#help-49

1 messages · Page 129 of 1

gusty falcon
midnight plankBOT
gusty falcon
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This may be a dumb question but this person who answered this question is wrong about the green part right?

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Like he's assuming that the % score is positively correlated with the probability of being hired

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is that why he wrote 0.64 or lower? But that makes no sense because it feels like the assumption is unfounded

dreamy lichen
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they probably shouldve written less than 0.65 instead, ye

gusty falcon
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where did they get the upper bound of 0.65?

gusty falcon
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but why?

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isn't that assumption just a guess?

dreamy lichen
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purely mathematically, you cant make that assumption

radiant roost
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It's sloppy notation

dreamy lichen
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but it's a reasonable assumption to make irl anyway

gusty falcon
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yeah i mean even in real life, this assumption might be wrong cuz someone might have other factors besides grades

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but also he's an "expert" so i wanted to clarify

dreamy lichen
gusty falcon
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oh yeah

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okay here's my mathematical reasoning

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without this assumption

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Quantity A can be anything between 0 and 1,inclusive, because the two events are independent

The complement of "an applicant who scores 80 percent of greater on the test..." -> an applicant who scores 80 percent or lower on the test is 0.35 but this doesn't say anything about Quantity A, so i guess it's just word play?

dreamy lichen
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its a pretty weird question honestly

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i just read the paragraph below it and I dont like it

gusty falcon
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Lol i'm not sure what's being tested either

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He also said "this question is hard"

dreamy lichen
gusty falcon
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but am i being dumb or i'm missing where exactly the question is supposed to be hard

dreamy lichen
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if i understand that correctly, i think he meant sth like
"This question appears to be hard, but it's really not"

gusty falcon
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and he's showing that Quantity A can be on either side of 0.35

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hence a comparison can't be made

gusty falcon
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but i still don't get it

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what's so hard about this question

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wouldn't everyone get this right

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cuz there's just no information

dreamy lichen
gusty falcon
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cuz we don't know about other outside factors?

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and not bound it above by 0.65

digital leaf
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quantity A is indeed any probability

dreamy lichen
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purely mathematically, yeah

gusty falcon
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yeah cuz there are many factors that could've influenced a person's score, but that doesn't take away from his chances of landing a job?

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idk i don't rsee a reason to bound it above by 0.65

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Lol

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Like okay kinda makes sense but surely there are exceptions too?

digital leaf
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the question only mentions what happens to a >=80% scorer, and nothing about a <80% scorer, so yee

dreamy lichen
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but if you take reality into account, 0.65 is a reasonable bound to make, and what if this bound actually made the question solvable?

radiant roost
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They could hire 65% of those who score well and none who don't, or they could hire 65% of those who score well and all who score poorly. You can't know

gusty falcon
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this is maybe a bit subjective?

digital leaf
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we do not even know if the test is supposed to be graded positively - what if 0% was the maximum? ;)

gusty falcon
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I saw in another site that this question was also listed hard with some entry level olympiad questions

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That's why i thought

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i'm missing something lol

dreamy lichen
digital leaf
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strictly speaking, I'd also think that this is too little context to even fit into reality

gusty falcon
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wait

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maybe this is a logic test

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but also this is a math portion

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so i think anything goes right?

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Okay i guess that's that

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This question is pretty stupid

digital leaf
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ye

gusty falcon
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😭

dreamy lichen
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the solution is more stupid though

digital leaf
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the solution is stupidest

dreamy lichen
gusty falcon
digital leaf
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the question is stupid, but ultimately acceptable

dreamy lichen
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What's the probability that a natural number between 1 and 100 is even?

gusty falcon
digital leaf
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the solution writer believed that score change must mean pass probability change

gusty falcon
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so you can't compare with quantity B

digital leaf
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quantity A should not have been bounded to 0.65, at all

dreamy lichen
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What's the probability that a natural number between 1 and 100 is even?
"Well, we cannot know, because if the number was not divisible by 4, the probability would be different"

dreamy lichen
gusty falcon
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because ultimately the question is like

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to compare with 0.35

digital leaf
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the solution writer was doing it, yes

gusty falcon
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he's showing A can be either < 0.35 or > 0.35

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so isn't it okay?

digital leaf
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only that their answer was wrong

gusty falcon
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yeah i don't believe the 0.65 upper bound

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imo it's 1

digital leaf
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their final choice is right, but their reasoning is wrong

gusty falcon
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but i think that's debatable?

dreamy lichen
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he says that in case he scored 10%, the probability would be <0.35, and in case he scored 75% the probability would be >0.35

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he is splitting it up into cases to argue that we cant know what the probability is

dreamy lichen
digital leaf
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lol

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equally confusing

dreamy lichen
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if he argued that it could be >0.35 and <0.35 depending on how strict the company is, it would be completely fine

gusty falcon
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he's just doing too much

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💀

gusty falcon
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not sure why

dreamy lichen
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the previous assumption was at least "common sense"

dreamy lichen
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he argues that B could be < 0.35 if the applicant scored 10%

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but you cant handle the cases seperately like that

digital leaf
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the two cases should not have yielded something relative to 35%
each case is just from 0 to 1, amirite 😎

dreamy lichen
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there is just one probability

gusty falcon
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should've written "for example" maybe lol

dreamy lichen
gusty falcon
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isn't it just like a proof by contradiction, to an extent

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10% is attainable and it is striclty less than 35%

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and also 75% is assumedly attainable too which is greater than 35%

dreamy lichen
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the core of his argument is this:

it's possible that B < A, which happens when applicant scores 10%
it's also possible that B > A, which happens when applicant scores 75%

dreamy lichen
gusty falcon
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so two examples could work as a proof here? cuz this isn't an proof by example but rather just contradiction ro something like that

dreamy lichen
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not the probability

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that's the problem

gusty falcon
dreamy lichen
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he doesnt compare 10% to 0.35 at all

gusty falcon
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doesn't he say 10% < 0.35 😭

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i'm confused

digital leaf
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the solution writer does not mean that at all

gusty falcon
radiant roost
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Idk what the solution is trying to sayopencry

gusty falcon
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i think maybe i should write a solution on that site

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😭

digital leaf
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let me write it lol

gusty falcon
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this is all way too confusing

dreamy lichen
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the quantity A itself is probability

gusty falcon
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"part of the solution involves explaining why the expert is wrong"

gusty falcon
dreamy lichen
# gusty falcon

if he compared 10% on a test to 0.35, it would be wrong as well

gusty falcon
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yeah okay, so?

gusty falcon
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i think i get your point

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righttt

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i think he was doing too much

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idk why

digital leaf
# gusty falcon this is all way too confusing

Read the question.
The stem tells us that an applicant scoring 80% or greater on the test has a 65% chance of being hired.
It does not tell us what happens to applicants scoring less than 80% on the test.
Therefore, we cannot assign a probability to quantity A.

As such, D is the answer.

dreamy lichen
# gusty falcon

I read this as
"The applicant could score 10%, in which case quantity A < 0.35", in other words, the probability that he gets accepted < 0.35

digital leaf
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that's also how I read that

digital leaf
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it's not "0.10 is less than 0.35", but rather "0.10 on the test means a probability of passing less than 0.35"

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and both views are incorrect.

gusty falcon
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mmmmmm right

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this question is messing with my head for no reason

dreamy lichen
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What's the probability that a natural number between 1 and 100 is even?
"Well, we cannot know, because if the number was not divisible by 4, the probability would be 33%, but if it was divisible by 4, it would be 100%." Therefore D is the right answer

digital leaf
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ye

gusty falcon
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actually

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his solution is

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not the question

dreamy lichen
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yeah, that solution is just senseless

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it doesnt make sense from the mathematical perspective, nor from the common sense perspective

gusty falcon
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so you mean he just brought up the test score of the applicant

digital leaf
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ye

gusty falcon
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which has nothing to do with the comparison

dreamy lichen
digital leaf
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ye * 2

dreamy lichen
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you were supposed to determine the probability of the applicant getting the job given just that his score was below 80%

gusty falcon
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right i seee now

dreamy lichen
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and you are supposed to calculate that probability as a whole

gusty falcon
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okay i get how the question was hard

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it was his solution all along

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which was hard

dreamy lichen
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that probability doesnt change if you are given a different applicant

digital leaf
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*shouldn't

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;)

gusty falcon
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75% on the test is basically = 30% on the test

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cuz they're both

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less than 80%

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for this question

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so for quantity A it gives you the same answer

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mmmm okay

digital leaf
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that's how you were supposed to group them, ye

dreamy lichen
digital leaf
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it should apply to everyone

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as long as their score was < 80%

gusty falcon
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right okay thanks

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this is sorted

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😭

digital leaf
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you can propose to edit the solution :3

gusty falcon
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u can if u want

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i found the question online

digital leaf
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oopid site lol

dreamy lichen
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thanks

gusty falcon
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oh it's recent too

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😭

digital leaf
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...not recent - it's nearly 6 months old

gusty falcon
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A) recent
B) 7 months old

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😭

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recent could be 8 months so A > B but recent could also be yesterday so B > A

digital leaf
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lol

gusty falcon
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also it's recent bc uh i think all his solutions

digital leaf
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in the context of answering questions, 3 months or older is already not ideal
I swear

gusty falcon
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like most of it are an year old

digital leaf
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ah

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then that whole account is dead

gusty falcon
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like see

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he made an account almost a decade back

digital leaf
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the dude can cope

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!done

midnight plankBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

gusty falcon
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alright thanks

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guys

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.close

midnight plankBOT
#
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frail cosmos
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hey anyone from econ background?

midnight plankBOT
last slate
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?

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economics??

frail cosmos
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yea

last slate
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this is math. unless you combining math and economics

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i know about finances

frail cosmos
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maths+ stats

last slate
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but ive never experienced it

frail cosmos
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okay

last slate
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umm, do you have like an actual question or formula

frail cosmos
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nvrmnd it was related to econ

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thanks tho

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:))

last slate
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if you wanna chill, scroll down to the chill section

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np

frail cosmos
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kk

smoky forge
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yeah

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1+1=

last slate
#

2

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11

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window

smoky forge
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thanks

midnight plankBOT
#

@frail cosmos Has your question been resolved?

surreal moon
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.close

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tidal turret
#

Cicadas have an unusual life cycle. The adults live for a few weeks to lay eggs underground before dying. The offspring spend several years underground as eggs and larvae before they emerge as adults to repeat the cycle. All the cicadas of the same species emerge as adults in the same year. Four different species of cicadas have life cycles of $2,$ $4,$ $13$ and $17$ years. If all four species were present in their adult form in the year $2000,$ what is the next year in which the adults of exactly three of the four species will be present?

grand pondBOT
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938c2cc0dcc05f2b68c4287040cfcf71

tidal turret
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guys can someone explain what they mean with the exercise statement

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"all the cicadas of the same species emerge as adults in the same year"

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"four different species of cicadas have life cycles 2,4,13 and 17 years"

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<@&268886789983436800>

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why post that in my help channel?

hollow helm
hollow helm
tidal turret
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in year 2000 they layed eggs even though they are from different species

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such a coincidence

hollow helm
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Yes, and the question wants to know what would be the next year this coincidence happens, given that it happened in 2000.

tidal turret
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but depending on which three species the year changes

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it wants to find the year in which different three random species layed eggs by coincidence

hollow helm
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Yes. Let $a,b,c,d$ be the four species, and $\ell_x$ be the length of the life cycle of each species $x \in {a,b,c,d}$. So $\ell_a = 2$, $\ell_b = 4$, $\ell_c = 13$ and $\ell_d = 17$. Notice that a species $x$ will lay eggs in the year $2000+t$, where $t \in \mathbb{N}$, if and only if $\ell_x | t$.

grand pondBOT
hollow helm
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From that, you can find $t$ such that exactly three species lay eggs in $2000 + t$.

grand pondBOT
tidal turret
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why l_x div t

hollow helm
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We have that species $a$, for example, lays eggs every 2 years. Since they laid eggs in 2000, we know that they will lay eggs in 2002, 2004, 2006, etc. That is, they lay eggs exacly after a multiple of $\ell_a$ has passed since 2000.

grand pondBOT
hollow helm
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Can you see that?

tidal turret
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ok

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2 div 2
2 div 4
2 div 6 etc

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like that?

hollow helm
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Yes. So species $x$ will lay eggs after $t$ years since 2000 if and only if $\ell_x | t$.

grand pondBOT
tidal turret
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so?

hollow helm
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So you want to find the smallest $t$ such that $\ell_x | t$ for exactly three values of $x \in {a,b,c,d}$.

grand pondBOT
tidal turret
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also, the year in which three species lay eggs at the same time doesnt it changes if the three chosen species changes

hollow helm
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Yes!

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You just want to find the smallest year for which that happens for any 3 species.

tidal turret
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like I need to compare lcm (a,b,c) with lcm (b,c,d)

hollow helm
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Yes, you want to find the smallest lcm of three of the four values (:

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If it helps, notice that 2, 13 and 17 are prime

tidal turret
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how does that help

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,w definition prime number

grand pondBOT
hollow helm
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Think about the prime factorization of $t$

tidal turret
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ohh

grand pondBOT
tidal turret
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t = (2×13 × 17)

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because 2,13,17 are primes

hollow helm
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This specific values of $t$ satisfies what we want!

grand pondBOT
hollow helm
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But is it the smallest one?

tidal turret
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yes because 4 > 2

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idk

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4 = 2 × 2 in prime factorization

hollow helm
hollow helm
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So, the smallest $t$ that is divisible by 2, 4 and 13 is $4 \times 13 = 52$ :)

grand pondBOT
hollow helm
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Since that is the smallest multiple of three of the four values, that would be the smallest number of years in which exactly three species will lay eggs

tidal turret
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2052

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damn

hollow helm
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Did you understand the thought process?

tidal turret
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kinda yeah, but is hard to explain with words

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lcm(2,4,13) is the least

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common multiple

hollow helm
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Yes

tidal turret
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I mean I see I see

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thank you for the help

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.solved

midnight plankBOT
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velvet nebula
#

Hi

midnight plankBOT
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Please don't occupy multiple help channels.

weary fjord
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!noask

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!dontask

worthy wing
#

#

This loop is weird

surreal moon
#

@velvet nebula stop spamming help channels. If you have a math question, ask it. If you just want to chat, go to #discussion or #chill

worthy wing
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.close

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elder viper
#

hi

midnight plankBOT
elder viper
#

Not exactly a question but advice

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I have a C+ like 79.73 percent I want to boost my grade upto a b+ and i have one month only before the semester ends

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any tips shall i do extensions

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or anything to improve my quiz or tests scores

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ping me

carmine sigil
#

Well, do you know how much percentage of the course grade you are done with?

elder viper
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What do you mean by that.

carmine sigil
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As in, you currently have a 79.73%

elder viper
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Yes

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for entire semester yes

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including quarter 1 and 2 combined

carmine sigil
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If this represents 50% of the weight of your grade, then if you get a 100% on every single test from here on in, then you can achieve a B+ but not an A. (100% * 0.5 + 79.73% * 0.5 = 89.5ish%)

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But if this represents 80% of your grade then it's not possible.

elder viper
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I don't need a A because if I get b+ or higher for first semester then I can join geometry.

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next year

carmine sigil
#

My recommendation is if you need to get your grade up, the number one thing you can do is ask your teacher or professor for extra credit and for direction

carmine sigil
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He or she will have a much stronger idea of your weaknesses and the material you need

elder viper
#

I always wondered why I get bad scores in Math

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but I get straight A's in everything else

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I don't go to any outside extra learning or extra curs for now

rain wasp
#

math is not for everyone, it is totally okay

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like omni said, try asking your teachers on resources and credits

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some practice would help too, look for problem sets and practice them until you master the concepts you are struggling with

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tight jasper
#

what formula do i use to solve this

midnight plankBOT
hearty rune
#

up to you
could be something like y=A2^{t/20}

or y=Ae^{kt} and find k

#

just something exponential

tight jasper
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.close

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remote owl
#

I need help

midnight plankBOT
remote owl
#

I dont understand what the negative in front means

knotty frost
#

its -i

remote owl
#

Ohhh

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.close

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tidal turret
#

Euler discovered that the polynomial $p(n) = n^2 - n + 41$ yields prime numbers for many small positive integer values of $n$. What is the smallest positive integer $n$ for which $p(n)$ and $p(n+1)$ share a common factor greater than $1$?

grand pondBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

lavish venture
#

well do you know the first value of n such that p(n) is not prime

viral dagger
#

well if you plug in p(n+1)=n^2+2n+1-n-1+41=n^2+n+41
gcd(p(n),p(n+1))=gcd(n^2-n+41,n^2+n+41)

#

continue with euclids division algorithm

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fossil urchin
#

what happens to a k dimensional linear surface under a homorphism h mapping R^n to R^m

west iron
#

a homomorphism of what kind?

midnight plankBOT
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spark gazelle
#

for this problem

midnight plankBOT
spark gazelle
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can i put the power of 4

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in front of ln

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to make

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it

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4ln(x^5/(4x^2+1))

lavish venture
#

is that a property of logs

spark gazelle
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im not sure thats what my teacher told me

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but im doing it with this method and for some reason im getting my questions wrong

lavish venture
#

$\ln(x^n) = n\ln x$

grand pondBOT
lavish venture
#

you should also use $\ln \left(\frac{a}{b}\right) = \ln a - \ln b$

spark gazelle
#

im trying to do derivatives though

grand pondBOT
lavish venture
#

instead of having to do quotient rule

#

for your chain rule

spark gazelle
#

oh

austere hare
#

yo can soemeone help me rq

lavish venture
#

quandale

austere hare
#

ye

lavish venture
#

!occupied

midnight plankBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

austere hare
#

oops

spark gazelle
#

im still getting the wrong answer

#

What am I doing wrong

#

its supposed to be 48x^2

lavish venture
#

all wrong tbh

#

how is the derivative of 4ln(x^5) = 4x^5/x^5

spark gazelle
#

i did the derivative of ln(x^5)

#

uhh derivative of ln is 1/x

#

so i put 1/x^5

#

did chain rule

#

and power rule x^5 to get 5x^4?

#

its wrong up there but i changed it when i was going down

#

to 5x^4

last slate
#

the lack of parenthesis is ..

#

not good

spark gazelle
#

i just want to konw where the 48 came from 😭

#

pls

#

nvm i figured it out

#

.close

midnight plankBOT
#
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terse robin
#

the fathers age is six time his sons age. four years hence, the age of the father will be four times his sons age. find the present ages (in years) of the son and the father

terse robin
#

.close

midnight plankBOT
#
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prime hornet
humble drift
midnight plankBOT
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last slate
#

.

#

hi

midnight plankBOT
strong lava
last slate
#

i am sendin my question

last slate
dawn dagger
twilit jetty
#

Anjali I’m literally typing one right now can you please go to a different channel, it’s not easy to copy paste on mobile

Hello, just wondering if what I’m thinking of makes sense:

If you graph the derivative of x^2 sin(1/x)

strong lava
#

its envelope near 0 is a double-parabola yes

twilit jetty
#

However it is not

viral dagger
#

you were 10 seconds close from seeing the light

twilit jetty
#

What are it’s coefficients

strong lava
#

coefficients as what?

twilit jetty
#

I’ve computationally figured out that it fits
1 + 2x^2 - 2x^4 + 4x^6 - 10x^8 + 28x^10 at least so far

#

Now I don’t see a pattern here since the method I’m using to find them is very manual

strong lava
#

you're trying to Taylor approximate f'(x) near 0?

twilit jetty
#

I would recommend that you plot this, I can’t show you since I’m on mobile

#

I’ve got a solution for showing you I think

#

This graph is a year old so it is mostly unorganized

#

You can see the nested fraction which from there the coefficients come out, edit and see

#

The general look is for the peaks to appear constant (or for the parabolic peaks in the center to have a “y-intercept” of 0) before moving on to the next nest, also it’s assuming the coefficients are all integers (which shouldn’t be the case if this was more rigorous)

#

In retrospect this isn’t very solid, but that it appears and simplifies similar to a series is what’s keeping it to me

Now I am going to sleep zzzzzzzz

midnight plankBOT
#

@last slate Has your question been resolved?

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last slate
#

.lol

rancid flame
#

I wanna ask the math wizards or math enthusiast on how should one understand/study mathematics in general? And how should one cope with every defeat of confidence in each failed process of solving or a mind gobbling sessions of "what the heck does that thing means" or "how does that work"?

I'm starting to try and build a passion on learning mathematics, but it seems that in each lessons or process or solutions i gather, i have this troubling question of, "how should i understand this?" Or how should i approach into trying to understand this one? But in each process of trying to feel my way of understanding it, i always end up being all drained and is still not confident on the idea that i did understood what ive been studying for a couple of hours.

weary fjord
#

That’s a big yapp

tawdry laurel
#

(grade)

tawdry laurel
rancid flame
tawdry laurel
#

Understandable

rancid flame
tawdry laurel
#

Treat math like a game

#

If you do it reward yourself

rancid flame
tawdry laurel
#

What

rancid flame
tawdry laurel
#

Ah

#

Then practise is key

rancid flame
#

Im having trouble on conceptualizing what it means to "i understand this shit at its core"

astral bough
tawdry laurel
#

Just make sure you can do questions about the topic at a certain accuracy

#

And you understand the sols

#

Taking time to understand is normal

rancid flame
tawdry laurel
#

...

weary fjord
last slate
rancid flame
weary fjord
tawdry laurel
#

@weary fjord very polite.

tawdry laurel
#

For me its around 90%

rancid flame
#

Thats the way on understanding every concept in a way that you could get them by its how and why they work

#

(?)

tawdry laurel
#

I meant do more questions, as long as you understand the sols and get more than like say 80% correct then youre good

rancid flame
tawdry laurel
tawdry laurel
rancid flame
tawdry laurel
#

Do them blud

last arch
#

Frfr

rancid flame
#

@tawdry laurel but then my worry would be that, i should just memorize techniques and solutions?

#

Until i perfected them?

devout cove
#

What do you mean by techniques

tawdry laurel
#

应用做题

last arch
rancid flame
last arch
#

Second guess taiwanese

tawdry laurel
#

Some methods have to remember tho

tawdry laurel
last arch
#

Ah ok

#

I guessed correct yippee

tawdry laurel
#

But if you didnt look there then youre a good guesser

last arch
#

It's the lah fr

devout cove
last arch
#

Average singlish moment😭

rancid flame
#

The much you do them, the much you'll understand them(?)

tawdry laurel
last arch
devout cove
#

You will not recall anything if you do it without understanding

#

You’ll forget it after a week or so

last arch
tawdry laurel
#

😂

devout cove
#

I suggest you to get a teacher

rancid flame
devout cove
#

They’ll accelerate the learning process

last arch
#

Can you give an example of what you mean by technique

rancid flame
#

Waits

last arch
#

Because I'm not sure if we're thinking about the same thing frfr

rancid flame
#

Now what i want to know is why do they work

#

I cant seem to visualize them or something

tawdry laurel
tawdry laurel
rancid flame
# tawdry laurel Graph

Nah i meant, i cant understand why they work in a way that i could see it and be able to explain why they work

last arch
#

And use that expression in the other equation

rancid flame
#

Oh man....

#

But at its core, i should just do more problems and learn along the way?

#

Or should i first understand the why and how they work and stuff(?)

devout cove
#

Practicing first then looking at the theory part makes stuff less foggy

#

Going in head first not knowing what the topic is about is kind of difficult

rancid flame
#

So i first try to figure out how they are solved

#

Then move to why they work

devout cove
#

Sure , gotta revise them though

#

You’re gonna forget about this if you will not revise frequently

#

I assume you’re an entrant

rancid flame
devout cove
#

If you’re trying to get into a university, I would just get a teacher if I were you

#

I wouldn’t worry about the theory part

#

In the entrance exams you’ll not be asked to explain a topic

rancid flame
midnight plankBOT
#

@rancid flame Has your question been resolved?

#
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tender vector
midnight plankBOT
tender vector
#

yo no clue what to do here

twilit field
#

Try arcatn(x/5)=u

tender vector
#

tyty

#

.close

midnight plankBOT
#
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full ridge
#

who tf even made this server lmao

tawdry laurel
last arch
midnight plankBOT
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last slate
#

Hi

midnight plankBOT
last slate
#

say I have 2 linear equations with 2 variables

#

$a_{11}x + b_{11}y= b_1$

grand pondBOT
last slate
#

$a_{21}x + b_{21}y= b_1$

grand pondBOT
last slate
#

The book said that these would represent 2 lines

#

And the solution of these equations would give us the intersection of these 2 lines

#

How to relate this to vectors 😅

rotund oar
#

If you do this for both, you can then notice that it's the same as this matrix equation:

#

Which is the more complete vector picture

#

(not fond of the double-use of b in your eqs btw lol)

last slate
rotund oar
#

Neither of those vectors are basis vectors

#

It's just an equation that is true at every point on the line

#

You have some constant vector [a11, b11], and you dot that with your position vector [x, y]. The result of that dot product is constant (= b1) along the line.

#

If I call the first vector A, and the second vector r, then the dot product is |A| |r| cos(θ). Clearly |A| is constant. Now |r| cos(θ) is the distance to the position |r| from the origin in the direction of A.

last slate
#

I should be watching 3B1b videos again ig 😔

#

Hmm

rotund oar
#

The dot product equation means that |r| cos(θ) is constant, which describes a line

#

Constant offset from the origin along the direction of A

#

That's the geometrical picture if you really want it

last slate
#

Could you give me some time

rotund oar
#

(A can be any length, I've just drawn it up to the line for neatness)

#

Yea

#

At this point I'm not talking about any sort of change of basis or anything like that

#

It's just regular vector geometry stuff

#

Honestly it would be enough just to see that the dot product equation is exactly the same thing numerically as the original, if you multiply it out

last slate
#

Yeah that clears it up but

#

Alright

#

I was stuck at the thought of a matrix multiplication always having one basis vector and the other being an arbitrary position vector :p

last slate
#

Thanks

#

.close

midnight plankBOT
#
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rotund oar
#

Np 👍

#

You can think about basis vectors once you're at the matrix equation

#

The matrix M changes the vector [1, 0] into [a11, a21], and the vector [0, 1] into [b11, b21], so you can think of it as this kind of change of basis

last slate
#

.reopen

midnight plankBOT
#

rotund oar
#

Solving the matrix equation is finding the answer to the question "How do I express [b1, b2] in that new basis?"

last slate
#

That I understand

#

One more thingg

last slate
#

?

rotund oar
#

Perpendicular to it - the line of your equation is the upper dotted line there

last slate
#

Shitz

rotund oar
#

Since you require that the component of r in the direction of A is constant, which is true all along that dotted line

#

(The length of the blue line is constant)

last slate
#

The dot product gives me the component of x y along the vector a b

rotund oar
#

Yeah with an extra factor

last slate
#

Wait how can the length of the blue line be a constant ?

#

Doesn't it change with changing x y

rotund oar
#

If I add a second r to compare it to:

#

As long as r is on the line, that distance is constant

last slate
#

Ah

#

So the line depends on a b

rotund oar
#

Yeah it depends on a11, b11, and b1

last slate
#

Which is just the slope and the intercept

#

Lol I'm overcomplicating it

#

Thanks a lot!

#

.closr

#

.close

midnight plankBOT
#
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midnight plankBOT
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tidal turret
#

Given that $a$ is an odd multiple of $1183$, find the greatest common divisor of $2a^2+29a+65$ and $a+13$.

grand pondBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

tidal turret
#

hmm

#

can I have some help tbh

#

do I need to know the prime factorization of 1183?

#

I never understand this gcd exercises tbh

wind oxide
tidal turret
#

using synthetic division?

#

or can I do long division of polynomials?

#

let me bring pen and paper

wind oxide
wind oxide
tidal turret
#

middle term splitting?

tidal turret
#

,rotate

grand pondBOT
tidal turret
#

how do I find out 29^2

#

I am trying

#

how do I find sqrt(321)

grand pondBOT
tidal turret
#

hmm?

fathom tendon
#

well first thing i notice is both of them must be even

#

so maybe that might mean something idk

tidal turret
#

why even

fathom tendon
#

since a must be odd

#

a+13 is even

#

(odd) + (odd) = (even)

#

and 2a² + 29a + 65 is even

#

(even)(odd)² = (even)
(odd)(odd) = (odd)
(even) + (odd) + (odd) = (even)

tidal turret
#

so?

fathom tendon
#

they both have common factor 2

#

that might not be their gcf but they atleast have a common factor 2

tidal turret
#

okay

#

I never understand why he wanted me to factor the polynomial

#

$\polylongdiv{2x^2+29x+65}{x+13}$

grand pondBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

tidal turret
#

2a^2 + 29a + 65 = (a+13)(2a+3) + 26

fathom tendon
#

ok so maybe you need to know the prime factorization of 1183

tidal turret
#

,calc 1183/7

fathom tendon
#

do you want the factors

#

i have them already

grand pondBOT
#

Result:

169
tidal turret
#

1183 = 7 × 169

fathom tendon
#

169 is 13²

tidal turret
fathom tendon
#

so its 7 x 13 x 13

tidal turret
#

ye

fathom tendon
#

ok so lets say a = 1183N

#

where N is some odd number bec odd multiple and what not

#

try plugging a in for the first eq

#

but dont evaluate bec youll get a headache doing so

tidal turret
#

wdym

fathom tendon
#

like

#

plug in 1183N as a

tidal turret
#

in where

fathom tendon
#

actually just wait a moment

#

2(1183N)² + 29(1183N) + 65

#

and

#

(1183N) + 13

midnight plankBOT
#

@tidal turret Has your question been resolved?

midnight plankBOT
#
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midnight plankBOT
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tidal turret
#

An equilateral triangle $ABC$ shares a common side $BC$ with a square $BCDE,$ as pictured. What is the number of degrees in $\angle DAE$ (not pictured)?

grand pondBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

tidal turret
main owl
#

square is all right angles

#

and equilateral triangle has same angles

tidal turret
#

What about dae

main owl
#

what do you think the answer is

#

and why do u think it

tidal turret
#

Idk

main owl
#

bruh

#

0 idea?

tidal turret
#

Im not sure

last blade
#

Can you find DCA?

tidal turret
#

120

#

No

urban eagle
#

you sure?

tidal turret
#

Wait

#

90 + 60

#

= 150

urban eagle
#

good

#

what do you notice about triangle DCA?

tidal turret
#

Isoceles

urban eagle
#

yes

#

so base angles are equal; try compute angle CAD

tidal turret
#

15

urban eagle
#

yes

#

finally, express angle CAB in terms of the sum of 3 smaller angles

tidal turret
#

Dae = 30

urban eagle
#

yes, how did you arrive at that?

tidal turret
#

Because 15+15+30=60

urban eagle
#

yes

#

well done

tidal turret
#

Thank you, it was hard tho

urban eagle
#

as you practice more they become easy and obvious

#

practice makes perfect

#

you can close now

tidal turret
#

.solved

midnight plankBOT
#
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midnight plankBOT
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midnight plankBOT
grand pondBOT
#

Quaster
Compile Error! Click the errors reaction for more information.
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surreal moon
#

rip

deft ravine
#

Oops it closed sorry

deft ravine
surreal moon
#

(but proving may be difficult)

deft ravine
thorn sorrel
#

!done

midnight plankBOT
#

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tidal turret
midnight plankBOT
tidal turret
#

Let the line $\mathcal{L}: \lambda(-1, 1, 3) + (0, -1, 1)$ and the point $P = (-5, 7, 4)$. Determine, if possible, a line $\mathcal{L}'$ that simultaneously satisfies:
[
\mathcal{L}' \cap \mathcal{L} \neq \emptyset, \quad P \in \mathcal{L}', \quad \text{and} \quad \mathcal{L}' \perp \mathcal{L}.
]

grand pondBOT
#

938c2cc0dcc05f2b68c4287040cfcf71

tidal turret
#

if L' is orthogonal to L, their directions vectors are orthogonal aswell

#

,w (-5,7,4) × (-1,1,3)

grand pondBOT
tidal turret
#

,w (-5,7,4).(17,11,2)

grand pondBOT
tidal turret
#

let me bring pen and paper

#

we know this lines intersect right, so lets find the intersection, shall we

grim vector
#

Well if there perpendicular they neccessarly have a non-empty intersection

tidal turret
#

help

grim vector
tidal turret
#

oh

grim vector
#

Its equivalent

tidal turret
#

like

#

idk what to do doe

grim vector
#

You want to fine a perpendicular line

#

To L

tidal turret
#

like when I was

grim vector
#

P is a point

#

But

#

Think

#

Think of a vector that can start from the line and go to the point

tidal turret
#

doing (a,b,c).(-1,1,3) = 0
I got a = b+ 3c
now
(b+3c,b,c) = b(1,1,0) + c(3,0,1)
so its a 3d subspace <(1,1,0),(3,0,1)> the possibles direction vectors for L'

#

,w (1,1,0) x (3,0,1)

grand pondBOT
midnight plankBOT
#

@tidal turret Has your question been resolved?

tidal turret
midnight plankBOT
#

@tidal turret Has your question been resolved?

midnight plankBOT
#

@tidal turret Has your question been resolved?

midnight plankBOT
#
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midnight plankBOT
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twilit field
#

Prove that $

midnight plankBOT
twilit field
#

shit

#

.close

midnight plankBOT
#
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twilit field
#

.reopen

midnight plankBOT
#

twilit field
#

prove that $\frac{2n+1}{5n+4}$ converges to $\frac{2}{5}$

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

twilit field
#

$\abs{\frac{10n+5-2(5n+4)}{5n+4}} < \varepsilon \implies \frac{3}{5n+4} < \varepsilon$

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

twilit field
#

$n>\frac{1}{5} \left(\frac{3}{\varepsilon}-4 \right)$

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

twilit field
#

so something like this suffices for n

#

right

#

Thanks!

#

One more limit

#

just a minute

#

Same question for $\frac{2n^2}{n^3+3}$

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

twilit field
#

$\frac{2n^2}{2n^3+3}< \frac{2n^2}{2n^3}$

#

does this work

fallow scarab
#

Why not 2n^3 in denominator

twilit field
#

oops

#

my bad

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

twilit field
#

so $\frac{1}{n} < \varepsilon \implies n> \frac{1}{\varepsilon}$

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

twilit field
#

Thanks

#

one last one

fallow scarab
twilit field
#

yeah

#

typos

fallow scarab
#

You just need to multiply your 1/eps by 2 or 1/2

twilit field
#

$\frac{sin(n^2)}{n^{\frac{1}{3}}}$

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

twilit field
#

This is a bit more tricky as the numerator can be negative

sage helm
#

doesn't matter you're working with absolute values anyways

twilit field
#

$\abs{$\frac{sin(n^2)}{n^{\frac{1}{3}}}} < \frac{1}{\varepsilon}$

grand pondBOT
#

ƒ( wai ina teacup)= I don't know
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

twilit field
#

[
\abs{\frac{\sin(n^2)}{n^{\frac{1}{3}}}} < \varepsilon ]\

sage helm
#

uh

#

well okay

twilit field
#

oops

#

[
\abs{\frac{\sin(n^2)}{n^{\frac{1}{3}}}} < \varepsilon
]

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

sage helm
#

do you need help or do you got it

twilit field
#

im thinking

#

do i comapre it with a simpler function

sage helm
#

yes

twilit field
#

hmm

sage helm
#

if you need a hint ||use the fact that |sin x| is bounded||

twilit field
#

just 1/n^{1/3}

#

so that gives n>

#

(1/varepsilon)^3

sage helm
#

yep

twilit field
#

thanks

#

.close

midnight plankBOT
#
Channel closed

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Use .reopen if this was a mistake.

midnight plankBOT
#
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twilit field
#

Give an example of a seqeunce with an infinite number of ones that doesn't converge to 1

twilit field
#

I was thinking of $a_n= (-1)^n$

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

misty gorge
twilit field
#

Thanks!

misty gorge
#

if you have an infinite number of 1’s in your sequence, the sequence will either approach 1 or diverge.

#

by the way

twilit field
twilit field
misty gorge
#

one can show that the sequence doesn’t converge from a specific choice of epsilon

twilit field
#

yeah, that's what I meant

#

oops

misty gorge
#

i’m being a bit pedantic

#

but i like being pedantic in this situation

twilit field
misty gorge
#

yeah

twilit field
#

$\abs{-1-1}$ isn't less than $1$

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

misty gorge
#

yep

twilit field
#

Next question

#

A seqeunce with an infinite number of ones that converges to a number not equal to 1

#

This sisn't possible

fallow scarab
twilit field
#

I'm trying to think of a proof

misty gorge
#

i just made this remark out of nowhere lol

twilit field
#

Let's suppose such a sequence did exist. Let this limit be $a$. It then implies for all $n \geq N, \abs{x_n-a} < \varepsilon$ for all $\varepsilon >0$

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

clear void
twilit field
#

yea

clear void
#

alr

clear void
#

if a is not 1 then..

twilit field
#

Let's suppose such a sequence did exist. Let this limit be $a$. It then implies for all $n \geq N, \abs{x_n-a} < \varepsilon$ for all $\varepsilon >0$. If $a \neq 1$. Then we have two cases. Suppose $a>1$, then setting $\varepsilon =x_n-1$, we arrive at a contradiction

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

twilit field
#

similarly for $a<1$

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

clear void
#

how do you know xn -1 is positive

twilit field
#

|x_n-1|

#

my bad

clear void
#

then also do you need to take two separate cases?

clear void
#

doesn't seem right to me

#

you have yo show that for some epsilon ( you have yo tell which one)
there will always be a Xn for some n that |Xn-a| is not less than epsilon

twilit field
#

|x_n-a|/2

clear void
#

yeap

twilit field
#

Thanks!

#

.close

midnight plankBOT
#
Channel closed

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midnight plankBOT
#
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Show your work, and if possible, explain where you are stuck.
After 15 minutes, feel free to ping <@&286206848099549185>.
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twilit field
#

Does a sequence exist such that for every $n \in \N$ it is possible to find $n$ consecutives ones somewhere in the sequence

grand pondBOT
#

ƒ( wai ina teacup)= I don't know

twilit field
#

I don't think such a sequence exists

surreal moon
#

!occupied

midnight plankBOT
#

Someone else is already using this help channel. If you need help with a question, please open your own help channel/thread (see #❓how-to-get-help for instructions).

surreal moon
#

no. you are not.

brazen moth
#

💀

surreal moon
#

<@&268886789983436800> trolls

brazen moth
#

Gone

twilit field
#

💀 , what was that

brazen moth
#

Reduced to atoms

surreal moon
#

anyway....

surreal moon
twilit field
#

I;ll send a picture of the OG question

#

that's better

sage helm
twilit field
#

something like that

#

question (c)

#

does such a sequence exist is the questoion

sage helm
surreal moon
#

god dammit why is there a show called "the divergent series". Ruining my google searches

twilit field
sage helm
#

sure do that

twilit field
#

I mean intutively it can only converge to 0 or 1

sage helm
#

you can't get arbitrarily close to 1 since there's always a 0 somewhere

twilit field
#

But I have to show it cannot converge to any other value either

sage helm
#

okay

#

do that

#

this is probably easier done with a Cauchy sequence

twilit field
#

I don't know cauchy sequences 😭

#

I mean the book doesn't explicitly ask for a proof

#

so idk

sage helm
#

then skip it

twilit field
#

👍

#

Thanks

#

.close

midnight plankBOT
#
Channel closed

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midnight plankBOT
#
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Remember:
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After 15 minutes, feel free to ping <@&286206848099549185>.
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barren onyx
midnight plankBOT
#

@barren onyx Has your question been resolved?

twilit field
#

yes?

#

what's your question

barren onyx
#

<@&286206848099549185>

midnight plankBOT
#

@barren onyx Has your question been resolved?

barren onyx
#

.close

midnight plankBOT
#
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midnight plankBOT
#
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vast junco
#

john and pete have 3 pieces of paper each of the boys pick up one piece teares it up and puts the smmaller peices back john only ttears a piece of paper into 3 smaller peices while pete only tears a piece of paper into 5 smaller piece aftera few minutes can there be exactly 100 peices

my working was each time john tears its (2n + 1) + 2 when oete tears its (4p+1) + 2 so it is possible

vast junco
#

but answers not possible

#

nvm i misread

#

.close

midnight plankBOT
#
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#
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twilit field
#

I'm trying to understand the proof of : Every convergent sequence is bounded

twilit field
#

I'll share my books proof

#

I don't get how n is in the interval (l-1,l+1)

formal blade
#

The idea is usually that the tail of the sequence is bounded. So you can take that bound and all the finitely many remaining terms then take the max.

subtle zinc
twilit field
#

yes

subtle zinc
#

|x_n - l| < 1

formal blade
#

Do reverse triangle to the above and you get the bound for the tail basically.

twilit field
#

Ah

#

I see

#

okay

#

Thanks

fervent ember
twilit field
#

Thanks

#

.close

midnight plankBOT
#
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midnight plankBOT
#
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Remember:
Ask your math question in a clear, concise manner.
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After 15 minutes, feel free to ping <@&286206848099549185>.
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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.