#help-49

1 messages · Page 37 of 1

wary thorn
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1 and 1/2 apple

steel trout
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Its like Stanley’s parable writing

last slate
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so 127 filled circles that are 3/10 like 127.3 circles

wary thorn
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3 apple

wary thorn
last slate
last slate
last slate
# wary thorn

3 whole apples , why did u draw fractions in them̄? thats confusing

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i got ghosted

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<@&286206848099549185>

hexed birch
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he made the apples black

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id avoid

last slate
hexed birch
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have you ever seen 0.3 whole people?

last slate
last slate
hexed birch
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i wouldnt say that 0.3 of a person is a whole person

last slate
#

yea

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ik

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this true?
ikkk i said 127.3 mini whole circles

hexed birch
#

tbh i dont even know whats your question about

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im guessing this

last slate
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tho yea i cant imagine that too

hexed birch
#

where?

last slate
#

but thats what it means tho right?

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ok 127.368 circles

hexed birch
#

they mean they have 127 circles and 0.368 of a 1 cricle

last slate
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both of them were yappon @wary thorn

hexed birch
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lmao

last slate
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thank u

hexed birch
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❤️

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i just randomly came here to troll, but sure if i helped

last slate
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u^

nova yoke
#

Without additional context, it's challenging to determine the precise meaning of "both of them were yappon" when communicated by 🤫. However, "yappon" could potentially be a term used to describe a certain characteristic or behavior exhibited by the two individuals being referred to.

hexed birch
#

😎

hexed birch
last slate
#

they mean they have 127 circles and 0.368 of a 1 cricle

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👍👍👍🫡🫡🫡

nova yoke
last slate
hexed birch
#

better hide this channel from goverment then

last slate
#

ya fr

#

.close

midnight plankBOT
#
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midnight plankBOT
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halcyon patrol
midnight plankBOT
halcyon patrol
#

hey, just wondering where I went wrong on this question and lost 2 points

cerulean sinew
#

i don't think you got the correct answer either

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but the question specifically wanted you to solve it graphically

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although in solving algebraically you could have done 0 = x(x-2) and the solutions are obvious

halcyon patrol
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💀

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what does it mean graphically, only ever did it with algebra

cerulean sinew
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that's how the algebraic way works too

halcyon patrol
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redoing it now i dont understand how i even got half points lol

cerulean sinew
#

it's good you realize, your teacher is generous for giving you more than 1 hahah

cerulean sinew
#

you're supposed to graph the two original equations

halcyon patrol
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yeah i’m seeing that now

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thanks for the help

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i’ll send a pic of the changed answer

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is this more accurate?

cerulean sinew
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the line became a little too steep at x = 1 to 2

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i think the pt of intersection should be at (2, 0)

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so instead of going from y = -2 to 1 here, it's supposed to be -2 to 0

halcyon patrol
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yeah the line is drawn pretty bad lol

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i have a question about another problem if your intrested

cerulean sinew
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send it

halcyon patrol
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how would I solve for k?

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i just assumed I could use the vertex as my x intercept and plugged it in to solve for k

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but i assume i needed to find something else?

cerulean sinew
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solving x^2 - 5x + 3 - k = 0 will give you the points of intersection, right?

halcyon patrol
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yeah

cerulean sinew
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if you have a line and a parabola there are only three cases for intersection

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it's either they don't intersect

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or they intersect twice

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or only once

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in what case will they intersect only once

halcyon patrol
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when the line is tangent

cerulean sinew
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so what you've established is that x^2 - 5x + 3 - k = 0 must have only one solution

halcyon patrol
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ohhhhhhhhhhhhhhhhhh

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the discriminant

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thing

cerulean sinew
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yes

halcyon patrol
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b^2 - 4ac

cerulean sinew
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that must be equal to...?

halcyon patrol
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0

cerulean sinew
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yeah thats it

halcyon patrol
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i got the same answer though

cerulean sinew
#

ah check your algebra when you equated the two y's

halcyon patrol
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okay

cerulean sinew
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wait ... there's a lapse in my judgment. i think your solution also works

cerulean sinew
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because if any other part of the parabola was the x-intercept, then there would have been 2, necessitating that the eqn have two solutions

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the vertex being the unique x-intercept means that it is the only root for the expression

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so if im not mistaken your solution is also right!!! you just made a mistake in the first part

halcyon patrol
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yeah i’m thinking the same thing, I think he wanted me to solve it with the b^2 - 4ac

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i was on vacation and missed a lot of class time and they only did it that way and i assumed they just plugged in an x intercept

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anyways i need to go to bed, thanks for all your help today 🙂

midnight plankBOT
#

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raven gorge
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.

midnight plankBOT
midnight plankBOT
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@last slate Has your question been resolved?

tribal temple
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I would think that would work out, though I say that just by looking at it catThink

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It should give you a couple of equations to work with, which I think should be decent to get enough information from RooThink

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Yea was about to say, just noticed that at the same time SCgoodjob2

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Yea x can't be zero so you have to have c = 0, you're doing well, so otherwise both A and B must be diagonal

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Yep, looks good, A is like that and you can then relate B to A as you've done, pleased with that I think happyCat

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last slate
#

how do i determine the amount of regions in a 7 set venn diagram?

last slate
#

this is the thing, but as you can see, not particularly helpful to count manually

raven abyss
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combinations permutations?

last slate
#

yeah of course

raven abyss
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ok cool

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so do you need help setting that up

last slate
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yeah

raven abyss
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ok so we need all the cases for how many overlaps there are

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do you konw what the cases are

last slate
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i think its a bit hard to write them all out manually, but if we represent the existence of a region in an area by a binary string of length 7 i suppose you have 2^7 possible states of whether a particular region is occupying that place thonk2

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so 100 0100 means the 3rd circle and the 7th are intersecting solely

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wait oh

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i guess thats it then?

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its just 128 regions?

latent elk
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2^n - 1

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n is the number of set

last slate
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i guess 0 is not a particular region to consider so we can omit that

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makes sense

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aight thanks

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.cl9se

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kind sundial
#

on a circle race track there are 2 cars that are moving. they meet each other every 40 mins when they go the same way and they meet in 10 mins when thy move the oppisete way. what time would it take for each car to go around the whole track

midnight plankBOT
#

@kind sundial Has your question been resolved?

kind sundial
#

<@&286206848099549185>

midnight plankBOT
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@kind sundial Has your question been resolved?

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bleak pier
midnight plankBOT
bleak pier
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.close

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deft flint
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I noticed u could tan both sides as long as u remove the tan later. is this always applicable and does it work with other trig functions?

neon rune
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here for example xy<1

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if the case is of xy>1, then you need to add/subtract some multiples of pi

deft flint
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ok

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so assumptions are required to tan() both sides

neon rune
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well you can prove the restriction

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for example arctan(tan(8)) ≠ 8

deft flint
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is arctan(x) domain small?

neon rune
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wait

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I mean arctan(tan(8))

deft flint
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yeah the other way around doesn't work

neon rune
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there's a whole lotta proof for 3 cases

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you can look them up on youtube

deft flint
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im good

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i dont want to be traumatized

neon rune
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yep, inverse trig gets ugly at some point

deft flint
#

from this step to the screenshot, did they just arctan both sides?
tan(arctan(a)+arctan(b))=(a+b)/(1-ab)

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median ridge
midnight plankBOT
median ridge
#

i tried using the sine rule, finding the distance between the two particles and try to use the forces of mg and repulsion to find the force in total but none of it works

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i cant use the force equation using q1q2/r^2 because i dont know the quantity of charge

vale zephyr
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suds i remember you helped me once with physics

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have you made any fbd for this?

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@median ridge

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well the main concept here is that theyre gonna subtend same angle from the normal

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like 7 degrees

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well u gotta be quick i have to leave for my classes

midnight plankBOT
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@median ridge Has your question been resolved?

median ridge
#

yeah i got it

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sorry

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its just the question is literally stupid

median ridge
#

i was solving for the total force like someone who can actually read

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and the answer is also wrong because it should be x 10^-3 for the mass because they give it in grams

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so this is a stupid question and i won

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but its still stupid

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.close

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vale zephyr
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sharp shadow
#

how to make it

midnight plankBOT
rain wasp
midnight plankBOT
#

@sharp shadow Has your question been resolved?

sharp shadow
rain wasp
#

well, what have you tried so far?

sharp shadow
#

i just know lim x->inf (1+1/x)^x=e

rain wasp
#

well this is also akin to that

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in fact they are thr exact same

sharp shadow
#

but you cant do this question in the same

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its wrong

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needy help

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<@&286206848099549185>

void magnet
#

??

sharp shadow
#

could u make it?plz

rain wasp
#

what would you get?

void magnet
#

well 1/roote

rain wasp
midnight plankBOT
# void magnet well 1/roote

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

rain wasp
void magnet
#

well i only see the e part

sharp shadow
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wtf

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(e/e)^∞is not exit

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its obviously

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the answer is e^(-1/2) if i didnt remember wrong

rain wasp
sharp shadow
void magnet
#

how about substitue 0 in there

sharp shadow
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its surely wrong

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lol,br

rain wasp
void magnet
#

((1+x)^1/x)^1/x / x root e

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(1+x)^1/x^2 / x root e

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i think you have to rewrite the limit

rain wasp
#

!nogpt

midnight plankBOT
#

Please do not trust ChatGPT or similar AI tools for mathematical tasks, as they often generate output which "sounds correct" but has numerous factual or logical errors. Use of these AI tools to answer other people's help questions is strictly against server rules (see #rules).

sharp shadow
rain wasp
#

the fraction

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or similar AI tools

sharp shadow
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its a commom lim

void magnet
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limx-> 0 = e ^ ln(x+1) / x^2 - 1/x

sharp shadow
#

i forget how to get it

void magnet
#

wrong ping

rain wasp
void magnet
#

try lim x->0=e^(ln(x+1)/x^2 - 1/x)

sharp shadow
#

surely

rain wasp
#

now, as 1/x tends to 0, it becomes infinity

sharp shadow
#

e is a normal num

rain wasp
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in other words, this is an 1^infty limit

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do you know what you usually do for this limit?

void magnet
#

you have to get e ^ .... i think

sharp shadow
rain wasp
sharp shadow
#

its pleasure to discuss each others

rain wasp
sharp shadow
#

welcome to talk

rain wasp
#

now do you know why bring everything to the exponent?

sharp shadow
#

anyone could get the right answers?

void magnet
#

you probably have to get x on it own to do this

sharp shadow
rain wasp
sharp shadow
rain wasp
#

$\ln a^x = x\ln a$

grand pondBOT
#

فطر

rain wasp
#

this sets up very nicely for l'hopital

sharp shadow
#

obviously

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Is there a specific deduction?

rain wasp
#

what do you mean

sharp shadow
#

this question how to finish

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it my homework

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i should hand in it soon

rain wasp
#

!noans

midnight plankBOT
#

The purpose of this server is to help you learn, not to hand out answers. Do not ask someone to give you the answer directly.

void magnet
#

i will turn it into ((1+x)^1/x)^1/x. / x root e first

rain wasp
#

i recommend setting the whole thing to a value

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like A

rain wasp
#

then e^ln() both sides

void magnet
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then you get (1+x)^(1/x^2). / x root e

sharp shadow
rain wasp
#

this way you can bring the 1/x down

sharp shadow
#

could u write it in paper,thx

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im no the english learner

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i just know the math mark

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u r all nice guy

rain wasp
#

you should do the work yourself

sharp shadow
#

hahah

rain wasp
#

you are the learner, im simply guiding you where to go

sharp shadow
#

i have no idea

rain wasp
sharp shadow
#

sure

rain wasp
#

$A=\lim_{x\to0}\left(\frac{(1+x)^{\frac1x}}e\right)^{\frac1x}$

grand pondBOT
#

فطر

rain wasp
#

now e^ln() both sides

sharp shadow
#

whwt then?

void magnet
sharp shadow
sharp shadow
void magnet
sharp shadow
sharp shadow
#

good

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👍🏻

sharp shadow
#

bec ln(x+1)~x in 0 point

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but the right answer is

void magnet
#

and you turn x to 0

sharp shadow
#

why its this answer instead of 1

void magnet
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so you get 0/0

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so you can do ln(x+1)=x-(x^2/2)and cancelx^3

sharp shadow
void magnet
#

this is from the sin(x)=x-(x^n/n!)

sharp shadow
#

oooo

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thx,i get it

void magnet
#

i havent learn exponencial before

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just trying hardest from what i haev already learned

sharp shadow
#

hahah

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u r talent

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its very beautiful

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void magnet
#

???

midnight plankBOT
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slim nova
#

how to prove that xy=z^2 plots an infinite elliptic cone?

slim nova
#

I'm trying to find some geometric interpretation to at least make it more intuitive for myself to understand, but that's proving to be quite flimsy haha

midnight plankBOT
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@slim nova Has your question been resolved?

midnight plankBOT
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@slim nova Has your question been resolved?

slim nova
#

<@&286206848099549185>

midnight plankBOT
#

@slim nova Has your question been resolved?

midnight plankBOT
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@slim nova Has your question been resolved?

final monolith
midnight plankBOT
#

@slim nova Has your question been resolved?

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coral bobcat
#

Hi help

midnight plankBOT
coral bobcat
#

💀

#

I got csc

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Idk what to do now

stoic zinc
#

ummmm, you need to find the values of each of the letters

coral bobcat
#

?

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Oh yeah

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So i got csc as 3

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But idk what to do now

stoic zinc
#

do you know how to do b?

coral bobcat
#

No 😭

solid hornet
#

im not 100% sure because i didnt do this in class yet but

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if we have sinx

stoic zinc
#

can there be multiple solutions for each of the letter?

solid hornet
#

then we can find sin^2(x) right

coral bobcat
#

Maybe?

solid hornet
#

then we can use sin^2(x)+cos^2(x)=1

coral bobcat
#

Omg

solid hornet
#

not sure

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maybe that works

coral bobcat
#

So cos = sqrt(8)/3?

solid hornet
#

it would be sqrt(8/3)

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but

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i dont know about the signs

stoic zinc
#

dawg

solid hornet
#

woh

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wai

tribal temple
#

helpparens placement matters

solid hornet
#

oh

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righ

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i forgot

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i was thinking sqrt(8/9)

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but i see you simplified to sqrt(8)/3

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i c

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yes ur right

coral bobcat
#

Ok thank you! :DD

stoic zinc
#

can't it also be - sqrt(8)/3?

tribal temple
#

[yea, they didn't give any quadrant info catAngery I'm assuming you're meant to take it as first quadrant though, if they state that(?)]

coral bobcat
#

Oh oops i forgot to close this

#

Thanks guys! :))

#

.close

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coral bobcat
#

Hii how would i do 47 😭

midnight plankBOT
#

Please don't occupy multiple help channels.

coral bobcat
#

Oops

tribal temple
#

Quadrant info, finally catThink

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The best thing to find first would most likely be tan(theta), there's a identity that links sec to tan directly...

coral bobcat
#

So the quadrants would either be 2 or 4

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?

tribal temple
#

Yep, but then you can rule one of those out!

coral bobcat
#

Is it quadrant 4?

tribal temple
#

It's in quadrant 4 SCgoodjob2

coral bobcat
#

YAY

tribal temple
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[because that's where cos, and so sec, are positive, and here you know that sec is positive happyCat]

coral bobcat
#

Oooh :DD

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Would cos be -5/6

tribal temple
#

cos and sec have the same sign OathLove

coral bobcat
#

OH

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OH YEAH

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💀

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Would i use a trig identity to find the rest?

tribal temple
#

Yep catThumbsUp

coral bobcat
#

Would it be 36/25-1 = tan^2

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Amd so tan = sqrt(11)/5

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Hooray 😄

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And so sin would be (6)sqrt(11)/25?

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And csc would be [(25)sqrt(11)]/66

tribal temple
coral bobcat
#

YAY :DDDD

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THANK YOU!!!

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stoic wing
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stoic wing
#

i dont know how to attempt ii

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silent sorrel
midnight plankBOT
silent sorrel
#

#14

#

I’m not sure what it means to find the compass heading for the plane

#

Does it mean the compass heading that she should go to make the plane go east again

#

?

#

Ping pls when someone helps

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@silent sorrel Has your question been resolved?

silent sorrel
#

<@&286206848099549185>

#

@fallen galleon quick question

fallen galleon
#

?

silent sorrel
#

Number 14

fallen galleon
#

compass heading huh

silent sorrel
#

Does it mean that I need to find the angle that resets the plane back to east

#

Or just the resultant angle

silent sorrel
#

But the resultant angle is very easy

fallen galleon
#

the angle between the heading of your Aircraft and the Compass North.

#

i also dont really know what compass heading is

#

thats what i found on google

silent sorrel
#

North is 90 degrees

#

And that is the new 0

#

So 90 bearing is 0 degrees

silent sorrel
#

Wait hold on I think I Joe

#

Know

fallen galleon
silent sorrel
#

Yes

#

I got the question though

#

Thanks

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civic iris
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civic iris
#

Can anyone walk me through this question,i understood the second part after differentiating but my why question is if it has a postive point of maximum is it nessary that the minimum should also lie in the postive point i dont get the graph.

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civic iris
#

<@&286206848099549185>

quasi pasture
# civic iris Can anyone walk me through this question,i understood the second part after diff...

Because the dominant term is x^3, as you go more left the graph goes towards -infinity and when you go right the graph will go towards +infinity, if there is a maximum, then you know that immediately to the right the graph should be decreasing because that is how the max is defined. But you also know that in the long run that when you go towards the right you go towards infinity, so the graph has to turn around with a min to go back up.

civic iris
#

hello

quasi pasture
#

hi

civic iris
#

that makes so much sense

#

ty so much

#

and for find if odd degree function is first coming -infinty or +infinty you just substitute values and check right?

quasi pasture
#

It depends on the sign of the dominant term.

#

If it is positive, its as above, if it is negative it is flipped.

civic iris
#

ahh alright

#

tysm

quasi pasture
#

No problem happy to help!

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last slate
#

wat do restrictions Meanhere

midnight plankBOT
novel herald
#

they get rid of all the stuff that wouldn't make f one to one

#

in their example if you take the domain [-10,10]

#

then $f(-2) = (-2)^2 = 4 = 2^2 = f(2)$

grand pondBOT
#

chebyshev's infinite pee norm

novel herald
#

so 4 (from the range) is coming from both -2 and 2 (from the domain)

#

and in particular, x^2 in the range comes from -x as well as x in the domain

#

when you restrict it to [0, 10]

#

x^2 can only come from x, it can't come from -x anymore

last slate
#

likw how does it limit

#

the domain

novel herald
#

they made it smaller

#

it went from [-10,10] to [0,10]

last slate
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last glen
#

Can someone state the series for this. I'm outta go crazy

gusty seal
#

Seems to be $\left { 1 + \left(-\frac{1}{3}\right)^n \right }_{n \geq 1}.$

grand pondBOT
#

lpieleanu

last glen
gusty seal
#

i noticed that the 1st, 3rd, 5th, etc. are slightly above 1 by a power of (1/3) and the 2nd, 4th, 6th, etc. are slightly below 1 by a power of (1/3)

last glen
#

That actually makes sense thanks for helping

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steady sierra
#

Can you prove that a function is surjective in discrete with a graph ?

runic hamlet
#

depends on what you mean by graph

steady sierra
#

like if given a function x^2 and I graph that

runic hamlet
#

no

steady sierra
#

but I could use a graph to prove that a function is injective right ?

runic hamlet
#

no

steady sierra
#

dayumn.... alright well thank you

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nocturne marlin
#

im stupid

#

xD sry

cobalt sigil
#

Hi

#

Hey bro

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hexed talon
midnight plankBOT
hexed talon
#

WHy are they choosing specifically 3 points to look for combination A to f(A), B to f(B) and C to f(C)?

#

i dont get how that is related to the statement

#

nvm i think drawing it out helped me visualize

#

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hexed talon
midnight plankBOT
hexed talon
#

Im not understanding this paragraph

#

"w has direction u from v if w - v is a multiple of u"

runic hamlet
#

if you are at v and want to go to w, you have to go in the direction of u

hexed talon
#

would it be possible to draw it out?

hexed talon
#

w-v is the blue line?

runic hamlet
#

the arrowhead needs to be on the other end

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#

@hexed talon Has your question been resolved?

hexed talon
runic hamlet
#

yes

hexed talon
#

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abstract aurora
midnight plankBOT
gleaming latch
#

no solution means the lines never intersect

abstract aurora
#

and this btw

#

ty

gleaming latch
#

these are linear so that means they have the same slope

abstract aurora
gleaming latch
#

put the equations into y = mx + b form

blissful pier
#

well solve each equation for y and equate the slopes

abstract aurora
#

I've got 1/(1/6.5) what i suspected to be wrong

abstract aurora
blissful pier
abstract aurora
#

they werent the same y

#

nvm I rechecked and I got 1/4 for z

#

and 4 for the slope of equation 2

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sick lodge
#

yo

midnight plankBOT
sick lodge
#

i cant find my error

static thunder
#

How did you get this

tribal tartan
#

yeah that part is wrong

#

since if you used a u sub

sick lodge
#

i splited it in 2

static thunder
#

If you did int f'/f, its wrong

tribal tartan
#

du=2x+1 dx

sick lodge
#

i split the integral in 2

static thunder
#

x^2+x+2 goes to x+1

sick lodge
#

its like integral of x + 2x is integral of x + integral of 2x

static thunder
#

2x+1*

tribal tartan
sick lodge
#

can u tell me why

tribal tartan
#

you used a u substitution i presume

sick lodge
#

i tried to split them

tribal tartan
#

did you do u=x^2+x+1?

sick lodge
#

i did u = x+1/é

#

1/2

tribal tartan
#

that’s the second integral

#

i’m talking about the first one

static thunder
#

The one I highlighted

sick lodge
#

for the first one i just split the integral in half

tribal tartan
#

what do you mean split it in half?

#

it’s already split

sick lodge
#

its like integral of x + 2x is integral of x + integral of 2x

static thunder
#

Let me show you how to do it

#

Give me a min

#

I think this isn't getting anywhere

tribal tartan
#

$\int\frac{x}{x^2+x+1}\dd x$ cannot be split up any further

grand pondBOT
sick lodge
tribal tartan
sick lodge
#

i did that and i got 1/2 ln(3)

tribal tartan
#

how?

sick lodge
#

multiply by 2

#

and 1/2

#

u get ln(x^2+x+1)

#

between 1 and 0

tribal tartan
#

that’s incorrect

#

if you differentiate that

#

you won’t get that integrand

#

since the derivative of the inside would be 2x+1

#

not 2x

#

you can’t simply just multiply by 2 here to compensate for that

sick lodge
#

my bad

#

so the 2 in the second integral

#

should be 1

#

no more 2

#

i got it now thank you

#

.close

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last slate
#

for b
can it be
(5-3)^2 < (x-3)^2
as (x-3)^2 = f(x) anyway

and ik all squared values are <0 but wat does it mean by 0 being equal to a squared value?
like 0^2 =0
dis the only possible case anyway

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last slate
#

.reopej

#

.reopen

midnight plankBOT
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midnight plankBOT
#

@last slate Has your question been resolved?

last slate
#

.reopen

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.close

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last slate
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.reopen

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last slate
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static salmon
#

im stuck on 28, and these are the formulas we can use

static salmon
#

full question: “ write the first function in terms of the second”

nova yoke
#

well you have tan = sin/cos available

#

can you write sin in terms of cos?

midnight plankBOT
#

@static salmon Has your question been resolved?

static salmon
#

cos(90-x)?

nova yoke
#

yea

static salmon
#

would that just be the answer?

static salmon
#

.close

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static salmon
#

new question, new channel- no idea what to do for 32 or 36

tawny gyro
static salmon
#

zhuh

tawny gyro
#

It will take a while to write out

static salmon
#

which trig identity

#

there are multiple

hearty rune
#

32, just expand, tan^2+1=sec^2 is the key

tawny gyro
#

The one that he said times cos^2

static salmon
#

how do you get to tan^2

opal yarrow
#

sin and csc cancel out, and then the other 2 result in tan^2, so it becomes 1 + tan^2

#

u can do sec^2 as 1/cos^2

#

and then its sin^2 / cos^2

static salmon
#

ive located my fatal error

#

when I wrote down the problem i forgot to square sin

tawny gyro
#

It took longer because I had to set up a highlighter

static salmon
#

okay I’ve gotten to that

#

oh wait im dumb-

tawny gyro
#

What are you stuck on on 32?

static salmon
#

okay it’s like 10:30 pm and someone is knocking on my door

#

give me just a moment if i die tell my family

#

nvm we good

static salmon
#

Ok im good with 32

#

with 36 I just have no idea where to go

tawny gyro
#

Now multiply the entire thing by the reciprocal of the right side on 36

static salmon
#

From the start, or from where i got?

tawny gyro
#

Start

static salmon
#

Ik

#

Ok*

tawny gyro
#

Any other questions?

static salmon
#

According to my teacher we’re only allowed to change one side though

tawny gyro
#

Thats annoying

static salmon
#

tell me about it

tawny gyro
#

Well, just combine the fractions of the left side first

static salmon
#

this unit sucks it’s almost as bad as geometric proofs

tawny gyro
#

Now any other questions

static salmon
#

to be honest im incapable of like half of these

#

but I’ll keep going

tawny gyro
#

:/

static salmon
#

🫡

tawny gyro
#

Ngl I don’t understand how people struggle with these

static salmon
#

i think it’s just like too much information to me to process

tawny gyro
#

But a good tip is to convert them to their cos and sin forms

static salmon
#

oh thanks!

#

okay so after getting to (sin^2+cos^2)/(co^2 x sin^2) where do i go from there?

tawny gyro
#

What is the basic trig Identity

#

Btw for your “test” I choose someone random for Q10 and got that person

static salmon
#

who’d you get

#

rumi? jay? chip? lord forbid William?

static salmon
tawny gyro
#

The one I mentioned earlier

tawny gyro
static salmon
#

i always forget Ashe isn’t a woman

#

how’s parent issues going lmao

tawny gyro
#

Idk those characters

static salmon
#

yeah most don’t

#

pretty obscure fandom

#

rate the accuracy of the description x/10

tawny gyro
#

I would have to reread it

static salmon
#

did you close the tab bc i have it saved on my camera roll if needed

tawny gyro
#

Lol I did the same answers but changed the “who I thought I would get” and got something different

static salmon
#

who’d you get this time

tawny gyro
#

Gillian

static salmon
#

Jay or gillion

#

yeah that’s what i thought

#

still parent issues!

tawny gyro
#

Lol its the only accurate thing

static salmon
#

fair it’s really targeted at depressed gay children

#

anyway i think im gonna turn in

#

the math is not mathing and I want more than 6 hours of sleep tonight

tawny gyro
#

In college you don’t have school on Fridays so I can stay up lol

static salmon
#

good for you /gen

#

goodnight

#

.close

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marble ruin
#

How do you do part c and I was wondering if I got part a correct

midnight plankBOT
#

@marble ruin Has your question been resolved?

marble ruin
#

.helpers

#

<@&286206848099549185>

tawny gyro
#

a) is wrong

#

For c) what is the lowest y value on the graph?

midnight plankBOT
#

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crimson totem
#

help pls...

midnight plankBOT
#

Please don't occupy multiple help channels.

light comet
#

L

crimson totem
light comet
crimson totem
#

3

light comet
#

so factor a 3 out

crimson totem
#

how

light comet
#

3(-12/3p^2q -9/3pq^2)

#

yeah just give him the answer

#

dont make him think

#

at that stage i didnt know how to do prime factorization

#

the easiest way is to continually divide out common factors

#

starting with 3 cause its obvious

#

then find the next comon factor

midnight plankBOT
#

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wide dagger
midnight plankBOT
wide dagger
#

Is this answer wrong ?

slender walrus
#

yes, its wrong

wide dagger
#

Crap

#

What did I do wrong?

slender walrus
#

you summation represents
$$5.\overline{8}$$

wide dagger
#

What does that mean

#

Only the 8 is repeating

slender walrus
#

yes

#

but you ignored that it only starts repeating after a few positions

#

actually, misrepresented what you did

wide dagger
#

wdym

slender walrus
#

what you did was actually
$$5 + \frac{8}{10} + \frac{8}{10^2} + \frac{8}{10^3} + \frac{8}{10^4}$$
which represents
$$5.8888$$

wide dagger
#

so I should've done 5.67 + 8/10... ?

slender walrus
#

no

grand pondBOT
#

ℝαμΩℕωⅤ

slender walrus
#

$$5.67\red{8}\overline{8}$$
what's the value of that red \red{8}?

grand pondBOT
#

ℝαμΩℕωⅤ

wide dagger
#

The repeating started at the first 8

#

There was no 5.678 then 8 repeating

slender walrus
#

$5.67 + \what = 5.678$

grand pondBOT
#

ℝαμΩℕωⅤ

wide dagger
#

The answer it was looking for was a fraction

slender walrus
#

yes

#

answer my question first

#

as i'm guiding you step by step

wide dagger
#

.008?

slender walrus
#

yes

#

and what is that as a fraction

wide dagger
#

1/125?

slender walrus
#

what did you have before simplifying

#

its more convenient when doing the summation that way

wide dagger
#

Am I including the 5.67 ?

slender walrus
#

forget about that for now

#

focus on what i'm asking for

wide dagger
#

8/1000?

slender walrus
#

yes

#

that should be the first thing you'd be adding to the 5.67 and so on
instead of starting from 8/10

#

$5.67\overline{8} = 5.67 + \frac{8}{10^3} + \frac{8}{10^4} + \dots$

grand pondBOT
#

ℝαμΩℕωⅤ

wide dagger
#

Darn I messed up on my exam

#

Rip

slender walrus
#

and then do the infite summation and combine terms into a single fraction

#

are you required to do it this way?

wide dagger
#

Yes

slender walrus
#

so you're not allowed to use the
x = 5.678
100x = 567.8...
1000x = 5678.8...
etc?

wide dagger
#

probably could but im just going by the method my professor gave us

#

nah I wasn't. But its alright. I was just curious if I did the correct thing on my exam

#

clearly not. rip

midnight plankBOT
#

@wide dagger Has your question been resolved?

midnight plankBOT
#
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midnight plankBOT
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bleak pier
#

Limit of floor(sinx)
X tends to π/2

midnight plankBOT
lofty cargo
#

floor ?

bleak pier
#

Greatest integer function

full marlin
#

Sin(pi/2) is 1 but the values of sinx are less than 1 near pi/2 so the limit of floor(sinx) at pi/2 would be 0

bleak pier
#

I meant it will be 0 or 1?

#

X tends to π/2

full marlin
#

The value at that point is 1 but the limit is 0

bleak pier
#

Ohh so we are talking about tends

#

,w limit x tends to floor(sinx)

#

Thank you

lofty cargo
midnight plankBOT
#

@bleak pier Has your question been resolved?

ebon sable
#

do you have any other question?

bleak pier
#

.close

midnight plankBOT
#
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lament fox
#

$\lim_{x\to\infty}\int_{-\infty}^{\infty}\frac{1}{1+|t^x|}dt$

grand pondBOT
#

The د

lament fox
#

how can i approach this?

waxen linden
#

$\lim_{x \to \infty} t^x = 0$ for $t \in (-1, 1)$ , $\infty$ otherwise

dawn dagger
#

\lim*

#

(-1, 1) was correct

#

1^(oo) = 1

grand pondBOT
waxen linden
#

you're helping me more than this guy lmao

dawn dagger
#

but the real question is

#

if we can pull the limit operator inside the integrand

#

then we can use your hint

#

Apparently we can pull in the limit operator inside the integrand, if the convergence of the integrand is uniform

#

,, \norm{f_n - f}{\infty} =\sup{n \in \mathbb{R} } \abs{\frac{1}{1+\abs{t^n}} - 1}

#

hmm

midnight plankBOT
#

@lament fox Has your question been resolved?

lament fox
#

ahh ok so $\int_{-\infty}^{\infty}\lim_{x\to\infty}\frac{1}{1+|t^x|}dt$

grand pondBOT
#

The د

lament fox
#

we can say $\int_{-\infty}^{-1}\lim_{x\to\infty}\frac{1}{1+|t^x|}dt$ + $\int_{-1}^{1}\lim_{x\to\infty}\frac{1}{1+|t^x|}dt$ + $\int_{1}^{\infty}\lim_{x\to\infty}\frac{1}{1+|t^x|}dt$

grand pondBOT
#

The د

lament fox
#

which = 0 + 2 + 0 = 2

#

perfect!

#

right?

dawn dagger
#

You would have to prove first if the integrand converges uniformly

#

then you can pull the limit operator inside

#

but doesnt seem to be

#

only pointwise convergent

lament fox
#

what does uniform convergence refer to?

dawn dagger
#

because of it wouldn't be continous since for 0 < t < 1 f = 1, for t = 1/2 f = 1 and t > 1 is f = 0

lament fox
#

if x is like 9999 it would be continuous

#

but like barely yk

dawn dagger
#

depending on t you get different limit functions

dawn dagger
#

to split the integral

lament fox
#

yeah?

#

it works?

#

I mean graphically it does

dawn dagger
#

yea

#

it should be uniformly convergent

#

yea

#

if you prove that additionally then you can pull in the limit operator and evaluate it like you did

grand pondBOT
#

𝔸dωn𝓲²s

dawn dagger
#

We can do the proof for the first Integral together

lament fox
#

ok sure

lament fox
dawn dagger
#

can you tell me where you currently are math level wise

lament fox
#

i know calc 2

dawn dagger
#

oh

dawn dagger
lament fox
dawn dagger
#

So that is your task?

lament fox
#

to understand unifrom convergence?

#

sure

dawn dagger
#

Well we do that prove so you can justify pulling in the limit operator

#

But that doesnt seem calc 2

dawn dagger
# grand pond **The د**

But that should be the same as

$$\lim_{x\to\infty}\int_{-\infty}^{\infty}\frac{1}{1+|t^x|}\dd t = \lim_{x\to\infty}2\int_{0}^{\infty}\frac{1}{1+t^x}\dd t$$

grand pondBOT
#

𝔸dωn𝓲²s

dawn dagger
#

To make things easier

#

So we actually have 2 cases

#

or 3 with t = 1

#

,,\norm{f_x(t) - f(t)}{\infty} = \sup{t \in (1, \infty)} \abs{\frac{1}{1+t^x} - 0}

grand pondBOT
#

𝔸dωn𝓲²s

dawn dagger
#

We can actually estimate this up

#

but unformally convergence is no calc 2

#

level

midnight plankBOT
#

@lament fox Has your question been resolved?

midnight plankBOT
#
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versed path
#

Hi how to solve this limit without L'Hospital?

midnight plankBOT
last slate
versed path
#

What did I say in the question

slender walrus
#

your factorisation of the denominator is incorrect

versed path
#

whoops

slender walrus
#

try factorising again

versed path
#

oh lmao sorry

#

missed that somehow

#

thanks

last slate
versed path
#

.close

midnight plankBOT
#
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errant onyx
#

Can someone verify my answers? Here is the question: Consider the region R, which is enclosed by the graphs of x=y^2+2y+3, x=3y+5, and the vertical line x=6.

a) Find the area of R
b) Region R is the base of a solid. For the solid, at each x, the cross-section of the solid perpendicular to the x-axis is represented by F(x)=1/(x+2). Find the volume of the solid.
c) Write an integral expression that gives the volume of the solid generated when R is rotated about the horizontal line y=2.
Graph of the lines below

a) 8/3
b) ln(2)
c) (see photo below)

midnight plankBOT
#

Please don't occupy multiple help channels.

errant onyx
#

heres my work

errant onyx
# midnight plank

also about this i had just asked a question in another channel and i had closed it but then i immdiately opened this one so i think the server thought i was in two channels at once

#

.close

midnight plankBOT
#
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midnight plankBOT
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short cove
#

can someone help me

midnight plankBOT
hexed elbow
#

do you know how to find a general expression for the slope of a tangent of the given function

short cove
#

no but please give me answer and can u explain aftre this is due in 8 minutes

#

please

#

i beg

#

explain to me after

#

this is vey crucial

hexed elbow
#

i cant give u the ans rn causelike

flat spire
#

Is this a test?

hexed elbow
#

i dont have a working space

#

thats y i wanted to explain\

#

if i explain it fast enough

#

can u do the working urself

short cove
#

no its hw

#

yeah i can

#

i just need steps

hexed elbow
#

okay so to find the slope

#

what do you normally do

#

like if i know the point on the function where i wanna draw my tangent

#

how do i find the slope for that point's tangent

#

just differentiate basically

short cove
#

ok

#

i did that

hexed elbow
#

now u need to find the maximum slope

#

you have an expression for the slope ( dy/dx)

#

let dy/dx be some other kinda function

#

lets say its sum g(x)

#

so how do i find the maximum value of g(x)?

#

(you find the points where g'(x)=0 then perform the second derivative test)

#

man

#

at this pace

#

idk if youll finish in 8 mins

short cove
#

its fine i got it

#

thx tho

midnight plankBOT
#

@short cove Has your question been resolved?

midnight plankBOT
#
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#
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autumn folio
#

hi, need some help with finding the vertical asymptote
of the following function

autumn folio
#

.close

midnight plankBOT
#
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#
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floral minnow
#

can someone explain to me why this is wrong

midnight plankBOT
floral minnow
#

discrete math

#

<@&286206848099549185>

novel herald
#

what does (x) mean

floral minnow
#

wdym