help-49

[midnight plank]

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[rugged sage]

my bad!

it has been 15 min tho

[last slate]

well yes

10 minutes but yes

lemme see

whats the question lol

[rugged sage]

10:51

it's 11:06 now

[last slate]

oh

[rugged sage]

this is my answer

but the book has AB^-1(BA) + A

so would it be correct or did i do something wrong?

?

<@&286206848099549185>

[last slate]

i dont know lol

my eyes hurt and the red blends in

💀

[rugged sage]

fuck

[last slate]

.-.

[rugged sage]

are you in highschool still

?

<@&286206848099549185>

[last slate]

yes

[rugged sage]

ah ok

can u get someone to help lol

[last slate]

just wait a bit?

[rugged sage]

@sour spindle

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[late harness]

Hi, I have some difficulties doing this question and have no idea where to start. I know that trig identities can be used, but our teacher does not allow that. Instead, she told us to find cosine of that angle using sine of that angle. Any hints?

[fallow scarab]

,rccw

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[balmy jacinth]

help please

[balmy jacinth]

i need help with my math quiz currently

<@&286206848099549185>

[fallow scarab]

don't cheat on quizzes/tests/exams

[balmy jacinth]

its an reviewer quiz 😭

i was hoping someone to explain how to solve

not the answer

[junior flower]

the solution is the point that is on both lines

[balmy jacinth]

okay thank you

also

what is a consistent and dependent linear equation?

sigh

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[sonic canopy]

I got d

[midnight plank]

Please don't occupy multiple help channels.

[sonic canopy]

Is it correct

[midnight plank]

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[verbal kindle]

i need some difficult (or just normal) practice problems for simultaneous equations + linear graphs

[verbal kindle]

if your wondering around what level im freshman but im in extended maths

i need some matrice (row operations) problems (3 or 4 variables) that are pretty difficult and

some difficult word problems or linear programming difficult problems

ive tried to find some online but they were either too difficult or too easy

nvm my friend found a bunch for me

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[last slate]

I had an query regarding double differentiation
dv = dx/dt
da = dv/dt = d/dt(dv/dt) = d^2 v/dt^2
How does this double integration states/proves that twice the x (distance) will make twice the a(acceleration). This is true but in books and some lecture they directly explains it by saying "twice x make twice a because of double differentiation
"Differentiating twice, we find that the acceleration of A is twice the acceleration of B" How?

[strong lava]

Let A(t) and B(t) be the displacements of the points at time t
Then A(t) = 2B(t)
So A'(t) = 2B'(t)
And then A''(t) = 2B''(t)

i.e. since differentiation is a linear operator, linear relationships are preserved under differentiation (and integration)

[last slate]

In this notation it makes more sense now

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[odd mortar]

hello, i need explanations for C,D,E like i am 5

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[tidal rampart]

need help with number 12.

[flat halo]

um

u can try to get rid of the ln and the e

to get normal linear equations

so like

x = e ^(ln x)

x = ln( e^x)

so just throw in a e^ or a ln on both sides

[tidal rampart]

alr

ty

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[flat halo]

wo

u done with just that?

lol

gj

[midnight plank]

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[fallow scarab]

,rotate

[verbal obsidian]

Use calculator

[midnight plank]

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[low gale]

I need help with identifying the m, p, and n of this problem. It's already 2:26 am and I'm still answering. I keep getting the wrong answers, maybe because I'm using the wrong values

[low gale]

I keep getting these answers. It's too low to be the answer, it should be 120,000+

I feel like I'm using the correct formula but I get the m, p and n wrong?

Here's an example for reference

Heyyy guys

Chat here

Not in genshin impact server

Hey guys! Could this be the correct answer?

Wait so Elmar and Pamela will both have 127,200 in 5 years, so they're equal?

That means I'm wrong? 😭

Idk anymore...

Idk if I can answer they're equal

I feel like one of them should get greater amount

[midnight plank]

@low gale Has your question been resolved?

[low gale]

No

[vagrant imp]

You're still on the same problem?

Broski

[low gale]

Yes

I didn't use the formula when I'm supposed to. Maybe that's why the answer isn't right

[vagrant imp]

what is

is that amount of payments in a year

[low gale]

Based on this example, I think it's how many times the person pays in a year

If they pay monthly then it's 12

If they pay quarterly it's 4

[vagrant imp]

let me see the full problem

not just calc

[low gale]

If semi-annually it's 2

Here

You change the interest rate into decimal

6% becomes 0.06

I'm thinking this isn't the right formula because I get the wrong answer when I use this formula but it makes sense in the example but when I do it it doesn't make sense

This my answer for j

But when solving the FV it stops making sense

i=6% or 0.06
m=4 (every quarter so it's 3 months every year)
p=12 (he deposits monthly each year)
n=5 years

I got a new answer which is 41,631,729 but I don't think that's the correct answer

Wait, it might be

[low gale]

Omg is this the answer?!

Oh my god thank youuu

I'm gonna give you Welkin Moon

[vagrant imp]

i mean, its better if u understand the formula

rather than just copying what i showed u

[low gale]

This is exactly what I did idk why I kept getting the wrong answers

[vagrant imp]

u probably calculated wrong

write them out on a paper and do them step by step

[low gale]

I knew the n is 60 because 12 months × 5

[vagrant imp]

Rounding error but close enough

[low gale]

So the reason why I kept getting wrong asnwer is this!

My calculator is broken

[vagrant imp]

no ur broken

[vagrant imp]

https://www.desmos.com/calculator/s1unkf0t8g

heres a interactable formula for u to mess around with

[low gale]

I swear my calcu is the problem not me

[vagrant imp]

thats correct tho

[low gale]

It has too much decimals that's why I always get the wrong answer

[vagrant imp]

it doesnt matter

u can round them

[low gale]

Alright

[vagrant imp]

where my welkin tho

[low gale]

Later

[vagrant imp]

scammed

[low gale]

I will give it later

My answer is a little different than yours but it's okay

It's because I used 5 decimals, you used 4

[vagrant imp]

yes cuz theres bound to be rounding errors

called inaccuracy

[midnight plank]

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[kind zealot]

Is there an easy way to do Taylor-series of composite functions? If I as an example need to do a 2nd degree Taylor-expansion of cos(x² + 2x) at c = 0. I can of course differentiate the composite function twice and find the Taylor-expansion manually, but can I do this more quickly with the knowledge that T₂f(x) = 1 - x²/2! for cos(x)?

[elder zephyr]

yes

[bold badger]

can someone help in channel help-18?

[elder zephyr]

im not good in probability

[kind zealot]

Can you show me how?

[prime schooner]

Brute force. Collect the terms from 1 - (x^2+2x)^2/2!....

[elder zephyr]

yes

Thats the way

but respect the order

[kind zealot]

I tried that but got a 4th degree polynomial. Should I just throw away all degrees bigger than 2?

[elder zephyr]

Did you see taylor expansion with little-o notation ?

[kind zealot]

No

[elder zephyr]

welp

$f(x) = \sum_{k=0}^{n} \frac{f^{(n)} (a)}{n!} (x-a)^n + o((x-a)^n)$

yikes

[grand pond]

Ｈｅｒｅｌｓ

[bold badger]

Hey can someone help me in help-18?

[elder zephyr]

for example for cos(x) at a=0, it will be :
cos(x) = 1-x^2/2! + o(x^2) (Taylor expansion of degree 2)

[elder zephyr]

Plz, wait for someone

If i could do probability I would have helped you

[bold badger]

sure!

[kind zealot]

So it's notation for "the rest of the series with degree bigger than n"?

[bold badger]

thanks,waiting for you!

[elder zephyr]

huh nah, I cant do your exercises, I dont even know what markov chain is

[bold badger]

ooh okay

[elder zephyr]

it specifies the order of taylor expansion

in general, the little o notation means that :
if f=o(g) that means that f/g is really close to 0

anything greater than (x-a)^n isnt a o((x-a)^n)

so its just a notation to specify the order of the taylor expansion

[prime schooner]

Isn't little o the opposite of big O?

[elder zephyr]

they are not opposite, they have differents meanings

[kind zealot]

But in practice, to find the Taylor expansion of the composite, I should just substitute inner function (if polynomial) into Taylor expansion of outer function and remove the degrees higher than I need the Taylor expansion to be?

[elder zephyr]

thats the spirit

[kind zealot]

Nice

[prime schooner]

What was the opposite of big O..

[kind zealot]

Practising for a test, so even though I can find it manually, a quicker way like this will hopefully save me some time.

Thanks!

[elder zephyr]

np

[prime schooner]

ah Omega

[kind zealot]

.close

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[tame obsidian]

how did i get from here to there?

[velvet compass]

wdym

[tame obsidian]

how i do i simplify
i kinda get this one

[velvet compass]

this is just cos(2 theta)

(cos^2 + sin^2 gives 1)

[tame obsidian]

wait no way, i actually thought i had to simplify what i was given to the trig functions , lol

[velvet compass]

I thought simplified product is cos(2 theta) ?? or 2cos^2(theta) - 1

[tame obsidian]

heres the full equation if i wanted to see it

[velvet compass]

so what's your problem, what part don't you understand

[tame obsidian]

Naw I got it,thank you

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[heady tendon]

Hello

[heady tendon]

What is base of triangle?

[vapid mountain]

what have you tried?

[heady tendon]

I went and tried

15×11 /2

=82.5

[vapid mountain]

15 is the base of the rectangle

[heady tendon]

9×6 /2
=27

[vapid mountain]

I'm guessing this is the area of the triangle?

[heady tendon]

Yes, big imaginary triangle

[vapid mountain]

ohhh you've made a big triangle, you can do it more simple than that

split it into a rectangle and triangle like you have in the picture

[heady tendon]

Like I divided into big and small triangle

[slender walrus]

you're making an invalid assumption

[heady tendon]

Ok. Tell me why

And what is invalid

[slender walrus]

you tried to split the shape by connecting those two corners,
that doesn't split the shape into two triangles

[heady tendon]

How come?
Why not

[slender walrus]

different slopes etc

that'd be a scaled drawing

instead of trying to be fancy,
why not just just calculate what's already split for you

[heady tendon]

This is like that optikal ilusion , isn't it

Where there's a piece extra in the end

[slender walrus]

no

[heady tendon]

Ok.never mind

Thanks for explaining what's wrong

[slender walrus]

i suppose its somewhat related

[heady tendon]

Btw I already solved this, it is 105

Just wanted to understand what's wrong with my 2nd approach

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[spring widget]

what does d/dx mean

[spring widget]

tryna derivative or however u spell it

7lnx

which turn into 7 * d/dx

which against turn into

7/1 * 1/x

which emans 7/x

but what is d/dx

i dont get it ;-;

[jagged saffron]

can you send a picture of whatever youre looking at

[spring widget]

uh sure

Top one B)

[jagged saffron]

yes but where are you seeing someone change lnx into d/dx

[spring widget]

tryna do g'(x)

oh

gimme a sec

ln x turns into d/dx

it says that in my book too

but like

what does it mean

what is** d**

[jagged saffron]

lnx does not turn into d/dx, d/dx is another notation for the derivative, d/dx(f(x)) is the same as f'(x)

[spring widget]

yuh

but how do i use it for thederivative

i suppose x is x

but what is d

[jagged saffron]

its just notation, take the derivative normally

[spring widget]

idk how

not with 7lnx

-4 just becomes 0 so not that important

but 7lnx

[jagged saffron]

oh then i recommend you look up how to differentiate natural logarithms

its most likely in that book youre using

[spring widget]

is differentiate the verb for getting the derivative

im not english so just guessing

[jagged saffron]

yes

differentiate means to take the derivative of something

[spring widget]

i see

oh

so

lnx

becomes 1/x

cuz d/dx

if im correct

if it then were ln 2

could i do 2/2x

[jagged saffron]

forget about the d/dx, just remember the derivative of lnx is 1/x

ln2 is just a number

[spring widget]

yeh but when i differentiate ln 2

could i use 2/2x as in d/dx

[jagged saffron]

no because ln2 is a number, not a function with a variable x

[spring widget]

hmm

ok so

therefore

if no x

it will become 0

[jagged saffron]

yes

[spring widget]

but on the other hand

if it were 2x

ln 2x

thennn

it would end up being 1/x

is that correct?

[jagged saffron]

it would, but why?

[spring widget]

cuz with the d/dx formula it will turn into 2/2x

meanign 1/x

and if that is wrong

then idk

i have understood at least that if it is a normal number without x it = 0 and yeah with x = 1/2

[jagged saffron]

the derivative of lnx is NOT d/dx, im not sure where you're getting this from, nowhere in the solution you posted does lnx get replaced with d/dx

d is not a number/variable

[spring widget]

yeh thats what im saying, im soryy if i make it seem like i mean its getting replaced lol

jsut a formula for finding the derivative of ln(x), correct?

[jagged saffron]

just completely ignore d/dx

its another notation for taking the derivative

(lnx)' = d/dx(lnx)

[spring widget]

ye

[jagged saffron]

you just need to know that (lnx)' is 1/x at the moment

later when you learn the chain rule you'll be able to deal with ln(other stuff)

or you can just write ln(ax) as ln(a) + ln(x)

[spring widget]

we already learned it, i get that with ease. i was just confused by what the variables in d/dx and what (d and x)was supposed to be

but thanks, got it now

[midnight plank]

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[steady dagger]

1 + sqrt(5) * 1 - sqrt(5), (a+b) (a-b) = a²-b², a² = 1, b² = 5 -> a²-b² = 1-5 = -4

[grand pond]

Yousuf

[midnight plank]

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[jade stag]

I got 8 * e^10 * pi

Wait I might be wrong nvm

[midnight plank]

@grand dust Has your question been resolved?

[grand dust]

how

[jade stag]

I’m wholly wrong

[grand dust]

.close

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[foggy thicket]

Can someone assist me with this, I'm having trouble figuring out how to do it

[foggy thicket]

I got the velocity function, and don't know if im solvingfor x y or z

also idk if im using t = 0 for this

i think the velocity function is p'(t) = (290,90,63-32t)

but what do i do now?

[midnight plank]

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[last slate]

gimme da coolest math phenomenon thats not fractals

[junior flower]

hedgehog theorem

[midnight plank]

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[mighty moon]

I am getting 3.80

Not sure if I am doing something wrong or the answers are incorrect

[lyric charm]

,w standard deviation {10,9,12,14,8,10,1}

[grand pond]

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Requested by Ann#0413

[lyric charm]

[velvet oar]

lol

[mighty moon]

Im using the population

should I have used sample?

[zinc forge]

@mighty moon A levels?

[mighty moon]

I dont know what you mean by that?

[zinc forge]

ah ok nvm ig

btw u need to show the full qn so ppl know if sample is needed @mighty moon

[mighty moon]

That is the full question.

Thats all that was given to me

<@&286206848099549185>

[velvet oar]

Using the sample SD, i also get 3.80. I think you're correct

[mighty moon]

Okay thank you

.close

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[eager grotto]

Can anyone help me solve this question?

[foggy thicket]

cross multiply

[eager grotto]

How the x-5?

[foggy thicket]

do 2x(3) and (x-5)*(2) then set them equal each other

[eager grotto]

2x(3) = 6x?

[foggy thicket]

so 2x(3) = (x-5)*2

no

[eager grotto]

What?

[eager grotto]

Yes now we need to find x

[foggy thicket]

yes, so when u do this out u get 6x = 2x-10

then u just subtract 2x from both sides

and then simplify

to get x

[eager grotto]

I asked you if 2x(3) =6 and you said no

[foggy thicket]

sorry ur right i misread

yes 2x(3) = 6x

[eager grotto]

So x = 10/4

[foggy thicket]

yes, u can simplify it more though

x = 5/2

but it's -5/2

[eager grotto]

Yes true

No wait what

It’s -10/4 so simplified to -5/2

Can you help me factorise this?

@foggy thicket

[ember echo]

did you learn the rule for
a^2-b^2=(a+b)(a-b)?

[eager grotto]

No never heard of that

[ember echo]

well now you know xD

[eager grotto]

Well yea it makes sense if you multiply the brackets

[ember echo]

so on the left side you have (y)^2

[ember echo]

yea

what do you have on the right side?

it needs to be something squared

[eager grotto]

X^2

[ember echo]

no,

[eager grotto]

9x^2?

[ember echo]

you have 9x^2 which is actually..?

do you want me to just tell u

[eager grotto]

Wait no no

[eager grotto]

3x?

[ember echo]

Yesss

(3x)^2

is the same as 9x^2

[eager grotto]

So after factorise?

[eager grotto]

Yes laws of indices agree

[ember echo]

yes now write them as
y^2-(3x)^2 and use the rule

[eager grotto]

Okay and then what?

[eager grotto]

I can’t find the answer

[ember echo]

They asked you to factor

what did you get so far?

[eager grotto]

y^2-(3x)^2

[ember echo]

ok now use the rule I mentioned here^

what is "a" in our case?

[eager grotto]

So is it going to be (y+3x)(y-3x)?

[ember echo]

Yes thats correct

[eager grotto]

Thank you sir

[ember echo]

np!

[eager grotto]

But wait tho

Let’s say they ask to factorise 6y^2 - 15xy

[ember echo]

ok

[eager grotto]

The answer you get is 3y(2y-5x)

[ember echo]

thats right

[eager grotto]

How do you put it in the rule format?

[ember echo]

Well we cant use the previous rule here

[eager grotto]

Ohhhh

[ember echo]

since you need something squared minus another thing squared

Here you can just take out the common multiplier

which is 3y

[eager grotto]

Btw how do you find area of trapezoid?

[ember echo]

add both bases, divide by two and multiply by height

[eager grotto]

So 1/2 (a+b)h

[ember echo]

like so

[ember echo]

you cant write is as 1/2(a+b)h since that means you divide by 2(a+b)h

its like in the pic

[eager grotto]

No you only divide (a+b)

[ember echo]

like in the picture when typing it its weird

[eager grotto]

Ohhh alr

Thank you

For your time

[ember echo]

sure

[eager grotto]

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[lethal knot]

I want to find AC with my given numbers but without using any other numbers I get. Because if I use sinus for AC I have to either use BC from sinus angle A or sinus angle C and use AB which neither I have "given." Both those sinus when I tried to do the full equation were different.

[dire zealot]

let the mid pt of bc be d, what is angle abd and angle dac and the length of ad

[lethal knot]

dac is 31 degrees, ad lenght is 4,8, bad is 19 degrees

[dire zealot]

okay

abc is right angle?

@lethal knot

[lethal knot]

b is 90 degrees yea.

Sinus and such need to have that

[dire zealot]

but wouldnt there be too much information then

[lethal knot]

I've tried to do a full equation but I couldn't find how to get AC with just given numbers.

The full equation wasn't about AC but it was a part that's important.

[dire zealot]

do uk cosine rule

or is only sin rule required

[lethal knot]

I can use any sin cos or tan

[dire zealot]

abc is 90, bac is 50 so bca is 40
sin40/48=sin31/AC

[lethal knot]

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[opal star]

This may be a weird thing, but at what stage of the fibonacci sequence is 446, 744, 073, 709, 551, 615 passed? Stage meaning like 0 is the first, 1 si the second, 1 is the third, 2 is the fourth, etc..

[strong lava]

You mean the 18 digit number ?

[opal star]

Yes

[strong lava]

fn ~ phi^n / sqrt(5)

[opal star]

Dunno what that means

[strong lava]

Wait

,w closed formula for Fibonacci sequence

[grand pond]

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[strong lava]

Where phi = (1+sqrt(5))/2

[strong lava]

Which leads to this approximation whose inaccuracy decreases exponentially fast

And is therefore always accurate to the nearest integer here

[opal star]

I need it for a computer program, the upper limit of the biggest data type, an unsigned long long is 446, 744, 073, 709, 551, 615, meaning I need to make sure that the user cannot enter any user above the upper amount of fibonacci numbers

[strong lava]

So you want fn > k
That's phi^n > k sqrt(5)
n > log_phi(k sqrt(5))

[opal star]

You are saying things I have no idea about

[strong lava]

,w ln(sqrt(5) * 446744073709551615) / ln((1+sqrt(5))/2)

[opal star]

...

[strong lava]

Idk where it find an x in this text

[grand pond]

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[strong lava]

So no bigger than the 87th Fibonacci number

the 86th number is 420196140727489673
the 87th number is 679891637638612258
the max number is 446744073709551615

as you can see, this is correct

@opal star This is simple at an undergraduate level, but if you're in high school then yes, that formula for the Fibonacci numbers isn't quite well known, though you may be able to prove it by induction

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[upbeat fern]

I'm supposed to describe the path of an object following this path

where y-axis is meters and x-axis is time

So the object accelerates until about 5 seconds, and from 5-8 seconds the speed is constant and then it deaccelerates to a stop and ends at 200 meter after 10 seconds

Does that seem like a good answer?

[weak nebula]

f(x) is the displacement correct?

or is it velocity

[upbeat fern]

displacement yes

[midnight plank]

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[upbeat fern]

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[steady musk]

Hello, how can I solve this?

[steady musk]

but I thought I could just swap out h(x) for Y then solve for x to get the new inverse value

don't understand what is happening there

<@&286206848099549185>

well I tried that but it told me I had the wrong answer

oh sorry it appears I made some mistake when I redid it now it was the correct answer

but thanks for the help anyways @last slate

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[hidden fox]

Can someone help integrate this ?

[hidden fox]

I did a u-sub, then got to 2 * integral ( u^2 / (u^2 - 4) du

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[tender pasture]

It means that $y^{(5)}$ is just
$$\dv[5]{y}{x} = -4y'$$
Then, $y^{(6)}$ is
$$\dv[6]{y}{x} = -4y''$$
and so on until you are back at $y^{(8)} = -4y^{(4)} = -4(-4y)$. The derivatives basically repeat in a cycle of length $4$.

[grand pond]

nvx

[tender pasture]

So you just need the first 3 derivatives

[jolly gull]

ohhhh I see now

tysm bro

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[clever reef]

[west iron]

pythagorean theorem

first name all the variables ig

no

height is an easy name to choose

what's height

actually you don't even need implicit differentiation for this if you don't want

find the height in terms of t

find the width in terms of t

no

find height in terms of t

read the problem

height

what do you know about height

good luck

[fast estuary]

Dont have time right now to help with another

[west iron]

hmm

ur on the right track

but what is height at t=0

hmm

well the problem doesn't really give a time when t=0 right

but it makes sense if we say it's when the bicyclist is directly under the balloon

so what's the height when the bicyclist is directly under the balloon

right

39 meters

so what's height in terms of t

[midnight plank]

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[lean lagoon]

Im not sure how to solve this

[jagged saffron]

which?

[fallow scarab]

53 of course

[fallow scarab]

There really isn't a coherent, self contained question here. Define all your variables

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[flat halo]

ello im back again

ready for my next breakthrough

im curious about notation

ive not really seen this notation before

wait actually

this 3 stuff i dont get

[fallow scarab]

Oof

#advanced-probability maybe?

[flat halo]

wow

idl advanced channels

[midnight plank]

@flat halo Has your question been resolved?

[last slate]

the blue: Omega is a subset of the power set satisfying a few conditions (see probability measure), basically a set of subsets closed under complements

the green: defines a function mu that takes a set from Omega to the interval [0,1] (maybe? not too sure about this one)

can you send the link to the article?

Fancy E is expectation (a fancy avErage)

[flat halo]

https://en.wikipedia.org/wiki/Generative_adversarial_network

[fallow scarab]

TOBY TO THE RESCUE

[flat halo]

@last slate

[fallow scarab]

Ugh ML

[flat halo]

whats the stuff in the subscript

[flat halo]

lol

[last slate]

ah shit machine learning

best of luck

[flat halo]

it did say GAN on top

[fallow scarab]

I read bottom to top

[flat halo]

LOL

[last slate]

nnameir

[fallow scarab]

Yes usernames should be read in the same order as function composition

[flat halo]

ok how about this thing

i clicked on markov kernel and got thrown into this well

i feel sad rn so ill go play some games

n come back alter

[last slate]

I skimmed the entire thing an understood a total of 3 words

[flat halo]

later

https://en.wikipedia.org/wiki/Markov_kernel

sauce btw

ok maybe

i shld ask my question more directly

what models or algorithms should i start with for making a general chat bot

i was thinking of using GANs

but im not sure if theres anything more suitable

[last slate]

its L for loss, and we are trying to mimimise that function. no idea what the tilde means, perhaps something to do with distributions

[last slate]

something premade :p

theres a cs server in #old-network

[flat halo]

lol thrs that

but i wanna try to do the algs stuff

[flat halo]

that dead server

why u wan me go to dead sea

D:

[last slate]

o

oops

[flat halo]

all the linked servers r dead n traps

[last slate]

oh damn

[flat halo]

jk but idk

i went to like 1 of em

[last slate]

I feel bad for all the people i've told to bugger off to another server

[flat halo]

it was so dead

had so many ppl but had no msgs for a few days

unbelievable

[last slate]

maths is the coolest science 😎

[flat halo]

mayb

wtv

ima reask about markov kernel

ty

💕

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[last slate]

something to do with measure theory here

[flat halo]

no breakthru this time

:c

[last slate]

gl

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[wraith raptor]

Let's approximate a solution to the Traveling Salesman Problem using the Repetitive Nearest Neighbor method

Here is a graph with 5 vertices.

5-5_NNPractice1.png
Edge Weights
AB = 15
AC = 14
AD = 13
AE = 12
BC = 31
BD = 36
BE = 18
CD = 17
CE = 38
DE = 22

If we start at vertex A, which vertex is the "nearest" to vertex A?
What is the weight to get from A to the "nearest" vertex?

As you go through the rest of this problem, make sure to keep a running total of the weight as you build the circuit.

You started at A and went somewhere else. What is the closest vertex to where you are now?

Where should you go next?

Where should you go next?

Now that we've gone everywhere, return to A

To create the Hamilton Circuit, list the vertices in the order that you visited them, starting at A. (Remember, you must also return to A at the end)

What is the total weight of this circuit?

heres the image

[midnight plank]

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[unkempt pendant]

.close

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[lament swift]

Help

[lament swift]

I do not get the first problem at all

The way my teacher taught related rates was just confusing

[small jasper]

Here's the equation $P=\frac{k}{V}$. Find $\frac{dP}{dt}$ using implicit differentiation given $k$ is a constant.

[grand pond]

Civil Service Pigeon

[small jasper]

the end

[lament swift]

yes but how would i solve that

[small jasper]

I'd start by thinking of $V$ as $V(t)$ so we can apply the chain rule

[grand pond]

Civil Service Pigeon

[small jasper]

the LHS differentiated w.r.t $t$ is just $\frac{dP}{dt}$

[grand pond]

Civil Service Pigeon

[small jasper]

for the right hand side, use chain and quotient rule

[lament swift]

what is LHS

ive never heard of that before

[small jasper]

left hand side

Similarly, RHS would be right hand side

[lament swift]

Ah got it

[last slate]

hence proven

lol

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[last slate]

ik stationary value is where the slope = 0

[last slate]

idk how answer tho

[fallow scarab]

The derivative gives you the slope

[last slate]

how to do derivative

[fallow scarab]

https://youtu.be/5yfh5cf4-0w

[last slate]

ayt bet

.close

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[worthy raft]

This is my first time in the server and I suck at word problems

[worthy raft]

.close

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[late nimbus]

im genuinely stumped over this question here, ive tried checking my work over and seeing multiple answer sources
$sqrt[3]{-0.027^4}$

[tired shadow]

Can't you just put it in a calculator

[late nimbus]

i tried that

but it made a negative

[tired shadow]

Well yeah

[late nimbus]

literally everything i find says its positive

for some reason

[tired shadow]

Unless you mean (-0.027)⁴

[late nimbus]

im rather confused if i solved it wrong or literally everything else just has it wrong

yeah ok nvm i just cant trust this textbook

.close thanks

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[sand geode]

I need help with writing two or one points with a slope and convert it to standard form

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@sand geode Has your question been resolved?

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[river rapids]

2=1^2x+1

What's the value of x?

[river rapids]

Can some help

[last slate]

Do you know how to use logarithms?

[river rapids]

What's that

Algorithms?

[last slate]

Okay well basically the question is impossible

Unless you mean 2=1^(2x)+1

[midnight plank]

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[wet vector]

Hey

[wet vector]

How do you solve one of the problems

I forgot

,rotate

[wet vector]

Any

Do 15

I’m confused

Step by step?

Ye

What’s next

Yep

Can u show work

Would really help

Ye

Wait

How u get x2/2y

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[last slate]

SOMEONE

[midnight plank]

Please don't occupy multiple help channels.

[lilac halo]

I would help you butI have a math test in like 2 hours

[last slate]

I finished this test

Km just trynna mark it

I been waiting for hours

[ebon viper]

Sorry, what's the problem you are trying to solve on this?

Is it question 2.?

All of them?

[midnight plank]

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[cold root]

There are 52 cards, i need to get 5 specific cards and i can grab 8 cards to get those 5 specific cards, what is the formula to this?

[cold root]

i need the formula to the chance of getting these 5 specific cards

they can be in any order

[winter swift]

$P = \frac{\mathrm{C}^5_5 * \mathrm{C}^3_{47}}{\mathrm{C}^8_{52}}$

[grand pond]

Mehdi_Moulati

[cold root]

bro if this is actually the correct one then rlly thank you i been stuck on it for like 3 hours😂

[winter swift]

anytime 😉

i have a question

[cold root]

• is x right and C is them thingd below eachotter?

[cold root]

go ahead

[winter swift]

is all the 52 cards are different ?

[cold root]

yes the cards are different

[winter swift]

• is multiply

[cold root]

they are playing cards

like this?

[winter swift]

yeah

i m not 100% sure
80% sure hh

[cold root]

it says undefined

can it be this?

maybe math in my country is diff or something

1 in 46410 probability?

?

[winter swift]

1081/81171090

https://www.wolframalpha.com/input?i=combination(47%2C3)*+combination(5%2C5)%2Fcombination(55%2C8)

[cold root]

Brooooo TYSM that is the correct answer

appreciate it bro😀

.close

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[winter swift]

welcome bro

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[granite plover]

sin(θ+40) = 0.25

[granite plover]

i know its using a cast diagram but i dont know what to do

[ebon viper]

are you supposed to use radians or degrees

for theta

[granite plover]

i think degrees,idk what radians are

[ebon viper]

okay

do you know the unit circle diagram?

just googled cast diagram and its just another word for that

roughly

same principal

[granite plover]

okay cool

[ebon viper]

So essentially I would rewrite it as a fraction because the values on the unit circle are usually fractions

$sin(\theta + 40) = 1/4$

[grand pond]

Hydro

[ebon viper]

well this wont be on the unit circle but it will be doable with cast diagram

[granite plover]

okay

[ebon viper]

do you want me to paste the diagram here or

[granite plover]

nah its fine but thanks, i just need to know the solving part

[ebon viper]

ok well basically you will need a calculator since this isnt on the base unit circle, heres how you would do it let me just draw it in paint

[granite plover]

haha thanks

XD

[ebon viper]

so did you know that sin(90) is 1

wait

i mean 1

sin(90) is 1

not a half

yeah Im just asking if he knew that

or they knew that

[granite plover]

he is fine, and yeah i know that

[ebon viper]

yeah okay

and do you know in which quadrants sin is positive like in this case? since 1/4 is positive?

[granite plover]

top left and right

[ebon viper]

yeah

so basically sin (theta + 40) is somewhere in the top left and top right

so what we can do is use a calculator and that should return one angle

we can determine if that is the top left or top right angle

[granite plover]

what do i put in the calc

[ebon viper]

and then we can do 180 - that angle

to get the second

oh

do you know about inverse sin

[granite plover]

yeah, is it just sint^-1(0.25)

[ebon viper]

yep

[granite plover]

14.48 (2dp

[ebon viper]

ok so that is clearly between 0 and 90

so thats the top right one

so do 180 - 14.48 to get the second angle

[granite plover]

do i not do anything about the +40?

[ebon viper]

thats for last

[granite plover]

ok

i got 165.52

[ebon viper]

ok so now we know that

sin (14.48) = 1/4 and sin (165.52) = 1/4
but we also know that sin (theta + 40) = 1/4
so we can conclude that theta + 40 = 14.48 and theta + 40 = 165.52

so you can find the two values of theta

[granite plover]

ah okay, thank you so much!

[ebon viper]

ah also

you might want to check if the question says anything like theta is acute

or some domain

like 0<theta<360 because then theres a few more steps but

if not then ur good to go

[granite plover]

its between -180 and 180 so i just add or take away 360

[ebon viper]

ah okay

neither of your values will be in the domain if you add or take away 360

so its all good like it is

[granite plover]

sounds good, thank ya!

.close

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[ebon viper]

np 😄

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[wet vector]

hey

[wet vector]

how do i factor this

i forgot how to do it

n^2-144=20

any1?

[cobalt silo]

Notice that 144=12^2

[wet vector]

yea

?

[cobalt silo]

a^2-b^2=(a+b)(a-b)

[wet vector]

mhm

[cosmic elk]

@wet vector are you trying to factor n^2 - 144?

or solve for n

[wet vector]

yes

factor

@cosmic elk

[cobalt silo]

This should be enough then

[wet vector]

no

is it

[cosmic elk]

yes

[wet vector]

(n+12)(n-12)

?

[cobalt silo]

That's the factorization

[wet vector]

oh shoot i feel so dumb

.close

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[last slate]

hi can someone explain this

[hard tangle]

give this a read

then see if you can apply it to this problem

[last slate]

i know how to solve it lol

i just was unsure about the designation of an object here

but i realized it

thx

[hard tangle]

np

[midnight plank]

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[stable ridge]

\

[stable ridge]

someone please help me find the perimeter

[proud temple]

perimeter is sum of all sides of the figure

[glad canyon]

https://discord.com/channels/268882317391429632/908076667224854568
The same problem in this channel

[stable ridge]

alright thanks!

.close

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[royal junco]

Hi how could I know how long would it takes until the two investments have the same values

[royal junco]

<@&286206848099549185>

[terse spear]

!15m

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[outer quail]

Where is the question at?

[royal junco]

For example p=$80000 r=7% m=365 the other one is p=$70000 r=10% m=4

[grand pond]

peri
Compile Error! Click the reaction for more information.
(You may edit your message to recompile.)

[royal junco]

It’s the rate of interest in calculus

How do I find the time where both of them are equal

In amount

[midnight plank]

@royal junco Has your question been resolved?

[royal junco]

<@&286206848099549185>

.close

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[pastel surge]

How do I do this

[jagged saffron]

Write M as a linear combination of the guys in B

[pastel surge]

Do I turn it into equations?

From a matrix

[midnight plank]

@pastel surge Has your question been resolved?