geometry-and-trigonometry

[dire meteor]

hello can someo ne help me with a problem

[trail tendon]

whtas the problem

[dire meteor]

can i copy paste it here

[trail tendon]

sure

[dire meteor]

it shouldnr rake to loong i

its geometry

basic

did u get it

what would the work and answer look like for that

[trail tendon]

how do you find the odd one out?

[onyx bough]

i got a B in it last summer ☠️ good luck

[dire meteor]

can someone solve this

[devout elm]

its written its a message

[trail tendon]

what is it?

[devout elm]

is there more info in question

[trail tendon]

i don't see any 💀

[faint pasture]

upload a normal file format

[faint pasture]

how can i find the minimum distance of a given point from a curve? (without differentiating that is)

[dusky locust]

depends on the “curve”

[faint pasture]

well is there no way for it to be generalisable to all continuous curves

[dusky locust]

i’m not sure how you’re expecting to generalize a problem like that without calculus

[quick stump]

what's a codomain?

oh nvm

[onyx leaf]

given 3 circles, the coordoantes of their centers and their radius, let's say I have two points A, B, also with given coordonates, so that they form an arc. How can I check if the arc(A,B) intersects with any other circle? for example with circle with center F in my draw

what I mean is, how to check that smaller arc AB intersects with circle F, while longer arc AB intersects with circle E

or any link to where I can read about this particular case would also be great 🙂

[faint pasture]

well one way would be to find the point of intersections first
then find the slope of the AC, BC and the points of intersections with C, and if the slopes of points of intersection and C are in between the slopes of AC and BC then it would lie both the point would lie in the arc

but it looks like theres probably a better way which im looking over rn

[onyx leaf]

I don't really have experience with geometry, but my idea was to check if the two circles F and C intersect (comparing the distance between centers and the radius). and if they intersect, to somehow see if AB is oriented to circle F or not (if this would be possible)

because if I have A(a1, a2), B(b1, b2) and F(f1, f2), and I know that F intersects with C, then could I check that f1 is between a1 and b1 and f2+radius of f is between a2 and b2?

not sure if it makes sense

[faint pasture]

well checking for intersections is rather doable, get the equations for both circles

then find the solutions

[faint pasture]

the f2+radius of f part doesnt seem right to me

[onyx leaf]

f2+radius compared to a2+radius and b2+radius

each with their radius

right, it's wrong

[faint pasture]

that wont probably be the case, judging from the diagram

[onyx leaf]

what if, if circles F and C intersect, then I have to check if line CF intersects line AB?

for example, CE does not intersect AB

[faint pasture]

oh thats a good approach

[faint pasture]

CF intersecting AB is enough to check if the arc intersects the circle too

provided that we know the circle intersect

[onyx leaf]

yep, thanks a lot 😄

[deft drum]

I see, now I also got the essence of implication $p \to q$

[somber coyote]

ĐARK々MÁTTER

[deft drum]

Its not like that function can't take negative real numbers, but the area of disk is defined for positive real numbers. Right?

[grave pond]

So what we'd consider the default "domain" depends on which definition we're looking at.
If the definition is "area of circle with radius r", then the domain (unless something else is specified) would be the positive reals.
If the definition is "pi times the square of r", then the domain (unless something else is specified) would be all reals.

[tranquil mirage]

yo can you hit me with a random trig question

i will attempt to solve it

[faint pasture]

simplify tan(x/2)(1+sec(x)(1+sec(2x))....(1+sec(2^nx))

[faint pasture]

here

[tranquil mirage]

not that deep into identities yet TnT

is it 1

[faint pasture]

nope, also it is not too many identities

do you know tan(2x) and cos(2x)?

[tranquil mirage]

idk tan(2x) is sin(2x)/cos(2x)?

[faint pasture]

sure but thats not what am looking for

well if you dont know these there is no fun que i can give

[tranquil mirage]

well ill try i guess

[faint pasture]

ah if you dont know the identity then you cant do it dont waste your time ig

[tranquil mirage]

cos2x = 1/2(cos^2-1)

or was it +1

idk what sin2x is

[tranquil mirage]

i just learned it, the power reduction thing

but im not sure if im doing aight

[obsidian harness]

nope, cos 2x = 2 cos^2 x - 1

you got it confused with the rearrangement for cos^2 x

[faint pasture]

then youll have to write this in terms of tan for the question

[tranquil mirage]

sec is the reciprocal of cos iirc wait

im trying to remember stuff

[obsidian harness]

yep

[tranquil mirage]

lemme do it step by step

[somber coyote]

Tetronix

[tranquil mirage]

istg this will be messy

[faint pasture]

i mean the solution is much simpler

[tranquil mirage]

I dont know identities fully so ill just wing jt

[faint pasture]

💀 i doublt if its even possible without the identity

[tranquil mirage]

i mean, im solving, can I have a list of the identities i could use pls

would serve as nice reference material

[faint pasture]

i dont have one rn

but all you really need for this one is

cos(2x) = (1-tan^2(x))/(+tan^2(x))
and tan(2x) = 2tanx/(1-tan^2(x))

[warm minnow]

lowkey cursed ngl

my brain can't comprehend anything rn

[tranquil mirage]

cos(2x) = (1-tan^2(x))/(1+tan^2(x))?

[faint pasture]

hmmm

[faint pasture]

💀 idk its rather doable if you know the identities

[warm minnow]

ain't sinx just 1/cosx? or am I tripping balls?

[tranquil mirage]

whats the elipses for

[faint pasture]

you are

[tranquil mirage]

do I just multiply that fourth one too

[faint pasture]

the terms in the middle

its like an series

[tranquil mirage]

is this even correct

[obsidian harness]

tripping

sec x = 1/cos x

[faint pasture]

no

there are a lot of terms in between that (well it depends on the value of n but yea)

[tranquil mirage]

so ur telling me im dealing with a potentially infinite series (without the summation)

[faint pasture]

who said anything about n approaching infinity

its finite

and the answer is just one term

[tranquil mirage]

that's secx

[tranquil mirage]

yeah i dont think im at that level yet

sorry

[valid gull]

trippin

[velvet relic]

HOI

[faint pasture]

oh drug guy

[velvet relic]

PLZ MAN

I MISSPELLED MATH

[faint pasture]

did you 🤡 ?

[velvet relic]

YEP

I AM AN 8TH GRADER

[faint pasture]

are you sure

[velvet relic]

YES

[faint pasture]

8th graders and drug guyz arent mutually exclusive

[velvet relic]

what does that mean?

[faint pasture]

you can be both at once

[velvet relic]

yes

I am a 8th grader

not a drug addict

[faint pasture]

lol i trust you

i definitely do

[velvet relic]

thanks

[faint pasture]

(do i?)

[velvet relic]

yes

[devout elm]

how much time does it take to get rid of the newbi header

[vernal pilot]

?

[vernal pilot]

Idk what that is, also this probably isn’t meant for this channel.

[shut bronze]

it's either 1 week or 2 weeks I forgot

you can just google it

[devout elm]

ok

[frozen ocean]

a week

[devout elm]

ohhh cool

[frozen ocean]

although it doesn't show on mobile

only pc

[shut bronze]

yeah

[warm minnow]

Balls so go-

omw to find the list of identities ig

[foggy granite]

someone help me

im gon die

[obsidian harness]

just ask your q

[drifting turtle]

look at AC

[foggy granite]

k

[faint pasture]

uhm i tried this and got (4,4) can anyone confirm

[keen rain]

First solve for ac with then use that to calculate bc. You should leave ac as a square root when you calculate it because you need to square it again anyway to get bc

[grave pond]

Yes, (4,4) looks right. I wonder if there's a typo in the problem -- where would all those sevenths in the answer options come from?

[faint pasture]

yea
i mean 3+4 is 7 but i dont see how it could have a connection to this problem at all

[neat python]

can someone help me

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[neat python]

3 i got wrong answer and idk how to solve it differently

[grave pond]

In that case you should describe how you got that wrong answer, which answer you got, and how you know it is wrong.

[neat python]

to be honest i was doing random tests in google and i dont know how to solve it XD and it would be helpfull if someone explain it to me if he/she has free time

[faint pasture]

nd what was the wrong answer you got?

[grave pond]

I know you've just been redirected once, but I don't think this is really a trigonometry problem. Saying "sin(blah)=0" is just a way of saying "blah is an integer multiple of pi", and from that point onwards, there's no trigonometry left.
Where did you find this problem? To be honest, it smells more like a #competition-math problem.

[neat python]

i got k=6 a=29

[faint pasture]

there is no k in here

[faint pasture]

i mean sure

but like blah = 0 is the intended solution probably

[neat python]

okay ty

[faint pasture]

oh no lol

[faint pasture]

ah soo yea you dont need any of that

basically it's given that sqrt(ax - x^2) = npi
square both sides
x^2 - ax + (n*pi)^2 = 0

by vietas relation

sum of solutions = a

but its given to be 100

so yea

[grave pond]

I don't think so, because you should be summing the solutions over all values of n.

[faint pasture]

for all values of n its just gonna be 100, so if we do that then the answer is just infiinity

oh nvm

[grave pond]

Yeah, that looks odd.

[faint pasture]

the que asked for the value of a anyways

[grave pond]

It looks like no matter which a we pick, there will be infinitely many values of x such that sqrt(ax+x²) is a multiple of pi.

About half of those infinitely many solutions will be negative, so what would it even mean that their sum is 100?

[faint pasture]

the que didnt ask for x though

it asked for a

[grave pond]

The question asked for values of a with the property that the sum of { x | sin(sqrt(ax+x²))=0 } is 100

[faint pasture]

yea

a is gonna be 100 in all cases

[grave pond]

In the vacuous sense that there is no a such that the sum of { x | sin(sqrt(x(a+x))) = 0 } is even defined!

So "a is 100 in all cases" only because there are no cases.

[faint pasture]

its sqrt(ax-x^2) not sqrt(ax+x^2)

[grave pond]

Oh whoops.

[neat python]

btw

need help on this too XD

[faint pasture]

also idk what if im getting you right, but a = x is a solution to the que always so yea

[neat python]

 For what value of parameter B(cost; sint) and C(-cost; -sint).t will the area of ​​triangle ABC be the largest
value if t∈(0;1)?```(translated)

[faint pasture]

well do you know formula for area of triangle if vertices are given?

[grave pond]

x is an unknown. You can't set a=x because x doesn't even exist outside the question!

[neat python]

yes

i want to make sure that answer is correct XD

[faint pasture]

but for all values of a, whenever x = a, the original condition is satisfied not talking about the sum part rn just the sin() part

[grave pond]

Okay.

Need to go afk for 30-40 minutes, may get back later.

[faint pasture]

and then for sqrt(ax-x^2) when it is equal to zero
we get x = a or x = 0, and acc to the given condition a + 0 = 100, hence a = 100 so like there is definitely at least 1 solution

[neat python]

got like that

[grave pond]

Hmm, I think we were both wrong ... but each of us was also a bit right, so we can possibly salvage a full solution.
a=100 is not one of the answers, though.
It's true that x=0 and x=100 both solve sin(sqrt(100x-x²))=0. But there's a different pair of solutions that make sqrt(100x-x²)=pi, and another pair of solutions that make sqrt(100x-x²)=2pi, and so forth up to the pair of solutions that makes sqrt(100x-x²)=15pi.
The maximal value of sqrt(100x-x²) is 50, which is less than 16pi, so the solutions end there.
We want the sum of all those 2·16 solutions for x to be 100 -- but actually (as you pointed out) each pair sums to 100, so the sum of all of them is 1600, which is not the 100 it should be. So a=100 is out.

[neat python]

yes

[grave pond]

If we choose a smaller a, two things happen: 1) each pair of solutions only sum up to a; 2) there are fewer pairs of solutions to sum, namely only as many as there are multiples of pi in [0,a/2].

So the sum of solutions should roughly scale as the square of a. Since a=100 gave a sum that was sixteen times too large, let's try a=25.

The maximum of sqrt(25x-x²) is 12.5, which is just below 4pi. That's good, because we get a pair of solutions from each of {0,pi,2pi,3pi}. The sum of all those solutions is then 4·25 = 100. 🎉

Looking closer at the argument above, it actually tells us that the sum of the solutions increases monotonically with a (with jumps when a/2 passes a multiple of pi). So anything above a=25 will be too large; anything below it is too small.

So a=25 is the single parameter that gives the desired result.

[celest wave]

can someone help me with this

[clear owl]

Do I get the maximum/minmum value of a sinusoidal function by dividing the 360 by the k value?

[grave pond]

No, almost certainly not.
(With the caveat that I have no idea what you mean by "the k value" -- but dividing 360 by anything doesn't sound like something that ought to give values that belong in the output of a sinusodial function).

[ruby flame]

use volume of a cylinder, $V=\pi r^2h$

[somber coyote]

jasoney

[celest wave]

is this right

[sand epoch]

bro im not checking your homework if you cant even format it right 💀

[cunning lion]

,rotate

[celest wave]

why is everyone mean i dont know how to do that and its straight for me in my camera roll

[trail tendon]

how did you get 61.77

[hoary prism]

i was trying to figure this out

i got 7*2^pi = 61.7748447895

no idea how one would come to that tho

[trail tendon]

so you got 61.77

but you don't know HOW you got 61.77

so uh

[hoary prism]

Nah it doesnt have anything to do with this problem 😂

[trail tendon]

oh bruh 💀

[hoary prism]

i was just trynna figure out where that number couldve come from

LMAO

but yeah how did you get 61.77 @celest wave

ignore what i said above

[trail tendon]

your answers are right except the third one

there aren't necesarily 30 days in a month 🤔

XD

it prolly wants u to do that tho

[faint pasture]

damn that question gave a fun ride

[faint comet]

Can someone please explain to me how it’s b-a when there’s no b or a line ??

I’m struggling really bad with proof with vecotrs

[lime dune]

take some arbitrary point O to be the origin

now draw the vectors from O to A and from O to B

[obsidian harness]

Don't forget the direction matters!
So you go backwards, from A back to O

That's negative a

a is O to A ofc

So what I'm saying is that AO + OB is just -OA + OB

[lime dune]

^ that too lmao

[fluid lynx]

Can someone help me with (ii) (iii) (iv)?? I know it might be a dumb qn BC I just started learning by myself and I don't understand anything 😭😭😭

[deep tangle]

so cos40=sin50

sin50=sin130 there fore ii=k

tan230 = tan(270-40) which is
tan40 = sin40/cos40
since cos40 equals sin50
sin40= 1-k^2 in a root is equals

1-k^2 in root/k

[fluid lynx]

Tysm!! Lol I was so confused by how many formulas there were 😭

[deep tangle]

is iii

[deep tangle]

you're welcome

do u need iv

[fluid lynx]

Yes pls

[deep tangle]

ok wait a second

[deep tangle]

do u understand this

i explained like shity

[fluid lynx]

Wait I don't get where the tan 40 came from

[deep tangle]

for iv: if we add 360 to -220 we'll find 140 degree which is sin140 and sin40 and it equals 1-k^2 in a root

[deep tangle]

it is tan230 right?

if u do

tan(270-40) u will find tan 230

and because of the trigonometry rules tan(270-40)=tan40

these are reductions

[fluid lynx]

Ah now I see

[deep tangle]

ask me anything u didn't understand

[fluid lynx]

Can I use tan(360-130)?

[deep tangle]

sorry it's cot40

not tan

[deep tangle]

as i know u have to do it as near as possible

the angle you're reducing must be an acute angle.

this is the correct answer actually

You can't reduce angles greater than 90

[fluid lynx]

Oh OKK tysm for Ur help

[deep tangle]

you're welcome have a good one

[fluid lynx]

Wait so how to do

[deep tangle]

it's reverse

nothing's changed

tan40 = 1/cot40

[fluid lynx]

Oh gosh that's dumb of me thank U sm I just realised ,,

[deep tangle]

no

no

take your time lol

cya

[fluid lynx]

Bye :))

[celest wave]

$\lim_{n \to 0} n^n = 1$ — Yesterday at 5:59 PM
day = 1d
week = 7d
month = 30d
year = 365d
Are u seriously asking this blud?

[somber coyote]

exloria

[celest wave]

someone told me

[faint comet]

Like wdym

[celest wave]

Mika — Yesterday at 5:47 PM
close
we need to consider the units
so its π (2in)^2 *3in
= 61.77

[trail tendon]

February be like:

[celest wave]

yes can u help me

please

[trail tendon]

3 * 2^2 * pi is not 61.77

what are the "correct units"

is it not in^3 ?

[celest wave]

no

[trail tendon]

what are the correct units then?

oh is 61.77 the density of the yogurt?

no :l

[celest wave]

61.77 is the units

[trail tendon]

units is not a number

units is like

pounds

or feet

or ounces

how did you get 61.77

did you convert inches to some other units?

[celest wave]

its 61.77 in^3
thats the volume of one cup of yogourt
now x5 for one day
x35 (= 5x7) for a week and so on...

[celest wave]

someone told me that

Mika — Yesterday at 5:47 PM
close
we need to consider the units
so its π (2in)^2 *3in

[trail tendon]

i'm 99% sure someone is wrong

unless you changed the units

but nah you said in^3

pi (2in)^2 * 3in = 12pi in^3 is not even close to 61.77

[celest wave]

so did i do everything wrong

[trail tendon]

yea i mean your base cyllinder volume was wrong

[celest wave]

noooooooooooooo

[trail tendon]

but all you have to do is compute 3in * (2in)^2 * pi

[trail tendon]

its not hard to fix 😭

[celest wave]

do i erase everything

[trail tendon]

no

the stuff in the boxes maybe

[celest wave]

that would equal to 617.77 right

[trail tendon]

its about 37.7

its also 12pi

i don't know how exact they want you to be

[celest wave]

it says round all answers to decimal places

[trail tendon]

to 2 decimal places mk

since its 37.699 i think it wants you to put 37.70

then you can multiply it by 5, and by 35, like you did before ect.

[celest wave]

so i erase 61.77 and replace it with 37.70

[trail tendon]

yea

[celest wave]

ok for a day i got 188.5

[trail tendon]

i would actually use 3 * (2)^2 * pi in your calculations

instead of 37.70

:L

and then round each number

like use 12pi * 5 = 188.495559 = 188.50

[celest wave]

ok so no more using 37.70? i switch it to 188.50 x 5

[trail tendon]

no, instead of 37.70 use 12pi

to calculate

because its accurate

[celest wave]

12pi x 5?=188.49

[trail tendon]

thats the first one

yeh

because 12pi * 5 * 7 = 1319.47 whereas 7 * 37.70 * 5 = 1319.5

and the more you multiply the more off you become :l

[celest wave]

1319.47 is the second answer

[trail tendon]

yeah

[celest wave]

for a week

[trail tendon]

yea

and i think you can assume a month is 30 days but that question is horrible because that is not necesarily true, depends on the month :l

[celest wave]

its ok i will tell my teacher about that

[trail tendon]

alr

[celest wave]

12 pi x 5 x 30 =5654.86677646

5654.87

[trail tendon]

yes

[celest wave]

12 pi x 5 x 365=68800.8791136

68800.88

and for the last question is it correct?

[trail tendon]

lemme see

yep

[celest wave]

okay thank so much

[trail tendon]

i mean

you still have to do the last last question

[vernal pilot]

Bro how are you in every channel???

[celest wave]

i would have to solve it?

[trail tendon]

isn't it your homework?

[trail tendon]

lol

[celest wave]

no thats not what i mean sorry

because this guy just told me to leave it like that

[upper karma]

how are u everywhere bro

[trail tendon]

💀

bro i talk in like 2 channels and suddenly i'm "everywhere"

[celest wave]

he said "Literally do the numbers I did the process
"

[trail tendon]

except 61.77 is wrong

[upper karma]

everything, everywhere, all at once

[celest wave]

ohhh

ok so do i put 12pi

[trail tendon]

instead of 61.77 yeah

um

how many ounces in a cubic inch?

[celest wave]

1

[trail tendon]

1 ounce? nah 💀

like serious question

is i 0.585 i do not know lol

[celest wave]

0.554

[trail tendon]

oh nah they said .585 ounces in cubic inch

0.585 is correct

mb

[celest wave]

okay thank u

can i please add u i have more questions later

[trail tendon]

why is there another 6?

sure

[celest wave]

where

[celest wave]

i dont know

[trail tendon]

💀

[celest wave]

i erased it

[trail tendon]

well

yeha ok

[celest wave]

i doodle

[trail tendon]

XD

[celest wave]

droodle i dont know whats it called

im going to take a picture one more time of my paper to double check

[trail tendon]

yep now evaluate it

[celest wave]

i also removed the 37.70 replacing it with 12pi

[trail tendon]

is called doodle

[celest wave]

evaluate what

[trail tendon]

12 * pi * 365 * .585 * 0.0625

with correct units

[celest wave]

in the bottom??

[trail tendon]

yeah

its asking how many pounds

you should have like <a number> lbs

you have it set up but now you have to evaluate

multiply it out

prolly with a calculator

[celest wave]

503106.428518

503106.43 is the answer

[trail tendon]

uh

[celest wave]

i put it in google calculator i dont have a real one with me right now

[trail tendon]

oh wait

btw it needs uh

0.585

not 585

mb i shoulda seen that

right

cuz theres 0.585 ounces in a lb^3

[celest wave]

okay so its 503.106428518

503.11

[trail tendon]

uh

12pi * 5 * 365 * 0.585 * 0.0625?

i got sum different

[celest wave]

ohh

i forgot the 5

[trail tendon]

💀

[celest wave]

2515.53214259

[trail tendon]

yes

[celest wave]

2515.53

[trail tendon]

yes

[celest wave]

like this

how do u rotate

,rotate

[trail tendon]

😭

😂

uh

i think you should just do this honestly

or sorry a rounding equals

not regular equals

like this

and make sure you put the units (lbs)

[celest wave]

,rotate

[celest wave]

is everything good now

[trail tendon]

yep!

[celest wave]

yay thank u so much

[plain scarab]

Can anybody help me

Ik it’s a dumb question but

I wanna make sure it’s right

[trail tendon]

wouldn't it be r(180, 0)

360 would be a full rotation, 180 a half rotation

[plain scarab]

Ah ok

[trail tendon]

it only does a half rotation right?

yeh

[plain scarab]

Tysm

I need an explanation on this

Sorry for the blur

I just don’t understand

[undone flicker]

i think its A

[undone flicker]

option 2

[trail tendon]

how u know

[trail tendon]

do u understand or nah

💀

[plain scarab]

Yea it makes sense now

Thanks

[trail tendon]

alr

[plain scarab]

I just like

bad at math

[trail tendon]

nah bro

[plain scarab]

I gotta lock in

[trail tendon]

XD

[plain scarab]

Is this right?

[trail tendon]

yes

[plain scarab]

ok one more I promise

[trail tendon]

XD

theres a reason this chat exists lol

[plain scarab]

is this right as well

[trail tendon]

yes

[plain scarab]

Let’s go

[trail tendon]

xD

[plain scarab]

💪💪

Thank you

most of the 25 minutes was spent on my phone

😭

[trail tendon]

🗿

[obsidian harness]

Canvas is everywhere man

[upper karma]

Is that cg?

[obsidian harness]

hey Rachit longtimenosee

[upper karma]

hi southy

I forgot about this server lol

[obsidian harness]

oh lol

[elfin cave]

Does anyone have the formulas for special right triangles? ive lost my notes and i cant find any resources online

[lime dune]

are you sure there's nothing online?

what did you search

[elfin cave]

"Formulas for special right triangles" all i see is like different types of triangles like 30-60-90

[lime dune]

it should tell you the ratios of their sides?

anyway i'll help you out and pass along smth i wrote up a while back

(you likely don't need the 15-75-90 stuff)

[elfin cave]

Thank you

[left elk]

I scored 100% on my geometry final.

And did pretty well in my semester class honors accelerated trig.

And although I'm not in calculus, I can already do basic derivatives like f(x) = x^2 + x + 1

(And therefore I can do the integrals of those functions)

[sturdy stone]

congrats

[plain scarab]

What’s cg mean

[plain scarab]

It really is lmao

I’ve used it my whole life

😭

[upper karma]

wow

[upper karma]

oh, coordinate geometry

[plain scarab]

Ah ok

[upper karma]

congrats, pikachuballs27

[plain scarab]

I think it indeed is

[upper karma]

damn

glad to know

[plain scarab]

I’m back again

does anybody know how to do this

[shut nest]

determine the dimensions of both the pre image and the image

measure the key dimensions for both shapes

then calculate the scale factor

scale factor = width of A'/width of A

[plain scarab]

Ty 🙏

[plain scarab]

Can anybody help with this?

[plain scarab]

What the

How’d I get 2 wrong

Oh nvm

I think it’s the bottom one

[wind shard]

Sketch:

We have a quadrilateral, M und N are the midpoints of the diagonals. From N and M we, respectively, construct a line that is parallel to the other diagonal, the intersection is O.
Does someone know why NH=1/2*CD and NE=1/2BC?

[grave pond]

NH=CD/2 doesn't look true in your sketch.

You have switched N and M around in your drawing.

[wind shard]

oops, you're right

[grave pond]

Triangles AHM and ADC (with your names) are similar.

[wind shard]

Sorry, my geometry is a little rusty. I see that they share an angle. Is <AHM the same as <ADC?

[grave pond]

AD and AC are twice as long as AH and AM, respectively.

[wind shard]

Right.

And then, because these are similiar we have that MH=1/2*CD?

[grave pond]

Yes.

[wind shard]

Okay, think I got it. Thanks. I will have to brush up on similarity. It seems as if, given the similarity of ADC and AMH, the fact that AH=1/2AD and AC=1/2AM dictates that also MH=1/2*CD. The ratio of (all!) sides must be the same.

[grave pond]

Yes.

[dire grove]

I FUCKING HATE GEOMETRY!!!!!!!

[trail tendon]

real

[dull pilot]

how do i calculate P

no trig if possible

apparently calculating p is possible using vectors and shit

[celest wave]

,rotate

[celest wave]

can someone help me with this please

[proud nest]

How is alpha 50? Shouldn't it be 40?

[grave pond]

270° + 50° = 320­° ?

[proud nest]

oh

oh my gosh im dumb my bad

[celest wave]

,rotate

[celest wave]

,rotate

[faint pasture]

shouldnt it lie on two straight lines ie, a = 0 and a = b?

[silent plank]

don't conflate concurrent with coincident

or how are you reaching that conclusion

[faint pasture]

oh shit

[faint pasture]

well the matrix condition

thanks

[sharp ruin]

Concurrent just means intersecting right?
We just need to solve for x and y separately

Like we do to all linear equations

[faint pasture]

thats gonna be too damn time consuming

[sharp ruin]

Hmm maybe use the options

Trying to satisfy the given conditions

[faint pasture]

the options arent really usable

anyways finding the answer is not the motive anyways am learning so i avoid using the options too much

[sharp ruin]

Not really I guess
We can use the general equation of the figures in the options

[sharp ruin]

Yes that's a better approach

I agree with you on that

[faint pasture]

how do you plan on doing that without making it take a millenia?

[sharp ruin]

Yeah that would take long

[faint pasture]

;-;

[sharp ruin]

There must be some observation we're missing

[faint pasture]

well idk if you know about that

but there is a condition for concurrency

of three lines

which is used to arrive at my original conclusion

[sharp ruin]

Have you tried assigning x=0 or y=0 arbitrarily?

[sharp ruin]

That's for "coincident" I suppose

[faint pasture]

nah

there is one for concurrent too

[sharp ruin]

The determinant way that you described above right?

[faint pasture]

yea

oh

am tripping hard

yea i meant coincident

[sharp ruin]

Yes
I literally doubted myself for that lol

I haven't reviewed geometry in a bit now

[faint pasture]

xD

im sleep deprived rn

lmao

yea so the coincident condition is what i used

to arrive at that

[sharp ruin]

Just sleep then
Get your head straight and work on this tomorrow

You won't retain anything anyways if that's the case

[sharp ruin]

Yeah I see but that shouldn't be our approach 'cause we need the lines to be concurrent

[faint pasture]

oh then these cant ever be concurrent can they? cuz the first and third lines

[sharp ruin]

There must be some combination

The numbers look good

[faint pasture]

a = b = 0 is the only one i see

for any non zzero value of a

the first and third lines aint concurrent

[sharp ruin]

a=0 for non zero values of a

Nice

[faint pasture]

no like i meant that as in seperate cases

[sharp ruin]

Ohh

I mean we should think a bit
We need at least two combinations

In order to predict something

[faint pasture]

i really think the question is just a typo and it means coincident 💀 cuz like the answer matches if we consider coincident

[sharp ruin]

Maybe idk
xD

Which reference is this from?

Is it some practice sheet or something like that?

[faint pasture]

my tchr sent it to me so yea

[sharp ruin]

Hmm maybe ask them

[faint pasture]

well yea but its like 2 in the night rn

cant text them

soo yea

💀

[sharp ruin]

I am in my bed too away from pen and paper so I can't really do any good

Definitely not a good time

[faint pasture]

you really hate privacy dont you-

[sharp ruin]

Sorry:)

Lemme delete that

Maybe text them tomorrow

[silent plank]

they can be, how are you reaching that conclusion?

[sharp ruin]

Yes I had the same question

[faint pasture]

unless a = 0 how can x + 2ay + a = 0 and x + 4ay + a = 0 be concurrent?

cuz these intersect at only one point for all non zero a so yea

oh-

fuck i just realised

sorry

[silent plank]

feels like you're still mixing coincident and concurrent

[faint pasture]

i got confused in coincident vs concurrent

[sharp ruin]

Some other combination with negative numbers might do the deed

[faint pasture]

yea i was

;-;

[sharp ruin]

Maybe think about this with a cool mind

And tell me too lol

I'm curious too now

I'll try it too

[faint pasture]

💀 the concurrency condition is all we gotta apply

[sharp ruin]

There's no determinant thing like there is for coincident

[faint pasture]

we get a cool equation
from that the two solutions are a= 0 or a = b
but we reject a = 0 cuz that leads to coincident lines (1st and 3rd) so yea

[faint pasture]

the determinant thing was for concurrency iirc 😭- but atp i cant trust myself

[sharp ruin]

I'm not sure too

[faint pasture]

yea its for concurrency acc to ggl too

[sharp ruin]

Maybe

I'll review it in the morning lol

[sharp ruin]

Hmmm that seems like something

But I'll still trust my notes over this

Will check it out tomorrow

[faint pasture]

xD my notes are not to be trusted but i have the discriminant condition for concurrency listed over there too

[sharp ruin]

That must be a thing then
I just said I haven't reviewed it so...

[cunning lion]

well that will be very useful when you invent the determinant for non-square matrices then

[faint pasture]

that condition's only for three lines

[sharp ruin]

I don't think I know anything at this point 💀

[faint pasture]

relatable

[sharp ruin]

Maybe we should both just sleep at our own places

xD

[faint pasture]

that sounds weird-

[sharp ruin]

💀

Is that alright now 💀

[faint pasture]

💀 yea lmao

[sharp ruin]

I just got done with my exams 2 days ago

And I already feel dumb

💀

[upper karma]

What is 1/2 ab sin theta?

Like I get that it's the formula for area of a triangle

But what is ab?

[cunning lion]

the lengths of the two sides adjacent to angle theta

[upper karma]

Ahh alright

[upper karma]

Btw what's a sector?

I get no good explanations neither in my book or internet

[trail tendon]

like the area of a part of a circle usually

ig

maybe it doesnt have to be a circle

[upper karma]

Ah alright yeah

[upper karma]

Oh

[cunning lion]

a circular sector is essentially a "pie slice" taken from a disk (inside of a circle)

[trail tendon]

but i've usually seen it referred to in circles so idrk

[upper karma]

Alright yeah in my case it's a circle

Wait but like I got a triangle which is

OAB

But there is a Area of sector OAB

So can a triangle be a sector?

[trail tendon]

no

sector includes the arc

triangle is straight across

[upper karma]

Then why do they say sector OAB

Like OAB is a triangle

[trail tendon]

like this

[cunning lion]

triangle in blue, sector includes red

[trail tendon]

thats a better picture 💀

[cunning lion]

they are bordered by the same points, though

[upper karma]

Area in between is the shaded area??

[cunning lion]

the area between (shaded area) is the area included in the sector but not the triangle

[trail tendon]

big area is area of sector, smaller area is the area of triangle, the shaded area is the difference between them

[upper karma]

Aha

Alright

[hoary prism]

shaded area i think is called circular segment

[trail tendon]

huh

[hoary prism]

just the shaded

[upper karma]

Minor segment in my book

[hoary prism]

yeah

[upper karma]

So like the area of sector is the area of the unshaded part

And the area of triangle is the area of triangle

[hoary prism]

sector is enclosed by the green here @upper karma

[cunning lion]

well that's because it's formed from the smaller ("minor") of the two circular sectors bordered by the points

[trail tendon]

area of the sector is the shaded AND the unshaded

[upper karma]

So the entire thing is a sector?

[trail tendon]

yea

not the entire circle but that entire part yeah

[cunning lion]

here the green is the minor sector and the white is the major sector

[upper karma]

Ahhhh

That clears up alot

[upper karma]

When to get the minor segment we have to - triangle from area of major segment ?

[cunning lion]

the minor arc is the portion of the circle (outside bounding curve) which borders the minor sector

[upper karma]

So L is the minor segment?

No wait

God

Alright

[cunning lion]

L is the minor arc in this diagram

[upper karma]

I am too slow

[cunning lion]

red is the minor segment here

[upper karma]

Alright yep

I got it now

Thanks

[harsh crow]

generally ppl use C not theta

btw

a and b are the sides adj. to the < theta

[halcyon yew]

sum1 pls help I need to find the distance of EF when I know endpoints A,B,C,D. & F but don't know E its on my finaly preformance task and idk how to do it atall

[halcyon yew]

@shrewd glade y u on the math server too 💀

[elfin cave]

what did i do wrong? i did 80tan(22)

sorry if this is really dumb, i missed a few classes due to allergies

[hoary prism]

$\tan(22) = \frac{80}{x} \Longrightarrow x = \frac{80}{tan(22)}$

[somber coyote]

chipotle

[elfin cave]

thank you

[obsidian harness]

also to check if your answer makes sense next time

the longest side is always opposite to the largest angle, and the shortest side is always opposite to the smallest angle

that's a consequence of the sine rule

So x has to be larger than 80, in fact a fair bit larger than 80 as the answer shows

[clever yarrow]

anyone got any idea I would truly appreciate any help google did not help nothing has helped me so far

[obsidian harness]

Search up the volume formulas for a sphere and cylinder

Then rate of volume change × time in hours = volume

[plain scarab]

Could anybody explain this to me

[celest wave]

hello would anyone be kindlly dm me if they can help me with my homework if interested pls private dm me ( please no pay i just want help )

,rotate

[upper karma]

what grade

[celest wave]

11th grade

[upper karma]

send, ill try

[celest wave]

ok

[upper karma]

dont expect much tho

[plain scarab]

ok I got 8 down

[formal geyser]

How do i find x

[upper karma]

integration i guess

no wait

the height of the triangle is root(3)/2

[formal geyser]

I solved it

It's approximately 0.11

[upper karma]

i got root(3)/12

[formal geyser]

Right triangle is similar to left small triangle

[upper karma]

yeah

i saw that

[formal geyser]

I can't draw red and blue lines in left triangle as i did in the right one

But the ratios of their "legs" are the same, so i made the equation

[grave pond]

That doesn't look right to me. I get around 0.12, namely 1/(6+4/sqrt(3)).

[formal geyser]

x/(1 - 6x - xroot(3)) = 3x/(6x - xroot(3)

[upper karma]

i got 0.14 lol

well, i tried

[formal geyser]

Can you explain

[grave pond]

In the 60-90-30 triangle, the short side (which you've marked in red) is 1/sqrt(3) of the one at right angles to it (which you've marked in blue).

[upper karma]

i see an equilateral triangle

oh

[grave pond]

Since the base of the large triangle is 1, I get the equation
1 = x/sqrt(3) + x + 2x + 3x + 3x/sqrt(3)

I'm assuming that the length labeled 1 in the figure is the entire side of the equilateral triangle, rather than just the distance between the corner of the red square and the 60° angle at the top ...

[upper karma]

hmm

[formal geyser]

The actual answer was 0.12 as you said

Mine is around 0.11

But is my solution bad or something?

I mean yours looks more logical, but cant i apply triangle similarity?

[grave pond]

I don't quite understand how you got your equation.

[formal geyser]

Okay, i will write it in a moment

[grave pond]

The denominators are supposed to be the lengths I write as 3x/sqrt3 and x/sqrt3, right? It looks suspect that the initial "1 -" is only there in one of them.

[upper karma]

damn bro is really a mod

[formal geyser]

Here is my equation

It's fixed and gives x = 0.12

But yours is much better

Mine is based on small left and big right triangles similarity

@grave pond maybe you know any website with high school geometry problems? I feel like i am not good at geometry at all

[grave pond]

No, sorry.

[plain scarab]

Could anybody help me out with a geometry problem?

high school level

[grave pond]

Yes, that one looks right. It becomes the same as mine if you rewrite the right-hand side to 1/sqrt(3), and then cross-multiply and collect terms.

[faint pasture]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[plain scarab]

Sorry

[upper karma]

hmm

[plain scarab]

It’s just this that I’m struggling on

I have no clue what to do

[formal geyser]

Yeah. There was something wrong with my first solution

What is composition

[grave pond]

That is almost certainly badly typeset and they meant something like: "... using the composition $T_{(-1,5)} \circ r_{180^\circ, O}$".

Composition means combining two functions to one by aplying them in sequence. In other words, the composition of f and g, written f∘g, is the function defined by (f∘g)(x) = f(g(x)).

[somber coyote]

Troposphere

[grave pond]

Hmm, but in that case none of the answer options are correct!

[faint pasture]

lets just say the question is wrong and move on

[grave pond]

The only way we can get one of the options would be to interpret the question as

1. Take the point (1,-3)
2. Then translate it by (-1,5), giving (0, 2)
3. Finally rotate by 180° around the origin, giving (0, -2)
   But there's absolutely no reasonable way to make the notation in the problem mean that.

[formal geyser]

Guys, is it ok if am good at algebra, but often fall into a stupor while solving geometry problems? I'm tring to practice more, but i still need a lotta time to solve a geometry question

[upper karma]

maybe

You're never perfect

[plain scarab]

Bro can anybody save me 😭🙏

[raven jay]

ive put a help request, but can anyone just give a hint on how to solve a problem

[faint pasture]

as we said

the que is just wrong

[plain scarab]

what the heck what you guys just said loaded for me

sorry

I’ll take a wild guess

before I submit I just wanna make sure this is right if anybody doesn’t mind

nvm I think I did it wrong

[raven jay]

how do you solve this?

Find Area

Its not a help request, its just a sttupid question

[faint pasture]

whats being asked?

[raven jay]

area

only thing given is that, all lines are straight

[faint pasture]

if am correct that shouldnt be possible :/

[raven jay]

It was sent by my prof

he said it was meant to be a fun challenge

[celest wave]

can someone help me wwith this asap

,rotate

[faint pasture]

well were you given some angles or smthn

[raven jay]

Nope, ive exhausted every means of solving it

[faint pasture]

yea then its not possible if no angles are given

[raven jay]

oh-

[faint pasture]

if even one angle was given itd have been rather doable

but yea

[raven jay]

I guess ill mail him, if he forgot anything

he wont do this just so that the answer is not possible to obtain

[sturdy stone]

is the upper side 118*125 long?

[celest wave]

<@&286206848099549185>

[spark dune]

#❓how-to-get-help

[raven jay]

118.125

[sturdy stone]

oh

if the sum of lengths of the two pairs of opposite sides were equal then it would've been possible

[whole smelt]

is this the question?

[raven jay]

yep

[whole smelt]

||Nvm oops||

oh no

[raven jay]

what

[whole smelt]

mb

i hoght it was a rectangle

[raven jay]

Thats only for rectangle and square

[whole smelt]

ik

oops

i closed it

[celest wave]

can someone please help me asap im sorry for bothering buti really need help because this is due tomorrow please anyone

[whole smelt]

about 10131.82 ?

[whole smelt]

me

[faint pasture]

what do you want help with specifically?

[celest wave]

god bless u thank u

i sent it here

[faint pasture]

yea what in here

[celest wave]

im not sure if my formula is right for brand a

[whole smelt]

oh ik

[celest wave]

vcyclinder = 12 pi x 2^2 x 3

[whole smelt]

is it a cylinder

[celest wave]

is that right

[whole smelt]

volume of a clyder:

[faint pasture]

not readable so um

[celest wave]

wym

[whole smelt]

Pi x R^2 X H

pi the raduis squared thimes the hight

[celest wave]

pi x 2^2 x 3

[faint pasture]

what doyou even mean

[whole smelt]

is the radus 2 and hight 3?

[celest wave]

idk

[whole smelt]

then yes

[celest wave]

yes

[faint pasture]

they want the formula for area not volume?

[whole smelt]

for wat

surface area?

[faint pasture]

yea

total surface area

[upper karma]

I literally solved it for her @faint pasture

[whole smelt]

oh

[faint pasture]

lmfao

[upper karma]

lmao

[whole smelt]

pi x r^2 x 2 is for the top and bottem sa

[upper karma]

I told her she needs total surface area

And she fucking ghosted me

[celest wave]

what about the 3

[upper karma]

2πr(r+h)

USE THIS

[faint pasture]

💀 my man got ghosted while helping someone rip

[upper karma]

Fr

-1000 charisma

[faint pasture]

xD

[faint pasture]

calculate area of hexagon
add that twice
also calculate perimeter and multiply that with height

[raven jay]

real

[whole smelt]

?

[raven jay]

btw the answer for that question is...

[whole smelt]

👍

I remeber my teacher gave those questions

[raven jay]

Prof: Haha i squeezed your brain juices didnt i?? Theres no answer!!

😭

These were his exact words

[faint pasture]

💀 Lmfao

[celest wave]

i dont get it is it this answer 37.6991118431 or wrong

[raven jay]

he had me solving this for 1 hour

[faint pasture]

thats wrong

[celest wave]

25.1327412287

[faint pasture]

not correct

[celest wave]

how

[faint pasture]

how are you arriving at these numbers anyways?

[celest wave]

pi x 2^2 x 2

[faint pasture]

no.

this is not a circle

[whole smelt]

no

[faint pasture]

or a cylinder

[whole smelt]

that is a clinder

[whole smelt]

yeah

[celest wave]

oh do i erase it

so whats the formula i am confused

[whole smelt]

2 circles

then the lateral surface area

[celest wave]

what

[whole smelt]

tell the diameter, circumference, hight, radius and things here

[celest wave]

volumee = 2 pi x 2^2 x 3

[whole smelt]

it shows radius 2, hight: 3

u wanted for a right?

In a clinder there are 2 circle on the top and bottem

[whole smelt]

the question is surface area

[celest wave]

A=2πrh+2πr2

[whole smelt]

no

[celest wave]

i give up can u just tell me what it is

pls

[whole smelt]

1 circle is pi x raius ^2

approsimate pi for 3.14

so 3.14 x 2^2 = 3.14 x 4 = 12.56

12.56 x 2 is 15.12

[celest wave]

ohhhhhhh

[grave pond]

Whut?

[celest wave]

is that for surface area / per container?

[whole smelt]

so now the red parts are fond, so now to find the green (middle)

[celest wave]

ohhhhh

[whole smelt]

im finding the suface area of the clinder

for the green part find the circumfrance and mutiply that by the hight to get the full green side

so first the circumfrance

[grave pond]

A=2πrh+2πr² is indeed the final formula for the surface area of a cylinder including ends.

[whole smelt]

oh yea

A=2πrh+2πr^2

[upper karma]

SUIIII

[celest wave]

ok so a = 2 pi 3 + 2pi 2^2

[whole smelt]

?

[upper karma]

WHATS WRONG WITH YOU

[whole smelt]

who

[upper karma]

WHERES THE OTHER 2??

[celest wave]

so what do i do with the 12.56

[upper karma]

MULTIPLYING WITH 365

[faint pasture]

chill out-

[whole smelt]

another way: find the circle area(of both) then the layer in the middle

[celest wave]

i hate terry this is confusing

[whole smelt]

keep untill the end

[upper karma]

TERRY IS A DUMBFUCK

Loser