#help-49

1 messages · Page 13 of 1

old sapphire
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and the hint on the hw was to use kinetic energy

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:/

dull yoke
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oh thats why

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ok well

old sapphire
dull yoke
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ye u can use WE theorem

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i was just abt to type that lol

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but kinematics is enough

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if u wanna use WE go ahead ig

old sapphire
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i thought i was doing correct

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above

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either is fine with me

dull yoke
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W+ K_i = K_F, then (1150-625)(40) + 0.5(90)(0^2) = 0.5(90)(v_f)^2

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thats how u do it with WE thm

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with kinematics you can do

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(1150-625) = 90 * a, v_f ^ 2 = v_i^2 + 2ad

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you should get the same answer for both

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just 2 different approaches

old sapphire
dull yoke
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if ur using WE, u dont need to calc acceleration

old sapphire
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for the net force

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anways

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ty 🙏

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close

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random wharf
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random wharf
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is D correct?

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<@&286206848099549185>

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u sure

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@last slate

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wraith aurora
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wraith aurora
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I would like some assistance on the end behavior asymptotes

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nvm got it

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trail stone
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trail stone
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Help me out please!

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No idea how to do this

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answer

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bitter tide
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draw the diagonal, it might help u visualize it

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coarse quartz
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This question confuses me. Is it asking me to find the lim or derivative?

coarse quartz
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derivative = 0 but limit = 1/2

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im lost

keen herald
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The limit is part of the definition of the derivative

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By finding the limit of that equation, you get the derivative of the function sin(pi/3)

coarse quartz
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limit = derivative?

keen herald
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Not quite

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That limit of that expression = the derivative of the function sin(pi/3)

coarse quartz
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i got it thanks!

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last slate
midnight plankBOT
last slate
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correct?

balmy brook
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yes

last slate
wary thorn
midnight plankBOT
solar fractal
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Correct, also cool name

last slate
midnight plankBOT
# solar fractal Correct, also cool name

As a helper, please do not give out answers that could be copied as a homework solution. Have the student work through the problem themselves and guide them along the way.

wary thorn
last slate
last slate
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because im paranoid

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simple acorn
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simple acorn
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Did i miss something over here?

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I need both 20 and 3 to be negative to add up to -23 but I also need to multiply to -60

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<@&286206848099549185>

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last slate
midnight plankBOT
last slate
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I cant visualize this question

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if that makes sense

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i dont understand the wording

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<@&286206848099549185>

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what are the 3 focal points ?

midnight plankBOT
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coarse quartz
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@last slate find the compound interest for year 11 and year 19

last slate
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what abt the 2 equal payments ??

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do i only need to solve for 1 of them

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bcs theyre equal anyways

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midnight plankBOT
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Please don't occupy multiple help channels.

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silent sorrel
midnight plankBOT
silent sorrel
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Is this the right setup

grand pondBOT
silent sorrel
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<@&286206848099549185> pls help me sorry for the ping

rose kayak
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seems reasonable. What did you get for x?

silent sorrel
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I didn’t solve yet

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Whoops

bronze wigeon
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Should mention that technically it’s reciprocated, but if t1=t2 then 1/t1=1/t2 so

silent sorrel
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What

rose kayak
# silent sorrel What

they're saying that it makes more sense for you have them "flipped", i, e, 400/(x + 5) = 360/(x)

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but it doesnt' technically matter in this specific example

silent sorrel
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Oh ok

rose kayak
silent sorrel
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,help

grand pondBOT
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A brief description and guide on how to use me was sent to your DMs!
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rose kayak
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,rccw

grand pondBOT
rose kayak
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yep that seems reasonable! Let's see if they come out to the same amount of time

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,calc 400/50

grand pondBOT
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Result:

8
rose kayak
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,calc 360/45

grand pondBOT
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Result:

8
rose kayak
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yay!

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So they both took 8 hours 🙂

silent sorrel
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yippee

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that’s a long time

rose kayak
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lol tell me about it

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I actually just took that trip this weekend

silent sorrel
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How do you tell which is numerator and which is in denominator

silent sorrel
silent sorrel
rose kayak
silent sorrel
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the only problem is that I have a test on this tomorrow

rose kayak
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ah ok

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so let's take this example

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speed is usually calculated as "miles per hour" aka "miles/hour" aka "mph" etc, right?

silent sorrel
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yes

rose kayak
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ok

silent sorrel
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wouldn’t speed be equal to the ratio and not in the ratio

rose kayak
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can you clarify what you mean by that?

silent sorrel
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I mean that it would be mph = m/h?

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Idk if that’s right

rose kayak
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they mean the same thing. "per" in this case would be "divided by"

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colloquially

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ok

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so let's take your example

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give me some time to set this up please

silent sorrel
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Ok

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did I just write the ratios wrong

rose kayak
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they were just inverted

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that's all

silent sorrel
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Wait

rose kayak
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I wouldn't think too hard into this, lol

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my example will show you why though

silent sorrel
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The ratios are equal to time, so it’s just h/mph?

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Like they’re algebraicly swapped

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like this one

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,rccw

grand pondBOT
rose kayak
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Say if you we know that the average speed is 45 miles per hour and we know that we traveled 360 miles. We want to know how long it took.
$\\$
So we can set up a ratio and orient our units based on our goal. We want to know how long it too.
$\\$
So we have: $\frac{45 \text{ miles}}{1 \text{ hours}} \cdot \frac{1}{360 \text{ miles}} = \frac{45 \text{ miles}}{360 \text{ hours} \cdot \text{ miles}} = \frac{1}{8 \text{ hours}}$. We can cancel out the miles since we have both units in the numerator and denominator.
$\\$

However, $\frac{1}{8 \text{ hours}}$ doesn't make a whole lot of sense for this context. If we flipped it at the beginning then we could have the miles be the correct unit.

$\\$

$\frac{1 \text{ hours}}{45 \text{ miles}} \cdot \frac{360 \text{ miles}}{1} = \frac{360 \text{ hours} \cdot \text{ miles}}{45 \text{ miles}} = \frac{8 \text{ hours}}{1} = 8$ hours.

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ugh hold on

silent sorrel
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wait what are you writing

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with those dollar signs

rose kayak
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it's a script way to write out LaTex

storm shore
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Hey, can anyone help me with this... Kind of basic but I've been working on it for several hours and can't get it.. it's the last (bottom) problem

rose kayak
# silent sorrel Like they’re algebraicly swapped

Pretty much yeah.

In this example, it's simple enough (and what I assuming what you'll be working on for this section) where you can just probably flip it and get the proper answer.

But sometimes the orientation matters

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hey I gotta head out for a bit but hopefully that example made sense

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good luck with your test tomorrow

silent sorrel
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@rose kayak is that 8mph

silent sorrel
rose kayak
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NO WAIT

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sorry

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it'd be 8 hours

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let me correc that real quic

grand pondBOT
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MellowDramaLlama

rose kayak
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just read through that part step by step

silent sorrel
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Ok thanks bro

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sage adder
#

can someone help me b and c?

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leaden mural
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Help!!!!!

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ASSISTANCE NEEDED

crystal sandal
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shy totem
#

For the top question how do I make an expression for area?

verbal rain
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2(6x + 2 + 3x) is right but your final answer is not.

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area of a rectangle is L*W.

shy totem
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18x + 4

verbal rain
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A = LW

shy totem
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Ohhh

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Okay

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Thanks

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last slate
#

Greetings from laptop
I have a inquisition into a mater that involved number theory.
I know that a number n evenly divides a number a if $a = nk$ for some integer value k

grand pondBOT
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<:F_button:1095679234497843251>

last slate
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How would I use this knowledge to figure out if a number [a] is divisible by some number b who's digits are the number n

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I'm asking this question because of this problem
https://codeforces.com/problemset/problem/122/A

Petya loves lucky numbers. Everybody knows that lucky numbers are positive integers whose decimal representation contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.

Petya calls a number almost lucky if it could be evenly divided by some lucky number. Help him find out if the given number n is almost lucky.

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4
7
47, 74, 77, 44
777, 774,744, 444, 447, 477, 474, 747

are lucky numbers

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If the number I'm checking is less than 1000 I would have to check if my number is divisible by any of the above lucky numbers

next rover
#

that would make sense

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you don't have to check the repeating ones

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77,44,777 and 444

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744 is also redundant

last slate
#

This was the trival solution i came up with

fn main() {
   let mut scanner = Scanner::default();
   //Gets number from standard input
   let number:usize = scanner.next();

   let almost_lucky:bool =   Vec::from([
            4usize,7usize,
            47usize,74,44usize,77usize,
            444usize,777usize,447usize,477usize,774usize,744usize,747usize,474usize
        ])
        .iter()
        .any(|lucky| number % lucky == 0);

    println!("{}",
             if almost_lucky { "YES" } else { "NO" } 
             );
}

But there has to be a way that doesn't involve enumerating all the possible lucky numbers

steep ledge
#

to generate them, you can notice that the lucky numbers are of the form sum a_k * 10^k where a_k is either 4 or 7

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you can generate the list of lucky number with a simple list

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a for loop that goes through all theses sums gives every lucky number

last slate
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if the number im checking is extremely large then generating them might not work

steep ledge
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you can't predict every single lucky number tho, bc of Dirichlet theorem

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the further you go, you'll eventually get prime lucky numbers again and again

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and if you could predict their pattern, you would be solving some part of millenium problems

last slate
#

That is surprising

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I have not learnt enough about number theory to know Dirichlet theorem

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I am saddened to know there is no O(1) solution to this

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TY for help

#

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blissful trench
#

A group of friends decides to share a cake. If it takes Alice $2$ hours to eat the entire cake, Bob $3$ hours, and Carol $4$ hours, how long will it take them to eat the cake together?

grand pondBOT
#

Akira 🍇

blissful trench
#

!status

midnight plankBOT
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What step are you on?
1. I don't know where to begin.
2. I have begun but got stuck midway.
3. I got an answer but I was told that it's wrong.
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5. I have a question about someone else's work/solution.
6. I have completed the problem and don't need help anymore. Thank you.
7. None of the above
blissful trench
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1

vale zephyr
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i dont remember why we do this, i learned this like 2 years ago, but we take thier least common mulitple iirc

blissful trench
#

how

main current
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Think in terms of rates.
Alice eats 1/2 of a cake in an hour
Bob eats 1/3 of a cake
Carol eats 1/4 of a cake

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How much do they eat in an hour combined

blissful trench
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$\frac{1}{2} + \frac{1}{3} + \frac{1}{4} = \frac{1}{t}$

grand pondBOT
#

Akira 🍇

blissful trench
#

solve for t now?

main current
#

That's exactly it

cedar coral
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i would put it as t, not 1/t. It's gonna be easier to work with

blissful trench
#

okay

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thanks

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main current
#

You can sum them for a rate, but then you have to flip that for the time taken

slow moon
#

okay

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can someone help me

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where am i getting this sh wronf

main current
#

Take an open channel

slow moon
#

how do i do that

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OHHH

midnight plankBOT
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cedar vortex
#

quick notational question @steep ledge

midnight plankBOT
cedar vortex
#

oops sorry

obtuse flame
#

Sorryyyy

cedar vortex
#

so I got the basis

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and everything but the last one is skew symmetric

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so it should be something like [0 0 0 2]

steep ledge
#

what's f ?

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also, show your basis

cedar vortex
cedar vortex
steep ledge
#

f(A) = null matrix if A is symmetric, and 2A if skew

cedar vortex
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so [0, 0, 0, 2]

steep ledge
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is [f]b a notation to say image of the basis in the basis ?

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if yes, I guess so

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but that seems weird use of notation

cedar vortex
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the notation is so confusing

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I know how this works

steep ledge
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the problem is that the definition of the notation isn't in this theorem

steep ledge
#

but I guess [0, 0, 0, 2] makes sense if it means image of something expressed in basis B

cedar vortex
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I'm so confused lmao

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but like shouldn't it be a constant

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like$[0, 0, 0, 2x_4]$

grand pondBOT
#

nosqldb

steep ledge
#

again, I simply don't know this notation

cedar vortex
#

ty

#

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waxen silo
#

could someone explain why theres a 3 here?

midnight plankBOT
waxen silo
#

original question

rose cobalt
#

You were adding the 3 P’(x) together in the step before

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b+b+b = 3b

waxen silo
#

could you care to highlight that? I cannot see it in the answer

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btw I have a slight understanding on how this stuff works

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so I may falter under some explaination, I apologise in advance

rose cobalt
#

$P’(\alpha) , P’(\beta) , P(\gamma) $ all has 1 $b$

grand pondBOT
waxen silo
#

wait... what??

rose cobalt
#

Ok lemme ask you what is P’(Alpha)

waxen silo
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oh, if I were to put all the roots in like (x+a)(x+b)(x+y)

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and expand it

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I would get 3 b's

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is that what your saying?

rose cobalt
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Not rly

waxen silo
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ah

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also I am not sure what P alpha is

rose cobalt
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$P’(x)= 3x^2 + 2ax + b$

grand pondBOT
waxen silo
#

mhm I understand that

rose cobalt
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Just plug in x=alpha

waxen silo
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3a^2+2aa +ab

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the two a's are different things yes?

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ahh that makes sense now

rose cobalt
#

Write down what you get after plug in x=beta and x=gamma

waxen silo
#

oh you do get 3b's

rose cobalt
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Add all of them together and what will you get

waxen silo
#

WOW THIS MAKES MORE SENSE NOW

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3a^2+ 3B^2+ 3y^2 + 2aA +2aB +2ay + 3b

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facortise 3 and 2 out respectively

rose cobalt
#

Yes and a can be factorised out too

waxen silo
#

goode gawd

#

it all makes sense now

#

I get it now

#

thank you for the help

#

could I quickly ask just one more related to this?

rose cobalt
#

Sure

waxen silo
#

I just want to understand the correlation of this

#

the top part

#

I know its to do when you add all the roots together and they correlate to the P(x) becuase math laws

rose cobalt
#

Those two parts are independent
The first part is the given info
The second part is what you write down

waxen silo
#

well I should be more specific

#

how did they find out a= that

rose cobalt
#

You have $\alpha, \beta, \gamma$ as the roots of $P(x)$

waxen silo
#

and so and so

grand pondBOT
waxen silo
#

mhm I get that

rose cobalt
#

Well it’s called Vieta formula

#

Or more intuitively
Think of $P(x)=a(x-\alpha)(x-\beta)(x-\gamma)$

grand pondBOT
waxen silo
#

ok know what Vieta's formula are

waxen silo
# grand pond **Afi**

I assume if we were to expand this, every coefficient of x would line up to something right?

rose cobalt
#

Yes

#

Try it yourself

waxen silo
#

oh boy time to expand a cubic catscream

rose cobalt
#

I have to go now

#

Sry

waxen silo
#

that ok

#

I understand now

#

.close

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#
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last slate
#

bit new to recipirocal functions, i got the top part (local max=local min for reciprocal functions), but the bottom two I don't understand why they have a point there and cross through the parabola

last slate
#

what is the equation of the function and what is the equation of its reciprocal

main current
#

Any time the function crosses through y = 1 or y = -1, you could put one of those points

last slate
#

so reciprocal is constant if there are 1's

main current
#

Because those are the numbers that aren't changed when you take a reciprocal

#

1/(1) = (1)
1/(-1) = (-1)

last slate
#

right, makes sense

#

and it's decreasing because it's increasing

#

on the normal graph

main current
#

Yeah you could say that too

last slate
#

perfect, thanks so much

#

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last slate
#

How to prove this using proof by exhaustion?
For every n ∈ N, n(n+1) is even

last slate
#

do you know what a proof by exhaustion is?

#

(its all about cases)

last slate
last slate
#

what are those two things?

#

odd and even?

lyric charm
#

in proofs involving parity, it is sometimes (but not always) to split into two cases based on parity of one thing or another

last slate
#

yes

#

so you can consider both cases individually

#

i.e. consider when n is even and also consider when n is odd

last slate
last slate
#

yeah

#

so start with n = 2k

#

substitute that into your expression

#

observe what your resultant expression would be

#

I'm sorry I don't understand why we assume that n is even, we're supposed to prove that n(n+1) is even

#

Its a proof by exhaustion

#

So what we are doing is this

dawn hazel
#

suppose n is odd

last slate
#

we know that n can be any natural number

dawn hazel
#

then n+1 = even

#

even * odd = even

#

suppose n= even

#

well then it's even easier

#

since even*anything is even

lyric charm
#

one case in which n is even

dawn hazel
#

thus we have exhausted the two cases

lyric charm
#

the other case in which n is odd

last slate
#

so if you can verify that both the even and odd n's give you an even expression, then you thus verify it for the entirety of the natural numbers as well

#

ok i will leave 3 helpers will just confuse

last slate
#

so suppose that n is even so n=2k and then from that we build to n(n+1)?

dawn hazel
#

no

#

N= even, then we have that n(n+1)= even

#

that is because even* anything is even

#

and for n= odd we have that n+1=even

#

so we again have even*anything=even

last slate
#

so we got the first case, the when n is even

#

now we check for when n is odd

dawn hazel
#

Yes

#

Or even easier to visualise

#

n and n+1 are two consecutive numbers

#

so one must be even and one must be odd

#

and since we're multiplying them, it doesn't matter which one is odd or even

#

since odd*even=eventimesodd

#

and that is also equal to even

#

since 2k(2n+1)=4kn+2k=2(2kn+k)

last slate
#

okayokay that makes sense

dawn hazel
#

ok

last slate
# dawn hazel ok

what happens when we check for the second case tho? when n is odd

#

oh wait

#

yes

dawn hazel
#

try plugging n=2k=1

last slate
#

but why

dawn hazel
#

wait sorry

#

2k+1

#

forgor to hold shift

#

and that is because 2k is even and when we add 1 to an even we get an odd

last slate
dawn hazel
#

to n(n+1)

#

when n is even, n=2k

#

when n is odd, n=2k+1

#

plug each value into the equation

#

and see how it works out

last slate
#

we get 4k square +2k when it's even

#

but what does it mean

dawn hazel
#

what can you say about the number 4k^2 + 2k

last slate
#

I can write it as 2(2k^2+1) which means it's an even number times an odd number which means it's even?

dawn hazel
#

yes

#

it is even, because it is a multiple of 2

last slate
#

that makes sense

dawn hazel
#

2(2k^2+1)

#

yeah

#

now try plugging in n=2k+1

#

the case where is odd

last slate
#

4k^2 + 4k +1

#

it's not a multiple of 2 so it's not even?

dawn hazel
#

remembe

#

r

last slate
#

no way

dawn hazel
#

you are plugging in n=2k+1

#

so n(n+1)=(2k+1)(2k+2)

last slate
#

where did the 2 come from

dawn hazel
#

plug in 2k+1 for n

last slate
#

oh wait I got it i got it

dawn hazel
#

n+1=2k+1 +1

last slate
#

I forgot about the n

dawn hazel
#

ok

#

so all is clear now>

#

?

last slate
#

yes so we get 4k^2 + 6k +2 right?

dawn hazel
#

yeah

last slate
#

and it's a multiple of 2 so it's even

dawn hazel
#

yeah

#

So you've exhausted both cases

#

When n=even and where n=odd

#

and you've shown that n(n+1) is even for both of them

last slate
#

okay thanks a lot for the help!!

dawn hazel
#

np

#

what grade are you in btw

last slate
#

first year computer science

dawn hazel
#

wait so like university

last slate
#

yep

dawn hazel
#

dang

#

.close

midnight plankBOT
#

@last slate Has your question been resolved?

last slate
#

.close

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#
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last slate
#

there you go

midnight plankBOT
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gentle fossil
#

what would be a domain for this?

midnight plankBOT
gentle fossil
#

0 through 5?

dawn hazel
#

nah

#

any positive x except for ,45

#

4,5

gentle fossil
dawn hazel
#

wait no

#

they meant domain for v

#

sorry

gentle fossil
dawn hazel
#

idk what domain really means in english lmao

#

domain of V is like values of V?

#

or values of x?

gentle fossil
dawn hazel
#

Volume has to be >0 right

gentle fossil
#

what is that last number

dawn hazel
#

infinity

gentle fossil
#

the numbers cant be negative

dawn hazel
#

V can't be neg

#

if you plug in let's say x=10

#

we have 10(-11)(-11)

#

=1210

gentle fossil
#

but that doesnt make any sense

#

because the cut is longer

#

then the paper

dawn hazel
#

oh

#

then

#

2x<9

#

I just skipped to the equation

gentle fossil
#

what about this

The reasonable domain for V is x ∈ [0,9].

dawn hazel
#

did you write v(x) correctly?

gentle fossil
dawn hazel
#

I double checked

#

it's correct

gentle fossil
dawn hazel
#

Yes

#

I forgot to read the first part

#

now it's obvious

#

x>0

#

9-2x>0

#

=>9>2x

#

=>x<4.5

#

so 4,5>x>0

#

so we have x=(0;4.5)

gentle fossil
dawn hazel
#

x cannot equal 4.5

#

you'd be cutting the whole paper

gentle fossil
dawn hazel
#

idk

#

is it really a open top box

#

if there is nothing

gentle fossil
#

its fine

dawn hazel
#

alr

#

.close

#

/close

#

!CLOSE

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#

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last slate
#

in a poker hand consisting of 5 cards, find the probability of holding 2 aces and 3 jacks

last slate
#

so uh, im not quite familiar with how poker is played usually

wind current
#

poker has 52 cards

last slate
#

yeah

hard shard
#

Pick 5

#

Uniform at random

wind current
#

4 of them are aces (ace of hearts/spades/clubs/diamonds)

#

4 of them are jacks (jack of hearts/spades/clubs/diamonds)

hard shard
#

Do you remember the full house question?

last slate
#

no sadly its been a bit, but i do remember our discussion

hard shard
#

Its similar

#

This is a specific full house

last slate
#

aces are not distinguisable from each other right

wind current
#

the problem is not asking for specific types of aces in your hand

#

so they are not distinguishable

last slate
#

oh i see

#

so we are dealing with combinations

next rover
#

a hand is uniformly one of 52c5 hands

last slate
#

okay so

next rover
#

it's just counting combinations, you can phrase it with people

last slate
#

lets find the sample space first i suppose

#

so our sample space is

#

any set of hands

#

which is $\ds \binom{52}5$

grand pondBOT
next rover
#

absolutely

last slate
#

so,

#

we are trying to find the possibility of being dealt 2 aces and 3 jacks

#

there are 4 cards of each

#

so

#

Assuming that $A$ is the event that you get 2 aces and 3 jacks: [
\map P A = \f{\binom 4 2 \binom 4 3}{\binom{52}5}
]

grand pondBOT
last slate
#

right?

next rover
#

yes

last slate
#

okay this might sound really weird but im like in the middle of like distingushing between when to be considering permutations and combinations.

What would you modify in the original scenario to turn that 52c5 to like 52p5

#

just for my own understanding

next rover
#

you don't have to modify it, it would give the same answer if you do permutations

last slate
#

oh what really?

#

how so

next rover
#

okay no

#

like your sample space becomes 52p5

#

but then 4p2 × 4p3 undercounts hands

#

it makes you only consider hands that look like AAJJJ, but it could be JAJAJ

sudden needle
#

basically if its asking that something needs to be in a specific order

#

you do permutations

next rover
#

(4p2 × 4p3 × 5c2) / 52p5 would work

sudden needle
last slate
#

ok the "ordeR" becomes a bit vague in some situations

#

but i get your idea yes

#

okay as another exercise

#

lets calculate the chance of getting the royal flush

next rover
#

combination is essentially amounts

#

a multiset

#

"3 of something and 6 of something"

#

to visualize it, you put the elements in some sort of fixed order like alphabetically

sudden needle
#

for number of royal flushes you dont need anything you can just count them, spade, clubs hearts and diamond = 4 possible royal flushes

#

and for probability just divide by 52C5 (total no of cases)

last slate
#

ok i think i get it for both of what you said

#

thanks guys

#

.clsoe

#

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slate talon
#

can anyone explain how n was solved and got to that answer

slate talon
#

of 150.5

wooden dock
#

we just move the numbers over

#

640000/5000

#

then multiply that by (0.0264/12)

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vale zephyr
midnight plankBOT
vale zephyr
#

Is this right $\mathrm{T_n = \frac{3n\sum_{r=1}^{n}(r^2)}{2n+1}}$?

grand pondBOT
#

!Yajat!

vale zephyr
#

this is the general term i have made of thos sequence

#

the only problem is i think im abusing any summation notation, any help would be appreciable, thanks

midnight plankBOT
#

@vale zephyr Has your question been resolved?

vale zephyr
#

<@&286206848099549185>

#

ping when reply please

mighty sleet
#

@vale zephyr Looks right to me.

#

I don't think you are abusing summation notation, but you may be able to express the whole sum without nesting summations, and that might be more convenient in some cases

vale zephyr
#

like to show the summation in expanded form?

vale zephyr
mighty sleet
#

No, I mean if you express the sum as a sum over Tn, you will have a sum inside a sum

#

You might be able to avoid that, but I would not bother until you need to

vale zephyr
#

no i will open this summation likes sum of squares of first n term = n (n+1) (2n+1) / 6, and then simplify a bit and then apply the final Sum of this sequence summation

#

so it wont be a summation inside summation

mighty sleet
#

Yes, that simplification is what I am talking about

vale zephyr
#

yea okay, thanks dude

#

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grand falcon
#

Is a rectangle a rhombus always, sometimes, or never

grand falcon
#

I had this question on my homework and I’m not sure

#

If i were to make a guess though

#

sometimes if the rectangle has all congruent sides?

heady lark
grand falcon
heady lark
#

then it's rhombus also

grand falcon
#

So the answer is never

heady lark
grand falcon
#

I mean

#

Ok look

#

A rectangle with all equal sides is a square

#

So my answer is right?

grand falcon
next rover
#

sometimes is right

#

you guessed right

grand falcon
#

Let’s goooooo

#

Thank you

#

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slim valve
#

if i have a number x which is divisible by 7 and 2 how do i prove that x has to be divisible by 14 as well?
i guess you can say x = 7a and x = 2b, but how does knowing that imply x = 14 c??

floral apex
#

more or less i think

#

just argue that both 7 and 2 exist in the factorization

#

so x = 7 2 b where b is some natural

slim valve
#

so you can substitue a for 2b?

#

wouldnt u have to then prove a is divisible by 2

#

i dont think its always true tho?

#

for example 4 * 6 = 24 by 36 which is divisble by 4 and 6 is not divisible by 24

#

i think perhaps it has to do with even and odd integers

steep ledge
#

Gauss lemma, if a divides bc and gcd(a, b) = 1, then a divides c

#

you can prove it from Bezout's identity

slim valve
#

i cant use things not covered in the class :(

steep ledge
#

since x = 7k for some integer k, 2 divides x = 7k, and 2 is coprime with 7, 2 divides k, and k = 2q
then x = 14q

slim valve
#

how do you know 2 divides k because they are coprime?

steep ledge
#

Gauss lemma

#

2 is coprime with 7

#

so 2 divides k

slim valve
#

i dont think i can use that assumption tho

#

maybe there is another way without that lemma

steep ledge
#

then justify that both 2 and 7 needs to appear in the prime factorization

#

and factor 2 and 7 ig

slim valve
#

🤔

steep ledge
#

2 and 7 are prime numbers, so if your number is divisible by 2 and 7, in the prime factorisation, 2 and 7 appear with some exponent >= 1

#

and your number is written as a product

#

factor a 14 out of it since it's possible bc of 2 and 7 being in the prime decomposition

slim valve
#

i dont think i can use prime factorization since that isnt covered and not defined in the class im in

steep ledge
#

did you see something in that class lmao

slim valve
#

my prof said one way is to use the lemma even * odd = even

steep ledge
#

well, you can reformulate Gauss like that ig
since x is divisible by 7, it's a multiple of 7, that has to be even since x is divisible by 2, and the even multiples of 7 are the multiples of 14

#

but then to prove it you would still need some arithmetic results, we're running in circles

slim valve
#

ok i think i got it :/

#

so 7b = 2a = x so since 7b is even since x is even. b must be even since 7 is odd and the only way to get an even number is for b to be even so sub in b for 2c and you get 14c

steep ledge
#

indeed

#

and that's gauss lemma, you're using that 7 is not even (ie coprime with 2)

slim valve
#

hmm ok

#

i didnt rlly understand that lemma

#

but i think thats outside this course

steep ledge
#

you're saying 2 divides 7b, but 2 is coprime with 7, so 2 divides b

#

you're just formulating it by saying 7 is odd, but being odd is the same as being coprime with 2

slim valve
#

hmm yea my prof wants to use only definitions that we have gone over

#

thanks for ur help

#

👍

#

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spiral iron
midnight plankBOT
spiral iron
#

Help

#

@robust isle

shell pendant
#

Well what does colinear mean and what does rank less than 3 mean?

midnight plankBOT
#

@spiral iron Has your question been resolved?

spiral iron
#

Collinear means they lie on the same line, right?

#

But I don't know how to show that their rank is less than 3.

wary thorn
spiral iron
#

But how do I show the number of pivots?

#

Given the matrix above.

#

Help.

spiral iron
#

<@&286206848099549185>

midnight plankBOT
#

@spiral iron Has your question been resolved?

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@spiral iron Has your question been resolved?

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@spiral iron Has your question been resolved?

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#

@spiral iron Has your question been resolved?

storm spindle
# spiral iron

I’d probably assume that x3 stands in some relation to x1 and x2 and write y as mx+b

#

But thats just intuition, it might not lead to anything

livid bramble
# spiral iron

=> they are a line so write (xi,yi)'s as (x1,y1),(x1+a,x1+b),(x1+La,y2+Lb) as they have the same slope
then find a way to eliminate a column or something
<= rank<3 <-> dim(column space)<3 so the column vectors are linearly dependent, then do what you have to do

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rare shuttle
#

What’s the name of combinatoric problems similar to this How many ways are there for a checker to travel from the bottom left corner to the top right corner of a 5x5 board if it can only move right or up by one square each time, but it cannot pass through the center square?

narrow jungle
#

i think its called grid path problem

midnight plankBOT
#

@rare shuttle Has your question been resolved?

frank pecan
# spiral iron

this is formula for findin area of triangle using matrices

#

u just have to prove that determinent of this is equal to zero

#

we know are of a line is zero

#

so these points are collinear

midnight plankBOT
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hallow mauve
#

Hi

midnight plankBOT
hallow mauve
#

idk how to solve this question

#

can anyone help me pls?

steep hinge
#

mh..

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@hallow mauve Has your question been resolved?

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@hallow mauve Has your question been resolved?

hallow mauve
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<@&286206848099549185>

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cedar olive
#

Question 3G

midnight plankBOT
cedar olive
#

The goal is to remove the radical from the denominator

#

Textbook ans is below

#

I dont know where to begin

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If i could get the first step it would be nice

crystal rivet
#

Well first I would try to remove the fraction from the denominator

cedar olive
#

How to do that?

crystal rivet
#

By multiplying top and bottom by 3

cedar olive
#

Perfect my answer matches

#

I was stuck on what to multiply by

#

Thank you mate

#

Good night

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.close

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last slate
#

hey just a general question

midnight plankBOT
last slate
#

for domains, how would you include multiple segments of it

#

in set notation

#

for example i have (-3,-2)U(3,inf)

#

how would I write that in set notation

#

${xeR|-3<x<-2, x>3}$

grand pondBOT
#

RecRio

last slate
#

seperated by a comma?

midnight plankBOT
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dense chasm
#

What are the next two numbers 4,9,61,52,63,94,46

midnight plankBOT
wary thorn
#

!original

midnight plankBOT
#

Please show the original problem, exactly as it was stated to you. A picture or screenshot is best.

If the original problem is not in English, then post it anyway! The additional context might still help helpers help you. Do your best to translate.

dense chasm
last slate
#

I assume it wants you to spot the pattern

dense chasm
#

43

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yes

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sorry

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not the best camera

wary thorn
#

Is this a test?

dense chasm
#

no

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homework

tall copper
#

2x2= 4
3x3 = 9
4x4 = 16 reverse 61
5x5 = 25 reverse 52

dense chasm
#

ohhh

#

thank you

midnight plankBOT
dense chasm
#

.close

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naive flint
midnight plankBOT
naive flint
#

hi

#

This seems tough to graph

#

THere is also no HA

#

So do i just use a calculator or something

small ore
naive flint
#

horizontal asymptote

#

i mean to say

small ore
#

Have you learned differentiation?

#

Try to find roots of the numerator

naive flint
#

Ok

#

I have not learn that yet

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I can do root tho

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i think

small ore
#

factor theorem

naive flint
#

so

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2 is one of the rots

small ore
#

x=2? are you sure

naive flint
#

o

#

o

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-2

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-2,0

small ore
#

yh

#

ok so you have root

#

Find what the graph does as x approaches negative infinity, positive infinity, x=3 from positive direction and x=3 from negative direction

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then find where the graph crosses the y-axis (x=0)

#

then u should have enough info to do rough sketch

naive flint
#

what is confusing me is how zoomed out these are

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I sketch it but the coordinates r so hard to locate idek

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they tell me to use graphing device

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i guess i will do the same coordinates as them

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up to -150

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and 150

#

i got a question

#

isnt the VA the dotted Line

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and nothing crosses it

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magic magnet
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magic magnet
bitter vine
#

haloooooooooooooooo

#

i need help

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last slate
midnight plankBOT
sick fossil
# last slate

can you state the definition of “increasing from the right to the left”, because usually that’s called “decreasing”

last slate
#

I Sent the wrong one

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last slate
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last slate
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what went wrong?

#

<@&286206848099549185>

#

<@&286206848099549185>

#

<@&286206848099549185>

midnight plankBOT
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@last slate Has your question been resolved?

last slate
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<@&286206848099549185>

wet rune
#

Damn man this helpers ain't do nun to the poor guy

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@last slate Has your question been resolved?

last slate
#

<@&286206848099549185>

fallen galleon
#

@last slate do you have the answer to this?

last slate
fallen galleon
#

didnt really find anything wrong in your steps

fallen galleon
last slate
fallen galleon
#

yeah maybe some accuracy is lost during the middle but nothing is wrong really in your steps

last slate
#

ok thank you

#

as long as my steps are correct

#

.close

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naive flint
#

Hi

midnight plankBOT
naive flint
#

How would i find the vertical asymptote here again

#

Like it is weird for me as

#

i have to set x^2+x=0 xd

#

Idk how to do anything

barren blade
#

.

fallen galleon
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magic field
#

What's the definition of an nth power residue? Also, is it only defined for prime powers? Why so? I see no reason why not to define it for any modulus m.

magic field
#

I have seen a textbook define it for a general modulus m.

#

But most of the internet seems to suggest it being defined only for prime moduli.

#

For (a,m)=1, if x^n congruent to a (mod m) has a solution, then we say that a is an n-th power residue mod m.

#

Also, why do most people seem to drop the co-prime condition of 'a' with m when defining so? Is that another variant of the definition..?
Or is it like understood that a has to be coprime with m?

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@magic field Has your question been resolved?

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@magic field Has your question been resolved?

magic field
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<@&286206848099549185>

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.close

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bronze helm
midnight plankBOT
bronze helm
#

In the sheded region can we not do
Int 0 to 9 √x-x dx

warm veldt
#

?

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warm veldt
#

it's a extrema point

#

one notable thing about it that the derivative of the curve at that point is zero

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raw grove
midnight plankBOT
raw grove
#

How would I do part b

#

Not sure where to start

lyric charm
#

ok so you have 4 math books, 3 science books, 2 geo books and 4 history books

#

for 4 subjects in total

#

to arrange them in a way that groups them by subject, you need to first decide which order the subjects go in (4! ways), then decide within each subject which order that subject's books go in (4! * 3! * 2! * 4! ways)

raw grove
#

Ahhhh thank uuu

#

how did u come up with this in under a minute? 😭😭

#

.close

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last slate
#

hi, i was wonderinng how long would it take approximately to learn calculus from michael spivak's book? and also what other resources complement it?

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lavish cairn
#

Write three rational numbers (as a fraction) between the following rational numbers.
9. -1/4 and 1/2

lavish cairn
#

Help

midnight plankBOT
#

@lavish cairn Has your question been resolved?

lavish cairn
#

<@&286206848099549185>

magic stone
#

3/10

balmy brook
#

there's an infinity if number that verify those conditions

magic stone
#

Yeah you can pick anything in between .25 and .5

#

And find it's fraction and your done

balmy brook
#

-0.25

magic stone
#

Ah

#

Well same thing applies still

lavish cairn
#

Why