geometry-and-trigonometry

[hoary totem]

[visual flume]

wait what i thought median length formula was based on the side lengths

[torn sleet]

Help how do I solve this?…

[dark sparrow]

,rccw

[obsidian harness]

what have you tried?

[rapid hearth]

i got 0.93g/cm^3

This is how

[odd pivot]

Across 60 degree it has to be square root of 3. "Has" that's ok but why? I swear these guides pissing me off. Anyone can help how he know that 'has'

I understand how he got that reference angle of 60

I believe we assume its an unit circle, so the radius is 1

[sonic tundra]

what exactly is the problem

why across 60 degrees should be sqrt(3)?

[odd pivot]

how he come to that square root of 3

Like i know that there are some rules, like we got that reference angle and its 60 so the other is 30 by the sum of angles 90+60+30 its a special triangle. The line on the x axis is 1 since its unit circle so im not sure how he got that opposite side without knowing hypotenuse

[sonic tundra]

Ok that's easy

you said

"we assume its an unit circle"

so radius is 1

but we also remember the rule in the triangle 30-60-90

In a this triangle with angles of 30°, 60° and 90°, the hypotenuse (the longest side facing the right angle of 90°) is always equal to twice the length of the shortest leg (the one opposite 30°).

[odd pivot]

WHAT, is that true? is that only for the 30, 60, 90 triangle or in general?

[sonic tundra]

no only for it

maybe

proof goes from the equilateral

triangle

divide angle 60 and get 30

[odd pivot]

im just a bit confuse which side represents which angle

[sonic tundra]

actually

from their picture we get (\sqrt(3))^(2)+x^(2)=(2x)^(2)

and x = 1

hypotenuse can't be negative

so radius is actually 1

[odd pivot]

didint understand a thing

[sonic tundra]

where AB=1 BC=2

i think

they maybe didn't actually use unit circle

it confused you

maybe

but they just took 1 as a unit

[odd pivot]

might be true, the hypotenuse cant be 2 if its unit cirle no?

[sonic tundra]

as a side length

[sonic tundra]

no

[odd pivot]

because the unit circle is ~0-1

[sonic tundra]

AB=1

as a radius

but i think it is not a unit circle

they just took side length 1 as example

[odd pivot]

but BC is 2 and try that on unit circle

[sonic tundra]

I think they don't use unit circle because this triangle is too big for unit circle

here we can figure out everything we need of course if we know that AB=1 or smth else

[sonic tundra]

just consider equilateral triangle with side a

and divide it into 2 parts

then sine(60) will be a (\sqrt(a^(2)-((a)/(2))^(2)))/(a) which is sqrt(3)/2

and cosine(60) will be ((a)/(2))/(a) = 1/2

[spiral token]

Could someone please help me solve these? Thank you.

[sonic tundra]

2 question length of KL=6

because KL is radius

using formula S= pi* r^2 theta/360

we define r

next question

using the same formula we get (pi*17^(2)*92)/(360)

[spiral token]

thank you!

[sonic tundra]

232.02

[spiral token]

okay!

[sonic tundra]

nearest hundredth

next question the same

[spiral token]

The last 3 are the ones I am quite concerned about

[sonic tundra]

the

last one

FGH

is also 21

degree

because it's the same ARC

[spiral token]

Are you sure not 42?

Cuz FJH is an inscribed angle

And FGH is a central angle

[sonic tundra]

yeah

youre right

its 42

[spiral token]

Yay

[spiral token]

And the 5th image would be 48?

[sonic tundra]

not sure

[visual flume]

help?

ok i have a method but i think my calculations r kinda cooked

[sonic tundra]

hmm

why

[wooden epoch]

Can someone help me with 3D trig

[dark sparrow]

just send the thing lol

[wooden epoch]

ill @ u

i made a forum

[last jolt]

my geometry teacher is gonna fail me for the year 💔

god damn it

[sudden solstice]

Does anyone know how to do this?

[sonic tundra]

1 question 75

360-255=105

360-(90+90+105)=75

[wary temple]

can someone help me understand 3D geometry, im stuck on the exercises, ive drawn the points where this are located but I don't know how to connect them together and how to form.

[sonic tundra]

second the same way

360-248=112 360-(90+90+112)=68

[lofty flame]

do i need to memorize shit on the unit circle or is it kind of like the periodic table where i only need to learn how to navigate it?

[dark sparrow]

"learn how to navigate it" is definitely much better than just blindly memorizing shit

i would say it's less like the periodic table and more like the times table

[lofty flame]

and i have that one 100% memorized XD

[maiden brook]

at worst u have to memorize just sin(30) sin(45) sin(60) and that’s it

[south echo]

Y'all I may be cooked possibly and I need someone to help me with this question 😭

The answer's supposed to be 119.4 but anything I try i get a close number but not that similar

this's my work so far

3d trig may be the most effort I've ever puttin on math

Everything else is simplistic because Im following a method

Im forced to create my own diagram in which I'm jst gonna jump off a ledge

[honest fractal]

Does cosin law apply?

Does it give same answer?

[south echo]

Im not sure

I did only sin law

[honest fractal]

I think we can use cosin law but I totally forgot the formula😫

Since we had three angle

[fossil spear]

How do you know what the defined angles on the circles mean🥀 like for one, would the 225° be the angle measure between s & u🥀🥀🥀

[south echo]

The cosine law is c^2=a^2+b^2-2abCos angle

ima try it out

[south echo]

I dont think it'll work out since we dont have the required amount of sides

and we only have angles found

[knotty quiver]

<@&268886789983436800>

looks like they left

[mystic umbra]

<@&268886789983436800> remove ts 😭

[dark sparrow]

<@&268886789983436800> scam

[thick sleet]

Is this where i can ask questions?
How can I mathematically prove that the radius of a circumscribed circle around a normal hexagon is always equal to the side lengths?

[dark sparrow]

by normal do you mean regular

ie all sides and angles are equal

[thick sleet]

yes sorry

[dark sparrow]

draw a diagram

[honest fractal]

Ohh sorry

[thick sleet]

is that the only way? so there isn't any fancy way of writing it in a formula of idk? i can only prove it visual?

thanks for the quick answer though

[dark sparrow]

i mean geometry proofs are 99% visual

in your case you will end up with a bunch of equilateral triangles

in fact it's useful to remember six of those fit together to make a regular hexagon

[thick sleet]

oh damn, never thought about it like that

so i can only prove it visual? right?

[dark sparrow]

i guess?

you should not be aiming for visual-less proofs in geometry

[pale sentinel]

It's basically the fastest way to show that too

[obsidian hornet]

You can show this by constructing hexagon for any circle using compass and ruler

[upper karma]

gutenmorning

[thorn mica]

How does one find the intersection of two planes

[dark sparrow]

depends on what form they're given in, but generally:

• determine if the planes are parallel or not. if they are, then their intersection is empty (or they're actually the same plane)
• otherwise, they will intersect in a line. the direction vector of this line should be parallel to both planes and so orthogonal to both their normals -- so take the cross product of said normals and that'll be it
• also find a point that lies on both planes by solving a system of 2 eqs in 3 unknowns from the planes' equations

[upper karma]

Uhh solutions of a pair of 3 variable funcs

[thorn mica]

So n1 x n2 = v? Ignore the messed up notation

[upper karma]

Your a duck 🦆

[thorn mica]

True

[dark sparrow]

that's what i said yes

you can go with either order for the normals -- the difference will be only that you get a direction vector of the opposite direction

[upper karma]

Duck duck

Quack

https://tenor.com/view/utka-utka-ah-ah-gif-10639011062558167830

Ok I’ll stop

[thorn mica]

Of course I didn’t make that very clear sorry
Just wanted to avoid writing n x n

[thorn mica]

It’s a beautiful gif but my final exam in math is coming up in two days and I feel like I’m cooked

[upper karma]

A cooked duck is tas… oh nevermind

[upper karma]

Do ducks also have exams? 😮

[silent plank]

do you have notes / what have you been taught so far?

have you been introduced to sine,cosine,tangent?

do you know what they do in a right triangle?

what doubts do you have?

ok

,tex .sohcahtoa

[somber coyote]

ℝαμOmeganato5

[silent plank]

do you have any issues with that?

one step at a time, starting the the basics

did you make any attempt at question 1?

can you show what you did for Q1

its correct, you actually applied one of the more advanced methods to that question

i.e. the sine rule/law
as opposed to basic right triangle trig

which is seem what they intend for you to use,
to use the first triangle to get a side present in the second triangle
and then use that to get your angle

which third triangle

you mean Q3?

no

you shouldn't be dividing angles by sides

for this, first try using the top triangle to determine the length of the red line segment

is incorrect, can you show what you did

[pale sentinel]

Is that red line opposite the angle?

[silent plank]

you used the incorrect function

[pale sentinel]

ye

because it's adjacent to the 43-degrees angle

[south echo]

Can anyone possibly solve this question please as Im gonna get cooked on my exam tmrw if I have absolutely no idea how to solve this

[south echo]

@everyone

[full lily]

Is there a 3 dimensional object with only regular hexagons for sides

[thorn mica]

Whats the easiest way to find the distance between 3d objects
Im looking for something that’s applicable in any combination of these things:
point, vector, plane

[thorn mica]

DONUT

[untold nova]

How do you get the angles of a circle? Can someone explain all of this and what each line means, like I have no idea😭

[vocal charm]

Yeah I got you

[normal plover]

a football

but this can actually make it look more angular without being bended to create circular ball

[frosty wave]

Can someone tell me the formula for solving this?

[pale sentinel]

A football shape actually has (dark) pentagons against (light) hexagons

That ball posted must necessarily have curved edges to work

[normal plover]

yes I know but you can still create a 3d shape with hexagons

[pale sentinel]

...With just regular hexagons?

[normal plover]

sure it can look ugly

[pale sentinel]

Surely not, since that's a forced tesselation

[mystic umbra]

sine and cosine law

[normal plover]

Im not trying to create a sphere

[mystic umbra]

🤔

[normal plover]

just a normal shape

[pale sentinel]

(was explained in a help channel 👍)

[mystic umbra]

anything to do with triangles is

sine and cosine law 😔

[frosty wave]

Alr ty 🙏

[pale sentinel]

Yh I figured, but with three reg. hexagons at a corner, it's completely flat

It won't create a 3D vertex, so you don't get a closed shape

[normal plover]

I also figured that you do need other shapes and not every side as hexagonal

[pale sentinel]

yeah

[pale sentinel]

Hence my saying this is unfeasible (since the edges are not all straight)

[normal plover]

yeah so it is possible

but you need to strech the hexagonal sides

so orginal hexagonal shapes as the same size cannot work as flat to create a 3d prism

[cunning lion]

it doesn't work for ball-shaped objects, it's possible on torus like objects as demonstrated

[normal plover]

but other shapes like triangles, rectangle, square can do this.

also pentagon and after that can't work.

so the only way to do this is by streching, bending, and making a difference to a flat hexagon to create a 3d shape.

[wooden epoch]

is anyone good at 3d trig?

[vivid oyster]

Umm. Can anyone help me with Maths. I am very weak at maths

[dark sparrow]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[dark sparrow]

(resolved in #1021175428326633542 )

@vivid oyster you should just send your question(s)

[strange lark]

Bruh I got stuck on a trig questions for 20 minutes because I forgot isoceles triangle have 2 same angles smh.

[arctic hatch]

Hi

I have a question on maths

See if anyone can teach

me

I am so dumb

[strange lark]

Maybe I can. (Only maybe)

[arctic hatch]

Trigonometry

Just the simplest Sine, Cosine, And Tangent

[strange lark]

What do you mean "simplest" Like we go over the definition?

[brave nebula]

sine is op/hy

cos is ad/hy

tan is sine/cos

thTS THE SIMPLE THING

then the next basic this is sin^2 + cos^2 Equal to 1

[arctic hatch]

No

Teacher only teach

SOH

CAH

and

TAO

Just like what he said first

[brave nebula]

remember like this

cos has a o in it

so it will not be o/h

therefore sin will be o/h

then cos will be a/h

[arctic hatch]

I knew

But I got a question

And tmr test will be hard

[brave nebula]

send me the question let me see the difficulty

[arctic hatch]

Can we dm?

[brave nebula]

ok

[arctic hatch]

If anyone can explain this briefly, tmr I will have a test on this question but the topic is trigonometry

[dark sparrow]

TOA*

[thorn mica]

Is the distance of a vector to a plane always the same?
As in it’s either 0 or a constant value because they’d have to be parallel

[steady agate]

triangle
tri=3
angle=angle
3 angle
triangles have 3 angle
im smar't

[thorn mica]

Does this formula apply to any pair of vectors/lines

Will it work if they’re parallel for example

[charred grove]

HEY SO LIKE WHEN UM

B×h

Does B stand for Base?

[charred grove]

I don't know but I hope you understand soon idk i felt bad that i asked a question without answering yours

[proud hazel]

b*h is base times height

[arctic hatch]

Idk how to do a trigonometry question

7 minites then test

Please help

[arctic hatch]

I fucked up maths

The fucking teacher XM made a question which it doesnt in trigonometry and the test have

I fucked up

I gave up that question

I dont fuck know what that is

Absolute error, she didnt teach me any and made on the test

[deep flint]

i fvcking hate maths. Like i know my teache was a fking genious when she was a student but like why tf would you assume that we sre geniuses as well

[arctic hatch]

She mother fucker want to let us all fail

Orginally my maths mark rate is 85-90%

Now maybe 50% because of her

Xiran Ma

[deep flint]

Like i know there is a guy in our class who does A level exams at like 13 14 but i am not a fking genious bro

[arctic hatch]

Like someone in our class is good at maths and tested the A level, and then the maths teacher made the test so fucking hard and make the normal student fail

[deep flint]

what a teacher👏👏

https://tenor.com/view/enojado-gif-6930705070173779193

[arctic hatch]

if anyone can help me report this teacher

Report her

[trail tendon]

what is this about?

[arctic hatch]

@deep flint

about her

She is the worst math teacher that I saw

[trail tendon]

r u mad cuz u got a bad grade?

[arctic hatch]

Report her

[trail tendon]

[arctic hatch]

I am mad because she made a topic that isnt on that test and she didnt teach

And only give a less time in the test

[trail tendon]

you do realize none of us experienced that right 💀

i mean

from that teacher

other people have experienced that from their teachers but

can't "report" or give bad reviews on someone you haven't taken cuz of what someone says bruh :l

[deep flint]

i dont expect someone would report her

Like just wanted to express my anger

[trail tendon]

oh ok ;-;

thats too bad man

[deep flint]

sigh

[grave pond]

This is not the place, though.

[arctic hatch]

@deep flint This guy and me experienced

[deep flint]

then where

[arctic hatch]

What I want to say is

She made a 5 marks question in the test

Which she didnt teach clearly

[grave pond]

I don't think making posts to attack a specific named person is welcome anywhere in this server.

[arctic hatch]

And that is 1/6 mark in the exam

It makes a big affect to my classwork mark

[vivid oyster]

This question solution please

Or any short trick

[exotic yarrow]

Consider squaring $x+\frac{1}{x}$

[somber coyote]

Civil Service Pigeon

[vivid oyster]

Ok thanks

[strange lark]

I hate geometry.

I do really well in every branch of methametics but not geometry for some reason.

[obsidian harness]

synthetic geometry?

coordinate geometry is very different

[strange lark]

Just geometry in general.

I got screwed over in 8th grade because of congruent and similarity of triangles, Euclidean construction. In 9th grade we have to learn inscribed circle and circumcircle which I also do poorly. And last semester I got 50% on exam bc of coordinate geometry.

[arctic hatch]

Can anyone explain what is errors in measurement?

Briefly here

[spiral lodge]

What does it have to do with geometry? 🤔

[violet sequoia]

am i cooked chat

AAAA

[spiral lodge]

Why yy6xxyyxx ???

What's up with that notation?

Can't you simply write 6x⁴y⁴?

[violet sequoia]

I'm goofing off

behold, the most zoomed into desmos that is possible

[pale sentinel]

oh shet you're right I checked

you can make some silly graphs with this

[dark sparrow]

and this is the most zoomed OUT it can get

[empty yew]

how much patience do you guys have?🤣

I'm already tired of zooming in to the order of -20!💀

[dark sparrow]

you can manually enter the viewing window in settings

💀

[violet sequoia]

or put a high speed object on your mouse wheel

like i did

🗿 bowtie

[novel beacon]

Can someone please explain to me how Proofs work? I am in geometry this year and my exams are coming up. My teacher has told us nothing, but I know its going to be a decent part of our exam please send help I don't want to redo this class.

[mystic umbra]

What exactly?

Because proofs are like logical chains of just $p\implies q$ where q is something you intend to prove and p is something that has been proven true which all lead to Euclid's postulates as the source in a geometric context...

[somber coyote]

parabolicinsanity

[mystic umbra]

you take what you already know is true

and then demonstrate other things true

and also maybe

define things along the way

😢 ts mathematical logic 101

i could give you an example for a proof

[novel beacon]

It's Okay, Thank you! 🙏 That was all I needed, for some reason my teacher won't explain the simple stuff a lot (I think its her first year I had to show her how to use Kahoot)

[mystic umbra]

good luck then

decently many people don't know mathematical logic 101 😢

weird

especially for highschool and stuff

and wonder why they don't understand shiii

[trail tendon]

more the school system fault lol

[mystic umbra]

fair

~~but i learned logic at school too 💔 ~~

[rotund arrow]

Ik it's a simple thing (probably) but how do we solve this?

[spiral lodge]

Those angles are the same, right?

Taken as pairs, of course

So the two triangles are similar

[rotund arrow]

I wasn't given the yellow, but most likely. As of the green, it's that way every time since they intercept?

[spiral lodge]

Yes

[strange lark]

How do I use SSA?

[silent plank]

that's a bit vague
is there more context? what's the question where this is coming up

[mystic umbra]

what does it mean to "use" SSA? you just find SSA and declare the triangles congruent

[odd pivot]

Im trying to find a formula on arcsecant and so on, i couldnt find in a readable fashion 😄 , i know its inverse of secant, so is it something like
arcsec(hypotenuse/adjacent) = theta

if it is, I assume its similar for arcsecant and arccotangent

[obsidian harness]

yes

be careful of the domains of the functions though

well it comes from the fact that hypotenuse > adjacent and hypotenuse > opposite

[odd pivot]

im not great on things like that about domains, but i think there is domain and range

[obsidian harness]

if the side lengths are positive

[obsidian harness]

absolutely

if you haven't gotten to precalculus/functions yet don't worry too much

[odd pivot]

I also assume that i can rewrite the equation in different manner right,
like arcsec(1/cos(theta))

[strange lark]

I know the length of 2 sides and size of an angle not formed by the said 2 sides, how do I deduce the length of third side?

[mystic umbra]

sine and cosine law

🤷

cosine law gives you the third side

directly

oop

not directly

[strange lark]

I got a triangle ACD, AC is √21, DC is 1, ∠D is 120 degrees.

[mystic umbra]

yeah so AC/sin angle D = DC / sin angle A

you find angle A

you've found angle C

then again sine law

🤷

[strange lark]

I tried applying law of sines. √21/sin120=1/sin∠DAC=AD/sin∠ACD.

[mystic umbra]

and?

[strange lark]

Let's just say arcsine of 2√7/7 isn't too pretty to work with.

Wait, I just use laws of cosine instead and it give me a much easier process.

[grave pond]

If you prefer coordinates instead, imagine a coordinate system with the origin at the known angle and the positive x-axis in the direction of the unknown side. You then have enough information to find coordinates for the point where the two known sides meet, and the x-coordinate of the last point is then just Pythagoras and a quadratic equation.

[strange lark]

I set the length of DC as x. And now I can plug the numbers back into a²+b²-2abcosC and got a quadratic.

[grave pond]

Sure, just pointing out an alternative way to think about it.

[proud hazel]

I’m stuck 💔

[silent plank]

,rotate

[silent plank]

what were the exact instructions of the question

[proud hazel]

Resolve cos70+cos100

[silent plank]

resolve?

[proud hazel]

It was just cos70+cos100=?

[silent plank]

there isn't much you can do with the cos(85°) unless they want you to use a calculator for a decimal approximation

[proud hazel]

Nvm I’m just dumb and I copied wrong 💔

It was 110

Not 100

[silent plank]

you can use compound or half angle identity for the cos(15°)
i recommend compound as that avoids pesky roots within roots

[odd pivot]

Anyone can explain, im not sure i understand. I got the idea that domain is an input range and range is an output range
so does that mean the input for sine is opposite and hypotenuse can be of infinity and the output is what we get of opposite over hypotenuse? I tried to think from perspective of unit circle and degrees but it feels weird, i know that 1 is 90 degree so its -90 greater or equal of y or y is less or equal to 90 but im not sure how they got those 90 degree. If sin is related to y axis why it cant be -180 greater or equal of y or y is less or equal to -360

[silent plank]

sohcahtoa is for basic right triangle trig can't really be applied to angles outside of (0,90°)
read up on the unit circle definitions of sine and cosine

[strange lark]

sine is y/r and cosine is x/r. At 90° it's (0,1) on the coordinate plane and r is √(0²+1²)=1

[visual flume]

guys is it 9/4

asdf

oh

mb my cache was too large so i thought the images didnt upload rahhh

[smoky shale]

is there a formula for the number of possible unique shapes that can be formed with a give number of lines?

[final ferry]

Help

[upper echo]

nope

[prisma jackal]

Can anyone help me prove this identity? Ive been trying and i have no idea what im doing wrong but i just cant seem to express it as the right side. The identity is true though

[trail tendon]

try starting from the top and factoring instead

factor the numerator and denominator of the left side

[pale sentinel]

Also for one thing, sec^2 is the sum of 1 and tan^2, not their difference

[visual flume]

aw

hint pls?

i used medial triangles and stuff

[visual flume]

erm is it 4/11

ohno i added wrong

bruh

[visual flume]

help pls

[hoary totem]

my solution is a bit long but tbh i just went with whatever came to my brain first

call AB = c, CB = a
call HG = BP = c', PG = HB = a'
call CH = a - a' = h, PA = c - c' = p
call BG = x
area of △CGB = area of △BGA = 1/3 area of △ABC
-> a * c' / 2 = c * a' = 1/3 * a * c / 2
-> ac' = ca' = ac/3
-> c' = c/3 and a' = a/3
-> p = 2c/3 and h = 2a/3
thus by pythagoras in CHG
4a²/9 + c²/9 = 9
and by pythagoras in APG
4c²/9 + a²/9 = 16
multiply both equations everywhere by 9
-> 4a² + c² = 81
-> 4c² + a² = 144
sum the two equations
-> 5a² + 5c² = 225
divide everything by 5
-> a² + c² = 45
by pythagoras in either HBG or BPG
x² = a²/9 + c²/9 = (a² + c²)/9 = 45/9 = 5
-> x = sqrt(5)

[hoary totem]

in fact using the same steps one can prove
CG² + AG² = 5BG²
for any right triangle

[red crypt]

I need helppp

I srsly can't fucking solve this

[obsidian hornet]

If AD is bisector line, then easy to see that 90-a+b=90-c-b=>2b=a-c

[red crypt]

Bro what

[obsidian hornet]

?

[red crypt]

Where did u get c

[obsidian hornet]

C is gamma(angle c aka)

[red crypt]

Ye but

Why 90-

A+b

Did u mean 180

[red crypt]

I need to prove that beta = alfa : gama

• alpha - Gamma divided by 2

[obsidian hornet]

But you wrote b=(a-c)/2 or its a part of condition?

[red crypt]

Nothing my friend wrote that

We need to prove b=(a-c)/2

[obsidian hornet]

Ok, Is AD bisector line?

[red crypt]

Yes

[obsidian hornet]

Sorry, I still can’t get it, we need to prove that b=a/c or b=(a-c)/2?

[red crypt]

B=(a-c)/2

That's what we need to prove

[obsidian hornet]

Ok, i proved it already

[red crypt]

Ye but I don't understand

[obsidian hornet]

What exactly?

[red crypt]

90-alpha+beta

Isnt it 180-(alpha+beta)

[obsidian hornet]

I just rewrote the bisector equal angles

[obsidian hornet]

No, 90-a is from right triangle and for bisector angle we need to add b

Same for c: from right triangle we get 90-c and for getting bisect angle we subtract b

And then just equalise and getting b from the equation

[red crypt]

OK 👍

[dusk stag]

who can help me with a geometry problem very hrad

hard

[grave pond]

You'll never know until you let people see which geometry problem you need help with. How would people know whether they can help you with a problem they don't yet know what is?

[dusk stag]

bro all problems i give are very hard

if i ask for help is because i dont know how is it

[grave pond]

Okay, keep your problem secret, don't get any help with it.

[dusk stag]

i sent a help forum if i say here for help is because it is posted no ?

[deft sail]

If y=0 how do I solve for x?

[upper echo]

In this case the exact roots cannot be expressed in terms of a finite number of some elementary constants or functions. Though you can solve it numerically with any given precision.

[deft sail]

You got this

[severe rock]

I have to make a geomonster for a project ( some like monster made of geometric shapes). I plan on cutting off part of a sphere. Is there any way to calculate the surface area and volume of a portion of a sphere?

[sick badger]

If anyone can help, I was out for the last two weeks really sick and missed the whole unit now my teacher is giving me the test trm, and I dont understand this thing on the review

Like I am hella lost

[median plaza]

actually going to crash how do i do ts

[mystic umbra]

angle chasing, a lot of angle chasing

[mystic umbra]

can you explain whats written there?

radius is 10 in. and measure or whatever they call if for arc AB? is 345°... but how can one find length of arc AC without the angle measure?

[visual flume]

wait 345 is arc cb+ba right

15/360*20π

300π/360

dwait

what

how is it 115π/6

oh after 4 minutes of watching tiktok

ac as in cb+ba

[median plaza]

i got it right after using gpt but it made no sense now im stuck ehre

[visual flume]

205/360*17.6π

[median plaza]

wait what howd you get that

[visual flume]

uh so arc abc has an angle of 205

[median plaza]

360-155?

[visual flume]

yeah

[median plaza]

i see

but howd you get 17.6

[visual flume]

the circumference of the circle

8.8*2π

help pls

[median plaza]

ok so i put that in i got it wrong...

[upper karma]

ok so like u got this big square abcd and inside it there's this smaller square efgh right. they tell u ae is 7 and ed is 4 so the whole ad side is 11 ya. that means the big square has side 11 easy

now efgh is tilted in there between e and d, and u can see ef goes from e (which is 7 across) to f (which is like 4 up and to the right). so to get the length of that side u just look at the change in x and y, both 4, so do √(4² + 4²) which is √32 which is 4√2

then like since it's a square, area is side² so u do (4√2)² and that gives 16×2 which is 32. so yeah area of efgh is 32 ez

[visual flume]

ty

[visual flume]

wait

how is df 4

[median plaza]

no clue gonna ask my teach tmrw

[visual flume]

lol

[median plaza]

deltamath?

[visual flume]

nah

@upper karma how is df 4

[upper echo]

GC=GF=GH are radiuses of the circle centered at G (as ∠HCF = 1/2 ∠HGF). So, △GFC is made of two triangles equal to △EDF, thus FC=2ED=8 and DF=11-8=3.

[proud zinc]

im famous

ima Temperature

[upper karma]

I have to solve the area for each shape, but im confused as to what shape putting green 2 and sand trap 2 are?

[hoary totem]

DF is not 4 and the answer is not 32

triangle PEH is congruent to triangle EDF by HA (both triangles are right, the hypotenuses EF = EH cuz EFGH is a square, and angle PEH = angle EFD)
thus PH = 4
also, quadrilateral APHQ is a square, so knowing PH = 4, we can say AP = 4
then PE = 7 - 4 = 3
since △PEH is a right triangle, EH² = 3² + 4² -> EH = 5
thus the area of the square EFGH is 25

[grave pond]

They are trapeziums, but you can also handle them as just being a rectangle and a triangle put together.

[upper karma]

ok! Tysm!

[rain knot]

does anyone have some practice questions for inverse trig? nothing crazy, hs level but i need some more questions and i haven't bought my ref book yet 😅

ping me if you do!

[trail pecan]

i tried it using
partial differ.
using trigno identities
got no where close

[fossil thorn]

Chat help

Friend told me that adding parallel line EG will help

I bashed in a lotta numbers but it didnt lead me anywhere

EC not parallel to AB

My drawing is L

[visual flume]

lol thats exactly what i did

i was vbored in math class

[warped rock]

open a ticket thingy ill help you there

[visual flume]

!status

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[visual flume]

dude… i got x = 0

[mystic umbra]

are there any side relationships? or is it all thats provided?

[visual flume]

………………………………………………………………………

i keep on getting x

=0

im going to crash out

[mystic umbra]

hmmm ABC is isosceles that means this figure is not to scale 😢

[warped rock]

you can get d by adding a and b full angles and sub by 180

get F the same way

get the angle right of F by subtracting 180-D

then you can get C the same way as F

[warped rock]

F is the same on the other side if yk what i mean

[mystic umbra]

strange, it might not be possible hmmm

[warped rock]

lemme see it

[mystic umbra]

angle ACE + angle BEC = 110

dont think you can get clearer than that

[warped rock]

wait no i got it

its kinda wonky though

@mystic umbra @fossil thorn

[mystic umbra]

i dont think that you can determine them

hmmm

[warped rock]

yeah you can wait im a genius

call?

oh wait no you cant

ok basically

big triangle

bottom angle is known to be 20

[mystic umbra]

hmmm how did you

[warped rock]

180-20-20=140

[mystic umbra]

determine 75 and 85

how did you find them?

[warped rock]

wait lemme do this again

[mystic umbra]

im more interested in how you found them

[warped rock]

ok im in progress im doubting myself

but its basically because

40 and 50 angle

wait now that i think of it

[mystic umbra]

okay?

[warped rock]

those angles dont look equal

[mystic umbra]

ignore the

looks

ts not to scale

but

[warped rock]

wait this is messing with me

[mystic umbra]

explain how that would make them equal 85 and 75

[warped rock]

i think im wrong

[mystic umbra]

perchance an ambiguous solution if its not determinable

[warped rock]

yeah its not possible

i checked over and over

let me see if i can use quadralaterals

[fossil thorn]

That's all provided

[fossil thorn]

I think ? = 80

[warped rock]

are you trolling

[fossil thorn]

According from my friends who solved it

[fossil thorn]

No

[warped rock]

bro

[fossil thorn]

💀

Im fr

[warped rock]

this is unsolvable

[fossil thorn]

Fr?

[mystic umbra]

seems so, it seems ambiguous

[fossil thorn]

He drew smth from E to G or smth and EG is pp to AB

I sent it in gc and someone said 80 too

[mystic umbra]

what even is G

its not even well illustrated

[warped rock]

its a troll pls say its a troll

[fossil thorn]

A point which creates EG that is parallel to AB. I created it just incase u need to use it

[fossil thorn]

:(

[fossil thorn]

No it's not

😭 This was on my classroom's board as a challenge problem

[warped rock]

ITS PARALELL????????????????

NAHHH BRO

wait wait what

[fossil thorn]

EG pp AB. Not EC pp AB

._.

E is a created point

I put it there cuz friend told me that's how u solve it

He gave me G as a hint

That's it

[warped rock]

so b is like an imaginary point

could have said that

[fossil thorn]

No B is up there

G is imaginary lil bro

[warped rock]

i mean G

[fossil thorn]

Yes

[warped rock]

holy

alr

[fossil thorn]

[mystic umbra]

well clearly you didnt tell us

[fossil thorn]

:(

I thought u big brain an will understand

[mystic umbra]

not like it solves ts anyway

[fossil thorn]

Idk

I did a bit of grinding

And

Ang FCE = a

Ang FEC = b

Ang GCE = c

Ang GEC = d

And then bashing in some alt int pp

I got

a + b = 110 deg

c + d = 80 deg

a + c = 130 deg

b + d = 60 deg

Chat can we solve those equations

[warped rock]

yeah i got it too

bruv

[fossil thorn]

:(

Chat

Did it work

Yeah no

Doesn't work

It's stuck in a loop

[warped rock]

yeah no it doesnt wrok nvm

this question is depressing

[fossil thorn]

Fr

Chat

[mystic umbra]

yeah

[fossil thorn]

A friend who said they solved it just got on

Im asking him rn

[mystic umbra]

you can solve it

[fossil thorn]

Fr?

[mystic umbra]

trivially might i add

[fossil thorn]

._. Then solve it.

Did u use like elimination or smth?

[warped rock]

its impossible

its literally impossible

i tried quads

triangles

everything

[fossil thorn]

Aight chat

I pulled up

Guy in GC finally responded

[warped rock]

holy

shit

[mystic umbra]

uh oh

[warped rock]

YOU DDINT SAY THEY WERE PARALLEL

[fossil thorn]

[fossil thorn]

._.

[warped rock]

HOLY SHIT YORUE SO BAD AT EXPLAINING

[fossil thorn]

^^^

😭

[warped rock]

and thats still wrong

[mystic umbra]

yeah its not possible

[fossil thorn]

Oh

[mystic umbra]

give up

[fossil thorn]

Fr?

Where wrong fr

[mystic umbra]

the coefficient matrix is singular, its so over

[warped rock]

no you literally altered the numbers

its literally impossible

[mystic umbra]

😭

[warped rock]

basically if you solve it enough

30 = 30 + 30 now

[fossil thorn]

He did that

[warped rock]

how did he get 10 and 20

for the point on the left

thats assuming

[fossil thorn]

No clue

💀

[mystic umbra]

if you overcomplicate it enough, you will make a mistake and get an answer

[warped rock]

fr

[fossil thorn]

connect AG
AEGB is cyclic quad

[warped rock]

im done with this shi

youre teacher gave an impossible question

[fossil thorn]

😭 No helppp

It's due tmrw

[fossil thorn]

thus EBG is equal to GAE

[warped rock]

womp womp

[fossil thorn]

But lowk fr

Like it is a cylic quad

[warped rock]

if im wrong

the answer is 50

[fossil thorn]

Cap

Byte

Am I sped

Or is it a cyclic quad

[warped rock]

answer is 50 bucko

cyclic quad or whatever is bs

[fossil thorn]

Nah bruh

[warped rock]

every quad equals 360 degrees thats all you need to know

[fossil thorn]

Nah bruh

[warped rock]

yeah and im in precalculus

[fossil thorn]

Wow

Cool

But uh

[visual flume]

what grade

[warped rock]

10th

[visual flume]

lol in in 8th

[warped rock]

ap

[visual flume]

ap precalc?

w

[warped rock]

yeah im done talking to munchkins

wasted my time over a stupid question

answer is 50 yall

i asked deepseek

[fossil thorn]

Deepseek sped

U gotta check

[warped rock]

no screw you

[fossil thorn]

Why u tripping bruh

[warped rock]

https://tenor.com/view/mods-cut-his-pizza-into-squares-cut-pizza-pizza-squares-gif-12519099119807951061

https://tenor.com/view/meme-anime-girl-angry-scary-gif-21631852

[fossil thorn]

It's solveable

I finally did it

Took me long enough

But yes

i did it

[fossil thorn]

I had to do use a cyclic quad

And then force make a kite

To use angle bisector

Or else they would just cancel out

[glacial crypt]

help

,rotate 180

[rustic swift]

any people have html/scripting experience?

[obsidian hornet]

There is a plenty ways to solve problems like this, but, actually, i think its more interesting to answer a question about how people came up with this problems? So, there is the answer, then they just erase obvious part and the problem becomes hard

[thick sleet]

hey guys, i need to find the area of a pyramid but without the base area

how does one do that

[fossil thorn]

Fr fr

Very elegant problem

[obsidian hornet]

agree

[signal root]

i had my first class of trig today

[glacial crypt]

just gonna say I still need help, my lesson is law of sines & cosines

[quaint chasm]

kinda stupid but does anyone know the (euler) angles that have cube stand on a corner (like an equation for it), and why it's that angle?

i.e a cube laying flat is (0,0,0), standing on an edge would be like (45, 0, 0) or (0, 45, 0), but (45, 45, 0) does not stand on its corner, it's off by a bit, it seems closer to (45, 35.25, 0)

specifically what i'd like is that the line between two of the corners of the cube would be perfectly vertical, like how you usually show a trigonal trapezohedron

[versed kraken]

(45, 35.26, 0)

[quaint chasm]

like, exactly?

[quaint chasm]

oh looking that angle up got me the answer for the exact angle i think, atan(sin(45°)) apparently

[pale sentinel]

I recognise Blender

[pale sentinel]

But yh roughly along those lines; it's analogous to finding out the equivalent Euler angles for the vector (1,1,1)

[modest bane]

surface area and volume pls

[visual flume]

average insane bashing

[stiff thorn]

i had the same paper as a quiz grade wish i took a pic

[manic hatch]

does anyone here have a PDF about geometry?

i need it to study

[modest bane]

broo

[obtuse sundial]

Is it possible to use identities (like half angle) in order to derive the exact values of any trig function by hand?

[median whale]

I feel rational expressions can be obtained for some

[mystic umbra]

usually you use power series to derive values

dont think so

only standard angles have "nice" values for trigonometric functions

[round spoke]

We’re doing trig review in my algebra 2 class and I didn’t pay attention last year when I did this stuff…can someone help me 😭

I didn’t want to open a help chat because I can just skip the question

But it’d be nice not to

[median whale]

so do you want how to do or not

[round spoke]

Nvm my dad helped me

[median whale]

ok

[little meadow]

oh i remember...

[little meadow]

to find x, you need to use cos(46) = x/4.1

then just solve for x

bring the 4.1 to the other side.

so cos(46) * 4.1 = x

so yeah

pls double check 🙏

[median whale]

correct

[little meadow]

thx

[signal root]

hows angle of elevation/depression work

[little meadow]

oh cool

so there is also pythagoream theorems and all that stuff?

[obtuse sundial]

You can calculate factorials by hand...?

[obsidian harness]

yeah

it's just multiplication

tedious but doable given enough time and patience

[obsidian harness]

that's definitely very expected at algebra 2 level

I mean Pythag comes up in related rates in calculus too

[obsidian harness]

I think you're referring to this then

https://en.wikipedia.org/wiki/Exact_trigonometric_values

yes, absolutely

it's mainly half angle but sometimes triple angle too

and like symmetries involving pi/2, pi, 3pi/2

[iron frost]

bro whos good in bio i have an exam im gonna cru

[obsidian harness]

sum and difference formulas

[obsidian harness]

you're in the wrong server mate...

is this for IGCSE or A levels?

[plucky abyss]

[sweet spruce]

Me and my friend have math test tomorrow would anyone like to call to help us understand geometry?? It’s about calculating volume with formulas

We are Spanish so it would be easier if whoever would like to help can speak Spanish but if not it’s ok I can help translate it to my friend

[fossil spear]

https://tenor.com/view/chatgpt-te-amo-coração-coração-abrindo-ia-gif-1702084030504635687

Its been very helpful for me in math

[gritty geyser]

Hey everybody. So I'm trying to write this proof (this is a steroegraphic projection problem that uses circular inversion but I can't seem to figure out how to revise the proof in the way that my professor suggested. Bare in mind that the class is synthetic. Most importantly, I need help with the first highlighted paragraph section. She told me to "use a similar strategy to our day 15 notes", which I've attached to the message. Hopefully that helps. If anyone can help me I'd super appreciate it! the proof is due tonight so hopefully someone can figure it out by then. If not It's okay. Thanks!

[safe ibex]

can anyone help me with basic trignometry?

[obsidian harness]

!help

[lime crown]

To ask for mathematics help on this server, please open your own help channel or help thread. See #❓how-to-get-help for instructions.

[safe ibex]

oh ok

[obsidian harness]

for high school level or below, you'll get quicker help in the help channels

even though this is the right place too

[topaz nimbus]

yall who can help me in tail to tail method rn in physics

im still a noob so pls dont judge me

[earnest geyser]

hey guys, so i recently found out geometry is actually very important for making video games

so here i am

can i get some basic resources for learning some geometry

probably just the stuff in a typical american geometry curriculum

please consider the fact that i have more or less no experience with geometry past super basic shit (and also i learned trig functions)

[plucky abyss]

YouTube

[lunar jackal]

the organic chemistry tutor

[earnest geyser]

can i get some links?

[obsidian harness]

https://www.khanacademy.org/math/geometry-home

https://www.youtube.com/watch?v=KtZai86htng&list=PL0o_zxa4K1BVkRxCZubMPcCJ5Q5QwZdEM

also these two from PurpleMath

https://www.purplemath.com/modules/geoform.htm
https://www.purplemath.com/modules/perimetr.htm

[exotic cradle]

Hi everyone! I'm from Ukraine, student, today I will take the annual geometry exam for grade 11. I wish improve my level of mathematics and geometry in future by discussing here.

I hope my questions won't be taken badly, even if they're stupid, because I've studied my whole life under a different program than others here (I think). We only taught sine, cosine, tangent, cotangent, for example. I sometimes hear that the mathematics curriculum in our country is somewhat more difficult for the same age as that of foreigners. I would like to know if this is true. So, in 11th grade geometry, do you study prism, pyramid, cone, sphere, their volume, area, etc.?

[flint moat]

Id say math education in Ukraine is kinda mess, its almost impossible to put all that theory with proper proofs and usecases in 11 grades. Its not bad, but not everything is tought on good level.

For comparison in Germany there are 2 years Q1 and Q2 after 11th grade and before uni. This 2 years you learn subjects for your specialization deeply, like detailed Stereometrie (like the three-perpendiculars theorem). So id say its pretty close level when we talking about pre-university.

I could be wrong not so long in Germany

Actually. If i remember correctly. in Ukraine students learn only very basics of calculus in 11th grade, while in UK, 12th and 13th grades almost fully cover calculus (please correct me if im wrong)

[obsidian harness]

well a lot of the depth in the UK A level system only comes in the final year (year 13 = grade 12)

so it's not that different from Ukraine

[upper karma]

hi

[signal root]

icl ts pmo, wy d we hv to stdy trg, lk its js so usls, i dnt wnt to d ts anymr

[heavy bison]

Someone explain trig? My teacher isn't the best at teaching.. He gives us problems and expects us to know

[silent plank]

what sort of problems are you being given?

[heavy bison]

Wdym?

[mystic umbra]

trig problems

erm like maybe solving sin²x-2cosx=sinx

[heavy bison]

I don't have any problems to show

I js needed help w like understanding

[mystic umbra]

side ratios

SOHCAHTOA

hmm

[heavy bison]

Wha

Let me just get a smth then... If it'll be easier

Finding the length of DE

[obsidian harness]

ah these ones, so right-triangle trig

[obsidian harness]

can you identify which side is the hypotenuse?

then the opposite side (to the 50 deg angle) should be easy to identify

the last side will hence be the adjacent

[heavy bison]

The bottom one??

I'm not sure actually

[obsidian harness]

yep!

there's a nice trick actually

the hypotenuse is always opposite to the right angle

a lot of people have never thought to see it like that

[heavy bison]

Ohhh

[sharp trout]

nooo noo

[heavy bison]

Teacher never said anything like that

[obsidian harness]

what

[sharp trout]

sry i just accidentaly typed what was on my mind

[heavy bison]

I is need a better understanding bc I have an exam in 5 days

Js

[sharp trout]

I just wanted to lurk in advanced mathematics to learn more, bu i selected just undegraduate math and was dissapointed assuming thta i can't change roles ;-;

[heavy bison]

What

[obsidian harness]

so for all of these right triangle problems there's a set procedure

it's like a maths recipe!

1. identify the opposite, adjacent, hypotenuse on the triangle
2. choose the 2 relevant sides: the one you have and the one you don't know
3. SOHCAHTOA to choose sin, cos, tan

4. then you can use this cover-up method to find the missing side

[upper karma]

yo man hru

[obsidian harness]

ah there's also ones where you have to find the missing angle, so it's actually the same steps except you just skip step 2
don't forget also that you can use Pythag to find all 3 sides

[obsidian harness]

hey

[upper karma]

remember me from igcse server

[heavy bison]

Ah yes.. It was js setting it up that was weird

[obsidian harness]

well yeah it's practice

[obsidian harness]

no sorry

but glad to see you here ig

[upper karma]

😭

[obsidian harness]

oh I think I might?

[upper karma]

yes

c'mon

hint

i do jee

[obsidian harness]

that's a million people here

[upper karma]

from igcse server

...

[obsidian harness]

okay sorry

[heavy bison]

Could you perhaps give an example

[obsidian harness]

https://mryangteacher.weebly.com/unit-6-right-triangle-trig.html

sorry these ones don't have answers

but yeah every trig test is like this one

[heavy bison]

What we did it had some sort of power symble

Symbol

I can't spell

[obsidian harness]

$^\circ$?

[somber coyote]

south

[obsidian harness]

that's the degree symbol

[heavy bison]

Noo I mean like

Hold on

Ok nvm im tweaking out

Is the ones that are connected any different

These,

[obsidian harness]

interesting

yeah well you can just erase BC and CD

it's just a classic "extra unneeded information in the question" scenario

[heavy bison]

Ohh ok

Yeah that kinda confused me 😭

[proper sinew]

hello. is this also the thread for modern geometries?

[obsidian harness]

yeah

I don't know what you mean by modern geometry though

[proper sinew]

im learning projective geometries

finite geometries

im talking bout geometries taught in undergraduate math

[trail tendon]

what sort of topics?

[proper sinew]

three-point, four-line, four-point finite geometries

[violet sequoia]

i told you they were cracked at math

🗿

[heavy bison]

... Doesn't make me hate it less

[violet sequoia]

Same

[upper karma]

TRIGONOMETRY AAAAAAAAAAAAAAAAAAAAAAA

[oblique patio]

It looks easy but I’m really struggling

[granite marsh]

I think @oblique patio all the triangles are isoceles

I think 1st u should find the height from the topmost Vertex to base

[mystic umbra]

for AO and CO you could just sine law cosine law bash

find side lengths of triangle AOC and bash

for AOB and COD, i suggest that you make a triangle with O and midpoints of AB and DC hmmm

then again, cosine law bash

[timid gale]

any tips for my geometry state test tomorrow?

im pretty bad at math so im trying to cram tonight before it need atleast the equivalent of a 70% for the grading scale

[silent plank]

draw diagrams

[plucky abyss]

Write what is given

Let answer be x, assume it is true

[slow pasture]

i use SACN, sine against cosine near.

it includes that tan=sin/cos

[worthy eagle]

I don't think there is enough information to solve it. Maybe I am wrong, can anyone give the solution?

[grave pond]

I think we need to assume that O is right above the center of the square base. So all of the edges touching O have the same length, by symmetry, and triangle AOC have known side lengths 17, 17, sqrt(2)·16

We can then solve some right triangles to find the distance between O and the midpoint of BC, and then the height of O above the base.

[worthy eagle]

Yes if you assume symmetry then it seems possible

[grave pond]

Without that assumption I agree there wouldn't be enough information.

[worthy eagle]

I was thinking how to get other sides or angles then I noticed it isn't dependent on anything. I can imagine grabbing the vertex and moving it up down, right, left in my head and the figure does change but it doesn't violate the given information so there are no fixed solution

Idk if you understand the grabbing vertex and moving it in my head part

[grave pond]

Yeah, without symmetry we could draw ABCD and then put O anywhere on a sphere centered at C.

[worthy eagle]

[grave pond]

Since A is outside the sphere, angle AOC could be anywhere between 0° and 180°.

[wary edge]

Hellooooo i need help figuring out how i can find a and b if both intercepts are given- i can't even figure out the slope TOT

[exotic yarrow]

Turn the intercepts into coordinates

[wary edge]

What am i supposed to do with those coordinates?

[exotic yarrow]

You said you can’t figure out the slope

But if you have coordinates

Then you can use the slope formula

[wary edge]

Oh wait so i use those coordinates and then i get the slope already???

Omg wait that was it????

😭😭😭😭

Thanks i would have never noticed that

[obsidian harness]

Clever problem

[fringe parcel]

a=-3 and b=10

[dark sparrow]

!nosols