help-49

[violet hedge]

https://www.matemaks.pl/tablice-wartosci-funkcji-trygonometrycznych-dla-katow-ostrych.html

[pale fog]

.close

[midnight plank]

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[last slate]

I'm not sure where to go from here

i thought i could just power rule it but

[midnight plank]

@last slate Has your question been resolved?

[sudden yacht]

You can, indeed

[last slate]

1/106 * (2x-3)^106

?

[sudden yacht]

What's the integral of u¹⁰⁵?

[sudden yacht]

No...

[last slate]

did i do it backwards,

1/106 * u^106?

or is it

1/104 * u^104

[sudden yacht]

Yep, exactly

[sudden yacht]

Well, if you know the correct formula you also know the correct answer 😅

And remember taht you can always check your answer by taking the derivative of what you got

[last slate]

im confused

i kind of forgot how to get it back to x

[sudden yacht]

What was u?

[last slate]

i know i substitute baxk in the value u is replacing

but i don't know what to do with du

[sudden yacht]

Nothing ?!

[last slate]

?

i tried just subbing back in the value of U

[sudden yacht]

The du is just notation for the integral

[last slate]

but im being told its wrong for these questions

[sudden yacht]

Why? You have an expression in the variable u, and now you only need to remember what u was in terms of x

[last slate]

i came here cause

i answered 1/106 * (x^2 - 3)^106 and it said it was wrong,

oh wait i'm dumb

[last slate]

i still don't understand this though,

oh i forgot c

ah welll

thank you for the help thoughh

[sudden yacht]

You're welcome

[sudden yacht]

Omg I feel it

[midnight plank]

@last slate Has your question been resolved?

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• Show your work, and if possible, explain where you are stuck.
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[flint anchor]

find domain of
f(x) = sqrt ((4x^2) + 2x) / 3x - 6

[flint anchor]

i have found denominator

but how do i go on about numerator

[nimble copper]

what must be true about the stuff within the sqrt?

[flint anchor]

i have solved until x(2x+1)>=0

but dont know any further

[nimble copper]

one option is to solve it as if it were an equality, and then test points in between the two zeros to see where it's above or below 0

[flint anchor]

so x>=0 ; 2x+1>=0 and x<=0 ; 2x+1<=0

[nimble copper]

not exactly

your zeros are x = -1/2, 0. So test a point under -1/2, above 0, and one in between to see where the quadratic is pos/neg

[flint anchor]

hmm

where do i test it

[strong stump]

$f(x) = \frac{\sqrt {(4x^2 + 2x)}} {3x - 6}$

[nimble copper]

what do you mean "where"?

[flint anchor]

you said test

[grand pond]

mohammed

[flint anchor]

how do i test

[strong stump]

Is this it? @flint anchor

[nimble copper]

pick a point that's convenient to compute

[flint anchor]

mhm

[flint anchor]

under -1/2 like smaller than -1/2?

[nimble copper]

indeed

[flint anchor]

yes

[flint anchor]

so -1

[nimble copper]

sure

[flint anchor]

what do i do with it

[nimble copper]

is your quadratic positive or negative at x = -1?

[flint anchor]

negative

[nimble copper]

you sure?

[flint anchor]

no

[nimble copper]

well answer only when you're sure

[flint anchor]

ok

[flint anchor]

idk

[nimble copper]

that's concerning

[flint anchor]

why

[nimble copper]

your quadratic is x(2x+1)

when x = -1, is that positive or negative?

[flint anchor]

oh that

it is negative

[nimble copper]

you sure?

[flint anchor]

yes

[nimble copper]

that's unfortunate

,calc -1*(2*(-1) + 1)

[grand pond]

Result:

1

[flint anchor]

oh yeah

-1 * -1 is 1 im stupid

its 1 am my brain is fried

[nimble copper]

fair enough

is it really the best time to be doing math then?

[flint anchor]

no but i have to

i have a test tomorrow

ok so we got 1 what does that mean

[nimble copper]

it means your quadratic is positive

now what does that tell you about all other x-values below -1/2?

[flint anchor]

that they will be positive

or wait

no

if we plug any x value below -1/2 into the quadratic it will be positive

[nimble copper]

much better answer

ok so x-values of at most -1/2 are allowed in the domain

carry on

[flint anchor]

idk

[nimble copper]

i didn't ask you a question

[flint anchor]

wdym

[nimble copper]

i think the sentence is pretty self-explanatory

[flint anchor]

but i still dont know the domain

[nimble copper]

nobody said you were done searching

there are more tests to do

[flint anchor]

so how can i do them

[nimble copper]

i've explained that already

[flint anchor]

.close

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[ember sage]

Can someone tell me what i did wrong for 2 and 4 since the answer used a graphing calculator

[ember sage]

2. is supposed to be 36.5 and 4) is 25.6

[spiral osprey]

it's really hard to read. could you try retaking it so that your writing is clearer?

[ember sage]

Is it better now?

wait ignore #2 i just put in 76 instead of 78 in the calculator

but idk about #4

[spiral osprey]

you want to set the equatio to 20 and solve for d

[ember sage]

h(d) becomes 20?

[spiral osprey]

so you set 20 to the quadratic equation

[ember sage]

i got d = 130.45 and 25.5533...

why reject the 130?

[spiral osprey]

bc it says for the first time

[midnight plank]

@ember sage Has your question been resolved?

[midnight plank]

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• Show your work, and if possible, explain where you are stuck.
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[upbeat plinth]

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[upbeat plinth]

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[digital crag]

When second derivative is positive = concave up and when negative = concave down

[digital crag]

Yes find the cp

[upbeat plinth]

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[digital crag]

Critical points

[upbeat plinth]

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[digital crag]

If it’s a negative value then it’s concave down

Find the critical point first tho

[upbeat plinth]

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[upbeat plinth]

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[digital crag]

Ok so u know at the point -7/4 the graph can have a chance of switching from negative to positive right since that’s the only point it hits 0

[upbeat plinth]

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[digital crag]

Plug in a value from (-infinity, -7/4) and (-7/4, infinity)

[upbeat plinth]

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[digital crag]

Concave up would be from interval (-7/4, infinity)

[upbeat plinth]

One message removed from a suspended account.

[digital crag]

Cause if u plug in any value on thay interval it’ll be positive

[upbeat plinth]

One message removed from a suspended account.

[digital crag]

Yes

[upbeat plinth]

One message removed from a suspended account.

[digital crag]

U can do any point from (-7/4, infinity)

0 would be easiest

Then for (-infinity, -7/4) u can do like -10 and then you can see it’s negative

[upbeat plinth]

One message removed from a suspended account.

[digital crag]

To plug in ur values?

[upbeat plinth]

One message removed from a suspended account.

[digital crag]

Use the second derivative

[upbeat plinth]

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[midnight plank]

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• Show your work, and if possible, explain where you are stuck.
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[eager lantern]

derivative of volume with respect to time is 2 ftcubed per min

tryna find derivative of the height of the trough w/ respect to time at time 2 min

given that they're isoceles with hypoteneus 2 ft (as shown above), so i can imagine h as a straight line from right angle up

I tried making a volume function incorporating height with 1/2 l * w * d but it doesn't work

key says l * h^2

I understand how the latter works

but I do not see the error in mine

actually, is it because width is not always 2?

I imagine I can put width in as width, then use a secondary function with width in terms of height to get the same thing...

.close

[midnight plank]

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Remember:
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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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[steel sigil]

help

[steel sigil]

graph this equation

HELP

YAYAYYAYAYAYYAAYYA SM1 FINAALLLY

NVM

[drifting acorn]

up 10 over 1

[steel sigil]

oh wow

like can i see that in paper?

ur a life saver dude

[drifting acorn]

I can do it in desmos

[steel sigil]

no like i mean do it in paper and send it to me here

so i can see

[drifting acorn]

if 10 is the slope, then you do rise/run

think of 10 as 10/1

meaning you go up 10, and then you move right one

and then at that point (1,10) you'll go up 10 again and over 1

[steel sigil]

ohh yea ur right

[steel sigil]

so on paper it would look like this

[drifting acorn]

yes but draw your scale by 5 so you can go up 10 easier

[steel sigil]

oh ok thxs

if i need any help may i ask here?

thxs dude

[drifting acorn]

yeah js ping me

[steel sigil]

ok thxssss

[steel sigil]

where u from?

[drifting acorn]

colo

[steel sigil]

colorado?

[drifting acorn]

yeah

[steel sigil]

oh niceee

nice metting you

@drifting acorn

[drifting acorn]

you too

[steel sigil]

@drifting acorn

[drifting acorn]

yeah?

[steel sigil]

may i ask a question

math question

[drifting acorn]

sure

[steel sigil]

graphing the equation

like i would know these stuffs if my teachers teaches well

like u should see our math class

it aint a math class no more 😭

mb if i keep bothering u

[drifting acorn]

nah you're good

if you graph it think of it as -7/1 for slope

• usually means left on a graph

So think of -7 as going down 7

and to the right 1

[steel sigil]

so

(-7,1)?

[drifting acorn]

yeah

[steel sigil]

may i ask how it would look like in the graph

[drifting acorn]

lemme pull it up rq

[steel sigil]

alr

[steel sigil]

thank youuuuu

sorry again

[drifting acorn]

don't be sorry you're fine

you can use desmos.com to plug in your equation

[steel sigil]

its js i always have this thing i feel like i bother pple too much

[drifting acorn]

just make sure you have y=

[steel sigil]

yk

[drifting acorn]

sometimes

[steel sigil]

?

[drifting acorn]

I sometimes feel like I bother people

[steel sigil]

ohh haha

[drifting acorn]

but just read the room and you'll be fine

[steel sigil]

whats ur hobby

if u dont mind

me askin....

[drifting acorn]

math
science
basketball
chess
more math

[steel sigil]

oh wow

must be hella smart in math huh

[drifting acorn]

not really

[steel sigil]

oh rlly

[drifting acorn]

its all patterns

[steel sigil]

well lemme tell u that i suck at math

[steel sigil]

real

[drifting acorn]

everyone gets stuck but if you get thru the rest comes easy

[steel sigil]

ye ig thats true

[drifting acorn]

if you use khan academy and yt you'll get better answers

[steel sigil]

oh truuue

may i ask u a question

if u dont mind...

not math

dw 😭

[drifting acorn]

alr

[steel sigil]

what grade r u in?

[drifting acorn]

10th

[steel sigil]

ohh ok

well if i need help ill js text if ur ok with that

ig

[drifting acorn]

yeah fs I'll probably answer 3 PM MST to 8:30 PM MST

[steel sigil]

u in cal?

[neat spoke]

think its 1 hr ahead

[steel sigil]

brug

[neat spoke]

so no.

[steel sigil]

oh hi

[neat spoke]

hello

[steel sigil]

want me to introduce u to this club

not club but math smth ig

[neat spoke]

pass

[steel sigil]

bruh cmon

plz

[neat spoke]

think ik what the purpose is

but go ahead if u wn

[steel sigil]

itll be fun u can know who i am is too

[steel sigil]

yayyy

so uhm im aziza

im tryna learn some math with my friend over here @drifting acorn

and uhm if u need any help im right here

[neat spoke]

me need help?

lol im good

[steel sigil]

alr ig...

[neat spoke]

is that it?

[steel sigil]

no therres more

[neat spoke]

?

[steel sigil]

well like i said im aziza

and im learning math

and thats it ig

not much

[neat spoke]

mhm...

like said...

[steel sigil]

yea

[neat spoke]

u play games fr?

[steel sigil]

yea

[neat spoke]

which?

[steel sigil]

roblox

idk j when im bored

ig

hey uhm @drifting acorn

i js need help on this last one

[drifting acorn]

yeah fs

[steel sigil]

would u explain it to me

[drifting acorn]

slope of 1

think of y = x as y = 1x

[steel sigil]

mhm

ok

[drifting acorn]

the 1 is implied because a 0 would make it y = 0 which is just the x axis

this means you go up 1

and then right 1

[steel sigil]

ok

so then it would be

[drifting acorn]

(1,1) (2,2) etc

[steel sigil]

oh okk

thxs

yo @drifting acorn mb

[drifting acorn]

yeah

[steel sigil]

but would u plz show me how it would look on the graph

sorry....

[drifting acorn]

\

[steel sigil]

thxsss so much

mb again 😅

[drifting acorn]

ur good

[steel sigil]

mh

[midnight plank]

@steel sigil Has your question been resolved?

[midnight plank]

Channel closed

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[steel sigil]

.reopen

[midnight plank]

✅

[idle valley]

shat is your question?

what

[steel sigil]

sorry to bother

need to graph this

[idle valley]

all good

[steel sigil]

but my teacher doesnt know how to teach

[idle valley]

mkay

[steel sigil]

so my math class aint a math class

[idle valley]

do you have graphing paper?

[steel sigil]

yea

[idle valley]

mkay make a little graph

[steel sigil]

already did

[idle valley]

like a big plus sign

ok cool

so let’s do some cute numbers

[steel sigil]

☺️

[idle valley]

what is the value of y when x= 6?

[steel sigil]

1?

[idle valley]

well you have

,,(\frac{7}{6})*6

[grand pond]

☠ cj Σ

[idle valley]

ignore the parentheses

[steel sigil]

ye ye

[idle valley]

so it would just be 7 right since the 6’s cancel out?

[steel sigil]

oh yea

[idle valley]

yeee

[steel sigil]

and how would we graph it tho?

[idle valley]

so now you go to the x axis, find 6 over, and graph 7 up

[steel sigil]

the x axis would be the straighline like this ways right

like straight down

[idle valley]

that’s the y axis

so that’s where you would find seven

[steel sigil]

hold up

lemme send u a graph

here

[idle valley]

soo you see the one that goes from left to right?

that’s the x axis

[steel sigil]

oh ya

[idle valley]

the one that goes from bottom to top is the y axis

[steel sigil]

ok got it

[idle valley]

so now you need to plot a point and we have seen that when x=6, y=7

[steel sigil]

and we need to graph it

[idle valley]

correct

[steel sigil]

(6,7) or (7,6)

[idle valley]

(x,y)

so 6,7

[steel sigil]

oh ok

lemme graph it

[idle valley]

over 6 up 7

[steel sigil]

and see if i did it right

so i would put the 6 on the x axis

and the 7 on the y axis

[idle valley]

not on it

you would do this

you see how that point is at 6 on the x axis and 7 on the x axis?

[steel sigil]

ohh yea

oh ok

so would i put a straight line thru the point

how would the line go then?

[idle valley]

you will need to graph one more point

so let’s see what happens when x is 12

[steel sigil]

ok

[idle valley]

tell me what you get

[steel sigil]

ok

i need help

can u explain whta happenes when x is 12

[idle valley]

yes

you will have

,,\frac{7}{6}*12

[grand pond]

☠ cj Σ

[idle valley]

this is equivalent to

,,\frac{726}{6}

[grand pond]

☠ cj Σ

[idle valley]

since 2 times 6 is 12

from here the 6’s cancel out leaving you with 7 times 2

which is 14

[steel sigil]

yes

[idle valley]

so when x=12 y=14

[steel sigil]

ohh

[idle valley]

it should look something like this

and now you can just draw a line

now notice how the rise over run (the slope) is always equal to 7/6

[steel sigil]

oh ur right

yea i know about the slope

[idle valley]

yeee

[steel sigil]

i js have a hard time understanding and learning especcially in math

[idle valley]

that’s ok

[steel sigil]

and i have exams coming up

[idle valley]

maybe see if there is some after school tutoring you can do if you don’t feel ready

[steel sigil]

wouldu show how the line would be i did it i js wanna check

[steel sigil]

ye i was thinking but idk

[idle valley]

it’s messy but something like that

[steel sigil]

oh then im right

[idle valley]

yayyy

[steel sigil]

thanks sooo much

[idle valley]

no

problem

[steel sigil]

🙂

[idle valley]

have a gn/day

[steel sigil]

u too

[idle valley]

i’m going to go to sleep so feel free to @ helpers if you need help on a diffrent problem

[steel sigil]

ok thxs

[midnight plank]

@steel sigil Has your question been resolved?

[steel sigil]

yes

[brazen moth]

.close

[midnight plank]

Channel closed

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Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[last slate]

Your second step is wrong

[terse mural]

how

[last slate]

sin(4x) is 2sin(2x)cos(2x), not 2sin(2x)cos(x)

[terse mural]

oh

yea

[last slate]

cos(2x) then cancels with the other cos(2x) in the other fraction

[midnight plank]

@terse mural Has your question been resolved?

[terse mural]

help

the thing next 2 the sin at the bottom is an 8

[terse mural]

<@&286206848099549185> sorry 4 ping

idk what 2 do

[midnight plank]

@terse mural Has your question been resolved?

[terse mural]

anybody

plz

<@&286206848099549185>

sry 4 shit handwriting i can explain if confused

[terse mural]

<@&286206848099549185>

[gaunt otter]

@terse mural

sin(4x) = 2sin(2x)cos(2x)

1-cos(2x) = 2sin^2(x)

1-cos(4x) = 2sin^2(2x)

[terse mural]

hold on

[gaunt otter]

leave the cos(2x) in denominator

but use formula to change all others

if you have doubt ping me

[terse mural]

why

[gaunt otter]

wdym

[terse mural]

like how does 1-cos4x = 2sin^2(2x)

[gaunt otter]

insert x = 2x

[terse mural]

what

1-cos4(2x)??

[gaunt otter]

insert A = 2x

[terse mural]

oh

so just factor 2 outta 4x

[gaunt otter]

these are enough

you don't have to expand cos(2x)

the terms will cancel out

[terse mural]

wait

[terse mural]

shouldnt it be 2+2sin^2(2x)

cuz cos2x = 1 - 2sin^2x

and since its 1-cos4a u can add the 1s

[gaunt otter]

what

[terse mural]

like

ok wait

the 1s get subtracted but like

[gaunt otter]

no

[terse mural]

what

[gaunt otter]

the 1 gets subtracted and then multiplied by (-1) both sides

[gaunt otter]

and it give you this

[terse mural]

why are they multiplied by -1

[gaunt otter]

I mean you can leave it as it is

[terse mural]

but why are they multiplied by -1

[gaunt otter]

just sin is negative

[terse mural]

but like

why multiply by -1

where do u get the -1 from

[gaunt otter]

you can multiply and divide by -1 on any one side and then take that -1 to another side

[terse mural]

ok but where do u get the -1 from

[gaunt otter]

cuz -1/-1 = 1

tricks of manipulation

[terse mural]

man

ok

[gaunt otter]

you can introduce anything

like sinx/sinx

[terse mural]

what

ig

i dont understand where ur getting the -1 from to divide it

[gaunt otter]

cos(2x) -1 = -2sin^2(x)

we have this

if you multiply by 1 on both sides will it affect the equation

[terse mural]

where is cos2x - 1

[gaunt otter]

I am giving an example

[terse mural]

ok i get that

but where are u getting hte -1 from in this question

[gaunt otter]

question?

[terse mural]

.

[gaunt otter]

I'm not talking about the question

[terse mural]

im so lost bro

[gaunt otter]

send your work

[terse mural]

one sec

[gaunt otter]

I was talking something not related to the original question, sorry about that

[gaunt otter]

do you know that 1-cos(2x) = 2sin^2(x)

[terse mural]

on the right denom i mean tto write cos2x my bad

[terse mural]

yes'

[gaunt otter]

use that and sin(4x) = 2sin(2x)cos(2x)

[terse mural]

wait

gimme a sec rq

[terse mural]

shouldnt it be -2sin^2x

[gaunt otter]

no bc its 1-cos(2x)

it would be -2sin^(x) = cos(2x) -1

but here we have 1-cos(2x)

[terse mural]

why is my thing wrong

[gaunt otter]

so adjust the equation according to that

cos(2x) -1 = -2sin^2(x)

same as 1-cos(2x) = 2sin^(x)

[terse mural]

why is my thing wrong tho i dont get it

[gaunt otter]

what is cos(2x)

[terse mural]

cos2x is 1-2sin^2x

so its 1-1-2sin^2x

1-1 is 0

so u have -2sin^2x

[gaunt otter]

cos(2x) = 1-2sin^2(x)

send 1 to LHS

cos(2x)-1 = -2sin^2(x)

in the question it's 1-cos(2x)

[gaunt otter]

this equation can be written as 1-cos(2x) = 2sin^2(x)

observation is that cos(2x) -1 is same as (-1)*(1-cos(2x))

[terse mural]

ok

wat

[gaunt otter]

@terse mural

1-cos(4x) = 2sin^2(2x)

[terse mural]

o

yea

[gaunt otter]

now use sin(2x) formula

[grand pond]

Alaska

[gaunt otter]

use sin(2x)^

[gaunt otter]

nono

wait

[terse mural]

?????

[grand pond]

Alaska

[gaunt otter]

numerator sin(2x) gets cancelled

[terse mural]

wait what

how

[gaunt otter]

you only have to expand denominator sin(2x)

what is x/x^2

[terse mural]

x

[gaunt otter]

1/x

[terse mural]

oh

[gaunt otter]

think like this

in denominator we have sin(2x) * sin(2x)

in numerator sin(2x)

one term gets cancelled

you are left with one sin(2x) in denominator

[terse mural]

so what its just 2sin2x

[gaunt otter]

cancel the 2

[terse mural]

oh

yea

[gaunt otter]

then this

from here

you expand sin(2x)

once you practice enough questions, you will understand when and where to use trigonometric formulas

[gaunt otter]

yes

[terse mural]

i am not passing this test man

[gaunt otter]

practice more questions

[terse mural]

idk how to do any of them man

i got a handout with like 40 questions i could only do the first 3

other ones i did my teacher basically walked me thru the whole thing

[gaunt otter]

mmm

I mean trigonometry is like a different topic

you gotta rememember formulas and then its mostly manipulation

you will understand it when you solve more questions

[terse mural]

yea but in every question i have to notice some obscure ass factoring method taught on caveman paintings in 5 zillion BC i have to apply

[gaunt otter]

ye

[terse mural]

its so confusing

what does sin even do man

[gaunt otter]

but its useful in your higher studies

[midnight plank]

If you are done with this channel, please mark your problem as solved by typing .close

[terse mural]

.close

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[humble wraith]

where do i start?

[icy knot]

Eulers identity

$ e^{i\pi} $

[edgy schooner]

what does the omega mean? cube root of unity?

[humble wraith]

uh

omega its just a value in this case

otherwise its resonance

[humble wraith]

huh

[novel lion]

$e^{i\theta} = \cos(\theta) + i\sin(\theta)$

[grand pond]

Astar777

[humble wraith]

ye i've done that

how do i simplify it though

[novel lion]

did u simplify it before using euler's formula

$\frac{e^{i4\omega\theta}}{e^{i\omega\theta}} + \frac{e^{-2i\omega\theta}}{e^{i\omega\theta}}$

[grand pond]

Astar777

[novel lion]

$e^{i3\omega\theta} + e^{-i3\omega\theta}$

[grand pond]

Astar777

[icy knot]

That looks right and now you can simplify it

Using the aforementioned identity

[humble wraith]

ohhh

let me try

i got it

thanks guys 😎

.close

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[frank acorn]

Little curiosity, how can one procedurally solve this?

[frank acorn]

I thought of moving (net/100*tax) on the left side, but then net = gross-(net/100*tax)

which doesn't make much sense :\

[keen saddle]

do you want to solve for net here?

if yes then
isolate net which you have already done
now just add the coeff of net and take them to the other side

[midnight plank]

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[frank acorn]

Solved

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[eternal pine]

how do i see that it is convergent or divergent, and how can i calculate this?

[fresh sparrow]

$\frac{\sqrt{i}}{i^2} = \frac{1}{i^{3/2}}$

[grand pond]

artemetra

[fresh sparrow]

hint: ||it's a p-series, with p=3/2||

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[outer plume]

i need some help with triangles (its in danish so i will translate real quick

[outer plume]

"about a right triangle ABC is given, af area of 24 and one catheter is 6"

"Decide the sidelengt of the triangle ABC"

i really just need a easy way to get it done as i havent been taught this yet for some reasone

[alpine gyro]

What is the formula of a triangles area?

[outer plume]

all i know is that the area of the triangle is 24 and that one of the catheters is 6 no more has been provided

[alpine gyro]

What about a square?

[last slate]

The area of a right angled triangle = 1/2 bh

[outer plume]

so i should try to make it into a square?

[alpine gyro]

Hvilken trinn går du på?

[outer plume]

1.G

[alpine gyro]

Førsteklasse grunnskole?

[outer plume]

high school

[alpine gyro]

https://www.youtube.com/watch?v=NnlJkTgwt8U&pp=ygUQYXJlYWwgYXYgdHJla2FudA%3D%3D

You have two values, and by using the formula, you subtitute the known values into the corresponding variables, and you'll solve for the unknown one.

[midnight plank]

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[wraith heath]

Given: ABCD - parallelogram; AN:NB = 3:2; BM:MC = 2:5.
Find: OM:OA; ON:OD.
I assume this problem can be solved by extending DN and BC until they interset and do same with AM and CD and then get similar triangles. But I am supposed to solve this using the Intercept theorem by constructing some parallel lines, problem is that I don't see which ones lead to any useful ratios.

(some additional discussion over here: #help-46 message)

[feral sedge]

what is "intercept theorem"

[wraith heath]

Googled it, pretty sure this is the one I was trying to refer to: https://en.wikipedia.org/wiki/Intercept_theorem

[midnight plank]

@wraith heath Has your question been resolved?

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@wraith heath Has your question been resolved?

[last slate]

Wait are you asking about mx2+nx1/m+n?

[midnight plank]

@wraith heath Has your question been resolved?

[midnight plank]

@wraith heath Has your question been resolved?

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[dapper nebula]

More + Hope > (Mr + 7)oe
can help this solve math?

[carmine sigil]

There isn't much you can say

you can multiply both sides out, and subtract away More, and then you get hp * oe > 7 * oe. So depending on if oe is positive or negative you have hp > 7 or hp < 7

[dapper nebula]

how did the hp?

[carmine sigil]

\begin{align*}
More + Hope &> (Mr + 7)oe \
More + Hope &> Mroe + 7oe \
Mroe + Hpoe &> Mroe + 7oe \
Hpoe &> 7oe \
\end{align*}

[grand pond]

OmnipotentEntity

[dapper nebula]

i dont unstertand

why the (mr + 7)oe?

[carmine sigil]

if we are assuming that "More" means "M times o times r times e"

[dapper nebula]

so the mr+7 oe

[carmine sigil]

and so on

[dapper nebula]

hm?

[carmine sigil]

I don't understand your question. Can you be a little more specific about your confusion?

[dapper nebula]

its answer is 6 lol

[carmine sigil]

No it's not

[dapper nebula]

its is

[carmine sigil]

at least, not based on the information that you have provided.

Based on the information you provided, the best we can do is either oe > 0 and hp > 7 or oe < 0 and hp < 7.

[dapper nebula]

MR ratios HP

there ratio

[carmine sigil]

Mr is entirely unconstrained by this inequality

!original

[midnight plank]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[dapper nebula]

More + Hope

mOrE + hOpE

[carmine sigil]

yes, I see that

[dapper nebula]

(Idk what this means)OE

[carmine sigil]

o times e, presumably

where o and e are, again presumably, being treated as independent variables.

But you know what would help?

!original

[midnight plank]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[dapper nebula]

no thank you :)

cya

[carmine sigil]

cya

[dapper nebula]

.close

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[edgy knot]

watched some videos about Lagrange Multipliers and i cant sumarize it how it works in theory. like the picture pasted bellow, what does it mean/tell us

[midnight plank]

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[edgy knot]

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[cobalt jetty]

what is the derivative of a definite integral and why is 2𝑔′(𝑥)𝑔(𝑥)=[𝑔(𝑥)2]′ true

[fallow scarab]

https://math.libretexts.org/Bookshelves/Calculus/Calculus_(OpenStax)/05%3A_Integration/5.03%3A_The_Fundamental_Theorem_of_Calculus

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[last slate]

stuck on this hw problem no idea how to solve it hm (statistics)

[west iron]

Do you have formulas for confidence intervals?

[last slate]

ya

(a) n = 3613
(b) n = 4148

i think?

[west iron]

Are those your answers or do you have no idea how to solve

[last slate]

my brothers hes trying to run me through but idk if hes doing it right cuz he hasnt taken stats in forever

could u show me how to solve?

[west iron]

Well I asked you if you have formulas for confidence interval

Do you know what a formula is?

[last slate]

i have them idk how to use rly this is week 2

[west iron]

You know 3613 isn't the formula right

[last slate]

ya

thats what he got though so i just put it there

[west iron]

Ok

What are the formulas

[last slate]

nvm

thats diff application

im unsure

could u show

[west iron]

This is for when you don't have a previous estimate right

You should use the 99% and set the error ± to 2

And solve for n

[midnight plank]

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[nova wharf]

Problem of Integral calculus

[nova wharf]

Why does this describes a solid_

I-m ask to find out the volume

[midnight plank]

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[last slate]

This is kind of a specific topic so not sure if anyone would know how, but basically

Would B just be an 8x8 matrix of 1/8 since there are 8 nodes?

Also not sure if the transition matrix A is right in the first place

[drowsy adder]

diabolical

im struggling with 3x3 determinants but look at u

[midnight plank]

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@last slate Has your question been resolved?

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@last slate Has your question been resolved?

[versed salmon]

@tribal temple can u help my friend

he struggling

[last slate]

[last slate]

.close

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[oak socket]

i got to (2x^(3/2))/3

[shadow stirrup]

that’s the general anti derivative, you just have to evaluate it at 4 and 1 now.

[oak socket]

how do i do that i forgot

[shadow stirrup]

,,\int_{a}^{b}f(x)dx=F(b)-F(a)

[grand pond]

TheLord26

[shadow stirrup]

you currently have F(x)

[oak socket]

ok

[oak socket]

wait what do i put in for the + C?

[shadow stirrup]

this is a definite integral, you dont need +C

[oak socket]

ohh ok

[shadow stirrup]

,,\int_{a}^{b}f(x)dx=(F(b)+C)-(F(a)+C)=F(b)-F(a)

[grand pond]

TheLord26

[oak socket]

wait it equals 14/3 right

[shadow stirrup]

,w \int_1^4\sqrt{x}dx

[grand pond]

Results provided by WolframAlpha

Click here to refine your query online
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Requested by thelord262

[shadow stirrup]

yep

[oak socket]

ok

wait so my textbook says to evaluate the integral... like solve for the antiderivative?

cause i just realized that it already gave me the answer

[shadow stirrup]

no, that just means finding the value

[oak socket]

omg i so stupid i read the question wrong

the 1 and 4 are swapped

it should be 1 at the top and 4 at the bottom

[shadow stirrup]

just multiply by -1

[oak socket]

oh

is that a rule

[shadow stirrup]

you can show that it works by showing what a definite integral does

,,\int_a^b f(x)dx=F(b)-F(a)

[grand pond]

TheLord26

[shadow stirrup]

mupltiply everything by -1

and youll get

[oak socket]

OHHH cause u swap the order of b and a

so it swaps

ohhhh i get it

[shadow stirrup]

,,-\int_a^b f(x)dx=F(a)-F(b)=\int_b^a f(x)dx

[grand pond]

TheLord26

[oak socket]

suppose the variabe of the original equation changes to a different variable, i'd assume it'd be the same answer

14/3

[shadow stirrup]

like if it were t instead of x?

[oak socket]

ya

[shadow stirrup]

yep

[oak socket]

👍

[shadow stirrup]

we call that the "dummy variable" in caclulus

[oak socket]

ill take note of that

ok what about adding two integrals together

for example if i wanted to add the original equation with it self

it would just be 14/3 + 14/3

(28/3)

[shadow stirrup]

theres a few rules for adding integrals

,,\int_a^b f(x)dx + \int_a^b g(x)dx = \int_a^b f(x)+g(x)dx

[grand pond]

TheLord26

[shadow stirrup]

,,\int f(x)dx + \int g(x)dx = \int f(x)+g(x)dx

[grand pond]

TheLord26

[shadow stirrup]

,,\int_a^b f(x)dx + \int_b^c f(x)dx = \int_a^c f(x)dx

[grand pond]

TheLord26

[oak socket]

what if one of them its interval a to b but then the next one its b to a

and the antiderivative is the same

[shadow stirrup]

that this rule

[oak socket]

oh but instead of c its a

okok

[shadow stirrup]

the a, b and c are just placeholders

[oak socket]

wait but then whats the interval

if the interval is the same number at the bottom and top

[shadow stirrup]

[a, c]

[oak socket]

like what if a = c

[shadow stirrup]

if its along the interval [a,a], the integral will equal 0

[oak socket]

is that bc theres basically no area to calculate

[shadow stirrup]

yeah

imagine a box with 0 width and some arbituary height, the area will be 0.

[oak socket]

i see thanks

[shadow stirrup]

np

remember to .close if you are finished with a help channel

[oak socket]

yep

[shadow stirrup]

and if you ever have more problems feel free to ask them in #calculus

[oak socket]

alrighty then

thanks!

.close

[midnight plank]

Channel closed

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[oak socket]

.reopen

[midnight plank]

✅

[oak socket]

I forgot how to do this

[vocal agate]

You can make the expression there into a function of x and then integrate over the bounds on the x-axis, or you can make the expression there into a function of y and integrate over the bounds on the y-axis

Your choice 🫡

[oak socket]

wdym by "intergrate over the bounds on the x-axis"

[vocal agate]

like $\int_a^b f(x)$dx where [a,b] is the interval bounding this region here

[grand pond]

FEIN FEIN FEIN FEIN FEIN FEIN FE

[vocal agate]

So in this case it’s [0,4] if each of those tick marks are 1

[oak socket]

i see

so if i isolate the y

then i have to use the bounds of the y?

[vocal agate]

If you isolate the x then use the bounds of y

[oak socket]

i isolated y

so then i'd use the x bounds?

[vocal agate]

Like you either have something like y = f(x) or x = f(y)

[vocal agate]

Yea

[oak socket]

ohh ok

thanks

[vocal agate]

No problem

[oak socket]

and f(x) would jsut be the expression y equals right?

[vocal agate]

Yeah

[oak socket]

thanks

[vocal agate]

And as a gut check to see if you did it right you can just compute the area normally as 1/2 base*height

And see if it matches

[oak socket]

alr

.close

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Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[wanton ore]

hi yall

[wanton ore]

i need help in trigo

[midnight plank]

No need to ask “Can I ask…?” or “Does anyone know about…?”—it’s faster for everyone if you just ask your question! See https://dontasktoask.com/

[lethal path]

do you have a specific question?

[lusty mango]

hi yall

[wanton ore]

its about finding how many degrees in a right triangle

[lethal path]

can you post the image?

[last slate]

!xy

[midnight plank]

Please show the original problem, exactly as it was stated to you, with the entire original context. A picture or screenshot is best. If the original problem is not in English, then post it anyway! The additional context might still be helpful. Do your best to provide a translation.

[wanton ore]

bet

yall sorry for the dely

delay*

#23 only

[lethal path]

,rotate

[lethal path]

can you draw the triangle out?

ah you've already done it, yes that drawing is correct

[lethal path]

so they want the angle opposite to the 282 ft

[wanton ore]

yes

doesnt it go like

[lethal path]

so what is the 137 ft relative to that angle, opp/adj/hyp?

[wanton ore]

tan^-1 (282/137)

[lethal path]

yes!

[wanton ore]

then it becomes 64 deg

[lethal path]

tan theta = 282/137 and then inverse tan both sides

,w arctan(282/137) in degrees

[grand pond]

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[wanton ore]

Oh yeahh

thats what i did

but the book said the aswer was 58

oh well as long as my answer is correct and solvable

ig the book is wrong

hey sir/ma'am

thanks for helping me with this one

[lethal path]

no worries!

yeah textbook answer can often be wrong

[wanton ore]

thank you soo muchhh

i really need to get my grades straight this sem

thank you @lethal path

may god bless you

[lethal path]

God bless you too!

[midnight plank]

@wanton ore Has your question been resolved?

[lethal path]

.close

[midnight plank]

Channel closed

Closed by @lethal path

Use .reopen if this was a mistake.

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[manic bison]

What even is this

[lethal path]

linear recurrence relations

the +6^n is the non-homogenous case

[manic bison]

So I'm supposed to find the sum of Tr?

[lethal path]

,w t(n) = 3t(n - 1) + 6^n

[manic bison]

Oh wait

[grand pond]

Results provided by WolframAlpha

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Requested by sooouth.

[lethal path]

do you know anything about this topic?

for instance you can find the solution to t(n) = 3t(n - 1) first

then sub a guess in for the particular solution with +6^n

[manic bison]

This is supposed to be a question on series on progressions 😭

I don't understand 😭

[lethal path]

yeah then this question is not for you

[manic bison]

I think I'm supposed to find the sum of Tr from 1 to n

And then equate it to the thing

[lethal path]

yes and you haven't studied this topic so you can't do that

but that is the method yes

[manic bison]

It's literally my homework 😭

[manic bison]

How do we do it?

Telescopic?

[lethal path]

cba to explain

[manic bison]

Oh

I'll try it myself somehow

.close

[midnight plank]

Channel closed

Closed by @manic bison

Use .reopen if this was a mistake.

[lethal path]

https://www.themathdoctors.org/non-homogeneous-recurrence-relations/

[lethal path]

but this page might help

also non-homogenous recurrence relations on YT does have results, but finding one with +2^n or +3^n might take some searching

[manic bison]

I'll give it a read

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[cerulean pendant]

I need help with a proof for a solution to an algorithmic task:
Given a list of numbers, find a permutation such that the sum of the absolute differences between consecutive terms is maximal. The optimal strategy is to sort the list and choose the smallest, greatest element, smallest of whats left and so on, for example for (1,3,2,7) the optimal permutation would be (7,1,3,2). How do I prove that this is indeed optimal

[cerulean pendant]

lol its not optimal

ok then maybe starting from the smallest one

(1,7,2,3)