#help-49
1 messages · Page 129 of 1
This may be a dumb question but this person who answered this question is wrong about the green part right?
Like he's assuming that the % score is positively correlated with the probability of being hired
is that why he wrote 0.64 or lower? But that makes no sense because it feels like the assumption is unfounded
they probably shouldve written less than 0.65 instead, ye
that's fair enough but still
where did they get the upper bound of 0.65?
using this assumption
purely mathematically, you cant make that assumption
It's sloppy notation
but it's a reasonable assumption to make irl anyway
yeah i mean even in real life, this assumption might be wrong cuz someone might have other factors besides grades
but also he's an "expert" so i wanted to clarify
its not grades, its skill test thats part of the application
oh yeah
okay here's my mathematical reasoning
without this assumption
Quantity A can be anything between 0 and 1,inclusive, because the two events are independent
The complement of "an applicant who scores 80 percent of greater on the test..." -> an applicant who scores 80 percent or lower on the test is 0.35 but this doesn't say anything about Quantity A, so i guess it's just word play?
its a pretty weird question honestly
i just read the paragraph below it and I dont like it
here he literally says "hey, the probability will be different if he scores 10% and if he scores 70%"
but am i being dumb or i'm missing where exactly the question is supposed to be hard
only apparently
if i understand that correctly, i think he meant sth like
"This question appears to be hard, but it's really not"
Okay i think this is his way of saying quantity A can be anything between 0 and 0.65 i think
and he's showing that Quantity A can be on either side of 0.35
hence a comparison can't be made
oh
but i still don't get it
what's so hard about this question
wouldn't everyone get this right
cuz there's just no information
we shouldn't assume anything else about the applicant
is it okay if i say quantity A can be anything between 0 and 1
cuz we don't know about other outside factors?
and not bound it above by 0.65
quantity A is indeed any probability
that depends
purely mathematically, yeah
yeah cuz there are many factors that could've influenced a person's score, but that doesn't take away from his chances of landing a job?
idk i don't rsee a reason to bound it above by 0.65
Lol
Like okay kinda makes sense but surely there are exceptions too?
the question only mentions what happens to a >=80% scorer, and nothing about a <80% scorer, so yee
but if you take reality into account, 0.65 is a reasonable bound to make, and what if this bound actually made the question solvable?
yeah exactly
They could hire 65% of those who score well and none who don't, or they could hire 65% of those who score well and all who score poorly. You can't know
yeah but the bounds have to be the only case?
this is maybe a bit subjective?
we do not even know if the test is supposed to be graded positively - what if 0% was the maximum? ;)
I saw in another site that this question was also listed hard with some entry level olympiad questions
That's why i thought
i'm missing something lol
if we are supposed to solve the problem purely mathematically, then I agree. But if you were supposed to solve it from persepctive of e.g. an economist or someone like that, then you should take the other factors into account
strictly speaking, I'd also think that this is too little context to even fit into reality
no perspective
wait
maybe this is a logic test
but also this is a math portion
so i think anything goes right?
Okay i guess that's that
This question is pretty stupid
ye
😭
the solution is more stupid though
the solution is stupidest
especially this paragraph
why?
the question is stupid, but ultimately acceptable
What's the probability that a natural number between 1 and 100 is even?
why? isn't this just his way of saying that quantity A is bounded below by 0 and above by 0.65
the solution writer believed that score change must mean pass probability change
so you can't compare with quantity B
quantity A should not have been bounded to 0.65, at all
What's the probability that a natural number between 1 and 100 is even?
"Well, we cannot know, because if the number was not divisible by 4, the probability would be different"
this is literally how the solution works
no but isn't he doing this
because ultimately the question is like
to compare with 0.35
the solution writer was doing it, yes
only that their answer was wrong
their final choice is right, but their reasoning is wrong
but i think that's debatable?
he says that in case he scored 10%, the probability would be <0.35, and in case he scored 75% the probability would be >0.35
he is splitting it up into cases to argue that we cant know what the probability is
thats the same thing I did here
if he argued that it could be >0.35 and <0.35 depending on how strict the company is, it would be completely fine
but this is just stupid
yeah i think he was providing examples with this
not sure why
the previous assumption was at least "common sense"
its not providing examples, its the core of his argument unfortunately
he argues that B could be < 0.35 if the applicant scored 10%
but you cant handle the cases seperately like that
the two cases should not have yielded something relative to 35%
each case is just from 0 to 1, amirite 😎
there is just one probability
should've written "for example" maybe lol
then the argument would be incomplete
isn't it just like a proof by contradiction, to an extent
10% is attainable and it is striclty less than 35%
and also 75% is assumedly attainable too which is greater than 35%
the core of his argument is this:
it's possible that B < A, which happens when applicant scores 10%
it's also possible that B > A, which happens when applicant scores 75%
10% is the score on the test
so two examples could work as a proof here? cuz this isn't an proof by example but rather just contradiction ro something like that
why does "for example" not fix his solution?
The 10% is the score on a test, not probability
he doesnt compare 10% to 0.35 at all
the solution writer does not mean that at all
Idk what the solution is trying to say
mmmm
i think maybe i should write a solution on that site
😭
let me write it lol
this is all way too confusing
"part of the solution involves explaining why the expert is wrong"
oh so it's between 0 and 1
if he compared 10% on a test to 0.35, it would be wrong as well
yeah okay, so?
oh
i think i get your point
righttt
i think he was doing too much
idk why
Read the question.
The stem tells us that an applicant scoring 80% or greater on the test has a 65% chance of being hired.
It does not tell us what happens to applicants scoring less than 80% on the test.
Therefore, we cannot assign a probability to quantity A.As such, D is the answer.
I read this as
"The applicant could score 10%, in which case quantity A < 0.35", in other words, the probability that he gets accepted < 0.35
that's also how I read that
and this is really stupid
it's not "0.10 is less than 0.35", but rather "0.10 on the test means a probability of passing less than 0.35"
and both views are incorrect.
What's the probability that a natural number between 1 and 100 is even?
"Well, we cannot know, because if the number was not divisible by 4, the probability would be 33%, but if it was divisible by 4, it would be 100%." Therefore D is the right answer
ye
yeah, that solution is just senseless
it doesnt make sense from the mathematical perspective, nor from the common sense perspective
so you mean he just brought up the test score of the applicant
ye
which has nothing to do with the comparison
exactly
ye * 2
you were supposed to determine the probability of the applicant getting the job given just that his score was below 80%
right i seee now
and you are supposed to calculate that probability as a whole
okay i get how the question was hard
it was his solution all along
which was hard
that probability doesnt change if you are given a different applicant
yes fair enough
75% on the test is basically = 30% on the test
cuz they're both
less than 80%
for this question
so for quantity A it gives you the same answer
mmmm okay
that's how you were supposed to group them, ye
you should treat them equally basically
you can propose to edit the solution :3
u can if u want
i found the question online
oopid site lol
thanks
...not recent - it's nearly 6 months old
A) recent
B) 7 months old
😭
recent could be 8 months so A > B but recent could also be yesterday so B > A
lol
also it's recent bc uh i think all his solutions
in the context of answering questions, 3 months or older is already not ideal
I swear
like most of it are an year old
If you are done with this channel, please mark your problem as solved by typing .close
Closed by @gusty falcon
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hey anyone from econ background?
yea
maths+ stats
but ive never experienced it
okay
umm, do you have like an actual question or formula
kk
thanks
@frail cosmos Has your question been resolved?
.close
Closed by @surreal moon
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Cicadas have an unusual life cycle. The adults live for a few weeks to lay eggs underground before dying. The offspring spend several years underground as eggs and larvae before they emerge as adults to repeat the cycle. All the cicadas of the same species emerge as adults in the same year. Four different species of cicadas have life cycles of $2,$ $4,$ $13$ and $17$ years. If all four species were present in their adult form in the year $2000,$ what is the next year in which the adults of exactly three of the four species will be present?
938c2cc0dcc05f2b68c4287040cfcf71
guys can someone explain what they mean with the exercise statement
"all the cicadas of the same species emerge as adults in the same year"
"four different species of cicadas have life cycles 2,4,13 and 17 years"
<@&268886789983436800>
why post that in my help channel?
All of the eggs laid by a single species will hatch in the same year
The life cycle of a species is the time it takes from the eggs being laid until they hatch and lay new eggs.
if all were present in their adult form in the year 2000
in year 2000 they layed eggs even though they are from different species
such a coincidence
Yes, and the question wants to know what would be the next year this coincidence happens, given that it happened in 2000.
but depending on which three species the year changes
it wants to find the year in which different three random species layed eggs by coincidence
Yes. Let $a,b,c,d$ be the four species, and $\ell_x$ be the length of the life cycle of each species $x \in {a,b,c,d}$. So $\ell_a = 2$, $\ell_b = 4$, $\ell_c = 13$ and $\ell_d = 17$. Notice that a species $x$ will lay eggs in the year $2000+t$, where $t \in \mathbb{N}$, if and only if $\ell_x | t$.
ucheo
From that, you can find $t$ such that exactly three species lay eggs in $2000 + t$.
ucheo
why l_x div t
We have that species $a$, for example, lays eggs every 2 years. Since they laid eggs in 2000, we know that they will lay eggs in 2002, 2004, 2006, etc. That is, they lay eggs exacly after a multiple of $\ell_a$ has passed since 2000.
ucheo
Can you see that?
Yes. So species $x$ will lay eggs after $t$ years since 2000 if and only if $\ell_x | t$.
ucheo
so?
So you want to find the smallest $t$ such that $\ell_x | t$ for exactly three values of $x \in {a,b,c,d}$.
ucheo
also, the year in which three species lay eggs at the same time doesnt it changes if the three chosen species changes
Yes!
You just want to find the smallest year for which that happens for any 3 species.
how
like I need to compare lcm (a,b,c) with lcm (b,c,d)
Yes, you want to find the smallest lcm of three of the four values (:
If it helps, notice that 2, 13 and 17 are prime
Think about the prime factorization of $t$
ohh
ucheo
This specific values of $t$ satisfies what we want!
ucheo
But is it the smallest one?
It is not
Right!
So, the smallest $t$ that is divisible by 2, 4 and 13 is $4 \times 13 = 52$ :)
ucheo
Since that is the smallest multiple of three of the four values, that would be the smallest number of years in which exactly three species will lay eggs
Did you understand the thought process?
kinda yeah, but is hard to explain with words
lcm(2,4,13) is the least
common multiple
Yes
Closed by @tidal turret
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Hi
@velvet nebula stop spamming help channels. If you have a math question, ask it. If you just want to chat, go to #discussion or #chill
.close
Closed by @worthy wing
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
hi
Not exactly a question but advice
I have a C+ like 79.73 percent I want to boost my grade upto a b+ and i have one month only before the semester ends
any tips shall i do extensions
or anything to improve my quiz or tests scores
ping me
Well, do you know how much percentage of the course grade you are done with?
What do you mean by that.
As in, you currently have a 79.73%
If this represents 50% of the weight of your grade, then if you get a 100% on every single test from here on in, then you can achieve a B+ but not an A. (100% * 0.5 + 79.73% * 0.5 = 89.5ish%)
But if this represents 80% of your grade then it's not possible.
I don't need a A because if I get b+ or higher for first semester then I can join geometry.
next year
My recommendation is if you need to get your grade up, the number one thing you can do is ask your teacher or professor for extra credit and for direction
I will try that
He or she will have a much stronger idea of your weaknesses and the material you need
Tysm for the tip.
I always wondered why I get bad scores in Math
but I get straight A's in everything else
I don't go to any outside extra learning or extra curs for now
math is not for everyone, it is totally okay
like omni said, try asking your teachers on resources and credits
some practice would help too, look for problem sets and practice them until you master the concepts you are struggling with
@elder viper Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
what formula do i use to solve this
up to you
could be something like y=A2^{t/20}
or y=Ae^{kt} and find k
just something exponential
.close
Closed by @tight jasper
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I need help
its -i
Closed by @remote owl
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Euler discovered that the polynomial $p(n) = n^2 - n + 41$ yields prime numbers for many small positive integer values of $n$. What is the smallest positive integer $n$ for which $p(n)$ and $p(n+1)$ share a common factor greater than $1$?
938c2cc0dcc05f2b68c4287040cfcf71
well do you know the first value of n such that p(n) is not prime
well if you plug in p(n+1)=n^2+2n+1-n-1+41=n^2+n+41
gcd(p(n),p(n+1))=gcd(n^2-n+41,n^2+n+41)
continue with euclids division algorithm
@tidal turret Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
what happens to a k dimensional linear surface under a homorphism h mapping R^n to R^m
a homomorphism of what kind?
@fossil urchin Has your question been resolved?
Closed by @fossil urchin
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
for this problem
is that a property of logs
im not sure thats what my teacher told me
but im doing it with this method and for some reason im getting my questions wrong
$\ln(x^n) = n\ln x$
knief
you should also use $\ln \left(\frac{a}{b}\right) = \ln a - \ln b$
im trying to do derivatives though
knief
yes it makes it easier
instead of having to do quotient rule
for your chain rule
oh
yo can soemeone help me rq
quandale
ye
!occupied
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
oops
ok let me try it with this
im still getting the wrong answer
What am I doing wrong
its supposed to be 48x^2
i did the derivative of ln(x^5)
uhh derivative of ln is 1/x
so i put 1/x^5
did chain rule
and power rule x^5 to get 5x^4?
its wrong up there but i changed it when i was going down
to 5x^4
Closed by @spark gazelle
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
the fathers age is six time his sons age. four years hence, the age of the father will be four times his sons age. find the present ages (in years) of the son and the father
.close
Closed by @terse robin
Use .reopen if this was a mistake.
In Figure P-420, assume that counter diagonals act from B to E and from E to F in addition to the counter diagonals CD and DG shown in the figure. Assuming that these counter diagonals can support tension only, determine which diagonals are acting and the force in each.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

i am sendin my question
?
today is no help channel day
Anjali I’m literally typing one right now can you please go to a different channel, it’s not easy to copy paste on mobile
Hello, just wondering if what I’m thinking of makes sense:
If you graph the derivative of x^2 sin(1/x)
its envelope near 0 is a double-parabola yes
However it is not
you were 10 seconds close from seeing the light
What are it’s coefficients
coefficients as what?
I’ve computationally figured out that it fits
1 + 2x^2 - 2x^4 + 4x^6 - 10x^8 + 28x^10 at least so far
Now I don’t see a pattern here since the method I’m using to find them is very manual
you're trying to Taylor approximate f'(x) near 0?
I would recommend that you plot this, I can’t show you since I’m on mobile
I’ve got a solution for showing you I think
This graph is a year old so it is mostly unorganized
You can see the nested fraction which from there the coefficients come out, edit and see
The general look is for the peaks to appear constant (or for the parabolic peaks in the center to have a “y-intercept” of 0) before moving on to the next nest, also it’s assuming the coefficients are all integers (which shouldn’t be the case if this was more rigorous)
In retrospect this isn’t very solid, but that it appears and simplifies similar to a series is what’s keeping it to me
Now I am going to sleep zzzzzzzz
@last slate Has your question been resolved?
Closed by @humble meteor
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
.lol
I wanna ask the math wizards or math enthusiast on how should one understand/study mathematics in general? And how should one cope with every defeat of confidence in each failed process of solving or a mind gobbling sessions of "what the heck does that thing means" or "how does that work"?
I'm starting to try and build a passion on learning mathematics, but it seems that in each lessons or process or solutions i gather, i have this troubling question of, "how should i understand this?" Or how should i approach into trying to understand this one? But in each process of trying to feel my way of understanding it, i always end up being all drained and is still not confident on the idea that i did understood what ive been studying for a couple of hours.
Which level are you at
That’s a big yapp
(grade)
...
Im at grade 12 rn, like a senior high type shit going around my country
Understandable
Just a kid asking for a help, yap police
But im starting math at algebra 1
What
Yes, cause im trying to understand each concept at its core
As what you can read here
Im having trouble on conceptualizing what it means to "i understand this shit at its core"
Pick up Principia Mathematica then. That's as fundamental as math gets.
Just make sure you can do questions about the topic at a certain accuracy
And you understand the sols
Taking time to understand is normal
Are you suuureee??? Isnt that just being like a follower to a certain techniques and such, and having know idea how and why they work
...
Oh! I think you accidentally put 1 in there.
Wdym?
or 2
Hey
Mhm
@weary fjord very polite.
Anyway as long as youre satisfied with the accuracy
For me its around 90%
So basically, just ask the right question and thats it?
Thats the way on understanding every concept in a way that you could get them by its how and why they work
(?)
I meant do more questions, as long as you understand the sols and get more than like say 80% correct then youre good
Wdym by sols...
Questions, like problems and stuff to answer?
Solutions
Do you have worksheets or mock tests
As far as i know, i do. Whyd u ask?
Do them blud
Frfr
@tawdry laurel but then my worry would be that, i should just memorize techniques and solutions?
Until i perfected them?
No lah
What do you mean by techniques
应用做题
I'll guess you're Singaporean
Like the how to solve this one
Second guess taiwanese
Some methods have to remember tho
My bio
But if you didnt look there then youre a good guesser
It's the lah fr
You understand them as you practice, you are not gonna invent something that has already been invented
Average singlish moment😭
So just do the problems and then you'll get it?
The much you do them, the much you'll understand them(?)
Yes siah
Memorizing techniques is fine but you should also know how they work
You will not recall anything if you do it without understanding
You’ll forget it after a week or so
Abuden
😂
I suggest you to get a teacher
Now what do you mean by knowing how they work(?)
They’ll accelerate the learning process
The reasoning behind why we use such techniques
Can you give an example of what you mean by technique
Because I'm not sure if we're thinking about the same thing frfr
Say in system of equations, isnt substitution a form of technique to solve them?
Now what i want to know is why do they work
I cant seem to visualize them or something
Nah we cant help with that
Graph
Nah i meant, i cant understand why they work in a way that i could see it and be able to explain why they work
So in substitution we find one variable in terms of another
And use that expression in the other equation
https://youtu.be/jLhMemW5pfI?si=Jypfq9kxXOLCmR0s this guy explains stuff in-depth, I recommend watching his videos
https://www.patreon.com/ProfessorLeonard
What a System of Linear Equations represents and how to find a solution.
We find the variable in a way that we're finding its equation or how its graphed technically?
Oh man....
But at its core, i should just do more problems and learn along the way?
Or should i first understand the why and how they work and stuff(?)
Practicing first then looking at the theory part makes stuff less foggy
Going in head first not knowing what the topic is about is kind of difficult
Ohhhh.. okioki ill try this method next time i learn something new
So i first try to figure out how they are solved
Then move to why they work
Sure , gotta revise them though
You’re gonna forget about this if you will not revise frequently
I assume you’re an entrant
Ig soo
If you’re trying to get into a university, I would just get a teacher if I were you
I wouldn’t worry about the theory part
In the entrance exams you’ll not be asked to explain a topic
But ion know, ig im more concerned with the idea of learning things than just simply passing
@rancid flame Has your question been resolved?
Closed by @rancid flame
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
yo no clue what to do here
Try arcatn(x/5)=u
Closed by @tender vector
Use .reopen if this was a mistake.
who tf even made this server lmao
...
Someone probably
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Hi
$a_{21}x + b_{21}y= b_1$
The book said that these would represent 2 lines
And the solution of these equations would give us the intersection of these 2 lines
How to relate this to vectors 😅
That's right yeah. Each equation is true along some line, so if you find where both equations are true at the same time, it has to be a point that is on both lines. There's only 1 (or 0) possible intersection points like that.
_ _
One way to relate it to vectors is by turning the equations into dot product equations, like this for your 1st:
If you do this for both, you can then notice that it's the same as this matrix equation:
Which is the more complete vector picture
(not fond of the double-use of b in your eqs btw lol)
But having just one basis vector doesn't make any sense
Neither of those vectors are basis vectors
It's just an equation that is true at every point on the line
You have some constant vector [a11, b11], and you dot that with your position vector [x, y]. The result of that dot product is constant (= b1) along the line.
If I call the first vector A, and the second vector r, then the dot product is |A| |r| cos(θ). Clearly |A| is constant. Now |r| cos(θ) is the distance to the position |r| from the origin in the direction of A.
Isnt the constant vector the transformed basis vector?
I should be watching 3B1b videos again ig 😔
Hmm
The dot product equation means that |r| cos(θ) is constant, which describes a line
Constant offset from the origin along the direction of A
That's the geometrical picture if you really want it
Could you give me some time
(A can be any length, I've just drawn it up to the line for neatness)
Yea
At this point I'm not talking about any sort of change of basis or anything like that
It's just regular vector geometry stuff
Honestly it would be enough just to see that the dot product equation is exactly the same thing numerically as the original, if you multiply it out
Yeah that clears it up but
Alright
I was stuck at the thought of a matrix multiplication always having one basis vector and the other being an arbitrary position vector :p
Lol I will use a_12 from next time
Thanks
.close
Closed by @gleaming geode
Use .reopen if this was a mistake.
Np 👍
You can think about basis vectors once you're at the matrix equation
The matrix M changes the vector [1, 0] into [a11, a21], and the vector [0, 1] into [b11, b21], so you can think of it as this kind of change of basis
.reopen
✅
Solving the matrix equation is finding the answer to the question "How do I express [b1, b2] in that new basis?"
Perpendicular to it - the line of your equation is the upper dotted line there
Shitz
Since you require that the component of r in the direction of A is constant, which is true all along that dotted line
(The length of the blue line is constant)
The dot product gives me the component of x y along the vector a b
Yeah with an extra factor
Wait how can the length of the blue line be a constant ?
Doesn't it change with changing x y
If I add a second r to compare it to:
As long as r is on the line, that distance is constant
Yeah it depends on a11, b11, and b1
Which is just the slope and the intercept
Lol I'm overcomplicating it
Thanks a lot!
.closr
.close
Closed by @gleaming geode
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Given that $a$ is an odd multiple of $1183$, find the greatest common divisor of $2a^2+29a+65$ and $a+13$.
938c2cc0dcc05f2b68c4287040cfcf71
hmm
can I have some help tbh
do I need to know the prime factorization of 1183?
I never understand this gcd exercises tbh
Factorise your quadratic.
using synthetic division?
or can I do long division of polynomials?
let me bring pen and paper
Its a quadratic 💀
Bro sure u can do that..do u not know middle term splitting?
middle term splitting?
hmm?
well first thing i notice is both of them must be even
so maybe that might mean something idk
why even
since a must be odd
a+13 is even
(odd) + (odd) = (even)
and 2a² + 29a + 65 is even
(even)(odd)² = (even)
(odd)(odd) = (odd)
(even) + (odd) + (odd) = (even)
so?
they both have common factor 2
that might not be their gcf but they atleast have a common factor 2
okay
I never understand why he wanted me to factor the polynomial
$\polylongdiv{2x^2+29x+65}{x+13}$
938c2cc0dcc05f2b68c4287040cfcf71
2a^2 + 29a + 65 = (a+13)(2a+3) + 26
ok so maybe you need to know the prime factorization of 1183
,calc 1183/7
Result:
169
1183 = 7 × 169
169 is 13²
13 is prime
so its 7 x 13 x 13
ok so lets say a = 1183N
where N is some odd number bec odd multiple and what not
try plugging a in for the first eq
but dont evaluate bec youll get a headache doing so
wdym
in where
@tidal turret Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
An equilateral triangle $ABC$ shares a common side $BC$ with a square $BCDE,$ as pictured. What is the number of degrees in $\angle DAE$ (not pictured)?
938c2cc0dcc05f2b68c4287040cfcf71
What about dae
Idk
Im not sure
Can you find DCA?
you sure?
Isoceles
15
Dae = 30
yes, how did you arrive at that?
Because 15+15+30=60
Thank you, it was hard tho
as you practice more they become easy and obvious
practice makes perfect
you can close now
.solved
Closed by @tidal turret
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Quaster
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.
rip
Oops it closed sorry
But yeah was wondering for that, and sorry my english might be a little bad
Yes, you could. It's just the same idea.
(but proving may be difficult)
Oh alright! Thanks!
!done
If you are done with this channel, please mark your problem as solved by typing .close
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Let the line $\mathcal{L}: \lambda(-1, 1, 3) + (0, -1, 1)$ and the point $P = (-5, 7, 4)$. Determine, if possible, a line $\mathcal{L}'$ that simultaneously satisfies:
[
\mathcal{L}' \cap \mathcal{L} \neq \emptyset, \quad P \in \mathcal{L}', \quad \text{and} \quad \mathcal{L}' \perp \mathcal{L}.
]
938c2cc0dcc05f2b68c4287040cfcf71
if L' is orthogonal to L, their directions vectors are orthogonal aswell
,w (-5,7,4) × (-1,1,3)
,w (-5,7,4).(17,11,2)
let me bring pen and paper
we know this lines intersect right, so lets find the intersection, shall we
Well if there perpendicular they neccessarly have a non-empty intersection
help
Vectors are orthogonals, lines are perpendiculars
oh
Its equivalent
like when I was
No sense
P is a point
But
Think
Think of a vector that can start from the line and go to the point
doing (a,b,c).(-1,1,3) = 0
I got a = b+ 3c
now
(b+3c,b,c) = b(1,1,0) + c(3,0,1)
so its a 3d subspace <(1,1,0),(3,0,1)> the possibles direction vectors for L'
,w (1,1,0) x (3,0,1)
I am trying
@tidal turret Has your question been resolved?
@tidal turret Has your question been resolved?
@tidal turret Has your question been resolved?
Closed due to timeout
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Prove that $
Closed by @twilit field
Use .reopen if this was a mistake.
.reopen
✅
prove that $\frac{2n+1}{5n+4}$ converges to $\frac{2}{5}$
ƒ( wai ina teacup)= I don't know
$\abs{\frac{10n+5-2(5n+4)}{5n+4}} < \varepsilon \implies \frac{3}{5n+4} < \varepsilon$
ƒ( wai ina teacup)= I don't know
$n>\frac{1}{5} \left(\frac{3}{\varepsilon}-4 \right)$
ƒ( wai ina teacup)= I don't know
so something like this suffices for n
right
Thanks!
One more limit
just a minute
Same question for $\frac{2n^2}{n^3+3}$
ƒ( wai ina teacup)= I don't know
Why not 2n^3 in denominator
ƒ( wai ina teacup)= I don't know
so $\frac{1}{n} < \varepsilon \implies n> \frac{1}{\varepsilon}$
ƒ( wai ina teacup)= I don't know
Oh wait did the original question not have a 2
You just need to multiply your 1/eps by 2 or 1/2
$\frac{sin(n^2)}{n^{\frac{1}{3}}}$
ƒ( wai ina teacup)= I don't know
This is a bit more tricky as the numerator can be negative
doesn't matter you're working with absolute values anyways
$\abs{$\frac{sin(n^2)}{n^{\frac{1}{3}}}} < \frac{1}{\varepsilon}$
ƒ( wai ina teacup)= I don't know
Compile Error! Click the
reaction for more information.
(You may edit your message to recompile.)
[
\abs{\frac{\sin(n^2)}{n^{\frac{1}{3}}}} < \varepsilon ]\
ƒ( wai ina teacup)= I don't know
do you need help or do you got it
yes
hmm
if you need a hint ||use the fact that |sin x| is bounded||
yep
Closed by @twilit field
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Give an example of a seqeunce with an infinite number of ones that doesn't converge to 1
I was thinking of $a_n= (-1)^n$
ƒ( wai ina teacup)= I don't know
12121212…
this works
Thanks!
if you have an infinite number of 1’s in your sequence, the sequence will either approach 1 or diverge.
by the way

I suppose I have to prove the limit doesn't converge , don't I?
the limit is a number so it can’t converge or not converge
one can show that the sequence doesn’t converge from a specific choice of epsilon
I suppose epsilon =1 works here
yeah
$\abs{-1-1}$ isn't less than $1$
ƒ( wai ina teacup)= I don't know
yep
Next question
A seqeunce with an infinite number of ones that converges to a number not equal to 1
This sisn't possible
Are you saying this as a guess or do you have a proof
I'm trying to think of a proof
i am so good at foreshadowing
i just made this remark out of nowhere lol
Let's suppose such a sequence did exist. Let this limit be $a$. It then implies for all $n \geq N, \abs{x_n-a} < \varepsilon$ for all $\varepsilon >0$
ƒ( wai ina teacup)= I don't know
does this seq count as diverging?
yea
alr
Now what

if a is not 1 then..
Let's suppose such a sequence did exist. Let this limit be $a$. It then implies for all $n \geq N, \abs{x_n-a} < \varepsilon$ for all $\varepsilon >0$. If $a \neq 1$. Then we have two cases. Suppose $a>1$, then setting $\varepsilon =x_n-1$, we arrive at a contradiction
ƒ( wai ina teacup)= I don't know
similarly for $a<1$
ƒ( wai ina teacup)= I don't know
how do you know xn -1 is positive
then also do you need to take two separate cases?
also, what's the logic behind setting epislon to xn-1
doesn't seem right to me
you have yo show that for some epsilon ( you have yo tell which one)
there will always be a Xn for some n that |Xn-a| is not less than epsilon
|x_n-a|/2
yeap
Closed by @twilit field
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
Does a sequence exist such that for every $n \in \N$ it is possible to find $n$ consecutives ones somewhere in the sequence
ƒ( wai ina teacup)= I don't know
I don't think such a sequence exists
!occupied
Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).
no. you are not.
💀
<@&268886789983436800> trolls
Gone
💀 , what was that
Reduced to atoms
I'm not following what you are asking here
won't this just be (1, 0, 1, 1, 0, 1, 1, 1, 0, 1, 1, 1, 1 ...)
I mean I guess this diverges so yeah
god dammit why is there a show called "the divergent series". Ruining my google searches
But I'd have to show it diverges
sure do that
I mean intutively it can only converge to 0 or 1
you can't get arbitrarily close to 1 since there's always a 0 somewhere
But I have to show it cannot converge to any other value either
I don't know cauchy sequences 😭
I mean the book doesn't explicitly ask for a proof
so idk
then skip it
Closed by @twilit field
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
@barren onyx Has your question been resolved?
.close
Closed by @barren onyx
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
john and pete have 3 pieces of paper each of the boys pick up one piece teares it up and puts the smmaller peices back john only ttears a piece of paper into 3 smaller peices while pete only tears a piece of paper into 5 smaller piece aftera few minutes can there be exactly 100 peices
my working was each time john tears its (2n + 1) + 2 when oete tears its (4p+1) + 2 so it is possible
Closed by @vast junco
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
I'm trying to understand the proof of : Every convergent sequence is bounded
The idea is usually that the tail of the sequence is bounded. So you can take that bound and all the finitely many remaining terms then take the max.
u mean x_n
yes
|x_n - l| < 1
Do reverse triangle to the above and you get the bound for the tail basically.
because of that:
Closed by @twilit field
Use .reopen if this was a mistake.
Send your question here to claim the channel.
Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!
Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.
