help-49

[uneven violet]

hi

[dusk pier]

!da2a

[midnight plank]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

@uneven violet Has your question been resolved?

Channel closed

Closed by @uneven violet

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fringe holly]

hello if a point P is at a distance of 50cm of Q=+4.0C then draw the electric field strength.

[midnight plank]

@fringe holly Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[glad mountain]

Helpp

[glad mountain]

What do i do?

[fallow scarab]

https://www.mathsisfun.com/geometry/circle-intersect-chords.html

[glad mountain]

It would be 2x(x+2) = 3x²?

[sterile kraken]

is this a level maths?

[glad mountain]

What you mean?

[glad mountain]

Then then it would be

2x²+ 4x = 3x²

???

<@&286206848099549185>

What next?

[tired osprey]

solve for x

[glad mountain]

Howww

I knowww

It would be 2x² + 3x² = -4x?

Wrong?

Umm...

Helpppp

[last slate]

no

3x^2-2x^2-4x=0

[tired osprey]

2x^2+3x^2 = 5x^2

[glad mountain]

This?

[glad mountain]

Yuppp

But what next steps

[last slate]

u will be surprised...

[glad mountain]

What nextttt

[fallow scarab]

x isn't 0 so divide by x

[glad mountain]

I have to times it first? Then divide by x?

[lyric charm]

what's "it"

<@&268886789983436800> scam

[glad mountain]

Ummm

[lyric charm]

what did you mean when you said "times it"?

[glad mountain]

...

[glad mountain]

...

What's next step after that?

Or is that wrongg?

I have exam later i need to know how to do it😭😭😭

Anyone pleasee

[lyric charm]

your way is correct so far

[glad mountain]

After what do i do?

[lyric charm]

2x^2 + 4x = 3x^2
from here you can do two things, and it does not really matter which order

[glad mountain]

Do thiss?

Or no?

[glad mountain]

What things is it?

[lyric charm]

no, this is illegal

[glad mountain]

Oh...

[lyric charm]

1. divide out by x
2. subtract 2x^2 from both sides

(but don't be blind)

[glad mountain]

What you meaannn😭

[lyric charm]

nothing, don't worry about it

[glad mountain]

It would be 2x + 4 = 3x

?

Idkkk

Or nahhh

[lyric charm]

yes, that's what you get once you divide by x

you're now 1 step away from the answer

[glad mountain]

Now i will do

4 = 3x - 2x?

[lyric charm]

well maybe you will and maybe you won't, who am i to predict your actions?

[glad mountain]

Then it would be 4 = x

[lyric charm]

indeed

[glad mountain]

So 4 is the answer?

Yeas i agree

[glad mountain]

Ann said "Yes, Thats The answer"

yes thankk youuu

Thank youuu

[lyric charm]

my, what an explicit placement of words in my mouth... are you being sarcastic right now?

but i mean yes you got to the right answer

[lyric charm]

and i confirmed it here

[glad mountain]

Bruh are you french Royal queen or something

Such a royal way to talk

[lyric charm]

i am none of those three

not French, not royal, and not a queen

[glad mountain]

Britishh

[lyric charm]

i am not British either

you will not guess where i am from unless you know me

say, how old are you?

[glad mountain]

Your from the planet earth

[lyric charm]

no actually im from fucking Venus or something 💀

[glad mountain]

Oh your gracee... Such an honor that you askk.

[dusk pier]

Trolling a helper is wild

[glad mountain]

Your highness... Thats for you to find you😉

[lyric charm]

eh idk

[glad mountain]

Anyways

[lyric charm]

don't call me "your highness"

it's kinda gross

[glad mountain]

HAHAHAH i know

Thats why i used it

[lyric charm]

...

anyway do you have anything else to ask

[glad mountain]

Anyways thanks for the help

[dusk pier]

Alive Internet Theory

[glad mountain]

I regret to inform you , i dont have an answer for your such difficult answer

[dusk pier]

Ayyy it's my username

Using Chord-Chord Power theorem!

[glad mountain]

Please Accept my deepest gratitude as i am most grateful for your help

[glad mountain]

Or simply Thank you everyone

[lyric charm]

jeez man knock it off with the over the top politeness already

[glad mountain]

Guess who started it

Anyway

Farewell.

.close

[midnight plank]

Channel closed

Closed by @glad mountain

Use .reopen if this was a mistake.

[lyric charm]

????

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[safe onyx]

force vs velocity squared

I need to solve for mass and radius

$\Sigma F = ma$

[grand pond]

smeagol

[safe onyx]

$a = \frac{v^2}{r}$

[grand pond]

smeagol

[safe onyx]

Thus $F = \frac{m v^2 } r$

[grand pond]

smeagol

[safe onyx]

How can I use this to solve for m and r?

SHould I use the best fit line?

I tried doing that and got bad results

.close

[midnight plank]

Channel closed

Closed by @safe onyx

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dusty portal]

So

Where to start?

[brazen stream]

I think the first thing you should do is regroup -y^2, +2yz, and -z^2

[dusty portal]

Ah

[brazen stream]

Which gives you like quadratic

[dusty portal]

I thought there was not a negative term

Lemme do that

$x^2-(y-z)^2+x+(y-z)$

[grand pond]

;(

[brazen stream]

No aint like that

[dusty portal]

How

[brazen stream]

you know the rule $a^2 + 2ab + b^2 = (a+b)^2$

[grand pond]

nerfLeander

[brazen stream]

Go back here, and separate this terms from the expression

Ima try to break it so that it can't be complicated for you

[dusty portal]

Oh

$(-y^2+2yz-z^2)+x^2+x+y-z$

[brazen stream]

+2yz should in middle

and apply the rule

[grand pond]

;(

[dusty portal]

$-(y-z)^2+x^2+x+y-z$

[grand pond]

;(

[brazen stream]

Good boy 😏

[dusty portal]

...

[brazen stream]

Maybe like this

$x^2 - (y - z)^2 + x + y - z$

[grand pond]

nerfLeander

[dawn dagger]

lmao

[brazen stream]

You can see that the first two terms shows that you can apply differences of squares right?

Try to apply that

[dusty portal]

OH

.close

[midnight plank]

Channel closed

Closed by @dusty portal

Use .reopen if this was a mistake.

[brazen stream]

Wait what?!

[fair monolith]

I mean he did it right the first time, he just didnt see the negative term

[brazen stream]

It's not finished yet

Maybe he his

He's a good boy 😏

[fair monolith]

[dusty portal]

I factored it

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sterile prism]

Hey could someone help me with this? I think I know how to do it but im not too sure

[sterile prism]

does A = S?

[dusty portal]

For which question

Nevermind, B=S

[sterile prism]

The first one

Oh wait

[dusty portal]

Yeah the first one is the only one with A and S

Anyways

[sterile prism]

So A would = T

And C = R

D = U

AB = ST

DA = TU

I think I got it

[urban widget]

Yep I think it looks good

[sterile prism]

Wait what are the little lines for on part 2

[midnight plank]

@sterile prism Has your question been resolved?

[sterile prism]

I don’t get the 2nd part

The lines

[dusty portal]

Indicating the lines are congruent

[sterile prism]

Ohhh okay

Thanks

[midnight plank]

@sterile prism Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[obsidian mountain]

I need help with understanding the Lagrange error bound

[midnight plank]

@obsidian mountain Has your question been resolved?

[obsidian mountain]

.close

[midnight plank]

Channel closed

Closed by @obsidian mountain

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[radiant roost]

To show a set $A$ is an equivalence class of a relation $\sim$\
Should I show $a\sim b$ for all $a,b \in A$, and $a\not\sim b$ if $a\in A$ and $b\not\in A$?

[grand pond]

Axe

[main current]

Yes that would work

[radiant roost]

thanks 🙏

.close

[midnight plank]

Channel closed

Closed by @radiant roost

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[radiant roost]

Show that if $\sigma$ is a cycle of odd length, then $\sigma^2$ is a cycle.

[grand pond]

Axe

[radiant roost]

Let $\sigma=(a_1,a_2,\ldots a_{2n+1})$ for some positive integer $n$.\
Then $\sigma^2=(a_1,a_3,\ldots,a_{2n+1},a_2,a_4,\ldots,a_{2n}).$

[grand pond]

Axe

[radiant roost]

is this enough?

[midnight plank]

@radiant roost Has your question been resolved?

[dawn dagger]

hmm

i mean you ended up with a cycle

[radiant roost]

yeah

[dawn dagger]

i cant tell if it's trivial or a trap

i think it's okay

[radiant roost]

thanks 🙏

[midnight plank]

@radiant roost Has your question been resolved?

Channel closed

Closed by @radiant roost

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[primal ginkgo]

Can someone help me

I don’t know how to approximate the graph

[dawn dagger]

Look up the formulas of Simpsons and Trapezoidal rule

[midnight plank]

@primal ginkgo Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[twilit field]

I would like help with all 3 of these

[twilit field]

so to start (a)

$\int_{0}^{1} (1-t^2,t^2-t^3,t^2+t^3) \cdot ( 1,-1,2t) dt$

[grand pond]

What a wonderful world !

[twilit field]

Does this seem about right

[dawn dagger]

yes

[twilit field]

Cool onto the next problem then

[dawn dagger]

💀

[twilit field]

Oh right, I have to integrate it

[dawn dagger]

💀

[twilit field]

$\int_{0}^{1} ( 1-t^2-t^2+t^3+2t^3+2t^4 )dt$

[dawn dagger]

this is just copy and paste

[twilit field]

yah

same idea, right

[dawn dagger]

2t * t^2 is not t^3

[subtle blaze]

We are…missing a 2

Don’t fail algebra in calculus

[grand pond]

What a wonderful world !

[twilit field]

I think this is a pretty easy integral

thanks

1-2/3+3/4+2/5

How would I do this

As the path is via origin, I guess (t,mt) works for that's path's parametrization?

[dawn dagger]

yes

[twilit field]

so I'd then have $\int _{a}^{b} (mt,-t) \cdot (1,m) dt$

which is 0

so the path integral is 0?

[lyric charm]

(1, m) not (t, mt)

but your thing still equals 0

[grand pond]

What a wonderful world !

[dawn dagger]

yes

[twilit field]

Thanks

Will be back in a bit, have something I want to check

thanks

.close

[midnight plank]

Channel closed

Closed by @twilit field

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[narrow dragon]

would I find this by subbing x-3? For a

[fresh sparrow]

yes

[narrow dragon]

Yay ok thank u

So would it work like so:

[devout summit]

This may sound dumb but how is the number of students 4

and for c where it says how many students come from fans w 6 or more children

[narrow dragon]

Look at the frequency part on the left

See where the column for 1 children line up

At frequency 5

Under that

Would be four

[devout summit]

So it falls under one correct

That’s what I thought but copilot was telling me to look at 0 instead

[narrow dragon]

Copilot going crazy

Same thing for c

The column for 6 goes up to 2 on the frequency scale

[devout summit]

yep finally

I knew one of us was dumb

For this one is a =0

Thx for ur help btw

[narrow dragon]

yes

[devout summit]

alright and how do I calculate modal interval please

[narrow dragon]

uhh I lowkey don’t remember that part

[devout summit]

I asked ChatGPT and said a ling ahh rule

long

Which I highly doubt is right

I think modal interval is 60-70

[midnight plank]

@narrow dragon Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[oblique ravine]

,rotate

[grand pond]

Couldn't find an attached image in the last 10 messages.

Feb 24, 2025, 11:03 AM

[oblique ravine]

Could someone please help me answer Question 2 part c

,rotate

[oblique ravine]

<@&286206848099549185>

Pwease help me

[midnight plank]

@oblique ravine Has your question been resolved?

[oblique ravine]

.close

[midnight plank]

Channel closed

Closed by @oblique ravine

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[quaint crag]

someone pls help, I don't understand how to do this 😭 it came up in my a level maths mock and I'm struggling to figure out the answer.

[umbral timber]

lemme give it a go

ill let you know

[quaint crag]

I tried another approach that didn't work 😭😭

[quaint crag]

alr ty

[umbral timber]

okay got it

should i tell you step by step

or send the whole thing

[quaint crag]

uh whatever works best for u

[umbral timber]

okay sending
let me write things out properly

oh shi
i made i mistake in the last step while isolating i but you get it..

[quaint crag]

thank you sm!!!

.close

[midnight plank]

Channel closed

Closed by @quaint crag

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cedar yacht]

how do i do radicals :')

[cedar yacht]

I have no clue how to do radicals, can somone give me a run down?

[lyric charm]

what do you mean by "do radicals"? do you mean simplifying radicals?

do you have any specific questions that you are stuck on?

otherwise look up the organic chemistry tutor on YouTube, he has lots of videos on school level math stuff

incl radicals

[cedar yacht]

I think, I just dont know where to start (Context: I missed school and my teacher did a bad explanation over email)

[cedar yacht]

unfortunatley the video cant help me, its nonvariable, just simpilifing

[lyric charm]

ok so do you have a problem you're doing right now

[cedar yacht]

√16

wouldnt it be
√4√4
2√4

[lyric charm]

formally correct so far, but if you're gonna simplify the first sqrt(4) into 2, why not do the same for the second?

you'll get that the entire thing equals 2*2

or just 4

[cedar yacht]

oh-

[lyric charm]

or simply recognize from the start that 16 is 4^2 so its root is 4 lol

[cedar yacht]

yeah

brain go dum dum

alright, how would i go about

2√121

[lyric charm]

well, how does 121 factorize?

[cedar yacht]

11

2√11√11

so

√22√11?

[midnight plank]

@cedar yacht Has your question been resolved?

Channel closed

Closed by @cedar yacht

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[fervent forge]

Y=6x+2
Write this in the form of a+b=c
Abc should be written in integres

[fervent forge]

<@&286206848099549185>

[midnight plank]

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

[urban widget]

!original

[midnight plank]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[fervent forge]

This is all I remember from my exam

I don't have any pic

[polar star]

this does not make any sense

was it like:
Write it in the form of ax+by = c?

[fervent forge]

Yes

[polar star]

okay what did you try

[cedar yacht]

isint it already like that?

[polar star]

no its in the form y=mx+c

[fervent forge]

Yes

[cedar yacht]

oh MB

[fervent forge]

Can you please assist me 👦

[cedar yacht]

What did you try?

if you remember, can you show me how you solved the problem?

[fervent forge]

I just wrote 6a +2b=c

[cedar yacht]

okay so this is turning a slope intercept into an equasion

do you want me to show you how i would solve it?

[fervent forge]

Yes

[cedar yacht]

Alright

so its literally

you flip which side the X is on

so y=6x+2 >> y-6x=2

[fervent forge]

Ok thx

.close

[cedar yacht]

ur welc

[midnight plank]

Channel closed

Closed by @fervent forge

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[tall thorn]

can someone please help me understand this

[lethal path]

#help-8 message

[modern shore]

try to understand

a limit is what a functions value approache as x approaches a certain value

given here is a piecewise function

so its limit simpliy does not exist as x approaches -1

as there is no value of x

such tha f(x) =-1

[queen herald]

In the question we're approaching -1 from the left, which gives a well-defined limit

[modern shore]

oh

id didnt know that

[queen herald]

$x\to a-$ means x approaching a from the left

[grand pond]

spindle

[slow thorn]

first plot all the points in the graph whose x coordinates you see in the question

[queen herald]

Analogously x --> a+ means x approaching a from the right

[slow thorn]

yeah

[modern shore]

so the answer is -1?

[tall thorn]

is this correct

[queen herald]

correct

[tall thorn]

thanks!

.close

[midnight plank]

Channel closed

Closed by @tall thorn

Use .reopen if this was a mistake.

[slow thorn]

fast

[queen herald]

I really hope you used correct reasoning for that

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[magic pilot]

Does anyone know how to use Typst

[magic pilot]

I'm having trouble working out how to do bounds on integrals in typst

[buoyant yoke]

!da2a

[midnight plank]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[midnight plank]

@magic pilot Has your question been resolved?

Channel closed

Closed by @magic pilot

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight plank]

Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[fervent lava]

.close

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[unreal imp]

.open

.reopen

hello

[lyric charm]

FYI: .reopen works only if you've already closed a channel but it hasn't disappeared yet.

[unreal imp]

how can i do it?

[lyric charm]

also, starting your message with a . will prevent the channel from opening on that message

[unreal imp]

thanks

[lyric charm]

anyway,

do you know your exponent laws?

[unreal imp]

I ain't sure

i don't remember about it

[lyric charm]

$x^m \cdot x^n = ; ?$

[grand pond]

Ann

[unreal imp]

x^m+n

[lyric charm]

x^(m+n) more properly, but yes

$x^m \cdot x^n = x^{m+n}$ is one of the exponent laws

[grand pond]

Ann

[lyric charm]

do you remember any others?

[unreal imp]

How do I do this?

What should I do?

[lyric charm]

i think we should still try and recall some other exponent laws before trying to tackle that expression

or any part thereof

by this point you could have also gone off to google and searched "exponent laws" yourself and brought up something like this image.

do you know these? yes or no

[unreal imp]

yeah

[lyric charm]

ok right

now on to this problem of yours.

the fraction 2/3 obviously appears a great many times in your expression, yes?

(im not done yet but i want you to acknowledge this observation)

[unreal imp]

there are 5

[lyric charm]

yes, sure.

now what im suggesting is that you can actually make your life a lot easier by temporarily replacing 2/3 with a letter

such as a

this alone makes the expression appear much lighter: $$\frac{a^5 \cdot a^0 \cdot a^{-3} \cdot \paren{\frac{81}{16}}^{-2}}{\paren{\frac32}^{-5} \cdot a \cdot (a^5)^2 \cdot \paren{\frac{8}{27}}^3}$$ (note i am deliberately holding off on applying any exponent laws or even simplifying any of the fractions that aren't overt $2/3$)

[grand pond]

Ann

[unreal imp]

It's a task from high school.

[lyric charm]

yes, and?

[unreal imp]

a^(5+0+(-3) = 2)

a^2

[lyric charm]

hold off on this

i mean ok fine we can replace that top bit with a^2 sure

i was now going to explain that 3/2 = a^-1 and 81/16 = a^-4 and also 8/27 = a^3

do you understand what i just said? yes/no

[unreal imp]

ah ok

I ain't sure

aahhh okay

81/16^-2 change to 16/81^2

[lyric charm]

missing brackets.

but yes, (81/16)^-2 = (16/81)^2. that's legal.

[unreal imp]

I remember somethings

and (3/2)^-5 change too?

[lyric charm]

where is (2/5)^-5 ?

[unreal imp]

my mistake

[unreal imp]

.

[lyric charm]

you can change it to (2/3)^5 by the same token, yes

or a^5

[unreal imp]

well

how do i do this?

[lyric charm]

this is now $(a^5)^2$

[grand pond]

Ann

[lyric charm]

if you look at the reference i gave you earlier for exponent laws, then you will definitely find something there that works.

[unreal imp]

multiply or only (a)^52?

[lyric charm]

mn means m times n.

it does not mean "smush the digits of m and n together"

[unreal imp]

xD

[unreal imp]

5x2 = 10

(a)^10

[lyric charm]

...yes

[unreal imp]

xD

now (8/27)^3

?

[midnight plank]

@unreal imp Has your question been resolved?

[zinc mist]

$\frac{8^3}{27^3}$

[grand pond]

Luh Roub

[unreal imp]

yes

[zinc mist]

It isnt written there but

[unreal imp]

must i do 8-3?

[zinc mist]

$(\frac{a}{b})^x=\frac{a^x}{b^x}$

[grand pond]

Luh Roub

[zinc mist]

not exactly

Thats only if you got a^x/b^y

[zinc mist]

8 is a, 27 is b, x is 3, therefore → $(\frac{8}{27})^3=\frac{8^3}{27^3}$

[grand pond]

Luh Roub

[zinc mist]

[unreal imp]

aaah okay

[zinc mist]

yip

[zinc mist]

now try solving that with the rules

[unreal imp]

first (2/3)^5+0+(-3)

=

2

true?

(2/3)^2

[zinc mist]

wait

$x^0$ for x\neq0 , \text{equals what}

[grand pond]

Luh Roub
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[zinc mist]

right

@unreal imp

[unreal imp]

okay

[zinc mist]

whats that

whats a number

to the power of 0 equal to

[unreal imp]

0 = 1?

[zinc mist]

$x^0=1$ , yes

[grand pond]

Luh Roub

[zinc mist]

be careful of notations

[zinc mist]

now try to solve it

[unreal imp]

Then 5+1+(-3)

= 3

(2/3)^3

$(2/3)^3$

[grand pond]

Angel

[unreal imp]

XD

[zinc mist]

oh i didnt see the first 3 are the same numbers dafuq

in that case

we add the exponents up

so u were originally right

5+0-3

is 2

Now we got $(\frac{2}{5})^2..$

[grand pond]

Luh Roub

[zinc mist]

now i personally would look for other rules

[unreal imp]

Yes

[zinc mist]

$(\frac{a}{b})^{-1}=?$

[grand pond]

Luh Roub

[unreal imp]

Change

[zinc mist]

$\frac{b}{a}$

[grand pond]

Luh Roub

[zinc mist]

so do that

[unreal imp]

(b/a)^1

[zinc mist]

exactly

exchange them

[unreal imp]

(16/81)^2

[zinc mist]

right

and 1st one from the bottom

[unreal imp]

Wait

@zinc mist

[zinc mist]

forgot the division line

but yes

[unreal imp]

How do I do another 👇

[zinc mist]

write that line

[unreal imp]

Thanks

??

[zinc mist]

now as u see

The bottom 2 are the same

what rule do we use

[unreal imp]

Yes

[zinc mist]

dont forget these 2

[unreal imp]

Must multiply 5x2

[zinc mist]

right

[zinc mist]

okay

now

[zinc mist]

These 3 got the same base

[unreal imp]

@zinc mist

[zinc mist]

good

[unreal imp]

Now?

Then?

@zinc mist

[zinc mist]

Calculator

[unreal imp]

How?

Can you give any examples?

@zinc mist

[midnight plank]

@unreal imp Has your question been resolved?

[unreal imp]

.close

[midnight plank]

Channel closed

Closed by @unreal imp

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wide sluice]

What r some fun places dynamic programming is used in math

[wide sluice]

Outside of the usual cs algos

[grim vector]

What do you mean by dynamic programming ?

[midnight plank]

@wide sluice Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vocal briar]

i've done

$x^e = lny$

[grand pond]

gamer75431

[vocal briar]

$log_x{lny} = e$

[dusk pier]

Looks good

[grand pond]

gamer75431

[vocal briar]

$\frac{1}{lny\cdot{lnx}}\cdot\frac{1}{y}\cdot\frac{dy}{dx} = 0$

[grand pond]

gamer75431

[vocal briar]

$\frac{dy}{dx} = \frac{1}{lny\cdot{lnx}}y$

[grand pond]

gamer75431

[dusk pier]

You don't need a fraction

It's $\frac{dy}{dx}=y\cdot\ln(y)\ln(x)$

[grand pond]

mathisfun

[dusk pier]

Besides your work that you showed is already good

[vocal briar]

why don't i need the fraction?

oh

wait

ya

lmao

[dusk pier]

You're multiplying ln(y) and ln(x) on both sides

[vocal briar]

is that equivalent though?

to the final ans

[dusk pier]

Sure, if you work out the algebra

[vocal briar]

im getting $(x^elnx)e^{x^e}$

[grand pond]

gamer75431

[dusk pier]

Hmm

,w differentiate log_x(ln(y))

breh

[grand pond]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by mathisfun111

[dusk pier]

This is very sus

[vocal briar]

feel like this is right tho

i double checked

oh wait

im confused now

isn't the deriv of e = 0?

[vocal briar]

so then here how can i multiply by lny lnx y on both sides

wouldn't it js mean dy/dx = 0?

[dusk pier]

No

I think this method is too confusing

[vocal briar]

hmm

[vocal briar]

yeah apparently even upto here is incorrect

[twilit jetty]

yea this is correct, what youre doing of logarithmic differentiation is usually what people to do to solve those

[vocal briar]

this is my teacher lol

but im trying to do soemthing similar but its wrong

[twilit jetty]

you can follow along with their steps first

do you understand the steps they are doing

[vocal briar]

well yeah that is obv now that im looking at it

but if i was on an exam

and lets say i didn't see that way

but i decided to do it this way

where am i going wrong?

if i convert the expression into $\log_x{\ln{y}}=e$

[grand pond]

gamer75431

[twilit jetty]

this isnt usually a good idea because having ln(ln(anything)) does not look that good when differentiated

usually just doing one ln on both sides is enough, if it doesnt work, you then ln again

also you try to avoid having a log with base x, logs with constant bases are easier to work with

@vocal briar you can see here the steps dont look very nice
log_x(ln(y)) = e
ln(ln(y))/ln(x) = e
(ln(ln(y))' ln(x) - ln(ln(y)) (1/x))/(ln(x)^2) = 0
ln(ln(y))' ln(x) - ln(ln(y)) (1/x) = 0
ln(ln(y))' ln(x) = ln(ln(y))/x
ln(ln(y))' = ln(ln(y))/(x ln(x))
(1/ln(y)) (1/y) dy/dx = ln(ln(y))/(x ln(x))
dy/dx = ln(ln(y)) ln(y) y /(x ln(x))
dy/dx = ln(ln(e^x^e)) ln(e^x^e) (e^x^e) /(x ln(x))
dy/dx = ln(x^e) x^e (e^x^e) /(x ln(x))
dy/dx = e ln(x) x^e (e^x^e) /(x ln(x))
dy/dx = e x^e (e^x^e) /(x)
dy/dx = e x^(e-1) (e^x^e)

you do get the correct answer at the end, but at more work

[vocal briar]

from your first to second step, cant you start differentiation from there?

[vocal briar]

like doing this

or is there something im doing wrong here

[twilit jetty]

it looks like youre messing up chain rule when doing that

I cant really see how its correct

log_x(y) = ln(y)/ln(x), so differentiating it requires quotient rule

log_c(y)'s derivative works because c is a constant

since x is not a constant, log_x(y) uses a different derivative

[vocal briar]

isn't log_x(y) = (1/ylnx)* dy/dx?

[dusk pier]

Props for writing that out.

[vocal briar]

fr

[twilit jetty]

think of x^e and x^x

do you think the derivative of x^x is x * x^(x - 1)?

compare that with the derivative of x^e being e x^(e - 1)

[vocal briar]

yeah no i get that

[twilit jetty]

that is why d/dx log_c(y) = 1/(y ln(c)) * dy/dx

[vocal briar]

oh

[twilit jetty]

but d/dx log_x(y) = d/dx ln(y)/ln(x) is completely different

[twilit jetty]

so this is not correct

[vocal briar]

base has to be a constant for that rule then?

[twilit jetty]

you have to see the difference between the constant c and the variable x

[twilit jetty]

yep, just like how power rule requires a constant for the exponent

[vocal briar]

ah i see

okok

well ill js have to remember that ig lol

anyways thank you both

[twilit jetty]

yea

np

[vocal briar]

.close

[midnight plank]

Channel closed

Closed by @vocal briar

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[floral grail]

can someone please explain why the correct answer is divergent? somehow i got ln(3)/4 (i am doing improper integrals)

[lethal owl]

1/(4x-1)
Has a domain of x ≠ 1/4
Which lies between 0 and 1

So there's a vertical asymptotes there

Also the function itself is negative at x < 1/4
And positive at x > 1/4

[floral grail]

okay, i'm just wondering why my evaluation is wrong becuase I got a constant

[odd solar]

last line, -inf + inf =/= 0

[floral grail]

why?

so whenever i add infinities is the answer going to be divergent?

[odd solar]

because inf is not really a single value

inf + inf = inf

[floral grail]

is that the case even though i am adding positive and negative infinity?

[odd solar]

but subtracting inf from inf is undefined

[floral grail]

infinity is so confusing

either way thanks for answering my question

.close

[midnight plank]

Channel closed

Closed by @floral grail

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[sturdy schooner]

How do I do this?

[sturdy schooner]

I’ve been trying to do this for an hour and I just can’t do it right I keep getting different answers

.close

[midnight plank]

Channel closed

Closed by @sturdy schooner

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gray jackal]

Guys are these correct

[cosmic junco]

p(4 wheel drive | SUV) = 18/24 and not 66 but 3/4 is correct. Last one should be 24/ 66 and not 30/64

[midnight plank]

@gray jackal Has your question been resolved?

Channel closed

Closed by @gray jackal

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight plank]

@proven elbow Has your question been resolved?

[midnight plank]

@proven elbow Has your question been resolved?

[dusk pier]

Could you provide the untranslated version?

[proven elbow]

Do you speak German?

[dusk pier]

No, but it's fine.

I just need to make sure the actual labeled points and lines are correct.

Seems like the translator had a rough time.

[proven elbow]

@dusk pier

[midnight plank]

@proven elbow Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[desert prism]

25k^2+40k+16

[midnight plank]

@desert prism Has your question been resolved?

[midnight plank]

@desert prism Has your question been resolved?

[desert prism]

<@&286206848099549185>

[patent shard]

is this a solve for k question?

$25k^{2} + 40k + 16$

[grand pond]

Loki

[patent shard]

idt u can split the middle term

but the discriminant is 0

so u can js use the quadractic equation

$k = \frac{-40 + \sqrt{0}}{50}$

[grand pond]

Loki

[patent shard]

and

$k = \frac{-40 - \sqrt{0}}{50}$

[grand pond]

Loki

[patent shard]

will yeild the same ans

$k = \frac{-4}{5}$

[grand pond]

Loki

[patent shard]

@desert prism

[desert prism]

ahhhh

i see i see

thank you loki! that was the answer correct?

[patent shard]

yes thats the only calue for k

[desert prism]

yes alright thank you so much!

[patent shard]

yw!!

[desert prism]

really saved me from pulling all nighters 😂

[patent shard]

lol

for any quad eqn

just check the discriminant first

thats the important bit

[desert prism]

ahhh i see

[patent shard]

after that its mostly easy

[desert prism]

yea yea i just realized that, better at explaning then my teacher

well gl with everything yk, you are very cool, and thank you so much

[crystal night]

thats cool

[desert prism]

.close

[midnight plank]

Channel closed

Closed by @desert prism

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[vivid fjord]

d

[vivid fjord]

how d othey get this

on the bottom i get (x-7)-(5x-10)

[lyric charm]

show your work

[old rampart]

can you shjow work

[vivid fjord]

on my computer rn

il try

got top part n ot bottom

@lyric charm

[lyric charm]

this scrawl is nigh impossible to read

[vivid fjord]

bottom 1(x-7)/x-2 - 5(x-2)/x-7

so x-7 -(5x-10)

[lyric charm]

hold on

can you describe in words what you did

you multiplied the outer top and bottom by (x-7) ?

or... what did you do actually

[vivid fjord]

i found th elast coomon denominator and it was x-2 x-7 so i plug in on the ones missing either

[old rampart]

start from scratch

[vivid fjord]

i only needd help on bottom part i got the top part

[old rampart]

you know that 1/(2-x) = -1/(x-2)

I see you did that

no

[vivid fjord]

wdym

[old rampart]

nvm

lol

[vivid fjord]

the botom i multiply the 1 by x-7 and the 5 by x-2

and get x-7 minus (5x-10)

[old rampart]

yea

idk

[vivid fjord]

do you tjink the key is wrong?

[old rampart]

I do

4x+3 should be the correct bottom

[vivid fjord]

yeah

isee ty

[old rampart]

well

-4x + 3

[vivid fjord]

yeah

[midnight plank]

@vivid fjord Has your question been resolved?

Channel closed

Closed by @vivid fjord

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wicked prism]

Can someone help me with solving this?

[modern shore]

use log(a-b) = log(a)/log(b)

[prime garden]

?

[twilit field]

eh?

[modern shore]

its log(5)

let it equal to log(6-1)

[twilit field]

Isn't it $\log(a/b) = log(a) - log(b)$

[grand pond]

What a wonderful world !

[prime garden]

Yes.

[modern shore]

i forogt

mb

[prime garden]

What's to be done?

Is the expression, this:
log_6 (5) - 1/4?

[twilit field]

well, the best you can do is write 1/4 as log_6( something)

[wicked prism]

Hey, sorry I was busy solving other ones

[wicked prism]

It just says “calculate”

[prime garden]

Is this true?

[wicked prism]

😵‍💫

[glacial elm]

i think u write wrong the question...

[wicked prism]

That’s why I’m curious

[glacial elm]

oh

[wicked prism]

I’ve solved it all

[glacial elm]

i see wrong

[wicked prism]

This one is just hard

Or I’m stupid

[glacial elm]

it mean calculate or simplify?

the answer is inf decimal number

[wicked prism]

Calculate

But caclculate is used sometimes as simplify

😵‍💫

[glacial elm]

if it means
36^(log_6 5) -1/4

then theres a fraction answer

if is 36^(log_6 5 -1/4)

then thats decimal number for the ans

[wicked prism]

Ye

Umm

Actually

Idk

And I don’t have the answer sheet

[wicked prism]

Ima close cuz fr there is no answer

.close

[midnight plank]

Channel closed

Closed by @wicked prism

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[dark locust]

hey guys im trying to learn derivatives. (scope)

did he put 1/h here (multiply to it) bcs he put the missing denominator terms in the numerator?do i have to put 1/h everytime i do that or does 1/h have another purpose

[short gorge]

I believe the 1/h is on the outside for neatness

i think he just took the 1/h out

[dark locust]

wait wait sorry what do u meaaan? 😭

[short gorge]

one seocnd

[dark locust]

okayy

[short gorge]

as in he went from

to

[dark locust]

AHHH bcs theres no h below theree

I GET ITTT

[short gorge]

yeaaa

[dark locust]

thank youuu 😭

[short gorge]

np

[dark locust]

^^

.close

[midnight plank]

Channel closed

Closed by @dark locust

Use .reopen if this was a mistake.

[hazy reef]

.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[midnight plank]

Please don't occupy multiple help channels.

[bright mango]

ok

[lyric charm]

.close

[midnight plank]

Channel closed

Closed by @lyric charm

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[shell fractal]

the range for theta

the one i got isnt matchin the ans

not sure why

[visual tiger]

what's your answer?

and maybe show your process to finding the answer

[shell fractal]

1min

bruh

phone isnt uploading the pic

but i got r

as 4 cos square (thetha - pi/2)

i solved for |r|<1

finally

[visual tiger]

so $\cos^2\left(\theta- \frac \pi 2\right) < \frac 14$

[grand pond]

rafilou is not not born in 2003

[visual tiger]

or $-\frac 12 < \cos\left(\theta- \frac \pi 2\right) < \frac 12$

[grand pond]

rafilou is not not born in 2003

[shell fractal]

yes

[visual tiger]

so now we can for example look at trig circle

[shell fractal]

alr

[visual tiger]

So you can notice

that we want theta- pi/2

to result in a point in between the lines

[shell fractal]

yes

[visual tiger]

we can use this trig circle as reference of values

[shell fractal]

💀

[visual tiger]

(it's just basic values don't worry too much about it)

[shell fractal]

i got it

but

i dont think

il have that

to refer in tmrs exam

i can just use quadrant rue

but it aint givin ans that matches ans

[visual tiger]

technically you only need three values

pi/6, pi/4, pi/3

and 0 or pi/2

[lethal path]

neat

[visual tiger]

then you can infer all the other values using "quadrant rules" as you said

[visual tiger]

also I just noticed that we need vertical lines here

[lethal path]

yep so if you start from the 4th quadrant

it's -2pi/3 < theta - pi/2 < -pi/3 and pi/3 < theta - pi/2 < 2pi/3, just to confirm

[visual tiger]

because cos

so those are the correct strips

[lethal path]

ah shit yeah we were working with theta - pi/2

[visual tiger]

afterwards

to start finding the points cos(...) = 1/2

[shell fractal]

wdym here

[lethal path]

fixed, the answer was right before but I skipped a step

[visual tiger]

you only need to remember cos and sin of pi/6, pi/4 and pi/3

[shell fractal]

ye

[visual tiger]

all the other values that appear here

can be found using formulas such as cos(x+pi/2), etc...

[lethal path]

wait one sec with my thing

[shell fractal]

so if i solved the right hand

[shell fractal]

for this

[visual tiger]

say you wanna solve cos(...) < 1/2 sure

[shell fractal]

theta - pi/2 can be 60 or 300

theta < 150 or 390 only 150 fits in range

[visual tiger]

small hiccup

[shell fractal]

ye what

[visual tiger]

actually two problems

you're solving for =

or < ?

[shell fractal]

< right

[visual tiger]

we need a more visual approach if you wanna solve trig inequalities

because we're gonna miss out a lot

and we need to remember that no matter the inequality we get on theta

we can always shift it by a multiple of 2pi

[shell fractal]

alr

[visual tiger]

so

first you need to settle on a branch of angles to solve "cos(...) < 1/2" on