#help-49
1 messages · Page 13 of 1
ye u can use WE theorem
i was just abt to type that lol
but kinematics is enough
if u wanna use WE go ahead ig
ok how to do it with kinemtaics?
i thought i was doing correct
above
either is fine with me
W+ K_i = K_F, then (1150-625)(40) + 0.5(90)(0^2) = 0.5(90)(v_f)^2
thats how u do it with WE thm
with kinematics you can do
(1150-625) = 90 * a, v_f ^ 2 = v_i^2 + 2ad
you should get the same answer for both
just 2 different approaches
ok i will get back to u in a sec
if ur using WE, u dont need to calc acceleration
i see so i think my kinematics thing was correct just was using a wrong value
for the net force
anways
ty 🙏
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u can easily determine a
draw the diagonal, it might help u visualize it
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This question confuses me. Is it asking me to find the lim or derivative?
The limit is part of the definition of the derivative
By finding the limit of that equation, you get the derivative of the function sin(pi/3)
limit = derivative?
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correct?
yes
what about this one
!show
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Correct, also cool name
so to get the same denomotar i made it 2/8 then minused
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good, that's right
Thanks
im just double checking my answer rn
because im paranoid
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Did i miss something over here?
I need both 20 and 3 to be negative to add up to -23 but I also need to multiply to -60
<@&286206848099549185>
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I cant visualize this question
if that makes sense
i dont understand the wording
<@&286206848099549185>
what are the 3 focal points ?
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@last slate find the compound interest for year 11 and year 19
what abt the 2 equal payments ??
do i only need to solve for 1 of them
bcs theyre equal anyways
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Is this the right setup
<@&286206848099549185> pls help me sorry for the ping
seems reasonable. What did you get for x?
Should mention that technically it’s reciprocated, but if t1=t2 then 1/t1=1/t2 so
What
which is t1 and which is t2
they're saying that it makes more sense for you have them "flipped", i, e, 400/(x + 5) = 360/(x)
but it doesnt' technically matter in this specific example
Oh ok
t1 and t2 are just other words for variables. The key here is that it's the same amount of time taken for both trips
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,rccw
yep that seems reasonable! Let's see if they come out to the same amount of time
,calc 400/50
Result:
8
,calc 360/45
Result:
8
How do you tell which is numerator and which is in denominator
cool
In the context of the rational word problems
This is where units are helpful. You'll learn about something called "dimensional analysis" at some point
the only problem is that I have a test on this tomorrow
ah ok
so let's take this example
speed is usually calculated as "miles per hour" aka "miles/hour" aka "mph" etc, right?
yes
ok
wouldn’t speed be equal to the ratio and not in the ratio
can you clarify what you mean by that?
they mean the same thing. "per" in this case would be "divided by"
colloquially
ok
so let's take your example
give me some time to set this up please
Wait
The ratios are equal to time, so it’s just h/mph?
Like they’re algebraicly swapped
like this one
,rccw
Say if you we know that the average speed is 45 miles per hour and we know that we traveled 360 miles. We want to know how long it took.
$\\$
So we can set up a ratio and orient our units based on our goal. We want to know how long it too.
$\\$
So we have: $\frac{45 \text{ miles}}{1 \text{ hours}} \cdot \frac{1}{360 \text{ miles}} = \frac{45 \text{ miles}}{360 \text{ hours} \cdot \text{ miles}} = \frac{1}{8 \text{ hours}}$. We can cancel out the miles since we have both units in the numerator and denominator.
$\\$
However, $\frac{1}{8 \text{ hours}}$ doesn't make a whole lot of sense for this context. If we flipped it at the beginning then we could have the miles be the correct unit.
$\\$
$\frac{1 \text{ hours}}{45 \text{ miles}} \cdot \frac{360 \text{ miles}}{1} = \frac{360 \text{ hours} \cdot \text{ miles}}{45 \text{ miles}} = \frac{8 \text{ hours}}{1} = 8$ hours.
ugh hold on
Hey, can anyone help me with this... Kind of basic but I've been working on it for several hours and can't get it.. it's the last (bottom) problem
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Pretty much yeah.
In this example, it's simple enough (and what I assuming what you'll be working on for this section) where you can just probably flip it and get the proper answer.
But sometimes the orientation matters
hey I gotta head out for a bit but hopefully that example made sense
good luck with your test tomorrow
@rose kayak is that 8mph
Thanks
no in this case it'd just be 8 miles
NO WAIT
sorry
it'd be 8 hours
let me correc that real quic
MellowDramaLlama
just read through that part step by step
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can someone help me b and c?
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no one helped 💀
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try working out conditions to be in kerL then pick out a basis
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Try finding an element of ker L
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For the top question how do I make an expression for area?
I know how to fix and I will I’m just asking about area idk how to express it
18x + 4
A = LW
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Greetings from laptop
I have a inquisition into a mater that involved number theory.
I know that a number n evenly divides a number a if $a = nk$ for some integer value k
<:F_button:1095679234497843251>
How would I use this knowledge to figure out if a number [a] is divisible by some number b who's digits are the number n
I'm asking this question because of this problem
https://codeforces.com/problemset/problem/122/A
Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find out if the given number n is almost lucky.
4
7
47, 74, 77, 44
777, 774,744, 444, 447, 477, 474, 747
are lucky numbers
If the number I'm checking is less than 1000 I would have to check if my number is divisible by any of the above lucky numbers
that would make sense
you don't have to check the repeating ones
77,44,777 and 444
744 is also redundant
This was the trival solution i came up with
fn main() {
let mut scanner = Scanner::default();
//Gets number from standard input
let number:usize = scanner.next();
let almost_lucky:bool = Vec::from([
4usize,7usize,
47usize,74,44usize,77usize,
444usize,777usize,447usize,477usize,774usize,744usize,747usize,474usize
])
.iter()
.any(|lucky| number % lucky == 0);
println!("{}",
if almost_lucky { "YES" } else { "NO" }
);
}
But there has to be a way that doesn't involve enumerating all the possible lucky numbers
to generate them, you can notice that the lucky numbers are of the form sum a_k * 10^k where a_k is either 4 or 7
you can generate the list of lucky number with a simple list
a for loop that goes through all theses sums gives every lucky number
I do not want to generate them either
if the number im checking is extremely large then generating them might not work
you can't predict every single lucky number tho, bc of Dirichlet theorem
the further you go, you'll eventually get prime lucky numbers again and again
and if you could predict their pattern, you would be solving some part of millenium problems

That is surprising
I have not learnt enough about number theory to know Dirichlet theorem
I am saddened to know there is no O(1) solution to this
TY for help
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A group of friends decides to share a cake. If it takes Alice $2$ hours to eat the entire cake, Bob $3$ hours, and Carol $4$ hours, how long will it take them to eat the cake together?
Akira 🍇
!status
What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
4. I got an answer and would like my work checked.
5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
1
i dont remember why we do this, i learned this like 2 years ago, but we take thier least common mulitple iirc
how
Think in terms of rates.
Alice eats 1/2 of a cake in an hour
Bob eats 1/3 of a cake
Carol eats 1/4 of a cake
How much do they eat in an hour combined
Akira 🍇
solve for t now?
That's exactly it
i would put it as t, not 1/t. It's gonna be easier to work with
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You can sum them for a rate, but then you have to flip that for the time taken
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quick notational question @steep ledge
Sorryyyy
so I got the basis
and everything but the last one is skew symmetric
so it should be something like [0 0 0 2]
f(A) = A - A^T
basis is {[1 0 | 0 0], [0 0 | 0 1], [ 0 1 | 1 0], [0 1 | -1 0]}
f(A) = null matrix if A is symmetric, and 2A if skew
yeah
so [0, 0, 0, 2]
is [f]b a notation to say image of the basis in the basis ?
if yes, I guess so
but that seems weird use of notation
uh yeah
the notation is so confusing
I know how this works
the problem is that the definition of the notation isn't in this theorem
yeah
but I guess [0, 0, 0, 2] makes sense if it means image of something expressed in basis B
so it's good?
I'm so confused lmao
but like shouldn't it be a constant
like$[0, 0, 0, 2x_4]$
nosqldb
again, I simply don't know this notation
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could someone explain why theres a 3 here?

could you care to highlight that? I cannot see it in the answer
btw I have a slight understanding on how this stuff works
so I may falter under some explaination, I apologise in advance
Afi
wait... what??
Ok lemme ask you what is P’(Alpha)
oh, if I were to put all the roots in like (x+a)(x+b)(x+y)
and expand it
I would get 3 b's
is that what your saying?
Not rly
$P’(x)= 3x^2 + 2ax + b$
Afi
mhm I understand that
Just plug in x=alpha
Write down what you get after plug in x=beta and x=gamma
oh you do get 3b's
Add all of them together and what will you get
WOW THIS MAKES MORE SENSE NOW
3a^2+ 3B^2+ 3y^2 + 2aA +2aB +2ay + 3b
facortise 3 and 2 out respectively
Yes and a can be factorised out too

goode gawd
it all makes sense now
I get it now
thank you for the help
could I quickly ask just one more related to this?
Sure
I just want to understand the correlation of this
the top part
I know its to do when you add all the roots together and they correlate to the P(x) becuase math laws
Those two parts are independent
The first part is the given info
The second part is what you write down
You have $\alpha, \beta, \gamma$ as the roots of $P(x)$
and so and so
Afi
mhm I get that
From here
Well it’s called Vieta formula
Or more intuitively
Think of $P(x)=a(x-\alpha)(x-\beta)(x-\gamma)$
Afi
ok know what Vieta's formula are
I assume if we were to expand this, every coefficient of x would line up to something right?
oh boy time to expand a cubic 
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bit new to recipirocal functions, i got the top part (local max=local min for reciprocal functions), but the bottom two I don't understand why they have a point there and cross through the parabola
what is the equation of the function and what is the equation of its reciprocal
Any time the function crosses through y = 1 or y = -1, you could put one of those points
so reciprocal is constant if there are 1's
Because those are the numbers that aren't changed when you take a reciprocal
1/(1) = (1)
1/(-1) = (-1)
Yeah you could say that too
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How to prove this using proof by exhaustion?
For every n ∈ N, n(n+1) is even
I understand the concept but I don't know how to use it in practice
So, for any natural number, it can be one of two things
what are those two things?
odd and even?
in proofs involving parity, it is sometimes (but not always) to split into two cases based on parity of one thing or another
yes
so you can consider both cases individually
i.e. consider when n is even and also consider when n is odd
writing this down
once you are done writing that, do you know how to represent an even number, to start with the even case?
2k for an even number and 2k+1 for an odd number ?
yeah
so start with n = 2k
substitute that into your expression
observe what your resultant expression would be
I'm sorry I don't understand why we assume that n is even, we're supposed to prove that n(n+1) is even
Its a proof by exhaustion
So what we are doing is this
suppose n is odd
we know that n can be any natural number
then n+1 = even
even * odd = even
suppose n= even
well then it's even easier
since even*anything is even
we break into two cases
one case in which n is even
thus we have exhausted the two cases
the other case in which n is odd
odd numbers + even numbers = the entirety of the natural numbers
so if you can verify that both the even and odd n's give you an even expression, then you thus verify it for the entirety of the natural numbers as well
ok i will leave 3 helpers will just confuse
thanks for your time!
so suppose that n is even so n=2k and then from that we build to n(n+1)?
no
N= even, then we have that n(n+1)= even
that is because even* anything is even
and for n= odd we have that n+1=even
so we again have even*anything=even
okay got this
so we got the first case, the when n is even
now we check for when n is odd
Yes
Or even easier to visualise
n and n+1 are two consecutive numbers
so one must be even and one must be odd
and since we're multiplying them, it doesn't matter which one is odd or even
since odd*even=eventimesodd
and that is also equal to even
since 2k(2n+1)=4kn+2k=2(2kn+k)
okayokay that makes sense
ok
what happens when we check for the second case tho? when n is odd
oh wait
yes
try plugging n=2k=1
but why
wait sorry
2k+1
forgor to hold shift
and that is because 2k is even and when we add 1 to an even we get an odd
why would we plug it? and plug it where? im confused
to n(n+1)
when n is even, n=2k
when n is odd, n=2k+1
plug each value into the equation
and see how it works out
what can you say about the number 4k^2 + 2k
I can write it as 2(2k^2+1) which means it's an even number times an odd number which means it's even?
that makes sense
no way
where did the 2 come from
plug in 2k+1 for n
oh wait I got it i got it
n+1=2k+1 +1
I forgot about the n
yes so we get 4k^2 + 6k +2 right?
yeah
and it's a multiple of 2 so it's even
yeah
So you've exhausted both cases
When n=even and where n=odd
and you've shown that n(n+1) is even for both of them
okay thanks a lot for the help!!
first year computer science
wait so like university
yep
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there you go
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what would be a domain for this?
0 through 5?
wdym 4.5?
whats the difference?
idk what domain really means in english lmao
domain of V is like values of V?
or values of x?
x
Volume has to be >0 right
infinity
what about this
The reasonable domain for V is x ∈ [0,9].
did you write v(x) correctly?
the function?
my equation?
Yes
I forgot to read the first part
now it's obvious
x>0
9-2x>0
=>9>2x
=>x<4.5
so 4,5>x>0
so we have x=(0;4.5)
so 0≤x≤4.5
thats fine tho, no?
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in a poker hand consisting of 5 cards, find the probability of holding 2 aces and 3 jacks
so uh, im not quite familiar with how poker is played usually
poker has 52 cards
yeah
4 of them are aces (ace of hearts/spades/clubs/diamonds)
4 of them are jacks (jack of hearts/spades/clubs/diamonds)
Do you remember the full house question?
no sadly its been a bit, but i do remember our discussion
aces are not distinguisable from each other right
the problem is not asking for specific types of aces in your hand
so they are not distinguishable
a hand is uniformly one of 52c5 hands
okay so
it's just counting combinations, you can phrase it with people
lets find the sample space first i suppose
so our sample space is
any set of hands
which is $\ds \binom{52}5$
absolutely
so,
we are trying to find the possibility of being dealt 2 aces and 3 jacks
there are 4 cards of each
so
Assuming that $A$ is the event that you get 2 aces and 3 jacks: [
\map P A = \f{\binom 4 2 \binom 4 3}{\binom{52}5}
]
right?
yes
okay this might sound really weird but im like in the middle of like distingushing between when to be considering permutations and combinations.
What would you modify in the original scenario to turn that 52c5 to like 52p5
just for my own understanding
you don't have to modify it, it would give the same answer if you do permutations
okay no
like your sample space becomes 52p5
but then 4p2 × 4p3 undercounts hands
it makes you only consider hands that look like AAJJJ, but it could be JAJAJ
if the question said something like first 2 cards you pick need to be aces and next 3 should be jacks, then you'd do permutations
basically if its asking that something needs to be in a specific order
you do permutations
(4p2 × 4p3 × 5c2) / 52p5 would work
and if order doesnt matter you do combinations
ok the "ordeR" becomes a bit vague in some situations
but i get your idea yes
okay as another exercise
lets calculate the chance of getting the royal flush
combination is essentially amounts
a multiset
"3 of something and 6 of something"
to visualize it, you put the elements in some sort of fixed order like alphabetically
for number of royal flushes you dont need anything you can just count them, spade, clubs hearts and diamond = 4 possible royal flushes
and for probability just divide by 52C5 (total no of cases)
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can anyone explain how n was solved and got to that answer
of 150.5
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Is this right $\mathrm{T_n = \frac{3n\sum_{r=1}^{n}(r^2)}{2n+1}}$?
!Yajat!
this is the general term i have made of thos sequence
the only problem is i think im abusing any summation notation, any help would be appreciable, thanks
@vale zephyr Has your question been resolved?
@vale zephyr Looks right to me.
I don't think you are abusing summation notation, but you may be able to express the whole sum without nesting summations, and that might be more convenient in some cases
like to show the summation in expanded form?
in this?
No, I mean if you express the sum as a sum over Tn, you will have a sum inside a sum
You might be able to avoid that, but I would not bother until you need to
no i will open this summation likes sum of squares of first n term = n (n+1) (2n+1) / 6, and then simplify a bit and then apply the final Sum of this sequence summation
so it wont be a summation inside summation
Yes, that simplification is what I am talking about
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Is a rectangle a rhombus always, sometimes, or never
I had this question on my homework and I’m not sure
If i were to make a guess though
sometimes if the rectangle has all congruent sides?
only if rectangle is a square
Huh
then it's rhombus also
So the answer is never
no, answer is when it is square
I mean
Ok look
A rectangle with all equal sides is a square
So my answer is right?
yes
?
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if i have a number x which is divisible by 7 and 2 how do i prove that x has to be divisible by 14 as well?
i guess you can say x = 7a and x = 2b, but how does knowing that imply x = 14 c??
more or less i think
just argue that both 7 and 2 exist in the factorization
so x = 7 2 b where b is some natural
so you can substitue a for 2b?
wouldnt u have to then prove a is divisible by 2
i dont think its always true tho?
for example 4 * 6 = 24 by 36 which is divisble by 4 and 6 is not divisible by 24
i think perhaps it has to do with even and odd integers
Gauss lemma, if a divides bc and gcd(a, b) = 1, then a divides c
you can prove it from Bezout's identity
i cant use things not covered in the class :(
since x = 7k for some integer k, 2 divides x = 7k, and 2 is coprime with 7, 2 divides k, and k = 2q
then x = 14q
how do you know 2 divides k because they are coprime?
i dont think i can use that assumption tho
maybe there is another way without that lemma
then justify that both 2 and 7 needs to appear in the prime factorization
and factor 2 and 7 ig
🤔
2 and 7 are prime numbers, so if your number is divisible by 2 and 7, in the prime factorisation, 2 and 7 appear with some exponent >= 1
and your number is written as a product
factor a 14 out of it since it's possible bc of 2 and 7 being in the prime decomposition
i dont think i can use prime factorization since that isnt covered and not defined in the class im in
did you see something in that class lmao
my prof said one way is to use the lemma even * odd = even
well, you can reformulate Gauss like that ig
since x is divisible by 7, it's a multiple of 7, that has to be even since x is divisible by 2, and the even multiples of 7 are the multiples of 14
but then to prove it you would still need some arithmetic results, we're running in circles
ok i think i got it :/
so 7b = 2a = x so since 7b is even since x is even. b must be even since 7 is odd and the only way to get an even number is for b to be even so sub in b for 2c and you get 14c
you're saying 2 divides 7b, but 2 is coprime with 7, so 2 divides b
you're just formulating it by saying 7 is odd, but being odd is the same as being coprime with 2
hmm yea my prof wants to use only definitions that we have gone over
thanks for ur help
👍
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Well what does colinear mean and what does rank less than 3 mean?
@spiral iron Has your question been resolved?
Collinear means they lie on the same line, right?
But I don't know how to show that their rank is less than 3.
if the matrix's RREF has less than 3 pivots
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I’d probably assume that x3 stands in some relation to x1 and x2 and write y as mx+b
But thats just intuition, it might not lead to anything
=> they are a line so write (xi,yi)'s as (x1,y1),(x1+a,x1+b),(x1+La,y2+Lb) as they have the same slope
then find a way to eliminate a column or something
<= rank<3 <-> dim(column space)<3 so the column vectors are linearly dependent, then do what you have to do
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What’s the name of combinatoric problems similar to this How many ways are there for a checker to travel from the bottom left corner to the top right corner of a 5x5 board if it can only move right or up by one square each time, but it cannot pass through the center square?
i think its called grid path problem
@rare shuttle Has your question been resolved?
this is formula for findin area of triangle using matrices
u just have to prove that determinent of this is equal to zero
we know are of a line is zero
so these points are collinear
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Hi
mh..
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@hallow mauve Has your question been resolved?
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Question 3G
The goal is to remove the radical from the denominator
Textbook ans is below
I dont know where to begin
If i could get the first step it would be nice
Well first I would try to remove the fraction from the denominator
How to do that?
By multiplying top and bottom by 3
Perfect my answer matches
I was stuck on what to multiply by
Thank you mate
Good night
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hey just a general question
for domains, how would you include multiple segments of it
in set notation
for example i have (-3,-2)U(3,inf)
how would I write that in set notation
${xeR|-3<x<-2, x>3}$
RecRio
seperated by a comma?
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What are the next two numbers 4,9,61,52,63,94,46
!original
Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.
If the original problem is not in English, then post it anyway! The additional context might still help helpers help you. Do your best to translate.
I assume it wants you to spot the pattern
Is this a test?
2x2= 4
3x3 = 9
4x4 = 16 reverse 61
5x5 = 25 reverse 52
As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.
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hi
This seems tough to graph
THere is also no HA
So do i just use a calculator or something
HA?
factor theorem
x=2? are you sure
yh
ok so you have root
Find what the graph does as x approaches negative infinity, positive infinity, x=3 from positive direction and x=3 from negative direction
then find where the graph crosses the y-axis (x=0)
then u should have enough info to do rough sketch
what is confusing me is how zoomed out these are
I sketch it but the coordinates r so hard to locate idek
they tell me to use graphing device
i guess i will do the same coordinates as them
up to -150
and 150
i got a question
isnt the VA the dotted Line
and nothing crosses it
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can you state the definition of “increasing from the right to the left”, because usually that’s called “decreasing”
I Sent the wrong one
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what went wrong?
<@&286206848099549185>
<@&286206848099549185>
<@&286206848099549185>
@last slate Has your question been resolved?
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Damn man this helpers ain't do nun to the poor guy
@last slate Has your question been resolved?
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@last slate do you have the answer to this?
unfortunately no, but the website says my answer is wrong
didnt really find anything wrong in your steps
did it specify anything about significant numbers or decimal points
3 significant digits
maybe it's a calculation error
yeah maybe some accuracy is lost during the middle but nothing is wrong really in your steps
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How would i find the vertical asymptote here again
Like it is weird for me as
i have to set x^2+x=0 xd
Idk how to do anything
.
Set x^2 + x = 0, factor it to find your vertical asymptotes
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What's the definition of an nth power residue? Also, is it only defined for prime powers? Why so? I see no reason why not to define it for any modulus m.
I have seen a textbook define it for a general modulus m.
But most of the internet seems to suggest it being defined only for prime moduli.
For (a,m)=1, if x^n congruent to a (mod m) has a solution, then we say that a is an n-th power residue mod m.
Also, why do most people seem to drop the co-prime condition of 'a' with m when defining so? Is that another variant of the definition..?
Or is it like understood that a has to be coprime with m?
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In the sheded region can we not do
Int 0 to 9 √x-x dx
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it's a extrema point
one notable thing about it that the derivative of the curve at that point is zero
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ok so you have 4 math books, 3 science books, 2 geo books and 4 history books
for 4 subjects in total
to arrange them in a way that groups them by subject, you need to first decide which order the subjects go in (4! ways), then decide within each subject which order that subject's books go in (4! * 3! * 2! * 4! ways)
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hi, i was wonderinng how long would it take approximately to learn calculus from michael spivak's book? and also what other resources complement it?
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Write three rational numbers (as a fraction) between the following rational numbers.
9. -1/4 and 1/2
Help
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3/10
there's an infinity if number that verify those conditions
Yeah you can pick anything in between .25 and .5
And find it's fraction and your done
-0.25
Why
