geometry-and-trigonometry

[red flax]

My teacher wants me to do it idk

Wait okay

So x is that

Then what?

Do I just substitute after or something

[lime dune]

$X$ is your matrix

[somber coyote]

elrichardo1337

[lime dune]

it has to be a 2x2 matrix since that's the only way the dimensions line up for multiplication

you solve for each of the entries individually

(you're gonna need some linear systems)

then put them back together to get your final matrix $X$

[somber coyote]

elrichardo1337

[red flax]

So

[upper karma]

Which math is this?

[red flax]

I was given it in algebra 2 after finishing cramers rule

But idk he gives my extra work

And I’m like mad confused on how to solve it without using the inverse

Since idk what to do

[upper karma]

Interesting, I've never seen that problem type before.

[red flax]

It’s matrix equations but he wants me to solve it without inverse and use systems of equations

But there’s no videos on how to do it

[lime dune]

"without using the inverse" is a pointlessly tedious exercise unless you didn't already learn inverses

[upper karma]

Have you used chatgpt?

[lime dune]

!nogpt

[lime crown]

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

[lime dune]

NEVER

use chatgpt.

[red flax]

No

My other math teacher showed me how to do it no inverse

But it still doesn’t make sense

Since I keep getting it wrong

I end up with like 51x21=18

[lime dune]

??????????????

[red flax]

Wait mb

Lemme send a image

On how he wants me to do it

Wait

Lowkey

[lime dune]

you essentially get two 2-var linear systems which don't depend on each other

[red flax]

I figured it out

[lime dune]

you should be able to solve them easily

[red flax]

Broooo

Wait

😭

I’m so slow

Ofc after I send this I figure it out

Thank you for the help

[lime dune]

npnp

,texsp $\begin{bmatrix}-3&6\-7&7\end{bmatrix}$

bruh texit can't spoiler its images rip

[red flax]

😭🙏

Wait I might be cooked here

[trail tendon]

coulda shown that a while ago 💀

so yeh its basically what i was thinking

[red flax]

I think it’s a 1x2

[trail tendon]

but thats horrible

[red flax]

😭

[trail tendon]

🤣

[red flax]

Wait

[trail tendon]

why?

[red flax]

2x1

😭🙏

[trail tendon]

yea

wait what

[red flax]

Do I make x a 2x2?

[cunning lion]

you can use ,texsp at the start of the message

[red flax]

😭🙏

Wait nvm

I think I got it

[trail tendon]

what did u do 💀

🤣

[somber coyote]

elrichardo1337

[trail tendon]

:O

[red flax]

Idk

I’m fried af rn

[trail tendon]

why did your matrices change before you even did anything XD

im so confused

[red flax]

Bro

Wait

I might’ve sent

Oh

😭🙏

Wrong pic

This the right one

[trail tendon]

Oh

So ye u right X will be 2x1

[red flax]

😭🙏🙏🙏

I made it into a damn 2x2

[trail tendon]

🤣

[red flax]

Whadahell

😞

My teacher didn’t even teach me how to do it

[trail tendon]

you cant swap the order of matrix

and its supposed to be a 2 x 1 matrix

[red flax]

Whaat

Wait so

[trail tendon]

do you know how to multiply two matrices btw

[red flax]

Uuuuh

🥲

No

[lime dune]

well the work above appears correct

[trail tendon]

wait really?

[lime dune]

oh wait 😭

ok so

[trail tendon]

he swapped it and he needs a 2x1 matrix right

[cunning lion]

that first step looks a little suspicious

[lime dune]

say you have a matrix A that's mxn

and B is nxk

then AB is a mxk matrix

[red flax]

Wait what

[lime dune]

besides your initial mistake of having X be 2x2 your work appears fine?

[red flax]

Wait no cause

[lime dune]

generally you want your dimensions to match

[trail tendon]

he swapped the order tho?

[red flax]

I dropped the negative sign

[trail tendon]

am i trippin?

[cunning lion]

what is -15 - (-8)?

[lime dune]

you have a 2x2 matrix being multiplied by another matrix of unknown dimension, and you want the product to be 2x1

[red flax]

-6

[lime dune]

so X is 2x1

[trail tendon]

no

[cunning lion]

,calc -15 - (-8)

[somber coyote]

Result:

-7

[red flax]

Wait

7

Omg

[trail tendon]

lol

[red flax]

🙏😭

[red flax]

Okay

So

[trail tendon]

wait mb he never swapped th eorder i was looking at wrong problem 💀

[red flax]

Is turns into that?

[trail tendon]

wait even then he never swapped the order what am i on 💀

[lime dune]

yea yea

[red flax]

What do I do then

Cause there’s a - sign multiplying the whole thing

[trail tendon]

you can distribute that into either matrix i believe

or you could do it after you multiply

[red flax]

Uuuh

Multiply

😭🙏

Yeaaah idk how to do that

Lemme look that up rq

[trail tendon]

yeaa

[red flax]

Wdym

[trail tendon]

i mean

if you multiply a constant by a matrix

you can just multiply it by every term in the matrix

and you can do that for literally any of the three matrices there sorta lol

like - [a b] = [-a -b]

ignore my horrible notation 👍

[red flax]

A

So

It should turn into this

?😭

It looks wrong

I think I’m cooked

🥲

Imma just have to ask him tomorrow I think

[trail tendon]

actually

i think thats right

i thought you said you dont know how to do matrix multiplication 💀

[red flax]

😭🙏

Guys I swear my algebra 2 is only a semester

I’m in 10th grade

Okay but then what

[trail tendon]

turn it into system of equations

[red flax]

So

[trail tendon]

hold up

[red flax]

Then x21=1?

Wait I might not be cooked

Omg

[trail tendon]

i think thats right

i do want to make sure

[red flax]

It’s one of the

Answers for multiple choice

😭😞

[trail tendon]

XD

[red flax]

So is gotta be right then right 😭🙏

[trail tendon]

yep im pretty sure XD

[red flax]

Great now there’s a 3x1 matrix

😭😞

[trail tendon]

🗿

[red flax]

Watch this

This gotta be easy

Imma do this

[worthy acorn]

Can someone help solve a trig problem?

[upper karma]

What is it regarding?

[worthy acorn]

Its sine and cosine law, i thought i was doing it but the textbook says otherwise

[upper karma]

I will likely be able to help, I'm studying that as well

[worthy acorn]

9

Also struggling with 8 but i figure if i get 9 i can solve 8

[red flax]

Idk where I went wrong in mine

[worthy acorn]

I have this, solved x for 273

[weary remnant]

is this valid?

[upper karma]

Im going to try it right now

[worthy acorn]

K

[inner lark]

someone help me 😭

it aint workin

i think i can do (b) when I figure out (a) but idk how to do (a)

i gtg now - ping me if u reply so i can check back later thx 🙂

[weary remnant]

i got 273 too

[worthy acorn]

Textbook might be wrong than damn wasted an hour on that

[weary remnant]

what does the textbook say

[worthy acorn]

299.8

[upper karma]

What is the answer for #9?

[worthy acorn]

Textbook says 299.8, i got 273

[upper karma]

oh man

[worthy acorn]

Whatd you get?

[upper karma]

I got 97.6 lol, but maybe I visualized it wrong

[upper karma]

ohh I see

[worthy acorn]

Yea, hoffdog got 273 too, so i think the books wrong

[upper karma]

I got 273 as well with your triangle visual

but isn't your 54 and 71 degree angles considered angles of elevation? not depression?

@worthy acorn

[worthy acorn]

I thought they were depressions from the balloon because its looking down to each end

From the bridge thing they become elevations because of alternate angle pattern

[upper karma]

I think the problem is the same formatting/mapping as 8, your visual is angles of elevation I believe

but I'm going to continue to look into it

[worthy acorn]

Alr

They are the same no?

[weary remnant]

if u format it like 8 where both ends of the aqueduct are on the same side of the balloon then wouldnt the aquaduct be even smaller

so def not 299

[weary remnant]

i get 97 too if i do it with both ends of the aqueduct on the same side

[upper karma]

Gotcha, so it must be 273

[weary remnant]

ig

[worthy acorn]

Suppose so

[weary remnant]

can someone check this ^

[upper karma]

What class is this for?

[weary remnant]

none

i just came up with it

[upper karma]

How did you teach yourself to write proofs like that?

[weary remnant]

i spent 3 hours figuring it out yesterday. then i use chatgpt to help me write it all in latex today

[upper karma]

Also, how did you learn to prove pythag?

[upper karma]

Very cool

[weary remnant]

could u look it over and lmk if it makes sense

[worthy acorn]

it can be both apparently

because the question is not specific enough there is no answer for sure, according to some deep dive google searchs

idk why the textbook says 299.8, but i continue to see 97.3 and 273

[lusty dirge]

Please help, I try but get confused in the end

[trail tendon]

well

if ABCD is a square

then angle 1 is a right angle right

yea

[lusty dirge]

Yeah D1 is a right angle

But in order to prove it I have to either prove its a rhombus with interior right angles or its rhombus with equal diagonals

I dont know if its classified as proved because Im not sure its even proved as a rhombus

Or I need to prove its a parm with an interior rit angle and a pair of adjacent sides are equal

[trail tendon]

i mean

im bad at proofs but if i were to try to prove it

actually nvm

[fathom summit]

i neede help with this 3 question quiz and its timed😭

[trail tendon]

do you know the formula for arc length based on the angle and radius?

[fathom summit]

no

[trail tendon]

its s = r(theta)

where s is the arc length, r is the radius, theta is the angle

do you know how to do it now lol

[fathom summit]

no i dont ):

[trail tendon]

do you know what i said though

arc length = radius * angle

basically

for partial circles

do you know the radius?

[fathom summit]

no im really confused

[trail tendon]

do you know what a radius is?

[fathom summit]

not really

[trail tendon]

its the blue line

[jagged wyvern]

Its a line to anywhere on the vertex of the arc from the center point

[trail tendon]

the length of the blue line

do you know the length of the blue line

[fathom summit]

105

[trail tendon]

no thats the angle

[fathom summit]

oh

[trail tendon]

you have to use the graph they give you

do you know how far away A is from B

[fathom summit]

3 units?

[trail tendon]

yep

the radius (the length of that line) is 3

so

arc length = 3 times the angle

first of all do you know the angle?

and also can you put it in radians?

actually do you know how to put it in radians?

lol

[fathom summit]

no now im lost

[trail tendon]

ok

1. whats the angle

[fathom summit]

105

[trail tendon]

yeah

do you know what radians are

[fathom summit]

b and c?

[trail tendon]

no

105 * pi/180 to calculate radians

:l

[fathom summit]

how would i type that in

[trail tendon]

do you know pi

[trail tendon]

you mean into a calculator or just

[fathom summit]

yea

[trail tendon]

what kind of calculator do you have

[fathom summit]

im using desmos

[trail tendon]

oh

try writing pi

and then you have to multiply that by the radius

[fathom summit]

i think i did it

[trail tendon]

to get the arc length

[trail tendon]

what did u get

[trail tendon]

good

and then u gotta multiply by the radius to get the arc length

[fathom summit]

how do i figure out that

[trail tendon]

the radius is 3

[fathom summit]

oooh i see

[trail tendon]

yeh

[fathom summit]

i got the answer thanks

[trail tendon]

👍

[fathom summit]

i got it right

(:

actually i might need more help

[trail tendon]

arc length = angle * radius

you have arc length

you have angle

how do you get radius

[fathom summit]

uhhh

is that how i would type it?

[trail tendon]

you'd actually divide it

because arc length = angle * radius

so radius = arc length/angle

[fathom summit]

oh i ran out of time for that question so im in a whole new thing now

[trail tendon]

oh lol

[upper karma]

Yeah that’s what I was thinking, the question was too ambiguous that it could be drawn either the way I did it or the way you did it.

Glad we got it all sorted out

[trail tendon]

AB is a radius, not a diameter

a diameter is a chord that passes through the center

[fathom summit]

oh its IJ then

[trail tendon]

yeh

[fathom summit]

ok ok the question confused me for a second

[trail tendon]

XD

[lavish widget]

hey guys

does anyoine know trigonometry ?

[stiff karma]

me

[lavish widget]

oh k i have a question

3rd sub question

[stiff karma]

ok wait a minute

you solved 1st question?

[lavish widget]

yes

[novel scaffold]

this?

[lavish widget]

yes

[novel scaffold]

make the denominator same first

you can do that by writing tanx as 1-cotx and then lcm

it will turn to (tanx/1-cotx) - (cot^2x/1-cotx)

now (tanx-cot^2x/1-cotx)

write tanx as 1/cotx again

[lavish widget]

can u once do in a page and send me

[novel scaffold]

okie

[lavish widget]

lol i cant understand like this

😅

[novel scaffold]

@lavish widget

[lavish widget]

alr leme check

[vernal pilot]

!noans

[lime crown]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[novel scaffold]

damn

okay

[stiff karma]

nice answer btw

[novel scaffold]

thx

[lavish widget]

bot guy he was trying to make me understand from his answer

[lavish widget]

understood man thanks!!

[novel scaffold]

[finite basin]

Hey guys do you think geometry should be taken as a full year course or is it too important to rush the whole class into a few weeks?

I’m thinking of doing it over the summer

[lavish widget]

i think it depends which course ur taking in higher grades

[stiff karma]

different by cases

[lavish widget]

yeah

[stiff karma]

are you good at math?

[finite basin]

Kind of

[stiff karma]

then it isn't bad choice to learn it with few weeks, I did it long time ago and it was pretty good choice

[finite basin]

Okay thanks!

[lavish widget]

wow u guys have a lot of idea in mat hs

[stiff karma]

I like math

[lavish widget]

i joined this grp for doubt clearing and understanding caus im struggling with trignometry and linear equations

and i got bad in my trigonometry test....................

[stiff karma]

it's helpful to think trigonometry with circle and right triangle instead formulars

actually I was not good at trigonometry.. but it was very helpful

[lavish widget]

so how can someone be good at trigonometry

is it by practicing ?

[stiff karma]

rather than depth of understanding

researching about trigonometry is better than problem solving

researching? i'm not good at english so i can't sure it's fitted

[tidal shell]

Anyone know how to get CH and UH?

its hard to see because my camera sucks but the degree next to H is 42.9

[dark sparrow]

CUH is a right triangle

[tidal shell]

Yeah I know see the ? marks next to the sides i need to find those out

its hard to see sorry my camera is really bad

[dark sparrow]

do you know basic trigonometry?

[tidal shell]

I suck at it

no honestly

[dark sparrow]

🥁

...not even SOH-CAH-TOA shit?

[tidal shell]

nope

[dark sparrow]

...then how did you calculate the measurements for triangle CQU lol

anyway

https://youtu.be/PUB0TaZ7bhA

[tidal shell]

right triangle side caluclator carried me

[dark sparrow]

give this a watch

you will need a calculator to evaluate the trig functions

[tidal shell]

will that explain how to get the sides?

[dark sparrow]

that video will get you up to speed on basic trig yes

[tidal shell]

alright thanks

[low shuttle]

guys why r vectors so hard

[tidal shell]

i dont know waht a vector is

[low shuttle]

its an ARROW!

[dark sparrow]

this convo went downhill in 3 messages

new record

[low shuttle]

and i have 3 weeks and i know nothing about them

[dark sparrow]

bc to someone who hasnt done anything with them before they are highly unfamiliar territory

[low shuttle]

weve been doing them for 11 weeks

[tidal shell]

real bro we been doing trig for like 5 weeks and havn't learned anything

[low shuttle]

sine and cosine rule?

[tidal shell]

something like that

[low shuttle]

maybe they give you formula sheet

gotta remember ur sohcahtoa

[tidal shell]

theres two triangles in one idk what im doing

[dark sparrow]

well i have been telling you to look at triangle CUH since the start.

if it helps you, make a copy of your diagram but with point Q and segment UQ erased.

[tidal shell]

but i need UQ

to calculate QH

i just don't know how

[low shuttle]

use sien ruel

[tidal shell]

idk what that is

[low shuttle]

sina/a=sinb/b=sinc/c

[dark sparrow]

no you don't?

[dark sparrow]

overkill!!!

he doesnt even know soh-cah-toa and you're trying to feed him the sine rule? come on!

[low shuttle]

what

[dark sparrow]

@tidal shell did you watch the video y/n

[low shuttle]

SOH CAH TOA IS THE PREMISES OF TRIGERNOMETRY

[tidal shell]

some of it

[dark sparrow]

yes and plung here has told me he does not even know that

but also

[tidal shell]

like opp adj part

and hyptonuse

[dark sparrow]

this is a right triangle so sine rule is overkill ANYWAY.

[low shuttle]

i didnt even see the right angle

[dark sparrow]

@tidal shell watch the vid in its entirety THEN come back here.

side, not site.

also it's spelled hypotenuse.

[low shuttle]

ENlgish no first

[tidal shell]

its not that deep

[dark sparrow]

what is your first language?

[upper karma]

Rust #1

[low shuttle]

japaner

and chiner

[tidal shell]

me gusta

so uh QH anyone?

[dark sparrow]

find CH

[tidal shell]

oh yeah CH

[dark sparrow]

CQ is known, so QH = CH - CQ.

[tidal shell]

nevr

[dark sparrow]

never what

[tidal shell]

i forgot what i was going to say

sorry

i need QH though

right

CQ + QH = CH

[dark sparrow]

you're the ONLY one who knows what YOU need.

i will ask you once again

did you or did you not watch the vid

i think that instead of watching the vid you chatted in here

[tidal shell]

i did

he didn't explaingood

[dark sparrow]

ok in that case let me reproduce the diagram...

[tidal shell]

this right though?

[dark sparrow]

yes CQ + QH = CH is correct, it's literally a restatement of what i said.

[tidal shell]

okay how i get QH?

i have CQ

[dark sparrow]

uhguwharwk??

let me repeat myself

i am telling you that you should get CH FIRST, and from that get QH.

[tidal shell]

okay

[dark sparrow]

here is a diagram with ONLY the relevant data.

[tidal shell]

okay

[dark sparrow]

can you write down the relevant trig ratio based on this info?

if you can't then type these exact words: "No, I cannot do it myself. I want you to take me through it step by step in full detail."

[tidal shell]

i cant

step by step plese

[dark sparrow]

so much for following my instructions exactly as stated.

ok.

look at the diagram.

[tidal shell]

yes

[dark sparrow]

in this triangle there are two sides we care about:

• CU, because it is known
• CH, because it is sought

do you understand this? Y/N

[tidal shell]

yes

[dark sparrow]

ok

look at angle H, which i have marked for you here with its size (47.1°).

which of the following three words:

• opposite
• adjacent
• hypotenuse
  describes the position of side CU, relative to angle H?

[tidal shell]

adjacent?

[dark sparrow]

wrong

[tidal shell]

oopp?

[dark sparrow]

adjacent means next to.

ok, you got it right on your second guess.

[tidal shell]

oh

[dark sparrow]

opposite means across from the angle.

adjacent means next to the angle.

[tidal shell]

whats the differnece?

between across and enxt to?

[dark sparrow]

what is your first language? maybe it will be easier if i translate.

[tidal shell]

spanish

but i know english to

[dark sparrow]

ok nevermind that

[tidal shell]

ok

[dark sparrow]

each angle lies between two sides

in a right triangle, each acute angle lies between the hypotenuse and one other side

that other side is its adjacent

[tidal shell]

okay

[dark sparrow]

ok

so with all this in mind

which of the following three words:

• opposite
• adjacent
• hypotenuse
  describes the position of side CH, relative to angle H?

[tidal shell]

adj

[dark sparrow]

right.

so the two sides we care about are the opposite (CU) and adjacent (CH).

which part of the SOH-CAH-TOA mnemonic:

• SOH
• CAH
• TOA
  will we need?

[tidal shell]

soh?

[dark sparrow]

why?

[tidal shell]

i guessed

[dark sparrow]

bad!

badbadbadbadbad

DO NOT make any more guesses.

[tidal shell]

okoay

[dark sparrow]

we're looking at the __O__pposite and __A__djacent sides

which part of SOH-CAH-TOA do we need?

[tidal shell]

i dont know

[dark sparrow]

ok...

if you write out "SOH" in full, what does it stand for?

[tidal shell]

side

thing thing

oppostie

?

hypotuse?

oh

i get it?

[dark sparrow]

ok in that case

we're looking at the __O__pposite and __A__djacent sides
which part of SOH-CAH-TOA do we need?

[tidal shell]

soh

wait

awit

cah

because adjcent we need

rgih

right

[dark sparrow]

wrong BOTH times.

i gave you a peg and 3 holes to put it in

the peg fits in one of those holes only

you went for BOTH wrong holes

[tidal shell]

pause

[dark sparrow]

it is as if you actively try not to think

[tidal shell]

i just suck at math

[dark sparrow]

which i really really hope is not reality

[dark sparrow]

the math has not even begun

you are letting your math phobia stop you from accomplishing the simplest of tasks

[tidal shell]

so toa?

[dark sparrow]

yes!

like

i highlighted the letters O and A

which stand for Opposite and Adjacent

TOA

it's right there!

[tidal shell]

oh i see now

underline

but dont we need UH?

which is hypotnuse?

[dark sparrow]

no

i mean

we can find UH later

but right now we're focusing on finding CH

[tidal shell]

okay

so tao

tanjecnt

thing

[dark sparrow]

$\tan(47.1\dg) = \frac{???}{???}$

[somber coyote]

|Ann⟩

[dark sparrow]

replace the ???'s with the sides we have been talking about. DON'T try to put their values in for now -- ONLY write "CU" and "CH" in the respective places.

[tidal shell]

so tanj of 47,1 equal CH?

ok so

CU over CH

[dark sparrow]

yes

$\tan(47.1\dg) = \frac{90.05}{CH}$

[somber coyote]

|Ann⟩

[dark sparrow]

can you now solve this equation for CH?

[tidal shell]

yes probably but idk how

[dark sparrow]

how can you say "yes" and "i don't know how" in the same breath?

[tidal shell]

because you haev 2 numbers up there

[dark sparrow]

if you don't know how, then surely it would be more honest to say you can't?

[tidal shell]

2 numbers mean you can get the 3rd

usually

[dark sparrow]

ok

let's make a simpler equation

the structure is the same but all the numbers are different

$\frac{12}{z} = 8$

[somber coyote]

|Ann⟩

[dark sparrow]

how do you find z here

[tidal shell]

uh

why is this so hard its so simple but idk what number goes into 12 8 times

[dark sparrow]

don't call me bro.

please edit that word out of your message.

[tidal shell]

why what wrong?

[dark sparrow]

i don't like being called "bro".

[tidal shell]

oh

i heard from my friend it good word for friends

is it a insult?

[dark sparrow]

it's not an insult.

it is just masculine.

too masculine for my taste.

[tidal shell]

Ohhhh

it like chico and chica

okay i think i get it

[dark sparrow]

anyway

[tidal shell]

96?

[dark sparrow]

no.

12/96 is 1/8 not 8.

[tidal shell]

1.5?

[dark sparrow]

how did you find this?

[tidal shell]

i don't know

[dark sparrow]

so it is just another guess.

[tidal shell]

1.5 divide

[dark sparrow]

bad.

[tidal shell]

12

= 8

[dark sparrow]

from 12/z = 8,
multiply both sides by z to get 12 = 8z,
then
divide both sides by 8 to get z = 12/8.

do you understand this? Y/N.

[tidal shell]

no

i just did it in my head

[dark sparrow]

which part of this do you not understand?

[tidal shell]

i didn't take algebra thing

for 9th grade and 8th

i was out of school for those years

how do you multiply by z

it equal nothing

[dark sparrow]

well, it sounds like you need a review of algebra and not just geometry.

right now we are getting nowhere.

[tidal shell]

i can learn all of algebra in 2 days i need trig though

i have test in 2 days

[dark sparrow]

well THAT'S new.

now i can tell you for a fact that you are screwed.

big time.

[tidal shell]

no i just need trig

learn it

how to get angle

and side

im good

[tidal shell]

i can solve it just don't know how to tell u i did

that fine

[dark sparrow]

fact of the matter is, you are unable to get from

tan(47.1) = 90.05/CH

to

CH = 90.05/tan(47.1)

[tidal shell]

so i need tan 47.1

find that number right

then divide by 90.005

or what

and that = CH

[empty yew]

@dark sparrow sorry to interrupt.do you know what is maple?

[cunning lion]

in a math context that usually refers to https://en.wikipedia.org/wiki/Maple_(software)

[empty yew]

what is the use of this?

[tidal shell]

so tan of 47 = 1.0724

[empty yew]

what is the use of this software?

[tidal shell]

1.0724 / 90.05? = CH

CH = 83.9?

[cunning lion]

the article has examples of its usage

[tidal shell]

@dark sparrow did j get it?

[empty yew]

is it like desmos?

or it has more functions?

@cunning lion

[cunning lion]

significantly more features

[dark sparrow]

you are writing division backwards

but yes

[tidal shell]

it said it was wrong

it didn't work

[empty yew]

is it useful for calculus? @cunning lion

[tidal shell]

@dark sparrow why is it wrong?

[cunning lion]

it has calculus capabilities from what i've read

[dark sparrow]

can you post a picture of the entire written instructions?

i think it is most likely some rounding bullshit.

,w 90.05/tan(47.1°)

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by ann_dec

[dark sparrow]

if you post partial or incomplete or something else entirely then i can't help you.

i will be back in 10.

[tidal shell]

In the diagram:

• CU forms the altitude for CUQ and CUH
• QC = 44.4
• UQ = 100.4 yd
• CUH = 47.1

these what it said for instructions

USe the diagram to determine the measure of the sought sides and angles

ping me when u back please

i watch video again

[limber sigil]

do you guys think the unit circle tastes good

[dusky locust]

yeah

[empty yew]

what's a unit circle?

[cunning lion]

https://www.khanacademy.org/math/algebra2/x2ec2f6f830c9fb89:trig/x2ec2f6f830c9fb89:unit-circle/v/unit-circle-definition-of-trig-functions-1

[uncut umbra]

Am I right if X is 48 and y is square root of 3?

[pine arch]

hi

i solved this q but i need to confirm the answer cuz i cant find the markscheme for this

[clear anvil]

well it’s just the area of the equilateral triangle - the area of those 60 degree sectors

[pine arch]

ya ok thanks

[upper karma]

Yes 30-60-90 triangle

[rich scroll]

Help with no 17 plz i dont get it

It seems like evry answer is wrong

Letter A is correct cuz of the hinge theorem,
B is wrong cuz its true
C is wrong cuz theres no postulate that supports it
D is wrong cuz its not on the same triangle

So A is the true correct answer, but technically, C is also because it is false

What am i supposed to choose

[dark sparrow]

i mean D is false right

so it is what you're looking for

you're looking for the false stmt

[rich scroll]

C and D are both false

So i now have 2 possible answers

[merry mulch]

If $2sec2\alpha=Tan\beta+Cot\beta$, then value of $(\alpha+\beta)$ =

[somber coyote]

Nischal

[low shuttle]

no thats wrong

[buoyant nova]

x=16sqrt(3), y=8sqrt(3)

[low shuttle]

when i use the vector projection does it still have i and j components

[echo hill]

yea

[worthy acorn]

Still stumped on how 9 is 299.8

[vernal pilot]

I feel like I recognise that textbook.

[worthy acorn]

Gr 11 Canadian math

[vernal pilot]

Huh, what’s the name of the textbook?

Btw you should try drawing the problem out if you are having difficulties with it.

[worthy acorn]

Not sure, would have to check, thats just what grade you get it in

[worthy acorn]

I drew this

[vernal pilot]

You can use the law of sines

,,\frac{A}{\sin(a)}=\frac{B}{\sin(b)}

[somber coyote]

TheLord26

[worthy acorn]

I did, but still got the “wrong” answer

[vernal pilot]

Hmm

[worthy acorn]

You try it rq

[vernal pilot]

Ight

,w \frac{270}{\sin(\frac{54\pi}{180})}

,w \sin(\frac{55\pi}{180})\frac{270}{\sin(\frac{54\pi}{180})}

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by thelord262

[worthy acorn]

So the texbook was wrong

[vernal pilot]

Hmm

Looks like it

Trying to see if I’ve done something wrong, but I think the textbook is wrong.

[worthy acorn]

Oh good

[uncut umbra]

How

[trail tendon]

pie is better

[upper karma]

Can we determine the exact values of trig functions of every angle, and can we compute a cyclometric function for any argument inside its domain?

[vernal pilot]

Wdym?

[upper karma]

What is the sine of 20 deg \ pi/9

and the inverse

[vernal pilot]

We can calculate that. Whether or not there is an exact value of it depends though.

[upper karma]

without a calculator?

[vernal pilot]

Yes

The simplest way to calculate sin and cos is to use the Taylor series of the functions.

There are other ways, like using the complex definitions.

Ofc there’s also a geometric approach.

[upper karma]

hyperbolic?

[vernal pilot]

No. That is different.

Anyways, there’s not really a use to doing it by hand, unless it’s an easy to compute angle, like 90, 45, 60, and 30. But if I was forced to calculate sin of 20 degrees by hand, I would use Taylor series approximations.

Idk if that’s what you wanted, but that’s my answer.

As for the inverses, there is also a Taylor series for them, not very good albeit.

[upper karma]

thanks a lot

also why is there i in sine's denominator

[dark sparrow]

$e^{iz} = \cos(z) + i \sin(z)$ and $e^{-iz} = \cos(z) - i \sin(z)$

[somber coyote]

|Ann⟩

[dark sparrow]

solve for sin(z) and you will see that i go there

[upper karma]

but from sin(x) = -isinh(ix) we get $\frac{-ie^{ix} + ie^{-ix}}{2}$

[vernal pilot]

They are different things.

sin and sinh are different

I would recommend watching a video explaining how to derive the formula for each.

[dark sparrow]

can you please use some parentheses and proper formatting

$\sin(x) = -i \sinh(ix)$, ok?

[somber coyote]

|Ann⟩

[dark sparrow]

and anyway,

[dark sparrow]

yes, we do. is that an issue?

[somber coyote]

Hollow Knight Addict

[upper karma]

I dont even know anymore

[dark sparrow]

you yourself don't know where the issue is, but you know for a fact that an issue exists.

[upper karma]

and whats the geometric approach

[void eagle]

Hello everyone!
I am not getting the point of how the sum of angles of n sided polygon was proved.
I understood everything besides how we get n - 2 triangles.

[upper karma]

Guys

What's the difference

Between

Trigonometry

Geometry

And

Mensuration?

I did some research now, i feel stupid.

Anyways, what's the difference between trig and geo?

[void eagle]

Yeah my question sounds stupid but I just wanted to know why exactly the formula of an n-sided polygon is 180 * (n-2).
But how can you prove that there will be n-2 triangles in the picture below?

or from this

[wild thunder]

Help prove this please

[celest wave]

hello

i need help before i pass out and have a heart attack call 911

Call 911

[trail tendon]

if you pass out and have a heart attack you probably won't be able to call 911

whats the issue

[celest wave]

i just need ur attention

hello

[trail tendon]

hi...?

._.

[celest wave]

do you know how to solve transformations

rotations reflections ext

[trail tendon]

i don't think "solve" would be the correct term but maybe

could you give me an example

if ur stuck on a problem or smthn

[celest wave]

i have a project and im on computer right now can u please help me later

like in 40 minutse

[trail tendon]

i may not be here in 40 minutes but if you post ur problem here i bet someone would help

[celest wave]

we have to plot points and i feel like im doing something wrong

then why does no one answer them

[trail tendon]

why does no one answer when

[celest wave]

today

[trail tendon]

but thats the first thing you said today lol

[celest wave]

yes why dont they answer them

the people who need them no hate

[trail tendon]

i answered

[celest wave]

because i lied of saying 911

[trail tendon]

oh

[celest wave]

work harder not smarter

[trail tendon]

nobody answers to "hello"

they answer to a problem

💀

just post the problem

don't post "hello"

that tells us nothing

[celest wave]

hello

[trail tendon]

lol

[celest wave]

why

its good to greet everyone

i have manners

[trail tendon]

yeah

[celest wave]

do you

[trail tendon]

if you just say hello i wouldn't expect ppl to respond lol

[celest wave]

I have a feeling you play pixel gun 3d

[trail tendon]

i don't 😂

[celest wave]

u said hello

i expected

[dark sparrow]

scummy.

[mild hound]

??

[trail tendon]

☠️

[celest wave]

whats that

[celest wave]

do you play snapchat games

[dark sparrow]

i don't even have snapchat, so no.

and i don't see how that's relevant.

[trail tendon]

we're here to do math, so if you say hello thats fine but don't expect ppl to respond they mostly just here to do math lol

[celest wave]

scummy is not math

[dark sparrow]

staging a heart attack with the express purpose of "just getting someone's attention" is scumbag behavior.

that is what i was saying.

[celest wave]

LMAO Wait

wtf

is this an AI

[trail tendon]

it was obviously exaggerated lol

[dark sparrow]

@celest wave the fuck are you on

[celest wave]

very realistic

[trail tendon]

no, but the nearest thing to it 😂 🗿

[mild hound]

I think pre-uni section mostly has Indian students 😅

[celest wave]

so theres real ai humans

[dark sparrow]

fuck you for calling me an AI.

[trail tendon]

do you have any reason for thinking that

[dark sparrow]

also i saw that

you just called me the N-word

[trail tendon]

ayo 💀

i mean you did kinda just swear at them

[dark sparrow]

i said fuck

[trail tendon]

thats a swear word

lol

[dark sparrow]

do you wanna take this to #discussion and moralize at me about how i can't say fuck

[trail tendon]

uh not really?

[mild hound]

Yup just answered some student and many question I see are from many coaching and school modules

[trail tendon]

ahh

[dark sparrow]

@celest wave you still there, or what?

oh wait no

you're most likely muted

[trail tendon]

💀

when you don't read the rules

[hexed kernel]

hello

[hexed kernel]

umm why is there a rude AI

@granite axle Help me solve an equation of rotations.

Um, the AI doesnt seem like it's working. Can someone help me with homework.

[grand turtle]

Hello yeah I help bro XD

Also it ai???? I think it real bro XD

[dark sparrow]

???

are you also going to accuse me of being an AI?

[thin sentinel]

wtf

[spark stag]

uh

[grand turtle]

Are there bro??

[spark stag]

i think they somehow catastrophically misread your name

"|A" became "AI"

[dark sparrow]

very catastrophic indeed

@hexed kernel @grand turtle i'd like to hear an apology from at least one of y'all

cause again, for the record, i'm not an AI

[hexed kernel]

Um hey i need help,

what?

[grand turtle]

What need help with bruh

I will

I help man

[grand turtle]

Also I did not call ai

[hexed kernel]

Dont tell me what to do.

[dark sparrow]

ok, then it's from jezel specifically that i want an apology.

[grand turtle]

Wait dude what?

[hexed kernel]

@granite axle Remove chat

[grim bronze]

guys who else dislikes... geometry🥰

[grand turtle]

I love math friend

[dark sparrow]

there is no AI here.

[hexed kernel]

Dude since when are AI's are getting out of hand.

Elon musk created these crazy AI

[dark sparrow]

<@&268886789983436800> can we do sth about this?

[grand turtle]

I not complete fruend lil

[hexed kernel]

they dont even work?

[grand turtle]

Lol

[clear haven]

what is jezel talking about bruh

[grand turtle]

I have no mind friend

[clear haven]

ok i will just mute bc this seems super weird/in bad faith

[hexed kernel]

why is there a minecraft player

[grand turtle]

@hexed kernel you need help bruh?

I helped you

[clear haven]

come back in an hour when you want to actually use the server

so strange

[grand turtle]

Who jezel

She bully???

[clear haven]

idk

[grand turtle]

She actually have disability she message

Mine direct

She printed dyslexia

Maybe mistake?

[grand turtle]

Hey friend

My friend yes bro

It look good!

Yes

What my friend

._.

Uhh

Ok

Uh

????

[signal briar]

[inner vapor]

🤔

[obtuse field]

They're gone

[inner lark]

help me bru

im not getting help from anyone 💀

[maiden brook]

this is from AOPS?

[solid needle]

notice that the problem mentions centroids

there are three extremely critical theorems of centroids you should always remember:

[inner lark]

the 2/3 one?

[solid needle]

1. the 2/3rds one yes

2. centroids are formed by medians

3. the medians divide the triangle into 6 smaller triangles of equal area

2 is definition-ish (collinearity needs to be rigorously proven)

1 and 3 should be pretty easy to prove

these facts about centroids will be important details in like 90% of all problems involving centroids

keep them in your pocket

lemme know if that helps

[static heath]

Help please

[trail tendon]

label all the sides that you know, and look at the angles of each triangle

like you see that you have two triangles right

one is inscribed in the other

look at those angles

[jagged wyvern]

Look at the smaller triangle in the big one

[upper karma]

List all sides of AWV and ACB out

[jagged wyvern]

You're not given any angles, so use proportionality from both triangles to prove the SAS theorem

[upper karma]

This is wrong

The triangles share a common angle (WAV)

[static heath]

so would it be not similar?

[upper karma]

Figure it out yourself

||yes they aren’t similar||

[jagged wyvern]

Proportionality

🤷‍♂️

[inner vapor]

sin(2x) = 2sin(2x)cos(x)

how do I solve for x?

[upper karma]

Divide 2sin(2x) to both sides

Sin(2x)/2sin(2x) simplifies to 1/2 = cos(x)

[inner vapor]

this is the solution

how and why and what?

[upper karma]

Yes sin(2x) divided by sin(2x) is like 10/10 it equals 1

The 2 stays in the denominator

[upper karma]

You forgot a really important thing here

[upper karma]

What’s that?

[upper karma]

The case when sin(2x) is 0

Yes this is true, there’s two potential cases

[upper karma]

This is because cosx = 1/2

On the unit circle, there’s two points where cosx is 1/2

Pi/3 and 5pi/3

[upper karma]

How do you get to this case?

By implying that x = 0

?