#help-49

1 messages · Page 267 of 1

twilit jetty
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yep

lusty python
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which solves for $m = -1$ and $n = 1$

grand pondBOT
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1 divided by 0 equals Infinity

twilit jetty
#

yep, thats the only solution

lusty python
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ty

twilit jetty
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nice

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midnight plankBOT
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midnight plankBOT
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gusty sky
#

How is infinity one of the answers ?

midnight plankBOT
wooden badger
#

wht is the ques?

compact copper
#

Looks odd

gusty sky
compact copper
gusty sky
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Took 2 days to reach here 😭

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So does anyone have any idea why infinity is one of the solutions

compact copper
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I mean

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that implies the slope is 90 degrees

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or the angle is

gusty sky
compact copper
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Sorcery✨

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Nah but seriously

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They aren't technically WRONG

gusty sky
compact copper
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like put m2 = infinity in the first equation after (2) and it makes somewhat sense

wooden badger
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it reduces the degree of the equation

gusty sky
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then, If a quadratic equation gets reduced to a linear one then infinity is one of the solutions?

wooden badger
gusty sky
hard umbra
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it's abuse of notation

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if instead you consider the equation ax + by - 5/2 b = 0 for the line

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you end up with the following equation for a and b

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,w (a + 3b - 5/2 b)^2/(a^2 + b^2) = 1

hard umbra
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in such a case, you arrive at the lines x = 0 and 3x + 4y - 10 = 0

wooden badger
hard umbra
#

i mean it is just abuse of notation and when interpreted literally is utter nonsense

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one shouldn't set up the equation like that because a vertical line has no representation as y - 5/2 = mx

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to set up the line equation that is agnostic to whether it's vertical, you should just use a form like ax + by + c = 0 where there is no problem

midnight plankBOT
#

@gusty sky Has your question been resolved?

midnight plankBOT
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somber saffron
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just gave my maths exam

midnight plankBOT
somber saffron
#

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compact copper
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.Hope you did well though

pearl hull
lyric charm
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inland patio
#

In my book there's the following problem:\

Suppose that we have $n$ boxes numbered $1,\ldots, n$, and that the $i$th box contains $r_i$ red balls and $n_i$ black boxes, where $r_i,n_i\geq 1$. Imagine that one chooses a box uniformly at random, and then picks a ball (again at random) in the chosen box. Compute the probability that the $i$th box was chosen knowing that a red box was picked.\

Is there a typo in the last sentence? First the author speaks about red balls, then about red boxes. How do I approach this?

grand pondBOT
runic hamlet
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yes likely a typo

inland patio
runic hamlet
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red balls

inland patio
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floral ruin
midnight plankBOT
floral ruin
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How should I start in this question?

lyric charm
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simplify the Re(trig bs)

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maybe writing c and s for cos(θ) and sin(θ) could save you some effort

floral ruin
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sure lemme give it a try

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should I rationalize?

slow thorn
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yes

floral ruin
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alright

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$Re(\frac{2\cos^2{\theta} + 7\iota \sin{\theta}\cos{\theta} -3\sin^2{\theta}}{9\sin^2{\theta} + \cos^2{\theta}})$

grand pondBOT
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Prathmesh

floral ruin
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this is what I got

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on rationalizing

slow thorn
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awesome

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find the real part now

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the one without i

floral ruin
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(2c^2 - 3s^2)/9s^2 +c^2

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this?

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is this right?

slow thorn
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yeah

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assuming the equal was a +

floral ruin
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ohh

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yea

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thanks

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in this question should I first use that property that z + z' = 2Re(z) and then put z = x+iy or is there any better and short way of solving this ?

slow thorn
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if would simplify to $Re\left(\frac{z-1}{2z+i}\right) = 1$

grand pondBOT
slow thorn
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and then i guess nothing to do other than z = x+iy

floral ruin
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yea

midnight plankBOT
#

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pallid granite
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Can i get a hint about the following integral

grim vector
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2 = 1 +1

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Complete the square and consider arctan

pallid granite
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I did complete the square but what i do with the x in the numerator

umbral timber
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P and Q are real numbers

grim vector
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x/((x+1)² + 1) = (x+1 - 1)/((x+1)² +1) no ? And then you separate and proceed with u = x+1 for the first integral

umbral timber
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then you can separate into two integrals. one of them can be solved via a u-sub and the other by trigonometric sub

pallid granite
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Aaa ok thx

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cerulean temple
#

how to find residue of $\frac{1}{(x^2+1)^3} $ at $e^{i\frac{\pi}{2}}$

grand pondBOT
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Slowaq

cerulean temple
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solving this limit seems to he hard
$$\lim _{z\to e^{i\frac{\pi}{2}}}\left((z-e^{i\frac{\pi}{2}})^3\frac{1}{(z^2+1)^3}\right)^{''}$$

grand pondBOT
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Slowaq

cerulean temple
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nvm i can factor out denominator

lethal path
cerulean temple
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ah of course thanks for pointing it out!

lethal path
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no worries!

cerulean temple
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dawn dagger
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,, (P) \begin{cases} \sum_{i=1}^4 z_i \ra \max & \ 3z_1+z_2+4z_3 &\le 1 \ z_1+2z_2+5z_4 &\le 1 \ z \ge 0 \end{cases}

grand pondBOT
dawn dagger
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can somebody spot my mistake

midnight plankBOT
#

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mint ravine
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Help please

midnight plankBOT
pure wraith
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Have you set an equation up?

mint ravine
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like with modular arithmetic?

pure wraith
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No just the equations you need to do this

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I don't think you'll need any modular arithmetic

lilac finch
mint ravine
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ok

mint ravine
pure wraith
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yep

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Do you know about stars and bars

mint ravine
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i heard of it but i forgot what it was

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let me search it up rq

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ok yeah i remember it now

pure wraith
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Do you know how to use it in this case

mint ravine
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we use the formula a=nk+b?

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and then find out n and k?

pure wraith
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Nvm wait, you can't use stars and bars

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Modular arithmetic it is

mint ravine
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oh ok

pure wraith
mint ravine
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yeah we can take mod x and mod y for both equations

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oh wait or you could just get mod x i think that'll work

pure wraith
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You're supposed to take the moduluo wrt one of the coefficients

mint ravine
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yeah i am taking the mod with the smaller coefficient to make it easier

vivid yoke
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you can get it down to 1 variable lol, you have 2 equation for 3 variables

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Plotting it into 3d graph gives a line

pure wraith
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Besides it reduces the tedious casework

vivid yoke
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Ig so

midnight plankBOT
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midnight plankBOT
sudden yacht
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Don't ping everyone

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What you can do is pinging helpers, instead

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...

fallow scarab
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Jesus christ

sudden yacht
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<@&268886789983436800>

fallow scarab
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<@&268886789983436800> idk

brittle edge
sudden yacht
summer kestrel
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Ok

lofty beacon
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<@&268886789983436800>

brittle edge
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I need help

sudden yacht
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tribal temple
midnight plankBOT
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chrome swift
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hello

midnight plankBOT
chrome swift
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this set of vectors in r3 are linearly dependent right?

dreamy lichen
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the third vector is 3*first + 2*second

small jasper
chrome swift
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then this is false

pure wraith
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It's true

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That's kind of why that set is linear dependent

chrome swift
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just tryna get this in my head

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mb

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sharp coral
chrome swift
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.reopen

midnight plankBOT
chrome swift
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does my answer here work

pure wraith
chrome swift
sharp coral
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it's not a scalar multiple of either

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it's a linear combination of the others, which would be a more generally true condition

chrome swift
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guys what about this new question if yall can kindly give feedback

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does it work

sharp coral
chrome swift
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thanks

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a set of more than 2 vectors in R^n is lin dep if at least one of the vectors can be written as a linear combination of the other vectors right?

midnight plankBOT
#

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chrome swift
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hi

midnight plankBOT
chrome swift
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so the co domain matches the number of rows matrix A has?

frank wolf
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Yes

chrome swift
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if we deal with n by n matrcies it's just always n then right

wraith dirge
chrome swift
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the co-domain is smaller than the range right

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or they the same size

hybrid crow
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lol

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range is a subset of co-domain

wraith dirge
hybrid crow
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I wouldn't use the words greater than or equal

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but

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yeah

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subset

wraith dirge
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well they used "smaller"

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same thing

hybrid crow
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yeah

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they shouldn'tve

chrome swift
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so the range is a subspace of R^m

hybrid crow
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correct

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possibly all of R^m

chrome swift
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ok

hybrid crow
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possibly just 0

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in the case of the 0 map

chrome swift
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it can be all of R^m when?

hybrid crow
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hm

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here's an example

chrome swift
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identifiy matrix right

hybrid crow
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identity matrix from R^m to R^m

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but it doesn't have to be identity

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you will learn later

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it just has to be "surjective"

chrome swift
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naw tell me

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i got my final in 2 days

hybrid crow
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idk where you are at in linear algebra

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but there is a ton of theory to develop

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regarding surjectivity

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injectivity

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and such

chrome swift
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the last thing we learned is single value decomp

hybrid crow
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as I've now realized, the order of math curriculum is far from homogenous

chrome swift
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we hit IMT, eigenvectors and markov chains

hybrid crow
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I haven't hit any of that

chrome swift
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yes imt mb

hybrid crow
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but I am quite knowledgeable in linear maps

wraith dirge
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and other equivalent conditions

chrome swift
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help me out u two ima cover all of linear algebra in 2 hours

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let's see what yall know

hybrid crow
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is your class proof-based

chrome swift
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nope

hybrid crow
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oh great

chrome swift
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a lotta shit though

hybrid crow
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than u probably can cover it all

chrome swift
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ye

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thank q guys

hybrid crow
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well idk if u need to know injectivity and surjectivity then for your test

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you tell me

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and I can explain them

chrome swift
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nope

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glad we don't

hybrid crow
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lol

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crazy work

chrome swift
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i don't think we're that theory based

hybrid crow
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ngl

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I couldn't imagine linear algebra without stuff like that

chrome swift
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wait

hybrid crow
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I guess my version of it is far different from a non-proof based course

wraith dirge
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so you've just covered matrix operations, determinants, vector spaces, inner product spaces, eigenvalues, and linear transformations?

chrome swift
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does injectivity have different phrases

hybrid crow
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one-to-one

chrome swift
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i mean not yet

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we covered all that in class, but not in my self review session

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also we covered a lot of stuff on orthogonality

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then some symettrical matrices stuff

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and markov chains (im bad at)

wraith dirge
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yeah thats typical

chrome swift
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ok good

wraith dirge
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just practice a ton of problems

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in every section you can

chrome swift
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im reviewing everything while doing problems on them

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then i'll do some practice tests

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still gonna bomb this final but i'll take a B

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so image is the specific output vector pretty much

wraith dirge
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you should be good, the only "proofs" you will do are just showing something is a vector space, or something is an inner product

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everything else is just memorizing how to solve a specific kind of problem basically

chrome swift
wraith dirge
chrome swift
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yeah pretty much

wraith dirge
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could you give an example

chrome swift
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oh

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this was my paper

wraith dirge
chrome swift
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yeah they're tricky and niche

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some of them are easy theorems, others are kinda a stretch on theorems like the 4 sub-spaces one was kinda hard (question 1)

wraith dirge
chrome swift
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yeah i lowkey gussed

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guessed

wraith dirge
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you got 3, 4, and 6 wrong

chrome swift
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naw 3 is right

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but 4 and 6 were wrong yes

wraith dirge
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oh i misread it nvm

chrome swift
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how tf did u know

wraith dirge
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some of them you can intuitively think through

chrome swift
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i see why 4 is false tho DMANNIT

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4 is false because if the vectors are linearly dependent, u can't do gram schmidt

wraith dirge
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yeah, its tricky

chrome swift
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oh P^2

wraith dirge
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it requires you to remeber the definition

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but also, this will probably just be one part of your final. since your time is limited, you should focus more on problems that you're struggling with

chrome swift
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for sure ima lock in

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linear transformations is something I need to master bbecause i don't have a good grasp on it

wraith dirge
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what textbook are you using?

chrome swift
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not as intuitive as eigenvectors

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im using my professors slides who uses the book linear algebra and it's applications 6th edition by Lay

hybrid crow
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oh lord

chrome swift
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we were given that W = m btw

chrome swift
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wow i explained that bad i edited it

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is consciousness something from our brains or a metaphysical thing

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@wraith dirge @hybrid crow

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professor said this is very powerful

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but what does this mean in words?

hybrid crow
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and is just like electrical impulses and neurons fired collectively

hybrid crow
chrome swift
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because i sent this in the wrong chat mb

hybrid crow
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this basically means every linear map is uniquely determined by its action on basis vectors

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because T is a linear map and has the properties of both additivity and homogeneity

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knowing where the basis vectors goes

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allows us to derive

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where any other vector goes

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since every vector is just a linear combination of those basis vectors

chrome swift
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naw you lost me hold on

hybrid crow
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i'ma give u an example rn

wraith dirge
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the map of any vector is a combination of the maps of the basis vectors

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geometrically, if you know where the basis vectors are mapped by T, you can figure out where any vector will be mapped

chrome swift
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ok waeit

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it's like you get the simpliest vectors e1 e2....ep right

hybrid crow
#

Suppose $v_1,...,v_n$ is a basis of $V$. Define $T \in \mathcal{L}(V,W)$ by $T(v_k) = w_k$ for each $k = 1,...,n$. Now, let $v$ be an arbitrary vector such that $v \in V$. Since $v_1,...,v_n$ is a basis, we know that $v = a_1v_1+\dots + a_nv_n$ for $a_j \in \textbf{F}$. From this, we know that $T(v) = T(a_1v_1+\dots + a_nv_n) = a_1Tv_1+\dots + a_nTv_n = a_1w_1+\dots + a_nw_n$.

grand pondBOT
#

holo_morph

hybrid crow
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Essentially, this shows that you can define a linear map T just based on its action on basis vectors

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then you can "linearly extend" it across the domain

chrome swift
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naw you lost me

hybrid crow
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to see what it does to any other vector

chrome swift
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is V a subspace?

hybrid crow
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V is an arbitrary vector space

chrome swift
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like is it R^n

wraith dirge
hybrid crow
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as is W

chrome swift
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let's say u have a mystery transformation matrix right

wraith dirge
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since the transformation map is linear, you can also represent the map of any vector as a linear combination of the maps of the basis vectors

chrome swift
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you know what the outputs are for e1 and e2

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and u wanna find the output for an arbuitrary vector in R^2

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you just do the first entry times e1 and second times e2 right

hybrid crow
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for the arbitrary vector

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express it as a linear combination of e_1 and e_2

chrome swift
#

ok

hybrid crow
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v = a_1e_1 + a_2e_2

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where the a's are scalars

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then apply the linear map/matrix to both sides of the equation

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Tv = T(a_1e_1+a_2e_2)

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now the right side can be simplified

chrome swift
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that's essentially the matrix A

hybrid crow
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using the properties of a linear map

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Tv = a_1Te_1 + a_2Te_2

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so we have expressed Tv

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as a linear combination

chrome swift
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damn ur proofs class got u messed up if u know this shit like the back of ur hand

hybrid crow
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of the images of e_1 and e_2 under the map T

chrome swift
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are u a TA or something

hybrid crow
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no I just study on my own

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not even for school ngl

chrome swift
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ok need to grind thanks tho

chrome swift
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so idc if I get a b here

hybrid crow
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I've never heard that

chrome swift
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in college not high school

hybrid crow
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do you know

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additivity and homogeneity

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for matrices/linear maps

chrome swift
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homogeneity?

hybrid crow
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well u probably do

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A(v+w) = Av + Aw

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A(a_1v) = a_1Av

chrome swift
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oh yeah

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we called that scalar

hybrid crow
#

btw Mittens

wraith dirge
hybrid crow
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that second property

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you've probably seen it used in integrals

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integral of 3x = 3 * integral of x

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typa deal

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or when differentiating

chrome swift
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integral of 3x is 3x^2/2 right

wraith dirge
hybrid crow
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yes

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which is 3 * integral of x dx

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  • C but yeah
wraith dirge
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integral of (f + g) = integral of f + integral of g

hybrid crow
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anyways what I am trying to highlight here

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is that differentiation and integration are both linear maps

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because they follow the properties

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and you can even

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represent them

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as matrices

chrome swift
#

is this a multivariable thing

hybrid crow
#

in a vector space

#

consisting of polynomials

#

for instance

hybrid crow
#

I see green's theorem typing now

cerulean oyster
#

Property of a linear transformation can be summed up as follows:

$T(a\mathbf v + b\mathbf u) = aT(\mathbf v) + bT(\mathbf u)$

grand pondBOT
cerulean oyster
#

Just to leave visual reference

chrome swift
#

thanks

cerulean oyster
#

You can see that line combines both core concepts.
And V and U are vectors

#

Always remember that vectors are in reality mostly anything

chrome swift
#

looked up green's thorem it looks like multivariable is gonna be hard

cerulean oyster
#

Functions can be vectors, etc...

wraith dirge
#

applying it isnt that complicated

cerulean oyster
#

for calc3, greens and stokes are just a tool

wraith dirge
#

the problems will be simple unless you have a bs professor

cerulean oyster
#

if youre doing real analysis tho blankstare

chrome swift
#

do electrical engineers need to do real analysis

wraith dirge
#

well kind of but not really

cerulean oyster
#

Depends on your college and country, but most engineering carreers settle with Calculus instead of Analysis

#

Luckily.

chrome swift
#

that;s it?

#

we need diff eq

cerulean oyster
#

Thats calculus too.

chrome swift
#

oh ok

#

linear algebra is harder than multi i heard is that true

wraith dirge
#

the theoretical side of electrical engineering definitely needs real analysis, but if you are working as a regular electrical engineer you dont. i would assume you will fall into the latter category

cerulean oyster
#

Most techniques sat "unproven" for a while > more like not a formal proof of them actually working

wraith dirge
chrome swift
#

i gotchu

#

no wonder drop out rate is high

wraith dirge
#

multi and differential equations involve a lot of calculus, so it will depend a lot on how well you did in calc 1-2

#

linear algebra is (mostly) unrelated

chrome swift
#

ask me a question in calc 1 and 2 real quick

wraith dirge
chrome swift
#

wdym by sqrt 2 to 2

wraith dirge
#

the limits of the integral

chrome swift
#

ohh

#

ngl i kinda forgot the techniques but looks like a trig sub question

wraith dirge
#

it is

chrome swift
#

let me see if i got it

#

naw forgot

wraith dirge
#

what grade did you get in calc 2

#

or calc bc if you took that

chrome swift
#

i failed bc but took a placement exam in my uni and passed

#

but in bc we didn't learn trig sub

wraith dirge
#

you didnt?

chrome swift
#

yeah i don't recall it

wraith dirge
#

im pretty sure thats on the exam

chrome swift
#

it wasn't

#

but for the college exam i had to take it was

wraith dirge
#

oh wait it isnt lol

#

thats weird

chrome swift
wraith dirge
chrome swift
#

naw bro this is kinda hard i'd have to re-learn it

#

but re-learning is very easy if u learned it once already

wraith dirge
#

that was just an example problem, i was just saying if you did okay in calc 1-2 you will probably do okay in multi and diffeq

chrome swift
#

that's good

wraith dirge
#

differential equations is lowkey easier than multi, a lot of it is just memorizing specific techniques

#

if you're an ee major, you probably are only required to take those 5 classes (calc 1-3, linalg, diffeq)

#

depends on the program though

chrome swift
#

yeah we do need to do all that

midnight plankBOT
#

@chrome swift Has your question been resolved?

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chrome swift
midnight plankBOT
chrome swift
#

this matrix is size 3 by 3

hybrid crow
#

it is

chrome swift
#

so it's domain is 3

#

but its co-domain is 2 tho why

junior flower
chrome swift
junior flower
#

missing some details here

chrome swift
junior flower
#

also are you sure co-domain is the word you're looking for?

chrome swift
#

should i say range

junior flower
#

that seems better yes

chrome swift
#

i think co-domain is better actually

junior flower
#

and by 2 and 3 you mean dimension 2 and dimension 3 right

chrome swift
#

yeah that's what i mean

#

R^3 and R^2

sharp coral
sharp coral
chrome swift
#

oh so it's range is R^2

junior flower
#

no

chrome swift
#

my professor said this

junior flower
#

its range is like, a subspace of R^3 that looks 2 dimensional (but still made of elements of R^3)

sharp coral
unkempt sluice
#

Ax is linear combination of columns of A with components of x being coefficients. So the range is simply the column space

chrome swift
unkempt sluice
#

Its dimension thus is the dimension of the column space, namely the rank

chrome swift
#

i gotchu thanks bro

unkempt sluice
#

Okay, Ax is this

chrome swift
#

that makes sense

#

naw it clicked

unkempt sluice
#

Okay

chrome swift
#

so it's dim(col A) which is basically rank

unkempt sluice
#

Yes

chrome swift
#

and is that for the range or co-domain

#

range right

unkempt sluice
#

range

sharp coral
#

range = column space, they are exactly the same

chrome swift
junior flower
#

the co-domain isn't something you compute

sharp coral
#

well for matrices yes

unkempt sluice
#

codomain is just what the target of the map is, can be as large as you want.

sharp coral
#

the codomain is just set of all vectors of the type the matrix spits out. so because the matrix outputs vectors in R^3, its codomain is R^3, even though it will not output every possible vector in R^3

unkempt sluice
#

When you give a map you have to give a domain and a codomain. The codomain can be anything, image is another thing. Like f: R->C; f(x)=x. Codomain is C but image(f)=R

chrome swift
#

wait we talking about complex stuff now?

sharp coral
#

domain and codomain are things that apply to all functions

unkempt sluice
#

I just gave an example saying that codomain doesn’t mean anything

chrome swift
#

so i can ignore co-domain

unkempt sluice
#

Yes

chrome swift
#

all i need to know is every output vector b is in R^m

unkempt sluice
#

It’s just the target of a mapping. You have to give it for the sake of definition

#

Doesn’t imply anything

sharp coral
chrome swift
#

why wouldn't it be in R^m

#

if the example i gave is still R^3

sharp coral
#

it's standard for the codomain to be all of R^m because then you don't have to do any calculations, it is evident purely from the matrix's size

unkempt sluice
#

Put it this way, change your linear map to this: R^3->R^100
x|->Bx, B=(your A, 3 times 97 size 0 matrix). Range is still of dimension 2, codomain is R^100, It doesn’t matter.

#

Domain and codomain is for the sake of definition. We compute range/image, codomain we leave it behind knowing there is such a thing we don’t need to think about it.

chrome swift
#

ok i guess i get it

unkempt sluice
#

(Mapping (x_1, x_2, x_3) to (x_1, x_2, 98 many 0 in the example above)

chrome swift
#

range and image are the only important things because it's the actual answers we get or outputs we get

unkempt sluice
#

Yeah

chrome swift
#

range is the output space i mean

#

where all the images live

#

or the span of all images?

unkempt sluice
#

Same thing, image of a linear map is still a linear space

chrome swift
#

question

#

does range = span { image of e1 ........ image of ek}
or is this wrong

unkempt sluice
#

It is correct

sharp coral
#

range = image

#

different words same thing

chrome swift
#

but range is bigger than image right

sharp coral
#

no?

unkempt sluice
#

Synonym

chrome swift
#

i thought image is the specific output whereas range is where all the outputs live

unkempt sluice
#

I treat range as image, it’s like in some fields, people give special names. But image is for all cases

chrome swift
#

guess im confusing myself. main take away is forget about codomain for this final

sharp coral
#

well you can say "the image of vector x under T is T(x)" but you also say "the image of T" which is the set of all images of elements of the domain, i.e. the range

sharp coral
#

just don't overthink its importance

unkempt sluice
#

Exactly. It’s just something you have to give when you define a map.

chrome swift
#

ight

#

this is also important to know right

#

v= c1e1 + c2e2

#

Tv = T(c1e1 + c2e2)

#

Tv = c1T(e1) + c2T(e2)

hybrid crow
#

i'm proud of you mittens

chrome swift
#

naw thank you @hybrid crow LOL

sharp coral
#

as long as the domain of T is 2-dimensional, sure

hybrid crow
chrome swift
hybrid crow
#

yes

sharp coral
#

although the math doesn't change much for higher dimensions other than making the linear combination longer

hybrid crow
#

image can also be used for an individual vector

#

namely, the image of v under T is Tv

chrome swift
unkempt sluice
#

Exactly the same thing. Synonym, literally no difference in my mind, range and image.

unkempt sluice
#

Your case domain is R^3, codomain is R^3, image is isomorphic to R^2, kernel is isomorphic to R

#

My case domain is R^3, codomain is R^100, image is still isomorphic to R^2, kernel is still isomorphic to R

chrome swift
#

ok

sharp coral
#

i would describe the image as being a 2-dimensional subspace of R^3

#

same thing but i'm not sure isomorphism has been introduced yet

hybrid crow
#

yeah I don't think mittens knows that

chrome swift
#

never heard of that

hybrid crow
#

image is a 2d subspace of R^3

unkempt sluice
#

Anyway, we think now you get the idea that codomain is not important.

hybrid crow
chrome swift
#

so image's subspace is the R^Rank A

sharp coral
#

rank = dimension of image

#

the image is always a (rank)-dimensional subspace of (codomain)

chrome swift
#

so image is related to column space?

sharp coral
#

image = range = column space

unkempt sluice
#

You construct any linear map from R^3 to R^a million, rank, which is the dimension of image, will still be <=3. Codomain can be as large as you like.

#

Same thing

sharp coral
#

all three are exactly the same subspace

chrome swift
#

what about null space

sharp coral
#

null space = kernel

chrome swift
#

?

#

that's for popcorn gang

sharp coral
#

don't worry about it then

#

but kernel is always a (nullity) - dimensional subspace of (domain)

chrome swift
#

never heard of kernel in my life. when do i need to

hybrid crow
chrome swift
#

like what math is that

sharp coral
#

for m x n matrix domain is R^n and codomain is always R^m

hybrid crow
#

kernel is linear algebra

#

it truly is another name for null space

sharp coral
chrome swift
#

ok good that's why we don;t know it

unkempt sluice
#

Linear algebra itself is just a special case of algebra, like linear spaces, just modules over PID. I think reading algebra first can completely cover linear algebra. The latter seems abundant.

hybrid crow
#

indeed

chrome swift
#

explain single value decomposition in terms of linear transformations

#

didn't learn SVD yet but i need to later

unkempt sluice
#

That involves a decomposition, A=UDU^H

#

For any complex square matrix A, there exists a hermitian matrix U and a upper triangular matrix D such that A=UDU^H

chrome swift
#

why is x in R^m not in R^n

unkempt sluice
#

You can prove this by induction. This will be a lemma in SVD. You need to know this decomposition first

sharp coral
chrome swift
chrome swift
unkempt sluice
#

Oh he said it

chrome swift
#

is it a coincidence that the columns are derivatives

#

for context*

unkempt sluice
# chrome swift isn't it just a rotation, an axis dilation, and a reflection

You will need to use this decomposition to prove existence of SVD, I believe it’s called Schur decomposition or something: A^H A=VDV^H, for hermitian matrix V and diagonal matrix with non-positive real entries D. Thus D=Λ^2 , taking square root of entries. Let U=AVΛ^-1, clearly U is hermitian, thus A=UΛV^H, the SVD you wanted

unkempt sluice
unkempt sluice
#

You wanted to know SVD then you need to know those definitions and the Schur decomposition first

#

It involves those

#

When A is real, U and V can be orthogonal matrix instead of hermitian matrix. Parallel proof in real case. That’s why you said rotation and stretch. U and V will represent rotation, Λ will be the stretch

chrome swift
#

we only know about the orthogonal matrix part

unkempt sluice
#

U and V will represent rotation or rotation and reflection I mean, depending on the determinant of U and V being 1 or -1

chrome swift
#

so we find eigen vectors of A^TA

unkempt sluice
#

Yes, which let you obtain D

chrome swift
#

ngl i need to lock tf in rn this is a lot of stuff

#

tryna do a whole semester in a day is a bad idea

unkempt sluice
#

A^T A=VDV^T, you need to keep this V btw, since you will define U=AVΛ^-1. So don’t throw away V when you got D

#

It’s a good idea I think. Your thoughts will be continuous right, no interruption by taking breaks

chrome swift
#

shoot taking one right now is that bad

unkempt sluice
#

I think you already got what you needed. A symmetric real (Hermitian complex) matrix B equals UDU^T (UDU^H) for orthogonal real (hermitian complex) U and diagonal non-positive real matrix D is a special case of this Schur decomposition. So you already know it. It just when B is regular (BB^H=B^H B, when B is real it becomes BB^T=B^T B), D, the upper triangular matrix, by calculation has to be diagonal.

#

You don’t need the general Schur decomposition if you want to skip it for now. It seems you already know the special cases so good to go. I didn’t use the general case in my proof.

chrome swift
#

naw we didn't dive into the depths

#

u sure did

#

we learned one way to calculate it

#

it's with orthogonal matrices

unkempt sluice
#

I prefer to read the general cases first, then take a glimpse at the special cases and say, oh I knew it already, skip.

#

By a row of skipping, linear algebra is done. The reading part appears in algebra, my case.

chrome swift
#

ok

#

i only stop for the weird stuff or important stuff

unkempt sluice
#

Many cases like this, like Jordan form is a special case of Jacobson form. Depending on what you need. If your interest is not math but something else, chemistry, engineering… it’s perfectly fine to know the usual linear algebra version. General forms won’t be used at all.

chrome swift
#

yeah im an engineer

unkempt sluice
#

Then your way is more efficient. You are doing well.

midnight plankBOT
#

@chrome swift Has your question been resolved?

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midnight plankBOT
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twilit field
midnight plankBOT
twilit field
#

Just to clarify

unkempt sluice
#

What is i’, U’, V’? And what is U^0, what is i’ tilde?

#

Okay what is i’ tilde?

twilit field
unkempt sluice
#

tilde thing and U^0 definitions please

twilit field
#

U^0 is the annhilator of U

unkempt sluice
#

What do you mean annihilator of U?

twilit field
#

one min

unkempt sluice
#

c) comes from a) and b), as i’ tilde: V’/ker(i’) \cong im(i’). By a) ker(i’)=U^0, by b) im(i’)=U’. Thus we only need to show a) and b):
a) directly comes from definition.
b) you simply need to show that any linear f: U->F can be extended to V->F, i.e. there exists g:V->F such that g|U=f. And you can use Zorn’s lemma to show this

twilit field
#

Why do I need zorn's lemma for a fin dim case

unkempt sluice
#

Consider the set of (W, g), where U<=W<=V, and g:W->F such that g|U=f. This set is not empty since (U,f) belongs to it. Any chain has upper bound: a chain of some (W_j, g_j), you let W=union of all W_j, and g(x)=g_j(x) if x is in W_j. Done

twilit field
#

no, no

#

Why do I even needs zorn's lemma

unkempt sluice
#

It’s just how I would do it

#

You want to avoid it?

twilit field
#

I mean it's not necessary is it

unkempt sluice
#

Okay I guess we can. No zorn, induction on dim(V)-dim(U)

twilit field
#

Lemme send my proofs?

unkempt sluice
#

Sure

twilit field
#

I'll start with (a)

unkempt sluice
#

f: U->F choose a v in V not in U, and expand f to U’=U+Fv ->F mapping v to zero, dim(V)-dim(U’)=dim(V)-dim(U)-1, thus b) holds by induction on dim(V)-dim(U). Done, no Zorn

twilit field
#

for (c).Can't I just use the 1st iso theorm

unkempt sluice
#

(Actually on second thought, you can just take W to be the direct summand complement of U in V, i.e. V=U \oplus W, then f can extend to V simply by mapping W to 0)

unkempt sluice
twilit field
#

cool

#

thanks

unkempt sluice
#

Anyway, direct sum or induction on dim(V)-dim(U), both work for b). Though latter requires this finite dimension

twilit field
#

(b) can probably be done by double inclusion too

unkempt sluice
#

Whatever works

twilit field
#

tq

#

I

#

I

#

I

#

I'll close this now

unkempt sluice
#

Sure

twilit field
#

.close

midnight plankBOT
#
Channel closed

Closed by @twilit field

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midnight plankBOT
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humble bronze
#

G is a finite abelian group and a positive integer n is prime to o(G) . Prove that every element $ x \in G $ has an nth root in G.

humble bronze
#

How do I solve this

unkempt sluice
#

I thought i have answered it

#

uo(G)+vn=1, a=(a^v)^n

humble bronze
#

Ohh thank you again

#

Can you check this

unkempt sluice
#

Good

humble bronze
#

.close

midnight plankBOT
#
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midnight plankBOT
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waxen shoal
#

how would we graph this on paper if we wanted to

waxen shoal
#

$$ f(x,y) = (x^2 - 1)(y^2-1) $$

grand pondBOT
midnight plankBOT
#

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tacit vortex
#

I want to ask for the green part, which one is correct.. or both are accepted

tacit vortex
#

Karnaugh, logic gates

grim vector
#

Both are correct, also should be accepted i think

#

Wait in the draw you need to add a not

#

And change D by B

shut cargo
#

3rd times the charm

tacit vortex
#

Oh right, i miss that one. Thanks 👍

#

.close

midnight plankBOT
#
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midnight plankBOT
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wispy mortar
#

yo

midnight plankBOT
wispy mortar
#

@twilit field what happened, u were typing angerysad

twilit field
#

Like if G is of order 2

#

all H will be a subgroup

#

If |H|>2, consider {e,x} where x is an element of some order less than the order of the group abnd x isn't its own inverse

junior flower
#

but what if G isn’t order 2

twilit field
bold peak
#

Order of the element x?

wispy mortar
#

1 or even

flat spire
wispy mortar
junior flower
#

his ritual is FeelsMeowTastyBusiness

wispy mortar
bold peak
#

You want elements of even order that multiply to an element of odd order hmm

junior flower
#

all subgroups will be abelian

bold peak
#

I'm thinking of the S_n groups

#

Oh S_3 just straight up works lmao

hard umbra
#

i think those aren't abelian

junior flower
bold peak
#

Oh shit

#

Got too excited

hard umbra
#

i think you should Z/6

bold peak
#

Huh idt that works

junior flower
hard umbra
bold peak
junior flower
#

snow is so smart

bold peak
#

Who is snow

flat spire
#

snow is @silent dock

bold peak
#

I mean, looking at their roles, they're definitely a prodigy KEK

unkempt sluice
#

I don’t get the question. H seems to always be a subgroup

bold peak
#

Z_6 is a counter example I believe

wispy mortar
#

works cathandshake

#

thanks a lot u guys cathandshake

hard umbra
#

bluds never heard of snow pensibthis

unkempt sluice
#

But H={0,3}, isn’t it a subgroup?

bold peak
#

But 2 has order 3

unkempt sluice
#

oh {0,1,3,5}

#

I see

hard umbra
#

mfw 6 is even but has an odd factor

bold peak
#

Same thought process behind me jumping to S_3

#

Just forgot the abelian requirement

hard umbra
#

abelian't

wispy mortar
#

i will close this now

#

thanks a lot kannawave

#

.close

midnight plankBOT
#
Channel closed

Closed by @wispy mortar

Use .reopen if this was a mistake.

flat spire
#

thanks for helping snow

#

junior flower
midnight plankBOT
#
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rapid yew
#

Can someone pls help with these I'm so stuck

midnight plankBOT
umbral timber
#

and are you allowed to use graphing tools or do you have to sketch this by hand

rapid yew
#

I have these facts also

umbral timber
umbral timber
rapid yew
#

Oh ok

#

is there like a specific relationship between them or can it be anything

umbral timber
rapid yew
#

I don't know how precise it wants it but that looks like what I have on my graphing calc 😞

#

maybe the ends matter

#

the sketching thing is really bad so I can't really get a levelling line

midnight plankBOT
#

@rapid yew Has your question been resolved?

rapid yew
#

no

midnight plankBOT
#
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#
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lusty python
#

Can anyone give me a brief explanation of the chain rule? And I have an example question right here: find the derivative of $2^x$

grand pondBOT
#

1 divided by 0 equals Infinity

dreamy lichen
#

do you wanna know why chain rule works or how to apply it?

lusty python
#

so far im just trying to learning derivatives by myself

#

and i proved some stuffs through the definition

late rover
#

Aren't you 9th grade?

lusty python
late rover
#

Have you learnt limit?

lusty python
dreamy lichen
#

Have u checked khanacademy & 3b1b? khanacademy shows how to apply it and the proof through definition, 3b1b offers great intuition

gaunt imp
late rover
lusty python
gaunt imp
#

If I were you, well, I'd first make sure I know everything before it, that is, the basics, like the palm of my hand

dreamy lichen
late rover
#

Okay lol, just watchi 3b1b videos

gaunt imp
#

And then look for a somewhat gentle introductory text with proofs

lusty python
#

$f'(x) = \frac{dy}{dx} f(x) = \lim_{h \to 0} \frac{f(x + h) - f(x)}{h}$

grand pondBOT
#

1 divided by 0 equals Infinity

lusty python
#

not really scary for me but at least it can scare some secondaries

dreamy lichen
#

there are simpler ways to scare ur classmates than learning calculus lol

late rover
#

Pull out some IMO geometry problem, it can even scare a 12th grader

gaunt imp
lusty python
#

these kiddos in my class only finished through quad formula and intersections between $y = mx + b$ and $y = ax^2$

grand pondBOT
#

1 divided by 0 equals Infinity

dreamy lichen
#

sounds normal

lusty python
gaunt imp
#

One thing you should keep in mind, not by learning faster are you learning better

lusty python
#

like, learning by rote is just a worse way to kill yourself

gaunt imp
#

If you want my opinion, you'd get more benefit out of making sure you've got what you should know covered, and maybe proving some results you've seen in class or playing a bit around with them

lusty python
forest iron
#

Yea

dreamy lichen
#

No, they force u to take one

lusty python
#

im cooked

gaunt imp
#

Jumping straight to learning calculus will, most likely, force you to learn by rote as you're saying, do keep that in mind

late rover
#

You're Vietnamese, right?

lusty python
#

get a triangle ABC, and get 3 median lines of each side in ABC, get the interesection point of it. and the distance between A, B, C with the intersection is always = 2/3 vertex line

lusty python
late rover
#

I do know what vietnamse ( the language )looks like

lusty python
#

the only thing is that i don't think if you see i use the language before

late rover
#

I have a friend, he always complaint that 9th grade geometry is crazy diffucult there

#

So you probably should get better at those first

lusty python
#

my bad

dreamy lichen
#

Idk at what level you're rn, but maybe to test ur understanding of algebra and trig, try taking the unit test here. If you pass it without any issue, you should be more or less ready to learn calculus. That said, there is probably still a ton of simpler topics to be learnt in more depth.
https://www.khanacademy.org/math/precalculus

forest iron
#

Calc isnt hard

lusty python
forest iron
#

If a 14 year old can learn it by himself then why cant you

visual elk
#

1/0 is NOT infinity

gaunt imp
#

A type of annoyance I believe people should deal with in due time

late rover
#

Tbh, you should only learn calcs only if you confident with your work at school

#

And you have time

late rover
#

You're studying for exam mostly

dreamy lichen
# lyric charm what 14yo

Someone green does real anal at 14, so i guess there'll be quite a few 14yo's doing calc in here

forest iron
forest iron
gaunt imp
lyric charm
#

oh yeah ok because expecting yourself to be the model for all ppl your age worldwide is such a reasonable thing to think

gaunt imp
#

I'm starting to get the feeling the guy came here with some strange intention to flex

late rover
#

Hey, if you love hard problems, try probability and combinatorics instead

dreamy lichen
#

@lusty python any questions left?

lusty python
#

kek

#

.close

midnight plankBOT
#
Channel closed

Closed by @lusty python

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lusty python
grand pondBOT
#

Result:

Infinity
lusty python
#

i let you say it again

visual elk
#

1/0 is NOT infinity

eternal pawn
#

Checkmate

midnight plankBOT
#
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visual elk
#

,w 1/0

midnight plankBOT
visual elk
#

Look

dreamy lichen
#

i forgor the factord

eternal pawn
#

da2a i think

dreamy lichen
#

!da2a

midnight plankBOT
#

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question!

visual elk
#

.close

midnight plankBOT
#
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visual elk
#

I accidentally opened bro

round skiff
#

dang

#

🫩🫩

serene coral
#

then do .close

visual elk
#

I already did

midnight plankBOT
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gilded oasis
#

HI

midnight plankBOT
lyric charm
#

hello and welcome to the server

#

you have just claimed a help channel

#

do you have a math question to ask?

gilded oasis
#

NO

lyric charm
gilded oasis
#

ok

fallow scarab
midnight plankBOT
# gilded oasis ok

If you are done with this channel, please mark your problem as solved by typing .close

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ocean hare
#

lim x to a of ((ln(x)-ln(a))/(x-a))

The answer is 1/a but I don't understand my profs justification. This is the justification:

ln(x)=y
y'=1/x
y'(a)=1/a

I'm confused what this means since we haven't solved problems like this before

sudden yacht
#

They've just recognized the limit definition of the derivative

#

And consequently used the fact that the derivative of lnx is 1/x

fallow scarab
#

A bit circular I suppose

sudden yacht
#

Yeah true but I can only think of this

#

At least from how it's written

midnight plankBOT
#

@ocean hare Has your question been resolved?

midnight plankBOT
#
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calm hazel
#

if you had f(x)=1 if x has more 1's than 0's in its digits and f(x)=0 if x has more 0's than 1's in its digits, or 0.5 if the amount is equal, would f(x) be defined for irrationals?

hard shard
#

,calc 1/99

grand pondBOT
#

Result:

0.01010101010101
hard shard
#

how would f(x) be defined here?

#

thats a 01 repeating

calm hazel
#

true

mystic condor
#

oh my god stop changing the message lol

calm hazel
#

sorry

fathom onyx
#

You'd need to define what f's domain is

hard shard
#

ok consider

#

,w 11/999

hard shard
#

are they equal or are there more 1s?

#

both are infinite

mystic condor
#

thats a rational number tho

calm hazel
#

yeah i forgot rational numbers can also have infinite digits

fathom onyx
#

Sure, but you can't explore irrationals here without having this checked first

hard shard
#

ok fine

#

0.01 011 0111 01111...

fathom onyx
calm hazel
calm hazel
fathom onyx
#

See 10-adic numbers

calm hazel
#

I shall

#

.close

midnight plankBOT
#
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midnight plankBOT
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chrome swift
midnight plankBOT
chrome swift
#

is there a sort of algorithm here

#

for finding U

grim vector
#

Row reduction

#

I think we say that A ~ U

sharp coral
#

to find U in an LU decomposition, you perform gaussian elimination but only the adding rows to other rows part, not any other row operations

chrome swift
#

i gotchu

#

i learned the theory i think it makes sense

#

you put A in echelon form without row swapping, and you construct u as the inverse of every row operation

midnight plankBOT
#

@chrome swift Has your question been resolved?

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chrome swift
midnight plankBOT
chrome swift
#

why is that bad?