#help-49
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I didn't get help with all sections of this last night but I did not see section D.
Can you please help me figure out the equation for section d? Those are the correct answers I just need to know how to find it I know how to do a -c
@ me pls
When u see this
@unkempt stratus same way as you did with c)
just this time, you dont want the population to be 8M
you want it to be double the initial population
neither
Oof
just translate the words into math 😛
you want the population to be twice the initial population
let me ask you, what is the initial population?
6.14
right, so we want the population to be double of 6.14
we want it to be 12.28M
now, the population is modeled using the function you found in a)
so, just set P(t)=12.28
and find out what t has to be
12.28=6.14e^0.0238t
yes, now just solve it
isolate the time t
that would be the number of years that have to pass in order for the population of the city to become 12.28
entiendes
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I can’t wrap my head around how I would word this
Like 5 times the distance from 2x + 3 ???
The wording is so confusing
the distance from chenoas school is x?
i dont know
the wording is throwing me off so much
I dont know how I would write it down
+3 because 3 times more
but thats only from the coffee shop to the school
exactly
so how do we know what x is referring to
yes so that is one expression
its only referring to the distance from the coffee shop to the school
sorry now it threw me off too 
the second part anyway
you might need multiple variables and do some kind of equation system
ah alright
hmm
you might need a different helper sry i couldnt assist you further
i wanna see how to solve this as well
<@&286206848099549185>
Ye?
yes hi this
i guess for me my personal question is if you would need an equation system or not
I see
then if camarozzz wants to ask for more help then by all means he should
It would be 1 equation
ofc it would be 1 equation?
No worries bro
wait I think I got it
i just didnt know i am not familiar with what 1 unit of geometry means
language barrier or new concept for me
this should be right think about it
home to coffee shop is 3 miles more than twice
so that means the coffee shop to school is half minus the 3 miles
and the home to school is 5 times coffee shop to school which is 2 miles
so 10x
6x+3=10x
sounds like you meet the condition with that yeah
damn
I could have used
20x+3 and 10x and 50x
probably not equivelant
so im stuck
OOOOH
I got it
it would be 2x + 3 + x = 5x
in sorry i just figured out that x is the distance from coffee shop the school 
lol
but nice good job man
the wording is really challenging
I had to get it wrong to see the explanation but I was on the right track :/
still good job but sad you didnt just logic it all the way
its only 1 point out of 80 anyways
at least u have more experience now
big win have a nice day good luck with the rest
thanks man
How did I get this wrong
3x+1 is equal to 2x+8
if you solve for x you get 7
then do 3(7)+1+4(7)-6+2(7)+8
and get 22+22+22
so 66
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Is this right?
Yes
how about this?
That’s fine too
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could I have a hint?
So the first thing I did was to find the number of possible combinations, which is c(100,10)
next the possible digits in each places
So The sum of the first 90 natural numbers has 4 digits
This is the same as the number of possible sums for a ten-element subset. How can you bound said sum? Are all values in the range achievable?
The sum can be bounded by chosing the 10 largest numbers in the set , for that will give us an upper bound
we then find the summation of the 10 smallet numbers in the set
and that gives us a lower bound
the lower bound is 55
the upper bound is 1045
sus
,w sum of first 10 natural numbers
oh that part is fine
,w sum of natural numbers from 91 to 100
it should be 1000-45 not +
another way is add 90 to each term
55+90*10=955
how do you get from ten terms summing to 55 to summing to 56
I don't follow
which part?
how do you get from ten terms summing to 55 to summing to 56
First 10 elements
what ten elements sum to 56?
can anyone help me
!occupied
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elements from 2 to 10 +12
check that sum
oops
note that you only need to add one to one of the elements
Yeah, I realise that. I have to add one element and remove one element
so remove say 9, add 11
removing 9 is the same as doing what to the total?
yes, however, since the increment is 1 the difference should be 1.
reducing it by 9
and then putting in 11 does what?
increases it by 2 units
so how can you make the net effect +1?
I would add 10, but 10 would be repeated then
yes
I can remove 10 and add 11
yup
11
what about 55 to 955?
901
yup
youre welcoem
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there is a little bit more care that you need to put to prove this
.reoepn
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so Induction I would guess?
specifically, when you reach 1,2,3,4,5,6,7,8,9, 100 what do you do now?
yeah!
if you have $a_1,\ldots, a_{10}$ that sums to $k$, then can you create a set of distinct numbers that sum to $k+1$?
suppose the $k$ is not 945
qwertytrewq
Remove say $a$ and to that add $a+1$
(why am i here )= idk
but what if a+1 is also in the set?
what if a+1 is 101?
et the last element be $d$ , then we have $k=d-a$ we we add the number d+k
(why am i here )= idk
k=d-a?
what is a?
qwertytrewq
I think I'll come back to this in a bit
Maybe after I become a bit more familiar with induction
sorry
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yeah 901
cool
why the fuck is your name sweatyballs_123
bad
💔 i hope things get better for u soon
that would be nice
🙏
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this is part of my friends solution
im confused on where the 1 went from the -2a^2k+1
oh nvm she just wrote it wrong
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perhaps your sir divided through by "a"
the second term doesnt have an a to be divided
yes it does
it actually had 2k+1 a's to be divided by
😂
then there would be inconsistency in the first term tho
yea probs
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is there any manipulation used cause I’m stuck
@chilly cobalt Has your question been resolved?
x^11
x isnt real :(
11th root of unity
just wondering how 1/1 + x + x^2 would even simplify
what have you tried?
tried simplifying didn’t work
$\f{1-x^{3n}}{1-x^{n}}=1+x^{n}+x^{2n}$
🫎 Moosey 🫎
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which set is this?
natural numbers including 0
why didnt they just write W 💀
because nearly no one cares about W
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Please help understand this question.
@delicate helm Thank you for your help yesterday!
I would like to show how it works, but I am a bit confused, if it works at all.
We have the usual propositions:
φ, ψ, θ in {false, true}
So one way of composition of logical and operators, or functions would be:
(φ ∧ ψ) ∧ θ
Here the result of (φ ∧ ψ) is used as input in another and function … ∧ θ
A proposition is a subset P ⊆ X of subsets of X, for which P holds.
The logical and operation is an intersection of such subsets P ⋂ Q ⊆ X
For instance, if X is all the possible states of a potato, and P means boiled, while Q means cooked, then P ⋂ Q are all the states of a potato when it is both boiled and cooked.
⋂: A → B
⋂: (P, Q) ↦ ⋂(P, Q)
and: Boolean × Boolean → Boolean
Boolean is the set {false, true}:
and: {false,true} × {false,true} → {false,true}
∩: P(X) × P(X) → P(X)
and seems to be analogous to multiplication in integers modulo 2.
from sympy import symbols, And
# Define abstract Boolean variables
a, b, c = symbols('a b c')
# Compose the logical AND function using symbolic variables
result = And(And(a, b), c)
print(result) # Output: And(a, b, c)
So can we do the following:
$and \circ and$
kytsu
I think and(a, b) could be composed like this: and(and(a,b), c)
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We can compose two functions if they have the same codomain and domain:
dom g = cod f, so dom f = dom(g ∘ f) and cod(g ∘ f) = cod g
dom ∧ = {false, true} × {false, true}
cod ∧ = {false, true}
Perhaps this is why we can't compose, because the domain of and has a different form, than codomain of and.
Thanks @shell wigeon
@shut canyon Has your question been resolved?
Yeah I wouldn't use this notation for it, as it's ambiguous if the right AND is occurring in the first or second argument of the left AND
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I am stuck on this proof. I don't know where to begin
If 10^x = 2 then x is irrational
a simple proof by contradiction should work. Assume that x = p/q for integers p and q
The furthest I know how to get from this is then by saying p/q = ln(2)/ln(10)
oh no dont use any logs
try taking log with base 10 instead, if log
$10^{\frac{p}{q}}=2$
rbit
theres one simple thing you can do from here
Raise both sides to q/p is the only other thing I can think of
raising both sides is good, try to just get rid of the fraction
Raise both sides by q?
yeah
Lhs and rhs are both integers now
$10^p = 2^q$ and just think about whether this is possible or not
rbit
right (unless ofc p is zero but that can be excluded)
Oh true yeah thank you
also negatives
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Why only when it converges?
When it converges the limit will have a finite value
I am guessing that's the reason
Even if it is I don't understand why
Help?
take point 1. the limit is a real number with a special property, then if either the limit of the a_n or b_n does not exist as a real number then adding these limit will not make sense.
Oh
Yeah
Makes sense
A lot
Same with the rest of the properties too right?
Division with infinity as denominator won't make sense
Okay
Thanks!
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I think "start with y = r sinθ" is typo, should be start with r = sinθ ,this is a circle
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${(x,x+y) : x \in R, y\in \Z}$
(why am i here )= idk
(why am i here )= idk
why do you think so
hmmm, doubt it.
I mean say x=2, it maps to (2,3),(2,4),(2,5) \dots (2,2+y)
what about when x = 0?
it maps to (0,1),(0,2).....(0,n)
so, how would you get something like (0, pi)?
hmm, you can't
I mean it isn't R^2
But It surely isn't a standard curve either, is it
can you try a small plot for a constant y?
Y/N
Put y = 0 and see what you get
For a constant y , it'x x=k
you mean (k,k)?
and is that a standard curve?
and so on for all y
if you see a countable set, try enumerating the set element by element if you dont get a clear idea immediately
so It's the family of curves parallel to x=y
Wouldn't that just be all of R^2?
All of R^2 is contained on some line that's parallel to the line x=y
.
yeah, it's a family of curves. Saying the is a little strong
or you need more qualifiers on that set
@twilit field Has your question been resolved?
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Could someone please give an example opposite to the case shown here.
The first or second ?
Both are not the same?
I thought since they both were proving that the limit exists,they are the same
Hmmm, "the same" how?
^
So you want an example where the limit doesn't exist ?
You can try with (-1)^n
Okay I will try
Lt n tends infinity (-1)^n = ?
No
Like
What shpuldni take the value of L as ?
Should*
I
@grim vector ?
Funny
The next example
Is the one you gave
Support me by checking out https://www.supportukrainewithus.com/.
In this video, we are going to show that lim(-1)^n when n goes to infinity does not converge.
-~--~--~--~
Please watch: "Real Projective Space, n=1"
https://www.youtube.com/watch?v=2ottRuDA5WA
-~---~-
I cant write a lot actually, but its explained here
Okay I will watch this too
Ty
Famous one dealing with sequences
Yes it is alternating sequence
@grim vector
?
The ending would have been true
Can you show the whole ?
^,Is this what you meant ?
Ye
@last slate Has your question been resolved?
Is it because the definition says "for every epsilon >0"?
So we have to take every case
Just taking some epsilon >1 won't do
Am I right?
@grim vector ?
If epsilon is greater than 1 that would work indeed
But making it tends to zero
It became wrong
Moreover this is true cuz all value of (-1)^n are between -1 and 1 so the abs value is < 1
Making what tend to zero?
Epsilon
I didn't get you
Epsilon, in the meaning iirc has to tends to zero, with that, at a certain point you have all the values of the sequence/function close to the limit, but since epsilon tends to zero and has to be greater than 1 its not logical so limit does not exist
Its a little positive number in the meaning
Thats how i see it
Okay so 0<epsilon<1 ?
I took value in it indeed
Since you need counterexample
Ig it works
So it's just for this example that we had to take the above range unordered to prove that the limit doesn't exist
Am I wrong again?
(That will probably works the same with cos(n) and sin(n) as well)
Soz bad internet
Epsilon has to be little cuz otherwise we cant figure the limit out ( imagine it being like epsilon = 3, it means that all the terms are around the limit with a max distance of 3 at a certain step. So its better to have a little distance rather than a big one, its more precise
@last slate Has your question been resolved?
Okay
Thanks a lot!
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so using chain rule for z_t I get
z_t = f_x(x_t) + f_y(y_t) = f_x(2ts) + f_y(2)
whats the next step
z_ts = f_x(x_t)(x_s) + f_xy(x_s)(y_s) + f_y(y_t)(y_s) ?
oh wait is it:
z_ts = f_xx(x_t)(x_s) + f_xy(x_t)(y_s) + f_yy(y_t)(y_s) + f_xy(y_t)(x_s)
-2(2ts)(t^2) + 5(2t)(3) + 2/3(2)(3) + (5)(2)(t^2)
0 + 0 + 4 + 0 = 4?
shit idk

@real pivot Has your question been resolved?
<@&286206848099549185>
0+0+4+0 = 4 that is correct 
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brain died a bit
What am I doing wrong?
could it be asking for something else?
yea?
whats it asking
the amount of cell phones will minimaze the cost
mhm
so, is that asking for the cost?
yea
its asking in thousands
if you do this your basically saying there is 1380 thousand phones
wdym
like 13.8 *100
no
so itd be in thousands
yeah sorry
fuck how do i say it
if i say the answer is just 13.8 will you understand me
alr
just this part
was making me rethink everything
ah
omg
isee
im dumb
thank you
the thousand is already in the answer-----
yeah thats what i wanted to say i had no idea how
good job
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bye
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Find the amount of (A,B) such that A and B are subsets of {1, 2, 3, 4, 5, 6}
and. |A| |B| = |AUB| |AUB|
I got that A = B and |A| = 1,2
Are you sure? A=B={1,2,3,4,5,6} is possible.
any A=B works
and with a bit of effort you can show that A=B is necessary as well
Also, is this question written correctly?
Is $|A \cup B|$ actually written twice on the right hand side?
Civil Service Pigeon
@chilly cobalt Has your question been resolved?
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for what class?
heres a hint: the function of air density is based on what?
hello?
bawangs hint is good
you could think about this as maybe like, what'd be the easiest way to do this?
and to me, itd be easiest to add up all these slices
if in each slice, the density was the same all over the slice
because if we have something like idk $\sum _{\text{slice}} \text{density}(s,w)$
jan Niku
where s and w are the other two variables describing some point on our one dimensional slice
this is pretty not so bad if density is constant over that slice, i think
does that help at all
yeah its f
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how to express U(n) in function of n? I want a brief demonstration if possible.
Try
Like
Computing the first 2
for n = 0 and n = 1
and n = 2
and look at what you have
Oh nvm I dun goofd
are you sure its possible 
i mean
what makes u doubt that
well i mean it wouldnt be hard to write down a recurrence relation you cant solve just like its not hard to write down a differential equation with no solution
just asking though
nothing poking at it seems straightforward but im pretty bad at math
have you tried oeis?
hm?
Looks like a Mobius function
never heard of that
Could be overkill
numerator appears to be OEIS A060819
I'd start by trying polynomial division
if u just plug in numbers u will figure it out fairly easily
how
pretty sure i wont waste my time
and the denominator is a shifted version of the top
this isnt a special sequence
how will i do that
$U_n = \frac{ (n+7) }{ \text{gcd}(n+7, 4) }\frac{ \text{gcd}(n+4,4) }{ (n+4) }$
jan Niku
my gad
hmm might be off by 1
u don't need to express it like this
i think i am, actually
nah, I'm just stealing from OEIS
this is where i'd start
PERSONALLY
only because im bad at math
prove that An is arithmetic by calculating its three first values
then express Vn in function of n since its arithmetic
then substitute it
in
using equations
solve for Un
,w x = (5x-1)/(x+3)
wtf
whats right
i dont remember
It's not an ap
i didnt think so
Maybe the numerator is at least in an unreduced version
did u not understand my way
anyways
it appears that the numerator is a translated version of the denominator
why not try starting there
if u really dont want to just rip the sol from oeis
altho i should scribble to make sure its actually helpful
idek whats oeis
the hell is that
This is like proof by asspull
It probably works but there's 0 motivation
wait
don't you want Un-1 on the bottom anyways
jan Niku
.
oeis is the hammer for figuring out sequences next to other techniques
most likely expressing a function in terms of n would require an arithmetic sequence
cause u can express those in terms of n
use a computer to calculate whatever, 25 terms, put them into oeis
it tells you some esoteric function that generates that sequence
check the next 75 terms or so and see if theyre right
it appears to be the relationship between the numerator and denominator
theyre translated off each other
this isn't even necessary
why am i so dumb and i cant understand anything
cause yes
since the discussion here is a mess. it's not ur fault
Well he asked jan what oeis was and he replied with this
So it's probably not his fault he can't follow
oeis is an online encyclopedia of integer sequences
i guess i figured theyd have googled it i'm not super together tonight the obvious thing to do would be just explain, thats my bad
no
is this a site
yes
it is
yeah oeis probably not the way to do this
do that
you do what the other people are suggesting
this is something youd do when you need the answer for some other reason
isnt my way efficient still tho
did i say +1
yes
i js do random shit
here
its what my school does
and wants us to do
its also a method
lets see
+1 doesnt work
yeah -1 probably
do i js follow ur method
did u understand tho
eh
my intuition is that the sequence harmonically converges
checking fixed points shows it would have to converge to 1
i think it does
so subtract one and now it converges harmonically to 0
take the reciprocal and now it's an AP
Weird way of spelling "correct"
np lol
ur cooked

Closed by @twilit coyote
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rip
we did all we could man
i think it converges to 2
we provided algebra
:/
we even pulled calculus
It would be weird to converge to something that isn't a fixed point
@twilit coyote if u want the answer tho based on what i did
uh
am i allowed to tell him
Idk I won't tell
i got struck by a certain 77^2 guy after i answered for smn
ill dm ya
thnks
nvm i cant
why?
friend first
done
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what have you tried?
for part c
do you know what a left hand riemann sum with dx=1 means
@grave haven
i was typing at the same time as you 😭 where could you possibly have gone
x
sure
but you can write x_i better
theyre evenly spaced right
whats x_0?
whats n?
oky
that doesnt answer the question though 
whats x_0?
these should go what, x0, x1, x2, ...
and theyre evenly space
I guess, maybe you could explain how early into this you get stuck, don't let me drag you along
unless you are stuck now
you have a sequence in your sum
I'm asking you to define it
I'm telling you its arithmetic lets say
$x_i = x_0 + i \cdot d$
jan Niku
whats d? whats x_0?
do you believe that this is the form for x_i?
evenly spaced along some interval?
okay
Are you able to answer my questions? or what's giving you trouble
this what?
they're numbers
Yea
delta x is given right
in your sum
but you have stuff written there you havent defined
you need to define n
and you need to define x_i
then, everything in your answer is just a number
instead of some general form
I'll be honest you're racing the clock against my sleeping pill @grave haven
Is there any way you can decrease the latency a little here
I worry I'm going to lose you
if not no biggie I just have to hand you off
@grave haven Has your question been resolved?
@grave haven Has your question been resolved?
@grave haven Has your question been resolved?
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what's wrong with my domain?
the domain of the inverse function is the same as the range of the original function
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Please solve Q8.
@subtle minnow Has your question been resolved?
<@&286206848099549185>
what have u tried
Firstly I don’t understand how it has 3 solutions
Then put t= mod of x-2
And made the equation quadratic in terms of t
Then I checked the solution.
Well here’s the solution for you
Please explain the solution
that's quite neat of a solution
have u tried writing the roots out in terms of K ?
i think the root 0 would give u some possibilities and the root positive is your condition of k
No idea
delta
I did everything but nothing made sense
really? lemme try 1 min
Got it!!!
We made the equation quadratic in terms of t
And t is mod x-2
Thus mod of x-2 has 2 solutions
Which means x has 4 solutions in total
Now, for 3 distinct solutions for x
2 values of x must be equal
0
Yeah
But one case im still getting confused with
Let’s say the equation in t has two roots t1 and t2
Each t1 and t2 will give 2 values of x
Let’s say t1 gives x1 and x2 and t2 gives x3 and x4
So for 3 distinct solns 2 of the xs must be equal
Why can only x1 = x2 or x3=x4
Why can’t it be x1=x3 and we’d still get 3 solutions
not necessary
cause t1/2 don't always give 2 xs
t = 0 only gives 1 x
and since u proved that one of the t has to be zero
this happen
Also is this true that mod gives equal roots only when it is equal to 0?
mod of a linear equation ye
Ok thanks
That’s the entire question
It was only tricky
Almost all the questions here have some trick behind them and they don’t even require bulky solutions
.close
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One more question
Will it be k=2 always
Even for the other non zero root of t?
oh hold up
you wonders if K would still be the same if u plug in the other root right
K would have to be 2 cause f(t=0)=0 is not a possibility but a true equation
k would change if it is either f(t=0)=0 or f(t=other t)=0
but in your case, both have to happen at the same time
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I feel like I've screwed up big time here (Y/N)
the stray is 3
you just need to reduce -2 to 1
I multiply R_1 by -3/4.5 and add it to R_3
yeah
Also, why not follow the algorithmic process? Like from leftmost column to rightmost?
That leaves less chances to be confused
The guassian algorithm that is?
Yeah
That's the next section in my book
Ohh
I think the aim is to motivate a need for the guassian algorithm via such examples
but yeah, if you convert it to upper triangular or any triangular, it makes the process more mechanical and you get easier time doing it
I dont think gaussian algorithm is any different. It is just the one order of operations that is most natural for the computers to follow. All row ops do the same thing basically
Does this look about right?
seems alright
But I wouldnt rely on me. Just verify with any random online calcs
,w solve 2x+y+z=-1;x+2y+z=0;3x-2z=5
also btw you only need to make it upper triangular
Well, I've messed up somewhere
tbf, back substitution is also elementary rw ops
true, but you could avoid a few row ops that way
but only in programs. Humans dont calculate 0*0 anyways
im having a stroke reading fractions of decimals
dont build bad habits now
*dont build bad habits ever
Is this better?
Hi, convergence !
hello wai hows uni going?
i see ,wait what tutorial?
iirc dont you know that already
I do
Right so far?
Math and physics students, yes
thats good,have fun over there
Does this look fine? The solutions seem to check out
Now make the left hand side identity matrix (I wanna see 0.5/4.5 on right
)
dont use mixed fractions
here you go
Will not in the future
sorry
thanks everyone
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Chat could any of y'all give me some questions similar to question 50?
Or even similar to 49
${(p, q) : p,q\in\bN, \gcd(p, q)=1}$
