#help-49
1 messages · Page 181 of 1
What a wonderful world !
and here delta is the foward difference for which term?
This is wher I'm currently at
what do I do now
nvm, I made mistakes
<@&286206848099549185>
clarficiation, first want to use the regular newton polynomial method
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factor x³+y²+1
$x^3+y^2+1$
rivenrivers
Is it what you're asked to do or its part of a bigger problem?
ill handle myself on the bigger problem
i just dont know how to factor this one
i doubt this is factorable
Yeah me neither
difference of squares should be possible on 2 variables right
all my factoring methods cant do this specific problem
you cannot factor this
gotta find a way for this
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
i got myself some new factoring methods but this one, idk anymore
my problem is the integral of 1/(x³+y²+1)
this needs partial fractions procedure
with respect to x?
i already solved 1/(x⁵+1)
it's a double integral, inner int is dx, outer is dy
oh okay
bounds or indefinite ?
i doubt i can do definite integration on this one though
rivenrivers
there is the problem
ill work on this for days
it's way harder than the integrals i solve than usual
wtf?!
how did this calculator manage to solve it
i think i can try my old factoring methods
but since theres +1
it would be like
(±√u) once again
so
2 variables
where'd you get the problem from
my mind,i keep thinking of hard integrals
well theres no guarantee there is a nice form for these integrals
just as a warning
even ones like this that dont look super out there
i know
i looked at the answer of calces
so it has answers and doesnt have any weird symbols
meaning theres a way to factor it
OH
(u)²
wait since the form is x³+y²+1¹
i can just do
wait this is cuberoot i think
i havent tried factoring resulting in cuberoots
nah how tf
calces is cracked
if you write a^3 = y^2 + 1
then its x^3 + a^3 = (x + a)(x^2 - ax+ a^2)
i dont think its particularly helpful, but you can do that
no thats not too helpful
finding x's solution
i think
it will be
³√(-y²-1)
this integral is cracked
how tf do i factor
there might be a brilliant idea here
ill take 2x+1 roots
(x±√1x+1)
OHHHHHHHHHHHH
I GET IT
nvm, i dont
how tf
i swear if i finally discover a factoring method for ts im gonna try to publish my factoring methods
i need help
WAIT PERHAPS TRANSFORMING?
transforming?
so thats if a=√(y²+1)
if it's possible
then partial fractions
im looking to factor x³+y²+1
i recognize the form, thank you
ill gamble this
seems incorrect
wait im wrong that should be x+
seems wrong
i conclude that this has no factor
ok if this is the case
this has a factor
i cant just prove it somehow
maybe i can try this
it should match
i need some serious help
,w
.w
,w integral of 1/(x^3+y^2+1)
@last slate Has your question been resolved?
struggled on an integral
@last slate Has your question been resolved?
so you don't need help anymore?
i still do
but you were already told
that it cant be factored?
the denominator only
wolfram used cubic formula and partial fractions
read that and factor your denominator while treating y as a constant
where's the partial fraction step
,w expand (x-(-y^2-1)^(1/3)) * (x^2 + (-y^2-1)^(1/3) * x + (-y^2-1)^(1/3))
check that it equals x^3 + y^2 + 1
don't think you used the right formula
try using this one
The sum of cubes formula is also called the a cube plus b cube formula. Learn to derive the sum of cubes formula. Understand the a^3 + b^3 or sum of cubes formula with derivation, examples, and FAQs.
,w factor x^3+y²+1
how about the +1
can you ask a complete question
there are no actual factors? ☠️
how do i factor x^3+y^2+1 for partial fraction
there are if you write x = a and b^3 = y^2 + 1
$\int\int\frac{1}{x^3+y^2+1}dxdy$
rivenrivers
this is my problem
really? b³ as y²+1
that's what i said yes
if you're confused you can ask a question about what you're confused by
substitution yes
can you ask a complete question
this
use cube roots for what?
x=a
b³=y²+1
(x)(x²)
it's this
to find the factor for the denominator to start partial fractions
i mean what are you trying to solve for with cube root
just in case theres a need to cancel
?
like the factor i managed to make with 2x+1
that doesn't answer my question
(x+√1x+1)(x-√1x+1)
it does
with foil method
there are some that can be left
what is this supposed to be?
can you start writing equations rather than random expressions
... a factor for 2x+1
2x + 1 can't be factored any further
yeah try foil then
unless you count 2(x + 1/2)
it cancels out
x² - √1x² + x
√1x² - x² + √1x
x - √1x + 1
wait did i do it right
yeah i did
2x + 1
cancel like terms
i just did
you factored it in terms of square roots?
factoring usually means factoring in terms of linear factors
yes
saying x can be factored as sqrt(x) * sqrt(x) is not common language
my factoring method is pretty confusing
because then you can say sqrt(x) = x^(1/4) * x^(1/4) and you can factor sqrt(x) even further
please don't make up your own definitions for words that already have an established definition
i dont think this is what i meant
i only put squares to cancel out terms to receive the final input
what
i mean i only used square roots to cancel things out
did you factor x^3 + y^2 + 1 yet?
the thinf is, i cant
it's too confusing
set x = a and b^3 = y^2 + 1. then the right side becomes (x + ...) (x^2 - ...) and it's factored as a product of a linear term times a quadratic term.
then you can further factor the quadratic term with quadratic formula
you fill in the ... with the equation i gave
no that's not the right order
this is what you do first
$x^3 + y^2 + 1 = a^3 + b^3$
riemann
solve for b
and plug b into the right side
(x+a)(x²-ax+a²)
x³-a³+y²+1=b³
transpose?
im guessing
cuberoot(x³-a³+y²+1)
if b is that value
then uhh
read this again.
x = a
oh wait x = a
so i dont need to solve for a
skrry
is there a way to get cuberoot in keyboard
∛
cbrt is fine
b=∛(x³-a³+y²+1)
going back, do i have to perform an operation?
i dont know whats next
factor?
.
this?
,w simplify cbrt(x³-a³+y²+1)
i really do not
if x = a then x^3 - a^3 = ?
my brain isnt braining at all for the first time
the left side of this is what you're starting with. the right side is what the form factoring sum of cubes gets you
yes substitute 0 into your expression for b
.
no
so i dont substitute it?
expression for b means
b=∛(x³-a³+y²+1)
x^3 - a^3= 0
use that in the right side of b
get in the habit of writing complete equations
you're confusing everyone by writing random expressions without context
this is correct
am i even doing it right
plug your a and b into the right side
what does split mean
(x+cbrt(y²+1))(x²-cbrt(y²+1)x+cbrt(y²+1)²)
like splitting the factors, i dont know the actual term
OHHHH SHIT
THATS REALLY IT
THANKS
cuz i tried calculating it in my mind via foil method
then i got
x³+y²+1=0
ok this is the hardest factoring method ive learned so far, thanks!
,w expand (x+cbrt(y²+1))(x²-cbrt(y²+1)x+cbrt(y²+1)²)
nice
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how do i give this man an upvote
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https://www.instagram.com/reel/DILpKWUS6yp/?igsh=MW5rOTl5M3JnN3g0Mw==
Can someone explain/translate what he did please
!ss
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lol i know this account
Lmao
multiplied and completed the square i think
,tex .cts
riemann
-x^2+x-(1/2)+1/2=x^2-x+(1/2)-(1/2)=x^2-x+(1/4)+1/4-1/2=(x-1/2)²-1/4=(1/4-(x-1/2))²)
?
I should've added and subtracted 1/4 right ??
I technically did it but with more steps I think
What did he do here ?
How is it arcsin
Because $\dv{x}\arcsin(x)=\frac{1}{\sqrt{1-x^2}}$.
;(
But denominator has 1/4
Isntead of 1
Isn't it $\dv{x}\arcsin(f(x))=\frac{1}{\sqrt{1-f(x)^2}}$.
prograce
this is incorrect
do some factoring and u sub to get it into the form where you can use the arcsin formula here
Yes, with the modification you have.
You’re meant to take ||u=x-1/2||.
And also $\int\frac{1}{\sqrt{a^2-x^2}}dx=\arcsin(\frac{x}{a})$.
;(
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!nogpt
Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).
can you show the original question? I can't really tell which forces are which from the diagram alone
yeah im aware
what is F' here?
you cant demonize ai
F_CB and F' look orthogonal to one another; are they?
no clue
ok but can you show the diagram that came with the question?
?
hang on
i cant send it all in one ss is what im saying
im gonna die
they made it astronomically spaced out
ok then paste it into Paint or something and scale it down
make it ten screenshots in one message
or that
it's very hard to comprehend when we don't have the question in front of us and cannot scroll back and forth through the parts
most real reaction
Do you understand this
Do you know how to write the forces
at which part do you stop following?
yeah
i just dont understand where they get 3F/2
i understand how they got sqrt2 f
pythagoras right?
What even is the question
they are at right angles, so the pythagorean theorem applies
One side is f/2 the other is root2f
but then dont you get sqrt(2)/2
What
Can you solve it on paper and send a pic
,tikz[thick, -Latex, scale=2]
\draw (0,0) coordinate(O) -- node[below left]{$\sqrt 2 F$} (-45:{sqrt(2)}) coordinate(A);
\draw (A) -- node[below right]{$F/2$} ++ (45:0.5) coordinate(B);
\draw (O) -- node[above right]{$3 F/2$} (B);
\draw pic[draw, -, thin]{right angle=O--A--B};
cloud
@wicked mauve
oh type shit
i got it
i forgot about the 1 in 1/4
which makes it 9/4 under the radical
lol
thanks folks
.close
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Hi! I was wondering if anyone has good website recommendations for checking problems like these
I suspect my answer is wrong
why dont you just use wolfram?
is that a cursive s
oh alright im not sure of any that do but good luck
@subtle peak Has your question been resolved?
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I need help with my calc 2 homework. I am learning about taylor polynomials and im confused about what im doing wrong here. The screenshot on the right is the one the video from my homework shows how to do. The squared paper on the left is my attempt. I am confused as to why im not getting the same answer.
Where are these pi/2 comings from?
@blissful zinc
f^n (pi/2) aren't involving pi/2 anymore
Its the numbers that you calculated
Its supposed to be just -1 here
Same for the other pi/2 that is lasting
Oh I thought I was supposed multiply pi/2 times the derivatives shown in the formula here
ohhhhhh I see
that makes more sense, thanks!
Yw
You're ending with their result normally if you erase these pi/2
Oh and btw pi/2 * pi/2 is pi/4 not pi
Fact

pi²/4
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I am trying to decipher how this problem works.
From what I understand, this means that the derivative and the parent function have the same value the entire time, but I'm not really sure how that works.
The only function I know that has this behavior is e^x.
That’s a différential equation
But if they want the instantaneous rate of change and the value itself to be the same, is this not the only way to do that? I guess I'm not really understanding the question.
Is that different from what I said? In my head it's the same thing.
It is !
Now you can solve it, and use initial conditions to get rid of the intégration constant
Wait what am I solving
This
Is that not already an equation
It's been nearly a decade since I've taken calculus, so I don't really comprehend much of what I'm reading.
Ok let’s take it slow
This does not give you the value of P
You need to have an expression for P(t)
In order to do that, you are given a differential équation that you can solve
I am not understanding what you mean by "solve" at all.
You gotta know I've been extremely out of the calculus game.
What am I solving?
Wait
when you are given f’(x) + a f(x) = 0
That’s called a différential equation
You can solve it to find an expression for f(x)
Dang teach really got me doing differential equations in an Algebra 2 class.
It’s a simple one
What kind of function does not change when you take its derivative ?
So $f(x)=-\frac{1}{a}f'(x)$?
MJames
Ok, but that does not solve it, cause you don’t know f’(x)
I don't know any of these terms
We just got our feet wet with separable differential equations, so now let's look at something slightly trickier. Solving linear first-order differential equations will require a little bit more effort, involving something called an integrating factor. Let's see how this works with a few examples.
Script by Lorcan Nicholls
Watch the whole Diff...
That's a whole lot of stuff I don't know lol
e^x is the same
Good but it’s not the only possibility !
I got nothing then.
Any function of the form : A.exp(t) could work
I'll be frank with you, I'm super sick right now, but teach wants this assignment today, so I'm just trying to struggle through it as best as I can.
How come you haven’t done calculus in 10 years ?
I appreciate the help, I'm just not understanding any of it.
Haven't had to for my major.
I'm surprised I have to now for an algebra class.
Ok I can give you the full solution but you have to catch up on this or it’ll only get harder
Give me 5 min
Well this is the last assignment of the entire class then I'll never have to use it again. But I understand what you mean.
Oh that's what you meant by solve. I thought you meant integrate.
I forgot there were points and stuff. My brain just skipped over them.
It IS a form or intégration but Let’s not get into that
What is exp?
Exponential
This is exp
MJames
Where A is the initial conditions?
Close but not quite
Here's a link if you want the general form
So $A=\frac{3000}{e^{2015}}$?
MJames
I plugged in y=3000e^(x-2015) into a graphing calculator and it didn't behave how I expected.
How so ?
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Let $G$, $G'$ be abelian groups, and let $\varphi \colon G \to G'$ be an isomorphism of groups. Prove that:
[
G_t \cong G'_t.
]
Halex
I'm suspecting the same function works
but would have to restrict both domain and codomain
and show it is still well defined
can anyone confirm?
What's Gt ?
Oh, sorry, should have defined that first
Gt is a group in which every element has finite order.
It is called, Torsion group
Oh ok, I'm sorry I can't help
Actually Can’t you prove that phi(Gt) = Gt’ ?
You know that phi(Gt) is a subgroup cause phi is an isomorphism.
You can prove that any element of phi(Gt) is of finite order using phi^-1, so that gives you phi(Gt) included Gt’.
@meager ore Has your question been resolved?
I was afraid I had to prove that phi(Gt) is a subset of Gt’, and phi^{-1} (Gt') is a subset of Gt
Don’t phi(Gt) and Gt’ have the same cardinal ? (as Gt)
would it prove phi is well defined?
since phi is surj and Gt is a subset of G, phi(Gt) = Gt
Soo you're done ?
I'm sorry I haven't done abstract algebra in years, so perhaps there is some fancy theorem out there
But this looks like it works !
wouldn't this mean that Gt = Gt'?
Isn't f(Gt) = Gt as well? since f is surj
No !
am I confusing things
cause the image of f is not in G, it's in G'
No no you just proved that f(Gt) = Gt'
and since f is an isomorphism, you're done
yes that's a given
Andy
!occupied
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@meager ore Has your question been resolved?
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hi again
so im trying to find the inverse of a 3x3 matrix
and im doing the row operations
but i dont know how to continue from where im at
i will take a photo of where im at and send it
i want to turn this 2 into a 0
but i dont see how i can do that without turning that 0 to something non-zero
oh nvm
i multiply the second row by -2 and add it
whoops
.close
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The referential sets in Russell’s paradox has a contradiction Like for example R = set of x Such that x is not an element of its self
We can use first order set logic
I dont know how to prove that
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When it is mentioned as "an isosceles triangle PQR" without mentioning which side is the base or which angle is opposite to it, what am I supposed to consider?
That Q is the angle opposite to the base?
is there nothing else at all?
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'A frog starts on the line at x = 0 and chooses either to go to the right 2 units, to the right 1 unit or to the left 1 unit with an equal probability of them happening. What is the probability that, in 6 turns the frog is at x = 6?'
im lowkey trash at probability and idk what to do..
here is how you can rephrase this problem:
every turn, the frog slides 2 to the left unconditionally, then with a 50% probability chooses to leap 3 to the right
after 6 turns:
- how far would the leftward drift have taken the frog?
- how many leaps of size 3 would place it at x=+6?
uhhh it would have to go to the right 3 times? then do nothing for 3 other turns
and then these events can happen in different orders? i think
... no
leaping right 3 times would put it at -12 + 3*3 = -3 and not 6
in fact you should have gotten that the frog has to leap EVERY turn
oh wait i think i read what you wrote wrong sorryy
oh yeah i see
so.. then what do i do? the probability of this happening should be 1/64
congratulations you just got the answer
'A frog starts on the line at x = 0 and chooses either to go to the right 2 units, to the right 1 unit or to the left 1 unit with an equal probability of them happening. What is the probability that, in 6 turns the frog is at x = 6?'
oh so the frog has 3 choices.
that complicates things a bit...
think of it as there being a constant 1 push to the left, so find the number of ways of it not going anything, its either the frog do nothing fully, the frog go left once and right twice, or the frog goes left twice and the right 4 times
for the first way, ill let you do it
for the second way, choose 2, then choose 1 from the remainding
for the third way you can choose 2
wait how do you guys think of these..
what did i even write in the first time 😭
magic
i am scared of people that can do combi
anyways thanks! ill go think about it
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i suck at combi so dont fear me :p
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Can someone check 12)b)
Is the final answer correct?
!msgdel
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How does a graph of this function look?
dense set of points on y=0 and dense set of points on y=1
1 for almost all values, and infinite number of jump discontinuities for all the irrational numbers?
kinda but its not just infinite number but dense at any point.
on each segment of x there are rationals and irrationals. So there is no segments its dense set of points
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How to do qn b
What is the objective and what have you tried so far?
I've tried doing the cross method but it doesnt seem to work for me
What is the objective?
factorise it
how many options of cross method did you checked?
wym
Do you know the AC method of factorization?
there's three formulas right?
a^2-b^2
a^2+2ab+b^2
a^2-2ab+b^2
isnt there 3?
These are three identities
im talking about cross method
there's also completing the square and quadratic formula I suppose
oh Im not really sure on that
I mean luckily enough for you, since you know these identities, it does fit one of these
what would you have done tho
HitenTandon
uh I dont really understand this
Which part?
what's the point of multiplying 1 with the constant 4
Have you considered the quadratic formula or, writing it as a perfect square
no but I dont think that formula applies here tho
it does
The proof is a bit complicated but I can go over that if you want to
how
sure
Solve for x in terms of y
Ok, if we factorize this expression completely can you see that the answer would be of form $(ax + by)(cx + dy)$?
HitenTandon
but there's another term as xy
is this like the (a+b)(a-b)
In what sense?
@fossil wagon do you know that in cross method you sometimes need to check different factorizations?
probably the way ita written
what are the 4?
It is product of two binomials but the similarity ends there
ill just drop example
ok so how do I go about doing it then
yeah I've tried that but you said that there are 3 other types
Can you expand (x+y)^2 for me
show it because you made mistake somewhere
HitenTandon
x^2+2xy+y^2
good, now try something similar here
true
you mean the qn I'm stuck in is similar?
HitenTandon
yes
HitenTandon
How does what happen?
how would you get acbd by multiplying x^2 and y^2
Not them
their coefficients
HitenTandon
oh ok yeah I get it now
Ok cool
So yea that's what we were doing
yeah so
$x^2 + 4xy + (2y)^2$
can you write the middle term into something like +2ab in the original identity?
Oh hey @slow thorn nice meeting you again
hi
Something like this?
oh yeah because the b value is 2y right?
yes
Yep
Alr if your question has been solved, use .close to close the thread
wait that's it?
HitenTandon
Sure
I changed it after you guys taught me
That's one step before the answer
then how does part b not have a second step then
correct
it does
You ve almost found it man, true
you didnt finish it
It does, we want you to do it
compress it to (a+b)^2
All you have to do is find what a and b are
for a its (x-3)^2?
Yes
Nice
for b its (x+2y)^2?
YES
Now do the same for b)
🎊
You're welcome
High five
can I add yall
high five
how do I close this again its been quite a while since I used this server
Use .close
Closed by @fossil wagon
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Hi, need some help with this
How about we start by assuming $x = 0.5^{\frac{t}{40}}$?
Suika
It will make the equation easier to write
👍
And then the other one will be sqrt x
No, assume $x = 0.5^{\frac{t}{20}}$
Suika
This one is right
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can anyone explain the differnce between increasing and stricftly increasing? and also, given then interval [a,b], why are endpoints excluded for increasing wheras included for strictly increasing?
Increasing has that non-strict Inequality defn and strict has the strict Inequality defn.
@young mortar Has your question been resolved?
Idk about the endpoint thing. If a function~$f$ is strictly increasing, that means that $x<y\Longrightarrow f(x)<f(y)$. But if $f$ is just increasing, that just means that $x<y\Longrightarrow f(x)\le f(y)$
depression
strict is a<b and f(a)<f(b)
The function $f(x)=1;\forall x$ is increasing for example
depression
But it's not strictly increasing
yes increasing means non-decreasing from waht ive seen
but im unsure about the endpoints
consider y=x, for interval [0,1] its strictly increasing, but in that same restriction, its only increasing from (0,1)
I feel like if you allow closed intervals for increasing function and the values at the endpoints are equal, it forces the graph to be a trivial horizontal graph. That's probably one of the reason.
Where have you read this thing about the endpoints though?
It's quite new (and a little weird) to me
On literally any domain with an order on it
Oh sorry
im saying y=x is restircted
You're talking about the function "y = x" on the restricted interval [0,1]
My point still stands though, f(x) is also always increasing (as well as strictly increasing)
yes i agree
Oh you mean bounded?
yeah
like a piecewise function
which is what the question was
we werebasically asked for what values was a piecewise function increasing vs strictly increasing
My guess is that that definition (with the (a,b) mentioned) is to do with discontinuities
!original
Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.
Damn, there's a bot message for this?
For future, "restricted" means something completely different to "bounded"
useful
alr
Yh I did think this and was a little confused lol
do you mean differntiability?
That is a related theme, yes
what i inferred for the reasoning is that, increasing would refer to a interval where the deritive is >=0
I'm looking on the Wikipedia article on monotone functions and the only bit where they didn't include endpoints in a given domain had to do with continuity, so...
but what ive seen online hasnt been that defintion so idrk
If you're working from that definition (i.e. from the derivative), then (a,b) instead of [a, b] kind of makes sense
Because a derivative has to be defined as a limit from both sides
Not necessarily, y=-x^3 is strictly decreasing but has 0 derivative at 0
If it's only defined on one side and not the other, it's a lot more messy
Sorry meant to reply to this message
i said increasing, not strictly increasing (which is also why for strictly increasing, the endpoints would be included)
Yeah it's not increasing anywhere
as it isnt realted to differnetiabillity
and instead relies on the original function
"If the derivative is non-negative everywhere, then the function is increasing everywhere"
It's strictly decreasing everywhere. If the derivative is 0 then you can't say anything about if it's increasing
... is what he meant
*first derivative more precisely, I think.
That is implied
That's what derivative means
I don't think I've ever heard someone talk about a "derivative" to mean any higher-order derivative
But yeah this is correct afaik (assuming the derivative is defined everywhere)
Back to what I think you're actually asking, you can only say that a function is increasing if you also specify what domain you're talking about. To say "which values is this function increasing on" basically means "on which intervals is this function increasing"
But yes it can get quite murky
And that's why they probably did that
A function can be (strictly) increasing on [a,b] and (strictly) decreasing on [b,c]
And it doesn't really mean anything to say that f is increasing/decreasing at b
just on its own that is
But you can get around a lot of those problems by using open intervals (intervals without endpoints)
i've looked some more and I think this is a case where the way to define something as inceasing for my class is different to i assume the accepted convention which is why the endpoints are excluded for an interval, rather than included which seems to be the accepted defintion. This i assume is because we utilise a lot of piecewise functions, and for assement purposes wanted to distinguish between students that understood this distinction. anyways thanks for the help everyone
.close
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Fwiw the normal definition doesn't care if there are endpoints. It makes perfect sense either way
i mean, given the same piecewise function, the endpoints are considered included as they satisfy a<=b f(a)<=f(b)
but our class defines it as f'(x)>=0
hence the discrepency
and since they cannot be differentiated at these points
they aren't included
Oh sure yeah. I don't want to confuse you more so I won't labor the point. But a function having nonnegative derivative means that the function is increasing, but not the other way around. An increasing function has a different meaning and does not have to be differentiable
But yeah that's fair enough
Yeah I got that point, its just that for our purposes it doesn't go beyond that consideration. ty tho 👍
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yo guys
danke
OMG
bro
finally
u spawned
A sports aircraft Gamma passes point A (10|10|0.8) at 10:00 AM and two minutes later passes point B (15|7|1). One unit in the coordinate system corresponds to one kilometer. The aircraft flies at a constant speed.
a) Set up the equation of the line g along which the aircraft Gamma is flying. Explain the connection between the line parameter and the corresponding time interval.
omg spezi is here
i will despawn
today gonna be a long day bro
so basically i dont understand like
explain between the line parameter and the time interval
like
yeah
hello?
You have a start position vector and a direction-of-travel vector
yeah
i can have the direction vector
ik but
what is the connectivity of line prameter and time interval
idk what they mean
Well what line do you get for g?
e.g. if your direction vector comes straight from B - A, that vector is how far the plane travels in 2 minutes
uhh
i cant calculate that rn im on mobile
oh
so
every 2 minutes theres a point
You can use whatever for the scalar
ok so uhh
You can use t, that's not a problem
My point is, the question asks for the relationship between that scalar and the time elapsed
yes
so
1 scalar is 2 minutes
:02 on the clock
yee
ok thats cool
okay man
my heart is pounding
tomorrow i got my test
30 minute test
im so nervous
i cant even do this shit
@lyric scroll Has your question been resolved?
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So rank of the matrix and rank of augmented Matrix should not be same
So except b option all other options are giving unequal rank
@molten bay Has your question been resolved?
can you show your work?
Thats not proper row echelon form. If you make the k terms 0 then the last row has to be all zeros
Well you need REF to get rank. The determinant would work too tho yes
The determinant method doesn't account for all cases
Why not. You can just set it up as a polynomial and find the roots
It can actually get lengthier than the regular method
Because in A|B you can have two 3X3 matrices, right?
This makes sense
Closed by @molten bay
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The rank of A|B will always be greater than or equal to A
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,rotate
Is this wrong
how to factorise x⁴+x²+1
i heard it's pretty famous
You'll have to ask in a different channel, you've lost this one 
And is that $\pdv{f_2}{p_2}$ you're trying to work out? If so, what's $f_2$?
@tribal temple
which one
#help-18 just go here and start typing
Funny username
Lol chartbit to the rescue 😌
I would guess maybe that $f_2 = y - p_2 q_2$ maybe(?)
@tribal temple
In which case, it would work out as they have 
You'd get 0, if q2 doesn't depend on p2 
Is this possible
You'd have to give me a little while to get back to you
on the move atm
Thxxx
Yep that's perfectly fine
sorryyyy for the wait 
Dw thanks
@tiny gate Has your question been resolved?
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What does it even mean to reduce a recursive language to a recursively enumerable one (like the HP)? Given that NPH includes some RE \ R languages, it would mean that any NP language is reducible to some language isn't even decidable, how would that work?
CS?
Yea, is it wrong to put it here, I've received help before so I put it up
No its ok but you might wanna try also there https://discord.com/channels/268882317391429632/1313711459385081876
There's no way to put anything in there
Just that here its mostly math thing but i hope you will find someone that can help you
It's closed
Now it should be unlocked

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.reopen
✅
.close
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I need help on the 1st and 3rd ones
@wicked beacon Has your question been resolved?
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