help-49

[tender linden]

Then plug in x=3

And get the values from the table

Rinse and repeat for the other questions

[vast swift]

why is it f'(x)g(x)+f(x)g'(x)

[tender linden]

Product rule

[vast swift]

isnt it f(x) * (g)

hmm ill try

[tender linden]

Yeah, but I took the derivative of h(x)

[vast swift]

it just seems that the question is really unclear with what it uses it

[tender linden]

I think it's clear enough, just remember the derivative rules and find the general equation for h'(x)

With what's given

Then plug in whatever x is, and solve

[vast swift]

Yea, your right It's just that I wouldn't know why to use the product rule since it already gives the equation of f(x) * f(g) like do I know I should use it \

[tender linden]

Well, h(x) is equal to the product of two functions

In the first question

[vast swift]

so just replace f(x) with f'(x) *g(x) and g(x) with f(x)*g'(x)

[tender linden]

Not exactly, it's not replace, but h'(x) = f'(x)g(x)+f(x)g'(x)

You just use the rule to find h'(x)

[vast swift]

oh so use the product rule for second and chain rule for third?

I kind get it since it just showing equations of each rule correct?

[tender linden]

Use quotient rule for the second, and chain rule for the third

Yeah

Basically

[vast swift]

Oh tyty

I couldnt understand that

ty

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[tender linden]

Np

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[last slate]

i am literally lost with this one i need to find the area of abc

[last slate]

<@&286206848099549185>

as I understand

i think i need to find ab first no?

[vast swift]

youve learned sine rule cosine rule yes or no?

[last slate]

yes

[vast swift]

so AC is 10

[last slate]

how so

[vast swift]

so c share same angle

Bc is shared together

[last slate]

i am idiot i was thinking it was not sharing the same angles for like 4h

now

;DDDDDDDDDDDDDDDDD

[vast swift]

180-90+20

[last slate]

so i find ab

with cos?

[vast swift]

70 +70 140 forb

[last slate]

then find D?

why 70+70?

[vast swift]

tech nically u doint even need to use the sine rule or cosine rule

[last slate]

because it divides them again?

by two?

[vast swift]

16^2-10

you would be able to find the hight

[flat halo]

im so lost how u got ac as 10

[last slate]

yeah

he says it divides because of 90 degree

[vast swift]

doesnt it say ad is 20

[flat halo]

um yea?

but that doesnt mean the line cuts ad in half

[vast swift]

the angles sould be same since BC hight is equal to both triangle

so A and D anre same angle meaning you could find the B angle

[flat halo]

wow ive no idea what u did but if sqk follows allg ig

[vast swift]

Naw you can prob explain better

since its a right triangle

[flat halo]

i think i finally got the Q

but idk what u were sayin still

[vast swift]

NvM im tripping

1/2 ab since C

[last slate]

yeah now i lost it

[vast swift]

1/2 16 20 sine of 20degrees

https://mathbitsnotebook.com/Geometry/TrigApps/TAarea.html

[last slate]

i got my answer 68.4

the area

of abc

68.4

how much did you get

[vast swift]

I got 54.72322293

[vast swift]

isnt it sine of 20?

[last slate]

i don't think that corner a = corner d

it's possible, but it's not good to make assumptions bc the picture isn't always drawn to scale

[vast swift]

i guess U can use 16/sin 20 = 20/sin x to find angle of b

then you can find angle of D

and use 1/2 * 16 * 20 sin of D

<@&286206848099549185> Am I wrong or right I'm having an identity christ here

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[sharp summit]

does anyone know what it means by on the interval

[west bloom]

interval just means that the x value cannot be outside of that

so its like the x value can be between -2 and 2

[sharp summit]

but how do i set that on the graphing calculator

[west bloom]

lemme find mine 1 sec

if you set up the equation of the graph in y= on the calc, then go to window and set the intervals

then you can view the shape of the graph on the graph page

[sharp summit]

hmm i have scale

xmin and max and all that

[west bloom]

right

so xmin would be -2, xmax would be 2, ymin would be -4, ymax would be 10

keep scale at 1

[sharp summit]

my min at -4

[west bloom]

yes

[sharp summit]

why*

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[flat nebula]

ive subtracted the right side over to the left side so that everything is equal to 0

then factored the denominators

to (x-3)(x+1) and (x-1)(x+1)

i think the next step is to find the LCD, then simplify

and if that is the case, that's what I need help with

am i totally out to lunch or is this looking correct so far?

so i keep them separated?

ok, so then what?

@last slate

so i cross multiply?

right, so then where would i go from there>

?

ok, so how exactly do i do that in this situation?

multiply both sides by (x-3)? because both sides already have (x+1)

ok, so then just evaluate with different values to see which parts of the domain satisfy the inequality, right?

that seems like a lot of terms...

can't i go ahead and subtract the 2 numerators?

to get one fraction

[flat nebula]

instead of this

ok

would i expand 30 first?

to (x-1)?

or just leave it how it is

so it'd be 30x-30

and for the "other side"

do i leave those factored?

because if not i'd get x^2, but i want everything factored, right?

and since im sutracting the x^2-3x+10x-30

would the minus sign distribute?

changing the signs?

so i have -x^2 + 23x / (x-1)(x-3)(x+1)

does that seem right?

and that numerator wouldn't factor...

so i'd use the quadratic formula to find the y intercepts?

or like, where the function is actually equal to zero

k, makes sense

riiight

@last slate just got it right! thanks for the help!

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[keen sand]

hello, I am confused here on this problem

[trim bone]

i am too

[keen sand]

here, to find the P,Q

[open hatch]

Wth is gamma

[keen sand]

is it correct to find them by r(0) and r(1)

[keen sand]

Г

[open hatch]

? I know it's a Greek letter but what does it mean in this context

[sage helm]

Hangman's gallows

[keen sand]

oh lol sorry, its just used to name the curve

[open hatch]

Assuming P,Q are the endpoints of gamma, yes

Have u found f

[keen sand]

I am also confused there, isnt the given h the f?

mm so no

how to you find d

f*

[lyric charm]

where do any of y'all see a Gamma?

oh

at the very end...

[keen sand]

is the f xe^(2y)-x^(2)y?

[open hatch]

,w grad xe^(2y)-x^(2)y

[grand pond]

Results provided by WolframAlpha

Click here to refine your query online
Upgrade to WolframAlpha Pro!

Requested by giannis_money#9853

[open hatch]

Doesn't seem to be correct

[keen sand]

it matches

[open hatch]

It's missing a +1 in the y component

[keen sand]

xe^(2y)-x^(2)y + C

would that mean anything?

[open hatch]

No the grad of that is the same

[keen sand]

oh i see

[open hatch]

You can add a y

[keen sand]

you mean xe^(2y)-x^(2)y+y?

[open hatch]

Yes

[keen sand]

okk

[keen sand]

over here

it states that t is 0<t<1

so how can you find the P, Q?

[open hatch]

? @keen sand

[keen sand]

okay

I have another problem that Im not sure if it is correct

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[ornate steeple]

can someone help me put that into just one equation that only has x and y

[sweet night]

t=x/130

y=3.2+42(x/130)-16(x/130)^2

[ornate steeple]

hmmm

ok i see

thank you

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[leaden sonnet]

@sweet night don't give answers away

[sweet night]

huh?

I gave the steps

[cold rain]

Can someone go through how to solve this problem.

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[graceful pumice]

can someone help me with 53 please

[dark oasis]

Rise/run

G(-3)-g(1)/(-3-1)

[graceful pumice]

i did this, however, the answer in the book states the solution is -1.6 somehow

and i dont see how that is possible

[dark oasis]

(3.9-(-2.5))/(-3-1)

[graceful pumice]

why would you use the point (1,-2.5) though?

[dark oasis]

Because question 53 as for between '-3 and 1

Ask(

So u would use those points

[graceful pumice]

so why couldnt i use 0,0?

its between that too

[dark oasis]

No

Average rate of change is from 1 point to another

U could use 0,0 bur the question doesn't ask for that

It asked for between x = -3 and 1

[graceful pumice]

ohhhhhhhh, i understand now, i thought i was supposed to use the -3, 1 as an individual point, thank you

[dark oasis]

Np!

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[graceful topaz]

.reopen

hello can someone teach me on how to do this?

[terse spear]

https://youtube.com/watch?v=TQTMcUWG6QU

[graceful topaz]

i still dont get it

[last slate]

What are you confusing about

[graceful topaz]

this

i have an upcoming exam with that

[last slate]

Yes what part of the question is confusing you

Do you know what scientific notation is?

[graceful topaz]

nope

its the test b 1st question

the test 2 1st question actually

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[serene apex]

does anyone know how to do this?

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[late sparrow]

For 6 c

I did it

Or i tried at least

But it’s wrong and I wanna know why

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@late sparrow Has your question been resolved?

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@late sparrow Has your question been resolved?

[last slate]

@late sparrow looking

[late sparrow]

Thank you

[last slate]

@late sparrow got part a

Working on part b

[late sparrow]

Thank touuu

[last slate]

This is a dumb question. The problem statement is vague

[late sparrow]

Yeah that’s why I wanted to ask

Like

How would you know when to use Pythagorean theorem and when to use the component method if that’s what your using

Oh wait

No don’t do it all

Just part c

6. c.

[last slate]

@late sparrow is this physics or math?

[late sparrow]

Physics

[last slate]

I got part c

I didn’t really use vectors

@late sparrow

You can find the angle.

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[uncut drift]

#old-network there is a physics discord too fyi

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[robust shale]

Can someone assist me with setting up b? I got 0.94 but apparently that's wrong

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[knotty forge]

Hi

So a common misconception that people bounce back to is dividing one number by the other. Don't do that

Moreover, ratios can have more than 2 numbers

If we have a pancake recipe that says the ratio of cups of flour to milk is 1:2, that means you need 1 cup of flour for every 2 cups of milk

And here is where people run into trouble: trying to convert ratio to proportion

"What proportion (or what fraction) of this recipe's volume is flour?"

?

Any ideas?

@last slate

[glad kite]

hi

how are you

[visual tiger]

Hello @glad kite, this channel is reserved to thegreatgamer2011. If you want to get help, go to #❓how-to-get-help then go into an empty help channel. If you just want to chat, use general chats instead :)

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[glad kite]

33

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[flat halo]

LOL

PSLE

[scarlet snow]

HAHA

[flat halo]

i think its system of linear

[scarlet snow]

NAH

[flat halo]

just make 2 equ

[scarlet snow]

this is very eays

[flat halo]

and rref

[scarlet snow]

its primary school

no system of eq

they have the same number of coins

helen has 40 less twenty cent coin than ivan

therefore 40 more 50 cent

so 40 * (0.5-0.2) = 40 * 0.3 = 12 dollars more

then try and use a similar process for the second part

[hot sandal]

but

[flat halo]

wow u actually solving it

[hot sandal]

how heavy is a god damn coin

:/

[scarlet snow]

you dont need to know masses of either coin

you know how much more fifty cent is

and you know that helen has 40 more 50 cent coin

and 40 less 20 cent

so first try and find how much more mass helen has

[hot sandal]

x(0.5)+64(0.2)=x(50)+104(0.2)

[scarlet snow]

huh

[hot sandal]

coins

[flat halo]

idk if thats right

but u shldnt just

throw in an x

say what it means first

like

[hot sandal]

x is (a number of) 50 s

[flat halo]

let x denote the number of bananas i used to make a cake

[flat halo]

a number of what

[scarlet snow]

banana cake 🤮

carrot cake 🥕 👍

[flat halo]

LOL

carrot cae

[hot sandal]

how to count how much more

ehh

[flat halo]

just

🥣

[flat halo]

what r u sayin

[scarlet snow]

okay try doing this seperately for 20 cent and 50 cent

so for 20 cent how much more ivan has

coins

[hot sandal]

40

[scarlet snow]

yeah

so the mass difference is

[hot sandal]

800 cent

[scarlet snow]

40 * 20 cent weight

[hot sandal]

800/50

[scarlet snow]

then for 50 cent

the mass difference is 40 * 50 cent weight

[hot sandal]

16 (50) cent

[scarlet snow]

WHAT NUMBERS ARE U SpTITIn

[flat halo]

spittin facs

[hot sandal]

you say we dont need to count mass

[scarlet snow]

yeah we dont

find the difference between

50 cent mass diff and 20 cent mass diff

40 * 50 cent weight - 40 * 20 cent weigh

whats tha

hint factor 40

[hot sandal]

x(0.5)=8+y(0.5)

dude

[scarlet snow]

dawf

[hot sandal]

im at the first floor

dont bully me

[scarlet snow]

stop

introducing variables

[flat halo]

what

[scarlet snow]

this is literally a primary school quesiton

[flat halo]

eh

thrs nth wrong with introducing vars

just denote em first

like

🪵 = number of cakes i stole

[scarlet snow]

i mean sure

[flat halo]

🥣 =number of pizzas i stole

[scarlet snow]

making random equatiion

with variables

[hot sandal]

weird

[flat halo]

💕 =number of cakes i ate

[hot sandal]

same number of coins

[flat halo]

yea the prob is that

[hot sandal]

but different value

[flat halo]

a random eq just popped with unintroduced vars

like

💕 * 3 = 🥣 * ❤️ + / 💔

not actually

but close

[last slate]

Another algebra situation

[flat halo]

💔

[reef pelican]

Easy. Answers 4

[hot sandal]

question

[lament sleet]

🧑🏻‍🦼 = 🧎🏻 + 🦽

[flat halo]

HAHAHA

[scarlet snow]

👶 = 🍆 + 🍑

[reef pelican]

Hmmmmm I think it’s a citrus instead

[scarlet snow]

oops

[hot sandal]

im stuck at the limit

idk how many coins are possible

yeet

[flat halo]

ok first

nicely define what var u r using

ill use

x = number of 20C coins, y=num of 50C coins

then work from here

[hot sandal]

x is helen's number of 50 cent coins

y is the other's guy number of 50 cent coins

[flat halo]

oh its 2 ppl

hahaha

ok

[hot sandal]

x+64=y+104

they have the god damn

same amount of coins

how

they both have the same number of coins,

20 cents and 50 cents mixed

they want to know who is the richer kid

and the difference of their value

whoever made this ass question

[reef pelican]

ok hol on im doing it

[flat halo]

oh

ok

i finally read the Q

hahahhaa

yea u dont need 2 vars

u just need 1

o well

with that crasher doin it

ull prob get a fully worked soln

[hot sandal]

idk if its even possible to do

seems rigged

[flat halo]

ok

miku b takin awhile

[reef pelican]

i am writing sebtebces

sentences

[flat halo]

oh mikus back

[reef pelican]

for explanaing

explaning

[flat halo]

oki

u got this then

miku

y u writing this tho

isnt this a

pretty trivial prob tho

also whys it take u so long

imma just do it lol

let num of coins helen has be x

so

[reef pelican]

(a)

[flat halo]

hel val = 64*.5 + (

ok

well

finally

hm wonder what psle Q5 means

isit a mcq

prob not

[hot sandal]

primary exam

[reef pelican]

maybe a section b qn

[flat halo]

o well

i dont rmb what the sections mean

[hot sandal]

didnt know swapping those works

x=y+40

[flat halo]

omg

miku

ur handwriting is beatiful

[reef pelican]

ty

[flat halo]

hm idk i would just stuck to just 1 var all the way

[reef pelican]

b

ok

[flat halo]

🥣

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[lost pond]

Please help me

[viral marlin]

On what exactly?

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[minor onyx]

If I divide all values by x in the denominator, what value would I divide a root numerator by? My brain wants to say 1/x but it's giving me the wrong answer.

[slender walrus]

your question is unclear

can you show exactly what you're working with and what you're trying to do

[minor onyx]

This is the equation:

I'm now realizing I phrased my question wrong

in any case I'm trying to figure out how to do the question but if I divide the bottom by x, I don't know what to do with the top

like 3/half an x?

But I know this is wrong.

[slender walrus]

recall properties of sqrts

sqrt(a/b) = sqrt(a)/sqrt(b)

dividing the radicand like that,
you're effectively dividing the denominator by sqrt(x)
and you would do the same to the numerator

[minor onyx]

Seem to still be running into an error?

[hallow olive]

You can simplify x/√x

$\sqrt x=x^{\frac 12}$

[grand pond]

Andrea276

[hallow olive]

And x=x¹

[hallow olive]

@minor onyx

[minor onyx]

So it would become x^3/2 and then I could insert x=infinity? And my bottom row would be (0-infinity)/1, which equates to -infinity?

[hallow olive]

It's x divided by √x, not multiplied

So you wouldn't get x^3/2, but x^1/2

But then the reasoning is correct

And you would still get -inf

[hallow olive]

@minor onyx is it clear why your division was wrong?

[minor onyx]

I'll always be good for like 20 questions and the struggle on one because I forget some fundamental algebra thing. :/ I'm currently googling to remember how to do division of same base exponents.

[hallow olive]

$\frac{a^n}{a^m}=a^{n-m}$

[grand pond]

Andrea276

[hallow olive]

With products you instead sum the exponents: $$a^n \times a^m=a^{n+m}$$

[grand pond]

Andrea276

[hallow olive]

@minor onyx

[minor onyx]

That definitely clears it up.

I think that's all the help I needed. Thank you. 🙂

[hallow olive]

yw : )

[minor onyx]

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[kindred kestrel]

hello, i've been stuck with this particular question for a while now, i followed my professors directions that he had listed for my online class but can't seem to get the right answer when i submit my result, here is my question and my work

[halcyon trellis]

How did you get to xy+sin(x)?

[kindred kestrel]

i followed along the lecture that he posted, i didn't really understand where he got the xy

the example that he did was similar to the question i have

[halcyon trellis]

I don’t think it’s a valid step. Instead differentiate the given equation sin(xy)=y^4

[kindred kestrel]

ok, let me try it

its just that i tried doing that earlier but that answer didn't work out either

[olive zephyr]

also as a note, $\frac{d}{dx}(y^4) \neq 4y \cdot \frac{dy}{dx}$

[grand pond]

Shell

[olive zephyr]

it's almost right but it's missing something

[kindred kestrel]

alright

would it be -ycos(xy)/4y^3 -xcos(xy)

damn that layout is terrible

still didn't work god damn it

oh i see my problem

thank you for your help gentlemen @halcyon trellis @olive zephyr

[olive zephyr]

course

[kindred kestrel]

im gonna close the thing

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[stone pasture]

What's a's value? I thought a is always in the left whether it's bigger or not in hyperbola

[stone pasture]

But in here it said that a=2 instead. Was I thinking wrong? Is y/b^2 is the default?

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@stone pasture Has your question been resolved?

[stone pasture]

Wrong pic @_@

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[stiff flame]

how do i do d

[midnight plank]

@stiff flame Has your question been resolved?

[stiff flame]

<@&286206848099549185>

[stiff flame]

<@&286206848099549185>

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@stiff flame Has your question been resolved?

[stiff flame]

hmmm

quite the delay

[unkempt halo]

well, how did you solve c?

if P(6,7,8)=3/8=0.375, then the probability that a player has not been able to start after the sixth attempt is the same as the probability a player spun numbers in the range 1-5 six times in a row, which can be represented as (1-.375)^6=0.625^6=0.06 (hopefully that's the same answer you got for c).
The probability that a player has not spun 6,7, or 8 within the first n tries, by the same logic, is then (1-.375)^n=0.625^n

So, if we know the probability that a player has not spun 6,7, or 8 in a certain amount of tries, but we don't know how many tries, then we have to solve for n using the confidence given to you in the problem

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[eager cliff]

What should I do next after getting the point estimate? Or am I wrong for getting the point estimate?

[eager cliff]

<@&286206848099549185>

[reef pelican]

Ok

So in the qn we are given the following
1048 teens
698 had a tele
95 confidence

So
n = 1048
x = 692
c = 0.95

[eager cliff]

Then I'll divide 692 by 1048 right?

[reef pelican]

So we use the following formula :

Then refer to ur table
where
z multiplier is 1.960

[reef pelican]

Then yes this step , which is p hat

[reef pelican]

Then sub values into this formula

Then just convert the interval to their respective percentages

[eager cliff]

how is it 1.96?

[reef pelican]

Do u have math table

I just refer there

[eager cliff]

is the p hat's value 0.6603 then I substitute it here?

[reef pelican]

Yes

[eager cliff]

okay okay, but i do not know the basis for the 1.96 value on the z table

when i look at my table, the 1.96 value shows 0.9750

should i look at the z table or t table

oh lol nevermind i was looking at the wrong table

[reef pelican]

95% of area of a normdist is within 1.96 sd of the mean

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[last slate]

is (AnBcnC)U(AcUBc) equivalent to (AnBnC)c

[polar mortar]

no

[polar mortar]

i don't think anyway.

[last slate]

i have no idea how to rigorously prove it

[polar mortar]

those don't say the same thing.

[last slate]

do you have a counterexample

or anything

[polar mortar]

no, like your first post doesn't say the same thing as the image.

[last slate]

oh

oops

[polar mortar]

which one is it supposed to be?

[last slate]

2nd

[polar mortar]

ah, ok, that's true

DeMorgan's Laws $(A\cap B)^c = A^c\cup B^c$

and

[grand pond]

Zybikron

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[boreal pecan]

Could someone explain this to me?

I always get confused when it involves and "e" and dont know what to do

[dull yoke]

do u know product rule

@boreal pecan

[boreal pecan]

Yes

f'(x) = (x^2)(e^x) + (e^x)(2x)

Ive gotten up tp here

Now i need the second derivative

[dull yoke]

ok so

thats correct

now u just need to do product rule on both of those terms

once on the left term and once on the right term and then u will have the 2nd derivative

[boreal pecan]

f''(x) = (x^2)(e^x) + (e^x)(2x) + (e^x)(2) + (2x)(e^x)

like that?

[dull yoke]

ye

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[deft zodiac]

to solve for n when T=1/8

how would i approach this?

[warm magnet]

Rewrite 1/8 as an exponent

[deft zodiac]

2^-3?

[warm magnet]

Yeah, perfect

And then use exponential properties

$$\log{a^b} = b\log_{a}$$

[grand pond]

Umbraleviathan

[deft zodiac]

yes thank you

do you mind if i keep this open just in case i get stuck?

[warm magnet]

Please do, yeah

[deft zodiac]

tysm

im stuck

my next thought is to get rid of the denominator

by multiplying both sides by 3

giving me

3n =3-(21log2^-3)

is this wrong? @warm magnet

[warm magnet]

Yeah I have no idea what you did

[warm magnet]

I just said to use this

[deft zodiac]

ouhh

i useed thee wrong one

think i got it

let mee take a picture

@warm magnet

[warm magnet]

Yeah

[deft zodiac]

okayyy

tysm

[warm magnet]

Np

[deft zodiac]

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[hollow pier]

in the mean value theorem, what does c stand for?

[flat halo]

i think its just some inbetween val

[austere nest]

c is a point in [a,b]

a<c<b

just means it is between those 2 nums

[hollow pier]

got it got it

tyty

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[tired pewter]

can someone help me understand question 6?

[manic garnet]

From the graph you should have made in question 3 shade the parts of the curve that verifies the inequality

[tired pewter]

this is what i placed in q3

do i just do this?

[manic garnet]

Yea so that square you shaded represent every possibility of how many regular and ho many special can be made in one 360 hrs go

[tired pewter]

thanks fam

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[willow scroll]

https://cdn.discordapp.com/attachments/908078008609431674/1030350400425050202/IMG_0017.png

[willow scroll]

2nd part of this
i assume you use pigeonhole bc of the ceiling and floors but idk how to do this

i know the 3 in front comes from the fact that there are 3 gates and you need to have a gate at the beginning of the formula

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[willow scroll]

<@&286206848099549185>

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[flat halo]

i find the first n 3rd option weird,

the 1st option, shldnt it say phi instead of y

3rd option shldnt it say phi in ]phi0, 0[ , or well, ]0,phi0[, depending

like both feel wrong to me

[hard umbra]

notation is actually just so bad

[flat halo]

ye the 2nd doesnt even hv a |

[hard umbra]

"holomorph" lol

[flat halo]

ye its not a real thing

but im guessing it means holomorphic

[hard umbra]

like

it doesnt have all the conditions

for some reason?

or the first option is a typo

and its meant to say 0 < sign(φ0)φ < |φ0|

like

basically it needs to be holomorphic on the sector

and then the arc needs to vanish when you push it to infinity

[flat halo]

basically what i said

[hard umbra]

oh

i didnt read lol

[flat halo]

y is like a new world that appeared

idk the 3rd option feels just plain weird tho

[hard umbra]

3rd option is wrong

[flat halo]

its jsut sayin it has to work on the whole um

[hard umbra]

its not weird its wrong

[flat halo]

circle

[hard umbra]

no

[flat halo]

no?

[hard umbra]

the r < r0 is wrong

[flat halo]

hm?

isnt it like some

wait

..

im a bit confused

but generally its just some huge val we go to

n r0 is just a random thing

ye?

[hard umbra]

r0 is a constant

the function needs to be holomorphic on the entire sector

like

infinite sector

like

[hard umbra]

on that entire sector

[flat halo]

ye um

[hard umbra]

for all r > 0

[flat halo]

what does this

r0

or z0

even stand for

[hard umbra]

the function needs to be holomorphic

its a complex number

a point in C

[flat halo]

ok well

kinda get it

ok

thanks

level up!!!

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[blazing arch]

How should I approach this discrete math proof
Let f : A → B be a function. Prove that if f is not one to one, then f −1 is not a function.

[blazing arch]

to me it seems intuitive to believe that if there are 2 or more values in the domain that result in the same value, then when you inverse the function, then there will exist a point in the inverse function where the domain has 2 or more values in the image/range

[midnight plank]

@blazing arch Has your question been resolved?

[runic hamlet]

yes then put that into words

if f is not one-to-one, then z=f(x)=f(y). then what is f^-1(z)?

and that's it

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[golden spindle]

Hello there, I would appreciate hints to solve the following question.

I am unsure about how to form the cdf here?

Thank you!

[golden spindle]

I was thinking maybe this could be modeled by some distribution like Bernoulli or Binomial and then I could just write their cdf's as the answer

but im not sure if I should think of this as one trial or many trials so im not sure which to pick between Bernoulli or Binomial

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[ember jewel]

guys a subspace is a plane that passes through the origin?

[ember jewel]

so for example in R^3

a (x, y, z) + (0, 0, 0)

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@ember jewel Has your question been resolved?

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[lilac flare]

$\int_{v_1}^{v_2} v^{-\gamma} dv = \frac{1}{-\gamma + 1} \left( v_2^{-\gamma+1} - v_1^{-\gamma+1}\right)$

[grand pond]

Sacha

[lilac flare]

is this right? gamma is constant

[steel night]

correct

[lilac flare]

then idk where i went wrong

thanks

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[distant ocean]

I'm having a hard time to understand derivatives can someone give me concrete idea and a resources?

[hard shard]

khan academy

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[hexed talon]

Why is $e^t/2 <1$

[grand pond]

KN

[vernal junco]

IN a GP sum of infinite gp is a/1-r.
Whenever r<1

[hexed talon]

i see

thanks

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[last slate]

can someone help me with this pls

box is 10 disk (9 at 22.75 and 1 free), how much is a box?

how much is per box ?

yeah

254.85

how do you find this?

wait no

204.75

typo

Then if he made 3003 in total you can find the number of boxes he sold

by multiplying the 204.75 ?

to a number that makes the 3003 ?

yeah

how can i find it easily ?

do i have to multiply until i get it

Well either you have a calculator and you do 3003/204.75

14.67?

Alright so he sold 14 complete boxes of 10 disk

And some more disks

Now we have a problem

We said that a box is 9 paid disk and 1 free

That's the case for our 14 first boxes

but then the 0.667 is not a complete box so it doesn't have the free disk right?

yeah

So we need to try something else

What about the number of paid disks he sold

disk is 22.75 and total is 3003

the number of paid ?

ohh yeah

So how many paid disk did he sell? (not counting the free ones)

9?

im so confused sorry

Alright let's try to do it with easier numbers

Let's say a disk is 2$ and he made 10$ in total

How many disk did he sell?

5

Alright

Let's say a disk is 22.75$ and he made 3003$ in total

How many disk did he sell?

It was 10/2 and now it is

oh yeah sorry

divide total money made by the money per disk

to find the number of disks

132 ?

ok!

So he made money with 132 Disks

BUT

We need the number of boxes

the box right ?

?

so our case is the box now

thats what i was saying

What we want is the total number of disks sold so we can divide by 10 and find the number of boxes

Can you see that?

Yeah

so its 132 divide by 10 ?

but one is free ?

Wait

We have the number of paid disk :132

But we don't have the number of free disk he sold

Can you find it? every box is 9 paid and one free disk and he sold 132 paid disk

im still getting 14.67

Yes but now it's not the number of boxes

But the number of free disk

And it can't be 14.67 right?

yeah

That means he made 14 boxes with one free disk each

And then he didn't complete the last box so he didn't add one

so the .67 was the incomplete one ?

Yes it's the incomplete box

and its 140 so 8 free disks ?

no wait

So what is the total number of disk?

132

That's the paid ones

What about the free ones

9

That's not what you found

Alright let's see what we did

We found the number of paid disk he sold: 3003/22.75 = 132, total money divided by money per disk

Then we found the number of free disk he sold: 132/9 =14.6777 so 14, number of paid disk divided by 9 (because one is free every 9 paid)

isnt 14 our answer ?

The answer we need is the number of boxes

We worked on the number of disk for now

Let's see it another way

We're making boxes

we put 9 paid disk and one free in each box

We have 132 paid disk, that's what you found

So there is 132 disks per box

no there are 10 disk per box

Alright

We're making boxes

We have 132 paid disk

How many boxes can we make?

13.2 ?

we put 9 paid disk and one free in each box

How many boxes can we make?

should i multiply 132 and 9 ?

You did it great just a few moments ago

It's about dividing here

14 boxes

Alright

14.666666667 boxes

So we sold 14 complete boxes and some disk

How many disk?

132

and free ones

Well yes but now we made 14 complete boxes

So we don't have 132 paid disk anymore

how many do we have?

We started with 132 disk and we did 14 boxes with 9 disk each

so its 1?

i just divided 14 and 9

Yes you need to understand why you're dividing

It's not 1

Alright let's do it with easier numbers

We started with 10 disk and we made 1 box with 9 disk each

How many disk do we have?

90

Sorry i think i need to rewrite it

We started with 10 disk and we did put 9 disk in 1 box

How many disk do we have left?

1

ok

Now

We started with 132 disk and we did put 9 disk in 14 boxes

How many disk do we have left?

123

hmm no

3

132 - 9*14

I don't know how to rephrase it sorry

its all g

im worried if im taking too much of ur time lmao

we can stop this

No but it's a bit unclear for u

Well he sold 14 boxes and 6 disk so 14.6 boxes (or 14 complete boxes)

so thats the answer ?

cuz were finding the box

yeah

alright thanks

.close

[midnight plank]

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[midnight plank]

Please don't occupy multiple help channels.

[untold bobcat]

im on question c

im nottt?

.close

[midnight plank]

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[midnight plank]

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[calm halo]

Yes

Never had to prove anything, just had to find out the coordinates for vector x in terms of the basis vectors in basis B