geometry-and-trigonometry

[hollow barn]

@limber kernel

[limber kernel]

These are the answers

[gilded sand]

ya so the general solution of $\cos(u)=0$ is $u=\frac{\pi}{2}+2\pi{n}$, where for your example $u=3\qty(x-\qty(\frac{\pi}{4}))$ and after getting that you just divide however many terms u want by 3 and add $\frac{\pi}{4}$ and ya you're done

general eqn is wrong here mb

[somber coyote]

Anonymous

[limber kernel]

It's from -pi to 2pi

[gilded sand]

oops i didnt see that sorry

[limber kernel]

I'm still confused how to get those first points

[gilded sand]

which

[limber kernel]

the 3(x - pi/4) = -7pi/2, -5pi/2, -3pi/2

ect

[hollow barn]

@gilded sand my solutions are invalid?

[gilded sand]

its the general solution, you choose n=1,2,3,4 etc and see if its within the domain

[limber kernel]

i don't think i know how to do that

[gilded sand]

you messed up somewhere

[hollow barn]

Oh no

[gilded sand]

no like literally do \pi/2 + 2\pi(0), \pi/2 + 2\pi(1), \pi/2 + 2\pi(2), etc

you also do n=-1,-2,-3,etc until it exceeds the domain of $x\in[-\pi,2\pi]$

[somber coyote]

Anonymous

[limber kernel]

can you do some working out cause im stil a bit confused

[gilded sand]

do you see how those are some of the solutions from the answers?

[hollow barn]

$\sin^-1\br{0} = \frac{9\pi}{2}$ ?

Oh my gosh

[gilded sand]

?

[hollow barn]

cos inverse of 0 = 9pi/2?

[somber coyote]

Anonymous

Anonymous

[gilded sand]

of whatever you have on the inside

[limber kernel]

Can't I just plus pi/4 to the current x values

i really don't understand the way you do it sorry

this is just my understanding of it

[gilded sand]

first off, you're solving for when y=0, y=2 on that graph for x=pi/4

and you can do it that way, but that'd only give a single solution

[limber kernel]

im doing question b

if i plus pi/4 to each x intercept would it not give me the answer for all of them how only a single

[gilded sand]

first off i think your graph is wrong here

[limber kernel]

oh no

i didn't draw it to 2pi cause i didnt have room

[gilded sand]

so you have a few options here:

either you solve for the maximum value of y, and plot them periodically

or solve for the zeros of the function and find for which values of x does this occur

[gilded sand]

no as in like if i plug -\pi/6 into you're equation you don't get 0

even though your graph says its 0

I know this all sounds pretty confusing but here's a video that should explain the concept pretty well, I suggest you watch it:https://www.youtube.com/watch?v=bm8oYKKlCXI

[limber kernel]

okay thank you

[dark sparrow]

do you have a diagram?

oh yeah, a 1-minute silence means i'm "ded".

can you like

not act entitled for a moment

[lime crown]

Helpers are just people volunteering their time to help you. Be polite and patient.

[dark sparrow]

also dont ping everyone, it's disabled but it's still rude.

i am in a call.

and it sounds like you're trying to cheat on a test.

<@&268886789983436800>

[spark stag]

so weird that they think the wording of the rules matters more than the intent

"my teacher would kill me for posting this" means its cheating lmao

[lime dune]

my god some people are just shameless 😭

how many of these cheaters have y'all had to nuke

[reef charm]

Yo

[hollow barn]

Is there a way to solve $\sin(\frac{\pi}{9})$ using Half Angle formulas?

[somber coyote]

Angel_15

[dark sparrow]

probably not

[next pumice]

No

[mortal crow]

All of them?

[bleak root]

how to do this question

[dark sparrow]

!status

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[cinder elbow]

Use euclid

[bright pebble]

So my math class gives me hw every class and I have to turn it in by next class every day. But we had summatives making our math classes class from 1 hr and 30 min to 30 minutes and it’s with passing period combined and we really didn’t have time to learn anything but he still gave us this it’s already overdue and my friend with all A+ for her life can’t solve this is because we didn’t learn it someone pls help

[upper karma]

im so tired of math

[fickle rose]

for the first one, if 2 corrosponding angles are congruent in 2 triangles then the triangles are similar

one of the angles are congruent since both are right triangles, but you need to check if there are any other ones

[upper karma]

Hi yall ❤️

...

[shrewd axle]

for the third image just use linear pair(sum of angles on the same line is equal to 180 degrees) so 4x +x = 180 and (x-20) + x = 180

then find x and then find the value of each angle by substituting x

[shrewd axle]

Wait woah what kind of homework is this i thought it was just the labelled angles not EVERY ANGLE in the diagram

its not hard but its just too much if they just started teaching this

[lime dune]

ehh i think it's reasonable

(if not a bit tedious)

[shrewd axle]

thats what i mean, its a little too much

[craggy violet]

this is how i drew it

[upper karma]

yes, that diagram is right

now use the pythagorean theorem

[craggy violet]

ty

[dark sparrow]

btw paint has a line tool

also you can hold shift while using the ellipse tool to make perfect circles

[craggy violet]

🤯

[dark sparrow]

also if you hold shift with the line tool the direction of the line will snap to the nearest queenwise direction

so you get pixel perfect horizontals, verticals and 45° diagonals

[craggy violet]

so its

then i do 37 + 12

[regal badge]

there is someone that understand this?

[lucid schooner]

bro its so easy

basic math

[devout gale]

can sombody help me with this

[dark sparrow]

gonna need a higher-res version

[regal badge]

for me no

[dark sparrow]

did you mean to post a picture? or did you delete it already

[regal badge]

i need to learn how to solve this

or this

[dark sparrow]

do you know how to solve basic trigonometric equations?

[regal badge]

no

[dark sparrow]

i.e. ones of the form sin(x) = a, cos(x) = a or tan(x) = a

where a is a number

[regal badge]

no i dont

[dark sparrow]

ok then you have to start with those

[regal badge]

and how i start

like what should i do

[dark sparrow]

well you have a textbook or something, right?

learn how to solve such equations from that

or from khanacademy

or from organic chemistry tutor

[regal badge]

ok

[fallow ore]

I love trigonometry

[viral mauve]

type shit

[fallow ore]

[viral mauve]

[lament smelt]

You know those trig identities that are super easy to prove but super hard to derive

[dark grove]

hello

[upper karma]

dont you love it when your teachers just put you in the deep end

i feel terrible since i cant do logarithms well

[dark sparrow]

do you struggle with easier types of equations like quadratics? @upper karma

[fickle rose]

what do u need help on?

[ancient rapids]

hi

can someone help me

please can anyone show me how to do this along with the explaination

[dark sparrow]

we won't do it for you, mind you

[ancient rapids]

alright

[dark sparrow]

but your best first step is to make a diagram.

[ancient rapids]

gimme a min

[dark sparrow]

(as it is in basically every geometry problem.)

[ancient rapids]

yeah

done

next

?

@dark sparrow

(sry to ping)

[dark sparrow]

next is you need to show me your diagram

[ancient rapids]

uhh i am on laptop and my camera does not work

😭

wait lemme try the thing again and i will tell the answer please tell me if i am correct or wrong

[dark sparrow]

do you not have a phone that can take photos

but ok whatever

[ancient rapids]

i'm 13 (turning 14)

and they do not give kids phones this early in india

[dark sparrow]

ok then you could recreate your diagram in Paint maybe

it has a straight line tool so yours should not be hard to make

[ancient rapids]

it is option 4 right

[dark sparrow]

so it appears.

[ancient rapids]

alrighty thank you very much

[dusty ginkgo]

depends on parents, i got mine at 11 smth i believe

[coral cobalt]

same

but i know a kid who didnt have one till 15 too

[frank rain]

Draw a qualitative triangle ABC, and the circle (C) surrounding it, H is a point where its heights meet, 'H is a counterpart to (BC), and K is a counterpart to H with respect to I, the middle of [BC].
Show that each of the points K and H belong to the circle (C).

[empty yew]

In a triangle ABC,DE||BC then what are the conditions we have here???

[abstract niche]

SOMEONE PLS HELP ME

[dark sparrow]

,rccw

[dark sparrow]

DO YOU STILL NEED HELP WITH THIS?

ALSO, WHY ARE YOU SHOUTING?

[dark sparrow]

1. don't give out answers, esp. potentially wrong ones
2. don't write square roots like that. you meant 8 sqrt(15).

it doesn't matter

please do not call me "bruv", "brother" or any variations thereof. @restive moss

no, i'm not.

do you want to keep acting like a dick to me?

cause now you're the one being rude.

[river solstice]

alright break it up kiddos

[dark sparrow]

not a "kiddo" (unless you're like 40) but yes, i'd prefer this to end.

i'm a she.

[river solstice]

[dark sparrow]

<@&268886789983436800> we got a misgendering + transphobia + overall dickishness over here

[river solstice]

well

[young gust]

lol

[dark sparrow]

ok and hes gone

[river solstice]

as much as i respect the trolling unfortunately thats not allowed

emphasis on unfortunately

anyways

[dark sparrow]

trolling should not be respected

trolling is trolling

[river solstice]

x = x

[dark sparrow]

and this is transphobia, not trolling

i kind of did pull it out of him eventually.

[river solstice]

so you just

ok whatever

[river solstice]

am i right when i assume this is 45 45 ?

[dark sparrow]

what?

you asked a question, you got an answer.

no, you cannot assume the right angle is being bisected.

[river solstice]

no im just sad cause it makes life harder

[dark sparrow]

is not a "sad" emoji.

is more of a "what the fuck are you talking about" emoji.

[river solstice]

did you decide that on your own or are there like guidelines here that writes about it

[dark sparrow]

i have been here long enough to witness it being created.

[river solstice]

gotcha

[upper karma]

guys sorry to ask

what was the Apollonius theorem

?

[dark sparrow]

https://en.wikipedia.org/wiki/Apollonius's_theorem

[upper karma]

ok

👍

[ember river]

dfsdf

[dark sparrow]

#chill ?

[upper karma]

does anyone have a solid top for f math in general

not some specific hmw but just a general tip

[empty yew]

What is the first theorem in mathematics?

[vivid ferry]

I believe pythagoras theorem

[tawny panther]

How to find a intersection of a sphere and a circle

[clever pewter]

hi

is there someone online

please

I have an urgent doubt regarding trigonometry

[dark sparrow]

why urgent?

[dark sparrow]

show how they are given to you

[tawny panther]

Actually i was reading an equation which says intersection of sphere and a plane will be s+lambda n

[dark sparrow]

... can we see that equation

and context surrounding it

[fervent copper]

I have a test
who can help me

[stable kettle]

Geometry question of the month: Find the area of this shape.

[jagged wyvern]

Use geometric mean theorem, or just use logic and see it as 3 triangles and use proportionality

[stable kettle]

Unsure if this is even right... I used Heron's Formula.

[empty yew]

Ok

[empty yew]

Breaking the mixed fraction and just simplify. Am I right?

Anyone solve the second question
(Challenge)

[trail tendon]

am i stupid or do you just divide the volume and the base area to get the height?

nope

nvm

wait

yes

[trail tendon]

yea don't you?

[tawny panther]

@dark sparrow

The first line says the equation of sphere passing through a circle and plane

[dark sparrow]

i don't speak hindi

so i can't really make sense of this

[tawny panther]

I have a little tiny brain so i have written already in English for you 😆

Rest is just mathssss

I was asking what is that formula from last night

[dark sparrow]

well i for one don't understand the math either. what's C? what's λ? what's N? am i supposed to know what all those things stand for with 0 context???

[tawny panther]

As i have said 100 times is this a formula for intersection of sphere and plane? If yes then please suggest some more context so that i can read more

Nevermind leave it

[dark sparrow]

you were talking about the intersection of a sphere and CIRCLE earlier?

[tawny panther]

Last night i mentioned this

Have you read any formula or any equation something like first equation?

S=c+lambdaN=0

[dark sparrow]

no

[tawny panther]

Okay fine

[dark sparrow]

because again i don't know what any of these letters mean

[tawny panther]

Letter doesn't matter either they can be different for you too

But any something similar equation?

[dark sparrow]

no, not in connection to this.

i can tell you from a purely geometric standpoint that the intersection of a sphere with a plane is either a circle, a single point, or empty.

[tawny panther]

If i find any context similiar today in my books. I will send it to you

[dark sparrow]

if only we had a concrete problem to look at. but we don't.

[tawny panther]

So that i hope you can help me to understand that context

Yes. I was trying to see these in desmos 3d last night

It can be a point 🙄

[dark sparrow]

why are you rolling your eyes at that statement?

[tawny panther]

I don't know if it can be a single point

Circle and empty is fine

[dark sparrow]

the sphere and plane can be tangent to each other

that is when their intersection is a single point

as an example you could think of the sphere x^2+y^2+z^2=1 and the plane z=1

[tawny panther]

Thanks let me visualise in desmos

When the spehere is just touching the plane

[dark sparrow]

that is what i said, yes

[rotund sphinx]

The focus of a parabola y²=4ax is S and P is a point on a parabola. The circle drawn using SP as diameter:
i) touches the axis of the parabola
ii) touches the tangent drawn on vertex
iii) touches the directrix of the parabola
iv)none

help

[dark sparrow]

!status

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[ember river]

No more hesitation

[bronze wind]

How do I solve for x using the 30-60-90 rule

[lime dune]

what are the ratios of the sides of such a triangle

let’s say the shortest leg has length s, then what is the length of the longer leg and the length of the hypotenuse

[vivid ferry]

maybe using shift tan(14/x) = 60 to find the length of that beside 14 cm side, then you can use pythagoras theorem to get x

[bronze wind]

well I only have the length of one of those sides

and its dealing with radicals

[silent plank]

do you know the ratios of sides in a 30-60-90 triangle

[lime dune]

that there are radicals literally does not matter

the whole point of the 30–60-90 ratios is that knowing one side length uniquely determines the entire triangle

[lime dune]

and you still haven’t answered this

if you can’t answer that then look it up

[bronze wind]

I know the formula for the sides

but when I try to solve for the shortest side I get a weird radical

[lime dune]

show me what you’re getting

[bronze wind]

I get 14 sqrt 3 over 3

[lime dune]

what’s so scary about that?

[bronze wind]

is that right?

[lime dune]

and no, you’re off by a factor of 2

can you figure out why?

[bronze wind]

no

[lime dune]

😭

why would the HYPOTENUSE be shorter than a LEG

[bronze wind]

im trash at math man

[lime dune]

you found the length of the shorter leg

now the hypotenuse

[bronze wind]

im solving for the shorter leg

[lime dune]

is twice that

the picture you provided seems to suggest that they want the hypotenuse

[bronze wind]

yeah thats easy though

is the radical I got for the shorter leg correct

[lime dune]

yes

[bronze wind]

ok

[lime dune]

and it’s not “weird” in any sense, you’ve probably seen way nastier radicals pop up in other places

[bronze wind]

ok

I just multiply the numerator for the hypotenuse right

[lime dune]

what

too vague be more specific

[bronze wind]

like I only multiply the 14 in the measure of the shorter leg

not the denominator

[lime dune]

uh yes

that’s like true in general? ie basic algebra?

[dark sparrow]

!status

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[dark sparrow]

@upper karma

tfw

ok well can you read the bot's msg and answer me regarding your progress?

[vivid ferry]

I'm assuming this is a regular octagon, so all the angles are the same.

The total angle of an octagon 1080, and we can divide it by 8 to get each angle value. The answer would 135. Then we can use the value to get the angle of that next to square root 18. Using sine law, we can determine the length of one side and get our answer, 3 cm. Now we can add up the height of the triangle: 3+4+3 = 10 cm and use Pythagoras theorem to get the length of m: square root 10^2 + 4^2

[bronze wind]

again, I am shit at math

I shouldn’t be passing honestly

[vivid ferry]

Anytime

[dark sparrow]

!nosols

[lime crown]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[dark sparrow]

also you are wrong in assuming this octagon is regular.

[vivid ferry]

ah ok

sorry

[rotund sphinx]

@dark sparrow 1

[dark sparrow]

ok show what you've got thus far

[rotund sphinx]

sorry i meant 1

[dark sparrow]

bruh

[dark sparrow]

you can draw an actual circle in desmos lol

[rotund sphinx]

i want solution and understanding

for approaching the problem

[dark sparrow]

we won't give out solutions

but your desmos approach is good i would say

[rotund sphinx]

The focus of a parabola y²=4ax is S and P is a point on a parabola. The circle drawn using SP as diameter:
i) touches the axis of the parabola
ii) touches the tangent drawn on vertex
iii) touches the directrix of the parabola
iv)none

[rotund sphinx]

ok

[dark sparrow]

also in answer option 2:

touches the tangent drawn on it
what does "it" refer to?

[rotund sphinx]

i am in grade 11 rn

[rotund sphinx]

this is a multiple choice question

option 2 maybe wrong

[dark sparrow]

please do not call me "bro".

[rotund sphinx]

sorry i didnt see the pronouns

[dark sparrow]

the icons

but ok whatever. please edit the "bro" out of your msg.

[rotund sphinx]

done

[dark sparrow]

well i think we need to understand what option 2 says before dismissing it as wrong

so you're saying "it" refers to the circle??

[rotund sphinx]

i think so

[dark sparrow]

then option 2 sounds weird

[rotund sphinx]

yeah

[dark sparrow]

any circle touches its own tangent

we wouldn't have needed to know any of this parabola shit

[rotund sphinx]

@dark sparrow sorry i mistakenly wrote wrong option

option 2 said tangent drawn on vertex

[dark sparrow]

https://www.youtube.com/watch?v=kpwNjdEPz7E

so that would be the y-axis in our case.

[rotund sphinx]

hmm

i wish focus was given in the question lol

[dark sparrow]

you put the focus correctly as (a, 0)...

[stiff moon]

Guys im actually so confused can someone explain how to do this for me?

[meager python]

could anyone help me with this?

[edgy stirrup]

i think it goes this way

[stiff moon]

I tried that but the answer isnt 47 🙁

[edgy stirrup]

for number 8

[edgy stirrup]

how did u do it ?

[trail tendon]

you can't set the lines equal because...you don't know they are equal lol

unless they were both passing through the center of the circle

[stiff moon]

My teacher said if the answer is correct the box will turn white and i did it thr same way you did and got 47 but its wrong

[edgy stirrup]

i did that because AE and BD are diameter of circle

[trail tendon]

how do you know?

[edgy stirrup]

by the figure...

[trail tendon]

if it doesn't go through the middle of the circle, you can't confirm its a diameter

right?

[edgy stirrup]

idk 😭

[trail tendon]

no like

they are actually secant lines

they are not the diameter

they seem to be random length

but idk why im talking i have no idea ohw to do it 💀

[edgy stirrup]

lmaoaoao

[trail tendon]

i just know thats NOT how to do it 💀

[edgy stirrup]

it seemed like diameter to me😭

lmao

what if creating triangles by them?

[stiff moon]

I font even know how to do it

I hate geometry

Id rather eat shit thrn do geometry

😡

[edgy stirrup]

omg😂😂😂

[trail tendon]

i literally would love to learn geometry because i somehow don't know it???

i think i literally forgot my geometry

[stiff moon]

LILE I LISTENED TO THE TEACHER DURING THE ENTIRE LESSION AND I STILL CANT UNDERSTAND THE LAST 3 QUESTION ☹️

[edgy stirrup]

what about 10

[stiff moon]

I gave up for all of them

[dark sparrow]

do you want to bitch about it or do you want us to help

[edgy stirrup]

does it have to do with the pythagorian

[stiff moon]

😞

[stiff moon]

Probably

[trail tendon]

hgelp

[dark sparrow]

if you wanna bitch about it that's fine, but do it in #chill

[stiff moon]

Please help

[dark sparrow]

can i see the question again

[dark sparrow]

which one of these

[stiff moon]

Just 9 and 8

[edgy stirrup]

all of em

oh

[stiff moon]

I can kinda understand 10

Not really tho

I need someone to explain or smtnn

[dark sparrow]

do you know basic trig?

like soh-cah-toa kind of trig

for 10 you don't need much more than that

for 9 the key idea is that tangent segments to the same circle from the same point have the same length

and for 8, power of a point

[trail tendon]

there's no angles...
i mean you could calculate it inverse trig... or r u thinking of a better way

[dark sparrow]

oh, hold on.

sorry, i misread the diagram and thought x was an angle.

[trail tendon]

ah lol

[dark sparrow]

ok then you don't even need any trig.

[edgy stirrup]

it only has to do w geometry

[dark sparrow]

just pythagoras, since the angle at A is right.

[trail tendon]

how do you know

you know that AB is tangent, but

[dark sparrow]

AB is stated as being tangent to the circle

yes

[trail tendon]

you don't know C goes in the middle

or is perpendicular

[dark sparrow]

hm

you're right

[edgy stirrup]

because tangeng to the circle creates a right angle

[dark sparrow]

we actually arent given that C is the center

but then there is insufficient info

[trail tendon]

💀

what about 8

if C were the center in 8, then you could just set the lines equal

but it clearly isn't

so you odn't know the lines are diameters

[edgy stirrup]

no

it doesnt have to be the center

[trail tendon]

why not?

[edgy stirrup]

idk but u can tell theyr diameters

[dark sparrow]

@stiff moon you still there or what?

[edgy stirrup]

or no

[vernal pilot]

No.

[edgy stirrup]

bro idk

[trail tendon]

they aren't

[stiff moon]

IM HWRE

[trail tendon]

you can clearly tell they aren't lol

[stiff moon]

They arent at the center

[trail tendon]

they have to go through the center to be a diameter, and they have to be a diameter to be equal

[dark sparrow]

ok so @stiff moon for problem 10 the statement needs to include that C is the center.

otherwise it's impossible.

[edgy stirrup]

u probably create triangles by them then

[vernal pilot]

8 is impossible with the given information, same with 10 (although I’m betting they mean for C to be the centre, because of obvious naming conventions).

[dark sparrow]

is 8 really impossible?

[stiff moon]

C is center

[trail tendon]

is 8 impossible?

[vernal pilot]

There is not enough information given.

[trail tendon]

😭

[stiff moon]

Theres no way the teacher would give me an impossible question 😭

[trail tendon]

me thinking i failed geometry:

nah but actually tho...

[vernal pilot]

Unless C is the centre, but that isn’t obvious from the information given.

[trail tendon]

yea

[stiff moon]

C is center in #10

[trail tendon]

and nobody is talking about 7

what happened to 7

[dark sparrow]

power of a point is a thing, yknow

[edgy stirrup]

theres no 7

[trail tendon]

9

im dumb

💀

[vernal pilot]

Perhaps your teacher told you something which would mean something in your class? Like “oh yeah, always assume C is the centre”?

[edgy stirrup]

u blind

[trail tendon]

can't numbers

ye

z

[edgy stirrup]

jk

[trail tendon]

are 4 and 5 side lengths? or...

[stiff moon]

Teacher told us C is center

[trail tendon]

oh

that

changes things

[stiff moon]

I got no clue 😭

[vernal pilot]

But for 8, C can’t be the centre because they intersect with different lengths.

[trail tendon]

true

[stiff moon]

Yeah theres no center in 8

[edgy stirrup]

i have my math exam tmrrw

[stiff moon]

Me fr

[edgy stirrup]

wish me luck

[trail tendon]

something telling me your teacher is on smthn 💀

good luck!

[edgy stirrup]

Lmao

[edgy stirrup]

tyty

[dark sparrow]

for #10 specfically, yes?

[stiff moon]

Yes

[vernal pilot]

And because C isn’t the centre in question 8, I would definitely not go under the assumption that it is the centre in question 10.

[trail tendon]

OHH

[vernal pilot]

Thus neither question is possible.

[stiff moon]

Shes like in her 60s 😭

[dark sparrow]

lord you are just wrong

twice

[trail tendon]

💀

[vernal pilot]

Don’t say I’m wrong. Prove to me how I am wrong.

[stiff moon]

Yeah. I just wanna know how to solve 8 and 9

[trail tendon]

wait 8 is possible?

[dark sparrow]

#8: power of a point
#10: fucking pythagoras

[trail tendon]

i think thats coming soon

[stiff moon]

#10 os most definitely possible

[dark sparrow]

CA * CE = CB * CD for 8

[edgy stirrup]

why so?

[dark sparrow]

look up "power of a point"

[trail tendon]

oh yeah

bro

[dark sparrow]

need i namedrop it a 6th time

[vernal pilot]

In question 10, we are not told it’s a tight angle, thus YOU CANT USE PYTHAGORUS

[dark sparrow]

hopefully not

[trail tendon]

i don't remember geometry 💀💀💀

[stiff moon]

OHHH THANKYOU GOOD SIR

[dark sparrow]

for #10, since it's now known C is the center, CA is a radius, and that's how you know it's perp to AB.

[trail tendon]

look up jusroka said it actually was the center

[dark sparrow]

@vernal pilot do you agree or disagree

[dark sparrow]

please don't call me "sir".

[edgy stirrup]

both

[vernal pilot]

I disagree.

[dark sparrow]

why?

[vernal pilot]

The question doesn’t state that C is the centre.

[dark sparrow]

do you reject the notion that the tangent to a circle is perp to its corresponding radius?

[dark sparrow]

op told us the teacher did say that C is the center in 10.

[trail tendon]

yo

he did

[stiff moon]

Yeah

[vernal pilot]

No I reject the fact that it isn’t explicitly stated.

[trail tendon]

like here

[trail tendon]

oh

yeah

[dark sparrow]

dude we literally got confirmation from OP.

[trail tendon]

well

hard times man

XD

[edgy stirrup]

bro bye

[dark sparrow]

what else of hers do you wanna cast doubt on

[stiff moon]

MY BAD 😞 im sorry ma'am

[vernal pilot]

Bruh

[edgy stirrup]

geometry isnt geometrying

[stiff moon]

Real

[vernal pilot]

It’s not casting doubt, I’m just saying it’s a poorly worded question.

[trail tendon]

this man is einstein

[stiff moon]

All the questions are poorly worded 😭

[trail tendon]

with the power to detect horrible quesitons

[dark sparrow]

i mean you were a literal hardass just now about my use of the info "C is the center"

like

jusrkora told us her teacher did mean for C to be the center

so we have that confirmation

[trail tendon]

jusrkora*

[dark sparrow]

yes sorry typo

[trail tendon]

i typod 💀

[stiff moon]

Its okay guys

[vernal pilot]

If you read my earlier message you would know that I said “Perhaps your teacher told you something which would mean something in your class? Like “oh yeah, always assume C is the centre”?”

[dark sparrow]

again

the teacher did not say that

but they did, according to OP, say that in problem 10, C is supposed to be the center.

what are you trying to accomplish here?

[trail tendon]

people like to argue on here, its okay

xD

[dark sparrow]

it feels as if you might be disagreeing for the sake of disagreement.

[vernal pilot]

Wtf, did you even read my message LOL

[vernal pilot]

Bruh

[dark sparrow]

ops teacher DID NOT SAY "C always stands for the center"

they DID say "C is the center for problem 10"

[trail tendon]

you said that. and then they gave an unsatisfactory answer, but then they gave another answer which was more definite and thats what we're going based on

[stiff moon]

I cant even be part of the arguement because math aint mathin for me

[dark sparrow]

@stiff moon can you back me up here please? is this what your teacher said?

[vernal pilot]

How can you absolutely misunderstand the word “like”?

[trail tendon]

🤣

[stiff moon]

C is center for #10

[dark sparrow]

ok right

[trail tendon]

bro reread the chat

[stiff moon]

Thats it

[dark sparrow]

@vernal pilot the way you worded the question, it was as if you were going to point out that "C is always the center" renders q8 impossible

literally idk whether this was on purpose or not but you kind of made the convo flamey.

we're here to help people with their fucking homework, not dunk on them in an "i'm right you're wrong" fashion.

[vernal pilot]

I obviously didn’t say C is always the centre, don’t misconstrue my words. I merely said that I wouldn’t think of C as the centre unless the teacher gave some additional information.

Which, wow, they did.

[trail tendon]

why is it that whenever theres like geometry problem here i can't solve it but whenever i look up like khan academy or stuff i do samples of problems from almost every section and i know it like the back of my hand???

but when i actually have to apply it/use it i have no idea what im doing?

[dark sparrow]

problems ppl come with here are a mixed bag

KA is stuff you're familiarish with

[ripe bison]

Honestly feels like that's pretty much true for all pre-uni channels, lol. It always feels like everyone comes in with a different curriculum based on their school size/competition

[edgy stirrup]

did u guys solve those problems?

[rotund sphinx]

i meant numerical value of a lol

[slow aurora]

so I'm learning about the addition and subtraction identities, and I'm wondering what the difference between plus or minus and minus or plus is

does it imply that they are opposite signs from each other but both malleable?

[dark sparrow]

$\mp$ only appears together with a $\pm$ somewhere else in the equation, and it means that the two symbols have to be resolved as opposite signs.

[somber coyote]

Ann

[slow aurora]

ok thank you!

[dark sparrow]

... so yes, basically.

[slow aurora]

great, google and my professor just weren't very clear in that

[lucid schooner]

you hard work in the math

[edgy stirrup]

help

the vertices of a regular pentagon are located in the circle with a radius of 5 cm. find the perimeter and the surface/area of the pentagon.

[dark sparrow]

@edgy stirrup do you know trigonometry in general?

[edgy stirrup]

yea

ig

💀

[dark sparrow]

ok

this pentagon is broken up into 5 triangles as you should see clearly

can you tell me anything about these triangles?

[edgy stirrup]

hold on

[edgy stirrup]

reds are equal

idk how this type of triangle is called

[merry mulch]

Isosceles triangles

[edgy stirrup]

ty

@merry mulch u have any idea how to solve this ?

[merry mulch]

Not really.

[dark sparrow]

as in you don't know the english word or you don't know the word in any language?

but ok, yes, that's correct. the triangles are isosceles.

can you tell me what the size of each central angle is?

[edgy stirrup]

the english word💀

[dark sparrow]

as in, the size of the angles that meet at the center

[edgy stirrup]

u mean the blue one?

[merry mulch]

The angle between those two red lines.

[edgy stirrup]

oh its 180-45-45 so its 90

[dark sparrow]

incorrect on all counts.

[edgy stirrup]

what

[dark sparrow]

1. you highlighted the wrong angle
2. there are no 90 or 45 degree angles anywhere in the pic

[edgy stirrup]

1. english is not my language

[edgy stirrup]

2. ok

[dark sparrow]

"meet at the center" is the best i could do.

this is the angle im talking about

what is its size?

(also unfortunately i do not speak albanian.)

[edgy stirrup]

idk i think i should find the one i highlighted first the blue one

[dark sparrow]

you think that you should ignore my directions?

ok

i can just stop lmao

[edgy stirrup]

i didnt expect u to

[edgy stirrup]

no just trying to make it easier for me to find it

[dark sparrow]

this is unnecessary

you can find the angle i marked without finding yours.

[edgy stirrup]

u cant find it if u dont find the one i highlighted first

[dark sparrow]

yes you can.

[merry mulch]

You can since the complete turn is 360⁰.

[edgy stirrup]

oh

so its 360/5

[dark sparrow]

yes exactly.

[edgy stirrup]

so now i find the other angles the ones that are equal

[dark sparrow]

your pentagon is made of 5 triangles like this

your job now is to a) find the missing side and b) find the area of each triangle

and then from those, get the perimeter and area of the whole thing

[edgy stirrup]

i can use the cos theorem

ok

found them

i still need to find the height

so i can get the area

yea i can do it

ok ty

[edgy stirrup]

@dark sparrow how do u know i speak albanian?

[trail tendon]

LOL

[dark sparrow]

the "shtë" gave it away

in the picture

i happen to sometimes recognize orthographic things about other languages, even ones i do not speak

[edgy stirrup]

oh i see

[dark sparrow]

what do you want to find? the length of that gun?

[solid thorn]

its a walking stick innit

[dark sparrow]

oh is it

might very well be

[solid thorn]

bro it dosent fit

[dark sparrow]

sqrt(77^2 + 34.5^2 + 36.5^2) is how you would do it

and also you have to put parentheses when talking about square roots

otherwise square root of a + b is ambiguous as to whether it means sqrt(a)+b or sqrt(a+b)

[solid thorn]

help me

my teacher decided to challenge me since im ahed of my grade

[solid thorn]

help pls

[dark sparrow]

don't troll

<@&268886789983436800> we got a collatz troll here

[solid thorn]

bro

[dark sparrow]

please do not call me "bro".

[unreal thicket]

don't troll the help channels homedawg

[solid thorn]

im not

[dark sparrow]

one more for the block list huh

[unreal thicket]

oh ok my mistake!

[solid thorn]

chill why you so mad

[dark sparrow]

wew can you banish the other guy please

[dark sparrow]

i am not mad

i am just stating a fact

[unreal thicket]

yeah I'll do a cheeky 10 min mute so they get bored and leave

[dark sparrow]

the fact is that the other guy specifically reared his head to misgender me immediately after i asked not to be called "bro"

which is obviously deliberate and malicious, so i wasted no time and just blocked his sorry ass

[unreal thicket]

smurf is muted ann

lets just drop it

[dark sparrow]

ok

[past geyser]

nahhh your teacher bugging 😭

this is the collatz conjecture lil bro

[dark sparrow]

lets just drop it

[lime dune]

next thing you know they come in on a ban evading alt asking how to prove the riemann hypothesis

[hoary totem]

wait 10 minutes lol

[lime dune]

starting now

lmfao

[silent moss]

if u solve it and gimme the answer ill give u cookie ong

[ornate igloo]

🤔

[raw solar]

8-9

[north kindle]

9 I think

[raw solar]

anyone?

how is this not right anyone?

it was idk how hto

tho

[north kindle]

!noans

[lime crown]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[ornate igloo]

oops sorry

[ornate igloo]

review similar triangle theory

[trail tendon]

no it isn't

[hoary totem]

how are yall getting 8 or 9

i count 13

[north kindle]

Oh shit true

I missed some

[tulip wasp]

13 is what I got

[vocal bison]

can someone help how do i find the area of a rhombus only given one diagonal and nothign else

[empty yew]

Send the question

[vocal bison]

wiat

ooo

nvm

[empty yew]

Do you found the answer?

[tulip wasp]

Any of y'all know of a way to draw polyhedra using a compass and straightedge?

[vocal bison]

yea

[inland eagle]

Yoooo

[rich scroll]

Can some1 provide me with an outline or a roadmap for algebra 2 and trig?

[urban epoch]

Is anyone willing to tutor or explain some geometry things to me?🥲 I'm free rn

[proper otter]

,tex Given the pyramid S.ABCD with a rectangular base ABCD, AD = 3a, the triangle SAB is equilateral with side a and is perpendicular to the base. Let G be triangle ABC center. Calculate the distance from CD to SG

[somber coyote]

Fungus 34A05

[proper otter]

id like to check my answer, which is $\frac{a\sqrt{111}}8$

[somber coyote]

Fungus 34A05

[proper otter]

apparently its wrong

[tawny panther]

If we draw a perpendicular on hypotenuse from right angle point then it divides its area into?

Any ratio?

[lime dune]

depends on the triangle

[tawny panther]

It is right angle @lime dune triangle

[upper karma]

obviously

[tawny panther]

@upper karma

What?

I am asking for what ratio it divides

[median heath]

Litteraly have no idea where to start

[lime dune]

that it is a right triangle is not enough information by itself

try a few cases and this should be obvious

[river solstice]

hello

i have a solution for this

(4+3)3 = x^2

[median heath]

Thanks a lot

But can you explain it to me lil bit

[river solstice]

alright

we have a secant and a tangent

forming a weird triangle like shape at the outside

the secant has 2 sides

internal and external

pretty self explanatory

formula is
(internal + external secant segment) times external segment = tangent segment^2

so first we simplify terms
4+3 is 7
7 * 3 is 21
21 = x^2

square root them

square root of 21

is x

[median heath]

Ooohh

I get it now

[river solstice]

internal+external secant segment = secant segment itself

so if youre given the length of the secant then just use that

ofc you would need the external segment in order to solve

questions like these for example where the entirety of the secant length is given

[median heath]

So this would be x equals 6?

[river solstice]

yes

[median heath]

Ok thx

Do u know the solution to this?

[river solstice]

where is s?

[median heath]

S is area

[river solstice]

damn this is cool

ok

lets solve for the area of the rectangle first

[median heath]

That would be 40

[river solstice]

we know that the up and down sides are congruent as well as the dotted line and the 4

[river solstice]

great

so we know that the dotted line

is 4

right?

[median heath]

Yes

[river solstice]

ok and what do we have on the right

what kind of shape is that

i meant left

sorry

[median heath]

Yea thats where im getting confused

[river solstice]

no just tell me what it is

is it a circle?

[median heath]

Lets just assume its half of a circle then

It probably is

[river solstice]

it IS indeed half a circle

or a semicircle

so we know that the dotted line split the circle in half

what line in a circle splits a circle in half

starts with letter d

[median heath]

Diametr

[river solstice]

exactly

now what is the formula for area of circle

[median heath]

Ohh ye and u just divide it by 2?

[river solstice]

pi r squared yes

you have to divide by 2 in order to get radius

[median heath]

4pi

Divide by 2 so

[river solstice]

no dont

dont divide pi by 2

its just 4

diameter is 4

not 4 pi

[median heath]

No im just calculating the area of the circle

Pi 2 squared

Rig by

Right

[river solstice]

funnily enough we didnt have to divide by 2

since 2^2 is just 4 anyways

so 4 times pi is

this according to desmos

[median heath]

Ok

[river solstice]

so you add this to 40

its 42.57

units squared

[median heath]

Oh ok

Thank you

[strange spear]

While looking for practice exercises stumbled upon this

Doesnt have an answer key

idk what to do tbh

central angle?

[silent plank]

considering that will be helpful, yes

first goal would be to first find DE

[pine wigeon]

easy

[vivid ferry]

what is it asking for?

x?

[dire furnace]

I’m like really doubting I got this right, but (rounded) I got 6.58 meters for this question, would anyone mind checking?

[dull pilot]

i remember you

arent you the one in the other math server?

[river solstice]

sorry i dont remember you

[river solstice]

there is another?

[dull pilot]

yea lol

[river solstice]

https://tenor.com/view/yoda-there-is-another-star-wars-jedi-gif-5140031

[dull pilot]

well

i dont think this server and other one are related tho

[prime adder]

Hi

[river solstice]

yeah wassup

[fast carbon]

Hello! I'm having some trouble finding the height. Not for the prism, but for the triangle. Can someone help me?

[autumn raft]

This may not be the right channel, so please let me know if there is a better place to post this on this Server. I assume that the Venn diagram of gamers and people who are into math would be high here and I am looking for likeminded people in that regard.

I am in the very early stages of making a math game for high-school and possibly early university math. The ambition for the game is to feel like a real game. Therefore, I keep the math optional, so that players self-motivate to use math (vs. virtually all math games, I am aware of, where not doing the math stops the gameplay). In line with George Polya's view on guessing being fundamental to math problem solving, you can always get around the math through guessing. To keep it short, take a look here: https://baugarten.game

Please let me know of places, where I can find other like-minded groups. Good games are built on feedback, even when it is early days. So, please let me know what you think.

[strange spear]

Yes

x

[dark sparrow]

#discussion if anywhere

[strange spear]

Hi there

[rugged shuttle]

how would one go about (trying to) solve this manually (without a calculator)?

or this one

[dark sparrow]

you would not

arctan(3) is not a clean value.

who's forcing you to calculate that without a calculator...?

[heavy apex]

Anyone know of an elegant derivation of the formula for an ellipse? I can do the usual derivation but it just seems so long and messy. I've been trying to find nice abstractions of certain steps, but nothing seems to make it work out in a very compact sequence of steps.

[dark sparrow]

what do you think

[maiden brook]

yes

one per side

I should have said

wait nvm

@dark sparrow this is what I meant to say: You are given four points such that each lies on a distinct side of some square. Under what conditions do there exist other squares such that each point also lies on them, one per side?

[leaden epoch]

Try to solve it for the simpler case where the vertices of the new square are in those 4 points

[maiden brook]

sorry wdym?

the points can’t lie on vertices

only edges

[leaden epoch]

the vertices are part of the edges o-o

[maiden brook]

ok u know what I mean

[leaden epoch]

in that case take two square which intersect in the edges

what you'd have?

you can take a particular example

[maiden brook]

sorry ur phrasing things weirdly

idk what u mean

[leaden epoch]

mb

Draw a square A

Once you did it, draw a second square B in such a way that every edge of A intersects at least one edge of B

[maiden brook]

yep

[leaden epoch]

Now choose 1 point in each edge

and think about 3 things you can say about those points

[maiden brook]

idk exactly sorry

there are 8

well it depends

[leaden epoch]

I know 2 in each side

[maiden brook]

yeah

they dont even necessarily have to be the same size right

[leaden epoch]

no day don't

ok so can you choose them in wayt the forms a square?

[maiden brook]

like this

but still would also work

(doesnt form a square but two squares pass through it)

[leaden epoch]

yeah, nice

[maiden brook]

but this @leaden epoch has two squares that pass through the four points

[leaden epoch]

can you tell when they form a square?

[maiden brook]

if u label the intersections in clockwise order then every odd/even pairs

[maiden brook]

why does that matter though?

[leaden epoch]

look you can't use this

those two points are in the same size

top and left points

[maiden brook]

oh yeah im stupid

[leaden epoch]

So, what you need now is to proof that those 4 points in fact form an square

and the other 4 as well, and argue why you can chose only those 2 combinations

[maiden brook]

so i guess the argument is that this is only true if the four points lie on a common square themselves

[leaden epoch]

yup

[maiden brook]

thanks

one more thing

the original problem was to be given the same setup and asked to construct a square through those four points

how would u do that?

[leaden epoch]

you could just extend the segments to be lines

and take the intersections

[maiden brook]

so if i was given four points like this what should i do?

[leaden epoch]

That's wrong :V

I'll explain later

[maiden brook]

@leaden epoch can u explain then

[leaden epoch]

I thought something would work but it only guarantees it is a rectangle

not idea for a squre

[restive hinge]

I need help with floor plan conversions

[maiden brook]

any ideas?

[leaden epoch]

No :/

[rugged shuttle]

Lol alright the book said to use a calculator but I was also trying to do it without one

[empty yew]

These points would make another square i think

[restive hinge]

Yes

[maiden brook]

that doesn’t rlly matter

I came up with a solution earlier

messy but it works:

1. Start with points E, F, G and H and then construct pairs of circles by diameters of points on adjacent sides (labeled I and J). It is clear that two of the vertices with lie along the circumference of the circle (circumcenter of right triangle is midpoint of hypotenuse).
2. Construct the midpoints of arc EH and FG, K and L, respectively, and by a triangle similarity argument the diagonal of the square must contain points L and K. So u have one diagonal.
3. Construct the other and you are done

https://cdn.discordapp.com/attachments/885647909067038767/1220558874596085830/image.png?ex=660f6108&is=65fcec08&hm=52d2fdcee59419b30d56f4e26d6bd0a89d5ea649429705838a3c7768e2da4ee1&

[sly cargo]

no i dea how to solve

[lime dune]

draw a picture

label lengths

[lime dune]

now connect some radii

assign variables, see if you can make any equations out of them

[main mountain]

y=-9(|x^2-0.5|)+2 Does anyone know how to describe this transformation?

[lime dune]

don’t spam the same problem in multiple channels

[swift light]

sorry if this sounds dumbs im 3 energy drinks in right now, is the angle i highlighted with blue also 90 degrees???

[cunning lion]

assuming the line from A to B is one straight line, then the two angles have to add up to 180

[swift light]

okay thank you\

[upper karma]

yeah the angle that makes an 'L' is always a 90 degree angle, keep that in mind.

[clear anvil]

https://cdn.discordapp.com/attachments/1081837589780234241/1220633267976536066/image.png?ex=660fa651&is=65fd3151&hm=51181885c4211bc7794ca0433a7eae6db9e441196bf66656bf05f75810fe71e2&

How to show that red is similar to green for instance?

and that all these 4 triangles are congruent

I used these assumptions to actually solve the problem, but looking back i can't really justify how i made these assumptions

[lime dune]

angle chase a bunch

all the right triangles here produce a lot of angle equalities

[clear anvil]

i can do that in a minute?

[lime dune]

very easily

like for example

let x be the smaller angle of triangle 4

[clear anvil]

okay so angle chasing means just writing out -> 90 -> 90 - x and stuff like that?

[lime dune]

what other angles equal x in the diagram?

yea

[clear anvil]

okay sure i can try

[lime dune]

all the parallel lines/right angles/whatnot should make this very easy

[clear anvil]

okay sorry for the shitty writing cuz mouse plus i wasn't really focused on the effort

but like this?

[clear anvil]

so the answer to this is AA similarity

[lime dune]

yeah

[clear anvil]

the answer to this is all congruent triangles

[clear anvil]

okay what if i were to go from here to get my answer

what am i doing?

[clear anvil]

for this

[lime dune]

ok lemme draw smth

[clear anvil]

okay well i can use my approach

but tbh i don't think i can do all this in like 2 mins lmao

i used that:

,,\frac{A_B}{A_s} = \qty(\frac{l_b}{l_s})^2

[somber coyote]

nyxie9151

[clear anvil]

so what i did is find the hypotenuse of the big triangle

[lime dune]

yeah

(i arbitrarily set the square side length to 2)

[clear anvil]

and use similarity on green

[lime dune]

yep