help-49

[fleet terrace]

yeah

[midnight plank]

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

[sterile crypt]

one moment

[fleet terrace]

lmao its not homework

im doing self-pratice

[torn compass]

if we just give solutions , u would never learn

[fleet terrace]

i have an idea of what to do im just stuck so meh

[torn compass]

also try factorizing the numerator , rewrite
x^4 - 1^4 as (x^2)^2 - (1^2)^2

[fleet terrace]

im not clueless

[torn compass]

if ur taking conjugate of that , u are

[fleet terrace]

u want me to do x squared -1 and x squared plus 1?

oh wait thaaats what ur saying lemme try that

[torn compass]

u cant expand x^2+1 , but yeah expand x^2-1

ye

[torn compass]

.

[fleet terrace]

hmm yeah i think i go tit

[fleet terrace]

shaddup

[torn compass]

:c

[sterile crypt]

i asked him though

[fleet terrace]

mods, eviscerate this man

yeah its fine i understand through the solution

[sterile crypt]

alr

[fleet terrace]

fo some reason i didnt think to expand that

thanks guys, both of yall

appreciate the help

.close

[midnight plank]

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[umbral scroll]

can someone explain me the notation of asymptotical limits

[midnight plank]

@umbral scroll Has your question been resolved?

[umbral scroll]

<@&286206848099549185>

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[wind marsh]

hey can someone pls help me in solving this circle theorem questinon

[midnight plank]

Please don't occupy multiple help channels.

[wide isle]

to compute "a", remember that the triangle with 2 endpoints on a diameter of a circle, and 3rd endpoint on the circle, is ...what kind of triangle?

[wind marsh]

right angle?

[wide isle]

yes

so 30 + a =?

[wind marsh]

90

so a would be 60?

[wide isle]

yes

now it's time to compute the 3rd angle of the big triangle.

[wind marsh]

ok got it

[wide isle]

know how to find b?

[wind marsh]

actually no, i dont know how to find b

[wide isle]

well, XY is tangent to the circle, so the angle OXY is...?

[wind marsh]

90 degrees

[wide isle]

yes

did you compute the 3rd angle of the big triangle?

[wind marsh]

would it be 60?

[wide isle]

afraid not. How do we calculate 3rd angle of the big triangle?

I mean the triangle that has an angle of 40, and an angle of 90, from the picture you gave

the largest one

Did I confuse you? Please tell me if you don't understand which triangle I mean

[wind marsh]

ok for the big triangle would it be 30+ 90+ x = 180

[wide isle]

Are you sure it's 30 and 90?

I think one of the angles is 30+a, which is 90, like you said. but I am not sure about the other one

[wind marsh]

hold on, sorry the angle on top is 40

and now we calculated a which is 60

so 40 + 60+ 30 + x = 180

[wide isle]

correct

[wind marsh]

so x would be 50

[wide isle]

Yes. How to find "b", now?

[wind marsh]

so 50 + x = 90

[wide isle]

to not confuse ourselves, let's say 50+b. But yes

[wind marsh]

ok so 50 + b = 90
b = 40?

[wide isle]

Yes.

[wind marsh]

ok great tysmmmm for your help!!!

[wide isle]

you're welcome! 🙂

To close thread, you have to write ".close" I think

[wind marsh]

oh yes tysm

.close

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[timber lichen]

Hello i need help with this equation (univrsity level maths )

3 x ℯ^(x)-2=0

[storm spindle]

You want to solve 3*e^x - 2 = 0 for x?

[timber lichen]

yes

[storm spindle]

Are you familiar with the natural logarithm?

@timber lichen

[timber lichen]

yes

[storm spindle]

Where exactly are you stuck then?

[timber lichen]

which theorem can solve this form xe^x

[grim vector]

it's not x

its time

or not ?

[timber lichen]

it x the variable

not multiply

[timber lichen]

no

3. x ℯ^(x)-2=0

[grim vector]

ah

ok ok

then xe^x = 2/3

[timber lichen]

exacltly and x+ ln x = ln(2/3)

[storm spindle]

I think you need lambert w function

[timber lichen]

how to apply the lambert w function ?

[storm spindle]

Idk, I’d have to look it up myself

But it’s what I’ve seen being used for these equations

[timber lichen]

i thought i should useTaylor theorem but it will not work

[midnight plank]

@timber lichen Has your question been resolved?

[midnight plank]

@timber lichen Has your question been resolved?

[midnight plank]

@timber lichen Has your question been resolved?

[last slate]

Is this solving for the exact value of x

or finding an approximation?

You could use the Newton-Raphson method a few times to get a good approximation of the value of x

or apply inverse lambert w function on both sides, if it's even possible

[timber lichen]

i don't think it is possible to find the exact value or ?

[last slate]

I doubt you can, except using the Lambert W function

are you familiar with it?

I am not

if not then just getting an approximation will probably do in this case

[timber lichen]

i am not familiar with ittbh

[last slate]

don't worry about it

what about the newton raphson method?

it is a way to approximate the root of a function

by iterations

[timber lichen]

yes i am

[last slate]

try it

use approximation to find the root of xe^x -3 = 0

[timber lichen]

i will do it tmrw it is too late for me now

[last slate]

and that should be your answer

[last slate]

okay

[timber lichen]

and thank ya for the support

[last slate]

no worries!

[midnight plank]

@timber lichen Has your question been resolved?

[midnight plank]

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[untold jackal]

Question d

All in raidans

Between 0 and 2pi

[dull yoke]

what have u tried

actually nvm i dont have time

use pythagorean trig identity

convert sec^2 to cot^2

then solve quadratic

cya

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[lethal estuary]

what

[fallow scarab]

<@&268886789983436800> spam

[midnight plank]

@white shale Has your question been resolved?

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[oak crest]

need help for this question

[oak furnace]

Make quadratic by changing sin² to t

And keep in mind the range of t

[0,1]

[gray raptor]

wait what do you mean by t

[oak crest]

@oak furnace

[oak furnace]

Change sin²x to t

It will be 2t² -3t+1=0

[oak crest]

and then what

do we long divide?

[oak furnace]

Middle term splitting

T =1 or 1/2

[oak crest]

so we replace t for 1

[oak furnace]

And half too

[oak crest]

so two equations

for both 1 and 1/2

[oak furnace]

So sinx =+1,- 1, +1/✓2 and -1/✓2

[oak crest]

test values right?

to equal zero?

[oak furnace]

By equating sin²x to t

[oak crest]

okay

thank u

[oak furnace]

No problem

[oak crest]

.close

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[mint ravine]

please help

[viral dagger]

you can try to find the remainder of (2a^2+29a+65)/(a+13)

the gcd of that and a+13 is the same as the original problem

[mint ravine]

oh yeah because of the euclidean algorithm

[viral dagger]

yes!

do you have any progress?

[mint ravine]

i simplified it down into gcd (2a+3+(26/(a+13), a+13)

and then i plugged 1183 into a

@viral dagger

[viral dagger]

and what did you get?

[mint ravine]

well i got a fraction in there too

so i might have done something wrong

[viral dagger]

yeah you did

2a^2+29a+65-2a(a+13)=2a^2+29a+65-2a^2-26a=3a+65

[mint ravine]

idk

[viral dagger]

its simplified to gcd(3a+65,a+13)

[mint ravine]

ok thanks i got 26

.close

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[midnight plank]

Please don't occupy multiple help channels.

[rugged bay]

huh

[rugged bay]

i dont understand this at all

.close

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[keen seal]

how is x-x_o here parallel to v?

[keen seal]

they dont look too parallel

[sharp coral]

the vector pointing from x0 to x in the diagram is x - x0

we can see from the diagram that such a vector is in the plane

[keen seal]

yes

i meant that vector

it doesnt look parallel to v

[sharp coral]

what is v?

[wary epoch]

I think they meant v1 and v2

And, yes, $x-x_0$ aren't parallel to both of them.

[grand pond]

Xwtek

[wary epoch]

$v_1$ and $v_2$ are parallel to the plane doesn't mean that they are parallel to $x-x_0$

[grand pond]

Xwtek

[keen seal]

oh

okay yeah vuz

they said contain a point x_o parallel to v and v2

[wary epoch]

It's the plane $W$ that they are parallel to, not $x_0$

[grand pond]

Xwtek

[keen seal]

okay okay

they worded that 💀

tysm

.close

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[keen seal]

i figured out 13 like by logic but i want to know if there's a systematic way to do this

[keen seal]

.close

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[twilit field]

so I'm trying to prove $cgcd(a,b) = gcd(ca,cb)$

[grand pond]

A dense set(Ping when reply)

[worthy spruce]

Do you know Euclid alg?

[keen saddle]

i vaguely remember another person doing this like a month ago

[twilit field]

One minute

let me send my proof

let gcd(ca,cb)= m \implies m|a, m| b \land m|c

[strong lava]

Bezout?

[worthy spruce]

This is not necessarily true

c=1, a=2, b=2 so m=2

[twilit field]

what

oh

right

[twilit field]

oh right

I always forget that

[runic hamlet]

wai has been doing this problem a dozen times over the past few months. you are probably remembering that

[midnight plank]

@twilit field Has your question been resolved?

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[manic bison]

dunno how to begin

[winged fossil]

Ok

Ill help

Very ezz solution

Ask chat gpt

[azure basin]

did you even read the rules

[winged fossil]

Erm what the sigma

What are rules

I dont have that word in my dictionary

.close

How to close

[manic bison]

doesnt work

[winged fossil]

Bruhh

[gaunt otter]

you can only close the channel if you have opened it

[winged fossil]

Okk

Ok then ask math chat gpt

[exotic pelican]

do you know the geometric sum formula?

can you please be quiet?

[manic bison]

yes

what is bro on

[elfin fox]

<@&268886789983436800> This guy is trolling

[exotic pelican]

do you see where you could apply it?

let the adulds have a conversation

[manic bison]

1/2 , 1/4 ig

but the problem is with the other part

[exotic pelican]

nope hard to apply there

[manic bison]

oh

[manic bison]

its hard to apply the GP sum fomula without some tricks first ig

[exotic pelican]

you have these 1+1/5+1/5² inner sums

[manic bison]

yea

[exotic pelican]

what is 1+1/5+...+1/5^n?

[manic bison]

gp sum

1(1/5^n-1)/1/5-1

[abstract steppe]

what is the question

[exotic pelican]

almost

[manic bison]

this one

[exotic pelican]

the power should be n+1

[abstract steppe]

that is not a question

what do you want to do with the expression

[manic bison]

oh my bad

[manic bison]

sum

of it

[abstract steppe]

you want to write it as a sum

[manic bison]

no

the sum

[exotic pelican]

and then simplify this term

[manic bison]

like a number

[manic bison]

alr

[exotic pelican]

wrong

[elfin fox]

What about it?

[exotic pelican]

the power needs to be n+1

[abstract steppe]

ye

you made a mistake

[elfin fox]

Which one?

[abstract steppe]

the Tn

and an

[manic bison]

so this is the method?

[abstract steppe]

no not an

[abstract steppe]

yes but that is not complete

[elfin fox]

I'm confused. Do you mind going in more detail?

[abstract steppe]

the formula says the sum of 1+a+a2+a3+a4+a5 ......an

is

[manic bison]

oh

[abstract steppe]

the first term *(1-a(n+1)number of therms is n+1)divided by 1- a

in this case the first term is 1

and the number of terms is n-0+1

so n+1

[manic bison]

i checked the answer key

its saying the answer is 20/9

[abstract steppe]

ye is missing as i said

after you do what alglowowl sent

you can use the first formula again

[manic bison]

ill try

[abstract steppe]

i am writing it rn

give it a try and i will send it

[manic bison]

nevermind got it

i had to multiply the enitre thing by 1/2

and subtract it from the original

[abstract steppe]

there is another method if you want

after you do this but in the right way

[manic bison]

hm

i see

[abstract steppe]

you will get 2 other tems in the form of 1+a2+a3+a4

...

you apply the formula

[manic bison]

oh

[abstract steppe]

you get something in function of n

you apply the limit to infinity

you will get 5/2-1/9*4

which is equal to the result

[manic bison]

seems doable i guess

[abstract steppe]

ye

[manic bison]

tysm

[abstract steppe]

its really easy just apply the formula three times

[manic bison]

alr

thanks

.close

[midnight plank]

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[steady trail]

$\int \frac{x}{1+\sin(3x)} dx$

[grand pond]

IceCream

[steady trail]

i dont know what to do

[last slate]

u sub

[steady trail]

what

[last slate]

u-sub
u=3x

[steady trail]

Not what it is

Can I do it by parts?

[last slate]

oh mb :P

[last slate]

yes

[steady trail]

Could you help me?

[last slate]

sure

?

[steady trail]

I choose x as the factor to derive

[main owl]

u should probably bring the denominator to the numerator first

[steady trail]

$\frac{1}{1+sin(3x)}$

[grand pond]

IceCream

[steady trail]

I had to integrate this

[last slate]

sin^2 x + cos^2 x+sin(2x) = (cosx+sinx)^2

[main owl]

why would u use a trig idenity

u can literally just integrate

[last slate]

fr

how?

[main owl]

1 turns into x

than

u

integrate sin(3x)

and ur done

+c

[lethal path]

https://www.integral-calculator.com/

[main owl]

oh no

power

i forgot

ima solve this rq

[steady trail]

But isn't there a formula for making them?

[main owl]

thats messed up

i wanted to do it

[last slate]

you could refer to thid

[steady trail]

The solution is wrong I think

[last slate]

sorry forgot to turn off ping

[steady trail]

Why is there still an integral?

Ah but that's not all

[lethal path]

yes I'm not spoiling it but should be straightforward from here

[last slate]

he didnt send the complete thing

[steady trail]

Yes

I see

[lethal path]

you can simplify 1/(tan u + sec u)

[steady trail]

Why is there a u?

[lethal path]

u = 3x

you could actually sub that in at the very beginning

[steady trail]

Why

[lethal path]

bruh

[steady trail]

I don't know this technique

[lethal path]

you don't know integration by substitution?

[steady trail]

No

[lethal path]

why the hell are you doing this problem

[steady trail]

By parts

Or some formula

[lethal path]

I know but a lot of times you need both by parts and u-sub

[steady trail]

Okay

Is there a formula?

I mean can it be done mechanically?

[lethal path]

https://www.youtube.com/watch?v=sdYdnpYn-1o

try watching this video first

[steady trail]

Mmm

There is no my case

Oh right I can also use the chain rule

[lethal path]

yes integration by substitution is the reverse chain rule

[main owl]

reverse chain rule

[lethal path]

well this case, when you have u = constant * x

[steady trail]

But I have a formula

For the chain rule

[lethal path]

you need to go look at some worked examples of integration by substitution

or reverse chain rule

before you attempt this question and do this step yourself

[strong stump]

i think he wants to apply a formula

[steady trail]

$\int (f(x))^\alpha \cdot f'(x)=\frac{1}{\alpha+1}\cdot (f(x))^{\alpha+1}$
⚠️⚠️⚠️

[grand pond]

IceCream

[steady trail]

Can i use this ?

[steady trail]

.

[lethal path]

you're wasting our time

[strong stump]

@steady trail i have an idea

guys look at this

[lethal path]

you are missing some essential knowledge

you should go learn it yourself

[steady trail]

What

[strong stump]

use this

[lethal path]

otherwise you're wasting our time and energy

[steady trail]

Thanks

[lethal path]

not helpful at all

in terms of understanding how to do things

but also why they work

[steady trail]

It's what I needed

[lethal path]

fine

[steady trail]

But is this integral done with formulas?

[strong stump]

blud is gonna memorize all that

[lethal path]

I am telling you it's a combination of u-substitution and integration by parts

[steady trail]

If it's long, yes

[lethal path]

integration by parts you told me you know how to do

[steady trail]

Yes

The problem is the other

Alright, I'll go watch the video

$u=3x$

[grand pond]

IceCream

[steady trail]

Right ?

Im on 2:36

$du=3 dx$

[grand pond]

IceCream

[steady trail]

$1/9\int \frac{u}{1+\sin(u)}du$

[grand pond]

IceCream

[steady trail]

Im still here

[lethal path]

ok

[lethal path]

ah yes that's correct, $\frac{1}{3} \int \frac{3x}{\sin(3x) + 1} \ dx = \frac{1}{3} \cdot \frac{1}{3} \int \frac{u}{\sin(u) + 1} \ du$

[grand pond]

southlander!

[lethal path]

now use integration by parts

and then you should be left with constant times $\int \frac{1}{\sin(u) + 1} \ du = \int \frac{1 - \sin(u)}{\cos^2 u} \ du = \cdots$

[grand pond]

southlander!

[steady trail]

$\frac{1}{1+sin(u)}$

[grand pond]

IceCream

[steady trail]

I have to integrate this

[lethal path]

try continuing from here

[steady trail]

By chance I have to use $\cos^2(\alpha/2)=1+\cos(\alpha)/2$?

[grand pond]

IceCream

[steady trail]

$\int 1/cos^2(u) du$

[grand pond]

IceCream

[steady trail]

Here

Ah no wait

Its tan(u)

$\int -\frac{sin(u)}{cos^2(u)}du=\int dt/t^2$

[grand pond]

IceCream

[steady trail]

Right?

So -1/t

-1/cos(u)

Right ?

I made the substitution $cos(u)=t$

[grand pond]

IceCream

[main owl]

how

did u turn

1/1+sin

to sin/cos^2

[steady trail]

From here

[lethal path]

multiply top and bottom by 1 - sin(u)

[steady trail]

Anyway

[lethal path]

cool, yeah

[main owl]

ah

[steady trail]

I think I did

[main owl]

i was gonna say he could multiply top and bottom by sin ^2 to just get rid of the denom

[steady trail]

$tan(u)-1/cos(u)$

[grand pond]

IceCream

[main owl]

from this point

[lethal path]

yeah this is better I know

[lethal path]

you can evaluate that integral right

[main owl]

yea

i guess no point not to

[steady trail]

Now all I have to do is put u=3x and I'm done?

[main owl]

u didnt integrate yet

u just simplifed it no?

tan(u) - sec(u)

integrate that

and plug 3x in for u

and add a +c

and u win

[steady trail]

But this is already a primitive

[main owl]

its niot

1/cos

= sec

[steady trail]

Wait

[steady trail]

I made the primitive of this one

Why didn't I integrate?

[lethal path]

yes so the integral of this is -sec(u) + c or -sec(3x) + c

you already integrated this part correctly

now onto the integral of 1/cos^2 u

[steady trail]

I also have a tan(u)

[lethal path]

ah you should just search this one up

can you leave this question to Diamond

I'm helping someone else

[main owl]

im honestly not sure what part hes on

[steady trail]

This Is tan(u)

[main owl]

if he explains what hes doing i can help

[steady trail]

Okay

[main owl]

walk me through your thought process from the beginning

[steady trail]

I did the last integral

I start from scratch

[main owl]

ok

whats the problem

[steady trail]

$\int \frac{x}{1+\sin(3x)} dx$

[grand pond]

IceCream

[main owl]

how do you think we should approach this problem

[steady trail]

U subsitution

[main owl]

ok whats u

[steady trail]

3x

[main owl]

lets see ur work

[steady trail]

Do I have to write?

[main owl]

just tell me what u do

[steady trail]

Okay

$du=3dx$

[grand pond]

IceCream

[steady trail]

$du/3=dx$

[grand pond]

IceCream

[steady trail]

$x=u/3$

[grand pond]

IceCream

[main owl]

huh'

u / 3?

[steady trail]

Yes

From u=3x

[main owl]

u had du/3 = dx

than u replace the dx

with du/3

[steady trail]

Yes

[main owl]

which divides the entire function by 3

[steady trail]

In the numerator is x

[main owl]

yes

oh

i see

we do usub differently

[steady trail]

I have to turn it into u

Oh okay

[main owl]

just continue past that

[steady trail]

$1/9\int \frac{u}{1+\sin(u)}du$

[grand pond]

IceCream

[steady trail]

So I get this

[main owl]

where did 1/9 come from

it should be 1/3

[steady trail]

Why

[main owl]

i lokey have no idea how ur doing this usub

i learned it way diff

[steady trail]

Wait

If I replace x=u/3

Here is a 1/3

[lethal path]

no they're correct

[lethal path]

.

[main owl]

i know i ust dont integrate like that

[steady trail]

Same with dx

1/3 * 1/3

[main owl]

also the oslution to this problem is fucking crazy

why do u wanna solve this

[steady trail]

But I think I'm done

[lethal path]

I'm just in no mood to teach you why the integral of sec^2 u is tan u

at least you figured out the integral of sec u tan u is sec u

[main owl]

whats ur answer

[lethal path]

cause these derivations are easily available online

[strong stump]

guys remember this

[steady trail]

The derivative of the tangent is 1/cos^2(x)

[main owl]

not wrong

[lethal path]

,w differentiate 1/9 * (tan(3x) - (sec(3x))

[main owl]

this is like a problem a crazy person would do

for fun

[strong stump]

just use the formula above then

[steady trail]

It comes out different to me

[strong stump]

more easy than that

[main owl]

is this like a homework problem

or u just having fun

[strong stump]

,w int x/(1+sin(3x))

[grand pond]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by jandro0103

[lethal path]

^

[steady trail]

But it doesn't come out that way for me

I followed all the suggestions

[strong stump]

[main owl]

unfortunately the million dollar company probably isnt wrong

[steady trail]

This

[strong stump]

at this point just use the formula i sent above, who agree here?

[main owl]

i think he should solve this problem in assembly

[steady trail]

$1/9(tan(3x)-1/cos(3x))$

[grand pond]

IceCream

[steady trail]

I got this

[lethal path]

also you need the integration by parts step, don't forget

[steady trail]

...

This was only the first part 😱

[lethal path]

sorry I think my technique doesn't work

[steady trail]

I got lost

[lethal path]

you can't reduce it to the one I suggested

let me think

[steady trail]

Ah

[lethal path]

yes after integration by parts, you get 1/9 times:

$\frac{u^2}{2} \frac{1}{1 + \sin(u)} - \int 1 \cdot - \frac{\cos(u)}{(1 + \sin u)^2} \ du$

$u \mapsto \frac{1}{1 + \sin(u)}$ and $dv \mapsto u$

[grand pond]

southlander!

[lethal path]

you have to differentiate 1/(1 + sin u)

ah but you're integrating it again anyways

wait no, the above is wrong cause it should be the integral of u^2/2 times that arghhhh

I think you really needed to use the trick here

it doesn't work unless you divide top and bottom like this

[steady trail]

So is it necessarily done like this?

[lethal path]

yes

you have to use their approach not mine

[steady trail]

Okay

[midnight plank]

@steady trail Has your question been resolved?

[midnight plank]

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• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
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• Be polite and have a nice day!

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[pale field]

Anyone ?

[pale field]

Do I it for small cases and generalise it somehow ?

[midnight plank]

@pale field Has your question been resolved?

[midnight plank]

Channel closed

Closed due to timeout

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[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[gusty falcon]

guys is this correct?

why does this definition give Q(0.25) = 17 while

the “high school” definition of Q1 is the average between 12 and 17

what’s going on

[placid thistle]

Give me a minute, I'll look at this

yes it's correct

[gusty falcon]

okay then

[gusty falcon]

^

what about that

[placid thistle]

i mean in the high school definition it's interpolation no??

it's two different contexts

so you get two different answers

[gusty falcon]

then is quantile not related to median?

which one is correct and why can they be used interchangeably

[placid thistle]

i mean quantiles are related to the median because the median is a specific quantile i.e $Q(0.5)$, but they differ in calculation. theyre not always interchangeable unless the quantile definition explicitly matches the method used to calculate the median if that makes sense?

[grand pond]

imo2025

[gusty falcon]

okay but if someone asks u for the median of a data set

a discrete one

there’s not a range of possible answers, right?

[placid thistle]

no there's not

[gusty falcon]

then here there’s no different answers ?

using quintiles we have that the median is 17

[placid thistle]

quantiles are different to medians

[gusty falcon]

they read the same to me

[placid thistle]

cus quantiles can be defined in different ways

okay nevermind the median would be different cus you can define it differently

let me give an example

idk if im being clear or stupid

using interpolation method, median is 22, but using the Q(0.5) method we get 17

its just two definitions

[gusty falcon]

okay but what do we use?

[placid thistle]

it's really depending on context if they just taught you about the quantile stuff you should use that

[gusty falcon]

definitions usually don’t give wholly different answers to discrete cases, no?

[placid thistle]

well

okay it's like if i ask for the average of something

that's kind of ambigious

even if i ask for the mean

it's still ambigious i.e you have arithmetic mean (standard high school mean), geometric mean, harmonic mean etc

[fervent ember]

if you use different definitions you get different results.

[gusty falcon]

which is the mainstream definition though?

[placid thistle]

probably high school one

[gusty falcon]

quintiles are used for discrete cases?

[gusty falcon]

yeah that’s what i thought too

[placid thistle]

but if you just learnt about quintiles then use that one

[gusty falcon]

no i dont learn about anything

[placid thistle]

oh lol

[gusty falcon]

this is in a standardized test

[placid thistle]

high school test?

[gusty falcon]

it shouldn’t matter?

bc like

[fervent ember]

no.

[gusty falcon]

there should be only one right answer, no?

[placid thistle]

no there's not one answer

cus its ambigious

[gusty falcon]

okay what is Q1?

[fervent ember]

no, the result depends on the udes definition. different definitions give different results.

[gusty falcon]

if quantile isn’t median

[gusty falcon]

my actual question is to find IQR

what would a mainstream solution look like

[fervent ember]

whatever IQR is for you.

[placid thistle]

i mean if it's like the SAT use high school definition if its a standardised test for a statistics program use quintiles

[gusty falcon]

what about conventional definition? the one on wiki

[gusty falcon]

yeah but then wouldn’t they say the question is ambiguous

cuz tutors can point out that there are multiple answers

hence the question legitimacy is at stake

[placid thistle]

not realy bc the sat wouldnt expect you to use the quintiles definition

[placid thistle]

but yeah you can make that case

[gusty falcon]

also i’m p sure phd students audit

questions for standardized tests

[fervent ember]

Q1 is typically the first quartile. you have 13 values, the first quartile is the 3.25th value.

[placid thistle]

i mean the sat probably has a few questions about the mean and im pretty sure they expect the arithmetic mean

[gusty falcon]

and quantile is not related to quartile?

[gusty falcon]

i think that’s clear from context

[fervent ember]

where did i say that?

[gusty falcon]

no i was asking

okay well

idk what to do with this

😭

anything can be anything so idk what to do with that

[placid thistle]

i mean its context dependent im going to assume use the high school definition

[fervent ember]

with this definition the neares value is 17. so i would say Q1 = 17.

[gusty falcon]

but this definitions uses interpolation, right?

am i correct in saying that Q1 is the average between 12 and 17 then?

[gusty falcon]

okay but a whole bunch of “calculators” online

also use the mainstream definition

[fervent ember]

and with the same argument Q3 = 24, so you rIQR = 7.

[last slate]

Hii

What's going on here?

I am new here sorry

[gusty falcon]

okay, could u also clarify the wiki definition?

they said linear interpolation

and that’s high school definition right?

[fervent ember]

what should i clarify? i have explained Q1, Q3, and IQR with your sample. If you understand this, its ok, if not, ask what is not clear. and btw. my argumenation is in line with your screensht.

[gusty falcon]

oh i mean the person above said high school definition uses interpolation

and wiki mentioned interpolation so i thought wiki is talking about high school definition

[fervent ember]

how should i know what the person above ment with high school definition? Interpolation is used when more than one value fulfill the defintion. but when you need the 3.25th value there is only one valiue (17) and the same with Q3, so there is no need for interpolation.

[gusty falcon]

okay i think

i’ll just answer this then

idk

wait

quartile is a type of quantile

i need 1st quartile bc that is Q1

[fervent ember]

for example. if your set is 1, 2, 3, 4, 5 the median = Q2 is exactly 3. if your set is 1,2,3,4,5,6 all numbers between 3 and 4 fulfill the condtion for Q2. in this case interpolation is used to get Q2 = 3.5

[fervent ember]

i have done this already,

[gusty falcon]

oh

[gusty falcon]

but the definition provided in picture is for continuous case right?

https://en.wikipedia.org/wiki/Quartile

if we go to computing methods section

[fervent ember]

i cant see anything specific for the continuus case.

i did it the same way for yur example.

[gusty falcon]

yep i get what u did

but there are 4 definitions for finding quartiles

well methods in wikipedia

none of which says any value between a whole range works

for example this is method 1

the high school method

[fervent ember]

no one said, that there is only one defintion. i said many times: the result depends on the definition you use.

[gusty falcon]

the other ones are similar in nature but little different

[gusty falcon]

but it can’t be anything between 3 and 4 right?

for the example u provided

there’s 4 definitions for discrete cases

at most 4 different answers

unless we treat this as a continuous data

[fervent ember]

for which one? i provided two examples.

[gusty falcon]

{1,2,3,4,5,6}

[fervent ember]

Q1=2, Q3=5

[gusty falcon]

that sounds good okay

what about Q2?

[fervent ember]

i said q2 here.

[gusty falcon]

but how is that correct

4 definitions in example 2

u see how all of them gives the same median

these are all the different definitions for discrete case

[fervent ember]

its fully inline with this example, or where do you think there is a difference?

in example 2 all methods give the same Q2 as mean between the third and fourth value. -> 3.5 in my example.

[gusty falcon]

yes but u said any

value between 3 and 4 works

that would only be a definition for cts case, no?

considering these are the only 4 mainstream definitions

[fervent ember]

please read and cite exactly what i said.

[gusty falcon]

“all numbers between 3 and 4 fulfill the condition for Q2”

[fervent ember]

you missed: in this case interpolation is used to get Q2 = 3.5 sorry, thats waste of my time.

[gusty falcon]

okay hmm all of them do satisfy it but u mean i would mostly use the interpolated answer which is the average

[gusty falcon]

okay sorry

i didn’t miss it i just saw the “in this case” but like isn’t it “always”

i’m not trying to be rude bc i’m genuinely confused

but it’s okay i hope im not wasting your time

[fervent ember]

the condition for q2 is half of the values should be smaller, half of the values should be bigger. in the case 1,2,3,4,5,6 all values between 3 and 4 fulfill this condtion. as we wanna have unique values the definition is specified for such cases as the mean of the lowest and highest, so we get 3.5.

[gusty falcon]

okay thank you

this answers most things

the first time everyone was saying there’s no right answer

at least i get now that most definitions try to keep unique outputs

so interpolation is used

anyway thanks again

[fervent ember]

youre welcome

[gusty falcon]

.close

[midnight plank]

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[midnight plank]

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• Show your work, and if possible, explain where you are stuck.
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Channel closed

Channel closed due to the original message being deleted.
If you did not intend to do this, please open a new help channel,
as this action is irreversible, and this channel may abruptly lock.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
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• Show your work, and if possible, explain where you are stuck.
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• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[main owl]

bro is opening a new ticket

to get a new answer

figure it out your self this time smh bro didnt even say thank you

[surreal escarp]

i said thanks

[main owl]

oh

[surreal escarp]

but calm

[main owl]

my bad

i forgive u

[surreal escarp]

.close

[midnight plank]

Channel closed

Closed by @surreal escarp

Use .reopen if this was a mistake.

[midnight plank]

Available help channel!

Send your question here to claim the channel.

Remember:
• Ask your math question in a clear, concise manner.
• Show your work, and if possible, explain where you are stuck.
• After 15 minutes, feel free to ping <@&286206848099549185>.
• Type the command .close to free the channel when you're done.
• Be polite and have a nice day!

Read #❓how-to-get-help for further information on how to ask a good question, and about conduct in the question channels.

[pale fog]

In triangle ABC, angle B = 50°, angle C = 55°, and ha = 8 cm
Find the sides of the triangle

[pale fog]

I already found AC

Now I need to do tg(C) = 8 / b

[rigid tangle]

HA is the line dividing the triangle in half right?

[pale fog]

obviously

thats what height does

drawn from an angle

[fervent ember]

if you have AC and you know angle at B and at C (then you also know angle at A) then use sin rule to get the other sides.

[pale fog]

im doing it chillax

1/2 b = 5,60 cm

5,60 * 2= b

, calc 5,6 * 2

[grand pond]

The following error occured while calculating:
Error: Unexpected operator , (char 2)

[pale fog]

, calc 5,6*2

[grand pond]

The following error occured while calculating:
Error: Unexpected operator , (char 2)

[pale fog]

wtf

,calc 5.6*2

[grand pond]

Result:

11.2

[pale fog]

@fervent ember Somethig doesn't add up.

Something

if c = 9,77 cm

then a = 9,77 cm?

[cedar mason]

what the hell is h

[pale fog]

HEIGHT?

[cedar mason]

median or altitude

ok altitude

[pale fog]

wym?

help me

[cedar mason]

idk use a bunch of sine rule maybe

[rigid tangle]

You know rule of sins right?

[pale fog]

ik..

[rigid tangle]

Ok

[pale fog]

i found c...

c = 9,77 cm

[rigid tangle]

Ok

What is your next target

Wait

[pale fog]

i found that b is 5,6 cm

[rigid tangle]

From what i know every side faces its angle

Side B=9,77

Not c

[rigid tangle]

Show me your work

[rigid tangle]

Why tan?

[pale fog]

to find b

[rigid tangle]

You only need sin, and it seems you divided by B which is the hyp for the other triangle

Your tan equation is wrong from what i can read

You only sin

[pale fog]

i need to find

b

I CAN'T USE SIN

WITH THAT

[fervent ember]

maybe. but how shuld i help if you do not show your work?

[pale fog]

HERE.

[rigid tangle]

I retract my words

Your work is correct

[pale fog]

im so smart

i need to find another traingle

[rigid tangle]

Well since you found 5,6 you should multiply by 2 for the whole side

[fervent ember]

9.77 / sin (50) = c / sin (55) take a calulator and calulate c.

[steady trail]

Why you here than🙂

[pale fog]

i dont think a = 9.77

[rigid tangle]

You havent shared your way work for side a

[pale fog]

i just assumed that it's 9.77 because of

[rigid tangle]

Do not assume

[pale fog]

isosceles triangle

[rigid tangle]

Is it?

[pale fog]

but it can't be now

[rigid tangle]

It’s not tho, one angle is 55 and one is 30, and the last one must be 95

[violet hedge]

Co musisz policzyc

[fervent ember]

this.

[pale fog]

if its not right, isoscele or equilateral triangle then what is it?

[rigid tangle]

I forgot the term, but simply just a triangle with unequal side lengths

And so unequal angles

Anyways do your work for side a, and show it

[pale fog]

@fervent ember

[fervent ember]

why do you mention me?

[rigid tangle]

He trusts you more, i was one of the nutcases helping him in the last channel

We confused him so much

[fervent ember]

he didnt follow a single hint. so, no, he doesnt trust me.

[pale fog]

i found it out either way

[rigid tangle]

he does things his own way sometimes

[pale fog]

a = 10,44 cm
b = 12,31 cm
c = 9,78 cm

[rigid tangle]

Prove it through rule of sines

Or show your work for side a idc really

[violet hedge]

masz w karcie wzorow maturalnych

[rigid tangle]

Why side b not equal to 11.2?

[pale fog]

I did this correctly

[pale fog]

bc height does not divide the length

centerline of an angle does that

if it was ma then it was in the middle

[pale fog]

?

[violet hedge]

w ktorej jestes klasie

[pale fog]

1

[violet hedge]

liceum/technikum?

[pale fog]

lo.

[violet hedge]

zajebiscie ze jestes tu na serverze, polecam powoli uczyc sie wzorow maturalnych i jak korzystac z nich

fajnie sie obeznac co tam jest i gdzie jest na pozniej

[pale fog]

no ale ten serwer jest bardzo ciężki

[violet hedge]

co masz na mysli

[pale fog]

bo prostu 4 typow pisze i jest mętlik

[violet hedge]

uroki najwiekszego servera matematycznego 😄

dasz sobie rade, jaki dzial teraz przerabiacie

[pale fog]

trójkąty

roblisimy powtorke z pitagorasa

[violet hedge]

Nie wiem jak was ucza teraz, ale z tego co mi sie kojarzy to w polsce uzywaja tg i ctg zamiast tan i cot. Aczkolwiek nie wiem

[pale fog]

i tez trojkaty przystajace

[pale fog]

no wlasnie!!

tez uzywam tg ale oni nie ogarniają

[rigid tangle]

Aight you’re correct

unconventional but correct

[violet hedge]

Zostan tak jak robisz, bo sie glupio nauczysz i beda Ci pewnie punkty na sprawdzianasz zabierac

https://cke.gov.pl/images/_EGZAMIN_MATURALNY_OD_2023/Informatory/wybrane_wzory_matematyczne_EM2023.pdf

tutaj masz link do wzorow

[rigid tangle]

And dont chat here please

It’s a help channel

[violet hedge]

I am helping him

Because he is a high schooler in Poland and I finished high school

[rigid tangle]

Well ok then sorry to assume wrong

[violet hedge]

Yeah, next time dont assume

[rigid tangle]

[pale fog]

cotg to cotanges

my uzywamy tez cos

[violet hedge]

ctg

sin = sinus
cos = cosinus
tg = tangens
ctg =cotangens

W Polsce sie takiego zapisu uzywa

Z tego co pamietam

[pale fog]

no wlasnie

tan to chyba w usa uzywaja

[violet hedge]

Tak

[pale fog]

@rigid tangle we use tg

[violet hedge]

Ale warto znac obie wersje bo jak tutaj prosisz o pomoc, to po angielsku beda pisac

[pale fog]

instead of tan

[violet hedge]

^

They also dont have arcus functions in high school and they dont have secants and cosecants

[pale fog]

no wlasnie uzylem tan bo kiedys tutaj zrobilem tg to jeden zaczal sie pytac co to jest

[violet hedge]

To next time napis ze tg to tangens i chuj

Zapis jest tak naprawde umowny

[pale fog]

a po co mi cotangens

przeciez te wszystkie funkcje wystarczą

[violet hedge]

tak naprawde jak znasz sinus i tangens

to cosinus i cotangens

mozesz na spokojnie policzyc

Jest taka tabelka trygonometryczna

pewnie kojarzysz

dla katow 0, 30, 45, 60, 90

jezeli spojrzysz na wartosci to sinus od lewej do prawej to cosinus od prawej do lewej

i tangens i cotangens tak samo

zamknij kanal, ja lece dorbanoc

[pale fog]

nie

[violet hedge]

aa

[pale fog]

ok dobranoc

[violet hedge]

to wpisz sobie w internecietabelę wybranych wartości funkcji trygonometrycznych

[pale fog]

dzieki