#help-49
1 messages · Page 37 of 1
Its like Stanley’s parable writing
so 127 filled circles that are 3/10 like 127.3 circles
no, 127 circles that are entirely filled in, not just 3/10 filled in
ikkk i said 127.3 mini whole circles
hallo
3 whole apples , why did u draw fractions in them̄? thats confusing
i got ghosted
<@&286206848099549185>
this true?
ikkk i said 127.3 mini whole circles
have you ever seen 0.3 whole people?
but thats what it mwans tho right??
no
i wouldnt say that 0.3 of a person is a whole person
like therr are 127.3 circles?
tho yea i cant imagine that too
where?
they mean they have 127 circles and 0.368 of a 1 cricle
see this is what i needed to know
both of them were yappon @wary thorn
lmao
Without additional context, it's challenging to determine the precise meaning of "both of them were yappon" when communicated by 🤫. However, "yappon" could potentially be a term used to describe a certain characteristic or behavior exhibited by the two individuals being referred to.
😎
yapper
gosh what the hell happens on this channel
this is where all wisdom ultimately resides
❤️
better hide this channel from goverment then
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hey, just wondering where I went wrong on this question and lost 2 points
your graph doesn't have y=2x-4
i don't think you got the correct answer either
but the question specifically wanted you to solve it graphically
although in solving algebraically you could have done 0 = x(x-2) and the solutions are obvious
oh shit i forgot to draw the whole other line
💀
what does it mean graphically, only ever did it with algebra
graph both equations and look at where they intersect
that's how the algebraic way works too
redoing it now i dont understand how i even got half points lol
it's good you realize, your teacher is generous for giving you more than 1 hahah
my mistake here, i think you graphed your final eq (x-1)^2 - 1 = 0
you're supposed to graph the two original equations
yeah i’m seeing that now
thanks for the help
i’ll send a pic of the changed answer
is this more accurate?
the line became a little too steep at x = 1 to 2
i think the pt of intersection should be at (2, 0)
so instead of going from y = -2 to 1 here, it's supposed to be -2 to 0
yeah the line is drawn pretty bad lol
i have a question about another problem if your intrested
send it
how would I solve for k?
i just assumed I could use the vertex as my x intercept and plugged it in to solve for k
but i assume i needed to find something else?
solving x^2 - 5x + 3 - k = 0 will give you the points of intersection, right?
yeah
if you have a line and a parabola there are only three cases for intersection
it's either they don't intersect
or they intersect twice
or only once
in what case will they intersect only once
when the line is tangent
so what you've established is that x^2 - 5x + 3 - k = 0 must have only one solution
yes
b^2 - 4ac
that must be equal to...?
0
yeah thats it
ah check your algebra when you equated the two y's
okay
wait ... there's a lapse in my judgment. i think your solution also works
ok, i just realized, the logic here is correct too
because if any other part of the parabola was the x-intercept, then there would have been 2, necessitating that the eqn have two solutions
the vertex being the unique x-intercept means that it is the only root for the expression
so if im not mistaken your solution is also right!!! you just made a mistake in the first part
yeah i’m thinking the same thing, I think he wanted me to solve it with the b^2 - 4ac
i was on vacation and missed a lot of class time and they only did it that way and i assumed they just plugged in an x intercept
anyways i need to go to bed, thanks for all your help today 🙂
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.
@last slate Has your question been resolved?
I would think that would work out, though I say that just by looking at it 
It should give you a couple of equations to work with, which I think should be decent to get enough information from 
Yea was about to say, just noticed that at the same time 
Yea x can't be zero so you have to have c = 0, you're doing well, so otherwise both A and B must be diagonal
Yep, looks good, A is like that and you can then relate B to A as you've done, pleased with that I think 
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how do i determine the amount of regions in a 7 set venn diagram?
this is the thing, but as you can see, not particularly helpful to count manually
combinations permutations?
yeah of course
yeah
ok so we need all the cases for how many overlaps there are
do you konw what the cases are
i think its a bit hard to write them all out manually, but if we represent the existence of a region in an area by a binary string of length 7 i suppose you have 2^7 possible states of whether a particular region is occupying that place 
so 100 0100 means the 3rd circle and the 7th are intersecting solely
wait oh
i guess thats it then?
its just 128 regions?
i guess 0 is not a particular region to consider so we can omit that
makes sense
aight thanks
.cl9se
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on a circle race track there are 2 cars that are moving. they meet each other every 40 mins when they go the same way and they meet in 10 mins when thy move the oppisete way. what time would it take for each car to go around the whole track
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I noticed u could tan both sides as long as u remove the tan later. is this always applicable and does it work with other trig functions?
as stated the formula is valid with some constraint
here for example xy<1
if the case is of xy>1, then you need to add/subtract some multiples of pi
why not? isnt tan(arctan(x))=x
is arctan(x) domain small?
yeah the other way around doesn't work
yep, inverse trig gets ugly at some point
from this step to the screenshot, did they just arctan both sides?
tan(arctan(a)+arctan(b))=(a+b)/(1-ab)
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i tried using the sine rule, finding the distance between the two particles and try to use the forces of mg and repulsion to find the force in total but none of it works
i cant use the force equation using q1q2/r^2 because i dont know the quantity of charge
suds i remember you helped me once with physics
have you made any fbd for this?
@median ridge
well the main concept here is that theyre gonna subtend same angle from the normal
like 7 degrees
well u gotta be quick i have to leave for my classes
@median ridge Has your question been resolved?
basically, it says "The force acting on each sphere" but it actually just means the repulsive force
i was solving for the total force like someone who can actually read
and the answer is also wrong because it should be x 10^-3 for the mass because they give it in grams
so this is a stupid question and i won
but its still stupid
.close
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yea you won nice lol
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how to make it
does the numerator limit looks familiar to you
@sharp shadow Has your question been resolved?
not at all
well, what have you tried so far?
i just know lim x->inf (1+1/x)^x=e
but you cant do this question in the same
its wrong
needy help
<@&286206848099549185>
??
just try evaluating only the numerator
what would you get?
well 1/roote
!nosols
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
@sharp shadow
well i only see the e part
wtf
(e/e)^∞is not exit
its obviously
the answer is e^(-1/2) if i didnt remember wrong
and what is e/e?
how about substitue 0 in there
@sharp shadow ???
((1+x)^1/x)^1/x / x root e
(1+x)^1/x^2 / x root e
i think you have to rewrite the limit
!nogpt
Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).
the fraction is e/e
and what does it evaluate to
the fraction
or similar AI tools
its a commom lim
limx-> 0 = e ^ ln(x+1) / x^2 - 1/x
i forget how to get it
wrong ping
my man im just asking what e/e equals
try lim x->0=e^(ln(x+1)/x^2 - 1/x)
e is a normal num
in other words, this is an 1^infty limit
do you know what you usually do for this limit?
you have to get e ^ .... i think
Equivalent substitution
im not asking you
yes
its pleasure to discuss each others
but yes, like samach said, you bring the whole thing to exponent
welcome to talk
now do you know why bring everything to the exponent?
anyone could get the right answers?
you probably have to get x on it own to do this
itsconvenientto compute。i guess
because logarithms
Is there a specific deduction?
$\ln a^x = x\ln a$
فطر
this sets up very nicely for l'hopital
you are right
obviously
Is there a specific deduction?
what do you mean
!noans
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i will turn it into ((1+x)^1/x)^1/x. / x root e first
haha,sorry
then e^ln() both sides
then you get (1+x)^(1/x^2). / x root e
sure
this way you can bring the 1/x down
could u write it in paper,thx
im no the english learner
i just know the math mark
u r all nice guy
you should do the work yourself
hahah
you are the learner, im simply guiding you where to go
i have no idea
read my messages again
sure
$A=\lim_{x\to0}\left(\frac{(1+x)^{\frac1x}}e\right)^{\frac1x}$
فطر
now e^ln() both sides
whwt then?
its cool
what then
i guess the answer is 1
bec ln(x+1)~x in 0 point
but the right answer is
and you turn x to 0
why its this answer instead of 1
Taylor unfolded?
this is from the sin(x)=x-(x^n/n!)
i havent learn exponencial before
just trying hardest from what i haev already learned
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???
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how to prove that xy=z^2 plots an infinite elliptic cone?
I'm trying to find some geometric interpretation to at least make it more intuitive for myself to understand, but that's proving to be quite flimsy haha
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@slim nova Has your question been resolved?
@slim nova Has your question been resolved?
this shape? you can sort of see it with special cases, like x or y 0 makes z 0 so you get an X-shape in the z=0 plane, and x=y=z or -z gives another X-shape at an angle and you just draw a curved surface around those lines
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Hi help
ummmm, you need to find the values of each of the letters
do you know how to do b?
No 😭
can there be multiple solutions for each of the letter?
then we can find sin^2(x) right
then we can use sin^2(x)+cos^2(x)=1
Omg
So cos = sqrt(8)/3?
dawg
placement matters
oh
righ
i forgot
i was thinking sqrt(8/9)
but i see you simplified to sqrt(8)/3
i c
yes ur right
can't it also be - sqrt(8)/3?
[yea, they didn't give any quadrant info
I'm assuming you're meant to take it as first quadrant though, if they state that(?)]
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Hii how would i do 47 😭
Please don't occupy multiple help channels.
Oops
Quadrant info, finally 
The best thing to find first would most likely be tan(theta), there's a identity that links sec to tan directly...
Yep, but then you can rule one of those out!
Is it quadrant 4?
It's in quadrant 4 
YAY
[because that's where cos, and so sec, are positive, and here you know that sec is positive
]
cos and sec have the same sign 
Yep 
Would it be 36/25-1 = tan^2
Amd so tan = sqrt(11)/5
Hooray 😄
And so sin would be (6)sqrt(11)/25?
And csc would be [(25)sqrt(11)]/66
All good to me 
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i dont know how to attempt ii
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#14
I’m not sure what it means to find the compass heading for the plane
Does it mean the compass heading that she should go to make the plane go east again
?
Ping pls when someone helps
@silent sorrel Has your question been resolved?
?
I’m not sure of the meaning of the wording of this question
Number 14
compass heading huh
Does it mean that I need to find the angle that resets the plane back to east
Or just the resultant angle
Because I don’t know how to do this
But the resultant angle is very easy
the angle between the heading of your Aircraft and the Compass North.
i also dont really know what compass heading is
thats what i found on google
It says to find the compass heading that the plane should follow
Wait hold on I think I Joe
Know
so basically how many angles the plane should fly from north?
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Can anyone walk me through this question,i understood the second part after differentiating but my why question is if it has a postive point of maximum is it nessary that the minimum should also lie in the postive point i dont get the graph.
@civic iris Has your question been resolved?
<@&286206848099549185>
Because the dominant term is x^3, as you go more left the graph goes towards -infinity and when you go right the graph will go towards +infinity, if there is a maximum, then you know that immediately to the right the graph should be decreasing because that is how the max is defined. But you also know that in the long run that when you go towards the right you go towards infinity, so the graph has to turn around with a min to go back up.
hello
hi
that makes so much sense
ty so much
and for find if odd degree function is first coming -infinty or +infinty you just substitute values and check right?
It depends on the sign of the dominant term.
If it is positive, its as above, if it is negative it is flipped.
No problem happy to help!
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wat do restrictions Meanhere
they get rid of all the stuff that wouldn't make f one to one
in their example if you take the domain [-10,10]
then $f(-2) = (-2)^2 = 4 = 2^2 = f(2)$
chebyshev's infinite pee norm
so 4 (from the range) is coming from both -2 and 2 (from the domain)
and in particular, x^2 in the range comes from -x as well as x in the domain
when you restrict it to [0, 10]
x^2 can only come from x, it can't come from -x anymore
what does restrictioj mean
likw how does it limit
the domain
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Can someone state the series for this. I'm outta go crazy
Seems to be $\left { 1 + \left(-\frac{1}{3}\right)^n \right }_{n \geq 1}.$
lpieleanu
How did you get it so fast?
i noticed that the 1st, 3rd, 5th, etc. are slightly above 1 by a power of (1/3) and the 2nd, 4th, 6th, etc. are slightly below 1 by a power of (1/3)
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Can you prove that a function is surjective in discrete with a graph ?
depends on what you mean by graph
like if given a function x^2 and I graph that
no
but I could use a graph to prove that a function is injective right ?
no
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WHy are they choosing specifically 3 points to look for combination A to f(A), B to f(B) and C to f(C)?
i dont get how that is related to the statement
nvm i think drawing it out helped me visualize
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Im not understanding this paragraph
"w has direction u from v if w - v is a multiple of u"
if you are at v and want to go to w, you have to go in the direction of u
would it be possible to draw it out?
SO like this?
w-v is the blue line?
the arrowhead needs to be on the other end
@hexed talon Has your question been resolved?
like pointing towards the other side (towards the tip of w)?
yes
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no solution means the lines never intersect
these are linear so that means they have the same slope
yes but how can I get z
put the equations into y = mx + b form
well solve each equation for y and equate the slopes
I did that
I've got 1/(1/6.5) what i suspected to be wrong
wb this guys?
what did you get for y in both of these expressions?
they werent the same y
nvm I rechecked and I got 1/4 for z
and 4 for the slope of equation 2
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yo
i splited it in 2
If you did int f'/f, its wrong
du=2x+1 dx
i split the integral in 2
x^2+x+2 goes to x+1
its like integral of x + 2x is integral of x + integral of 2x
2x+1*
yes but you evaluated the first integral wrong
can u tell me why
you used a u substitution i presume
i tried to split them
did you do u=x^2+x+1?
The one I highlighted
for the first one i just split the integral in half
its like integral of x + 2x is integral of x + integral of 2x
$\int\frac{x}{x^2+x+1}\dd x$ cannot be split up any further
y0shi
i know that
yeah definitely not
i did that and i got 1/2 ln(3)
how?
that’s incorrect
if you differentiate that
you won’t get that integrand
since the derivative of the inside would be 2x+1
not 2x
you can’t simply just multiply by 2 here to compensate for that
my bad
so the 2 in the second integral
should be 1
no more 2
i got it now thank you
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for b
can it be
(5-3)^2 < (x-3)^2
as (x-3)^2 = f(x) anyway
and ik all squared values are <0 but wat does it mean by 0 being equal to a squared value?
like 0^2 =0
dis the only possible case anyway
yea
@wet wagon
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^
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im stuck on 28, and these are the formulas we can use
full question: “ write the first function in terms of the second”
@static salmon Has your question been resolved?
yea
would that just be the answer?
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new question, new channel- no idea what to do for 32 or 36
Use the trig identity, but divide it by sin^2
zhuh
It will take a while to write out
32, just expand, tan^2+1=sec^2 is the key
The one that he said times cos^2
how do you get to tan^2
sin and csc cancel out, and then the other 2 result in tan^2, so it becomes 1 + tan^2
u can do sec^2 as 1/cos^2
and then its sin^2 / cos^2
What are you stuck on on 32?
okay it’s like 10:30 pm and someone is knocking on my door
give me just a moment if i die tell my family
nvm we good
I kept looking past the bit where it said tan^2+1 was equal to sec^2
Ok im good with 32
with 36 I just have no idea where to go
Now multiply the entire thing by the reciprocal of the right side on 36
From the start, or from where i got?
Start
Any other questions?
According to my teacher we’re only allowed to change one side though
Thats annoying
tell me about it
Well, just combine the fractions of the left side first
this unit sucks it’s almost as bad as geometric proofs
Now any other questions
:/
🫡
Ngl I don’t understand how people struggle with these
i think it’s just like too much information to me to process
But a good tip is to convert them to their cos and sin forms
oh thanks!
okay so after getting to (sin^2+cos^2)/(co^2 x sin^2) where do i go from there?
What is the basic trig Identity
Btw for your “test” I choose someone random for Q10 and got that person
I’m also not sure what you mean by this
The one I mentioned earlier
Ashe cause I thought his name sounded cool lol
Idk those characters
I would have to reread it
did you close the tab bc i have it saved on my camera roll if needed
Lol I did the same answers but changed the “who I thought I would get” and got something different
who’d you get this time
Gillian
Lol its the only accurate thing
fair it’s really targeted at depressed gay children
anyway i think im gonna turn in
the math is not mathing and I want more than 6 hours of sleep tonight
In college you don’t have school on Fridays so I can stay up lol
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How do you do part c and I was wondering if I got part a correct
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help pls...
L
yes
what factors do the two terms have in common
3
so factor a 3 out
how
3(-12/3p^2q -9/3pq^2)
yeah just give him the answer
dont make him think
at that stage i didnt know how to do prime factorization
the easiest way is to continually divide out common factors
starting with 3 cause its obvious
then find the next comon factor
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Is this answer wrong ?
yes, its wrong
you summation represents
$$5.\overline{8}$$
yes
but you ignored that it only starts repeating after a few positions
actually, misrepresented what you did
wdym
what you did was actually
$$5 + \frac{8}{10} + \frac{8}{10^2} + \frac{8}{10^3} + \frac{8}{10^4}$$
which represents
$$5.8888$$
so I should've done 5.67 + 8/10... ?
no
ℝαμΩℕωⅤ
$$5.67\red{8}\overline{8}$$
what's the value of that red \red{8}?
ℝαμΩℕωⅤ
$5.67 + \what = 5.678$
ℝαμΩℕωⅤ
The answer it was looking for was a fraction
.008?
1/125?
what did you have before simplifying
its more convenient when doing the summation that way
Am I including the 5.67 ?
8/1000?
yes
that should be the first thing you'd be adding to the 5.67 and so on
instead of starting from 8/10
$5.67\overline{8} = 5.67 + \frac{8}{10^3} + \frac{8}{10^4} + \dots$
ℝαμΩℕωⅤ
and then do the infite summation and combine terms into a single fraction
are you required to do it this way?
Yes
so you're not allowed to use the
x = 5.678
100x = 567.8...
1000x = 5678.8...
etc?
probably could but im just going by the method my professor gave us
nah I wasn't. But its alright. I was just curious if I did the correct thing on my exam
clearly not. rip
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Limit of floor(sinx)
X tends to π/2
floor ?
Greatest integer function
Sin(pi/2) is 1 but the values of sinx are less than 1 near pi/2 so the limit of floor(sinx) at pi/2 would be 0
But why?
I meant it will be 0 or 1?
X tends to π/2
The value at that point is 1 but the limit is 0
you can try with graph as well
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do you have any other question?
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$\lim_{x\to\infty}\int_{-\infty}^{\infty}\frac{1}{1+|t^x|}dt$
The د
how can i approach this?
$\lim_{x \to \infty} t^x = 0$ for $t \in (-1, 1)$ , $\infty$ otherwise
b
you're helping me more than this guy lmao
but the real question is
if we can pull the limit operator inside the integrand
then we can use your hint
Apparently we can pull in the limit operator inside the integrand, if the convergence of the integrand is uniform
,, \norm{f_n - f}{\infty} =\sup{n \in \mathbb{R} } \abs{\frac{1}{1+\abs{t^n}} - 1}
hmm
@lament fox Has your question been resolved?
ahh ok so $\int_{-\infty}^{\infty}\lim_{x\to\infty}\frac{1}{1+|t^x|}dt$
The د
we can say $\int_{-\infty}^{-1}\lim_{x\to\infty}\frac{1}{1+|t^x|}dt$ + $\int_{-1}^{1}\lim_{x\to\infty}\frac{1}{1+|t^x|}dt$ + $\int_{1}^{\infty}\lim_{x\to\infty}\frac{1}{1+|t^x|}dt$
The د
You would have to prove first if the integrand converges uniformly
then you can pull the limit operator inside
but doesnt seem to be
only pointwise convergent
what does uniform convergence refer to?
because of it wouldn't be continous since for 0 < t < 1 f = 1, for t = 1/2 f = 1 and t > 1 is f = 0
thats why we are taking the limit though no?
if x is like 9999 it would be continuous
but like barely yk
depending on t you get different limit functions
yea
it should be uniformly convergent
yea
if you prove that additionally then you can pull in the limit operator and evaluate it like you did
𝔸dωn𝓲²s
We can do the proof for the first Integral together
ok sure
but I haven't been exposed to the notation you are using here
oh
can you tell me where you currently are math level wise
i know calc 2
oh
Is this all the information you got?
it wasn't a question i was given, just something i thought about
So that is your task?
Well we do that prove so you can justify pulling in the limit operator
But that doesnt seem calc 2
But that should be the same as
$$\lim_{x\to\infty}\int_{-\infty}^{\infty}\frac{1}{1+|t^x|}\dd t = \lim_{x\to\infty}2\int_{0}^{\infty}\frac{1}{1+t^x}\dd t$$
𝔸dωn𝓲²s
To make things easier
So we actually have 2 cases
or 3 with t = 1
,,\norm{f_x(t) - f(t)}{\infty} = \sup{t \in (1, \infty)} \abs{\frac{1}{1+t^x} - 0}
𝔸dωn𝓲²s
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Hi how to solve this limit without L'Hospital?
Use L'Hopital
What did I say in the question
your factorisation of the denominator is incorrect
whoops
try factorising again
To not use L'HOSPITAL
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Can someone verify my answers? Here is the question: Consider the region R, which is enclosed by the graphs of x=y^2+2y+3, x=3y+5, and the vertical line x=6.
a) Find the area of R
b) Region R is the base of a solid. For the solid, at each x, the cross-section of the solid perpendicular to the x-axis is represented by F(x)=1/(x+2). Find the volume of the solid.
c) Write an integral expression that gives the volume of the solid generated when R is rotated about the horizontal line y=2.
Graph of the lines below
a) 8/3
b) ln(2)
c) (see photo below)
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also about this i had just asked a question in another channel and i had closed it but then i immdiately opened this one so i think the server thought i was in two channels at once
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can someone help me
do you know how to find a general expression for the slope of a tangent of the given function
no but please give me answer and can u explain aftre this is due in 8 minutes
please
i beg
explain to me after
this is vey crucial
i cant give u the ans rn causelike
Is this a test?
i dont have a working space
thats y i wanted to explain\
if i explain it fast enough
can u do the working urself
okay so to find the slope
what do you normally do
like if i know the point on the function where i wanna draw my tangent
how do i find the slope for that point's tangent
just differentiate basically
now u need to find the maximum slope
you have an expression for the slope ( dy/dx)
let dy/dx be some other kinda function
lets say its sum g(x)
so how do i find the maximum value of g(x)?
(you find the points where g'(x)=0 then perform the second derivative test)
man
at this pace
idk if youll finish in 8 mins
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hi, need some help with finding the vertical asymptote
of the following function
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can someone explain to me why this is wrong
what does (x) mean
wdym

