help-49

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plucky prairie]

not sure how to solve this either

[unique juniper]

linear equation

distance travelled is the same

so use

(velocity of aircraft - velocity of wind) * time_2 = (velocity of aircraft + velocity of wind)*time_1

is your issue resolved?

[plucky prairie]

ive never seen it doen like that

i thought you were soppossed to do
time(vel of aircraft + vel of wind) = distance
time2(vel of aircraft - vel of wind) = distance

and then eliminate

@unique juniper

[unique juniper]

thats the same thing bro 😭

[plucky prairie]

oh alr

[unique juniper]

dont think too hard but its the same thibg

then solve for velocity of wind you get your answer

[plucky prairie]

wiat i just relised

i still had a after addign the equations

thats why i got it wrong

instead of 2a

.close

[midnight plank]

Channel closed

Closed by @plucky prairie

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cursive scaffold]

do i use the product rule on x Sqrt 36-x^2?

[buoyant yoke]

Yes

Or you pull the x into the sqrt then you only need the chain rule

[cursive scaffold]

how would i do that?

distribute or somethin?

.close

[midnight plank]

Channel closed

Closed by @cursive scaffold

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[civic sky]

really simple problem here

[civic sky]

i have a matrix L

and i know Lx=x

how do i solve for x

[midnight plank]

@civic sky Has your question been resolved?

Channel closed

Closed by @civic sky

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[thorn hinge]

my answer key says that this limit approaches 0 but when u test paths like x,0 0,y and x,-x it doesnt all give that the limit approaches 0 so shouldnt it just be dne ?

[lyric charm]

x,0 0,y and x,-x
you cannot drop the brackets here

but also all of these paths you took go to (0,0)

while this has (x,y) -> (2, 3)

[thorn hinge]

am i trying to get it to (2,3) at the end ?

[thorn hinge]

oh yeah my bad

[lyric charm]

well (x,y) approaches (2,3) so yes

[thorn hinge]

oh wait

oh i plugged in 0,0

when u plug in 2,3 it becomes 0/7 so thats why the limit is 0 right ?

[lyric charm]

don't drop the brackets!

but yes.

[thorn hinge]

for this other limit when i plugged in (1,2) it gives 0/0 so 0 would i just stop there or do i check the other paths like (x,0) (0,y) etc...

or what paths would i have to use to check would it be (x,2) (1,y) in this case ?

[lyric charm]

do i check the other paths like (x,0) (0,y) etc...
again, if you try the path (x,0) as x -> 0 you don't approach (1,2)...

[lyric charm]

that'd be a good starting point

remember however that even if you check a million paths it will not be enough evidence to show the limit exists

[thorn hinge]

i got it now thank you so much

.close

[midnight plank]

Channel closed

Closed by @thorn hinge

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quaint field]

dumb question but what do I do if my latex goes off the screen

[quaint field]

[
0^\infty ; 10 ; 40^{n_1} ; 411 ; 40^{n_2} ; \dots 411 ; 40^{n_k=1} ; \textrm{<B} ; 0^\infty ; \rightarrow ; 0^\infty ; 40^{n_1} ; 4 ; 40^{n_2} ; \dots 4 ; 40^{2k+2} ; \textrm{<B} ; 0^\infty
]

[grand pond]

Peacemaker II

[quaint field]

also do I need all these semicolons for the spaces?

[lyric charm]

what... are you even trying to write?

[buoyant yoke]

if its going off the screen, consider using a linebreak

[quaint field]

a turing machine rule

[quaint field]

I would like it on one line if possible

[lyric charm]

can you describe it in plain English

[quaint field]

https://wiki.bbchallenge.org/wiki/Directed_head_notation

I don't really use latex so any advice on how to format this is helpful

[quaint field]

the link describes it better than me but basically it represents the tape of a turing machine, and the arrow shows a rule for how the tape changes

I have these rules so far but they are getting cut off:
[
0^\infty ; 10 ; 40^{n_1} ; 411 ; 40^{n_2} ; \dots 411 ; 40^{n_k=1} ; \textrm{<B} ; 0^\infty ; \rightarrow ; 0^\infty ; 40^{n_1} ; 4 ; 40^{n_2} ; \dots 4 ; 40^{2k+2} ; \textrm{<B} ; 0^\infty
]
[
0^\infty ; 111 ; 40^{n_1} ; 411 ; 40^{n_2} ; \dots 411 ; 40^{n_k=1} ; \textrm{<B} ; 0^\infty ; \rightarrow ; 0^\infty ; 40^{n_1} ; 4 ; 40^{n_2} ; \dots 4 ; 40^{2k+2} ; \textrm{<B} ; 0^\infty
]

[grand pond]

Peacemaker II

[quaint field]

!close

.close

[midnight plank]

Channel closed

Closed by @quaint field

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wraith flower]

hello , I need some help simplifying/factoring a function

[wraith flower]

Like that

After doing this first step Im struggling to see what I need to do next

[slender walrus]

multiply numerator and denom by (x+1)^(1/2)

[wraith flower]

thank you

after that it was easy to see what else I needed to do

.close

[midnight plank]

Channel closed

Closed by @wraith flower

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[ionic magnet]

How many times is the volume of one cylinder larger than the volume of the 2nd cylinder, the height of which is reduced by 60%, and the diameter - by 50%?

[grim vector]

Whats the volume of cylinder?

[flat veldt]

The formula

[ionic magnet]

$$ V = piR^2 h $$

[grim vector]

Ok

\pi

[grand pond]

www.

[ionic magnet]

okay let it be as it is

so

[grim vector]

Ok

[grand pond]

David

[ionic magnet]

i know that thing

[ionic magnet]

thank

you

[flat veldt]

First step

[ionic magnet]

that $$V1/V2 = (a1/a2 )^3$$

[grand pond]

www.

[last slate]

??

[flat veldt]

Express the diameters and heights in terms of each other

[ionic magnet]

wdym

?

David

[flat veldt]

Let's call the height of the bigger (original) cylinder $h_1$

[grand pond]

David

[flat veldt]

and let's call the height of the smaller cylinder $h_2$

[grand pond]

David

[flat veldt]

Then the diameters $d_1$ and $d_2$

[grand pond]

David

[ionic magnet]

yes

[flat veldt]

Find relationships between
the diameters $d_1$ and $d_2$ like $d_1$ = f($d_2$)
And the same for heights $h_1$ , $h_2$

[grand pond]

David

[ionic magnet]

$$ (10h_2 -6)/10$$

[grand pond]

www.

[flat veldt]

Are you sure?

[ionic magnet]

$$(2d_2 -1)/2$$

yes

[grand pond]

www.

[ionic magnet]

$$h_2 - 6/10$$

[grand pond]

www.

[flat veldt]

You forgot it says reduced by 60% of h_2

[ionic magnet]

yes

h_2 - 6/10

same as

[flat veldt]

$h_2 = h_1 - \frac{6h_1}{10}$

[ionic magnet]

why?

[flat veldt]

Of means times

[grand pond]

David

[flat veldt]

Remember we selected h_1 as the original

[ionic magnet]

what next

[flat veldt]

Factor h_1

$h_2 = h_1(1- \frac{6}{10})$

[grand pond]

David

[ionic magnet]

yes

[flat veldt]

Then simplify and do the same for d_1 and d_2

[ionic magnet]

$d_1 = (2d_2 - 1)/2$

[grand pond]

www.

[flat veldt]

Try again

You forgot it's 1/2 of d_1

[ionic magnet]

i dont understand

[flat veldt]

Of means times

50% of d_1 means 50/100 x d_1

[ionic magnet]

$d_1/2$

[grand pond]

www.

[flat veldt]

Yeah

Remember the variables matter

Now, V = $\frac{\pi d^2 h}{4}$

[grand pond]

David

[flat veldt]

Then express v_1 and v_2 in terms of their variables

[ionic magnet]

$V= (pi * (d_1)/2) * h_1(1-6/10))/4$

[grand pond]

www.

[flat veldt]

Not quite

This is V_2

But you forgot d is squared

[ionic magnet]

i give up

its too hard

[flat veldt]

It's almost done it's too late to give up.

[ionic magnet]

uhh

i am messed up actually

i dont know

can u express V for me please

[flat veldt]

$V_1$ = $\frac{\pi d_1^2 h_1}{4}$

$V_2$ = $\frac{\pi d_2^2 h_2}{4}$

[grand pond]

David

David

[flat veldt]

@ionic magnet

Then replace d_2 with its d_1 value and h_2 with its h_1 value

[ionic magnet]

ahaha

$Then replace d_2 with its d_1 value and h_2 with its h_1 value$

[grand pond]

www.

[ionic magnet]

$V_1 = (pi*((d_1)^2)/4*) h_1(1- \frac{6}{10}))/4$

[grand pond]

www.

[ionic magnet]

i very tired dude

5 mins and ill sleep good

💤

[flat veldt]

You only replace in v_2

[ionic magnet]

how

[flat veldt]

.

$d_2$ = $d_1/2$

[grand pond]

David

[midnight plank]

@ionic magnet Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dense warren]

Hello everyone, I’m not sure where to go about this after subbing in sin. I think what is stumping me is the 4 multiplied by sin

[hearty rune]

try x=1/2 sin(theta) instead

[dense warren]

Where did you get x=1/2sin theta from?

[hearty rune]

you want the 4 to go, (1/2)^2=1/4

1-4[1/4 sin^2]=1-sin^2

[dense warren]

Ohhhhh i see now okay thank you so much

.close

[midnight plank]

Channel closed

Closed by @dense warren

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plucky sleet]

What do you do here I have no clue

[floral junco]

the graph passes through the given points

[fallow scarab]

plug your points and plug x=-10 and x=-4 into p(x) to get 3 equations and 3 uknowns

[plucky sleet]

Wouldn’t I have 4 equations

[dusk pier]

How so?

[plucky sleet]

2 points and x=-10 and x=-4

[dusk pier]

Actually, no.

One of the points produces the same result as one of the x-values.

Do you see which ones?

[fallow scarab]

do the calculations and see

[dusk pier]

Note that ||p(x) is symmetric about x=-5||.

Wait a minute.

Oh, this is funny.

[plucky sleet]

Wouldn’t there only be 2

Equations

[dusk pier]

Yeah.

[dusk pier]

Because of this.

[plucky sleet]

Oh this is easy nvm

[dusk pier]

Yeah, dead giveaway.

[plucky sleet]

Alr thanks

.close

[midnight plank]

Channel closed

Closed by @plucky sleet

Use .reopen if this was a mistake.

[dusk pier]

Just checking, did you guys get ||372||?

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[agile snow]

hey guys what was that website which allows u to graph linear quesitons

[agile snow]

eqautions

[cerulean solar]

Desmos ? 💀

Is that what you’re talking about

[agile snow]

yea

thanks

thank

-close

.close

[midnight plank]

Channel closed

Closed by @agile snow

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gusty vortex]

hello i have some idea of where to start but im still a but confused

[foggy inlet]

oh lol someone had this same exact question

[gusty vortex]

actually

[cobalt roost]

lmao looks like calc bc

[gusty vortex]

ab

[cobalt roost]

darn i was close

[gusty vortex]

almost got it

[foggy inlet]

so if they want to find f

but you have f'(x) atm what do you do first

[gusty vortex]

you take the antideriv of fprime(x)

maybe

idk hgow to do with graph tho

[foggy inlet]

yep

so on a graph

[gusty vortex]

OMG

[fringe pine]

we deadass have the same question for hw 😭 😭 😭

[foggy inlet]

how do you find an anti?

[gusty vortex]

its the area under the curve

[foggy inlet]

yes

[gusty vortex]

actually

like in the same slides

or just the same questions

[fringe pine]

nah

[fringe pine]

same question

[foggy inlet]

aight so what do you do next?

[gusty vortex]

i think thats where im stuck

[fringe pine]

my teacher chose the 2017 ap calc ab frq

[gusty vortex]

oh so thats what it is

[tame badger]

Yo

[foggy inlet]

ok so what do integrals show in general?

[tame badger]

Are any of yall good at geometry?

[gusty vortex]

the antideriv

[fringe pine]

i gotchu

[foggy inlet]

well like what does the area show 💀

[tame badger]

Thx brother

[gusty vortex]

uh

it shows the

wait

[foggy inlet]

or wait lemme be more specfic

what does the area between (-6,-2) mean

[gusty vortex]

brooooooo

ur gonna skull emoji

now im scared

[foggy inlet]

srry

ight but what does ^^ mena

[gusty vortex]

its Fb-Fa?

[foggy inlet]

yes

[gusty vortex]

ok

now what

[foggy inlet]

so what does this mean

lol

nvmrind ill tell you

its the difference between those numbers

[gusty vortex]

alr

[foggy inlet]

but so the issue is that we don't know the y

[gusty vortex]

right

[foggy inlet]

like where it starts or stops

sorry imma steal this

but

[fringe pine]

😭 😭

[foggy inlet]

but we know what f(-2)=7 exactly is right?

[gusty vortex]

yes

[foggy inlet]

so we can ultize this to solve for -6 and 5

[gusty vortex]

how would u use that

[foggy inlet]

so lets set up an integral

limits -6 and -2

[gusty vortex]

ok

[foggy inlet]

lmk what you get

[gusty vortex]

4?

so what is that

f(6)?

or is there more steps

[fringe pine]

*-6

[gusty vortex]

oh yeah

[fringe pine]

that was basically it

for f(-6)

[gusty vortex]

so you just take whatever number is given and use that for the limits?

[foggy inlet]

yeah so you'll get f(-2)-f(-6)=?

[gusty vortex]

oh

[foggy inlet]

well no

[gusty vortex]

so 7 - 4

[fringe pine]

OH FUCK I DID MINE WRONG 😭 😭 😭 😭

[foggy inlet]

we only use f(-2) because it contains the actually

the acutal

plot

[gusty vortex]

so what if it gave us f(-3) = 7 instead of f(-2)

would we use -3

[fringe pine]

omg we’re in the same grade

(i’m taking apush too)

[foggy inlet]

f

[gusty vortex]

that was from last year

[foggy inlet]

that class sucks

[foggy inlet]

yes

[gusty vortex]

i forgot to take out of bookmarks

[fringe pine]

it’s fun 😭 😭 i love my teachers

[gusty vortex]

HELL NAH

my teacher called me out in front of my whole class cus i didnt know what the people threw at police during the stonewall riots

and she said i would fail the ap test

[foggy inlet]

my teacher yelled at us bc we all missed an "easy " question

[gusty vortex]

what was the question

[foggy inlet]

i forgot

i alr graduated

[fringe pine]

STONEWALL RIOTS? 😭 😭 😭 (i’m in ww2)

[gusty vortex]

shoot

[gusty vortex]

ww2 is so nice

not like that

like easy to learn

its just like Zimmerman telegram

ot maybe that was ww1

idk

[fringe pine]

my teachers so sweet. she gave us all cookies and had them plated on every table so we can watch each other’s project presentations. she called me out in the nicest, funniest way possible for eating before the presentation started

[gusty vortex]

broo luckyy

my teacher was a bitch

but anyways

[gusty vortex]

.

why is it -2 - (-6)

cus ur going

ohhhh

b-a

[fringe pine]

yeah

[foggy inlet]

yes

[gusty vortex]

k so then for f 5

[foggy inlet]

f(-2)-f(-6)=?

[gusty vortex]

3

[foggy inlet]

so subsitute vaules for this

[gusty vortex]

right

[foggy inlet]

and youll get it

yes

[gusty vortex]

k bet

[foggy inlet]

nice

[foggy inlet]

wait now

no

no

lol

for -6

[gusty vortex]

i was boutta start writing

from f(-2) to f(5)

right

for f(5)

4pi/2

2pi

plus

[fringe pine]

*-2pi

under the x axis remember?

[gusty vortex]

oh right

so 3-2pi

for that integral

then

[foggy inlet]

hm

for the difference yes

[gusty vortex]

3-2pi-7

for f(5)

[foggy inlet]

hm

nope

not exactly

[gusty vortex]

AHHHHHHHHH

[foggy inlet]

so

f(5)-f(-2)=3-2pi

[gusty vortex]

k..

[foggy inlet]

ye

[gusty vortex]

thats the answer?

[foggy inlet]

well

its the setup to it

cuz we know f(-2)=7

so f(5)-7=3-2pi

so f(5)=10-2pi

[gusty vortex]

rightttt

ok yeah i remember now

he did that in class

[foggy inlet]

ye

u need anything else?

[gusty vortex]

ok i think that all for tonight 😭

[foggy inlet]

ight

[gusty vortex]

thanks for the help

[foggy inlet]

u a senior?

[gusty vortex]

junior

[foggy inlet]

oh

nice

good stuff

[gusty vortex]

thanks man

[foggy inlet]

remember

its jsut gets harder from there

lol

[gusty vortex]

i thought u were boutta inspire me

[fringe pine]

not rlly

[gusty vortex]

i hvnt even taken sat yet broooo

[fringe pine]

second semester calc for me is easier

[gusty vortex]

and i forgot to sign up for the march one

[fringe pine]

u don’t have to most colleges don’t require it anymore

[gusty vortex]

i just want to

[foggy inlet]

i mean life in general

lol

[gusty vortex]

for my mental

my dad says he will buy me a car if i get 1550 plus

[fringe pine]

if only i had that money 😭 🙏 🙏

[gusty vortex]

lowkey it is expensive

[fringe pine]

if only my dad had that money 😭 🙏 🙏

[gusty vortex]

collegeboard just greedy

[gusty vortex]

just lock in

rags to riches

[fringe pine]

i paid $60 for 4 ap tests 💀

[gusty vortex]

also not like an expensive car

prolly like used 2k dollar car

[foggy inlet]

its still recommended

[foggy inlet]

cheaper long term

[gusty vortex]

i think mine are free

[fringe pine]

i go to a ghetto school (not hood) so we don’t got the funds

[gusty vortex]

or my school pays

oh fr

[foggy inlet]

i still rec it bc its not rec but itll still look good

if you have a good score

if its bad

dont lol

[fringe pine]

i got a bad score on the psat ☠️

i got in the 900s for math and english

[foggy inlet]

cooked ngl

[fringe pine]

for some reason the second parts of both english and math got significantly worse

[fringe pine]

I DID NOT COOK 😭 😭 🙏 I DEADASS FORGOT HOW TO DO SYSTEM OF EQUATIONS MID TEST

[foggy inlet]

you still need help?

i think your channel got deleted

[fringe pine]

idk why it deleted

but yeah

[foggy inlet]

its bc u were to slow to solve your problem

jk

[fringe pine]

i could use this channel right?

since we reunited here

[foggy inlet]

sure itll be fine

how long are you gonna take to solve the prob?

im plannign to get a drink

[fringe pine]

drink up now 😭

we’ll be stuck for a while

[foggy inlet]

aight

jsut call me or sum when u r ready

idk how long ill be gona

cuz i dont do notifs on my phone

[fringe pine]

got it

[foggy inlet]

Done?

[midnight plank]

@gusty vortex Has your question been resolved?

[fringe pine]

i locked out

☠️

[fringe pine]

i have a test on it friday, and an apush test tmrw so ima study for apush, sleep, and study for calc later

[gusty vortex]

Get some sleep

I need sleep too

Ok I figured the first one out now there’s

Whatever bro

If I fail I fail

Good night guys

[foggy inlet]

Alr gl then

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wind oxide]

alfohers is crazy

[wind oxide]

anyhow

simplified it to proving $f(x,y) = 1+xy-x^2-y^2 >0$ in the interval $0 <x,y <1$ after substituting $x=|a|, y=|b|$

[grand pond]

rak³en

[wind oxide]

problem is i dont think my statement is true actually

<@&286206848099549185>

HELLOOO!?

bro where is everybody

[midnight plank]

@wind oxide Has your question been resolved?

[dawn dagger]

Are a and b complex cause there is a bar over a you didnt seem to have considered

[wind oxide]

yes a and b are complex

[wind oxide]

i did consider it?

if you square both sides

(i am proving it backwards)

u get |a+b|^2 < |1-a^c b|^2

which is |a|^2 + |b|^2 + 2Re(a b^c) < 1 + |a|^2 |b^2| + 2 Re(a^c b)

so all you gotta prove is-

OH WAIT

thanks @dawn dagger i am so stupid man

[wind oxide]

.close

[midnight plank]

Channel closed

Closed by @wind oxide

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[mystic dune]

how do you do b??

[lyric charm]

what are the smallest and largest values for x that could possibly make sense?

geometrically speaking

[mystic dune]

something above 0 and 100-2x for the largest??

[mystic dune]

i don’t know 😭

[lyric charm]

... i think you're overcomplicating it a bit here

first off: x is a length, yes?

what's one thing lengths cannot be?

[mystic dune]

negative ?

[mystic dune]

oh is itt??

[lyric charm]

indeed

so x must be >=0 among other things

[mystic dune]

is y the height then?

[lyric charm]

there's no y

[mystic dune]

ohh yeahh

Oh

[lyric charm]

when i say length i just mean distance

[mystic dune]

oh okoko

[lyric charm]

wherever it might be in the picture

note that the dimensions of your box at x by 70-2x by 100-2x

the other two also can't be negative, yes?

[mystic dune]

mhm

[lyric charm]

70-2x >= 0

solve this for x

[mystic dune]

X <35

right

[mystic dune]

Wait what about 100-2x

isn’t it bigger ??

[lyric charm]

<= but yes

[lyric charm]

it's bigger, and thus redundant

whenever 70-2x is nonnegative, 100-2x will be also

[mystic dune]

what does that mean

[mystic dune]

would i still get the question right if i wrote x < 50 then

[lyric charm]

no

x<=35 is more restrictive than x<=50 so you have to write 0<=x<=35

[mystic dune]

why do i have to make it restrictive

[midnight plank]

@mystic dune Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[real glacier]

after a markup of 35% an appliance is on sale for $36.45. what was the cost before the markup?

[real glacier]

the price would have went down right making it 27, but im lost on the wording saying markup

<@&286206848099549185>

.close

[midnight plank]

Channel closed

Closed by @real glacier

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[molten bay]

Is this correct?

[polar star]

how did u go to cos(theta) = ....

[molten bay]

I don't know someone wrote this

@polar star

Cos theta=<sin^2x how?

[polar star]

cos(2x) = sin^2(x) is not correct in the first place

[molten bay]

Cos2x=1-2sin^2x

Cos2x=2cos^2x-1

Sinx=√((1+cos2x)/2)

[polar star]

cos(2x) = 1-2sin^2(x)
1-cos(2x) = 2sin^2(x)
√((1-cos(2x))/2) = sinx

[molten bay]

So whole solution was wrong?

[midnight plank]

@molten bay Has your question been resolved?

Channel closed

Closed by @molten bay

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shut canyon]

Can we create an algebra with an infinity of axioms?

[shut canyon]

With infinitely many axioms, all the axioms possible. I guess not because this is a system complex enough to contain arithmetic, and so there would be axioms outside the system.

A sort of totality.

[midnight plank]

@shut canyon Has your question been resolved?

[lilac sage]

If this means infinite axioms, then I believe it depends if your axioms need to be independent

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[young spire]

Q 10

[lyric charm]

ok just to transcribe that for my own sake at least:

\textbf{Q10}. If the roots of the equation $x^3 + px^2 + qx + r = 0$ are consecutive terms of a geometric progression, show that $q^3 = p^3 r$. Show that this relationship is satisfied for the equation $8x^3 - 100x^2 + 250x - 125 = 0$ and solve this equation.

[grand pond]

Ann

[young spire]

i did the vieta formula

i used the roots as $alpha/beta$ $alpha$ and $alpha beta$

[grand pond]

Storm09

[lyric charm]

$\alpha/\beta$, $\alpha$ and $\alpha\beta$

[grand pond]

Ann

[lyric charm]

ok so show what that gave you

[lyric charm]

is there a reason why you chose not to separate the roots with commas in line 4?

but ok

do you see how q = -alpha*p?

[young spire]

i dont get the p part

[lyric charm]

"the p part"?

[young spire]

ye the exponent

why is it -alpha

[lyric charm]

what exponent?

i said $q = -\alpha p$.

[grand pond]

Ann

[young spire]

so why is it negative

o nvm

ye i c

[lyric charm]

you also see that r = -α^3, yes?

[young spire]

ye

[lyric charm]

you are almost there

[young spire]

do i have to make an equation with p the subject

or do i sub from the equation given

[lyric charm]

your goal is q^3 = rp^3

you know q = -alpha*p

you're like two steps away

[young spire]

do i sub for q and r

[lyric charm]

i don't know what you mean by that

but it's likely not what i was thinking of.

[young spire]

from here

[young spire]

sub into here

[young spire]

and here

[lyric charm]

i guess that's fine-ish yes

i would more simply just cube both sides in q = -alpha*p to get q^3 = -alpha^3 p^3

[young spire]

o

and then alpha cubed is r

[lyric charm]

-r

[young spire]

i meant -alpha cubed

[lyric charm]

you should be more careful with that shit

a missed minus sign can screw you over big time

[young spire]

i forgot to type it

.close

[midnight plank]

Channel closed

Closed by @young spire

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[graceful ferry]

Prove/Disprove: if $a_n$ converges to a finite limit then $\lim_{n \to \infty}(\frac{a_n}{n})^n=0 \
Proof: $a_n$ converges therefore $a_n$ is bounded. let's look at the expression $(\frac{a_n}{n})$. $\lim_{n \to \infty} \frac{a_n}{n} = \lim_{n \to \infty} \frac{1}{n} \cdot a_n = 0$ (a series converging to zero multiplied by a bounded series, converges to zero) using the definition of limit let's choose $\epsilon = 1$ there exists N such that for all $n \geq N$ we get $|\frac{a_n}{n}| < 1$ therefore $|\frac{a_n}{n}|^n$ is a geometric series with |r|<1 therefore $\lim_{n \to \infty}(\frac{a_n}{n})^n = 0$

[grand pond]

prograce
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[graceful ferry]

Hi, can someone please check the proof

[midnight plank]

@graceful ferry Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight plank]

@molten bay Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[lyric shore]

find (the first integral), if we know that (the integral from -5 to 0)=-8 and (the integral from -5 to 2)=3

[twilit field]

Well, can you think of some properties of definite integrals that could help here

[lyric shore]

could you explain bit more

[twilit field]

okay, so I'll just give the general property,is that fine?

let $a≤c≤b$. Then $\int_{a}^{b} f(x) dx =\int_{a}^{c} f(x)dx+ \int_{c}^{b} f(x) dx$

[grand pond]

What a wonderful world !

[twilit field]

Can you manipulate this to get the desired result ?

[lyric shore]

-5?

[twilit field]

-5 ?

[lyric shore]

how can i use this if 'c' doesn't line up?

[twilit field]

Well, notice $\int_{-5}^{2} f(x) d(x) = \int_{-5}^{0} f(x) dx + \int_{0}^{2} f(x)dx$

[grand pond]

What a wonderful world !

[lyric shore]

no the last one is from -5 to 2

[twilit field]

That's from -5 to 2

-5 is the lower bound, 2 is the upper bound

[lyric shore]

11?

[twilit field]

yup

unless I'm tripping

[midnight plank]

@lyric shore Has your question been resolved?

Channel closed

Closed by @lyric shore

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight plank]

@molten bay Has your question been resolved?

[midnight plank]

@molten bay Has your question been resolved?

[midnight plank]

@molten bay Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[graceful ferry]

given f is uniformly continuous on [0,inf) prove that f is bounded

[graceful ferry]

just some pointers on my thought process is assume it isnt bounded then by definition for every M>0 there exists x such that f(x)>M then I use epsilon delta definition of uniformly continiuous with epsilon=f(x0)-M (?)then choose delta>0 such that for every |x-x0|<delta we get |f(x)-f(x0)|<M-f(x0) which is f(x)<M-f(x0)+f(x0)=M which is contradiciton ?

how do i make sure that epsilon is bigger than 0

[viral robin]

Hi

[graceful ferry]

hi

<@&286206848099549185>

[midnight plank]

@graceful ferry Has your question been resolved?

[visual tiger]

uh not sure thats even true

f(x) = x is uniformly continuous because it's lipschitz (of lipschitz constant 1)

but it's not bounded

also I'm just noticing but

[visual tiger]

in your proof what is x0?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[visual tiger]

wait so you wrote |f(x)-f(x0)|<M-f(x0)?

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[visual tiger]

even though epsilon = f(x0)-M?

[visual tiger]

if epsilon = f(x0)-M it should be |f(x)-f(x0)|<f(x0)-M

[visual tiger]

so yeah lots of problematic stuff about that proof

.close

[midnight plank]

Channel closed

Closed by @visual tiger

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[graceful ferry]

.reopen

No its true

[graceful ferry]

Its an exam question

[graceful ferry]

Idk then... im really confused now

[graceful ferry]

Ugh I wrote the epsilon wrong, I meant epsilon=M-f(x0)

Anyways my proof is wrong i think

My god I'm dizzy

I wrote the question wrong and I understood it wrong

Its let $f:(0,1] \rightarrow \mathbb{R}$ be uniformly continuous prove that f is bounded

[grand pond]

prograce

[graceful ferry]

Does that change things

[unreal mortar]

i mean, dunno if im speaking outta my ass here, but the straight line f(x)=x being unbounded and uniformly continuous on [0,infinity) is a serious problem in my mind

[graceful ferry]

but is it uniformly continuous on (0,1]

[unreal mortar]

if you restrict the domain i believe the statement is true

[graceful ferry]

ill try to prove it

[unreal mortar]

was the original statement not f is uniformly continuous on [0, infinity)?

[graceful ferry]

no how, it is obviously bounded on (0,1]

[graceful ferry]

no, I misunderstood it

[unreal mortar]

Maybe you can use the definition of uniformly continuous:
Let epsilon > 0
Then there exists some delta > 0 such that for x,y in (0,1] |x-y| < delta |f(x)-f(y)| < epsilon or in other words f(x)-epsilon <

Now subdivide the interval (0,1] into intervals of length delta.

Then for each interval of length delta, where z is the midpoint of the delta interval, you know that f(z) + epsilon is an upper bound for that interval

[solid iris]

the interval doesnt matter bc x is uniformly continuous on any

[unreal mortar]

but the statement was that f(x) is unbounded

and on the interval 0 to infinity

f(x)=x is unbounded

[solid iris]

oh hmm f bounded on same interval

[unreal mortar]

but uniformly continuous

[solid iris]

is this a prove or true/false q?

[graceful ferry]

Prove

[unreal mortar]

they changed the interval to f:(0,1]-> R

[graceful ferry]

f(x)=x is defined on interval (0,1] so its bounded

[unreal mortar]

i was confused about uniform continuity when i took real analysis. i went to office hours and my prof told me to envision moving a fixed interval across some curve. you should be able to contain the curve within the rectangle of height epsilon and width delta

[unreal mortar]

i believe this suffices as a proof?

[graceful ferry]

How do I subdivide the intervals ?

[solid iris]

yeah this looks about right

[unreal mortar]

well either delta is greater than 1 or less than 1

if it's greater than 1 our job is easy

[solid iris]

you want to define N via delta

[graceful ferry]

Yes

[solid iris]

use N and delta to define a partition

[graceful ferry]

uhhh

[solid iris]

smth like $N=\floor{1/\delta}$ and $x_i=i\delta$ for $1\le i\le N$

[grand pond]

𝓡𝓞𝓚𝓔𝓣𝓣𝓞─୨ৎ─❥ ♡ <𝟹❤

[graceful ferry]

Ill try to understand it a bit

[solid iris]

then you should see for all $x$ we have $|x-x_j|<\delta$ for some $j$

[grand pond]

𝓡𝓞𝓚𝓔𝓣𝓣𝓞─୨ৎ─❥ ♡ <𝟹❤

[solid iris]

from there you should see a bound on f(x)

[midnight plank]

@graceful ferry Has your question been resolved?

[midnight plank]

@graceful ferry Has your question been resolved?

[midnight plank]

@graceful ferry Has your question been resolved?

Channel closed

Closed by @graceful ferry

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[inland patio]

I have a basic doubt. Consider two sets $S$ and $U$, not necessarily finite, such that their union is linearly independent. What does this mean in terms of the representation of the zero vector? Does it mean that $$0=\sum_{i=1}^na_iv_i+\sum_{j=1}^mb_ju_j,$$for vectors $v_i\in S$ and $u_j\in U$, implies $a_i=b_j=0$ for all index $i$ and $j$? I'm confused about what linear independence means in terms of a union of two sets.

[grand pond]

psie

[gray leaf]

7th grade question

I have an exam in a few hours plz help

[runic hamlet]

union or not, who cares. its still a lin independent set

[steady dome]

literally bruh use a closed channel

this one is occupied

[runic hamlet]

you can separate the linear combination like you did but it changes nothing about how the linear combination behaves

[inland patio]

ok, makes sense 👍

[steady dome]

@gray leafdid you ever read this channel #❓how-to-get-help ?

[solid iris]

just reindex the union

use a single index set

[steady dome]

go read the channel

and then open a new ticket

that is not occupied

[gray leaf]

Bro my exam would start in that much time

[solid iris]

@gray leaf channel occupied, open a new one

[inland patio]

.close

[midnight plank]

Channel closed

Closed by @inland patio

Use .reopen if this was a mistake.

[steady dome]

did you see my ping?

[gray leaf]

No

[steady dome]

#help-47

talk there

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal briar]

how can i tell they symmetry of this?

i have no idea where to begin

is this right

[fallow scarab]

surprisingly yes

,w plot log(9-x^2)

[grand pond]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by rie.mann

[vocal briar]

oh

is that how you always determine symmetry

what if its symmetrical across the x axis

then how do i determine

[fallow scarab]

functions only have 1 unique y value for each x value

so it depends on how your graph is defined

[vocal briar]

oh yeah true

[midnight plank]

@vocal briar Has your question been resolved?

[vocal briar]

.close

[midnight plank]

Channel closed

Closed by @vocal briar

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[plucky spire]

I’m confused on b and c

[plucky spire]

And for A , if I said, this doesn’t contradict the IVT because IVT states that if the function is continuous it guarantees that if k is in between f(a) and f(b) then c will exist between the intervals [a,b] , but since this function has a jump discontinuity at x=2 the graph is discontinuous which doesn’t meet the IVT requirement which means that the IVT can’t guarantee x will equal 10? Would I be correct?

[midnight plank]

@plucky spire Has your question been resolved?

[plucky spire]

<@&286206848099549185>

[vast ginkgo]

yes

the discontinuity basically makes IVT invalid here

[plucky spire]

Yess okay ty for confirming

[plucky spire]

Can u help me with b and c?

[vast ginkgo]

what's confusing about b

[plucky spire]

For b would I have to find what t equal basically?

[vast ginkgo]

well you just have to prove $\cos{t} = t^3$

[grand pond]

BuilderDolphin

[vast ginkgo]

has a solution

which you can do using IVT

it might help to rearrange this equation to equal a number

[plucky spire]

From what intervals thou

[vast ginkgo]

well you have to figure that out

[plucky spire]

like idk what to do with this equation lol

Usually the interval is given

like do I try to isolate T?

[vast ginkgo]

well you can rearrange to get $\frac{\cos{t}}{t^3} = 1$

[grand pond]

BuilderDolphin

[plucky spire]

Can I do that property where sin(x)/ x =1 or does that only apply to SIN

[vast ginkgo]

well that's a limit

so no

in this case you're trying to find a value that's above 1 and one below 1

to prove that the solution exists

(note there's a discontinuity/asymptote at t = 0)

[plucky spire]

Idk why I’m so stumped on this

nothings popping in my head

[vast ginkgo]

try plug in $\frac{\pi}{4}$ and $\frac{\pi}{2}$

[grand pond]

BuilderDolphin

[plucky spire]

Would I just do the reciprocal?

[vast ginkgo]

when dividing by a fraction yes

$\frac{a}{\frac{b}{c}} = a \cdot \frac{c}{b}$

[grand pond]

BuilderDolphin

[plucky spire]

Sorry I think this is the most I can do

Oh then ig I think I can simply that to square root of 128 over pi

[midnight plank]

@plucky spire Has your question been resolved?

[midnight plank]

@plucky spire Has your question been resolved?

[midnight plank]

Channel closed

Closed by @plucky spire

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[molten bay]

I have a confusing doubt over multiplication of complex numbers and their arguments

Arg(z1z2)=Argz1+Argz2+2kπ

arg(z1z2)=argz1+argz2

[molten bay]

but i know that Arg lies between (-π,π]

So question is this

arg(z)+arg(z') will be?

arg(zz')=arg(|z|^2) so it will be always x axis

Hence 0,2π,4π?

.close

[midnight plank]

Channel closed

Closed by @molten bay

Use .reopen if this was a mistake.

[clever igloo]

Undefined, when z = 0.

[molten bay]

Yes

But here z=\0

Argz can be 0

@clever igloo

[clever igloo]

Yes, should only be 0 if z is not 0.

[molten bay]

But why?

argz is multi variable na?

[clever igloo]

Becaise |z|^2 would be a² + b² given that z = a +ib.

[molten bay]

.

[clever igloo]

And it will only lie on Real Axis, when z isnt equals to 0.

[molten bay]

That is what I am asking you that when it's will be x axis

An argument Z is multivariable function

So it can be two pie 4 Pi?

[clever igloo]

It shouldnt be, as 2pi and 4pi are not in its range

[molten bay]

What range?

It is argz not Argz

[clever igloo]

Range of principal argument

[molten bay]

But principal argument is denoted by ?

[clever igloo]

Amp, i guess

[molten bay]

argz or Argz?

[clever igloo]

Idk abt that

We usually work for principal arguments

Othervise, we could always add or subtract 2npi from an angle and it would still remain same in alot of sense

But we work with principal range

General Solution: 2npi, where n is an integer
Principal solution: 0

@molten bay

[molten bay]

Yeah

Thanks

.close

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twilit field]

$\int_{C} \frac{ (x+y) dx - (x-y)dy}{x^2+y^2}$ Over the circle $x^2+y^2=a^2$ traversed once in a counter clockwise direction

[grand pond]

What a wonderful world !

[twilit field]

so to start, I'd paramatrize the circle as $(a\cos(t), a\sin(t))$

[grand pond]

What a wonderful world !

[twilit field]

so Firstly, splitting the path integral into two integrals

$\int_{C} \frac{x+y dx}{x^2+y^2} - \int_{C}\frac{(x-y) dy}{x^2+y^2}$

[grand pond]

What a wonderful world !

[twilit field]

hmm

Can I have a hint

so this would concievabley be

$\int_{0}^{2 \pi} \frac{ a \cos(t) + a \sin(t)}{a^2}dt -\int_{0}^{2 \pi} \frac{a \cos(t) - a \sin(t)}{a^2}dt$

[grand pond]

What a wonderful world !

[twilit field]

Okie, so this is a vector field, my bad

.close

[midnight plank]

Channel closed

Closed by @twilit field

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[earnest forge]

How do I simplify further?

[lyric charm]

transparent background...

[earnest forge]

I tried making the background color white, but this site is faulty

[lyric charm]

(-2)^(2/3) = 2^(2/3) and (-2)^(1/3) = -2^(1/3)

2^1 / 2^(2/3) simplifies in a transparent fashion

[earnest forge]

Oh yeah

I forgot cube root of x is an odd function

Thanks

.close

[midnight plank]

Channel closed

Closed by @earnest forge

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[silent torrent]

can someone help me question 69 how to find the distance when we only know v?

[silent torrent]

can we use D=V^2 sin2alpha/g

V=Vo* cos alpha +15 -35

the fomula is Vo

but can ii change to Vx because i dont know how to deal with 2 tanks since both of them are moving,i cant write (Vo +15-35) so i change Vo to Vx

[midnight plank]

@silent torrent Has your question been resolved?

Channel closed

Closed by @silent torrent

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[median creek]

show your work

[rapid crest]

The time here is 2 seconds for the maximum height according to the question

But once the (t) is substitued for 2 the answer is 16

which isnt in the options for the 11th one

[median creek]

is it!

?*

[rapid crest]

look at the options

16 is not options

an option*

[median creek]

No no…

I see the problem here

[vague seal]

the time scale is not accurate

[median creek]

Can you tell me how u calculated the time for the maximum height?

[vague seal]

at least it's too vague to accurately use it

[rapid crest]

its given in the image

at 2 seconds the height is max

[median creek]

.

It’s ot accurate

not*

[rapid crest]

So what should i do then?

[median creek]

Please calculate the maximum time from the quadratic equation given

[rapid crest]

Ok

give me a sec

[median creek]

Alrighty

[vague seal]

but calculating the time itself gives a different answer than what is shown

[rapid crest]

The time is 4 seconds

[median creek]

Oh?

What did you do?

[rapid crest]

Splitting the mid term

[rapid crest]

Yea

[median creek]

That is a process done for finding where the given is zero

You found where the h is zero

that is, where the ball touches the group

Ground

But we were asked to find the time of the maximum height

[rapid crest]

Yea

oh

[vague seal]

Have you had derivatives?

[rapid crest]

whats tht

[median creek]

to do that, do you know derivatives?

[rapid crest]

Nope

[median creek]

Alright, is his question from kinematics?

this*

[rapid crest]

No its from CBSE

Class 10

[median creek]

.

HELP?

[vague seal]

here is a more accurate picture

[median creek]

they won’t give the picture in the exam though..

No?

[vague seal]

i don't think so

[rapid crest]

yea they wont

[median creek]

How are we supposed to find maximum heights without using derivatives

[vague seal]

but if you don't know derivatives

[median creek]

or formulaes for maximum heihts?

[rapid crest]

Nope

[vague seal]

This was given as an exercise?

[rapid crest]

Dont worry guys i just comfirmed with my teacher

[median creek]

Oh

[rapid crest]

Its not in the syllabus

[median creek]

?

Yeaa alright

It uses concepts of derivatives

[rapid crest]

Thanks for the help tho

[rapid crest]

Yeah she said the same thing

[median creek]

Oh alr alr 😭

Ywww

[floral junco]

.close

[midnight plank]

Channel closed

Closed by @floral junco

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twilit field]

In each of Exercises 1 through 12, a vector field f is defined by the formulas given. In each case determine whether or not f is the gradient of a scalar field. When f is a gradient, find a corresponding potential function φ.