we r supposed to do it only using th stuff we learne
#geometry-and-trigonometry
granite void
we ddnt do probability yet
i told you the steps - im answering kade on the probability now 👍
upper karma
ok, thanks bro
granite void
do you need to prove independence mathematically or can you just do it with words?
rapid wraith
do you need to prove independence mathematically or can you just do it with word...
mathematically
granite void
yeesh
rapid wraith
yeesh
this was my friends as an example, he had different data
p(a)(b)= 19.57% and p(a|b) was 20%
granite void
wait yeah oops 🤦♂️
P(A|B) = 1
P(A) = 11/50
since isn't the probability of choosing cheerios given the fact that you drank the milk after eating cheerios 100%?
rapid wraith
since isn't the probability of choosing cheerios given the fact that you drank t...
If this helps, 5 people drank milk and 6 people did not drink the milk
after they ate cheerios
sorry for a late response
Thats why I was saying p(B) is 5/11
@granite void Sorry
So the question is basically
granite void
ope mb
rapid wraith
How do you find the probabilty of A given B
P(A∩B)
how do you find that
P(B)= 5/11
P(A) = 11/50
granite void
can you not use P(A|B) != P(A)?
rapid wraith
Whats the !
green forge
dark sparrow
do you want us to help you with some geometry problems
near harness
can you not use P(A|B) != P(A)?
Ah. Good old programming
lavish portal
Can anyone help to solve this? find the total area of the circles. ABCD is a unit square
edgy bone
So I've only been able to use linear algebra, but not fully understood how to interpret cos, sin etc. Now I'm looking at cos and I don't see how cos(0) = 1. I've learned that cos describes a vectors force/dir in the x-axis, right? If we say we have a hypotenuse with (1, 0) then cos == 1/1 = 1. So why is cos(0) == 1? Do they mean that cos(0) is the angle in radians between the hypotenuse and the x-axis-aligned unit vector and that if they are parallell (aka givs 1 as a result) is the same as if cos == 0 degrees? What confuses me thought is that cos(delta) = adjecent/hypo, so why doesnt my example give cos(1) when adj and hype are parallell and in the same dir?
and how is cos(alfa) = 0 the same as alfa = pi/2? can i device both sides if I have 0 on one?
nvm, i just saw why cos(alfa) = 0 <=> cos(alfa) = pi/2. we know that cos(alfa) = adjecent(which has zero in x-axiz) / hyp gives cos(alfa) = 0/1 which is cos(alfa) = 0 which means that they have a 90 degree (aka pi/2) angle inbetween except if the adjacent isnt a 0-vector, right?
sick hemlock
Can anyone help to solve this? find the total area of the circles. ABCD is a uni...
Approach this by writing out what areas you can find out
Maybe divide the figure into seperate parts by numbering them
dry current
Can someone explain to me how to set proportions to solve this question?
heavy shale
Can someone explain to me how to set proportions to solve this question?
Use the Similarity Criterion
Corresponding sides of Similar triangles are Proportional.
torn gazelle
Can someone help me with this?
smoky jetty
for Q5, it's a 30-60-90 right triangle case where the the hypotenuse is twice the measure of the shortest side (x) while the longest side is sqrt.3 times the measure of the shortest side (x)
for Q6, a since it's a square (sides are equal, angles measure 90 deg each), then can use the pythagorean theorem to find the value of x (the diagonal)
hypotenuse^2=base^2+altitude^2
violet raft
for Q4 you can set up a proportion x over 3 = 3 over 5
sick hemlock
You could also try solving Q4 using Pythagorus Theorem
upper karma
Can anyone help me on this
dark sparrow
@upper karma do you still need help with this
upper karma
<@456226577798135808> do you still need help with this
I do
upper karma
I think so; it's the total area of all shapes involved, yes?
dark sparrow
"all the shapes involved" is a little vague.
but yes, for a polyhedron -- a solid whose surface consists of a number of flat faces -- the surface area is just the sum of all faces' areas
so with that in mind
can you say what is causing you trouble with this particular prism?
(a) I am unable to take inventory of what faces the prism has.
(b) I know what faces the prism has, but I am unable to calculate some or all of their areas.
(c) I know what faces the prism has, and I am able to calculate their areas and add them up, but I get the wrong answer.
A
dark sparrow
do you know what faces a prism has generally?
upper karma
Yes.
dark sparrow
...
you're generalizing too far
okay, let's try this again
how many faces does YOUR prism have, and what shapes are they?
torn gazelle
This is what I got from the values. Is it right?
timber cargo
Yeah, pythagorean theorem your way to victory
lime crownBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
I don’t see the scalar product working here?
is the answer 48.6 degrees?
if it is, then i can explain how i did it
toxic linden
This is what I got from the values. Is it right?
You got 4 and 6 correct, though for 5, could you just provide working out? I'm not sure what you did.
toxic linden
I might be wrong, but for the dimensions of the whole parallelogram, I think it's 10 inches by 20.
deft lark
okay but how would u get the triangle areas
torn gazelle
You got 4 and 6 correct, though for 5, could you just provide working out? I'm n...
I multiplied the first one by radical three, then doubled the hypotenuse
smoky jetty
This is what I got from the values. Is it right?
seems about right, but maybe try to provide a solution and statement regarding q5
smoky jetty
not completely sure about this (just giving it a try), but the parallelogram could be made up of 4 equilateral triangle triangles as the edge to the midpoints of height & length of the parallelogram essentially measures half the complete measure of each dimension. so, triangle ADF has sides =10, then segment EF cuts the equilateral triangle into two congruent right triangles, hence, we could find the base using pythagorean theorem..
wait im lost sorry.. (maybe someone nerdy can verify these initial steps I did)
A=1/2(base*height)
smoky jetty
the problem i countered is that the area of the triangle ADF (combining the area of right triangles DEF & AEF) from the measures DE = 5 & DF = 10 then using pythagorean theorem to find EF, finding the area of DEF and multiplying it to 2, (refer to previous statement) multiplied to 4 (as 4 equilateral triangles make up the whole parallelogram) isn't sufficient to meet the area of parallelogram which is 200 in.^2 (assuming the dimensions of the parallelogram is 20l by 10h)
violet shadow
is the answer 48.6 degrees?
Nah it’s 135
upper karma
aight ill try that one again in a bit
violet shadow
Markscheme says 135.5 degrees
silent plank
show work
lament tree
uh idk if that's the place to ask this type of kinda abstract tip but
I have too much intuition at geometry
and that's about it
I have a lot of dificulty proving what my intuition says
how do I improve proving specially geometrical stuff? that also counts for other subjects but specially geometry
I actually have an easy time proving algebraic stuff but geometry breaks me
toxic linden
What was your answer?
obtuse patio
uh idk if that's the place to ask this type of kinda abstract tip but
I have too...
You just have to learn the rules
Like for triangles
You have to reference preexisting ideas in proofs, so you just need to learn what those ideas are
Like for example triangle similarity and congruency rules
lament tree
Like for example triangle similarity and congruency rules
hm
thx
maybe I lack the basics
cus yk, bad school
obtuse patio
yeah np
upper karma
How do i beg for help
obtuse patio
@upper karma#❓how-to-get-help
toxic linden
Did you put your answer to 1 decimal point?
lyric sonnet
using :
area of cross section times l,
$1.1 times 1.7 times 3$
somber coyoteBOT
Ishigami Senku
lyric sonnet
VOLUME OF ANY PRISM = CROSS SECTIONAL AREA TIMES LENGTH
torn gazelle
Can someone help me figure this out?
timber cargo
Can someone help me figure this out?
Use the Pythagorean theorem
and for b) operate with inverse functions
smoky jetty
Use the Pythagorean theorem
smallest triangle in the 7th problem must be 45-45-90 right?
timber cargo
Yeah
pliant roost
Use the Pythagorean theorem
yeah, it all shall go to sqrt(13), which is fun
torn gazelle
This is another one I need help with?
obtuse patio
Which part
obtuse patio
I’m not experienced with slope
Slope is rise/run rememeber
Calculate from A to B since they’re whole numbers
toxic linden
I’m not experienced with slope
Are you familiar with a linear graph equation?
torn gazelle
Are you familiar with a linear graph equation?
y=mx+b
thin locust
to prove that H is the orthocenter of ΔABC, is it enough to prove that 2 altitudes of ΔABC intersect at point H?
floral shale
Yes
lament tree
ah yes
pliant roost
it's useful, eh?
timber cargo
yeah, it all shall go to sqrt(13), which is fun
I don’t follow? What is that particularly fun
torn gazelle
Do you need help with the linear equation problems?
yes
toxic linden
Which question?
toxic linden
For 10a, the slope is determined by rise/run, which in over words is the change in y divided by the change in x. So for the slope of the hill AB, It would be -8/10. The negative is necessary because you read a graph from left to right, and in this case the slope is declining from left to right. So from the slope -8/10, you would simplify it to -4/5
For 10b, to write an equation, the form of it would be y = mx+b. The y is obviously just the y value. The 'm' is the slope, x is the x value, and the b is the y intercept. So for the slope, we are given that it is -1/3. So then we can substitute the value into m, giving us y = -1/3(x) + b. From this, we are missing the y intercept. The intercept is given on the graph, and from this we know it is 8. So from this info, we can write the equation as y = -1/3(x) + 8.
For 10c, your asked to find the x intercept. To find x intercept, you have to let your y = 0, because the y of any x intercept will always be 0. So from here you would get the equation, and write it as 0 = -1/3(x) + 8, and solve x as normal.
toxic linden
I have a, it’s -0.8
no you got it right
just in decimal form
Try to write the answer in a fraction
torn gazelle
-0.8 over 10?
toxic linden
Can someone help me figure this out?
For this a = sqrt of 2, b = sqrt of 3, c = sqrt of 4 or 2, d = sqrt of 5 and etcetera.
toxic linden
-0.8 over 10?
No the answer is -4/5
but if you actually divide those 2 numbers you would get -0.8
which is the same thing
So you basically got it correct
torn gazelle
For this a = sqrt of 2, b = sqrt of 3, c = sqrt of 4 or 2, d = sqrt of 5 and etc...
I got that one
Ty
toxic linden
No problem
toxic linden
- is the definition of a complementary, (2 angles that add to 90 degrees). Though for 9. because it says both angles are complementary, that means they both add to 90 degrees. Though, I don't know how to put that into an answer form. I assume you would say the definition of a complementary or = 90 degrees?
toxic linden
Brackets aren't necessary for x in question b but it doesn't really make a difference.
But you do what's best for you
torn gazelle
Brackets aren't necessary for x in question b but it doesn't really make a diffe...
Ok
torn gazelle
Brackets aren't necessary for x in question b but it doesn't really make a diffe...
For c I just have 0=-1/3x+8
Is that good?
torn gazelle
Oh ok
toxic linden
So it would be 8 = -1/3x
and then times 3 both sides to get 24 = -x
wait
No i messed up
torn gazelle
I would multiple -1/3 from both sides right?
toxic linden
So it would be 8 = -1/3x
it should have been -8 = -1/3x my bad
I'm not used to solving algebra on keyboard
torn gazelle
I understand that😂
toxic linden
it should have been -8 = -1/3x my bad
And then 8 = 1/3x
times 3 on both sides and you get x = 24
So the answer would be (24,0)
Dont just write x = 24
toxic linden
So the answer would be (24,0)
Their asking for the coordinate so this would be the answer
torn gazelle
So the answer would be (24,0)
If I knew anything from that, I remember to put that😂😂
torn gazelle
If you don't understand anything just ask
Can you respond in dms?
It would be easier to ask there
toxic linden
Can you respond in dms?
Yeah sure
obtuse patio
I just like it
What about it makes it interesting
toxic linden
I just like it
same
pliant roost
What about it makes it interesting
you don't encounter sqrt k as a sequence often
unkempt egret
guys
position of a circle with respect to and the circle
i really dont understand
smoky jetty
For 10a, the slope is determined by rise/run, which in over words is the change ...
should the slope for 10a be -4/-5= 4/5?
or im just quite confused
obtuse patio
you don't encounter sqrt k as a sequence often
No but like what’s the pattern of the sequence
It looked pretty random to me
pliant roost
just sqrt k
errant lake
Yeah I meant like is there anything I can use to find XY2
errant lake
thats just the question
It is the question but idk what concept I should use to find XY2. In learning polygons rn and it would be nice to get some hints
grave pond
Note that PQX and SRY are both 3-4-5 triangles, so you can draw the whole configuration nicely on graph paper.
(Draw it such that PX and QX are parallel to the grid of your graph paper, and the lines of length 10 are diagonal...)
grave pond
No, that does not have the orientation I'm describing -- and it's not to scale either...
errant lake
U want me to use a distance formula to find the answer?
I don’t think it’s the point of the question
grave pond
No, I want you to draw a nice TO SCALE diagram on graph paper.
Start by drawing a 6-8-10 triangle such that the right angle between the "6" and "8" sides align with the grid of the graph paper.
Or, in yet other words select your coordinate system such that X is at (0,0), P is at (8,0) and Q is at (0,6).
When you complete the drawing from that starting point, all the points in the configuration ends up being grid points.
And you can then read off the coordinates of Y directly by counting grid squares on your drawing.
errant lake
Oh
Yeah that’s easy but like as I said it’s not the point of the question. I also wanna know the relation in between polygons with XY^2 cuz that’s what I’m learning and this question is related to polygons and not drawing a perfectly scaled graph on a specific type of paper and counting squares
grave pond
So you're saying the question you posted is no the question you want to answer?
errant lake
Oh wait actually nvm I just realized smth thanks
errant lake
So you're saying the question you posted is no the question you want to answer?
Well I also wanna understand how to do it. Yk is kinda like cheating if I answer that way
grave pond
To me it looks like the author of the problem when to great lengths to make it possible to answer it the way I describe. ¯_(ツ)_/¯
If they wanted a more cumbersome procedure, they could easily have chosen the given lengths such that they wouldn't fit a simple grid-point solution.
grave pond
Ah, clever! But it seems to be a detour to begin talking about sqrt(2) when the problem explicitly asked for |XY|² rather than |XY| itself. We could just use Pythagoras directly on triangle XWY.
obtuse patio
To me it looks like the author of the problem when to great lengths to make it p...
You’re saying the point was just to draw it out and count?
That seems not really to be the point imo
There’s no geometry/trig knowledge then
Just basic math
grave pond
Noticing that a given situation has nice properties that allow a shortcut is a valuable mathematical skill.
obtuse patio
Noticing that a given situation has nice properties that allow a shortcut is a v...
completely agree
but I've never thought that counting grid squares would count
like that seems too detached from the content they are actually learning
pliant roost
What is special about the decimal sequence of sqrt13
it's cool that it occurred in geometry
that's it
obtuse patio
it's cool that it occurred in geometry
What?
obtuse patio
Wdym occurred in geometry
pliant roost
the sqrt k sequence
obtuse patio
What’s that
pliant roost
sqrt 1, sqrt 2, sqrt 3, etc
toxic linden
should the slope for 10a be -4/-5= 4/5?
No
Because it's declining, the whole fraction would be a negative
pliant roost
Every whole number occurs in that sequence
but not whole too
rapid coral
anyone know this
honest token
smoky jetty
tropo's right. That's clever and im quite surprised to see it that way
looks fun to solve such geo-problem
light sage
stop multiposting
serene wigeon
anyone here know how to solve theorems?
paying nitro if i get my activities answered and correctly
silent plank
paying nitro if i get my activities answered and correctly
no monetary compensation talk here. people are willing to help you free of charge.
(as long as you put in the effort and listen)
serene wigeon
silent plank
can you post your problem as an image,
people are wary of downloading files
near harness
For every "n"th figure, the number of points are 4n.
fig.3 - 4(3) = 12 points
fig.4 - 4(4) = 16 points
fig.5 - 4(5) = 20 points
Similarly you can find number of points for fig.50 and 200.
pliant roost
bro youre trolling
no, just cool sequence, what?
rare nebula
Guys can this be used to prove putagoras therium and if it can how
Pythagoras' theorem
minor mountain
I'm having a couple of chapters for it in 10th grade
So you’re in 9th
lament tree
guys I think going straight to that olympiad geometry book without knowing basic geometry ain't working
lament tree
You just have to learn the rules
I think what I'm going to do for practice is go through a basic geometry book from start to finish and justify pretty logically all my answers to exercises, even the ones in the start that are like "if there are two points A and B such that A=B, there is a straight line r such that A belongs to r and B belongs to r"
thin locust
the first one is how the points lie right? or does the order not matter at all
lament tree
the first one is how the points lie right? or does the order not matter at all
I know for some things in cyclic quadrilaterals it matters
like that one first theorem from this book
in that first image, two angles are the same an the other ones are different, same for some quadrilaterals in that triangle with the orthic triangle
lament tree
the first one is how the points lie right? or does the order not matter at all
and yes I think this one matters
thin locust
and yes I think this one matters
oh someone helped me and it doesnt matter
but ty
❤️
thin locust
you also doing egmo?
lament tree
I was but
thin locust
guys I think going straight to that olympiad geometry book without knowing basic...
i did like a few chapters geometry from aops vol 1
which was enough
i can send you the file if you want
lament tree
yk, two hours solving some simple problems and getting very stuck at proofs cus idk the basic rules of geometry and stuff
lament tree
i can send you the file if you want
nah I already have a basic geometry book of preference
thin locust
oh ok
lament tree
it's a brazilian book from a famous series which like, everyone recommends to everyone cus they're very good
thin locust
oh nice
lament tree
"fundamentals of elementary mathematics" vol 9: Plane Geometry
I'm also doing its combinatorics
lament tree
im just doing algebra and geometry rn
my algebra is pretty ok, I just need geometry and combinatorics, which are the most useful for the olympiad I'm going for
also geometry makes me have some like, spiritual experiences sometimes, and combinatorics is amazing for answering my stupid questions I make myself sometimes
so they're very cool
(I mean, my high school algebra, never studied the real stuff)
thin locust
oh i do algebra just for fun
geometry because in school we do nearly no geometry
i want to do number theory and combinatorics too, but dont have time rn
idk if i want to do math competitions
lament tree
idk if i want to do math competitions
I think they're cool to have an objective
and they can help entering universities and stuff
upper karma
Did i do this right?
coarse axle
Hi, could you figure out the volume of a cone with only the slant height?
dark sparrow
ONLY the slant height? no.
tall flume
hey would anyone be able to help me with vectors
can u figure out polar form of a vector just from its magnitude
violet shadow
How are you supposed to do part b for this
Because we aren’t given any individual i and j components so I can’t use the scalar product
dark sparrow
part ii, you mean?
so I can’t use the scalar product
can't as in unable or can't as in unauthorized?
sonic stone
I’m having a hard time trying to prove that all equilateral triangles are equiangular
like i created the altitude and used the pythagorean theorem, but i end up just defining the length of the sides
rare nebula
How does this thing prove phyntagora therium
austere vault
I love trignometry
smoky jetty
I’m having a hard time trying to prove that all equilateral triangles are equian...
afaik, by pythagorean theorem, the ratio of the trig function respective to its angle is equal to the ratio of the trig func of the angle that corresponds the other angle (which are congruent), if you cut the equilateral triangle in half with the altitude
although idk how to formally construct this proof, if it's even considered one
smoky jetty
afaik, by pythagorean theorem, the ratio of the trig function respective to its ...
eg, the given values of angles are 60-60-60, hence by cutting the triangle in half, you'd get a 60-30-90 special triangle,and the ratio of the corresponding side lengths of both triangles are in proportion. Hence, using the ratio of the sides that corresponds to the trig func, we can find the angle and prove thay the triangle with equal sides have congruent interior angles
not sure if this is sufficient, hopefully others could elaborate or verify this (personally intrigued as well)
rapid sigil
A rhombus has sides of length 51 units each and a shorter diagonal of length 48 units. What is the length, in units, of the longer diagonal?
Isn't the ans 45?
silent plank
no
how can the longer diagonal be shorter than the shorter diagonal
how are you getting 45
burnt arch
A rhombus has sides of length 51 units each and a shorter diagonal of length 48 ...
^^^ Yeah how are you getting a longer short diagonal than the actual long diagonal itself?
smoky jetty
in my head, the difference between the longer diagonal and shorter diagonal measures based on the given doesnt seem to make a rhombus? or maybe it does
rapid sigil
I didn't notice this😢
Well shorter diagonal is 48 so half is 24 and side is 51 then using a^2 + b^2 = c^2, 24^2 + x^2 = 51^2.
burnt arch
I didn't notice this😢
Well shorter diagonal is 48 so half is 24 and side is 51...
Was just about to say to use the Pythagorean Theorum.
burnt arch
Could you directly explain me the answer?
Take the given diagonal, divide it in half, use the Pythagorean Theorum and plug 51 in for c, and 24 in for b, just solve for a.
rapid sigil
Take the given diagonal, divide it in half, use the Pythagorean Theorum and plug...
did exactly this!
rapid sigil
did you draw a diagram?
yeah very rough
silent plank
and can you show what x represents in that diagram?
does x actually represent the full diagonal or something else?
rapid sigil
x represents half of the long diagonal? thus the long diagonal is 90
oh I forgot doing 2(45)
silent plank
yes
rapid sigil
Thanks...
silent plank
always remember what your variable(s) represent
rapid sigil
A rectangular tile measures 3 inches by 4 inches. What is the fewest number of these tiles that are needed to completely cover a rectangular region that is 2 feet by 5 feet?
How do I look at this?
smoky jetty
not sure about this, but here's my attempt to help:
Let's first convert the rectangular region's dimensions into
inches for convenience, where 1ft=12inches
so its width would be (2 feet times 12 inches)/1ft, and its length would be (5 feet times 12 inches)/1ft. Hence, from here, you can get the area of the rectangular region where Area=length timeswidth
On the phrase fewest number of these tiles (referring to the rectangular tile with lengths measuring 4 inches and widths measuring 3 inches), im not quite sure bcoz of the wording. So, I'd say it meant how many of the tiles would fit in the area of the rectangular region without any overlaps.
If it is, then the ratio of the dimensions of the rectangular tile is stated as 3:4, where 3 is the width and 4 is the length. A=l times w
Here, we divide the area of the rectangular region by the area of the rectangular tile, thus giving us the fewest number of tiles needed to completely cover the said region.
night sparrow
I was given this question in my homeowork and I have no idea how to solve it, anyone able to help?
smoky jetty
is 28cm the measure of the whole base?
night sparrow
Yup
smoky jetty
have u don right triangle theorems?
night sparrow
Yes, I have.
smoky jetty
what do u know so far that u think is helpful for this
night sparrow
Idk what you mean by that
smoky jetty
like name the edges as A B or C, to not get confused with instructions
smoky jetty
add letter D on the intersection of BC and the height as well😅
timber cargo
Calculate the area of the whole triangle? Is that what it is asking
night sparrow
Calculate the area of the whole triangle? Is that what it is asking
Yes
night sparrow
add letter D on the intersection of BC and the height as well😅
Wdym and the hight?
smoky jetty
the broken line with 10cm measure
night sparrow
Put the letter d in the middle?
night sparrow
smoky jetty
yeah like that
night sparrow
Okay, sorry
smoky jetty
is 28cm the measure of BD? or BC?
night sparrow
BC
timber cargo
Okay, then bh/2 to victory
Your base is 28
And your height is 10
Multiply the two and divide by 2
night sparrow
Okay
timber cargo
Don't forget to change the units to cm^2
night sparrow
Okay, thanks!
knotty talon
@Underjuice
finite elbow
im stumped
i'm going to fail my tests bro
pi/2 and 3pi/2 is part of the answers but so is pi/4 and 5pi/4
however that would mean that the work above is like
possibly completely off from what the actual answer is
maybe csc 2x isn't 1/sin 2x and maybe multiplying both sides by sin 2x doesn't work either
i don't know
can someone steer me in the right direction
nocturne remnant
There is a glaring mistake when you multiplied sin 2x to the whole equation
finite elbow
@nocturne remnant i am afraid i am still stumped
nocturne remnant
<@471271187771555844> i am afraid i am still stumped
can you show your work
finite elbow
can you show your work
i just dont know where to go from this and even here i think i'm already wrong
mental block 
bleak blade
the whole thing is * sin2x, not just 1/sin2x
nocturne remnant
i think multiplying by sin 2x is a reasonable thing to do, especially considering the identity sin 2x = 2 sin x cos x
then ||see if you can express everything in terms of sin 2x and cos 2x||
nocturne remnant
i think multiplying by sin 2x is a reasonable thing to do, especially considerin...
||after the dust settles you should get tan 2x = -1 which gives the solutions||
@finite elbow
trail birch
i really don't have the brain for gemoetry
craggy escarp
is CDM a right triangle
timber cargo
is CDM a right triangle
Yes
rapid sigil
If the border added is 2 inches, how are the dimensions increased to 4 instead of 2.
upper karma
i just dont know where to go from this and even here i think i'm already wrong
maybe expand sin2x, sub in cos^2 (x) + sin^2(x) instead of 1
and u have urself a hidden quadratic
somber coyoteBOT
near harness
There may have been some errors in approximating the values but this is the process
stable gulch
Hi
crimson pawn
Can someone explain why b is correct? Not a
Ik that it should be equal to a positive number probably because r^2 but idk what to do tbh
viscid tinsel
Can someone explain why b is correct? Not a
do you know how to complete the square?
that way you are able to get (x-h)^2 + (y-k)^2 = r^2
where (h,k) is the coordinates of the center of the circle
lost sky
upper karma
do you know how to complete the square?
That is not necessary
upper karma
Can someone explain why b is correct? Not a
silent plank
necessary? no.
ideal? yes.
upper karma
@viscid tinsel
upper karma
necessary? no.
ideal? yes.
I mean the post above works for me. It is up to the person to use what is best for them.
silent plank
best not to blindly apply formulae without knowing where they come from
foggy ledge
Are those first two correct and can anyone help with the second two?
silent plank
the first two are wrong
your values aren't even in the range of the given functions
silent plank
consider applying trig formula/rules applicable to non-right triangles
trig formula for area could be used to determine a
after getting a, cos rule/law can be used to determine b
rapid sigil
somber coyoteBOT
rapid sigil
What's wrong with the approach
raven sable
What's wrong with the approach
The left side of the figure has a different length than what you wrote
rapid sigil
The left side of the figure has a different length than what you wrote
I found the area of the missing region to complete the rectangle, added both areas, and then found the length. What's wrong with this approach?
raven sable
What would be the area if the whole rectangle were filled in?
rapid sigil
What would be the area if the whole rectangle were filled in?
69
raven sable
How did you get that?
raven sable
Yes. First figure out what the area of the full rectangle would be
rapid sigil
Yes. First figure out what the area of the full rectangle would be
How ?
raven sable
Make a guess. How did you get 69 before?
rapid sigil
adding both the given area and the area of the missing region right.
raven sable
Yes, so how can you figure out the area of that missing region?
rapid sigil
Make a guess. How did you get 69 before?
idk,
raven sable
You're given enough information to calculate the missing area. Draw a picture and think about it; there's a simple approach you might be missing
rapid sigil
ok I'll try
raven sable
Don't just solve a problem for someone else
celest osprey
no tell me if its right im not sure
raven sable
no tell me if its right im not sure
It's not
raven sable
How do i even find area of this region?
That's what I asked you. There's a way to simplify the area
rapid sigil
That's what I asked you. There's a way to simplify the area
what way?
raven sable
Think of geometric figures for which it is very easy to calculate areas
rapid sigil
😕
raven sable
😕
? Look very closely at your drawing. What is the "simplest" geometric figure that you know the area of, in general?
rapid sigil
? Look very closely at your drawing. What is the "simplest" geometric figure tha...
Is the area 8ft^2?
rapid sigil
? Look very closely at your drawing. What is the "simplest" geometric figure tha...
square
raven sable
Is the area 8ft^2?
No, but how did you arrive at that value?
rapid sigil
No, but how did you arrive at that value?
considering it a square, area would be 16, then divide by 2 to find the area of the staircase
raven sable
considering it a square, area would be 16, then divide by 2 to find the area of ...
There's a simpler way. You're still thinking of the whole missing portion, which is complicated
But you can do it that way as well, it wouldn't be exactly half though
rapid sigil
hmm.
raven sable
How about this, what do most bathroom floors look like (in the US, at least, not sure where you live)?
rapid sigil
area is 10?
raven sable
area is 10?
Yes! How did you get it
rapid sigil
Yes! How did you get it
considering each square separately and finding the area
then adding them all
raven sable
considering each square separately and finding the area
Awesome, that's what I was getting at w/ the bathroom floor (think of connected tiles)
OK so if the missing portion has area = 10, then...
rapid sigil
OK so if the missing portion has area = 10, then...
perimeter is 63
raven sable
Not the perimeter
rapid sigil
then?
raven sable
You tell me... why did I even ask you to find the area of the missing part? What can you do w/ that information
rapid sigil
then the area of the whole square would be 63, we already know the width which is 9 so now we can find the length
which would be 22.5
@raven sable
raven sable
The length of what?
rapid sigil
The length of what?
the whole square.
rapid sigil
.
raven sable
That doesn't add up. Don't skip steps
The area of the given figure is 53; the area of the whole square (filled in) would be 63. The bottom line has length 9
What does all that tell you about another unknown that you need for perimeter?
rapid sigil
The area of the given figure is 53; the area of the whole square (filled in) wou...
how do we know that its a square, I mean adding the given area and the area we found
sorry for poor eng, btw
raven sable
Sorry, I meant rectangle. You're right, but that shouldn't matter. (Your english is fine)
Total area (filled in) would be 63. Bottom length is 9. What's the one thing you can calculate from those 2 pieces of information?
rapid sigil
What does all that tell you about another unknown that you need for perimeter?
it tells us that the other unknown is of length 22.5
raven sable
You're jumping ahead again. I'm trying to take you through it step by step
rapid sigil
Total area (filled in) would be 63. Bottom length is 9. What's the one thing you...
from these 2 pieces of information we can find the length.
raven sable
Length of what?
rapid sigil
Length of what?
the whole square
raven sable
The whole thing is a rectangle, actually. But no, you're jumping ahead.
The whole area (if it were filled in), is 63. The bottom side is length 9. Think about the formula for the area of a rectangle
rapid sigil
The formula of the area of the rectangle is A = 2(L + W).
rapid sigil
That's the formula for the perimeter
oh yeah sorry I forgot its the formula for the perimeter
the formula for A is L * W
raven sable
the formula for A is L * W
Exactly. So what can you solve for there
rapid sigil
Exactly. So what can you solve for there
the length of the left side
Thanks a lot @raven sable
raven sable
Thanks a lot <@1055123692608294912>
Did you get it?
rapid sigil
yeah
crimson pawn
necessary? no.
ideal? yes.
Yea i figured it out by completing the square, ty
stable gulch
Hi
opal bear
45.3cm I think
opal bear
Trig ratios for the top triangle ABD and you can use Sin law for the bottom one.
sand ingot
<@&286206848099549185>
balmy gorge
!show
lime crownBOT
Show your work, and if possible, explain where you are stuck.
agile marsh
<@&286206848099549185>
is this a test?
sand ingot
no
sand ingot
and work
bright marten
<@&286206848099549185>
D
agile marsh
yes
sand ingot
ok that’s what i got
sand ingot
it’s fine
bright marten
can you show him the work?
ok
bright marten
wait me some time
bright marten
yeah, thanks
sand ingot
ty
bright marten
<@&286206848099549185>
We need to grasp the conditions given by the topic
floral shale
!status
lime crownBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
Wait so 13m is thr hypotenuse
floral shale
Yes
ruby zinc
So 25m plus x2 = 169
Deduct 169-25
144
144=x2
Square root of 144
12
Is that right?
floral shale
Yeah
sudden crystal
Try to calculate AC
upper karma
How?
From what it looks like you can use Right angle trig but it’s been a minute since I’ve done these questions 😂
lime crownBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
delicate owl
```
What step are you on?
1. I don't know where to begin
2. I have begun but got...
.
<@&268886789983436800> Ban please.
void shale
<@&268886789983436800>
delicate owl
Okay so
delicate owl
```
What step are you on?
1. I don't know where to begin
2. I have begun but got...
.
Answer this when you online
sudden crystal
Use trigno my guy
Without trigonometry is also possible to solve
But if you don't want to use trigonometry you have to know about Heron's formula
But I'm curious about the way to solve this question in trigonometry.
I can't figure it out.
rapid sigil
Yep you need it
One more thing
delicate owl
Yea?
sudden crystal
But if you don't want to use trigonometry you have to know about Heron's formula
This also reach the answer, if you have no idea how to use trigonometry in this question, like me.
delicate owl
This also reach the answer, if you have no idea how to use trigonometry in this ...
Yep I did herons
rapid sigil
Take AC as
solve how?
delicate owl
solve how?
Area of it?
sudden crystal
Take AC as
Not just AC can be the base and get the answer.
delicate owl
Not just AC can be the base and get the answer.
I am just giving him the clue
Can't give him the entire answer
sudden crystal
Ah I see
rapid sigil
WHat's the formula for area?
rapid sigil
I am looking into heron's formula, but to use it we need 3 sides
delicate owl
1/2 * base * height
Cause you have height here
You use herons formula when there is no height
rapid sigil
Cause you have height here
what is height here?
delicate owl
Wait
sudden crystal
Make your own height
delicate owl
There's no height
delicate owl
Make your own height
Yes
sudden crystal
Make your own height
Making a new line to help you is one of the technique to solve geometry problems.
pallid vine
Thinking about it, if we think about the bases being AD or AB, what are the perpendicular heights of each triangle? Does it matter whether the height isn't given?
delicate owl
Thinking about it, if we think about the bases being AD or AB, what are the perp...
Depends on the way you wanna solve it
rapid sigil
Make your own height
I have only one side
don't I need atleast two
to find height by dividing the triangle in middle making it right-angled and then applying Pythagoras theorem
sudden crystal
Em make it but not mean to calculate it
delicate owl
Em make it but not mean to calculate it
Yeah
It's gonna be a variable
Take it as
X
And using that X
Solve that entire question
Tip: Always try to have one variable
Not more
rapid sigil
@delicate owl
sudden crystal
If triangles have same height but different bases, what is the ratio of their area based on?
delicate owl
<@819409474976481300>
Yep
rapid sigil
Wha to do next?
rapid sigil
If triangles have same height but different bases, what is the ratio of their ar...
idk
somber coyoteBOT
Buddy
delicate owl
You know this right?
rapid sigil
yeah
rapid sigil
Base
sudden crystal
Yes
rapid sigil
so 2/5 is the ans
delicate owl
Yeah-
delicate owl
so 2/5 is the ans
Yes.
rapid sigil
<@819409474976481300>
still, how do I find the height of this triangle?
Is it possible?
Thanks @delicate owl and @sudden crystal for help
delicate owl
still, how do I find the height of this triangle?
Well you can't
sudden crystal
still, how do I find the height of this triangle?
With not height or area or base or angles or sides
Then
Of course Impossible
rapid sigil
ok thnx
rapid sigil
Use trigno my guy
you on?
delicate owl
!status
lime crownBOT
What step are you on?
1. I don't know where to begin
2. I have begun but got stuck midway
3. I got an answer but I'm told it's wrong
4. I got an answer and would like my work checked
5. I have a question about someone else's worked solution
6. None of the above
Yes
rapid sigil
so how can I use law of cosinces
rapid sigil
yeah
delicate owl
You needa find
DC-DA
BD is perpendicular to AC
Meaning there's a 90 degree formed
I will give you a clue
You can use this
But it also might not work
Assume value of X
Or
You can go with trigno
Whatever sails yo boat
slender acorn
Hi, do you wanna hear something awful?, I was doing my trigonometry test last thursday and there was an problem that needed to solve the length of a castle, I was doing it really good, because it was a normal triangle, at first I realized that it have an angle of 80 grades, so it wasn't a right triangle, so i used trigonometric ratios... I think it was to easy so I decide to use the leg theorem (It doesnt work on a 80 grades triangle!!!) so i fucked up 🙂
rapid sigil
Meaning there's a 90 degree formed
still law of cosines won't work because it needs atleast 2 sides and one angles
delicate owl
still law of cosines won't work because it needs atleast 2 sides and one angles
Why do you need law of cosines?
Why not normal trigno?
delicate owl
Hi, do you wanna hear something awful?, I was doing my trigonometry test last th...
That's sad dude
rapid sigil
Why not normal trigno?
what do you mean by normal trig?
delicate owl
what do you mean by normal trig?
The normal formulas
rapid sigil
c^2 = a^2 +b^2?
delicate owl
No
slender acorn
still law of cosines won't work because it needs atleast 2 sides and one angles
I will use the height teorem ... i am learning trigonometrics so dont listen to me
with the height you can solve the base
rapid sigil
yeah
delicate owl
Tan= opp/adj
Which one you gonna use?
And which side you want
Think
I will drop the question here for you to think
rapid sigil
Base
rapid sigil
DC and AD
slender acorn
ABC is a right triangle?
delicate owl
ABC is a right triangle?
No
rapid sigil
BDC
delicate owl
BDC
Good
To find DC
What and all can you use?
You have BDC as 90 degrees
BC as X+1
slender acorn
That is
delicate owl
Is?
delicate owl
What and all can you use?
Which exact formula?
rapid sigil
considering BDC we get cos theta = base/x + 1
delicate owl
considering BDC we get cos theta = base/x + 1
B?
slender acorn
BD i think so
delicate owl
Okay
I will give the answer
But will you promise to send the answer that you tried out in DMs?
rapid sigil
But will you promise to send the answer that you tried out in DMs?
ok tomorrow for sure
after test
rapid sigil
ok np and thanks
stable gulch
Hi
crystal thorn
how would i go about solving a problem like this if anyone could help
grave pond
The right triangles to the left and right of the x are similar. You can use this to find an equation for x.
obtuse patio
!nosols
lime crownBOT
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
late pilot
use the altitude on hypotenuse theorem, which states that the altitude squared equals the smaller parts of the bigger triangles hypotenuses multiplied together
wispy sapphire
I despise geometry and trigonometry to the max... Idk how yall do this but help me please
obtuse patio
I despise geometry and trigonometry to the max... Idk how yall do this but help ...
whats your question
upper karma
obtuse patio
dont crosspost
upper karma
dont crosspost
wdym
polar plaza
i dont understand how my maths teacher got this answer can anyone help?
stable gulch
Hi
round oracle
which channel would i talk graph theory in
outer sinew
How can I prove that cos(x) and sec(x) are always leq and meq (respectively) than x/sin(x) between the domain (-1, 1)? (Ofc, we could define the domain to be anywhere so long as within the domain, cos(x) <= x/sin(x) <= sec(x). yes, squeeze theorem shinnanigans at it again, in this case im trying to prove that limit of x/sin(x) as x approaches 0 is 1)
I heard that this is a special case which is proved via geometry. How would this be done?
civic bay
A circle with an area of 100pi square cm is dilated so that it’s image has an area of 25pi square cm. What is the scale factor of the dilation?
It was 1/2 got it right
obtuse patio
It was 1/2 got it right
!show
lime crownBOT
It was 1/2 got it right
Show your work, and if possible, explain where you are stuck.
limpid oracle
How can I prove that cos(x) and sec(x) are always leq and meq (respectively) tha...
,w true or false cos(x)<x/sin(x)
somber coyoteBOT
outer sinew
Leq*
limpid oracle
,w true or false cos(x)<=x/sin(x)
somber coyoteBOT
limpid oracle
,w true or false sec(x)>=x/sin(x)
somber coyoteBOT
outer sinew
When we do squeeze theorem, we're defining it at a domain
Mb
Should have specified, lemme fix my original qn
outer sinew
How can I prove that cos(x) and sec(x) are always leq and meq (respectively) tha...
Ok fixed
dark sparrow
well, you resolved the ± sign incorrectly, for one
and you might actually not be wrong aside from that...
,calc cos(195 deg)
somber coyoteBOT
Result:
-0.96592582628907
,calc sqrt(1/2 + sqrt(3)/4)
somber coyoteBOT
Result:
0.96592582628907
yeah so it's only a sign error you committed
gonna be difficult to simplify your root-inside-a-root into the form that the value is typically expected to be in
rapid warren
,calc (sqrt(2)-sqrt(6))/4
somber coyoteBOT
Result:
-0.25881904510252
brisk zenith
You are using the wrong formula. Thats the compound angle formula for sine not cosine
amber quartz
Can anyone solve this...I have solved it a whole ago but now I don't remember the way I did it..iirc it's from EGMO
obtuse patio
Can anyone solve this...I have solved it a whole ago but now I don't remember th...
probably ask in #competition-math then
latent compass
latent compass
@ me when solved I just need help on this problem 😭😭
latent compass
What’s the value of x tho?
obtuse patio
We aren’t here to give you answers
vague mica
Can anyone help me understand area of a sector
vapid patio
obtuse patio
Thanks for sending what I sent you
do you get it now
vague mica
A little
timber cargo
Or one halve times the radius squared times theta
upper karma
Can someone help me prove these theorems
Using
SAS
SSS
ASA
AAS
HL
Or not congruent
late pilot
um for number 1
it's SSA
because the right angle, congruent side, then BC being the same(refl. prop)
humble moss
2cnd is sas
silent plank
!nosols
lime crownBOT
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
silent plank
especially not if the solution is wrong
vapid patio
Thanks for sending what I sent you
dummy ask for help
vague mica
dummy ask for help
Don't call me a dummy
vapid patio
Don't call me a doofus dingaling
oh damn, why you so sensitive smellfungus
vapid patio
no
that didn’t hurt at all
oh
we’re acting right
ohh nooo
that was so offensive
vapid patio
what ☠️
vague mica
Stfu
vapid patio
no thanks 
floral shale
Least toxic mathcord conversation
floral shale
Don't call me a doofus dingaling
Aw man you took it too far
You can't call them a dingaling
vapid patio
You can't call them a dingaling
real
vapid patio
It hurt my feelings
don’t be a sensitive silly doofus
vapid patio
ew
vague mica
You unleashed the darkness side
vague mica
YOU STINKY POOPOO FAT HEAD STINKY BUTT
vapid patio
I have a whole life ahead of me
vapid patio
YOU STINKY POOPOO FAT HEAD STINKY BUTT
that’s not bad
vague mica
Im about to curse now cuz u unleashed senpai dark wolf apon your self
upper karma
hi
vapid patio
Im about to curse now cuz u unleashed senpai dark wolf apon your self
shrunkenpenis with ittybittytitties
upper karma
vague mica
Ass head
vapid patio
uh oh!!
vague mica
😈😈😈😈😈😈
vapid patio
now I’m cursed!!
upper karma
nononn
vapid patio
oh what shall i do!?
vague mica
Nothibg
vague mica
Only one of them is true
Maybe both
But
your ass cheeks are shriveled
And u etupid
And you are dumb
And stupid
vapid patio
atleast ion sat facting is a word 💀
vague mica
Its a word
vapid patio
whoa
vague mica
Nah jk