help-49

[glad cypress]

💀

[pastel sentinel]

oh

lmfao

better learn quick

[glad cypress]

😭

im warm

i know that

ive done most the steps

im just missing something

the mf didnt think i could do it 💀😭

[pastel sentinel]

prove them wrong!! let that be ur motivation
along w that thing ur supposed to get

[glad cypress]

💀

i jst care about the item

this is what i get for talking to asians 😭

traversal 🥀

i cant even get the name right

im doomed

[pastel sentinel]

lock in

[glad cypress]

yo

im within 500 range

IM LOCKIN IN

[pastel sentinel]

omg????

thats amazing dude

[glad cypress]

the working bro 😭

based on this my 12th term still lands on 344, 999 divided by 12 is 83 rounded. 83*344=28,552<— our 99-83=16. The 16th cycle is 463.

it seems

wrong though.

[pastel sentinel]

🤷
if u can
round at the end so ur numbers are more accurate
if u round too much, ur numbers will like offset more

[glad cypress]

ye i get 83.25

i round to 83

hm

ye nah

makes 100 difference

er

wait

WAIT

youre onto smth

i fucked smth up

YOOO

[slate ferry]

😭 what the fuck is this sequence? good luck

[glad cypress]

NOOOO

U CANT ABANDON ME TOO

LMAO

[slate ferry]

I'm def not the one to ask for... whatever this is

[glad cypress]

ping an expert

💀

[slate ferry]

you can ping helpers if its been more than 15 minutes

[glad cypress]

idk who

name someone whos good at sequences 😭

[slate ferry]

no, i mean the helpers role

[glad cypress]

<@&286206848099549185>

that?

[slate ferry]

yes..

now you wait

[glad cypress]

i doubt its too hard

some guy with no degree has been able to help me get the answer 500 above

💀

[glad cypress]

i realize

he technically

leaked the answer.

[pastel sentinel]

bro...?

😭😭

[glad cypress]

u can assume

numbers

until u get the answer

I NEEVER PLAY BY THE RULES ANYWAYS

let me go do

major act yapping yippe im so surprised got the answer

💀

[glad cypress]

i know its not above 30k

i know its within >500

[pastel sentinel]

yeah

[glad cypress]

the answer cannot be less

thus greater than 29k

[glad cypress]

nvm i tthink

im just forgetting to

respect the sequence

@pastel sentinel omg

look

2+19=21
21+29=50
50+23=73
73+48=121
121+10=131
131+44=175
175+17=192
192+5=197
197+57=254
254+73=327
327+17=344
STOPS HERE AND REPEAT BACK SKIP 2 and START WITH 19
344+19=363
363+29=392

[pastel sentinel]

u got it???

[glad cypress]

read the steps

i figured out the sequence

[pastel sentinel]

omg!!!

ohhh i see

[glad cypress]

solved within uhh

5 hours including a 2 hour food trip

💀

[pastel sentinel]

jesus 😭😭
did ya get it right at least

[glad cypress]

no lemm check

im tired af

i woke up at 5 am

[pastel sentinel]

dont celebrate yet 💔

[glad cypress]

i did this so many times hhahah

im on the right path

[pastel sentinel]

yeah!!

[glad cypress]

he confirmed that

lemm try for an answer now

and then im out this server 💀

[pastel sentinel]

lmaoo

[rough fox]

wtf is this question

[glad cypress]

sequence

if u can help lmk

[rough fox]

the pattern doesn't repeat itself

[glad cypress]

everyone runs off 5 seconds later

[rough fox]

start at 2, end at 17

[glad cypress]

it does

i figured it out after hours

[glad cypress]

sad bit is

bro called it simple

😭

im still struggling

[pastel sentinel]

he prob just said that

once u get it, it might make more sense

[glad cypress]

im getting 30036

ee

[pastel sentinel]

nooo what 😭😭😭

ur so close in the range too like

[rough fox]

what's the pattern here even 💀

as far as I can tell this is a troll question

197 -> 254 is ambiguous

It can be either 29 + 19 + 2 + 7 or 17 + 37 + 3

[midnight plank]

@glad cypress Has your question been resolved?

[glad cypress]

dont think so

[glad cypress]

i realize

i can possibly make a formula

because

it repeats every 12 values.

[rough fox]

it clearly is

[pastel sentinel]

lowk wouldn't be surprised..

[glad cypress]

i think i solved it wait

[glad cypress]

look it repeats every 12 values

11 sequences anyways oops

[glad cypress]

might be

ngl

[rough fox]

wait i found how they generated the numbers

int decide_next_number() {
    int steps = (std::rand() % 4) + 1;
    int sum = cur_node->value;
    for (int i = 0; i < steps; ++i) {
        Node* next_node = cur_node->get_random_neighbour();
        cur_node = next_node;
        sum += cur_node->value;
    }
    return sum;
}```

[glad cypress]

so

its possible?

hmm

@rough fox ye or na

i jst need an answer 😭

[rough fox]

read what I wrote

[glad cypress]

o

💀

mb im sleepy

[midnight plank]

@glad cypress Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[half idol]

I applied to checking z_2

z_3

It gives a and d

Z5

Z_7

Z_11

[runic hamlet]

kinda overthinking

you know how these polynomials factor in C

[midnight plank]

@half idol Has your question been resolved?

[half idol]

Yeah?

x^2+1=(x+i)(x-i)

x^2+2=(x+√2i)(x-√2i)

rest like that

[sick fossil]

so if it had factors in Z[x], then by unique factorization those factors would be associate to the factors in C[x]

and you can get a contradiction

alternatively, you can use the Factor Theorem for all of these questions

[half idol]

What do you mean?

I don't get clear vision

I have not learnt the theorems properly that is why i am trying such examples so that i understand how theorems tells

[sick fossil]

do you know what the factor theorem states?

[half idol]

I don't know which theorem you assign

[sick fossil]

oh

well, x^2 + 1 has no root in Z, so it has no linear factor in Z[x], so it must be irreducible in Z[x]

[midnight plank]

@half idol Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[small jasper]

,w 7^(1-x)-4^(3x+1), x=\frac{log_7 (4)-1}{-1-3 \log_7 (4)}

[grand pond]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by civil_service_pigeon

[small jasper]

who said that it's wrong

[jaunty ivy]

looks correct to me as well

[small jasper]

you have two people and a calculator who think it's fine

[ashen jasper]

did you accidentally typoed the equation in symbolab?

I know symbolab is a bit funky with the input sometimes.

[midnight plank]

Channel closed

Closed by @west junco

Use .reopen if this was a mistake.

[small jasper]

why does everyone use everything but wolfram alpha (genuine question)

[ashen jasper]

no problem.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[flat geyser]

idk what to do for this

[burnt wraith]

Alright, what have you tried?

@flat geyser

[burnt wraith]

The third line is incorrect

@flat geyser Are you still here with me?

[flat geyser]

third line?

Un = Uo?

[flat geyser]

ahhhhh

so how do i solve it after that

[burnt wraith]

So you get U_0 = 50 right?

[burnt wraith]

you replace U_n with U_0 in this equation to get U_1

after you get U_1, you do the same to get U_2

[flat geyser]

so like

Un+1 IS Uo+1

U1 is what value

[burnt wraith]

you plug 50 into the formula to find out

[burnt wraith]

here

[flat geyser]

ah so like

(0.4x50) + 10 = 30?

is 30 the answer>#

[violet oar]

yep

[flat geyser]

hell yeah

[burnt wraith]

no

[violet oar]

you get u1

[flat geyser]

oh

[burnt wraith]

You're looking for U2

yeah

[flat geyser]

oh like

so i do the same for U2

[burnt wraith]

just do it again

yes

[violet oar]

you get u1 by putting u0 and then you get u2 by putting u1

[flat geyser]

so the answer is 22?

[violet oar]

ye

[flat geyser]

(0.4 x 30) + 10 = 22

okay great

[burnt wraith]

anything else?

Alright, if you're done with the question, please type .close to close the channel @flat geyser

[flat geyser]

nah thats all

thank you man

appreciate you 🙏

.close

[midnight plank]

Channel closed

Closed by @flat geyser

Use .reopen if this was a mistake.

[burnt wraith]

no worries

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fallow scarab]

oooh fun problem

[twilit field]

It looks very similar to bernouilli

(As mikkel pointed out in #「helpers-lounge」 )

[twilit field]

Any hints?

[fallow scarab]

Calculate P(Y=1) and P(Y=0)

[twilit field]

I'm just really confused.. DO you think it's worth coming back to this when I;n fresher?

(like is this problem worth self solving)?

[spiral rock]

If you have the time for it, yes

most problems are worth solving

[twilit field]

Like my midsem for probability is only on 11th Oct

,w how many days to 11th october

[grand pond]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by math_rocks

[twilit field]

A little under 3 weeks

[twilit field]

I suppose I do

Thanks!

.close

[midnight plank]

Channel closed

Closed by @twilit field

Use .reopen if this was a mistake.

[lusty furnace]

Hint: Dirac

oh you solved it

why is the channel still open then

[lusty python]

it'll close in a moment

[bold peak]

How channels close is a mystery known to no one

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cinder bay]

help

[cinder bay]

can someone tell me how to find them

[bold peak]

Well what have you tried

[cinder bay]

i think y = 80 because there is 100* there so 100-180 is 80

[bold peak]

Good

[cinder bay]

is it right

?

[bold peak]

Yes

[cinder bay]

and a = 75

what is x

idk that

[bold peak]

Let's find z first

[cinder bay]

ok

z = 80

[bold peak]

Good

Now can you find x

[cinder bay]

no

[bold peak]

What's the sum of angles in a triangle

[cinder bay]

oh 180

[bold peak]

Good

[cinder bay]

75

[bold peak]

Good

[cinder bay]

yes thanks

🫡

.close

[midnight plank]

Channel closed

Closed by @cinder bay

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tired sonnet]

probably really stupid, but i just learned today. i need help with (d) onwards

[verbal tiger]

looking at (d), do you know how we write y = g(x)?

[tired sonnet]

not really

[verbal tiger]

oh ok

so have you seen something like

x^2 + 2x + 3 = 0

[tired sonnet]

yes

[verbal tiger]

have you seen that before?

what does that represent

do you know?

[tired sonnet]

Uh

quadratic equation

is it like the u and the n

[verbal tiger]

im not asking you to solve it!

[verbal tiger]

do you know what it represents graphically?

on a graph?

[tired sonnet]

is it where it intersepts the x axis

[verbal tiger]

exactly!

[tired sonnet]

okay

[verbal tiger]

the x axis is at y=0

do you agree?

[tired sonnet]

yes

[verbal tiger]

so x^2 + 2x + 3 = 0 means "when is the y coordinate of x^2 + 2x + 3 equal to 0"!

do you agree with that?

[tired sonnet]

yes

wait

[verbal tiger]

mhm?

[tired sonnet]

isnt the 3 where it crosses the y

axis

[verbal tiger]

yes thats when it crosses the y axis

but when you set the graph equal to 0 and solve it

x^2 + 2x + 3 = 0

thats when x^2 + 2x + 3 crosses the x axis

and the x axis is when the y coordinate is 0

i.e. y=0

[tired sonnet]

yes

[verbal tiger]

is that making sense or?

[tired sonnet]

partially

[verbal tiger]

lmk which part isnt

and i can explain it

[tired sonnet]

this

[verbal tiger]

x^2 + 2x + 3 is the graph (just an example i made up)

[tired sonnet]

ok

[verbal tiger]

SORRY this is a terrible example it doesnt even cross the y axis 😭

change that to x^2 + 2x - 3

so x^2 + 2x - 3 is a graph i made up just for an example

we write y=x^2 + 2x - 3

agreed?

[tired sonnet]

why

why is y=x^2+2x-3

[verbal tiger]

y = means "the y coordinate is equal to"

and the rest of the equation is x^2 + 2x - 3

actually lets go simpler

[tired sonnet]

ok

[verbal tiger]

are you comfortable with linear equations?

[tired sonnet]

ye

[verbal tiger]

y=2x+1

etc etc

[tired sonnet]

yes

[verbal tiger]

so if i said

"find the y coordinate at x=5"

what would you do?

[tired sonnet]

im lost bro deadass

is it 0

[verbal tiger]

hmm not quite

okay lets start from fundamentals

[tired sonnet]

wait is it 5

nvm

[verbal tiger]

not quite

this is a cartesian plane

agreed?

[tired sonnet]

yes

[verbal tiger]

so if i say y = 2x+1

[tired sonnet]

yes

[verbal tiger]

can you graph that?

[tired sonnet]

no

sorry i havent done graphing ever and i start with quadratic stuff

[verbal tiger]

have you not done linear equations yet?

[tired sonnet]

yes just to find the variables though

[verbal tiger]

thats interesting because

graphing is a very big part of this

i mean atm i dont have too much time but

[verbal tiger]

g(x) > 0 just means "when is g(x) above the x axis"

can you see that?

[tired sonnet]

yes

cuz its greater than 0

[verbal tiger]

exactly

very similar to g(x) = 0

"when does g(x) cross the x axis"

g(x) > 0 means when is g(x) above the x axis

[tired sonnet]

ah

[verbal tiger]

now on the right, the blue graph is g(x)

can you tell me when g(x) is above the x axis?

[tired sonnet]

when its greater than approximately 0.6 and -1.7

[verbal tiger]

now you wanna write that in fancy maths language

we agree that g(x) is above the x axis when x is between -1.7 and 0.6

so we're saying x > -1.7, x < 0.6

agreed?

[tired sonnet]

yes

[verbal tiger]

that first inequality

x>-1.7

you can actually write that as -1.7 < x

its the same thing we just switched it around

do you agree?

[tired sonnet]

yes

[verbal tiger]

so we have -1.7 < x, and x < 0.6

so you can combine those to make -1.7 < x < 0.6

does that make sense?

help theres a moth on my laptop

[tired sonnet]

ye

[verbal tiger]

so your answer for (d) wouold be -1.7 < x < 0.6

does that make sense?

[tired sonnet]

yes

[verbal tiger]

now try e

[tired sonnet]

its just -b formula right

[verbal tiger]

it wants you to use teh graphs

it says -x^2 - x + 1 = 0

so when does -x^2 - x + 1 cross the x axis

look for which graph is -x^2 - x + 1

which one is that?

[tired sonnet]

blue

[verbal tiger]

when does it cross the x axis

[tired sonnet]

is it 0.5 and -1.6

[verbal tiger]

we said its above the x axis for -1.7 < x < 0.6 right

so it should cross the x axis at -1.7 and 0.6!!

[tired sonnet]

so same thing

just not with signs

[verbal tiger]

x=-1.7, x=0.6

dooes that make sense?

[tired sonnet]

yes

[verbal tiger]

now what about (f)

[tired sonnet]

its where the 2 lines intersect

i remember that

[verbal tiger]

mhm

and wheres that

[tired sonnet]

1 and -3

[verbal tiger]

now wb (g)

[tired sonnet]

cuz its x

-5 so its x^2+3x+8 = 0

[verbal tiger]

first of all, x^2 + 3x + 3 = 5

subtracting 5 from both sides gets x^2 + 3x - 2 = 0

second, they want you to use the graph

[tired sonnet]

lol what am i thinknig

[verbal tiger]

so they're asking "when is h(x) equal to 5"

which graph is h(x)

[tired sonnet]

purp

0.5?

[verbal tiger]

x=0.5 is one

what about another?

[tired sonnet]

and

-3.6

[verbal tiger]

yes

so x=0.5, x=-3.6

wb (h)?

[tired sonnet]

hm

[verbal tiger]

what does (h) say in words?

[tired sonnet]

when is p(x) greater than hx

[verbal tiger]

exactly! and when is that?

[tired sonnet]

Above like 0.8 on y

[verbal tiger]

not quite

its asking "when is the graph of p(x) above the graph of h(x)"

agreed?

[tired sonnet]

ye

[verbal tiger]

and where will that be?

what set of x values will that be?

[tired sonnet]

i dont really get it

cuz what determines if its above it

[verbal tiger]

ohh yes good question!

first lets see where they intersect

[tired sonnet]

-4.1

and -0.9

[verbal tiger]

its it goes a little further than -4

but anyways

[tired sonnet]

ya

[verbal tiger]

imagine drawing a horizontal line at each intersection

[tired sonnet]

yes

[verbal tiger]

something like this right

[tired sonnet]

yes

[verbal tiger]

sorry lemme draw that better

[tired sonnet]

its ok

[verbal tiger]

something like this right?

[tired sonnet]

ye

when its above the 2 lines

is answer

i think

[verbal tiger]

now idk think ab any x coordinate within the region where they intersect

which graph is the "above" graph on that x coordinate

[tired sonnet]

ike -4.3

[verbal tiger]

hang on lets slow donw alittle

[tired sonnet]

ok

[verbal tiger]

so you said they intersect at like

-4.1, and -0.9

yes?

[tired sonnet]

Yea

[verbal tiger]

now lets pick an x coordinate

so pick a number on the horizontal axis

[tired sonnet]

-5

[verbal tiger]

thats within this zone

[tired sonnet]

Oh

[verbal tiger]

so its gotta be between -4.1 and -0.9

[tired sonnet]

-2

[verbal tiger]

lets just say -3.5 yeah?

ok

-2

lets do -2

[tired sonnet]

Ok

[verbal tiger]

at x=-2

that vertical line is just x=-2

agreed?

[tired sonnet]

Yes

[verbal tiger]

now which graph is the "above" graph there?

[tired sonnet]

Green

[verbal tiger]

exactly

now imagine varying this

so idk

-1

maybe -1.5

[tired sonnet]

i understand

[verbal tiger]

just imagine that vertical line sliding around

if the vertical line is between -4.1 and -0.9 then the green graph will always be the "above" graph

anytime the vertical line is outside of that region, the purple graph will be the "above" graph

[tired sonnet]

ye

[verbal tiger]

this means green graph > purple graph so p(x) > h(x)

[tired sonnet]

yes

[verbal tiger]

so we've found that p(x) > h(x) when x is between...?

[tired sonnet]

-4.1 and -0.9

[verbal tiger]

bingo

so -4.1 < x < -0.9

[verbal tiger]

you can read this as "x is between -4.1 and -0.9"

does allat make sense?

[tired sonnet]

yea

thanks

[verbal tiger]

np

[tired sonnet]

i might need mor help

[tired sonnet]

is the answer it has none because it doesnt touch the x axis

[verbal tiger]

correct

[verbal tiger]

mhm rn ive gtg its 1:27am and im doing my own stuff rn

but im sure someone else is happy to help

[tired sonnet]

oh alright thank you for everything

[verbal tiger]

no problem

[forest iron]

im here

[tired sonnet]

hi

[forest iron]

which question rn

[forest iron]

!show

[midnight plank]

Show your work, and if possible, explain where you are stuck.

[tired sonnet]

i dont know where to start

is x1 2.4

and x2is 25.3 or something

so you minus them

[forest iron]

wait lemme use quadratic formula

[tired sonnet]

nvm im ok

i dont need help anymore

[verbal tiger]

need to use graph

[forest iron]

somehow i got negative numbers from the roots tho

[verbal tiger]

approximate value using the graph

[forest iron]

ahhh yes

then its easy

[tired sonnet]

ya its ok you can close this if u want

[forest iron]

any more questions?

[tired sonnet]

thank u @verbal tiger and roy

[verbal tiger]

and negative number roots are correct

no probelm

[forest iron]

anymore questions?

!done

[midnight plank]

If you are done with this channel, please mark your problem as solved by typing .close

@tired sonnet Has your question been resolved?

Channel closed

Closed by @tired sonnet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[median arrow]

Can anyone help me with that

[median arrow]

, rotate

[median arrow]

X and y are real numbers ≠0

[vocal raft]

can you not just find y in terms of x and substitute in the inequality?

[median arrow]

It only says x and Y real numbers ≠0

[shell wigeon]

Shubh means: find y = f(x) and consider 1/(x^2 + f(x)^2)

[median arrow]

Yeah

[shell wigeon]

Well, what expression do you get for 1/(x^2 + f(x)^2) ?

[median arrow]

Im sorry I study math's in French so it may be not the same terms used for things

[grim vector]

Isole y

[median arrow]

Ohh

[grim vector]

Et remplace la valeur de y dans l'expression à droite

C'est ce qu'ils te proposent

[median arrow]

Ohhh, thankss

[grim vector]

Après si il y a marqué : "application" je suppose que tu as un theoreme quelconque à utiliser non?

[median arrow]

Donc après cela je pose la négations de la deuxième proposition ?

[median arrow]

C le contraposé

[grim vector]

Ah

Je me disais que ça s'y prêtait bien aussi

A => B est équivalent à !B => !A

1/(x²+y²) <= 20 est équivalent à une inéquation remarquable

[median arrow]

J'ai fait cela

[grim vector]

Ça me semble pas mal et si tu resoud pour x ?

[median arrow]

Je le fait maintenant

[grim vector]

Je pensais à résoudre pour x ici

[grim vector]

Après si tu veux résoudre pour y ça fonctionne aussi mais ton inegalite ici est fausse, il manque le ² sur le y

[median arrow]

Ah oui

Je ne savait pas quoi faire après cela

C'est just la

?

[grim vector]

Ce qu'il faut faire c'est ce que tu as rayé

[grim vector]

Et ducoup tu as x² + y² < 1/20 et tu remplace y par sa valeur que tu as trouvé ici

[grim vector]

Il y a une erreur ici

[median arrow]

C'est (1-2x)²/4*4

[grim vector]

Et (1-2x)² =

[median arrow]

1 +4x +4x^2

Ohhh

-4x

Oui

[grim vector]

Oui voilà

[median arrow]

Et puis je fait quoi

[grim vector]

Tu connais l'inégalité de Cauchy Schwarz ?

Sur les produits scalaire plus précisément

[median arrow]

Non

[grim vector]

Ok

[median arrow]

Le prof nous a dit c'est pas nécessaire d'utiliser le contraposée (il a été trompé c'est un exercice pas une application)

[grim vector]

Enfaite l'idée qu'on faisait doit sûrement marcher mais elle est assez calculatoire et utilise pas trop la contraposée

Suppose x² + y² < 1/20

[median arrow]

Je dois trouvez que 2x+4y≠1

[grim vector]

Et considère (2x+4y)² en essayant de l'écrire comme A(x² + y²) - B(2x - y)²

Donc (2x+4y)² = A(x² + y²) - B(2x - y)²

[median arrow]

A et B deux entiers ?

[grim vector]

Réels pour l'instant, soyons général on ne sait pas, même si ils sont probablement entiers au final

[median arrow]

D'accord

[midnight plank]

@median arrow Has your question been resolved?

[median arrow]

. Close

[midnight plank]

Channel closed

Closed by @median arrow

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lunar ridge]

why we not using = here ?

[spiral rock]

because its not equality

[grim vector]

Equivalence sign for equivalence, equality sign for equality

[spiral rock]

its equivalence

[lunar ridge]

sorry whats the difference ?

[spiral rock]

equivalence means the have the same truth values

equality means they are the same object

[lunar ridge]

ok so 2+2=4 and 1+1=2, equivalence and 1=1, equality ? like that ?

[shell wigeon]

If you were to evaluate the statements with specific values of p, q, and r, you would use equality

The equivalence symbol just means the statements are equivalent, that is their evaluations are equal for any values of the variables

It's mostly semantics though (but sometimes it matters)

[lunar ridge]

okok

thanks bro

.close

[midnight plank]

Channel closed

Closed by @lunar ridge

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[night gyro]

easy way to do this

[sudden yacht]

Where do you find difficulty in?

[midnight plank]

@night gyro Has your question been resolved?

[night gyro]

is ok

.close

[midnight plank]

Channel closed

Closed by @night gyro

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wary ferry]

wouldnt it be int(1+cos(xpi))sx from 0 to 10?

[fallow scarab]

what is the question

[wary ferry]

is that what you mena

@fallow scarab

[fallow scarab]

yes now people can help once they know what you're calculating

[wary ferry]

mb

[midnight plank]

@wary ferry Has your question been resolved?

[wary ferry]

<@&286206848099549185>

[stoic walrus]

I think this exercise is not completely explicit so it is normal to be confused. Firstly, I think that you have to consider that the density function is radial which prompts you to use a polar coordinate system. Even if that's not the case your answer is incorrect since what you've written is basically calculating the mass of a wire with length 10 and linear density given by that function

[wary ferry]

i ment

int[(1+cos(xpi))^2]dx from 0 to 10

[stoic walrus]

Either way isn't really what the problem is asking

[wary ferry]

idk what its asking

[stoic walrus]

If you want to calculate the mass of a 2D object you have to do this integral $\int\int_A \rho(x,y) dx dy$

[grand pond]

KonoEmllikDa

[wary ferry]

so id have to integrate it then integrate agian with the limits?

[stoic walrus]

The problem with that exercise is that it gives a single-variable density function which could mean one of two things: either the function is radial and therefore you can solve it easily by integrating in polar coordinates, or the density only depends on x and the limits are given by the shape of the object, in this case a circle of radius 10

[stoic walrus]

yes it needs to be within the limits of the shape

[wary ferry]

so would this be the same then

its not

[stoic walrus]

I might be wrong but I think that in that case you approximate the antenna to a thin wire, and the integral should be one-dimensional

[wary ferry]

i did this the same way i did that and got the right answer

int(3x+2 from 0 to 3

[stoic walrus]

moreover in that question the units of the density function suggest it to be a linear density function

[stoic walrus]

that is correct because the problem is different

[wary ferry]

yea

ig

it just confuzing

i got a exam tomorrow

so i may be screwed

[stoic walrus]

I don't think you understood what I meant. Basically in the first problem the integration is over a circle, a 2D object, while in the second it is over a thin wire, which is a 1D object

[wary ferry]

i see

but wouldnt the ^2 make it the 2d?

[stoic walrus]

No because the density function itself is already given, supposedly, in units of mass/area, it should be said in the exercise, but it is not there, you are meant to assume that

Just to make sure do you have the answer to the first question?

[wary ferry]

so your saying i dont square it

[stoic walrus]

Yes but that alone wouldn't fix your answer

[wary ferry]

int(x+xsin(pix))

from 0 to 10

[stoic walrus]

No, i guess you tried to integrate it twice to respect to x, but that's not how it's done

[wary ferry]

im so confused

[stoic walrus]

Ok so let's return to this formula

Your problem is that you are not defining the limits of integration correctly

[wary ferry]

so this but different limits?

[stoic walrus]

Still a no

[wary ferry]

so i do the limis of the 1st integral then find limits of 2nd?

[stoic walrus]

Firstly do you know what are the limits of the area integral in this case?

[wary ferry]

no

o to 10?

[stoic walrus]

So the area is a circle, right?

[wary ferry]

pi100

[stoic walrus]

That is not correct

[stoic walrus]

Is that the answer?

[wary ferry]

area of circle

pir^2

pi10^2

pi 100

[stoic walrus]

Ok, i got what you meant, but that is not what i've asked

The region where you are doing the integration is a circle, right?

[wary ferry]

yea

[stoic walrus]

Do you know of any equation that defines a circle?

[wary ferry]

y^2=x^2+r?

somthing like that?

[stoic walrus]

It should be $x^2+y^2=r^2$

[grand pond]

KonoEmllikDa

[wary ferry]

that what i ment

[stoic walrus]

Can you solve it with respect to y?

[wary ferry]

isnt it the same as x

[stoic walrus]

You can choose any of the variables, I just think that y would be easier in this problem

[wary ferry]

y=-+sqrt100-x^2

[stoic walrus]

That's correct, but notice that both the positive and the negative solutions are needed. What you've done now is defining the limits of integration over y. Now can you say for which values of x that expression is defined?

[wary ferry]

-10 10

[stoic walrus]

Correct, those are the limits for x, now if you put everything together the integral should be $\int_{-10}^{10}\int_{-\sqrt{10-x^2}}^{\sqrt{10-x^2}}{1+\cos{(\pi x)}} dydx$. However the problem that I mentioned in the beginning is that $\rho(x)$ can be a radial density function which means that the integral should be a little bit different, if the result you get from this integral is not the solution to the problem, then it means that you have to use polar coordinates

[grand pond]

KonoEmllikDa

[wary ferry]

i doubt this will be on the exam

ive never seen this before

and 100pi is the answer according to the book

i just dont know how to get there

i tried putting into my calculator and saying illegal nest

[stoic walrus]

Allow me to then explain what I think the exercise is really asking. So $\rho(x)$ is a radial density function, which means that you have to use polar coordinates those being $r^2=x^2+y^2$ and $\theta=\arctan(\frac{y}{x})$. In that case, this is true $\int\int_A\rho(x,y)dxdy=\int\int_A\rho(r,\theta)rdrd\theta$.

[grand pond]

KonoEmllikDa

[stoic walrus]

It's normal, that's way I think this exercise is not well written

[wary ferry]

ive never seen 2 integrals befroe tho

[stoic walrus]

Usually what it means is that you integrate one of the variables, then you integrate the other

[wary ferry]

i mighbt just dkip this one

i dont have time to figure that oout

[stoic walrus]

In this case the problem is solved by calculating $2\pi\int_0^{10}r(1+\cos{\pi r})dr$

[grand pond]

KonoEmllikDa

[wary ferry]

605?

[stoic walrus]

Just to be sure are you taking physics or engineering, because, usually they give problems when you didn't really learn every mathematical tool needed to solve them

[wary ferry]

this is for calc 2

[stoic walrus]

I don't think that is the result of that integral

[wary ferry]

im going into engineering thi

[stoic walrus]

Ok, then in this case you can basically imagine that, since you are calculating the integral with a radial density function, its the same to doing the integral over the radius of the circle, but since the area between two circles separated by $dr$ is $2\pi r dr$ then the integral is $2\pi\int_0^R r\rho(r)dr$ instead of $\int_0^R \rho(x)dx$

[grand pond]

KonoEmllikDa

[stoic walrus]

If you need the proof for the area between those circles that is easier to do

[wary ferry]

2pi int(x(1+cos(pix))dx from 0 to 10

[stoic walrus]

In this case, yes

[wary ferry]

when i plug in i get 605

[stoic walrus]

I think most of the problems will have that symmetry, so you can just do it

[wary ferry]

i mean the area is the answer

pi10^2

[wary ferry]

100pi

[stoic walrus]

I know it is, it's just because of the density function happens to give that result, it's not a general case

[wary ferry]

im stupid

[stoic walrus]

That's in degrees

[wary ferry]

i was in degrees

lol

[stoic walrus]

It happens to all of us

Don't stress to much about it

[wary ferry]

i have been changina alot

i have physics as well

i got the right answer

[stoic walrus]

I get it, it can be really annoying

[stoic walrus]

Nice, I think I didn't explain it really well, but I hope you understand that what you did was not correct

[wary ferry]

$\int_0^R \rho(x)dx$

[stoic walrus]

I can't really give a better explanation because I got to go, so I wish you good luck for you exam tomorrow

[grand pond]

SolidDragon05

[wary ferry]

how i do that way

[stoic walrus]

What do you mean by that?

[wary ferry]

ik im missing pi

[stoic walrus]

I'm sorry but I don't really understand what you are asking

[wary ferry]

.

the other way

[stoic walrus]

You mean by using the two integrals?

[wary ferry]

oh that one dont work does it

$\int_0^R \rho(x)dx$

[grand pond]

SolidDragon05

[stoic walrus]

In this problem, the answer should be given by that formula that I gave you. So the "two integrals" solution is not correct. However if you were to calculate it in your calculator you can always try this $\int_{-10}^{10}\int_{-\sqrt{100-x^2}}^{\sqrt{100-x^2}}{1+\cos{(\pi x)}} dydx= $\int_{-10}^{10}{\left.{\left(y(1+\cos{(\pi x)})\right)}\right|{;y=-\sqrt{100-x^2}}^{;y=\sqrt{100-x^2}}} dx=\int{-10}^{10}{2\sqrt{100-x^2}(1+\cos{(\pi x)})} dx$

[grand pond]

KonoEmllikDa
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[stoic walrus]

If that's not what you are asking, again I'm really sorry, but I got to go, so I can't help you. I wish you good luck on your exam tomorrow

[wary ferry]

Its ok, thanks for your help tho it's greatly appreciated!

.close

[midnight plank]

Channel closed

Closed by @wary ferry

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[static salmon]

why is this incorrect?

[static salmon]

for my work, i changed it into (2/3)(x^-1)

AHA! i have discovered my error!

nevermind chat!

.close

[midnight plank]

Channel closed

Closed by @static salmon

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[static salmon]

hello friends i return, why isnt THIS one right?

[onyx shell]

you need the equation in point slope form

-21 is just the slope of the tangent line at that point not the equation

[static salmon]

ah

how would i convert it into point slope form

[onyx shell]

its y - f(3) = -21(x -3)

you need to find the y by plugging 3 into the original equation

[static salmon]

oh okay

[compact copper]

well y = mx + c, and IG m is 0 here

Oh wait this doesn't help

[onyx shell]

i think you're supposed to do point slope

[static salmon]

i thought m is -21?

[onyx shell]

it is

at that point

you get a lot of attemps on delta math lol

[static salmon]

yeah the examples use point slope

[compact copper]

Yup I'm insane today, ignore me

[onyx shell]

you good bro

[static salmon]

i have done it!

thank you!!!!

goodnight

.close

[onyx shell]

gn

[midnight plank]

Channel closed

Closed by @static salmon

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cloud adder]

How did they get -1 in the numerator

If 2-2 is 0 and h is left in the numerator as 0

[last arch]

-h•(1/h)=-1

[cloud adder]

the 1/h does nothing to the denominator?

[last arch]

Wait I'll draw this on my coffee cup

(I have no paper)

[cloud adder]

okay

[last arch]

The h gets uh

Cancelled out

[cloud adder]

Oh I see it now

Okay that feels obvious idk why I didn't see that

Thank you

[last arch]

Np

[flint gyro]

Coffee cup sacrifice

[cloud adder]

.close

[midnight plank]

Channel closed

Closed by @cloud adder

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal flame]

,rccw

[vocal flame]

Can any one help me with b and c

I know you plug something to the h to 0 equation

But I don’t know what

[pastel garden]

Do you know the difference quotient? Question b* asking you to find the limit of the difference quotient as h approaches 0 given that x = 3 for f(x)

[vocal flame]

I’m not sure but this is all we are given

[pastel garden]

Okay well do you know how to find the slope of a line given two points?

[vocal flame]

Yes

[pastel garden]

if you think about it it can be expressed as [f(x2) - f(x1)] / (x2 - x1)

[vocal flame]

Yes

But the slopes not 8

[pastel garden]

But your teacher before derivatives never needed to show it as that because lines follow a pattern

Oh they've already done some of the work there f(a + b) - f(a) yeah so you can think of it as finding the derivative so they want

the limit as b approaches 0 of (12b + 2b^2) / b

Can you do that?

[vocal flame]

Yep

Ok so the slope is 12

Ok why is a x in this problem though

Like it sounds dumb

Well ig it doesn’t matter

Either one you plug it into give u 12 and 4x

/4b/4a

[pastel garden]

Yes

[vocal flame]

Wait would c be 4ab

Or just 4b/4x

Nvm I’ll factor it out

Thanks

[pastel garden]

You are welcome and i believe you are correct yes about problem c

[vocal flame]

.close

[midnight plank]

Channel closed

Closed by @vocal flame

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tiny shale]

how i do this

i get to

(1/sin(x) - cos(x)/sin(x)) / 1 -cos(x)

so that becomes

( (1-cos(x) ) / sin(X) ) / 1- cos(x)

now what

[compact copper]

Just cancel it out

[spiral rock]

cancel the 1-cos(x) from the numerator and denominator

[tiny shale]

oh im stupid

.close

[midnight plank]

Channel closed

Closed by @tiny shale

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[leaden seal]

so im thinking

my a and y axis have been labelled wrong

[midnight plank]

@leaden seal Has your question been resolved?

[brisk iris]

What are you struggling with ?

[leaden seal]

this is my answer

does it seem correct?

.close

[midnight plank]

Channel closed

Closed by @leaden seal

Use .reopen if this was a mistake.

[brisk iris]

.reopen

[midnight plank]

✅

[brisk iris]

This is what you need to solve @leaden seal

[leaden seal]

so is my working incoorect?

because i seem to get similar to the answer

[brisk iris]

If it’s the same as the answer then it’s correct

But it’s different from the answer

[leaden seal]

by a couple of decimal places

[brisk iris]

By 2 … which is not negligible

[leaden seal]

right

if we round

its by 1

becus the answer would be 21 and 31

so what im asking is if my working is correct?

[brisk iris]

I did the math and I get exactly the same answer

[leaden seal]

as 22?

[brisk iris]

Yes

Here

[leaden seal]

for F1

wich is 50

for sum of vertical forces i got -50

[brisk iris]

50

It’s the same as my first equation

[midnight plank]

@leaden seal Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glad merlin]

Hello, I'm really really confused on how to even start this or what thinking I'm supposed to adopt. I saw some stuff regarding proving a contradiction by looking at the different possibilities of the partial order but other than that im quite lost.

[midnight plank]

@glad merlin Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[half idol]

Can anyone help me to find inverse of factor ring?

[half idol]

I am not understanding the concept properly

(5z+3)^-1

(5z+3).(5z+a)=(5z+1)

=(5z+3a)=(5z+1)

3a=0?

Ohh wait i did a mistake

3a=1

a=2

(5z+2)

Am I right yooo?

[forest iron]

What is that . there

Is that times, divide, minus, or plus

[half idol]

Multiplication@forest iron

[lethal path]

this is in Z/5Z right?

[half idol]

Yes

[lethal path]

yeah, looks good then

[half idol]

One more question

Q/Z is not a quotient ring why?

@lethal path

no problem

.close

[midnight plank]

Channel closed

Closed by @half idol

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glad merlin]

Hello, I'm really really confused on how to even start this or what thinking I'm supposed to adopt. I saw some stuff regarding proving a contradiction by looking at the different possibilities of the partial order but other than that im quite lost.

[wheat nymph]

I think the observation to show is that a function f exists iff every pair x in X, y in Y satisfies the monotone function property x <. y implies f(x) <= f(y)

[wheat nymph]

Then u can just brute force the m*n pairs, which I think is what u r saying here

There probably is a more clever solution tho, and I'm also not completely sure what variables r allowed for the polynomial time criteria (sry I'm not a computer scientist)

[midnight plank]

@glad merlin Has your question been resolved?

[midnight plank]

@glad merlin Has your question been resolved?

[midnight plank]

@glad merlin Has your question been resolved?

[glad merlin]

Could i maybe think about all of the possibilities between pairs in a set

for example, given x and y in a set, the only possible orderings are (<< indicates the partial order):
x << y
y << x
x and y have no relation

<@&286206848099549185>

[glad merlin]

okay so consider that we have two sets X and Y given that every element in set X produces 0 via a function f and every element in set Y produces 1 via the same function f

between every element in the same set, a monotonic boolean function will always be present.

Now, the only thing to test is interactions between elements from the two different sets

between elements in these sets, considering that x is an element from set X and y is an element from set Y, then there are three possible interactions:

• x << y
• y << x
• x and y have no relation

if y << x, then f(y) <= f(x) or 1 <= 0 which is false meaning that there can't be a monotonic boolean function if this is the case

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

<@&286206848099549185>

[glad merlin]

<@&286206848099549185>

[golden crescent]

#1021175428326633542

[glad merlin]

very sadge

anyways i think my answer is pretty much correct

just don't understand some of the nuances in it

such as how we can order different binary strings in a graph representation

[wary epoch]

@glad merlin I think your algorithm is correct. If Y = {0110, 0101, ...} for example, you can a find a minimal monotone Boolean function f(a,b,c,d) = b&c | b&d | ...
if there is x ∈ X such that f(x) = True, then there is no monotone Boolean function.

[midnight plank]

@glad merlin Has your question been resolved?

[glad merlin]

Thanks for the answer. I just had another question regarding ordering these binary strings on a number line. How would you got about even trying to do that. Would it be arbitrary?

[glad merlin]

Like for this graph here, how would you order the strings cause if you dont do it properly then it no longer becomes monotonic.

[wary epoch]

I don't bother, tbh.

I just note that if two function f and g are monotone, then f & g and f | g are also monotone.

After then, you can simply express the boolean function in terms of its disjunctive normal forms (without NOT operator, of course)