🔒 how can i use double index i need help for my project

[minor veldt]

@river barn

Python help channel opened

Remember to:

• Ask your Python question, not if you can ask or if there's an expert who can help.
• Show a code sample as text (rather than a screenshot) and the error message, if you've got one.
• Explain what you expect to happen and what actually happens.

:warning: Do not pip install anything that isn't related to your question, especially if asked to over DMs.

Closes after a period of inactivity, or when you send !close.

[hearty spire]

Hi, can you clarify what you mean by "double index"?

I guess you mean "two-dimensional" or nested lists, like

a = [[1, 2, 3], [4, 5, 6]]
print(a[0][2])

but I'm not sure, so I want you to clarify.

[river barn]

no for example i got mike tyson i need to make it M.T using index and i got list of names i need to do same as the example name

and using for loop i forgot to add that

[hearty spire]

Look into the str.split method. It'll let you split a string by whitespace, so "Mike Tyson" will become ["Mike", "Tyson"]. From there you can think about how to get the first letter from each element 🙂

[river barn]

i will try that give me min to try it i will send the result if it worked

ok but how can i add the name of lists so it can know like do i do list_friends.str.split(", ")?

[hearty spire]

no, it would be something like: (one min)

!e

list_friends = ["Mike Tyson", "John Brown"]
for friend in list_friends:
    print(friend)
    print(friend.split())

[minor veldt]

:white_check_mark: Your 3.14 eval job has completed with return code 0.

001 | Mike Tyson
002 | ['Mike', 'Tyson']
003 | John Brown
004 | ['John', 'Brown']

[hearty spire]

str.split means that the .split method is available on strings

each element in the list_friends is a string, so we can use .split on them and get this

[river barn]

it is giving me this error AttributeError: 'list' object has no attribute 'split'

[hearty spire]

yes, you can't .split on lists directly

you must use it on a string

even a list of strings won't work 🙂

[river barn]

🥲 sooo what do i do im confused

[hearty spire]

you would need to break out the for loop, to get at each individual string in the list, then apply it to that

[hearty spire]

OK, so list_friends is not actually a list of strings. it's a list of list of strings, see?

[river barn]

well if i wanted to add different names i need to do this

[hearty spire]

yes, but since you did the .split(", ") at the input stage, you already have the first and last name in two separate items

we don't need to .split anymore

[river barn]

ok but it made mike tyson how can i turn it into M.T

[hearty spire]

first, let's think about the data we're working with.

imagine the user enters Mike, Tyson into the input

your code does .split(", "), so we get ["Mike", "Tyson"]

now our task is to turn this into "M.T"

can you write a loop that, given a list like ["Mike", "Tyson"], prints the first letter of each string inside the list?

[river barn]

let me see show you the project it might be easy

i need to do this

[hearty spire]

yes, so our task is to get the first letters. can you write a loop that does that?

[river barn]

yeah i need to use for loop

[hearty spire]

write it. then the next steps will be clearer.

[river barn]

but how im confused on how to make it to m.t like i got names already but not in square bracket

my last step to make M.T

[hearty spire]

you already have them in a list (i.e. "square bracket") because of the .split(", ") that you did, as I said

try this:

for friend in list_friends:
    print(friend)

(in place of the loop you showed above)
what do you get?

[river barn]

🥲

[hearty spire]

right. so that is one element of your friends list, see?

so your list_friends actually looks like

[
  [ "Mike Tyson", "Muhammad Ali", "John Cena"]
]

there's another layer of list involved

[river barn]

really were? i only got one list one layer?

[hearty spire]

you did for friend in list_friends: print(friend) and got that

[river barn]

yeah it printed me a list

[hearty spire]

which means, that ["Mike Tyson", ...] is itself one element of list_friends

[river barn]

ohh ok how can i make it into two elements so i can use index

[hearty spire]

so, in list_friends there is a nested layer like I showed

[hearty spire]

what I would say is: don't append to list_friends

instead, directly do

list_friends = input("Enter the names etc etc").split(", ")

then you will end up with just one layer of list

[river barn]

ok i did that but it printed me two times

[hearty spire]

you also have print("\n".join(list_friends)) 🙂

[river barn]

yes ;-; so it can be down not stuck together

[hearty spire]

that's why it's printing twice

anyway, from here, can you work out how to turn each name string like "Mike Tyson" into initials?

[river barn]

initials idk about that my english knowledge is not that good tbh my bad 🥲

[hearty spire]

oh OK, that's fine. you don't need to apologize for it.
"initials" of a name just means the first letters of the name joined together. like M.T. for Mike Tyson, like you want.

[river barn]

oh yeah i need to that

[hearty spire]

now, coming back to the .split I discussed earlier...

[river barn]

but how 🥲 im confused on it like i can do two dimensional but in one element it is confusing

[hearty spire]

one step at a time

what should your first step be?

[river barn]

idk maybe try using index to get len letter i think

[hearty spire]

what do you mean by "get len letter"?

[river barn]

;-; nvm it doesn't exist

[humble rune]

I think it’d be helpful to deep dive into nested loops first @river barn

[hearty spire]

think, perhaps, about how you would solve this problem. if I gave you a random name and told you to abbreviate it, what are you doing in your head?

[river barn]

true but i still didn't reach that lesson

[hearty spire]

you're mentally splitting the word by spaces, isn't it?

[river barn]

yes or i use comma

[hearty spire]

so you just need to do the same in Python

how do you get the individual words out of the string "Mike Tyson" is the question then, right?

[river barn]

yeah

[hearty spire]

now, you've already used .split(", ") to turn "Mike Tyson, Muhammad Ali" into ["Mike Tyson", "Muhammad Ali"]. can you use something similar here as well? think about it.

[river barn]

ohhh does split work if it is empty like friend.split(" ")

[hearty spire]

yep!

[river barn]

ok then now it got turned into two elements now do i do friend([0][0])

[hearty spire]

you're on the right track. play with it and see.

[river barn]

TypeError: 'str' object is not callable 😭

what does callable

mean

[hearty spire]

friend([0][0]) is not directly valid...
to explain the error, "calling" is something you do to a function. for example, print is a function, that you call by adding parentheses like print("something").
so when you wrote friend([0][0]), because of the parentheses, you tried to call friend. but friend, being a str, is not callable.

[river barn]

sooo print(friend[0][0])?

[hearty spire]

that will run, yes. but it's not the full solution.

[river barn]

bro im sooo close i got the first letter in the first name

[hearty spire]

one thing, doing friend.split(" ") doesn't change friend. it gives you a new list.

[river barn]

well im close but not the right second letter

[hearty spire]

right, it's because of what I noted here ^^

you need to use the new list returned by splitting.

[river barn]

new list hmm

ok now the proplem is how do i make new list ;-;

do i do name_1.split(" ")?

[hearty spire]

well, you don't need to make it. friend.split(" ") already gives you the list.

you just need to use it.

store it in a variable, and then use it, for example.

[river barn]

i dont understand?

[river barn]

like i did it using name_2

[hearty spire]

you know how you did

list_friends = input("blah blah").split(", ")

?

[river barn]

yeah

oh no it has to be in one not two inputs

[hearty spire]

there, you stored the list given by split into a variable called list_friends

similar idea here

[river barn]

wait you sure i don't need use list to do that ;-;

[hearty spire]

I'm not sure what you mean by "use list to do that" 🙂

[river barn]

like i need to make list of names mike tyson, mohammad ali, john cena and by using split it could be two elements instead one so i can use index to do that getting first letter

[hearty spire]

yes, you need to do that

but as I said, split already gives you a list. you just need to store it in a variable, and then index into that variable.

name_parts = "Mike Tyson".split()
print(name_parts[0])  # M
print(name_parts[1])  # T

[river barn]

nope still same thing ;-;

[hearty spire]

ah sorry

[humble rune]

Can you explain the problem once again?

[river barn]

let me show you it is easy showing instead of explaining

[hearty spire]

name_parts = "Mike Tyson".split()
print(name_parts[0][0])  # M
print(name_parts[1][0])  # T

corrected ^^

[river barn]

it will work if it is single name but i got mulitple names

[humble rune]

!e

list_friends = ["Mike Tyson", "John Brown"]
for friend in list_friends:
    tmp = ""
    for short in friend.split():
      if short:
        tmp += short[0] + "."
    print(tmp)

[minor veldt]

:white_check_mark: Your 3.14 eval job has completed with return code 0.

001 | M.T.
002 | J.B.

[hearty spire]

that's where the loop comes in. you just need to run this inside the loop that goes over list_friends.

like nafez showed

[river barn]

huh what does tmp stand for 😭

and there is soo many stuff im confused

[humble rune]

just a random variable name i picked, this doesn't matter

[river barn]

but why using if statement here?

[humble rune]

You need to revise the basics 🙂

[humble rune]

there might be the case like list_friends = ["Mike Tyson", "John Brown", " "]list with an empty string, just ignore it

[river barn]

🥲 can we go vc perchance so you can explain it because it is confusing in many levels tbh

if you dont want to it's okay

[humble rune]

vc perchance?

[river barn]

voice chat

[humble rune]

voice chat sorry bro 🙁

[river barn]

ok then it's okay bro

[humble rune]

you can freely ask here, I'm available to help

[river barn]

i have too many questions ;-; like i got the names right but the initials still getting it wrong

[humble rune]

How are entering names?

[river barn]

list_friends=input("Enter the first and last name of your friend separated by a comma:").split(", ")
print("\n".join(list_friendsfriends))

[humble rune]

avoid input() for now, as this is confusing you.

[river barn]

really it is easy i think

[humble rune]

instead this do
list_friends = ["Mike Tyson", "John Brown"]

[river barn]

ok i did that now what list_friends=["Mike Tyson","John Brown"]
print("\n".join(list_friends))

[humble rune]

okay, what next u wanna know

[river barn]

hmm idk let me try something

[humble rune]

sure

[vale schooner]

There is also multiple Assignment which you can use

!e

list_friends = ["Mike Tyson", "John Brown"]
for friend in list_friends:
    a,b = list_friends.split()
    print(a) # Mike

[humble rune]

that's great, but difficult for beginners to understand it a, b = ...

[vale schooner]

Thats the basics i believe

[humble rune]

maybe, but i believe this might confuse them 🙂

le my confused brain* what if the name consists of three words hhh

[vale schooner]

We are not talking about edge cases here.. what if there is no space to begin with .. this code is not build for that

Bruh

[river barn]

sorry im back from suffering ;-;

all my methods didn't work 🥲

[cyan elbow]

!e if you just want to split once, then str.partition works, even for the edge case you mentioned ```py
forename, _, surname = 'Mike Tyson'.partition(' ')
print(forename)

forename, _, surname = 'Cara'.partition(' ')
print(forename)

[minor veldt]

:white_check_mark: Your 3.14 eval job has completed with return code 0.

001 | Mike
002 | Cara

[river barn]

well maybe but the str.partition i didn't take lesson about his function

[humble rune]

let's keep this thread specific to @river barn's problem, our edge cases will confuse him 🙂

[river barn]

😭 bruh

[humble rune]

yes

[river barn]

;-; i got all them right i got only initials i need to do

[cyan elbow]

(feel free to ignore this; I clearly didn't read up enough :)

[river barn]

it's okay

but for new someone im trying to get Mike Tyson turn into M.T and it need to be in for loop and with different name

[humble rune]

can you please share the code? I’m not really getting it

[vale schooner]

Naah

[humble rune]

!paste

[minor veldt]

Pasting large amounts of code

So that everyone can easily read your code, you can paste it in this website:
https://paste.pythondiscord.com/

After pasting your code, save it by clicking the Paste! button in the bottom left, or by pressing CTRL + S. After doing that, you will be navigated to the new paste's page. Copy the URL and post it here so others can see it.

[river barn]

ok then give me min to show you the project im dealing with

i need to do this project

[humble rune]

you need to enter names at runtime instead of depending on a static list now, right?

[river barn]

well i did that like i used input to write names and i got the first one right but the second one the initials are confusing

[humble rune]

Everything looks fine here.

[river barn]

nafez do you mind asking are you arab by any chance? so i can explain to you in arabic if you want

[vale schooner]

Show the code

[river barn]

ok give me min

[humble rune]

i know hindi/urdu 🙂

[river barn]

nvm ;-; idk hindi

[vale schooner]

tafa Salah .. did you put that name for example?

[river barn]

no this is video i took

[river barn]

here you go

i added : to the loop no need to fix it

[vale schooner]

I think our conversion confused you.. you are trying to mix many methods.. the friend.split() is unnecessary

[humble rune]

if im not wrong friend.slip(" ") return list?

[vale schooner]

Yes

[river barn]

idk someone told me to do that

[humble rune]

that's why he is getting unexpected output

replace line 4-8 with this code

for friend in list_friends:
    abbreviation = ""
    for res in friend.split():
        abbreviation = abbreviation + res[0] + "."
    print(abbreviation)

[river barn]

well it worked but it has one problem

[vale schooner]

And what is that?

[river barn]

it shouldn't print like that

[humble rune]

put the print outside the second loop

[vale schooner]

That looks harder

[river barn]

🥲

[vale schooner]

Make it more pythonic

[river barn]

huh pythonic???

[vale schooner]

Simple and clean

[river barn]

😭 bruh isn't python like easy language bruh why did it reach that level

[humble rune]

for res in friend.split():
abbreviation = abbreviation + res[0] + "."
print(abbreviation)

[vale schooner]

Yeah it is trust me

I think nested loops are too much for beginner

[river barn]

bro i still didn't take lesson about nested loops

[humble rune]

As a beginner, writing clean code doesn't matter tbh

[humble rune]

as i said hhh

[vale schooner]

Have you learned multiple assignment thats the easiest way

[river barn]

;-; yeah alot

[vale schooner]

Obv not you

Let me say this your indexing method was perfect only one line was unnecessary.. even if you leave it there it wouldn’t change anything

@river barn

You can either use multiple assignment
Or partition method if you don’t know about nested loops

[river barn]

pratition idk what it do

[minor veldt]

Python help channel closed for inactivity

This help channel has been closed. Feel free to create a new post in #1035199133436354600. To maximize your chances of getting a response, check out this guide on asking good questions.