#help-49

1 messages · Page 274 of 1

sand flume
#

Ok I see this but when we try to actually so that it hits a value again we can't

crystal rivet
#

Wouldn’t g(2) be zero? Or is that not an assumption i should be making

sand flume
#

how would we get that? I can't see how we can do it from part a

crystal rivet
#

I might be over generalizing, but I’m just assuming that f is a sinusoidal function of some sort, so the integral over the period would be 0

sand flume
#

if we don't make that assumption how can we proceed?

solid iris
#

what was your answer to (b)?

sand flume
#

and in general given g(2n) = we have 2nA

solid iris
#

perfect

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from (a), do you see that g having period 2 is equivalent to g(2)=0?

sand flume
#

I don't see it from a I just see it from g(0) = 0 and we need g(x+2) = g(x). if x = 0 then g(2) must also equal 0

solid iris
#

g having period 2 is equivalent to g(x+2)=g(x) for all x, which is equivalent to g(x+2)-g(x)=0 for all x

sand flume
#

yes

solid iris
#

and using (a) this is equivalent to g(2)=0

sand flume
#

I see

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what about the role of A then?

solid iris
#

as you said g(2)=2A

sand flume
#

oh

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everything makes sense now. Could we not say that you can make g have any period?

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oh wait nvm

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f always has to have the same period as g

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ok thx

#

.solved

midnight plankBOT
#
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solid iris
#

np

solid iris
midnight plankBOT
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woeful turret
midnight plankBOT
woeful turret
#

a+b+c not a+b+x

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i did integration by parts

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(1)(1-x^10)^20 = x(1-x^10)^20 +integral 200 x^10 (1-x^10)^19

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and x(1-x^10)^20 with limits = 0

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so my a = 200

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b=11

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c=20

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but this gives a huge answer which is wrong

midnight plankBOT
#

@woeful turret Has your question been resolved?

woeful turret
#

<@&286206848099549185>

tawdry kraken
#

IBP seems like a good approach

woeful turret
tawdry kraken
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I know I'm saying I agree with your idea

woeful turret
#

oh ok

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do u know why my ans is wrong?

tawdry kraken
#

But I'm not sure about your process here

woeful turret
#

o what is wrong

tawdry kraken
#

So you have this: $$\int_0^1(1)(1-x^{10})^{20}dx = x(1-x^{10})^{20} + \int_0^1 200 x^{10} (1-x^{10})^{19}dx$$

grand pondBOT
#

Coolempire93

tawdry kraken
#

Verify that that's what you meant before I critique it

woeful turret
#

yeah thats what i meant

tawdry kraken
#

Ah this is after simplification, okay I agree so far

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Unfortunately this integral is not the form of $\beta$

grand pondBOT
#

Coolempire93

woeful turret
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huh isnt it the form

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x(1-x^10)^20 with the limits becomes 0

tawdry kraken
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Right

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But $\int_0^1 200 x^{10} (1-x^{10})^{19}dx$ is not $\beta$ of anything

woeful turret
#

oh

grand pondBOT
#

Coolempire93

woeful turret
#

the inside is 1-x not 1-x^10

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shit broooooooo

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i can get it now

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thank u idk what i was thinking

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.close

midnight plankBOT
#
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tawdry kraken
#

No problem haha

#

It's easy to miss

midnight plankBOT
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maiden bridge
#

I’ve been trying to learn for 10 minutes now, how is this possible?

grand canopy
maiden bridge
#

c(a-bc)?

grand canopy
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when you factorised the c out, notice how the a no longer has a c term? this is correct, so it should be the same with the b term

maiden bridge
#

So what now

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What is the proper way to facrorise

grand canopy
#

what is your revised factorisation?

grand canopy
grand canopy
grand canopy
grand canopy
maiden bridge
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2?

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(3x-2) is common

grand canopy
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good spot

maiden bridge
#

Ok I get it now

#

.cllse

midnight plankBOT
#

@maiden bridge Has your question been resolved?

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twilit field
midnight plankBOT
twilit field
#

Couple of questions

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firstly , this is the term I'm looking for , right

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spamming is against server rules

sharp coral
#

@astral hare this is a channel to help with wai's question, do not spam here.

twilit field
twilit field
#

like given an interval I could bound it( as it's increasing on (0,infty) and decreasing on (-infty ,0)

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<@&268886789983436800>

formal blade
#

This is not appropriate for the help channels

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It distracts people from getting help

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Because it is in the way of the help channel

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Ah wait you were already warned for this earlier even

unkempt sluice
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This guy is also in channel 25,23,44

formal blade
#

They are now muted for misusing the help channels

twilit field
viral dagger
twilit field
viral dagger
unkempt sluice
#

[a,b] means [b,a] when a>b in my message

twilit field
#

so if $x_0 >0$the error term is this where $\zeta=x_0$

grand pondBOT
unkempt sluice
#

When n is odd, sinh monotonical, so yeah max(|sinh(x_0)|, |sinh(x)|}

twilit field
unkempt sluice
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Even n have to consider multiple cases

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Oh your n is 43, odd

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Solved then

twilit field
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cool

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thanks

unkempt sluice
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Np

twilit field
#

.close

midnight plankBOT
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gusty sky
#

Can anyone please help with this

midnight plankBOT
livid python
grand pondBOT
olive matrix
#

what have you tried so far

gusty sky
midnight plankBOT
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twilit field
midnight plankBOT
twilit field
#

!status

midnight plankBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
twilit field
#

1

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wait is $\overline{X}$ just $\mu$ here

grand pondBOT
brazen onyx
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mu is the true population mean (which is a fixed constant).

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X bar is the sample mean which is a random variable

twilit field
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right

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Then Idk what to do

brazen onyx
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soo we are told that $X_{n+1} \sim N(\mu,1)$. You should think about rewriting the pieces as squares standard normals!

grand pondBOT
twilit field
#

i see

twilit field
grand pondBOT
subtle zinc
#

yes and iid

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have you seen sample variance?

twilit field
#

yea

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but. never really worked with it

subtle zinc
#

the sum ur given should remind of u that

twilit field
subtle zinc
#

yes

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(n-1)S^2 ~ chi^2(n-1)

twilit field
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wait , I missed a fomula I suppose

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hmm, no nvm

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sorry just so lost rn

subtle zinc
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@twilit field what's up

twilit field
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Looking ip formulae

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one min

subtle zinc
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alright

twilit field
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just this?

subtle zinc
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mhm

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what's the distribution of X_{n+1} - mu?

twilit field
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normal

subtle zinc
#

what parameters

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?

twilit field
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wait isn't it just $\xi^2(1)$

grand pondBOT
twilit field
#

or is that the square of this

subtle zinc
#

what

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ok dude, im gonna leave this to someone else catthumbsup

twilit field
#

Sorry

subtle zinc
#

not a problem.

twilit field
#

I'll close this for now have to re-read the theory I gues

#

.close

midnight plankBOT
#
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midnight plankBOT
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inland patio
#

Suppose we have a map $f:\mathbb{R}^n\to\mathbb{R}^m$, the total derivative of $f$ at $x$ is denoted $f'(x)$. In other words, the map $x\mapsto f'(x)$. This is not to be confused with the linear transformation $h\mapsto f'(x)h$. \

Is there something analogous as a differential in $g:\mathbb{R}\to\mathbb{R}$ in this setting, i.e. in $1$-dimension I sometimes see people write $dg=\frac{dg}{dt}dt$ and they call $dg$ the differential of $g$. So is there such a thing also for $f$?

grand pondBOT
main current
#

What comes to mind is the Jacobian. If X is a vector of "small input errors", then JX = Y is a vector of "small output errors"

#

But maybe that's the linear transformation you're telling me not to be confused with?

inland patio
main current
#

So to bring that to the 1-D case, we have dg = Jdt

Where the Jacobian J = dg/dt

inland patio
#

Makes sense. 👍

inland patio
main current
#

Yeah what's up?

inland patio
# main current Yeah what's up?

On Wikipedia (see link below), we have the following identity $$\operatorname{det} '(A)(T)=\det A\operatorname{tr}(A^{-1}T).$$I'm wondering how to go from this equality to $$d\det A = \det A\operatorname{tr}(A^{-1} \cdot d A)?$$

grand pondBOT
inland patio
#

Do we simply "plug in" T = dA in the first equation, where dA is a small vector?

midnight plankBOT
#

@inland patio Has your question been resolved?

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woeful turret
midnight plankBOT
woeful turret
#

i tried making denom into a perfect square

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(a-cos x)^2 + 1 - cos^2 x

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= (a-cos x)^2 + sin^2 x

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and then i thought ill multiply and divide by sec^2 x

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but that didnt help

soft stone
#

isn’t this just the fourier series identity

woeful turret
#

what is that lol

tough basin
#

Hi guys im a student of class 10 and my boards are from feb 17 and im starting syllabus from tommorow like fresh do u have any idea that how i can complete all my topics and memorize them thouroughly and get 90 percent plus

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in maths and other subjects

soft stone
tough basin
#

sure my bad

woeful turret
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im in high school

soft stone
#

oh mb 😭

plucky lark
woeful turret
# woeful turret

btw i got the answer by putting a=1/2 but i still wanna know how to do it properly

soft stone
#

uhh you can try rewriting the denominator in terms of sin²(x/2) then use the substitution t = tan(x/2)

woeful turret
#

oh

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alright im just going to leave this

woeful turret
#

.close

midnight plankBOT
#
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midnight plankBOT
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twilit field
#

Usually won't alpha be 0

midnight plankBOT
twilit field
#

well, whenever it converges

runic hamlet
#

no

twilit field
#

hmm., okay, why not

unkempt sluice
#

Literally impossible

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λ>0

twilit field
#

I'm confused becauses doesn't p_{n+k} tend to p

lyric charm
#

try writing out what it would mean for alpha to be 0

twilit field
zealous schooner
#

don't use the approximation

twilit field
#

well, now that I read it again, we've literally defined it for alpha >1

lyric charm
#

=1

twilit field
#

okay, got it

#

thanks

#

.close

midnight plankBOT
#
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native pagoda
#

hi guys 🤓👋🏾

midnight plankBOT
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royal vigil
#

kill me now

midnight plankBOT
royal vigil
#

this question is literally impossible

prime hornet
#

what’ve you tried? pikathink

royal vigil
#

ok so

late rover
royal vigil
#

desmos on the other hand

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so im literally getting like 10 different answers

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none of which seem correct

prime hornet
# royal vigil

you’re missing a minus sign in front of all your factors, I believe MiniheraBow

royal vigil
#

basically for x > 0
x(1+2x-x^2) > 2 (no sign flip)
(x+1)(x-1)(x-2) > 0
and i got
-1 < x < 1 , x>2

for x < 0
same thing
(x+1)(x-1)(x-2) < 0 (sign flip)
so
x < -1, 1 < x < 2

prime hornet
#

oh sorry, you flipped the inequality

royal vigil
#

wat am i doing wrong

prime hornet
#

you are indeed missing the minus-

royal vigil
#

i am missing both the point and the minus

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which minus 😭

prime hornet
royal vigil
#

wait

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but that still doesnt explain this

prime hornet
#

then you should consider the roots of the expression, divide R up into intervals, and check the sign of the function on each interval

royal vigil
#

where is desmos getting this from..................

prime hornet
#

what’s the issue in the photo? pikathink

royal vigil
#

y is it from -1 to 0 and not -1 to 1 like that seems more intuitive no? its an entier gap under 0 not

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idk i dont really get it either way

prime hornet
#

well, on the interval (-1, 0), both (x-1) and (x-2) are negative

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combine that with your minus sign at front, and you have three negatives

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meanwhile (x+1) is positive on that interval

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so all in all, you’ve got a negative sign on your function, so it’s below zero

royal vigil
#

but isnt the entier line from -1 to 1 below 0 anyways

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why does it matter which factors are below 0 and which arent

prime hornet
#

hold on, give me a moment EB_JolteonGiggle2

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there’s a mistake somewhere

prime hornet
#

and hence if it’s negative or positive somewhere

royal vigil
#

help

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ive gone from dying to laughing because this is getting to a point where its like

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wtf

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what is going on here

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this is apparently for x > 0

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where is it getting those intervals from

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where are those intervals coming from

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the 0 < x < 1
1 < x < 2
x > 2

prime hornet
#

those are the roots of the polynomial

native pagoda
#

Is there a way to calculate this quickly?

prime hornet
royal vigil
royal vigil
#

theres only (x+1)(x-1)(x-2)

prime hornet
#

you’re right, that’s odd pikathink

#

I’m kind of confused now too haha

royal vigil
#

and why is the answer still right..

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even desmos is treating it like 0 is a root

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even though its not

prime hornet
#

ah wait, zero is excluded since it’s an asymptote

royal vigil
#

So why r we considering it

prime hornet
#

we need to consider the intervals to the left and right of it

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we’re not considering the function at 0 itself

prime hornet
# royal vigil

I’m starting to think it might be easier to not multiply by x and then subtract 2 initially

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try subtracting both sides by 2/x and forming a common denominator

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then you’ll have the roots of the numerator and the denominator as your partition

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and you can make the sign chart off of the roots plus the asymptote

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that should work better I think

royal vigil
#

Okok idek what a sign chart is but let me try that

prime hornet
#

just a table to keep track of the sign of a function across intervals

royal vigil
#

ok like

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its working

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but i dont understand WHY its working

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like..

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i dont understand why my way didnt work

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dude why did this work but not my other way

prime hornet
prime hornet
#

you just missed the sign

royal vigil
#

OK

#

I FIGURED IT OUT

prime hornet
#

nice giggle

royal vigil
#

yes i did in fact miss the sign

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so

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i missed the sign and graphed incorrectly and then i also didnt consider the asymptote at 0

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otherwise would have been fine...

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okay

#

thanks for helpinggggggggg

prime hornet
prime hornet
#

glad you figured it out!

royal vigil
#

hehe

#

bai now

#

.close

midnight plankBOT
#
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balmy cypress
midnight plankBOT
grand pondBOT
#

Professor Edward C. Hawthorne

balmy cypress
#

Here I can't use $Lt^n=\frac{n!}{s^{n+1}}$?

grand pondBOT
#

Professor Edward C. Hawthorne

balmy cypress
#

Then a negative factorial would come out

#

Anyway I should do the Laplace Transform

snow niche
#

$\mathcal{L}{f(t)}(s)=F(s)=\int_{0}^{+\infty} e^{-st}f(t)dt$

grand pondBOT
snow niche
#

so

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$\int_{0}^{+\infty} e^{-st} t^{-3/2}dt$

grand pondBOT
snow niche
#

Wait

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We must first see if it is Laplace transformable

tawdry kraken
#

They gave the entry from the table for t^n already

balmy cypress
#

But I don't think it works

tawdry kraken
#

I'm not sure if the gamma function extension works or not (I am betting it does, but was verifying by hand)

snow niche
#

For t close to 0 diverges

balmy cypress
#

So the Laplace transform doesn't exist?

snow niche
#

If you write 1/t^(3/2)

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$\int \frac{1}{t^p} \mathrm dt$

grand pondBOT
snow niche
#

When does it converge?

balmy cypress
#

p>1

snow niche
#

So

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If you have

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$\int^1_0 1/t^p$

grand pondBOT
snow niche
#

When it converges

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@balmy cypress

balmy cypress
#

p>1

dusky vessel
#

$\frac{1}{\sqrt(t^3)}$

grand pondBOT
#

elijah

snow niche
balmy cypress
#

-p+1

snow niche
#

p<1

balmy cypress
#

-p+1>0

#

p<1

snow niche
#

👍

balmy cypress
#

👍

snow niche
#

And

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$\int_1^{\infty} 1/t^p$

grand pondBOT
balmy cypress
#

1-p<0
p>1

midnight plankBOT
#

@balmy cypress Has your question been resolved?

midnight plankBOT
#
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maiden bridge
#

How to factor this?

midnight plankBOT
maiden bridge
#

x(x+5-6)?

dawn dagger
midnight plankBOT
#

@maiden bridge Has your question been resolved?

clear lion
clear lion
# maiden bridge x(x+5-6)?

x(x+5-6/x) since the 6 is one degree lower than the 5 they cant be the same degree after factorisation

maiden bridge
#

And now what ?

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How to do it proper way

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How to factorise using two brackets

inner barn
#

fuzzix do you know how to expand brackets?

#

@maiden bridge

wanton vault
# maiden bridge How to factorise using two brackets

you gotta divide the integer part (-6 in this case) so that the summations of the terms will create the coefficient of the middle term (aka term with the smallest order of variable, in this case its the x to the power of 1)

maiden bridge
#

Idk how to do that

wanton vault
#

you cant find 2 numbers that when multiplied makes -6?

inner barn
maiden bridge
#

no

wanton vault
maiden bridge
#

2,449 does

#

,calc 2,449

grand pondBOT
#

The following error occured while calculating:
Error: Unexpected operator , (char 2)

maiden bridge
#

,w 2,449*2,449

brazen onyx
#

😭 where did you get that number from

maiden bridge
#

Anyways How to expand it?

brazen onyx
# maiden bridge Anyways How to expand it?

This video might prove helpful!
https://youtu.be/xMeI1S6VfNU?si=u1nW5STfqCyBn2hK

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Get Involved with...

▶ Play video
maiden bridge
#

I’ll see.

midnight plankBOT
#

@maiden bridge Has your question been resolved?

maiden bridge
#

Didn’t help

#

Didn’t do what I wanted

#

<@&286206848099549185>

outer portal
#

Yes?

celest jacinth
#

or multiply out?

maiden bridge
opaque rose
celest jacinth
#

But also learning how FOIL multiplies out two binomials may help.

outer portal
#

Just do the quadratic formula no better way exists

celest jacinth
celest jacinth
celest jacinth
#

If you don’t understand, I’d be willing to go deeper into an example.

outer portal
cloud moth
celest jacinth
outer portal
celest jacinth
outer portal
#

You can say subtract to 5 and multiply to 6

celest jacinth
maiden bridge
celest jacinth
celest jacinth
maiden bridge
celest jacinth
maiden bridge
celest jacinth
#

The quadratic formula, however, is this

maiden bridge
#

I want to learn FACTORISE

#

TO SAVE TIME

#

celest jacinth
#

what two numbers add to get 5 and multiply to -6

celest jacinth
maiden bridge
#

Okay great

#

Now what

#

What can I do with these numbers

celest jacinth
# maiden bridge Now what

since there is no coefficient in front of the x^2, those two numbers can be put into two binomials (two parentheses)

maiden bridge
#

Okay

#

(x)(x)

celest jacinth
#

(x[+/- first number]) (x[+/-second number])

#

the positive negative is just to reaffirm what sign it is

cloud moth
celest jacinth
#

i.e. “3” is positive 3

cloud moth
#

(x+6)(x-1)

celest jacinth
#

so (x+6)(x-1)

cloud moth
#

then if you wanna solve it you have to do the null factor law

celest jacinth
maiden bridge
#

How do you know that it’s not the other way around?

#

-1 first and 6 second

celest jacinth
cloud moth
celest jacinth
#

in this scenario

cloud moth
#

youre multiplying them

celest jacinth
#

when there’s no “a” in this kind of equation

#

it doesn’t matter

cloud moth
#

u can do (x-1)(x+6) or (x+6)(x-1) both r right

maiden bridge
#

Cassie is being bossy rn…

cloud moth
#

bro what

maiden bridge
#

Okay so

x = 1
x = -6

celest jacinth
#

another example is “x^2+2x-3”, where -3 is the product of 3 and -1, which also, when added, is positive 2 (middle term); the factored form would be (x+3)(x-1)

cloud moth
maiden bridge
#

Without calculating with use of formula

maiden bridge
celest jacinth
maiden bridge
#

I don’t know

celest jacinth
# maiden bridge I don’t know

Are you done with the question? If so, you can close this one and create a new one at a later time when you have a new question.

midnight plankBOT
#

@maiden bridge Has your question been resolved?

midnight plankBOT
#
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near geyser
#

Hints

midnight plankBOT
near geyser
#

Mod 10?

tawdry kraken
#

Jesus

#

And yes

near geyser
#

You seem very active helper

small jasper
near geyser
#

Hey pigeon

#

Ohhhh

lyric charm
#

yes mod 10

#

as a first step: $k \equiv 8^{100} + 7^{84} - 3^{37} \pmod{10}$

grand pondBOT
near geyser
#

2^100+3^84-3^37

tawdry kraken
lyric charm
#

sure, that also works.

near geyser
#

What should I do next?

tawdry kraken
#

I was using phi(10) = 4 to reduce the exponents 😆

near geyser
#

Should I apply it?

tawdry kraken
#

I think that would be easiest now that you have primes

near geyser
#

2^4+0-3

#

13

#

And we get 3

lyric charm
#

hold on a bit

near geyser
#

As remainder

lyric charm
#

how did 0 come

near geyser
#

3^84 exponent fully divided by 4

lyric charm
#

that means 3^84 ends in a one not zero!

near geyser
#

,w 3^84 mod 10

lyric charm
#

see

tawdry kraken
#

anything^0 = 1

near geyser
#

Ayyyega

#

16+1-3=14

#

So 4

#

Can I ask one more tricky?

#

In running channel?

tawdry kraken
#

Let's check our answer

near geyser
tawdry kraken
#

,w 8^100 + 7^84 - 3^37 mod 10

tawdry kraken
#

Oh okay great

#

👍

near geyser
lyric charm
near geyser
midnight plankBOT
# near geyser Can I ask one more tricky?

It is suggested that you limit yourself to one question per help channel, opening a new one once your original question is answered and your original channel has been closed. This is to make your channel easier to follow for potential helpers and can bring attention to the fact that your question has changed.

near geyser
#

.close

midnight plankBOT
#
Channel closed

Closed by @near geyser

Use .reopen if this was a mistake.

tawdry kraken
#

They were just telling someone to stop doing that the other day

#

Because they backtoback opened them and had like 4 stuck open waiting to close

#

They said it was against the rules but !1q suggests otherwise

#

I'll keep that in mind

near geyser
#

Hey are you coming?

tawdry kraken
#

Yeah

#

I was seeing if Ann had anything to add

#

Since they're helpful they have more experience

midnight plankBOT
#
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tulip kiln
#
  1. The circles k1 (with centre M1 and radius 13) and k2 (with centre M2 and radius 15)
    intersect each other in the points P and Q. The length of the distance PQ is 24. What
    possible value could the distance M1M2 be?
    A) 2 B) 5 C) 9 D) 14 E) 18
tulip kiln
#

I am unable to visualize this.

lyric charm
midnight plankBOT
#

@tulip kiln Has your question been resolved?

next bobcat
#

@tulip kiln you with me?

#

so firstly do you know the property about perpendiculars from the center?

willow spindle
next bobcat
#

but I have to wait for OP first

midnight plankBOT
#
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stone ivy
#

How to solve this equation?
$2^{\ln x}=-3$

midnight plankBOT
grand pondBOT
#

fort craft 🇵🇸

lyric charm
#

therefore no real solutions

next bobcat
#

damn that was quick

#

yeah

lyric charm
#

nothing else to say

stone ivy
next bobcat
#

oh

lyric charm
#

oh blergh

#

should have specified

next bobcat
#

I have a weird method

tawdry kraken
#

Take ln both sides, recall ln(-1) = i*pi 👌

#

In the principal branch anyway

west iron
#

take log_2 of both sides

tawdry kraken
#

Yeah but log 2 gets messy because you have to base change to get the i*pi out

#

So usually I prefer ln

next bobcat
#

isn’t $2^ln(x) = x * 2/e$?

stone ivy
grand pondBOT
next bobcat
#

I mean it shouldn’t help here

tawdry kraken
next bobcat
#

the basic definition of logarithms is to find the exponent such that x^y = z where y is logx(z)

tawdry kraken
#

So since we know $e^{i\cdot\pi} = -1$

grand pondBOT
#

Coolempire93

next bobcat
#

so here z is to take a negative value

tawdry kraken
#

Then $\ln(e^{i\cdot\pi}) = i\cdot\pi = \ln(-1)$, at least in the principal branch

#

This is a challenge on mobile

grand pondBOT
#

Coolempire93

stone ivy
tawdry kraken
#

Yes, but not in the complex field

stone ivy
tawdry kraken
#

Once raising to a power becomes rotation, now its just a question of what rotation gives us -1

#

Which makes a lot more sense when you are working with the unit

stone ivy
#

@tawdry kraken okay bro I accept that ip = ln(-1). How do we solve the initial equation given this new information?

tawdry kraken
#

Recall the log rule $\log(a^b) = b\cdot\log(a)$

grand pondBOT
#

Coolempire93

pure wraith
#

I don't think you should only restrict it to the principal branch in this case, the question probably expects all solutions

tawdry kraken
tawdry kraken
#

Although the raising as a power of e will collapse it back down again

pure wraith
tawdry kraken
#

Ah well now we're out of my depth because I don't know about branch cuts

#

I saw someone talking about them the other day

#

But as a reference I was going to suggest

#

\ln(2)\ln(x) = \ln(-3)

pure wraith
#

It's probably better to ignore the branch cuts for now and use $\log z = \ln \abs{z} + i\arg(z)$

grand pondBOT
#

jewels!

tawdry kraken
#

Listen to jewels this and follow her instructions

#

Also I just remembered the formula $a^{\log_b(c)} = c^{\log_b(a)}$ which may have made the problem easier (then x = ln(2)th root of -3) but I'm not sure if it holds for complex

grand pondBOT
#

Coolempire93

tawdry kraken
#

How many ln 2th roots of unity are there anyway xd

stone ivy
#

I am utterly confused by all the input given.

#

$(\ln x)(\ln 2)=\ln -3$

grand pondBOT
#

fort craft 🇵🇸

stone ivy
#

$(\ln x)=\frac{\ln -3}{\ln 2}$

grand pondBOT
#

fort craft 🇵🇸

stone ivy
#

$\ln x=log_2{-3}$

outer scaffold
#

llike this

grand pondBOT
#

fort craft 🇵🇸

stone ivy
#

$x=e^{log_2{(-3)}}$

grand pondBOT
#

fort craft 🇵🇸

stone ivy
#

Is this the correct solution?

outer scaffold
stone ivy
#

@outer scaffold what happened to the negative sign behind 3?

outer scaffold
tulip kiln
#

Yes

#

Sorry

outer scaffold
#

if it is really this then this has no solution

#

we are moving into complex numbers then

stone ivy
outer scaffold
#

let me figure in complex world then.

pure wraith
outer scaffold
midnight plankBOT
pure wraith
#

$\log z = \ln \abs{z} + i\arg (z)$ for $z \in \mathbb C$

grand pondBOT
#

jewels!

outer scaffold
#

I just took my student thru logs.

stone ivy
# lyric charm !noai

bro if I wanted ai response I would go use AI. I'm here to recieve human feedback.

stone ivy
pure wraith
#

It's the argument of z

#

The angle it makes with the positive real axis, and it is multivalued

#

If $\theta$ is an angle, then so is $\theta + 2n\pi$ for all $n \in \mathbb Z$

grand pondBOT
#

jewels!

pure wraith
#

So what angle does -3 make (as a vector) with the positive real axis?

stone ivy
pure wraith
pure wraith
stone ivy
pure wraith
#

The polar form?

stone ivy
stone ivy
pure wraith
grand pondBOT
#

jewels!

pure wraith
#

It is your preference if you want to use the notaton "ln" for complex inputs, but I don't

stone ivy
pure wraith
#

yes

#

Don't forget to add the 2n*pi though

midnight plankBOT
#

@stone ivy Has your question been resolved?

midnight plankBOT
#
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twilit field
midnight plankBOT
grim vector
#

Tried anything?

twilit field
#

okay, so I have some ideas

#

yes

#

I'm using this method

grim vector
#

moment method right ?

twilit field
#

yes

pure wraith
#

spam calculate moments until you get it

twilit field
#

so the first moment is 0

grim vector
#

So first moment, second moment, empiric moment and you solve the equality between all

twilit field
#

what's empiric moment?

grim vector
#

The sum

pure wraith
#

I think this one is doable with the second moment alone

grim vector
twilit field
#

The second moment is $\frac{\theta^2}{3}$

grand pondBOT
grim vector
#

I agree

twilit field
#

and that is equal to $\frac{1}{n} \sum_{i=1}^{n} X_i^2$?

grand pondBOT
grim vector
#

Yes

#

Now is just a solve for theta thing

twilit field
#

mhm, my question is what do I do with the sum

pure wraith
#

what about it?

grim vector
#

Nothing, let it as a sum

twilit field
#

this is very similar to sample variance

pure wraith
#

You're meant to leave it as M_2

#

That is the point of estimating with moments

twilit field
#

so $\theta^3/n = M_2 \implies \theta = \sqrt[3] {nM_2}$?

grim vector
#

M_2 is already a standart thing

grand pondBOT
grim vector
#

Ja

twilit field
#

wat

#

that's seriously it?
😭

grim vector
#

The exercice ?

#

Yeah i mean its some stats

twilit field
#

I mean how would I find M_2

grim vector
#

Given by observations of the phenomen

twilit field
#

I know there are n values all with idetical dist

grim vector
flat spire
#

yakuu

twilit field
#

thanks!

#

.close

midnight plankBOT
#
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midnight plankBOT
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woeful turret
midnight plankBOT
woeful turret
#

i took 3 cases
D4 shows same as D1,D2,D3

#

since all 3 cases are same we can multiply by 3

#

D1 D2 D3 D4
say D1 is the dice with same number, it can have any number
D1 = 6/6
D2 cannot have the same number as D1 so D2= 5/6
D3 cannot have same number as D1 so D3=5/6
D4 has to have same number as D1 to 1/6

#

so on multiplying by 3 i get 75/216 which dosent match anything

#

can someone help?

bold peak
#

Holy shit I hate this problem so much

woeful turret
#

oh why

bold peak
#

Nothing in the problem restricts that

hard shard
#

if D1 D2 D3 roll 1 2 3 respectively, what is the probability D4 is the same as one of the other dice?

#

now consider D1 D2 D3 roll 1 2 2

woeful turret
bold peak
#

Doesn't say exactly one

woeful turret
#

it dosent say atleast one

#

so i thought exactly

bold peak
#

In usual english, it would mean at least one

woeful turret
#

oh alr alr i get what ur saying

woeful turret
#

let me try again

#

im getting 81/216 now

#

i took 3 cases
All distinct
2 same
3 same

#

for all distinct (6/6)(5/6)(4/6)(3/6) = 60/216

#

2 same (6/6)(5/6)(2/6)(2/6) = 20/216

#

3 same (6/6)(1/6)(1/6)(1/6) = 1/216

#

where have i gone wrong

#

@bold peak

hard shard
#

do you account for a roll of 2 2 1?

#

(for the first three dice)

woeful turret
hard shard
#

look carefully

#

6/6 means first dice doesnt matter

woeful turret
#

yeah

hard shard
#

5/6 means second dice isnt the same as first

woeful turret
#

yeah

hard shard
#

2/6 means third dice is the same as one of the first two

woeful turret
#

yea

hard shard
#

so it will count 1 2 2 and 2 1 2, but not 2 2 1

woeful turret
hard shard
#

thats like saying rolling a 1 2 is the same as rolling 2 1, so the probability of that happening is 1/36

#

obviously thats nonsense, its 2/36

#

maybe i shouldnt say obviously

woeful turret
#

oh ok its the same but we still have to count it..my bad

hard shard
#

yes, the case can appear in multiple scenarios

#

one of the hardest things to get right in probability questions is understanding what cases have equal probability/weight

woeful turret
#

so do i make another case inside 2 same in which 1st is same as 2nd?

#

ok yes if i do that it gives me a + 10

#

= 91/216

#

thanks a lot bro

#

dont feel good tho cause u gave me lots of help for this

#

.close

midnight plankBOT
#
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hard shard
midnight plankBOT
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woeful turret
midnight plankBOT
woeful turret
#

i took 3 cases S1={1,2} , {1,3} and {2,3} and tried to calculate each set

woeful turret
#

in my book its given Let E2-S1 and F2 = F1 U S1

#

let me try again then..seems like a misprint

#

.close

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twilit field
midnight plankBOT
twilit field
#

My initl thought is to solve for $10^{-3}=3/2^n$

#

but that feels sus

hard shard
#

.3?

twilit field
#

I thought I had corrected it

grand pondBOT
hard shard
#

this should not be equal

twilit field
#

mhm

#

wait. why not

hard shard
#

alligator eats the bigger number

twilit field
#

okay yea

twilit field
hard shard
#

the ceiling exists later

twilit field
#

so $\ceil{\log_{2} ( 3000)}$

grand pondBOT
twilit field
hard shard
#

which is?

twilit field
#

12

hard shard
#

i wouldnt put it past your teacher to have you calculate this

#

yeah 12

twilit field
#

wait, it's that easy 😭 ?

I was sure I had messed up somewhere

hard shard
#

assuming the bisection method is bascially just binary search, yes its that easy

twilit field
#

Thanks!

midnight plankBOT
#
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near geyser
#

Start?

midnight plankBOT
lyric charm
#

show your book's definition of coplanar points

#

@near geyser

near geyser
#

What do you want to see?

lyric charm
#

i want to see where in your book the notion of "coplanar pts" is introduced for the first time

near geyser
#

Points coolinear

Or points coplaner never saw in the book

#

I guess they are saying vectors are co planer not points

#

What next?

lyric charm
#

can you read all of it in full?

#

i do not want to give you a solution only to find out that it's not how your book wants it done

near geyser
#

of course it says about vectors not points

lyric charm
#

ok well can you show me ANYTHING AT ALL that it says about coplanarity.

near geyser
#

Sure

midnight plankBOT
#

@near geyser Has your question been resolved?

soft stone
#

basically try rearranging the given vector equation into the form of the section formula

lyric charm
#

i was trying to get OP to show us anything from his textbook that'd talk about a formula

#

like yknow i could definitely say that e.g. the vectors PQ, PR, PS are linearly-dependent but i am not sure that this would be valid for op's context.

soft stone
#

mhmmm go ahead that's a valid concern

midnight plankBOT
#

@near geyser Has your question been resolved?

lyric charm
#

OP is you

#

🫵

midnight plankBOT
#
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inland patio
#

When someone says that the determinant is infinitely differentiable since it is a polynomial in the entries of the matrix, which derivative do they have in mind? Total derivative? Partial derivative with respect to one entry? I'm interested in knowing if $A\mapsto\det(A)$ is \emph{continuously} differentiable?

grand pondBOT
steady saddle
#

All of the partial derivatives

inland patio
steady saddle
#

As you said, it's a polynomial. Are polynomials infinitely differentiable? (yes) (but convince yourself they are)

inland patio
steady saddle
#

What do you mean by "funcion of A"?

#

What if I take the funcion (x,y,z) -> x+y+z?

inland patio
steady saddle
#

Yes

#

But A has real entries right?

inland patio
#

yeah (or complex)

steady saddle
#

Then you can really think of A simply as a vector of entries rearranged in a square

#

So a 2x2 matrix is just a 4-element vector

inland patio
steady saddle
#

I suppose this is what the question you were given meant

inland patio
#

thanks for the help!

#

.close

midnight plankBOT
#
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midnight plankBOT
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sand flume
#

I don't see how the inequalities provide anythign for part a. For it to be cont we need the limit of sin x at 0 to exist and to equal sin(0). The only thing I could possibly see that inequality being used for is sinx<|x| and sinx>-|x| we could then see left and right limits but we can just find lim x-> of sin(x) directly

wanton spade
remote bone
#

mods

wanton spade
#

<@&268886789983436800>

sand flume
wanton spade
wanton spade
sand flume
wanton spade
sand flume
#

Delta eplison

wanton spade
#

but itd be much easier to just use epsilon delta for continuity

wanton spade
wanton spade
sand flume
#

But don't we need to prove the limit exists for cont?

wanton spade
#

do you know the epsilon delta definition of continuity?

sand flume
#

kind of going to read the textbook section on it again

#

thx

wanton spade
#

gl

midnight plankBOT
#

@sand flume Has your question been resolved?

midnight plankBOT
#
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bold hill
#

After factorising, I don’t really know what to do

bold hill
#

Wrong question I meant

near cliff
slate ferry
# bold hill

-# also do you know series? eeveekawaii (I have a feeling that you dont... and you're supposed to magically do this...)

bold hill
#

they are decreasing by 3 inside the roots

#

assuming that you can write it as a series, what would the common difference be?

#

<@&286206848099549185>

#

.closer

#

.close

midnight plankBOT
#
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slate ferry
#

ending with n=30 but I dont think that's very solvable nor is a good idea.

#

It's been a while since I've done series.

midnight plankBOT
#
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maiden bridge
#

The table shows the prices of raisins and dried plums.

Price per 1 kg
raisins – 20.00 PLN
dried plums – 32.00 PLN

Zosia bought half a kilogram of dried plums. Ala bought only raisins and paid the same amount as Zosia paid for the plums.

Calculate the mass of raisins bought by Ala.

Write down all calculations.

maiden bridge
#

32-20=12 zl

#

She has 1 kg of raisings and 12 zl left

#

And now

#

12:20

#

,w 12/20

maiden bridge
#

And that’s 0,6 kg

#

So she bought 1,6 kg

#

,w 1.6*20

maiden bridge
#

THATS SOOO EASY

#

also this is 6th grade exam

#

😭😭😭😭

inner barn
maiden bridge
#

what does that have to do with anything?

scenic wyvern
#

that has to do with the fact that ToS and this server's rules do not allow users under 13.

inner barn
#

because I swear 6th grade in Poland is 11-12

scenic wyvern
#

I'm tempted to preping mods just in case

maiden bridge
#

XD I’m testing if I’m stupider than 6th grader relax

scenic wyvern
#

ToS violations are not exactly things to relax about in a partnered server, so do be careful about casually mentioning something that may imply you're under 13, regardless of whether you are.

#

now, are you done with your question?

inner barn
#

holy aura…

candid gull
#

!done

midnight plankBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

#

@maiden bridge Has your question been resolved?

scenic wyvern
#

@maiden bridge if you have another question, don't just ❌ the bot. do send your next question here or state what you still have left with your current one

#

and yes, we can tell you ❌'d the bot.

maiden bridge
#

I didn’t actually

scenic wyvern
#

in that case I'll be closing this, since it seems like you're done

#

.close

midnight plankBOT
#
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#
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maiden bridge
#

For what are logarithms used for? They’re just pointless and easy enough… basically the opposite of doing numbers under powers.

pearl hull
#

more like inverse of power

maiden bridge
#

Whatever

#

So useless

olive matrix
#

I don't think this question is well-formed, but for an early application of logarithms you can look at a slide rule, which was a pre-calculator method of multiplying two large numbers together very quickly

lusty python
grand pondBOT
#

1 divided by 0 equals Infinity

lusty python
#

tell me

maiden bridge
#

Sqrt of 5

#

,w sqrt(5)

mystic condor
#

Logs are often used for certain scales and are also big parts of calculus and differential equations, as well as other things but they are also just handy in general algebra and arithmetic

cerulean oyster
#

this guy/girl is surely trolling anyways

white moss
#

logarithms famously have zero applications

cerulean oyster
#

tbh reminds me of someone else that recently was doing something similar, wouldnt be surprised if its an alt.

maiden bridge
#

Okay can anyone show how’d I do 2^x = 5

#

Step by step

mystic condor
#

Well you convert it to a log equation

keen wigeon
#

its log2 of 5

#

so uhh

maiden bridge
#

Yea

#

It’s difficult to calculate that

keen wigeon
#

youd want to take log2 of both sides

#

and log2 of 2^x is x so

mystic condor
keen wigeon
maiden bridge
#

Exactly you guys can’t even calculate it

keen wigeon
bold peak
#

,w log_2(5)

mystic condor
#

"Stupid mathematicians cant calculate a log with an irrational result which is practically impossible to do on paper! What losers!"

keen wigeon
olive matrix
#

.close

midnight plankBOT
#
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near geyser
midnight plankBOT
near geyser
#

How do I solve it?

midnight plankBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
near geyser
#

1

unkempt sluice
#

Say four points a,b,c,d. As vectors a,b,c not dependent. Then as vectors d=ua+vb+wc for some u,v,w
d is on the plane containing a,b,c if and only if u+v+w=1
(w on the affine space generated by v_1,…,v_m if and only if expressing w as linear combination of these v_j, sum of coefficients being 1)

olive matrix
#

You already sent this problem last night, and did not respond to requests for elaboration at the time. Have you made any progress since then?
#help-49 message

near geyser
olive matrix
near geyser
#

i googled and found solutions and read out

unkempt sluice
near geyser
#

Why u+v+w=1

#

So we are using Linearly independence and dependence definition

unkempt sluice
#

I prove the more general thing I said in the bottom of my message: w is in the affine space generated by those v_j is the same thing as those v_j-w are linear dependent , there exists Σc_j (v_j-w)=0 thus w=Σ(c_j/ (Σc_k)) v_j. (Σc_k won’t be 0, since those v_j are linear independent) Sum of coefficients being 1
(v_j being dependent cases can be derived from this)

#

The special case being three dimensional space and plane case

#

5p-2q+6r-9s you will notice negation of one coefficient is the sum of other three coefficients

#

Second part same idea, xp+(1-x)r=yq+(1-y)s

midnight plankBOT
#

@near geyser Has your question been resolved?

near geyser
#

Tq so much cog

midnight plankBOT
#

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