#help-49

1 messages · Page 14 of 1

magic stone
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Because rational number is any number that can be represented as a/b with a and b being integers

lavish cairn
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Can you say the steps

balmy brook
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there is no step

lavish cairn
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What do I do

balmy brook
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sorry but what age are you ?

lavish cairn
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I do 2x2 and it’s 1/4?

balmy brook
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if you are under 13 y then you can't be here

lavish cairn
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Nvm

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I ddnt know to divide

balmy brook
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are you below 13 ?

lavish cairn
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Can u tell me how do do it pls

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Yo

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To

lavish cairn
balmy brook
# lavish cairn Why🥲

If you are then you can’t be on the server and sorry but for me it’s seems that you are below 13

lavish cairn
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Stop pls

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I didn’t say I’m under 13..

balmy brook
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I know

lavish cairn
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Help pls

balmy brook
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Do you know any rational number inferior to 1/2 or 0.5 ?

lavish cairn
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No

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Yes 0.4 I mean

balmy brook
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Another ?

lavish cairn
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0.3

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0.0

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0.99

lavish cairn
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Is one

balmy brook
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And so on

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Now you need to write it as a fraction

lavish cairn
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How

balmy brook
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I don’t know how to explain it so watch this instead

lavish cairn
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Ok

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They are 25/100 and 5/10?

balmy brook
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5/10 can be simplified as 1/2

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And 25/100 as 1/4

lavish cairn
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Ok

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What is the number in the middle?

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1/3

balmy brook
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What number ?

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1/3 work

lavish cairn
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Ok thx you

midnight plankBOT
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@lavish cairn Has your question been resolved?

vale apex
lavish cairn
#

.close

midnight plankBOT
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north pivot
midnight plankBOT
north pivot
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what concept solves this question

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so i can go study it

upper kindle
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Substitution

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Say the root of an equation is n, that means f(n) = 0

north pivot
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isee thanks

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arctic hollow
midnight plankBOT
arctic hollow
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Uhh for the first one Im thinking like

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Actually

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Idk😭

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400c+2600e<95000

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And for the second one

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20c+120e≤470

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Wat y'all's thoughts

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Oki i got it right

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midnight plankBOT
olive matrix
#

a few things...
when you say "think of literally any number" and then talk about random chance you need to define a distribution for those numbers

second, i don't understand what you mean - are you trying to guess the value of lim{x->inf} 1/x by guessing randomly somehow?

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do u mean like we each guess a real number and if we guess the same number you win? you're going to run into a lot of issues here, mostly around accurately sampling a random real (not just rational) number

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ok that's what i said yeah

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how do u describe an arbitrary real number in a finite amt of time?

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you also need a distribution but the normal distribution will be fine - note that uniform distribution over the reals is meaningless

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like we each write one down right?

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how do i do that for a real number that isn't rational?

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right so how do i communicate my guess to you

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and how do you check if it's right

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painstakingly write out your guess
how

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yep

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and, in fact, is 100% likely to be

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correct but it's 0% likely to be 2

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really it's 0% likely to be any specific value

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nope

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there are more irrationals than rationals

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rationals are countable

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rationals are pairs of integers

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or really smaller than pairs of integers since like 2/3 and 4/6 are the same

next rover
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it doesn't count again, it's 1

olive matrix
steep ledge
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if you only want to prove that rationals are countable and irrationals are not, then it's just the fact that rationals are and it's not hard to prove (bijection between N² and Q is obvious) and that reals are uncountable
if you want to deduce that the probability of getting rational is 0 as Miku said, it's related to the way you define the probability distribution and your measure, which you'll study later

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intuitively, the reason is that you're more or less assuming an uniform distribution, and rationals are very rare in real numbers

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their Lebesgue measure is 0

olive matrix
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yeah but that's not relevant

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rationale is specifically one integer over another

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with some restrictions

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uh

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what about it!

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?

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yes

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it's equal to 11/12

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two integers

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watch that video

steep ledge
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not really meaningless, it's just that you're mashing several questions together at the same time
for example take a disc of radius 1, and throw a dart at it
while it's definitely possible to hit exactly (0, 0), the center, the probability is 0

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but it is definitely possible, since your dart has to hit some point of the disc

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it's once again related to measure theory, intuitively, what happens is that a specific point of the disc represents an area of 0, it doesn't have any area and it's negligible

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so you can only put a 0 weight on it

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but if I told you what's the probability my dart touches the left half, you would have answered 1/2

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since the left half is 1/2 of my area

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when you deal with infinite possibilities, the way you define probabilities has to avoid some problems, and the way to avoid that is to think with measure theory and a somewhat geometrical approach

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if you take a random real number, it's the same idea but with "1 dimension geometry"

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while you'll necessarily get a real number, with probability one, the probability to get a specific number is 0

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it doesn't mean you won't get it, it's just the only probability you can assign to it

olive matrix
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I'd argue that the very idea of choosing a random real number from a continuous distribution is meaningless

btw she glosses over the proof that irrationals are uncountable in that video. it's called Cantor diagonalization and it's very cool, but it requires a lot of precision so that's probably why. I'd recommend looking it up, or trying it yourself (imagine i handed you an infinitely long list of real numbers. can you construct a real number that i missed?)

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it's easy to show that the chance would have to be smaller than any given positive number

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so, the only value we can assign it is zero

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or... zero plus epsilon but that again requires a lot of precision (what's epsilon? how does it work? what can i do with it?)

steep ledge
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intuitively, a probability of 0 means it's almost surely impossible, but not necessarily impossible
something almost surely impossible is when the "area" is 0 because it's nothing compared to the whole probability which represents an area of 1, distributed over infinitely many points
to take my example above once again, the probability that my dart hits the target is 1, but the probability it hits (0, 0) is 0
and same for hitting (0, 1) etc
the probability of hitting either (0, 0) or (0, 1) would be 0 again, because these two points still don't define an area, a consequent part of my target

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but the probability of hitting the right half would be 1/2, because now the event of hitting the right half is not negligible compared to the whole target

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what happens is that you can't compare points to length, area, or volume etc, points don't have any sort of mass (relatively to an infinite set of points), but in the end, a point is still chosen

midnight plankBOT
#

@last slate Has your question been resolved?

olive matrix
#

fun fact: if you've heard of the Halting Problem, this is directly related to the same idea

midnight plankBOT
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robust shale
midnight plankBOT
lyric charm
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what's the question

robust shale
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So

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I'm sort of confused why my book will write it like (e/3)^n but personally I find writing e^n / 3^n to think about the behavior easier. Am I missing something?

lyric charm
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writing this as (e/3)^n makes it more blatant that this is a geometric series with ratio less than 1

robust shale
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hmmm

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okay that's fair

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So with this ratio, wouldn't the num and denom just keep growing?

main current
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,w geometric series

main current
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Huh, didn't expect wolfram to run right into the good stuff. Normally never does

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There's a closed formula for geometric series.

robust shale
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does this look right?

main current
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For Σ 3(e/3)^n?

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Your sum is infinite

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So you don't need the n-1 power

robust shale
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yeah I got here and figured 3 was the a and (e/3) was the common ratio

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darn

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that's wrong

midnight plankBOT
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@robust shale Has your question been resolved?

midnight plankBOT
#

@robust shale Has your question been resolved?

midnight plankBOT
#

@robust shale Has your question been resolved?

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summer hornet
#

I have an ALU that handles the subtraction of 2 binary numbers. It works well for equations like 4 - 2, 4 - 5, or anything similar. But I've decided I want to be able to switch between signed (2's complement) and unsigned. Which works well and all but let's say I was to subtract 128 from 0. The expected output would be 128, but it actually puts out -128. Because the ALU "thinks" that 128 is in 2's complement which means it would be -128. Similar examples would include 11110000 - 00000000 which is equates to -16 in signed binary but to 240 in unsigned binary, but the ALU only supports signed so it will spit out -16 regardless of the signed/unsigned input.

Okay, maybe that was a bit of a confusing question. But TL;DR: how can my ALU work with unsigned inputs? I have a flag that will tell it whether or not the input is signed or unsigned, but I'm not sure how I would process that correctly.

summer hornet
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More examples for clarification would be:
(signed) 11111000 - 00000010 = 11110110 (-8 - 2 = -10)
(unsigned) 11111000 - 00000010 = 11110110 (248 - 2 = 246)
Which would be the same but both of them have the 'negative' flag output by the ALU meaning that the unsigned bit gets interpreted as -10

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So I guess it could be solved by changing the output of the negative flag, but how could I do that (currently the negative flag is based off last bit (the 'sign' bit))

midnight plankBOT
#

@summer hornet Has your question been resolved?

summer hornet
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<@&286206848099549185>

midnight plankBOT
#

@summer hornet Has your question been resolved?

midnight plankBOT
#

@summer hornet Has your question been resolved?

summer hornet
#

I've decided to just make my whole system signed (no more help needed)

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worthy copper
#

Help I got stuck

midnight plankBOT
last slate
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what are you supposed to find?

worthy copper
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x

floral gulch
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i dont think there is an integral ans maybe taking a log would help

floral gulch
worthy copper
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I am meant to use log base 10

floral gulch
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you can use any base

worthy copper
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really?

worthy copper
floral gulch
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yeah finally it would produce the same result

worthy copper
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okok

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ty

floral gulch
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yeah simplify and verify

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np

worthy copper
#

.close

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dusky relic
midnight plankBOT
dusky relic
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Is my process correct???

slender walrus
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no

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division by $\textbf{sin}$ is mega illegal

grand pondBOT
#

ℝαμΩℕωⅤ

dusky relic
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So what is the correct way??

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To find the value of theta?

torn compass
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take arcsin \ sin inverse

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to remove sin

dusky relic
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Huh?

dusky relic
torn compass
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sinx = 0
sin^-1(sinx) = sin^-1 (0)
x = 0

slender walrus
#

<@&268886789983436800>

viral oak
# dusky relic

think of sin(x) as a function that takes in x and returns some value. you cannot say f(x) / f = x

dusky relic
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Im solving how to make the equation equal

viral oak
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sin or f is not a variable that you can cancel

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but you can sometimes take the inverse of a function

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(right now) you can for sin

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taking the inverse of sin(x), gives you x. and taking sin of x, gives you sin(x)

slender walrus
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1 = 2sin(x)
dividing both sides by 2 only gives you
1/2 = sin(x)
taking sin^-1, (its the function inverse NOT the same as 1/sin which is the multiplicative inverse)
gives you one solution for x

viral oak
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<@&268886789983436800>

next rock
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Got them

dusky relic
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How do I inverse the 2sin?

slender walrus
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1 = 2sin(x)
dividing both sides by 2 only gives you
1/2 = sin(x)
taking sin^-1, (its the function inverse NOT the same as 1/sin which is the multiplicative inverse)
gives you one solution for x

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there is an excpetion in notation when that power is -1.
$$\sin^2(x) = \sin(x) \cdot \sin(x)$$
but
$$\sin^{-1}(x) \redneq \frac{1}{\sin(x)}$$

grand pondBOT
#

ℝαμΩℕωⅤ

viral oak
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maybe arcsin is a better way of expressing it...

slender walrus
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gives the angle of the arc from initial to terminal

viral oak
dusky relic
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Wait for context we are just starting trigonometry so I don't have much knowledge yet

slender walrus
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try finding some videos on:
special trig angles and ratios
inverse trig

dusky relic
viral oak
grand pondBOT
viral oak
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this triangle refers to the triangle in the unit circle

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: ). that's a job for the people making the calculators, lol. There are some formulas you can use to approximate the value of arcsin(x) which you can search up if you want to. you can assume it works by magic^TM, and do your calculations for now...

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(actually written this as meant to answer akio. idk your background, srry)

midnight plankBOT
#

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last slate
#

ok

midnight plankBOT
last slate
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so i've solved the hard part of the problem

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now the part that is supposed to be trivial

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i dont understand

viral oak
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so which problem do you mean?

last slate
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im taking a piture of it

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didnt mean to play guessing games

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a = -2 and b = -5 and c = 0

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why is it -2 and -5

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only way it can see is if you take your answer and plug into your very first equation with constants (a,b,c)

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because then you can see why a = -2 etc, but can you not solve the problem just by looking at the last matrix

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but that seems odd to me

shell wigeon
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Maybe it's clearer if you solve a system of equations

robust isle
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I mean what this row reduced form tells you is that is ax_1 + bx_2 + cx_3 = (8,2,-7), then c can be whatever you want, and a+3c = -2, and b+2c = -5

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so if you want fix c=0

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you get a=-2, b=-5

last slate
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if i suppose c = 0

robust isle
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honestly I always think of the linear system behind even if it's just in my head

last slate
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then yeah sure when i re-insert into the first equation i can see its trivial

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a + 0 + 0 = -2

robust isle
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otherwise I fuck it up

last slate
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so the row reduced form doesnt tell you it automatically

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you have to take what you found

shell wigeon
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Tbh you only need to know that the three vectors form a basis; you can get any vector from them

robust isle
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they don't form a basis here lol

shell wigeon
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Oh true my mistake

last slate
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but why must it be c

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that is 0

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the first equation is (a,b,c) and then repeated

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why do i now assume its (c,c,c) = 0?

robust isle
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the 3rd row of the row reduced form tells you no information

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0 = 0

last slate
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i know

robust isle
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so one of a, b, c can be treated as a free variable

last slate
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but why doesnt that say then a + b + c = 0

robust isle
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there's infinitely many possible lin combos that work

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(a,b,c) = (-2, -5, 0), (a,b,c) = (-5, -7, 1), (a,b,c) = (-8, -9, 2), ...

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for each c, you get a lin combo

last slate
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yes but from this picture alone

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or does this picture only tell me there is on x3=x3

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so there is one free varaibel

robust isle
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well yeah

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the last row represents 0a+0b+0c=0

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so you only really have 2 linear equations to satisfy

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(the 2 upper rows)

last slate
#

yh

midnight plankBOT
#

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spiral copper
#

not really sure how to solve for b and theta in this problem

spiral copper
#

I know I use toa to solve B, but I'm not too sure how to get theta

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#

@spiral copper Has your question been resolved?

midnight plankBOT
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@spiral copper Has your question been resolved?

unique cedar
#

Gyazo is not supported for my iPad but just by your response, to solve theta do inverse tangent and divide b by 20

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upbeat herald
midnight plankBOT
upbeat herald
#

Dont understand how to do this one (similar figures)

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First, I thought to do 4/x = 3/5

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To get x = 20/3 but thats wrong

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answer in back of the book says it's root x = 31 - 1

sour kelp
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Are you let; x=a?

upbeat herald
#

wdym

viral laurel
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huh, getting to the same answer as you

sour kelp
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The angle is a

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Not x ;-; (minor mistake lul)

upbeat herald
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oh you mean next to 5 cm? yeah, it's just supposed to show that both triangles are similar

sour kelp
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Oh wait nvm are we solving for x?

upbeat herald
sour kelp
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ah I understand

upbeat herald
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im losing

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mcfuckin mind

viral laurel
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Seems like your solution is correct.

upbeat herald
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yeah but

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book says it's root 31 - 1

viral laurel
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Author can make mistakes

upbeat herald
#

this book doesn't have a single mistake

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screw it, ill talk to the teacher tomorrow

viral laurel
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Checked with example in geogebra, seems to be right...

shell wigeon
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Perhaps it's the answer to another question

viral laurel
upbeat herald
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.closed

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.close

midnight plankBOT
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fading hull
#

Can someone explain where I went wrong because I got dne (does not exist) as the answer but it’s wrong

hearty rune
#

you cant take ln of each thing

lavish venture
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use lhopital

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i mean really e^2x increases faster

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so u just get infinity

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but yea use lhopital

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differentiate the top and bottom three times

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u would get 8e^2x/ 6

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so infinity

midnight plankBOT
# lavish venture so infinity

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

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@fading hull Has your question been resolved?

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last slate
#

If 1/x + x = 3, then 1/(x^2) + x^2 =

midnight plankBOT
last slate
#

i tried solving for x, but that got me no where

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i tried multiplying 1/x by x/x, so that I could have (x^2) in the denominator, but that didn't do anything

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now i don't know what to do

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please help

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i'm sped as fuck

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.close

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last slate
#

.reopen

midnight plankBOT
#

last slate
#

this was so easyu

#

just use (a+b)^2 formula

#

.close

midnight plankBOT
#
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cosmic river
midnight plankBOT
tacit rose
#

Multiply 1/sqrt(3) by sqrt(3)/sqrt(3)

cosmic river
#

what does rationalize mean

hearty rune
#

make the denominator a rational number

#

rather than an irrational one

tacit rose
#

It's just the process to eliminate radicals in the denominator

cosmic river
#

ok thanks

midnight plankBOT
#

@cosmic river Has your question been resolved?

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hardy shadow
#

Given that I know all the green lengths and angles, I need to solve for theta1 for my final answer in terms of a difference of arctangents, I know if I find alpha I can get it, but I'm currently stuck and don't know what step I should take next

hardy shadow
#

This is the question if anyone wants to read it as well

#

I've found $\cos(\theta_2)=\frac{(a_1)^2+(a_2)^2-x^2-y^2}{2a_1a_2}$

grand pondBOT
midnight plankBOT
#

@hardy shadow Has your question been resolved?

midnight plankBOT
#

@hardy shadow Has your question been resolved?

last slate
#

you can ping the helpers

#

this is beyond my knowledge

#

try pinging them

midnight plankBOT
#

@hardy shadow Has your question been resolved?

hardy shadow
#

<@&286206848099549185>

hardy shadow
#

.close

midnight plankBOT
#
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last slate
#

1+j to polar form

midnight plankBOT
last slate
#

how would I do that?

hearty rune
#

do you know polar form?

last slate
#

yes

#

I think

#

this right?

midnight plankBOT
#

@last slate Has your question been resolved?

hearty rune
#

yeah, sorry for my disappearance

#

do you know what r and theta are

midnight plankBOT
#

@last slate Has your question been resolved?

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waxen silo
#

if f(2) = 4 does that mean the inverse will be f^-1(4)=2

hearty rune
#

yes

fallen socket
#

No

sick fossil
fallen socket
#

f need not be an invertible function

sick fossil
#

But if there is, then you're right

hearty rune
#

ive been kerboodled, the lack of sleep is killing me, but ive come too far

waxen silo
#

hold on I thought I didn't have the question but I found it

#

its part ii)

#

i explained why f(x) is an inverse because its an lnx graph

main current
#

Problem is, it isn't. It's a 2x + ln(x) graph

waxen silo
#

but it passes the horizontal line test

main current
#

How do you know?

waxen silo
#

because I graphed it on desmos

main current
#

Any way you can prove it without using Desmos?

waxen silo
#

all values of y have one corresponding x value

#

which allows it have an inverse

main current
#

That's the definition of an invertible function, true! How do you know this function in particular is invertible?

waxen silo
#

I saw it an it has ln in it

main current
#

Note f(x) = ln(x) - 2x is not invertible

#

So if it passes a horizontal line test, then it for sure has no maximums or minimums

waxen silo
#

I don't know then

main current
#

Well, let me rephrase. If the function has a local maximum, then right below that maximum is a spot the function would fail a horizontal line test

waxen silo
#

yes but this graph has no maximum or minimum

#

due to the nature of a log graph

main current
#

If f has no local maximums/minimums, and is continuous on the domain, then it's gotta be invertible

#

Note that f(x) = ln(x) - 2x has a maximum

waxen silo
#

but its 2x + lnx

main current
waxen silo
#

its 1 mark

#

how much info do they need

#

also I want ii) to be answered

#

did my logic work out right in this context

#

becaue I got g'(2)=1

#

.close

midnight plankBOT
#
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near ravine
#

HELP

midnight plankBOT
near ravine
#

alr

lyric charm
#

you should post your question rather than just yell "HELP"

near ravine
#

oh mb

#

i am sorry

#

I need some assitance on fidning

#

angle number 3 in the middle row

lyric charm
#

so part b, angle 3?

near ravine
#

Yes.

lyric charm
#

will be easier if we give names to things

#

give me a minute

near ravine
#

alright

lyric charm
#

you found angle 2 already

near ravine
#

yes

#

122 degrees

lyric charm
#

look at triangle BCD

near ravine
#

Yes

lyric charm
#

do you notice anything about it

near ravine
#

ik that there are 2 congruent tick marks

lyric charm
#

indeed, two of the sides are congruent

#

what does this mean

near ravine
lyric charm
#

yes those are the congruent sides

#

what do we call a triangle with two congruent sides?

near ravine
#

Isoceles?

lyric charm
#

isosceles, yes

near ravine
#

noice

lyric charm
#

you've already used the main property of isosceles triangles on ABC to find angle 1

#

do it again in the same fashion

near ravine
#

ohh

#

so

#

180-122

#

58

#

58/2

#

Thank you

#

I have one more question sorry

lyric charm
#

yes?

near ravine
#

this one will be on my test so I have to really study this one

#

I dont know anyting baout it

lyric charm
#

oh god two col proofs

near ravine
#

this one really confuses me

lyric charm
#

uh yeah sorry i am not touching this lmao

#

best if you open a new channel w/ this question though

near ravine
#

oh alr

lyric charm
#

so just .close this one and repost that pic in a new channel

near ravine
#

so

#

open it

#

in help 10

#

.close

midnight plankBOT
#
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whole moon
#

The questions are in regards to those with a question mark next to it.
I don't understand how to find where a function is odd or even about. For "normal" functions i can just check whether f(-x) = f(x) and so on.

verbal rain
#

even means f(x) = f(-x)
odd means f(-x) = -f(x)

whole moon
#

But how do i figure out at which point a certain figure is odd or even about? If you look at 15. It says it's odd about (2,0)

verbal rain
#

i guess by about it means using that value as the origin of symmetry

#

origin for odd, axis for even.

#

so for (15), when x = 2, thats obv the asymptote

whole moon
#

.close

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hallow mauve
#

hi

midnight plankBOT
hallow mauve
#

can someone pls help me with this?

midnight plankBOT
#

@hallow mauve Has your question been resolved?

hallow mauve
#

<@&286206848099549185>

midnight plankBOT
#

@hallow mauve Has your question been resolved?

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hallow mauve
#

.reopen

grizzled lance
midnight plankBOT
grizzled lance
#

@storm spindle

#

I think I solved A2 and A3

#

but im lost on a1

storm spindle
#

Could have certainly helped you with those

#

Imma try my luck on the first one though

grizzled lance
#

I appreciate it

#

theres also this which I havent looked at yet, so idk how hard it is

#

I'll attempt it after we tackle A1

storm spindle
#

Not as easy as A2 and A3 though

midnight plankBOT
#

@grizzled lance Has your question been resolved?

storm spindle
#

Lol nvm

#

😂

#

It’s super easy once you take the right approach

midnight plankBOT
#
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storm spindle
#

@grizzled lance

#

Reopen this ffs

#

@grizzled lance fast

midnight plankBOT
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daring lark
#

Am i on the right track? Or am i not going anywhere

#

Oh wait i did a mistake

midnight plankBOT
#
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tiny gate
#

If I want to determine if a matrix B is orthogonal, is it sufficient to use B x It’s transpose= identity matrix

hazy bear
#

the product of the matrix and its transpose is the identity matrix

tiny gate
#

Thank you

#

.close

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crude lichen
#

how do i get cos(y) - 1. because sin(x + y) - sin(x) = sin(y) shouldnt the same relationship be for cos(x + y) - cos(x)?

crude lichen
#

.close

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remote fossil
#

I’m not sure if I’m losing my mind or what but I completely forgot how to simplify this

remote fossil
#

And the few Answers said I was wrong

#

Sooo 😅

remote fossil
#

These?

blissful trench
#

Yes

remote fossil
#

Oh ok

#

Thanks!

#

.close

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gilded chasm
#
Solve for x.```
midnight plankBOT
gilded chasm
#

ive been told that you have to find a common base but 87 isnt perfect

#

nvm

#

.close

midnight plankBOT
#
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tidal ice
midnight plankBOT
tidal ice
#

Unsure about this question.

#

I know that s = r(theta)

#

Let me send a screenshot of the previous question since they're all connected.

cosmic elk
#

you have arc length and you can find radius by dividing diameter by 2

tidal ice
#

560/2

#

r = 260

cosmic elk
#

ya

tidal ice
#

1478.8 = 260(theta)

#

divide both sides by 260?

cosmic elk
#

mhm

cosmic elk
tidal ice
#

I got 5.672307692

#

good?

cosmic elk
#

,calc 1474.8/260

grand pondBOT
#

Result:

5.6723076923077
cosmic elk
#

yeah

tidal ice
#

Is that it?

cosmic elk
#

now it wants you to convert to degrees

tidal ice
#

Is it already not in degrees?

cosmic elk
#

nope, s = r(theta) is where theta is in radians

tidal ice
#

So we multiply by pi/180

#

,calc (1474.8/260) * pi/180

cosmic elk
#

180/pi

grand pondBOT
#

Result:

0.099000445416971
tidal ice
#

oops.

#

,calc (1474.8/260) * 180/pi

grand pondBOT
#

Result:

324.99929086882
cosmic elk
#

yep

tidal ice
#

then round to the nearest degree?

cosmic elk
#

yeah ig

tidal ice
#

Thanks!

cosmic elk
#

np

tidal ice
#

.close

midnight plankBOT
#
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midnight plankBOT
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wary mauve
#

Hello can someone help me figure out how to start simplifying this

wary mauve
potent veldt
#

Google trig identities catthumbsup

#

Specifically for cos(pi - x) and sin(pi - x)

wary mauve
#

okay

steep hinge
#

or use $sin(a+b)=sin(a)cos(b)+sin(b)cos(a)$

grand pondBOT
wary mauve
#

no thats not the same?

#

wait

potent veldt
#

Yeah that works too

steep hinge
#

in this case $\pi-x+x=\pi$ and $sin(\pi)=0$

grand pondBOT
steep hinge
potent veldt
wary mauve
#

nono yea it wasnt the letters

potent veldt
#

!nosols

wary mauve
#

i realized after that the order of sin and cos doesnt matter

midnight plankBOT
#

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

steep hinge
wary mauve
#

i wont 😭

steep hinge
#

you have a brain that works quite well

potent veldt
#

idr if u do it now but don't do it in the future

#

Idrc

wary mauve
#

thank yall

#

.close

midnight plankBOT
#
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steep hinge
#

sure you 'll go to mac donald if you copy the answer

potent veldt
#

Should I call mods everg I'm

#

U don't seem to be taking it seriously

#

wasn't gonna bother but

wary mauve
#

bro is freaking out

#

it's not a big deal at least I know how to solve it now

potent veldt
#

ik

wary mauve
#

and they didnt tell me to google

potent veldt
#

Idc bout u getting this sol

#

Is that hes gonna do it again

wary mauve
#

omg

#

i closed the channel

steep hinge
#

992qqoloy wdym with Idrc?

potent veldt
#

I don't rly care if u made the mistake of giving a sol from like not knowing

#

just that u don't seem to care bout not doing it in the future

#

Cus u were being all facetiosu

midnight plankBOT
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potent veldt
#

Basically idrc means I wanna give u the benefit of the doubt this time

steep hinge
potent veldt
#

.close

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last slate
midnight plankBOT
last slate
#

WOuld this be correct

#

i am a bit uncertain :/

still rose
#

that looks correct to me

last slate
#

bit uncertain since it says -gradientV

still rose
#

ah then just make it negative

#

that's just physics semantics lol

last slate
#

feel like there should be negative sign in front of y^2/2

still rose
#

use the definition when in doubt

last slate
#

what branch of math is this under?

#

i have not seen this before yet it is a question

still rose
#

multivar calc and/or physics

#

this is a fundamental law of multivar calc

#

for instance, let's say you have a curve

#

it's wonky, crazy, you know it starts as r_0, ends at r_1, and goes through a conservative vector field F

last slate
#

conservative vector field

#

so it only cares about intial and final

still rose
#

if you can find some f such that Δf = F, then instead of integrating along the curve, you can simply do f(r_1)-f(r_0)

#

whereas a non-conservative one will require you to suffer because the path matters and you have to parametricize it and suffer

last slate
#

alright

#

what kind of math vidoes can i watch get the intution down?

#

what ought i search online?

midnight plankBOT
#

@last slate Has your question been resolved?

fallow scarab
#

Just do a bunch of problems

#

From your class's textbook preferably

#

Then search YouTube for example solved problems

last slate
#

there arent any

#

i only knew what −∇V meant as assumed you should do as i did

midnight plankBOT
#
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last slate
#

Can I use combinatorics to solve this problem?

midnight plankBOT
last slate
#

Could i use number theory?

#

I have a set of integers and I want to split them into three subsets with equal value ( the elements within sum to the same value )

main current
#

<@&268886789983436800>

#

Thx ilu

#

@last slate
Basically no, because we can't make any assumptions about the input vector

last slate
main current
#

Advertiser

last slate
main current
#

Are you having trouble with the programming challenge?

last slate
#

simpler

#

i think

main current
#

It's too random of a problem for math. We don't really know anything about this array, and can't say anything about this array

last slate
#

What if I was to use the input to create a prefix sum array?

#

idk

#

Okay nvm

#

I guess I do have to program

#

I think I know a way to solve using prefix sum arrays and two pointers

#

TY for help

#

.close

midnight plankBOT
#
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halcyon escarp
#

i need help on practicing plugging in my transformation. I always get the B incorrectly, so i want someone to explain how to plug it in correctly.

my step:
k(x) = 1/2 (3(x-4)-4
k(x) = 1/2 (3x-12)-4
k(x) = 3/2x-10 (my answer)

answer is y = 3/2x-6

fresh sparrow
#

that's the mistake

halcyon escarp
fresh sparrow
#

read the f(x) carefully

fresh sparrow
halcyon escarp
#

so

1/2 (3x-4)-4

fresh sparrow
#

firstly you need to have the understanding

#

then cheatsheets

fresh sparrow
halcyon escarp
#

OH I GOT IT NOW

fresh sparrow
#

just like that

halcyon escarp
#

alright give me a question

fresh sparrow
#

like a random question?..

halcyon escarp
#

uhhh sure

fresh sparrow
#

some random question about function tranformations?

halcyon escarp
#

nvm, i have a practice paper for transformation

#

it all good

#

thanks for the help

#

.close

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unique cedar
#

hi

midnight plankBOT
unique cedar
#

what does a^c mean in terms of sets

fresh sparrow
#

complement

#

basically everything that is not in a

unique cedar
#

ok. Thank you so much

#

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left hinge
midnight plankBOT
left hinge
#

pls help

olive path
#

Taylor series?

left hinge
#

I'm not sure

#

I need to expand until I get a coefficient with x^3 but idk where to start

midnight plankBOT
#

@left hinge Has your question been resolved?

left hinge
#

<@&286206848099549185>

wintry cave
# left hinge

did they give the value of the point of the series expansion ??

left hinge
#

idk if its Taylor series, binomial expansion perhaps?

wintry cave
#

it says series expansion

midnight plankBOT
#

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@left hinge Has your question been resolved?

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idle briar
#

im confused by this

midnight plankBOT
idle briar
#

here the context btw

#

MY FICTIOUS AMOUNT IS 19837 SO IM wondering if this method for iii is correct

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dense idol
#

yeah part 3 looks right
but for part 2, i'd assume that the 10% deposit is on the price of the car, not on how much money you have

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clever palm
#

Need help on bottom stuff

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brittle shale
#

<@&286206848099549185>

midnight plankBOT
midnight plankBOT
# brittle shale <@&286206848099549185>

Please only use the <@&286206848099549185> ping once if your question has not been answered for 15 minutes. Please do not ping or DM individual users about your question.

brittle shale
#

Hello, I need help I'm stuck in a math situation and I don't understand.

tribal temple
brittle shale
midnight plankBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
brittle shale
#
  1. I have begun but got stuck midway.
tacit rose
#

What exactly are you stuck on?

brittle shale
#

nvm, I cannot do this right now.

#

family issues

wary epoch
#

If you can't do it right now, you should close this and repost the question later.

midnight plankBOT
#

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orchid iris
midnight plankBOT
orchid iris
#

how do you find the roots of cot4theta

#

its not a polynomial

#

i just dont really understand this solution

fallen vigil
orchid iris
#

i get that

#

so youre finding the roots of the cos?

#

so if you set both the lhs and rhs to zero

#

so both cot 4 theta = 0 and the big long cot expression to 0

#

if you find the roots of cot 4 theta, you also find the roots of the big long cot expression

#

since both are equal?

fallen vigil
#

Yeah

orchid iris
#

.close

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open dew
midnight plankBOT
vale zephyr
#

!status

midnight plankBOT
#
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
steep hinge
#

try to use quadratic formula

open dew
#

alright

#

That's hella wrong

#

what did I mess up?

steep hinge
#

are you interested in integer solution right ?

open dew
#

Idk the answer is 2/5 and 1

#

I have no clue how to get that

steep hinge
#

do sum and then divide by 12

open dew
#

okay

#

wait like 54 ÷12?

steep hinge
#

do that sum before

open dew
#

yeah? then divide by 12?

#

OH I GET IT

#

here wait

#

I have -8 and 12? is that it

#

.close

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strange pond
#

The bolded text is my response so far. I'm not sure what to say as my proof for scenario 2.

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#

@strange pond Has your question been resolved?

strange pond
#

<@&286206848099549185>

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leaden mural
midnight plankBOT
#

Please don't occupy multiple help channels.

leaden mural
#

<@&286206848099549185>

midnight plankBOT
#

@leaden mural Has your question been resolved?

leaden mural
#

.close

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leaden mural
#

.reopen

midnight plankBOT
#

midnight plankBOT
#

@leaden mural Has your question been resolved?

last slate
#

p = (1/a)(unit vector of bxc)

#

@vale zephyr

leaden mural
#

Tagging to whom?

vale zephyr
#

bhai tu arjun hai na?, jo bar bar id badal ke question post krta hai?

leaden mural
#

What???

vale zephyr
vale zephyr
leaden mural
#

Yes i know hindi but not fluently

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#

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last slate
#

I'm doing this question and I keep getting ridiculous #s, what am I doing wrong

last slate
#

I have so far:
fx=y - 64x^-2 = 0 fxx = 128x^-3 fxy = 1
fy=x - 64y^-2 = 0 fyy = 128y^-3
Calculated using symbolab: x=8(8)^(1/5) , y=1/(8)^(2/5)

Hessian: 128^2(x^-3)(y^-3) - 1

midnight plankBOT
#

@last slate Has your question been resolved?

last slate
#

<@&286206848099549185>

limpid wraith
last slate
#

the question

midnight plankBOT
#

@last slate Has your question been resolved?

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#

@last slate Has your question been resolved?

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craggy arrow
#

can someone explain how step 3 becomes step 4?

craggy arrow
#

like im trying to calculate it but im never getting -40.2m/s

hard shard
#

!show

midnight plankBOT
#

Show your work, and if possible, explain where you are stuck.

hard shard
#

How did you plug it into your calculator?

craggy arrow
hard shard
#

The ² is for the m/s²

#

You dont add it

#

It should be -sqrt((35.0)²+2(-9.81)(-20.0))

craggy arrow
#

so i just do (-9.81)

hard shard
#

Yeah

craggy arrow
#

it gives me 6872

#

6872.603428

#

oh wait

hard shard
#

Can you send like a screenshot or pictur of your calculator

craggy arrow
#

i know why

#

cause i didnt put the square root over the whole hing

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spring heron
midnight plankBOT
#

Please don't occupy multiple help channels.

spring heron
#

oh sorry

nocturne jetty
fallow scarab
#

,w plot arcsin(1+x/2) + arcsin(x/2) - arccos(x) for -1<x<0

fallow scarab
nocturne jetty
#

I got in range

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topaz hamlet
midnight plankBOT
topaz hamlet
#

A police car is located 40 feet to the side of a straight road.

A red car is driving along the road in the direction of the police car and is 140 feet up the road from the location of the police car. The police radar reads that the distance between the police car and the red car is decreasing at a rate of 75 feet per second. How fast is the red car actually traveling along the road?

#

i am really confused abt the wording

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#

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round mural
midnight plankBOT
round mural
#

Using rollers theorem to find when f’(x) = 0

#

I’m confused what to do next

lyric charm
#

rollers theorem

#

🛼

round mural
#

Here’s the other work:

lyric charm
#

anyway rolle's theorem doesnt really help you find where f'(x) = 0

#

it only guarantees the existence of at least one such point in an interval

#

speaking of, on what interval are you considering this function

round mural
round mural
lyric charm
#

wait, what was the original function? sin(x/2)?

round mural
#

Yeah

#

Mb

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#

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round mural
#

.close

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placid vessel
#

suppose you have a function like this:

midnight plankBOT
placid vessel
#

clearly it is not continuous

#

but if you were to define it as a pointwise function

#

what would the value be at x = 0?

#

it could be anything in [-1,1]

#

wait maybe it is continuous

#

no it isn't

languid scroll
#

Not a function

placid vessel
#

what i drew above is the pointwise limit of this sequence

#

so would that mean there is no pointwise limit?

dry lance
#

is this occupied

placid vessel
#

yes

hearty rune
#

yes

lyric charm
dry lance
placid vessel
#

just taking the limit as n tends to infinity of that piecewise function

#

i see that no f(x) can exist s.t. the sequence will converge to f

#

so is it possible that a sequence of functions has neither a pointwise nor a uniform limit?

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#

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glossy pagoda
#

hey i have a proof problem

midnight plankBOT
glossy pagoda
#

a and b are positive integers

#

and i need to prove that the converse of this statement is true

trail quartz
#

Like 4|a and 4|b then 4|ab?

glossy pagoda
#

yh but it has that small line going through the line

#

meaning does not divide

glossy pagoda
#

so

#

if 4 does not divide ab then 4 does not divide a and 4 does not divide b

#

i was thinking proof by contradiction

#

well i tried to do proof by contradiction but i struggled

trail quartz
#

But you cant contradict something thats true

glossy pagoda
#

proof by contradiction is done by assuming the opposite of the converse statement

#

the opposite of the converse statement will lead to a contradiction which we would come to a conclusion would be that the converse statement is true

trail quartz
#

a and b have to be different right?

glossy pagoda
#

yh

steep hinge
#

what have you wanted prove ?

glossy pagoda
#

cuz their a and b

glossy pagoda
#

4 does not divide 15 then 4 does not divide 5 and 4 does not divide 3

steep hinge
#

if wlog 4|a then a=4k then ba=b4k=4(bk) then 4|ab contradiction

glossy pagoda
#

xD

#

im tryna understand it

steep hinge
#

take your time, and ask me anything you want ❤️

glossy pagoda
#

so thats the proof by contradiction

#

what is wlog

#

?

steep hinge
#

yes it is

glossy pagoda
steep hinge
#

without loss of generality

glossy pagoda
#

oh

#

wait

#

so what would be the assumption

steep hinge
#

4|a or 4|b

#

so "without loss of generality" i assumed 4|a

glossy pagoda
#

that if 4 does not divide ab then 4 divides a or 4 divides b, like that

steep hinge
#

yes