#help-49

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midnight plankBOT
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rich plaza
#

How do I do part C of this question?

midnight plankBOT
lavish venture
#

well what is the formula for speed

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given the position functions

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how would you find the velocity

rich plaza
lavish venture
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in calculus terms

rich plaza
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oh

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idrk

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I never learnt it

lavish venture
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oh actually they gave you v=(x,y)

rich plaza
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yeah

lavish venture
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ahh ok my fault i assumed x and y were functions of position

rich plaza
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ohh

lavish venture
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were you able to do parts a and b?

rich plaza
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yes

lavish venture
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right so how did you do part a then

rich plaza
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most of a and b was just graphing

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I plugged in 4 for t

lavish venture
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hmm you don’t need to graph

rich plaza
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and solved it out

lavish venture
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plugged 4 into what

rich plaza
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t

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the time

lavish venture
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yes but for what equation

rich plaza
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both x and y

lavish venture
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then you did what

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that would give you two numbers

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that isn’t the speed

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that’s the velocity in each direction

rich plaza
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that then gave me the vector (81, 21)

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ohhhh

lavish venture
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right but that’s not the speed

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that’s the velocity vector

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speed is a scalar quantity

rich plaza
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oh ok

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how do I do that>

lavish venture
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it gives only magnitude

rich plaza
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*?

lavish venture
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well given two vectors how would you find the magnitude of the resultant?

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you have two vectors

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velocity in the x and y direction

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how do you find the resultant

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hint: you used it in geometry class

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the formula is a meme

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does pythagorean theorem ring any bells

rich plaza
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ohh

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yes

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wait so the stuff with vectors is this supposed to be calculus?

lavish venture
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in general speed is the magnitude of velocity which is just =sqrt(vx^2+vy^2)

rich plaza
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OH

lavish venture
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generally you’ll be given the position in each direction as a function of time

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and have to find x’ and y’

rich plaza
lavish venture
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then that will be your vx and vy

lavish venture
rich plaza
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yeahhh

lavish venture
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i thought this was ap calc

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i think they still do a bit of calc though

rich plaza
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i had a feeling this was calc stuff

lavish venture
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i remember checking the curriculum in the beginning of last year

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there’s a good amount of calc still

rich plaza
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yeah

lavish venture
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but the x’ and y’ being the derivatives of the position functions is

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but that’s not needed here

rich plaza
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oh kk

lavish venture
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since they give you the velocity component functions

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so for part a you need to find the resultant of what you got

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and then for part c you set speed=0 then solve for t

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using

rich plaza
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ohh ok

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so for a

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How do I find the speed for that

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cuz i got the vector velocity

lavish venture
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mhm so you have essentially two legs of a triangle right?

rich plaza
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yes

lavish venture
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you can treat the vectors as such

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then find the resultant

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or hypotenuse so to speak

rich plaza
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im sorry give me a min

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ill brb

midnight plankBOT
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@rich plaza Has your question been resolved?

rich plaza
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sorry im back

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i solved for the resultant and got 83.68 (rounded)

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for part as

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A

rich plaza
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because its asking for a system of equations

lavish venture
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the only way for the sum of two squares to be zero is if both terms are zero

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since squared terms are always positive

rich plaza
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so do i plug in 0 for the x and y equations that r give

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given*

lavish venture
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yes

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x=0

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and y=0

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not t=0 though

rich plaza
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ohh

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ok

lavish venture
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you’re solving for the time t such that the speed is zero

rich plaza
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so my system of equations would be 0= (x equation) and 0= (y equation)

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i dont want to type it out

lavish venture
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mhm

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then solve it

rich plaza
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x doesnt equal 0

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like the 3^t

lavish venture
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exactly

rich plaza
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it never equals 0

lavish venture
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read the second part of the sentence

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"if it exists"

rich plaza
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so that means that it doesnt exist

lavish venture
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yup

rich plaza
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oh okkk

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tyy

lavish venture
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and your reason is because 3^t≠0

rich plaza
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that makes more sense now

lavish venture
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you’re welcome

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if you’re done with this channel type ".close"

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@rich plaza

rich plaza
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.close

midnight plankBOT
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midnight plankBOT
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twilit field
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Can I have this verified please?

midnight plankBOT
twilit field
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S(a set) denotes all the subsets of that set

unique stream
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Sure

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Usually P(set)

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As powerset

twilit field
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That's the set of the all subsets

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this is just the list of subsets

unique stream
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Ah k so including duplicates?

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Nah it'd be the same

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So S(...) yields the same as P(...) just as a list instead of set then

unique stream
twilit field
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I have 8 elements, yeah.

warm basin
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if you mean smn else i have no clue 😭

twilit field
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Is my answer right, is my question.

shell wigeon
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That's one too many parentheses

unique stream
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sry for delay

subtle zinc
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IS THE LHS A SET

twilit field
twilit field
crisp oxide
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Not my field, but shouldn’t the rhs be a set?

dreamy lichen
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I don't think it's a good notation, but it's whatever it is

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there is also P that denotes the set of all subsets

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Also @twilit field , perhaps you forgot to close this?

midnight plankBOT
#

@twilit field Has your question been resolved?

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urban viper
midnight plankBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
urban viper
urban viper
# urban viper

i worked out the line equation but idk where to go from there

small jasper
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Where did this come from

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You’re not necessarily drawing a tangent at a point where y=0

urban viper
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0 = cos2theta

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so theta = 1/4 pi

urban viper
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so then what do i do

small jasper
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Write the equation of the tangent for an arbitrary angle and then substitute x=3, y=0

urban viper
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arbitrary angle?

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idk what u mean

small jasper
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Basically find the tangent for any value theta rather than a specific value

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b/c you already found that $\frac{dy}{dx}=-\sin \theta$, so the equation is simply $$y=(-\sin \theta)( x-4\sin \theta)+\cos 2\theta$$

grand pondBOT
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Civil Service Pigeon

urban viper
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oh i see

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i found the cartesian equation instead

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i got y = 1 - x^2/8

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but idk what to do from there

small jasper
urban viper
small jasper
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Find the tangent for any point on the curve rather than a specific point

midnight plankBOT
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@urban viper Has your question been resolved?

urban viper
#

ive done that but it was wrong

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nvm found it

#

.close

midnight plankBOT
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midnight plankBOT
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dusky cradle
midnight plankBOT
prime hornet
feral sedge
#

this is a fairly unfortunate integral

dusky cradle
#

P/q form

dusky cradle
next bramble
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Can you use Laplace transforms for this?

dusky cradle
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If it works fine. I will surely use

next bramble
#

Where did you see that question from?

dusky cradle
feral sedge
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i fail to see how laplace transform would help here

next bramble
dusky cradle
#

So is this not solvable?

feral sedge
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it's solvable just not with a pretty process

dusky cradle
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Could you tell me the steps? I will try it

midnight plankBOT
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@dusky cradle Has your question been resolved?

dusky cradle
#

@feral sedge

midnight plankBOT
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@dusky cradle Has your question been resolved?

dusky cradle
#

Lol

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.close

midnight plankBOT
#
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bright shoal
#

@dusky cradle

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.reopen

dusky cradle
#

.reopen

midnight plankBOT
#

dusky cradle
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@bright shoal

bright shoal
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yes

dusky cradle
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Yes

bright shoal
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Let's see

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,w diff 1/t^3

dusky cradle
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Sure

bright shoal
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1/t^4

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Hmm

dusky cradle
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Hmm

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So

bright shoal
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take t^3 common from denominator

dusky cradle
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Then?

bright shoal
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So what it becomes

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t^4/t^9 right?

dusky cradle
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Yeah

bright shoal
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Okay

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Ok so then what are we left with

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?

dusky cradle
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Left with this

bright shoal
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Send

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,rotate r

dusky cradle
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Sent

grand pondBOT
bright shoal
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Okok

dusky cradle
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Use these sign

bright shoal
#

So now

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We have (1/t)*(1/t^4)

dusky cradle
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🤔

bright shoal
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1/t^5=1/t*t^4

dusky cradle
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This one is correct

dusky cradle
bright shoal
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So

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Do u know ibp?

dusky cradle
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We have another term

bright shoal
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Integration by parts

dusky cradle
bright shoal
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So see

dusky cradle
bright shoal
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,w diff (1-1/t^3)

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,w d/dt (1-1/t^3)

bright shoal
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See now

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@dusky cradle u have the derivative 1/t^4

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So u can integrate it easily

dusky cradle
bright shoal
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See the derivative of (1-1/t^3) is

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3/t^4

dusky cradle
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It is

bright shoal
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Now check on your tab

dusky cradle
#

But i am doing

bright shoal
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You can integrate it

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Wait imma help

dusky cradle
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Yeah

bright shoal
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,w int 1/[t^4*(1-1/t^3)^3]

bright shoal
#

Got it?

dusky cradle
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No no

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I am not asking this sit

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One second

bright shoal
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Oh k

dusky cradle
bright shoal
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Where did the 1 go

dusky cradle
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multiplied

bright shoal
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Ok

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So u integrated it

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And we differentiate 1/t

dusky cradle
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What??(

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I differentiate

bright shoal
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What

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See it

bright shoal
dusky cradle
bright shoal
#

dv and u

dusky cradle
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U and dv?

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U and du?

bright shoal
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Bro

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By parts

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u integrate dv

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And do the derivative of u

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,w define by parts

grand pondBOT
odd lagoon
#

wolfram alpha letdown

bright shoal
#

Lol

dusky cradle
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You are confusing me at these steps u and du

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And dv

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Let's back to it again

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And i know how the integrating by parts

bright shoal
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Okom

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@dusky cradle

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See imma tell simply

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Integrate the 1/t^4 and stuff

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And differentiate the 1/t

dusky cradle
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1/(1-1/t^3) is V

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In your way right

bright shoal
#

Integrate it

feral sedge
bright shoal
#

Noo

feral sedge
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also "NO" is wrong

bright shoal
#

U should type in a formal way

feral sedge
#

so i am not going to tell you "no" when the answer is "yes"

bright shoal
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That sry for the inconvenience but I don't have sufficient info on this topic to help u

feral sedge
#

also you are listening to someone who does not know how to integrate 🤷‍♂️ so your choice here

bright shoal
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U talking bout me?

feral sedge
#

yes

bright shoal
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What

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How

dusky cradle
#

he is helping perfectly

bright shoal
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We are just using ibp

dusky cradle
#

Why you are saying such things sir?

bright shoal
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Bro if u wanna help then

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Why being toxic

dusky cradle
bright shoal
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Ok

dusky cradle
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Sir we are lacking with some powers

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(1-1/t^3)^3

bright shoal
#

See

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U know ibp

dusky cradle
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I guess that is why they are saying you wrong

bright shoal
#

Take this as your second function

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And 1/t as your first

dusky cradle
#

I got to go

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Sry

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We will try after some time

#

.close

midnight plankBOT
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viral dagger
#

Given that subset $A={a_1, a_2, a_3, \dots, a_{2001}} \subset \mathbb{N}$, let m be the ammount of subsets of $A$ that has $3$ elements ${a_i, a_j, a_k}$ where $1\leq i < j < k \leq 2001$, such that $a_j=a_i+1$ and $a_k=a_j+1$, for every possibility of set $A$, what is the highest value of m?

viral dagger
#

im not sure if i translated this correctly, but i gave it my best shot

grand pondBOT
#

Skill_Issue

visual tiger
#

!status

midnight plankBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
viral dagger
#

1

visual tiger
#

Alr

#

So the first hint I would give you

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Is that integers a,b,c such that b = a+1 and c=b+1 have a name...

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(If you write them all in terms of a you will maybe see better)

viral dagger
#

like their ordered?

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a, a+1, a+2

visual tiger
#

More than just ordered

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Consecutive

viral dagger
#

wait, would the max be 1,2,3,4,...,2001

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so 1999?

visual tiger
#

Yeah

viral dagger
#

bruh ok lmao

#

the hard part was understanding it

#

ty

#

.close

midnight plankBOT
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feral barn
midnight plankBOT
modern sapphire
#

The equivalent way of writing AF = BG is OF = OG

#

so it would be great if you could prove the second statement instead

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try to create new triangles with one having OF as a side and other having OG as its side

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and prove they are congruent

midnight plankBOT
#

@feral barn Has your question been resolved?

midnight plankBOT
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midnight plankBOT
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midnight plankBOT
subtle zinc
#

1:2 isn't a number

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it is simply an idea, however you may also treat it like a number

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this is just a definition thing, not worth worrying about

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no it's never true

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let's say alice and bob both have apples in the ratio 1:2

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that means for every apple alice has, bob has 2 apples

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so bob has twice as many apples as alice

midnight plankBOT
#

@last slate Has your question been resolved?

midnight plankBOT
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dusky cradle
#

|ax|+|by|=1 it will draw a square always?

midnight plankBOT
dusky cradle
#

Is there any rhombus possible?

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Square is special case of rhombus when all amgles 90°

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So only case?

viral dagger
#

didnt you post this question before

dusky cradle
#

Yes I posted but i didn't get my desried answer properly

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It will be always a square?

dreamy lichen
#

rhombus would be if if a != b I think

dusky cradle
viral dagger
#

a=/=b

chilly cobalt
#

a is not equal to

viral dagger
#

$a\neq b$

grand pondBOT
#

Skill_Issue

dreamy lichen
#

a doesnt equal b

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this

dusky cradle
#

|2x|+|3y|=1

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It will be a rhombus right by your condition?

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Yes/no?

dreamy lichen
dusky cradle
#

Sides will be same

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But angles

dreamy lichen
#

this is graph of |2x| + |3y| = 1

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looks like a rhombus

dreamy lichen
dreamy lichen
#

so rhombus

dusky cradle
#

(0,1/2)(-1/2,0)(0,1/3)(0,-1/3)

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y2-y1/x2-x1

viral dagger
#

by the way, you can use a graphing calculator and experiment with it

dusky cradle
#

That is why i am here there is no calculator who can give about angles

viral dagger
dreamy lichen
viral dagger
#

you can calculate it yourself with trig

dusky cradle
viral dagger
dusky cradle
viral dagger
dusky cradle
#

I only know is slope formula

viral dagger
#

you said you used a graphing calculator 😭

dusky cradle
#

And i used it and i got angles 90°@dreamy lichen

dusky cradle
dreamy lichen
#

let's try it here

dusky cradle
#

(1/3/-1/2)=-2/3

dreamy lichen
#

so the slope is (1/3) / (1/2)

dreamy lichen
dusky cradle
#

Of course

dreamy lichen
#

2/3 and -2/3, depending on which line we take

dusky cradle
#

Aren't m1m2=-1 here?

dreamy lichen
#

no

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,calc (2/3) * (-2/3)

grand pondBOT
#

Result:

-0.44444444444444
dreamy lichen
#

not perpendicular

dusky cradle
#

Let me check another slope

dreamy lichen
#

in this pic there is no other slope

dusky cradle
#

I got 3/2

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So

dreamy lichen
#

parallel lines have same slope

dusky cradle
#

Wait let me check

dreamy lichen
#

the top right and down left have -2/3

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the top left and down right have 2/3

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Btw to calculate the exact angle, we can calculate angle of the bottom-right line relative to x axis

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,w arctan(2/3)

grand pondBOT
dreamy lichen
#

,w arctan(2/3) to deg

grand pondBOT
dreamy lichen
#

that gave us the blue angle

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note that blue = green

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and yellow = 2*green

#

so ,calc 2*33.69

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,calc 2*33.69

grand pondBOT
#

Result:

67.38
dreamy lichen
#

this is the yellow angle

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orange + blue = 90

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so orange = 90-blue

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and 2*orange = purple

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,calc 90 - 33.69

grand pondBOT
#

Result:

56.31
dreamy lichen
#

,calc 56.31*2

grand pondBOT
#

Result:

112.62
dreamy lichen
#

and this is the purple angle

#

the rhombus has angles 67.38 and 112.62

dusky cradle
#

Thanku very much for solve in detail

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Let me understand it slowly

dreamy lichen
#

sure, if you dont undestand some step, just ask

midnight plankBOT
#

@dusky cradle Has your question been resolved?

#
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midnight plankBOT
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last slate
#

in this book it says the monotonic law holds for addition of integers

last slate
#

it says
monotonic law - from a < b it follows that a + b < b + c

#

is this a misprint

#

associative law : (a + b) + c = a + (b + c)

#

monotonic law : from a < b it follows that a + b < b + c

#

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last slate
#

.reopen

midnight plankBOT
#

last slate
#

can someone explain please

bright shoal
#

Ok

bright shoal
#

!status

midnight plankBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
last slate
#

I dont know where to begin

bright shoal
#

Ok

#

1.Commutative law

#

It says that if there are two numbers a and b

#

And if we add a and b keeping anyone as the first number

#

The addition is equal

#

like

#

a+b=b+a

last slate
#

yes

bright shoal
#

You know both the laws right?

last slate
#

yeah

bright shoal
#

You are mainly asking for the monotonic law

last slate
#

i dont know monotonic

bright shoal
#

Ok we see

#

It is a misprint

#

It should be

#

a+c<b+c

#

Given if a<b

last slate
#

okay i was like confused

bright shoal
#

Okay

last slate
#

is this a bad book then

bright shoal
#

Now is your doubt resolved

last slate
#

should i write a bad review on amazon

bright shoal
#

If yes then

#

!done

midnight plankBOT
#

If you are done with this channel, please mark your problem as solved by typing .close

last slate
#

thank you

#

.close

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bright shoal
#

Welcome

last slate
#

thanks a ton

bright shoal
#

Np

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dense arch
#

i'm not stuck but somewhat confused as to what to do here, since r2,r3,r4 are all similar

midnight plankBOT
#

@dense arch Has your question been resolved?

dense arch
#

<@&286206848099549185>

dense arch
#

after going through RREF, the 2 rows obtained do not correspond with the answer

#

nvm got it

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rich plaza
midnight plankBOT
rich plaza
#

So they give us the 55%, would I put that in the bottom right box as .55

#

and then for the other two boxes I dont really know what to do

#

Like since its percentages, I was thinking that maybe u have to subtract 100-55 and that answer goes in the other 2 boxes or the top right one

#

or smth like that

#

idk tho

#

I've never done a matrix with percentages

#

or just a matrix like this

#

<@&286206848099549185>

#

<@&286206848099549185>

lean spade
#

Assuming that there's a 100% chance a customer will buy some sort of item during their visit, and that you only buy either a food item or a non food item, then I believe you can think of the first column of the matrix as representing the "probability vector" of a person who purchased a food item originally

fathom knoll
#

can you first tell what the NN entry should be?

lean spade
#

so the top left would be 0.6 and the bottom left would be 0.4

rich plaza
lean spade
rich plaza
fathom knoll
lean spade
#

well .45 at the top

rich plaza
#

yes

fathom knoll
#

now it depends on whether the rows represent the first time they bought or the columns

#

but if the rows do

#

the the rows need to sum to 1

#

so you can solve for the other 2

rich plaza
#

how do I know if the rows are the first time or the columns r

rich plaza
#

so for the first row I would add .6 and .45

#

and the second one i would do .4 and .55

#

but they dont add up to 1

fathom knoll
#

no no

#

I think maudran is doing it as columsn instead of rows

rich plaza
#

oh kk

lean spade
#

since it's standard to multipy vectors to the right of matrices

rich plaza
#

so the columns would be the first time?

lean spade
rich plaza
#

ohh

lean spade
#

but maybe either way is acceptable

rich plaza
#

so like if I chose the row f and column n block

#

the top right one

#

I would say that they bought a non food item the first time and bought a food item the second time

#

and thats 45% of them

#

How would I do this>

#

*?

#

do I just plug in the same matrix twice, multiple them

#

and then thats my answer?

lean spade
#

yeah but you'd need to specify which entry corresponds to the probability they're asking for

rich plaza
#

oh ok

lean spade
rich plaza
#

so would that be the top left box then?

lean spade
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lean spade
#

np

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twin crow
#

i was solving this problem where i have to prove RHS = LHS :

cos(2pi/7) + cos(4pi/7) + cos(8pi/7) = -1/2

but then i gave up on solving and checked the solution where they just multiplied and divided by 2sin(pi/7) and used product formula to expand.

my question is why would i even think of multiplying and dividing by 2sin(pi/7)??? how can someone think of approaching the problem this way? like what is the intuition behind multiplying and dividing by 2sin(pi/7)?

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visual comet
#

Can some pls check

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#

@visual comet Has your question been resolved?

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@visual comet Has your question been resolved?

small jasper
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rancid kestrel
#

how would i prove this

midnight plankBOT
rancid kestrel
hard shard
#

SAS

rancid kestrel
#

how would i prove oc and ob congruent

feral sedge
rancid kestrel
#

how do you know

visual tiger
#

by definition, points on the circle are which distance away from O?

rancid kestrel
#

yeah but what if they just are really close to the circle but theyre not actually on it

#

if it was just that i wouldve already solved it

#

is there no other method to prove the triangles congruent

visual tiger
#

I thought the drawing was obvious

rancid kestrel
#

what id the point isnt actually on the circlew

visual tiger
#

"what if A isn't actually on the circle"

rancid kestrel
#

in class sometimes they say u cant assume its on the circle

visual tiger
rancid kestrel
#

idfk

visual tiger
#

well I know

#

it's to tell you that A B C are all on it

rancid kestrel
#

alright

#

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digital crag
midnight plankBOT
digital crag
#

Why is this the graph for the parametric equation?

elder fulcrum
#

The graph is y with respect to x

#

e^t is always positive

#

Express y in terms of the x here

#

How do u say e^2t in terms of e^t

#

?

digital crag
#

is that like eliminating the parameter

elder fulcrum
#

Yes you can say that

digital crag
#

so y= e^2x?

elder fulcrum
#

But more than "eliminate" you can rather say you are expressing one variable in terms of another

elder fulcrum
#

What is x?

#

x is e^t

#

And y is e^2t

#

So u want to express y in terms of x

#

It's like you know a foot is how many cm, and yard is how many cm, so now you want to "eliminate" the cms to express how many feet is a yard

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#

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twilit field
midnight plankBOT
twilit field
#

let $(a,b) \in (\mathbb{R} - \mathbb{Z}) \times \mathbb{N}$. It then follows , from definition, that $a \in (\mathbb{R} - \mathbb{Z}) \implies a \in \mathbb{R}, b \in \mathbb{N}. $ so we have $(a,b) \in \mathbb{R - Z} \times \mathbb{N}.$ However $ a\notin \mathbb{Z}$

grand pondBOT
#

(why am i here )= idk

twilit field
#

This is my working so far?

#

Is it fine until now?

#

So what we essentially want to do is remove all points with integral abscissa

#

Which is what the operation on the right hand side achieves

#

but is this possible using set theory too?

#

(Like can I construct a proof using set theory ?

modern sapphire
#

Yeah, distribution works here too

twilit field
#

I know

#

but don't I have to prove that?

#

or is that an Axiom in set theory ?

#

yes/no please

modern sapphire
#

Well when you ask it like that, I remeber distributive law applied to only intersections and unions

twilit field
#

I mean we maybe could derive it using propositional logic

hard shard
#

do you think the statement is true or false?

twilit field
#

true

#

I mean via some calculations, I got false, but p sure that's wrong

prime hornet
#

well, if you think it's true you'll need to show equality of sets, which I think you've started to do but got stuck?

twilit field
#

Yes, pretty much

prime hornet
#

right, okay

#

so you let (a,b) \in (R \setminus Z) \times N, good

twilit field
#

and that imples a \in R \setminus Z

#

and b \in N

prime hornet
#

correct

#

so now tell me, is (a,b) \in (R x N)?

twilit field
#

Yes, I got that too

prime hornet
#

okay, good

#

is (a,b) \in (Z x N)?

twilit field
#

It Is NOT , but how do I show that

prime hornet
#

recall that a \in R \setminus Z

#

this means that a \notin Z

twilit field
#

😭 , thought of that, didn't know how to formally express it

#

Thanks a lot though!

prime hornet
#

there is nothing to express wdym

twilit field
#

I meant I told the exact same thing in words

prime hornet
#

"since a \in R \setminus Z, a \notin Z, so (a,b) \notin (Z x N)"

twilit field
#

Thanks!

#

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prime hornet
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past pulsar
bright shoal
#

!nopdf

midnight plankBOT
#

Please post images (such as PNGs or JPGs) of the question rather than other filetypes such as PDFs which have to be downloaded. Non-image downloads can potentially contain viruses or other security risks.

past pulsar
#

Everything makes sense other than the d(u) < d(y) part

#

<@&286206848099549185>

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#

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@past pulsar Has your question been resolved?

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@past pulsar Has your question been resolved?

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mighty zodiac
#

Can anyone take photo and send solution for integration of x sin inverse x?

hard shard
#

it takes time

pearl hull
#

It takes time

quiet hinge
#

It does take time indeed

slender walrus
#

searching will be faster than someone doing it and sending it

#

because they most likely won't

#

if however you want people to guide you, they'll be more than happy to help

mighty zodiac
#

.close

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#
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quiet hinge
#

Yeah, you can send your attempt at a solution or something of that sort

pearl hull
#

lol

slender walrus
#

or less happy now

clear pumice
pearl hull
quiet hinge
#

Also even if you claim your own help channel, no, people wont solve questions for you

slender walrus
#

and post embeded pics instead of files

clear pumice
#

ok

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radiant vector
midnight plankBOT
radiant vector
#

I checked answers and the 2/5 being probabilty of B was instead replaced with probabilty of chem if physics and I dont get why'

real pivot
radiant vector
#

Yep

#

but I dont understand why it would be used

real pivot
#

alright so in the second image you are given

P(A), P(B), P(B | A) respectively

radiant vector
#

yh

real pivot
#

P(B|A) = P(A n B)/P(A)

#

now solve for P(A n B)

#

and you will see why they plugged in P(B | A) instead of P(B)

radiant vector
#

alr ill try that

#

so do in the future how would Ik which one to use

real pivot
#

wdym which one

radiant vector
#

like between p(B) and P(B|A)

real pivot
#

well the third case in the second image is clearly a conditional prob case so you know that you are given P(B | A) and P(A) (case 1) so all you have to do is multiply those two

#

P(B | A)P(A) = P(A n B)
or
P(A | B)P(B) = P(A n B)

radiant vector
#

ohh

real pivot
#

ye so if they instead gave u the prob of students studying chemistry given they chose to study physics (P(A | B)) then you would have multiplied P(B)

midnight plankBOT
#

@radiant vector Has your question been resolved?

radiant vector
#

.close

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twilit field
midnight plankBOT
twilit field
#

The definition of union states that a given element belongs to the union if it belongs to any of the sets. On the other hand the definition of intersection states that an element belongs to the intersection if and only if it belongs to all the sets. The only way for this to be true is if all the sets have the same elements.

#

would this suffice as a proof?

visual tiger
#

as always you need a mathematical proof

unique stream
#

"The only way for this to be true is if all sets have the same elements." Prove that directly

visual tiger
#

you have intuited the result, you should formally prove it

twilit field
#

OK.

zealous schooner
#

this is basically just a fancy way of saying "it's true because obviously"

twilit field
#

So I basically have to prove that they are subsets of one another

zealous schooner
#

I think if you write your statement more mathematically then it's better

#

let $S=\bigcup_{

twilit field
#

By Definition $x\in \bigcap_{\alpha \in I} A_{\alpha} \iff x\in A_i \forall i\in I $
on the other hand $x\in \bigcup_{\alpha \in I} if x\in A_i \text{ for some } i\in I$.
So thus if $x\in \bigcap A_{\alpha}$ it's also in $\bigcup A_{\alpha}$.
\
so $\bigcap A_{\alpha} \subseteq \bigcup A_{\alpha}$

#

would be the proof in one direction

zealous schooner
#

\iff

twilit field
#

ah

grand pondBOT
#

(why am i here )= idk

visual tiger
#

we went through the proof earlier

twilit field
#

I'm taking that to be obvious because that's mentioned in my book

visual tiger
#

nothing is obvious to the one that's going to correct you

zealous schooner
#

if I is empty then both sides are empty sets

#

right?

visual tiger
#

intersection would be "for every i in empty set..."

#

which is always true

#

so it would be the universe set in which you're in

zealous schooner
#

what??

twilit field
#

OK. Added that

zealous schooner
#

that just broke my brain

visual tiger
zealous schooner
#

sure!

zealous schooner
grand pondBOT
#

kheerii

zealous schooner
#

something like this

twilit field
#

hm

#

This doesn't tell us anything about $A_{\alpha}$ though

grand pondBOT
#

(why am i here )= idk

zealous schooner
#

I wrote the intersection part of it

#

what happens with the union part?

twilit field
#

I think I have another idea

#

$x\in \bigcap_{\alpha \in I} A_{\alpha} \implies x\in A_{\alpha} \forall i \in I$

grand pondBOT
#

(why am i here )= idk

twilit field
#

Now $x \in \bigcup_{\alpha \in I} \implies x \in A_{\alpha} \text{ for some } i \in I$

grand pondBOT
#

(why am i here )= idk

zealous schooner
#

yeah this is basically what I wrote

twilit field
#

oops

#

sorry

#

now if they are equal

#

that is $\bigcap_{\alpha \in I} A{\alpha} = \bigcup_{\alpha \in I} A_{\alpha}$

grand pondBOT
#

(why am i here )= idk

visual tiger
#

wait what are you setting out to prove

#

aren't you trying to prove that A_alpha are all equal to each other?

twilit field
#

That all $A_{\alpha}$ are equal

grand pondBOT
#

(why am i here )= idk

visual tiger
#

ok

twilit field
#

yeah, going to argue that now

visual tiger
#

so double inclusion

#

just prove A_alpha_1 = A_alpha_2

zealous schooner
exotic pelican
#

try showing that $\bigcap_{\alpha \in I} A_{\alpha} \subseteq A_{\beta}$ and $A_{\beta} \subseteq \bigcup_{\alpha \in I} A_{\alpha}$ for all indices $\beta$

grand pondBOT
twilit field
#

now for a certain $x$ to belong to the union, it has to belong to atleast one of the sets. But if the same is true for the intersection, it must belong to all the sets. As this is true for all x, the sets are equal

grand pondBOT
#

(why am i here )= idk

twilit field
#

is this fine?

pure shore
# twilit field is this fine?

I would recommend that you start with a specific statement you wanna prove, write it down in mathematical terms then prove it.

zealous schooner
#

you want to prove $$x\in A_i\iff x\in A_j\ \forall\ i,j\in I$$

grand pondBOT
#

kheerii

pure shore
#

Simplest way to state it in my opinion would look like this:
for any two indicies $\alpha$ and $\beta$ where $\alpha \neq \beta$, $A_{\alpha} = A_{\beta}$

grand pondBOT
#

Mohamed Mohsen

twilit field
#

mhm

twilit field
zealous schooner
#

i mean if you just want an insight as to why this is true then your thing is good enough

visual tiger
#

For you proving = explaining in words

#

Problem is that proofs follow a very particular "syntax"

#

Such that explaining in words or visualising something isn't gonna fly

twilit field
#

I could try writing it mathematically, I guess?

pure shore
twilit field
#

Got it

zealous schooner
#

do 2 year old babies even know how to read?

twilit field
#

I did , If I remember right

pure shore
zealous schooner
pure shore
#

it clearly meant make it simple and clear

pure shore
zealous schooner
#

i am the most unserious person you'll meet

pure shore
#

read ya wrong

zealous schooner
twilit field
#

OK. So $x\in \bigcup A_{\alpha} \implies x\in A_{\alpha}$ for some $\alpha \in I$. However, we already know that $x \in \bigcap A_{\alpha}$ which means that $\bigcup \subseteq \bigcap $ in this case

jagged saffron
#

[Fyi its not inherently the fact that your "proof" is written in words that makes it not a proof (see hlounge discussion). It's that your argument written in words is missing logical steps]

twilit field
#

is this better?

grand pondBOT
#

(why am i here )= idk

visual tiger
twilit field
#

I think this is still missing a few steps

grand pondBOT
#

rafilou2003

twilit field
#

Oops

#

right

visual tiger
#

I think you would gain to write out exactly what you wanna prove at the end of your proof

#

something like:

pure shore
visual tiger
#

We suppose (Conditions)....$\$
Then... $\$
But... $\$
$(...) \$
thus (Goal)

grand pondBOT
#

rafilou2003

twilit field
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I guess what I'm trying to say that as x is in the union, it must belong to atleast one of the sets.

visual tiger
last slate
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the proof is simple, just apply aesop tactic. Just kidding

twilit field
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But as this same x is in the intersection, it must belong to all the sets

visual tiger
twilit field
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if a given x( An arbitrary element) belongs to all the sets, the sets must be equal

visual tiger
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?

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the x in the intersection are like that

twilit field
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yes.

visual tiger
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and btw do we need the intersection to be non-empty for "the sets must be equal" to be true?

twilit field
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But all the elements in the intersection, are also in the union

visual tiger
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sure

twilit field
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and for an element to be in the union it needs to belong to atleast one of the sets

visual tiger
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but I still don't think you understand what you want

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what was the "thing" you wanted to prove

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the sets must be equal right?

twilit field
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yup

visual tiger
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what are you given EXACTLY?

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intersection = union

twilit field
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yes

visual tiger
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so our goal

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can you write it mathematically?

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so at least we know where we're supposed to go in the mathematical proof

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just write the goal for now

twilit field
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The goal is to prove that $A_i = A_j $ for all $i,j \in I$

visual tiger
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for some?

zealous schooner
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for ALL

grand pondBOT
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(why am i here )= idk

visual tiger
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alright

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how do we prove a "forall" statement

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how does the proof start?

twilit field
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let $x$ be an arbitrary element in $A_i$

visual tiger
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?

grand pondBOT
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(why am i here )= idk

visual tiger
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there's a step before "Ai = Aj"

zealous schooner
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what is A_i?

twilit field
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A_i is a set

visual tiger
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any set?

twilit field
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a set where i \in J

zealous schooner
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an arbitrary set

zealous schooner
twilit field
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I see, okay.

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so $A_i$ is an arbitrary set such that $i \in I$

grand pondBOT
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(why am i here )= idk

visual tiger
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ok great

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so you need to introduce i first

pure shore
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I think it would be enough to state that i is arbitrary though, but that's just my opinion

visual tiger
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before going in the Ai=Aj territory

zealous schooner
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technically you need A_i and A_j both to prove that they're equal

visual tiger
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so same with j

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A forall statement proof starts with "Let ... be ..."

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"forall i,j in I ..."

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so the proof start with

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"let i,j \in I"

twilit field
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Let $i,j \in I $ where both are arbitrary

visual tiger
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drop " A_i, A_j be arbitrary sets such that"

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they come for free with your "i,j in I" package

twilit field
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Just this?

visual tiger
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no like seriously drop everything in the quotes

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drop "A_i, A_j be sets such that"

zealous schooner
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let A_i A_j where i,j in I

twilit field
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Let $i,j \in I$ where both are arbitrary

grand pondBOT
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(why am i here )= idk

visual tiger
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yeah

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"where both are arbitrary" is useless too

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since that's what "Let" does

twilit field
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now we know that $x\in \bigcap$

grand pondBOT
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(why am i here )= idk

visual tiger
twilit field
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so $x \in A_i, A_j$

grand pondBOT
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(why am i here )= idk

twilit field
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where $x \in \bigcap$

grand pondBOT
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(why am i here )= idk

visual tiger
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how is x defined here?

twilit field
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x is an element of the intersection

visual tiger
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ok

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problem

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how does this help us prove Ai = Aj

twilit field
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As I've said before $x \in \bigcup$

grand pondBOT
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(why am i here )= idk

twilit field
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so it belongs to either A_i or A_j

zealous schooner
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why?

twilit field
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oh right

visual tiger
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couldn't it belong to some other rando A_k

twilit field
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it could yeah

visual tiger
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yeah so

twilit field
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well, x is an arbitrary elemnt

visual tiger
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never proved a set equality before?

twilit field
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Not in 2 years or so

visual tiger
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ok well do you remember double inclusion at least?

twilit field
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yeah A \subseteq B

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and B \subseteq A

visual tiger
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to prove X = Y, you show every x is in Y and every y is in X

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great

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so let's do that

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so show A_i \subseteq A_j

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and then vice versa will be easy

twilit field
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But why is saying that $x\in A_i$ and $x\in A_j$ means that $A_i=A_j$ where both are arbitrary worng ?

grand pondBOT
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(why am i here )= idk

visual tiger
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so what?

twilit field
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we now repeat this for all their elements

visual tiger
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"all their elements"

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so where do you pick the x from

twilit field
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$x_1 from A_i$

grand pondBOT
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(why am i here )= idk

twilit field
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then $x_2$ from A_i

grand pondBOT
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(why am i here )= idk
Compile Error! Click the errors reaction for more information.
(You may edit your message to recompile.)

twilit field
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and so on until $x_n$ from $A_i$

grand pondBOT
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(why am i here )= idk

twilit field
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where $i \in I$

grand pondBOT
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(why am i here )= idk

visual tiger
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so you take a finite amount of x, and only from Ai?

twilit field
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And we then repeat this process for $A_j$

grand pondBOT
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(why am i here )= idk

visual tiger
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ok, just something to tell you

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once you took an ARBITRARY guy from the first set

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and shown it's in the other set

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it's done

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there's no "repeating the process"

twilit field
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I see

visual tiger
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showing it always works once is gonna have the same result as showing it always works multiple times

twilit field
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Okay, so now I prove that they are subsets of one another

visual tiger
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so as you said

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you pick x from Ai

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and you show it's in both

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and then same for Aj