Its basically the same as a parabolic projectile motion problem
#geometry-and-trigonometry
calm umbra
coral frigate
@calm umbra Sorry for delay, had to try and walk my dog really quick. I’m reading through your response now. Thanks for taking the time to help me out.
chrome remnant
coral frigate
@calm umbra
Ok, just to clarify:
User presses (not holds down) the RIGHT ARROW KEY:
- Set the player vertical velocity to (some value) ---- velocity.y = some value
- Calculate the horizontal velocity based on the information we have.
- Gravity is applied to the vertical velocity by some constant --- velocity.y += gravity
(NOTE: in computer graphics the origin of everything position on the screen is at the top left corner of the screen. So, moving down the screen increases the y position, and moving up decreases the y position)
Edit: Still finishing comment
Horizontal velocity has no acceleration component
Correct
So horizontal distance is xy*t
Here, what are the variables? I get time, but not sure about the xy or if it was a typo.
Set d = to that xy*t and you can solve for the horizontal velocity needed to clear thay distance in one jump
calm umbra
My bad
Typi
I just wass using your nomenclature
I would just call it x
And i made a typo i meant vx
Or xv whichever you had said
x is initial horizontal velocity
Im assuming you get all your x velocity right there at time of jump
coral frigate
Yes, the x velocity is calculated at the time of the jump.
calm umbra
So you are solving
D = x*t
Where t is the time it takes to land after jumping
D is the distance you want to clear
coral frigate
Oh, ok I see.
So, question about calculating the time of the jump as you mentioned above:
Once I have solved for t (time) using this formula:
t = vy / g
where t = time, vy = vertical velocity, and g = gravity
This tells me the time the jump lasted?
I rearranged the formula:
y = (vy - g*t) * t
to
t = vy / g
where y = y position
coral frigate
@calm umbra Thanks for your help, I believe I got it working 👍
molten harness
cosmic pebbleBOT
upper karma
Just post it
true pollen
Can someone explain what "tan" is?
hollow raven
tan θ = sin θ / cos θ
tangent (tan for short) is a type of trigonometric function that relates the opposite side of an angle with the side adjacent to the angle in a right angled triangle
Consider this triangle
The opposite side to the angle and adjacent side of the angle can related through a trigonometric ratio
tan A = (opposite side length) / (adjacent side length)
What is really cool about this ratio is that firstly, it is also equal to sin A / cos A
And secondly, we can isolate for a certain value we want to find:
Let's say we want to figure out the angle; we can simply do:
tan A = (opposite side length) / (adjacent side length)
**A **= tan ^-1( (opposite side length) / (adjacent side length) )
Note: tan^-1(x) is just the inverse of the tan function, or arctan
Similarly, if we wanted to find a certain side, we can isolate for that particular value:
tan A = (opposite side length) / (adjacent side length)
opposite side length = (adjacent side length) * tan A
tan A = (opposite side length) / (adjacent side length)
adjacent side length = (opposite side length) / tan A
@true pollen
true pollen
Thanks
upper karma
HELP PSL
PLS
i dont understand whats wrong with my solution:
So we label AE as y. Since AECF is a parallelogram, we have AF = 4sqrt13 and since EFHC is a rectangle, we have FH= 4sqrt13. This gives us AH = 8sqrt13. Since EF is the perpendicular bisector of AH, we also get that AEF and EFH as right triangles. Since EF = sqrt(y^2-208) and FH = 4sqrt13, we have EH = y. Now we can solve for y, as AEH is a right triangle with legs as y and y. This means that y*sqrt(2)= 8sqrt13 giving us y=4sqrt26. We also get DF = 2sqrt26 and AD = 2sqrt26 as they are 45-45-90 triangle. Angle DFH is 135 because AFD is 45. Finishing using LOC, we get DH = 2sqrt130.
why is this incorrect?
i am confuzled
visual crest
Need help with Geometry dm
hollow raven
@agile socket The period is 2pi because since there is no horizontal stretch/compression, the period does not change from its parent function cos(theta)
The period of a sinusoidal function is affected by the horizontal stretch / compression and the amplitude is affected by the vertical stretch / compression
hollow raven
Corresponding angles have to be equivalent for the lines to be parallel
if an angle is supplementary, it just means that angle that is paired with another, resulting in a 180 degree angle
dapper bronze
So it’s no?
hollow raven
Should be false yes
dapper bronze
Lanes full atm
upper karma
So we label AE as y. Since AECF is a parallelogram, we have AF = 4sqrt13 and since EFHC is a rectangle, we have FH= 4sqrt13. This gives us AH = 8sqrt13. Since EF is the perpendicular bisector of AH, we also get that AEF and EFH as right triangles. Since EF = sqrt(y^2-208) and FH = 4sqrt13, we have EH = y. Now we can solve for y, as AEH is a right triangle with legs as y and y. This means that y*sqrt(2)= 8sqrt13 giving us y=4sqrt26. We also get DF = 2sqrt26 and AD = 2sqrt26 as they are 45-45-90 triangle. Angle DFH is 135 because AFD is 45. Finishing using LOC, we get DH = 2sqrt130.
why is this incorrect?
hollow raven
Is this a test @dapper bronze
upper karma
dapper bronze
No it’s a study guide
hollow raven
Okay
upper karma
problem
dapper bronze
??
hollow raven
the converse is just reversing logic
upper karma
why is my sol incorrect
So we label AE as y. Since AECF is a parallelogram, we have AF = 4sqrt13 and since EFHC is a rectangle, we have FH= 4sqrt13. This gives us AH = 8sqrt13. Since EF is the perpendicular bisector of AH, we also get that AEF and EFH as right triangles. Since EF = sqrt(y^2-208) and FH = 4sqrt13, we have EH = y. Now we can solve for y, as AEH is a right triangle with legs as y and y. This means that y*sqrt(2)= 8sqrt13 giving us y=4sqrt26. We also get DF = 2sqrt26 and AD = 2sqrt26 as they are 45-45-90 triangle. Angle DFH is 135 because AFD is 45. Finishing using LOC, we get DH = 2sqrt130.
please help 🙏
hollow raven
For example, "if its raining its wet today" has a converse of the following: "if its wet today then its raining"
dapper bronze
Aboo can we go to a different channel
agile socket
@agile socket The period is 2pi because since there is no horizontal stretch/compression, the period does not change from its parent function cos(theta)
@hollow raven Thanks
hollow raven
np
Don't worry diego, im wrapping up
if a triangle is a right angled triangle then a^2 + b^2 = c^2
dapper bronze
Okay thanks
hollow raven
The converse in this case would be "If a^2 + b^2 = c^2, then the triangle is a right angled triangle", its like reversing the order of logic
upper karma
@upper karma I don't get where "H" is supposed to be
hollow raven
Is that understandable? @dapper bronze
upper karma
it's not on AF
af is a line
"the foot of the perpendicular from C to AF"
what does that even mean?
dapper bronze
So would D be the right answer aboo?
hollow raven
Yeah diego
upper karma
upper karma
how is this related to trig?
dapper bronze
Geometry
hollow raven
Well if today is thursday
and sam has wild cat mash for lunch when its thursday...
What can we conclude about what is going to happen today (Thursday)?
dapper bronze
A?
upper karma
yeah, it's probably a
hollow raven
Should be 😃
dapper bronze
That’s not an option
upper karma
hey @upper karma i asked the person he said it basically means where line AF intersects line CH such that they r perp
@dapper bronze you want other people to just give you the answers?
dapper bronze
No I want to know understand the study guide and know I’m studying the right stuff
placid vapor
Help the poor guy out
dapper bronze
Ur teaching me unlike the websites was my point
dim gyro
Can someone fact check me
hollow raven
Well, the angles equal to 70 degrees have to be corresponding or opposite to that angle or any related angles
dim gyro
I feel I messed up number 11
placid vapor
Bob go to a dif channel
upper karma
this is my sol: So we label AE as y. Since AECF is a parallelogram, we have AF = 4sqrt13 and since EFHC is a rectangle, we have FH= 4sqrt13. This gives us AH = 8sqrt13. Since EF is the perpendicular bisector of AH, we also get that AEF and EFH as right triangles. Since EF = sqrt(y^2-208) and FH = 4sqrt13, we have EH = y. Now we can solve for y, as AEH is a right triangle with legs as y and y. This means that y*sqrt(2)= 8sqrt13 giving us y=4sqrt26. We also get DF = 2sqrt26 and AD = 2sqrt26 as they are 45-45-90 triangle. Angle DFH is 135 because AFD is 45. Finishing using LOC, we get DH = 2sqrt130.
for this problem : https://cdn.discordapp.com/attachments/729759635501744139/768157096726233098/Screen_Shot_2020-10-20_at_9.43.03_AM.png
oh ok
dapper bronze
So angle 5?
placid vapor
I think 6
hollow raven
Not just 5, consider all the angles that correspond with related angles too
dim gyro
Also do i solve question 12 the same as 11
placid vapor
Oh only 5
dapper bronze
5,6,7?
hollow raven
5 and 7 dont make an F shape, nor are they opposite, they are supplementary to the 70 degrees angle
Try and experiment with other angles; what angles make an "F" shape with 70 degrees?
dapper bronze
Lemme go see
dim gyro
Nvm it says lateral not surface, lol 5head
visual crest
Given that E(-3, -3) and F(9, -15), find the length of EF. (Leave your answer in radical form.)
Your answer should be typed like the following example. \sqrt{3}
3
or root(3)
The length of EF is
hurry
dapper bronze
4?
hollow raven
Uh, why the rush?
hollow raven
You dont need midpoint
visual crest
ok
hollow raven
You can just use the distance formula
visual crest
ok
hollow raven
distance = sqrt((y2-y1)^2 + (x2-x1)^2)
visual crest
ok thank you
dapper bronze
2?
visual crest
can you put the decimal in radical form??
hollow raven
Nope 👀
dapper bronze
Jeesh 2,6,1?
hollow raven
Okay, what you have to see is that < 3 makes a F (corresponding) angle with 70 degrees
x2 and x1 are just the x values
so if you have (3, 4) and (5,6), x2 = 5, and x1 = 3
visual crest
can i add you to a call aboo
hollow raven
and y2 = 6 and y1 = 4
dapper bronze
Ohhhhhhh 2,6,3??
visual crest
its ok im screen shearing\
dapper bronze
Alr thanks
upper karma
HI can someone PLEASE HELP! I have been asking for the past 3 hours and no one has responded!
This is my situation
i got an answer which is not correct and i keep thinking it is correct
can you tell me what is wrong with my sol?
this is my sol: So we label AE as y. Since AECF is a parallelogram, we have AF = 4sqrt13 and since EFHC is a rectangle, we have FH= 4sqrt13. This gives us AH = 8sqrt13. Since EF is the perpendicular bisector of AH, we also get that AEF and EFH as right triangles. Since EF = sqrt(y^2-208) and FH = 4sqrt13, we have EH = y. Now we can solve for y, as AEH is a right triangle with legs as y and y. This means that y*sqrt(2)= 8sqrt13 giving us y=4sqrt26. We also get DF = 2sqrt26 and AD = 2sqrt26 as they are 45-45-90 triangle. Angle DFH is 135 because AFD is 45. Finishing using LOC, we get DH = 2sqrt130.
dapper bronze
dapper bronze
@hollow raven
humble pulsar
No aboo was helping them earlier
who pinged
silent plank
draw a diagram,
apply definition of bisect
hollow raven
^
upper karma
for whom?
hollow raven
@upper karma the question is sort of weird, how does <CEF = 90
upper karma
something like this
you can adjust it to fit the reqs
this is my full messy diagram
hollow raven
How would that be possible if AE = CF
upper karma
hollow raven
Oh like that
upper karma
yeah
hollow raven
hold on lemme just experiment a bit
upper karma
k
dapper bronze
Help??
upper karma
Hey @hollow raven how far r u?
i have to go now, is it possible you can DM me where i screwed up?
thanks 🙂
dapper bronze
indigo chasm
pastel oracle
Please can someone help with the math, not the code, just the math, Thanks!
ivory sequoia
can we get some help in math
pseudo pumice
Could someone explain to me the process of simplifying this function after cos and sin is found?
Simplifying the fractions has got me tripped up but I have 3(sqrt2/2) - 5(sqrt2/2)
severe thicket
@pseudo pumice easy one second
signal swallow
Simplifying the fractions has got me tripped up but I have 3(sqrt2/2) - 5(sqrt2/2)
@pseudo pumice what is 3 times sqrt2/2?
umbral snow
What if I gave you
3x - 5x?
pseudo pumice
...-2x
umbral snow
Of course! But in this case, I just used x to represent √2 / 2
umbral snow
So you have -2(√2 / 2)
pseudo pumice
oh that makes sense
umbral snow
Or, yes you can add them as fractions. Two different ways to do
pseudo pumice
didnt even click like that
severe thicket
First graph got me confused here
absolute value of a reciprocal sinusoidal, but how do I start
crystal marlin
- Discs of radius 4 cm are cut from a rectangular plastic sheet of length 84 cm and width 24 cm.
a) How many complete discs can be cut out?
P.S I got 30 complete discs as the answer,but just wanted to make sure.
pseudo pumice
I think that might be wrong I just did LxW to get area of sheet and got 2016cm^2 minus total area you can get from discs which would be 3.14x4^2=50.24? 2016/50.24=40.12 so total complete would be 40 I think
crystal marlin
I thought 8 by 8 square is equaled to 1 circle,since the diameter of the circle is 8.So it is 24 x 80/ 8x8=30??
crystal marlin
24 x 80/8x8 is equal to 30
pseudo pumice
8 x 8 what is equal to 30
This problem gives you the area of the plastic sheet, then you have to use the formula Pi x r^2 to find the area of the disc in order to subtract how many you can fit in the sheet
crystal marlin
Oh ok thanks a lot,that makes more sense.
valid wind
oh, hi guys. i wanted to ask how can i demonstrate the area of a trapeze? i know the formula, just the demonstration.
i think it is pretty easy, but i have a math project at geometry and i cant find any demonstration on the internet 
silent plank
split into rectangle and triangles
valid wind
oh yeah, thx.
grim cairn
any idea on how to do this?
upper karma
i think its impossible
grim cairn
same
upper karma
yea its on of the types of questions where humanity would've ended by the time its solved
humble pulsar
sin(theta) = y/r
so y=4, r =5 => x=3
sin(2theta) = 2sin(theta)cos(theta)
=2(y/r)(x/r)
=2xy/r^2
grim cairn
how does x = 3
grim cairn
ok so do i plug in 20?
grim cairn
yeah for the first one
humble pulsar
that's 2 times theta
west fox
hello ! I need help plz
grim cairn
so 2 times theta is sin20
grim cairn
oh im dumb
humble pulsar
you dont have any way shape or form of finding an exact value of sin(20) given sin(theta)=.8
west fox
let ABC be a triangle, B 'the foot of the height resulting from B, and C' the foot of the height resulting from C. Let Delta be the interior bisector of the angle A. Show that there exists a real lambda such that the indirect similarity f = hA, lambda s delta satisfies F (B) = B 'and F (C) = C'
Let H be the orthocent of ABC. Prove that f ^ -1 (H) is on the circle around ABC. what is this point?
grim cairn
so there's no answe?
humble pulsar
there is
grim cairn
but there is no shape or form of finding an exact value
humble pulsar
you're looking for sin(2theta) right?
grim cairn
yeah
humble pulsar
do you know the double angle formula?
grim cairn
no
humble pulsar
Well that's the problem lol
sin(2x) = 2sin(x)cos(x) for all x
You can find sin(theta) and cos(theta) based on the fact sin(theta) = 4/5
sage sandal
I'm trying to prove that cos^2xcsc^2x+cos^2xsec^2x=csc^2x and I'm honestly stuck.
So far I've changed the cos^2x to 1-sin^2x and expanded the equation, but from there I'm not sure where to go.
dark sparrow
yes you are.
wintry harbor
I don't understand why BX/XC is necessarily equal to BY/YC
If anyone can help it'd be much appreciated
Because the correct answer is E
green tree
hybrid solstice
i was joking lol
green tree
what is it then
wintry harbor
What's with these names
green tree
what?
hybrid solstice
bro why you gotta roast me like that
green tree
yeah
wintry harbor
Lol my problem is just ignored :((
hidden oak
yours requires more brainpower lol I'm running on low sleep I'll take a look afterwards
wintry harbor
XD sure thanks
green tree
@hidden oak whats mine
hidden oak
you tell me
green tree
i was thinking none of these
hidden oak
looks correct to me
upper karma
I would also choose none
hidden oak
seems like it
my brain still doesnt want to work lmfao but @wintry harbor what have you tried for yours
upper karma
@wintry harbor
wintry harbor
Yes
I know why A, C, D are necessarily equal to BY/YC
But there's only one correct option
So it's either B or E, and I think B is wrong (i.e. it is the correct option since the ratios are not necessarily equal) but Idk about E
wintry harbor
By the angle bisector theorem it's the same as AB/AC
upper karma
so if BC is 12, BY and YC are both what?
wintry harbor
And also the same as area(ABY)/area(AYC) and area(XBY)/(XYC)
so if BC is 12, BY and YC are both what?
@upper karma Doesn't that depend on where A is
upper karma
bisector means it splits it in half
blissful horizon
upper karma
therefore, BY = YC
blissful horizon
Im not sure what this is asking?
wintry harbor
But it's the angle bisector not the median
wintry harbor
Im not sure what this is asking?
@blissful horizon If by 'line' you mean it needs to be defined by two letters then KH
It's asking for line of symmetry basically
blissful horizon
sooo...
wintry harbor
Obviously there's the straight vertical one down the middle as well but there are no points to specify that
blissful horizon
so im still confused?
wintry harbor
sooo...
@blissful horizon So it needs to be a line of symmetry of both the hexagon and the square
blissful horizon
ok then...
wintry harbor
The square only has 4, you only need to consider 2 because of rotational symmetry but ignore that if you didn't understand
wintry harbor
Yes but those won't all be lines of symmetry of the square
blissful horizon
oh so what if it was of the square
wintry harbor
It needs to be for both
blissful horizon
any of the perpendicular bisectors of the sides of the square
wintry harbor
Yes
And you find FG satisfies that
Also consider the diagonals
Then you find KH is also a line of symmetry
And you find FG satisfies that
@wintry harbor Not FG, perpendicular bisector of FG
blissful horizon
ok thanks
wintry harbor
XD
coral kettle
Can someone help me out on questions 18-29
umm is there anyone that can help with it?? <@&286206848099549185>
humble pulsar
If the line between the midpoints of the 2 sides is parallel to the other side, then it's half the length iirc
coral kettle
so if 16 is parallel to x then x would be 8?
humble pulsar
for 18, yes
coral kettle
wait for 19 would AC be 8 then?
coral kettle
whats that
blissful horizon
its homework
cosmic pebbleBOT
winter smelt
I apologize
blissful horizon
ΔDEF rotates 90° clockwise about point A to create ΔD 'E 'F. Therefore, which equation must be true?
<@&286206848099549185>
which of these?
help please
winter smelt
Rotation is a type of transformation refered to a in which the shape of the original object is preserved and the angle of rotation is constanf for all the parts of the body.
Thus, when ΔDEF rotates 90° clockwise about point A to create ΔD 'E 'F.
m∠EAE ' = m∠FAF
@blissful horizon
blissful horizon
thank you
one more question I a realy strugling with it
The vertices of polygon ABCD are at A(1, 1), B(2, 3), C(3, 2), and D(2, 1). ABCD is reflected across the x-axis and translated 2 units up to form polygon A′B′C′D′. Match each vertex of polygon A′B′C′D′ to its coordinates.
what is A'B'C'D' new points?
unkempt heron
Hello
How would you go about solving these ( i know the answers but i just want to know the method)
winter smelt
The coordinates of image are A'(1,1), B'(2,-1), C'(3,0) and D'(2,1).
@blissful horizon
blissful horizon
oof I tried my best and submitted thanks anyways @winter smelt
unkempt heron
Since T is the midpoint of those segments, then QT=TS and PT=TR, which means RST and PQT are similar triangles
winter smelt
civic fiber
@unkempt heron so what would be the reason for QT = TS and PT = TR
unkempt heron
T is the midpoint of QS and PR, and thus the distance from the midpoint to one endpoint is equal to the distance from the midpoint to the other endpoint
civic fiber
is anyone else able to help me <@&286206848099549185> please
earnest echo
Where is your question?
civic fiber
earnest echo
What have you tried?
earnest echo
What is this??
Write angle symbol where you mean angles
civic fiber
"?????????
earnest echo
How do you know angle PQT=angle RST?
civic fiber
i dont know
thats what im guessing
because i dont know how to do it
you asked for what i tried thats my guess
earnest echo
Well, that's wrong
Angle PTQ=angle STR(Vertically opposite angles)
civic fiber
alright ty bro
fallow bluff
can someone help with my trig hw
humble pulsar
@fallow bluff if you post a question you're stuck with then someone can help
but no one will do your hw for you as a caveat
upper karma
Given b, h, θ, is this triangle solvable?
I think, it should be possible to find, c, with θ and h
nvm, noticed i can get all the angles pretty easily
90 + θ + C = 180, then I can find c, and then I have c, b, h and θ.
Which is more than enuf to use cosine or sine rule or something with
half ingot
does anyone have a good video on trig identities
I missed class on that chapter and can't make out anything ։(
upper karma
Maybe you can find a cheatsheet on Internet
silent plank
do you have specific examples where you're stuck?
fresh monolith
@half ingot i know a good video on youtube
half ingot
I would appreciate it if you could share it with me @fresh monolith
@silent plank I found a cheat sheet but how do I apply them to this problem
My professor goes so fast
silent plank
recognise the compound angle identity for cosine
half ingot
We do a new chapter every fime, I can't keep up
fresh monolith
ur familiar with unit circle right?
silent plank
$\cos(\frac{\pi}{15})\cos(\frac{\pi}{10}) - \sin(\frac{\pi}{15})\sin(\frac{\pi}{10})$ is in the form: \
$\cos(A)\cos(B) - \sin(A)\sin(B)$
half ingot
yes I know the unit circle
somber coyoteBOT
ramonov:
half ingot
Oh
silent plank
also try to keep your name hidden when cropping screenshots
fresh monolith
the trig identity video is just basic understanding them and using algebra to simplify them
half ingot
ramonov:
@somber coyote can this be done for without a calculator
fresh monolith
maybe this is more advanced than that?
silent plank
yes, it is intended to be done without a calculator
half ingot
Ok let me try solving again, this gave me a better perceptive
So my first thought is to convert the radians into degrees
Because I can find the exact values if I know the angle in degree mode
Is this fine?
fresh monolith
was that double angle formula @silent plank ?
silent plank
compound
silent plank
you don't need to explicitly get the numerical value
silent plank
also if you can be bothered to convert to degrees, learn the exact values for special angles/radians in radians
silent plank
bad notation
half ingot
Fair, but am I going in the right direction?
half ingot
also if you can be bothered to convert to degrees, learn the exact values for special angles/radians in radians
@silent plank ok I'll memorize this over the weekend
silent plank
the right side is the expanded form of the cos of a compound angle
fresh monolith
what tablet are you using
silent plank
$\cos(\frac{\pi}{15})\cos(\frac{\pi}{10}) - \sin(\frac{\pi}{15})\sin(\frac{\pi}{10})$ is in the form: \
$\cos(A)\cos(B) - \sin(A)\sin(B)$ \
and you should have access to a list of identities, one of which will be:
$$\cos(A + B) = \cos(A)\cos(B) - \sin(A)\sin(B)$$
somber coyoteBOT
ramonov:
half ingot
oof, I didn't have that identity in my cheat sheet
Alright I will go and watch the video
silent plank
can you show me your cheat sheet
fresh monolith
i gave u links to two youtube channels that helped me get through this stuff
silent plank
is extremely bad, none of those things are equal to each other
half ingot
i gave u links to two youtube channels that helped me get through this stuff
@fresh monolith thank you so much man
fresh monolith
no problem u cn also look up double angle compound angles on youtube
simplifying trig identities etc
half ingot
yeah I usually don't know what to search on youtube 😭
If I know what I need I can get by
fresh monolith
usually just look up the chapter section you are on
silent plank
if you insist, you could write:
$$\blue{\cos} \br{\frac{\pi}{3} \cdot \frac{180 \red{\deg}}{\pi} } = \blue{\cos}(60\deg) = \frac12$$
somber coyoteBOT
ramonov:
fresh monolith
this is converting between radians and degrees right?
fresh monolith
its been a few months since looking at this stuff
silent plank
and the degree symbol when multiplying by 180°/pi
half ingot
Man I was doing okay but a war broke out in my country
and I haven't been able to focus or learn anything during class
I'm gonna watch all the videos and try doing the homework again
fresh monolith
armenia?
half ingot
yeah, I already lost a cousin and I have two best friends in the front line, I haven't had sleep for weeks
fresh monolith
wow
half ingot
yep
fresh monolith
or isn't it azerbaijan and turkey is providing them support also?
half ingot
Armenia vs Azerbaijan supported by Turkey
And no one is supporting us
ok maybe we should go to the offttopic
silent plank
where did you get stuck?
silent plank
how much trig have you learned so far?
upper karma
They used the formula for perpendicular distance of point from a straight line
This one
where ax + by + c=0 is the equation of given line and (x0 , y0) is the point
Whose distance is to be calculated from the line
signal hemlock
given 3 corners in a parallellogram (1,0) (4,2) (2,-1) i need to find the 4th corner,, first i got (5,1, then (1,5) then (-3,-3) and lastly (3,3) (which was the right one) how do i make sure i get the right one without fucking around with the corner positions?
humble pulsar
plot the points firstly
signal hemlock
im not allowed to plot
only allowed to use vectors
if i draw it its really easy to solve
storm harness
;-; i m in wrong server i m in class 10 where shall i uplaod my problems
humble pulsar
@storm harness the pre-university section is for high school
so you're fine to ask questions
signal hemlock
@humble pulsar
humble pulsar
if it's vectors then pairs of sides need to be parallel, and diagonals are perpendicular iirc
humble pulsar
well if you plot the points, you can see what vectors need to be parallel
storm harness
Trigonometry(Height and distance)
Question...
The lower window of a house is at a height of 2m above the ground and its upper window is 4m vertically above the lower window. At a certain instant, the angle of elevation of the balloon from these windows is observed to be 60• and 30• respectively. Find the height of balloon
I dont have any idea to solve this plz help
wintry fog
earnest echo
Hint: corresponding angles
signal hemlock
Im give the equation of a line and the point where the line intersects the plane parallell to the planes normal vector
and i need to find the equation of the plane
humble pulsar
If the line is parallel to the plane's normal vector, then the direction vector of the line is the same as the normal vector of the plane
signal hemlock
yeah
humble pulsar
so what's the problem?
humble pulsar
yeah
signal hemlock
and i should have the equation
humble pulsar
yeah
Normal equation of planes: n.x=n.p for the normal vector n, co-ordinate vector x, point vector p
delicate laurel
the order of translation and reflection shouldn't matter right?
like if i were to reflect and translate a triangle
I should end up with the same if I perform a translation first then a reflection
as if I were to reflect then translate
silk patio
Why wouldn’t it matter
mighty egret
Hey
Guys
I need help
I was absent yesterday and I don't know how to do side angle side
silent rover
@delicate laurel the triangles end up at different positions, so the sequence does matter! on a side note, unless the question specifies the order of the transformations, always do Dilation, then Reflection, then Translation (DRT). at least that’s what i’ve been told at school, not sure if it’s the same for your curriculum :)
@mighty egret is that triangle congruency ?
final isle
Need Help With Two Column Proofs
mighty egret
Yes thx
final isle
@silent rover can you please help me?
silent rover
@final isle im really bad at proofs tho :(
limpid basin
what other equalities can you derive from the given statements?
also please dont post the same question in several channels
upper karma
PTQ and STR are vertical angles, the length of the collinear of T to SR is the same as T to PQ
@civic fiber too late?
pseudo pumice
So adjacent angles change with opposite angles based on where the given angle is in right triangle or are they always defined in one spot
dark sparrow
,rccw
somber coyoteBOT
dark sparrow
consider: $\overrightarrow{OB} = \overrightarrow{OA} + \overrightarrow{OC}$
somber coyoteBOT
Ann:
upper karma
So like you have 3 different vectors, so you have to find a way to express all of the 3 vectors on a single one
quick shale
silent plank
if you aren't able to justify it with a simple 1 line explanation, you shouldn't make the assumption.
upper karma
nyk0 they're all true
do you know what they're asking you for
like what all the symbols mean
@upper karma
dark sparrow
are they all true?
inland canyon
alright guys
so
ive been
basically winging math
since like 7th grade lmao ]
and i could learn everything else somewhere else
but im not understanding trig at all
so
in ABC the measure of c=90. the measure of a=57, and ca=2.6 feet. find the length of bc to the nearest tenth of a foot
this makes no fucking sense to me
at all
i think this is trig
maybe
ik were like breaking into it
oh wait itis trig
jeez i just filled chat
silent rover
in ABC the measure of c=90. the measure of a=57, and ca=2.6 feet. find the length of bc to the nearest tenth of a foot
@inland canyon c=90 and a=57, these two are the angles at vertex c and a respectively right?
@cinder nacelle lol what’d you sent ?
silent rover
i’m in bed and i’m too lazy to get up and do the working out, so i’ll try to explain it over text, is that okay ?
cinder nacelle
Sure
cinder nacelle
Yes
silent rover
yes, later. because you don’t have the value of CPD yet
do you know how to find CPD?
silent rover
to find the value of x, you need 3x+58 to equal to something, so you can solve for x. rn it’s just an expression, so u can’t solve for x
look at DPC
and the given angles
hint: it’s one angle take away another angle
do you know which angles?
cinder nacelle
Idk what to do now
silent rover
remember how i said you can’t solve for x if it doesn’t equal to something and it’s just an expression, can you find something that’s equal to 3x-25 and let it equal to that?
cinder nacelle
X+29?
silent rover
yup, because APB = DPC (given)
silent rover
yup
cinder nacelle
So x=27
silent rover
yup
cinder nacelle
And now I just plug in
silent rover
yes
cinder nacelle
@silent rover so 162?
silent rover
@cinder nacelle did you plug it into BPD?
silent rover
yup i got the same
silent rover
you can either do APB + BPC + CPD or APB + BPD
@cinder nacelle you can always look at the solutions, but diagrams are not drawn to scale most of the time, so you can’t look at the diagram and approximate the angle. there are formulas(cos rule and sin rule) you can use to check if the angles are right, but that’s if the lengths of the lines are given. other than that, the only way is to plug x into APB and DPC and see if they equal to each other like what the statement says, if they do, it means you have solved for x correctly.
i realised DPC is not directly given, and DPC = BPD- BPC, therefore you should plug x into that and APB, and see if the values are the same
silent rover
because an expression for DPC is not given
the only thing said about DPC in the question is that it equals to APB
but you can’t solve APB = APB right? cuz you’re gonna get 0=0 for your answer, which tells you nothing
@torpid thorn have you tried plotting H onto a cartesian plane? or visualising where it would be on the graph?
@torpid thorn there’s a quicker way
7 units right moves the graph in the positive direction of x
there for -3+7 will be the new x coordinate
6 units up moves the graph in the positive y direction
therefore -4+6 will be the new y coordinate
yes it is
it’s 4, not -4
i did not
that’s for y
(-3+7, -4+6)
^that should be the answer for the new coordinate
that’s good :) it always make more sense if you graph it, especially if you’re just learning transformations :)
silent rover
@inland canyon have you leanrt about sin, cos, tan
inland canyon
ik like
lunar sand
did i do this correctly
inland canyon
sin = the opposite side of the angle and the hypotenuse
cosine = the adjacent side of the angle and the hypotenuse
tangent = the side opposite to the angle and the side adjacent to the angle
silent rover
@lunar sand it should be 1/((root 3)* i)
lunar sand
ah
silent rover
as in, 1 should be on top of what u got
do you need to have a rational denominator? i.e. the denominator cant be a surd
@inland canyon thats right
SOH CAH TOA
lunar sand
teacher just told me to solve it, so anything goes ig
inland canyon
ye
thats what that shit is called
like
in the video
she showed how to get an angle
thats it
silent rover
but rather than 'and', it should be over, as in sin(x) = O/H, cos(x) = A/H, tan(x) = O/A
inland canyon
i knew that bit was just like
silent rover
did the video show u this?
inland canyon
like the example is like "in the figure below find the value of c, round your answer to the nearest tenth"
so its showing how to get the hypotenuse
silent rover
do you know what rule u should use for the question?
silent rover
yours
inland canyon
nope
silent rover
the one that u sent
inland canyon
no idea at all
i just now i gotta find the length
but idk how to find that length
lunar sand
sorry, just another quick question, whats the differnce between these 2
or is it the same thing
inland canyon
the i is in the square root
inland canyon
oh lmao
silent rover
@lunar sand the top one is 5 x root 3 i
the bottom one is root 3 i to the power of 1/5
silent rover
@inland canyon so you're trying to find BC, do you know if BC is represented by O(opposite), A(adjacent) or H(hypotenuse)
@lunar sand yup
silent rover
yup
inland canyon
but dont 2 rules work with opposite?
silent rover
so from the three formulas, the one that doesnt have O needs to go, because u cant find O
yup
inland canyon
the one with o??
silent rover
so from the remaining two rules, which is sin and tan, one has H and one has A
silent rover
yes lol, cant be bothered typing opposite, adjacent
inland canyon
ok so
the side im looking for
is opposite to the angle
so we get rid of the rules that deal with opposite?
silent rover
nono
inland canyon
ok i didnt think so
silent rover
u get rid of the rules that doesnt deal with opposite
inland canyon
thats why i was confused
silent rover
because then, u cant find opposite
inland canyon
oh oh oh so we get rid of cos?
silent rover
yup
inland canyon
ok go back to what u where saying
silent rover
ahh yessir
the remaining two rules, one deals with H and the other one deals with A
both deals with O
silent rover
yes
silent rover
yes
silent rover
what other information can u get from the diagram? hint: the length of one side is given, what side is that?
inland canyon
no idea
wait
would it be
adjacent
to the angle
so i would use the tangent formula thingy
inland canyon
alright
and i do that like
57/2.6
i feel like thats really wrong
jiaineedmorehelplol
silent rover
ahahaha it is lol but it’s okay i gotchu
inland canyon
ye man im honestly horrible at math sorry about that
inland canyon
so wouldnt that be like x / 2.6
silent rover
u said you were winging it all throughout school but you pick things up quick i didn’t even have to do that much explaination and u already understand it
you’ll need your calculator for this btw
inland canyon
im a quick learner i just dont like learning to much about certain things
ight
can i use like the standard windows 10 computer
calculator
silent rover
you’ll need one where u can calculate angles
x is the angle given in the question, x=57
inland canyon
idk if windows 10 calculator can do that or not
silent rover
windows 10 calculator looks kinda cute ngl
inland canyon
i dont think this is what im looking for is it
im looking for a layout that says like
tan and stuff
silent rover
now you have the value of tan(x) and you know the value of A, do you know how to solve for O?
silent rover
just the last line is relevant
silent rover
try standard?
silent rover
tan 57 = O / 2.6
if you transpose it to make O the subject, it would be tan (57) x 2.6
inland canyon
arnt we talking about o anyway
heres the image again
were talking about the opposite of 57
like side
silent rover
oh shit i must have been confusing u when i said tan(x)
inland canyon
was x just a varible right'
like could be anything
in my situation wouldnt it be 57
silent rover
but since in this question they already have x as the side, so you’re probably confused when i said tan(x)
ye ok
inland canyon
so once i have tan 57
i would divide by the opposite???
that doesnt sound right
u said tan 57 = opposite / 2.6
inland canyon
uhhh
2x2 ?
wait a min would it be 5.2
because like
wait no
im thinking like
30-60-90 triangle
so is 2x2 right tho lmao
silent rover
wait wait
^that wasn’t a triangle question
just a normal algebra question that asks u to solve for y
y would be 5 x 2
inland canyon
ohlol
inland canyon
oh ight i get that
so like
lemme reask rq
u said tan 57 = opposite / 2.6?
correct
silent rover
yes
silent rover
no
inland canyon
bruhwhatthefuck
so how the fuck do i get the opposite cuz thats what im trying to get
inland canyon
k ind a
silent rover
opposite is tan 57 multilplied by 2.6
inland canyon
ohlol
silent rover
but do you get why it’s that ?
silent rover
yes that
inland canyon
honestly i dont need to know why i just need to know how 😔
ok
lemme like
do that rq tho
silent rover
u need to know basic algebra for a lot of these questions
silent rover
my calculator is dead, can u show me what u got on the calc?
inland canyon
the purple is just cuz like
i have my windows 10 set to purple and i highlighed it
silent rover
@inland canyon yup
inland canyon
this is like the first time ive actually kinda understood something math related since the 7th grade lmao
inland canyon
can we try 1 more since like
i kinda understand what todo now
or like are u busy atm
silent rover
but dude pls understand the multiply both sides thingy lol
inland canyon
lol
trim sand
@silent rover can u help me?
silent rover
u can try it and show me your working out? just @polar rose if you’re stuck
trim sand
inland canyon
ok
i did the next problem
andit was the same kinda thing
so it only took me like
5 seconds todo
but i got it right
silent rover
@inland canyon PROUD OF YA
@trim sand wait i’ll see if i can remember anything about locus
trim sand
@silent rover ok
This is the solution if it helps
If u can explain what concept they are using
silent rover
@trim sand i did this for like 1 term last year and honestly i haven’t used it since, cant help sorry :(
r u a med student lol
silent rover
wait no i was asking if you’re a med student ahaha
trim sand
That emoji sucks