#geometry-and-trigonometry

1 messages · Page 125 of 1

spiral lodge
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And similarly sine is positive on 1st and 2nd

slim plinth
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Or ATCS

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All positive, tan positive, cos positive, sin positive

spiral lodge
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Yeah sure

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I don't like that but sure, it works

slim plinth
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What are some tips on trying to locate trig functions

spiral lodge
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Like what?

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Wdym with locate trig functions?

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Locating a function has no meaning 🤔

slim plinth
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Like this example

spiral lodge
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Radius and hypothenuse refer to lengths, hence they can't be negative indeed

spiral lodge
slim plinth
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Like this

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Is there tips on how to memorize these

spiral lodge
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Ohh I see

slim plinth
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Like I’m confused which quadrants are they in

spiral lodge
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Honestly I don't know which triangle they are talking about

slim plinth
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On the unit circle

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Xy graph

spiral lodge
slim plinth
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3rd

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Oh btw their coordinates are (cos(theta), sin(theta))

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1: (+,+), 2:(-,+), 3:(-,-), 4:(+,-)

spiral lodge
spiral lodge
slim plinth
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cos is negative, sin is positive

spiral lodge
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Huh?

slim plinth
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Csc, sec, cot

spiral lodge
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The reciprocal of a negative is negative and the reciprocal of a positive is positive

slim plinth
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Will it still imply the rule

slim plinth
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I do

spiral lodge
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Then what's the issue? Sorry I'm not getting you

slim plinth
spiral lodge
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What is it?

slim plinth
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Like on xy table

spiral lodge
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I really don't understand what you're talking about

spiral lodge
slim plinth
spiral lodge
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(cosθ, sinθ) is not at all equal to (secθ, cscθ)

slim plinth
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What will it equal to

slim plinth
spiral lodge
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Sure

slim plinth
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Over one

spiral lodge
slim plinth
spiral lodge
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I guess so

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I mean, it is much more common to be confused in trigonometry than in, let's say, log and exp

slim plinth
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Ik that

spiral lodge
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At least form my experience here and in my real life

slim plinth
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And got 100 and master it

spiral lodge
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On the other hand, I personally was way more confused in probability and combinatorics than in trigonometry, but I believe it depends a lot on the person itself and especially on how the teacher explains the topic

slim plinth
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Now what happens if I want to see which quadrant are sinθ=.5 and cosθ=-4.1 in

spiral lodge
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In none 😬

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Or you meant secθ = -4.1?

slim plinth
shrewd obsidian
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I love math

glacial pelican
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can somebody help me

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im cooked

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@everyone

shrewd obsidian
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Why

glacial pelican
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dms

tidal anvil
dry cave
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Prove that sum of 2 sides of a triangle is larger than half the median PLS HELP

opal raptor
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Suppose that half the median is larger than the sum of 2 sides of a triangle

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Do the working until it contradicts?

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Hmm

dry cave
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oh lemmetry

opal raptor
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Oh btw does it specify what median?

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Or just any old median?

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@dry cave

opal raptor
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Ah kk

half totem
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ok time to derive half tan identity
tan(2x)=2tan(x)/(1-tan^2(x))
=> tan(2x)(1-tan^2(x))-2tan(x)=0
=> -tan(2x)tan^2(x)-2tan(x)+tan(2x)=0
i dont like negative coefficient so
tan(2x)tan^2(x)+2tan(x)-tan(2x)=0
tan(x)=(-2 +/- sqrt(2^2-4(tan(2x))(-tan(2x)) ) / (2tan(2x))
= ( -2 +/- sqrt(4+4tan^2(2x)) ) / (2tan(2x))
= ( -2 +/- 2sqrt(1+tan^2(2x)) ) / (2tan(2x))
= ( -1 +/- sqrt(1+tan^2(2x)) )/tan(2x)
=(-1 +/- sqrt(sec^2(2x)) )/tan(2x)
now since theres a +/- i think the absolute value isnt necessary
= ( -1 +/- sec(2x) )/tan(2x)
=-cot(2x) +/- csc(2x)
so im assuming youre supposed to use the positive root maybe?
so
csc(2x)-cot(2x)=tan(x)
therefore
tan(x/2)=csc(x)-cot(x)

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why is there a frowny face

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ok anyway lets check now

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YESS

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i wonder why it cant be the second root though

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ok now cot(x/2)=1/(csc(x)-cot(x))=(csc(x)+cot(x))/(csc^2(x)-cot^2(x))=csc(x)+cot(x)
so cot(x/2)=csc(x)+cot(x)

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wait a second if theres a half angle identity does that mean theres a one third angle identity

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(cosx+isinx)^3=cos^3(x)+3icos^2(x)sin(x)-3cos(x)sin^2(x)-isin^3(x)
=> sin(3x)=3cos^2(x)sin(x)-sin^3(x)=3sin(x)-3sin^3(x)-sin^3(x)=3sin(x)-4sin^3(x)
=>4sin^3(x)-3sin(x)+sin(3x)=0

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cardanos formula would be perfect but damn it i havent learnt it yet

dry cave
royal citrus
#
\text{ If two tangential lines TP (t being the point of intersection} \\
\text{ between x-axis and the line)} \\
\text{ and LQ (l being the point of intersection between x-axis and the line) of} \\
\text{ a circle make points P and Q such that PQ is an arc, and TP makes an} \\
\text{ angle of $\psi$ and LQ makes an angle of $\psi + \triangle \psi$. Here, angle } \\ 
\text{TPL would be $\triangle \psi$. If we make enough lines, then a Kite would } \\
\text{ be formed with unequal angles x and $180 - \Delta \psi$. If someone could} \\
\text{ please explain how x would = $\Delta \psi$, it'd be huge.} 
somber coyoteBOT
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inheritance.

tidal anvil
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omggg

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wattt??

crimson wasp
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what are those

hexed plank
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Idk it was nothing in it

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Are they safe

fervent depot
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Why is 3 square root 8 not the answer?

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*the final answer i should say?

cunning lion
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presumably because they want you to pull all perfect squares out

glacial pelican
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can anyone help

lime crownBOT
# glacial pelican can anyone help

Asking the actual question right away is more likely to get responses.

Asking "Can I ask...?" or "Does anyone know about...?" doesn't give people enough information to decide whether they can help, and answering can feel like a promise to help with the actual question, which they might find themselves unable to.

glacial pelican
sharp girder
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so instead of 3√8 its (3*2)√2

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so 6√2

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and approx 6√2 via Newton's method (A friend taught me)

cunning lion
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pretty sure they are asking just for the radical and not a decimal

fervent depot
sharp girder
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Or you could ust use a calc and understand, somehow

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Yeah, so i in Algebra II, we learned about the 6 (We learned about really 9) of the trig functions. What are all of them???

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I know of:
sin(
cos
tan
asin
acos
atan
sec
csc
cot
sinh
cosh
tanh
sech
csch
coth
asinh
acosh
atanh

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and exsec
excsc
versin
haversin
and chord

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what are the others??

fervent depot
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alr bro ima add u

sharp girder
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dude, im in like 8 servers

fervent depot
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nah like as a dm

glacial pelican
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@everyone

sharp girder
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@glacial pelican

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so, my pfp has a unit circle with tan, cot, etc. on it

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I just don't understand their relationships

limber dagger
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can i have some help with this??

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im a bit confused on what exactly to do

rough bronze
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this is a 45-45-90 triangle

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if each side is x, the hypotenuse should be x sqrt 2

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that means 100 = x sqrt 2, if you can solve for x, you've got the answer

sharp girder
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50

limber dagger
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Yes….

sharp girder
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so the answer is 50 sqrt 2 as
45-45-90 triangles use

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x to x to x sqrt 2

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as the ratio of their sides

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Trig question!
(Trivia)

rough bronze
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it's like 55.99 or something right

sharp girder
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Ill check

limber dagger
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I may need

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Simpler terms

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I have the flu rn so my head is spinning

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What is 45-45-90

sharp girder
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so 180-90

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-45

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= 45

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so the 3 angles are 45, 45, 90

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the name is 45-45-90 triangles

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this is one of the special right triangles

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so it maintains a consistent side-to-side-to-side ratio

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which is:

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x to x to x * sqrt 2

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given that the hypotenuse (longest side) is the x*sqrt 2 side

limber dagger
rough bronze
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must really like trig

ornate rampart
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wowzers I could actually learn using ths

rough bronze
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also everything connects to the unit circle which is also not fun

marsh stratus
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I have to turn stuff like (1+cos(x))(csc(x)-cot(x)) into one trig function or constants like sin(x) for this specific problem

shut thorn
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fire

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why does the

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The question looks so familiar. I don't think it's in my book?

ornate rampart
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so im probably fine for a few months

shut thorn
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The hell could something like sin^(-1)(B) mean. Will it be the same as 1/sinB?

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Got curious about trigonometric functions and wanted to put a negative power on one of them

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Because like. Sin^2(B) => (sinB)² so shouldnt it be the same with sin^-1(B)?

cunning lion
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the notation is not consistent

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the exponent in sin^2 refers to multiplication, whereas the exponent in sin^(-1) refers to function composition

shut thorn
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or is that even real

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at all

cunning lion
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that is unclear notation

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and should not be used

cunning lion
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calling $f^2 = f \circ f$ and so on

somber coyoteBOT
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cloud ☁

gray blade
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whts f o f

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ima watch

shut thorn
cunning lion
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yes

shut thorn
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kk 👍

wanton yacht
shut thorn
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the hell is a arc

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😭 😭

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uh huh

trim hazel
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these are trigonomertical functions made for 1/sinx, 1/cosx, 1/tgx, 1/ctgx

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for 1/sin is arcsin, 1/cos is arccos, 1/tan is arctan and 1/cot is arccot

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but you'll barely use it in school

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because in most cases you'll need a calculator, which is mostly forbidden when learning math

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and while doing an exam

trim hazel
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oh yeah, sorry

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my bad

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i totally forgot about those

nocturne breach
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1/sin is csc

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1/cos is sec

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1/tan is cot

trim hazel
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i said i made a mistake

nocturne breach
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Oh

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Mb

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Ok

trim hazel
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i didn't do trigonometry for a while

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a few years

shut thorn
violet sluice
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just different names

shut thorn
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1/sinx the inverse of sinx

violet sluice
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im talking about the function inverse

shut thorn
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oh

violet sluice
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1/sinx is called the "multiplicative inverse" of sinx

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but if you have $f(x) = y$, the inverse function $f^{-1}$ satisfies $x = f^{-1}(y)$

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you'll learn about this in algebra

somber coyoteBOT
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Altanis

shut thorn
#

kk

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still havent learnt this much about functions

violet sluice
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so for example sin(pi/2) = 1. inverse sine should take 1 and give pi/2

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i.e., it should undo what sine does

shut thorn
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oh

violet sluice
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arcsin is the function that does that

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,w arcsin(1)

shut thorn
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ok so it just gives you the radians and their measurments

violet sluice
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arcsine takes a value and tells you what angle, when you take the sine of it, gives you that value

slim plinth
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arcsin(sin(theta))=1

candid plank
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Guys I'm so confused

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How does sin^-1 work

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Or like

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Why does it work

limber dagger
# candid plank How does sin^-1 work

"(sine) calculates a ratio of triangle sides (opposite/hypotenuse) based on an angle, whereas (inverse sine or arcsin) calculates the angle based on a given side ratio. takes an angle input, while takes a ratio between and to produce an angle (usually in degrees or radians)."

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can somebody help me with this?

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im on my last try

winged oyster
lime crownBOT
shut thorn
limber dagger
shut thorn
# limber dagger not really. I've been sick with the flu all week so I don't really know what's g...

hope you get well soon.
anyways. a right triangle has some ratios between the non-right angles, these ratios are known as trigonometric ratios. the ratios for an angle theta are as follows -> sin(thetha) = opposite/hypotenuse
cos(thetha) = adjacent/hypotenuse

tan(thetha) = opposite/adjacent.
there are also sec(thetha), cosec(thetha) and cot(thetha) which are 1/cos(thetha), 1/sin(thetha) and 1/cot(thetha) respectively.
But for the question, only the highlighted ones are necessary

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let me make a diagram to explain better

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lets call it angle A for simplicity. Using the ratios for sin(thetha) and cos(thetha) above. try to find the ratio for sinA and cosA.
This similar method can be used for the question.

shut thorn
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1/2 and sqrt(3)/2 respectively

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should be enough of a hint?

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feel free to ping me if you find any difficulty.
i will try my best to clear that doubt

limber dagger
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Uhm

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Okay

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So

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So would I use tan

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Then

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I’m confused

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Like

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If I need to find X

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What am I trying to find

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It’s the hypotenuse right

limber dagger
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I was there for the introductory lesson

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That was it

shut thorn
stray isle
shut thorn
stray isle
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ratio is x, x(sqrt(3)), 2x

shut thorn
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bro.

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dont give direct answers.

stray isle
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oh mb

shut thorn
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well i aint typing all that so uh

lime crownBOT
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As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

shut thorn
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thats why

stray isle
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alr gotcha

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but the 30 60 90 triangle hint kinds gave it away

shut thorn
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nah its good enough

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ok how do i explain the core concept of trig to someone more better

shut thorn
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the hypotenuse and one of the angle is given

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which trigonometric ratios use the hypotenuse in them?

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try to use that on the 30 deg angle

limber dagger
#

Hate to break it to you

shut thorn
limber dagger
#

Okay

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So

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Do I need to apply that to this equation

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I googled it

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It says like

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A ratio

shut thorn
limber dagger
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How do I know what I’m solving for

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I don’t understand that

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If I understood which one I need to use

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Id know how to solve from there

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But I don’t

shut thorn
#

ok look uh

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solve for x first

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what will cos(30) in that question be?

limber dagger
#

What do you mean

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What is cos(30)?

shut thorn
#

if i treat 30 as A.

limber dagger
#

yes

shut thorn
#

then what will cosA be?

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if

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-> sin(thetha) = opposite/hypotenuse
cos(thetha) = adjacent/hypotenuse

limber dagger
#

0.86?

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I’m confused

shut thorn
#

which ISNT the hypotenuse

limber dagger
#

y…

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Oh no

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Wait

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It’s gotta be

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Like

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Touching right

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The side?

shut thorn
#

yes

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the side which is touching

limber dagger
#

So it’d be x

shut thorn
#

which ISNT the hypotenuse

shut thorn
#

now

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the trig ratio for cosA is adjacent/hypotenuse

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so

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what is the hypotenuse?

limber dagger
#

15

shut thorn
#

ok nice

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now what was the angle?

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measurement of the angle i meant

limber dagger
#

Angle for what?

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30?

shut thorn
#

because thats the angle we are working with right

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so that measn

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cos(30) = x/15 where adjacent and hypotenuse are x and 15 respectively

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rearraging to isolate x. we get cos(30) x 15 = x.
now cos(30) has a specific value of sqrt(3)/2

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so plugging that in and solving for x

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we will get x.
similarly. try to use the sin of the angle

nimble ridge
#

hmm what's 2x2

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i think its 5

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nah im kidding its 4

spiral lodge
acoustic sphinx
#

Hi, I made this unit circle diagram for my obsidian notes. What do you think is it clear or too complex?

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I looked at many examples in google images and tried to make something between table and radial diagram.

exotic marlin
acoustic sphinx
#

Thanks!

Maybe you can also make a diagram with all the trigonometric ratios on the unit circle ?
Can you elaborate on what you would add? I looked a bit, and notice that tan, cot, sec, csc can be also added, but I am thinking about showing them in a separate table below.

vague geode
#

hello

exotic marlin
# acoustic sphinx Thanks! > Maybe you can also make a diagram with all the trigonometric ratios o...

I would add The basic formulas of tan, cot, sec and csc in terms of sin and cos and also I don't know which visualization you watched. But I would prefer the one in which a tangent is drawn from the point (cos(theta),sin(theta)) and let it cut the x axis and y axis and the two segments separated by that point are tan and cot (that's why it's called tan!) Honestly, it looks cool and also neat, another way is to also draw a vertical tangent at the point (1,0) and let it intersect the extended radius but I don't think in that version, cot will look so aligned with tan

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In the version I suggested, all the co- ratios like co-sine, co-tangent and co-secant will sit on the complementary angle side of the theta.

limber dagger
#

Can somebody help me with this problem?

visual trench
#

Did you try using Law of Sines?

exotic yarrow
#

overkill

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,w 30-60-90 triangle

somber coyoteBOT
limber dagger
exotic yarrow
visual trench
exotic yarrow
#

it's essentially a pattern matching exercise

visual trench
#

I didn't notice it was 30-60-90

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Yeah your point makes more sense than mine

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My bad

limber dagger
#

what i do

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after i know that

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though

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like

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im a bit overwhelmed beecause i missed almost all this week of class so i know very little about whats going on

visual trench
#

In your situation s=4

silent plank
#

use a different variable

visual trench
#

yeah

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makes sense

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better now

dull venture
#

Can anyone help me with sorting triangle congruence theorem examples?

These four examples i categorized it as not enough information

dull venture
real sentinel
#

which triangles do u have to show the congruence?

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In question 1

dull venture
dull venture
#

Ok

radiant rivet
#

does anyone know how to use eulers spiral to optimise racing line

candid plank
real sentinel
burnt crystal
#

Hi! I am new here.

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Could you help out with some trigonometrical sums I have some difficulty in?

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I am in Grade 9.

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The 16th and 17th.

rustic spruce
cerulean tundra
cerulean tundra
burnt crystal
cerulean tundra
#

Where are you from?

burnt crystal
cerulean tundra
#

Wth

burnt crystal
#

Yep

cerulean tundra
#

Board?

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Icse?

burnt crystal
#

There are worse sums-

burnt crystal
cerulean tundra
#

Makes sense

burnt crystal
#

And we have 19 chapters day after tomorrow-

cerulean tundra
#

In state boards this level aint even in 10th

burnt crystal
#

Ik

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Even in CBSE

cerulean tundra
#

Yep

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I will solve it for you

burnt crystal
#

Uhh... Suppose i need help with Theorems on Area and Mensuration.

Where am I supposed to write?

summer cradle
# burnt crystal The 16th and 17th.

for 16:
cos²(45+theta)
= ½(1+cos(2(45+theta))
= ½(1+cos(90+2theta))
= ½(1-sin(2theta))
cos²(45-theta)
= ½(1+cos(2(45-theta))
= ½(1+cos(90-2theta))
= ½(1+sin(2theta))
tan(60+theta)tan(30-theta)
= (sin(60+theta)/cos(60+theta))
(sin(30-theta)/cos(30-theta))
= (2sin(60+theta)sin(30-theta))/(2cos(60+theta)cos(30-theta))
= (cos((60+theta)-(30-theta))-cos((60+theta)+(30-theta)))/(cos((60+theta)-(30-theta))+cos((60+theta)+(30-theta)))
= (cos(30+2theta)-cos(90))/(cos(30+2theta)+cos(90))
= (cos(30+2theta)-0)/(cos(30+2theta)+0)
= cos(30+2theta)/cos(30+2theta)
= 1
so the denominator evaluates to 1 thus we now only need to care about the numerator
cos²(45+theta)+cos²(45-theta)
= ½(1-sin(2theta))+½(1+sin(2theta))
= ½(1-sin(2theta)+1+sin(2theta))
= ½ • 2
= 1

summer cradle
#

you're welcome

rustic spruce
#

Even though im also icse I never had these

olive dagger
burnt crystal
cerulean tundra
burnt crystal
#

thanks i got it

cerulean tundra
slim plinth
#

The SAT identity is this

cerulean tundra
slim plinth
#

For trig

slim plinth
#

For the SAT

cerulean tundra
#

Oh

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I remember all

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By a trick

slim plinth
#

I’m just did that

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Just by drawing triangle

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And subtract by 0,90,180, or 360

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To get to 30-60-90 or 45-45-90

cerulean tundra
#

Nah I remember it by even and odd multiple of 90 and for sign conventions take help from STSC rule

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If it's odd then the function will turn into the opposite one
If even it will remain same

minor heron
#

i just remember bcs the sine and cosine functions are pi/2 from each other

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tho i haven't taken the sat yet igs so idk how important most identities are

burnt crystal
#

sorry i forgot to mention it-

cerulean tundra
# burnt crystal The 16th and 17th.

Q17:
There are many methods by which I solved but I'd go with easier.
B) tan(2A)= cot(A-18)

WE CAN USE THE IDENTITY tan(90-A)=CotA
=> tan(90-(A-18)
=> tan (108-A)
Now, tan(2A)=tan (108-A)
2A= 108 - A
3A= 108
A= 36

C)Sec(2A) = Cosec(A-27l

Cosec(90-2A)= Cosec( A- 27)
90-2A= A -27
117= 3A
A=39

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Eww it's soo hard to type

lime crownBOT
cerulean tundra
burnt crystal
#

thanks i appreciate it

#

and...my earlier question. where do i ask if i want help in Theorems on area and Rectilinear figures?

burnt crystal
#

ok thanks

#

its a lil confusing-

cerulean tundra
#

But it's better if you ask about the method or idea

cerulean tundra
burnt crystal
#

yeah yeah'

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that only

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im capable of finding the answer

#

some sums are a lil tricky

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a sum of money placed at compound interest doubles itself in 5 years. It will amount to 8 times in -------- years.

how to find this out-😭
what sums are these😭

burnt crystal
minor heron
#

and, you want it to be equal to 8a in some x amount of years

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so divide out the a. does that make sense? i think thats what the probem is asking... if it is what the problem is asking i think you can figure it out from here

burnt crystal
#

So.... 15?

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Im getting that-

dull venture
#

Can someone help me identify which examples arent in their right category

minor heron
burnt crystal
burnt crystal
# dull venture

One angle and side are given... But the other is not.
So
Ig this is ASA

#

I am not sure tho

burnt crystal
#

The first one

burnt crystal
dull venture
burnt crystal
dull venture
#

I’ll recheck the first one

burnt crystal
#

Yes
It is the first one in SSS

dull venture
#

This is what i got from it

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It tels us UX And VW are congruent

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Y is midpoint of UW and VX so those two sides bisect

burnt crystal
#

Hmm..
Its confusing

#

All of them seem to be correct-

#

I have to do this ig

#

Can u wait?

dull venture
#

Yes

#

You might wanna check AAS first

#

It has 7 examples which is odd

minor heron
#

is there a wrong one in all categories all the sss one look right to me

burnt crystal
#

I am currently doing a sample, so i may not reply so quickly

burnt crystal
#

I thought it was the first one as per the instructions but it cant be-

burnt crystal
burnt crystal
#

Wait

burnt crystal
#

May I ask, which standard is this?

dull venture
burnt crystal
#

Which grade?

dull venture
#

10th

burnt crystal
#

Ohh ok ok

#

It is bound to be confusing then.

minor heron
#

is ssa instead of aas?

dull venture
#

SSA is not a congruence theorem

minor heron
#

OH wait

#

mbmb

dull venture
#

This is what i got

#

Also the arrows mean parallel lines

minor heron
#

nvm oops (srry i haven't done ts in a while)

dull venture
#

It’s fine this stuff is weird

minor heron
#

yeah lol

burnt crystal
#

I am doing a maths sample

I may have to ask questions too-

Its a little confusing

minor heron
#

like... a practice test, or something?

burnt crystal
#

Yes

#

Its my school's previous year paper
I am practicing those

minor heron
burnt crystal
#

i am ninth

burnt crystal
#

the question is

#

if x=7-4root3, find the value of root x + 1/root x

minor heron
#

or is 1 not under the root

burnt crystal
#

1 is not under the root
and wait im sending

#

root x + (1/root x)

minor heron
#

oh

#

like this?

burnt crystal
#

yea

minor heron
#

...so, try to express it as a square of an expression

#

then, you can easily write it and square root it to that expression...

#

make sense?

minor heron
burnt crystal
#

i...did not understand

#

welp-

minor heron
#

Like ah

burnt crystal
minor heron
#

think about it like

#

(a-b)^2

burnt crystal
#

yeah?

minor heron
#

how can you make x into that form

burnt crystal
#

.....

minor heron
#

the expanded form is a^2+b^2-2ab, so lets say 2ab is 4sqrt3

#

and a^2+b^2 would be the 7... so how could you simplify it

burnt crystal
#

ohhh...

#

im getting it

#

but then- its root-

stone carbon
#

hi there.

minor heron
#

if you have x as (a-b)^2 form

#

then sqrt x would be a-b

burnt crystal
burnt crystal
minor heron
#

so what would a-b be hmm

burnt crystal
#

OHHH....

#

THANKS

stone carbon
minor heron
#

yupppp

burnt crystal
#

I GET IT

#

I FINALLY GET IT

minor heron
#

after you plug it in its just one more "big" step (to simplify 1/sqrtx) and it should come out as a nice clean number

burnt crystal
#

I FEEL LIKE EINSTEIN-

stone carbon
#

you guys look like a couple of Einstein brains.

minor heron
#

yayyy

burnt crystal
#

thanks evelyn!

minor heron
#

phew i wasn't sure what grade you were so i was hoping i wasn't overcomplicating it lmao

minor heron
#

yey xd glgl with the rest of the.. sample

burnt crystal
burnt crystal
stone carbon
#

may i share my question.. uh eeveekawaii?

burnt crystal
#

ok

burnt crystal
#

me will try to solve-

stone carbon
#

yay!

minor heron
#

me will try to solve too~

stone carbon
burnt crystal
#

CIRCLES!

stone carbon
#

Angle BAC=90° btw.

minor heron
#

alr

burnt crystal
#

radius not given right?

minor heron
#

so to clarify, between o and c is 5, c and f is 4? and is that other value up there...8?

stone carbon
burnt crystal
stone carbon
#

OC=5, CF=4.

burnt crystal
#

wait..its mot in the middle tho

#

not

minor heron
#

is o the center

stone carbon
#

original question is this, if you wanna take a glance.

burnt crystal
#

ah thanks\

minor heron
#

oh, so i guess o is the center

stone carbon
#

yup.

burnt crystal
#

hey wait-

#

this q doesnt make sense-

minor heron
#

ummm im pretty sure its 5.6 but im not sure

#

gtg eat tho

stone carbon
#

bon aphetit!

burnt crystal
stone carbon
dull venture
#

@burnt crystal @minor heron

burnt crystal
#

Yeah?

dull venture
#

Heres the forum for my question btw

#

I explained pretty much every example

#

So if you find something wrong you can tell me

burnt crystal
#

Thanks

minor heron
#

lemme re-look

stone carbon
burnt crystal
#

Guys i have my maths exam tmrw and im freaking out

minor heron
#

hmm ah this problem might be a bit… above my level 😅

burnt crystal
#

19 chapters.... 19 CHAPTERS😭

minor heron
burnt crystal
minor heron
#

what are the chapters focused on

burnt crystal
#

EVERYTHING

#

WHAT IS NOT THERE?

#

Ok imma sleep now
Its 4:25 am
My parents will kill me
Gn

minor heron
#

oh glgl

#

😭

potent hollow
#

Anyone know a good source of practice question for high school vectors? (scalar/vector proj. dot product, parallel perpendicular components, relative vectors, applications) stuff like that

burnt crystal
#

One is AoPS

#

Khan Academy

#

R. D. SHARMA MATHEMATICS CLASS 11

#

OR

minor heron
#

mmhm khan academy was my goat in the past

#

had to be a bit picky thru lessons to find what i wanted but yeah

burnt crystal
#

NCERT MATHS TEXTBOOK OF CLASS 11

minor heron
#

tho it doesn't go the most in depth iirc

#

haven't learned some of the stuff u listed so not sure if that'l cover, but i guess just look around

burnt crystal
#

@stone carbon

Heyy a friend helped me to do ur sum
Here

#

Gn guys

potent hollow
real sentinel
stone carbon
#

seriously?

blissful pivot
#

ay joseph is here

#

i was literally here to post one of ur problem

blissful pivot
stone carbon
blissful pivot
#

please speed i need this

dull venture
devout summit
#

Does this cover college mathematics?

#

If so, I did not take additional mathematics in school and I am currently spending 3 hours on an addmath homework. Is there any channel to ask questions?

viral obsidian
#

Help me explain proof for volume of sphere

bright crater
#

slice a sphere horizontally into slices

#

each slice approximates a cylinder

#

calculate volume of cylinder and then take integral

dull venture
#

Are all of these ASA?

mellow epoch
#

no way

#

at least i think they're not

dull venture
spiral lodge
dull venture
#

Can you help me with AAS?

quasi remnant
patent crane
#

looking for team mate to study geometry (i am russian but small speak eglish)

dull venture
quasi remnant
#

Ok

dull venture
quasi remnant
#

Sure

dull venture
#

I put this in HL but i switched it to SAS recently

patent crane
#

looking for bro to study geometry together ( i am russian)

cerulean tundra
#

I am in

distant geyser
#

I am also in Geometry

minor heron
royal bluff
#

Hello! I am trying to help my friend on inscribed angles, is there anywhere where I could find some practice problems

rough bronze
#

i love aops for practice problems too

fathom helm
#

@exotic yarrow how often do u deliver mails

shrewd osprey
#

Am I wrong on this one?

silent plank
#

20/360 isn't 18

mild salmon
#

Does anyone know how to solve theses sort of questions?

shrewd osprey
#

Oh

mild salmon
#

huh

spiral lodge
exotic yarrow
#

But please don’t ping me unless you have a comment with actual substance

exotic yarrow
#

please don’t ping me unless you have a question or smt that’s not already answered by what I sent

burnt crystal
#

well...my maths exam was today.
THE PAPER WAS HELL-
LIKE
SOME THEM ARE NOT EVEN IN OUR BOOK-

burnt crystal
#

if yall want i can share the qp-

#

do yall want it?

icy hamlet
#

I want it

burnt crystal
#

wait

dull violet
#

Can someone help me solve this i have a test in 2 hours

#

How do you know which angle you’re supposed to find

coarse lance
#

i'm not good at geometry, and this problem that I need to solve has come up.

Say the blue arch represents the path of a ball, the ball bouncing around this circle forever. How do I figure out which way the ball should bounce/reflect off the circle?

dull violet
#

THANK YOU SOOO MUCH

#

Omg

#

Youre a lifesaver

#

No literally

karmic hamlet
#

theres this one problem I have where its a 30-60-90 triangle with the shortest side being x-1 and the middle side being x, when I solve for x I get x=1 which would make the shortest side 0, how would I solve this

karmic hamlet
#

about to send

#

crude recreation

#

i couldnt find the original sheet

potent hollow
#

Oh i see

#

The middle angle has the middle length send

#

And the hypotenuse is the longest

#

Oh waitp💀

#

I cant read

#

That kinda feels like giving the answer

surreal iron
#

yeah fairs

#

Think about tan

karmic hamlet
#

ok

#

would x = (3+sqrt(3))/2

foggy heron
potent hollow
foggy heron
#

kk, thank you!

weak hatch
#

Hey guys, please I need help on the question:

"Four angles of a pentagon are equal and the fifth is 60°. Find the equal angles and show that two sides of the pentagon are parallel."

How is it possible that 2 sides would be parallel?

rough bronze
#

you solve for internal angles to find the 4 congruent angles then use alternate interior to prove that the 2 sides shown are parallel

weak hatch
marsh dune
#

How do I solve for x? b*b(x-d)=-1/b (x-1)

exotic yarrow
# marsh dune How do I solve for x? b*b(x-d)=-1/b (x-1)

This is a glorified linear equation. Using the distributive property yields
$$b^2 x-b^2 d=-\frac{1}{b}x+\frac{1}{b}$$
Now, get your terms with $x$ on one side and the terms without $x$ on the other. Then divide by the coefficient of $x$.

somber coyoteBOT
#

Civil Service Pigeon

exotic yarrow
#

Oh I forgot to say earlier

#

This is an algebra question, not a geometry question.

young elm
#

anybody have some cool / interesting 3d vector planes or complex numbers questions?

exotic yarrow
young elm
#

thank you!

somber coyoteBOT
#

Civil Service Pigeon

exotic yarrow
#

wait no this is the shit one

young elm
#

oh like too easy?

exotic yarrow
#

it's just boring

young elm
#

oh alr alr

exotic yarrow
#

I mean feel free to do it if you want

young elm
#

u got any interesting ones?

young elm
#

lwk preparing for my yr 12 vectors and complex numbers test lol

#

it's just standard vector lines and planes

#

and some supplementary links to complex numbers, simple trig and sequences/series

neat kite
#

i lwk need help w this

Given a pyramid S.ABCD where the base ABCD is a rhombus with side length a and angle ABC equal to 60 degrees. The orthogonal projection of point S onto the plane ABCD coincides with the centroid of triangle ABC. (Let H be the centroid). Let P be the angle between the line SB and the plane SCD, Calculate the sine of angle P, knowing that SB = a.

#

i dont understand the 2/3 HK part much

green yew
#

,rotate

somber coyoteBOT
spice oar
#

shouldn't H be inside the triangle ABC if its the centroid? isn't it like the intersection of its medians?

green yew
#

yeah thats what i was wondering

neat kite
#

my bad

#

I accidentally mistook D n B

shrewd osprey
#

Which one here is correct???

spice oar
shrewd osprey
#

Oh

#

Okay

green yew
shrewd osprey
#

im uh

#

pretty mentally challenged

spice oar
#

if theres addision in a square root, you need to calculate it

green yew
shrewd osprey
#

I was trying to solve for the hypotenuse but i've gone with something simpler instead

#

a^2 + b^2 = c^2

#

literally just the Pythagorean theorem

green yew
shrewd osprey
#

welp my bad

green yew
#

hypotenuse is c

shrewd osprey
#

yeah

green yew
shrewd osprey
#

okiii

green yew
warm gulch
#

wow this is amazing

#

maths server

shrewd osprey
warm gulch
surreal moth
#

I am right, rigth ?

humble granite
surreal moth
#

Thank you sir

#

Just started doing these I. Trig they go from that’s pretty easy to fuuu that

humble granite
humble granite
burnt crystal
#

We also had standard angles

surreal moth
#

Like WAY easieer.

glacial pelican
#

can anyone help

burnt crystal
burnt crystal
glacial pelican
#

pythagorean triple]

burnt crystal
#

yeah sure!

#

tell me

quiet sequoia
#

a very neat triangle I came across when messing around with geometry

nocturne breach
quiet sequoia
#

I would definitely recommend just sitting down with graph paper and messing with geometry. things like this seem to come up out of nowhere when you do that

sonic ermine
#

can anyone tell me how to know if there are one or two or non ssa triagnels

#

this is gonna be on my precal test

#

also hwo do i do angular momentum

vocal pollen
minor heron
#

lwk idk its not on my precalc test i haven't done this since last year where i used ai to help.... guide my ah

#

idk what angular momentum is so glgl with that igs

sonic ermine
quasi remnant
#

Angular momentum is the same as linear momentum but for angles

sonic ermine
#

wait how do i do this problem

#

ignore my writing

quasi remnant
#

use this

sonic ermine
#

tyty

#

i am glad i joined this server

quasi remnant
#

Np

minor heron
fleet light
#

may I have help on this?

sonic ermine
#

there should be a formula or smth right

sly slate
sonic ermine
#

howd u do it

fervent depot
#

How does line DC correspond with line BC

sly slate
# sonic ermine howd u do it

I checked once again I think I did wrong first time so i reattempted it and got 81° this time I dont know it's correct or not I solved this as shown in img I don't know weather this is the right method or not😅

sly slate
# fervent depot How does line DC correspond with line BC

Since ABC triangle and BDC triangle are similar triangle due to ASA criteria AC/BC i.e hypotenuse of triangle ABC and BCD is equal to DC upon BC i.e DC short side of triangle BDC upon BD short side of triangle ABC
Here you are getting confused because You have fixated that BC is hypotenuse of triangle BDC but you should also keep in mind that it is also short side of triangle ABC

sly slate
sinful hatch
#

`

vivid ice
#

@fleet light here is another simple solution of ur problem

vivid ice
#

by AA similarity

vivid ice
#

Can anybody give me hint for 12th one

#

nvm I got it 😀

fierce karma
#

Any ideas why this is wrong?

#

Part ii where you have to find f(x) =0 is the problem

#

Because pi/2 doesn't work

exotic yarrow
somber coyoteBOT
exotic yarrow
#

,texsp ||Note that your $\theta+\frac{\pi}{2}$ is $2x+\frac{\pi}{3}$, so it should be
$$\cos \left(2x+\frac{\pi}{3} \right)=-\sin \left(2x+\frac{\pi}{3}-\frac{\pi}{2} \right)$$||

somber coyoteBOT
#

Civil Service Pigeon

quiet sequoia
#

another geometry thing

exotic yarrow
low cosmos
#

Anyone understand the law of cosines?

lime crownBOT
# low cosmos Anyone understand the law of cosines?

Asking the actual question right away is more likely to get responses.

Asking "Can I ask...?" or "Does anyone know about...?" doesn't give people enough information to decide whether they can help, and answering can feel like a promise to help with the actual question, which they might find themselves unable to.

quasi remnant
sharp void
low cosmos
#

sharp void
#

haha sorry, what is your confusion my friend

#

we'll sort it out no problem 👍

spiral lodge
low cosmos
#

Not wrong

spiral lodge
#

But yeah it's easier if you share a problem you can't do, or a question about it

quasi remnant
#

What’s going on?

sharp void
#

math

slim plinth
#

Hey I wonder what is borrowing in trig

sonic ermine
#

my precal test went good

surreal moth
#

My math correct or I got to go back and relearn mathematical properties.

violet oasis
#

And I don't know what you're doing XD.

limber dagger
#

Hey. Can somebody help me out here? This is on the review guide. When I did it, I got 9, not -680. What have I done wrong?

limber dagger
#

cus like

#

30^2 isnt 211

#

which confused me

#

so i dont know

#

what she's done

violet oasis
#

689 - 680cos(x) $\neq$ 9cos(x).

somber coyoteBOT
#

Restarter

limber dagger
#

oh wait

#

i see

violet oasis
#

$689\cos(x) - 680\cos(x) = 9\cos(x)$.

somber coyoteBOT
#

Restarter

limber dagger
#

shes done 900-689

violet oasis
limber dagger
#

ahh ok

vocal pollen
dense carbon
#

Find x without using trig I was told 😭

copper dirge
#

can a 3 dimensional frequecy table be used to display more complex data sets ?

slim plinth
vocal pollen
#

Think complex numbers

#

you can use trig to solve it

slim plinth
#

Okay

#

(-1)^1/6

queen juniper
slim plinth
#

?

slim plinth
queen juniper
#

igg

slim plinth
vocal pollen
formal bane
#

Hey can someone help me pls

#

I don’t understand the ambiguous case

#

<@&286206848099549185>

candid veldt
#

?

formal bane
#

Could u explain the ambiguous case pls 💔

fickle plume
#

Wdym by ambiguous case

formal bane
#

When ur trying to see how many triangles are possible given 1 angle and 2 sides

inland yarrow
eternal quiver
formal bane
slim plinth
#

I am doing sin(theta)=cos(90-theta), cos(theta)=sin(90-theta) and what else also like cot(theta)=tan(90-theta) and tan(theta)=cot(90-theta)

slim plinth
#

What’s this called

eternal quiver
#

Take theta = 45

slim plinth
#

x 2

fickle plume
#

it's ambiguous in that case

green yew
upper karma
#

hey guys can anyone help me , and explain to me how to solve it , cuz idk

upper karma
#

lol

#

like how am i supposed to know ??

upper karma
#

bro wth r u saying i dont understand

karmic hull
#

bruh wut r u talking about 🤔

upper karma
#

yeah i want u to explain how

#

like how do i solve it using the pythagoras theorem?

karmic hull
upper karma
#

lol

karmic hull
karmic hull
upper karma
#

yk what? idek anything so imma ask chatgpt , ty for helping

#

bruh

#

i aint drawing bro

#

u dont even know my bd , do u ?

elfin saddle
#

i would give up by now they don't even want to know

upper karma
#

i just know the c^2=a^2+b^2

#

so?

#

ohhh okk

#

okk tysmm

#

i understand now

wet flower
#

Anyone any doubts?

inland sonnet
#

is there one for probability

#

a channel

inland sonnet
#

ty

surreal moth
violet oasis
upper karma
#

can U guys help me with 4c

regal sedge
upper karma
regal sedge
#

i hope you know that the locus of this point P is a circle?

#

Since the radius is greater than the distance from the origin to the center, the origin lies inside the circle, right?

#

for maximum value of |z|
This is found by starting at the origin, going to the center, and continuing to the far edge of the circle. that is |z| max= d+r = 5+8=18

regal sedge
#

i hope you got it? @upper karma

upper karma
upper karma
charred meteor
#

the addition 5+8=13 its nothing much

upper karma
regal sedge
upper karma
# regal sedge ooh sorry, its a typo!

btw how do you know that the maximum the minimum value of z is on the straight line that goes through the origin and the center and where the line intersects the circle

#

like sure it makes sense when you look at the diagram but yk we just cant assume stuff like that

quiet sequoia
#

2 constants in one circle, pi and root two

warm gulch
#

OMG

slim plinth
acoustic sphinx
#

Hi, if anyone needs it, I made an extension to a unit circle diagram with tan,cot,sec,csc. I made it primarily for obsidian notes, so that it's easy to read even without zooming in.

stone drift
quiet sequoia
#

no, I wish I could do that though

slim plinth
#

Is it true that on Pythagorean triple its; Write odd squares consecutively. Add or subtract 1 to even- numbered semi- squares. Double it arbitrarily by three, four, or five

neon iris
#

I don't need help with this I was just messing around

fleet light
#

How do I solve this

quasi remnant
#

What are we solving for?

regal sedge
mint holly
#

hey so I need help im doing a study guide for similar triangles and need help understanding how to set up and solve problems and maybe find a pattern to use

karmic hull
mint holly
#

nobody i know is awake and so they cant help🥲

#

can anyone help?