#help-49
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Can you say the steps
there is no step
What do I do
sorry but what age are you ?
I do 2x2 and it’s 1/4?
if you are under 13 y then you can't be here
Ok can you tell me how to do it again
Nvm
I ddnt know to divide
are you below 13 ?
Why🥲
If you are then you can’t be on the server and sorry but for me it’s seems that you are below 13
I know
Help pls
Do you know any rational number inferior to 1/2 or 0.5 ?
Another ?
How
I don’t know how to explain it so watch this instead
This math video tutorial explains how to convert decimals to fractions. It contains a few examples and practice problems showing you how to do it.
Fractions - Basic Introduction: https://www.youtube.com/watch?v=3TklZi6MeJ4
Simplifying Fractions: https://www.youtube.co...
Ok thx you
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Uhh for the first one Im thinking like
Actually
Idk😭
400c+2600e<95000
And for the second one
20c+120e≤470
Wat y'all's thoughts
Oki i got it right
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a few things...
when you say "think of literally any number" and then talk about random chance you need to define a distribution for those numbers
second, i don't understand what you mean - are you trying to guess the value of lim{x->inf} 1/x by guessing randomly somehow?
do u mean like we each guess a real number and if we guess the same number you win? you're going to run into a lot of issues here, mostly around accurately sampling a random real (not just rational) number
ok that's what i said yeah
how do u describe an arbitrary real number in a finite amt of time?
you also need a distribution but the normal distribution will be fine - note that uniform distribution over the reals is meaningless
like we each write one down right?
how do i do that for a real number that isn't rational?
right so how do i communicate my guess to you
and how do you check if it's right
painstakingly write out your guess
how
yep
and, in fact, is 100% likely to be
correct but it's 0% likely to be 2
really it's 0% likely to be any specific value
nope
there are more irrationals than rationals
rationals are countable
rationals are pairs of integers
or really smaller than pairs of integers since like 2/3 and 4/6 are the same
it doesn't count again, it's 1
here's a slightly depressing video:
https://www.youtube.com/watch?v=10rA45pb7dk
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if you only want to prove that rationals are countable and irrationals are not, then it's just the fact that rationals are and it's not hard to prove (bijection between N² and Q is obvious) and that reals are uncountable
if you want to deduce that the probability of getting rational is 0 as Miku said, it's related to the way you define the probability distribution and your measure, which you'll study later
intuitively, the reason is that you're more or less assuming an uniform distribution, and rationals are very rare in real numbers
their Lebesgue measure is 0
yeah but that's not relevant
rationale is specifically one integer over another
with some restrictions
uh
what about it!
?
yes
it's equal to 11/12
two integers
watch that video
not really meaningless, it's just that you're mashing several questions together at the same time
for example take a disc of radius 1, and throw a dart at it
while it's definitely possible to hit exactly (0, 0), the center, the probability is 0
but it is definitely possible, since your dart has to hit some point of the disc
it's once again related to measure theory, intuitively, what happens is that a specific point of the disc represents an area of 0, it doesn't have any area and it's negligible
so you can only put a 0 weight on it
but if I told you what's the probability my dart touches the left half, you would have answered 1/2
since the left half is 1/2 of my area
when you deal with infinite possibilities, the way you define probabilities has to avoid some problems, and the way to avoid that is to think with measure theory and a somewhat geometrical approach
if you take a random real number, it's the same idea but with "1 dimension geometry"
while you'll necessarily get a real number, with probability one, the probability to get a specific number is 0
it doesn't mean you won't get it, it's just the only probability you can assign to it
I'd argue that the very idea of choosing a random real number from a continuous distribution is meaningless
btw she glosses over the proof that irrationals are uncountable in that video. it's called Cantor diagonalization and it's very cool, but it requires a lot of precision so that's probably why. I'd recommend looking it up, or trying it yourself (imagine i handed you an infinitely long list of real numbers. can you construct a real number that i missed?)
it's easy to show that the chance would have to be smaller than any given positive number
so, the only value we can assign it is zero
or... zero plus epsilon but that again requires a lot of precision (what's epsilon? how does it work? what can i do with it?)
intuitively, a probability of 0 means it's almost surely impossible, but not necessarily impossible
something almost surely impossible is when the "area" is 0 because it's nothing compared to the whole probability which represents an area of 1, distributed over infinitely many points
to take my example above once again, the probability that my dart hits the target is 1, but the probability it hits (0, 0) is 0
and same for hitting (0, 1) etc
the probability of hitting either (0, 0) or (0, 1) would be 0 again, because these two points still don't define an area, a consequent part of my target
but the probability of hitting the right half would be 1/2, because now the event of hitting the right half is not negligible compared to the whole target
what happens is that you can't compare points to length, area, or volume etc, points don't have any sort of mass (relatively to an infinite set of points), but in the end, a point is still chosen
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fun fact: if you've heard of the Halting Problem, this is directly related to the same idea
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what's the question
So
I'm sort of confused why my book will write it like (e/3)^n but personally I find writing e^n / 3^n to think about the behavior easier. Am I missing something?
writing this as (e/3)^n makes it more blatant that this is a geometric series with ratio less than 1
hmmm
okay that's fair
So with this ratio, wouldn't the num and denom just keep growing?
,w geometric series
Huh, didn't expect wolfram to run right into the good stuff. Normally never does
There's a closed formula for geometric series.
yeah I got here and figured 3 was the a and (e/3) was the common ratio
darn
that's wrong
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I have an ALU that handles the subtraction of 2 binary numbers. It works well for equations like 4 - 2, 4 - 5, or anything similar. But I've decided I want to be able to switch between signed (2's complement) and unsigned. Which works well and all but let's say I was to subtract 128 from 0. The expected output would be 128, but it actually puts out -128. Because the ALU "thinks" that 128 is in 2's complement which means it would be -128. Similar examples would include 11110000 - 00000000 which is equates to -16 in signed binary but to 240 in unsigned binary, but the ALU only supports signed so it will spit out -16 regardless of the signed/unsigned input.
Okay, maybe that was a bit of a confusing question. But TL;DR: how can my ALU work with unsigned inputs? I have a flag that will tell it whether or not the input is signed or unsigned, but I'm not sure how I would process that correctly.
More examples for clarification would be:
(signed) 11111000 - 00000010 = 11110110 (-8 - 2 = -10)
(unsigned) 11111000 - 00000010 = 11110110 (248 - 2 = 246)
Which would be the same but both of them have the 'negative' flag output by the ALU meaning that the unsigned bit gets interpreted as -10
So I guess it could be solved by changing the output of the negative flag, but how could I do that (currently the negative flag is based off last bit (the 'sign' bit))
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Help I got stuck
what are you supposed to find?
i dont think there is an integral ans maybe taking a log would help
yes
yeah I got stuck
I am meant to use log base 10
you can use any base
really?
so this is correct?
yeah finally it would produce the same result
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Is my process correct???
ℝαμΩℕωⅤ
Huh?
We are just starting trigonometry
sinx = 0
sin^-1(sinx) = sin^-1 (0)
x = 0
<@&268886789983436800>
think of sin(x) as a function that takes in x and returns some value. you cannot say f(x) / f = x
Im solving how to make the equation equal
sin or f is not a variable that you can cancel
but you can sometimes take the inverse of a function
(right now) you can for sin
taking the inverse of sin(x), gives you x. and taking sin of x, gives you sin(x)
1 = 2sin(x)
dividing both sides by 2 only gives you
1/2 = sin(x)
taking sin^-1, (its the function inverse NOT the same as 1/sin which is the multiplicative inverse)
gives you one solution for x
<@&268886789983436800>
Got them
How do I inverse the 2sin?
1 = 2sin(x)
dividing both sides by 2 only gives you
1/2 = sin(x)
taking sin^-1, (its the function inverse NOT the same as 1/sin which is the multiplicative inverse)
gives you one solution for x
there is an excpetion in notation when that power is -1.
$$\sin^2(x) = \sin(x) \cdot \sin(x)$$
but
$$\sin^{-1}(x) \redneq \frac{1}{\sin(x)}$$
ℝαμΩℕωⅤ
maybe arcsin is a better way of expressing it...
gives the angle of the arc from initial to terminal
this might get confusing hahah.
Wait for context we are just starting trigonometry so I don't have much knowledge yet
try finding some videos on:
special trig angles and ratios
inverse trig
Okey im going to do that
in any case, since i already written this: sin of t expresses the height of this triangle, when t is some value. taking the inverse of sin t is akin to finding t. when you have $$1/2 = sin x$$, taking the inverse you write $$arcsin(1/2) = x$$. this is akin to finding the angle x, when the height of this triangle is 1/2.
Ab
this triangle refers to the triangle in the unit circle
: ). that's a job for the people making the calculators, lol. There are some formulas you can use to approximate the value of arcsin(x) which you can search up if you want to. you can assume it works by magic^TM, and do your calculations for now...
(actually written this as meant to answer akio. idk your background, srry)
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ok
so i've solved the hard part of the problem
now the part that is supposed to be trivial
i dont understand
so which problem do you mean?
im taking a piture of it
didnt mean to play guessing games
a = -2 and b = -5 and c = 0
why is it -2 and -5
only way it can see is if you take your answer and plug into your very first equation with constants (a,b,c)
because then you can see why a = -2 etc, but can you not solve the problem just by looking at the last matrix
but that seems odd to me
Maybe it's clearer if you solve a system of equations
I mean what this row reduced form tells you is that is ax_1 + bx_2 + cx_3 = (8,2,-7), then c can be whatever you want, and a+3c = -2, and b+2c = -5
so if you want fix c=0
you get a=-2, b=-5
honestly I always think of the linear system behind even if it's just in my head
then yeah sure when i re-insert into the first equation i can see its trivial
a + 0 + 0 = -2
otherwise I fuck it up
so the row reduced form doesnt tell you it automatically
you have to take what you found
Tbh you only need to know that the three vectors form a basis; you can get any vector from them
they don't form a basis here lol
Oh true my mistake
but why must it be c
that is 0
the first equation is (a,b,c) and then repeated
why do i now assume its (c,c,c) = 0?
i know
so one of a, b, c can be treated as a free variable
but why doesnt that say then a + b + c = 0
there's infinitely many possible lin combos that work
(a,b,c) = (-2, -5, 0), (a,b,c) = (-5, -7, 1), (a,b,c) = (-8, -9, 2), ...
for each c, you get a lin combo
yes but from this picture alone
or does this picture only tell me there is on x3=x3
so there is one free varaibel
well yeah
the last row represents 0a+0b+0c=0
so you only really have 2 linear equations to satisfy
(the 2 upper rows)
yh
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I know I use toa to solve B, but I'm not too sure how to get theta
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Gyazo is not supported for my iPad but just by your response, to solve theta do inverse tangent and divide b by 20
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Dont understand how to do this one (similar figures)
First, I thought to do 4/x = 3/5
To get x = 20/3 but thats wrong
answer in back of the book says it's root x = 31 - 1
Are you let; x=a?
wdym
huh, getting to the same answer as you
oh you mean next to 5 cm? yeah, it's just supposed to show that both triangles are similar
Oh wait nvm are we solving for x?
yes
ah I understand
Seems like your solution is correct.
Author can make mistakes
this book doesn't have a single mistake
screw it, ill talk to the teacher tomorrow
Checked with example in geogebra, seems to be right...
Perhaps it's the answer to another question
Happens
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Can someone explain where I went wrong because I got dne (does not exist) as the answer but it’s wrong
you cant take ln of each thing
use lhopital
i mean really e^2x increases faster
so u just get infinity
but yea use lhopital
differentiate the top and bottom three times
u would get 8e^2x/ 6
so infinity
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
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If 1/x + x = 3, then 1/(x^2) + x^2 =
i tried solving for x, but that got me no where
i tried multiplying 1/x by x/x, so that I could have (x^2) in the denominator, but that didn't do anything
now i don't know what to do
please help
i'm sped as fuck
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what does rationalize mean
It's just the process to eliminate radicals in the denominator
ok thanks
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Given that I know all the green lengths and angles, I need to solve for theta1 for my final answer in terms of a difference of arctangents, I know if I find alpha I can get it, but I'm currently stuck and don't know what step I should take next
This is the question if anyone wants to read it as well
I've found $\cos(\theta_2)=\frac{(a_1)^2+(a_2)^2-x^2-y^2}{2a_1a_2}$
Ninja
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1+j to polar form
how would I do that?
do you know polar form?
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if f(2) = 4 does that mean the inverse will be f^-1(4)=2
yes
No
There may not be an inverse
f need not be an invertible function
But if there is, then you're right
ive been kerboodled, the lack of sleep is killing me, but ive come too far
hold on I thought I didn't have the question but I found it
its part ii)
i explained why f(x) is an inverse because its an lnx graph
Problem is, it isn't. It's a 2x + ln(x) graph
but it passes the horizontal line test
How do you know?
because I graphed it on desmos
Any way you can prove it without using Desmos?
That's the definition of an invertible function, true! How do you know this function in particular is invertible?
I saw it an it has ln in it
Note f(x) = ln(x) - 2x is not invertible
So if it passes a horizontal line test, then it for sure has no maximums or minimums
I don't know then
Well, let me rephrase. If the function has a local maximum, then right below that maximum is a spot the function would fail a horizontal line test
If f has no local maximums/minimums, and is continuous on the domain, then it's gotta be invertible
Note that f(x) = ln(x) - 2x has a maximum
but its 2x + lnx
Right. Just, recognizing a log isn't enough to say whether there's a maximum or minimum.
its 1 mark
how much info do they need
also I want ii) to be answered
did my logic work out right in this context
becaue I got g'(2)=1
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HELP
alr
you should post your question rather than just yell "HELP"
oh mb
i am sorry
I need some assitance on fidning
angle number 3 in the middle row
so part b, angle 3?
Yes.
alright
you found angle 2 already
Yes
do you notice anything about it
ik that there are 2 congruent tick marks
yes those are the congruent sides
what do we call a triangle with two congruent sides?
Isoceles?
isosceles, yes
noice
you've already used the main property of isosceles triangles on ABC to find angle 1
do it again in the same fashion
yes?
this one will be on my test so I have to really study this one
I dont know anyting baout it
oh god two col proofs
this one really confuses me
uh yeah sorry i am not touching this lmao
best if you open a new channel w/ this question though
oh alr
so just .close this one and repost that pic in a new channel
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The questions are in regards to those with a question mark next to it.
I don't understand how to find where a function is odd or even about. For "normal" functions i can just check whether f(-x) = f(x) and so on.
even means f(x) = f(-x)
odd means f(-x) = -f(x)
But how do i figure out at which point a certain figure is odd or even about? If you look at 15. It says it's odd about (2,0)
i guess by about it means using that value as the origin of symmetry
origin for odd, axis for even.
so for (15), when x = 2, thats obv the asymptote
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hi
@hallow mauve Has your question been resolved?
<@&286206848099549185>
@hallow mauve Has your question been resolved?
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.reopen
Yeah those seem to be the easy ones 😅
Could have certainly helped you with those
Imma try my luck on the first one though
I appreciate it
theres also this which I havent looked at yet, so idk how hard it is
I'll attempt it after we tackle A1
Looks reasonably simple at first glance
Not as easy as A2 and A3 though
@grizzled lance Has your question been resolved?
Yeah A1 is very difficult
Lol nvm
😂
It’s super easy once you take the right approach
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If I want to determine if a matrix B is orthogonal, is it sufficient to use B x It’s transpose= identity matrix
it is sufficient to check if B times its transpose (B^T) equals the identity matrix (I)
the product of the matrix and its transpose is the identity matrix
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how do i get cos(y) - 1. because sin(x + y) - sin(x) = sin(y) shouldnt the same relationship be for cos(x + y) - cos(x)?
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I’m not sure if I’m losing my mind or what but I completely forgot how to simplify this
Use exponent rules
These?
Yes
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Solve for x.```
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Unsure about this question.
I know that s = r(theta)
Let me send a screenshot of the previous question since they're all connected.
right
you have arc length and you can find radius by dividing diameter by 2
ya
mhm
*1474.8
,calc 1474.8/260
Result:
5.6723076923077
yeah
Is that it?
now it wants you to convert to degrees
Is it already not in degrees?
nope, s = r(theta) is where theta is in radians
180/pi
Result:
0.099000445416971
Result:
324.99929086882
yep
then round to the nearest degree?
yeah ig
Thanks!
np
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Hello can someone help me figure out how to start simplifying this
okay
or use $sin(a+b)=sin(a)cos(b)+sin(b)cos(a)$
everg
Yeah that works too
in this case $\pi-x+x=\pi$ and $sin(\pi)=0$
everg
i used a,b general real numbers
Don't give away sols
nono yea it wasnt the letters
!nosols
i realized after that the order of sin and cos doesnt matter
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
sura don t copy my answer pls
i wont 😭
you have a brain that works quite well
i like to believe so
thank yall
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sure you 'll go to mac donald if you copy the answer
Should I call mods everg I'm
U don't seem to be taking it seriously
wasn't gonna bother but
ik
and they didnt tell me to google
992qqoloy wdym with Idrc?
I don't rly care if u made the mistake of giving a sol from like not knowing
just that u don't seem to care bout not doing it in the future
Cus u were being all facetiosu
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Basically idrc means I wanna give u the benefit of the doubt this time
i am always facetiosu ...so they are indipendent events
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that looks correct to me
bit uncertain since it says -gradientV
feel like there should be negative sign in front of y^2/2
use the definition when in doubt
multivar calc and/or physics
this is a fundamental law of multivar calc
for instance, let's say you have a curve
it's wonky, crazy, you know it starts as r_0, ends at r_1, and goes through a conservative vector field F
if you can find some f such that Δf = F, then instead of integrating along the curve, you can simply do f(r_1)-f(r_0)
whereas a non-conservative one will require you to suffer because the path matters and you have to parametricize it and suffer
alright
what kind of math vidoes can i watch get the intution down?
what ought i search online?
@last slate Has your question been resolved?
Just do a bunch of problems
From your class's textbook preferably
Then search YouTube for example solved problems
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Can I use combinatorics to solve this problem?
Could i use number theory?
I have a set of integers and I want to split them into three subsets with equal value ( the elements within sum to the same value )
<@&268886789983436800>
Thx ilu
@last slate
Basically no, because we can't make any assumptions about the input vector
what happened here
Advertiser
What field of mathematics do you think I can use?
Are you having trouble with the programming challenge?
I am trying not to program and instead just use math
simpler
i think
It's too random of a problem for math. We don't really know anything about this array, and can't say anything about this array
What if I was to use the input to create a prefix sum array?
idk
Okay nvm
I guess I do have to program
I think I know a way to solve using prefix sum arrays and two pointers
TY for help
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i need help on practicing plugging in my transformation. I always get the B incorrectly, so i want someone to explain how to plug it in correctly.
my step:
k(x) = 1/2 (3(x-4)-4
k(x) = 1/2 (3x-12)-4
k(x) = 3/2x-10 (my answer)
answer is y = 3/2x-6
f(x)=3x-4, not 3(x-4)
that's the mistake
i thought that the 3 was the b
read the f(x) carefully
also this is so incomprehensible lol
so
1/2 (3x-4)-4
yep
OH I GOT IT NOW
just like that
alright give me a question
like a random question?..
uhhh sure
or like wdym lol
some random question about function tranformations?
nvm, i have a practice paper for transformation
it all good
thanks for the help
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hi
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pls help
Taylor series?
I'm not sure
I need to expand until I get a coefficient with x^3 but idk where to start
@left hinge Has your question been resolved?
<@&286206848099549185>
did they give the value of the point of the series expansion ??
no
idk if its Taylor series, binomial expansion perhaps?
it says series expansion
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@left hinge Has your question been resolved?
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im confused by this
here the context btw
MY FICTIOUS AMOUNT IS 19837 SO IM wondering if this method for iii is correct
@idle briar Has your question been resolved?
yeah part 3 looks right
but for part 2, i'd assume that the 10% deposit is on the price of the car, not on how much money you have
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Need help on bottom stuff
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Hello, I need help I'm stuck in a math situation and I don't understand.
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
- I have begun but got stuck midway.
What exactly are you stuck on?
If you can't do it right now, you should close this and repost the question later.
@brittle shale Has your question been resolved?
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how do you find the roots of cot4theta
its not a polynomial
i just dont really understand this solution
Well cot is cos/sin, so when cos4theta is 0 cot4theta is 0
i get that
so youre finding the roots of the cos?
so if you set both the lhs and rhs to zero
so both cot 4 theta = 0 and the big long cot expression to 0
if you find the roots of cot 4 theta, you also find the roots of the big long cot expression
since both are equal?
Yeah
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!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
try to use quadratic formula
are you interested in integer solution right ?
do sum and then divide by 12
do that sum before
yeah? then divide by 12?
OH I GET IT
here wait
I have -8 and 12? is that it
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The bolded text is my response so far. I'm not sure what to say as my proof for scenario 2.
@strange pond Has your question been resolved?
<@&286206848099549185>
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@strange pond Has your question been resolved?
@strange pond Has your question been resolved?
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@leaden mural Has your question been resolved?
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.reopen
✅
@leaden mural Has your question been resolved?
Shayad unit vector mai convert krke ho jaye?
p = (1/a)(unit vector of bxc)
@vale zephyr
Tagging to whom?
bhai tu arjun hai na?, jo bar bar id badal ke question post krta hai?
What???
kya?
u know hindi right?
Yes i know hindi but not fluently
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I'm doing this question and I keep getting ridiculous #s, what am I doing wrong
I have so far:
fx=y - 64x^-2 = 0 fxx = 128x^-3 fxy = 1
fy=x - 64y^-2 = 0 fyy = 128y^-3
Calculated using symbolab: x=8(8)^(1/5) , y=1/(8)^(2/5)
Hessian: 128^2(x^-3)(y^-3) - 1
@last slate Has your question been resolved?
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Yes?
the question
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@last slate Has your question been resolved?
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can someone explain how step 3 becomes step 4?
like im trying to calculate it but im never getting -40.2m/s
!show
Show your work, and if possible, explain where you are stuck.
How did you plug it into your calculator?
like this
-√(35.0)^2+2(-9.81^2)(-20.0)
so i just do (-9.81)
Yeah
Can you send like a screenshot or pictur of your calculator
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oh sorry
what's the answer given
,w plot arcsin(1+x/2) + arcsin(x/2) - arccos(x) for -1<x<0
What's the question
I got in range
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A police car is located 40 feet to the side of a straight road.
A red car is driving along the road in the direction of the police car and is 140 feet up the road from the location of the police car. The police radar reads that the distance between the police car and the red car is decreasing at a rate of 75 feet per second. How fast is the red car actually traveling along the road?
i am really confused abt the wording
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Here’s the other work:
anyway rolle's theorem doesnt really help you find where f'(x) = 0
it only guarantees the existence of at least one such point in an interval
speaking of, on what interval are you considering this function
What do I do next
wait, what was the original function? sin(x/2)?
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suppose you have a function like this:
clearly it is not continuous
but if you were to define it as a pointwise function
what would the value be at x = 0?
it could be anything in [-1,1]
wait maybe it is continuous
no it isn't
Not a function
what i drew above is the pointwise limit of this sequence
so would that mean there is no pointwise limit?
is this occupied
yes
yes
if it has somebody's name on it, it's occupied.
ye just saw it thx
just taking the limit as n tends to infinity of that piecewise function
i see that no f(x) can exist s.t. the sequence will converge to f
so is it possible that a sequence of functions has neither a pointwise nor a uniform limit?
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hey i have a proof problem
a and b are positive integers
and i need to prove that the converse of this statement is true
Like 4|a and 4|b then 4|ab?
but i need to do converse
so
if 4 does not divide ab then 4 does not divide a and 4 does not divide b
i was thinking proof by contradiction
well i tried to do proof by contradiction but i struggled
But you cant contradict something thats true
proof by contradiction is done by assuming the opposite of the converse statement
the opposite of the converse statement will lead to a contradiction which we would come to a conclusion would be that the converse statement is true
a and b have to be different right?
yh
what have you wanted prove ?
cuz their a and b
if 4 does not divide ab then 4 does not divide a and 4 does not divide b
4 does not divide 15 then 4 does not divide 5 and 4 does not divide 3
if wlog 4|a then a=4k then ba=b4k=4(bk) then 4|ab contradiction
take your time, and ask me anything you want ❤️
yes it is
i see
without loss of generality
that if 4 does not divide ab then 4 divides a or 4 divides b, like that
yes
