing ur in geo

so something like 8th or 9th grade math

[jaunty wren]

Yeah 7th grade actually

I'm 13

[wintry tundra]

ohh wow

impressive ur school lets u do geo in 7th

so ur gonna be taking calc in 10th O_O

im in 9th grade taking Alg2

[jaunty wren]

Well

I feel that geometry like this shouldnt be in 7th

[west basin]

it absolutely should

it should be taught even younger

[jaunty wren]

No

[wintry tundra]

geometry is pretty easy so

unless ur doing like proofs

[west basin]

This is barely geometry

[wintry tundra]

^

trig is where geometry gets funky

[jaunty wren]

My school untill 7th grade is pretty much repeated stuff

[west basin]

right triangle trig isnt that funky either

[wintry tundra]

im still waiting to learn trig cuz i dont really understand sin cos and tan besides that they are ratios

[jaunty wren]

Ight I got the first finished

The worst about 7th grade is well you learn about "the body"

And if you know what I mean

[wintry tundra]

eh

[west basin]

Dude youre a human you should know what parts you have

and how they work

[wintry tundra]

reproduction isnt too bad if ur mature enough

[jaunty wren]

No I mean

My schools

Currently doing at home school

And if we stay

We have to watch the videos about it

WITH OUR PARENTS

[wintry tundra]

my school doesnt do that but i know how meiosis works

oh that is weird

hmm

[jaunty wren]

Now

[wintry tundra]

wait

is it mitosis that is unique

[jaunty wren]

My teacher if you laugh or chuckle once I heard

[wintry tundra]

or is it meiosis

[jaunty wren]

You have to explain to him

Why

You laughes

[west basin]

just dont laugh then

[wintry tundra]

^

[west basin]

its not funny

[jaunty wren]

It isnt

But he makes it awkward

[wintry tundra]

not gonna lie gametic fusion is so funny

[west basin]

yeah its always like that

[jaunty wren]

I heard this from a friend

The videos are so corny

[wintry tundra]

$\int_{10}^{13} 2x \ddx$

[somber coyote]

hiidostuffmc
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[west basin]

as someone who has gone through the school system i can tell you its not fun

[wintry tundra]

amiright

[west basin]

69?

[jaunty wren]

And

[wintry tundra]

except it didnt put dx for some reason

[west basin]

lol

[jaunty wren]

The boys and girls dont separate ar my school

[wintry tundra]

so?

[west basin]

public schools dont separate by gender

its illegal

[wintry tundra]

i mean its important to learn how it works since its a part of life man

[jaunty wren]

Istg if I gotta watch it with my parents

[wintry tundra]

meiosis is pretty interesting

the cellular level of it i mean

[jaunty wren]

I wanna go back to preschool

[wintry tundra]

aaaanyways

[jaunty wren]

I liked finger painting

So imma get this done now

[wintry tundra]

ok

[jaunty wren]

Its 1am currently

[wintry tundra]

the rectangle with half circles out of it

[jaunty wren]

And once I do this I'm on Christmas break

[wintry tundra]

is $lw - pi(\frac{w}{2})^2$

[somber coyote]

hiidostuffmc

[wintry tundra]

w= height btw

[jaunty wren]

Ok

What about the one with the diamond lookin thing in middle?

Do you know

[wintry tundra]

what do the shapes look like