geometry-and-trigonometry

[ocean oracle]

then what would u use

[lime dune]

to get from V to T you move up 5 and right 5 right ?

[mental sigil]

how to solve C

[lime dune]

now since RS is parallel and congruent to VT

that means that to get from R to S

you also move up 5 and 5 right

[ocean oracle]

uhm

[lime dune]

wdym solve

[mental sigil]

simply I mean

[ocean oracle]

you see I know the answer from that

but

how do you solve it algebraiccaly

or however u spell it

cauz I dont think imma show my work like that

[lime dune]

ah you’d use slopes and distance in that case

[ocean oracle]

the slopes are the same

[lime dune]

it’s kinda annoying when you can just reason it out visually yea

[ocean oracle]

and the distance is square root of 50

[ocean oracle]

ye ik 😭

[lime dune]

slope is 1

[lime dune]

first write everything in terms of sine and cosine

and see if you can simplify using Pythagoras or smth

[ocean oracle]

what could you do with the slope

[mental sigil]

I did (1/cos)^2 + (sin/cos)^2

idk what to after rhat

[lime dune]

(y+6)/(x+2)=1

[lime dune]

I think this is some sorta tangent double angle

owait no

can I see some of the other questions on that sheet to see what kinda simplifications they do

[mental sigil]

okay

[ocean oracle]

wait what would you do after you find the slope

[lime dune]

you make another equation using distance formula

now solve that resulting system

[mental sigil]

do I divide by 1/cos each side

never mind

[lime dune]

oh wait is it not just

2sec^2-1?

[mental sigil]

The answers said 1+tan^2 theta

[ocean oracle]

wait but how would you use the slopes in there then

[mental sigil]

1+2tan^2

[lime dune]

I gave you the equation for that earlier

[lime dune]

yeah, that results from noting sec^2=1+tan^2

[mental sigil]

ohhhhh

I GET IT

Thank you!!!

[ocean oracle]

oh you make teh distances equal to each other?

[lime dune]

yeah

[lime dune]

npnp, glad to help

[ocean oracle]

wait a second

(I just came back from basketball practice)

wouldnt the distances cancel out each other

[lime dune]

no

[ocean oracle]

because they are congruent

[lime dune]

one of them involves your unknown coordinates

the other does not

[ocean oracle]

OH

[lime dune]

yea

[ocean oracle]

wait

but how are you going to solve the equation if there is the unknown coordinate

given points P (2,1) and D (7, 11), find the coordinates of a point T on segment PD such that PT/TD = 2/3

do you know how to do this question

using the midpoint formula

[foggy gust]

could anyone help me with it please?

In the isosceles trapezoid ABCD with acute angle A equal to 60°, a median EF is drawn, intersecting diagonal AC at point O. It is known that FO is 10 less than OE. Find EF if the perimeter of the trapezoid is equal to 120.

[dark sparrow]

!status

[lime crown]

What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above

[foggy gust]

i've got it

ty

[dark sparrow]

ok 🙃

[valid gate]

geo sucks

,w tanx=1

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by theprophetofthedamned

[valid gate]

why n int

[dark sparrow]

what a great opener.

[valid gate]

oly geo specifically

[dark sparrow]

anyway, WA is giving you the solutions of tan(x)=1 over the entire real line.

[valid gate]

especially when its bash

[dark sparrow]

..., -7pi/4, -3pi/4, pi/4, 5pi/4, 9pi/4, ...

[valid gate]

I hate bash

[dark sparrow]

bashing is by definition unpleasant

[valid gate]

I dont understand why the negative values

the positive ones make sense

Find the values of 'x' for which
(tan 3x - tan 2x)/(1+ tan 3x tan 2x) = 1

was solving this

[dark sparrow]

ok so it makes sense to you that adjacent ones are pi units apart right

[valid gate]

used tan(x-y) identity

[valid gate]

yes

[dark sparrow]

yeah just keep doing that but leftward from pi/4

periodicity applies both ways

pi/4 - pi is -3pi/4

that minus pi is -7pi/4

that minus pi is -11pi/4 etc etc

[valid gate]

dumb question but isnt tangent odd

[dark sparrow]

sure is.

[valid gate]

ok so

I get now

[dark sparrow]

tan(-3pi/4) = -tan(3pi/4) = -(-1) = 1

[valid gate]

I had to use tan(pi+x)=tanx n times

[valid gate]

would the answer be pi/4+npi

Ann?

imma plug into wa and see

,w (tan 3x - tan 2x)/(1+ tan 3x tan 2x) = 1

[somber coyote]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by theprophetofthedamned

[valid gate]

ok let's go

[dark sparrow]

yes

[bitter turtle]

In hyperbolic plane let $x,y$ be two points such that the hyperbolic distance $d(x,y)$ is very small then show that the Dirichlet Domain centred at $x$ is same as Dirichlet Domain centred at $y$.
Definition of Dirichlet Domain : which is denoted by $D_x(G) $ ,where $G$ is a Fuchsian group which acts properly discontinuously on the upper half plane, and $D_x(G)={z\in \mathbb{H}^2: d(z,x)\le d(z,gx) \forall g\in G-{1}}$.

Claim: Whenever $d(x,y)$ very small $D_x(G)=D_y(G)$. All the distance here is hyperbolic distance.

My approach: Let $z\in D_x(G) \implies d(z,x)\le d(z,gx) \forall g \in G-{1}$.
So , $d(z,y)\le d(z,x)+d(x,y)\le d(z,gx)+d(x,y)\le d(z,gx)+d(gx,gy)+d(x,y)= d(z,gy)+2d(x,y)$
I think next I need to use that distance is very small. I don't know what it actually mean by very small.

[somber coyote]

spectrum

[lucid path]

how is it 4.1?? when i do 1.4/cos70 (radian version btw) i get 2.2??

[dark sparrow]

why are you using radian mode on your calculator

the angle is literally written as 70 DEGREES in the triangle

[lucid path]

im going to harvard

[dark sparrow]

"I am going to Harvard, therefore I will keep my calculators in radian mode at all times, even to my detriment."

did i get you right?

[lucid path]

im just a girl

btw yes

[dark sparrow]

.....

well, those were two really shitty excuses.

when you are working with angles in degrees, you put your calculator in degree mode.

when you are working with angles in radians, you put your calculator in radian mode.

i'd imagine that somebody going to harvard would want to know this simple fact.

[past geyser]

LMAO

[lucid path]

i shouldnt have signed up for geo in the 8th grade

i have a 9 in that class but i cant remember the simplest of stuff 💀

anyways thanks

[dark sparrow]

9 out of what, if you don't mind sharing

[modern gull]

35 probably

[lucid path]

i MEANT 90

STOP

[dark sparrow]

ah, so 90%.

[past geyser]

is that not a good mark?

[dark sparrow]

@lucid path some countries have grading systems where a 9 is an actual commonly given grade.

so my question was completely genuine.

i was not making fun of you or anything.

[modern gull]

i think she just had caps lock on

i is not capitalized and everything else was

[lucid path]

yeah ik

[eternal pike]

how do i do this???

help plz!!

[mystic charm]

Do you know what happens when two triangles are similar?

[dark sparrow]

do you still need help with this

[warm magnet]

Use the properties of the similar triangles, friend

It's not that difficult

And if you don't manage to do that, try to read again your notes

The day of your exam, nobody will be able to help you

[fickle rose]

create a proportion

[torpid sigil]

Tales or whatever that thing is

Thales

You have everything there to find (BA)

Solve it with the thales' theorem

[sacred lance]

I have a question

if a hat is a pentagonal pyramid, then whats the minimum number of such hats in order to cover an icosahedron?

I really need ts

[dark sparrow]

"ts"?

[sacred lance]

this*

[dark sparrow]

okay,

tried anything so far?

[sacred lance]

well

I tried with 5

I don't really know if I put the hats well enough

[dark sparrow]

and did you succeed?

[sacred lance]

but it didn't work

nope

[dark sparrow]

can you show your best attempt, perhaps?

[sacred lance]

ok

[dark sparrow]

don't quite understand what i'm looking at here.

any way you could number the faces (like on a d20, say) and make the thing opaque?

i did some experimentation on my own and seem convinced that 5 hats is not possible but idk yet how to prove that

[terse hull]

What does trig functions actually represent? I wont believe that it's just relations in the right triangle

[dark sparrow]

they represent the x and y coordinates of a point moving along the unit circle CCW at 1 unit per second.

well, that's cos and sin specifically.

tan(x) is sin(x)/cos(x).

[sacred lance]

I mean

its an icosahedron

[dark sparrow]

that much is clear but i can't make out the hats

[sacred lance]

well the white one is seen clearly

the purple one is over under the white one

the cyan one is not very clearly seen

but

I could send the ggb project

yk

[azure orchid]

Fellas please help me

I’m doing pat tests for a high school test

18. Set ABCD to be square. There is a point M on the BC side that makes BM =14, a point N on the DC side that makes DN = 9. If AN divides half the MAD angle, what is the area of ABCD square?

I translated it to this

And I don’t understand stuff like 90-2theta

[jaunty dagger]

I don't know whether it is the simplest method but this is how I think: \
You can solve this question by $2 tan^{-1} ; \frac{9}{14 + x} + tan^{-1} ; \frac{14}{14 + x} = 90^{\circ}$ \
Let $a = tan^{-1} ; \dfrac{9}{14 + x}$ and $b = tan^{-1} ; \dfrac{14}{14 + x}$ \
Then $\tan (90^{\circ} - 2a) = \dfrac{14}{9} \tan a$

[somber coyote]

kelvinchan9786

[sacred lance]

Where is M?

[dark sparrow]

btw @sacred lance i did some kinda ugly case analysis

ive concluded that 5 hats is not enough no matter how you try to place them

basically after you place the 1st hat you get an arrangement of 15 triangles which can be flattened for easier view

and then up to symmetry there's only 3 spots for the second hat to go

and you look at all those cases

one of which is hairier than the others

[azure orchid]

Thanks

[azure orchid]

On bc and makes bm=14

But i already got it

[dry junco]

<@&286206848099549185>

How to do this?

[tough jolt]

if you have a question

i suggest going to #❓how-to-get-help

[upper karma]

Btw..
I searched the difference between a prism n a pyramid in internet. It said, a prism has two bases whereas a pyramid has 1. Well, what's the difference between faces and bases?

[dark sparrow]

bases are a special type of face

the constructions for a pyramid and a prism both start with a flat shape which you call the "base"

but for a prism, you take a copy of the same shape on a plane parallel to the original

while for a pyramid you take only a single point at the top

in terms of structure:

• a prism has two copies of the base-shape connected by a strip of rectangular (or more generally parallelogram) faces
• a pyramid has one copy of the base-shape with a triangular face attached to each side, and these triangular faces all meet at a single point outside the base plane. and that meeting point is called the apex of the pyramid.

or the "tip" if you're informal

@upper karma does this answer your question Y/N

[upper karma]

Y

[dark sparrow]

ok cool

[sweet grail]

let's say the circle has an area of x

how do i find the red covering the circle

[thorn mica]

Area of the red circle - area of the white circle

Or did I misunderstand the question

[dark sparrow]

not enough info

!xy

[lime crown]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[minor wolf]

what to do?

[dark sparrow]

do you still need help with this

[next phoenix]

one thing you can do is do cosinus theorem on PQR triangle and draw a right angle from point T to SU

to use sinTUS

the rest should follow

if im not mistaken you should get 2 equations including a and b

[dark sparrow]

why not use the law of sines instead

much more straightforward

[tired lily]

can't find x

🥺

[dark sparrow]

do you know the inscribed angle thm

@tired lily

[tired lily]

loosely

[dark sparrow]

wym loosely? you either know it or you don't.

state the inscribed angle thm as best you can.

[tired lily]

the bottom angle is 2x greater than the top angle

[dark sparrow]

no good

[tired lily]

learnt the inscribed angle theorem in a foreign language i barely understand

[dark sparrow]

... as in, your native language is English, but you live in [COUNTRYNAME] and don't speak their language well?

anyway, the correct stmt is:

an angle inscribed in a circle is equal to half of the arc it cuts out.

[tired lily]

yes

it took me like a month to realize a хөвч was a chord

[dark sparrow]

hm right

that sounds like Mongol, but i might be wrong.

[tired lily]

it is

[dark sparrow]

i don't speak that language so i can't help you with that.

right

[dark sparrow]

.

[tired lily]

for this i was thinking to

merge

[dark sparrow]

merge?

[tired lily]

don't know how to explain it

[dark sparrow]

... draw it?

[tired lily]

completely lost

[dark sparrow]

well i don't understand at all what you meant by "merge".

do you understand what i said above?

anyway, the correct stmt is:

an angle inscribed in a circle is equal to half of the arc it cuts out.

this

[tired lily]

mhm

[dark sparrow]

ok right

as a corollary, if two inscribed angles cut out the same arc, they are equal.

[tired lily]

so x = 60?

[dark sparrow]

indeed

[tired lily]

oh there's a list of every circle theorem

i shouve probably

read them all first

ok so for this

the angle in a semicircle is always a right angle

so just pythagorean theorem ?

no clue

[proper flax]

yo

[rough lodge]

can somone help me find maximum value of 160sin^2theta + 168sintheta cos theta

[rough lodge]

dont make it hard

you have to find the isoceles triangle

[proper flax]

how good are you with basic trig?

[rough lodge]

i know everything except trig calculus

[proper flax]

Good, can you help me with this?

[rough lodge]

at school standard

[proper flax]

I's gots an exam tomorrow, and this is the only part I am baffled with.

Do we do pythagorean theorem

[rough lodge]

i think so yeah

[proper flax]

Can you solve it for me? I need an exemplar.

this is the whole thing

[rough lodge]

first is 53 degrees you have to remember that value its important

[proper flax]

okay

[rough lodge]

bro this is hard

we can use the Pythagoras thm but it will only give round off ans

not to the decimal point

[proper flax]

what grade are u in?

[rough lodge]

10

you?

[proper flax]

9th

I understand everything but this bruh

and it's the only thing I know that is coming in the exam

[rough lodge]

i do not remember studying this in 9th grade

[proper flax]

Different curriculum.

[rough lodge]

which country are you from?

the second is 106 degrees

[proper flax]

uae.

[rough lodge]

sorry 116 degrees

[proper flax]

What is did is arctan(1.7/3.8) = 24.1

I then subtracted that by 180 which led theta to be 155.9m

I think thats the answer

waits who the smartest in trig

[rough lodge]

is used sin2theta for37 degrees and it came very close

idk maybe i am wrong

[proper flax]

How is it sin 🗿

[rough lodge]

and that is the mistake i made

are you given calculators during exams?

[proper flax]

ye

[fringe perch]

@tired lily x is 70 right

[rough lodge]

then you can easily calculate whats the problem

[proper flax]

wait nah

I think my answer is incorrect.

[rough lodge]

i think it is correct

[proper flax]

@dark sparrow are you good with trig

[proper flax]

I just emailed my math teacher, and he said it is 114.1.

[rough lodge]

i think you had to put 90-24 degrees

told ya

24 is on the other side

[lime crown]

Please do not ping individual helpers unprompted.

[proper flax]

Okay, I solved it.

[rough lodge]

ok

now help me with my question

can somone help me find maximum value of 160sin^2theta + 168sintheta cos theta

[proper flax]

I actually don't know how to do yours 😔

[tired lily]

zero clue

[fringe perch]

yes i found

its

70

[tired lily]

OHHHH

IC

[proper flax]

are you british

[fringe perch]

why?

no

[proper flax]

Idk your vibes give me british

[proper flax]

oh ok

[fringe perch]

what vibes?

[proper flax]

your aura

[fringe perch]

what?

aura?

how can u sense my aura?

[proper flax]

Homie, do you want me to explain the mathematical equation on why I THOUGHT you were british?

[proper flax]

Your vibes bro 😭

[fringe perch]

ok bro

[fringe perch]

yes

explain pls,

[proper flax]

Boy.

[fringe perch]

boy. ? wydm?

[fringe perch]

??

[inland jay]

If |x| > 0 and | y | < 0, then point P(x,y) lies in quadrant:
a) I
b) II
c) III
d) IV
e) None

Isn't this Question wrong?
The absolute value can never be smaller than zero, since it is merely the distance from origin.

[silent plank]

well the best option would be e)

[past plinth]

yeah its wrong

so e

[vocal bison]

Help plz i got this wrong on my quiz

Ping pls

[crude slate]

av 15 ?? @vocal bison

[vocal bison]

wiat how

oh wait nvm

thx

[median ledge]

no problem

[vocal bison]

wait i thought 15 was RA

[crude slate]

is it corret

[vocal bison]

idk ?? I got that quesiton wrong

tahts why im asking

[crude slate]

RA = RV

[vocal bison]

i just did it again and i got 15 for ra and 2 for av but i dont even know

[crude slate]

oh i mean RA = AV

[vocal bison]

wait

how

i thought the radius was 17 so 17-15=2

[crude slate]

oh yeah

ur right

yeah 2

wait

how did u get radius

[vocal bison]

its given

its rt

[crude slate]

yas 2

[vocal bison]

i think

[crude slate]

yup

[vocal bison]

ok thx

[turbid barn]

https://tenor.com/view/geometry-dash-flamewall-gd-gif-5918391188933860766

[green marten]

https://tenor.com/view/geometry-dash-fire-in-the-hole-lobotomy-normal-face-gif-15417335841440487130

[dusky locust]

certainly some of the geometry of all time

[shut cave]

pre trig is harder than trig (imo)

[dapper willow]

Alr

I need help

[fickle rose]

what even is pre trig

[north kindle]

geometry?

[shut cave]

its what comes after geometry 2 but before trig

[foggy skiff]

so like

between geometry 2 and trig

[broken wolf]

How would you go about solving that?

[lime dune]

similarity and then A=rs

[final vale]

How do you prove it?

[dark sparrow]

what does the star mean?

@final vale

[final vale]

Where star? Its plus and "bigger"

[final vale]

I see, it's a degree

[dark sparrow]

ok

so you want to prove $\sqrt{\cos(70\dg)} + \sqrt{\sin(70\dg)} > 1$

[somber coyote]

Ann

[final vale]

Got it, thanks.

[dark sparrow]

??

i wasn't done lol

what are you thanking me for

i just echoed the problem back to you

[final vale]

I mean the way to write a task through a bot.))

[dark sparrow]

wild guess:

are you russian?

[final vale]

Yea

[dark sparrow]

можем по-русски продолжить

[final vale]

хахаха

[dark sparrow]

тебя выдали скобочки-смайлы, если что)

[final vale]

Понял)))

[dark sparrow]

прогресс есть?

[final vale]

пока нет

[dark sparrow]

ну вот тогда тебе такая идея

для $0 < t < 1$ верно, что $\sqrt{t} > t$

[somber coyote]

Ann

[dark sparrow]

то есть если нам удастся доказать, что сумма самих синуса и косинуса 70° больше 1, то больше 1 будет и сумма корней

[final vale]

А, понял

только как это доказать

ну они оба положительны

[dark sparrow]

какие-нибудь тригонометрические формулы у нас есть?

типа sin(x+y) = sin(x)cos(y) + cos(x)sin(y), например

[final vale]

Да, все что следуют из cos2x+sin2x=1

[dark sparrow]

^

[final vale]

cos^2x+sin^2x=1

[dark sparrow]

да

то есть формулой для синуса суммы пользоваться можно, да?

[final vale]

Да

[dark sparrow]

тогда $\sin(x) + \cos(x) = \sqrt{2} \sin(x + 45\dg)$

[somber coyote]

Ann

[final vale]

А не такое я не знаю

Периодичность есть, простейшие уравнения есть и соотношения тригонометрических функций для одного аргумента

[dark sparrow]

из формулы синуса суммы следует напрямую

$\sin(x + 45\dg) = \sin(x)\cos(45\dg) + \cos(x)\sin(45\dg)$

[somber coyote]

Ann

[dark sparrow]

sin(45°) = cos(45°) = 1/sqrt(2)

[final vale]

Ну вот про это разложение я не вкурсах

[dark sparrow]

ы

[final vale]

что sin(x+45) можно расписать на sincos

[dark sparrow]

а что ж ты сказал "да", когда я спросила про формулу синуса суммы...

блин. ладно. можем и по-другому

[final vale]

ну я про эту только, и там модуль синуса чему равен или tg^2x=1/cos^2x

[dark sparrow]

tan^2(x) не равен 1/cos^2(x)

ты единичку забыл

ладно, проехали

[final vale]

da tochno

[dark sparrow]

вместо sin(70) + cos(70) > 1 можно доказать, что (sin(70) + cos(70))^2 > 1

а вот это уже поддается

[final vale]

Ой

я забыл условие дописать

[dark sparrow]

ы

да что ж такое

ну скинь скриншот исходного условия что ли

или фото

это все?

ок

ну вообще это мало что меняет

я все равно скажу, что (sin(x))^1/3 > sin(x)

все равно док-во исходного утверждения мы сведем к sin(70) + cos(70) > 1, а это -- к (sin(70) + cos(70))^2 > 1

и будет тебе счастье

как доказывать (sin(70) + cos(70))^2 > 1 ясно или требует пояснения?

[shut cave]

i dont speak/read russian 🙂

I also dont speac/read english

i only type english

random letters, and hope they make words

[frozen ocean]

there's no need to worry about that unless if it is not your first language

but if wish to learn the language then that's just fine I guess

as im not an English main or Russian either but still learning English

[sacred path]

Fantastic

[shut cave]

ok

[broken ledge]

[ripe prairie]

I was stuck in this for half the class

Help

[fringe perch]

which one is 63 degrees?

[dark sparrow]

the one that the label is closest to

presumably

[fringe perch]

ok

[dark sparrow]

this one

[ripe prairie]

ya

[dark sparrow]

ok i think it is best to give some points names

[ripe prairie]

it didnt give any but

ill label them sure

[dark sparrow]

i am not blind i can see just fine the points are not named

that's why i am suggesting that you give them names

[ripe prairie]

ill do that now

[dark sparrow]

show me what names you go with

so we're on the same page

[dark sparrow]

!nosols

[lime crown]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[fringe perch]

bro its 36 , is it correct?

[dark sparrow]

!nosols

[lime crown]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[fringe perch]

...

[ripe prairie]

idk

how is the bottom angle 54

ik all angles add up to 180

but

[fringe perch]

the both lines are radius bro

[ripe prairie]

wait what

[fringe perch]

it forms a isocles triangle

so base angles are equal

[ripe prairie]

but the 90 angle is cut into 2 pieces so its not 90 in the isoceles

right?

[dark sparrow]

fuck

ok

[ripe prairie]

its 90 in the whole right triangle

[fringe perch]

yes

[ripe prairie]

oh wait so that means that the cut up piece of the 90 is 63?

ohhhhhhhh

[ripe prairie]

i get it

i get it now

thanks

[fringe perch]

ok

the answer is 36 right?

[ripe prairie]

i dont have the answer key

but it looks riught

[fringe perch]

ok

[ripe prairie]

thanks

[fringe perch]

youre most welcome

[dark sparrow]

gonna tap the sign a third time despite clearly not being listened to

!nosols

[lime crown]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[fringe perch]

what does that mean?

[fringe perch]

tis one

[dark sparrow]

read what the bot says

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[dark sparrow]

do you know the "don't make me tap the sign" meme? that's what i am referencing. i am invoking a factoid, which i metaphorically refer to as "tapping the sign"

[fringe perch]

ok , idk about that meme.

[dark sparrow]

the important message is:

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[shut bronze]

is it the "because I can't read"

or the "if these children could read"

that's the only sign memes I know

[dark sparrow]

it's neither of those

[shut bronze]

I searched it up

[shut bronze]

haven't seen that before

I see

[fierce depot]

love this server

[upper karma]

anyone know how they got this

i dont get where that equation is from

[dark sparrow]

ultimately from similar triangles

one moment

triangles ACD and CBD are similar => DA/DC = DC/DB => DC^2 = AD * DB

[upper karma]

I see now thanks

[full vector]

pre university is like high school right?

So I had a question: Is it theoretically possible for a circle to have an infinite radius

[cunning lion]

it can sometimes be useful to think of a straight line as a circle of infinite radius

[full vector]

how does that work?

[lime dune]

it’s the “limiting case” of a circle

as you increase its radius more and more

it looks more and more like a straight line

[full vector]

no but why i dont get it im sorryh

[lime dune]

you gave no information as to why you don't get it

try drawing increasingly large circles

see what happens

[trail tendon]

its theoretically possible, but its not too useful. it would have an infinite radius, an infinite diameter, an infinite circumference, an infinite area, ect.

i mean usually basically everything is "theoretically" true

but i haven't heard of any use of a circle with an infinite radius

there's just kinda no point

unless its something i haven't seen, heard of, or studied yet

which is definitely possible

but im guessing not since this was in the geometry and trig section

lol

[dire meteor]

is someone here able to help me out i have been asking for a long time this one problem to confirm my ansers

[trail tendon]

depends, whats the question?

[trail horizon]

I’m doing a precalc sheet and wondering if someone could check my work because I have no clue if I’m right

[trail tendon]

do you wanna send it or smthn

[trail horizon]

Yeah hold on

Didn’t know I was in the geometry channel mb

[trail tendon]

its fine XD

im still checkin

they're correct, and I believe 14 is correct i haven't done in a while

[trail horizon]

I completely forgot all my precalc I’m basically re learning now because in retaking it at uni

[trail tendon]

thats relatable 💀

[trail horizon]

Thank you very much though

[trail tendon]

np

i'm going to review exponential decay 💀

i can't remember why its t/5 in the exponent

[trail horizon]

Ima be honest I guessed that I needed to put that there

[trail tendon]

oh 💀

maybe we should double check it idk

i mean i can't see where else it would go

[trail horizon]

Yeah I wasn’t to sure if I needed that

[trail tendon]

i still think its probably right

but

[trail horizon]

But since it’s the half life I was thinking that it needs to be applied to the time

And I just guessed by dividing

[trail tendon]

wait

nah

its the P = e^rt formula i think

maybe

because its half life exponential decay

i'm looking it up 💀

wait

nah i think you were right

[trail horizon]

Hmmm

[trail tendon]

i guess it is that one 💀

mb

[trail horizon]

No your all good I’m just as confused

[trail tendon]

loll

[trail tendon]

but this is what you had so yeah its correct

OHH

maybe e^rt was compound interest

wait

continuous compound interest

is what i meant

[trail horizon]

That sounds right

[trail tendon]

yeaah

i should not be getting those confused 💀

r e v i e w time :D

[trail tendon]

but yea im pretty sure all ur stuff is correct

[trail horizon]

Awesome thank you

[little fog]

Can someone tell me what y is

and x

[leaden prawn]

What do you know about the left triangle

[proper matrix]

Can someone help me I don’t know what I don’t know about this problem 😭 I keep doing it wrong

[leaden prawn]

Are those degrees, minutes and seconds?

That's so silly

131⁰18'19"

180-^

I think

I did it in my head so I don't know if it's right

[proper matrix]

But 180 turns into 179 59’ 60” right…?

[little fog]

It’s isocilies

And it’s 72 degrees

[proper matrix]

Sorry and yes they are degrees minutes and seconds

[vocal bison]

Help please i got majority of this wrong on my quiz 😁 i still dotn understand ping me

[vocal bison]

y is 72 degrees bc alternate interior <s
x is 54 degrees
180-72=108/2
i think

[languid mesa]

Can any one tell what will be it's answer

[dark sparrow]

Can any one tell what will be it's answer
no

!noans

[lime crown]

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

[dark sparrow]

however, if you have some progress to share, or if you're stuck with zero idea how to begin, say so

[languid mesa]

Can any one tell me what will be answer of this question

[proper matrix]

Bruh😂

[languid mesa]

Why you are laughing

[languid mesa]

Ohkk

So can you help me

[dark sparrow]

first tell us how much progress you've made on this problem

if you've made zero progress, say you've made zero progress

[languid mesa]

zero progress

[dark sparrow]

ok right

you might want to note that $Q = kP^{-1}$

[somber coyote]

Ann

[dark sparrow]

and you might want to recall something about finding the inverse of a 3×3 matrix

[languid mesa]

Ohkk

So answered will be b and c what you think

[dark sparrow]

i don't think anything, because i don't know how you got to either of those.

also, is this a "pick only one" or "select all that apply" kind of question?

[languid mesa]

No it's jee advance question

These question have more than 1 option or 1 option

It's jee advance 2016 question

[dark sparrow]

so then it's a "select all that apply"

[proper matrix]

Am I missing something it says it’s wrong 🥺

[jaunty maple]

I use Pearson too

I don't like it

[proper matrix]

Same

[dark sparrow]

this one's a bit of a -inducer

[proper matrix]

Is it wrong then…?

[dark sparrow]

well

60+40 is not 90, is it?

[proper matrix]

Omg I’m just dumb sorry

🥲

I love you Ann you are the smartest person I know now 😂

[dark sparrow]

such high praise

[proper matrix]

I’d give you the world thank you all to helping me 😭

[languid mesa]

Yess

My answere is comming b and c

[dark sparrow]

don't call me "bro".

don't call me "sir" either.

[languid mesa]

Then

[dark sparrow]

do you think i am a man?

clearly you do, since you've tried 3 obviously masculine forms of address.

[languid mesa]

Let's come back to the topic

My answer is b and c

[dark sparrow]

no, let's first make sure that it is crystal clear to you that

i'm a woman

[languid mesa]

What you think

Ya i gott it

[dark sparrow]

and the fact that your tried to call me "sir" and then "mr" is offensive

ok then edit it out of your message

i have a name. you can call me by my name.

[languid mesa]

Ohkk ann

[dark sparrow]

i will repeat myself: i don't think anything, because you haven't shown HOW you got B and C.
show me your work, then we will talk.

[languid mesa]

Okk

Are you a college student

?

[dark sparrow]

what's it to you?

also you still haven't shown your work.

also gonna ask you again to edit the "sir" out of this.

[languid mesa]

I delete the message

[dark sparrow]

deleting the message was easier than erasing three letters from it.

fucking WONDERFUL.

[languid mesa]

Sorry for that

[dark sparrow]

you are like a mushy grape.

[runic pasture]

do you still need help?

[languid mesa]

Yes

[runic pasture]

I just saw that you opened an own thread channel btw

Are they related?

#1215177211020181555 message

[languid mesa]

Yup

No one is helping me

[runic pasture]

i am looking rn

[languid mesa]

Ohkk

[languid mesa]

Yess

[runic pasture]

i think a is definitely wrong

[languid mesa]

Yess

A is wrong

Alpha is -1

B is also correct ig @runic pasture

[runic pasture]

i am trying to understand your work

but according to your numbers yes

[languid mesa]

C is also correct

Then

Cause |Q|is k^2/2

[runic pasture]

yea gimme a sec

[languid mesa]

Kk

[runic pasture]

can you explain your c)

|adj(Q)| = |Q|²

[languid mesa]

We can wright thill like
|P| |adj Q| =2^9
8×8^2= 2^9

[runic pasture]

yeah but how |adj Q| = 8^2

because it says det(Q) = k²/2 and since k = 4 then det(Q) = 8 = |adj Q|

det(Padj(Q)) = det(P) * det(adj(Q)) = 8 * k²/2 = 2^9

So then k = 8√2

[languid mesa]

|adj Q | will be |Q|^2

[runic pasture]

but how

adj Q = Q^T

[languid mesa]

its simple property

[runic pasture]

wait i think i am missing something

[languid mesa]

We can wright |adj Q | as Q^2

[runic pasture]

ah ok i found it

det(adj(A)) = det(A)^n-1

ok then i agree

i got something twisted so yea mb

about d)

det(Qadj(P)) = det(Q) * det(adj(P)) = det(Q) * det(P)² = 8 * 8² != 2^13

so it should be wrong

[languid mesa]

So the answer is b and c

[broken ledge]

geometry formula for triangles:

a2+ b2 = C2

or

C2 - a2 = b2

if the triangle missed the b angle

try this 1, it's for everyone to solve

🫡 follow the formula

[dark sparrow]

@broken ledge what exactly are you trying to accomplish by posting the pythagorean theorem in here

[median ledge]

pythagorean theorem? dont you mean "geometry formula for triangles"?

[north kindle]

the one and only geometry formula for triangles

there are no others

[dark sparrow]

this is not the place for jokes.

[vocal bison]

can someone help me plz or help me start off

[fringe perch]

approxiamately 8246 meters

is it correct?

7154.5 meters

[fresh mesa]

https://en.wikipedia.org/wiki/Neusis_construction

How do I do Neusis construction on the computer?

[upper karma]

yo if anyone could help with this

i mean i tried to square both sides

so a2 + b2 + 2a.b = 1

but then like

if i substitute 1 for a and b

2a.b=-1

a.b=-1/2

no way i just solved it while asking the question 😭

well ty anyways

[dark sparrow]

sloppy notation

[upper karma]

yes sorry my bad

ive been doing math the whole day

i think the notation has been drained from me 😔

finals on saturday

[dark sparrow]

....

take a break lol

[upper karma]

just another day left i can power thru it 😓

[dark sparrow]

don't

it is bad for your health

[silent moss]

yall gotta sleep

[upper karma]

^^ i will definitely sleep tho

i never sacrifice too much sleep for exams

[upper karma]

will do tysm

[dark sparrow]

the ideal amount of sleep to sacrifice for exams is 0

[upper karma]

thats true i didnt for physics and chem

but somehow im forgetting math

[calm ice]

hm

[eager forum]

Hey has anyone worked through Hilbert's geometry and can say if it's a good intro to proof based geometry?

I have so far had a Linear Algebra, Real Analysis and a Number Theory course in my first semester.

Looks a little intimidating ngl

[lime dune]

maybe ask in one of the university channels lmao

this channel is for pre university geometry (so like euclidean, coordinate, etc.)

[upper karma]

Hello

I have a trigonometry test in 5th period

it goes over special right triangles 45-45-90

30 60 90 special right triangles

Trigonometric ratios

Elevation and depression

please help me

[dusty ginkgo]

#rules

[upper karma]

I am not trying to cheat

[dusty ginkgo]

oh

[upper karma]

I am asking for help for studying

I want to ace this test

[inner vapor]

#❓how-to-get-help

?

[languid mesa]

Hey can any one help me in solving a physics question?

[dark sparrow]

!da2a

[lime crown]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[lone shuttle]

I can help with trigonometry guys

[rough lodge]

bot

[dark sparrow]

no shit sherlock

[lime crown]

This channel is only for on-topic discussion. Please take casual conversation to #discussion or #chill.

[languid mesa]

Ok then

This is a very hard one

[past geyser]

I've seen Tibees do this one

it's a JEE problem

[upper karma]

haha

trig identities are so fun

[pastel zealot]

hi

[opaque marten]

aw hell nah

[karmic thorn]

Reccomendation for beginner high school trigo book? Preferbably able to be found online.

[languid mesa]

Yess

JEE ADVANCE

I am having proble to solve this can you help me

[merry fiber]

Guys can someone help me find the modulus and an argument of this.

[dusty ginkgo]

bro isnt that a 2016 jee advanced phy problem??

i dont think its the right place to post the question

send it in a phy server ig

[trail tendon]

2016?? how do you know that specifically 🤣 🤣

thats crazy xD

[dusty ginkgo]

i am giving jee advanced this year so i haave been doing all jee questions past 2 years

[rugged hearth]

bot

[rugged hearth]

how much time do you expect to have for this question?

[dusty ginkgo]

theres 18 smth questions and u usually give like 55 mins for all of them

[languid mesa]

Yess

Ok

[languid mesa]

Yes it's 2016 jee question

[rugged hearth]

thx 👍 , are all the questions as hard as this one ?

[dark sparrow]

??

[glacial yacht]

1. In △ABC, AB = X + 1, BC = X, AC = X − 1. C = 2B, Find X.

need help

[patent oxide]

Idk

[fickle rose]

what does c = 2b mean

[glacial yacht]

angle

[dark sparrow]

@glacial yacht have you made a diagram?

[dark sparrow]

can you explain this joke to me? i don't get it.

[languid mesa]

Not all but there are some question like this

But the paper is not easy

[languid mesa]

Lag tha hai chips mang rahi hai

[dark sparrow]

i don't speak hindi, sorry

can you translate?

[languid mesa]

I mean you always work hard take a break

[dark sparrow]

ok...

[dusty ginkgo]

nah, this would be one of the harder questions, question paper varies year by year but theres some easy questions moderate and difficult. though this q is quite hard for its time and there were some even more hard/wrong questions that year

especially for this topic

[lilac narwhal]

Okay just a clarification:
sin(x) and cos(x) are the bases
tan(x) = sin(x)/cos(x)
csc(x) = 1/sin(x)
sec(x) = 1/cos(x)
cot(x) = 1/tan(x) or cos(x)/sin(x)

Oh yeah is tan(x) = 1/cot(x)?

[dusty ginkgo]

yes

btw what do u mean by bases?

[lilac narwhal]

Like they don’t have a definition do they?

[dusty ginkgo]

they do have a definition

[lilac narwhal]

Okay wait

Yeah

[dusty ginkgo]

in a right triangle they are defined by height/hypotenuse and base/hypotenuse respectively

[lilac narwhal]

If sin(x)^2 + cos(x)^2 = 1

Wait

That would give a negative square root in trying to isolate any of the two

[dusty ginkgo]

its not a if, it actually derives from pythagoras

[dusty ginkgo]

well cosine and sine can have -ve values

[lilac narwhal]

How would you undo the square on a cosine for example

[dusty ginkgo]

it depends on the angle

[lilac narwhal]

x

[dusty ginkgo]

u would have to see what range ur x belongs to

[lilac narwhal]

Hm

Wdym

Doesn’t sin or cos take any x

[dusty ginkgo]

they do

but their sign

depends on the value of x

if they are +ve or -ve

[lilac narwhal]

Okay here’s what I was tryna do

Take that pythagorean identity

Move one of them over like this:

sin(x)^2 = -cos(x)^2 + 1

Then in theory you’d square root but it’s negative cos

Wouldn’t that be impossible?

[dusty ginkgo]

wdym?

its 1-cos^2x

its always greater than 0

[lilac narwhal]

Would you be able to take the square root of that value though

So isolate sin(x)

[dusty ginkgo]

indeed u would be able to

i feel like u are skipping on a lot of stuff

u first need to study trigonometry from basics

your questions would automatically be answered

[lilac narwhal]

huh

interesting

Well

I just put these on a unit circle in desmos to see how they move around

[dusty ginkgo]

join center to the edges of the chord

[dark sparrow]

^

[dusty ginkgo]

the have the same length as its equal to radius

then the perpendicular is the same in 2 triangles

so we can just use congruency as we have 2 sides and a right triangle

i just explained it bro 💀

how to prove it

np mate

[rugged hearth]

ok very good so it is reasonable to be able to do this xd

[lime hinge]

Hii,

So, I stumbled upon this Q and while solving it, theoretically guessed it would be 90 and I was right but a person I know says it's supposed to be 180, can anyone help outt?

[hexed sky]

you can use central angle theorem

since the angle of the diameter is 180 degrees , the theorem states that the angle subtended at the centre is twice the angle subtended at any other point on the circle.

[dark sparrow]

what's a "theoretical guess"?

and how does it differ from a normal, no-adjectives "guess"?

[lavish zodiac]

can someone help me with this real quick?

just need NZ and XZ

pls fast

[mint nexus]

how do i prove #9?

[lime dune]

don't be careless with your words, it's "solve" not "prove"

what identity do we know that relates sine and cosine?

[mint nexus]

i am mentally not equipped for this rn

[lime dune]

think of a right triangle

that should give you an identity relating sin and cos

[mint nexus]

i lack any fundamental understanding of sine and cosine cuz my teacher does not teach so i need an elaboration

[lime dune]

gee how many times have i heard that old excuse

[mint nexus]

ive simply been told they are cofunctions, sine is odd and sine is even and then i was given the formula

[lime dune]

draw a right triangle ABC

right angle at C

find sin A

and cos B

what do you notice?

[mint nexus]

dude not everyone has a great teacher...?

[lime dune]

i'm a bit hesitant to blame everything on the teacher in a lot of cases

but go on, try what i suggested

[trail tendon]

did you do the problem before that?

and understand it?

[mint nexus]

yes

[trail tendon]

because its using the same idea

[lime dune]

ah yea that too

what domain are you solving over?

[mint nexus]

gotcha got ha

ill try that let me figure it out

[trail tendon]

ok

[trail tendon]

wdym

[lime dune]

like are we solving for x such that 0<x<360 or some other domain?

[trail tendon]

oh

[lime dune]

because that matters

[trail tendon]

i would assume so

[lime dune]

and if it's a sufficiently large domain

the method above will leave out solutions

[mint nexus]

do i just do x+x=90??? lol

2x=90 x=45

[trail tendon]

yeah lol 🤣

[lime dune]

depending on your domain you might also have to include x=225

[mint nexus]

got confuzzled with the other stuff the guy said

[trail tendon]

yeah

i'm not sure if you've done it yet

[mint nexus]

he didnt teach domain..

yea no

[trail tendon]

which means they don't expect you to kow

[mint nexus]

i just started trig LOL

[trail tendon]

which means they probably don't expect you to do that lol

[mint nexus]

shouldve said that first but its fine

[lime dune]

is there any specification at the top of the sheet that's like

[trail tendon]

yeah

[mint nexus]

no

[lime dune]

"solve for 0<x<180" or "solve for 0<x<360" or whatever

no?

huh

[mint nexus]

??????

[lime dune]

can i just see the whole paper for a moment

[mint nexus]

i think you are over complicating this