geometry-and-trigonometry

[upper karma]

Terry

[grave pond]

Do not shout at the helpees.

[upper karma]

I'm shoutibg at terry

[faint pasture]

(the shit being done is shoutworthy but yea i agree with you apparantely)

[celest wave]

i dont get ittttttttt i still dont know what to do after u said 3.14 x 2^2 = 3.14 x 4 =12.56

[whole smelt]

keep 12.56

next step

:

[celest wave]

okok

[whole smelt]

it shows radius 2, hight: 3

[celest wave]

can u teach me like if im a 6 year old

[whole smelt]

ok

do you know the circumfrance of a circle?

[celest wave]

yes C=2πr

[grave pond]

You already had the right formula at A=2πrh+2πr², but here you were computing 2πh+2πr² instead -- the first r was missing.

[whole smelt]

thats the same as C=D x Pi

beacuse 2r is diamter

[celest wave]

ok so c = 2 pi 2 ??

[whole smelt]

so the diamer is 4 beacus e 2 x 2 is4

[whole smelt]

no

[celest wave]

ok

[whole smelt]

c = diamter x pi

[celest wave]

im writing that down

[whole smelt]

diameter is 2 x radius

[whole smelt]

no wait

[celest wave]

ok

[whole smelt]

only in this case

[grave pond]

Where did the pi go here?

[whole smelt]

whatever the radius is, that times 2 is the diameter

[whole smelt]

im explaining diameter

[grave pond]

Whoops, diameter not circumference. Sorry, ignore that comment.

[whole smelt]

k

[whole smelt]

so since the radius is 2, do 2x2. its 4 so 4 is the diameter

only in this case

cause it drepens on the diameter

[celest wave]

ok

[whole smelt]

so, since C = pi x D

Pi is irrational also so it is usually estematied to 3.14

Subbsitue wat u kno so far

D =4 and Pi is always about 3.14

so C= 3.14 x 4

[celest wave]

ohhh

[whole smelt]

C = 12.56

[celest wave]

does thta mean i can write it down

[whole smelt]

Write this:

Diameter is 2 x the raius, or D = 2r

C = D X Pi

[celest wave]

im gonna write d = 2 r

[whole smelt]

to find the green area do C x H

[whole smelt]

okay

also u dont need to write the green area thign

[celest wave]

3.14 x 3

[whole smelt]

no what is the ircumfrance found

[celest wave]

oh 12.56

[whole smelt]

yea, so 12.56 x 3

[celest wave]

37.68

[whole smelt]

um

yea

u found the green space

[celest wave]

which is the surface are / per container, right
?

[whole smelt]

what is

[celest wave]

37.68

[whole smelt]

no its the diameter x h

[celest wave]

oh

ok continue

[whole smelt]

and the green space + red shows it makes a full clinder

so wat was the area of 1 circle?

[celest wave]

π r²

[whole smelt]

in that case it was 12.56

[celest wave]

oops

[whole smelt]

ur right

in general it is pi x r^2

when u keep 2 for r beacuse 2 is the radius u get 12.56

[celest wave]

yes

now whats the next step

[whole smelt]

this shows that the circles are = to each other

so that means 12.56 x 2 is = one circle's area + the other. (or any circle's area x 2)

[celest wave]

okok

and then

[whole smelt]

12.56 x 2 = 25.12

[celest wave]

writing that down

[whole smelt]

no

[celest wave]

ok

[whole smelt]

write in a clinder the 2 ciclles are = to each other

[celest wave]

ok

[whole smelt]

the non yellow parts are equall

[celest wave]

yes

[whole smelt]

the non yellow + the yellow for the surface are for the clyinder

so add them

[celest wave]

37.68 + 37.68 = 75.36

[whole smelt]

25.12 (the top and bottem circles) + 37.68 (things surrowding or the yellow space) = 62.8 (the surface area)

[whole smelt]

no that was the yeloow

[celest wave]

ok

[whole smelt]

25.12 were the 2 circles, 37.68 are the yellow, togeter they make the suface are of 62.8

[celest wave]

can i write that down

[whole smelt]

write that the circles in a cylinder + the lateral suface are = the total suface area.

[celest wave]

ok

[whole smelt]

thats the answer!

done

[celest wave]

thank u

finally

[whole smelt]

ur welcome

[celest wave]

it took one hour

[whole smelt]

oh

[celest wave]

i will be back

[whole smelt]

i gtg

[devout elm]

GUYYYSSS.. need helpp..

1. wats differsnce b/w tan and slope in unit circle

[whole smelt]

what

[devout elm]

differnce between slope and tan in a unit circle (trig)

[whole smelt]

according to Fiveable: "
The tangent of an angle is defined as y/x, and we related x and y to sine and cosine above, we can conclude that tan(θ) = sin(θ)/cos(θ). It is also important to realize that the tangent function represents the slope of the terminal ray , which is the line extending from the origin to the point on the unit circle ."

@devout elm https://library.fiveable.me/pre-calc/unit-3/tangent-function/study-guide/MmhWdpovNDRCpyBgCc0x here

[devout elm]

uhh so they are same

k'

thx

also..

[whole smelt]

im not sure

[devout elm]

uhh

in digrams tehy draw tan as very differnt

wait

[whole smelt]

"the value of tan is equal to the value of sin over cos. So, the tan function for a given angle does give the slope of the radius, but only on a unit circle or only when the radius is one. For instance, when the radius is 2, then 2tan(45∘)=2, but the slope of the 45 degree angle is still 1"

so it can depend

I gtgt

*gtg

[devout elm]

ahhh .. kk .. bye

[whole smelt]

wait

ru still confused

@devout elm

use a help chanell

bye!

[devout elm]

but this is wayy fast

bye'

[whole smelt]

oh ok then

[devout elm]

doen

[whole smelt]

I dint queit learn that so im not sure sry'

bye!

[devout elm]

byee !! cya

[whole smelt]

cyae

[devout elm]

heyy .. anyone wanna help me 😦

[celest wave]

can someone help me with this?

,rotate

[devout elm]

heyy i also want help

[celest wave]

why is everyone so busy 😦

[devout elm]

all sleeping ig ?

[celest wave]

a lot of people used to be online

[celest wave]

r u in highschool

[devout elm]

yep

[celest wave]

what grade

[devout elm]

9 th

[celest wave]

wth and ur taking geo

wow im 11th

i hate math so much thats why im so late

when is the last day of school for u?

[devout elm]

i curently have summer vactions

[celest wave]

do u have summer homework

[devout elm]

yes .. havent event started 😎 \

[celest wave]

that sucks

[devout elm]

will do in last 5 days ..

[celest wave]

wait what

u already have to go back to school soon??

[devout elm]

uhhhhhhhhhhhhhhhhhhhhhh......... i still have a lot of holidays

and my hoildays started 1 mont ago

[celest wave]

so when do u go back 2 school

[devout elm]

1 july

[celest wave]

oofff

wow

that suckss

[devout elm]

yha.. but its that way .. cant do anything

why on earth is no one comming

[celest wave]

no idea

it used to be full

i remember

a lot of helpers

[devout elm]

i think i should try the help channe;

[celest wave]

am i allowed to tag helpers

yes

i tried that

no one answer

thats why im here

[devout elm]

ahh

[celest wave]

hopefully i wont get in trouble for this

<@&286206848099549185>

[devout elm]

btw wheer is teh discussion channel

[spark dune]

?

U need help?

[celest wave]

help us

[devout elm]

yayy

[spark dune]

Show

[celest wave]

help God first

[devout elm]

thx

[spark dune]

show

[celest wave]

me next please

[devout elm]

differnce between slope and tan in a unit circle (trig)

[spark dune]

ok

Tan function for given angle

Gives slope of the radius

On a unit circle

[restive musk]

@celest wave what have you tried

[celest wave]

i need help im dumb

i dont know anything

i havent payed attention

[spark dune]

Oh nah I’m not doing inches

[celest wave]

but i do know a little bit since others helped me

[restive musk]

have you learned the formulas for surface area of these shapes?

[celest wave]

some i remember

like. v = pi r^2 x h

[devout elm]

just put values

[restive musk]

yeah, that would be the volume of a cylinder

[devout elm]

and sole like a equation

[spark dune]

Btw I answered ur question

[devout elm]

i still have doubt

[restive musk]

what would you do if you wanted to find the radius when you have the volume and height?

[celest wave]

the radius would be 30?

or divide 30/2

[restive musk]

the first step is to divide by the height yes, then you would get the area of the circle in the bottom of the culinder

[celest wave]

ok 30/2 = 15

now what

[restive musk]

$A = \pi r^2$

[somber coyote]

caspar

[restive musk]

$r = \sqrt{\frac{A}{\pi}}$

[somber coyote]

caspar

[celest wave]

i dont have the radius yet so what do i put for r

[celest wave]

15/pi

[restive musk]

$\sqrt{\frac{15}{\pi}}$

[somber coyote]

caspar

[celest wave]

what does that equal to

[silent spear]

4.77464829

[celest wave]

thank u

[silent spear]

inches*

[celest wave]

so is that the answer for the surface area or am i not done yet?

oh

did we find the radius yet or no?

[silent spear]

$S = 2\pi r^2+2\pi r h$

[somber coyote]

clonesolopros

[silent spear]

this is the radius

[celest wave]

ok 4.77

[silent spear]

well it simplifies a bit

[celest wave]

so 2pi4.77^2 + 2pi4.77+2

[celest wave]

is that right

[silent spear]

$S= 2\pi \frac{15}{\pi}+2\pi \sqrt{\frac{15}{\pi}} 2$

[celest wave]

can i write that down in my paper?

[silent spear]

srry im not that good

[celest wave]

is ok

[silent spear]

$r^2 = \frac{15}{\pi}$

[somber coyote]

clonesolopros

[celest wave]

4.77 = 15/ pi

[somber coyote]

clonesolopros

[silent spear]

that

[celest wave]

ok i write this

[silent spear]

you can cancel out things

[celest wave]

what does that equal to?

[silent spear]

$S = 30 + 4 \sqrt{15 \pi}$

[celest wave]

noted

i understand

yes

[silent spear]

nvm

[somber coyote]

clonesolopros

[celest wave]

what is it equal to

[silent spear]

57.458737 in^2

[celest wave]

is that the final answer?

[silent spear]

yes I guess

[celest wave]

ty ty

[silent spear]

just as I joined and I already helped someone 😂

[celest wave]

thank you

can you help me with the next one

[silent spear]

sure

[celest wave]

this is what my answer looks like btw

[silent spear]

Cone: $V=\frac{1}{3}\pi r^2 h$

[somber coyote]

clonesolopros

[silent spear]

I would always put the units on the answer sometimes its important which unit you use

[celest wave]

ok

[silent spear]

Cone: $r^2 = \frac{3V}{\pi h}$

[somber coyote]

clonesolopros

[silent spear]

so...

Cone: $r = \sqrt{\frac{3V}{\pi h}}$

[somber coyote]

clonesolopros

[silent spear]

r is the radius of the base

Cone: $S = \pi(r^2+r\sqrt{r^2+h^2})$

[somber coyote]

clonesolopros

[meager skiff]

So I'm practicing my trig skills but have no ideas on how to start this

[harsh crow]

do u still need help

[harsh crow]

first

find one of the sides of the triangle

using the right triangles

[meager skiff]

I used tan for the one on the left and got 45

[harsh crow]

dont use tan

actually

tan is fine

[meager skiff]

😭

[harsh crow]

now

look at the 56 degree triangle

wait

i used tan

and got

34.5

[meager skiff]

Wait what

Djdjjejdbdhd

Wait I did a mistake on the calculator 😔

[meager skiff]

Do we round it then To 34.5?

[harsh crow]

always round at the end

anyway

now that we have the height of the triangle

cos 56 degrees = 34.5/x

[meager skiff]

Ily bro like what the

[harsh crow]

lmao

no big deal

[meager skiff]

Yo I've been stuck for the past 2 hours

[celest wave]

<@&286206848099549185>

someone help me

is this right

@grave pond hi

im so sorry to bother but do u think u can help

no one is helping me please

[silent spear]

@celest wave hi whats your problem? 😇

[celest wave]

can u check if its correct\

please

the circle is my answers

[harsh crow]

,rccw

[harsh crow]

lemme check

[celest wave]

thank you

im crossing my fingers hoping its correct

[harsh crow]

first is correct

[celest wave]

2nd

[harsh crow]

correct

[celest wave]

yay yay yay

yay

[harsh crow]

3rd cor

but uh

i think somethings incorrect

@celest wave

[celest wave]

whats incorrect

[harsh crow]

on the bottom

part

surface

area

cylinder

shouldnt it be 4a

not 8a

[celest wave]

why

[harsh crow]

scale factor is 2

so the surface area is 2^2 times bigger

[celest wave]

ok so do i just erase that and replace it with 2 instead of

8

[harsh crow]

no

4

bro

u did it for cone

correctly

are u good

[celest wave]

what

[harsh crow]

for cone

[celest wave]

u said im wrong

OH

[harsh crow]

yeah

[celest wave]

no

r u pok

[harsh crow]

do you get it

[celest wave]

no

u said this is wrong

part 5

cylinder

its wrong??

[harsh crow]

yes

[celest wave]

ok

whats the answer

[harsh crow]

idk im too lazy

but u wrote 8A

[celest wave]

ok

[harsh crow]

the area should increase to 4a not 8a

[celest wave]

what else is wrong

[harsh crow]

i think thats all

[celest wave]

oh

thanks pooki zooki dooki im sorry for u getting angry

[harsh crow]

its all gud

[gentle haven]

Why?

[celest wave]

hey do u edit

[gentle haven]

Wdym

[gentle haven]

Wait nvm

[frail hawk]

Can someone give me clue how to count x?
Just clue

[maiden brook]

is ABCD a square?

[frail hawk]

Yes

[maiden brook]

so the alphas are 60

[frail hawk]

Yes

I tried to do this but x dissapear

[violet pine]

Could someone help me with this I’m low key lost

I forgot how to find the time it takes for h to e ball to hit the ground

[maiden brook]

yeah hmm

oh

[maiden brook]

I think it’s actually that x = 90 and that the line is AD

[obsidian harness]

you just have to see what the value of t is when -5(t - 2)^2 + 20 = 0

[maiden brook]

cause if u let the supplement to x be y

by the exterior angle theorem u have x = y + 90 - y

[obsidian harness]

you can get to that by setting h = 0

the height is 0

[violet pine]

so t equal to 2?

[obsidian harness]

nope, (t - 2)^2 = 4

[maiden brook]

@frail hawk

[violet pine]

im sorry im a bit lost could you explain it step by step if you don't mind sorry

[obsidian harness]

add 5(t - 2)^2 to both sides: 20 = 5(t - 2)^2
divide both sides by 4: 4 = (t - 2)^2

now when you have to take the square root, two solutions are possible

so $2 = t - 2 $or $-2 = t - 2$

[somber coyote]

southy

[violet pine]

so it would take the ball 4 seconds to hit the ground?

[obsidian harness]

yep!

[violet pine]

okok thank you I appreciate it

[obsidian harness]

also t = 0 is possible but that means the ball was on the ground at t = 0

no worries

[obsidian harness]

btw how I actually worked this out was -5 * 4 + 20 = 0
so (t - 2)^2 = 4

you might find that easier

[frail hawk]

Thank you
I just realize something 😭😭😭
I found it

[maiden brook]

yeah so that’s what it is right

this is not a very good problem though

it’s purposely misleading

[tiny wren]

can some 1 help pls

[upper karma]

can u help us by increasing the quality of the image? @tiny wren

[tiny wren]

wdym

by that @upper karma

[subtle apex]

they want a higher quality image

[devout elm]

whats teh differnce between slope and tan in a unit circle /

[lime anchor]

Can someone help me with this? Each problem should give me a letter. Number 1 gave me the letter G

[upper karma]

what is 3d geometry called

like sphere, pyramid,cone

[upper karma]

wdym @upper karma

[devout elm]

DUDE HELP ME

differnce between slope and tan in a unit circle

[tranquil musk]

Hello

What is BPT or Thales theorem

[obsidian harness]

two different angles can give the same slope

these different angles are separated by 180 deg

[devout elm]

??

[devout elm]

can u explainn

[obsidian harness]

The point A and the point directly opposite to A both give the same line

Hence the slopes are the same and tan is also the same

[grave pond]

"Solid geometry" seems to be the most formal name.

[vernal nexus]

k

[celest wave]

help

,rotate

[restive sigil]

You have to calculate their surface area and their volume

then just divide

surface area/volume

the lowest number is the environmentally friendliest option

[celest wave]

um

can u do the brand a for me

so i can do the other ones

like as an example for me

and i can do the others

@restive sigil

[restive sigil]

Thats the gist of it

you just need the right formula for every geometric body

[celest wave]

im sorry to ask but can u write it bolder

i cant see

that much

@restive sigil

[restive sigil]

just open the picture in your browser then it should be better

[celest wave]

ok ty

@restive sigil

why is there 3 answers

i thought theres supposed to be 2

nvm i get it

thanks

wait i actually need help with brand b

because theres length width and height

[restive sigil]

no problem

[restive sigil]

its just a rectangle extended into 3d space

[celest wave]

umm

can u help me with it

please

im stupid

[restive sigil]

is that helpful?

[celest wave]

a little but like how do u put the formula

[whole smelt]

hi

[celest wave]

i dont know where to start off

[whole smelt]

?

L x W X H

[celest wave]

oh

ok so 4.5 x 4.5 x 4

[whole smelt]

for rectangulat prizam volume?

[restive sigil]

yes

[whole smelt]

what i sthe question

[restive sigil]

for volume

[whole smelt]

oh

[restive sigil]

.

[whole smelt]

Lenth X Width X hight

[celest wave]

ok the answer is 81

thats the final answer for surface area

right>

?

[whole smelt]

no

[restive sigil]

no volume

[celest wave]

ok

[restive sigil]

total surface area would be to add all surface areas together

[celest wave]

so now what do i do

[restive sigil]

calculate the total surface area

[whole smelt]

u just did volume tho

[restive sigil]

yeah she need volume and surface area

[whole smelt]

wheres the question?

[whole smelt]

oh

ok

[restive sigil]

then calculate the surface to volume ratio

[celest wave]

how

can u give me the formula

[whole smelt]

isnt this from yesterday?

here

Right rectangular prism
Solve for surface area
A=2(wl+hl+hw)

[celest wave]

no

[whole smelt]

A=2(wl+hl+hw)

[celest wave]

ok

[whole smelt]

for suface area

[celest wave]

whats the l for

[whole smelt]

lenth

[restive sigil]

this rectangle has 6 sides one is the front with width * height then the sides with lenght * height and then the bottom and top with width * length

[celest wave]

ok so

[restive sigil]

then multiply it times 2

to get the total area

[celest wave]

a = 2(4.5) + (4) + (4.5)(4)

like that

?

[whole smelt]

where are the values?

[restive sigil]

no rather a = 2(4.5 * 4.5 + 4 * 4.5 + 4 * 4.5)

[celest wave]

ok

[restive sigil]

.

[celest wave]

i will right that down

[restive sigil]

these are the values

[whole smelt]

L = 4.5in W=4.5in H=4in

[restive sigil]

yes

[celest wave]

112.5

[restive sigil]

sounds about right

and now volume/area

[celest wave]

112.5 is the answer for surface / area container

right

[restive sigil]

no 112.5 is the answer for surface and 81 for volume

[celest wave]

ok

what about total surface area for a year

[whole smelt]

wait no this says SA to Volume

[whole smelt]

it says SA to Volume

Is anyone there

||?||

[upper karma]

can i help again

[upper karma]

*365

[whole smelt]

okay

[celest wave]

hi

oh

ok

[upper karma]

considering he buys every day

[celest wave]

so thats the answer for total surface area for a year

?

365 x 112.5

[whole smelt]

ist it 365 x the sa

[upper karma]

yeah

[celest wave]

ok

i will write that

41062.5

is the answer

can we move on to brand C

[whole smelt]

so how does the paper look like now?

[celest wave]

i will show u

[whole smelt]

ok

[upper karma]

send the paper

over

[whole smelt]

also yester day when you said "I will write that I thoght you ment as notes"

[upper karma]

im a mere helpless being since yesterday

[celest wave]

,rotate

[upper karma]

find the area for the prism now

[celest wave]

ok

[upper karma]

6s(a + h)

[celest wave]

can u help

oh

ok

[whole smelt]

In A its Sa not Va

[celest wave]

6x2 (a + 3)

[upper karma]

u gotta erase

[celest wave]

noooo

what do i have to erase

is it a lot

[whole smelt]

this

right

[celest wave]

which one

brand b

?

[upper karma]

the apothem isnt given

so i think this'd be it

TSA = 6ah + 3√3a^2

[celest wave]

wait

rachit what do i erase

brand a

[whole smelt]

no

[upper karma]

john will tell

[woven estuary]

can someone help me understand the sohcahtoa stuff

[celest wave]

ok

[woven estuary]

like a basic explanation

[upper karma]

yeah

[celest wave]

jonathan which brand do i erase in what brand

[upper karma]

what sohcahtoa stuff u wanna know

trigonometry?

[woven estuary]

yeah

[whole smelt]

I think she was talking about b

but

[whole smelt]

but in a

[upper karma]

its just the ratios of trigonometric functions

nothing in it

[celest wave]

oh

sa

[whole smelt]

u kept VA insted keep SA

[celest wave]

ok so i write sa

[woven estuary]

i dont really understand it 😭

[celest wave]

ok

[upper karma]

you know basic triangles right?

[woven estuary]

wait can i ask u in a help channel

i have some basic problems

[upper karma]

i think its for high level problems

the math help

[woven estuary]

oh

can i ask here

[upper karma]

sure

[woven estuary]

is that allowed

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[whole smelt]

but this doesnt make sence

[upper karma]

thats what i used to use

[celest wave]

,rotate

[upper karma]

what do you want to find?

[celest wave]

i fixed it

[upper karma]

nice

[whole smelt]

ok good

[upper karma]

i can reply with emojis to activities damn

[woven estuary]

im not sure what my teacher meant by that but probably the angle opposite 22m? idrk

[upper karma]

hmm

[woven estuary]

is there anything else besides this and the right triangle stuff

[upper karma]

can u name the triangle

to clarify more

[upper karma]

yeah

[celest wave]

guys can someone help me with brand c

i will be back in 10 minutes or more the bell is about to wring

ring

[upper karma]

i need you to clarify the question more. @woven estuary

[upper karma]

bet

[celest wave]

see you

[woven estuary]

is that better

[silent plank]

ideally you want to use capitals for the vertices/angles
and the respective lowercase for the opposite sides

[upper karma]

yes

[woven estuary]

oh ok

i can set it up but idk how to solve it

[upper karma]

I hate trigonometry, why did I get pinged

where

[woven estuary]

i was tryinf to ping rachit sorry 😭

[upper karma]

use the sine and cosine

property

[upper karma]

lol you should've kept it so i'd know it was a mistake

[woven estuary]

idk the cosine property

[upper karma]

bro came in and said i hate geometry who pinged me lol

[woven estuary]

i forgot all this stuff

[upper karma]

yeah i got confused

[upper karma]

a^2+b^2-2abCosTheta = c^2

i think so

plugin the valuies

[woven estuary]

what's CosTheta

is that js cos

[upper karma]

Cos42

degree

use a calculator

[upper karma]

theta is a greek letter or variable for an angle

the bisected 0

[woven estuary]

is that to find the side length

[upper karma]

yes

[woven estuary]

how do i do the abCosTheta part on a calculator

[upper karma]

ahh

put a^2

+b^2

-2ab and find the value of the cos42 in a calc.

then root all that

[woven estuary]

wheres that

ph wait

do i have to put in cos42 first

i got 0.743

[upper karma]

hope i did the calc right

[upper karma]

you gotta clear your concepts

well for now

lets just put in the values

ok i have it

i think

[celest wave]

hi

im back

can u please help me

[upper karma]

@woven estuary

[upper karma]

yeah, what part now?

[silent plank]

work is incorrect

[celest wave]

after ur done helping them

[upper karma]

where

[celest wave]

i can wait

[silent plank]

the first line after the cos law

[upper karma]

one second

[woven estuary]

my calculator gave me a weird answer

[upper karma]

the law?

[upper karma]

use the brackets

[silent plank]

the line after it

[upper karma]

this one?

[silent plank]

you didn't use your values properly, assigned them to the wrong variables

[woven estuary]

brackets where

[upper karma]

c^2 &= 22^2 + 17^2 - 2 \cdot 22 \cdot 17 \cdot \cos(42^\circ) \

waiting for latex.

fuck

[silent plank]

note that from labelling conventions, side c is opposite angle C
using C = 42°, you c should be 17

[upper karma]

calculator, no brackets = wrong output

[upper karma]

im taking diff values

a = 17

[celest wave]

can u check if this is rifht

this is part 5

,rotate

[upper karma]

low quality

[upper karma]

what error

are u having

[silent plank]

which is why the way you're setting it up was wrong

[celest wave]

can u see

[silent plank]

you can use a = 17, but then you'd use the variant with cos(A)

[upper karma]

hmm right

[silent plank]

a^2 = b^2 + c^2 - 2bc * cos(A) with A = 42°

[upper karma]

im finding the unknown side

c is unknown

wont it give the same result?

[silent plank]

the lowercase still needs to be opposite the capital angle

[upper karma]

i think the results would be same.

latex do smth buddy

[silent plank]

not if you don't set it up properly

[upper karma]

can u try once

[woven estuary]

it gave me like 200 something as my answer

[upper karma]

now root it

[woven estuary]

14.73

[upper karma]

sqrt of that should be the answer, unless I identify the error @silent plank is pointing

give me 1 sec

[silent plank]

the way you're setting it up is wrong because
the way you're setting up, c represents the unknown side (which isn't opposite the 42°)

HOWEVER
in the cos law and triangle labelling conventions,
c represents the side opposite angle C
if your use of variables isn't consistent, you won't get the correct result

[upper karma]

oh

[silent plank]

if you want to use C =42°
lowercase c NEEDS to be the side opposite that which is 17

and you can assign the other sides to a,b

[upper karma]

is this right?

[silent plank]

no

[upper karma]

ok, then correct me

like the

convention

[silent plank]

do you know what opposite means

[upper karma]

yeah?

[silent plank]

side c is opposite angle C

[upper karma]

yeah

and

[silent plank]

lower case side is opposite capital angle/vertex

[upper karma]

so in this fig, side b is opposite to angle beta

[woven estuary]

huh

[silent plank]

like you "could" deliberately define your variables that way
(if you were a cruel person)

[upper karma]

which I am

[silent plank]

ideally you'd associate
A, a, alpha
B, b, beta
C, c, gamma

[upper karma]

yeah

[silent plank]

in your diagram A is being linked with beta which isn't ideal

[upper karma]

u said opposite

...

[silent plank]

same for
C with alpha,
B with gamma

[woven estuary]

wait so was the answer right or wrong

[upper karma]

right

[silent plank]

wrong

[woven estuary]

okk

💀

[upper karma]

ok solve

[woven estuary]

what

[upper karma]

he will solve for you wait

[celest wave]

rachit

[upper karma]

yes

[celest wave]

can u help me now or ru still busy

[upper karma]

send the ques

[celest wave]

brand c

[silent plank]

lets start with proper conventions, going to use capital letter for both the vertex and angle for convenience

[upper karma]

this diagram is the same as mine

[silent plank]

no its not

[upper karma]

yes it is

im not associating the vertex naming with the sides

[silent plank]

your side c is opposite vertex B,
side b oppsoite A
and side a opposite C

[upper karma]

im associating the angle naming

[silent plank]

ok, but when applying the cos law, you used the vertex letter instead of the angle

[upper karma]

so my ans is correct

wait

did i ?

[upper karma]

use the hexagonal prism

formula

[celest wave]

tell me

example

so ican plug in

[upper karma]

its

[celest wave]

itsss

[upper karma]

how do i type

in latex

[silent plank]

should probs move to a new channel because that turned into a complete mess

[celest wave]

just screenshot or write

draw

[upper karma]

well its correct

A = \frac{3\sqrt{3}}{2} s^2

this should work

[celest wave]

wth is that

[upper karma]

CMON LATEX

[celest wave]

😦

whats even latex

[celest wave]

ok

[upper karma]

tool

[celest wave]

what does that equal too

[upper karma]

calculate

[celest wave]

i dont have

calculator

sadly

[upper karma]

use ur brain 😭

like

hand

[celest wave]

i dont have a brain

[upper karma]

hands

what

[celest wave]

i never solved

[upper karma]

life isnt that easy

[celest wave]

i have brain fog

[upper karma]

i may solve it for you

[celest wave]

9/2

= 3

[upper karma]

but it wont always happen

[celest wave]

yes

am i correct

[upper karma]

bro 9/2 is 4.5

not 3

[celest wave]

oh

oops

[upper karma]

it'd be 6*root(3)

[celest wave]

so whats the answer

18

or 36

[upper karma]

approx 10.39

[celest wave]

216

what

[celest wave]

thats the answer?

[silent plank]

what you're doing is. and trying to use cos(C) instead of cos(gamma, the angle that's actually opposite side c)

[celest wave]

for surgace are / per contianer

[upper karma]

just solve for her

[upper karma]

for 1 day, yes

per container

no wait

fuck

i forgot

[celest wave]

ok

ok

[upper karma]

the

[celest wave]

so what da answer

[upper karma]

its for one hexagonal base

[celest wave]

for surface area

[upper karma]

for two its 20.78

and for rectangle faces

its total 36

[celest wave]

the answer for sa is 36

[upper karma]

so 20.78 + 36 = 56.78

[celest wave]

ok ok

ok

im writing that

[upper karma]

per year it'd be around 20723.7

approx value

[celest wave]

ok

do u wanna

wsee

my paper

too double check

to*

[upper karma]

ok

[celest wave]

,rotate

[celest wave]

lil b

based god

[upper karma]

can u take

better photos

[celest wave]

ok

i was lazy

[upper karma]

thats not how life works.

[celest wave]

i know

[somber coyote]

Result:

20724.7

[celest wave]

,rotate

[celest wave]

is that better

[upper karma]

I ALWAYS DO THE RIGHT CALCULATIONS

what happened

this time

maybe typo

wait

yes

its 724

[upper karma]

replace it with the 20724.7

[celest wave]

is it right rachit

[upper karma]

hm yea

[celest wave]

ok

can u help brand d

[upper karma]

area of base is s^2

Area of Base=2*2 = 4 inches

4square inches

[celest wave]

ok

noted

and what about the hieght

what to do

[upper karma]

wait

$\text{Area of one triangle} = \frac{1}{2} \times \text{base} \times \text{slant height}$

[somber coyote]

'Rachit

[celest wave]

hacker

[upper karma]

no wait

wrong formula

[celest wave]

1/2 x 2 x 5

o

ok

[upper karma]

$\text{Total Area of Triangles} = 4 \times \left( \frac{1}{2} \times 2 \times \sqrt{\left(\frac{2}{2}\right)^2 + 3^2} \right)$

fuck

[celest wave]

still wrong

its ok

[upper karma]

is it right?

[celest wave]

i dont knwo

helpers

<@&286206848099549185>

dont kick me

i need this to be done

[upper karma]

wait

[celest wave]

can i copy that

[upper karma]

this is the slant height

[silent plank]

why 3^2

[upper karma]

put it into the area of triangle formula

[upper karma]

height = 3

[celest wave]

ok noted

[silent plank]

height = 5

[celest wave]

yes

i was going to say that

[upper karma]

then put 5

[celest wave]

okok

[upper karma]

shit image quality

[celest wave]

no

[upper karma]

yeah its 5

[celest wave]

iphone 13 pro max

[upper karma]

ok put 5

[celest wave]

ok

done

[upper karma]

did i ask

[celest wave]

sorry

[upper karma]

root(26)

then the area of triangle would be

1/2x2xroot(26)

whatever that is

then 2 would cancel 2

so its 4*root(26) cus of 4 sides

triangles*

then sum 4*root(26) and area of base = 4

u get per container

[celest wave]

SA= 4

[upper karma]

yes

[celest wave]

and noww

365 x 4

is the total surface area for a year

[upper karma]

no

[celest wave]

what

why

[upper karma]

.

[celest wave]

wait

[void roost]

Pls help 😟

[celest wave]

so whats the total surface area for a year

[upper karma]

do the maths

[upper karma]

is it 112?

[celest wave]

20.39607805

[upper karma]

are u sure

[void roost]

272 is the answer

But how?.

[upper karma]

let me thinjk

is it coordinate geometry ques or what

[upper karma]

use the .calc cmd

.calc root(69)

whats the cmd

,calc root(69)

[somber coyote]

The following error occured while calculating:
Error: Undefined function root

[celest wave]

undefined

[upper karma]

,calc sqrt(69)

[somber coyote]

Result:

8.3066238629181

[celest wave]

ok thats the total surface year

area

[upper karma]

no

[celest wave]

what