🔒 Issue

[spice ice]

@smoky night

Python help channel opened

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[smoky night]

d={}
word=input("Enter a word:")
for ch in word:
    word=word.lower()
    if ch.isalpha()== True and not ch in "":
        d[word]=d.get(word,0)+1
        word=input("Enter a word:")
        if ch == "":
            break
for w in d:
    print(f'{w}:{d[w]}')

i dont know what the issue is

i want to get rid of the space
(the :3)

when there is nothing it s supposed to print how many times u wrote a certain word

[latent sphinx]

to be clear, you want to
count how many times a certain word is repeated
it is not case-sensitive so the and The is same
and if input is empty, it should display the counts?

[smoky night]

Exactly

[latent sphinx]

can u show me ur latest code again? this output doesn't seem to be from the code u sent

[smoky night]

d={}
word=input("Enter a word:")
for ch in word:
    word=word.lower()
    if ch.isalpha()== True and not ch in "":
        d[word]=d.get(word,0)+1
        word=input("Enter a word:")
        if ch == "":
            break
for w in d:
    print(f'{w}:{d[w]}')

[latent sphinx]

ok right now you are taking the first input outside the loop and the 2nd input inside the loop

it is better if you put the input in a separate loop so that it is executed from the same place every time

are you familiar with while loops?

[smoky night]

yes

[latent sphinx]

you can use a while loop to take the input an indefinite amount of times. later when you get an empty input, you can break out of it

so smth like this:

counter = {}
while True:
  word = input('Enter a word: ')

[smoky night]

now ch is undefined

[latent sphinx]

we actually don't need ch

you are only trying to count the words not the charecters

so the whole loop over the word is useless

[smoky night]

this part?

[latent sphinx]

the for loop yes

[smoky night]

what do i do with the if statement

[latent sphinx]

lets first think about how we can stop if the input is empty cuz in that case we don't want to process it right?

[smoky night]

we use break

[latent sphinx]

so right after taking the word as input, we shouldcheck if its empty and break out of the loop if it is

[smoky night]

if word =="":

[latent sphinx]

yes

if word =="":
  break

and i suppose you don't want to include whitespaces. either right? os if user entered " " you also want to stop?

[smoky night]

Whats a white space?

[latent sphinx]

just the charrecter that appears when u hit the space bar
" " that is called a whitespace

[smoky night]

Yes

[latent sphinx]

do u know about the strip() method?

[smoky night]

Yes

Word.strip()?

[latent sphinx]

yeah that will remove the whitespaces so " " becomes ""

you can use it while taking the input so whitespaces are removed at that time

counter = {}
while True:
  word = input('Enter a word: ').strip()

[smoky night]

I see

[latent sphinx]

so now u can try putting in an empty string or a space and see if it stops or not

[smoky night]

Ok

thank you

it works

[latent sphinx]

can i see your code?

[latent sphinx]

do u understand how it works?

[smoky night]

Yes

It’s going to run the program until it hits false

Then when the word is nothing

We break out of the while loop

Right?

[spice ice]

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